MARC2 Variant Comparison March 26, 2026

Same puzzle, different metaphors — comparing results for qwen3.5-122b. ← Back to Inspector

Row colors: MARC valid  fail  too transparent

Task 136: 2601afb7

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original Musical chairs at a costume party — everyone moves one seat right but leav ... [23 chars truncated] MARC valid 1
alt-1 biology A row of trees in autumn: each passes its fruit to its neighbor on one side, whi ... [52 chars truncated] fail
alt-10 astronomy Nebulae in a galactic ring: their spectra redshift one position clockwise while ... [112 chars truncated] MARC valid 1
alt-11 ocean/sailing Signal flags on a fleet of masts — the tide carries each flag's color one ... [76 chars truncated] fail
alt-12 electronics A shift register with two buses running in opposite directions — the signa ... [92 chars truncated] fail
alt-13 mythology The gods play their annual trick: each titan passes its divine aspect to the sib ... [140 chars truncated] fail
alt-14 dance Partners in a contra dance — sashes pass to the right while the dancers' r ... [82 chars truncated] fail
alt-15 geology Mineral veins in a canyon wall: erosion carries the pigment one fissure downstre ... [136 chars truncated] fail
alt-2 cooking A sushi conveyor belt where the fish switches plates in one direction but the ri ... [32 chars truncated] fail
alt-3 music An orchestra pit where the instruments trade seats in one direction but the shee ... [89 chars truncated] fail
alt-4 sports Relay racers on a circular track — jerseys get passed clockwise but stamin ... [29 chars truncated] fail
alt-5 weather Storm fronts that trade their color with the eastern neighbor and their fury wit ... [72 chars truncated] fail
alt-6 architecture A colonnade where the marble facades rotate one direction along the boulevard wh ... [88 chars truncated] fail
alt-7 warfare Banners and battalions rotate in opposite directions around the fortress walls & ... [56 chars truncated] fail
alt-8 theater Actors in a chorus line swap costumes to the right but trade their monologue len ... [89 chars truncated] fail
alt-9 gardening In the enchanted garden, flower colors blow rightward on the wind while root sys ... [108 chars truncated] fail
original qwen3.5-122b: k=1
"Musical chairs at a costume party — everyone moves one seat right but leaves their shadow behind."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9561 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**

*   **Scene:** A ballroom floor (orange background).
*   **Elements:**
    *   "Costumed dancers": These are colored pixels standing in "lanes".
    *   "Lanes": The description says "evenly spaced lanes". Looking at the examples, the grid seems to be composed of columns.
    *   "Heights": The dancers have different heights (number of pixels in a column).
    *   "Rooted to the floor's edge": They stand at the bottom.
    *   "Empty aisles of orange light": The background is Orange (O).
    *   "Odd lanes": Dancers stand in odd lanes (1st, 3rd, 5th... if 1-indexed, or 0, 2, 4... if 0-indexed). Let's check the examples.
    *   "Even lanes": Filled with orange floor.
*   **Transformation:**
    *   "Music stops... strange double game."
    *   "Costume swap": Each dancer strips off their costume and tosses it one partner to the right. The dancer at the far end throws theirs to the front (wrap around).
        *   This implies the *color* of the column moves to the right.
    *   "Shadows slide opposite way": Shadows slide one partner to the left. The frontmost shadow wraps to the back.
        *   This implies the *height* (or the shape of the column) moves to the left.
    *   "Result": Each lane has a borrowed costume (color) and a borrowed height (stature).
    *   "Orange floor fills every even lane and all the empty air above the dancers."
    *   "Dancers only ever stand in the odd lanes".

**2. Analyze the Training Examples:**

**Example 1:**
Input Grid (9x9):
Row 0: O O O O O O O O O
Row 1: O O O O O M O O O
Row 2: O O O O O M O O O
Row 3: O O O O O M O O O
Row 4: O O O O O M O O O
Row 5: O O O O O M O O O
Row 6: O O O A O M O B O
Row 7: O W O A O M O B O
Row 8: O W O A O M O B O

Let's look at the columns (0-indexed).
Col 0: All O.
Col 1: O, O, O, O, O, O, O, W, W. (Height 2, Color W)
Col 2: All O.
Col 3: O, O, O, O, O, O, A, A, A. (Height 3, Color A)
Col 4: All O.
Col 5: M, M, M, M, M, M, M, M, M. (Height 9, Color M)
Col 6: All O.
Col 7: O, O, O, O, O, O, B, B, B. (Height 3, Color B)
Col 8: All O.

Wait, looking at the input:
Row 0: O O O O O O O O O
Row 1: O O O O O M O O O
...
Row 6: O O O A O M O B O
Row 7: O W O A O M O B O
Row 8: O W O A O M O B O

Columns with non-Orange content:
Col 1: W at rows 7, 8. (Height 2)
Col 3: A at rows 6, 7, 8. (Height 3)
Col 5: M at rows 1-8. (Height 8? Wait, Row 0 is O. So rows 1-8 is 8 pixels).
Col 7: B at rows 6, 7, 8. (Height 3)

Let's check the Output Grid (9x9):
Row 0: O O O O O O O O O
Row 1: O O O W O O O O O
Row 2: O O O W O O O O O
Row 3: O O O W O O O O O
Row 4: O O O W O O O O O
Row 5: O O O W O O O O O
Row 6: O B O W O A O O O
Row 7: O B O W O A O M O
Row 8: O B O W O A O M O

Columns with non-Orange content in Output:
Col 1: B at rows 6, 7, 8. (Height 3, Color B)
Col 3: W at rows 1-8. (Height 8, Color W)
Col 5: A at rows 6, 7, 8. (Height 3, Color A)
Col 7: M at rows 7, 8. (Height 2, Color M)

Let's map Input Columns to Output Columns.
Input Columns (Odd indices): 1, 3, 5, 7.
Input Data:
Col 1: Color W, Height 2.
Col 3: Color A, Height 3.
Col 5: Color M, Height 8.
Col 7: Color B, Height 3.

Output Data:
Col 1: Color B, Height 3.
Col 3: Color W, Height 8.
Col 5: Color A, Height 3.
Col 7: Color M, Height 2.

Let's trace the "Costume" (Color) movement.
Input Colors: [W, A, M, B] at indices [1, 3, 5, 7].
Output Colors: [B, W, A, M] at indices [1, 3, 5, 7].
Movement:
W (from 1) -> 3.
A (from 3) -> 5.
M (from 5) -> 7.
B (from 7) -> 1.
This is a shift to the **Right** by 1 position (cyclic).
Index $i$ gets color from Index $i-2$ (since step is 2 columns).
Wait, indices are 1, 3, 5, 7.
1 gets from 7.
3 gets from 1.
5 gets from 3.
7 gets from 5.
So Color moves Right.

Let's trace the "Shadow" (Height) movement.
Input Heights: [2, 3, 8, 3] at indices [1, 3, 5, 7].
Output Heights: [3, 8, 3, 2] at indices [1, 3, 5, 7].
Movement:
Height 3 (from 7) -> 1.
Height 8 (from 5) -> 3.
Height 3 (from 3) -> 5.
Height 2 (from 1) -> 7.
This is a shift to the **Left** by 1 position (cyclic).
Index $i$ gets height from Index $i+2$.
So Height moves Left.

**Summary of Rule:**
1.  Identify the "active" columns. These are the odd-indexed columns (1, 3, 5, ...). Even columns are background (Orange).
2.  Extract the properties of each active column: Color and Height (number of non-Orange pixels from the bottom).
3.  Shift the **Colors** of the active columns one step to the **Right** (cyclic).
    *   Column $k$ takes the Color of Column $k-2$.
    *   Last active column takes Color of First active column.
4.  Shift the **Heights** of the active columns one step to the **Left** (cyclic).
    *   Column $k$ takes the Height of Column $k+2$.
    *   First active column takes Height of Last active column.
5.  Reconstruct the grid.
    *   Even columns remain all Orange.
    *   Odd columns are filled w

... [4600 chars truncated]
alt-1 biology qwen3.5-122b: fail
"A row of trees in autumn: each passes its fruit to its neighbor on one side, while its roots creep toward the neighbor on the other."
Fail (best cell_acc=0.53 at k=1)
Best Attempt
vs
Expected
Reasoning (12424 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Visuals:** "Colored trunks of varying heights stand rooted in amber soil, spaced evenly like trees in an orchard."
    *   "Amber soil" likely refers to the background color. In the examples, the background is 'O' (Orange/Amber).
    *   "Trunks" are the colored vertical lines.
    *   "Spaced evenly" suggests columns.
*   **Action:** "Each tree donates its bark color to the tree on its left while stealing the root depth of the tree on its left — a symbiotic exchange where pigment flows one way and vigor flows the other."
    *   "Tree on its left": This implies a relationship between adjacent columns containing trunks.
    *   "Donates bark color": The color of the trunk moves to the left.
    *   "Steals root depth": The height/length of the trunk comes from the tree on the left.
    *   "Pigment flows one way": Color moves Left.
    *   "Vigor flows the other": Height/Depth moves Right (since it steals from the left, it takes the left's height). Wait, "stealing the root depth of the tree on its left". If Tree B steals from Tree A (left of B), Tree B gets Tree A's depth. Tree A gives its color to Tree B? No, "donates its bark color to the tree on its left".
    *   Let's re-read carefully: "Each tree donates its bark color to the tree on its left".
        *   Tree $i$ gives color to Tree $i-1$.
        *   Tree $i$ steals root depth from Tree $i-1$.
        *   So Tree $i-1$ receives color from Tree $i$ and gives depth to Tree $i$.
        *   Wait, "stealing the root depth of the tree on its left".
        *   Tree $i$ (current) takes depth from Tree $i-1$ (left).
        *   Tree $i$ (current) gives color to Tree $i-1$ (left).
        *   This sounds like a swap of attributes between adjacent trees, but specifically:
            *   New Color of Tree $i-1$ = Old Color of Tree $i$.
            *   New Depth of Tree $i$ = Old Depth of Tree $i-1$.
    *   Let's check the examples to verify this interpretation.

**2. Analyze Training Example 1:**
*   **Input Grid:** 9x9. Background 'O'.
    *   Columns with trunks:
        *   Col 1 (index 0): All 'O'. No trunk.
        *   Col 2 (index 1): All 'O'. No trunk.
        *   Col 3 (index 2): 'O' everywhere.
        *   Col 4 (index 3): 'O' everywhere.
        *   Col 5 (index 4): 'O' everywhere.
        *   Col 6 (index 5): 'M' (Magenta) from row 1 to 8 (indices 1-8). Wait, let's look closer.
        *   Let's map the input grid coordinates (row, col).
        *   Rows 0-8, Cols 0-8.
        *   Background is 'O'.
        *   Trunks appear in specific columns.
        *   Col 5 (index 5): Rows 1-8 are 'M'. (Height 8).
        *   Col 7 (index 7): Rows 6-8 are 'B' (Blue). (Height 3).
        *   Col 3 (index 3): Rows 6-8 are 'A' (Azure). (Height 3).
        *   Wait, let's look at the input text again.
        *   Input:
            ```
            O O O O O O O O O
            O O O O O M O O O
            O O O O O M O O O
            O O O O O M O O O
            O O O O O M O O O
            O O O O O M O O O
            O O O A O M O B O
            O W O A O M O B O
            O W O A O M O B O
            ```
        *   Let's identify the "trees" (vertical lines of non-O colors).
        *   Tree 1: Column 1 (index 1). Rows 7-8 are 'W' (Maroon). Height 2.
        *   Tree 2: Column 3 (index 3). Rows 6-8 are 'A' (Azure). Height 3.
        *   Tree 3: Column 5 (index 5). Rows 1-8 are 'M' (Magenta). Height 8.
        *   Tree 4: Column 7 (index 7). Rows 6-8 are 'B' (Blue). Height 3.
        *   Note: The description says "Trunks only on every other column".
        *   In Input:
            *   Col 1 has 'W'.
            *   Col 3 has 'A'.
            *   Col 5 has 'M'.
            *   Col 7 has 'B'.
            *   These are indices 1, 3, 5, 7. They are spaced by 1 column of 'O'.
        *   So we have a sequence of trees at indices 1, 3, 5, 7.
        *   Let's list their properties (Color, Height, Bottom Row).
            *   Tree at Col 1: Color W, Height 2 (Rows 7,8). Bottom at 8.
            *   Tree at Col 3: Color A, Height 3 (Rows 6,7,8). Bottom at 8.
            *   Tree at Col 5: Color M, Height 8 (Rows 1..8). Bottom at 8.
            *   Tree at Col 7: Color B, Height 3 (Rows 6,7,8). Bottom at 8.
            *   All rooted at the bottom (Row 8).

*   **Output Grid:**
    ```
    O O O O O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O B O W O A O O O
    O B O W O A O M O
    O B O W O A O M O
    ```
    *   Let's identify trees in Output.
    *   Tree at Col 1: Color B, Height 3 (Rows 6,7,8).
    *   Tree at Col 3: Color W, Height 5 (Rows 4,5,6,7,8).
    *   Tree at Col 5: Color A, Height 3 (Rows 6,7,8).
    *   Tree at Col 7: Color M, Height 3 (Rows 6,7,8).
    *   Wait, let's check the heights 

... [7469 chars truncated]
alt-10 astronomy qwen3.5-122b: k=1
"Nebulae in a galactic ring: their spectra redshift one position clockwise while their luminous reach blueshifts one position counterclockwise — light and extent orbit in contrary motion."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10051 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Visual:** "Colored nebular columns of varying extent rise from an amber void, evenly distributed like beads on a cosmic string."
    *   "Amber void" likely refers to the background color. In the examples, the background is 'O' (Orange).
    *   "Nebular columns" are vertical structures of a specific color.
    *   "Varying extent" means they have different heights.
    *   "Evenly distributed" suggests they are in specific columns.
*   **Action:** "Each nebula's spectral color rotates one position to the right while each nebula's extent (height) rotates one position to the left — hue and magnitude precess in opposite senses."
    *   "Spectral color rotates one position to the right": This implies the *color* of the columns shifts. If there are columns of colors $C_1, C_2, C_3...$, the new colors become $C_{last}, C_1, C_2...$ or something similar. Wait, "rotates one position to the right" usually means index $i$ gets color from index $i-1$. Let's look at the columns.
    *   "Extent (height) rotates one position to the left": This implies the *heights* of the columns shift. If heights are $H_1, H_2, H_3...$, the new heights become $H_2, H_3... H_1$.
    *   "Hue and magnitude precess in opposite senses": Color shifts right, Height shifts left.
*   **Grid details:** "Same dimensions. Amber void is the background. Nebulae occupy alternating columns, anchored at the bottom."
    *   Background is 'O'.
    *   Nebulae are in specific columns (likely alternating, e.g., 1, 3, 5 or 2, 4, 6).
    *   Anchored at the bottom means the colored pixels start from the bottom row and go up.

**2. Analyze Training Example 1:**
*   **Input Grid:** 9x9
    *   Background: 'O' (Orange).
    *   Columns with non-O colors:
        *   Column 6 (index 5, 0-based): 'M' (Magenta). Height: Rows 1 to 8 (8 pixels high? Let's count).
            *   Row 0: O
            *   Row 1: M
            *   ...
            *   Row 8: M
            *   Wait, let's look closer.
            *   Col 5 (6th col): M at rows 1,2,3,4,5,6,7,8. Height = 8.
        *   Column 3 (index 2, 0-based): 'A' (Azure). Height: Rows 6,7,8. Height = 3.
        *   Column 7 (index 6, 0-based): 'B' (Blue). Height: Rows 6,7,8. Height = 3.
        *   Column 1 (index 0, 0-based): 'W' (Maroon). Height: Rows 7,8. Height = 2.
    *   Wait, let's re-examine the input grid structure.
    *   Input:
        ```
        O O O O O O O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O A O M O B O
        O W O A O M O B O
        O W O A O M O B O
        ```
    *   Let's identify the "Nebulae" (columns with non-background colors).
    *   Col 0: W at rows 7, 8. (Height 2)
    *   Col 2: A at rows 6, 7, 8. (Height 3)
    *   Col 5: M at rows 1, 2, 3, 4, 5, 6, 7, 8. (Height 8)
    *   Col 7: B at rows 6, 7, 8. (Height 3)
    *   Background is O.
    *   The columns are at indices 0, 2, 5, 7. They are not strictly alternating (0, 2, 4, 6...). But they are distinct columns.
    *   Let's check the Output Grid.
    *   Output:
        ```
        O O O O O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O B O W O A O O O
        O B O W O A O M O
        O B O W O A O M O
        ```
    *   Let's identify the columns in the Output.
    *   Col 0: B at rows 6, 7, 8. (Height 3)
    *   Col 2: W at rows 1, 2, 3, 4, 5, 6, 7, 8. (Height 8)
    *   Col 5: A at rows 6, 7, 8. (Height 3)
    *   Col 7: M at rows 7, 8. (Height 2)
    *   Wait, let's look at the mapping.
    *   Input Columns (Left to Right):
        1.  Col 0: Color W, Height 2.
        2.  Col 2: Color A, Height 3.
        3.  Col 5: Color M, Height 8.
        4.  Col 7: Color B, Height 3.
    *   Output Columns (Left to Right):
        1.  Col 0: Color B, Height 3.
        2.  Col 2: Color W, Height 8.
        3.  Col 5: Color A, Height 3.
        4.  Col 7: Color M, Height 2.
    *   Let's check the rule: "Color rotates right, Height rotates left".
    *   List of Colors (Input): [W, A, M, B]
    *   List of Heights (Input): [2, 3, 8, 3]
    *   List of Colors (Output): [B, W, A, M] -> This is a Right Rotation of [W, A, M, B]. (B moves from end to start).
    *   List of Heights (Output): [3, 8, 3, 2] -> This is a Left Rotation of [2, 3, 8, 3]. (2 moves from start to end).
    *   So the rule holds:
        *   Identify the active columns (columns containing non-background colors).
        *   Extract the sequence of Colors and Heights for these columns from left to right.
        *   Rotate the Color sequence Right by 1.
        *   Rotate the Height sequence Left by 1.
        *   Reconstruct the grid using the original column positions, but assign

... [5063 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fail
"Signal flags on a fleet of masts — the tide carries each flag's color one mast starboard while the current drags each mast's height one position port."
Fail (best cell_acc=0.76 at k=3)
Best Attempt
vs
Expected
Reasoning (11278 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** Colored signal pennants of varying lengths fly from evenly spaced masts rising from an amber sea.
*   **Background:** Amber ocean (Color 'O').
*   **Masts:** Stand on alternating columns, rooted at the bottom.
*   **Pennants:** Colored signal pennants of varying lengths.
*   **Transformation:**
    *   "Each pennant's color drifts one mast to the right".
    *   "Each mast's pennant length drifts one mast to the left".
    *   "Color and length are carried by opposing currents."

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 9x9 grid. Background 'O'.
    *   Columns with non-O colors:
        *   Col 5 (0-indexed): M (magenta) from row 1 to 8. Length 8.
        *   Col 7: B (blue) from row 6 to 8. Length 3.
        *   Col 3: A (azure) from row 6 to 8. Length 3.
        *   Col 1: W (maroon) from row 7 to 8. Length 2.
    *   Wait, let's look closer at the structure.
    *   Input:
        ```
        O O O O O O O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O B O  <- Wait, row 6 col 7 is B? No, row 6 col 7 is O. Row 6 col 7 is O.
        Let's re-read the input grid carefully.
        Row 0: O O O O O O O O O
        Row 1: O O O O O M O O O
        Row 2: O O O O O M O O O
        Row 3: O O O O O M O O O
        Row 4: O O O O O M O O O
        Row 5: O O O O O M O O O
        Row 6: O O O O O M O B O  (Col 5 is M, Col 7 is B)
        Row 7: O W O A O M O B O  (Col 1 is W, Col 3 is A, Col 5 is M, Col 7 is B)
        Row 8: O W O A O M O B O
        ```
    *   Let's identify the "Masts". The description says "Masts stand on alternating columns".
    *   In the input, we see vertical lines of colors.
    *   Col 1: W (rows 7-8).
    *   Col 3: A (rows 6-8).
    *   Col 5: M (rows 1-8).
    *   Col 7: B (rows 6-8).
    *   These look like the "Masts" or "Pennants". The description says "Masts stand on alternating columns". Here columns 1, 3, 5, 7 are occupied. These are alternating (odd indices).
    *   The "Pennants" are the colored blocks.
    *   Transformation Rule Interpretation:
        *   "Each pennant's color drifts one mast to the right".
        *   "Each mast's pennant length drifts one mast to the left".
    *   Let's look at the Output for Example 1.
        ```
        O O O O O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O B O W O A O O O
        O B O W O A O M O
        O B O W O A O M O
        ```
    *   Output Columns with colors:
        *   Col 1: B (rows 6-8).
        *   Col 3: W (rows 1-8).
        *   Col 5: A (rows 6-8).
        *   Col 7: M (rows 7-8).
    *   Let's map Input to Output.
    *   Input Col 1 (W, len 2) -> Output Col 3 (W, len 8). Wait.
    *   Input Col 3 (A, len 3) -> Output Col 5 (A, len 3).
    *   Input Col 5 (M, len 8) -> Output Col 7 (M, len 2).
    *   Input Col 7 (B, len 3) -> Output Col 1 (B, len 3).
    *   This looks like a cyclic shift of columns?
    *   Col 1 -> Col 3?
    *   Col 3 -> Col 5?
    *   Col 5 -> Col 7?
    *   Col 7 -> Col 1?
    *   Let's check the lengths.
    *   Input Col 1 (W) len 2. Output Col 3 (W) len 8. Length changed.
    *   Input Col 3 (A) len 3. Output Col 5 (A) len 3. Length same.
    *   Input Col 5 (M) len 8. Output Col 7 (M) len 2. Length changed.
    *   Input Col 7 (B) len 3. Output Col 1 (B) len 3. Length same.
    *   This doesn't match "Color drifts right, Length drifts left" simply.
    *   Let's re-read the metaphor: "Each pennant's color drifts one mast to the right while each mast's pennant length drifts one mast to the left".
    *   This implies two separate properties: Color and Length.
    *   Let's define the "Masts". They are the columns 1, 3, 5, 7.
    *   Let's define the "Pennant" at a mast. It has a Color and a Length.
    *   Input State:
        *   Mast 1: Color W, Length 2.
        *   Mast 3: Color A, Length 3.
        *   Mast 5: Color M, Length 8.
        *   Mast 7: Color B, Length 3.
    *   Output State:
        *   Mast 1: Color B, Length 3.
        *   Mast 3: Color W, Length 8.
        *   Mast 5: Color A, Length 3.
        *   Mast 7: Color M, Length 2.
    *   Let's trace the properties.
    *   Colors:
        *   Input: W(1), A(3), M(5), B(7).
        *   Output: B(1), W(3), A(5), M(7).
        *   Mapping:
            *   W moved from 1 to 3. (Right 1 mast)
            *   A moved from 3 to 5. (Right 1 mast)
            *   M moved from 5 to 7. (Right 1 mast)
            *   B moved from 7 to 1. (Right 1 mast, wrapping around?)
    *   Lengths:
        *   Input: 2(1), 3(3), 8(5), 3(7).
        *   Output: 3(1), 8(3), 3(5), 2(7).
        *   Mappi

... [6383 chars truncated]
alt-12 electronics qwen3.5-122b: fail
"A shift register with two buses running in opposite directions — the signal type propagates right while the amplitude propagates left, and they meet at new junctions."
Fail (best cell_acc=0.30 at k=2)
Best Attempt
vs
Expected
Reasoning (11989 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Visual:** "Colored voltage bars of varying amplitude stand on alternating nodes along an amber circuit board, all grounded at the bottom."
    *   "Amber circuit board" likely refers to the background color 'O' (Orange/Amber).
    *   "Colored voltage bars" are the non-background colored cells.
    *   "Alternating nodes" suggests the bars are in specific columns.
    *   "Grounded at the bottom" suggests the bars start from the bottom row and go up.
*   **Action:** "Each node's signal type (color) shifts one node to the right while each node's amplitude (height) shifts one node to the left — data and power counterflow through the register."
    *   "Signal type (color)" shifts right.
    *   "Amplitude (height)" shifts left.
    *   "Counterflow": Color moves one way, Height moves the other.
*   **Grid Details:** "Identical dimensions. Amber PCB fills the background. Bars occupy alternating columns, rising from the bottom edge."
    *   This confirms the background is 'O'.
    *   Bars are vertical structures.
    *   "Alternating columns" implies columns 1, 3, 5... or 2, 4, 6... (0-indexed or 1-indexed). Looking at the examples will clarify which columns.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
O O O O O O O O O
O O O O O M O O O
O O O O O M O O O
O O O O O M O O O
O O O O O M O O O
O O O O O M O O O
O O O A O M O B O
O W O A O M O B O
O W O A O M O B O
```
Output:
```
O O O O O O O O O
O O O W O O O O O
O O O W O O O O O
O O O W O O O O O
O O O W O O O O O
O O O W O O O O O
O B O W O A O O O
O B O W O A O M O
O B O W O A O M O
```
*   **Background:** 'O' (Orange).
*   **Input Bars:**
    *   Column 1 (0-indexed): 'W' (Maroon) at rows 7, 8. Height = 2. Color = W.
    *   Column 3: 'A' (Azure) at rows 6, 7, 8. Height = 3. Color = A.
    *   Column 5: 'M' (Magenta) at rows 1-8. Height = 8. Color = M.
    *   Column 7: 'B' (Blue) at rows 6, 7, 8. Height = 3. Color = B.
    *   Wait, let's look closer at the columns.
    *   Input Grid (9x9):
        *   Col 0: All O.
        *   Col 1: W at bottom (rows 7,8).
        *   Col 2: All O.
        *   Col 3: A at bottom (rows 6,7,8).
        *   Col 4: All O.
        *   Col 5: M at bottom (rows 1-8).
        *   Col 6: All O.
        *   Col 7: B at bottom (rows 6,7,8).
        *   Col 8: All O.
    *   So bars are in columns 1, 3, 5, 7. These are odd indices (1, 3, 5, 7).
    *   Wait, the description says "alternating nodes".
    *   Let's check the Output Grid.
    *   Output Grid:
        *   Col 1: W at rows 1-6. Height = 6. Color = W.
        *   Col 3: B at rows 6,7,8. Height = 3. Color = B.
        *   Col 5: A at rows 6,7,8. Height = 3. Color = A.
        *   Col 7: M at rows 7,8. Height = 2. Color = M.
    *   Let's trace the movement.
    *   **Input:**
        *   Col 1: Color W, Height 2.
        *   Col 3: Color A, Height 3.
        *   Col 5: Color M, Height 8.
        *   Col 7: Color B, Height 3.
    *   **Output:**
        *   Col 1: Color W, Height 6.
        *   Col 3: Color B, Height 3.
        *   Col 5: Color A, Height 3.
        *   Col 7: Color M, Height 2.
    *   **Hypothesis:**
        *   "Signal type (color) shifts one node to the right":
            *   Input Col 1 (W) -> Output Col 3? No, Output Col 3 is B.
            *   Input Col 3 (A) -> Output Col 5? Yes, Output Col 5 is A.
            *   Input Col 5 (M) -> Output Col 7? Yes, Output Col 7 is M.
            *   Input Col 7 (B) -> Output Col 1? (Wrap around?) Output Col 1 is W.
            *   Wait, Input Col 1 is W. Output Col 1 is W.
            *   Let's re-examine Output Col 1. It has W. Input Col 1 had W.
            *   Let's re-examine Output Col 3. It has B. Input Col 7 had B.
            *   Let's re-examine Output Col 5. It has A. Input Col 3 had A.
            *   Let's re-examine Output Col 7. It has M. Input Col 5 had M.
            *   So Colors moved:
                *   Col 3 (A) -> Col 5. (Right shift)
                *   Col 5 (M) -> Col 7. (Right shift)
                *   Col 7 (B) -> Col 1? (Wrap around right shift?)
                *   Col 1 (W) -> Col 3? No, Output Col 3 is B.
            *   Let's look at the heights.
            *   Input Heights: Col 1=2, Col 3=3, Col 5=8, Col 7=3.
            *   Output Heights: Col 1=6, Col 3=3, Col 5=3, Col 7=2.
            *   Height Movement:
                *   Input Col 1 (2) -> Output Col 7 (2). (Left shift with wrap?)
                *   Input Col 3 (3) -> Output Col 3 (3). (Stay?)
                *   Input Col 5 (8) -> Output Col 1 (6). (Left shift?)
                *   Input Col 7 (3) -> Output Col 5 (3). (Left shift?)
            *   This is confusing. Let's look at the metaphor again.
            *   "Each node's signal type (color) shifts one node to the right"
            

... [7094 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"The gods play their annual trick: each titan passes its divine aspect to the sibling on the right, but steals the mortal stature of the sibling on the left — divinity and mortality rotate like a two-headed serpent."
Fail (best cell_acc=0.76 at k=3)
Best Attempt
vs
Expected
Reasoning (10799 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Titans of different divine colors and mortal heights stand on amber earth in evenly spaced sacred groves."
    *   "Amber earth" likely refers to the background color, which is 'O' (Orange) in the examples.
    *   "Titans" are the non-background colored pixels.
    *   "Evenly spaced sacred groves" suggests columns or specific positions.
*   **Action:** "Each titan's divine color cycles one position rightward while each titan's mortal stature cycles one position leftward — essence and presence contra-rotate around the pantheon."
    *   "Divine color" -> The color of the pixel.
    *   "Mortal stature" -> The vertical position (height) of the pixel? Or maybe the column index?
    *   "Cycles one position rightward" -> Horizontal shift?
    *   "Cycles one position leftward" -> Horizontal shift?
    *   "Contra-rotate" -> One goes right, one goes left.
    *   "Essence and presence" -> Color and Position?
*   **Grid details:** "Same dimensions. Amber earth is the background. Titans stand on alternating columns, rooted at the bottom."
    *   "Rooted at the bottom" suggests the objects are vertical bars or stacks of pixels starting from the bottom row and going up.
    *   "Alternating columns" suggests the objects are in specific columns (e.g., 1, 3, 5... or 2, 4, 6...).

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
O O O O O O O O O
O O O O O M O O O
O O O O O M O O O
O O O O O M O O O
O O O O O M O O O
O O O O O M O O O
O O O A O M O B O
O W O A O M O B O
O W O A O M O B O
```
Background: O (Orange).
Objects:
- Column 2 (0-indexed): W (Maroon) at rows 7, 8. (Height 2)
- Column 4: A (Azure) at rows 6, 7, 8. (Height 3)
- Column 6: M (Magenta) at rows 1, 2, 3, 4, 5, 6, 7, 8. (Height 8)
- Column 8: B (Blue) at rows 6, 7, 8. (Height 3)
Wait, let's look closer at the columns.
Input Grid (9x9):
Col 0: All O
Col 1: O, O, O, O, O, O, O, W, W (Rows 7,8 are W) -> Wait, looking at the text:
Row 0: O O O O O O O O O
Row 1: O O O O O M O O O
...
Row 6: O O O A O M O B O
Row 7: O W O A O M O B O
Row 8: O W O A O M O B O

Let's list the non-O pixels by column.
Col 1: W at (7,1), (8,1). Height 2.
Col 3: A at (6,3), (7,3), (8,3). Height 3.
Col 5: M at (1,5) to (8,5). Height 8.
Col 7: B at (6,7), (7,7), (8,7). Height 3.
Note: The columns are 1, 3, 5, 7. These are alternating columns (odd indices).
The objects are vertical bars rooted at the bottom (Row 8).

Output Grid:
Row 0: O O O O O O O O O
Row 1: O O O W O O O O O
...
Row 5: O O O W O O O O O
Row 6: O B O W O A O O O
Row 7: O B O W O A O M O
Row 8: O B O W O A O M O

Let's list non-O pixels in Output by column.
Col 1: B at (6,1), (7,1), (8,1). Height 3.
Col 3: W at (1,3) to (8,3). Height 8.
Col 5: A at (6,5), (7,5), (8,5). Height 3.
Col 7: M at (7,7), (8,7). Height 2.

Comparison:
Input Col 1 (W, H=2) -> Output Col 3 (W, H=8). Wait, W moved from Col 1 to Col 3. Height changed from 2 to 8?
Input Col 3 (A, H=3) -> Output Col 5 (A, H=3). A moved from Col 3 to Col 5. Height stayed 3?
Input Col 5 (M, H=8) -> Output Col 7 (M, H=2). M moved from Col 5 to Col 7. Height changed from 8 to 2?
Input Col 7 (B, H=3) -> Output Col 1 (B, H=3). B moved from Col 7 to Col 1. Height stayed 3?

Let's re-examine the "Divine color cycles one position rightward" and "Mortal stature cycles one position leftward".
Columns involved: 1, 3, 5, 7.
Let's map the columns cyclically: 1 -> 3 -> 5 -> 7 -> 1.
Input Col 1 (W) -> Output Col 3. (Right shift in column index).
Input Col 3 (A) -> Output Col 5. (Right shift).
Input Col 5 (M) -> Output Col 7. (Right shift).
Input Col 7 (B) -> Output Col 1. (Right shift).
So, the **Color** (the object identity) moves one column to the right (cyclically among the occupied columns).

Now about the "Mortal stature" (Height).
Input Heights:
Col 1: 2 (W)
Col 3: 3 (A)
Col 5: 8 (M)
Col 7: 3 (B)

Output Heights:
Col 1: 3 (B) -> This came from Col 7.
Col 3: 8 (W) -> This came from Col 1.
Col 5: 3 (A) -> This came from Col 3.
Col 7: 2 (M) -> This came from Col 5.

Let's check the mapping of heights.
Input Heights sequence (Col 1, 3, 5, 7): [2, 3, 8, 3]
Output Heights sequence (Col 1, 3, 5, 7): [3, 8, 3, 2]
It looks like the heights shifted **Left** relative to the columns.
Col 1 gets height from Col 7 (Left neighbor in cyclic order 1<-7<-5<-3<-1).
Col 3 gets height from Col 1.
Col 5 gets height from Col 3.
Col 7 gets height from Col 5.
So, the **Height** moves one column to the left (cyclically).

Let's verify this hypothesis with the metaphor:
"Each titan's divine color cycles one position rightward" -> The color (W, A, M, B) moves to the next column to the right.
"Each titan's mortal stature cycles one position leftward" -> The height associated with a column moves to the next column 

... [5982 chars truncated]
alt-14 dance qwen3.5-122b: fail
"Partners in a contra dance — sashes pass to the right while the dancers' reach extends from the left, so everyone ends up in a new costume at a new stretch."
Fail (best cell_acc=0.58 at k=2)
Best Attempt
vs
Expected
Reasoning (12116 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** Dancers in colored sashes of varying heights stand on amber marks, evenly spaced across the floor.
*   **Action:** Each dancer's sash color moves one place to the right while each dancer's extension (height) moves one place to the left — adornment and posture circulate as opposing spirals.
*   **Grid details:** Same grid size. Amber floor is the background. Dancers occupy alternating columns, anchored at the bottom.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Grid Size: 9x9
    *   Background: 'O' (Orange/Amber)
    *   Input Columns:
        *   Col 0: All 'O'
        *   Col 1: All 'O'
        *   Col 2: All 'O'
        *   Col 3: All 'O'
        *   Col 4: All 'O'
        *   Col 5: 'M' (Magenta) from row 1 to 8. (Height 8)
        *   Col 6: All 'O'
        *   Col 7: 'B' (Blue) from row 6 to 8. (Height 3)
        *   Col 8: All 'O'
        *   Wait, let's look closer at the input structure.
        *   Rows 0-5: Col 5 is 'M'.
        *   Rows 6-8: Col 5 is 'M', Col 7 is 'B'.
        *   Rows 6-8: Col 3 is 'A' (Azure).
        *   Rows 7-8: Col 1 is 'W' (Maroon).
        *   Let's re-examine the input grid for Example 1.
        *   Input:
            R0: O O O O O O O O O
            R1: O O O O O M O O O
            R2: O O O O O M O O O
            R3: O O O O O M O O O
            R4: O O O O O M O O O
            R5: O O O O O M O O O
            R6: O W O A O M O B O
            R7: O W O A O M O B O
            R8: O W O A O M O B O
        *   Columns with non-O colors:
            *   Col 1: 'W' at R7, R8. (Height 2)
            *   Col 3: 'A' at R6, R7, R8. (Height 3)
            *   Col 5: 'M' at R1..R8. (Height 8)
            *   Col 7: 'B' at R6..R8. (Height 3)
        *   Output:
            R0: O O O O O O O O O
            R1: O O O W O O O O O
            R2: O O O W O O O O O
            R3: O O O W O O O O O
            R4: O O O W O O O O O
            R5: O O O W O O O O O
            R6: O B O W O A O O O
            R7: O B O W O A O M O
            R8: O B O W O A O M O
        *   Columns with non-O colors in Output:
            *   Col 1: 'B' at R6..R8. (Height 3)
            *   Col 3: 'W' at R1..R8. (Height 8)
            *   Col 5: 'A' at R6..R8. (Height 3)
            *   Col 7: 'M' at R7..R8. (Height 2)
        *   Observation:
            *   Col 1 Input: 'W' (Height 2). Output Col 1: 'B' (Height 3).
            *   Col 3 Input: 'A' (Height 3). Output Col 3: 'W' (Height 8).
            *   Col 5 Input: 'M' (Height 8). Output Col 5: 'A' (Height 3).
            *   Col 7 Input: 'B' (Height 3). Output Col 7: 'M' (Height 2).
            *   It looks like the *colors* are shifting columns, and the *heights* are shifting columns.
            *   Let's check the metaphor: "sash color moves one place to the right while each dancer's extension (height) moves one place to the left".
            *   "Dancers occupy alternating columns". In Input, columns 1, 3, 5, 7 have dancers. These are alternating (odd indices).
            *   In Output, columns 1, 3, 5, 7 have dancers.
            *   Let's trace the "Sash Color" (the color of the block).
                *   Input Col 1 has 'W'. Output Col 3 has 'W'. (Moved Right 1 step? 1 -> 3 is +2).
                *   Input Col 3 has 'A'. Output Col 5 has 'A'. (Moved Right 1 step? 3 -> 5 is +2).
                *   Input Col 5 has 'M'. Output Col 7 has 'M'. (Moved Right 1 step? 5 -> 7 is +2).
                *   Input Col 7 has 'B'. Output Col 1 has 'B'. (Moved Right 1 step? 7 -> 1 is wrap around? Or maybe it's a cycle).
                *   Wait, the metaphor says "moves one place to the right". If columns are 1, 3, 5, 7. Moving "one place" in the sequence of dancer columns means 1->3, 3->5, 5->7, 7->1.
                *   So, Color at Col $i$ moves to Col $i+2$ (next dancer column).
            *   Let's trace the "Extension (Height)" (the number of blocks).
                *   Input Col 1 Height: 2. Output Col 7 Height: 2. (Moved Left 1 step? 1 -> 7 is previous in sequence).
                *   Input Col 3 Height: 3. Output Col 1 Height: 3. (Moved Left 1 step? 3 -> 1).
                *   Input Col 5 Height: 8. Output Col 3 Height: 8. (Moved Left 1 step? 5 -> 3).
                *   Input Col 7 Height: 3. Output Col 5 Height: 3. (Moved Left 1 step? 7 -> 5).
            *   So, Height at Col $i$ moves to Col $i-2$ (previous dancer column).
            *   Let's verify this hypothesis.
            *   Input:
                *   Col 1: Color W, Height 2.
                *   Col 3: Color A, Height 3.
                *   Col 5: Color M, Height 8.
                *   Col 7: Color B, Height 3.
            *   Transformation:
                *   New Col 1 gets Color from Col 7 (B) and Height from Col 3 (

... [7209 chars truncated]
alt-15 geology qwen3.5-122b: fail
"Mineral veins in a canyon wall: erosion carries the pigment one fissure downstream while tectonic pressure pushes the depth one fissure upstream — color and strata migrate in opposing currents through the rock."
Fail (best cell_acc=0.53 at k=1)
Best Attempt
vs
Expected
Reasoning (11583 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Colored mineral veins of varying depth stripe an amber cliff face at regular intervals, all anchored to the canyon floor."
*   **Action:** "Each vein's mineral color shifts one fissure to the right while each vein's depth (height) shifts one fissure to the left — pigment and pressure contra-flow through the geology."
*   **Grid Details:** "Identical dimensions. Amber rock is the matrix. Veins occupy alternating columns, rising from the bottom edge."

**2. Analyze the Training Example (Example 1):**
*   **Input Grid:** 9x9
    *   Background seems to be 'O' (Orange/Amber).
    *   There are vertical columns of other colors.
    *   Column 5 (0-indexed) has 'M' (Magenta) from row 1 to 8.
    *   Column 3 has 'A' (Azure) from row 6 to 8.
    *   Column 7 has 'B' (Blue) from row 6 to 8.
    *   Column 1 has 'W' (Maroon) from row 7 to 8.
    *   Wait, let's look closer at the columns.
    *   Col 0: All O
    *   Col 1: O, O, O, O, O, O, O, W, W (Rows 7,8 are W)
    *   Col 2: All O
    *   Col 3: O, O, O, O, O, O, A, A, A (Rows 6,7,8 are A)
    *   Col 4: All O
    *   Col 5: O, M, M, M, M, M, M, M, M (Rows 1-8 are M)
    *   Col 6: All O
    *   Col 7: O, O, O, O, O, O, B, B, B (Rows 6,7,8 are B)
    *   Col 8: All O
    *   So, "Veins occupy alternating columns". In the input, veins are in cols 1, 3, 5, 7. These are odd indices.
    *   "Rising from the bottom edge". Yes, the colored blocks start from the bottom row (row 8) and go up.
    *   "Amber rock is the matrix". 'O' is the background.

*   **Output Grid:** 9x9
    *   Col 0: All O
    *   Col 1: O, O, O, O, O, O, O, O, O (All O) -> Wait, looking at the output provided in the prompt.
    *   Let's check the Output provided in Example 1 text:
        ```
        O O O O O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O B O W O A O O O
        O B O W O A O M O
        O B O W O A O M O
        ```
    *   Let's map the columns in Output:
        *   Col 0: All O
        *   Col 1: O, O, O, O, O, O, B, B, B (Rows 6,7,8 are B) -> This was Col 7 in Input.
        *   Col 2: All O
        *   Col 3: O, W, W, W, W, W, W, W, W (Rows 1-8 are W) -> This was Col 1 in Input.
        *   Col 4: All O
        *   Col 5: O, O, O, O, O, O, A, A, A (Rows 6,7,8 are A) -> This was Col 3 in Input.
        *   Col 6: All O
        *   Col 7: O, O, O, O, O, O, O, M, M (Rows 7,8 are M) -> This was Col 5 in Input.
        *   Col 8: All O

*   **Transformation Logic:**
    *   The metaphor says: "Each vein's mineral color shifts one fissure to the right while each vein's depth (height) shifts one fissure to the left".
    *   "Vein's mineral color shifts one fissure to the right": This implies the column index increases by 1.
        *   Input Col 1 (W) -> Output Col 3 (W). Shift +2?
        *   Input Col 3 (A) -> Output Col 5 (A). Shift +2?
        *   Input Col 5 (M) -> Output Col 7 (M). Shift +2?
        *   Input Col 7 (B) -> Output Col 1 (B). Shift -6? Or wrap around?
        *   Wait, the metaphor says "shifts one fissure to the right".
        *   Let's look at the "Veins occupy alternating columns".
        *   Input Veins at indices: 1, 3, 5, 7.
        *   Output Veins at indices: 1, 3, 5, 7.
        *   Wait, in Output:
            *   Col 1 has B (from Input Col 7).
            *   Col 3 has W (from Input Col 1).
            *   Col 5 has A (from Input Col 3).
            *   Col 7 has M (from Input Col 5).
        *   So the columns are permuted.
        *   Col 1 <- Col 7
        *   Col 3 <- Col 1
        *   Col 5 <- Col 3
        *   Col 7 <- Col 5
        *   This looks like a cyclic shift of the *veins* themselves.
        *   Vein 1 (Col 1) moves to Col 3.
        *   Vein 2 (Col 3) moves to Col 5.
        *   Vein 3 (Col 5) moves to Col 7.
        *   Vein 4 (Col 7) moves to Col 1.
        *   This is a "shift one fissure to the right" in terms of the sequence of veins. Since veins are in alternating columns, moving to the "next" vein column is +2 indices.
        *   So, Column Index $c_{new} = c_{old} + 2$. If it exceeds the max vein column, it wraps to the first vein column.
        *   Let's check the "depth (height) shifts one fissure to the left".
        *   Input Col 1 (W): Height 2 (Rows 7,8). Output Col 3 (W): Height 8 (Rows 1-8).
            *   Wait, Input W is at bottom 2 rows. Output W is at bottom 8 rows. Height increased?
            *   Metaphor: "depth (height) shifts one fissure to the left".
            *   Usually "shift left" means decrease index.
            *   Let's look at the rows.
            *   Input W: Rows 7, 8. (Height 2).
            *   Output W: Rows 1, 2, 3, 4, 5, 6, 7, 8. (Height 8).
            *  

... [6646 chars truncated]
alt-2 cooking qwen3.5-122b: fail
"A sushi conveyor belt where the fish switches plates in one direction but the rice portions slide the other way."
Fail (best cell_acc=0.00 at k=1)
No grid
vs
Expected
Reasoning (12126 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** Colored ingredients on pedestals along an amber counter.
*   **Action:**
    *   "Each ingredient's identity (flavor/color) shifts one pedestal to the left".
    *   "Each pedestal's portion size shifts one position to the right".
    *   "The tastes rotate against the servings".
*   **Grid Details:**
    *   Grid matches input size.
    *   Amber is the counter surface (likely the background color, 'O' for Orange/Amber).
    *   Ingredients form vertical stacks on alternating columns, built up from the bottom edge.

**2. Analyze the Training Example 1:**
*   **Input Grid:** 9x9
    *   Background seems to be 'O' (Orange).
    *   There are vertical stacks of colors.
    *   Column 1 (index 0): All 'O'.
    *   Column 2 (index 1): 'O' at top, 'W' (Maroon) at bottom 3 rows.
    *   Column 3 (index 2): All 'O'.
    *   Column 4 (index 3): 'O' at top, 'A' (Azure) at bottom 3 rows.
    *   Column 5 (index 4): All 'O'.
    *   Column 6 (index 5): 'M' (Magenta) from row 1 to 8 (indices 1-8). Wait, let's look closer.
        *   Row 0: O O O O O O O O O
        *   Row 1: O O O O O M O O O
        *   Row 2: O O O O O M O O O
        *   Row 3: O O O O O M O O O
        *   Row 4: O O O O O M O O O
        *   Row 5: O O O O O M O O O
        *   Row 6: O O O A O M O B O
        *   Row 7: O W O A O M O B O
        *   Row 8: O W O A O M O B O
    *   Let's identify the "stacks".
        *   Col 1 (idx 1): W at rows 7,8. (Height 2)
        *   Col 3 (idx 3): A at rows 6,7,8. (Height 3)
        *   Col 5 (idx 5): M at rows 1-8. (Height 8)
        *   Col 7 (idx 7): B at rows 6,7,8. (Height 3)
    *   Wait, the description says "Ingredients form vertical stacks on alternating columns".
    *   Let's check the columns with non-O colors.
        *   Col 1: W (rows 7,8)
        *   Col 3: A (rows 6,7,8)
        *   Col 5: M (rows 1-8)
        *   Col 7: B (rows 6,7,8)
    *   These are indeed alternating columns (1, 3, 5, 7).
    *   The "counter surface" is 'O'.

*   **Output Grid:** 9x9
    *   Row 0: O O O O O O O O O
    *   Row 1: O O O W O O O O O
    *   Row 2: O O O W O O O O O
    *   Row 3: O O O W O O O O O
    *   Row 4: O O O W O O O O O
    *   Row 5: O O O W O O O O O
    *   Row 6: O B O W O A O O O
    *   Row 7: O B O W O A O M O
    *   Row 8: O B O W O A O M O

    *   Let's identify the stacks in the output.
        *   Col 1: B (rows 6,7,8). (Height 3)
        *   Col 3: W (rows 1-8). (Height 8)
        *   Col 5: A (rows 6,7,8). (Height 3)
        *   Col 7: M (rows 7,8). (Height 2)

    *   **Comparison:**
        *   Input Col 1 (W, height 2) -> Output Col 3 (W, height 8). Wait, height changed?
        *   Input Col 3 (A, height 3) -> Output Col 5 (A, height 3).
        *   Input Col 5 (M, height 8) -> Output Col 7 (M, height 2).
        *   Input Col 7 (B, height 3) -> Output Col 1 (B, height 3).

    *   Let's re-read the metaphor: "Each ingredient's identity (flavor/color) shifts one pedestal to the left while each pedestal's portion size shifts one position to the right".
    *   "Pedestals" are the columns. "Ingredients" are the colors. "Portion size" is the height of the stack.
    *   "Shifts one pedestal to the left": The color moves to the column to its left.
    *   "Portion size shifts one position to the right": The height moves to the column to its right.
    *   This implies a decoupling of Color and Height.
    *   Let's trace the columns.
        *   Input Col 1: Color W, Height 2.
        *   Input Col 3: Color A, Height 3.
        *   Input Col 5: Color M, Height 8.
        *   Input Col 7: Color B, Height 3.
    *   Output Col 1: Color B, Height 3.
    *   Output Col 3: Color W, Height 8.
    *   Output Col 5: Color A, Height 3.
    *   Output Col 7: Color M, Height 2.

    *   Let's check the mapping:
        *   Input Col 1 (W, H2) -> Output Col 3 (W, H8). Color moved Right? No, metaphor says "shifts one pedestal to the left".
        *   Input Col 3 (A, H3) -> Output Col 5 (A, H3). Color moved Right?
        *   Input Col 5 (M, H8) -> Output Col 7 (M, H2). Color moved Right?
        *   Input Col 7 (B, H3) -> Output Col 1 (B, H3). Color moved Left (wrap around)?

    *   Wait, let's look at the Output again.
        *   Output Col 1 has B. Input Col 7 had B. So B moved from Col 7 to Col 1. That is a shift Left (7 -> 1, assuming wrap or specific logic).
        *   Output Col 3 has W. Input Col 1 had W. So W moved from Col 1 to Col 3. That is a shift Right.
        *   Output Col 5 has A. Input Col 3 had A. So A moved from Col 3 to Col 5. That is a shift Right.
        *   Output Col 7 has M. Input Col 5 had M. So M moved from Col 5 to Col 7. That is a shift Right.

    *   This contradicts "shifts one pedestal to the left".
    *   Let's re-read carefully: "Each ingredient'

... [7279 chars truncated]
alt-3 music qwen3.5-122b: fail
"An orchestra pit where the instruments trade seats in one direction but the sheet music passes the other way — every musician plays a new part on a borrowed chair."
Fail (best cell_acc=0.30 at k=2)
Best Attempt
vs
Expected
Reasoning (10094 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "Colored sound columns of varying intensity rise from an amber stage floor at regular intervals."
    *   "Amber stage floor" likely refers to the background color, which is 'O' (Orange/Amber).
    *   "Colored sound columns" are vertical lines of non-O colors.
    *   "Rise from the bottom" implies the columns start at the bottom row and go up.
    *   "Regular intervals" implies they are spaced out. Looking at the examples, they seem to be in specific columns.
*   **What to do:** "The timbre (color) of each column cycles one position rightward while the volume (height) cycles one position leftward — each voice now sings another's melody at another's amplitude."
    *   "Timbre (color) ... cycles one position rightward": The color of a column moves to the column to its right.
    *   "Volume (height) ... cycles one position leftward": The height of a column moves to the column to its left.
    *   "Each voice now sings another's melody at another's amplitude": This confirms the swap of attributes between columns. Specifically, Column $i$ gets the Color of Column $i+1$ (or $i-1$?) and the Height of Column $i-1$ (or $i+1$?).
    *   Let's re-read carefully: "timbre (color) of each column cycles one position rightward". This usually means the color moves from Col $i$ to Col $i+1$. So Col $i+1$ gets the color of Col $i$.
    *   "volume (height) cycles one position leftward". This usually means the height moves from Col $i$ to Col $i-1$. So Col $i-1$ gets the height of Col $i$.
    *   Wait, let's look at the phrasing "each voice now sings another's melody at another's amplitude".
    *   Let's check the examples to clarify the direction.

**2. Analyze Training Examples:**

**Example 1:**
Input Grid (10x9):
Rows 0-5: Mostly O.
Row 6: O O O O O M O B O (Indices: 5 is M, 7 is B)
Row 7: O W O A O M O B O (Indices: 1 is W, 3 is A, 5 is M, 7 is B)
Row 8: O W O A O M O B O (Indices: 1 is W, 3 is A, 5 is M, 7 is B)
Wait, let's look at the columns.
Col 0: All O.
Col 1: O, O, O, O, O, O, O, W, W. (Height 2, Color W)
Col 2: All O.
Col 3: O, O, O, O, O, O, O, A, A. (Height 2, Color A)
Col 4: All O.
Col 5: O, O, O, O, O, O, M, M, M. (Height 3, Color M)
Col 6: All O.
Col 7: O, O, O, O, O, O, B, B, B. (Height 3, Color B)
Col 8: All O.

Columns with content (non-O):
Col 1: Color W, Height 2.
Col 3: Color A, Height 2.
Col 5: Color M, Height 3.
Col 7: Color B, Height 3.

Output Grid:
Col 1: O, O, O, O, O, O, O, B, B. (Height 2, Color B) -> Wait, looking at output rows 7,8.
Row 7: O B O W O A O M O
Row 8: O B O W O A O M O
Let's trace the columns in Output.
Col 1: O...O B B. (Height 2, Color B).
Col 3: O...O W W. (Height 2, Color W).
Col 5: O...O A A. (Height 2, Color A).
Col 7: O...O M M. (Height 2, Color M). Wait, Row 6 has M in Col 7?
Let's check Output Row 6: O B O W O A O O O.
Wait, let's look at the Output provided in the prompt text carefully.
Output:
O O O O O O O O O
O O O W O O O O O
O O O W O O O O O
O O O W O O O O O
O O O W O O O O O
O O O W O O O O O
O B O W O A O O O
O B O W O A O M O
O B O W O A O M O

Let's analyze Output Columns:
Col 1: Rows 7,8 are B. Height 2. Color B.
Col 3: Rows 3,4,5,6,7,8 are W. Height 6. Color W.
Col 5: Rows 6,7,8 are A. Height 3. Color A.
Col 7: Rows 7,8 are M. Height 2. Color M.

Let's compare Input vs Output attributes.
Input:
Col 1: Color W, Height 2.
Col 3: Color A, Height 2.
Col 5: Color M, Height 3.
Col 7: Color B, Height 3.

Output:
Col 1: Color B, Height 2.
Col 3: Color W, Height 6.
Col 5: Color A, Height 3.
Col 7: Color M, Height 2.

This doesn't look like a simple shift.
Let's re-read the metaphor: "timbre (color) of each column cycles one position rightward while the volume (height) cycles one position leftward".
"Rightward" usually means index increases. "Leftward" means index decreases.
If Color cycles right: Col $i$ gets Color of Col $i-1$.
If Height cycles left: Col $i$ gets Height of Col $i+1$.

Let's test this hypothesis on Example 1.
Input Columns (indices 1, 3, 5, 7):
C1: (W, 2)
C3: (A, 2)
C5: (M, 3)
C7: (B, 3)

Hypothesis:
New C1 Color = Old C0 Color? (C0 is empty/O).
New C1 Height = Old C2 Height? (C2 is empty/O).
This would imply empty columns get filled. But in Output, C1 has Color B and Height 2.
Where did B come from? C7 had B.
Where did Height 2 come from? C1 had Height 2. C3 had Height 2. C7 had Height 3.
Wait, Output C1 Height is 2. Input C1 Height is 2.
Output C3 Height is 6. Input C3 Height is 2.
Output C5 Height is 3. Input C5 Height is 3.
Output C7 Height is 2. Input C7 Height is 3.

This is confusing. Let's look at the "columns" again.
Maybe the columns are defined by the non-O cells.
Input:
Col 1: W (rows 7,8) -> Height 2.
Col 3: A (rows 7,8) -> Height 2.
Col 5: M (rows 6,7,8) -> Height 3.
Col 7: B (rows 6,7,8) -> Height 3.

Output:
Col 1: B (rows 7,8)

... [5160 chars truncated]
alt-4 sports qwen3.5-122b: fail
"Relay racers on a circular track — jerseys get passed clockwise but stamina is handed counterclockwise."
Fail (best cell_acc=0.53 at k=1)
Best Attempt
vs
Expected
Reasoning (12462 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "Differently colored, differently tall athletes stand in lanes separated by amber rest zones, all planted on the finish line."
    *   "Athletes": These seem to be the colored vertical columns.
    *   "Lanes separated by amber rest zones": This suggests columns of a specific color (Amber/Orange 'O') act as separators.
    *   "Planted on the finish line": The columns start from the bottom row.
    *   "Differently tall": The columns have different heights.
*   **Action:** "Each racer gives their jersey to the runner on their right while absorbing the endurance of the runner on their left — uniforms circle one way, energy the other."
    *   "Jersey": This likely refers to the color of the column.
    *   "Runner on their right": The column to the right.
    *   "Absorbing the endurance": This likely refers to the height or the position of the column.
    *   "Uniforms circle one way": Colors move in one direction (likely right).
    *   "Energy the other": Heights/positions move in the other direction (likely left).
*   **Grid details:** "Same grid size. Amber lanes separate the racers. Each athlete is a vertical column of color on alternating columns, rooted at the bottom."
    *   "Amber lanes": Columns of 'O' (Orange).
    *   "Athlete": A vertical column of a non-Orange color.
    *   "Rooted at the bottom": The columns extend upwards from the bottom row.

**2. Analyze the Training Example 1:**
*   **Input Grid:** 9x9
    *   Columns 0, 2, 4, 6, 8 seem to be the "lanes" or "athletes".
    *   Columns 1, 3, 5, 7 seem to be the "amber rest zones" (Orange 'O').
    *   Let's check the columns:
        *   Col 0: All 'O'. Wait, looking at the input:
            Row 0: O O O O O O O O O
            Row 1: O O O O O M O O O
            ...
            Row 6: O O O A O M O B O
            Row 7: O W O A O M O B O
            Row 8: O W O A O M O B O
        *   Actually, let's look at the structure.
        *   Col 0: All 'O'.
        *   Col 1: 'O' everywhere except rows 7,8 are 'W'.
        *   Col 2: All 'O'.
        *   Col 3: 'O' everywhere except rows 6,7,8 are 'A'.
        *   Col 4: All 'O'.
        *   Col 5: 'O' everywhere except rows 1-8 are 'M'.
        *   Col 6: All 'O'.
        *   Col 7: 'O' everywhere except rows 6,7,8 are 'B'.
        *   Col 8: All 'O'.
    *   Wait, the description says "Amber lanes separate the racers".
    *   In the input, 'O' is Orange.
    *   Let's identify the "Athletes". They are vertical columns of non-Orange colors rooted at the bottom.
    *   Col 1 has 'W' (White/Maroon? Key says W=maroon) at bottom. Height 2 (rows 7,8).
    *   Col 3 has 'A' (Azure) at bottom. Height 3 (rows 6,7,8).
    *   Col 5 has 'M' (Magenta) at bottom. Height 8 (rows 1-8).
    *   Col 7 has 'B' (Blue) at bottom. Height 3 (rows 6,7,8).
    *   The 'O' columns (0, 2, 4, 6, 8) act as separators.
    *   So we have Athletes at indices 1, 3, 5, 7.
    *   Athlete 1: Color W, Height 2.
    *   Athlete 2: Color A, Height 3.
    *   Athlete 3: Color M, Height 8.
    *   Athlete 4: Color B, Height 3.

*   **Output Grid:** 9x9
    *   Col 0: All 'O'.
    *   Col 1: 'O' everywhere except rows 1-8 are 'W'. Wait, let's look closer.
        Row 0: O
        Row 1: O
        ...
        Row 6: O
        Row 7: O
        Row 8: O
        Wait, looking at Output Col 1:
        Row 0: O
        Row 1: O
        Row 2: O
        Row 3: O
        Row 4: O
        Row 5: O
        Row 6: O
        Row 7: O
        Row 8: O
        Wait, I need to read the output grid carefully.
        Output:
        O O O O O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O B O W O A O O O
        O B O W O A O M O
        O B O W O A O M O

    *   Let's analyze the columns in the Output.
    *   Col 0: All 'O'.
    *   Col 1: 'O' at top, 'W' at bottom? No.
        Rows 0-5: 'O'.
        Rows 6-8: 'W'.
        Wait, looking at the text provided:
        Row 0: O O O O O O O O O
        Row 1: O O O W O O O O O  -> Col 3 is W.
        Row 2: O O O W O O O O O  -> Col 3 is W.
        Row 3: O O O W O O O O O  -> Col 3 is W.
        Row 4: O O O W O O O O O  -> Col 3 is W.
        Row 5: O O O W O O O O O  -> Col 3 is W.
        Row 6: O B O W O A O O O  -> Col 1 is B, Col 3 is W, Col 5 is A.
        Row 7: O B O W O A O M O  -> Col 1 is B, Col 3 is W, Col 5 is A, Col 7 is M.
        Row 8: O B O W O A O M O  -> Col 1 is B, Col 3 is W, Col 5 is A, Col 7 is M.

    *   Let's re-examine the Output Columns.
    *   Col 1: 'B' at rows 6,7,8. Height 3.
    *   Col 3: 'W' at rows 1-8. Height 8.
    *   Col 5: 'A' at rows 6,7,8. Height 3.
    *   Col 7: 'M' at rows 7,8. Height 2.

    *   Comparison Input vs Output:
        *   Inpu

... [7528 chars truncated]
alt-5 weather qwen3.5-122b: fail
"Storm fronts that trade their color with the eastern neighbor and their fury with the western one, like pressure systems swapping masks at the solstice."
Fail (best cell_acc=0.73 at k=1)
Best Attempt
vs
Expected
Reasoning (10918 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Visual:** "Colored weather columns of varying intensity rise from an amber horizon, evenly spaced like fronts on a satellite map."
    *   "Amber horizon" likely refers to the background color, which is 'O' (orange/amber).
    *   "Colored weather columns" are the non-background elements.
    *   "Varying intensity" likely refers to the height of the columns.
    *   "Evenly spaced" suggests a pattern in the columns.
*   **Action:** "Each front's hue drifts one position eastward (right) while each front's intensity (height) drifts one position westward (left) — the appearance and the power decouple and rotate in opposite directions."
    *   "Front's hue" = The color of the column.
    *   "Drifts one position eastward (right)" = The color moves to the right.
    *   "Front's intensity (height)" = The vertical extent of the column.
    *   "Drifts one position westward (left)" = The height/position of the column moves to the left.
    *   "Decouple and rotate in opposite directions" = This is the core transformation rule.
*   **Grid Details:** "Same dimensions. Amber sky fills the background. Storm columns stand on alternating columns, built upward from the bottom edge."
    *   Background is 'O'.
    *   Columns are on alternating columns (e.g., column 1, 3, 5... or 2, 4, 6...).
    *   Built upward from the bottom edge.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O O O O O O O O O
    O O O O O M O O O
    O O O O O M O O O
    O O O O O M O O O
    O O O O O M O O O
    O O O O O M O O O
    O O O A O M O B O
    O W O A O M O B O
    O W O A O M O B O
    ```
    *   Grid size: 9x9.
    *   Background: 'O'.
    *   Columns:
        *   Column 1 (index 0): 'O' everywhere.
        *   Column 2 (index 1): 'O' everywhere.
        *   Column 3 (index 2): 'O' everywhere.
        *   Column 4 (index 3): 'A' (azure) at rows 6, 7, 8 (0-indexed). Height 3.
        *   Column 5 (index 4): 'O' everywhere.
        *   Column 6 (index 5): 'M' (magenta) at rows 1-8. Height 8.
        *   Column 7 (index 6): 'O' everywhere.
        *   Column 8 (index 7): 'B' (blue) at rows 6, 7, 8. Height 3.
        *   Column 9 (index 8): 'O' everywhere.
    *   Wait, let's look closer at the columns.
    *   Col 3 (index 2): All 'O'.
    *   Col 4 (index 3): 'A' at bottom 3 rows.
    *   Col 6 (index 5): 'M' at bottom 8 rows.
    *   Col 8 (index 7): 'B' at bottom 3 rows.
    *   Actually, looking at the input:
        *   Row 0: All O.
        *   Row 1: M at col 5.
        *   Row 2: M at col 5.
        *   Row 3: M at col 5.
        *   Row 4: M at col 5.
        *   Row 5: M at col 5.
        *   Row 6: A at col 3, M at col 5, B at col 7.
        *   Row 7: W at col 1, A at col 3, M at col 5, B at col 7.
        *   Row 8: W at col 1, A at col 3, M at col 5, B at col 7.
    *   Let's identify the "columns" properly.
    *   Col 1 (index 1): 'W' at rows 7, 8. Height 2. Color W.
    *   Col 3 (index 3): 'A' at rows 6, 7, 8. Height 3. Color A.
    *   Col 5 (index 5): 'M' at rows 1-8. Height 8. Color M.
    *   Col 7 (index 7): 'B' at rows 6, 7, 8. Height 3. Color B.
    *   The columns are at indices 1, 3, 5, 7. These are alternating columns (odd indices).
    *   The background is 'O'.

*   **Output:**
    ```
    O O O O O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O B O W O A O O O
    O B O W O A O M O
    O B O W O A O M O
    ```
    *   Let's analyze the output columns.
    *   Col 1 (index 1): 'O' everywhere. (Was W, height 2).
    *   Col 3 (index 3): 'W' at rows 1-8. Height 8. Color W. (Was A, height 3).
    *   Col 5 (index 5): 'A' at rows 6-8. Height 3. Color A. (Was M, height 8).
    *   Col 7 (index 7): 'M' at rows 7-8. Height 2. Color M. (Was B, height 3).
    *   Col 9 (index 8): 'O' everywhere. (Was B, height 3). Wait, B was at col 7.
    *   Let's re-examine the mapping.
    *   Input Columns:
        1.  Col 1 (idx 1): Color W, Height 2.
        2.  Col 3 (idx 3): Color A, Height 3.
        3.  Col 5 (idx 5): Color M, Height 8.
        4.  Col 7 (idx 7): Color B, Height 3.
    *   Output Columns:
        1.  Col 1 (idx 1): Empty (O).
        2.  Col 3 (idx 3): Color W, Height 8.
        3.  Col 5 (idx 5): Color A, Height 3.
        4.  Col 7 (idx 7): Color M, Height 2.
        5.  Col 9 (idx 8): Color B, Height 3. (Wait, looking at output row 6, col 7 is 'O', col 8 is 'O'. Row 7, col 7 is 'M', col 8 is 'O'. Row 8, col 7 is 'M', col 8 is 'O'. Wait, let me check the output grid text again).
        Output Row 6: `O B O W O A O O O` -> Col 1 is B? No, index 1 is B.
        Output Row 7: `O B O W O A O M O` -> Col 1 is B. Col 3 is W. Col 5 is A. Col 7 is M.
        Output Row 8: `O B O W O A O M O` -> Col 1 is B. Col 3 is W. Col 5 is A. Co

... [6008 chars truncated]
alt-6 architecture qwen3.5-122b: fail
"A colonnade where the marble facades rotate one direction along the boulevard while the foundations shift the other — each pillar wears a new skin at a new depth."
Fail (best cell_acc=0.73 at k=1)
Best Attempt
vs
Expected
Reasoning (10650 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "Colored pillars of varying heights rise from an amber plaza, evenly spaced with amber corridors between them."
    *   "Amber plaza" likely refers to the background color, which is 'O' (orange/amber).
    *   "Pillars" are vertical structures of non-amber colors.
    *   "Evenly spaced with amber corridors" suggests pillars are in specific columns, separated by columns of 'O'.
*   **Action:** "The façade material (color) of each pillar moves one position to the right while the foundation depth (height) moves one position to the left — stone dresses migrate against structural ambition."
    *   "Façade material (color)" moves right.
    *   "Foundation depth (height)" moves left.
    *   This implies a swap or shift of properties between adjacent pillars or columns.
    *   "Stone dresses migrate against structural ambition" suggests a counter-movement.
*   **Grid details:** "Grid matches input exactly. Amber is the open plaza. Pillars exist only on alternating columns, anchored to the bottom."
    *   "Anchored to the bottom" means pillars grow upwards from the last row.
    *   "Alternating columns" means if a pillar is in column $i$, the next is in $i+2$, etc.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O O O O O O O O O
    O O O O O M O O O
    O O O O O M O O O
    O O O O O M O O O
    O O O O O M O O O
    O O O O O M O O O
    O O O A O M O B O
    O W O A O M O B O
    O W O A O M O B O
    ```
    *   Background: 'O' (Orange).
    *   Pillars:
        *   Column 1 (0-indexed): 'W' (Maroon) at rows 7, 8. Height = 2. Color = W.
        *   Column 3: 'A' (Azure) at rows 6, 7, 8. Height = 3. Color = A.
        *   Column 5: 'M' (Magenta) at rows 1-8. Height = 8. Color = M.
        *   Column 7: 'B' (Blue) at rows 6, 7, 8. Height = 3. Color = B.
    *   Wait, let's look closer at the columns.
    *   Col 0: All O.
    *   Col 1: W at bottom (rows 7,8).
    *   Col 2: All O.
    *   Col 3: A at bottom (rows 6,7,8).
    *   Col 4: All O.
    *   Col 5: M at bottom (rows 1-8).
    *   Col 6: All O.
    *   Col 7: B at bottom (rows 6,7,8).
    *   Col 8: All O.
    *   So pillars are in columns 1, 3, 5, 7. These are alternating columns (odd indices).
    *   Heights:
        *   Col 1: Height 2 (Color W)
        *   Col 3: Height 3 (Color A)
        *   Col 5: Height 8 (Color M)
        *   Col 7: Height 3 (Color B)

*   **Output:**
    ```
    O O O O O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O B O W O A O O O
    O B O W O A O M O
    O B O W O A O M O
    ```
    *   Let's check the pillars in the output.
    *   Col 1: 'B' at rows 6, 7, 8. Height 3. Color B.
    *   Col 3: 'W' at rows 1-8. Height 8. Color W.
    *   Col 5: 'A' at rows 6, 7, 8. Height 3. Color A.
    *   Col 7: 'M' at rows 7, 8. Height 2. Color M.
    *   Wait, let's re-examine the output columns.
    *   Col 1: B (rows 6,7,8). Height 3.
    *   Col 3: W (rows 1-8). Height 8.
    *   Col 5: A (rows 6,7,8). Height 3.
    *   Col 7: M (rows 7,8). Height 2.

    *   **Comparison:**
        *   Input Col 1: Height 2, Color W.
        *   Input Col 3: Height 3, Color A.
        *   Input Col 5: Height 8, Color M.
        *   Input Col 7: Height 3, Color B.

        *   Output Col 1: Height 3, Color B. (Matches Input Col 7's properties? No. Input Col 7 was Height 3, Color B. So Output Col 1 took Input Col 7's properties.)
        *   Output Col 3: Height 8, Color W. (Matches Input Col 1's properties? No. Input Col 1 was Height 2, Color W. Output Col 3 has Height 8, Color W. Wait. Input Col 5 was Height 8, Color M. Output Col 3 has Color W. This is confusing.)

    *   Let's re-read the metaphor: "The façade material (color) of each pillar moves one position to the right while the foundation depth (height) moves one position to the left".
    *   This implies a cyclic shift or a specific swap between adjacent pillars.
    *   Let's denote Pillar $P_i$ at column $C_i$.
    *   Properties: Height $H_i$, Color $K_i$.
    *   Rule: New Color at $C_i$ comes from somewhere. New Height at $C_i$ comes from somewhere.
    *   "Color moves one position to the right": $K_{new, i} = K_{old, i-1}$? Or $K_{new, i+1} = K_{old, i}$?
        *   If color moves right, the color at column $i$ moves to column $i+1$. So $K_{new, i+1} = K_{old, i}$.
        *   This means $K_{new, i} = K_{old, i-1}$.
    *   "Height moves one position to the left": $H_{new, i} = H_{old, i+1}$.
    *   Let's test this hypothesis on Example 1.
        *   Pillars at indices 1, 3, 5, 7.
        *   Input:
            *   $P_1$: $H=2, K=W$
            *   $P_3$: $H=3, K=A$
            *   $P_5$: $H=8, K=M$
            *   $P_7$: $H=3, K=B$
        *   Hypothesis:
            *   $K_{new, 1}

... [5683 chars truncated]
alt-7 warfare qwen3.5-122b: fail
"Banners and battalions rotate in opposite directions around the fortress walls — the flags march east while the armies march west."
Fail (best cell_acc=0.53 at k=1)
Best Attempt
vs
Expected
Reasoning (11931 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "Colored banners of different lengths hang from evenly spaced towers along an amber rampart, all touching the ground."
*   **Action:** "Each tower's banner color advances one tower to the right while each tower's garrison strength (banner length) advances one tower to the left — heraldry and might circle in opposition."
*   **Grid details:** "Same dimensions. Amber stone fills the walls. Banners hang on alternating columns, draped from the bottom upward."

**2. Analyze the Training Example:**
*   **Input Grid:**
    *   Size: 9 rows x 9 columns.
    *   Background: 'O' (Orange/Amber).
    *   Columns with non-O colors:
        *   Column 5 (0-indexed): 'M' (Magenta) from row 1 to 8. Wait, let's look closer.
        *   Row 0: All 'O'.
        *   Row 1-5: Col 5 is 'M'.
        *   Row 6-8: Col 5 is 'M'.
        *   Col 3: 'A' (Azure) in rows 6-8.
        *   Col 7: 'B' (Blue) in rows 6-8.
        *   Col 1: 'W' (Maroon) in rows 7-8.
    *   Let's check the structure.
    *   Input:
        R0: O O O O O O O O O
        R1: O O O O O M O O O
        R2: O O O O O M O O O
        R3: O O O O O M O O O
        R4: O O O O O M O O O
        R5: O O O O O M O O O
        R6: O O O O O M O B O
        R7: O W O A O M O B O
        R8: O W O A O M O B O
    *   Wait, looking at the input text provided in the prompt:
        Input:
        O O O O O O O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O B O
        O W O A O M O B O
        O W O A O M O B O
    *   Let's identify the "towers" and "banners".
    *   The description says "Amber stone fills the walls" -> 'O' is the background.
    *   "Banners hang on alternating columns". In the input, columns 1, 3, 5, 7 seem to have non-O colors.
        *   Col 1: 'W' at rows 7, 8. (Length 2)
        *   Col 3: 'A' at rows 6, 7, 8. (Length 3)
        *   Col 5: 'M' at rows 1 to 8. (Length 8)
        *   Col 7: 'B' at rows 6, 7, 8. (Length 3)
    *   Wait, the description says "Banners hang on alternating columns".
    *   Let's look at the Output:
        O O O O O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O B O W O A O O O
        O B O W O A O M O
        O B O W O A O M O
    *   Let's analyze the Output columns.
        *   Col 1: 'B' at rows 6, 7, 8. (Length 3)
        *   Col 3: 'W' at rows 1 to 8. (Length 8)
        *   Col 5: 'A' at rows 6, 7, 8. (Length 3)
        *   Col 7: 'M' at rows 7, 8. (Length 2)
    *   Comparison Input -> Output:
        *   Input Col 1 (W, len 2) -> Output Col 3 (W, len 8). Wait, length changed?
        *   Input Col 3 (A, len 3) -> Output Col 5 (A, len 3).
        *   Input Col 5 (M, len 8) -> Output Col 7 (M, len 2).
        *   Input Col 7 (B, len 3) -> Output Col 1 (B, len 3).
    *   This doesn't match the "color advances right, length advances left" description perfectly if I just look at columns.
    *   Let's re-read the metaphor: "Each tower's banner color advances one tower to the right while each tower's garrison strength (banner length) advances one tower to the left".
    *   "Tower" likely refers to the column index.
    *   "Banner color" is the color of the pixels in that column.
    *   "Garrison strength (banner length)" is the number of colored pixels in that column (or the height of the banner).
    *   "Advances one tower to the right": The color moves to the next column index (i+1).
    *   "Advances one tower to the left": The length moves to the previous column index (i-1).
    *   "Heraldry and might circle in opposition": This implies a cyclic shift or a swap of properties between columns.
    *   Let's check the columns again.
    *   Input Columns with data (ignoring background 'O'):
        *   Col 1: Color W, Length 2 (Rows 7-8).
        *   Col 3: Color A, Length 3 (Rows 6-8).
        *   Col 5: Color M, Length 8 (Rows 1-8).
        *   Col 7: Color B, Length 3 (Rows 6-8).
    *   Output Columns with data:
        *   Col 1: Color B, Length 3. (Matches Input Col 7 Color, Input Col 7 Length).
        *   Col 3: Color W, Length 8. (Matches Input Col 1 Color, Input Col 5 Length).
        *   Col 5: Color A, Length 3. (Matches Input Col 3 Color, Input Col 3 Length).
        *   Col 7: Color M, Length 2. (Matches Input Col 5 Color, Input Col 1 Length).
    *   This is confusing. Let's look at the "Color advances right" and "Length advances left" rule again.
    *   Maybe it means:
        *   New Color at Col $i$ = Old Color at Col $i-1$.
        *   New Length at Col $i$ = Old Length at Col $i+1$.
    *   Let's test this hypothesis.
    *   Input:
        *   Col 1: Color W, Len 2.
        *   Col 3: 

... [6955 chars truncated]
alt-8 theater qwen3.5-122b: fail
"Actors in a chorus line swap costumes to the right but trade their monologue lengths to the left — each performer debuts in borrowed clothes speaking stolen lines."
Fail (best cell_acc=0.53 at k=1)
Best Attempt
vs
Expected
Reasoning (12130 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "Costumed figures of varying stature stand on amber stage marks, evenly spaced under the lights."
    *   "Amber stage marks" likely refers to the background color, which is 'O' (orange/amber).
    *   "Costumed figures" are the non-background colors.
    *   "Varying stature" implies height (number of cells vertically).
    *   "Evenly spaced" implies columns.
*   **Action:** "Each actor's costume (color) shifts one position stage-right while each actor's role length (height) shifts one position stage-left — wardrobe and script rotate as counter-currents."
    *   "Costume (color) shifts one position stage-right": The color of the figure moves to the right column.
    *   "Role length (height) shifts one position stage-left": The height/structure of the figure moves to the left column.
    *   "Wardrobe and script rotate as counter-currents": This reinforces the idea that color and height/position are decoupled and move in opposite directions.
*   **Grid Details:** "Same grid size. Amber stage floor is the background. Figures occupy alternating columns, standing from the bottom."
    *   Background is 'O'.
    *   Figures are vertical bars standing from the bottom.
    *   They occupy specific columns.

**2. Analyze the Training Example (Example 1):**
*   **Input Grid:** 9x9
    *   Background: 'O'
    *   Column 5 (0-indexed): A vertical bar of 'M' (magenta) from row 1 to 8 (height 8). Wait, let's look closer.
    *   Row 0: All O.
    *   Rows 1-5: Col 5 is 'M'.
    *   Rows 6-8: Col 5 is 'M'.
    *   Actually, let's trace the columns.
    *   Col 0: All O.
    *   Col 1: All O.
    *   Col 2: All O.
    *   Col 3: All O.
    *   Col 4: All O.
    *   Col 5: Rows 1-8 are 'M'. (Height 8).
    *   Col 6: All O.
    *   Col 7: Rows 6-8 are 'B' (blue). (Height 3).
    *   Col 8: All O.
    *   Wait, let's look at the Input again.
    *   Input:
        ```
        O O O O O O O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O A O M O B O
        O W O A O M O B O
        O W O A O M O B O
        ```
    *   Let's identify the "figures".
    *   Figure 1: Color 'M' (Magenta). Located in Column 5.
        *   Rows: 1, 2, 3, 4, 5, 6, 7, 8.
        *   Height: 8.
        *   Bottom: Row 8.
    *   Figure 2: Color 'A' (Azure). Located in Column 3.
        *   Rows: 6, 7, 8.
        *   Height: 3.
        *   Bottom: Row 8.
    *   Figure 3: Color 'W' (Maroon). Located in Column 1.
        *   Rows: 7, 8.
        *   Height: 2.
        *   Bottom: Row 8.
    *   Figure 4: Color 'B' (Blue). Located in Column 7.
        *   Rows: 6, 7, 8.
        *   Height: 3.
        *   Bottom: Row 8.
    *   Wait, looking at the Input text provided in the prompt:
        Row 6: `O O O A O M O B O` -> Col 3 is A, Col 5 is M, Col 7 is B.
        Row 7: `O W O A O M O B O` -> Col 1 is W, Col 3 is A, Col 5 is M, Col 7 is B.
        Row 8: `O W O A O M O B O` -> Col 1 is W, Col 3 is A, Col 5 is M, Col 7 is B.
    *   So we have 4 figures standing on the bottom row (Row 8).
        1.  Col 1: Color W, Height 2 (Rows 7-8).
        2.  Col 3: Color A, Height 3 (Rows 6-8).
        3.  Col 5: Color M, Height 8 (Rows 1-8).
        4.  Col 7: Color B, Height 3 (Rows 6-8).

*   **Output Grid:**
    ```
    O O O O O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O O O W O O O O O
    O B O W O A O O O
    O B O W O A O M O
    O B O W O A O M O
    ```
    *   Let's identify the figures in the Output.
    *   Figure 1: Color 'W' (Maroon). Located in Column 3.
        *   Rows: 1, 2, 3, 4, 5, 6, 7, 8.
        *   Height: 8.
        *   Bottom: Row 8.
    *   Figure 2: Color 'B' (Blue). Located in Column 1.
        *   Rows: 6, 7, 8.
        *   Height: 3.
        *   Bottom: Row 8.
    *   Figure 3: Color 'A' (Azure). Located in Column 5.
        *   Rows: 6, 7, 8.
        *   Height: 3.
        *   Bottom: Row 8.
    *   Figure 4: Color 'M' (Magenta). Located in Column 7.
        *   Rows: 7, 8.
        *   Height: 2.
        *   Bottom: Row 8.

*   **Comparison (Input -> Output):**
    *   Input Figure at Col 1 (W, H=2) -> Output Figure at Col 3 (W, H=8).
        *   Wait, the color W moved from Col 1 to Col 3 (Right shift by 2?).
        *   The height 2 moved from Col 1 to Col 7 (Left shift?).
    *   Input Figure at Col 3 (A, H=3) -> Output Figure at Col 5 (A, H=3).
        *   Color A moved from Col 3 to Col 5 (Right shift by 2).
        *   Height 3 stayed at Col 3? No, look at Output Col 5. It has A and H=3.
        *   Wait, let's re-examine the Output.
        *   Output Col 1: B (H=3).
        *   Output Col 3: W (H=8).
        *   Output Col 5: A (H=3).
        *   Output Col 7: M (H=

... [7229 chars truncated]
alt-9 gardening qwen3.5-122b: fail
"In the enchanted garden, flower colors blow rightward on the wind while root systems creep leftward underground — by morning each stem wears a neighbor's bloom at a neighbor's depth."
Fail (best cell_acc=0.53 at k=1)
Best Attempt
vs
Expected
Reasoning (10821 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "Flowers of different colors and heights grow in alternating plots along an amber garden bed, all rooted at the bottom."
*   **Action:** "Each flower's petal color migrates one plot to the right while each flower's stem height migrates one plot to the left — bloom and stature spiral in opposite directions."
*   **Grid Details:** "Identical dimensions. Amber soil fills the bed. Flowers grow on every other column, rising from the bottom edge."

**2. Analyze the Training Example 1:**
*   **Input Grid:** 9x9 (rows x cols).
    *   Background seems to be 'O' (Orange/Amber).
    *   There are columns with non-O colors.
    *   Let's look at the columns.
    *   Col 0: All O.
    *   Col 1: All O.
    *   Col 2: All O.
    *   Col 3: All O.
    *   Col 4: All O.
    *   Col 5: Rows 1-5 are M, Rows 6-8 are M. Wait, let's look closer.
    *   Let's visualize the input grid structure.
    *   Rows 0-5: Mostly O.
    *   Rows 6-8: Some variation.
    *   Let's look at the columns specifically.
    *   Col 0: O O O O O O O O O
    *   Col 1: O O O O O O O W W
    *   Col 2: O O O O O O O O O
    *   Col 3: O O O O O O O A A
    *   Col 4: O O O O O O O O O
    *   Col 5: O M M M M M M M M
    *   Col 6: O O O O O O O O O
    *   Col 7: O O O O O O O B B
    *   Col 8: O O O O O O O O O
    *   Wait, let's re-read the input grid provided in the prompt.
    *   Input:
        O O O O O O O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O O O M O O O
        O O O A O M O B O
        O W O A O M O B O
        O W O A O M O B O
    *   Let's check the columns again.
    *   Col 0: All O.
    *   Col 1: O O O O O O O W W. (W at bottom 2 rows)
    *   Col 2: All O.
    *   Col 3: O O O O O O A A A. (A at bottom 3 rows)
    *   Col 4: All O.
    *   Col 5: O M M M M M M M M. (M from row 1 to 8)
    *   Col 6: All O.
    *   Col 7: O O O O O O O B B. (B at bottom 2 rows)
    *   Col 8: All O.
    *   So, "Flowers grow on every other column".
    *   Columns with flowers: 1, 3, 5, 7. (Indices 1, 3, 5, 7).
    *   Column 0, 2, 4, 6, 8 are "Amber soil" (O).
    *   The flowers are rooted at the bottom.
    *   Flower 1 (Col 1): Color W (Maroon). Height 2 (Rows 7, 8).
    *   Flower 2 (Col 3): Color A (Azure). Height 3 (Rows 6, 7, 8).
    *   Flower 3 (Col 5): Color M (Magenta). Height 8 (Rows 1-8).
    *   Flower 4 (Col 7): Color B (Blue). Height 2 (Rows 7, 8).

*   **Output Grid:**
        O O O O O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O O O W O O O O O
        O B O W O A O O O
        O B O W O A O M O
        O B O W O A O M O
    *   Let's analyze the output columns.
    *   Col 0: All O.
    *   Col 1: O O O O O O O B B. (B at bottom 2 rows).
    *   Col 2: All O.
    *   Col 3: O O O O O O W W W. (W at bottom 3 rows).
    *   Col 4: All O.
    *   Col 5: O O O O O O O O O. (All O). Wait, looking at the output text:
        Row 0: O O O O O O O O O
        Row 1: O O O W O O O O O
        Row 2: O O O W O O O O O
        Row 3: O O O W O O O O O
        Row 4: O O O W O O O O O
        Row 5: O O O W O O O O O
        Row 6: O B O W O A O O O
        Row 7: O B O W O A O M O
        Row 8: O B O W O A O M O
    *   Let's check Col 5 in Output.
        Row 0: O
        Row 1: O
        Row 2: O
        Row 3: O
        Row 4: O
        Row 5: O
        Row 6: O
        Row 7: M
        Row 8: M
        Wait, looking at the provided output text block:
        Row 6: O B O W O A O O O
        Row 7: O B O W O A O M O
        Row 8: O B O W O A O M O
        Col 5 in Output:
        Row 0-5: O
        Row 6: O
        Row 7: M
        Row 8: M
        So Col 5 has M at bottom 2 rows.
    *   Col 7 in Output:
        Row 0-5: O
        Row 6: O
        Row 7: O
        Row 8: O
        Wait, let's look at the output text again carefully.
        Row 6: O B O W O A O O O
        Row 7: O B O W O A O M O
        Row 8: O B O W O A O M O
        Col 7 is the 8th column (index 7).
        Row 6: O
        Row 7: M
        Row 8: M
        Wait, Row 6 is "O B O W O A O O O". Index 7 is 'O'.
        Row 7 is "O B O W O A O M O". Index 7 is 'M'.
        Row 8 is "O B O W O A O M O". Index 7 is 'M'.
        So Col 7 has M at bottom 2 rows.
    *   Let's re-examine the Output Grid structure based on the text provided.
        Row 0: O O O O O O O O O
        Row 1: O O O W O O O O O
        Row 2: O O O W O O O O O
        Row 3: O O O W O O O O O
        Row 4: O O O W O O O O O
        Row 5: O O O W O O O O O
        Row 6: O B O W O A O O O
        Row 7: O B O W O A O M O
        Row 8: O B O W O A O M O

        Col 0: All O.
        Col 1: O O O O O O B B B. (B at rows 6,7,8). Height 3.
        Col 

... [5869 chars truncated]

Task 194: 34b99a2b

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A curtain divides two dancers, and the spotlight finds whoever dances alone. MARC valid 1
alt-1 biology A membrane separates two colonies of cells. Only the mutations unique to one sid ... [33 chars truncated] fig alone solves
alt-10 astronomy A golden meridian divides two star charts. Red nebulae glow only where one chart ... [39 chars truncated] MARC valid 1
alt-11 ocean/sailing A golden reef divides two lagoons. Red coral grows only where one lagoon holds a ... [39 chars truncated] fail
alt-12 electronics Two signal lines feed into a gate separated by a golden bus. The output fires re ... [32 chars truncated] fig alone solves
alt-13 mythology A golden river separates the land of the living from the land of the dead. Souls ... [69 chars truncated] MARC valid 1
alt-14 dance A golden ribbon divides the ballroom floor. The choreographer marks red footprin ... [64 chars truncated] MARC valid 2
alt-15 geology A golden fault line splits two strata. Red magma surfaces only where one stratum ... [51 chars truncated] fig alone solves
alt-2 cooking Two halves of a sandwich are compared by a picky eater who only wants bites wher ... [51 chars truncated] fig alone solves
alt-3 music Two orchestral sections are separated by a conductor's baton — only the no ... [50 chars truncated] fig alone solves
alt-4 sports Two teams line up on opposite sides of a net, and the referee flags only the pos ... [76 chars truncated] MARC valid 2
alt-5 weather A cold front and a warm front collide along a stationary boundary — only w ... [64 chars truncated] fig alone solves
alt-6 architecture A load-bearing wall divides two mirror rooms. The inspector marks in red every s ... [90 chars truncated] MARC valid 2
alt-7 warfare Two armies face each other across a golden fortification. The battlefield scars ... [54 chars truncated] MARC valid 1
alt-8 theater A golden curtain parts to reveal two casts rehearsing the same play — the ... [78 chars truncated] fig alone solves
alt-9 gardening A golden trellis separates two garden beds. The gardener plants red flowers only ... [57 chars truncated] fig alone solves
original qwen3.5-122b: k=1
"A curtain divides two dancers, and the spotlight finds whoever dances alone."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11200 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A golden curtain hangs down the center, splitting the stage into two wings (left and right).
*   **Left Wing:** Azure performers (A) among empty squares (black/dots).
*   **Right Wing:** Grey performers (X) mirroring the layout.
*   **Black Squares:** Darkness/Empty stage floor.
*   **Action:** Raise the curtain, wings collapse into one stage.
*   **Transformation Logic:**
    *   Compare the left wing and the right wing.
    *   "Wherever a performer on one side finds only darkness across from them — no partner, no mirror — a red spotlight ignites on that square, marking the lonesome dancer."
    *   "But where two performers lock eyes across the divide, or where darkness meets darkness, the stage stays dark."
    *   "The spotlight only loves the unmatched."
    *   "The curtain vanishes and the two wings collapse into one stage." -> This implies the output grid is likely half the width of the input grid, or represents the comparison result.
    *   "What remains is a smaller floor plan lit only by red spotlights where solitary dancers stood, surrounded by the darkness of matched pairs and empty silence." -> Output contains Red (R) and Black (.).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . A . . Y . X X .
    A A . A Y X . . X
    A A . . Y X . . X
    . A . A Y . . X .
    . . A . Y . X . X
    ```
    *   Dimensions: 5 rows, 9 columns.
    *   Center column seems to be 'Y' (Yellow). Let's check indices.
    *   Row 0: `. A . . Y . X X .` -> Index 4 is 'Y'. Left side: `. A . .`, Right side: `. X X .`.
    *   Row 1: `A A . A Y X . . X` -> Index 4 is 'Y'. Left side: `A A . A`, Right side: `X . . X`.
    *   Row 2: `A A . . Y X . . X` -> Index 4 is 'Y'. Left side: `A A . .`, Right side: `X . . X`.
    *   Row 3: `. A . A Y . . X .` -> Index 4 is 'Y'. Left side: `. A . A`, Right side: `. . X .`.
    *   Row 4: `. . A . Y . X . X` -> Index 4 is 'Y'. Left side: `. . A .`, Right side: `. X . X`.
    *   The 'Y' column acts as the "curtain" or divider.
    *   Left Wing: Columns 0-3 (4 columns).
    *   Right Wing: Columns 5-8 (4 columns).
    *   The Right Wing seems to be a mirror image or just a separate set of data. The description says "grey performers mirror the same stage layout". This might mean spatial mirroring or just that they occupy the corresponding positions. Let's look at the mapping.
    *   Usually, in these puzzles, "mirror" implies reflection. If the curtain is in the middle, the right side is the reflection of the left side.
    *   Let's check the comparison logic.
    *   Output Dimensions: 5 rows, 4 columns. This matches the width of one wing.
    *   Output Content:
        ```
        . . R .
        . R . .
        . R . R
        . R R R
        . R R R
        ```
    *   Let's compare Left Wing (L) and Right Wing (R) cell by cell.
    *   Row 0:
        *   L: `. A . .`
        *   R: `. X X .` (Indices 5, 6, 7, 8)
        *   Comparison:
            *   Col 0: L=`.` (Dark), R=`.` (Dark). Match (Dark/Dark) -> Output `.`
            *   Col 1: L=`A` (Azure), R=`X` (Grey). Match (Performer/Performer) -> Output `.` (Dark)
            *   Col 2: L=`.` (Dark), R=`X` (Grey). Mismatch (Dark/Performer) -> Output `R` (Red)
            *   Col 3: L=`.` (Dark), R=`.` (Dark). Match (Dark/Dark) -> Output `.`
        *   Result Row 0: `. . R .` -> Matches Output.
    *   Row 1:
        *   L: `A A . A`
        *   R: `X . . X`
        *   Comparison:
            *   Col 0: L=`A`, R=`X`. Match (Perf/Perf) -> `.`
            *   Col 1: L=`A`, R=`.`. Mismatch (Perf/Dark) -> `R`
            *   Col 2: L=`.`, R=`.`. Match (Dark/Dark) -> `.`
            *   Col 3: L=`A`, R=`X`. Match (Perf/Perf) -> `.`
        *   Result Row 1: `. R . .` -> Matches Output.
    *   Row 2:
        *   L: `A A . .`
        *   R: `X . . X`
        *   Comparison:
            *   Col 0: L=`A`, R=`X`. Match -> `.`
            *   Col 1: L=`A`, R=`.`. Mismatch -> `R`
            *   Col 2: L=`.`, R=`.`. Match -> `.`
            *   Col 3: L=`.`, R=`X`. Mismatch -> `R`
        *   Result Row 2: `. R . R` -> Matches Output.
    *   Row 3:
        *   L: `. A . A`
        *   R: `. . X .`
        *   Comparison:
            *   Col 0: L=`.`, R=`.`. Match -> `.`
            *   Col 1: L=`A`, R=`.`. Mismatch -> `R`
            *   Col 2: L=`.`, R=`X`. Mismatch -> `R`
            *   Col 3: L=`A`, R=`.`. Mismatch -> `R`
        *   Result Row 3: `. R R R` -> Matches Output.
    *   Row 4:
        *   L: `. . A .`
        *   R: `. X . X`
        *   Comparison:
            *   Col 0: L=`.`, R=`.`. Match -> `.`
            *   Col 1: L=`.`, R=`X`. Mismatch -> `R`
            *   Col 2: L=`A`, R=`.`. Mismatch -> `R`
            *   Col 

... [6521 chars truncated]
alt-1 biology qwen3.5-122b: fig alone solves
"A membrane separates two colonies of cells. Only the mutations unique to one side survive the selection pressure."
alt-10 astronomy qwen3.5-122b: k=1
"A golden meridian divides two star charts. Red nebulae glow only where one chart shows a star and the other shows void."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10534 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A vertical yellow meridian splits the sky." -> There is a vertical column of 'Y' (yellow) in the input grid. This acts as a separator.
*   "Azure stars dot the left hemisphere; grey stars dot the right." -> To the left of the 'Y' column, there are 'A' (azure) pixels. To the right of the 'Y' column, there are 'X' (grey) pixels.
*   "Black is the void of space." -> '.' (black) represents empty space.
*   "Overlay the hemispheres and look for asymmetry: where one hemisphere has a star and the other has void, a red nebula ignites." -> This suggests comparing the left side and the right side. If one side has a star ('A' or 'X') and the other has void ('.'), the result is 'R' (red).
*   "Where both have stars or both are void, darkness persists." -> If both sides have stars (A and X) or both are void (.), the result is '.' (black).
*   "Grid details: A half-width star chart with red nebulae and black void." -> The output grid seems to be half the width of the input grid (excluding the separator).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . A . . Y . X X .
    A A . A Y X . . X
    A A . . Y X . . X
    . A . A Y . . X .
    . . A . Y . X . X
    ```
    Dimensions: 5 rows, 9 columns.
    The 'Y' column is at index 4 (0-indexed).
    Left side (cols 0-3): 4 columns.
    Right side (cols 5-8): 4 columns.
    The 'Y' column is the separator.

*   **Output:**
    ```
    . . R .
    . R . .
    . R . R
    . R R R
    . R R R
    ```
    Dimensions: 5 rows, 4 columns.
    This confirms the output width is half the input width (excluding the separator).

*   **Logic Verification:**
    Let's check row by row.
    Row 0:
    Left: `. A . .`
    Right: `. X X .` (Note: Input right side is `. X X .` based on indices 5,6,7,8)
    Wait, let's look at the input again.
    Input Row 0: `. A . . Y . X X .`
    Left: `. A . .`
    Separator: `Y`
    Right: `. X X .`
    Comparison:
    Col 0: Left `.` vs Right `.` -> Both void -> Output `.`
    Col 1: Left `A` vs Right `X` -> Both stars -> Output `.` (Wait, description says "Where both have stars... darkness persists". So A vs X should be `.`)
    Col 2: Left `.` vs Right `X` -> One star, one void -> Output `R`
    Col 3: Left `.` vs Right `.` -> Both void -> Output `.`
    Predicted Row 0: `. . R .`
    Actual Output Row 0: `. . R .` -> Matches.

    Row 1:
    Input: `A A . A Y X . . X`
    Left: `A A . A`
    Right: `X . . X`
    Comparison:
    Col 0: `A` vs `X` -> Both stars -> `.`
    Col 1: `A` vs `.` -> One star -> `R`
    Col 2: `.` vs `.` -> Both void -> `.`
    Col 3: `A` vs `X` -> Both stars -> `.`
    Predicted Row 1: `. R . .`
    Actual Output Row 1: `. R . .` -> Matches.

    Row 2:
    Input: `A A . . Y X . . X`
    Left: `A A . .`
    Right: `X . . X`
    Comparison:
    Col 0: `A` vs `X` -> `.`
    Col 1: `A` vs `.` -> `R`
    Col 2: `.` vs `.` -> `.`
    Col 3: `.` vs `X` -> `R`
    Predicted Row 2: `. R . R`
    Actual Output Row 2: `. R . R` -> Matches.

    Row 3:
    Input: `. A . A Y . . X .`
    Left: `. A . A`
    Right: `. . X .`
    Comparison:
    Col 0: `.` vs `.` -> `.`
    Col 1: `A` vs `.` -> `R`
    Col 2: `.` vs `X` -> `R`
    Col 3: `A` vs `.` -> `R`
    Predicted Row 3: `. R R R`
    Actual Output Row 3: `. R R R` -> Matches.

    Row 4:
    Input: `. . A . Y . X . X`
    Left: `. . A .`
    Right: `. X . X`
    Comparison:
    Col 0: `.` vs `.` -> `.`
    Col 1: `.` vs `X` -> `R`
    Col 2: `A` vs `.` -> `R`
    Col 3: `.` vs `X` -> `R`
    Predicted Row 4: `. R R R`
    Actual Output Row 4: `. R R R` -> Matches.

**3. Conceptual Digestion:**
1.  **CAST:**
    *   `Y` (Yellow): The vertical axis/separator.
    *   `A` (Azure): Star on the left side.
    *   `X` (Grey): Star on the right side.
    *   `.` (Black): Void/Empty space.
    *   `R` (Red): Result of asymmetry (XOR logic).
2.  **AFFORDANCES:**
    *   The grid is split into two equal halves by the `Y` column.
    *   The left half contains `A` and `.`.
    *   The right half contains `X` and `.`.
    *   The transformation compares corresponding cells in the left and right halves.
3.  **TRANSFORMATION RULE:**
    *   Identify the column containing `Y`. Let's call its index `mid`.
    *   The output grid has the same number of rows as the input.
    *   The output grid has width equal to `mid` (number of columns to the left of `Y`).
    *   For each row `r` and column `c` (where `0 <= c < mid`):
        *   Let `L = input[r][c]` (Left cell).
        *   Let `R = input[r][mid + 1 + c]` (Right cell).
        *   If (`L` is a star AND `R` is void) OR (`L` is void AND `R` is a star):
            *   `output[r][c] = 'R'`
        *   Else (Both stars OR Both void):
            *  

... [5876 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fail
"A golden reef divides two lagoons. Red coral grows only where one lagoon holds a pearl and the other holds empty water."
Fail (best cell_acc=0.09 at k=2)
Best Attempt
vs
Expected
Reasoning (10383 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A vertical yellow reef splits the sea. Azure pearls rest on the left seabed; grey pearls on the right. Black is open water."
    *   "Vertical yellow reef": There is a column of 'Y' (yellow) in the input grid. This acts as a separator.
    *   "Azure pearls": 'A' (azure) represents objects on the left side.
    *   "Grey pearls": 'X' (grey) represents objects on the right side.
    *   "Black is open water": '.' (black) represents empty space.
    *   "Left seabed" and "Right seabed": The grid is split into two halves by the yellow column.
*   **Transformation:** "Dive past the reef and compare the two floors: wherever one lagoon has a pearl and the other has open water, red coral blooms. Where both have pearls or both are empty, the seabed stays dark."
    *   "Compare the two floors": Compare the left side and the right side relative to the yellow separator.
    *   "Wherever one lagoon has a pearl and the other has open water": This implies an XOR operation.
        *   Left has 'A' (pearl) AND Right has '.' (water) -> Output 'R' (red coral).
        *   Left has '.' (water) AND Right has 'X' (pearl) -> Output 'R' (red coral).
    *   "Where both have pearls or both are empty":
        *   Left has 'A' AND Right has 'X' -> Output '.' (dark/black).
        *   Left has '.' AND Right has '.' -> Output '.' (dark/black).
    *   "Red coral blooms": Output is 'R'.
    *   "Seabed stays dark": Output is '.'.
*   **Grid details:** "A half-width seabed of red coral and black water."
    *   The output grid width seems to be half the input width (excluding the separator?). Let's check the dimensions.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
. A . . Y . X X .
A A . A Y X . . X
A A . . Y X . . X
. A . A Y . . X .
. . A . Y . X . X
```
Dimensions: 5 rows, 9 columns.
Yellow column ('Y') is at index 4 (0-indexed).
Left side: Columns 0-3 (4 columns).
Right side: Columns 5-8 (4 columns).
Output:
```
. . R .
. R . .
. R . R
. R R R
. R R R
```
Dimensions: 5 rows, 4 columns.
This confirms the output width is the width of one side (left or right). The separator column is removed.

Let's check the logic row by row.
Row 0:
Left: `. A . .`
Right: `. X X .`
Comparison (Left vs Right):
Col 0: `.` vs `.` -> Both empty -> `.`
Col 1: `A` vs `X` -> Both pearls -> `.`
Col 2: `.` vs `X` -> One empty, one pearl -> `R`
Col 3: `.` vs `.` -> Both empty -> `.`
Result: `. . R .` matches output.

Row 1:
Left: `A A . A`
Right: `X . . X`
Col 0: `A` vs `X` -> Both pearls -> `.`
Col 1: `A` vs `.` -> One pearl, one empty -> `R`
Col 2: `.` vs `.` -> Both empty -> `.`
Col 3: `A` vs `X` -> Both pearls -> `.`
Result: `. R . .` matches output.

Row 2:
Left: `A A . .`
Right: `X . . X`
Col 0: `A` vs `X` -> Both pearls -> `.`
Col 1: `A` vs `.` -> One pearl, one empty -> `R`
Col 2: `.` vs `.` -> Both empty -> `.`
Col 3: `.` vs `X` -> One empty, one pearl -> `R`
Result: `. R . R` matches output.

Row 3:
Left: `. A . A`
Right: `. . X .`
Col 0: `.` vs `.` -> `.`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `X` -> `R`
Col 3: `A` vs `.` -> `R`
Result: `. R R R` matches output.

Row 4:
Left: `. . A .`
Right: `. X . X`
Col 0: `.` vs `.` -> `.`
Col 1: `.` vs `X` -> `R`
Col 2: `A` vs `.` -> `R`
Col 3: `.` vs `X` -> `R`
Result: `. R R R` matches output.

**Logic Confirmed:**
1.  Find the column containing 'Y'.
2.  Split the grid into Left (columns before 'Y') and Right (columns after 'Y').
3.  The output grid has the same number of rows as the input, and width equal to the number of columns in Left/Right (assuming they are equal width).
4.  For each cell (r, c) in the output:
    *   Let `L = Input[r][c]`
    *   Let `R = Input[r][c + width + 1]` (where width is the number of columns before Y, and +1 skips Y).
    *   If (`L` is 'A' and `R` is '.') OR (`L` is '.' and `R` is 'X'): Output 'R'.
    *   Else: Output '.'.
    *   Wait, let's re-read the metaphor carefully: "wherever one lagoon has a pearl and the other has open water".
    *   Left pearls are 'A'. Right pearls are 'X'. Open water is '.'.
    *   So, (Left='A' AND Right='.') OR (Left='.' AND Right='X') -> 'R'.
    *   What if Left='A' and Right='X'? Metaphor says "Where both have pearls... seabed stays dark". So '.'.
    *   What if Left='.' and Right='.'? Metaphor says "both are empty... seabed stays dark". So '.'.
    *   Are there other characters? In the examples, only A, X, Y, . appear.
    *   So the rule is effectively XOR on the presence of a pearl, but specific to the side.
    *   Actually, it's simpler:
        *   Is there a pearl on the left? (L == 'A')
        *   Is there a pearl on the right? (R == 'X')
        *   If (Pearl_Left XOR Pearl_Right) is True -> 'R'.
        *   Else ->

... [5758 chars truncated]
alt-12 electronics qwen3.5-122b: fig alone solves
"Two signal lines feed into a gate separated by a golden bus. The output fires red only when the inputs disagree."
alt-13 mythology qwen3.5-122b: k=1
"A golden river separates the land of the living from the land of the dead. Souls glow red only where one bank is inhabited and the other is desolate."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10888 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A vertical yellow river flows between two realms. Azure spirits inhabit the left bank; grey shades haunt the right. Black is empty ground."
    *   This suggests the input grid contains a vertical column of 'Y' (Yellow) acting as a separator.
    *   To the left of 'Y', there are 'A' (Azure) and '.' (Black/Empty).
    *   To the right of 'Y', there are 'X' (Grey) and '.' (Black/Empty).
*   **Action:** "Ford the river and compare the banks: where one realm has a presence and the other is barren, a red soul manifests. Where both are populated or both are empty, nothing appears."
    *   "Ford the river": Cross the yellow line.
    *   "Compare the banks": Look at corresponding positions on the left and right sides of the river.
    *   "One realm has a presence and the other is barren": One side has a colored pixel (A or X), the other has '.' (Black).
    *   "Red soul manifests": Output 'R' (Red).
    *   "Both are populated or both are empty": Output '.' (Black).
*   **Output:** "A half-width spirit map of red souls and black emptiness."
    *   The output grid seems to be narrower than the input. Since the river is in the middle, the output likely represents the comparison result.
    *   Let's check the dimensions in the training example.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    . A . . Y . X X .
    A A . A Y X . . X
    A A . . Y X . . X
    . A . A Y . . X .
    . . A . Y . X . X
    ```
    *   Dimensions: 5 rows, 9 columns.
    *   The 'Y' column is at index 4 (0-indexed).
    *   Left side (cols 0-3): 4 columns.
    *   Right side (cols 5-8): 4 columns.
    *   Wait, let's look closer.
    *   Row 0: `. A . .` | `Y` | `. X X .`
    *   Row 1: `A A . A` | `Y` | `X . . X`
    *   Row 2: `A A . .` | `Y` | `X . . X`
    *   Row 3: `. A . A` | `Y` | `. . X .`
    *   Row 4: `. . A .` | `Y` | `. X . X`
    *   Left side width = 4. Right side width = 4.
    *   Total width = 4 + 1 + 4 = 9.

*   **Output:**
    ```
    . . R .
    . R . .
    . R . R
    . R R R
    . R R R
    ```
    *   Dimensions: 5 rows, 4 columns.
    *   This matches the width of one side (left or right).
    *   Let's check the logic row by row.
    *   **Row 0:**
        *   Left: `. A . .`
        *   Right: `. X X .`
        *   Comparison (Left vs Right):
            *   Col 0: `.` vs `.` -> Both empty -> `.`
            *   Col 1: `A` vs `X` -> Both populated -> `.`
            *   Col 2: `.` vs `X` -> Left empty, Right populated -> `R`
            *   Col 3: `.` vs `.` -> Both empty -> `.`
        *   Result: `. . R .` -> Matches Output Row 0.
    *   **Row 1:**
        *   Left: `A A . A`
        *   Right: `X . . X`
        *   Comparison:
            *   Col 0: `A` vs `X` -> Both populated -> `.`
            *   Col 1: `A` vs `.` -> Left populated, Right empty -> `R`
            *   Col 2: `.` vs `.` -> Both empty -> `.`
            *   Col 3: `A` vs `X` -> Both populated -> `.`
        *   Result: `. R . .` -> Matches Output Row 1.
    *   **Row 2:**
        *   Left: `A A . .`
        *   Right: `X . . X`
        *   Comparison:
            *   Col 0: `A` vs `X` -> Both populated -> `.`
            *   Col 1: `A` vs `.` -> Left populated, Right empty -> `R`
            *   Col 2: `.` vs `.` -> Both empty -> `.`
            *   Col 3: `.` vs `X` -> Left empty, Right populated -> `R`
        *   Result: `. R . R` -> Matches Output Row 2.
    *   **Row 3:**
        *   Left: `. A . A`
        *   Right: `. . X .`
        *   Comparison:
            *   Col 0: `.` vs `.` -> Both empty -> `.`
            *   Col 1: `A` vs `.` -> Left populated, Right empty -> `R`
            *   Col 2: `.` vs `X` -> Left empty, Right populated -> `R`
            *   Col 3: `A` vs `.` -> Left populated, Right empty -> `R`
        *   Result: `. R R R` -> Matches Output Row 3.
    *   **Row 4:**
        *   Left: `. . A .`
        *   Right: `. X . X`
        *   Comparison:
            *   Col 0: `.` vs `.` -> Both empty -> `.`
            *   Col 1: `.` vs `X` -> Left empty, Right populated -> `R`
            *   Col 2: `A` vs `.` -> Left populated, Right empty -> `R`
            *   Col 3: `.` vs `X` -> Left empty, Right populated -> `R`
        *   Result: `. R R R` -> Matches Output Row 4.

**3. Conceptual Digestion:**
1.  **CAST:**
    *   **Input Grid:** Contains a vertical separator column of 'Y' (Yellow).
    *   **Left Bank:** Columns to the left of 'Y'. Contains 'A' (Azure) and '.' (Black).
    *   **Right Bank:** Columns to the right of 'Y'. Contains 'X' (Grey) and '.' (Black).
    *   **Output Grid:** Represents the comparison result. Dimensions match the width of the banks (Left or Right).
2.  **AFFORDAN

... [6239 chars truncated]
alt-14 dance qwen3.5-122b: k=2
"A golden ribbon divides the ballroom floor. The choreographer marks red footprints only where one side has a dancer and the other side is empty."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10242 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A vertical yellow ribbon splits the dance floor. Azure dancers hold poses on the left; grey dancers hold poses on the right. Black is empty floor."
    *   This implies the input grid contains three main colors: Yellow (Y), Azure (A), and Grey (X). Black (.) is background.
    *   The "vertical yellow ribbon" suggests a column of 'Y's dividing the grid into a left side and a right side.
    *   "Azure dancers on the left": 'A's are on the left of the 'Y' column.
    *   "Grey dancers on the right": 'X's are on the right of the 'Y' column.
*   **Action:** "Pull the ribbon away and overlay the formations: wherever one side has a dancer and the other has open floor, stamp a red footprint. Where both have dancers or both are empty, the floor stays unmarked."
    *   "Pull the ribbon away": Remove the 'Y' column.
    *   "Overlay the formations": Compare the left side (A's) and the right side (X's).
    *   "Wherever one side has a dancer and the other has open floor": This sounds like an XOR operation.
        *   Left has A, Right has . -> Red (R)
        *   Left has ., Right has X -> Red (R)
        *   Left has A, Right has X -> Unmarked (.)
        *   Left has ., Right has . -> Unmarked (.)
    *   "Stamp a red footprint": The output color is Red (R).
    *   "Floor stays unmarked": The output color is Black (.).
*   **Output:** "A half-width floor plan with red footprints and black unmarked tiles."
    *   The output grid width should be half the input width (excluding the separator column).
    *   The output grid height should match the input grid height.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
. A . . Y . X X .
A A . A Y X . . X
A A . . Y X . . X
. A . A Y . . X .
. . A . Y . X . X

Grid dimensions: 5 rows, 9 columns.
Yellow column index: 4 (0-indexed).
Left side (cols 0-3): 4 columns.
Right side (cols 5-8): 4 columns.
Output dimensions: 5 rows, 4 columns.

Let's check the logic row by row.
Row 0:
Left: `. A . .`
Right: `. X X .`
Comparison:
Col 0: Left `.` vs Right `.` -> Both empty -> `.`
Col 1: Left `A` vs Right `X` -> Both dancers -> `.`
Col 2: Left `.` vs Right `X` -> One dancer -> `R`
Col 3: Left `.` vs Right `.` -> Both empty -> `.`
Expected Row 0: `. . R .`
Actual Output Row 0: `. . R .` (Matches)

Row 1:
Left: `A A . A`
Right: `X . . X`
Comparison:
Col 0: `A` vs `X` -> Both -> `.`
Col 1: `A` vs `.` -> One -> `R`
Col 2: `.` vs `.` -> Both empty -> `.`
Col 3: `A` vs `X` -> Both -> `.`
Expected Row 1: `. R . .`
Actual Output Row 1: `. R . .` (Matches)

Row 2:
Left: `A A . .`
Right: `X . . X`
Comparison:
Col 0: `A` vs `X` -> Both -> `.`
Col 1: `A` vs `.` -> One -> `R`
Col 2: `.` vs `.` -> Both empty -> `.`
Col 3: `.` vs `X` -> One -> `R`
Expected Row 2: `. R . R`
Actual Output Row 2: `. R . R` (Matches)

Row 3:
Left: `. A . A`
Right: `. . X .`
Comparison:
Col 0: `.` vs `.` -> `.`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `X` -> `R`
Col 3: `A` vs `.` -> `R`
Expected Row 3: `. R R R`
Actual Output Row 3: `. R R R` (Matches)

Row 4:
Left: `. . A .`
Right: `. X . X`
Comparison:
Col 0: `.` vs `.` -> `.`
Col 1: `.` vs `X` -> `R`
Col 2: `A` vs `.` -> `R`
Col 3: `.` vs `X` -> `R`
Expected Row 4: `. R R R`
Actual Output Row 4: `. R R R` (Matches)

**Example 2:**
Input:
. A . . Y X . X .
. A . A Y X . X X
. A . A Y . . . X
. A . A Y . X . X
. . . A Y . . X .

Grid dimensions: 5 rows, 9 columns.
Yellow column index: 4.
Left side: cols 0-3.
Right side: cols 5-8.
Output dimensions: 5 rows, 4 columns.

Row 0:
Left: `. A . .`
Right: `X . X .`
Col 0: `.` vs `X` -> `R`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `X` -> `R`
Col 3: `.` vs `.` -> `.`
Expected: `R R R .`
Actual: `R R R .` (Matches)

Row 1:
Left: `. A . A`
Right: `X . X X`
Col 0: `.` vs `X` -> `R`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `X` -> `R`
Col 3: `A` vs `X` -> `.`
Expected: `R R R .`
Actual: `R R R .` (Matches)

Row 2:
Left: `. A . A`
Right: `. . . X`
Col 0: `.` vs `.` -> `.`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `.` -> `.`
Col 3: `A` vs `X` -> `.`
Expected: `. R . .`
Actual: `. R . .` (Matches)

Row 3:
Left: `. A . A`
Right: `. X . X`
Col 0: `.` vs `.` -> `.`
Col 1: `A` vs `X` -> `.`
Col 2: `.` vs `.` -> `.`
Col 3: `A` vs `X` -> `.`
Expected: `. . . .`
Actual: `. . . .` (Matches)

Row 4:
Left: `. . . A`
Right: `. . X .`
Col 0: `.` vs `.` -> `.`
Col 1: `.` vs `.` -> `.`
Col 2: `.` vs `X` -> `R`
Col 3: `A` vs `.` -> `R`
Expected: `. . R R`
Actual: `. . R R` (Matches)

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** Contains a vertical separator line of 'Y' (Yellow).
    *   **Left Partition:** Contains 'A' (Azure) representing dancers and '.' (Black) representing empty flo

... [5629 chars truncated]
alt-15 geology qwen3.5-122b: fig alone solves
"A golden fault line splits two strata. Red magma surfaces only where one stratum has mineral deposits and the other is hollow rock."
alt-2 cooking qwen3.5-122b: fig alone solves
"Two halves of a sandwich are compared by a picky eater who only wants bites where one side has filling and the other is bare bread."
alt-3 music qwen3.5-122b: fig alone solves
"Two orchestral sections are separated by a conductor's baton — only the notes played by one section alone ring out as solos."
alt-4 sports qwen3.5-122b: k=2
"Two teams line up on opposite sides of a net, and the referee flags only the positions where one side has a player standing alone without a mirror opponent."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10284 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A yellow net stretches vertically down the court. Azure players stand in various positions on the left; grey players stand on the right. Empty positions are black."
    *   This suggests a grid with a vertical separator.
    *   "Yellow net" likely corresponds to the color 'Y'.
    *   "Azure players" correspond to 'A'.
    *   "Grey players" correspond to 'X'.
    *   "Empty positions" correspond to '.'.
    *   The "net" (Y) seems to divide the grid into a left side and a right side.
*   **Action:** "Drop the net and mark every position where exactly one team has a player — paint that spot red."
    *   "Drop the net": This might mean removing the 'Y' column or treating it as a boundary.
    *   "Mark every position where exactly one team has a player": This implies comparing the left side (Azure/A) and the right side (Grey/X).
    *   "Paint that spot red": The output color is 'R'.
    *   "Where both have players facing off, or both positions are empty, leave it unmarked": This implies if both sides have a player (A and X) at the same relative position, or if both are empty (.), the result is empty ('.').
    *   Wait, the output grids in the examples are smaller than the input grids. Let's look at the dimensions.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
. A . . Y . X X .
A A . A Y X . . X
A A . . Y X . . X
. A . A Y . . X .
. . A . Y . X . X
```
Dimensions: 5 rows, 9 columns.
The 'Y' column is at index 4 (0-indexed).
Left side (cols 0-3): 4 columns.
Right side (cols 5-8): 4 columns.
Output:
```
. . R .
. R . .
. R . R
. R R R
. R R R
```
Dimensions: 5 rows, 4 columns.
This confirms the output width is the width of one side (excluding the 'Y' column).
The output height matches the input height.

Let's check the logic row by row.
Row 0:
Left: `. A . .`
Right: `. X X .` (Note: Input right side is `. X X .` from indices 5,6,7,8)
Comparison:
Col 0: Left `.` vs Right `.` -> Both empty -> Output `.`
Col 1: Left `A` vs Right `X` -> Both players -> Output `.` (Rule: "Where both have players facing off... leave it unmarked")
Col 2: Left `.` vs Right `X` -> One player (Right) -> Output `R`
Col 3: Left `.` vs Right `.` -> Both empty -> Output `.`
Result Row 0: `. . R .` matches Example 1 Output Row 0.

Row 1:
Left: `A A . A`
Right: `X . . X`
Col 0: `A` vs `X` -> Both -> `.`
Col 1: `A` vs `.` -> One (Left) -> `R`
Col 2: `.` vs `.` -> Both empty -> `.`
Col 3: `A` vs `X` -> Both -> `.`
Result Row 1: `. R . .` matches Example 1 Output Row 1.

Row 2:
Left: `A A . .`
Right: `X . . X`
Col 0: `A` vs `X` -> Both -> `.`
Col 1: `A` vs `.` -> One -> `R`
Col 2: `.` vs `.` -> Both empty -> `.`
Col 3: `.` vs `X` -> One -> `R`
Result Row 2: `. R . R` matches Example 1 Output Row 2.

Row 3:
Left: `. A . A`
Right: `. . X .`
Col 0: `.` vs `.` -> `.`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `X` -> `R`
Col 3: `A` vs `.` -> `R`
Result Row 3: `. R R R` matches Example 1 Output Row 3.

Row 4:
Left: `. . A .`
Right: `. X . X`
Col 0: `.` vs `.` -> `.`
Col 1: `.` vs `X` -> `R`
Col 2: `A` vs `.` -> `R`
Col 3: `.` vs `X` -> `R`
Result Row 4: `. R R R` matches Example 1 Output Row 4.

**Logic Confirmed:**
1.  Identify the central column containing 'Y'. This acts as the divider.
2.  Split the grid into Left (columns before 'Y') and Right (columns after 'Y').
3.  The output grid has the same number of rows as the input, and the number of columns equal to the width of the Left/Right side (they should be equal width).
4.  For each cell $(r, c)$ in the output grid:
    *   Let $L$ be the value at Input$(r, c)$.
    *   Let $R$ be the value at Input$(r, c + \text{width} + 1)$. (Assuming 'Y' is at index `width`).
    *   If ($L$ is 'A' and $R$ is '.') OR ($L$ is '.' and $R$ is 'X'): Output is 'R'.
    *   Otherwise (Both 'A'/'X', or Both '.'): Output is '.'.
    *   Wait, let's refine the condition "exactly one team has a player".
    *   Team 1: Azure ('A'). Team 2: Grey ('X').
    *   Condition: (Left is 'A' AND Right is '.') OR (Left is '.' AND Right is 'X').
    *   What if Left is 'A' and Right is 'X'? Both have players -> '.'.
    *   What if Left is '.' and Right is '.'? Both empty -> '.'.
    *   What if Left is 'A' and Right is 'A'? (Unlikely based on description, but logically "exactly one team"). If Right is 'A', it's not a player from the other team. But the description says "Azure players... on the left; grey players... on the right". So we expect 'A' on left and 'X' on right.
    *   Let's check Example 2 to be sure.

**Example 2:**
Input:
```
. A . . Y X . X .
. A . A Y X . X X
. A . A Y . . . X
. A . A Y . X . X
. . . A Y . . X .
```
Dimensions: 5 rows, 9 columns. 'Y' at index 4. Left width 4, Right width 4.
Output:
```
R R R .
R R 

... [5680 chars truncated]
alt-5 weather qwen3.5-122b: fig alone solves
"A cold front and a warm front collide along a stationary boundary — only where one system pushes into calm air does a red storm cell form."
alt-6 architecture qwen3.5-122b: k=2
"A load-bearing wall divides two mirror rooms. The inspector marks in red every spot where one room has a pillar and the other has open space — structural imbalance."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10420 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:**
    *   "A yellow load-bearing wall runs floor to ceiling." -> There is a vertical column of Yellow (Y) pixels.
    *   "Azure pillars support the left room; grey pillars support the right." -> To the left of the Yellow wall, there are Azure (A) pixels. To the right of the Yellow wall, there are Grey (X) pixels.
    *   "Black is open floor." -> Black (.) pixels represent empty space.
*   **What to do:**
    *   "Remove the wall on the blueprint" -> The Yellow (Y) column is removed or ignored in the output.
    *   "flag imbalances: where one room has a pillar and the other has open floor, mark it red." -> Compare the left side (Azure/Black) and the right side (Grey/Black) at each row.
    *   "Where one room has a pillar and the other has open floor, mark it red." -> If (Left is A and Right is .) OR (Left is . and Right is X), then Output is Red (R).
    *   "Where both have pillars or both have open space, leave it unmarked." -> If (Left is A and Right is X) OR (Left is . and Right is .), then Output is Black (.).
*   **Grid details:**
    *   "A half-width blueprint with red imbalance flags on a black background." -> The output grid width is half the input width (excluding the wall). The input seems to be split by the wall.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
. A . . Y . X X .
A A . A Y X . . X
A A . . Y X . . X
. A . A Y . . X .
. . A . Y . X . X

Let's look at the structure.
Width = 9.
Center column (index 4) is 'Y'.
Left side (indices 0-3): 4 columns.
Right side (indices 5-8): 4 columns.
Output Width = 4.
Output Height = 5 (same as input).

Let's check the transformation rule row by row.
Row 0:
Left: `. A . .`
Right: `. X X .`
Wall: `Y`
Comparison:
Col 0: Left `.` vs Right `.` -> Both open -> Output `.`
Col 1: Left `A` vs Right `X` -> Both pillars -> Output `.`
Col 2: Left `.` vs Right `X` -> Left open, Right pillar -> Imbalance -> Output `R`
Col 3: Left `.` vs Right `.` -> Both open -> Output `.`
Expected Output Row 0: `. . R .`
Actual Output Row 0: `. . R .` (Matches)

Row 1:
Left: `A A . A`
Right: `X . . X`
Col 0: `A` vs `X` -> Both pillars -> `.`
Col 1: `A` vs `.` -> Left pillar, Right open -> `R`
Col 2: `.` vs `.` -> Both open -> `.`
Col 3: `A` vs `X` -> Both pillars -> `.`
Expected Output Row 1: `. R . .`
Actual Output Row 1: `. R . .` (Matches)

Row 2:
Left: `A A . .`
Right: `X . . X`
Col 0: `A` vs `X` -> `.`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `.` -> `.`
Col 3: `.` vs `X` -> `R`
Expected Output Row 2: `. R . R`
Actual Output Row 2: `. R . R` (Matches)

Row 3:
Left: `. A . A`
Right: `. . X .`
Col 0: `.` vs `.` -> `.`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `X` -> `R`
Col 3: `A` vs `.` -> `R`
Expected Output Row 3: `. R R R`
Actual Output Row 3: `. R R R` (Matches)

Row 4:
Left: `. . A .`
Right: `. X . X`
Col 0: `.` vs `.` -> `.`
Col 1: `.` vs `X` -> `R`
Col 2: `A` vs `.` -> `R`
Col 3: `.` vs `X` -> `R`
Expected Output Row 4: `. R R R`
Actual Output Row 4: `. R R R` (Matches)

**Example 2:**
Input:
. A . . Y X . X .
. A . A Y X . X X
. A . A Y . . . X
. A . A Y . X . X
. . . A Y . . X .

Width = 9. Center Y at index 4.
Left (0-3), Right (5-8).

Row 0:
Left: `. A . .`
Right: `X . X .`
Col 0: `.` vs `X` -> `R`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `X` -> `R`
Col 3: `.` vs `.` -> `.`
Expected: `R R R .`
Actual: `R R R .` (Matches)

Row 1:
Left: `. A . A`
Right: `X . X X`
Col 0: `.` vs `X` -> `R`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `X` -> `R`
Col 3: `A` vs `X` -> `.`
Expected: `R R R .`
Actual: `R R R .` (Matches)

Row 2:
Left: `. A . A`
Right: `. . . X`
Col 0: `.` vs `.` -> `.`
Col 1: `A` vs `.` -> `R`
Col 2: `.` vs `.` -> `.`
Col 3: `A` vs `X` -> `.`
Expected: `. R . .`
Actual: `. R . .` (Matches)

Row 3:
Left: `. A . A`
Right: `. X . X`
Col 0: `.` vs `.` -> `.`
Col 1: `A` vs `X` -> `.`
Col 2: `.` vs `.` -> `.`
Col 3: `A` vs `X` -> `.`
Expected: `. . . .`
Actual: `. . . .` (Matches)

Row 4:
Left: `. . . A`
Right: `. . X .`
Col 0: `.` vs `.` -> `.`
Col 1: `.` vs `.` -> `.`
Col 2: `.` vs `X` -> `R`
Col 3: `A` vs `.` -> `R`
Expected: `. . R R`
Actual: `. . R R` (Matches)

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Yellow (Y):** The central divider/wall. It defines the split point. It is removed in the output.
    *   **Azure (A):** Pillars on the left side.
    *   **Grey (X):** Pillars on the right side.
    *   **Black (.):** Open floor (empty space).
    *   **Red (R):** Imbalance flag (output color).

2.  **AFFORDANCES:**
    *   The grid is symmetric in width around the central Y column.
    *   Left side columns correspond to Right side columns (mirrored or direct mapping? Based on examples, it's direct m

... [5768 chars truncated]
alt-7 warfare qwen3.5-122b: k=1
"Two armies face each other across a golden fortification. The battlefield scars appear only where one army's soldiers stand unopposed."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10914 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A yellow fortress wall divides the field." -> There is a vertical line of 'Y' (yellow) cells acting as a separator.
*   "Azure infantry hold positions on the left; grey infantry hold the right." -> 'A' (azure) is on the left side of the wall. 'X' (grey) is on the right side of the wall.
*   "Black is no man's land." -> '.' (black) represents empty space.
*   "Breach the wall and survey the field: where one army stands unopposed by the other, the ground turns red with conflict." -> This suggests a comparison between the left side (Azure) and the right side (Grey). If there is an 'A' on the left and no 'X' on the corresponding position on the right, it becomes 'R' (red). Or vice versa? "Where one army stands unopposed by the other".
*   "Where forces are matched or both absent, the ground stays dark." -> If there is an 'A' and an 'X' at corresponding positions, or if there is neither, the result is '.' (black).
*   "Grid details: A half-width battlefield of red scars and black earth." -> The output grid seems to be half the width of the input grid. This implies the transformation involves comparing the left half and the right half relative to the wall.

**2. Analyze the Training Example:**
Input:
```
. A . . Y . X X .
A A . A Y X . . X
A A . . Y X . . X
. A . A Y . . X .
. . A . Y . X . X
```
Dimensions: 5 rows, 9 columns.
The 'Y' column is at index 4 (0-indexed).
Left side (cols 0-3): 4 columns.
Right side (cols 5-8): 4 columns.
The wall is at col 4.

Let's look at the Output:
```
. . R .
. R . .
. R . R
. R R R
. R R R
```
Dimensions: 5 rows, 4 columns.
This confirms the output width is half the input width (excluding the wall).

Let's map the logic row by row.
Row 0:
Left: `. A . .`
Right: `. X X .`
Wall: `Y`
Output: `. . R .`

Comparison logic hypothesis:
Col 0: Left `.` vs Right `.` -> Output `.` (Both absent)
Col 1: Left `A` vs Right `X` -> Output `.` (Matched forces? Or A vs X?)
Col 2: Left `.` vs Right `X` -> Output `R` (Right has X, Left has nothing -> Unopposed?)
Col 3: Left `.` vs Right `.` -> Output `.` (Both absent)

Wait, let's re-read the metaphor: "where one army stands unopposed by the other, the ground turns red".
"Where forces are matched or both absent, the ground stays dark."

Let's check Row 0 again with this hypothesis.
Col 0: Left `.` (No army), Right `.` (No army). Both absent -> Dark (`.`). Matches output.
Col 1: Left `A` (Azure), Right `X` (Grey). Forces matched? -> Dark (`.`). Matches output.
Col 2: Left `.` (No army), Right `X` (Grey). Grey unopposed -> Red (`R`). Matches output.
Col 3: Left `.` (No army), Right `.` (No army). Both absent -> Dark (`.`). Matches output.

Row 1:
Left: `A A . A`
Right: `X . . X`
Output: `. R . .`

Col 0: Left `A`, Right `X`. Matched -> `.`. Matches output.
Col 1: Left `A`, Right `.`. Azure unopposed -> `R`. Matches output.
Col 2: Left `.`, Right `.`. Both absent -> `.`. Matches output.
Col 3: Left `A`, Right `X`. Matched -> `.`. Matches output.

Row 2:
Left: `A A . .`
Right: `X . . X`
Output: `. R . R`

Col 0: Left `A`, Right `X`. Matched -> `.`. Matches output.
Col 1: Left `A`, Right `.`. Azure unopposed -> `R`. Matches output.
Col 2: Left `.`, Right `.`. Both absent -> `.`. Matches output.
Col 3: Left `.`, Right `X`. Grey unopposed -> `R`. Matches output.

Row 3:
Left: `. A . A`
Right: `. . X .`
Output: `. R R R`

Col 0: Left `.`, Right `.`. Both absent -> `.`. Matches output.
Col 1: Left `A`, Right `.`. Azure unopposed -> `R`. Matches output.
Col 2: Left `.`, Right `X`. Grey unopposed -> `R`. Matches output.
Col 3: Left `A`, Right `.`. Azure unopposed -> `R`. Matches output.

Row 4:
Left: `. . A .`
Right: `. X . X`
Output: `. R R R`

Col 0: Left `.`, Right `.`. Both absent -> `.`. Matches output.
Col 1: Left `.`, Right `X`. Grey unopposed -> `R`. Matches output.
Col 2: Left `A`, Right `.`. Azure unopposed -> `R`. Matches output.
Col 3: Left `.`, Right `X`. Grey unopposed -> `R`. Matches output.

**3. Define the Transformation Rule:**
1.  Identify the central column containing 'Y' (Yellow). This is the "wall".
2.  Split the grid into Left Subgrid (columns to the left of 'Y') and Right Subgrid (columns to the right of 'Y').
3.  The output grid has the same dimensions as the Left/Right subgrids (Height = Input Height, Width = (Input Width - 1) / 2).
4.  For each cell (r, c) in the output grid:
    *   Let `L` be the value at Input[r][c].
    *   Let `R` be the value at Input[r][c + Width + 1] (where Width is the subgrid width).
    *   If `L` is 'A' (Azure) and `R` is 'X' (Grey): Output is '.' (Black). (Matched forces)
    *   If `L` is '.' (Black) and `R` is '.' (Black): Output is '.' (Black). (Both absent)
    *   If `L` is 'A' and `R` is '.': Output is 'R' (Red). (Azure unopposed)
    *   If `

... [6301 chars truncated]
alt-8 theater qwen3.5-122b: fig alone solves
"A golden curtain parts to reveal two casts rehearsing the same play — the director spotlights only the actors who have no counterpart on the other side."
alt-9 gardening qwen3.5-122b: fig alone solves
"A golden trellis separates two garden beds. The gardener plants red flowers only in spots where one bed blooms and the other lies fallow."

Task 223: 3d6c6e23

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original Scattered seeds fall and pile into pyramids on the ground. MARC valid 2
alt-1 biology Dormant spores drift down the spine of an organism and crystallize into a layere ... [26 chars truncated] fail
alt-10 astronomy Stars strung along a filament collapse under gravity and accrete into a conical ... [29 chars truncated] fail
alt-11 ocean/sailing Signal flags run up a halyard are struck and draped over the bowsprit in a cerem ... [14 chars truncated] fail
alt-12 electronics Charged capacitors arrayed along a bus rail discharge and their energy pools int ... [52 chars truncated] fail
alt-13 mythology Runes inscribed at intervals on a world-pillar detach and reassemble as a sacred ... [28 chars truncated] fail
alt-14 dance Dancers poised on separate platforms along a pole leap down and form a tiered ta ... [25 chars truncated] fail
alt-15 geology Mineral veins exposed along a vertical fault line erode free and deposit into a ... [29 chars truncated] fail
alt-2 cooking Ingredients measured out along a skewer slide off and melt into a layered parfai ... [29 chars truncated] fail
alt-3 music Staccato notes hung high on a staff collapse into a resonant chord that swells a ... [13 chars truncated] fail
alt-4 sports Climbers roped at intervals along a cliff face rappel down and form a human pyra ... [18 chars truncated] fail
alt-5 weather Raindrops suspended in a column of air finally fall and accumulate into a snowdr ... [19 chars truncated] fail
alt-6 architecture Bricks stored on different scaffold platforms are lowered and mortared into a zi ... [23 chars truncated] fig alone solves
alt-7 warfare Scouts posted at watchtowers along a frontier withdraw and form ranked battle li ... [25 chars truncated] fail
alt-8 theater Spotlights hung at different heights on a fly tower descend and fan into a footl ... [30 chars truncated] fail
alt-9 gardening Buds clinging to a bare stem drop their petals, which settle into a mulch mound ... [17 chars truncated] fail
original qwen3.5-122b: k=2
"Scattered seeds fall and pile into pyramids on the ground."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11435 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "Colored seeds float in vertical columns... hovering in the upper air... ground below sits empty".
*   **Action:** "Gravity finally switches on. Every floating seed in a column falls... accumulate into a neat triangular mound resting on the ground floor".
*   **Shape:** "Triangular mound", "perfect pile", "pyramid".
*   **Ordering:** "Colors preserve their original layering: whatever was highest in the sky settles at the peak of the mound, and the deepest colors spread across its wide base."
*   **Result:** "The sky clears completely — all black — and only the triangular mounds remain, each sitting flush against the bottom edge of the grid, centered beneath where its seeds once floated."
*   **Multiple Columns:** "If multiple columns had seeds, multiple independent pyramids form side by side".

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 17 rows, 13 columns.
    *   Seeds: Orange (O) in column 6 (0-indexed, let's check).
        *   Row 1: O at col 6.
        *   Row 2: O at col 6.
        *   Row 4: O at col 6.
        *   Row 5: O at col 6.
        *   Row 6: O at col 6.
        *   Row 8: O at col 6.
        *   Row 10: O at col 6.
        *   Row 11: O at col 6.
        *   Row 12: O at col 6.
        *   Total O seeds = 9.
    *   Output:
        *   The seeds form a pyramid at the bottom.
        *   Row 13 (index 13): O at col 6. (1 seed)
        *   Row 14 (index 14): O at col 5, 6, 7. (3 seeds)
        *   Row 15 (index 15): O at col 4, 5, 6, 7, 8. (5 seeds)
        *   Total seeds in output = 1 + 3 + 5 = 9.
        *   The pyramid is centered on the original column index (col 6).
        *   The pyramid grows upwards from the bottom row.
        *   Wait, the description says "resting on the ground floor". In the output, the pyramid is at the bottom rows (13, 14, 15). The grid height is 17. So rows 13, 14, 15 are the bottom 3 rows.
        *   Shape: 1 on top, 3 in middle, 5 on bottom. This is a triangle/pyramid shape.
        *   Wait, usually a pyramid of height $h$ has $1 + 3 + 5 + ... + (2h-1)$ items. Here $1+3+5 = 9$. So height is 3.
        *   The seeds fall to the bottom. The "highest in the sky" (top-most seed in input) becomes the "peak of the mound" (top-most seed in output pyramid).
        *   In Example 1, all seeds are the same color (O), so layering doesn't matter visually, but the count matters.
        *   Input column 6 has 9 seeds. Output has a pyramid of 9 seeds centered at col 6, sitting on the bottom row.

*   **Example 2:**
    *   Input: 16 rows, 11 columns.
    *   Seeds: Orange (O) in column 5.
        *   Row 0: O
        *   Row 3: O
        *   Row 6: O
        *   Row 9: O
        *   Total O seeds = 4.
    *   Output:
        *   Pyramid at bottom.
        *   Row 14: O at col 5. (1 seed)
        *   Row 15: O at col 4, 5, 6. (3 seeds)
        *   Total seeds = 1 + 3 = 4.
        *   Height = 2.
        *   Centered at col 5.
        *   Bottom row is 15.
    *   Observation: The pyramid is built from the bottom up.
        *   Base layer (bottom row): width $2h - 1$.
        *   Next layer up: width $2h - 3$.
        *   ...
        *   Top layer: width 1.
        *   Total count = $h^2$.
        *   Wait, $1+3=4=2^2$. $1+3+5=9=3^2$.
        *   So the number of seeds $N$ determines the height $h$ such that $h^2 = N$.
        *   Let's check if $N$ is always a perfect square.
        *   Example 1: 9 seeds -> $3^2$. Height 3.
        *   Example 2: 4 seeds -> $2^2$. Height 2.
        *   What if $N$ is not a perfect square? The description says "neat triangular mound". Usually, this implies a specific shape. If $N$ isn't a square number, maybe it fills rows from bottom up?
        *   Let's re-read carefully: "accumulate into a neat triangular mound... The more seeds that fall, the taller and broader the pyramid they build."
        *   "Colors preserve their original layering: whatever was highest in the sky settles at the peak of the mound".
        *   This implies the order of colors matters. Top seed in input -> Top seed in output pyramid.
        *   Let's look at the Test Input to see if we have mixed colors.

**3. Analyze the Test Input:**
*   Grid Size: 30 rows, 10 columns.
*   Columns with seeds:
    *   Column 2 (0-indexed):
        *   Row 0: R
        *   Row 1: R
        *   Row 3: R
        *   Row 4: R
        *   Row 5: B
        *   Row 6: B
        *   Row 8: B
        *   Row 9: B
        *   Row 11: B
        *   Total seeds in Col 2: 4 R + 5 B = 9 seeds.
        *   Order from top (highest in sky) to bottom: R, R, R, R, B, B, B, B, B.
        *   Wait, let's list them by row index:
            *   0: R
            *   1: R
            *   3: R
            *   4: R
            *   5: B
            *   6: B
            *   

... [6495 chars truncated]
alt-1 biology qwen3.5-122b: fail
"Dormant spores drift down the spine of an organism and crystallize into a layered exoskeleton at its base."
Fail (best cell_acc=0.43 at k=3)
Best Attempt
vs
Expected
Reasoning (11117 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark tissue sample with pigmented cells dotting a central nerve column, separated by inert gaps, with blank tissue below."
    *   "Dark tissue sample" -> Background is black (`.`).
    *   "Pigmented cells" -> Colored pixels (R, B, O, etc.).
    *   "Dotting a central nerve column" -> The colored pixels seem to be arranged vertically, possibly in columns.
    *   "Separated by inert gaps" -> There are empty rows between the colored pixels.
    *   "Blank tissue below" -> The bottom part of the grid is empty.
*   **Transformation:** "The pigmented cells migrate downward, shed their scattered arrangement, and fuse into a structured growth anchored at the organism's foundation—each layer broader than the last, like a living coral polyp building outward from its foot."
    *   "Migrate downward" -> The colored pixels move to the bottom of the grid.
    *   "Fuse into a structured growth" -> They form a solid shape.
    *   "Anchored at the organism's foundation" -> The shape sits on the bottom row.
    *   "Each layer broader than the last" -> This suggests a pyramid or triangle shape. The bottom layer is the widest, the one above it is narrower, etc.
    *   "Symmetrically straddling the original nerve column" -> The shape is centered horizontally based on the column where the input pixels were found.
*   **Grid details:** "The specimen retains its original dimensions. All former cell sites go dark; the structured growth sits flush against the bottom edge, symmetrically straddling the original nerve column."
    *   Input grid size = Output grid size.
    *   Input colored pixels become black (`.`) in the output (except where the new structure is).
    *   The new structure is at the bottom.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 17 rows, 13 columns.
    *   Colored pixels: Orange (`O`) at column index 6 (0-indexed, middle).
    *   Rows with `O`: 1, 2, 4, 5, 6, 8, 10, 11, 12. (Total 9 `O`s).
    *   Output:
        *   Rows 0-12 are all `.`.
        *   Row 13: `O` at col 6.
        *   Row 14: `O O O` at cols 5, 6, 7.
        *   Row 15: `O O O O O` at cols 4, 5, 6, 7, 8.
        *   Wait, let's count the `O`s in the output.
        *   Row 13: 1 `O`.
        *   Row 14: 3 `O`s.
        *   Row 15: 5 `O`s.
        *   Total `O`s = 1 + 3 + 5 = 9.
        *   This matches the count of `O`s in the input.
        *   The shape is a triangle pointing up, centered on the column of the input pixels.
        *   The base is at the bottom (Row 15 is the last row? No, grid height is 17. Rows are 0-16).
        *   Let's check the row indices in Example 1 Output.
        *   Input height: 17 rows.
        *   Output rows with content: 13, 14, 15.
        *   Wait, row 16 is empty? Let's check the text.
        *   Output text:
            Row 0-12: `.`
            Row 13: `. . . . . . O . . . . . .` (1 `O`)
            Row 14: `. . . . . O O O . . . . .` (3 `O`s)
            Row 15: `. . . . O O O O O . . . .` (5 `O`s)
            Row 16: `. . . . . . . . . . . . .` (Empty)
        *   Wait, looking closely at Example 1 Output provided in the prompt:
            It ends at row 15?
            Let's count lines in Example 1 Output.
            1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17 lines.
            Line 13: `. . . . . . O . . . . . .`
            Line 14: `. . . . . O O O . . . . .`
            Line 15: `. . . . O O O O O . . . .`
            Line 16: `. . . . . . . . . . . . .`
            Line 17: `. . . . . . . . . . . . .`
            Wait, the prompt text for Example 1 Output shows:
            ...
            . . . . . . . . . . . . . (Line 13)
            . . . . . . . . . . . . . (Line 14)
            . . . . . . . . . . . . . (Line 15)
            . . . . . . . . . . . . . (Line 16)
            . . . . . . . . . . . . . (Line 17)
            . . . . . . . . . . . . . (Line 18)
            . . . . . . . . . . . . . (Line 19)
            . . . . . . . . . . . . . (Line 20)
            . . . . . . . . . . . . . (Line 21)
            . . . . . . . . . . . . . (Line 22)
            . . . . . . . . . . . . . (Line 23)
            . . . . . . . . . . . . . (Line 24)
            . . . . . . . . . . . . . (Line 25)
            . . . . . . O . . . . . . (Line 26)
            . . . . . O O O . . . . . (Line 27)
            . . . . O O O O O . . . . (Line 28)
            Wait, I need to count the lines in the provided text block carefully.
            Input Example 1 has 17 lines.
            Output Example 1 has 17 lines.
            Let's look at the last few lines of Output Example 1.
            Line 13: `. . . . . . . . . . . . .`
            Line 14: `. . . . . . . . . . . . .`
            Line 15: `. . . . . . . . . . . . .`
            Line 16: `. 

... [6153 chars truncated]
alt-10 astronomy qwen3.5-122b: fail
"Stars strung along a filament collapse under gravity and accrete into a conical nebula at the galactic floor."
Fail (best cell_acc=0.01 at k=1)
Best Attempt
vs
Expected
Reasoning (11843 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark void with luminous points of different colors spaced along a single cosmic filament, empty space below."
    *   "Dark void" = Black background (`.`).
    *   "Luminous points" = Colored pixels.
    *   "Spaced along a single cosmic filament" = The colored pixels seem to form a vertical line or a set of vertical lines. Looking at the training example, the input has a vertical column of `O`s.
    *   "Empty space below" = The bottom part of the grid is empty.
*   **Transformation:** "The filament destabilizes and each star falls, accreting into a nebula—the first arrival forms a lone point at the apex, each subsequent shell wider, their spectral colors ordered as they were originally strung, the broadest shell touching the lowest edge of the field."
    *   "Filament destabilizes and each star falls" = The vertical line of colored pixels disappears from its original position and moves downwards.
    *   "Accreting into a nebula" = They form a shape at the bottom.
    *   "First arrival forms a lone point at the apex" = The top-most pixel of the new shape is a single pixel.
    *   "Each subsequent shell wider" = The shape expands outwards as it goes down. It looks like a triangle or pyramid.
    *   "Spectral colors ordered as they were originally strung" = The order of colors in the vertical line is preserved in the layers of the pyramid from top to bottom.
    *   "Broadest shell touching the lowest edge of the field" = The bottom row of the pyramid touches the bottom of the grid.
*   **Grid details:** "The void retains its dimensions. All former star positions go dark; the nebula sits at the bottom, centered on the filament's axis."
    *   Grid size stays the same.
    *   Original positions become black (`.`).
    *   The new shape is centered horizontally on the column where the original line was.

**2. Analyze the Training Example:**
*   **Input:** 15 rows, 13 columns.
    *   There is a vertical line of `O` (orange) pixels.
    *   Let's count the `O`s.
    *   Row 1: `.`
    *   Row 2: `O` at index 6 (0-indexed).
    *   Row 3: `O` at index 6.
    *   Row 4: `.`
    *   Row 5: `O` at index 6.
    *   Row 6: `O` at index 6.
    *   Row 7: `O` at index 6.
    *   Row 8: `.`
    *   Row 9: `O` at index 6.
    *   Row 10: `.`
    *   Row 11: `O` at index 6.
    *   Row 12: `O` at index 6.
    *   Row 13: `O` at index 6.
    *   Row 14: `.`
    *   Row 15: `.`
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Input Example 1:
        Row 0: . . . . . . . . . . . . .
        Row 1: . . . . . . O . . . . . .
        Row 2: . . . . . . O . . . . . .
        Row 3: . . . . . . . . . . . . .
        Row 4: . . . . . . O . . . . . .
        Row 5: . . . . . . O . . . . . .
        Row 6: . . . . . . O . . . . . .
        Row 7: . . . . . . . . . . . . .
        Row 8: . . . . . . O . . . . . .
        Row 9: . . . . . . . . . . . . .
        Row 10: . . . . . . O . . . . . .
        Row 11: . . . . . . O . . . . . .
        Row 12: . . . . . . O . . . . . .
        Row 13: . . . . . . . . . . . . .
        Row 14: . . . . . . . . . . . . .
        Row 15: . . . . . . . . . . . . .
    *   Total rows: 16. Total cols: 13.
    *   Col index of `O`: 6 (7th column).
    *   Count of `O`s:
        Row 1, 2, 4, 5, 6, 8, 10, 11, 12.
        Total count = 9 `O`s.
    *   Wait, let's recount carefully.
        R1: O
        R2: O
        R3: .
        R4: O
        R5: O
        R6: O
        R7: .
        R8: O
        R9: .
        R10: O
        R11: O
        R12: O
        R13: .
        R14: .
        R15: .
        R16: .
        Wait, the example input text has 16 lines.
        Let's list the indices of rows containing `O`:
        1, 2, 4, 5, 6, 8, 10, 11, 12.
        Count = 9.
    *   Output Example 1:
        Rows 0-12 are all `.`.
        Row 13: . . . . . . O . . . . . . (1 `O` at center)
        Row 14: . . . . . O O O . . . . . (3 `O`s centered)
        Row 15: . . . . O O O O O . . . . (5 `O`s centered)
    *   Wait, the output has 3 rows filled.
    *   Row 13: 1 pixel.
    *   Row 14: 3 pixels.
    *   Row 15: 5 pixels.
    *   Total pixels in output = 1 + 3 + 5 = 9 pixels.
    *   This matches the count of `O`s in the input (9).
    *   The shape is a triangle/pyramid.
    *   The colors are all `O` in this example, so "spectral colors ordered" is trivial.
    *   The position is centered on column 6.
    *   The bottom of the pyramid is at the bottom of the grid (Row 15).
    *   The top of the pyramid is at Row 13.
    *   The width increases by 2 each row (1, 3, 5).
    *   This implies the number of rows in the pyramid is determined by the number of input pixels?
    *   If there are $N$ pixels, and the pyramid grows 1, 3, 5...
    *   Sum of first $k$ odd numbers is $k^2$.
   

... [6897 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fail
"Signal flags run up a halyard are struck and draped over the bowsprit in a ceremonial bunting."
Fail (best cell_acc=0.43 at k=1)
Best Attempt
vs
Expected
Reasoning (10561 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A dark harbor with colored pennants clipped at intervals along a single vertical halyard, open water below."
    *   "Dark harbor" likely refers to the black background (`.`).
    *   "Colored pennants clipped at intervals along a single vertical halyard" suggests a vertical line of colored pixels in the input grid.
    *   "Open water below" suggests empty space below the pennants.
*   **What to do:** "The pennants are hauled down and re-dressed as bunting along the bow—the topmost flag becomes the single peak pennant, each swag below it wider, their colors kept in the order they flew, the widest swag kissing the waterline."
    *   "Hauled down": The vertical line is removed.
    *   "Re-dressed as bunting along the bow": The colors are rearranged into a shape at the bottom.
    *   "Topmost flag becomes the single peak pennant": The first color in the vertical sequence becomes the top center of the new shape.
    *   "Each swag below it wider": The shape expands downwards. It looks like a triangle or pyramid.
    *   "Colors kept in the order they flew": The sequence of colors from top to bottom in the input determines the layers of the new shape.
    *   "Widest swag kissing the waterline": The bottom of the shape is at the bottom of the grid.
*   **Grid details:** "The harbor view keeps its dimensions. The halyard is bare; only the bunting remains, draped at the very bottom and centered under the mast line."
    *   Output grid size = Input grid size.
    *   Input vertical line is cleared (becomes `.`).
    *   New shape is at the bottom, centered.

**2. Analyze the Training Example:**
*   **Input:** 17 rows, 13 columns.
    *   There is a vertical line of `O` (orange) pixels.
    *   Let's find the coordinates of the `O`s.
    *   Row 1 (index 0): `.`
    *   Row 2 (index 1): `O` at col 6 (0-indexed).
    *   Row 3 (index 2): `O` at col 6.
    *   Row 4 (index 3): `.`
    *   Row 5 (index 4): `O` at col 6.
    *   Row 6 (index 5): `O` at col 6.
    *   Row 7 (index 6): `O` at col 6.
    *   Row 8 (index 7): `.`
    *   Row 9 (index 8): `O` at col 6.
    *   Row 10 (index 9): `.`
    *   Row 11 (index 10): `O` at col 6.
    *   Row 12 (index 11): `O` at col 6.
    *   Row 13 (index 12): `O` at col 6.
    *   Row 14 (index 13): `.`
    *   Row 15 (index 14): `.`
    *   Row 16 (index 15): `.`
    *   Row 17 (index 16): `.`
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Input:
        ```
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        ```
    *   Count of `O`s:
        *   Row 1: 0
        *   Row 2: 1
        *   Row 3: 1
        *   Row 4: 0
        *   Row 5: 1
        *   Row 6: 1
        *   Row 7: 1
        *   Row 8: 0
        *   Row 9: 1
        *   Row 10: 0
        *   Row 11: 1
        *   Row 12: 1
        *   Row 13: 1
        *   Row 14-17: 0
    *   Total `O`s = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 9? Let's count carefully.
    *   Rows with O: 2, 3, 5, 6, 7, 9, 11, 12, 13.
    *   Total count = 9.
    *   Column index: 6 (7th column).
    *   Grid width: 13. Center column is index 6. So the halyard is in the center.

*   **Output:**
    *   Rows 0-12: All `.`
    *   Row 13: `.` `.` `.` `.` `.` `O` `.` `.` `.` `.` `.` `.` `.` (One `O` at center)
    *   Row 14: `.` `.` `.` `.` `O` `O` `O` `.` `.` `.` `.` `.` `.` (Three `O`s centered)
    *   Row 15: `.` `.` `.` `O` `O` `O` `O` `O` `.` `.` `.` `.` `.` (Five `O`s centered)
    *   Wait, the output grid in the example has 17 rows.
    *   Let's check the output rows provided:
        ```
        . . . . . . . . . . . . .
        ... (13 rows of dots)
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .  (Row 13)
        . . . . . O O O . . . . .  (Row 14)
        . . . . O O O O O . . . .  (Row 15)
        ```
    *   Wait, counting the output lines in the example:
        1. . . . . . . . . . . . . .
        2. . . . . . . . . . . . . .
        3. . . . . . . . . . . . . .
        4. . . . . . . . . . . . . .
        5. . . . . . . . . . . . . .
        6. . . . . . . . . . . . . .
        7. . . . . . . . . . . . . .
        8. . . . . . . . . . . . . .
        9. . . . . . . . . . . . . .
        10. . . . . . . . . . . . . .
        11. . . . . . . . . . . . . .
        12. . . . . . . . . . . . . .
      

... [5567 chars truncated]
alt-12 electronics qwen3.5-122b: fail
"Charged capacitors arrayed along a bus rail discharge and their energy pools into a wedge-shaped heat signature at the board's edge."
Fail (best cell_acc=0.07 at k=1)
Best Attempt
vs
Expected
Reasoning (10712 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A dark circuit board with colored charge indicators lit at various points along a single vertical bus, unused board below."
*   **Action:** "The capacitors discharge simultaneously; their energy migrates to the board's lower edge and manifests as a thermal wedge—hottest point at the peak, each band below wider, thermal colors matching the original charge indicators top-to-bottom."
*   **Grid Details:** "The board dimensions are unchanged. All indicator positions go dark; only the thermal wedge glows at the bottom, centered on the bus rail."

**2. Analyze the Training Example:**
*   **Input:** A 15x13 grid (15 rows, 13 columns).
    *   There is a vertical column of 'O' (orange) pixels.
    *   Let's check the column index.
    *   Row 1: `.`
    *   Row 2: `O` at index 6 (0-indexed).
    *   Row 3: `O` at index 6.
    *   Row 4: `.`
    *   Row 5: `O` at index 6.
    *   Row 6: `O` at index 6.
    *   Row 7: `O` at index 6.
    *   Row 8: `.`
    *   Row 9: `O` at index 6.
    *   Row 10: `.`
    *   Row 11: `O` at index 6.
    *   Row 12: `O` at index 6.
    *   Row 13: `O` at index 6.
    *   Row 14: `.`
    *   Row 15: `.`
    *   Wait, let's count carefully.
    *   Input rows: 15.
    *   Input cols: 13.
    *   The 'O's are in column 6 (7th column).
    *   There are multiple 'O's scattered vertically.
*   **Output:** A 15x13 grid.
    *   Rows 0-12 are all `.` (black).
    *   Row 13: `.` `.` `.` `.` `.` `O` `.` `.` `.` `.` `.` `.` `.` (One 'O' at center).
    *   Row 14: `.` `.` `.` `.` `O` `O` `O` `.` `.` `.` `.` `.` `.` (Three 'O's centered).
    *   Row 15: `.` `.` `.` `O` `O` `O` `O` `O` `.` `.` `.` `.` `.` (Five 'O's centered).
    *   Wait, the input has 15 rows. The output has 15 rows.
    *   Let's check the indices of the output rows.
    *   Row 13 (index 13): 1 'O'.
    *   Row 14 (index 14): 3 'O's.
    *   Wait, looking at the provided output text:
        ```
        . . . . . . . . . . . . .
        ... (13 rows of dots)
        . . . . . O . . . . . . .
        . . . . O O O . . . . . .
        . . . O O O O O . . . . .
        ```
        Actually, counting the lines in the example output:
        1. `.`
        2. `.`
        3. `.`
        4. `.`
        5. `.`
        6. `.`
        7. `.`
        8. `.`
        9. `.`
        10. `.`
        11. `.`
        12. `.`
        13. `.`
        14. `. . . . . O . . . . . . .` (Row index 13)
        15. `. . . . O O O . . . . . .` (Row index 14)
        Wait, the example output shows 15 lines.
        Line 14 has 1 'O'.
        Line 15 has 3 'O's.
        Wait, looking closer at the provided text for Example 1 Output:
        It ends with:
        `. . . . . . . . . . . . .` (Line 13)
        `. . . . . O . . . . . . .` (Line 14)
        `. . . . O O O . . . . . .` (Line 15)
        `. . . O O O O O . . . . .` (Line 16??)
        Let me recount the lines in the Example 1 Output block.
        1. . . . . . . . . . . . . .
        2. . . . . . . . . . . . . .
        3. . . . . . . . . . . . . .
        4. . . . . . . . . . . . . .
        5. . . . . . . . . . . . . .
        6. . . . . . . . . . . . . .
        7. . . . . . . . . . . . . .
        8. . . . . . . . . . . . . .
        9. . . . . . . . . . . . . .
        10. . . . . . . . . . . . . .
        11. . . . . . . . . . . . . .
        12. . . . . . . . . . . . . .
        13. . . . . . . . . . . . . .
        14. . . . . . O . . . . . . .
        15. . . . . O O O . . . . . .
        16. . . . O O O O O . . . . .
        Wait, the input has 15 rows. The output text block seems to have 16 lines? Or did I miscount?
        Let's count the input lines in Example 1.
        1. . . . . . . . . . . . . .
        2. . . . . . . O . . . . . .
        3. . . . . . . O . . . . . .
        4. . . . . . . . . . . . . .
        5. . . . . . . O . . . . . .
        6. . . . . . . O . . . . . .
        7. . . . . . . O . . . . . .
        8. . . . . . . . . . . . . .
        9. . . . . . . O . . . . . .
        10. . . . . . . . . . . . . .
        11. . . . . . . O . . . . . .
        12. . . . . . . O . . . . . .
        13. . . . . . . O . . . . . .
        14. . . . . . . . . . . . . .
        15. . . . . . . . . . . . . .
        16. . . . . . . . . . . . . .
        Ah, the input has 16 rows.
        Let's recount.
        1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16.
        Yes, 16 rows.
        Output has 16 rows.
        Rows 0-12 (13 rows) are empty.
        Row 13: 1 'O'.
        Row 14: 3 'O's.
        Row 15: 5 'O's.
        Wait, looking at the output text again:
        Line 14: `. . . . . O . . . . . . .` (1 'O')
        Line 15: `. . . . O O O . . . . . .` (3 'O's)
        Line 16: `. . . O O O O O . . . . .` (5 'O's)
        So the wedge grows downwards.
        The "bus rail" is th

... [5718 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"Runes inscribed at intervals on a world-pillar detach and reassemble as a sacred cairn at the pillar's root."
Fail (best cell_acc=0.45 at k=2)
Best Attempt
vs
Expected
Reasoning (11343 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A dark void (black background `.`) bisected by a single pillar bearing colored runes (colored pixels) at scattered heights. Barren ground below.
*   **What to do:** The runes peel from the pillar and drift downward, stacking into a cairn at the base.
    *   "One rune crowns the peak": The top of the cairn has 1 rune.
    *   "Each tier below wider": The cairn is a pyramid/triangle shape.
    *   "Colors following the order they were carved from top to bottom of the pillar": The sequence of colors in the cairn corresponds to the vertical order of the colored pixels in the input pillar.
*   **Grid details:** The void keeps its dimensions. The pillar is blank (the original colored pixels disappear from their original positions). Only the cairn remains at the very bottom, centered on the pillar's axis.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 15 rows, 13 columns.
    *   Colored pixels: `O` (Orange).
    *   Locations of `O`:
        *   Row 1 (0-indexed): Col 6
        *   Row 2: Col 6
        *   Row 4: Col 6
        *   Row 5: Col 6
        *   Row 6: Col 6
        *   Row 8: Col 6
        *   Row 10: Col 6
        *   Row 11: Col 6
        *   Row 12: Col 6
    *   Total `O` count: 9.
    *   Output:
        *   Rows 0-12 are empty (`.`).
        *   Row 13: `O` at Col 6 (1 pixel).
        *   Row 14: `O O O` at Cols 5, 6, 7 (3 pixels).
        *   Wait, let's look closer at the output grid provided in the prompt.
        *   Output Grid:
            *   Row 13: `. . . . . . O . . . . . .` (1 pixel at center)
            *   Row 14: `. . . . . O O O . . . . .` (3 pixels centered)
            *   Wait, the input had 9 `O`s. The output has 1 + 3 = 4 `O`s.
            *   Let me re-read the input/output carefully.
            *   Input Rows: 15. Output Rows: 15.
            *   Input `O`s:
                *   Row 1
                *   Row 2
                *   Row 4
                *   Row 5
                *   Row 6
                *   Row 8
                *   Row 10
                *   Row 11
                *   Row 12
                *   Total = 9.
            *   Output `O`s:
                *   Row 13: 1 `O`
                *   Row 14: 3 `O`s
                *   Total = 4.
            *   This contradicts the "stacking into a cairn" idea if all runes are used.
            *   Let's check the position of the pillar. It's at Column 6 (0-indexed, 7th column). Width is 13. Center is 6.
            *   The output pyramid is centered at Col 6.
            *   Why only 4 `O`s?
            *   Maybe the "pillar" isn't just the column.
            *   Let's look at the metaphor again: "The runes peel from the pillar and drift downward... one rune crowns the peak, each tier below wider".
            *   Usually, a pyramid of height $h$ has $1 + 3 + 5 + \dots$ pixels? Or $1 + 2 + 3$?
            *   Row 13 has 1. Row 14 has 3. This looks like a triangle where width increases by 2 each row (1, 3, 5...).
            *   If there were 9 runes, we would expect a pyramid of height 3 (1+3+5 = 9).
            *   But the output only shows 2 rows of the pyramid (1+3=4).
            *   Why?
            *   Maybe the input grid in Example 1 is truncated in the prompt display?
            *   Let's count the rows in Example 1 Input.
            *   1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 rows.
            *   Let's count the rows in Example 1 Output.
            *   1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 rows.
            *   Wait, looking at the provided text for Example 1 Output:
                *   Rows 0-12 are empty.
                *   Row 13: `O` at center.
                *   Row 14: `O O O` at center.
            *   This implies only 4 runes were used.
            *   Is it possible the input actually had fewer runes?
            *   Let's recount Input Example 1 `O`s.
                *   Line 2: `O`
                *   Line 3: `O`
                *   Line 5: `O`
                *   Line 6: `O`
                *   Line 7: `O`
                *   Line 9: `O`
                *   Line 11: `O`
                *   Line 12: `O`
                *   Line 13: `O`
                *   Total 9.
            *   Why does the output only have 4?
            *   Hypothesis 1: The output is cut off? No, the prompt says "Output:".
            *   Hypothesis 2: The transformation rule is different. Maybe it only takes the bottom-most runes? Or top-most?
            *   Hypothesis 3: The "pillar" is defined differently.
            *   Hypothesis 4: I am miscounting the output rows.
                *   Output lines:
                *   1: . . . . . . . . . . . . .
                *   ...
                *   13: . . . . . . . . . . . . .
                *   14: . . . . . . O . . . . . .
               

... [6346 chars truncated]
alt-14 dance qwen3.5-122b: fail
"Dancers poised on separate platforms along a pole leap down and form a tiered tableau at the stage floor."
Fail (best cell_acc=0.43 at k=3)
Best Attempt
vs
Expected
Reasoning (11832 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A dark stage with costumed dancers balanced at different heights along a single vertical pole, open floor below."
    *   "Dark stage" likely means the background is black (`.`).
    *   "Costumed dancers" are the colored pixels.
    *   "Single vertical pole" suggests the dancers are aligned vertically in a specific column.
    *   "Balanced at different heights" means they are scattered vertically along that column.
*   **Action:** "Each dancer descends and joins a living tableau at the floor—the highest dancer stands alone on top, each tier below adds partners on both sides, costumes ordered as they were perched from top to bottom."
    *   "Descends and joins a living tableau at the floor": The colored pixels move to the bottom of the grid.
    *   "Highest dancer stands alone on top": The top-most colored pixel in the input becomes the single pixel at the top of the new structure at the bottom.
    *   "Each tier below adds partners on both sides": This implies a pyramid or triangle shape.
        *   Row 1 of the structure: 1 pixel (the highest one).
        *   Row 2 of the structure: 3 pixels (1 center + 1 left + 1 right).
        *   Row 3 of the structure: 5 pixels.
        *   Generally, row $k$ has $2k - 1$ pixels.
    *   "Costumes ordered as they were perched from top to bottom": The colors in the pyramid rows correspond to the order of the input pixels from top to bottom.
        *   Top pixel of input -> Top row of pyramid (1 pixel).
        *   Next pixel(s) of input -> Next row of pyramid (3 pixels).
        *   Next pixel(s) of input -> Next row of pyramid (5 pixels).
        *   Wait, the description says "costumes ordered as they were perched". If there is only one color per row in the pyramid, where do the extra pixels come from?
        *   Let's look at the examples to clarify the mapping between input pixels and output structure.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** 17x13 grid.
    *   Column 6 (0-indexed, 7th column) has Orange (`O`) pixels.
    *   Positions of `O`: (1,6), (2,6), (4,6), (5,6), (6,6), (8,6), (10,6), (11,6), (12,6).
    *   Total `O` pixels: 9.
    *   Wait, let's count carefully.
    *   Rows with `O`: 1, 2, 4, 5, 6, 8, 10, 11, 12.
    *   Total count = 9.
*   **Output:** 17x13 grid.
    *   The `O` pixels form a triangle at the bottom.
    *   Row 13 (index 13): 1 `O` at col 6.
    *   Row 14 (index 14): 3 `O`s at cols 5, 6, 7.
    *   Row 15 (index 15): 5 `O`s at cols 4, 5, 6, 7, 8.
    *   Total `O` pixels in output: 1 + 3 + 5 = 9.
    *   This matches the input count.
    *   The structure is a triangle centered at the column where the input pixels were.
    *   The input pixels were all the same color (`O`).
    *   The "highest dancer stands alone on top" -> The top row of the triangle has 1 pixel.
    *   "Each tier below adds partners on both sides" -> The next rows have 3, 5, etc.
    *   Since all input pixels were `O`, the color is uniform.

**Example 2:**
*   **Input:** 16x11 grid.
    *   Column 5 (0-indexed, 6th column) has Orange (`O`) pixels.
    *   Positions: (0,5), (3,5), (6,5), (9,5).
    *   Total `O` pixels: 4.
*   **Output:** 16x11 grid.
    *   Triangle at the bottom.
    *   Row 14 (index 14): 1 `O` at col 5.
    *   Row 15 (index 15): 3 `O`s at cols 4, 5, 6.
    *   Total `O` pixels: 1 + 3 = 4.
    *   Matches input count.
    *   Again, uniform color.

**Example 3:**
*   **Input:** 21x9 grid.
    *   Column 4 (0-indexed, 5th column).
    *   Pixels:
        *   Row 0: `Y`
        *   Row 1: `O`
        *   Row 2: `O`
        *   Row 3: `O`
        *   Row 5: `M`
        *   Row 7: `M`
        *   Row 10: `M`
        *   Row 12: `M`
        *   Row 14: `M`
    *   Total pixels: 1 `Y`, 3 `O`, 5 `M`. Total = 9 pixels.
*   **Output:** 21x9 grid.
    *   Triangle at the bottom.
    *   Row 18 (index 18): 1 pixel `Y` at col 4.
    *   Row 19 (index 19): 3 pixels `O` at cols 3, 4, 5.
    *   Row 20 (index 20): 5 pixels `M` at cols 2, 3, 4, 5, 6.
    *   Total pixels: 1 + 3 + 5 = 9.
    *   Matches input count.
    *   **Crucial Observation:** The colors in the output rows correspond to the groups of colors in the input, ordered from top to bottom.
        *   Input top pixel: `Y`. Output top row: `Y`.
        *   Input next 3 pixels: `O`, `O`, `O`. Output next row: `O`, `O`, `O`.
        *   Input next 5 pixels: `M`, `M`, `M`, `M`, `M`. Output next row: `M`, `M`, `M`, `M`, `M`.
    *   Wait, the input had `Y` at row 0. Then `O` at rows 1, 2, 3. Then `M` at rows 5, 7, 10, 12, 14.
    *   The input pixels are grouped by color? Or just by order?
    *   In Example 3, the input colors are `Y` (1), `O` (3), `M` (5).
    *   The output rows have sizes 1, 3, 5.
    *   The colors match the sequence of colors found in the inpu

... [6862 chars truncated]
alt-15 geology qwen3.5-122b: fail
"Mineral veins exposed along a vertical fault line erode free and deposit into a delta fan at the basin floor."
Fail (best cell_acc=0.93 at k=2)
Best Attempt
vs
Expected
Reasoning (12367 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A dark rock face with colored mineral bands exposed at irregular depths along a single fault, an empty basin below."
*   **Action:** "Erosion frees the minerals and they wash downward, settling into a delta—the first mineral forms a narrow point, each stratum below fans wider, their colors matching the original vein order from shallowest to deepest, the widest deposit resting on the basin floor."
*   **Grid details:** "The cross-section keeps its dimensions. The fault line is blank; only the delta fan remains at the very bottom, centered on the fault."

**Interpretation:**
*   **Input:** A grid containing colored pixels (minerals) scattered vertically along a specific column (the "fault line"). There are empty spaces (black '.') elsewhere.
*   **Output:** The colored pixels disappear from their original positions. They reappear at the bottom of the grid, forming a triangular or fan shape ("delta").
*   **Structure of the Delta:**
    *   It sits at the bottom of the grid.
    *   It is centered on the column where the minerals were found (the "fault").
    *   The colors are ordered from top to bottom based on their original vertical order (shallowest to deepest).
    *   The shape fans out: The top layer of the delta is narrow (1 pixel wide), the next is wider (3 pixels?), the next wider (5 pixels?), etc. Or maybe it's just a pyramid shape.
    *   Let's look at the examples to determine the exact shape and width progression.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** 17 rows, 13 columns.
    *   Colored pixels are all 'O' (orange).
    *   They are located in column index 6 (0-indexed, 7th column).
    *   Rows with 'O': 1, 2, 4, 5, 6, 8, 10, 11, 12. (Total 9 'O's).
    *   Wait, let's count carefully.
    *   Row 1: O
    *   Row 2: O
    *   Row 4: O
    *   Row 5: O
    *   Row 6: O
    *   Row 8: O
    *   Row 10: O
    *   Row 11: O
    *   Row 12: O
    *   Total count = 9 pixels.
*   **Output:**
    *   The 'O's are gone from the top.
    *   They appear at the bottom.
    *   Row 13 (index 13): One 'O' at col 6.
    *   Row 14 (index 14): Three 'O's at cols 5, 6, 7.
    *   Row 15 (index 15): Five 'O's at cols 4, 5, 6, 7, 8.
    *   Total pixels in output = 1 + 3 + 5 = 9.
    *   This matches the input count.
    *   Shape: A triangle/pyramid.
    *   Top of delta: 1 pixel.
    *   Middle of delta: 3 pixels.
    *   Bottom of delta: 5 pixels.
    *   The colors are all the same ('O'), so the "order" doesn't matter visually, but the metaphor says "colors matching the original vein order". Since they are all the same, it's consistent.
    *   The "fault line" is column 6. The delta is centered on column 6.

**Example 2:**
*   **Input:** 16 rows, 11 columns.
    *   Colored pixels are all 'O' (orange).
    *   Column index 5 (6th column).
    *   Rows with 'O': 0, 3, 6, 9.
    *   Total count = 4 pixels.
*   **Output:**
    *   Row 14 (index 14): One 'O' at col 5.
    *   Row 15 (index 15): Three 'O's at cols 4, 5, 6.
    *   Total pixels = 1 + 3 = 4.
    *   Matches input count.
    *   Shape: 1 pixel on top row of delta, 3 pixels on bottom row of delta.
    *   Centered on col 5.

**Transformation Rule Deduction:**
1.  **Identify the Fault Line:** Find the column index that contains the colored pixels. In both examples, all colored pixels are in the same column.
2.  **Count the Minerals:** Count the total number of colored pixels in the input grid. Let this be $N$.
3.  **Construct the Delta:**
    *   The delta is built at the bottom of the grid.
    *   It consists of rows filled with colored pixels.
    *   The width of the rows increases by 2 for each row going down (1, 3, 5, 7...).
    *   The colors in the delta rows correspond to the colors of the minerals found in the input, ordered from top to bottom (shallowest to deepest).
    *   Wait, in Example 1 and 2, all minerals were the same color ('O'). I need to check the Test Input to see if there are different colors.
    *   The metaphor says: "each stratum below fans wider, their colors matching the original vein order from shallowest to deepest".
    *   This implies that if there are different colors, they should be arranged in the delta rows corresponding to their original vertical order.
    *   However, the delta structure is defined by width (1, 3, 5...). Does a "stratum" correspond to a single row of the delta?
    *   In Example 1 (9 pixels): 1 + 3 + 5 = 9. This fits perfectly into 3 rows.
    *   In Example 2 (4 pixels): 1 + 3 = 4. This fits perfectly into 2 rows.
    *   So, the number of rows in the delta is determined by how many odd numbers sum up to $N$.
    *   Let $k$ be the number of rows in the delta. The total pixels $N = \sum_{i=1}^{k} (2i - 1) = k^2$.
    *   This implies $N$ must be a perfect square for this speci

... [7388 chars truncated]
alt-2 cooking qwen3.5-122b: fail
"Ingredients measured out along a skewer slide off and melt into a layered parfait at the bottom of the glass."
Fail (best cell_acc=0.43 at k=1)
Best Attempt
vs
Expected
Reasoning (12620 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A tall, narrow glass with spoonfuls of colored batter clinging to a central skewer at various heights, empty glass below."
    *   This suggests colored pixels (batter) are arranged vertically along a specific column (skewer).
    *   There is empty space below them.
*   **Transformation:** "The batter releases from the skewer, pools at the bottom, and sets into a parfait—each layer wider than the one above, colors stacking in the order they were threaded, the topmost dollop becoming the smallest cap of the dessert."
    *   "Releases from the skewer": The vertical line of pixels disappears.
    *   "Pools at the bottom": The pixels move to the bottom of the grid.
    *   "Sets into a parfait": They form a pyramid or triangle shape.
    *   "Each layer wider than the one above": This implies a pyramid structure.
    *   "Colors stacking in the order they were threaded": The order of colors from top to bottom in the input determines the order of layers from top to bottom in the output pyramid.
    *   "Topmost dollop becoming the smallest cap": The top color in the input becomes the top row of the pyramid (width 1). The next color becomes the next row (width 3?), etc.
    *   "The glass keeps its shape": The grid dimensions remain the same.
    *   "The skewer is bare; only the parfait remains": The original column is cleared.
    *   "Centered and resting on the bottom": The pyramid is centered horizontally and sits on the last row.

**2. Analyze the Training Example:**
*   **Input:** 15 rows x 13 columns.
    *   There is a column of 'O' (orange) pixels.
    *   Let's check the positions of 'O'.
    *   Row 1 (index 0): Empty
    *   Row 2 (index 1): Col 6 (0-indexed) is 'O'.
    *   Row 3 (index 2): Col 6 is 'O'.
    *   Row 4 (index 3): Empty
    *   Row 5 (index 4): Col 6 is 'O'.
    *   Row 6 (index 5): Col 6 is 'O'.
    *   Row 7 (index 6): Col 6 is 'O'.
    *   Row 8 (index 7): Empty
    *   Row 9 (index 8): Col 6 is 'O'.
    *   Row 10 (index 9): Empty
    *   Row 11 (index 10): Col 6 is 'O'.
    *   Row 12 (index 11): Col 6 is 'O'.
    *   Row 13 (index 12): Col 6 is 'O'.
    *   Row 14 (index 13): Empty
    *   Row 15 (index 14): Empty
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Input Grid:
        ```
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        ```
        Wait, counting rows.
        1. `.`
        2. `O`
        3. `O`
        4. `.`
        5. `O`
        6. `O`
        7. `O`
        8. `.`
        9. `O`
        10. `.`
        11. `O`
        12. `O`
        13. `O`
        14. `.`
        15. `.`
        16. `.`
        Total 16 rows? Let's count carefully.
        Line 1: `.`
        Line 2: `O`
        Line 3: `O`
        Line 4: `.`
        Line 5: `O`
        Line 6: `O`
        Line 7: `O`
        Line 8: `.`
        Line 9: `O`
        Line 10: `.`
        Line 11: `O`
        Line 12: `O`
        Line 13: `O`
        Line 14: `.`
        Line 15: `.`
        Line 16: `.`
        Okay, 16 rows.
        Columns: 13 columns.
        The 'O's are in column index 6 (7th column).
        The 'O's appear at rows: 1, 2, 4, 5, 6, 8, 10, 11, 12 (0-indexed).
        Wait, looking at the output.
        Output Grid:
        Rows 0-12 are empty.
        Row 13: `.` `.` `.` `.` `.` `O` `.` `.` `.` `.` `.` `.` `.` (One 'O' at center)
        Row 14: `.` `.` `.` `.` `O` `O` `O` `.` `.` `.` `.` `.` `.` (Three 'O's)
        Row 15: `.` `.` `.` `O` `O` `O` `O` `O` `.` `.` `.` `.` `.` (Five 'O's)
        
        Wait, the output shows a pyramid of 'O's.
        Row 13: 1 'O'
        Row 14: 3 'O's
        Row 15: 5 'O's
        Total 'O's in output = 1 + 3 + 5 = 9.
        Total 'O's in input = 9.
        So the transformation preserves the count of colored pixels.
        The shape is a pyramid centered at the bottom.
        The width increases by 2 each row going up? No, going down.
        Top row of pyramid (Row 13): Width 1.
        Middle row of pyramid (Row 14): Width 3.
        Bottom row of pyramid (Row 15): Width 5.
        This is a standard pyramid structure.
        
        Wait, the metaphor says "colors stacking in the order they were threaded".
        In Example 1, all pixels are 'O'. So color order doesn't matter.
        However, the metaphor implies distinct colors

... [7635 chars truncated]
alt-3 music qwen3.5-122b: fail
"Staccato notes hung high on a staff collapse into a resonant chord that swells at the finale."
Fail (best cell_acc=0.43 at k=1)
Best Attempt
vs
Expected
Reasoning (11985 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A silent score with isolated notes pinned along a vertical staff line, rests between them, and empty measures trailing below."
    *   This suggests there are colored pixels (notes) arranged vertically in a specific column (staff line).
    *   There are empty spaces (rests) between them.
    *   There is empty space below them.
*   **What to do:** "The notes release from their suspended positions and cascade to the closing bars, each successive bar gaining more voices, building from a single tone at top to a full harmonic spread at the bottom—preserving the original timbral ordering."
    *   "Cascade to the closing bars": The notes move downwards to the bottom of the grid.
    *   "Each successive bar gaining more voices": This implies a stacking or accumulation effect.
    *   "Building from a single tone at top to a full harmonic spread at the bottom": This sounds like a triangle or pyramid shape forming at the bottom.
    *   "Preserving the original timbral ordering": The colors of the notes should appear in the same order they appeared in the input column, from top to bottom.
*   **Grid details:** "The score's length is unchanged. All prior note positions become rests; the crescendo chord occupies the final measures, centered on the original staff line."
    *   Input grid size = Output grid size.
    *   Original positions of notes become empty (black/dots).
    *   The new structure (the "crescendo chord") is at the bottom.
    *   It is centered on the original staff line (the column where the notes were).

**2. Analyze the Training Example:**
*   **Input:**
    *   Grid size: 16 rows x 13 columns.
    *   Column of interest: Column 6 (0-indexed) or 7th column. Let's count.
    *   Row 1: `.`
    *   Row 2: `O` at index 6.
    *   Row 3: `O` at index 6.
    *   Row 4: `.`
    *   Row 5: `O` at index 6.
    *   Row 6: `O` at index 6.
    *   Row 7: `O` at index 6.
    *   Row 8: `.`
    *   Row 9: `O` at index 6.
    *   Row 10: `.`
    *   Row 11: `O` at index 6.
    *   Row 12: `O` at index 6.
    *   Row 13: `O` at index 6.
    *   Row 14-16: `.`
    *   Total 'O' notes: 2 + 3 + 1 + 3 = 9 notes.
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Input:
        ```
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . O . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        ```
    *   There are 9 'O's in column 6 (0-indexed).
    *   Rows with 'O': 1, 2, 4, 5, 6, 8, 10, 11, 12. (0-indexed: 1, 2, 4, 5, 6, 8, 10, 11, 12).
    *   Wait, counting rows in the example text:
        Row 0: .
        Row 1: O
        Row 2: O
        Row 3: .
        Row 4: O
        Row 5: O
        Row 6: O
        Row 7: .
        Row 8: O
        Row 9: .
        Row 10: O
        Row 11: O
        Row 12: O
        Row 13: .
        Row 14: .
        Row 15: .
    *   Total 'O's = 9.
*   **Output:**
    *   Rows 0-12 are all `.`.
    *   Row 13: `.` `.` `.` `.` `.` `.` `O` `.` `.` `.` `.` `.` `.` (One 'O' at center)
    *   Row 14: `.` `.` `.` `.` `.` `O` `O` `O` `.` `.` `.` `.` `.` (Three 'O's centered)
    *   Row 15: `.` `.` `.` `.` `O` `O` `O` `O` `O` `.` `.` `.` `.` (Five 'O's centered)
    *   Wait, let's look at the output provided in the prompt.
    *   Output:
        ```
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . O . . . . . .
        . . . . . O O O . . . . .
        . . . . O O O O O . . . .
        ```
    *   The output has 3 rows filled at the bottom.
    *   Row 13: 1 'O'.
    *   Row 14: 3 'O's.
    *   Row 15: 5 'O's.
    *   Total 'O's in output = 1 + 3 + 5 = 9.
    *   This matches the count of 'O's in the input.
    *   The shape is a triangle/pyramid pointing up, centered on the original column.
    *   The "notes" (colors) are preserved. In this example, all notes were 'O', so the output is all 'O'.
    *   The metaphor says "preserving the original timbral ordering". Since all notes are the same color here, we can't verify the orde

... [7003 chars truncated]
alt-4 sports qwen3.5-122b: fail
"Climbers roped at intervals along a cliff face rappel down and form a human pyramid on the ground."
Fail (best cell_acc=0.01 at k=1)
Best Attempt
vs
Expected
Reasoning (10884 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A sheer rock wall with athletes (colored pixels) clipped in at scattered heights along a single vertical route. Open ground below.
*   **Action:** Each climber descends and takes a position in a pyramid at the base of the wall.
*   **Pyramid Structure:**
    *   The highest climber stands alone on top.
    *   Each row below adds shoulders (width increases).
    *   Preserves the jersey colors in the order they were roped (top to bottom).
*   **Grid Details:**
    *   Wall dimensions stay the same.
    *   Every hold (original position of climbers) is now empty (black/dot).
    *   Only the pyramid stands on the bottom ledge, centered beneath the route line.

**2. Analyze the Training Example:**
*   **Input:** A 15x13 grid (15 rows, 13 columns).
    *   There are 'O' (orange) pixels scattered vertically in column 6 (0-indexed).
    *   Let's count the 'O's.
    *   Row 1: O
    *   Row 2: O
    *   Row 4: O
    *   Row 5: O
    *   Row 6: O
    *   Row 8: O
    *   Row 10: O
    *   Row 11: O
    *   Row 12: O
    *   Total 'O's = 9.
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Input rows:
        0: . . . . . . . . . . . . .
        1: . . . . . . O . . . . . .
        2: . . . . . . O . . . . . .
        3: . . . . . . . . . . . . .
        4: . . . . . . O . . . . . .
        5: . . . . . . O . . . . . .
        6: . . . . . . O . . . . . .
        7: . . . . . . . . . . . . .
        8: . . . . . . O . . . . . .
        9: . . . . . . . . . . . . .
        10: . . . . . . O . . . . . .
        11: . . . . . . O . . . . . .
        12: . . . . . . O . . . . . .
        13: . . . . . . . . . . . . .
        14: . . . . . . . . . . . . .
    *   Count of 'O': Rows 1, 2, 4, 5, 6, 8, 10, 11, 12. Total = 9.
*   **Output:**
    *   Rows 0-12 are all empty (.).
    *   Row 13: . . . . . O . . . . . . (1 'O', centered?)
    *   Row 14: . . . . O O O . . . . . (3 'O's)
    *   Row 15: . . . O O O O O . . . . (5 'O's)
    *   Wait, the output grid in the example has 16 rows? Let's check the input dimensions again.
    *   Input has 15 lines. Output has 16 lines?
    *   Let's count the lines in the example output provided.
    *   Output lines:
        0: . . . . . . . . . . . . .
        1: . . . . . . . . . . . . .
        2: . . . . . . . . . . . . .
        3: . . . . . . . . . . . . .
        4: . . . . . . . . . . . . .
        5: . . . . . . . . . . . . .
        6: . . . . . . . . . . . . .
        7: . . . . . . . . . . . . .
        8: . . . . . . . . . . . . .
        9: . . . . . . . . . . . . .
        10: . . . . . . . . . . . . .
        11: . . . . . . . . . . . . .
        12: . . . . . . . . . . . . .
        13: . . . . . O . . . . . . .
        14: . . . . O O O . . . . . .
        15: . . . O O O O O . . . . .
    *   The output grid seems to have 16 rows, while input had 15. Or maybe I miscounted the input.
    *   Input lines:
        1. . . . . . . . . . . . . .
        2. . . . . . . O . . . . . .
        3. . . . . . . O . . . . . .
        4. . . . . . . . . . . . . .
        5. . . . . . . O . . . . . .
        6. . . . . . . O . . . . . .
        7. . . . . . . O . . . . . .
        8. . . . . . . . . . . . . .
        9. . . . . . . O . . . . . .
        10. . . . . . . . . . . . . .
        11. . . . . . . O . . . . . .
        12. . . . . . . O . . . . . .
        13. . . . . . . O . . . . . .
        14. . . . . . . . . . . . . .
        15. . . . . . . . . . . . . .
    *   That is 15 rows.
    *   Output lines:
        1. . . . . . . . . . . . . .
        ...
        13. . . . . . . . . . . . . .
        14. . . . . . O . . . . . . .
        15. . . . . O O O . . . . . .
        16. . . . O O O O O . . . . .
    *   That is 16 rows.
    *   Wait, usually grid puzzles maintain dimensions. Let me re-read the prompt's example output carefully.
    *   Example 1 Output:
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . . . . . . . . .
        . . . . . O . . . . . . .
        . . . . O O O . . . . . .
        . . . O O O O O . . . . .
    *   Counting lines in the text block:
        1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16.
    *   Input had 15 lines. Output has 16 lines. This is strange. Usually, dimensions are preserved.
    *   Let's check the Test Input dimensions.
    *   Test Input:
        1. . . R . . . . . O .
        2. . . R . . . . . . .
        3. . . . . . . . . . .
        4. .

... [5893 chars truncated]
alt-5 weather qwen3.5-122b: fail
"Raindrops suspended in a column of air finally fall and accumulate into a snowdrift at the surface."
Fail (best cell_acc=0.01 at k=1)
Best Attempt
vs
Expected
Reasoning (12299 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A dark sky with droplets of color frozen at various altitudes along a single vertical updraft, clear air beneath."
    *   "Dark sky" implies the background is black (`.`).
    *   "Droplets of color" are the non-black pixels.
    *   "Single vertical updraft" implies the droplets are aligned in a specific column.
    *   "Clear air beneath" implies empty space below the droplets initially.
*   **Action:** "The updraft dies and the droplets precipitate, each one layering into a drift that grows wider toward the ground—the highest drops settle on top, the lowest spread the widest, their hues preserved in falling order."
    *   "Updraft dies": The vertical alignment is broken.
    *   "Precipitate": They fall to the bottom.
    *   "Layering into a drift": They stack up at the bottom.
    *   "Grows wider toward the ground": The shape at the bottom is a triangle or pyramid.
    *   "Highest drops settle on top": The order of colors from top to bottom in the output corresponds to the order of droplets from top to bottom in the input.
    *   "Lowest spread the widest": The bottom-most row of the drift is the widest.
    *   "Hues preserved in falling order": The color of the droplet determines the color of the layer.
*   **Grid details:** "The sky remains the same size. All former droplet positions clear to darkness; the drift sits at the very bottom, centered under the updraft column."
    *   Input grid size = Output grid size.
    *   Input droplet positions become `.` (black).
    *   The new structure (drift) is at the bottom rows.
    *   The drift is centered horizontally.

**2. Analyze the Training Example:**
*   **Input:** 17 rows, 13 columns.
    *   Droplets are all Orange (`O`).
    *   They are located in column index 6 (0-indexed, 7th column).
    *   Let's count the droplets.
        *   Row 1: `O` at col 6
        *   Row 2: `O` at col 6
        *   Row 4: `O` at col 6
        *   Row 5: `O` at col 6
        *   Row 6: `O` at col 6
        *   Row 8: `O` at col 6
        *   Row 10: `O` at col 6
        *   Row 11: `O` at col 6
        *   Row 12: `O` at col 6
    *   Total droplets = 9.
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Row 0: `.`
    *   Row 1: `O` (col 6)
    *   Row 2: `O` (col 6)
    *   Row 3: `.`
    *   Row 4: `O` (col 6)
    *   Row 5: `O` (col 6)
    *   Row 6: `O` (col 6)
    *   Row 7: `.`
    *   Row 8: `O` (col 6)
    *   Row 9: `.`
    *   Row 10: `O` (col 6)
    *   Row 11: `O` (col 6)
    *   Row 12: `O` (col 6)
    *   Row 13-16: `.`
    *   Total `O`s = 2 + 3 + 1 + 3 = 9.
*   **Output:**
    *   Rows 0-12 are all `.`.
    *   Row 13: `O` at col 6 (1 pixel wide).
    *   Row 14: `O O O` centered at col 6 (3 pixels wide).
    *   Row 15: `O O O O O` centered at col 6 (5 pixels wide).
    *   Wait, the output shows:
        *   Row 13: `.` `.` `.` `.` `.` `.` `O` `.` `.` `.` `.` `.` `.` (1 pixel)
        *   Row 14: `.` `.` `.` `.` `.` `O` `O` `O` `.` `.` `.` `.` `.` (3 pixels)
        *   Row 15: `.` `.` `.` `.` `O` `O` `O` `O` `O` `.` `.` `.` `.` (5 pixels)
    *   Total pixels in output = 1 + 3 + 5 = 9.
    *   This matches the count of input droplets.
    *   The structure is a triangle pointing up (pyramid base at bottom).
    *   The width increases by 2 each row going down (1, 3, 5).
    *   The colors are all `O`, so we can't verify color ordering from this example alone, but the description says "highest drops settle on top". Since all are `O`, this is consistent.
    *   The "drift sits at the very bottom". In a 17-row grid, the last 3 rows are used.
    *   The "updraft column" was column 6. The drift is centered on column 6.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Background:** Black (`.`).
    *   **Droplets:** Colored pixels (`R`, `B`, `O`, etc.) located in a specific vertical column.
    *   **Drift:** The resulting structure at the bottom of the grid.
*   **AFFORDANCES:**
    *   Droplets can be counted.
    *   Droplets have a vertical position (row index).
    *   Droplets have a color.
    *   The grid has a fixed width and height.
    *   The drift occupies the bottom rows.
*   **TRANSFORMATION RULE:**
    1.  **Identify Droplets:** Find all non-black pixels in the input grid. Note their column index (should be the same for all) and their row index.
    2.  **Count:** Let $N$ be the total number of droplets.
    3.  **Determine Shape:** The output forms a pyramid/triangle at the bottom of the grid. The rows of the pyramid have widths $1, 3, 5, \dots$ starting from the top of the pyramid.
    4.  **Determine Height:** Find the smallest integer $H$ such that $\sum_{i=1}^{H} (2i - 1) \ge N$. Actually, looking at the example, $1+3+5 = 9$. If $N=9$, height is 3. If $N$ was 10, would it be 1, 3, 5, 1? Or 1, 3, 5, 6?
      

... [7371 chars truncated]
alt-6 architecture qwen3.5-122b: fig alone solves
"Bricks stored on different scaffold platforms are lowered and mortared into a ziggurat at street level."
alt-7 warfare qwen3.5-122b: fail
"Scouts posted at watchtowers along a frontier withdraw and form ranked battle lines at the border's edge."
Fail (best cell_acc=0.00 at k=1)
No grid
vs
Expected
Reasoning (12933 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A dark frontier with sentinels stationed at irregular intervals along a single lookout column, open marshaling ground below."
    *   "Dark frontier": Likely the background color (black `.`).
    *   "Sentinels": Colored pixels (non-black).
    *   "Single lookout column": The sentinels are aligned vertically in one specific column.
    *   "Irregular intervals": They are not necessarily contiguous.
    *   "Open marshaling ground below": The space below the sentinels is empty.
*   **What to do:** "The sentinels abandon their posts and assemble into formation at the border—the highest-ranked officer stands alone at the front, each successive rank wider, their banner colors matching the order of their original postings from top to bottom."
    *   "Abandon their posts": The original positions become empty (`.`).
    *   "Assemble into formation at the border": The new formation is at the bottom of the grid ("border").
    *   "Highest-ranked officer stands alone at the front": The top row of the formation has 1 pixel.
    *   "Each successive rank wider": The rows below have more pixels (pyramid/triangle shape).
    *   "Banner colors matching the order of their original postings from top to bottom": The colors of the pixels in the formation correspond to the colors of the sentinels in the input column, ordered from top to bottom.
*   **Grid details:** "The frontier map keeps its dimensions. All towers go dark; the formation sits at the very bottom, centered on the lookout column."
    *   Dimensions remain the same.
    *   Original sentinel positions become black (`.`).
    *   Formation is at the bottom.
    *   Formation is centered on the column where the sentinels were.

**2. Analyze the Training Example:**
*   **Input:**
    *   Grid size: 16 rows x 13 columns.
    *   Column index of sentinels: Let's count. 0-indexed.
        *   Row 1: `O` at index 6.
        *   Row 2: `O` at index 6.
        *   Row 4: `O` at index 6.
        *   Row 5: `O` at index 6.
        *   Row 6: `O` at index 6.
        *   Row 8: `O` at index 6.
        *   Row 10: `O` at index 6.
        *   Row 11: `O` at index 6.
        *   Row 12: `O` at index 6.
    *   All sentinels are Orange (`O`).
    *   Total sentinels: 9.
*   **Output:**
    *   Grid size: 16 rows x 13 columns.
    *   Rows 0-12 are all black (`.`).
    *   Row 13: `O` at index 6. (1 pixel)
    *   Row 14: `O O O` centered at index 6. (3 pixels: indices 5, 6, 7)
    *   Row 15: `O O O O O` centered at index 6. (5 pixels: indices 4, 5, 6, 7, 8)
    *   Wait, let's look closer at the output structure.
    *   Row 13: `.` `.` `.` `.` `.` `.` `O` `.` `.` `.` `.` `.` `.` (Index 6)
    *   Row 14: `.` `.` `.` `.` `.` `O` `O` `O` `.` `.` `.` `.` `.` (Indices 5, 6, 7)
    *   Row 15: `.` `.` `.` `.` `O` `O` `O` `O` `O` `.` `.` `.` `.` (Indices 4, 5, 6, 7, 8)
    *   Total pixels in output formation: 1 + 3 + 5 = 9 pixels.
    *   This matches the count of sentinels in the input (9).
    *   The shape is a triangle/pyramid.
    *   Row 1 (top of formation): 1 pixel.
    *   Row 2: 3 pixels.
    *   Row 3: 5 pixels.
    *   It seems the formation fills rows from the bottom up.
    *   The colors are all `O` because all input sentinels were `O`.
    *   The column is centered at index 6.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Sentinels:** Colored pixels in a specific vertical column.
    *   **Background:** Black pixels (`.`).
    *   **Formation:** A pyramid of colored pixels at the bottom of the grid.
*   **AFFORDANCES:**
    *   Sentinels can be counted.
    *   Sentinels have a specific color.
    *   Sentinels have a vertical order (top to bottom).
    *   The grid has a fixed width and height.
    *   The formation can be constructed row by row from the bottom.
*   **TRANSFORMATION RULE:**
    1.  **Identify the Sentinel Column:** Find the column index `C` that contains the non-black pixels.
    2.  **Extract Sentinels:** List the colors of the non-black pixels in that column, ordered from top row to bottom row. Let this list be `L`. Let `N` be the length of `L`.
    3.  **Clear Grid:** Set all pixels in the grid to black (`.`).
    4.  **Construct Formation:**
        *   The formation is a pyramid centered at column `C`.
        *   It starts at the bottom row (Row `H-1`) and goes upwards.
        *   The rows of the formation have widths 1, 3, 5, 7, ... (odd numbers).
        *   We need to fill `N` pixels total.
        *   Fill the bottom-most row of the formation with 1 pixel (color `L[0]`).
        *   Fill the next row up with 3 pixels (colors `L[1]`, `L[2]`, `L[3]`).
        *   Fill the next row up with 5 pixels (colors `L[4]`...`L[8]`).
        *   Continue until all `N` pixels from `L` are used.
        *   Wait, let's re-read the metaphor: "highest-r

... [7978 chars truncated]
alt-8 theater qwen3.5-122b: fail
"Spotlights hung at different heights on a fly tower descend and fan into a footlight array at the stage floor."
Fail (best cell_acc=0.01 at k=1)
Best Attempt
vs
Expected
Reasoning (12066 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A dark proscenium with colored lanterns rigged at various battens along one fly line, empty stage below."
    *   "Dark proscenium" -> The background is black (`.`).
    *   "Colored lanterns rigged at various battens along one fly line" -> There are colored pixels scattered in the upper part of the grid, seemingly aligned vertically or in columns.
    *   "Empty stage below" -> The bottom part of the grid is empty (`.`).
*   **Action:** "The lanterns are flown down and re-hung as footlights—the top lantern becomes a single point, each row below it spreading wider, their gel colors kept in the original rigging order, all mounted flush against the stage floor."
    *   "Flown down" -> The colored pixels move to the bottom of the grid.
    *   "Re-hung as footlights" -> They form a shape at the bottom.
    *   "Top lantern becomes a single point" -> The first row of the new shape has 1 pixel.
    *   "Each row below it spreading wider" -> The shape expands outwards (like a pyramid or triangle).
    *   "Gel colors kept in the original rigging order" -> The sequence of colors matters.
    *   "Mounted flush against the stage floor" -> The shape sits at the very bottom row(s).
*   **Grid details:** "The proscenium dimensions are unchanged. The fly line goes dark; only the footlight fan remains at the bottom, centered under the original line."
    *   Dimensions stay the same.
    *   Original positions become empty (`.`).
    *   New shape is at the bottom.
    *   "Centered under the original line" -> This suggests the horizontal position of the new shape depends on where the original "fly line" was.

**2. Analyze the Training Example:**
*   **Input:** 17 rows, 13 columns.
    *   There is a vertical column of `O` (orange) pixels.
    *   Let's check the column index.
    *   Row 1: `.`
    *   Row 2: `O` at index 6 (0-indexed).
    *   Row 3: `O` at index 6.
    *   Row 4: `.`
    *   Row 5: `O` at index 6.
    *   Row 6: `O` at index 6.
    *   Row 7: `O` at index 6.
    *   Row 8: `.`
    *   Row 9: `O` at index 6.
    *   Row 10: `.`
    *   Row 11: `O` at index 6.
    *   Row 12: `O` at index 6.
    *   Row 13: `O` at index 6.
    *   Row 14-17: `.`
    *   Total `O` pixels: 2 + 3 + 1 + 3 = 9 pixels.
    *   Wait, let's count carefully.
    *   Rows with `O`: 2, 3, 5, 6, 7, 9, 11, 12, 13.
    *   Count: 1, 2, 3, 4, 5, 6, 7, 8, 9. Total 9 orange pixels.
    *   They are all in column 6 (7th column).
*   **Output:** 17 rows, 13 columns.
    *   Rows 1-13 are all `.`.
    *   Row 14: `.` `.` `.` `.` `.` `O` `.` `.` `.` `.` `.` `.` `.` (1 `O` at index 6).
    *   Row 15: `.` `.` `.` `.` `O` `O` `O` `.` `.` `.` `.` `.` `.` (3 `O`s centered at index 6).
    *   Row 16: `.` `.` `.` `O` `O` `O` `O` `O` `.` `.` `.` `.` `.` (5 `O`s centered at index 6).
    *   Total `O` pixels in output: 1 + 3 + 5 = 9.
    *   The count matches the input count.
    *   The shape is a triangle/pyramid pointing up, sitting at the bottom.
    *   The center column is preserved (index 6).
    *   The colors are preserved (all `O`).
    *   The "original rigging order" implies the sequence of colors from top to bottom in the input determines the sequence of colors in the output shape. Since all are `O`, this is trivial here.
    *   The shape fills from the bottom up.
    *   Row 16 (bottom-1): 5 pixels.
    *   Row 15 (bottom-2): 3 pixels.
    *   Row 14 (bottom-3): 1 pixel.
    *   Wait, the output shows the shape at rows 14, 15, 16. The grid has 17 rows (0-16). So it's at the very bottom.
    *   Row 16 is the last row.
    *   Row 15 is second to last.
    *   Row 14 is third to last.
    *   So the pyramid sits on the bottom edge.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Background:** Black (`.`).
    *   **Lanterns:** Colored pixels (`R`, `B`, `O`, etc.) scattered in the upper/middle part of the grid.
    *   **Fly Line:** The vertical alignment of the lanterns. In the example, they were all in one column. In the test input, they might be in multiple columns or a specific pattern.
    *   **Stage Floor:** The bottom rows of the grid.

*   **AFFORDANCES:**
    *   Lanterns can be counted.
    *   Lanterns have colors.
    *   Lanterns have vertical positions (rows).
    *   Lanterns have horizontal positions (columns).
    *   The "fan" shape can be constructed using the count of lanterns.

*   **TRANSFORMATION RULE:**
    1.  **Identify Lanterns:** Find all non-black pixels in the input grid.
    2.  **Count Lanterns:** Let $N$ be the total number of colored pixels.
    3.  **Determine Center:** Find the "center" of the original rigging. In the example, all lanterns were in column 6. The output pyramid is centered at column 6. In the test input, I need to determine the center column. It's likely the average

... [7111 chars truncated]
alt-9 gardening qwen3.5-122b: fail
"Buds clinging to a bare stem drop their petals, which settle into a mulch mound at the soil line."
Fail (best cell_acc=0.01 at k=1)
Best Attempt
vs
Expected
Reasoning (11518 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A dark garden bed with colored buds dotting a single upright stem at uneven intervals, bare earth below."
    *   "Dark garden bed" likely refers to the background color (black `.`).
    *   "Colored buds" are the non-black pixels in the input.
    *   "Single upright stem" implies the buds are aligned vertically in a column.
    *   "Uneven intervals" means there are gaps between the buds.
    *   "Bare earth below" implies empty space at the bottom.
*   **Action:** "Each bud sheds its color downward; the petals gather at the soil into a neat mound—one petal at the peak, each layer below wider, hues layered in the order the buds appeared from tip to root."
    *   "Sheds its color downward": The colored pixels move down.
    *   "Gather at the soil into a neat mound": They form a pyramid or triangle shape at the bottom.
    *   "One petal at the peak": The top of the mound is 1 pixel wide.
    *   "Each layer below wider": The width increases by 2 pixels per layer (1, 3, 5, 7...) or just increases (1, 2, 3...). Let's check the examples.
    *   "Hues layered in the order the buds appeared from tip to root": The colors in the mound correspond to the colors of the buds in the input, ordered from top to bottom. The topmost bud becomes the top of the mound? Or the bottommost bud becomes the bottom of the mound? "Order the buds appeared from tip to root" usually means top to bottom. So the first color encountered (top) goes to the top of the mound? Or does the "shedding downward" imply the top bud falls to the bottom?
    *   Let's re-read carefully: "hues layered in the order the buds appeared from tip to root".
    *   "Tip to root" = Top to Bottom.
    *   "Mound... one petal at the peak".
    *   Usually, if things fall down, the top one lands on top of the pile? Or does the pile build up from the bottom?
    *   Let's look at the Training Example 1 to clarify the structure and color ordering.

**2. Analyze Training Example 1:**
*   **Input:**
    *   Grid size: 16 rows x 13 columns.
    *   Column index of colored pixels: Column 6 (0-indexed). Let's count.
    *   Row 1: `.`
    *   Row 2: `O` at index 6.
    *   Row 3: `O` at index 6.
    *   Row 4: `.`
    *   Row 5: `O` at index 6.
    *   Row 6: `O` at index 6.
    *   Row 7: `O` at index 6.
    *   Row 8: `.`
    *   Row 9: `O` at index 6.
    *   Row 10: `.`
    *   Row 11: `O` at index 6.
    *   Row 12: `O` at index 6.
    *   Row 13: `O` at index 6.
    *   Rows 14-16: `.`
    *   Total colored pixels (buds): 2 + 3 + 1 + 3 = 9 pixels. All are Orange (`O`).
    *   Stem column: 6.
*   **Output:**
    *   Grid size: 16 rows x 13 columns.
    *   Colored pixels form a triangle at the bottom.
    *   Row 13: `O` at index 6. (1 pixel)
    *   Row 14: `O O O` at indices 5, 6, 7. (3 pixels)
    *   Row 15: `O O O O O` at indices 4, 5, 6, 7, 8. (5 pixels)
    *   Total pixels in output mound: 1 + 3 + 5 = 9 pixels.
    *   This matches the count of input pixels.
    *   Shape: A pyramid/triangle centered on the stem column.
    *   Width progression: 1, 3, 5. This is an odd-number progression centered on the stem.
    *   Color: All `O`. Since all input were `O`, color ordering is hard to verify here.
    *   Position: The mound sits on the bottom row (Row 15 is the last row with data, Row 16 is empty? Wait, let's check row indices).
    *   Input has 16 rows. Output has 16 rows.
    *   Output Row 13 (index 12): `O` at col 6.
    *   Output Row 14 (index 13): `O O O` at cols 5,6,7.
    *   Output Row 15 (index 14): `O O O O O` at cols 4,5,6,7,8.
    *   Output Row 16 (index 15): All `.`.
    *   Wait, the example output shows:
        Row 13: `. . . . . . . . . . . . .` (Wait, looking at the provided text)
        Let's count lines in Example 1 Output.
        1. . . . . . . . . . . . . .
        2. . . . . . . . . . . . . .
        3. . . . . . . . . . . . . .
        4. . . . . . . . . . . . . .
        5. . . . . . . . . . . . . .
        6. . . . . . . . . . . . . .
        7. . . . . . . . . . . . . .
        8. . . . . . . . . . . . . .
        9. . . . . . . . . . . . . .
        10. . . . . . . . . . . . . .
        11. . . . . . . . . . . . . .
        12. . . . . . . . . . . . . .
        13. . . . . . . . . . . . . .
        14. . . . . . O . . . . . . .  (Row 14)
        15. . . . . O O O . . . . . .  (Row 15)
        16. . . . O O O O O . . . . .  (Row 16)
    *   Okay, counting the lines in the provided text block for Example 1 Output:
        There are 16 lines.
        The last 3 lines contain the `O`s.
        Line 14: 1 `O` at center.
        Line 15: 3 `O`s centered.
        Line 16: 5 `O`s centered.
    *   So the mound sits on the very bottom row.
    *   The structure is a pyramid of height $h$ where $1 + 3 + 5 + ... + (2h-1) = N$ (total count).
    *   

... [6563 chars truncated]

Task 227: 3ee1011a

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original Russian nesting dolls carved from colored sticks MARC valid 1
alt-1 biology Cell membranes forming around organelles by size MARC valid 1
alt-10 astronomy Planetary rings sorted by the arc length of each debris field fail
alt-11 ocean/sailing Colored current bands pulled into a whirlpool by their reach MARC valid 1
alt-12 electronics Colored wire traces sheathed into a cable by gauge length MARC valid 2
alt-13 mythology Colored serpents coil around each other by their body length fail
alt-14 dance Colored ribbon dancers forming concentric squares by ribbon length fail
alt-15 geology Colored mineral veins compressed into strata by their extent fig alone solves
alt-2 cooking Layered sushi built from ingredient strips fail
alt-3 music Notes ranked by duration composing a resonance mandala fig alone solves
alt-4 sports Relay batons stacked into a champion's trophy by distance run fail
alt-5 weather Storm fronts coalescing into a hurricane eye by reach MARC valid 2
alt-6 architecture Walls built from salvaged beams, longest timber frames the outermost room fig alone solves
alt-7 warfare Defensive perimeters ranked by the length of each regiment's battle line fail
alt-8 theater Curtains drawn inward by the length of each act fail
alt-9 gardening Hedge borders planted by the length of each cutting fail
original qwen3.5-122b: k=1
"Russian nesting dolls carved from colored sticks"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (12117 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Scattered across a vast dark field lie colored sticks of different lengths — each a single pure color, each lying perfectly straight, no two alike."
    *   This implies the input grid contains lines (sticks) of specific colors.
    *   "No two alike" likely means no two sticks have the same length, or perhaps the same color. Let's check the examples.
    *   "Vast dark field" implies the background is black (`.`).
*   **Transformation:** "The longest stick claims authority and bends itself into a square frame — the outermost shell of a nesting doll. The next longest stick, humbled, curls inside that frame to form a smaller shell within. Each remaining stick, from longest to shortest, takes its turn nestling inside the one before it... The tiniest stick... finds itself cradled at the very heart."
    *   This describes a concentric square pattern.
    *   The sticks are transformed into square rings (frames).
    *   The order of nesting is determined by the length of the sticks: Longest -> Outermost, Shortest -> Innermost.
    *   "No darkness remains — every inch is claimed by a shell." This implies the output is a filled square where every cell belongs to one of the nested shells.
*   **Output:** "A perfect square portrait of nested shells, each exactly one layer thick".
    *   The output is a square grid.
    *   The layers are concentric squares.
    *   The thickness of each layer is 1 cell.

**2. Analyze the Training Example:**
*   **Input:**
    *   Grid size: 22 rows x 22 columns (counting dots). Let's verify.
    *   Rows 0-1: Empty.
    *   Row 2: `B` at col 11.
    *   Row 3: `G` at col 4, `B` at col 11.
    *   Row 4: `G` at col 4, `B` at col 11.
    *   Row 5: `G` at col 4, `B` at col 11.
    *   Row 6: `G` at col 4, `B` at col 11.
    *   Row 7: `B` at col 11.
    *   Row 8: `M` at col 8.
    *   Row 9: `M` at col 8.
    *   Rest empty.
    *   Let's identify the "sticks".
        *   Stick 1: Color `B`. Vertical line. Rows 2 to 7. Length = 6 cells.
        *   Stick 2: Color `G`. Vertical line. Rows 3 to 6. Length = 4 cells.
        *   Stick 3: Color `M`. Vertical line. Rows 8 to 9. Length = 2 cells.
    *   Wait, let's look closer at the input grid provided in the prompt text.
    *   Row 2: `... B ...` (index 11)
    *   Row 3: `... G ... B ...` (index 4, 11)
    *   Row 4: `... G ... B ...`
    *   Row 5: `... G ... B ...`
    *   Row 6: `... G ... B ...`
    *   Row 7: `... B ...`
    *   Row 8: `... M ...` (index 8)
    *   Row 9: `... M ...`
    *   So we have:
        *   Blue (`B`): Vertical segment from row 2 to 7. Length = 6.
        *   Green (`G`): Vertical segment from row 3 to 6. Length = 4.
        *   Magenta (`M`): Vertical segment from row 8 to 9. Length = 2.
    *   Are there horizontal sticks? No, they look vertical.
    *   Lengths: B=6, G=4, M=2.
    *   Sorted by length (Longest to Shortest): B (6), G (4), M (2).
*   **Output:**
    *   Grid size: 6x6.
    *   Outer layer: `B`.
    *   Next layer: `G`.
    *   Inner layer: `M`.
    *   Structure:
        *   Row 0: B B B B B B
        *   Row 1: B G G G G B
        *   Row 2: B G M M G B
        *   Row 3: B G M M G B
        *   Row 4: B G G G G B
        *   Row 5: B B B B B B
    *   This confirms the rule:
        1.  Identify distinct colored sticks (lines of contiguous same-colored cells).
        2.  Measure their lengths (number of cells).
        3.  Sort sticks by length descending.
        4.  Create a square grid. The size of the square seems to be determined by the longest stick?
            *   Longest stick length = 6. Output grid size = 6x6.
            *   Wait, is the output size always equal to the length of the longest stick?
            *   Let's check the logic. If the longest stick becomes the outermost frame, the perimeter of a square of size $N \times N$ is $4N - 4$. That doesn't match the length of the stick directly if the stick is just a line.
            *   However, the metaphor says "The longest stick ... bends itself into a square frame".
            *   If a stick of length $L$ bends into a square frame, does it mean the side length is $L$? Or the perimeter is $L$?
            *   In the example: Longest stick length = 6. Output grid size = 6x6.
            *   If the side length is 6, the perimeter is $6+6+4+4 = 20$ cells. The stick only had 6 cells.
            *   So the "stick" isn't physically reshaped cell-for-cell. Instead, the *length* of the stick determines the *dimension* of the square it forms.
            *   Hypothesis: The length of the longest stick determines the side length of the output square grid ($N$).
            *   Let's check the nesting.
            *   Outer shell (Layer 0): Color of longest stick. Size $N \times N$.
            *   Next shell (Layer 1): Color

... [7153 chars truncated]
alt-1 biology qwen3.5-122b: k=1
"Cell membranes forming around organelles by size"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11305 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Scattered protein filaments of different colors float in cytoplasm." This implies there are colored pixels scattered in a black background (represented by `.`).
*   **Transformation:** "The cell organizes itself: the longest filament becomes the outermost cell membrane, wrapping around everything. The next longest forms a membrane just inside, and so on, each enclosing the smaller ones. The tiniest fragment becomes the nucleus at the very center."
*   **Output:** "A square cell whose side length matches the longest filament, filled with concentric membrane layers — no cytoplasm remains, only nested living envelopes."
*   **Key constraints:**
    *   Identify filaments (connected components of the same color).
    *   Measure their length (number of pixels).
    *   Sort them by length (longest to shortest).
    *   Create concentric square layers.
    *   The outermost layer corresponds to the longest filament's color.
    *   The next layer corresponds to the next longest filament's color.
    *   The center corresponds to the shortest filament's color.
    *   The size of the output grid is determined by the length of the longest filament. Specifically, "side length matches the longest filament". This likely means the side length of the square output grid equals the number of pixels in the longest filament.
    *   Each membrane is exactly one layer thick.

**2. Analyze the Training Example:**
*   **Input:** 21x22 grid (approx, let's count).
    *   Row 0-1: All `.`
    *   Row 2: `B` at col 12.
    *   Row 3-7: `G` at col 4, `B` at col 12.
    *   Row 8-9: `M` at col 8.
    *   Rest: `.`
    *   Let's count the pixels for each color.
    *   **Blue (B):**
        *   (2, 12)
        *   (3, 12)
        *   (4, 12)
        *   (5, 12)
        *   (6, 12)
        *   (7, 12)
        *   Total count = 6 pixels.
    *   **Green (G):**
        *   (3, 4)
        *   (4, 4)
        *   (5, 4)
        *   (6, 4)
        *   Total count = 4 pixels.
    *   **Magenta (M):**
        *   (8, 8)
        *   (9, 8)
        *   Total count = 2 pixels.
    *   **Black (.)**: Background.
*   **Output:** 6x6 grid.
    *   Side length = 6. This matches the count of the longest filament (Blue = 6).
    *   Structure: Concentric squares.
    *   Layer 1 (Outer): Blue (B).
    *   Layer 2: Green (G).
    *   Layer 3 (Inner/Center): Magenta (M).
    *   Let's check the output grid:
        ```
        B B B B B B
        B G G G G B
        B G M M G B
        B G M M G B
        B G G G G B
        B B B B B B
        ```
    *   Outer ring (6x6): All B.
    *   Next ring (4x4): All G.
    *   Center (2x2): All M.
    *   This perfectly matches the rule: Longest -> Outer, Next -> Inner, Shortest -> Center.
    *   The size of the grid is $N \times N$ where $N$ is the count of the longest filament.
    *   The layers are filled based on the sorted order of filament lengths.

**3. Analyze the Test Input:**
*   **Grid Size:** Let's count rows and columns.
    *   Rows: 21 rows (0 to 20).
    *   Columns: 23 columns (0 to 22).
*   **Identify Filaments (Colored Pixels):**
    *   **Green (G):**
        *   Row 4, Col 6.
        *   Count = 1.
    *   **Orange (O):**
        *   Row 6, Col 10.
        *   Row 7, Col 10.
        *   Row 8, Col 10.
        *   Count = 3.
    *   **Magenta (M):**
        *   Row 11, Col 2.
        *   Row 11, Col 3.
        *   Row 11, Col 4.
        *   Row 11, Col 5.
        *   Row 11, Col 6.
        *   Count = 5.
    *   **Azure (A):**
        *   Row 12, Col 10.
        *   Row 13, Col 10.
        *   Row 14, Col 10.
        *   Row 15, Col 10.
        *   Row 16, Col 10.
        *   Row 17, Col 10.
        *   Row 18, Col 10.
        *   Count = 7.
    *   **Black (.)**: Background.

*   **Summary of Filaments:**
    1.  **Azure (A):** 7 pixels.
    2.  **Magenta (M):** 5 pixels.
    3.  **Orange (O):** 3 pixels.
    4.  **Green (G):** 1 pixel.

*   **Determine Output Grid Size:**
    *   Longest filament is Azure (A) with 7 pixels.
    *   Output grid side length = 7.
    *   Output grid is 7x7.

*   **Determine Layer Colors:**
    *   Layer 1 (Outermost, 7x7 ring): Azure (A).
    *   Layer 2 (Next, 5x5 ring): Magenta (M).
    *   Layer 3 (Next, 3x3 ring): Orange (O).
    *   Layer 4 (Center, 1x1): Green (G).

*   **Construct the Grid:**
    *   Size: 7x7.
    *   **Ring 1 (Outer):** All cells where row=0, row=6, col=0, col=6 are 'A'.
    *   **Ring 2:** All cells where row=1, row=5, col=1, col=5 (inside the 7x7) are 'M'.
    *   **Ring 3:** All cells where row=2, row=4, col=2, col=4 (inside the 5x5) are 'O'.
    *   **Center:** Cell (3,3) is 'G'.

    Let's visualize the 7x7 grid:
    Row 0: A A A A A A A
    Row 1: A M M M M M A
    Row 2: A M O O O M A
    Row 3: A M O G O M A
    Row 4: A M O O O M A

... [6353 chars truncated]
alt-10 astronomy qwen3.5-122b: fail
"Planetary rings sorted by the arc length of each debris field"
Fail (best cell_acc=0.25 at k=3)
Best Attempt
vs
Expected
Reasoning (11661 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Colored debris streams orbit through empty black space." This implies scattered colored pixels in a black background.
*   **Transformation:** "Gravity collapses them into a planetary cross-section: the longest debris arc becomes the outermost ring. Each successively shorter arc forms the next inner ring, compressing inward until the shortest fragment becomes the planetary core."
*   **Output:** "A square cross-section of a ringed planet — concentric colored bands from longest arc outside to shortest at the center, with no void remaining."
*   **Key Logic:**
    1.  Identify distinct colored objects (streams/arcs).
    2.  Measure the "length" of each object.
    3.  Sort objects by length (longest to shortest).
    4.  Construct a square grid where the outermost layer corresponds to the longest object, the next layer to the second longest, and so on, until the center.
    5.  The output grid is filled completely with these concentric rings.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 22x22 grid.
    *   Objects:
        *   Blue (B): Vertical line at col 13 (0-indexed? let's count). Rows 2-7. Length = 6.
        *   Green (G): Vertical line at col 4. Rows 3-6. Length = 4.
        *   Magenta (M): Vertical line at col 8. Rows 8-9. Length = 2.
    *   Lengths: B=6, G=4, M=2.
    *   Output: 6x6 grid.
    *   Structure:
        *   Outer ring (Layer 1): B (Length 6).
        *   Middle ring (Layer 2): G (Length 4).
        *   Inner core (Layer 3): M (Length 2).
    *   Wait, the output size is 6x6. Why 6x6? The longest object has length 6.
    *   Let's check the rings.
        *   Outer ring (6x6 perimeter): B.
        *   Next ring (4x4 perimeter): G.
        *   Inner core (2x2): M.
    *   This matches the "concentric colored bands" description. The size of the output grid seems to be determined by the length of the longest object.
    *   Let's verify the "length" definition.
        *   B: 6 pixels.
        *   G: 4 pixels.
        *   M: 2 pixels.
    *   Output dimensions: 6x6.
    *   Layer 1 (Outer): B.
    *   Layer 2: G.
    *   Layer 3 (Inner): M.
    *   This fits perfectly.

*   **Example 2:**
    *   Input: 23x23 grid.
    *   Objects:
        *   Red (R): Horizontal line. Row 4, cols 3-7. Length = 5.
        *   Azure (A): Vertical line. Row 9, col 18. Length = 1.
        *   Green (G): Horizontal line. Row 12, cols 8-11. Length = 4.
    *   Lengths: R=5, G=4, A=1.
    *   Output: 5x5 grid.
    *   Structure:
        *   Outer ring (5x5): R.
        *   Middle ring (3x3): G.
        *   Inner core (1x1): A.
    *   Wait, let's look at the output grid provided.
        ```
        R R R R R
        R G G G R
        R G A G R
        R G G G R
        R R R R R
        ```
    *   Outer ring is R.
    *   Next ring is G.
    *   Center is A.
    *   Lengths: R=5, G=4, A=1.
    *   Output size: 5x5.
    *   This confirms the rule: Output size = Length of longest object. Layers are filled by objects sorted by length descending.

*   **Example 3:**
    *   Input: 24x24 grid.
    *   Objects:
        *   Azure (A): Vertical line. Rows 0-7, col 13. Length = 8.
        *   Orange (O): Horizontal line. Row 8, cols 4-5. Length = 2.
        *   Yellow (Y): Vertical line. Rows 9-12, col 9. Length = 4.
        *   Green (G): Horizontal line. Row 15, cols 7-12. Length = 6.
    *   Lengths: A=8, G=6, Y=4, O=2.
    *   Output: 8x8 grid.
    *   Structure:
        *   Layer 1 (Outer): A.
        *   Layer 2: G.
        *   Layer 3: Y.
        *   Layer 4 (Inner): O.
    *   Let's check the output grid provided.
        ```
        A A A A A A A A
        A G G G G G G A
        A G Y Y Y Y G A
        A G Y O O Y G A
        A G Y O O Y G A
        A G Y Y Y Y G A
        A G G G G G G A
        A A A A A A A A
        ```
    *   Outer ring: A.
    *   Next ring: G.
    *   Next ring: Y.
    *   Inner core: O.
    *   This confirms the rule completely.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Debris Streams:** Connected components of non-black pixels of the same color.
    *   **Length:** The number of pixels in a stream.
    *   **Planetary Cross-section:** The output grid.
    *   **Rings:** Concentric square layers of the output grid.

2.  **AFFORDANCES:**
    *   Streams can be counted (length).
    *   Streams can be sorted.
    *   Grid cells can be assigned colors based on their distance from the center (or layer index).

3.  **TRANSFORMATION RULE:**
    *   **Step 1:** Identify all connected components of non-black colors in the input grid.
    *   **Step 2:** Calculate the size (number of pixels) of each component.
    *   **Step 3:** Sort the components by size in descending order.
    *   **Step 4:** Determine the output grid size $N \times N$, where $N$ is the size of the 

... [6670 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=1
"Colored current bands pulled into a whirlpool by their reach"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10986 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Colored ocean currents of different lengths flow across a dark sea." This implies there are lines or segments of colored pixels on a black background.
*   **Action:** "A maelstrom draws them in: the longest current wraps the outer rim of the whirlpool. The next longest spirals just inside. Each shorter current tightens into the next inner ring until the briefest eddy sits motionless at the whirlpool's heart."
*   **Output:** "A square cross-section of the whirlpool — concentric colored rings, each one layer thick, longest current on the outside, shortest at the still center."
*   **Key Insight:** The task involves identifying distinct colored objects (currents) in the input grid, measuring their "length" (number of pixels), sorting them by length (descending), and then arranging them as concentric square rings in the output grid. The longest goes to the outermost ring, the next longest to the next ring, and so on. The center will be the shortest one. The background is black ('.').

**2. Analyze the Training Example:**
*   **Input:** 22x22 grid (judging by the text, let's count).
    *   Row 0-1: All black.
    *   Row 2: One 'B' at col 13.
    *   Row 3-7: 'G' at col 4, 'B' at col 13.
    *   Row 8-9: 'M' at col 8.
    *   Rest: Black.
    *   Let's count the pixels for each color.
    *   Blue (B): Row 2 (1), Row 3 (1), Row 4 (1), Row 5 (1), Row 6 (1), Row 7 (1). Total = 6 pixels.
    *   Green (G): Row 3 (1), Row 4 (1), Row 5 (1), Row 6 (1), Row 7 (1). Total = 5 pixels.
    *   Magenta (M): Row 8 (1), Row 9 (1). Total = 2 pixels.
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Input Example 1:
        *   Row 2: `... B ...` (1 B)
        *   Row 3: `... G ... B ...` (1 G, 1 B)
        *   Row 4: `... G ... B ...` (1 G, 1 B)
        *   Row 5: `... G ... B ...` (1 G, 1 B)
        *   Row 6: `... G ... B ...` (1 G, 1 B)
        *   Row 7: `... B ...` (1 B)
        *   Row 8: `... M ...` (1 M)
        *   Row 9: `... M ...` (1 M)
    *   Counts:
        *   B: 1 + 1 + 1 + 1 + 1 + 1 = 6 pixels.
        *   G: 1 + 1 + 1 + 1 + 1 = 5 pixels.
        *   M: 1 + 1 = 2 pixels.
    *   Output Example 1:
        *   6x6 grid.
        *   Outer ring: B.
        *   Next ring: G.
        *   Center: M.
        *   Wait, the output is 6x6.
        *   Ring 1 (Outer): 6x6 perimeter. Number of pixels = $6 \times 4 - 4 = 20$.
        *   Ring 2: 4x4 perimeter. Number of pixels = $4 \times 4 - 4 = 12$.
        *   Ring 3 (Center): 2x2. Number of pixels = 4.
        *   This doesn't match the pixel counts (6, 5, 2).
        *   Let's re-read the metaphor. "longest current wraps the outer rim... next longest spirals just inside...".
        *   Maybe the output size is determined by the longest current? Or maybe the output size is fixed based on the number of distinct colors?
        *   In Example 1, there are 3 colors. The output is 6x6.
        *   Let's look at the structure of the output.
        *   Row 0: B B B B B B (6 Bs)
        *   Row 1: B G G G G B (2 Bs, 4 Gs)
        *   Row 2: B G M M G B (2 Bs, 2 Gs, 2 Ms)
        *   Row 3: B G M M G B (2 Bs, 2 Gs, 2 Ms)
        *   Row 4: B G G G G B (2 Bs, 4 Gs)
        *   Row 5: B B B B B B (6 Bs)
        *   Total Bs in output: $6 + 2 + 2 + 2 + 2 + 6 = 20$.
        *   Total Gs in output: $4 + 2 + 2 + 4 = 12$.
        *   Total Ms in output: $2 + 2 = 4$.
        *   This output grid is filled with concentric rings. The number of pixels in the rings does not match the input pixel counts.
        *   So the rule is not "move the pixels". The rule is "identify the colors, sort them by length (count), and create a concentric square pattern where the outermost ring is the color with the highest count, the next ring is the color with the second highest count, etc."
        *   What determines the size of the output grid?
        *   In Example 1, input has 3 colors. Output is 6x6.
        *   Is the size related to the max count? Max count is 6 (Blue). Output width is 6.
        *   Let's check if the output width equals the count of the longest current.
        *   Longest current (Blue) count = 6. Output width = 6.
        *   This seems plausible.
        *   Let's check the logic:
            1.  Count pixels for each non-black color.
            2.  Sort colors by count descending.
            3.  Determine output grid size $N \times N$. $N$ = count of the most frequent color.
            4.  Fill the grid with concentric rings.
            5.  Outermost ring (layer 0) gets the most frequent color.
            6.  Next ring (layer 1) gets the second most frequent color.
            7.  ...
            8.  Center gets the least frequent color.
            9.  If $N$ is even, the center is a 2x2 block. If $N$ is odd, the center is a 1x1 block.
            10. 

... [6028 chars truncated]
alt-12 electronics qwen3.5-122b: k=2
"Colored wire traces sheathed into a cable by gauge length"
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11981 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Colored wire traces of different lengths lie scattered across a dark circuit board." This implies there are distinct colored segments (lines) in the input grid.
*   **Action:** "The engineer bundles them into a shielded cable: the longest trace wraps the outermost sheath. The next longest becomes the next inner insulation layer. Each shorter trace nests inside the previous until the shortest forms the core conductor at the center."
*   **Output:** "A square cable cross-section with concentric colored insulation rings, longest trace as outer jacket, shortest as the central conductor."
*   **Key Insight:** The transformation involves identifying colored lines in the input, measuring their lengths, sorting them by length (longest to shortest), and then constructing a concentric square pattern (like a target or onion layers) where the outermost layer corresponds to the longest line, the next layer to the next longest, and so on, down to the center.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:**
        *   Blue (B) vertical line: 6 pixels long (rows 2-7, col 12). Wait, let's count carefully.
            *   Row 2: B
            *   Row 3: B
            *   Row 4: B
            *   Row 5: B
            *   Row 6: B
            *   Row 7: B
            *   Total length = 6.
        *   Green (G) vertical line: 4 pixels long (rows 3-6, col 4).
            *   Row 3: G
            *   Row 4: G
            *   Row 5: G
            *   Row 6: G
            *   Total length = 4.
        *   Magenta (M) vertical line: 2 pixels long (rows 8-9, col 8).
            *   Row 8: M
            *   Row 9: M
            *   Total length = 2.
    *   **Lengths:** B=6, G=4, M=2.
    *   **Output:** A 6x6 grid.
        *   Outer layer (border): B.
        *   Next layer: G.
        *   Inner layer: M.
        *   Wait, the output is 6x6.
        *   Layer 1 (Outer): B.
        *   Layer 2: G.
        *   Layer 3: M.
        *   Layer 4 (Center): M.
        *   Let's check the output grid structure.
            ```
            B B B B B B
            B G G G G B
            B G M M G B
            B G M M G B
            B G G G G B
            B B B B B B
            ```
        *   The outermost ring is B. The next ring inside is G. The center 2x2 block is M.
        *   The lengths were B=6, G=4, M=2.
        *   The output size seems to be determined by the longest length (6).
        *   The layers correspond to the sorted lengths.
        *   Longest (6) -> Outer ring.
        *   Next (4) -> Next ring.
        *   Shortest (2) -> Center.
        *   Since the center is 2x2, and the shortest length is 2, it fits perfectly.
        *   Wait, is the output size always equal to the longest length?
        *   In Ex 1, longest is 6. Output is 6x6.
        *   The rings are 1 pixel thick.
        *   Outer ring (B) takes up the perimeter. Remaining inner area is 4x4.
        *   Next ring (G) takes up the perimeter of the 4x4 area. Remaining inner area is 2x2.
        *   Next ring (M) takes up the perimeter of the 2x2 area. Remaining inner area is 0x0 (filled).
        *   So the logic holds: Sort lines by length. Create concentric square rings starting from the outside. The size of the grid is the length of the longest line.

*   **Example 2:**
    *   **Input:**
        *   Red (R) horizontal line: 5 pixels long (row 4, cols 3-7).
            *   R R R R R
            *   Length = 5.
        *   Azure (A) vertical line: 1 pixel long (row 9, col 10).
            *   A
            *   Length = 1.
        *   Green (G) horizontal line: 4 pixels long (row 12, cols 8-11).
            *   G G G G
            *   Length = 4.
    *   **Lengths:** R=5, G=4, A=1.
    *   **Output:** A 5x5 grid.
        *   Outer layer: R.
        *   Next layer: G.
        *   Center: A.
        *   Let's check the output grid.
            ```
            R R R R R
            R G G G R
            R G A G R
            R G G G R
            R R R R R
            ```
        *   Grid size 5x5 (matches longest length R=5).
        *   Outer ring (5x5 perimeter): R. Inner area 3x3.
        *   Next ring (3x3 perimeter): G. Inner area 1x1.
        *   Center (1x1): A.
        *   Logic holds perfectly.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Elements:** Colored pixels forming straight lines (horizontal or vertical). Background is black (.).
    *   **Output Elements:** Concentric square rings of colors.
    *   **Roles:**
        *   Longest line -> Outermost ring color.
        *   Second longest -> Second ring color.
        *   ...
        *   Shortest line -> Center color.
    *   **Grid Size:** Determined by the length of the longest line found in the input.

2.  **AFFORDANCES:**
    *   Lines can be counted t

... [7011 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"Colored serpents coil around each other by their body length"
Fail (best cell_acc=0.00 at k=1)
No grid
vs
Expected
Reasoning (10960 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Mythic serpents of different colors lie stretched across the void." This implies there are colored lines or segments in the input grid.
*   **Transformation:** "They coil into a nest: the longest serpent wraps the outermost coil of the square nest. The next longest coils just inside. Each shorter serpent takes the next inner ring until the smallest curls into a knot at the very center."
*   **Output:** "A square serpent's nest — concentric colored coils, each one body thick, greatest wyrm on the outside, smallest snake at the center."
*   **Key Insight:** The input contains disconnected colored segments (serpents). The output is a square grid where these segments are rearranged into concentric square rings (coils). The size of the ring corresponds to the length of the serpent. The longest serpent forms the outermost ring, the next longest the next ring, and so on. The center is filled by the smallest serpent.

**2. Analyze the Training Example:**
*   **Input Grid:** 22x22 (approx, let's count).
    *   Row 0-1: Empty
    *   Row 2: `B` at col 12.
    *   Row 3-6: `G` at col 4, `B` at col 12.
    *   Row 7: `B` at col 12.
    *   Row 8-9: `M` at col 8.
    *   Rest empty.
    *   Let's count the lengths of the colored segments.
    *   Blue (`B`): Rows 2, 3, 4, 5, 6, 7 at col 12. That's 6 pixels.
    *   Green (`G`): Rows 3, 4, 5, 6 at col 4. That's 4 pixels.
    *   Magenta (`M`): Rows 8, 9 at col 8. That's 2 pixels.
    *   Total colored pixels = 6 + 4 + 2 = 12.
*   **Output Grid:** 6x6.
    *   Outer ring (6x6 perimeter): 6*4 - 4 = 20 pixels? No, wait.
    *   Let's look at the output structure.
    *   Row 0: `B B B B B B` (6 B's)
    *   Row 1: `B G G G G B` (2 B's, 4 G's)
    *   Row 2: `B G M M G B` (2 B's, 2 G's, 2 M's)
    *   Row 3: `B G M M G B` (2 B's, 2 G's, 2 M's)
    *   Row 4: `B G G G G B` (2 B's, 4 G's)
    *   Row 5: `B B B B B B` (6 B's)
    *   Let's count the pixels in the output rings.
    *   Outer Ring (Blue `B`): Top row (6) + Bottom row (6) + Left col middle (4) + Right col middle (4) = 20 pixels?
    *   Wait, the input had 6 Blue pixels. The output has 20 Blue pixels. This contradicts the "serpent length" idea if it means pixel count.
    *   Let's re-read the metaphor. "The longest serpent wraps the outermost coil...".
    *   Maybe the "length" refers to the side length of the square ring?
    *   Outer ring is 6x6. Perimeter length = 6+6+4+4 = 20.
    *   Inner ring (Green `G`): It's inside the 6x6. So it's a 4x4 ring. Perimeter = 4+4+2+2 = 12.
    *   Innermost ring (Magenta `M`): It's inside the 4x4. So it's a 2x2 ring. Perimeter = 2+2+0+0 = 4.
    *   Input counts: B=6, G=4, M=2.
    *   Output ring sizes (side length): B=6, G=4, M=2.
    *   Ah! The number of pixels in the input segment corresponds to the *side length* of the square ring in the output, not the total number of pixels in the ring.
    *   Let's verify.
    *   Input Blue segment length = 6 pixels. Output Blue ring side length = 6.
    *   Input Green segment length = 4 pixels. Output Green ring side length = 4.
    *   Input Magenta segment length = 2 pixels. Output Magenta ring side length = 2.
    *   The output grid size is determined by the largest serpent. Here max length is 6, so output is 6x6.
    *   The rings are concentric.
    *   Outermost ring (side 6) is Blue.
    *   Next ring (side 4) is Green.
    *   Innermost ring (side 2) is Magenta.
    *   This matches the output perfectly.

**3. Conceptual Digestion:**
*   **CAST:**
    *   **Input:** A sparse grid containing straight line segments of single colors.
    *   **Output:** A dense square grid composed of concentric square rings.
    *   **Elements:** Colored pixels representing "serpents".
*   **AFFORDANCES:**
    *   Count the number of contiguous pixels of a specific color to determine the "length" of that serpent.
    *   Sort the colors by length (descending).
    *   Construct a square grid where the side length equals the length of the longest serpent.
    *   Fill the grid with concentric rings. The outermost ring corresponds to the longest serpent, the next inner ring to the next longest, etc.
    *   Each ring is 1 pixel thick.
*   **TRANSFORMATION RULE:**
    1.  Identify all distinct colors present in the input grid (excluding background `.`).
    2.  For each color, count the number of pixels belonging to that color. Let this count be $L_c$.
    3.  Determine the maximum length $L_{max} = \max(L_c)$. This defines the dimensions of the output grid ($L_{max} \times L_{max}$).
    4.  Sort the colors by their pixel counts in descending order.
    5.  Construct the output grid of size $L_{max} \times L_{max}$.
    6.  Fill the grid with concentric square rings starting from the outside.
        *   Ring 1 (Outermost): Color with the largest count. Side

... [5978 chars truncated]
alt-14 dance qwen3.5-122b: fail
"Colored ribbon dancers forming concentric squares by ribbon length"
Fail (best cell_acc=0.02 at k=2)
Best Attempt
vs
Expected
Reasoning (13890 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** Dancers with colored ribbons of different lengths scattered on a dark stage.
*   **Action:** They form concentric square paths.
*   **Rule:**
    *   Longest ribbon -> Outermost square.
    *   Next longest -> Square just inside.
    *   ...
    *   Shortest ribbon -> Center.
*   **Grid Details:** Square formation, concentric colored paths, each one step wide.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** A large grid (22x22) with scattered colored pixels.
    *   Blue (B): A vertical line of 6 pixels at column 12 (0-indexed? let's count).
        *   Rows 2-7, Col 12. Length = 6.
    *   Green (G): A vertical line of 4 pixels at column 4.
        *   Rows 3-6, Col 4. Length = 4.
    *   Magenta (M): A vertical line of 2 pixels at column 8.
        *   Rows 8-9, Col 8. Length = 2.
    *   Wait, let's look closer at the input grid.
    *   Row 2: `... B ...` (Col 12)
    *   Row 3: `... G ... B ...` (Col 4, Col 12)
    *   Row 4: `... G ... B ...`
    *   Row 5: `... G ... B ...`
    *   Row 6: `... G ... B ...`
    *   Row 7: `... B ...`
    *   Row 8: `... M ...` (Col 8)
    *   Row 9: `... M ...`
    *   Let's count the lengths of the colored segments.
        *   Blue (B): Rows 2, 3, 4, 5, 6, 7. Total 6 pixels.
        *   Green (G): Rows 3, 4, 5, 6. Total 4 pixels.
        *   Magenta (M): Rows 8, 9. Total 2 pixels.
    *   Wait, looking at the output:
        *   Output size: 6x6.
        *   Outer ring: Blue (B).
        *   Middle ring: Green (G).
        *   Inner core: Magenta (M).
    *   The lengths in the input correspond to the "size" or "perimeter" or "area" of the square in the output?
    *   Let's check the output structure.
        *   Outer square (6x6): Perimeter = 6+6+4+4 = 20? No, it's a ring of width 1.
        *   The output is a 6x6 grid.
        *   Outer layer (B): 6x6 border.
        *   Next layer (G): 4x4 border inside the 6x6.
        *   Inner layer (M): 2x2 block in the center.
    *   Relationship between Input Lengths and Output Dimensions:
        *   Blue (B) count = 6. Output outer dimension = 6.
        *   Green (G) count = 4. Output middle dimension = 4.
        *   Magenta (M) count = 2. Output inner dimension = 2.
    *   It seems the number of pixels of a specific color in the input determines the side length of the square ring of that color in the output.
    *   The colors are ordered by length: Longest (6) -> Outer, Next (4) -> Middle, Shortest (2) -> Inner.
    *   The output grid size is determined by the longest ribbon length (6).
    *   The structure is concentric squares.

**Example 2:**
*   **Input:** Large grid (24x27).
    *   Red (R): Row 4, Cols 3-7. `R R R R R`. Length = 5.
    *   Azure (A): Row 9, Col 10. `A`. Length = 1.
    *   Green (G): Row 12, Cols 8-11. `G G G G`. Length = 4.
    *   Let's verify counts.
        *   R: 5 pixels.
        *   G: 4 pixels.
        *   A: 1 pixel.
    *   Output:
        *   Size: 5x5.
        *   Outer ring: Red (R). (Corresponds to length 5).
        *   Middle ring: Green (G). (Corresponds to length 4).
        *   Inner core: Azure (A). (Corresponds to length 1).
    *   Structure:
        *   5x5 grid.
        *   Layer 1 (Outer): R.
        *   Layer 2: G.
        *   Layer 3 (Center): A.
    *   This confirms the hypothesis:
        1.  Identify distinct colors present in the input (excluding black `.`).
        2.  Count the number of pixels for each color.
        3.  Sort colors by count in descending order.
        4.  The largest count determines the size of the output grid (N x N).
        5.  Construct concentric square rings starting from the outside.
        6.  The outermost ring corresponds to the color with the largest count.
        7.  The next ring inward corresponds to the color with the next largest count.
        8.  Continue until the center is filled.
        9.  The "length" of the ribbon in the input seems to be the side length of the square in the output.
        10. Wait, in Example 1:
            *   B count = 6. Output size = 6.
            *   G count = 4. Output size = 4.
            *   M count = 2. Output size = 2.
            *   This implies the output is composed of nested squares of sizes 6, 4, 2.
            *   A 6x6 square has a border. Inside is a 4x4 area. Inside that is a 2x2 area.
            *   This fits perfectly.
        11. In Example 2:
            *   R count = 5. Output size = 5.
            *   G count = 4. Output size = 4.
            *   A count = 1. Output size = 1.
            *   A 5x5 square has a border. Inside is a 3x3 area.
            *   Wait, the next square is size 4. A 4x4 square inside a 5x5 square?
            *   If I put a 4x4 square inside a 5x5 square, it's not centered perfectly with integer coordinates if we think of rin

... [8962 chars truncated]
alt-15 geology qwen3.5-122b: fig alone solves
"Colored mineral veins compressed into strata by their extent"
alt-2 cooking qwen3.5-122b: fail
"Layered sushi built from ingredient strips"
Fail (best cell_acc=0.29 at k=1)
Best Attempt
vs
Expected
Reasoning (10829 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "strips of colored ingredients — some long nori sheets, some shorter fish slices, a tiny dab of wasabi."
    *   This implies the input grid contains disconnected colored shapes (lines/segments) on a black background.
    *   "Each ingredient is a different color and a different length."
*   **Transformation:** "The chef builds a square pressed sushi block: the longest strip wraps the outermost layer. The next longest wraps just inside that, forming the next ring. Each ingredient becomes one layer of the cross-section, nesting inward by size until the smallest morsel sits at the heart."
    *   This implies the output is a square grid.
    *   The output consists of concentric square rings.
    *   The rings are filled with colors corresponding to the input strips.
    *   The order of rings (from outside to inside) is determined by the length of the input strips (longest on outside, shortest on inside).
    *   "Each ingredient becomes one layer of the cross-section". This suggests a 1-to-1 mapping between input colored objects and output rings.
    *   "Square pressed sushi block": The output shape is a square.
    *   "Nesting inward by size": Largest area/length -> Outer ring. Smallest area/length -> Center.

**2. Analyze the Training Example:**
*   **Input:** 22x22 grid (approx, let's count).
    *   Row 0-1: Empty.
    *   Row 2: `B` at col 11.
    *   Row 3-6: `G` at col 4, `B` at col 11.
    *   Row 7: `B` at col 11.
    *   Row 8-9: `M` at col 8.
    *   Rest empty.
    *   Let's count the lengths of the colored segments.
    *   Blue (`B`): Rows 2, 3, 4, 5, 6, 7. That's 6 pixels.
    *   Green (`G`): Rows 3, 4, 5, 6. That's 4 pixels.
    *   Magenta (`M`): Rows 8, 9. That's 2 pixels.
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Input Grid:
        *   Row 2: `B` at index 11.
        *   Row 3: `G` at 4, `B` at 11.
        *   Row 4: `G` at 4, `B` at 11.
        *   Row 5: `G` at 4, `B` at 11.
        *   Row 6: `G` at 4, `B` at 11.
        *   Row 7: `B` at 11.
        *   Row 8: `M` at 8.
        *   Row 9: `M` at 8.
    *   Counts:
        *   Blue (`B`): 6 pixels (vertical line).
        *   Green (`G`): 4 pixels (vertical line).
        *   Magenta (`M`): 2 pixels (vertical line).
    *   Total pixels = 6 + 4 + 2 = 12.
    *   Output Grid: 6x6.
    *   Output Structure:
        *   Outer ring (Layer 1): Blue (`B`).
        *   Middle ring (Layer 2): Green (`G`).
        *   Inner core (Layer 3): Magenta (`M`).
    *   Wait, the output is 6x6.
    *   Ring 1 (Outer): 6x6 perimeter. Number of pixels = 6*4 - 4 = 20? No, usually rings are defined by the grid.
    *   Let's check the output grid content:
        *   Row 0: B B B B B B
        *   Row 1: B G G G G B
        *   Row 2: B G M M G B
        *   Row 3: B G M M G B
        *   Row 4: B G G G G B
        *   Row 5: B B B B B B
    *   This is a 6x6 square.
    *   Outer ring is Blue.
    *   Next ring is Green.
    *   Center 2x2 is Magenta.
    *   Why 6x6?
    *   Input lengths: B=6, G=4, M=2.
    *   Sum of lengths = 12.
    *   Output area = 36.
    *   This doesn't match sum of lengths directly.
    *   Maybe the size of the output square is determined by the longest strip?
    *   Longest strip is Blue (length 6). Output width is 6.
    *   Let's verify this hypothesis.
    *   Hypothesis: The side length of the output square equals the length of the longest input strip.
    *   Let's check the rings.
    *   Outer ring (Layer 1): Corresponds to longest strip (Blue, len 6).
    *   Next ring (Layer 2): Corresponds to next longest (Green, len 4).
    *   Inner core (Layer 3): Corresponds to shortest (Magenta, len 2).
    *   Does the "length" map to the "ring size"?
    *   In a 6x6 square:
        *   Outer ring thickness is 1.
        *   Inner square is 4x4.
        *   Next ring thickness is 1.
        *   Inner square is 2x2.
        *   Center is 2x2.
    *   The lengths are 6, 4, 2.
    *   The dimensions of the squares formed by the rings are 6x6, 4x4, 2x2.
    *   It seems the length of the strip determines the side length of the square *enclosed* by that ring (or the square defined by that layer).
    *   Actually, looking at the pattern:
        *   Blue (len 6) -> Outer boundary of 6x6.
        *   Green (len 4) -> Outer boundary of 4x4 (inside the 6x6).
        *   Magenta (len 2) -> Outer boundary of 2x2 (inside the 4x4).
    *   So, the rule is:
        1.  Identify all distinct colored connected components (strips) in the input.
        2.  Measure the "length" of each strip. (In the example, they are vertical lines, length = number of pixels).
        3.  Sort the strips by length in descending order.
        4.  The longest length determines the size of the output square (N x N).
      

... [5871 chars truncated]
alt-3 music qwen3.5-122b: fig alone solves
"Notes ranked by duration composing a resonance mandala"
alt-4 sports qwen3.5-122b: fail
"Relay batons stacked into a champion's trophy by distance run"
Fail (best cell_acc=0.00 at k=1)
No grid
vs
Expected
Reasoning (11622 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Across an empty field, relay batons of different colors are scattered. Each baton represents a leg of the race — some legs are long sprints, others short dashes. Each baton has a different color and length."
    *   This implies the input grid contains scattered colored segments (lines/batons) of varying lengths.
    *   The background is empty (black/dots).
*   **Transformation:** "The batons are assembled into a victory monument: the longest baton defines the square pedestal and wraps the outside. The next longest forms the next inner tier. Each successive baton nests inside, one layer deep, until the shortest baton crowns the center."
    *   This implies the output is a square grid.
    *   The structure is concentric squares (layers).
    *   The order of layers is determined by the length of the input batons.
    *   Longest baton -> Outermost layer.
    *   Next longest -> Next inner layer.
    *   ...
    *   Shortest baton -> Center.
*   **Grid details:** "A square trophy cross-section with colored concentric tiers, longest leg forming the outer edge, shortest at the core."
    *   Confirms the output is a square with concentric colored rings.

**2. Analyze the Training Example:**
*   **Input:** 22x22 grid (approx, let's count).
    *   Rows 0-1: Empty.
    *   Row 2: `B` at col 11.
    *   Row 3: `G` at col 4, `B` at col 11.
    *   Row 4: `G` at col 4, `B` at col 11.
    *   Row 5: `G` at col 4, `B` at col 11.
    *   Row 6: `G` at col 4, `B` at col 11.
    *   Row 7: `B` at col 11.
    *   Row 8: `M` at col 8.
    *   Row 9: `M` at col 8.
    *   Rest empty.
    *   Let's identify the "batons" (connected components of same color).
        *   **Blue (B):** Vertical line at col 11, rows 2 to 7. Length = 6 cells.
        *   **Green (G):** Vertical line at col 4, rows 3 to 6. Length = 4 cells.
        *   **Magenta (M):** Vertical line at col 8, rows 8 to 9. Length = 2 cells.
    *   Lengths: B=6, G=4, M=2.
    *   Order: Longest (B) -> Middle (G) -> Shortest (M).
*   **Output:** 6x6 grid.
    *   Outer layer (Layer 1): Color B.
    *   Middle layer (Layer 2): Color G.
    *   Inner layer (Layer 3): Color M.
    *   Structure:
        *   Row 0: B B B B B B
        *   Row 1: B G G G G B
        *   Row 2: B G M M G B
        *   Row 3: B G M M G B
        *   Row 4: B G G G G B
        *   Row 5: B B B B B B
    *   This matches the "concentric tiers" description.
    *   The size of the output grid seems to be determined by the longest baton.
    *   Longest baton length = 6. Output grid size = 6x6.
    *   Wait, let's check the logic.
    *   If the longest baton defines the square pedestal and wraps the outside...
    *   A square of size $N \times N$ has a perimeter of $4N - 4$ cells.
    *   However, the metaphor says "longest baton defines the square pedestal".
    *   In the example, longest baton length is 6. Output size is 6x6.
    *   Does the length of the baton equal the side length of the square?
    *   Let's check the number of cells in the outer ring of a 6x6 square. It's $6 \times 6 - 4 \times 4 = 36 - 16 = 20$ cells.
    *   The input baton B has 6 cells.
    *   So the "length" of the baton corresponds to the *side length* of the square, not the number of pixels in the ring.
    *   The metaphor says "longest baton defines the square pedestal". This likely means the side length of the output square is equal to the length of the longest baton found in the input.
    *   Let's verify with the layers.
    *   Layer 1 (Outer): Color B. Side length 6.
    *   Layer 2 (Inner): Color G. Side length 4. (6 - 2 = 4).
    *   Layer 3 (Inner): Color M. Side length 2. (4 - 2 = 2).
    *   This fits perfectly. The lengths of the batons found in the input are 6, 4, 2. These correspond exactly to the side lengths of the concentric squares in the output.
    *   So the rule is:
        1.  Identify all connected colored segments (batons) in the input grid.
        2.  Measure the length (number of cells) of each baton.
        3.  Sort the batons by length in descending order.
        4.  The length of the longest baton determines the size of the output square ($N \times N$).
        5.  Construct the output grid as concentric square rings.
        6.  The outermost ring corresponds to the longest baton.
        7.  The next ring corresponds to the next longest baton, and so on.
        8.  The side length of each ring decreases by 2 for each inner layer (standard concentric square logic).
        9.  Wait, does the input length *have* to match the side length sequence?
            *   Input lengths: 6, 4, 2.
            *   Output side lengths: 6, 4, 2.
            *   This implies the input lengths *are* the side lengths.
            *   What if the input lengths were 6, 5, 3? Would the output be 6

... [6679 chars truncated]
alt-5 weather qwen3.5-122b: k=2
"Storm fronts coalescing into a hurricane eye by reach"
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11871 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Weather bands of different colors drift across a calm black sky." This suggests the input grid contains scattered colored pixels (bands) on a black background.
*   **Transformation:** "The bands spiral inward to form a hurricane: the widest-reaching front wraps the outermost wall. The next widest tightens inside it. Each successively narrower band forms the next inner ring until the smallest disturbance becomes the quiet eye at the center."
*   **Output:** "A square cross-section of the storm — concentric colored rings from widest band on the outside to narrowest at the calm center."
*   **Key Concept:** The transformation involves identifying distinct colored "bands" or "objects" in the input, measuring their "width" or "size", and arranging them into concentric square rings in the output grid. The largest band becomes the outermost ring, the next largest becomes the next ring, and so on, until the center.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:**
    *   A vertical line of Blue (B) pixels: 6 pixels long (rows 2-7, col 12). Wait, let's count carefully.
    *   Row 2: B at col 12.
    *   Row 3: B at col 12.
    *   Row 4: B at col 12.
    *   Row 5: B at col 12.
    *   Row 6: B at col 12.
    *   Row 7: B at col 12.
    *   Total B count = 6.
    *   A vertical line of Green (G) pixels: 4 pixels long (rows 3-6, col 4).
    *   Row 3: G at col 4.
    *   Row 4: G at col 4.
    *   Row 5: G at col 4.
    *   Row 6: G at col 4.
    *   Total G count = 4.
    *   A vertical line of Magenta (M) pixels: 2 pixels long (rows 8-9, col 8).
    *   Row 8: M at col 8.
    *   Row 9: M at col 8.
    *   Total M count = 2.
    *   Background is black (.).
*   **Output:**
    *   A 6x6 grid.
    *   Outer ring: Blue (B).
    *   Middle ring: Green (G).
    *   Inner ring (center 2x2): Magenta (M).
    *   Wait, let's look at the output structure.
    *   Row 0: B B B B B B
    *   Row 1: B G G G G B
    *   Row 2: B G M M G B
    *   Row 3: B G M M G B
    *   Row 4: B G G G G B
    *   Row 5: B B B B B B
    *   This is a set of concentric square rings.
    *   Outermost ring (size 6x6): Color B.
    *   Next ring (size 4x4): Color G.
    *   Innermost ring (size 2x2): Color M.
    *   The size of the output grid seems determined by the largest band. The largest band has 6 pixels. The output is 6x6.
    *   The ordering is based on the count/length of the bands.
    *   B count = 6 -> Outer ring.
    *   G count = 4 -> Middle ring.
    *   M count = 2 -> Inner ring.
    *   The rings are filled completely.
    *   Wait, the "width" metaphor might refer to the length of the line segment.
    *   B is length 6. G is length 4. M is length 2.
    *   Output grid size is 6x6.
    *   Ring 1 (outer): B.
    *   Ring 2: G.
    *   Ring 3 (center): M.
    *   This matches the "widest-reaching front wraps the outermost wall" idea. Widest = longest line = outermost.

**Example 2:**
*   **Input:**
    *   Red (R) horizontal line: 5 pixels (row 4, cols 3-7). Count = 5.
    *   Azure (A) single pixel? No, let's look closer.
    *   Row 9: A at col 9. Just one A?
    *   Wait, let's check the input grid text for Example 2.
    *   Row 4: `. . . R R R R R . . .` -> 5 Rs.
    *   Row 9: `. . . . . . . . . A . . .` -> 1 A.
    *   Row 12: `. . . . . . . . G G G G . . .` -> 4 Gs.
    *   Let's check the counts.
    *   R: 5 pixels.
    *   G: 4 pixels.
    *   A: 1 pixel.
*   **Output:**
    *   5x5 grid.
    *   Outer ring: R.
    *   Middle ring: G.
    *   Center: A.
    *   Structure:
        *   R R R R R
        *   R G G G R
        *   R G A G R
        *   R G G G R
        *   R R R R R
    *   This confirms the hypothesis.
    *   Identify connected components of the same color.
    *   Count the number of pixels in each component.
    *   Sort components by count (descending).
    *   Create a square grid with side length equal to the count of the largest component.
    *   Fill concentric rings starting from the outside with the colors of the sorted components.
    *   If there are multiple components of the same color? The examples show single components per color.
    *   If the counts don't match the ring sizes perfectly?
        *   Ex 1: Counts 6, 4, 2. Grid 6x6.
            *   Ring 1 (6x6 perimeter): Needs $6^2 - 4^2 = 36 - 16 = 20$ pixels. We have 6 B's. Wait.
            *   The metaphor says "The bands spiral inward...". It doesn't say "fill the ring with the band's pixels". It says the band *forms* the ring.
            *   In Ex 1, B count is 6. The outer ring of a 6x6 grid has 20 pixels. But the output shows the outer ring is all B.
            *   So the *color* of the band determines the color of the ring. The *size* (count) of the band determines the *order* and potentially the *grid

... [6904 chars truncated]
alt-6 architecture qwen3.5-122b: fig alone solves
"Walls built from salvaged beams, longest timber frames the outermost room"
alt-7 warfare qwen3.5-122b: fail
"Defensive perimeters ranked by the length of each regiment's battle line"
Fail (best cell_acc=0.02 at k=3)
Best Attempt
vs
Expected
Reasoning (12212 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** Colored regiments (lines of colored pixels) are scattered on a dark (black) battlefield.
*   **Action:** Fortification.
*   **Rule:**
    *   Longest line -> Outermost defensive wall.
    *   Next longest -> Just inside.
    *   Smallest squad -> Center.
    *   Structure: Concentric colored defensive rings, each one soldier thick.
    *   Shape: Square fortress cross-section.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:**
        *   Blue (B) vertical line: 6 pixels long (rows 2-7, col 12).
        *   Green (G) vertical line: 4 pixels long (rows 3-6, col 4).
        *   Magenta (M) vertical line: 2 pixels long (rows 8-9, col 8).
        *   Background: Black (.).
    *   **Output:**
        *   A 6x6 square grid.
        *   Outer ring: Blue (B). Size 6x6.
        *   Next ring: Green (G). Size 4x4 (inside the 6x6).
        *   Inner ring: Magenta (M). Size 2x2 (inside the 4x4).
    *   **Observation:** The size of the output grid corresponds to the length of the longest line found in the input. The lines are stacked concentrically based on length. Longest on outside, shortest on inside.

*   **Example 2:**
    *   **Input:**
        *   Red (R) horizontal line: 5 pixels long (row 4, cols 3-7).
        *   Azure (A) vertical line: 1 pixel long (row 9, col 9). Wait, let's count.
            *   Row 9, col 9 is 'A'. Just one 'A'.
        *   Green (G) horizontal line: 4 pixels long (row 12, cols 8-11).
    *   **Output:**
        *   A 5x5 square grid.
        *   Outer ring: Red (R). Size 5x5.
        *   Next ring: Green (G). Size 3x3 (inside 5x5).
        *   Inner ring: Azure (A). Size 1x1 (inside 3x3).
    *   **Observation:**
        *   Longest line: Red (5). Output size 5x5.
        *   Next longest: Green (4). Wait, the output shows Green as the middle ring.
        *   Shortest: Azure (1). Output shows Azure as center.
        *   Wait, let's check the Green line length in input. Row 12: `G G G G`. That's 4 pixels.
        *   Output structure:
            *   Ring 1 (Outer): R (5x5)
            *   Ring 2 (Middle): G (3x3)
            *   Ring 3 (Inner): A (1x1)
        *   Why is Green the middle ring if its length is 4? The output grid is 5x5. The inner 3x3 is filled with G. The center 1x1 is filled with A.
        *   The metaphor says "next longest garrisons just inside".
        *   Lengths: R=5, G=4, A=1.
        *   Order: R (outer), G (middle), A (inner).
        *   This matches the lengths perfectly.

*   **Example 3:**
    *   **Input:**
        *   Azure (A) vertical line: 8 pixels long (rows 0-7, col 13).
        *   Orange (O) horizontal line: 2 pixels long (row 8, cols 4-5).
        *   Yellow (Y) vertical line: 4 pixels long (rows 9-12, col 9).
        *   Green (G) horizontal line: 6 pixels long (row 15, cols 7-12).
    *   **Output:**
        *   A 8x8 square grid.
        *   Outer ring: Azure (A). Size 8x8.
        *   Next ring: Green (G). Size 6x6.
        *   Next ring: Yellow (Y). Size 4x4.
        *   Inner ring: Orange (O). Size 2x2.
    *   **Observation:**
        *   Lengths: A=8, G=6, Y=4, O=2.
        *   Output layers (from outside in): A, G, Y, O.
        *   This confirms the rule: Sort lines by length (descending). Create concentric square rings. The outermost ring corresponds to the longest line, the next ring to the next longest, etc. The size of the grid is determined by the length of the longest line.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Elements:** Colored pixels forming straight lines (horizontal or vertical) on a black background.
    *   **Output Elements:** Concentric square rings of colors.
    *   **Roles:**
        *   Line Length: Determines the rank/order of the color in the output structure.
        *   Color: The identity of the regiment.
        *   Background: Ignored.

2.  **AFFORDANCES:**
    *   Lines can be counted to determine their length.
    *   Colors can be associated with specific lengths.
    *   Grid dimensions can be set based on the maximum length found.
    *   Rings can be drawn based on the sorted lengths.

3.  **TRANSFORMATION RULE:**
    *   **Step 1:** Identify all distinct colored lines in the input grid. A line is a contiguous sequence of the same color in a row or column.
    *   **Step 2:** Count the number of pixels (length) for each line.
    *   **Step 3:** Sort the lines by length in descending order.
    *   **Step 4:** Determine the output grid size $N \times N$, where $N$ is the length of the longest line.
    *   **Step 5:** Construct the output grid.
        *   Initialize an $N \times N$ grid.
        *   Iterate through the sorted lines. Let the current line have length $L$ and color $C$.
        *   This line corresponds to a square ring of size $L \times L$.
        *  

... [7224 chars truncated]
alt-8 theater qwen3.5-122b: fail
"Curtains drawn inward by the length of each act"
Fail (best cell_acc=0.02 at k=2)
Best Attempt
vs
Expected
Reasoning (12634 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** Colored curtain rods of different lengths scattered across a dark stage. Each rod holds a curtain of a unique color.
*   **What to do:** The stage manager hangs the curtains as nested reveals.
    *   Longest curtain -> outermost proscenium (outermost frame).
    *   Next longest -> just inside.
    *   Shortest -> center (spotlight).
*   **Grid details:** A square stage viewed from above. Concentric colored curtain frames, each one layer thick. Longest framing the outside, shortest revealing the center.

**Interpretation:**
The input grid contains scattered colored pixels (or lines of pixels) representing "curtain rods".
The output grid is a smaller square grid containing concentric square frames of colors.
The size of the output grid seems to depend on the number of distinct colors or the lengths of the "rods".
The "rods" in the input are lines of colored pixels.
The transformation involves:
1.  Identifying the distinct colors present in the input (excluding black '.').
2.  Measuring the "length" of each color's representation in the input.
3.  Sorting the colors by length (longest to shortest).
4.  Constructing a square output grid where the outermost layer is the color of the longest rod, the next layer is the color of the next longest rod, and so on, until the center.
5.  The output grid size seems to be determined by the number of distinct colors. If there are $N$ colors, the output is likely an $N \times N$ grid (or maybe $(2N-1) \times (2N-1)$? Let's check the examples).

**2. Analyze Training Example 1:**
*   **Input:** 22x22 grid (approx, let's count).
    *   Rows: 22. Cols: 22.
    *   Colors present: B (Blue), G (Green), M (Magenta).
    *   Let's count the pixels for each color.
    *   **B (Blue):**
        *   Row 2: 1 pixel (col 12)
        *   Row 3: 1 pixel (col 12)
        *   Row 4: 1 pixel (col 12)
        *   Row 5: 1 pixel (col 12)
        *   Row 6: 1 pixel (col 12)
        *   Row 7: 1 pixel (col 12)
        *   Total B pixels = 6.
        *   Wait, looking closely at the input text:
            Row 2 (index 2): `... B ...` (1 pixel)
            Row 3: `... B ...` (1 pixel)
            Row 4: `... B ...` (1 pixel)
            Row 5: `... B ...` (1 pixel)
            Row 6: `... B ...` (1 pixel)
            Row 7: `... B ...` (1 pixel)
            Actually, let's look at the structure.
            Rows 2-7 have a B at column 12 (0-indexed? Let's assume 1-based for counting).
            It looks like a vertical line of length 6.
    *   **G (Green):**
        *   Row 3: `... G ...` (col 5)
        *   Row 4: `... G ...` (col 5)
        *   Row 5: `... G ...` (col 5)
        *   Row 6: `... G ...` (col 5)
        *   Total G pixels = 4.
        *   Vertical line of length 4.
    *   **M (Magenta):**
        *   Row 8: `... M ...` (col 9)
        *   Row 9: `... M ...` (col 9)
        *   Total M pixels = 2.
        *   Vertical line of length 2.
    *   **Lengths:** B=6, G=4, M=2.
    *   **Order:** Longest to Shortest -> B, G, M.
    *   **Output:** 6x6 grid.
        *   Outer layer (Layer 1): B.
        *   Middle layer (Layer 2): G.
        *   Inner layer (Layer 3): M.
        *   Wait, the output is 6x6.
        *   Layer 1 (Border): B.
        *   Layer 2 (Inside border): G.
        *   Layer 3 (Center 2x2): M.
        *   Let's check the output grid provided:
            ```
            B B B B B B
            B G G G G B
            B G M M G B
            B G M M G B
            B G G G G B
            B B B B B B
            ```
        *   This is a 6x6 grid.
        *   Colors: B (outer), G (middle), M (inner).
        *   The number of colors is 3. The grid size is 6x6.
        *   Why 6x6? The longest rod had length 6.
        *   Hypothesis: The output grid size is $L_{max} \times L_{max}$, where $L_{max}$ is the length of the longest rod.
        *   The layers correspond to the sorted colors.
        *   Layer 1 (outermost): Color with length $L_{max}$.
        *   Layer 2: Color with next length.
        *   ...
        *   Layer $k$: Color with $k$-th length.
        *   Wait, if grid size is 6x6, there are 3 layers of thickness 1?
            *   Layer 1: Rows 0, 5 and Cols 0, 5. (Perimeter of 6x6).
            *   Layer 2: Rows 1, 4 and Cols 1, 4. (Perimeter of 4x4 inside).
            *   Layer 3: Rows 2, 3 and Cols 2, 3. (Perimeter of 2x2 inside).
            *   This matches the output perfectly.
            *   So, if there are $N$ colors, and the longest length is $L$, the grid is $L \times L$.
            *   The colors are assigned to concentric square rings starting from the outside.
            *   Ring 1 (outermost): Longest color.
            *   Ring 2: 2nd longest.
            *   ...
            *   Ring $N$: Shortest color.
            *   Does the number o

... [7664 chars truncated]
alt-9 gardening qwen3.5-122b: fail
"Hedge borders planted by the length of each cutting"
Fail (best cell_acc=0.02 at k=2)
Best Attempt
vs
Expected
Reasoning (12001 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Colored hedge cuttings of different lengths lie scattered on dark soil." This implies the input grid contains scattered colored pixels (hedge cuttings) on a black background (dark soil).
*   **Action:** "The gardener plants them as nested borders: the longest cutting defines the outermost garden hedge. The next longest is planted just inside. Each shorter cutting forms the next inner border ring until the smallest sprig marks the center of the garden."
*   **Output:** "A square garden plot with concentric colored hedge borders, each one row thick, longest on the perimeter, smallest at the heart."
*   **Key Insight:** The transformation involves identifying distinct colored segments (lines) in the input, measuring their lengths, sorting them by length (longest to shortest), and then arranging them as concentric square rings in the output grid. The longest color forms the outermost ring, the next longest forms the next ring inside, and so on. The center will be filled by the shortest color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:**
        *   Blue (B) vertical line: 6 pixels long (rows 2-7, col 11). Wait, let's count carefully.
            *   Row 2: B
            *   Row 3: B
            *   Row 4: B
            *   Row 5: B
            *   Row 6: B
            *   Row 7: B
            *   Total B count = 6.
        *   Green (G) vertical line: 4 pixels long (rows 3-6, col 4).
            *   Row 3: G
            *   Row 4: G
            *   Row 5: G
            *   Row 6: G
            *   Total G count = 4.
        *   Magenta (M) vertical line: 2 pixels long (rows 8-9, col 8).
            *   Row 8: M
            *   Row 9: M
            *   Total M count = 2.
    *   **Output:** A 6x6 grid.
        *   Outer ring (Row 0, Row 5, Col 0, Col 5): Blue (B).
        *   Next ring (Row 1, Row 4, Col 1, Col 4): Green (G).
        *   Inner ring (Row 2, Row 3, Col 2, Col 3): Magenta (M).
        *   Wait, the output is 6x6.
        *   Let's check the counts again.
        *   B count = 6.
        *   G count = 4.
        *   M count = 2.
        *   Total colored pixels = 6 + 4 + 2 = 12.
        *   Output grid size: 6x6 = 36 pixels.
        *   Wait, the output grid is filled with colors.
        *   Let's look at the structure of the output.
        *   Outer ring (perimeter of 6x6): 6*4 - 4 = 20 pixels.
        *   Next ring (perimeter of 4x4): 4*4 - 4 = 12 pixels.
        *   Inner ring (perimeter of 2x2): 2*4 - 4 = 4 pixels.
        *   This doesn't match the input counts (6, 4, 2).
        *   Let's re-read the metaphor. "longest cutting defines the outermost garden hedge".
        *   Maybe the length of the cutting determines the *size* of the square it forms?
        *   Or maybe the number of pixels of a specific color determines the *thickness* or *size* of the ring?
        *   Let's look at Example 1 Output again.
            *   B is the outermost ring.
            *   G is the middle ring.
            *   M is the innermost ring.
            *   Input counts: B=6, G=4, M=2.
            *   Output structure:
                *   B ring: 6x6 perimeter.
                *   G ring: 4x4 perimeter (inside B).
                *   M ring: 2x2 perimeter (inside G).
            *   Wait, the input counts match the *side length* of the square rings?
            *   B count = 6. Output B ring is on a 6x6 grid.
            *   G count = 4. Output G ring is on a 4x4 sub-grid.
            *   M count = 2. Output M ring is on a 2x2 sub-grid.
            *   This looks promising. The number of pixels of a color in the input determines the side length of the square ring of that color in the output.
            *   The rings are nested. The largest square (determined by the max count) forms the outer boundary. The next largest forms the next boundary inside, etc.
            *   Let's verify this hypothesis.
            *   Max count = 6 (Blue). So the output grid is 6x6.
            *   Next count = 4 (Green). So the Green ring is inside the Blue ring, effectively forming a 4x4 square boundary.
            *   Next count = 2 (Magenta). So the Magenta ring is inside the Green ring, forming a 2x2 square boundary.
            *   Does this fill the grid?
                *   6x6 grid.
                *   Ring 1 (B): Perimeter of 6x6.
                *   Ring 2 (G): Perimeter of 4x4 (centered).
                *   Ring 3 (M): Perimeter of 2x2 (centered).
                *   Center: 0x0? No, 2x2 perimeter leaves a 0x0 center.
                *   Let's check the output image for Example 1.
                *   Row 0: B B B B B B (6 B's)
                *   Row 1: B G G G G B (B, 4 G's, B) -> Inner width 4.
                *   Row 2: B G M M G B (B, G, 2 M's, G, B) -> Inner width 2.
                *   Row 3:

... [7013 chars truncated]

Task 363: 62b74c02

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A herald's banner unfurls across a great hall, its emblem reflected in the mirro ... [18 chars truncated] MARC valid 3
alt-1 biology A cell's membrane encloses its cytoplasm: the organelles cluster at both ends wh ... [61 chars truncated] MARC valid 2
alt-10 astronomy Twin nebulae drift at the edges of a dark expanse, mirror images of each other, ... [96 chars truncated] fig alone solves
alt-11 ocean/sailing Identical lighthouses mark both ends of a channel, and the water between each pa ... [72 chars truncated] fail
alt-12 electronics A circuit board has identical connector pins at both ends of each trace, and the ... [86 chars truncated] MARC valid 2
alt-13 mythology The gates of a divine realm bear twin guardian carvings — identical sentin ... [103 chars truncated] fail
alt-14 dance Dancers in formation begin and end their routine in the same pose at opposite en ... [108 chars truncated] fail
alt-15 geology A canyon reveals identical strata in its opposing cliff faces, and the sediment ... [85 chars truncated] fail
alt-2 cooking A sandwich is assembled: ornate garnishes bookend each layer, and the filling be ... [54 chars truncated] fail
alt-3 music An orchestra plays a motif, then a single instrument sustains a drone note until ... [45 chars truncated] fig alone solves
alt-4 sports Two teams in matching jerseys stand at opposite ends of the field; the grass bet ... [63 chars truncated] fig alone solves
alt-5 weather Storm fronts converge from both horizons — identical cloud formations appr ... [92 chars truncated] fig alone solves
alt-6 architecture Twin facades face each other across a courtyard, and each floor's corridor betwe ... [58 chars truncated] MARC valid 1
alt-7 warfare An army's vanguard and rearguard carry identical banners; between them, the marc ... [65 chars truncated] MARC valid 3
alt-8 theater The stage has identical wings on left and right — ornate set pieces frame ... [120 chars truncated] fail
alt-9 gardening Identical topiaries bookend a garden path, and each row of the walkway between t ... [60 chars truncated] fig alone solves
original qwen3.5-122b: k=3
"A herald's banner unfurls across a great hall, its emblem reflected in the mirror at the far wall."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (11547 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A "hall" (grid).
*   **Left Edge:** A "narrow heraldic banner" hangs on the left edge.
    *   "Each horizontal stripe bears a distinct coat of arms, framed on both sides by that stripe's own house color."
    *   Looking at the examples, the input grids have non-black pixels on the left side (columns 0, 1, 2 usually) and black pixels (.) on the right.
    *   The "banner" seems to be the non-black part on the left.
    *   "Framed on both sides by that stripe's own house color": This suggests the pattern on the left is symmetric or has a specific structure. Let's look at the examples.
*   **Action:** "The banner is carried in procession across the hall."
    *   "Each stripe leaves a ribbon of its house color trailing behind it".
    *   "When the procession reaches the far wall, a great mirror reflects the banner's image back — an identical copy appears flush against the opposite wall."
    *   "Between the real banner and its reflection, the hall is flooded with each row's house color".
*   **Result:**
    *   "The original banner holds its place at the left wall".
    *   "Its twin gazes back from the right".
    *   "Between them stretches an unbroken field of each row's own heraldic hue".
    *   "Every black stone is now draped in color".

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 4 rows, 12 columns.
        Row 0: `G R G . . . . . . . . .`
        Row 1: `B R B . . . . . . . . .`
        Row 2: `G R G . . . . . . . . .`
        Row 3: `B G B . . . . . . . . .`
    *   Output: 4 rows, 12 columns.
        Row 0: `G R G G G G G G G G R G`
        Row 1: `B R B B B B B B B B R B`
        Row 2: `G R G G G G G G G G R G`
        Row 3: `B G B B B B B B B B G B`
    *   Observation:
        *   The input has 3 non-black columns on the left.
        *   The output has the original 3 columns on the left.
        *   The output has 3 columns on the right that look like a mirror image of the left 3 columns.
            *   Row 0 Left: `G R G`. Right: `R G`. Wait, let's look closer.
            *   Row 0 Output: `G R G` (cols 0-2) ... `G G G G G G` (cols 3-8) ... `R G` (cols 9-10)? No.
            *   Let's check the indices. Width = 12.
            *   Left part: Cols 0, 1, 2. Pattern `G R G`.
            *   Right part: Cols 9, 10, 11. Pattern `G R G`?
                *   Row 0 Output ends with `R G`. Wait, `G R G G G G G G G G R G`.
                *   Indices: 0:G, 1:R, 2:G, 3:G, 4:G, 5:G, 6:G, 7:G, 8:G, 9:G, 10:R, 11:G.
                *   Left block: `G R G`.
                *   Right block: `G R G` (indices 9, 10, 11).
                *   Middle block: `G G G G G G` (indices 3 to 8).
                *   The middle block is filled with the "house color". What is the house color?
                *   In Row 0, the pattern is `G R G`. The outer colors are `G`. The middle is `R`. The "house color" seems to be the color of the outer frame (`G`).
                *   In Row 1, pattern `B R B`. House color `B`. Middle filled with `B`. Right block `B R B`.
                *   In Row 3, pattern `B G B`. House color `B`. Middle filled with `B`. Right block `B G B`.
        *   So the rule seems to be:
            1.  Identify the pattern on the left (non-black columns). Let's say width $W_{pattern}$.
            2.  Identify the "house color". In the examples, the pattern is symmetric: `A B A`. The "house color" is `A`.
            3.  Fill the middle columns (from $W_{pattern}$ to $Width - W_{pattern} - 1$) with the house color.
            4.  Mirror the pattern to the right edge. The rightmost $W_{pattern}$ columns should match the leftmost $W_{pattern}$ columns.
            5.  Wait, let's check the mirroring.
                *   Row 0: Left `G R G`. Right `G R G`.
                *   Row 1: Left `B R B`. Right `B R B`.
                *   Row 3: Left `B G B`. Right `B G B`.
                *   It seems the right side is an exact copy of the left side, not a mirror reflection (flipped horizontally). `G R G` is palindromic anyway.
                *   Let's check Example 2.

*   **Example 2:**
    *   Input: 3 rows, 10 columns.
        Row 0: `A R A . . . . . . .`
        Row 1: `B A B . . . . . . .`
        Row 2: `B A B . . . . . . .`
    *   Output:
        Row 0: `A R A A A A A A R A`
        Row 1: `B A B B B B B B A B`
        Row 2: `B A B B B B B B A B`
    *   Observation:
        *   Width = 10.
        *   Left pattern width = 3 (`A R A`, `B A B`).
        *   Right pattern width = 3.
        *   Middle width = 10 - 3 - 3 = 4.
        *   Row 0: Left `A R A`. Middle `A A A A`. Right `R A`?
            *   Output Row 0: `A R A A A A A A R A`.
            *   Indices: 0:A, 1:R, 2:A. 3:A, 4:A, 5:A, 6:A. 7:R, 8:A? No.
            *   Let's count characters.
            *   `A R A` (3) + `A A A A` 

... [6559 chars truncated]
alt-1 biology qwen3.5-122b: k=2
"A cell's membrane encloses its cytoplasm: the organelles cluster at both ends while the interior fills with the cell's own signature protein."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11613 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A living cell with complex structures pressed against its walls and a hollow interior waiting to be filled with cellular fluid." -> This suggests there are structures on the edges (walls) and empty space in the middle.
*   "The organelles at one wall replicate at the opposite wall" -> This implies symmetry or mirroring. Specifically, the pattern on the left edge appears on the right edge.
*   "the space between floods with the membrane's own essence — the color that defines each layer's boundary." -> This suggests the interior is filled with a specific color.
*   "Grid details: Output matches input dimensions. The pattern block appears at both left and right edges as mirror copies, with all interior cells filled by each row's outermost color." -> This is the most explicit instruction.
    *   Output dimensions = Input dimensions.
    *   Pattern block at left and right edges.
    *   "Mirror copies" might mean the left pattern is copied to the right, or the right pattern is copied to the left, or they are symmetric. Looking at the examples will clarify.
    *   "All interior cells filled by each row's outermost color." -> This means for each row, look at the color at the very left (or right, they should be the same based on the "outermost" description) and fill the middle with that color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G R G . . . . . . . . .
        B R B . . . . . . . . .
        G R G . . . . . . . . .
        B G B . . . . . . . . .
        ```
        Dimensions: 4 rows, 12 columns.
        Left side pattern (first 3 cols): `G R G`, `B R B`, `G R G`, `B G B`.
        Rest are dots (`.`).
    *   Output:
        ```
        G R G G G G G G G G R G
        B R B B B B B B B B R B
        G R G G G G G G G G R G
        B G B B B B B B B B G B
        ```
        Dimensions: 4 rows, 12 columns.
        Row 1: Starts `G R G`, ends `R G`. Wait, let's look closer.
        Input Row 1: `G R G . . . . . . . . .`
        Output Row 1: `G R G G G G G G G G R G`
        The first 3 chars are `G R G`. The last 2 chars are `R G`.
        Wait, the input has `G R G` at the start. The output has `G R G` at the start and `R G` at the end?
        Let's check the middle.
        Output Row 1: `G R G` (3 chars) + `G G G G G G G G` (8 chars) + `R G` (2 chars)? No, total length is 12.
        Let's count: `G R G` (3) + `G G G G G G G G` (8) + `R G` (2) = 13. That's too many.
        Let's count the output string: `G R G G G G G G G G R G`
        Chars: G, R, G, G, G, G, G, G, G, G, R, G. Total 12.
        Indices:
        0: G
        1: R
        2: G
        3: G
        4: G
        5: G
        6: G
        7: G
        8: G
        9: G
        10: R
        11: G
        So the pattern `G R G` is at the start (indices 0, 1, 2).
        The pattern `R G` is at the end (indices 10, 11).
        Wait, `G R G` reversed is `G R G`.
        The input row starts with `G R G`.
        The output row ends with `R G`.
        Is it mirroring the whole block?
        Input block width seems to be 3.
        If I mirror `G R G` to the right side, it would be `G R G`.
        So indices 9, 10, 11 would be `G R G`.
        But the output has `R G` at 10, 11. Index 9 is `G`.
        So indices 9, 10, 11 are `G R G`.
        Let's re-read the output string carefully.
        `G R G G G G G G G G R G`
        0: G
        1: R
        2: G
        3: G
        4: G
        5: G
        6: G
        7: G
        8: G
        9: G
        10: R
        11: G
        So the last 3 chars are `G R G`.
        The first 3 chars are `G R G`.
        The middle 6 chars (indices 3 to 8) are `G`.
        Wait, index 2 is `G`. Index 9 is `G`.
        So the "outermost color" for Row 1 is `G`.
        The interior (indices 3 to 8) is filled with `G`.
        The left edge is `G R G`.
        The right edge is `G R G`.
        Wait, looking at the output string provided in the prompt:
        `G R G G G G G G G G R G`
        Let's count again.
        1: G
        2: R
        3: G
        4: G
        5: G
        6: G
        7: G
        8: G
        9: G
        10: G
        11: R
        12: G
        Total 12 chars.
        Left 3: `G R G`.
        Right 3: `G R G`.
        Middle 6: `G G G G G G`.
        So the rule seems to be: Identify the non-empty block on the left. Copy it to the right (mirrored or direct?).
        In Row 1: Left `G R G`. Right `G R G`. It's a direct copy, not a mirror (since `G R G` is a palindrome).
        Let's check Row 2.
        Input: `B R B . . . . . . . . .`
        Output: `B R B B B B B B B B R B`
        Left 3: `B R B`.
        Right 3: `R B`? No, let's count.
        `B R B` (3) + `B B B B B B` (6) + `R B` (2)?
        Let's count the output string: `B

... [6637 chars truncated]
alt-10 astronomy qwen3.5-122b: fig alone solves
"Twin nebulae drift at the edges of a dark expanse, mirror images of each other, and the void between glows faintly with the spectral signature of each layer's dominant element."
alt-11 ocean/sailing qwen3.5-122b: fail
"Identical lighthouses mark both ends of a channel, and the water between each pair of signal lamps shimmers with the color of the beacons that frame it."
Fail (best cell_acc=0.29 at k=2)
Best Attempt
vs
Expected
Reasoning (11265 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A column of signal lamps stands at the port side, each row's top and bottom lamps matching in color, with open water stretching to starboard."
    *   "Port side" usually means left. "Starboard" means right.
    *   "Column of signal lamps" suggests the left part of the grid has some structure.
    *   "Each row's top and bottom lamps matching in color" suggests that for a given row, the first and last non-black (or specific) elements might define the color. Or perhaps the first and last columns? Let's look at the examples.
    *   "Open water stretching to starboard" suggests the rest of the row is empty (black/dots).
*   "What to do: Erect a mirror lighthouse at starboard. The channel water in each row takes the color of that row's matching beacon lamps."
    *   "Mirror lighthouse at starboard" suggests symmetry or reflection on the right side.
    *   "Channel water in each row takes the color of that row's matching beacon lamps" suggests filling the empty space with a specific color derived from the row.
*   "Grid details: Output same dimensions. Pattern at both edges, gap cells adopt row's edge color."
    *   "Pattern at both edges": The left edge pattern is preserved. The right edge pattern is created.
    *   "Gap cells adopt row's edge color": The empty cells between the left pattern and the right pattern are filled with the color of the edge.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G R G . . . . . . . . .
        B R B . . . . . . . . .
        G R G . . . . . . . . .
        B G B . . . . . . . . .
        ```
        Dimensions: 4 rows, 12 columns.
        Left side pattern: 3 columns wide (e.g., `G R G`).
        Right side: 9 columns of dots.
    *   Output:
        ```
        G R G G G G G G G G R G
        B R B B B B B B B B R B
        G R G G G G G G G G R G
        B G B B B B B B B B G B
        ```
        Dimensions: 4 rows, 12 columns.
        Observation:
        Row 1: `G R G` ... `G R G`. The middle is filled with `G`.
        Row 2: `B R B` ... `B R B`. The middle is filled with `B`.
        Row 3: `G R G` ... `G R G`. The middle is filled with `G`.
        Row 4: `B G B` ... `B G B`. The middle is filled with `B`.
        Wait, looking closely at Row 1 Output: `G R G G G G G G G G R G`.
        The first 3 chars are `G R G`. The last 3 chars are `R G`? No, let's count.
        Input Row 1: `G R G . . . . . . . . .` (12 chars)
        Output Row 1: `G R G G G G G G G G R G` (12 chars)
        Let's check the indices.
        Indices 0, 1, 2 are `G R G`.
        Indices 9, 10, 11 are `G R G`?
        Output string: `G R G G G G G G G G R G`
        Chars: G, R, G, G, G, G, G, G, G, G, R, G.
        Index 0: G
        Index 1: R
        Index 2: G
        Index 3-9: G (7 Gs)
        Index 10: R
        Index 11: G
        So the pattern `G R G` is at the start (indices 0-2) and at the end (indices 9-11).
        The middle (indices 3-9) is filled with `G`.
        Where does `G` come from? It's the color of the first and last element of the pattern `G R G`.
        Row 2: `B R B`. Start `B R B`. End `B R B`. Middle filled with `B`.
        Row 4: `B G B`. Start `B G B`. End `B G B`. Middle filled with `B`.
        So the rule seems to be: Identify the pattern on the left. Mirror it to the right. Fill the space in between with the color of the outer elements of the pattern.

*   **Example 2:**
    *   Input:
        ```
        A R A . . . . . . .
        B A B . . . . . . .
        B A B . . . . . . .
        ```
        Dimensions: 3 rows, 10 columns.
        Left pattern: 3 columns (`A R A`, `B A B`, `B A B`).
    *   Output:
        ```
        A R A A A A A A R A
        B A B B B B B B A B
        B A B B B B B B A B
        ```
        Row 1: `A R A` ... `A R A`. Middle filled with `A`.
        Row 2: `B A B` ... `B A B`. Middle filled with `B`.
        Row 3: `B A B` ... `B A B`. Middle filled with `B`.
        This confirms the hypothesis.
        1. Identify the non-black block on the left. In both examples, it's 3 columns wide.
        2. The first and last characters of this block are the same color (e.g., G..G, B..B, A..A). Let's call this the "Edge Color".
        3. Copy this 3-column block to the rightmost 3 columns of the row.
        4. Fill all columns between the left block and the right block with the "Edge Color".

**3. Analyze the Test Input:**
*   Input:
    ```
    G A A G . . . . . . . . . .
    R B B R . . . . . . . . . .
    B G G B . . . . . . . . . .
    R B B R . . . . . . . . . .
    ```
    Dimensions: 4 rows.
    Let's count columns.
    Row 1: `G A A G` followed by dots.
    `G`, `A`, `A`, `G` -> 4 characters.
    Dots: `.` `.` `.` `.` `.` `.` `.` `.` `.` `.` `.` `.` -> 12 dots?
    Let's count carefully.
    `G A A G . . . 

... [6280 chars truncated]
alt-12 electronics qwen3.5-122b: k=2
"A circuit board has identical connector pins at both ends of each trace, and the copper fill between runs at the voltage level set by each row's termination resistor."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11471 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A pin header sits at the left edge of the PCB, each row's first and last pins carrying the same signal color, with bare substrate extending right."
    *   This implies the input grid has colored cells on the left side (specifically the first few columns) and empty/black cells (represented by '.') on the right.
    *   "each row's first and last pins carrying the same signal color" suggests that for a given row, the leftmost colored block defines the color. Wait, looking at the examples, it seems like there's a pattern on the left.
*   **What to do:** "Solder a matching pin header at the right edge and flood-fill each trace row with the signal color of its terminating pins."
    *   "Matching pin header at the right edge": This implies the pattern on the left is mirrored or repeated on the right.
    *   "Flood-fill each trace row with the signal color of its terminating pins": This implies the empty space between the left pattern and the right pattern gets filled with a specific color.
*   **Grid details:** "Same dimensions. Pattern mirrored at right edge; interior cells filled with each row's border color."
    *   "Same dimensions": Output grid size = Input grid size.
    *   "Pattern mirrored at right edge": The non-empty pattern on the left is copied to the right side.
    *   "Interior cells filled with each row's border color": The empty space between the left pattern and the right pattern is filled with the color of the "border" or "terminating pins".

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G R G . . . . . . . . .
        B R B . . . . . . . . .
        G R G . . . . . . . . .
        B G B . . . . . . . . .
        ```
        Dimensions: 4 rows, 12 columns.
        Left pattern: 3 columns wide (G R G, B R B, etc.).
        Right side: 9 columns of '.'.
    *   Output:
        ```
        G R G G G G G G G G R G
        B R B B B B B B B B R B
        G R G G G G G G G G R G
        B G B B B B B B B B G B
        ```
        Dimensions: 4 rows, 12 columns.
        Left pattern (cols 0-2): `G R G`, `B R B`, `G R G`, `B G B`.
        Right pattern (cols 9-11): `R G`? No, let's look closer.
        Row 0: `G R G` ... `R G`. Wait, the output ends with `R G`. The input started with `G R G`.
        Let's check the indices.
        Input Row 0: `G R G . . . . . . . . .` (Indices 0,1,2 are G,R,G).
        Output Row 0: `G R G G G G G G G G R G`
        Indices 0,1,2: `G R G` (Same as input).
        Indices 9,10,11: `R G`? No, let's count.
        Total length 12.
        Output Row 0: `G` `R` `G` `G` `G` `G` `G` `G` `G` `G` `R` `G`
        Wait, looking at the last 3 chars: `R G`. That's only 2 chars.
        Let's count the characters in the output string provided in the example.
        `G R G G G G G G G G R G` -> 12 characters.
        Indices:
        0: G
        1: R
        2: G
        3: G
        4: G
        5: G
        6: G
        7: G
        8: G
        9: G
        10: R
        11: G
        So the rightmost 3 columns (9, 10, 11) are `G R G`.
        Wait, index 9 is G, 10 is R, 11 is G.
        So the rightmost 3 columns are `G R G`.
        This matches the leftmost 3 columns `G R G`.
        So the pattern is mirrored? Or just copied?
        Left: `G R G`. Right: `G R G`. It's a copy, not a mirror (reversal).
        Let's check Row 1.
        Input: `B R B` ...
        Output: `B R B B B B B B B B R B`
        Left: `B R B`. Right (last 3): `R B`? No.
        Let's count: `B` `R` `B` `B` `B` `B` `B` `B` `B` `B` `R` `B`
        Indices 0,1,2: `B R B`.
        Indices 9,10,11: `R B`?
        Wait, `B` (0), `R` (1), `B` (2).
        `B` (3), `B` (4), `B` (5), `B` (6), `B` (7), `B` (8), `B` (9).
        `R` (10), `B` (11).
        So the last 3 are `B R B`.
        Wait, index 9 is B. Index 10 is R. Index 11 is B.
        So the rightmost 3 columns are `B R B`.
        This matches the leftmost 3 columns `B R B`.
        So the rule seems to be: Copy the non-empty block from the left to the right edge. Fill the middle with the color of the "border".
        What is the "border color"?
        In Row 0: Left is `G R G`. Middle is filled with `G`.
        In Row 1: Left is `B R B`. Middle is filled with `B`.
        In Row 2: Left is `G R G`. Middle is filled with `G`.
        In Row 3: Left is `B G B`. Middle is filled with `B`.
        Wait, Row 3 Input: `B G B`. Output Middle: `B`.
        So the fill color is the color of the *outermost* column of the pattern?
        Row 0: `G R G`. Outer is `G`. Fill is `G`.
        Row 1: `B R B`. Outer is `B`. Fill is `B`.
        Row 3: `B G B`. Outer is `B`. Fill is `B`.
        It seems the fill color is the color of the first column (and last column of the pattern, since they match).
        The pattern

... [6483 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"The gates of a divine realm bear twin guardian carvings — identical sentinels at each threshold — and the hall between is bathed in the aura of each row's guardian spirit."
Fail (best cell_acc=0.29 at k=1)
Best Attempt
vs
Expected
Reasoning (10411 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "Guardian figures stand carved at the left gate": This suggests there is a pattern or structure on the left side of the grid.
*   "each tier's outermost figures sharing a divine color": This implies that for each row (tier), the leftmost elements have a specific color.
*   "with an empty hall stretching toward the far gate": The middle part of the grid is empty (represented by dots `.`).
*   "Identical carvings appear at the far gate": The pattern on the left is replicated on the right side of the grid.
*   "each tier's hall glows with the aura color of its guardian figures": The empty space in the middle is filled with the color of the "guardian figures".
*   "Grid details: Dimensions unchanged. Pattern at both edges; gap filled per-row with the border color."

**2. Analyze the Training Example:**
*   **Input:**
    ```
    G R G . . . . . . . . .
    B R B . . . . . . . . .
    G R G . . . . . . . . .
    B G B . . . . . . . . .
    ```
    Dimensions: 4 rows, 12 columns.
    Left side pattern:
    Row 0: `G R G`
    Row 1: `B R B`
    Row 2: `G R G`
    Row 3: `B G B`
    Rest are `.` (black/empty).

*   **Output:**
    ```
    G R G G G G G G G G R G
    B R B B B B B B B B R B
    G R G G G G G G G G R G
    B G B B B B B B B B G B
    ```
    Dimensions: 4 rows, 12 columns.
    Observation:
    Row 0: Starts with `G R G`, ends with `R G`. Wait, let's look closer.
    Input Row 0: `G R G . . . . . . . . .` (3 non-dot chars)
    Output Row 0: `G R G G G G G G G G R G`
    The first 3 chars are `G R G`.
    The last 2 chars are `R G`.
    The middle chars are `G`.
    Wait, let's count.
    Input width = 12.
    Output width = 12.
    Row 0 Input: `G`, `R`, `G`, then 9 dots.
    Row 0 Output: `G`, `R`, `G`, `G`, `G`, `G`, `G`, `G`, `G`, `G`, `R`, `G`.
    It looks like the left pattern `G R G` is mirrored or repeated on the right?
    Let's check the right side of the output.
    Last 3 chars: `G R G`.
    Wait, looking at the output string provided: `G R G G G G G G G G R G`.
    Indices:
    0: G
    1: R
    2: G
    3: G
    4: G
    5: G
    6: G
    7: G
    8: G
    9: G
    10: R
    11: G
    So the rightmost 3 chars are `R G`? No, index 10 is R, index 11 is G.
    Wait, `G R G` is length 3.
    If the pattern is mirrored, the right side should be `G R G`.
    Let's check the last 3 chars of Output Row 0: `G`, `R`, `G`.
    Wait, the text says `G R G G G G G G G G R G`.
    Let's count characters in the string provided in the example.
    `G R G G G G G G G G R G`
    1 2 3 4 5 6 7 8 9 10 11 12
    Chars: G, R, G, G, G, G, G, G, G, G, R, G.
    Last 3: G, R, G.
    First 3: G, R, G.
    Middle: G, G, G, G, G, G, G, G (8 Gs).
    Total length: 3 + 8 + 3 = 14? No.
    Let's count spaces.
    `G R G G G G G G G G R G`
    G (1)
    R (2)
    G (3)
    G (4)
    G (5)
    G (6)
    G (7)
    G (8)
    G (9)
    G (10)
    R (11)
    G (12)
    Okay, so the output row is 12 characters long.
    First 3: `G R G`.
    Last 3: `R G`? No, indices 9, 10, 11.
    Index 9: G
    Index 10: R
    Index 11: G
    So the last 3 are `G R G`.
    Wait, looking at the string `G R G G G G G G G G R G`.
    Let's parse it carefully.
    Pos 0: G
    Pos 1: R
    Pos 2: G
    Pos 3: G
    Pos 4: G
    Pos 5: G
    Pos 6: G
    Pos 7: G
    Pos 8: G
    Pos 9: G
    Pos 10: R
    Pos 11: G
    So the sequence is `G R G` followed by 7 `G`s followed by `R G`.
    Wait, 3 + 7 + 2 = 12.
    So the right side is `R G`.
    But the left side is `G R G`.
    This looks like a reflection.
    Left: `G R G`.
    Right: `G R G` reversed? `G R G` is a palindrome.
    Let's check Row 1.
    Input: `B R B . . . . . . . . .`
    Output: `B R B B B B B B B B R B`
    Pos 0: B
    Pos 1: R
    Pos 2: B
    Pos 3-9: B (7 Bs)
    Pos 10: R
    Pos 11: B
    So Right side is `R B`.
    Left side is `B R B`.
    It seems the pattern on the left is `X Y X`.
    The pattern on the right is `Y X`.
    Wait, if the left is `B R B`, the right is `R B`.
    If the left is `G R G`, the right is `R G`.
    If the left is `B G B`, the right is `G B`.
    It seems the right side is the left side pattern *without the first character*? Or is it a mirror image starting from the second character?
    Let's look at the "fill" color.
    Row 0: Left `G R G`. Fill is `G`.
    Row 1: Left `B R B`. Fill is `B`.
    Row 2: Left `G R G`. Fill is `G`.
    Row 3: Left `B G B`. Fill is `B`.
    The fill color seems to be the color of the *outermost* figures on the left.
    In `G R G`, outermost is `G`. Fill is `G`.
    In `B R B`, outermost is `B`. Fill is `B`.
    In `B G B`, outermost is `B`. Fill is `B`.
    So the rule for the middle is: Fill with the color of the first column (or the outermost color of the pattern).

    Now about the right side pattern.
    Input width = 12.
    Left pattern 

... [5414 chars truncated]
alt-14 dance qwen3.5-122b: fail
"Dancers in formation begin and end their routine in the same pose at opposite ends of the stage; between movements, each row holds a tableau in the color of the dancers' starting position."
Fail (best cell_acc=0.29 at k=1)
Best Attempt
vs
Expected
Reasoning (11967 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A formation of dancers poses at stage left, each row's lead and anchor wearing matching costumes, with empty stage stretching to the right."
    *   "Stage left" usually implies the left side of the grid.
    *   "Formation of dancers" implies a pattern of colored cells.
    *   "Each row's lead and anchor wearing matching costumes" suggests the first and last non-empty cells in a row might be the same color, or there's a specific pattern at the start and end of the non-empty section.
    *   "Empty stage stretching to the right" implies the rest of the row is filled with a background color (likely black/dot `.`).
*   **What to do:** "The formation reappears at stage right in mirror. Each row's empty stage between fills with the sustained color of that row's lead dancer."
    *   "Reappears at stage right in mirror": This suggests the pattern on the left is copied to the right side of the grid, possibly mirrored.
    *   "Each row's empty stage between fills with the sustained color of that row's lead dancer": The space between the left pattern and the right pattern gets filled with the color of the first cell (lead dancer) of that row.
*   **Grid details:** "Same grid dimensions. Pattern at left and right; interior cells take each row's first color."
    *   This confirms the output grid has the same dimensions as the input.
    *   Left side: Original pattern.
    *   Right side: Mirrored pattern.
    *   Middle: Filled with the first color of the row.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
G R G . . . . . . . . .
B R B . . . . . . . . .
G R G . . . . . . . . .
B G B . . . . . . . . .
```
Dimensions: 4 rows, 12 columns.
Row 1: `G R G` followed by 9 dots.
Row 2: `B R B` followed by 9 dots.
Row 3: `G R G` followed by 9 dots.
Row 4: `B G B` followed by 9 dots.

Output:
```
G R G G G G G G G G R G
B R B B B B B B B B R B
G R G G G G G G G G R G
B G B B B B B B B B G B
```
Dimensions: 4 rows, 12 columns.

Let's look at Row 1:
Input: `G R G . . . . . . . . .`
Output: `G R G G G G G G G G R G`
Left part: `G R G` (matches input start).
Right part: `R G`? No, the end is `R G`. Wait, let's look closer.
Output Row 1: `G R G` (indices 0,1,2) ... `R G` (indices 10,11).
The middle is filled with `G`.
The input pattern is `G R G`.
The output ends with `R G`. This looks like the reverse of `G R`? Or is it the reverse of the whole pattern `G R G`?
Reverse of `G R G` is `G R G`.
If the right side is a mirror of the left side, it should be `G R G`.
Let's check the indices.
Input width = 12.
Left pattern length = 3 (`G R G`).
Right pattern length = 2 (`R G`)? Or is it 3 (`G R G`)?
Output Row 1: `G R G` (3 chars) + `G G G G G G G G` (8 chars) + `R G` (2 chars)? Total 13? No.
Let's count characters in Output Row 1:
`G R G G G G G G G G R G`
1 2 3 4 5 6 7 8 9 10 11 12
Indices:
0: G
1: R
2: G
3: G
4: G
5: G
6: G
7: G
8: G
9: G
10: R
11: G

So the left part is `G R G` (indices 0-2).
The right part is `R G` (indices 10-11).
The middle is `G` (indices 3-9).
Wait, the input pattern was `G R G`.
If the right side is a mirror, usually it means the pattern is reflected.
If the pattern is `G R G`, a mirror reflection would be `G R G`.
But here the right end is `R G`.
Let's look at Row 2:
Input: `B R B`
Output: `B R B B B B B B B B R B`
Left: `B R B` (0-2)
Right: `R B` (10-11)
Middle: `B` (3-9)
Row 3: Same as Row 1.
Row 4:
Input: `B G B`
Output: `B G B B B B B B B B G B`
Left: `B G B` (0-2)
Right: `G B` (10-11)
Middle: `B` (3-9)

Observation:
The input pattern seems to be the first 3 columns.
The output keeps the first 3 columns.
The output fills the middle columns (3 to 9) with the color of the *first* column (Lead dancer).
The output fills the last 2 columns (10, 11) with the *reverse* of the first 2 columns of the pattern?
Input Row 1: `G R G`. First 2: `G R`. Reverse: `R G`. Matches output end.
Input Row 2: `B R B`. First 2: `B R`. Reverse: `R B`. Matches output end.
Input Row 4: `B G B`. First 2: `B G`. Reverse: `G B`. Matches output end.

Wait, why only the first 2 columns for the mirror?
The input pattern length is 3.
The grid width is 12.
Left pattern takes 3 cols.
Right pattern takes 2 cols?
Why 2?
Maybe the "anchor" is the last non-dot cell in the input?
In Input Row 1: `G R G`. Anchor is `G`. Lead is `G`.
In Output Row 1: End is `R G`.
If the pattern is `G R G`, and it mirrors, maybe the overlap is handled differently?
Or maybe the "mirror" is just the non-lead part?
Let's re-read the metaphor: "The formation reappears at stage right in mirror."
"Each row's empty stage between fills with the sustained color of that row's lead dancer."
"Pattern at left and right; interior cells take each row's first color."

Let's look at the "Test Input" to see if it clarifies the dimensions.
Test Input:
```
G A A G . . . . . . . . . .


... [6985 chars truncated]
alt-15 geology qwen3.5-122b: fail
"A canyon reveals identical strata in its opposing cliff faces, and the sediment floor between them is composed of whatever mineral defines each stratum's outer rind."
Fail (best cell_acc=0.29 at k=2)
Best Attempt
vs
Expected
Reasoning (12292 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A cliff face on the left shows layered strata, each layer's top and bottom surfaces sharing a mineral color, with an eroded gap stretching to the right."
    *   This suggests the input grid has a pattern on the left side (the "cliff face") and empty space (black/dots) on the right side (the "eroded gap").
    *   "Layered strata" implies rows.
    *   "Mineral color" implies the colors present in the non-empty part of the row.
*   **What to do:** "An identical cliff face is exposed at the right edge. The canyon floor at each layer's depth fills with the mineral color of that stratum's outer rind."
    *   "Identical cliff face is exposed at the right edge": This suggests mirroring or repeating the pattern found on the left to the right edge.
    *   "Canyon floor at each layer's depth fills with the mineral color of that stratum's outer rind": This suggests filling the gap between the left pattern and the right pattern with a specific color.
    *   "Outer rind": This likely refers to the color at the edge of the pattern on the left.
*   **Grid details:** "Output same size. Pattern mirrored at right edge; gap cells filled per-row with border color."
    *   "Output same size": The dimensions of the output grid match the input grid.
    *   "Pattern mirrored at right edge": The pattern on the left is reflected or copied to the right side. Looking at the examples will clarify if it's a mirror or a copy.
    *   "Gap cells filled per-row with border color": The empty cells between the left pattern and the right pattern are filled with the color of the border of the pattern.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G R G . . . . . . . . .
        B R B . . . . . . . . .
        G R G . . . . . . . . .
        B G B . . . . . . . . .
        ```
        Dimensions: 4 rows, 12 columns.
        Left pattern (cols 0-2): `G R G`, `B R B`, `G R G`, `B G B`.
        Right side (cols 3-11): All `.` (black).
    *   Output:
        ```
        G R G G G G G G G G R G
        B R B B B B B B B B R B
        G R G G G G G G G G R G
        B G B B B B B B B B G B
        ```
    *   Observation:
        *   Row 0: Input `G R G . . . . . . . . .` -> Output `G R G G G G G G G G R G`.
            *   Left part: `G R G`.
            *   Right part: `R G`. Wait, looking closely at the end.
            *   Let's check the indices.
            *   Input width = 12.
            *   Output Row 0: `G R G` (indices 0-2) ... `R G` (indices 10-11).
            *   The middle part (indices 3-9) is filled with `G`.
            *   The color `G` is the color of the last column of the left pattern (index 2).
            *   The right edge pattern is `R G`. This looks like the reverse of `G R`? Or is it `G R G` mirrored?
            *   Let's look at the structure.
            *   Left block: `G R G`.
            *   Right block: `R G`.
            *   Wait, the output ends with `R G`. The input starts with `G R G`.
            *   If it's a mirror of the whole row: `G R G` mirrored is `G R G`.
            *   If it's a mirror of the non-empty part: `G R G` -> `G R G`.
            *   Let's look at the output again: `G R G G G G G G G G R G`.
            *   Indices:
                0: G
                1: R
                2: G
                3: G
                4: G
                5: G
                6: G
                7: G
                8: G
                9: G
                10: R
                11: G
            *   The rightmost 2 columns are `R G`. The leftmost 3 columns are `G R G`.
            *   This looks like the left pattern `G R G` is placed at the start. The right pattern is `R G` placed at the end.
            *   Wait, `G R G` reversed is `G R G`.
            *   Maybe the "cliff face" is defined by the non-black pixels.
            *   In Row 0, non-black is `G R G`.
            *   In Output Row 0, the rightmost pixels are `R G`.
            *   Why `R G`?
            *   Let's look at Row 1: `B R B` -> `B R B B B B B B B B R B`.
                *   Left: `B R B`.
                *   Right: `R B`.
                *   Middle filled with `B`.
            *   Row 3: `B G B` -> `B G B B B B B B B B G B`.
                *   Left: `B G B`.
                *   Right: `G B`.
                *   Middle filled with `B`.
            *   Pattern hypothesis:
                *   Identify the non-black segment on the left. Let's say it has length $L$.
                *   The output keeps this segment at the start.
                *   The output places a segment of length $L-1$ at the end?
                *   Row 0: Left `G R G` (len 3). Right `R G` (len 2).
                *   Row 1: Left `B R B` (len 3). Right `R B` (len 2).
                *   Row 3: Left `B G B` (len 3). Rig

... [7313 chars truncated]
alt-2 cooking qwen3.5-122b: fail
"A sandwich is assembled: ornate garnishes bookend each layer, and the filling between is simply the bread that holds the row together."
Fail (best cell_acc=0.29 at k=1)
Best Attempt
vs
Expected
Reasoning (11512 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "Ingredients are stacked on the left side of the cutting board, each row's first and last morsels matching in flavor, with an empty counter stretching to the right."
    *   This suggests the input grid has data on the left and empty space (black/dots) on the right.
    *   "First and last morsels matching in flavor" implies the first and last non-empty cells in a row are the same color.
*   "What to do: Duplicate the garnish arrangement at the far end of the counter and spread each layer's binding ingredient — the flavor of its bookends — across the gap between."
    *   "Duplicate the garnish arrangement at the far end": This likely means copying the pattern found on the left to the right side.
    *   "Spread each layer's binding ingredient — the flavor of its bookends — across the gap between": This suggests filling the empty space between the left pattern and the right pattern with the color of the "bookends" (the first and last non-empty cells of the row).
*   "Grid details: Same dimensions as input. Pattern appears at left and right edges; all black cells become the border color of their row."
    *   This confirms the output grid has the same dimensions.
    *   The "Pattern appears at left and right edges": The input has a pattern on the left. The output should have this pattern on the left *and* on the right.
    *   "All black cells become the border color of their row": The empty space (black/dots) in the middle gets filled with the color of the row's border (the first/last non-black cell).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G R G . . . . . . . . .
        B R B . . . . . . . . .
        G R G . . . . . . . . .
        B G B . . . . . . . . .
        ```
        Dimensions: 4 rows, 12 columns.
        Row 1: `G R G` followed by 9 dots. First non-dot is `G`, last non-dot is `G`.
        Row 2: `B R B` followed by 9 dots. First non-dot is `B`, last non-dot is `B`.
        Row 3: `G R G` followed by 9 dots. First non-dot is `G`, last non-dot is `G`.
        Row 4: `B G B` followed by 9 dots. First non-dot is `B`, last non-dot is `B`.
    *   Output:
        ```
        G R G G G G G G G G R G
        B R B B B B B B B B R B
        G R G G G G G G G G R G
        B G B B B B B B B B G B
        ```
        Dimensions: 4 rows, 12 columns.
        Row 1: `G R G` (left pattern) + `G G G G G G G G` (fill) + `R G` (right pattern?). Wait, let's look closer.
        The output row 1 is `G R G G G G G G G G R G`.
        Left part: `G R G`.
        Right part: `R G`.
        Middle part: `G G G G G G G G`.
        Wait, the input row 1 was `G R G . . . . . . . . .`.
        The output row 1 is `G R G G G G G G G G R G`.
        Let's check the indices.
        Input length: 12.
        Output length: 12.
        Input Row 1: `G`, `R`, `G`, `.`...
        Output Row 1: `G`, `R`, `G`, `G`, `G`, `G`, `G`, `G`, `G`, `G`, `R`, `G`.
        It looks like the pattern `G R G` is mirrored or repeated?
        Actually, looking at the description: "Duplicate the garnish arrangement at the far end of the counter".
        If the input pattern is `G R G` (length 3), and the grid width is 12.
        The output has `G R G` at the start.
        The output has `R G` at the end? No, `R G` is the last two chars.
        Let's look at the "fill" logic. "Spread each layer's binding ingredient — the flavor of its bookends — across the gap between."
        Bookends of Row 1 are `G` and `G`. So the fill color is `G`.
        The output row 1 is `G R G` + `G`s + `R G`.
        Wait, `G R G` is 3 chars. `R G` is 2 chars. Total 5 chars. 12 - 5 = 7 chars of `G`.
        Let's count the `G`s in the middle of Output Row 1: `G R G` (3) + `G G G G G G G` (7) + `R G` (2) = 12.
        Wait, the output string is `G R G G G G G G G G R G`.
        Indices:
        0: G
        1: R
        2: G
        3: G
        4: G
        5: G
        6: G
        7: G
        8: G
        9: G
        10: R
        11: G
        So indices 0-2 are `G R G`. Indices 10-11 are `R G`. Indices 3-9 are `G`.
        Why `R G` at the end?
        Maybe the pattern is symmetric? `G R G` is symmetric.
        If I mirror `G R G`, I get `G R G`.
        If I place `G R G` at the start and `G R G` at the end, I would have `G R G` ... `G R G`.
        But the output ends with `R G`.
        Let's look at Row 2: `B R B` ... `B R B`.
        Output Row 2: `B R B B B B B B B B R B`.
        Start: `B R B`. End: `R B`. Middle: `B`s.
        Row 3: `G R G` ... `G R G`.
        Output Row 3: `G R G G G G G G G G R G`. Same as Row 1.
        Row 4: `B G B` ... `B G B`.
        Output Row 4: `B G B B B B B B B B G B`.
        Start: `B G B`. End: `G B`. Middle: `B`s.

    *   **Hypothesis:** The input contains a

... [6575 chars truncated]
alt-3 music qwen3.5-122b: fig alone solves
"An orchestra plays a motif, then a single instrument sustains a drone note until the motif returns in retrograde at the coda."
alt-4 sports qwen3.5-122b: fig alone solves
"Two teams in matching jerseys stand at opposite ends of the field; the grass between is painted in each lane's team color for the home stretch."
alt-5 weather qwen3.5-122b: fig alone solves
"Storm fronts converge from both horizons — identical cloud formations approach from east and west, and the sky between takes on the hue of each layer's pressure band."
alt-6 architecture qwen3.5-122b: k=1
"Twin facades face each other across a courtyard, and each floor's corridor between them is tiled in the color of that story's cornerstone."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11824 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A decorated facade stands at the left edge of the blueprint, each floor's first and last bricks sharing a color, with an empty lot stretching rightward."
    *   This implies the input grid has a pattern on the left side (columns 0 and 1, or maybe just column 0 and 1?).
    *   "each floor's first and last bricks sharing a color" -> In the input, the first column (index 0) and the second column (index 1) seem to define the pattern. Wait, looking at the examples might clarify.
    *   "empty lot stretching rightward" -> The rest of the grid is filled with black (.) or empty space.
*   "What to do: Erect a mirror-image facade at the right boundary and pave each floor's corridor with the cornerstone color that frames that level."
    *   "Erect a mirror-image facade at the right boundary" -> The pattern on the left is mirrored to the right side.
    *   "pave each floor's corridor with the cornerstone color that frames that level" -> The space between the left facade and the right facade (the "corridor") is filled with a specific color.
    *   "cornerstone color that frames that level" -> This likely refers to the color of the bricks at the edges of that row.
*   "Grid details: Same dimensions. Pattern at both edges; interior filled per-row with border color."
    *   Output dimensions match input dimensions.
    *   Left edge pattern remains.
    *   Right edge pattern is a mirror of the left edge pattern.
    *   Interior (between left and right edges) is filled with the color of the border bricks for that specific row.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
Row 0: `G R G . . . . . . . . .` (Length 12)
Row 1: `B R B . . . . . . . . .`
Row 2: `G R G . . . . . . . . .`
Row 3: `B G B . . . . . . . . .`

Output:
Row 0: `G R G G G G G G G G R G`
Row 1: `B R B B B B B B B B R B`
Row 2: `G R G G G G G G G G R G`
Row 3: `B G B B B B B B B B G B`

Observations:
*   Input width: 12. Output width: 12.
*   Input Left Pattern: Columns 0, 1, 2 seem to be `G R G`, `B R B`, `G R G`, `B G B`.
    *   Wait, let's look closer.
    *   Row 0 Input: `G R G . . .`
    *   Row 0 Output: `G R G G G G G G G G R G`
    *   The output starts with `G R G`.
    *   The output ends with `R G`. Wait, `G R G` at start, `R G` at end?
    *   Let's check the indices.
    *   Input Row 0: `G`(0), `R`(1), `G`(2), `.`(3)...
    *   Output Row 0: `G`(0), `R`(1), `G`(2), `G`(3), `G`(4), `G`(5), `G`(6), `G`(7), `G`(8), `G`(9), `R`(10), `G`(11).
    *   It looks like the first 3 columns `G R G` are preserved.
    *   The last 2 columns are `R G`.
    *   The middle columns (3 to 9) are filled with `G`.
    *   Why `G`? The first column is `G`, the last column is `G`. The "cornerstone color that frames that level" might be the color of the first column? Or the color of the outermost bricks?
    *   Let's look at Row 1.
    *   Input: `B R B . . .`
    *   Output: `B R B B B B B B B B R B`
    *   First 3: `B R B`. Last 2: `R B`. Middle filled with `B`.
    *   Row 3:
    *   Input: `B G B . . .`
    *   Output: `B G B B B B B B B B G B`
    *   First 3: `B G B`. Last 2: `G B`. Middle filled with `B`.

    *   Hypothesis 1: The input defines a "frame" on the left. The width of this frame seems to be 3 columns based on the examples? Or maybe it's just the first column and the second column?
    *   Let's re-read the metaphor: "each floor's first and last bricks sharing a color".
    *   In Input Row 0: `G R G`. First is G, Last (of the pattern part) is G. They share a color.
    *   In Input Row 1: `B R B`. First is B, Last is B.
    *   In Input Row 3: `B G B`. First is B, Last is B.
    *   So the input pattern is 3 columns wide: `A B A`.
    *   The transformation creates a symmetric structure.
    *   Output Row 0: `G R G` ... `R G`.
    *   Wait, the output ends with `R G`. The input started with `G R G`.
    *   If it's a mirror image at the right boundary:
        *   Left side: `G R G`
        *   Right side (mirrored): `G R G` reversed? `G R G`.
        *   If the right side is `G R G`, the last 3 columns would be `G R G`.
        *   But the output ends with `R G`. The last column is `G`. The second to last is `R`.
        *   So the right edge is `R G`.
        *   Let's check the indices again.
        *   Width = 12.
        *   Left Pattern: Cols 0, 1, 2. (`G R G`)
        *   Right Pattern: Cols 10, 11. (`R G`)
        *   Wait, is the right pattern a mirror of the left?
        *   Left: `G R G`. Mirror: `G R G`.
        *   If placed at the right edge (cols 9, 10, 11), it would be `G R G`.
        *   But the output has `R G` at cols 10, 11. Col 9 is `G`.
        *   So cols 9, 10, 11 are `G R G`.
        *   Let's check Output Row 0 again: `G R G G G G G G G G R G`.
        *   Indices:
            0: G
            1: 

... [6854 chars truncated]
alt-7 warfare qwen3.5-122b: k=3
"An army's vanguard and rearguard carry identical banners; between them, the marching column flies each regiment's flag color in an unbroken line."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (11374 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A formation of units is arrayed at the left flank, each row's leading and trailing soldiers bearing the same standard, with open ground ahead."
    *   This suggests there is a pattern on the left side of the grid.
    *   "Leading and trailing soldiers bearing the same standard" implies the first and last non-empty cells in a row (or the boundaries of the pattern) have the same color.
    *   "Open ground ahead" implies empty space (black/dots) to the right.
*   "What to do: Station an identical formation at the far flank, and fill the ground between with each regiment's standard color — an unbroken line of banners."
    *   "Station an identical formation at the far flank": Copy the pattern from the left to the right side of the grid.
    *   "Fill the ground between with each regiment's standard color": The space between the original pattern and the copied pattern should be filled with a specific color.
    *   "Each regiment's standard color": This likely refers to the color of the "leading and trailing soldiers" mentioned earlier. In the examples, the first and last columns of the pattern seem to define this color.
    *   "An unbroken line of banners": The fill should be continuous.
*   "Grid details: Output matches input size. Pattern duplicated at right; gap cells take each row's edge color."
    *   Output dimensions = Input dimensions.
    *   The pattern on the left is duplicated on the right.
    *   The gap (empty space) is filled with the color found at the edges of the pattern in that specific row.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G R G . . . . . . . . .
        B R B . . . . . . . . .
        G R G . . . . . . . . .
        B G B . . . . . . . . .
        ```
        Grid size: 4 rows x 12 columns.
        Pattern width: 3 columns (G R G, B R B, etc.).
        Empty space: 9 columns.
    *   Output:
        ```
        G R G G G G G G G G R G
        B R B B B B B B B B R B
        G R G G G G G G G G R G
        B G B B B B B B B B G B
        ```
    *   Observation:
        *   Row 1: Pattern `G R G`. Last char is `G`. First char is `G`. The fill is `G`. The pattern is repeated at the end. The output row is `G R G` + `G`x8 + `R G`. Wait, let's look closer.
        *   Input Row 1: `G R G . . . . . . . . .` (Length 12)
        *   Output Row 1: `G R G G G G G G G G R G`
        *   The pattern `G R G` is at the start (indices 0, 1, 2).
        *   The pattern `G R G` is at the end (indices 9, 10, 11).
        *   The middle part (indices 3 to 8) is filled with `G`.
        *   Why `G`? Because the first and last elements of the pattern `G R G` are `G`.
        *   Row 2: `B R B`. First/Last `B`. Fill `B`. Output: `B R B` + `B`x8 + `R B`.
        *   Row 4: `B G B`. First/Last `B`. Fill `B`. Output: `B G B` + `B`x8 + `G B`.
    *   Rule Hypothesis:
        1.  Identify the non-empty block on the left. Let's say it spans columns $0$ to $k-1$.
        2.  Identify the color $C$ of the first and last column of this block (they seem to be the same in the examples).
        3.  Copy the block to the right side, ending at the last column of the grid. So it occupies columns $W-k$ to $W-1$, where $W$ is grid width.
        4.  Fill the columns between $k$ and $W-k-1$ with color $C$.

*   **Example 2:**
    *   Input:
        ```
        A R A . . . . . . .
        B A B . . . . . . .
        B A B . . . . . . .
        ```
        Grid size: 3 rows x 10 columns.
        Pattern width: 3 columns (`A R A`, `B A B`).
    *   Output:
        ```
        A R A A A A A A R A
        B A B B B B B B A B
        B A B B B B B B A B
        ```
    *   Observation:
        *   Row 1: `A R A`. Edge color `A`. Fill `A`.
        *   Row 2: `B A B`. Edge color `B`. Fill `B`.
        *   Pattern `A R A` is at start (0-2) and end (7-9).
        *   Middle (3-6) filled with `A`.
        *   Matches hypothesis.

*   **Example 3:**
    *   Input:
        ```
        R G A R . . . . . . . . . .
        R A A R . . . . . . . . . .
        R A G R . . . . . . . . . .
        ```
        Grid size: 3 rows x 14 columns.
        Pattern width: 4 columns (`R G A R`, etc.).
    *   Output:
        ```
        R G A R R R R R R R R G A R
        R A A R R R R R R R R A A R
        R A G R R R R R R R R A G R
        ```
    *   Observation:
        *   Row 1: `R G A R`. Edge color `R`. Fill `R`.
        *   Pattern at start (0-3) and end (10-13).
        *   Middle (4-9) filled with `R`.
        *   Matches hypothesis.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Pattern Block:** The contiguous non-empty cells starting from the left edge of the grid.
    *   **Edge Color:** The color of the first and last cell of the Pattern Block in a given row. (In all examples, these ma

... [6395 chars truncated]
alt-8 theater qwen3.5-122b: fail
"The stage has identical wings on left and right — ornate set pieces frame both sides — and between them, each row of the stage floor glows under a spotlight matching its wing's trim color."
Fail (best cell_acc=0.29 at k=1)
Best Attempt
vs
Expected
Reasoning (12472 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A set piece stands in the left wing, each row trimmed with a consistent border color, and the stage extends bare to the opposite wing."
    *   "Set piece stands in the left wing": There is a pattern on the left side of the grid.
    *   "Each row trimmed with a consistent border color": The left pattern seems to define a color for that row.
    *   "Stage extends bare to the opposite wing": The right side of the grid is empty (black/dots).
*   "What to do: Build a mirror set piece in the right wing; flood each row of the bare stage with that row's trim color spotlight."
    *   "Build a mirror set piece in the right wing": The pattern on the left should be mirrored on the right side.
    *   "Flood each row of the bare stage with that row's trim color spotlight": The empty space in the middle should be filled with a specific color associated with that row.
*   "Grid details: Same dimensions. Pattern at both edges, interior cells filled with each row's border color."
    *   This clarifies the output structure.
    *   Left edge: Original pattern.
    *   Right edge: Mirrored pattern.
    *   Interior: Filled with a specific color.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    G R G . . . . . . . . .
    B R B . . . . . . . . .
    G R G . . . . . . . . .
    B G B . . . . . . . . .
    ```
    *   Dimensions: 4 rows, 12 columns.
    *   Left pattern (columns 0-2):
        Row 0: G R G
        Row 1: B R B
        Row 2: G R G
        Row 3: B G B
    *   Right side (columns 3-11): All dots (black).
*   **Output:**
    ```
    G R G G G G G G G G R G
    B R B B B B B B B B R B
    G R G G G G G G G G R G
    B G B B B B B B B B G B
    ```
    *   Dimensions: 4 rows, 12 columns.
    *   Left pattern (columns 0-2): Same as input.
    *   Right pattern (columns 9-11):
        Row 0: R G (Wait, let's look closer).
        Input Row 0: G R G . . . . . . . . .
        Output Row 0: G R G G G G G G G G R G
        Let's check the indices.
        Input width = 12.
        Output width = 12.
        Left pattern width = 3.
        Right pattern width = 3.
        Middle width = 12 - 3 - 3 = 6.
        Output Row 0: `G R G` (Left) `G G G G G G` (Middle) `R G` (Right?? No, wait).
        Let's look at the Output Row 0 again: `G R G G G G G G G G R G`
        Indices:
        0: G
        1: R
        2: G
        3: G
        4: G
        5: G
        6: G
        7: G
        8: G
        9: G
        10: R
        11: G
        Wait, the right side is `R G`? Or is it `G R G` mirrored?
        Input Left: `G R G`. Mirror of `G R G` is `G R G`.
        Output Right (last 3 chars): `G R G`.
        Let's check the string provided in the example output: `G R G G G G G G G G R G`
        Count: 12 chars.
        0-2: `G R G`
        3-9: `G G G G G G G` (7 chars)
        10-11: `R G`
        This doesn't look like a symmetric mirror of width 3.
        Let's re-read the output string carefully.
        `G R G G G G G G G G R G`
        Chars: G, R, G, G, G, G, G, G, G, G, R, G.
        Total 12 chars.
        Left 3: G R G.
        Right 3: G R G.
        Middle 6: G G G G G G.
        Wait, looking at the string `G R G G G G G G G G R G`:
        Index 0: G
        Index 1: R
        Index 2: G
        Index 3: G
        Index 4: G
        Index 5: G
        Index 6: G
        Index 7: G
        Index 8: G
        Index 9: G
        Index 10: R
        Index 11: G
        So the rightmost 3 are `G R G`.
        The middle 6 are `G G G G G G`.
        The leftmost 3 are `G R G`.
        So the pattern is: Left Pattern + Middle Fill + Right Pattern (Mirrored).
        Wait, `G R G` mirrored is `G R G`.
        So the right edge is `G R G`.
        The middle is filled with `G`.
        Where does `G` come from?
        Input Row 0: `G R G`. The "border color" or "trim color".
        The description says "each row trimmed with a consistent border color".
        In `G R G`, the outer colors are `G`. The inner is `R`.
        In `B R B`, the outer colors are `B`. The inner is `R`.
        In `G R G`, outer `G`.
        In `B G B`, outer `B`.
        The middle fill color seems to be the color of the outer columns of the left pattern.
        Let's check Row 1:
        Input: `B R B`
        Output: `B R B B B B B B B B R B`
        Left: `B R B`
        Right: `B R B`
        Middle: `B B B B B B` (6 Bs).
        So the fill color is `B`.
        Row 2:
        Input: `G R G`
        Output: `G R G G G G G G G G R G`
        Fill: `G`.
        Row 3:
        Input: `B G B`
        Output: `B G B B B B B B B B G B`
        Left: `B G B`
        Right: `B G B`
        Middle: `B B B B B B` (6 Bs).
        Fill: `B`.

    *   **Hypothesis:**
        1.  Identify the width of the "set piece" on the left. In the example, it's 3 c

... [7475 chars truncated]
alt-9 gardening qwen3.5-122b: fig alone solves
"Identical topiaries bookend a garden path, and each row of the walkway between them is mulched in the color of the hedgerow that borders it."

Task 386: 67e8384a

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A stained-glass window unfolds its hidden reflections when the cathedral doors s ... [10 chars truncated] MARC valid 2
alt-1 biology A cell reaches mitosis, its colorful organelles duplicating in mirror-image as t ... [135 chars truncated] fig alone solves
alt-10 astronomy A fragment of a nebula is caught in a gravitational lens that projects its light ... [107 chars truncated] fig alone solves
alt-11 ocean/sailing A signal flag arrangement on the port yardarm is matched by its mirror on the st ... [88 chars truncated] MARC valid 1
alt-12 electronics A small circuit pattern on one quadrant of a silicon die is lithographically ste ... [97 chars truncated] MARC valid 2
alt-13 mythology A god gazes into twin divine mirrors — the Mirror of East-and-West and the ... [118 chars truncated] fig alone solves
alt-14 dance A choreographer blocks three rows of dancers in colored costumes on one side of ... [174 chars truncated] fig alone solves
alt-15 geology A crystal seed grows by twinning — first extending a mirror lattice along ... [149 chars truncated] fig alone solves
alt-2 cooking A chef folds a thin crêpe of colored batter — first in half one way, ... [155 chars truncated] MARC valid 1
alt-3 music A short motif played by an ensemble is answered by its retrograde inversion R ... [116 chars truncated] fig alone solves
alt-4 sports A coach diagrams a play on a quarter of the field, then tells both wings to run ... [101 chars truncated] fig alone solves
alt-5 weather A small storm system meets its own reflection at a pressure boundary, then the e ... [90 chars truncated] MARC valid 2
alt-6 architecture A master mason carves one corner block of an ornamental ceiling tile, knowing th ... [61 chars truncated] MARC valid 2
alt-7 warfare A general positions a vanguard in one quadrant of the battlefield, then deploys ... [166 chars truncated] fig alone solves
alt-8 theater A troupe rehearses a tableau in one corner of the stage, then the director calls ... [130 chars truncated] fig alone solves
alt-9 gardening A gardener plants one corner of a formal parterre, then lets the pattern propaga ... [146 chars truncated] MARC valid 1
original qwen3.5-122b: k=2
"A stained-glass window unfolds its hidden reflections when the cathedral doors swing open."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10606 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("small square of stained glass, three panes across and three down").
*   **Transformation:**
    *   "Unfolds to the right": This suggests a horizontal reflection or mirroring. The 3x3 becomes a 3x6.
    *   "Drops its reflection downward": This suggests a vertical reflection or mirroring of the result from the previous step. The 3x6 becomes a 6x6.
    *   "Four copies of the fragment facing inward like hands pressed together in prayer, symmetric in every direction": This confirms the 2D mirroring process.
*   **Output:** A 6x6 grid.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input (3x3):
        ```
        R X R
        R M Y
        R R R
        ```
    *   Output (6x6):
        ```
        R X R R X R
        R M Y Y M R
        R R R R R R
        R R R R R R
        R M Y Y M R
        R X R R X R
        ```
    *   Let's check the mirroring logic.
    *   Top-left 3x3 is the input.
    *   Top-right 3x3:
        Row 1: `R X R` -> `R X R` (Wait, looking at output row 1: `R X R R X R`. The right half is `R X R`. This is a mirror of `R X R`? No, `R X R` reversed is `R X R`. Let's look at row 2.)
        Row 2: `R M Y` -> `Y M R`. Output row 2 is `R M Y Y M R`. So the right half is the reverse of the left half.
        Row 3: `R R R` -> `R R R`. Output row 3 is `R R R R R R`.
    *   So, the top half (rows 1-3) is constructed by taking the input row and appending its reverse.
        *   Row 1: `R X R` + `R X R` (Reverse of `R X R` is `R X R`) -> `R X R R X R`.
        *   Row 2: `R M Y` + `Y M R` (Reverse of `R M Y` is `Y M R`) -> `R M Y Y M R`.
        *   Row 3: `R R R` + `R R R` -> `R R R R R R`.
    *   Bottom half (rows 4-6):
        *   Row 4: `R R R R R R`. Matches Row 3.
        *   Row 5: `R M Y Y M R`. Matches Row 2.
        *   Row 6: `R X R R X R`. Matches Row 1.
    *   So the bottom half is the vertical mirror of the top half.
    *   Overall transformation:
        1.  Horizontal Mirror: For each row, append the reverse of that row.
        2.  Vertical Mirror: Append the reverse of the resulting rows (from bottom to top).
    *   Essentially, create a 6x6 grid where `Output[i][j]` depends on `Input`.
    *   Let $H=3, W=3$. Output is $2H \times 2W$.
    *   Top-Left quadrant ($0 \le i < 3, 0 \le j < 3$) = Input.
    *   Top-Right quadrant ($0 \le i < 3, 3 \le j < 6$) = Horizontal Flip of Input.
    *   Bottom-Left quadrant ($3 \le i < 6, 0 \le j < 3$) = Vertical Flip of Input.
    *   Bottom-Right quadrant ($3 \le i < 6, 3 \le j < 6$) = Vertical Flip of Horizontal Flip (or Horizontal Flip of Vertical Flip) of Input.
    *   Basically, it's a point reflection across the center of the 6x6 grid, or simply mirroring across the right edge and then the bottom edge.

*   **Example 2:**
    *   Input (3x3):
        ```
        O B X
        O O B
        X G B
        ```
    *   Output (6x6):
        ```
        O B X X B O
        O O B B O O
        X G B B G X
        X G B B G X
        O O B B O O
        O B X X B O
        ```
    *   Check Top Half:
        *   Row 1: `O B X` + `X B O` (Reverse). Correct.
        *   Row 2: `O O B` + `B O O` (Reverse). Correct.
        *   Row 3: `X G B` + `B G X` (Reverse). Correct.
    *   Check Bottom Half:
        *   Row 4 = Row 3.
        *   Row 5 = Row 2.
        *   Row 6 = Row 1.
    *   This confirms the rule: Horizontal Mirror followed by Vertical Mirror.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** A 3x3 matrix of colored cells.
    *   **Output Grid:** A 6x6 matrix of colored cells.
    *   **Elements:** Individual colored cells (pixels/shards).

2.  **AFFORDANCES:**
    *   Cells can be copied.
    *   Rows can be reversed (mirrored horizontally).
    *   The set of rows can be reversed (mirrored vertically).
    *   The grid can be expanded.

3.  **TRANSFORMATION RULE:**
    *   Let Input be $I$ of size $3 \times 3$.
    *   Construct Intermediate Grid $M$ of size $3 \times 6$.
        *   For each row $r$ in $I$: $M[r] = I[r] + \text{reverse}(I[r])$.
    *   Construct Output Grid $O$ of size $6 \times 6$.
        *   For $0 \le r < 3$: $O[r] = M[r]$.
        *   For $3 \le r < 6$: $O[r] = M[5-r]$ (which is $M[2-(r-3)]$). Effectively, append the rows of $M$ in reverse order.
    *   Alternatively: $O[i][j] = I[\min(i, 5-i)][\min(j, 5-j)]$? No, indices are 0-2 for input.
    *   Let's check indices.
        *   Input indices: $i \in \{0, 1, 2\}, j \in \{0, 1, 2\}$.
        *   Output indices: $I \in \{0, ..., 5\}, J \in \{0, ..., 5\}$.
        *   Mapping:
            *   $I_{row} = i$ if $i < 3$ else $5-i$.
            *   $I_{col} = j$ if $j < 3$ else $5-j$.
            *   $Output[i][j] = Input[I_{row}][I_{col}]$.
    *   Let's verify with Example 1

... [5687 chars truncated]
alt-1 biology qwen3.5-122b: fig alone solves
"A cell reaches mitosis, its colorful organelles duplicating in mirror-image as the membrane stretches to encompass two daughters, then the whole embryo folds along a second axis, producing a four-chambered blastula."
alt-10 astronomy qwen3.5-122b: fig alone solves
"A fragment of a nebula is caught in a gravitational lens that projects its light in four symmetric images around the lensing mass — each quadrant a perfect reflection of the others."
alt-11 ocean/sailing qwen3.5-122b: k=1
"A signal flag arrangement on the port yardarm is matched by its mirror on the starboard side, and then the whole rigging is reflected in the still water below the hull."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9699 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A small square of colored signal flags hoisted on one arm of the mast.
*   **What to do:**
    *   "The port flags are mirrored to starboard, creating a balanced horizontal display." -> This implies horizontal mirroring (reflection across a vertical axis).
    *   "Then the water's surface reflects the entire arrangement downward, doubling it vertically." -> This implies vertical mirroring (reflection across a horizontal axis) of the result from the first step.
*   **Grid details:**
    *   Original signal hoist is 3x3.
    *   Full display spans 6x6.
    *   Symmetry across both the mast (vertical axis) and the waterline (horizontal axis).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    R X R
    R M Y
    R R R
    ```
    (3 rows, 3 columns)
*   **Output:**
    ```
    R X R R X R
    R M Y Y M R
    R R R R R R
    R R R R R R
    R M Y Y M R
    R X R R X R
    ```
    (6 rows, 6 columns)

*   **Verification of the Rule:**
    *   **Step 1: Horizontal Mirroring.**
        *   Input Row 1: `R X R` -> Mirror -> `R X R` + `R X R` (reversed)?
        *   Let's check the output Row 1: `R X R R X R`.
        *   Input Row 1 is `R X R`. Reversed is `R X R`. Concatenated: `R X R R X R`. Matches.
        *   Input Row 2: `R M Y`. Reversed is `Y M R`. Concatenated: `R M Y Y M R`. Matches Output Row 2.
        *   Input Row 3: `R R R`. Reversed is `R R R`. Concatenated: `R R R R R R`. Matches Output Row 3.
        *   So, the first step creates a 3x6 grid by concatenating the input row with its reverse.
    *   **Step 2: Vertical Mirroring.**
        *   Current grid (3x6):
            ```
            R X R R X R
            R M Y Y M R
            R R R R R R
            ```
        *   Reflect downward. This means taking the rows in reverse order and appending them.
        *   Row 3: `R R R R R R`
        *   Row 2: `R M Y Y M R`
        *   Row 1: `R X R R X R`
        *   Appending these to the bottom creates the 6x6 grid.
        *   Output Row 4: `R R R R R R` (Matches Row 3)
        *   Output Row 5: `R M Y Y M R` (Matches Row 2)
        *   Output Row 6: `R X R R X R` (Matches Row 1)
    *   **Conclusion:** The transformation is a "double reflection". First, reflect horizontally (left-right) to double the width. Second, reflect vertically (top-bottom) of the resulting block to double the height. Effectively, the input 3x3 grid is the top-left quadrant of the 6x6 output grid. The top-right is the horizontal mirror of top-left. The bottom-left is the vertical mirror of top-left. The bottom-right is the vertical mirror of top-right (or horizontal mirror of bottom-left).

**3. Conceptual Digestion:**
1.  **CAST:**
    *   **Input Grid:** Represents the "signal hoist" on the "port" side (left side) of the mast. It is a 3x3 matrix of colors.
    *   **Output Grid:** Represents the full display including the "starboard" (right) side and the "water reflection" (bottom). It is a 6x6 matrix.
    *   **Colors:** Symbols representing specific states (R, X, M, Y, B, etc.).
2.  **AFFORDANCES:**
    *   **Mirroring:** Elements can be reflected across axes.
    *   **Concatenation:** Rows and columns can be joined.
    *   **Symmetry:** The final structure must exhibit bilateral symmetry horizontally and vertically.
3.  **TRANSFORMATION RULE:**
    *   Let $I$ be the input 3x3 grid.
    *   Let $I_{horiz}$ be the grid formed by concatenating each row of $I$ with its reverse. $I_{horiz}[i] = I[i] + \text{reverse}(I[i])$. This results in a 3x6 grid.
    *   Let $O$ be the output 6x6 grid.
    *   $O$ is formed by concatenating $I_{horiz}$ with its vertical reverse. $O = I_{horiz} + \text{reverse\_rows}(I_{horiz})$.
    *   Alternatively, $O[i, j]$ for $0 \le i, j < 3$ is $I[i, j]$.
    *   $O[i, 3+j] = I[i, 2-j]$ (Horizontal reflection).
    *   $O[3+i, j] = I[2-i, j]$ (Vertical reflection).
    *   $O[3+i, 3+j] = I[2-i, 2-j]$ (Point reflection / 180 rotation).

**4. Apply to Test Input:**
*   **Test Input:**
    ```
    B M M
    X R R
    R R R
    ```
    (3x3)

*   **Step 1: Horizontal Mirroring (Create Top Half 3x6)**
    *   Row 1: `B M M` -> Reverse: `M M B` -> Combined: `B M M M M B`
    *   Row 2: `X R R` -> Reverse: `R R X` -> Combined: `X R R R R X`
    *   Row 3: `R R R` -> Reverse: `R R R` -> Combined: `R R R R R R`

    *   Top Half:
        ```
        B M M M M B
        X R R R R X
        R R R R R R
        ```

*   **Step 2: Vertical Mirroring (Create Bottom Half 3x6)**
    *   Take the Top Half rows in reverse order (Row 3, Row 2, Row 1).
    *   Row 4 (copy of Row 3): `R R R R R R`
    *   Row 5 (copy of Row 2): `X R R R R X`
    *   Row 6 (copy of Row 1): `B M M M M B`

*   **Final Output Grid (6x6):**
    ```
    B M M M M B
    X R R R R X
    R R R R R R
    R R R R R

... [4756 chars truncated]
alt-12 electronics qwen3.5-122b: k=2
"A small circuit pattern on one quadrant of a silicon die is lithographically stepped-and-repeated with mirrored exposures to fill the full die area with symmetric interconnects."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10345 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A compact 3x3 array of colored circuit elements.
*   **Action:**
    1.  "The stepper mirrors the pattern laterally for the adjacent quadrant". This suggests horizontal mirroring (reflection across a vertical axis).
    2.  "then mirrors the combined half-die vertically to complete the full layout". This suggests vertical mirroring (reflection across a horizontal axis) of the result from step 1.
*   **Grid details:** Unit cell is 3x3. Completed die is 6x6. Mirror symmetry on both axes.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input (3x3):
        ```
        R X R
        R M Y
        R R R
        ```
    *   Output (6x6):
        ```
        R X R R X R
        R M Y Y M R
        R R R R R R
        R R R R R R
        R M Y Y M R
        R X R R X R
        ```
    *   **Observation:**
        *   Top-left 3x3 matches Input.
        *   Top-right 3x3 is the horizontal mirror of the Top-left 3x3.
            *   Row 1: `R X R` -> `R X R` (Symmetric)
            *   Row 2: `R M Y` -> `Y M R`
            *   Row 3: `R R R` -> `R R R` (Symmetric)
        *   Bottom half (Rows 4-6) is the vertical mirror of the Top half (Rows 1-3).
            *   Row 4 matches Row 3.
            *   Row 5 matches Row 2.
            *   Row 6 matches Row 1.
        *   Essentially, the output is constructed by reflecting the input horizontally to make a 3x6 block, then reflecting that 3x6 block vertically to make a 6x6 block.
        *   Let's check the indices.
            *   Input $I$ is $3 \times 3$.
            *   Output $O$ is $6 \times 6$.
            *   $O[i, j] = I[i, j]$ for $0 \le i < 3, 0 \le j < 3$.
            *   $O[i, j] = I[i, 5-j]$ for $0 \le i < 3, 3 \le j < 6$. (Horizontal reflection)
            *   $O[i, j] = O[5-i, j]$ for $3 \le i < 6, 0 \le j < 6$. (Vertical reflection)
            *   Alternatively, $O[i, j] = I[5-i, j]$ for $3 \le i < 6, 0 \le j < 3$.
            *   Let's verify Example 1 Row 5 (index 4). Input Row 1 (index 1) is `R M Y`. Output Row 5 is `R M Y Y M R`. Wait.
            *   Let's look at Example 1 Output again.
                Row 0: `R X R R X R`
                Row 1: `R M Y Y M R`
                Row 2: `R R R R R R`
                Row 3: `R R R R R R`
                Row 4: `R M Y Y M R`
                Row 5: `R X R R X R`
            *   Top half (Rows 0-2):
                Row 0: `R X R` + `R X R` (Mirror of `R X R`)
                Row 1: `R M Y` + `Y M R` (Mirror of `R M Y`)
                Row 2: `R R R` + `R R R` (Mirror of `R R R`)
            *   Bottom half (Rows 3-5):
                Row 3 is copy of Row 2.
                Row 4 is copy of Row 1.
                Row 5 is copy of Row 0.
            *   So the transformation is:
                1.  Take Input $3 \times 3$.
                2.  Create Top Half ($3 \times 6$) by concatenating Input with its horizontal reflection.
                3.  Create Output ($6 \times 6$) by concatenating Top Half with its vertical reflection.

*   **Example 2:**
    *   Input (3x3):
        ```
        O B X
        O O B
        X G B
        ```
    *   Output (6x6):
        ```
        O B X X B O
        O O B B O O
        X G B B G X
        X G B B G X
        O O B B O O
        O B X X B O
        ```
    *   **Verification:**
        *   Top Half:
            *   Row 0: `O B X` + `X B O` (Mirror of `O B X`) -> `O B X X B O`. Matches.
            *   Row 1: `O O B` + `B O O` (Mirror of `O O B`) -> `O O B B O O`. Matches.
            *   Row 2: `X G B` + `B G X` (Mirror of `X G B`) -> `X G B B G X`. Matches.
        *   Bottom Half:
            *   Row 3: Copy of Row 2 (`X G B B G X`). Matches.
            *   Row 4: Copy of Row 1 (`O O B B O O`). Matches.
            *   Row 5: Copy of Row 0 (`O B X X B O`). Matches.
    *   The rule holds perfectly.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** A 3x3 matrix of color characters. Represents the "unit cell" or "quadrant".
    *   **Output Grid:** A 6x6 matrix. Represents the "full die".
    *   **Elements:** Individual colored cells (characters).

2.  **AFFORDANCES:**
    *   **Mirroring:** The grid elements can be reflected horizontally and vertically.
    *   **Concatenation:** The reflected grids can be joined to form larger grids.

3.  **TRANSFORMATION RULE:**
    *   Let $I$ be the input 3x3 grid.
    *   Let $H$ be the horizontal reflection of $I$. $H[i, j] = I[i, 2-j]$ for $0 \le i, j < 3$.
    *   Construct the top half $T$ (3x6) by concatenating $I$ and $H$ horizontally. $T[i, j] = I[i, j]$ for $j<3$, $T[i, j] = I[i, 5-j]$ for $j \ge 3$.
    *   Construct the bottom half $B$ (3x6) by vertically reflecting $T$. $B[i, j] = T[2-i, j]$ for $0 \le i < 3$.
    *   Construct the final output $O$ (

... [5435 chars truncated]
alt-13 mythology qwen3.5-122b: fig alone solves
"A god gazes into twin divine mirrors — the Mirror of East-and-West and the Mirror of Sky-and-Earth — and sees a single sacred glyph multiplied into a mandala of four perfect reflections."
alt-14 dance qwen3.5-122b: fig alone solves
"A choreographer blocks three rows of dancers in colored costumes on one side of the stage, then calls 'mirror!' — the formation replicates to the opposite wing. Then 'echo!' — the whole company repeats the shape in reverse from back to front."
alt-15 geology qwen3.5-122b: fig alone solves
"A crystal seed grows by twinning — first extending a mirror lattice along one axis, then repeating the twin operation along the perpendicular axis, until the unit cell has propagated into a four-fold symmetric crystal face."
alt-2 cooking qwen3.5-122b: k=1
"A chef folds a thin crêpe of colored batter — first in half one way, then in half the other — but here you must imagine the folding in reverse, opening the crêpe out to reveal every layer's imprint on the surface."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (8353 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A "small square of dough" (3x3 grid).
*   **Action:** "Unfold the crêpe sideways first" (Horizontal reflection/mirroring).
*   **Action:** "Then unfold downward" (Vertical reflection/mirroring).
*   **Result:** A "6x6 surface" where every colored mark appears in four symmetric positions.
*   **Key Insight:** The input is a 3x3 quadrant. The output is a 6x6 grid formed by reflecting the input across the right edge, and then reflecting the resulting 6x3 block across the bottom edge. Or, more simply, the 3x3 input is the top-left quadrant of the 6x6 output. The output is constructed by mirroring the input horizontally to create the top half, and then mirroring the top half vertically to create the bottom half.
*   **Symmetry:** The description says "every colored mark appears in four symmetric positions". This implies 4-way symmetry (quadrant symmetry) centered at the intersection of the grid lines.
    *   Let the input be $A$ (3x3).
    *   Step 1 (Sideways): Create a 3x6 grid. The left 3 columns are $A$. The right 3 columns are $A$ mirrored horizontally.
        *   Row $i$ of output top half: $A[i] + \text{reverse}(A[i])$.
    *   Step 2 (Downward): Create a 6x6 grid. The top 3 rows are the result of Step 1. The bottom 3 rows are the top 3 rows mirrored vertically.
        *   Row $3+i$ of output: Row $2-i$ of the top half (where indices are 0,1,2).
        *   Essentially, the bottom half is the reverse of the top half.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    R X R
    R M Y
    R R R
    ```
*   **Output:**
    ```
    R X R R X R
    R M Y Y M R
    R R R R R R
    R R R R R R
    R M Y Y M R
    R X R R X R
    ```
*   **Verification:**
    *   Top-left 3x3 matches Input.
    *   Top-right 3x3 is horizontal mirror of Top-left.
        *   Row 0: `R X R` -> `R X R` (Palindrome)
        *   Row 1: `R M Y` -> `Y M R`
        *   Row 2: `R R R` -> `R R R` (Palindrome)
        *   Combined Top Half:
            `R X R R X R`
            `R M Y Y M R`
            `R R R R R R`
    *   Bottom Half is vertical mirror of Top Half.
        *   Row 3 = Row 2: `R R R R R R`
        *   Row 4 = Row 1: `R M Y Y M R`
        *   Row 5 = Row 0: `R X R R X R`
    *   This matches the Output exactly.

**3. Conceptual Digestion:**
1.  **CAST:**
    *   **Input Grid:** A 3x3 matrix of colored cells.
    *   **Output Grid:** A 6x6 matrix of colored cells.
    *   **Colors:** Specific characters representing colors (R, X, M, Y, B, etc.).
2.  **AFFORDANCES:**
    *   Cells can be copied.
    *   Rows can be reversed (horizontal reflection).
    *   The sequence of rows can be reversed (vertical reflection).
3.  **TRANSFORMATION RULE:**
    *   Let Input be $I$ with dimensions $3 \times 3$.
    *   Construct Top Half $T$ with dimensions $3 \times 6$.
        *   For each row $r$ in $I$ (0 to 2):
            *   $T[r] = I[r] + \text{reverse}(I[r])$
    *   Construct Output $O$ with dimensions $6 \times 6$.
        *   For each row $r$ in $T$ (0 to 2):
            *   $O[r] = T[r]$
            *   $O[5-r] = T[r]$
    *   Alternatively: $O$ is formed by tiling $I$ in a 2x2 pattern where the tiles are reflected.
        *   Top-Left: $I$
        *   Top-Right: $I$ mirrored horizontally.
        *   Bottom-Left: $I$ mirrored vertically.
        *   Bottom-Right: $I$ mirrored horizontally and vertically (or vertically then horizontally).

**4. Apply to Test Input:**
*   **Test Input:**
    ```
    B M M
    X R R
    R R R
    ```
*   **Step 1: Horizontal Reflection (Create Top Half)**
    *   Row 0: `B M M` -> Mirror: `M M B`. Combined: `B M M M M B`
    *   Row 1: `X R R` -> Mirror: `R R X`. Combined: `X R R R R X`
    *   Row 2: `R R R` -> Mirror: `R R R`. Combined: `R R R R R R`
    *   Top Half (Rows 0-2):
        ```
        B M M M M B
        X R R R R X
        R R R R R R
        ```
*   **Step 2: Vertical Reflection (Create Bottom Half)**
    *   Row 3 = Row 2: `R R R R R R`
    *   Row 4 = Row 1: `X R R R R X`
    *   Row 5 = Row 0: `B M M M M B`
*   **Final Output Grid:**
    ```
    B M M M M B
    X R R R R X
    R R R R R R
    R R R R R R
    X R R R R X
    B M M M M B
    ```

**5. Formatting:**
*   Need to output the grid with spaces between characters.
*   Need to wrap the final answer in the specified block.

**Double Check:**
Input:
B M M
X R R
R R R

Row 0: B M M. Reverse: M M B. Concat: B M M M M B.
Row 1: X R R. Reverse: R R X. Concat: X R R R R X.
Row 2: R R R. Reverse: R R R. Concat: R R R R R R.

Top 3 rows:
B M M M M B
X R R R R X
R R R R R R

Bottom 3 rows (reverse order of top 3):
R R R R R R
X R R R R X
B M M M M B

Combined:
B M M M M B
X R R R R X
R R R R R R
R R R R R R
X R R R R X
B M M M M B

Looks correct.
Color key check:
B=blue, M=magenta, X=grey, R=red.
Input uses B, M, 

... [3405 chars truncated]
alt-3 music qwen3.5-122b: fig alone solves
"A short motif played by an ensemble is answered by its retrograde inversion — first the melody is reversed in pitch across a horizontal mirror, then the whole passage is palindromed in time."
alt-4 sports qwen3.5-122b: fig alone solves
"A coach diagrams a play on a quarter of the field, then tells both wings to run the mirror-image of each other, and both halves of the field to execute the same symmetric formation."
alt-5 weather qwen3.5-122b: k=2
"A small storm system meets its own reflection at a pressure boundary, then the entire doubled front collides with an identical system arriving from the opposite latitude."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10179 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A "compact weather cell" (3x3 grid).
*   **Transformation:**
    *   "Vertical pressure wall that bounces its pattern sideways, creating a mirror twin." -> This suggests a horizontal reflection (mirroring across a vertical axis).
    *   "Combined system hits a horizontal jet stream that reflects the whole formation downward." -> This suggests a vertical reflection (mirroring across a horizontal axis) of the result from the first step.
*   **Output:** A "mega-system" covering a 6x6 area with "four-fold meteorological symmetry".
*   **Dimensions:** Input is 3x3. Output is 6x6.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input (3x3):
        ```
        R X R
        R M Y
        R R R
        ```
    *   Output (6x6):
        ```
        R X R R X R
        R M Y Y M R
        R R R R R R
        R R R R R R
        R M Y Y M R
        R X R R X R
        ```
    *   **Observation:**
        *   Top-left 3x3 matches Input.
        *   Top-right 3x3 is the horizontal mirror of the Top-left 3x3. (Row 1: R X R -> R X R. Row 2: R M Y -> Y M R. Row 3: R R R -> R R R). Wait, let's look closer.
        *   Input Row 1: `R X R`. Output Row 1: `R X R R X R`. This is Input Row 1 concatenated with its reverse.
        *   Input Row 2: `R M Y`. Output Row 2: `R M Y Y M R`. This is Input Row 2 concatenated with its reverse.
        *   Input Row 3: `R R R`. Output Row 3: `R R R R R R`. This is Input Row 3 concatenated with its reverse.
        *   So far, the top half (rows 1-3) is the input mirrored horizontally.
        *   Now look at the bottom half (rows 4-6).
        *   Output Row 4: `R R R R R R`. Matches Output Row 3.
        *   Output Row 5: `R M Y Y M R`. Matches Output Row 2.
        *   Output Row 6: `R X R R X R`. Matches Output Row 1.
        *   So the bottom half is the vertical mirror of the top half.
        *   Essentially, the output is constructed by taking the input, mirroring it horizontally to make a 3x6 block, and then mirroring that 3x6 block vertically to make a 6x6 block.
        *   Alternatively, it's a 2x2 tiling where:
            *   Top-Left = Input
            *   Top-Right = Horizontal Flip of Input
            *   Bottom-Left = Vertical Flip of Input
            *   Bottom-Right = 180-degree rotation of Input (or Vertical Flip of Top-Right)

*   **Example 2:**
    *   Input (3x3):
        ```
        O B X
        O O B
        X G B
        ```
    *   Output (6x6):
        ```
        O B X X B O
        O O B B O O
        X G B B G X
        X G B B G X
        O O B B O O
        O B X X B O
        ```
    *   **Verification:**
        *   Top-Left (3x3): Matches Input.
        *   Top-Right (3x3):
            *   Row 1: `X B O` (Reverse of `O B X`)
            *   Row 2: `B O O` (Reverse of `O O B`)
            *   Row 3: `B G X` (Reverse of `X G B`)
            *   Matches Horizontal Flip.
        *   Bottom-Left (3x3):
            *   Row 4: `X G B` (Matches Input Row 3)
            *   Row 5: `O O B` (Matches Input Row 2)
            *   Row 6: `O B X` (Matches Input Row 1)
            *   Matches Vertical Flip of Input.
        *   Bottom-Right (3x3):
            *   Row 4: `B G X` (Reverse of `X G B`)
            *   Row 5: `B O O` (Reverse of `O O B`)
            *   Row 6: `X B O` (Reverse of `O B X`)
            *   Matches Horizontal Flip of Bottom-Left (or Vertical Flip of Top-Right).
    *   **Conclusion:** The transformation rule is consistent. Create a 6x6 grid where the top-left 3x3 is the input. The top-right is the horizontal reflection of the input. The bottom-left is the vertical reflection of the input. The bottom-right is the reflection of the top-right (or bottom-left). Effectively, reflect horizontally, then reflect the result vertically.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** A 3x3 matrix of colored cells.
    *   **Output Grid:** A 6x6 matrix of colored cells.
    *   **Symmetry Axes:** A vertical axis between columns 3 and 4, and a horizontal axis between rows 3 and 4.

2.  **AFFORDANCES:**
    *   Cells can be copied.
    *   Rows can be reversed (horizontal reflection).
    *   The order of rows can be reversed (vertical reflection).

3.  **TRANSFORMATION RULE:**
    *   Let $I$ be the input 3x3 grid.
    *   Let $H(I)$ be the horizontal reflection of $I$ (each row reversed).
    *   Let $V(I)$ be the vertical reflection of $I$ (rows order reversed).
    *   The output grid $O$ is constructed as:
        $$
        O = \begin{bmatrix} I & H(I) \\ V(I) & V(H(I)) \end{bmatrix}
        $$
        Note: $V(H(I))$ is equivalent to $H(V(I))$.
    *   In simpler terms:
        1.  Take the input grid.
        2.  Append the horizontally flipped version of the input to the right of the input. (Result is 3x6).

... [5229 chars truncated]
alt-6 architecture qwen3.5-122b: k=2
"A master mason carves one corner block of an ornamental ceiling tile, knowing the mold will be pressed four ways to produce the full rosette."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10891 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A "square corner piece" (3x3 grid).
*   **Output:** A "completed ceiling tile" (6x6 grid).
*   **Transformation:**
    *   "The corner block is flipped to create its lateral twin": This suggests mirroring horizontally.
    *   "then the paired blocks are flipped again along the perpendicular axis": This suggests mirroring vertically.
    *   "every inlay appears in four rotationally related positions": This confirms a 4-quadrant symmetry.
    *   "The carved corner is 3×3. The completed ceiling tile is 6×6": Input size is 3x3, Output size is 6x6.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input (3x3):
        ```
        R X R
        R M Y
        R R R
        ```
    *   Output (6x6):
        ```
        R X R R X R
        R M Y Y M R
        R R R R R R
        R R R R R R
        R M Y Y M R
        R X R R X R
        ```
    *   Let's check the quadrants.
        *   Top-Left (0-2, 0-2): Matches Input.
        *   Top-Right (0-2, 3-5):
            Row 0: `R X R` -> `R X R` (Wait, looking at output row 0: `R X R R X R`. The right half is `R X R`. This is a horizontal mirror of `R X R`? No, `R X R` mirrored is `R X R`. Let's look at row 1: `R M Y` -> `Y M R`. Output row 1 is `R M Y Y M R`. So the right half is the horizontal mirror of the left half.
            Row 2: `R R R` -> `R R R`. Output row 2 is `R R R R R R`.
        *   Bottom-Left (3-5, 0-2):
            Row 3: `R R R`. Matches Row 2 of input? No, Row 2 of input is `R R R`.
            Row 4: `R M Y`. Matches Row 1 of input.
            Row 5: `R X R`. Matches Row 0 of input.
            So the bottom half is the vertical mirror of the top half.
        *   Bottom-Right (3-5, 3-5):
            Row 3: `R R R`.
            Row 4: `Y M R`.
            Row 5: `R X R`.
            This is the vertical mirror of the Top-Right quadrant, or horizontal mirror of Bottom-Left.

    *   **Transformation Logic:**
        1.  Take the 3x3 input grid $A$.
        2.  Create a 3x3 grid $B$ which is the horizontal reflection of $A$.
        3.  Concatenate $A$ and $B$ horizontally to form a 3x6 grid $C$.
        4.  Create a 3x6 grid $D$ which is the vertical reflection of $C$.
        5.  Concatenate $C$ and $D$ vertically to form the 6x6 output grid.
        *   Alternatively:
            *   Top-Left = Input
            *   Top-Right = Horizontal Flip of Input
            *   Bottom-Left = Vertical Flip of Input
            *   Bottom-Right = Horizontal Flip of Vertical Flip of Input (which is 180 degree rotation).

    *   Let's verify with Example 1 Row 1: `R M Y`.
        *   Horizontal Flip: `Y M R`.
        *   Output Row 1: `R M Y` + `Y M R`. Correct.
    *   Let's verify with Example 1 Row 4 (which corresponds to Input Row 1 flipped vertically):
        *   Input Row 1: `R M Y`.
        *   Vertical Flip puts this at Row 4 (index 4 in 0-5).
        *   Output Row 4: `R M Y` + `Y M R`. Correct.

*   **Example 2:**
    *   Input (3x3):
        ```
        O B X
        O O B
        X G B
        ```
    *   Output (6x6):
        ```
        O B X X B O
        O O B B O O
        X G B B G X
        X G B B G X
        O O B B O O
        O B X X B O
        ```
    *   Top-Left: Input.
    *   Top-Right: Horizontal Flip of Input.
        *   Row 0: `O B X` -> `X B O`. Output: `O B X X B O`. Correct.
        *   Row 1: `O O B` -> `B O O`. Output: `O O B B O O`. Correct.
        *   Row 2: `X G B` -> `B G X`. Output: `X G B B G X`. Correct.
    *   Bottom-Left: Vertical Flip of Input.
        *   Row 3 (Input Row 2): `X G B`. Output: `X G B`. Correct.
        *   Row 4 (Input Row 1): `O O B`. Output: `O O B`. Correct.
        *   Row 5 (Input Row 0): `O B X`. Output: `O B X`. Correct.
    *   Bottom-Right: Horizontal Flip of Bottom-Left (or Vertical Flip of Top-Right).
        *   Row 3: `X G B` -> `B G X`. Output: `B G X`. Correct.
        *   Row 4: `O O B` -> `B O O`. Output: `B O O`. Correct.
        *   Row 5: `O B X` -> `X B O`. Output: `X B O`. Correct.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** A 3x3 matrix of colored cells (characters).
    *   **Output Grid:** A 6x6 matrix of colored cells.
    *   **Elements:** Individual cells containing color codes (R, X, M, etc.).

2.  **AFFORDANCES:**
    *   Cells can be copied.
    *   Rows can be reversed (horizontal flip).
    *   The order of rows can be reversed (vertical flip).
    *   Sub-grids can be concatenated.

3.  **TRANSFORMATION RULE:**
    *   Let the input grid be $I$ of size $3 \times 3$.
    *   Let $H(I)$ be the horizontal reflection of $I$ (columns reversed).
    *   Let $V(I)$ be the vertical reflection of $I$ (rows reversed).
    *   The output grid $O$ is constructed as:
        $$
        O = \begin{bmatrix} I & H

... [5960 chars truncated]
alt-7 warfare qwen3.5-122b: fig alone solves
"A general positions a vanguard in one quadrant of the battlefield, then deploys identical mirror-formations to guard every flank — what threatens from the east is matched from the west, what advances from the north is echoed from the south."
alt-8 theater qwen3.5-122b: fig alone solves
"A troupe rehearses a tableau in one corner of the stage, then the director calls for the scene to be performed simultaneously by mirror-casts on both wings, and again by shadow-casts above on a raised platform."
alt-9 gardening qwen3.5-122b: k=1
"A gardener plants one corner of a formal parterre, then lets the pattern propagate by reflection — hedgerows mirror left to right, then the whole bed mirrors top to bottom, creating the classic four-quadrant knot garden."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (7809 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A small square planting bed (3x3).
*   **Action 1:** "Extend the bed rightward by planting the mirror image of each row."
    *   This implies horizontal reflection. If the input is $3 \times 3$, the output after this step would be $3 \times 6$.
    *   Let's check the wording: "mirror image of each row". Usually, this means reflecting the row across its right edge. So, row $[A, B, C]$ becomes $[A, B, C, C, B, A]$.
*   **Action 2:** "Then extend the combined bed downward by mirroring the whole arrangement."
    *   This implies vertical reflection. If the current grid is $3 \times 6$, the final output would be $6 \times 6$.
    *   "Mirroring the whole arrangement" usually means reflecting across the bottom edge. So, if the top half is rows $1, 2, 3$, the bottom half becomes rows $3, 2, 1$ (or $1, 2, 3$ repeated? No, "mirror image" implies symmetry).
    *   "so each bloom has three symmetric siblings". This suggests 4-way symmetry or rotational symmetry? Let's look at the example.
*   **Grid details:** "The planted corner is 3×3. The completed parterre is 6×6 with the formal bilateral symmetry of a French garden."
    *   Input size: $3 \times 3$.
    *   Output size: $6 \times 6$.
    *   Symmetry: Bilateral (reflectional).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    R X R
    R M Y
    R R R
    ```
*   **Output:**
    ```
    R X R R X R
    R M Y Y M R
    R R R R R R
    R R R R R R
    R M Y Y M R
    R X R R X R
    ```
*   **Step-by-step verification:**
    *   **Horizontal Mirror:**
        *   Row 1: `R X R` -> Mirror -> `R X R` + `R X R` reversed?
            *   Input Row 1: `R X R`. Reverse: `R X R`. Concatenation: `R X R R X R`. Matches Output Row 1.
        *   Row 2: `R M Y`. Reverse: `Y M R`. Concatenation: `R M Y Y M R`. Matches Output Row 2.
        *   Row 3: `R R R`. Reverse: `R R R`. Concatenation: `R R R R R R`. Matches Output Row 3.
        *   So, the first step is indeed: For each row, append the reverse of that row.
    *   **Vertical Mirror:**
        *   Current Top Half (Rows 1-3):
            ```
            R X R R X R
            R M Y Y M R
            R R R R R R
            ```
        *   Output Bottom Half (Rows 4-6):
            ```
            R R R R R R
            R M Y Y M R
            R X R R X R
            ```
        *   Row 4 matches Row 3.
        *   Row 5 matches Row 2.
        *   Row 6 matches Row 1.
        *   So, the second step is: Append the reverse of the rows (i.e., reflect the grid vertically).

**3. Conceptual Digestion:**
*   **CAST:**
    *   Input Grid: A $3 \times 3$ matrix of colored cells.
    *   Output Grid: A $6 \times 6$ matrix.
    *   Elements: Individual colored cells (pixels).
*   **AFFORDANCES:**
    *   Rows can be mirrored horizontally.
    *   The grid of rows can be mirrored vertically.
*   **TRANSFORMATION RULE:**
    1.  Take the input $3 \times 3$ grid.
    2.  Create a $3 \times 6$ intermediate grid by concatenating each row with its reverse. (Horizontal Symmetry).
    3.  Create the final $6 \times 6$ grid by concatenating the intermediate grid with its vertical reverse (rows in reverse order). (Vertical Symmetry).
    4.  Essentially, the output is a reflection of the input across the right edge, and then a reflection of that result across the bottom edge. The input is the top-left quadrant.

**4. Apply to Test Input:**
*   **Test Input:**
    ```
    B M M
    X R R
    R R R
    ```
*   **Step 1: Horizontal Mirror (Row-wise)**
    *   Row 1: `B M M` -> Reverse: `M M B` -> Combined: `B M M M M B`
    *   Row 2: `X R R` -> Reverse: `R R X` -> Combined: `X R R R R X`
    *   Row 3: `R R R` -> Reverse: `R R R` -> Combined: `R R R R R R`
    *   Intermediate Grid ($3 \times 6$):
        ```
        B M M M M B
        X R R R R X
        R R R R R R
        ```
*   **Step 2: Vertical Mirror (Grid-wise)**
    *   Take the intermediate grid rows: $R_1, R_2, R_3$.
    *   Append $R_3, R_2, R_1$.
    *   Row 4 = Row 3: `R R R R R R`
    *   Row 5 = Row 2: `X R R R R X`
    *   Row 6 = Row 1: `B M M M M B`
*   **Final Output Grid ($6 \times 6$):**
    ```
    B M M M M B
    X R R R R X
    R R R R R R
    R R R R R R
    X R R R R X
    B M M M M B
    ```

**5. Verification:**
*   Input:
    B M M
    X R R
    R R R
*   Top-Left 3x3 matches input.
*   Top-Right 3x3 is mirror of Top-Left.
    *   Row 1: B M M | M M B. Correct.
    *   Row 2: X R R | R R X. Correct.
    *   Row 3: R R R | R R R. Correct.
*   Bottom-Left 3x3 is mirror of Top-Left (vertically).
    *   Row 4 = Row 3. Correct.
    *   Row 5 = Row 2. Correct.
    *   Row 6 = Row 1. Correct.
*   Bottom-Right 3x3 is mirror of Top-Right (vertically) / Bottom-Left (horizontally).
    *   Row 4: R R R R R R.
    *   Row 5: X R R R R X.
    *

... [2861 chars truncated]

Task 416: 6e02f1e3

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Ex5 In
Ex5 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A conductor reads the harmony of an orchestra to choose the curtain call formati ... [3 chars truncated] MARC valid 3
alt-1 biology A cell biologist examines a tissue sample under the microscope. The diversity of ... [130 chars truncated] MARC valid 2
alt-10 astronomy An astronomer catalogs the spectral classes of stars in a cluster. A uniform clu ... [168 chars truncated] MARC valid 2
alt-11 ocean/sailing A navigator reads the colors of the ocean currents on the chart. Uniform waters ... [184 chars truncated] MARC valid 3
alt-12 electronics A circuit designer examines the voltage levels on an input bus. A single voltage ... [183 chars truncated] MARC valid 2
alt-13 mythology An oracle peers into a mosaic of colored tiles and reads the fate of nations. Wh ... [153 chars truncated] MARC valid 4
alt-14 dance A choreographer watches the dancers' costumes swirl and decides the final pose. ... [177 chars truncated] MARC valid 2
alt-15 geology A geologist cores a rock face and reads the mineral composition. A pure formatio ... [156 chars truncated] MARC valid 2
alt-2 cooking A chef tastes a stew and judges its complexity. A simple broth gets a flat garni ... [129 chars truncated] MARC valid 2
alt-3 music A composer listens to a chord and scores the resonance pattern. A unison note hu ... [126 chars truncated] MARC valid 3
alt-4 sports A referee surveys the jerseys on a playing field and signals the formation. Iden ... [149 chars truncated] MARC valid 2
alt-5 weather A meteorologist reads the colors of the sky at dawn. A monochrome sky means the ... [183 chars truncated] MARC valid 3
alt-6 architecture An architect surveys the materials delivered to a building site. If every brick ... [200 chars truncated] MARC valid 3
alt-7 warfare A general studies the banners on the battlefield. A single banner means the troo ... [167 chars truncated] MARC valid 3
alt-8 theater A stage director counts the speaking roles in a script. A monologue places the s ... [179 chars truncated] MARC valid 2
alt-9 gardening A gardener inspects the flower bed and decides where to lay stepping stones. A b ... [168 chars truncated] MARC valid 2
original qwen3.5-122b: k=3
"A conductor reads the harmony of an orchestra to choose the curtain call formation."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (10147 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A stage with performers in colored costumes.
*   **Action:** Curtain falls, stage goes dark.
*   **Spotlight Operator:** Counts distinct factions (colors).
*   **Rule:**
    *   "The fewer the factions, the more unified the bow — a single troupe lines up shoulder to shoulder across the front of the stage." -> 1 faction = 1 row of spotlights?
    *   "A duo takes a bow along the grand staircase from balcony to pit." -> 2 factions = diagonal line?
    *   "A trio crosses paths, saluting from opposite wings through center stage." -> 3 factions = ?
*   **Output:** "Exactly three spotlights (grey) illuminate the bowing positions against the blackout".
*   **Grid details:** Output grid size is same as input. Background is black (.). Spotlights are grey (X).
*   **Key Insight:** The number of distinct colors in the input grid determines the pattern of grey 'X's in the output grid. The rest of the grid is black '.'.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        G G G
        G G G
        G G G
    *   Colors present: Green (G). Count = 1.
    *   Output:
        X X X
        . . .
        . . .
    *   Pattern: Top row filled with X.
    *   Interpretation: 1 distinct color -> Top row of Xs.

*   **Example 2:**
    *   Input:
        G G G
        Y R R
        Y Y R
    *   Colors present: Green (G), Yellow (Y), Red (R). Count = 3.
    *   Output:
        . . X
        . X .
        X . .
    *   Pattern: Anti-diagonal (top-right to bottom-left).
    *   Interpretation: 3 distinct colors -> Anti-diagonal of Xs.

*   **Example 3:**
    *   Input:
        Y Y Y
        Y Y Y
        Y Y Y
    *   Colors present: Yellow (Y). Count = 1.
    *   Output:
        X X X
        . . .
        . . .
    *   Pattern: Top row filled with X.
    *   Interpretation: 1 distinct color -> Top row of Xs. (Consistent with Example 1).

*   **Missing Case:** What about 2 distinct colors?
    *   The metaphor says: "A duo takes a bow along the grand staircase from balcony to pit."
    *   "Grand staircase from balcony to pit" usually implies a diagonal.
    *   In a 3x3 grid, there are two diagonals: Main diagonal (top-left to bottom-right) and Anti-diagonal (top-right to bottom-left).
    *   Example 2 (3 colors) used the Anti-diagonal.
    *   Example 1 & 3 (1 color) used the Top Row.
    *   Hypothesis for 2 colors: Main diagonal (top-left to bottom-right).
    *   Let's check the metaphor again: "A trio crosses paths, saluting from opposite wings through center stage." This sounds like an X shape or crossing lines, but the output for 3 colors is a single anti-diagonal line. Wait, "opposite wings through center stage" could imply the anti-diagonal (top-right wing to bottom-left pit/wing).
    *   "A duo takes a bow along the grand staircase from balcony to pit." Balcony is usually top, pit is bottom. Staircase implies diagonal. If 3 colors is anti-diagonal, maybe 2 colors is main diagonal? Or maybe the metaphor implies specific positions.
    *   Let's look at the counts again.
        *   1 Color -> Row 0 (Top).
        *   3 Colors -> Anti-diagonal (Top-Right to Bottom-Left).
        *   2 Colors -> ? Likely Main Diagonal (Top-Left to Bottom-Right).
    *   Why? Usually, these puzzles map counts to specific geometric patterns.
        *   1 -> Horizontal line.
        *   2 -> Diagonal line (Main).
        *   3 -> Diagonal line (Anti).
    *   Let's verify the "3 colors" output in Example 2.
        Input:
        G G G
        Y R R
        Y Y R
        Distinct: G, Y, R. Count = 3.
        Output:
        . . X
        . X .
        X . .
        This is indeed the anti-diagonal.
    *   So, the mapping seems to be:
        *   Count = 1: Top Row (Row 0).
        *   Count = 2: Main Diagonal (0,0), (1,1), (2,2).
        *   Count = 3: Anti-Diagonal (0,2), (1,1), (2,0).

**3. Analyze the Test Input:**
*   Input:
    Y Y Y
    R G R
    G R G
*   Identify distinct colors:
    *   Row 0: Y (Yellow)
    *   Row 1: R (Red), G (Green)
    *   Row 2: G (Green), R (Red)
    *   Set of colors: {Y, R, G}.
    *   Count = 3.
*   Apply Rule for Count = 3:
    *   Pattern: Anti-diagonal of Grey (X).
    *   Grid size: 3x3.
    *   Positions: (0, 2), (1, 1), (2, 0).
    *   Rest of grid: Black (.).

**4. Construct the Output:**
*   Row 0: . . X
*   Row 1: . X .
*   Row 2: X . .

**5. Conceptual Digestion:**
1.  **CAST:**
    *   Input Grid: Represents the "stage" with "performers" (colored cells).
    *   Colors: Represent "factions".
    *   Output Grid: Represents the "dark stage" with "spotlights".
    *   Grey (X): Represents a spotlight.
    *   Black (.): Represents darkness/empty stage.
2.  **AFFORDANCES:**
    *   The input grid allows counting the number of unique color valu

... [5245 chars truncated]
alt-1 biology qwen3.5-122b: k=2
"A cell biologist examines a tissue sample under the microscope. The diversity of cell types determines whether the organism's skeleton crystallizes as a flat plate, a right-handed helix, or a left-handed helix."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (12654 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Tissue sample of colored cells", "petri dish", "skeleton that forms across the dark medium", "biodiversity".
*   **Grid Size:** 3x3.
*   **Key Elements:**
    *   "Dark medium" -> likely the background color (black `.`).
    *   "Colored cells" -> the input grid contains colors.
    *   "Skeleton" / "Imprint" -> The output grid.
    *   "Three calcified grey nodes" -> The output contains exactly three grey (`X`) pixels.
    *   "Arranged in a pattern that echoes the richness of the sample" -> The position of the grey nodes depends on the input pattern.
    *   "Dark except for three calcified grey nodes" -> The output background is black (`.`), and there are exactly three `X`s.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
        (All Green)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey `X`, rest is Black `.`)
    *   Observation: Input is uniform. Output has 3 `X`s in the top row.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
        (Top row Green, Middle Yellow/Red, Bottom Yellow/Red)
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
        (Diagonal from top-right to bottom-left is Grey `X`, rest is Black `.`)
    *   Observation: Input is mixed. Output has 3 `X`s on the anti-diagonal.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: Represents the "tissue sample" or "biodiversity". It contains various colors.
    *   Output Grid: Represents the "skeleton" or "imprint". It is a 3x3 grid.
    *   Elements:
        *   Input Colors (G, Y, R, etc.): Indicate the state of the sample.
        *   Output Colors (X, .): X represents the "calcified nodes" (active points), . represents the "dark medium" (inactive background).

*   **AFFORDANCES:**
    *   The input grid determines the configuration of the output grid.
    *   The output grid always has exactly three `X`s and six `.`s.
    *   The position of the `X`s seems to correspond to some property of the input grid.

*   **TRANSFORMATION RULE:**
    *   Let's look at the relationship between Input and Output positions.
    *   **Example 1:** Input is all `G`. Output `X`s are at (0,0), (0,1), (0,2). This is the top row.
    *   **Example 2:** Input has `G` in top row, `Y` and `R` elsewhere. Output `X`s are at (0,2), (1,1), (2,0). This is the anti-diagonal.

    *   Hypothesis 1: Count colors?
        *   Ex 1: 9 Green. Output: Top row.
        *   Ex 2: 3 Green, 3 Yellow, 3 Red. Output: Anti-diagonal.
        *   This doesn't immediately suggest a mapping to specific rows/cols/diagonals based on counts alone without more data.

    *   Hypothesis 2: Look at the "dominant" color or specific color locations.
        *   Ex 1: All Green. Top row.
        *   Ex 2: Top row is Green. Middle/Bottom are Y/R. Anti-diagonal.
        *   Wait, in Ex 1, the top row is Green. In Ex 2, the top row is Green.
        *   In Ex 1, the output is the top row.
        *   In Ex 2, the output is the anti-diagonal.
        *   Why the difference?
        *   Maybe it depends on the *uniqueness* or *uniformity*?
        *   Ex 1 is uniform. Ex 2 is not.
        *   Maybe it depends on the specific colors present?
        *   Ex 1: Only G.
        *   Ex 2: G, Y, R.

    *   Hypothesis 3: Look at the "skeleton" metaphor. "Skeleton that forms across the dark medium reflects the complexity".
    *   Maybe it's about finding a specific pattern in the input that matches a "skeleton" shape?
    *   Or maybe it's simpler. Let's look at the Test Input.
    *   Test Input:
        ```
        Y Y Y
        R G R
        G R G
        ```
    *   Colors: Y (3), R (4), G (2).
    *   Top row is all Y.
    *   Middle/Bottom are mixed R/G.

    *   Let's re-evaluate Ex 1 and Ex 2.
    *   Ex 1: Top row is G G G. Output is Top Row X X X.
    *   Ex 2: Top row is G G G. Output is Anti-Diagonal.
    *   Wait, in Ex 2, the top row is also G G G.
    *   So, "Top row is all same color" is true for both.
    *   Why different outputs?
    *   Ex 1: Entire grid is G G G.
    *   Ex 2: Only top row is G G G. The rest is mixed.
    *   Test Input: Top row is Y Y Y. The rest is mixed.
    *   This looks like Ex 2's structure (Uniform top row, mixed rest).
    *   If the structure matches Ex 2, the output should match Ex 2's output pattern (Anti-diagonal).
    *   Let's check if there's a deeper logic.
    *   Maybe it's about the "majority" color?
        *   Ex 1: Majority G. Output Top Row.
        *   Ex 2: G=3, Y=3, R=3. Tie. Output Anti-Diagonal.
        *   Test: R=4, Y=3, G=2. Majority R.
    *   Maybe it's about the color of the top row?
       

... [7714 chars truncated]
alt-10 astronomy qwen3.5-122b: k=2
"An astronomer catalogs the spectral classes of stars in a cluster. A uniform cluster emits radiation in a flat band across the observatory sensor; binary systems cast a diagonal streak; triple-star systems refract light along the opposing diagonal."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (13190 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A 3x3 star cluster with colored spectral signatures." This implies the input is a 3x3 grid of colored cells.
*   **Task:** "Classify the spectral diversity and record the grey emission pattern on the dark sensor array."
*   **Output:** "The sensor array is 3x3 black with three grey readings." This implies the output is a 3x3 grid where most cells are black (`.`) and some are grey (`X`). Specifically, it mentions "three grey readings".

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
        (All Green)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest Black)
    *   Observation: Input has 1 unique color (Green). Output has 3 Grey cells in the top row.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
        (Colors: G, Y, R)
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
        (Diagonal from top-right to bottom-left is Grey, rest Black)
    *   Observation: Input has 3 unique colors (Green, Yellow, Red). Output has 3 Grey cells on the anti-diagonal.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: Represents a "star cluster" or a set of data points with "spectral signatures" (colors).
    *   Output Grid: Represents a "sensor array" (black background) recording "grey emissions".
    *   Colors in Input: Represent the "spectral diversity".
    *   Grey (`X`) in Output: Represents the "recorded emission".
    *   Black (`.`) in Output: Represents the "dark sensor array" (no emission).

*   **AFFORDANCES:**
    *   The input grid's colors can be counted or categorized.
    *   The output grid's pattern seems to depend on the properties of the input grid (specifically the number of unique colors).
    *   The position of the grey cells changes based on the input.

*   **TRANSFORMATION RULE:**
    *   Let's look at the number of unique colors in the input.
    *   Example 1: Input has only `G`. Count = 1. Output has 3 `X`s in the first row (Row 0).
    *   Example 2: Input has `G`, `Y`, `R`. Count = 3. Output has 3 `X`s on the anti-diagonal (Row 0, Col 2; Row 1, Col 1; Row 2, Col 0).
    *   Wait, the description says "record the grey emission pattern... with three grey readings". Both examples have exactly 3 grey cells in the output.
    *   So the number of grey cells is constant (3). The position depends on the input.
    *   What determines the position?
    *   Example 1 (1 unique color): Top row (`X X X`).
    *   Example 2 (3 unique colors): Anti-diagonal (`X` at (0,2), (1,1), (2,0)).
    *   Let's check the Test Input.
    *   Test Input:
        ```
        Y Y Y
        R G R
        G R G
        ```
        Colors present: `Y`, `R`, `G`.
        Unique colors: Yellow, Red, Green. Count = 3.
    *   If the rule is based on the count of unique colors:
        *   Count = 1 -> Top Row.
        *   Count = 3 -> Anti-diagonal.
    *   Is there a pattern for Count = 2? Or Count = 3?
    *   Let's look closer at Example 2.
        Input:
        G G G
        Y R R
        Y Y R
        Colors: G, Y, R.
        Output: Anti-diagonal.
    *   Test Input:
        Y Y Y
        R G R
        G R G
        Colors: Y, R, G.
        This is the same set of colors as Example 2 (Green, Yellow, Red). Just arranged differently.
        In Example 2, the output was the anti-diagonal.
        In the Test Input, the set of unique colors is {Y, R, G}. This is the same set as Example 2.
        Therefore, the output pattern should likely be the same as Example 2.

    *   Let's consider if the specific arrangement matters.
        Example 2 Input:
        Row 0: G G G (All same)
        Row 1: Y R R
        Row 2: Y Y R
        Test Input:
        Row 0: Y Y Y (All same)
        Row 1: R G R
        Row 2: G R G
        Both have a row of identical colors at the top.
        Both have 3 unique colors total.
        The output for Example 2 was the anti-diagonal.
        Hypothesis: The output pattern depends on the number of unique colors.
        If Unique Colors = 1 -> Top Row.
        If Unique Colors = 3 -> Anti-Diagonal.
        What if Unique Colors = 2? We don't have an example.
        However, the Test Input has 3 unique colors (Y, R, G).
        So it should follow the rule for 3 unique colors.

    *   Let's check if there's a more specific mapping.
        Maybe it's about the "dominant" color or the color of the first row?
        Example 1: First row G. Unique count 1. Output Top Row.
        Example 2: First row G. Unique count 3. Output Anti-Diagonal.
        Test Input: First row Y. Unique count 3.
        If the rule is purely based on unique count, the first row c

... [8253 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=3
"A navigator reads the colors of the ocean currents on the chart. Uniform waters send the wake straight across the bow; two currents meeting carve a diagonal course to starboard; where three currents converge, the ship tacks hard to port along the counter-diagonal."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (12299 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A 3x3 ocean chart with colored current zones."
*   **Output:** "Read the currents and plot three grey waypoints on the dark nautical chart."
*   **Grid details:** "The chart is 3x3 black with three grey waypoints marking the vessel's course."
*   **Key implication:** The output grid is 3x3. The background is black (`.`). There are exactly three grey (`X`) waypoints. The input grid seems to contain information that determines where these waypoints go.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
        (All Green)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest is Black)
    *   Observation: Input is uniform color (Green). Output has 3 Grey pixels in the top row.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
        (Top row Green, Middle/Bottom mixed Yellow/Red)
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
        (Diagonal from top-right to bottom-left is Grey, rest is Black)
    *   Observation: Input is mixed. Output has 3 Grey pixels on the anti-diagonal.

*   **Example 3:**
    *   Input:
        ```
        Y Y Y
        Y Y Y
        Y Y Y
        ```
        (All Yellow)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest is Black)
    *   Observation: Input is uniform color (Yellow). Output has 3 Grey pixels in the top row.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: 3x3 matrix of colored cells.
    *   Output Grid: 3x3 matrix of black (`.`) and grey (`X`) cells.
    *   The "currents" in the metaphor likely refer to the colors in the input grid.
    *   The "waypoints" are the grey pixels (`X`).

*   **AFFORDANCES:**
    *   The input colors determine the pattern of the output.
    *   The output always has exactly 3 grey pixels.
    *   The output background is always black.

*   **TRANSFORMATION RULE:**
    *   Let's look at the relationship between Input and Output patterns.
    *   **Case 1 (Uniform Input):**
        *   Ex 1: All Green -> Top Row Grey (`X X X`, `. . .`, `. . .`).
        *   Ex 3: All Yellow -> Top Row Grey (`X X X`, `. . .`, `. . .`).
        *   Hypothesis: If all cells in the input are the same color, the output is the top row filled with Grey.
    *   **Case 2 (Mixed Input):**
        *   Ex 2: Mixed (G, Y, R) -> Anti-diagonal Grey (`. . X`, `. X .`, `X . .`).
        *   Hypothesis: If the input cells are not all the same color, the output is the anti-diagonal filled with Grey.

    *   Let's check the Test Input:
        ```
        Y Y Y
        R G R
        G R G
        ```
        *   Row 1: Y Y Y
        *   Row 2: R G R
        *   Row 3: G R G
        *   Are all cells the same color? No. There are Y, R, and G.
        *   Therefore, this falls under the "Mixed Input" category (like Example 2).
        *   Expected Output Pattern: Anti-diagonal Grey.
        *   Pattern:
            ```
            . . X
            . X .
            X . .
            ```

    *   Wait, is there a more specific rule based on the specific colors?
        *   Ex 1 (All G) -> Top Row.
        *   Ex 3 (All Y) -> Top Row.
        *   Ex 2 (Mixed) -> Anti-diagonal.
        *   Test Input (Mixed) -> Anti-diagonal?

    *   Let's consider if the specific colors matter for the position.
        *   Ex 1: Green -> Top Row.
        *   Ex 3: Yellow -> Top Row.
        *   Ex 2: Green, Yellow, Red -> Anti-diagonal.
        *   Test: Yellow, Red, Green -> Anti-diagonal.

    *   Is there a distinction between "Uniform" and "Mixed"?
        *   Ex 1: Uniform.
        *   Ex 3: Uniform.
        *   Ex 2: Non-uniform.
        *   Test: Non-uniform.

    *   Is there a distinction based on the dominant color?
        *   Ex 1: 9 Green.
        *   Ex 3: 9 Yellow.
        *   Ex 2: 3 Green, 3 Yellow, 3 Red. (Actually: Row 1: GGG, Row 2: YRR, Row 3: YYR. Counts: G=3, Y=3, R=3).
        *   Test: Row 1: YYY, Row 2: RGR, Row 3: GRG. Counts: Y=3, R=4, G=2.
        *   The counts in Ex 2 are perfectly balanced (3 of each). The counts in Test are not (3 Y, 4 R, 2 G).
        *   However, the primary distinction seems to be Uniform vs. Non-Uniform.
        *   If Uniform -> Top Row.
        *   If Non-Uniform -> Anti-diagonal.

    *   Let's check if there's any other interpretation.
        *   Maybe it's about the first row?
            *   Ex 1: First row GGG. Output Top Row.
            *   Ex 3: First row YYY. Output Top Row.
            *   Ex 2: First row GGG. Output Anti-diagonal.
            *   This contradicts the "First row determines output" idea be

... [7374 chars truncated]
alt-12 electronics qwen3.5-122b: k=2
"A circuit designer examines the voltage levels on an input bus. A single voltage level routes current straight across the top trace; two distinct levels activate the main diagonal path through the resistor matrix; three levels trigger the cross-diagonal failsafe."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11663 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A 3x3 bus of colored voltage indicators." This suggests the input is a 3x3 grid of colored cells.
*   **Action:** "Measure the distinct signal levels and light up three grey LEDs on the dark circuit board."
*   **Output:** "The board is 3x3 black with three grey LEDs." This suggests the output is a 3x3 grid where most cells are black (`.`) and exactly three cells are grey (`X`).
*   **Key Insight:** The transformation involves counting or identifying something in the input grid and placing 3 grey pixels (`X`) in the output grid based on that information. The background of the output is black (`.`).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
        (All Green)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest Black)
    *   Observation: The input has only one distinct color (Green). The output has 3 grey pixels in the top row.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
        (Colors: Green, Yellow, Red)
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
        (Diagonal from top-right to bottom-left is Grey, rest Black)
    *   Observation: The input has 3 distinct colors (Green, Yellow, Red). The output has 3 grey pixels arranged diagonally.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: Represents "colored voltage indicators".
    *   Output Grid: Represents a "dark circuit board" with "grey LEDs".
    *   Colors in Input: Represent "signal levels".
    *   Grey (`X`) in Output: Represents "lit LEDs".
    *   Black (`.`) in Output: Represents "dark board".

*   **AFFORDANCES:**
    *   Input colors can be counted or categorized.
    *   Output positions can be determined by the count or type of input colors.
    *   The output always has exactly 3 grey pixels.

*   **TRANSFORMATION RULE:**
    *   Let's look at the relationship between input colors and output pattern.
    *   **Example 1:** Input has 1 distinct color (Green). Output pattern: Top row (Row 0).
    *   **Example 2:** Input has 3 distinct colors (Green, Yellow, Red). Output pattern: Anti-diagonal (Top-Right to Bottom-Left).
    *   Wait, let's look closer at the counts.
    *   Example 1: 9 Green cells. 1 distinct color. Output: 3 X's in Row 0.
    *   Example 2: 3 Green, 2 Yellow, 4 Red. 3 distinct colors. Output: 3 X's in Anti-diagonal.
    *   Is it based on the number of distinct colors?
        *   1 distinct color -> Row 0 (X X X)
        *   3 distinct colors -> Anti-diagonal (X at (0,2), (1,1), (2,0))
    *   What about the Test Input?
        *   Input:
            ```
            Y Y Y
            R G R
            G R G
            ```
        *   Colors present: Yellow (Y), Red (R), Green (G).
        *   Count of distinct colors: 3 (Y, R, G).
    *   If the rule is "Number of distinct colors determines the pattern":
        *   1 distinct color -> Top Row.
        *   3 distinct colors -> Anti-diagonal.
    *   Let's check if there's another interpretation.
    *   Maybe it's about the specific colors?
        *   Ex 1: All Green.
        *   Ex 2: Green, Yellow, Red.
        *   Test: Yellow, Red, Green. (Same set of colors as Ex 2).
    *   If the set of colors is the same (G, Y, R), the output pattern should likely be the same as Example 2.
    *   Let's check the counts of specific colors in Ex 2 vs Test.
        *   Ex 2: G=3, Y=2, R=4.
        *   Test: Y=3, R=4, G=2.
        *   The counts are different, but the set of distinct colors is the same {G, Y, R}.
    *   In Ex 1, the set is {G}.
    *   Hypothesis: The output pattern depends on the *set* of distinct colors present in the input grid.
        *   If {G} -> Top Row.
        *   If {G, Y, R} -> Anti-diagonal.
    *   Test Input has {Y, R, G}. This is the same set as Example 2.
    *   Therefore, the output should match Example 2's output pattern.

    *   Alternative Hypothesis: The output pattern depends on the *number* of distinct colors.
        *   1 distinct color -> Top Row.
        *   3 distinct colors -> Anti-diagonal.
        *   Test Input has 3 distinct colors (Y, R, G).
        *   Therefore, output should be Anti-diagonal.

    *   Both hypotheses lead to the same result for the Test Input. The Anti-diagonal pattern is:
        ```
        . . X
        . X .
        X . .
        ```

    *   Let's consider if there is a mapping based on specific colors.
        *   Maybe Green corresponds to Row 0?
        *   Maybe Red corresponds to Row 1?
        *   Maybe Yellow corresponds to Row 2?
        *   In Ex 1 (All Green): Output is Row 0. This fits "Green -> Row 0".
        *   In Ex 2 (

... [6717 chars truncated]
alt-13 mythology qwen3.5-122b: k=4
"An oracle peers into a mosaic of colored tiles and reads the fate of nations. When the tiles speak with one voice, destiny marches in a rank. Two voices weave fate from throne to grave. Three voices unravel fate from grave to throne."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (11794 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A 3x3 mosaic of colored prophetic tiles."
*   **Task:** "Divine the number of voices in the mosaic and inscribe the grey fate-marks on the dark tablet."
*   **Output:** "The tablet is 3x3 obsidian black with three grey fate-marks."
*   **Key terms:**
    *   "Voices": Likely refers to the distinct colors or specific colored regions in the input grid.
    *   "Grey fate-marks": These correspond to the color 'X' (grey) in the output.
    *   "Dark tablet": The background of the output grid is black ('.').
    *   "Three grey fate-marks": The output grid always contains exactly three 'X's.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: All Green (G).
    *   Output: Top row is X X X, rest is black.
    *   Observation: Input has 1 color (Green). Output has 3 X's in the first row.

*   **Example 2:**
    *   Input:
        G G G
        Y R R
        Y Y R
    *   Colors present: G, Y, R. (3 distinct colors).
    *   Output:
        . . X
        . X .
        X . .
    *   Observation: The X's form a diagonal from top-right to bottom-left.
    *   Wait, let's look at the counts.
    *   Input colors: G (3), Y (3), R (3). Total 9 cells.
    *   Output: 3 X's.
    *   Pattern of X's: (0,2), (1,1), (2,0). Anti-diagonal.

*   **Example 3:**
    *   Input: All Yellow (Y).
    *   Output: Top row is X X X, rest is black.
    *   Observation: Same as Example 1. Input has 1 color. Output has 3 X's in the first row.

*   **Example 4:**
    *   Input:
        Y Y Y
        Y Y Y
        G G G
    *   Colors present: Y, G. (2 distinct colors).
    *   Output:
        X . .
        . X .
        . . X
    *   Observation: The X's form a diagonal from top-left to bottom-right.
    *   Wait, let's re-evaluate the "Voices" concept.
    *   Example 1: 1 Color (G) -> Row 0 filled with X.
    *   Example 3: 1 Color (Y) -> Row 0 filled with X.
    *   Example 4: 2 Colors (Y, G) -> Main Diagonal filled with X.
    *   Example 2: 3 Colors (G, Y, R) -> Anti-Diagonal filled with X.

    *   Hypothesis: The number of distinct colors in the input determines the pattern of the 3 'X's in the output.
    *   1 Distinct Color -> Top Row (Row 0).
    *   2 Distinct Colors -> Main Diagonal (Top-Left to Bottom-Right).
    *   3 Distinct Colors -> Anti-Diagonal (Top-Right to Bottom-Left).

    *   Let's check the counts of colors in Example 2 again.
        G G G (3 Gs)
        Y R R (1 Y, 2 Rs)
        Y Y R (2 Ys, 1 R)
        Total: 3 G, 3 Y, 3 R.
        Distinct colors: 3.
        Pattern: Anti-diagonal.

    *   Let's check Example 4 again.
        Y Y Y
        Y Y Y
        G G G
        Total: 6 Y, 3 G.
        Distinct colors: 2.
        Pattern: Main Diagonal.

    *   Let's check Example 1 & 3 again.
        All one color.
        Distinct colors: 1.
        Pattern: Top Row.

    *   Is there a connection to the specific colors?
        Ex 1: G -> Row 0.
        Ex 3: Y -> Row 0.
        Ex 4: Y, G -> Main Diag.
        Ex 2: G, Y, R -> Anti Diag.

    *   It seems the specific colors don't matter, only the *count* of distinct colors.
    *   Count = 1 -> Row 0 (X X X / . . . / . . .)
    *   Count = 2 -> Main Diag (X . . / . X . / . . X)
    *   Count = 3 -> Anti Diag (. . X / . X . / X . .)

    *   Wait, is it possible the pattern depends on the *majority* color or something else?
    *   In Ex 1 & 3, the whole grid is one color.
    *   In Ex 4, it's split by rows (Top 2 rows Y, Bottom 1 row G).
    *   In Ex 2, it's mixed.

    *   Let's look at the "Voices" metaphor again. "Divine the number of voices".
    *   "Voices" = Distinct Colors.
    *   "Inscribe the grey fate-marks" = Place 3 'X's.
    *   "Dark tablet" = Background '.'.

    *   So the rule is: Count distinct colors $N$.
    *   If $N=1$: Fill Row 0 with X.
    *   If $N=2$: Fill Main Diagonal with X.
    *   If $N=3$: Fill Anti-Diagonal with X.

    *   Are there other possibilities?
    *   Maybe it depends on the number of connected components?
    *   Ex 1: 1 component.
    *   Ex 3: 1 component.
    *   Ex 4: 2 components (Top block Y, Bottom block G).
    *   Ex 2: 3 components?
        G G G (connected)
        Y R R (Y connected to Y below? No, Y at (1,0) connects to Y at (2,0). R at (1,1) connects to R at (1,2) and (2,2).
        Let's trace connectivity (4-way):
        G: (0,0)-(0,2), (1,0). All connected. 1 component.
        Y: (1,0), (2,0), (2,1). (1,0) touches (2,0). (2,0) touches (2,1). All connected. 1 component.
        R: (1,1), (1,2), (2,2). (1,1) touches (1,2). (1,2) touches (2,2). All connected. 1 component.
        So Ex 2 has 3 connected components of distinct colors.
    *   Ex 4:
        Y: (0,0)-(1,2). All connected. 1 component.
        G: (2,0)-(2,2). All connected. 1 component.
     

... [6913 chars truncated]
alt-14 dance qwen3.5-122b: k=2
"A choreographer watches the dancers' costumes swirl and decides the final pose. A troupe in uniform freezes in a chorus line across the stage; two costume groups finish in a cascading fall from corner to corner; three groups end in the mirror-image cascade."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (12809 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A 3x3 stage of dancers in colored costumes.
*   **Action:** Read the costume diversity and place the three grey spotlights for the final freeze-frame on the dark stage floor.
*   **Grid details:** The floor is 3x3 black with three grey marks.
*   **Key implication:** The output grid is always 3x3. The background is black (`.`). There are exactly three grey marks (`X`). The input is a 3x3 grid of colored cells. The position of the grey marks depends on the "costume diversity" of the input.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
        (All Green)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest Black)
    *   Observation: All cells are the same color (Green). The output has 3 grey cells in the top row.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
        (Row 1: GGG, Row 2: YRR, Row 3: YYR)
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
        (Diagonal from top-right to bottom-left is Grey, rest Black)
    *   Observation: The input has mixed colors. Let's look at the counts or patterns.
        *   Row 1: G, G, G (3 same)
        *   Row 2: Y, R, R (2 same, 1 diff)
        *   Row 3: Y, Y, R (2 same, 1 diff)
        *   Total counts: G=3, Y=3, R=3.
        *   Wait, let's look at the output pattern. It's an anti-diagonal.
        *   Let's check the diversity per row or column.
        *   Example 1 Output: Top row filled. Input: All rows identical.
        *   Example 2 Output: Anti-diagonal filled. Input: Mixed.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: 3x3 matrix of colors. Represents "dancers".
    *   Output Grid: 3x3 matrix of Black (`.`) and Grey (`X`). Represents "spotlights".
    *   Constraint: Output always has exactly 3 Grey cells (`X`) and 6 Black cells (`.`).

*   **AFFORDANCES:**
    *   The input colors determine the positions of the `X`s.
    *   The output is binary (Spotlight or Floor).

*   **TRANSFORMATION RULE:**
    *   I need to find a property of the input rows or columns that maps to the positions of the `X`s.
    *   Let's look at Example 1 again.
        Input:
        G G G
        G G G
        G G G
        Output:
        X X X
        . . .
        . . .
        The `X`s are at (0,0), (0,1), (0,2). This corresponds to Row 0.
        Why Row 0? Maybe because all rows are identical? Or maybe it's based on the most frequent color?
        If all rows are identical, maybe the "diversity" is low.
    *   Let's look at Example 2 again.
        Input:
        G G G
        Y R R
        Y Y R
        Output:
        . . X
        . X .
        X . .
        The `X`s are at (0,2), (1,1), (2,0). This is the anti-diagonal.
        Why the anti-diagonal?
        Let's check row uniqueness.
        Row 0: GGG (Uniform)
        Row 1: YRR (Mixed)
        Row 2: YYR (Mixed)
        Let's check column uniqueness.
        Col 0: G, Y, Y (Mixed)
        Col 1: G, R, Y (All different)
        Col 2: G, R, R (Mixed)

    *   Hypothesis 1: The output pattern depends on the number of unique colors in each row or column.
        *   Ex 1: All rows have 1 unique color. Output: Row 0 is X.
        *   Ex 2: Row 0 has 1 unique (G). Row 1 has 2 unique (Y, R). Row 2 has 2 unique (Y, R).
            Output is anti-diagonal. This doesn't seem to map directly to row indices.

    *   Hypothesis 2: The output pattern represents the "majority" or "dominant" feature.
        *   Ex 1: All Green. Output: Top row.
        *   Ex 2: 3 Green, 3 Yellow, 3 Red. Output: Anti-diagonal.

    *   Hypothesis 3: Look at the specific positions of the `X`s.
        *   Ex 1: (0,0), (0,1), (0,2).
        *   Ex 2: (0,2), (1,1), (2,0).
        *   These are specific geometric shapes.
        *   Is there a relationship between the input grid values and the coordinates?
        *   Maybe it's about sorting?
        *   Maybe it's about the "diversity" mentioned in the prompt. "Read the costume diversity".
        *   Diversity usually implies variance.
        *   In Ex 1, diversity is 0 (all same).
        *   In Ex 2, diversity is high.

    *   Let's look at the Test Input:
        ```
        Y Y Y
        R G R
        G R G
        ```
        Row 0: YYY (Uniform)
        Row 1: RGR (Mixed)
        Row 2: GRG (Mixed)
        This looks structurally similar to Example 2.
        Ex 2 Input:
        G G G
        Y R R
        Y Y R
        Test Input:
        Y Y Y
        R G R
        G R G

        In Ex 2, Row 0 is uniform. Row 1 and 2 are mixed.
        In Test, Row 0 is uniform. Row 1 and 2 are mixed.
        However, Ex 2 output was Anti-Diagonal.
        Ex 1 ou

... [7868 chars truncated]
alt-15 geology qwen3.5-122b: k=2
"A geologist cores a rock face and reads the mineral composition. A pure formation fractures in a clean horizontal shear; a binary composite cracks along the grain from surface to depth; a triple-mineral matrix cleaves against the grain."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (13140 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A 3x3 rock face of colored mineral deposits." This implies the input is a 3x3 grid of colored cells.
*   **Task:** "Assay the mineral diversity and mark the three grey fracture points on the dark cross-section."
*   **Output:** "The cross-section is 3x3 black with three grey fracture points." This implies the output is a 3x3 grid where most cells are black (`.`) and exactly three cells are grey (`X`).
*   **Key Insight:** The transformation maps a 3x3 colored input grid to a 3x3 output grid containing only black (`.`) and grey (`X`) cells. Specifically, there are exactly three `X`s. The positions of the `X`s depend on the input grid's content.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
        (All Green)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest Black)
    *   Observation: All cells are the same color (Green). The output has `X`s in the top row.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
        (Mixed colors: G, Y, R)
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
        (Diagonal from top-right to bottom-left is Grey, rest Black)
    *   Observation: The input has diversity. The output has `X`s on the anti-diagonal.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: Represents "mineral deposits". Colors represent types of minerals.
    *   Output Grid: Represents a "cross-section". Black (`.`) represents the rock matrix. Grey (`X`) represents "fracture points".
    *   Constraint: Output always has exactly 3 `X`s.

*   **AFFORDANCES:**
    *   Colors in input can be counted or compared.
    *   Positions in output can be determined by patterns in input.
    *   The "diversity" mentioned in the metaphor likely refers to the variety of colors present in the input grid.

*   **TRANSFORMATION RULE:**
    *   Let's look at the relationship between input colors and output `X` positions.
    *   **Example 1:** Input is uniform (1 color: G). Output `X`s are at (0,0), (0,1), (0,2) -> Top Row.
    *   **Example 2:** Input has 3 colors (G, Y, R). Output `X`s are at (0,2), (1,1), (2,0) -> Anti-diagonal.
    *   **Hypothesis:** The number of unique colors determines the pattern of the `X`s.
        *   1 Unique Color -> Top Row?
        *   3 Unique Colors -> Anti-diagonal?
    *   Let's check the Test Input.
    *   **Test Input:**
        ```
        Y Y Y
        R G R
        G R G
        ```
        Colors present: Y (Yellow), R (Red), G (Green).
        Count of unique colors: 3 (Y, R, G).
    *   If the rule is based on the count of unique colors:
        *   1 unique color -> Top Row.
        *   3 unique colors -> Anti-diagonal.
    *   Wait, is it just the count? Or is it specific colors?
    *   In Example 1, color is G. Output is Top Row.
    *   In Example 2, colors are G, Y, R. Output is Anti-diagonal.
    *   In Test Input, colors are Y, R, G. This is the same set of colors as Example 2 (G, Y, R).
    *   If the set of colors is the same, should the output be the same pattern?
    *   Example 2 Input:
        G G G
        Y R R
        Y Y R
        Unique: G, Y, R.
    *   Test Input:
        Y Y Y
        R G R
        G R G
        Unique: Y, R, G.
    *   Since the set of unique colors is identical (Green, Yellow, Red), it is highly probable that the output pattern should be the same as Example 2.
    *   Pattern for 3 unique colors (G, Y, R): Anti-diagonal (`X` at (0,2), (1,1), (2,0)).

    *   Let's consider if there's a more complex rule.
    *   Maybe it's about the most frequent color?
        *   Ex 1: G (9 times). Output: Top Row.
        *   Ex 2: R (3 times), G (3 times), Y (3 times). All equal frequency. Output: Anti-diagonal.
        *   Test: Y (3 times), R (4 times), G (2 times).
            *   Y: (0,0), (0,1), (0,2) -> 3
            *   R: (1,0), (1,2), (2,1) -> 3
            *   G: (1,1), (2,0), (2,2) -> 3
            *   Wait, let me recount Test Input.
            *   Row 0: Y Y Y (3 Y)
            *   Row 1: R G R (2 R, 1 G)
            *   Row 2: G R G (1 R, 2 G)
            *   Total: Y=3, R=3, G=3.
            *   Ah, I miscounted R in my head.
            *   Row 1: R, G, R -> 2 R.
            *   Row 2: G, R, G -> 1 R.
            *   Total R = 3.
            *   Total G = 1 (Row 1) + 2 (Row 2) = 3.
            *   Total Y = 3.
            *   So Test Input also has equal frequency of 3 colors (Y, R, G).
    *   This strengthens the hypothesis:
        *   Case 1: 1 Unique Color (Uniform) -> Top Row `X`s.
        *   Case 2: 3 Unique Colors (Equal distribution or just presence) -> Anti-diag

... [8251 chars truncated]
alt-2 cooking qwen3.5-122b: k=2
"A chef tastes a stew and judges its complexity. A simple broth gets a flat garnish across the rim; a two-flavor blend earns a cascading drizzle corner to corner; a three-spice medley receives a contrary slash."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (12801 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A pot of ingredients fills the kitchen counter, each ingredient a different hue." -> Input grid contains various colors.
*   "Taste the stew and judge its complexity." -> Analyze the input grid.
*   "Plate the grey sauce on a dark dish in the pattern that honors the depth of flavor." -> Output grid is mostly black (dark dish) with grey (X) sauce drops.
*   "Both the pot and the plate are 3x3." -> Input and Output are 3x3 grids.
*   "The plate is clean black except for three drops of grey sauce whose arrangement speaks to the palate." -> Output grid is 3x3, mostly black (`.`), with exactly three `X` (grey) pixels.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
        (All Green)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest Black)
    *   Observation: Input is uniform color. Output has 3 grey pixels in the top row.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
        (Top row Green, Middle: Yellow, Red, Red, Bottom: Yellow, Yellow, Red)
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
        (Diagonal from top-right to bottom-left is Grey, rest Black)
    *   Observation: Input is mixed colors. Output has 3 grey pixels in a diagonal pattern.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: Represents the "pot of ingredients". Colors represent different ingredients.
    *   Output Grid: Represents the "plate". Background is black (`.`), foreground is grey sauce (`X`).
    *   Transformation: Maps the content of the input grid to a specific pattern of 3 grey pixels on a black background.

*   **AFFORDANCES:**
    *   The input grid's colors determine the pattern.
    *   The output grid is always 3x3.
    *   The output always contains exactly 3 `X` pixels.
    *   The rest of the output pixels are `.`.

*   **TRANSFORMATION RULE:**
    *   I need to find a property of the input grid that dictates the position of the 3 `X`s in the output.
    *   Let's look at the counts of colors in the input.
    *   **Example 1:**
        *   Input: 9 Green (`G`).
        *   Output: Top row `X X X`.
        *   Maybe it relates to the most frequent color? Or the specific color?
        *   If all are Green, maybe it means "Row 1"?
    *   **Example 2:**
        *   Input:
            *   G: 3
            *   Y: 3
            *   R: 3
        *   Output: Anti-diagonal `X . .` / `. X .` / `X . .` (Wait, let's check the example output again).
        *   Example 2 Output:
            ```
            . . X
            . X .
            X . .
            ```
            This is the anti-diagonal (top-right to bottom-left).
    *   Let's check the counts again.
        *   Example 1: 9 G. Output: Row 1.
        *   Example 2: 3 G, 3 Y, 3 R. Output: Anti-diagonal.
    *   Is there a connection between the colors and the positions?
    *   Maybe it's about the *number* of distinct colors?
        *   Ex 1: 1 distinct color (G). Output: Row 1.
        *   Ex 2: 3 distinct colors (G, Y, R). Output: Anti-diagonal.
    *   What about the Test Input?
        *   Input:
            ```
            Y Y Y
            R G R
            G R G
            ```
        *   Colors present: Y, R, G.
        *   Counts:
            *   Y: 3 (Row 1)
            *   R: 3 (Row 2: 2, Row 3: 1) -> Total 3.
            *   G: 3 (Row 2: 1, Row 3: 2) -> Total 3.
        *   This looks exactly like Example 2 in terms of color distribution (3 of each of 3 colors).
        *   In Example 2, the output was the anti-diagonal.
        *   However, the arrangement of colors in Example 2 was:
            ```
            G G G
            Y R R
            Y Y R
            ```
            Top row is all G.
        *   In the Test Input:
            ```
            Y Y Y
            R G R
            G R G
            ```
            Top row is all Y.
        *   Does the specific color matter? Or just the count?
        *   In Ex 1, Top row was G, Output was Top row X.
        *   In Ex 2, Top row was G, Output was Anti-diagonal.
        *   This suggests the specific color *might* matter, or the arrangement matters.
        *   Let's look for a mapping between colors and positions.
        *   Common mappings in ARC-like tasks:
            *   Colors map to directions or specific cells.
            *   Counts map to shapes.
    *   Hypothesis 1: The output pattern depends on the number of unique colors.
        *   1 unique color -> Top Row.
        *   3 unique colors -> Anti-diagonal.
        *   Test Input has 3 unique colors (Y, R, G). So maybe Anti-diagonal?
    *   Hypothesis 2: The output pattern depend

... [7888 chars truncated]
alt-3 music qwen3.5-122b: k=3
"A composer listens to a chord and scores the resonance pattern. A unison note hums across a single staff line; a dyad vibrates along the descending strings; a triad reverberates against the ascending brass."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (12647 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A chord of colored tones rings out across a 3x3 sound field." -> Input is a 3x3 grid of colors.
*   "Listen to how many distinct voices sing in the chord" -> Count the number of unique colors in the input grid.
*   "then etch the resonance pattern in grey on a silent black score." -> Output is a 3x3 grid. Background is black ('.'). The "resonance pattern" is grey ('X').
*   "The score is 3x3, silent black, with three grey notes placed where the resonance lands." -> This part is slightly confusing. "three grey notes"? Does it mean exactly three 'X's? Or does it mean the number of 'X's corresponds to the number of distinct voices? Let's look at the examples.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        G G G
        G G G
        G G G
    *   Colors present: Green (G). Count = 1.
    *   Output:
        X X X
        . . .
        . . .
    *   Grey notes ('X') count: 3.
    *   Wait, the metaphor says "three grey notes placed where the resonance lands". But Example 1 has 3 'X's. The input has 1 distinct color.
    *   Let's check the position. Top row is all X.
    *   Maybe the number of 'X's isn't the count of distinct colors.
    *   Let's re-read: "Listen to how many distinct voices sing in the chord, then etch the resonance pattern in grey... with three grey notes placed where the resonance lands."
    *   This phrasing "with three grey notes" might be a fixed property of the output description, or it might be specific to Example 1.
    *   Let's look at Example 2.

*   **Example 2:**
    *   Input:
        G G G
        Y R R
        Y Y R
    *   Colors present: Green (G), Yellow (Y), Red (R). Count = 3 distinct colors.
    *   Output:
        . . X
        . X .
        X . .
    *   Grey notes ('X') count: 3.
    *   Positions: (0,2), (1,1), (2,0). This is the anti-diagonal.
    *   In Example 1, positions were (0,0), (0,1), (0,2). This is the top row.
    *   Why top row in Ex 1 and anti-diagonal in Ex 2?
    *   Input Ex 1: All Green.
    *   Input Ex 2: Mixed G, Y, R.
    *   Maybe the pattern depends on the arrangement of colors?
    *   Or maybe it depends on the count of distinct colors?
    *   Ex 1: 1 distinct color -> Top row filled with X.
    *   Ex 2: 3 distinct colors -> Anti-diagonal filled with X.
    *   Let's check Example 3.

*   **Example 3:**
    *   Input:
        Y Y Y
        Y Y Y
        Y Y Y
    *   Colors present: Yellow (Y). Count = 1.
    *   Output:
        X X X
        . . .
        . . .
    *   Grey notes ('X') count: 3.
    *   Positions: Top row.
    *   This matches Example 1. Both have 1 distinct color. Both output top row of X's.

*   **Hypothesis 1:** The output depends on the number of distinct colors in the input.
    *   1 distinct color -> Top row (X X X / . . . / . . .).
    *   3 distinct colors -> Anti-diagonal (. . X / . X . / X . .).
    *   What about 2 distinct colors? Or other patterns?
    *   The metaphor says "Listen to how many distinct voices sing in the chord". This strongly suggests the count of unique colors is the key variable.
    *   The metaphor also says "with three grey notes placed where the resonance lands". This implies the output always has exactly 3 'X's.
    *   So the task is: Count unique colors $N$. Map $N$ to a specific pattern of 3 'X's on a 3x3 black grid.
    *   From Ex 1 & 3: $N=1 \rightarrow$ Top Row.
    *   From Ex 2: $N=3 \rightarrow$ Anti-diagonal.
    *   What determines the pattern?
    *   Maybe it's related to the specific colors?
    *   Ex 1: G. Ex 3: Y. Both result in Top Row. So specific color doesn't matter, just the count.
    *   Ex 2: G, Y, R. Result: Anti-diagonal.
    *   Is there a pattern for $N=2$? I don't have an example.
    *   Let's look at the Test Input.

*   **Test Input:**
    *   Y Y Y
    *   R G R
    *   G R G
    *   Colors present: Yellow (Y), Red (R), Green (G).
    *   Count of distinct colors: 3 (Y, R, G).
    *   This matches Example 2's distinct color count (3).
    *   Example 2 Input:
        G G G
        Y R R
        Y Y R
        Distinct: G, Y, R. Count = 3.
    *   Test Input Distinct: Y, R, G. Count = 3.
    *   If the rule is purely based on the count of distinct colors, the output should be the same as Example 2.
    *   Output for Ex 2:
        . . X
        . X .
        X . .
    *   Let's verify if there are other factors.
    *   Ex 2 Input structure:
        Row 0: G G G (1 color)
        Row 1: Y R R (2 colors)
        Row 2: Y Y R (2 colors)
    *   Test Input structure:
        Row 0: Y Y Y (1 color)
        Row 1: R G R (2 colors)
        Row 2: G R G (2 colors)
    *   The structure is very similar. Row 0 is uniform. Rows 1 and 2 are mixed.
    *   In Ex 2, Row 0 was the dominant color of the top row? No, Row 0 was all G.
    *  

... [7731 chars truncated]
alt-4 sports qwen3.5-122b: k=2
"A referee surveys the jerseys on a playing field and signals the formation. Identical kits mean the team lines up shoulder to shoulder; two rival colors march in lockstep down the pitch; three factions scatter to opposite flanks."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (13489 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "Players in colored jerseys fill the 3x3 pitch." -> The input is a 3x3 grid filled with colored cells (non-black).
*   "Count the factions on the field and signal the grey markers into formation on the dark scoreboard." -> The output is a 3x3 grid. The "dark scoreboard" implies a black background (`.`). The "grey markers" (`X`) are placed based on the count of "factions".
*   "Factions" likely refers to the distinct colors present in the input grid.
*   "Signal the grey markers into formation" suggests the number of grey markers corresponds to the number of factions, and their arrangement might follow a specific pattern.
*   "Scoreboard is 3x3 black with three grey markers arranged according to the referee's call." -> This part is slightly confusing. It says "three grey markers" but the examples show different numbers of X's. Let's look at the examples to clarify.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
    *   Colors present: Green (G). Count = 1 faction.
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
    *   Output contains 3 Grey (X) markers.
    *   Wait, the metaphor says "Count the factions". If there is 1 faction, why are there 3 markers?
    *   Maybe it's not counting the *number* of factions, but something else.
    *   Let's look at the arrangement. The top row is filled with X.
    *   Is it related to the dominant color? Or the count of cells of a specific color?
    *   Input has 9 Green cells. Output has 3 X cells.
    *   Maybe it's counting the number of *rows* or *columns* that are uniform?
    *   Let's check Example 2.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
    *   Colors present: Green (G), Yellow (Y), Red (R). Count = 3 factions.
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
    *   Output contains 3 Grey (X) markers.
    *   Arrangement: Diagonal from top-right to bottom-left.
    *   In Example 1, the arrangement was the top row.
    *   Let's re-read the metaphor: "Count the factions on the field and signal the grey markers into formation on the dark scoreboard."
    *   Maybe the number of markers equals the number of factions?
        *   Ex 1: 1 faction (Green). Markers = 3. (Doesn't match 1).
        *   Ex 2: 3 factions (G, Y, R). Markers = 3. (Matches 3).
    *   This hypothesis is inconsistent.
    *   Let's look at the counts of specific colors.
        *   Ex 1: 9 Green.
        *   Ex 2: 3 Green, 3 Yellow, 3 Red.
    *   In Ex 2, each color appears exactly 3 times.
    *   In Ex 1, Green appears 9 times.
    *   Maybe the number of markers is always 3?
        *   Ex 1: 3 markers.
        *   Ex 2: 3 markers.
    *   If the number of markers is always 3, what determines the *position*?
    *   Ex 1 Position: Top row (0,0), (0,1), (0,2).
    *   Ex 2 Position: Anti-diagonal (0,2), (1,1), (2,0).
    *   What distinguishes Ex 1 from Ex 2?
    *   Ex 1 Input is uniform (all one color).
    *   Ex 2 Input is mixed (three colors).
    *   Is there a mapping from the input pattern to the output pattern?
    *   Let's look at the "factions" idea again.
    *   Ex 1: 1 Faction. Output: Row 0 filled.
    *   Ex 2: 3 Factions. Output: Anti-diagonal filled.
    *   Is there a Test Input?
        ```
        Y Y Y
        R G R
        G R G
        ```
    *   Colors: Yellow (Y), Red (R), Green (G).
    *   Counts:
        *   Y: 3 (Row 0)
        *   R: 3 (Row 1 has 2, Row 2 has 1) -> Total 3.
        *   G: 3 (Row 1 has 1, Row 2 has 2) -> Total 3.
    *   So, Test Input has 3 factions, each appearing 3 times. This looks structurally similar to Example 2 (3 factions, each appearing 3 times).
    *   In Example 2, the output was the anti-diagonal.
    *   In Example 1, the output was the top row.
    *   Why the difference?
    *   Ex 1: All cells are the same color.
    *   Ex 2: Cells are mixed.
    *   Test Input: Cells are mixed.
    *   Hypothesis: If the grid is monochromatic, output top row. If the grid is polychromatic (specifically 3 colors with 3 of each?), output anti-diagonal.
    *   Let's check if there's a more specific rule.
    *   Maybe it counts the number of *distinct colors*?
        *   Ex 1: 1 color. Output: 3 X's.
        *   Ex 2: 3 colors. Output: 3 X's.
        *   Test: 3 colors. Output: Likely 3 X's.
    *   Why 3 X's? The metaphor says "signal the grey markers". It doesn't explicitly say the number of markers equals the number of factions. It says "Count the factions... and signal...".
    *   Maybe the "3x3 pitch" implies the output is always 3 markers?
    *   Let's look at the arrangement logic.
    *   Ex 1 (1 color): Top Row.
    *   Ex 2 (3 col

... [8531 chars truncated]
alt-5 weather qwen3.5-122b: k=3
"A meteorologist reads the colors of the sky at dawn. A monochrome sky means the storm front rolls in flat along the horizon; two-toned skies send lightning arcing from one corner down to the other; a sky of three hues drives the wind diagonally against the grain."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (12872 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A 3x3 patch of dawn sky painted in colored bands." -> Input is a 3x3 grid of colors.
*   "What to do: Read the atmospheric palette and chart the grey storm pattern on the dark radar screen." -> Output is a 3x3 grid. "Dark radar screen" implies a black background (represented by `.`). "Grey storm pattern" implies grey pixels (represented by `X`).
*   "Grid details: The radar is 3x3 black. Three grey blips appear in a formation dictated by the sky's chromatic complexity." -> Output is 3x3, mostly black (`.`), with exactly three grey pixels (`X`). The position of these three `X`s depends on the input grid's colors.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        G G G
        G G G
        G G G
    *   Output:
        X X X
        . . .
        . . .
    *   Observation: Input is all Green. Output has 3 Grey pixels in the top row.

*   **Example 2:**
    *   Input:
        G G G
        Y R R
        Y Y R
    *   Output:
        . . X
        . X .
        X . .
    *   Observation: Input has mixed colors (G, Y, R). Output has 3 Grey pixels on the anti-diagonal (top-right, center, bottom-left).

*   **Example 3:**
    *   Input:
        Y Y Y
        Y Y Y
        Y Y Y
    *   Output:
        X X X
        . . .
        . . .
    *   Observation: Input is all Yellow. Output has 3 Grey pixels in the top row. Same as Example 1.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: 3x3 matrix of colored cells.
    *   Output Grid: 3x3 matrix of black (`.`) and grey (`X`) cells.
    *   Specific Elements:
        *   `.` (Black): Background/Empty.
        *   `X` (Grey): Active markers/blips.
        *   Input Colors: G (Green), Y (Yellow), R (Red).

*   **AFFORDANCES:**
    *   The input grid determines the pattern of `X`s in the output grid.
    *   The output grid is always 3x3.
    *   The output grid always contains exactly three `X`s.
    *   The rest of the output grid is `.`.

*   **TRANSFORMATION RULE:**
    *   I need to find a mapping from the input color configuration to the position of the three `X`s.
    *   Let's look at the counts of colors in the input.
    *   **Example 1:** All Green (9 Green). Output: Top row (Row 0).
    *   **Example 3:** All Yellow (9 Yellow). Output: Top row (Row 0).
    *   **Example 2:**
        *   Row 0: G G G (3 Green)
        *   Row 1: Y R R (1 Yellow, 2 Red)
        *   Row 2: Y Y R (2 Yellow, 1 Red)
        *   Total counts: G=3, Y=3, R=3.
        *   Output: Anti-diagonal (Top-Right, Center, Bottom-Left). Coordinates: (0,2), (1,1), (2,0).

    *   Wait, let's look closer at the input patterns.
    *   Example 1: Uniform Green. Output: Row 0 filled.
    *   Example 3: Uniform Yellow. Output: Row 0 filled.
    *   Example 2: Mixed. Output: Anti-diagonal.

    *   Is there a simpler rule? Maybe it depends on the dominant color?
    *   In Ex 1, Green is dominant. Output is Row 0.
    *   In Ex 3, Yellow is dominant. Output is Row 0.
    *   In Ex 2, counts are equal (3 of each). Output is Anti-diagonal.

    *   Let's check the Test Input:
        Y Y Y
        R G R
        G R G
    *   Counts:
        *   Row 0: Y Y Y (3 Yellow)
        *   Row 1: R G R (2 Red, 1 Green)
        *   Row 2: G R G (2 Green, 1 Red)
        *   Total: Y=3, R=3, G=3.
    *   This matches the color distribution of Example 2 exactly (3 of each color).
    *   In Example 2, the output was the anti-diagonal:
        . . X
        . X .
        X . .
    *   If the rule is based on the set of colors present or their counts, the Test Input has the same counts as Example 2.
    *   However, the arrangement is different.
        *   Ex 2 Input:
            G G G
            Y R R
            Y Y R
        *   Test Input:
            Y Y Y
            R G R
            G R G
    *   Does the specific arrangement matter, or just the counts?
    *   In Ex 1 and Ex 3, the arrangement is uniform. The output is the same (Top Row).
    *   In Ex 2, the arrangement is mixed. The output is Anti-diagonal.
    *   In Test Input, the arrangement is mixed.
    *   Hypothesis 1: If the grid is monochromatic (all same color), output is Top Row. If the grid is polychromatic (mixed colors), output is Anti-diagonal.
    *   Hypothesis 2: The output depends on the specific colors.
        *   Green dominant -> Top Row?
        *   Yellow dominant -> Top Row?
        *   Mixed -> Anti-diagonal?
    *   Hypothesis 3: Look at the rows.
        *   Ex 1: All rows are GGG. Output Row 0 is XXX.
        *   Ex 3: All rows are YYY. Output Row 0 is XXX.
        *   Ex 2: Row 0 is GGG. Row 1 is YRR. Row 2 is YYR. Output is Anti-diagonal.
        *   Test: Row 0 is YYY. Row 1 is RGR. Row 2 is GRG.
    *   Hypothesis 4: Look at the colors mapping to rows.
        *   Maybe specific 

... [7989 chars truncated]
alt-6 architecture qwen3.5-122b: k=3
"An architect surveys the materials delivered to a building site. If every brick is the same stone, the load-bearing wall runs flat across the foundation. Mixed materials require diagonal bracing — and the more diverse the supply, the more the brace tilts against convention."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (13196 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A 3x3 lot of colored building materials." This implies the input is a 3x3 grid with various colors.
*   **Task:** "Assess the variety of materials and place three grey structural supports on the dark blueprint in the bracing pattern the site demands."
*   **Output:** "The blueprint is 3x3, black background, with exactly three grey supports."
*   **Key constraints:**
    *   Input is 3x3.
    *   Output is 3x3.
    *   Output background is black (`.`).
    *   Output contains exactly three grey (`X`) supports.
    *   The placement of the grey supports depends on the "variety of materials" in the input.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
        (All Green)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest Black)
    *   Observation: Input is uniform (1 color). Output has 3 grey pixels in the top row.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
        (Mixed colors: G, Y, R)
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
        (Diagonal from top-right to bottom-left is Grey, rest Black)
    *   Observation: Input is mixed. Output has 3 grey pixels on the anti-diagonal.

*   **Example 3:**
    *   Input:
        ```
        Y Y Y
        Y Y Y
        Y Y Y
        ```
        (All Yellow)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest Black)
    *   Observation: Input is uniform (1 color). Output has 3 grey pixels in the top row. Same as Example 1.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: Represents the "colored building materials".
    *   Output Grid: Represents the "dark blueprint" with "grey structural supports".
    *   Colors in Input: Indicate the type of material.
    *   Grey (`X`) in Output: Represents the structural supports.
    *   Black (`.`) in Output: Represents the empty blueprint background.

*   **AFFORDANCES:**
    *   The input grid's color composition determines the pattern of the output grid.
    *   The output grid is always 3x3.
    *   The output grid always has exactly 3 `X`s and 6 `.`s.
    *   The `X`s form a specific line or pattern.

*   **TRANSFORMATION RULE:**
    *   Compare Example 1 (All Green) and Example 3 (All Yellow). Both result in the top row being `X X X`.
    *   Compare Example 2 (Mixed Green, Yellow, Red). This results in the anti-diagonal being `X X X` (positions (0,2), (1,1), (2,0)).
    *   Hypothesis 1: If the input grid is monochromatic (all cells same color), the output is the top row filled with `X`.
    *   Hypothesis 2: If the input grid is polychromatic (multiple colors), the output is the anti-diagonal filled with `X`.
    *   Let's check the Test Input.
    *   Test Input:
        ```
        Y Y Y
        R G R
        G R G
        ```
    *   Colors present: Y (Yellow), R (Red), G (Green).
    *   Is it monochromatic? No.
    *   Is it polychromatic? Yes.
    *   Based on Example 2, a mixed input should result in the anti-diagonal pattern.

    *   Wait, let's look closer at Example 2.
        Input:
        G G G
        Y R R
        Y Y R
        Colors: G, Y, R.
        Output: Anti-diagonal.

    *   Let's look at the Test Input again.
        Y Y Y
        R G R
        G R G
        Colors: Y, R, G.
        This is also mixed.

    *   Is there a more specific rule?
        Maybe it depends on the number of unique colors?
        Ex 1: 1 unique color -> Top Row.
        Ex 3: 1 unique color -> Top Row.
        Ex 2: 3 unique colors -> Anti-diagonal.
        Test: 3 unique colors (Y, R, G).

    *   What if it depends on the specific colors?
        Ex 1: G -> Top Row.
        Ex 3: Y -> Top Row.
        Ex 2: G, Y, R -> Anti-diagonal.
        Test: Y, R, G -> Anti-diagonal.

    *   Is there a distinction between "Uniform" and "Mixed"?
        The metaphor says "Assess the variety of materials".
        "Variety" implies diversity.
        If there is no variety (all same), pattern A.
        If there is variety (mixed), pattern B.

    *   Pattern A: Top row (`X X X`, `. . .`, `. . .`).
    *   Pattern B: Anti-diagonal (`. . X`, `. X .`, `X . .`).

    *   Let's check if there are other possibilities.
        Could it be related to the count of specific colors?
        Ex 1: 9 G.
        Ex 3: 9 Y.
        Ex 2: 3 G, 3 Y, 3 R. (Wait, let's count Ex 2 input).
        Row 1: G G G (3 G)
        Row 2: Y R R (1 Y, 2 R)
        Row 3: Y Y R (2 Y, 1 R)
        Total: 3 G, 3 Y, 3 R.
        Test Input:
        Row 1: Y Y Y (3 Y)
        Row 2: R G R (2 R, 1 G)
        Row 3: G R G (1 R, 2 G)
        Total:

... [8321 chars truncated]
alt-7 warfare qwen3.5-122b: k=3
"A general studies the banners on the battlefield. A single banner means the troops hold the line; two opposing banners demand a flanking advance from high ground to low; three banners trigger a counter-flanking retreat from the opposite direction."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (12980 chars)
The user wants me to solve a grid transformation puzzle based on provided examples and a metaphorical description.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A 3x3 battlefield with colored banners." This implies the input is a 3x3 grid of colored cells.
*   **Output:** "deploy grey sentinels on the dark war map". This implies the output is a 3x3 grid where most cells are black (dark war map) and some are grey (sentinels).
*   **Key:** `.` = black, `X` = grey.
*   **Task:** "Read the allegiances on the field and deploy grey sentinels... in the appropriate strategic formation." This suggests the positions of the grey sentinels depend on the colors in the input grid.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        G G G
        G G G
        G G G
        ```
        (All Green)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest Black)
    *   Observation: All Green -> Top Row Grey.

*   **Example 2:**
    *   Input:
        ```
        G G G
        Y R R
        Y Y R
        ```
        (Mixed colors)
    *   Output:
        ```
        . . X
        . X .
        X . .
        ```
        (Diagonal from top-right to bottom-left is Grey)
    *   Observation: Mixed colors -> Anti-diagonal Grey.

*   **Example 3:**
    *   Input:
        ```
        Y Y Y
        Y Y Y
        Y Y Y
        ```
        (All Yellow)
    *   Output:
        ```
        X X X
        . . .
        . . .
        ```
        (Top row is Grey, rest Black)
    *   Observation: All Yellow -> Top Row Grey.

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: 3x3 matrix of colored cells (G, Y, R, etc.).
    *   Output Grid: 3x3 matrix of Black (`.`) and Grey (`X`) cells.
    *   "Banners": The colors in the input grid.
    *   "Sentinels": The Grey cells (`X`) in the output grid.
    *   "Dark War Map": The Black cells (`.`) in the output grid.

*   **AFFORDANCES:**
    *   The input grid determines the pattern of the output grid.
    *   The output grid is binary (Black or Grey).
    *   The pattern seems to be determined by the uniformity or specific arrangement of colors in the input.

*   **TRANSFORMATION RULE:**
    *   Let's look at the relationship between Input Colors and Output Pattern.
    *   **Case 1 (Ex 1 & 3):** Input is monochromatic (All G or All Y). Output is Top Row Grey (`X X X` / `. . .` / `. . .`).
    *   **Case 2 (Ex 2):** Input is mixed (G, Y, R). Output is Anti-Diagonal Grey (`. . X` / `. X .` / `X . .`).
    *   Wait, let's look closer at Example 2.
        Input:
        G G G
        Y R R
        Y Y R
        Output:
        . . X
        . X .
        X . .
    *   Is there a specific color mapping?
        *   Ex 1: All Green -> Top Row.
        *   Ex 3: All Yellow -> Top Row.
        *   Ex 2: Mixed -> Anti-diagonal.
    *   Hypothesis 1: If the input grid is uniform (all cells same color), output is Top Row Grey. If the input grid is mixed, output is Anti-Diagonal Grey.
    *   Hypothesis 2: Maybe it depends on the specific colors present?
        *   Ex 1: Green only.
        *   Ex 3: Yellow only.
        *   Ex 2: Green, Yellow, Red.
    *   Hypothesis 3: Maybe it counts something?
        *   Ex 1: 9 Green.
        *   Ex 3: 9 Yellow.
        *   Ex 2: 3 Green, 3 Yellow, 3 Red.
    *   Hypothesis 4: Maybe it's about the rows?
        *   Ex 1: Row 1 = GGG, Row 2 = GGG, Row 3 = GGG.
        *   Ex 3: Row 1 = YYY, Row 2 = YYY, Row 3 = YYY.
        *   Ex 2: Row 1 = GGG, Row 2 = YRR, Row 3 = YYR.
    *   Let's check the Test Input.
        ```
        Y Y Y
        R G R
        G R G
        ```
        Row 1: Y Y Y (Uniform)
        Row 2: R G R (Mixed)
        Row 3: G R G (Mixed)
        Overall: Mixed (Y, R, G).

    *   Comparing Test Input to Examples:
        *   Ex 1 & 3 are fully uniform grids.
        *   Ex 2 is a mixed grid.
        *   Test Input is a mixed grid.
    *   If the rule is "Uniform -> Top Row, Mixed -> Anti-Diagonal", then the Test Input should produce the Anti-Diagonal pattern.
    *   Let's check if there's a more specific rule.
    *   Maybe the colors map to specific rows/positions?
        *   Green (G) -> ?
        *   Yellow (Y) -> ?
        *   Red (R) -> ?
    *   In Ex 1 (All G), Top Row is X.
    *   In Ex 3 (All Y), Top Row is X.
    *   This suggests G and Y map to the same output pattern (Top Row) when uniform.
    *   In Ex 2 (Mixed G, Y, R), Anti-Diagonal is X.
    *   In Test Input (Mixed Y, R, G), it is also Mixed.
    *   Is there a distinction between "Mixed" types?
        *   Ex 2 has 3 of each color (3G, 3Y, 3R).
        *   Test Input has:
            *   Y: 3 (Row 1)
            *   R: 4 (Row 2: 2, Row 3: 1) -> Wait.
                Row 1: Y Y Y
                Row 2: R G R
                Row 3: G R G
                Counts: Y=3, R=4, G=2. Total 9.
            *   Ex 2

... [8105 chars truncated]
alt-8 theater qwen3.5-122b: k=2
"A stage director counts the speaking roles in a script. A monologue places the spotlight straight across the proscenium; a dialogue angles it from upstage-left to downstage-right; a three-voice ensemble reverses the angle from upstage-right to downstage-left."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (12637 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A 3x3 stage filled with costumed players in various colors.
*   **Action:** Count the distinct roles and aim the grey spotlights on the dark stage accordingly.
*   **Grid details:** The stage is 3x3 black with three grey spotlights.
*   **Key terms:** "Count the distinct roles", "aim the grey spotlights", "dark stage".
*   **Colors:**
    *   Input: Various colors (G, Y, R, etc.).
    *   Output: Black (.) and Grey (X).
    *   "Dark stage" implies the background is black (.).
    *   "Grey spotlights" implies the active elements are grey (X).
    *   "Count the distinct roles" suggests counting unique colors in the input.
    *   "Aim... accordingly" suggests the position of the grey spots depends on the count or distribution of the colors.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
G G G
G G G
G G G
Output:
X X X
. . .
. . .

*   **Input Analysis:** All cells are Green (G).
*   **Distinct Colors:** Only 1 distinct color (Green).
*   **Output Analysis:** Top row is Grey (X), rest is Black (.).
*   **Observation:** There are 3 Grey spots. The input has 1 distinct color. The output has 3 X's. Wait, let's look at the count.
    *   Input count of G: 9.
    *   Distinct colors: 1.
    *   Output X count: 3.
    *   Output pattern: Row 1 is all X.
    *   Maybe it's related to the number of distinct colors? 1 distinct color -> 3 X's? Or maybe it's related to the specific color?
    *   Let's check the position. Top row.

**Example 2:**
Input:
G G G
Y R R
Y Y R
Output:
. . X
. X .
X . .

*   **Input Analysis:**
    *   Row 1: G G G
    *   Row 2: Y R R
    *   Row 3: Y Y R
    *   Colors present: G, Y, R.
    *   Distinct colors: 3 (Green, Yellow, Red).
*   **Output Analysis:**
    *   Diagonal from top-right to bottom-left (anti-diagonal).
    *   X at (0, 2), (1, 1), (2, 0).
    *   Total X count: 3.
*   **Comparison with Example 1:**
    *   Example 1: 1 distinct color -> 3 X's in Row 1.
    *   Example 2: 3 distinct colors -> 3 X's in Anti-diagonal.
    *   Wait, the number of X's is always 3 in the output?
    *   Let's re-read the metaphor: "aim the grey spotlights on the dark stage accordingly". "The stage is 3x3 black with three grey spotlights."
    *   This implies there are *always* 3 spotlights (X's) in the output. The task is to determine *where* they go.
    *   The position depends on the input.
    *   What determines the position?
    *   Example 1: Input is all G. Output is Row 1 (Top).
    *   Example 2: Input has G, Y, R. Output is Anti-diagonal.
    *   Is it counting the distinct colors?
        *   Ex 1: 1 distinct color. Output: Row 1.
        *   Ex 2: 3 distinct colors. Output: Anti-diagonal.
    *   What if there are 2 distinct colors? I don't have an example.
    *   Let's look at the "roles".
    *   Maybe the distinct colors map to specific patterns?
    *   Or maybe the count of distinct colors maps to a pattern index?
        *   Count = 1 -> Pattern 1 (Row 1).
        *   Count = 3 -> Pattern 2 (Anti-diagonal).
    *   Let's look at the Test Input.

**Test Input:**
Y Y Y
R G R
G R G

*   **Input Analysis:**
    *   Row 1: Y Y Y
    *   Row 2: R G R
    *   Row 3: G R G
    *   Colors present: Y, R, G.
    *   Distinct colors: 3 (Yellow, Red, Green).
*   **Hypothesis 1:** The number of distinct colors determines the pattern.
    *   If 1 distinct color -> Row 1.
    *   If 3 distinct colors -> Anti-diagonal.
    *   Test Input has 3 distinct colors. So it should be Anti-diagonal.
    *   Output:
        . . X
        . X .
        X . .
*   **Hypothesis 2:** The specific colors matter.
    *   Ex 1: Only G.
    *   Ex 2: G, Y, R.
    *   Test: Y, R, G. (Same set as Ex 2).
    *   If the set of colors is the same, the output should be the same.
    *   Ex 2 Input: G, Y, R. Output: Anti-diagonal.
    *   Test Input: Y, R, G. Output: Anti-diagonal.
    *   This seems consistent.

*   **Hypothesis 3:** Is there a mapping based on the count of each color?
    *   Ex 1: G=9.
    *   Ex 2: G=3, Y=3, R=3.
    *   Test: Y=3, R=4, G=2.
    *   The counts are different in the Test Input compared to Ex 2.
    *   Ex 2 counts: G:3, Y:3, R:3.
    *   Test counts: Y:3, R:4, G:2.
    *   If the rule depends on the *set* of colors present, the output should be the same as Ex 2.
    *   If the rule depends on the *count* of distinct colors, the output should be the same as Ex 2 (since both have 3 distinct colors).
    *   If the rule depends on the specific arrangement...
        *   Ex 2: Top row G, Middle Y/R, Bottom Y/R.
        *   Test: Top row Y, Middle R/G, Bottom G/R.
        *   The structure is somewhat similar (Top row uniform, others mixed).
        *   Ex 1: Top row uniform (all G), others uniform (all G).
    *   Let's check the metaphor again: "Count the distinct roles".


... [7715 chars truncated]
alt-9 gardening qwen3.5-122b: k=2
"A gardener inspects the flower bed and decides where to lay stepping stones. A bed of one bloom gets stones along the garden wall; two varieties earn a winding path from gate to gazebo; three species demand a crossing path from the opposite corner."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (12975 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A 3x3 flower bed of colored blooms." -> This implies the input is a 3x3 grid containing various colors.
*   **Action:** "Survey the floral diversity and place three grey stepping stones on the dark soil." -> This implies the output will be a 3x3 grid where some cells are "grey stepping stones" (X) and others are "dark soil" (.).
*   **Constraint:** "place three grey stepping stones". This means exactly three 'X's in the output grid.
*   **Condition:** "whose path reflects the variety of blooms." -> This suggests the position of the 'X's depends on the colors in the input grid.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        G G G
        G G G
        G G G
    *   Output:
        X X X
        . . .
        . . .
    *   Observation: The input is all Green (G). The output has three Grey (X) stones in the top row.
    *   Hypothesis: Maybe it counts unique colors? Or maybe it's about specific colors?
    *   Let's look at the counts. Input has 9 Gs. Output has 3 Xs.
    *   Let's look at the positions. Top row.

*   **Example 2:**
    *   Input:
        G G G
        Y R R
        Y Y R
    *   Output:
        . . X
        . X .
        X . .
    *   Observation: The input has G, Y, R.
    *   Output has 3 Xs.
    *   Positions: (0,2), (1,1), (2,0). This is the anti-diagonal.
    *   Input colors:
        Row 0: G G G
        Row 1: Y R R
        Row 2: Y Y R
    *   Let's check the colors at the positions of the Xs in the output.
        (0,2) is G.
        (1,1) is R.
        (2,0) is Y.
    *   So the Xs are placed where the colors are G, R, Y?
    *   Wait, in Example 1, the Xs are at (0,0), (0,1), (0,2). The colors there are G, G, G.
    *   This suggests the Xs replace specific cells based on some logic.
    *   Let's look at the "variety of blooms".
    *   Example 1: Only one color (G). Output: Top row filled with X.
    *   Example 2: Three colors (G, Y, R). Output: Anti-diagonal filled with X.
    *   Is it related to the number of unique colors?
        *   Ex 1: 1 unique color (G). Output: Row 0.
        *   Ex 2: 3 unique colors (G, Y, R). Output: Anti-diagonal.
    *   What about the Test Input?
        Y Y Y
        R G R
        G R G
        Unique colors: Y, R, G. (3 unique colors).
        This matches Example 2's count of unique colors.
        Does that mean the output should be the anti-diagonal like Example 2?
        Let's check the colors in the Test Input.
        (0,0)=Y, (0,1)=Y, (0,2)=Y
        (1,0)=R, (1,1)=G, (1,2)=R
        (2,0)=G, (2,1)=R, (2,2)=G
        Unique colors present: Y, R, G.
        In Example 2, the unique colors were G, Y, R.
        The Xs in Example 2 were at (0,2) [Color G], (1,1) [Color R], (2,0) [Color Y].
        Wait, (0,2) in Ex 2 Input is G. (1,1) is R. (2,0) is Y.
        So the Xs mark the positions of the *first occurrence* of each unique color? Or specific instances?
        In Ex 2:
        G appears at (0,0), (0,1), (0,2). X is at (0,2).
        Y appears at (1,0), (2,0), (2,1). X is at (2,0).
        R appears at (1,1), (1,2), (2,2). X is at (1,1).
        This doesn't seem like "first occurrence".
        (0,2) is the last G in the first row.
        (1,1) is the first R in the second row.
        (2,0) is the first Y in the third row.
        This seems arbitrary.

    *   Let's reconsider the "path reflects the variety of blooms".
    *   Maybe it's about the *count* of each color?
        Ex 1: G=9. Output: 3 Xs.
        Ex 2: G=3, Y=3, R=3. Output: 3 Xs.
        Test: Y=3, R=4, G=2.
        Wait, let's count Test Input carefully.
        Row 0: Y Y Y (3 Y)
        Row 1: R G R (2 R, 1 G)
        Row 2: G R G (1 R, 2 G)
        Total: Y=3, R=3, G=3.
        Ah! The Test Input also has exactly 3 of each color (Y, R, G).
        Example 2 also had exactly 3 of each color (G, Y, R).
        Example 1 had 9 of one color (G).

    *   So, the rule might depend on the distribution of colors.
    *   Case 1: All cells same color (9 of one). -> Output: Top row (Row 0) is X.
    *   Case 2: 3 distinct colors, 3 of each. -> Output: Anti-diagonal is X.
    *   Test Input: 3 distinct colors (Y, R, G), 3 of each.
    *   This matches Case 2 exactly in terms of color distribution statistics.
    *   Therefore, the output pattern should likely be the same as Example 2.
    *   Pattern: Anti-diagonal (Top-Right, Center, Bottom-Left).
    *   Coordinates: (0,2), (1,1), (2,0).
    *   Output Grid:
        . . X
        . X .
        X . .

    *   Let's verify the "path reflects the variety" metaphor.
    *   If there is only one variety (Ex 1), the path is a straight line (Row 0).
    *   If there are three varieties (Ex 2), the path is a diagonal line connecting them?
    *   In Ex 2, the Xs are at (0,2), (1,1), (2,0).
    *   In Te

... [8029 chars truncated]

Task 430: 72a961c9

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original Rockets on a launchpad ignite according to their fuel type. MARC valid 3
alt-1 biology Certain enzymes along a chromosome express themselves differently depending on t ... [78 chars truncated] MARC valid 3
alt-10 astronomy Anomalous stars embedded in a galactic arm emit jets of plasma — red dwarf ... [68 chars truncated] fail
alt-11 ocean/sailing Buoys anchored to a sea chain surface at different depths depending on their cla ... [88 chars truncated] MARC valid 3
alt-12 electronics Components soldered to a bus line discharge at different voltages — each t ... [78 chars truncated] fail
alt-13 mythology Runes carved into Yggdrasil's root each summon a different spirit — fire r ... [72 chars truncated] fail
alt-14 dance Dancers in a chorus line leap at their cue — soloists in crimson leap four ... [84 chars truncated] MARC valid 2
alt-15 geology Mineral veins trapped in a bedrock stratum erupt under tectonic pressure — ... [71 chars truncated] MARC valid 3
alt-2 cooking Spices pressed into a roll of dough bloom upward when the heat hits, each releas ... [60 chars truncated] fail
alt-3 music Notes embedded in a drone string resonate upward, each pitch sustaining harmonic ... [66 chars truncated] MARC valid 4
alt-4 sports Players standing in a scrimmage line break formation at the whistle — each ... [78 chars truncated] MARC valid 4
alt-5 weather Storm cells embedded in a pressure front push updrafts of different heights R ... [61 chars truncated] MARC valid 4
alt-6 architecture Keystones set into a foundation wall dictate how tall their supporting columns m ... [73 chars truncated] fail
alt-7 warfare Signal flares lodged in a trench wall launch at different altitudes depending on ... [84 chars truncated] MARC valid 3
alt-8 theater Trapdoors in the stage floor spring open and raise performers on lifts — l ... [106 chars truncated] fail
alt-9 gardening Seeds of different species planted along an irrigation channel send shoots upwar ... [95 chars truncated] fail
original qwen3.5-122b: k=3
"Rockets on a launchpad ignite according to their fuel type."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (10142 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A launchpad (solid blue runway) with special rocket engines embedded in it.
*   **Engine Colors:** Azure (A) or Red (R).
*   **Action:** When triggered, engines fire a plume straight up.
*   **Plume Composition:** A column of blue exhaust (B) capped by a bright flare matching the engine's color (A or R).
*   **Height:** Red rockets burn hotter and reach higher than Azure ones.
*   **Constraints:** Engines stay bolted to the launchpad. Plumes only fire upward. Nothing falls below. No rocket escapes the edge.
*   **Background:** Night sky stays dark (black '.') except for exhaust trails.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 9x6 grid. Row 4 (0-indexed) is `B A B B B B`.
    *   Output: Row 4 is `B A B B B B`. Above it, at column 1 (where 'A' is), there is a column going up.
    *   Let's check the column above 'A' at (3, 1).
    *   Output grid at (2, 1) is 'B'. Output grid at (1, 1) is 'B'. Output grid at (0, 1) is 'A'.
    *   Wait, let's look closer.
    *   Input Row 3 (0-indexed): `B A B B B B`.
    *   Output Row 3: `B A B B B B`.
    *   Output Row 2: `. B . . . .` (Col 1 is B)
    *   Output Row 1: `. B . . . .` (Col 1 is B)
    *   Output Row 0: `. A . . . .` (Col 1 is A)
    *   So, for an 'A' engine at row $r$, column $c$:
        *   The engine stays at $(r, c)$.
        *   A column of 'B's goes up from $(r-1, c)$ to some height.
        *   The top of the column is 'A'.
        *   In this example, the 'A' is at row 3. The plume goes up to row 0.
        *   Height calculation: Row 3 to Row 0 is 3 steps up.
        *   Is there a specific height rule? "Red rockets burn hotter and their plumes reach higher than azure ones."
        *   Here we only have 'A'. The plume reaches the top edge (row 0).
        *   Let's check the other cells in the row. They are 'B'. They don't seem to trigger plumes. Only 'A' and 'R' are engines. 'B' is the runway.

*   **Example 2:**
    *   Input: 10x7 grid. Row 5 is `B B B R B B B`.
    *   Output: Row 5 is `B B B R B B B`.
    *   Above the 'R' at (5, 3):
        *   Row 4: `B`
        *   Row 3: `B`
        *   Row 2: `B`
        *   Row 1: `R`
        *   Row 0: `.`
    *   So the plume for 'R' goes from row 4 up to row 1.
    *   Height: 4 cells high (rows 1, 2, 3, 4).
    *   Top cell is 'R'. Rest are 'B'.
    *   Compare with Example 1 ('A' engine):
        *   'A' at row 3. Plume went to row 0. Height = 3 cells (rows 0, 1, 2).
        *   Wait, in Ex 1, 'A' was at row 3. Plume occupied rows 0, 1, 2. That's 3 cells.
        *   In Ex 2, 'R' was at row 5. Plume occupied rows 1, 2, 3, 4. That's 4 cells.
        *   Wait, let's re-read the height rule. "Red rockets burn hotter and their plumes reach higher than azure ones."
        *   In Ex 1, 'A' reached the top (row 0).
        *   In Ex 2, 'R' reached row 1.
        *   This contradicts "Red reaches higher". Unless "higher" means more cells, or it depends on available space.
        *   Let's look at the distance from the engine to the top.
        *   Ex 1: Engine at row 3. Top is row 0. Distance = 3. Plume height = 3.
        *   Ex 2: Engine at row 5. Top is row 0. Distance = 5. Plume height = 4.
        *   Maybe the height is fixed based on color?
        *   Hypothesis 1: Azure height = 3. Red height = 4.
        *   Let's check Example 3.

*   **Example 3:**
    *   Input: 9x9 grid. Row 7 is `B A B B B A B R B`.
    *   Engines at:
        *   Col 1: 'A' (Row 7)
        *   Col 5: 'A' (Row 7)
        *   Col 7: 'R' (Row 7)
    *   Output:
        *   Col 1 ('A'):
            *   Row 6: `B`
            *   Row 5: `A`
            *   Row 4: `.`
            *   Wait, looking at the output grid provided:
            *   Row 7: `B A B B B A B R B`
            *   Row 6: `. B . . . B . B .` (Cols 1, 5, 7 are B)
            *   Row 5: `. B . . . B . B .` (Cols 1, 5, 7 are B)
            *   Row 4: `. A . . . A . B .` (Cols 1, 5 are A. Col 7 is B)
            *   Row 3: `. . . . . . . R .` (Col 7 is R)
            *   Row 2: `. . . . . . . . .`
        *   Let's trace the plumes carefully.
        *   **Engine 'A' at (7, 1):**
            *   Row 6: B
            *   Row 5: B
            *   Row 4: A
            *   Height = 3 cells (Rows 4, 5, 6). Top is A.
        *   **Engine 'A' at (7, 5):**
            *   Row 6: B
            *   Row 5: B
            *   Row 4: A
            *   Height = 3 cells. Top is A.
        *   **Engine 'R' at (7, 7):**
            *   Row 6: B
            *   Row 5: B
            *   Row 4: B
            *   Row 3: R
            *   Height = 4 cells (Rows 3, 4, 5, 6). Top is R.
    *   **Conclusion on Heights:**
        *   Azure (A) engine produces a plume of height 3.
        *   Red (R) engine produces a plume of height 4.
        *   The plume consists of (Height - 

... [5151 chars truncated]
alt-1 biology qwen3.5-122b: k=3
"Certain enzymes along a chromosome express themselves differently depending on their type, sending protein chains of varying lengths toward the cell membrane."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (11408 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A horizontal strand of uniform genetic material (likely a row of cells) with differently-colored enzyme markers embedded within it.
*   **What to do:** Each enzyme activates and synthesizes a protein chain that extends away from the strand.
*   **Chain details:** The chain length and cap molecule depend on the enzyme's identity.
*   **Grid details:** The strand remains fixed. Protein chains grow perpendicular to the strand from each enzyme site, capped by a copy of the enzyme at the distal end.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 9x6 grid.
    *   Row 4 (0-indexed) contains: `B A B B B B`.
    *   Output:
        *   Row 4 remains `B A B B B B`.
        *   Above the 'A' at (3, 1) [row, col], there is a chain going up.
        *   The chain consists of `B` at (2, 1), `B` at (1, 1), `A` at (0, 1).
        *   Wait, let's look closer.
        *   Input Row 3 (0-indexed): `B A B B B B`.
        *   Output Row 3: `B A B B B B`.
        *   Output Row 2: `. B . . . .` (Under the A)
        *   Output Row 1: `. B . . . .` (Under the A)
        *   Output Row 0: `. A . . . .` (Under the A)
        *   Wait, the metaphor says "extends away from the strand". In Example 1, the strand is at row 3. The chain goes *up* (rows 2, 1, 0).
        *   The enzyme is 'A' (Azure).
        *   The chain starts adjacent to the enzyme.
        *   The chain ends with a copy of the enzyme ('A').
        *   The intermediate cells are filled with 'B' (Blue).
        *   Why 'B'? The strand itself is mostly 'B'. Maybe the "uniform genetic material" is 'B'.
        *   Let's check the length. The chain goes from row 3 to row 0. That's 3 cells above the strand.
        *   Is the length determined by the enzyme? Or is it fixed? Or does it go to the edge?
        *   In Example 1, the 'A' is at col 1. The chain goes up to row 0. Length = 3 cells (excluding the enzyme itself).
        *   The cells are: (2,1)=B, (1,1)=B, (0,1)=A.
        *   So the chain is B-B-A.
        *   The other cells in the strand are 'B'. They don't produce chains. Only 'A' produces a chain.

*   **Example 2:**
    *   Input: 10x7 grid.
    *   Row 5 contains: `B B B R B B B`.
    *   Output:
        *   Row 5 remains `B B B R B B B`.
        *   Above the 'R' at (5, 3), there is a chain.
        *   Row 4: `. . . B . . .`
        *   Row 3: `. . . B . . .`
        *   Row 2: `. . . B . . .`
        *   Row 1: `. . . R . . .`
        *   Row 0: `. . . . . . .`
        *   The chain goes up from row 5.
        *   Cells: (4,3)=B, (3,3)=B, (2,3)=B, (1,3)=R.
        *   The chain is B-B-B-R.
        *   Length is 4 cells.
        *   The enzyme is 'R' (Red).
        *   The background strand color is 'B' (Blue).
        *   The chain consists of background color 'B' followed by the enzyme color 'R' at the tip.
        *   Why length 4? In Example 1, length was 3.
        *   Maybe the length depends on the enzyme type?
        *   Example 1: Enzyme 'A' -> Length 3.
        *   Example 2: Enzyme 'R' -> Length 4.
        *   Let's check if there's a pattern.
        *   Maybe it depends on the position?
        *   Ex 1: 'A' at col 1. Grid height 9. Strand at row 3. Distance to top = 3. Distance to bottom = 5. Chain goes up.
        *   Ex 2: 'R' at col 3. Grid height 10. Strand at row 5. Distance to top = 5. Distance to bottom = 4. Chain goes up.
        *   Wait, in Ex 1, the chain stops at row 0. In Ex 2, the chain stops at row 1.
        *   Why did Ex 2 stop at row 1? There is space at row 0.
        *   Maybe the length is specific to the enzyme color.
        *   'A' -> Length 3.
        *   'R' -> Length 4.
        *   Let's look at Example 3.

*   **Example 3:**
    *   Input: 9x9 grid.
    *   Row 7 contains: `B A B B B A B R B`.
    *   Strand is at row 7.
    *   Enzymes: 'A' at col 1, 'A' at col 5, 'R' at col 7.
    *   Output:
        *   Row 7 remains `B A B B B A B R B`.
        *   Chain from 'A' at col 1:
            *   Row 6: `. B . . . . . . .`
            *   Row 5: `. B . . . . . . .`
            *   Row 4: `. A . . . . . . .`
            *   Chain: B-B-A. Length 3. Goes up.
        *   Chain from 'A' at col 5:
            *   Row 6: `. . . . . B . . .`
            *   Row 5: `. . . . . B . . .`
            *   Row 4: `. . . . . A . . .`
            *   Chain: B-B-A. Length 3. Goes up.
        *   Chain from 'R' at col 7:
            *   Row 6: `. . . . . . . B .`
            *   Row 5: `. . . . . . . B .`
            *   Row 4: `. . . . . . . B .`
            *   Row 3: `. . . . . . . R .`
            *   Chain: B-B-B-R. Length 4. Goes up.
    *   This confirms the hypothesis:
        *   The strand is a horizontal row containing 'B's and specific "enzyme" colors (A, R, etc.).
        *   'B' is the background/stra

... [6450 chars truncated]
alt-10 astronomy qwen3.5-122b: fail
"Anomalous stars embedded in a galactic arm emit jets of plasma — red dwarfs produce longer jets than blue giants before the plasma dissipates."
Fail (best cell_acc=0.86 at k=1)
Best Attempt
vs
Expected
Reasoning (12285 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A galactic arm of uniform starlight sweeps across the void, with a few distinctly colored stellar anomalies embedded within it."
    *   "Galactic arm of uniform starlight": This likely refers to a line or row of a specific color (or pattern) that acts as the "arm". In the examples, there's a row of 'B's (blue) with some other colors mixed in.
    *   "Distinctly colored stellar anomalies": These are the non-background, non-arm colors embedded in the arm.
*   **Action:** "Each anomaly emits a plasma jet perpendicular to the arm."
    *   "Perpendicular to the arm": If the arm is horizontal, the jets go up or down.
    *   "Jet length depends on the star's spectral class": This implies the length might vary based on the color of the anomaly.
    *   "Star's color visible at the jet terminus": The end of the jet has the same color as the anomaly.
*   **Grid details:** "The galactic arm persists. Plasma jets extend from each anomaly, tipped with the anomaly's color."
    *   The original row remains.
    *   New pixels are added extending from the anomalies.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:**
        ```
        . . . . . .
        . . . . . .
        . . . . . .
        B A B B B B
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        ```
        (9 rows, 6 columns)
        Row 3 (0-indexed) is `B A B B B B`.
        The "arm" seems to be the row of `B`s.
        There is an anomaly `A` (azure) at position (3, 1).
    *   **Output:**
        ```
        . A . . . .
        . B . . . .
        . B . . . .
        B A B B B B
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        ```
        The row `B A B B B B` is preserved.
        Above the `A` at (3, 1), there are new pixels.
        At (2, 1) is `B`.
        At (1, 1) is `B`.
        At (0, 1) is `A`.
        Wait, let's look closer.
        Input anomaly: `A` at (3, 1).
        Output changes:
        (2, 1) became `B`.
        (1, 1) became `B`.
        (0, 1) became `A`.
        So a vertical line was drawn upwards from the anomaly.
        The line consists of `B`s (the arm color) and ends with `A` (the anomaly color) at the top.
        Length: From row 3 to row 0 is 3 steps up.
        The pixels filled are (2,1), (1,1), (0,1).
        (2,1) is `B`.
        (1,1) is `B`.
        (0,1) is `A`.
        So the jet goes up. The "body" of the jet is the arm color (`B`), and the "tip" is the anomaly color (`A`).
        Why does it go up? Maybe because there is space? Or is it always up?
        Let's check the position. Row 3 is the 4th row. There are 3 rows above it. The jet fills all 3 rows above it.
        Is the length determined by the color `A`? Or is it just "fill to the edge"?
        Let's look at the "spectral class" hint. "Jet length depends on the star's spectral class".
        In Example 1, the anomaly is `A`. The jet length is 3 (reaching the top edge).
        Is `A` associated with length 3? Or is it just filling available space?
        Let's look at the Test Input to see if there are multiple anomalies or different colors.

*   **Test Input:**
    ```
    . . . . . . . . . . .
    . . . . . . . . . . .
    . . . . . . . . . . .
    . . . . . . . . . . .
    . . . . . . . . . . .
    . . . . . . . . . . .
    B R B A B B B A B R B
    . . . . . . . . . . .
    . . . . . . . . . . .
    ```
    (9 rows, 11 columns)
    Row 6 (0-indexed) is `B R B A B B B A B R B`.
    The "arm" is the row of `B`s.
    Anomalies in the arm:
    1.  `R` (red) at (6, 1).
    2.  `A` (azure) at (6, 3).
    3.  `A` (azure) at (6, 7).
    4.  `R` (red) at (6, 9).
    The rest are `B`.

    **Hypothesis 1: Direction.**
    In Example 1, the anomaly was at row 3 in a 9-row grid. The jet went UP.
    In the Test Input, the arm is at row 6 in a 9-row grid.
    If the rule is "go up", the jet would go from row 6 to row 0.
    If the rule is "go down", the jet would go from row 6 to row 8.
    If the rule is "go both ways", it would go both.
    In Example 1, there was space above (3 rows) and space below (5 rows). The jet went UP.
    Why UP?
    Maybe the "galactic arm" implies a specific orientation or the "void" is above?
    Or maybe it depends on the color?
    Let's re-read the metaphor: "A galactic arm ... sweeps across the void".
    "Each anomaly emits a plasma jet perpendicular to the arm."
    Usually, in these puzzles, if there's a choice, there's a pattern.
    In Example 1, the jet went UP.
    Let's assume the direction is UP for now, or check if there's a reason for it.
    Wait, look at the output of Example 1 again.
    Input Row 3: `B A B B B B`
    Output Col 1:
    Row 0: `A`
    Row 1: `B`
    Row 2: `B`
    Row 3: `A` 

... [7321 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=3
"Buoys anchored to a sea chain surface at different depths depending on their class — red channel markers ride higher on longer tethers than blue navigation buoys."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (11462 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A chain on the sea floor with colored buoy anchors.
*   **Action:** Each anchor releases a tether rising toward the surface.
*   **Details:**
    *   The chain stays on the bottom.
    *   Tethers extend upward from each anchor.
    *   The tether length depends on the buoy class (color).
    *   The colored buoy floats at the top of the tether.
*   **Interpretation:**
    *   There is a "chain" row at the bottom containing colored blocks (anchors).
    *   Above each colored block in the chain, a vertical column of blocks (tether) is created.
    *   The top of this tether is the "buoy" (the same color as the anchor).
    *   The rest of the tether seems to be a specific color or pattern. Looking at the examples will clarify the tether color.
    *   The "sea floor" is likely the row containing the chain.
    *   "Rising toward the surface" means going upwards in the grid (decreasing row index).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 9 rows, 6 columns.
    *   Row 3 (0-indexed) is `. . . . . .`. Wait, let's count.
    *   Input Grid:
        ```
        . . . . . .
        . . . . . .
        . . . . . .
        B A B B B B  <- Row 3
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        ```
    *   Output Grid:
        ```
        . A . . . .
        . B . . . .
        . B . . . .
        B A B B B B
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        ```
    *   Observation:
        *   The chain is at Row 3.
        *   Above the 'A' at (3, 1), there is a column going up.
        *   At (2, 1) is 'B'. At (1, 1) is 'B'. At (0, 1) is 'A'.
        *   Wait, the anchor is 'A'. The top is 'A'. The middle is 'B'.
        *   Above the 'B's at (3, 0), (3, 2), (3, 3), (3, 4), (3, 5), there are no tethers?
        *   Let's check the output again.
        *   Output Row 0: `. A . . . .` -> Col 1 is A.
        *   Output Row 1: `. B . . . .` -> Col 1 is B.
        *   Output Row 2: `. B . . . .` -> Col 1 is B.
        *   Output Row 3: `B A B B B B` -> The chain.
        *   So for the 'A' anchor, a tether of height 3 is created. The top is 'A', the rest are 'B'.
        *   Why height 3? Maybe it depends on the color 'A'.
        *   Why are the other 'B' anchors not generating tethers? Or maybe they do, but they are 'B' and the background is '.'? No, the tether color is 'B'. If the anchor is 'B', the tether would be 'B' on top of 'B', indistinguishable from the background if the background was 'B', but the background is '.'.
        *   Wait, look at the output for columns 0, 2, 3, 4, 5. They are all `.` above the chain.
        *   So 'B' anchors do *not* generate tethers? Or the tether is invisible?
        *   Let's look at Example 2.

*   **Example 2:**
    *   Input: 10 rows, 7 columns.
    *   Chain is at Row 5: `B B B R B B B`.
    *   Output:
        ```
        . . . . . . .
        . . . R . . .
        . . . B . . .
        . . . B . . .
        . . . B . . .
        B B B R B B B
        . . . . . . .
        . . . . . . .
        . . . . . . .
        . . . . . . .
        ```
    *   Observation:
        *   Anchor 'R' at (5, 3).
        *   Tether goes up to Row 1.
        *   Row 4: `B`
        *   Row 3: `B`
        *   Row 2: `B`
        *   Row 1: `R`
        *   So for 'R', height is 4 (rows 1, 2, 3, 4). Top is 'R', rest are 'B'.
        *   'B' anchors at (5, 0), (5, 1), (5, 2), (5, 4), (5, 5), (5, 6) do not produce visible tethers (or tethers of height 0).
        *   It seems 'B' is the "tether material" color.
        *   'A' and 'R' are "buoy" colors that trigger tethers.
        *   In Ex 1, 'A' triggered a tether of height 3 (rows 0, 1, 2). Top 'A', rest 'B'.
        *   In Ex 2, 'R' triggered a tether of height 4 (rows 1, 2, 3, 4). Top 'R', rest 'B'.
        *   Wait, in Ex 1, the grid height is 9. Chain at row 3. Tether goes to row 0. Height = 3.
        *   In Ex 2, the grid height is 10. Chain at row 5. Tether goes to row 1. Height = 4.
        *   Is the height determined by the color?
        *   'A' -> Height 3?
        *   'R' -> Height 4?
        *   Let's check Example 3.

*   **Example 3:**
    *   Input: 9 rows, 9 columns.
    *   Chain at Row 7: `B A B B B A B R B`.
    *   Output:
        ```
        . . . . . . . . .
        . . . . . . . . .
        . . . . . . . . .
        . . . . . . . R .
        . A . . . A . B .
        . B . . . B . B .
        . B . . . B . B .
        B A B B B A B R B
        . . . . . . . . .
        ```
    *   Observation:
        *   Chain at Row 7.
        *   Anchor 'A' at (7, 1). Tether goes up.
            *   Row 6: `B`
            *   Row 5: `B`
            *   Row 4: `A`
            *   Height = 

... [6507 chars truncated]
alt-12 electronics qwen3.5-122b: fail
"Components soldered to a bus line discharge at different voltages — each type drives a signal trace of proportional length along the perpendicular rail."
Fail (best cell_acc=0.86 at k=1)
Best Attempt
vs
Expected
Reasoning (12897 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A uniform bus line runs across the circuit board, with distinctly colored components soldered at specific positions."
*   **Action:** "Each component activates, sending a signal trace perpendicular to the bus. The trace length depends on the component type, with the component's identifier visible at the trace end."
*   **Grid details:** "The bus line remains. Signal traces extend from each component position, terminated by the component's color."

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . . .
    . . . . . .
    . . . . . .
    B A B B B B
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    ```
    *   Grid size: 9 rows x 6 columns.
    *   There is a horizontal line of colored cells in row 4 (0-indexed: row 3).
    *   The line consists of `B A B B B B`.
    *   The rest of the grid is empty (`.`).

*   **Output:**
    ```
    . A . . . .
    . B . . . .
    . B . . . .
    B A B B B B
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    ```
    *   The bus line `B A B B B B` at row 3 remains unchanged.
    *   Above the bus line, there are new colored cells.
    *   Let's look at the columns where the bus line has components.
    *   Column 0: `B` at row 3. Output has `.` at row 0, 1, 2. Wait, looking closely at the output.
    *   Output Row 0: `. A . . . .` -> Col 1 has `A`.
    *   Output Row 1: `. B . . . .` -> Col 1 has `B`.
    *   Output Row 2: `. B . . . .` -> Col 1 has `B`.
    *   Output Row 3: `B A B B B B` -> The bus line.
    *   Wait, let's align the columns.
    *   Input Row 3: `B` (col 0), `A` (col 1), `B` (col 2), `B` (col 3), `B` (col 4), `B` (col 5).
    *   Output changes:
        *   Col 0: `B` at row 3. No change above.
        *   Col 1: `A` at row 3. Above it, at row 2 is `B`, row 1 is `B`, row 0 is `A`.
        *   Col 2: `B` at row 3. No change above.
        *   Col 3: `B` at row 3. No change above.
        *   Col 4: `B` at row 3. No change above.
        *   Col 5: `B` at row 3. No change above.
    *   Wait, looking at the output provided in the prompt:
        ```
        . A . . . .
        . B . . . .
        . B . . . .
        B A B B B B
        . . . . . .
        ...
        ```
    *   Let's check the indices.
    *   Row 0: `.` `A` `.` `.` `.` `.`
    *   Row 1: `.` `B` `.` `.` `.` `.`
    *   Row 2: `.` `B` `.` `.` `.` `.`
    *   Row 3: `B` `A` `B` `B` `B` `B`
    *   So, in Column 1 (where the input was `A`), we have a vertical trace going upwards.
    *   The trace consists of `B`, `B`, `A` from bottom to top (rows 2, 1, 0).
    *   Why `B` and `A`?
    *   The component at (3, 1) is `A`.
    *   The trace goes up.
    *   The length seems to be 3 cells (rows 0, 1, 2).
    *   The colors in the trace are `B`, `B`, `A`.
    *   Is there a relationship between the component color `A` and the trace colors `B, B, A`?
    *   Maybe the trace length is determined by the color?
    *   Maybe the trace colors are determined by the color?
    *   Let's look at the other columns.
    *   Col 0: `B`. No trace.
    *   Col 2: `B`. No trace.
    *   Col 3: `B`. No trace.
    *   Col 4: `B`. No trace.
    *   Col 5: `B`. No trace.
    *   So only `A` generated a trace? Or maybe `B` generates a trace of length 0?
    *   Hypothesis 1: Different colors have different trace lengths. `A` has length 3. `B` has length 0.
    *   Hypothesis 2: The trace colors are related to the component color.
        *   Component `A`. Trace: `B`, `B`, `A`.
        *   This looks like a countdown or a specific pattern.
        *   Or maybe it's copying the bus line? No, the bus line is `B A B B B B`.
        *   The trace is in column 1. The values are `A` (at row 0), `B` (at row 1), `B` (at row 2).
        *   Wait, the output shows:
            Row 0: `.` `A` `.` ...
            Row 1: `.` `B` `.` ...
            Row 2: `.` `B` `.` ...
            Row 3: `B` `A` `B` ...
        *   So the column 1 reads from top to bottom: `A`, `B`, `B`, `A`.
        *   The component is `A`.
        *   The trace extends upwards.
        *   The colors are `A`, `B`, `B`.
        *   Why `B`? `B` is the color of the neighbors in the bus line?
        *   Neighbors of `A` in the bus line are `B` (left) and `B` (right).
        *   So maybe the trace is filled with the neighbor color?
        *   But the top cell is `A`.
        *   Let's re-read the metaphor: "The trace length depends on the component type, with the component's identifier visible at the trace end."
        *   "Component's identifier visible at the trace end".
        *   If the trace goes up, the "end" is the top cell.
        *   In the example, the top cell (Row 0, Col 1) is `A`. This matches the component color `A`.
        *   The cells below it (Row 1, Col 1 a

... [7939 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"Runes carved into Yggdrasil's root each summon a different spirit — fire runes call forth taller flame pillars than ice runes raise frost columns."
Fail (best cell_acc=0.86 at k=1)
Best Attempt
vs
Expected
Reasoning (13631 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A great root stretches across the world, inscribed with mostly uniform markings but bearing a few distinctly colored runes at certain points."
    *   This suggests a horizontal line (the "root") containing specific colored cells ("runes") amidst a background (likely black/dots).
*   **Action:** "Each rune awakens, summoning a pillar of elemental force perpendicular to the root."
    *   "Perpendicular to the root" means vertical pillars extending from the horizontal line.
    *   "Pillar's height depends on the rune's element". This implies different colors might have different heights.
    *   "The rune's glow crowning the top." This implies the top of the pillar has the same color as the rune.
*   **Grid details:** "The root remains unchanged. Elemental pillars extend from each rune, topped by the rune's color."
    *   The original horizontal line stays as is.
    *   Vertical lines (pillars) grow upwards or downwards from the rune positions.
    *   The top cell of the pillar matches the rune's color.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . . .
    . . . . . .
    . . . . . .
    B A B B B B
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    ```
    *   Grid size: 9 rows x 6 columns.
    *   Row 3 (0-indexed) contains the "root": `B A B B B B`.
    *   The background is `.` (black).
    *   The "runes" seem to be the non-background colors. Here we have `B` (Blue) and `A` (Azure).
    *   Wait, the description says "mostly uniform markings but bearing a few distinctly colored runes". In the input row `B A B B B B`, `B` appears 5 times and `A` appears 1 time.
    *   Let's look at the Output.
*   **Output:**
    ```
    . A . . . .
    . B . . . .
    . B . . . .
    B A B B B B
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    ```
    *   The root row (Row 3) is unchanged: `B A B B B B`.
    *   Above the `A` at (3, 1), there is a vertical column of `A` and `B`.
    *   Specifically, at column 1:
        *   Row 3: `A` (Root)
        *   Row 2: `B`
        *   Row 1: `B`
        *   Row 0: `A`
    *   Wait, let's look closer at the output column 1.
        *   Row 0: `.`
        *   Row 1: `B`
        *   Row 2: `B`
        *   Row 3: `A`
        *   Row 4-8: `.`
    *   Actually, looking at the provided output text:
        ```
        . A . . . .
        . B . . . .
        . B . . . .
        B A B B B B
        ...
        ```
        Row 0: `. A . . . .` -> Col 1 is `A`.
        Row 1: `. B . . . .` -> Col 1 is `B`.
        Row 2: `. B . . . .` -> Col 1 is `B`.
        Row 3: `B A B B B B` -> Col 1 is `A`.
    *   So above the `A` at (3,1), we have `B`, `B`, `A` going upwards?
    *   Let's re-read the output carefully.
        Row 0: `. A . . . .`
        Row 1: `. B . . . .`
        Row 2: `. B . . . .`
        Row 3: `B A B B B B`
    *   Column 1 content from top to bottom: `A`, `B`, `B`, `A`.
    *   This looks like a pillar extending upwards from the `A`.
    *   What about the `B`s in the root?
        *   Col 0: `B` at Row 3. Output Col 0 is `.` everywhere else.
        *   Col 2: `B` at Row 3. Output Col 2 is `.` everywhere else.
        *   Col 3: `B` at Row 3. Output Col 3 is `.` everywhere else.
        *   Col 4: `B` at Row 3. Output Col 4 is `.` everywhere else.
        *   Col 5: `B` at Row 3. Output Col 5 is `.` everywhere else.
    *   So only the `A` triggered a pillar. The `B`s did not.
    *   Why? The description says "mostly uniform markings but bearing a few distinctly colored runes".
    *   In the input row `B A B B B B`, `B` is the "uniform marking" (background color of the root?) and `A` is the "distinctly colored rune".
    *   Or perhaps `B` is the root color and `A` is the special one.
    *   The pillar extends upwards.
    *   The pillar consists of `B`, `B`, `A` above the root `A`.
    *   Wait, the top is `A`. The cells below it are `B`.
    *   Let's check the height. The pillar goes from Row 3 up to Row 0. That's 3 cells above the root.
    *   The colors in the pillar (excluding root) are `B`, `B`, `A` (from bottom to top).
    *   Wait, Row 2 is `B`, Row 1 is `B`, Row 0 is `A`.
    *   So the sequence from the root upwards is: `A` (root), `B`, `B`, `A` (top).
    *   Why `B`? `B` is the dominant color in the root.
    *   Why `A` at the top? "The rune's glow crowning the top." So the top cell matches the rune color (`A`).
    *   Why `B` in the middle? Maybe the pillar is filled with the "root color" (`B`) except for the top?
    *   Or maybe the height is determined by something else.
    *   Let's look at the "Conceptual Digestion" requirements.
    *   **CAST:**
        *   Root: The horizontal line of cells.
        *   Runes: Specific colored cells within the root that d

... [8646 chars truncated]
alt-14 dance qwen3.5-122b: k=2
"Dancers in a chorus line leap at their cue — soloists in crimson leap four beats high while those in teal leap only three, each hanging suspended at the peak."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10313 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A "chorus line of uniformly costumed dancers stretches across the stage". This implies a horizontal line of colored cells in the grid.
*   **Action:** "Each costumed dancer leaps perpendicular to the line." This suggests vertical movement from the horizontal line.
*   **Detail:** "The height of the leap depends on the costume color, with the dancer visible at the apex and a motion trail connecting back to the line."
*   **Grid details:** "The chorus line stays grounded. Vertical motion trails extend from each leaping dancer, with their costume color at the peak."

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: A 9x6 grid. Row 4 (0-indexed) contains `B A B B B B`. All other cells are `.` (black).
    *   Output: The row `B A B B B B` remains at Row 4.
    *   Above the `A` at (3, 1) [row, col], there is a column of `A`s going up? No, let's look closer.
    *   Input Row 3: `B A B B B B` (Wait, let's count rows).
        *   Row 0: `.`
        *   Row 1: `.`
        *   Row 2: `.`
        *   Row 3: `B A B B B B`
        *   Row 4: `.`
        *   ...
    *   Output:
        *   Row 0: `. A . . . .`
        *   Row 1: `. B . . . .`
        *   Row 2: `. B . . . .`
        *   Row 3: `B A B B B B`
        *   ...
    *   Observation:
        *   The `A` at (3, 1) in the input seems to have generated a vertical line upwards.
        *   The `B`s at (3, 0), (3, 2), (3, 3), (3, 4), (3, 5) seem to have generated vertical lines upwards.
        *   Let's check the heights.
        *   For `A` at col 1: Output has `A` at (0, 1), `B` at (1, 1), `B` at (2, 1). Wait, the input `A` is at (3, 1). The output has `A` at (0, 1). The cells between (0, 1) and (3, 1) are (1, 1) and (2, 1). In the output, (1, 1) is `B` and (2, 1) is `B`. This is strange. Why `B`?
        *   Let's re-examine the input.
        *   Input Row 3: `B A B B B B`.
        *   Output Col 1: `A` (row 0), `B` (row 1), `B` (row 2), `A` (row 3).
        *   Output Col 0: `.` (row 0), `.` (row 1), `.` (row 2), `B` (row 3).
        *   Output Col 2: `.` (row 0), `.` (row 1), `.` (row 2), `B` (row 3).
        *   Wait, looking at the output provided in Example 1:
            ```
            . A . . . .
            . B . . . .
            . B . . . .
            B A B B B B
            . . . . . .
            ...
            ```
        *   It seems only the `A` triggered something? Or did the `B`s trigger something but they are `.`?
        *   Let's look at the colors. `A` is Azure. `B` is Blue.
        *   Maybe the height depends on the color.
        *   `A` (Azure) -> Height 3? (From row 3 to row 0 is 3 steps up).
        *   `B` (Blue) -> Height 0? (Stays at row 3).
        *   Let's check the trail. The trail connects back to the line.
        *   For `A` at (3, 1): The apex is at (0, 1) which is `A`. The trail connects (0, 1) to (3, 1). The cells in between are (1, 1) and (2, 1). In the output, these are `B`. Why `B`?
        *   Maybe the trail color is determined by the *base* color? The base is `A`. The trail is `B`.
        *   Or maybe the trail color is determined by the *neighbor*?
        *   Let's look at Example 2.

*   **Example 2:**
    *   Input: 10x7 grid. Row 5 contains `B B B R B B B`.
    *   Output:
        *   Row 1: `. . . R . . .`
        *   Row 2: `. . . B . . .`
        *   Row 3: `. . . B . . .`
        *   Row 4: `. . . B . . .`
        *   Row 5: `B B B R B B B`
        *   ...
    *   Observation:
        *   The `R` (Red) is at (5, 3).
        *   In the output, at col 3:
            *   Row 1: `R`
            *   Row 2: `B`
            *   Row 3: `B`
            *   Row 4: `B`
            *   Row 5: `R`
        *   The `B`s in the input row (cols 0, 1, 2, 4, 5, 6) remain `B` at row 5, and nothing above them.
        *   So `B` (Blue) has height 0.
        *   `R` (Red) has height 4 (from row 5 to row 1).
        *   The apex is `R`.
        *   The trail cells (rows 2, 3, 4) are `B`.
        *   Why `B`? In Example 1, the trail cells for `A` were `B`.
        *   Hypothesis: The trail color is always `B` (Blue)? Or is it the color of the "chorus line" which is mostly `B`?
        *   In Example 1, the line is `B A B B B B`. The dominant color is `B`.
        *   In Example 2, the line is `B B B R B B B`. The dominant color is `B`.
        *   So the "chorus line" is primarily Blue (`B`). The special dancers are `A` and `R`.
        *   The "motion trail" seems to be filled with the base color of the line (`B`).
        *   The "apex" is the color of the special dancer.
        *   The height depends on the color.
        *   Let's check the heights.
        *   Example 1: `A` (Azure) at row 3. Apex at row 0. Height = 3 rows up.
        *   Example 2: `R` (Red) at row 5. Apex at row 1. Height = 4 rows up.
        *   

... [5352 chars truncated]
alt-15 geology qwen3.5-122b: k=3
"Mineral veins trapped in a bedrock stratum erupt under tectonic pressure — basalt intrusions push farther than quartz dikes before cooling solid."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (12737 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A horizontal stratum of uniform bedrock cuts across the formation.
*   **Elements:**
    *   "Stratum": A row of cells.
    *   "Mineral deposits": Specific colored cells within the stratum.
    *   "Intrusion": An extension from the deposit perpendicular to the stratum.
    *   "Intrusion length": Depends on the mineral type.
    *   "Leading edge": The tip of the intrusion has the deposit's color.
*   **Action:** Tectonic stress forces intrusions perpendicular to the stratum.
*   **Constraint:** The stratum remains.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Grid Size: 9 rows x 6 columns.
    *   Stratum Location: Row 4 (0-indexed: row 3). It contains `B A B B B B`.
    *   Deposits:
        *   Col 0: B (Blue)
        *   Col 1: A (Azure)
        *   Col 2: B (Blue)
        *   Col 3: B (Blue)
        *   Col 4: B (Blue)
        *   Col 5: B (Blue)
    *   Output Grid:
        *   Row 3 remains `B A B B B B`.
        *   Above the stratum (Rows 0, 1, 2):
            *   Col 0: `.` `.` `B` (Wait, looking at output)
            *   Output Row 0: `. A . . . .` -> Col 1 is A.
            *   Output Row 1: `. B . . . .` -> Col 1 is B.
            *   Output Row 2: `. B . . . .` -> Col 1 is B.
            *   Wait, let's look closer at the output provided in the prompt.
            *   Output:
                ```
                . A . . . .
                . B . . . .
                . B . . . .
                B A B B B B
                . . . . . .
                ...
                ```
            *   Let's check the columns.
            *   Col 0: Input `B`. Output Row 3 is `B`. Rows 0-2 are `.`. No intrusion? Or maybe intrusion length is 0?
            *   Col 1: Input `A`. Output Row 3 is `A`. Row 2 is `B`. Row 1 is `B`. Row 0 is `A`.
                *   Wait, the output shows:
                    Row 0: `. A . . . .`
                    Row 1: `. B . . . .`
                    Row 2: `. B . . . .`
                    Row 3: `B A B B B B`
                *   So at Col 1 (Azure `A`):
                    *   Row 3: `A` (Base)
                    *   Row 2: `B`
                    *   Row 1: `B`
                    *   Row 0: `A`
                *   This looks like an intrusion going UP.
                *   Length: 3 cells above the base?
                *   Colors: `A` (tip), `B`, `B`, `A` (base).
                *   Wait, the description says "tipped with the deposit's color".
                *   Deposit is `A`. Tip is `A`.
                *   The cells between base and tip are `B`.
                *   Why `B`? `B` is Blue. `A` is Azure.
                *   Maybe the "intrusion" is a column of `B`s topped with `A`?
                *   Let's check other columns.
            *   Col 2: Input `B`. Output Row 3 is `B`. Rows 0-2 are `.`. No intrusion.
            *   Col 3: Input `B`. Output Row 3 is `B`. Rows 0-2 are `.`. No intrusion.
            *   Col 4: Input `B`. Output Row 3 is `B`. Rows 0-2 are `.`. No intrusion.
            *   Col 5: Input `B`. Output Row 3 is `B`. Rows 0-2 are `.`. No intrusion.
    *   **Hypothesis 1:** Only specific minerals trigger intrusions. `A` triggers an upward intrusion. `B` does not?
    *   **Hypothesis 2:** Intrusion length depends on mineral type.
        *   `A` (Azure) -> Intrusion length 3? (Rows 0, 1, 2).
        *   `B` (Blue) -> Intrusion length 0?
    *   **Hypothesis 3:** The intrusion consists of the deposit color at the tip, and something else in the middle. In Example 1, the middle is `B`.
    *   **Hypothesis 4:** Direction. In Example 1, the intrusion goes UP. Why? Maybe because the stratum is in the middle? Or maybe it depends on the mineral?
    *   Let's look at Example 2.

*   **Example 2:**
    *   Input Grid Size: 10 rows x 7 columns.
    *   Stratum Location: Row 5 (0-indexed). `B B B R B B B`.
    *   Deposits:
        *   Col 0-2: `B`
        *   Col 3: `R` (Red)
        *   Col 4-6: `B`
    *   Output Grid:
        *   Row 5 remains `B B B R B B B`.
        *   Above Row 5 (Rows 0-4):
            *   Col 3 has changes.
            *   Row 4: `.`
            *   Row 3: `.`
            *   Row 2: `.`
            *   Row 1: `.`
            *   Row 0: `.`
            *   Wait, let's read the output carefully.
            *   Output:
                ```
                . . . . . . .
                . . . R . . .
                . . . B . . .
                . . . B . . .
                . . . B . . .
                B B B R B B B
                . . . . . . .
                ...
                ```
            *   Col 3 (Red `R`):
                *   Row 5: `R` (Base)
                *   Row 4: `B`
                *   Row 3: `B`
                *   Row 2: `B`
                *   Row 1: `R`
                *   Row 0: `.`
           

... [7797 chars truncated]
alt-2 cooking qwen3.5-122b: fail
"Spices pressed into a roll of dough bloom upward when the heat hits, each releasing its aromatic tower at a height that matches its potency."
Fail (best cell_acc=0.56 at k=3)
Best Attempt
vs
Expected
Reasoning (12142 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A long roll of uniform dough stretches across the baking sheet, with distinctly colored spice plugs pressed into it at various points."
    *   This suggests a row of cells (the "roll") containing specific colored cells ("spice plugs") amidst a background (the "dough", likely black `.`).
    *   Looking at the examples, there is indeed a specific row containing colored cells, while the rest are black `.`.
*   **Action:** "When baked, each spice plug sends a rising column of infused dough upward, crowned by the spice itself."
    *   "Rising column... upward": This implies vertical growth from the source row towards the top of the grid.
    *   "Crowned by the spice itself": The top of the column should be the color of the spice plug.
    *   "Infused dough": The column itself seems to be made of the same color as the spice plug.
*   **Constraint:** "Stronger spices push higher columns than milder ones."
    *   This implies a hierarchy of colors. Some colors produce taller columns than others.
    *   I need to determine the height of the column for each color based on the examples.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Grid Size: 9 rows x 6 columns.
    *   Source Row: Row 3 (0-indexed) or Row 4 (1-indexed). Let's use 0-indexed. Row 3 contains `B A B B B B`.
    *   Output Grid:
        *   Row 3 remains `B A B B B B`.
        *   Above Row 3:
            *   Col 1 (index 1): `A` at Row 2, `B` at Row 1, `.` at Row 0. Wait, let's look closer.
            *   Input Row 3: `B A B B B B` (indices 0 to 5).
            *   Output Col 0: `B` at Row 3. Above it: `.` at Row 2, `.` at Row 1, `.` at Row 0. Wait, looking at the output provided:
                ```
                . A . . . .
                . B . . . .
                . B . . . .
                B A B B B B
                . . . . . .
                ...
                ```
            *   Let's check the columns.
            *   Col 0: Input `B`. Output has `B` at Row 3. Above it `.` at Row 2, `.` at Row 1, `.` at Row 0. Wait, the output shows:
                Row 0: `. A . . . .`
                Row 1: `. B . . . .`
                Row 2: `. B . . . .`
                Row 3: `B A B B B B`
            *   Let's re-read the output carefully.
                Row 0: `. A . . . .` -> Col 1 is `A`.
                Row 1: `. B . . . .` -> Col 1 is `B`.
                Row 2: `. B . . . .` -> Col 1 is `B`.
                Row 3: `B A B B B B` -> Col 0 is `B`, Col 1 is `A`, Col 2 is `B`, Col 3 is `B`, Col 4 is `B`, Col 5 is `B`.
            *   Wait, the output text says:
                ```
                . A . . . .
                . B . . . .
                . B . . . .
                B A B B B B
                ```
            *   Let's map indices (row, col).
                (0, 1) = A
                (1, 1) = B
                (2, 1) = B
                (3, 0) = B
                (3, 1) = A
                (3, 2) = B
                (3, 3) = B
                (3, 4) = B
                (3, 5) = B
            *   Input at Row 3: `B A B B B B`.
            *   Col 0: Input `B`. Output has `B` at (3,0). No column above it? Wait, looking at the output block again.
                Row 0: `. A . . . .`
                Row 1: `. B . . . .`
                Row 2: `. B . . . .`
                Row 3: `B A B B B B`
            *   It seems only Col 1 has a column rising. Why?
            *   Input Col 1 is `A`. Input Col 0 is `B`. Input Col 2 is `B`.
            *   The column rising from `A` (at 3,1) goes up to (0,1). Height = 3 cells above source? Or total height?
            *   The column rising from `B` (at 3,0) seems to be just the source cell.
            *   The column rising from `B` (at 3,2) seems to be just the source cell.
            *   Hypothesis: `A` is a "stronger" spice than `B`. `A` creates a taller column. `B` creates a shorter column (height 0 above source?).
            *   Let's check the height.
                *   `A` at (3,1). Column extends to (0,1). That's 3 cells above the source row.
                *   `B` at (3,0). Column extends to (3,0). That's 0 cells above.
            *   Wait, look at Row 1 and Row 2 in Col 1. They are `B`.
                *   (2,1) is `B`.
                *   (1,1) is `B`.
                *   (0,1) is `A`.
            *   So the column consists of `B`s rising from the source `A`, topped by `A`?
            *   Metaphor: "sends a rising column of infused dough upward, crowned by the spice itself."
            *   "Infused dough" might mean the color of the column is the same as the spice? Or is it the background color?
            *   In Example 1, the column above `A` is `B B A`. The source is `A`. The cells above are `B`.
            *   Wait, the source row is `B A B B B B`.
        

... [7166 chars truncated]
alt-3 music qwen3.5-122b: k=4
"Notes embedded in a drone string resonate upward, each pitch sustaining harmonics whose overtone count depends on the instrument that produced it."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (11316 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A sustained drone hums across one line": This suggests there is a specific row (or column) in the grid that acts as a "drone line". Looking at the examples, there is always a row filled with colors (mostly B, with some other colors).
*   "certain positions colored by distinct tonal signatures breaking the monotone": In the drone line, most cells are one color (let's call it the "base color"), but some cells have different colors. These are the "tonal signatures".
*   "Each tonal signature vibrates and projects a stack of harmonic overtones away from the drone": This implies that from the non-base color cells in the drone line, something extends outwards perpendicular to the line.
*   "The number of overtones varies by timbre — some voices ring longer than others": This suggests the length of the extension depends on the specific color of the "tonal signature".
*   "The drone line persists unchanged": The original row remains exactly as it was in the input.
*   "Overtone stacks extend perpendicular from each colored position, with the original tone at the far end": This is a crucial detail. The stack extends *away* from the drone line. The "original tone" (the color of the signature) is at the *far end* of the stack. The cells between the drone line and the far end are filled with something else. Looking at the examples, the cells in the stack seem to be the "base color" of the drone line, except for the tip which is the "signature color". Wait, let's look closer.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 9x6 grid. Row 3 (0-indexed) is `B A B B B B`.
    *   Base color seems to be `B` (Blue).
    *   Signature color is `A` (Azure) at index 1.
    *   Output: Row 3 is unchanged `B A B B B B`.
    *   Above the `A` at (3, 1), there is a column of colors.
    *   (2, 1) is `B`.
    *   (1, 1) is `B`.
    *   (0, 1) is `A`.
    *   So, extending upwards from the `A` at (3, 1):
        *   Distance 1: `B`
        *   Distance 2: `B`
        *   Distance 3: `A`
    *   Wait, the description says "original tone at the far end". The original tone is `A`. The far end is (0, 1). The cells in between are `B`.
    *   How many cells? The stack goes from row 3 up to row 0. That's 3 cells above the drone line.
    *   Why 3? Maybe it depends on the color `A`? Or maybe it goes to the edge?
    *   Let's check other examples.

*   **Example 2:**
    *   Input: 10x7 grid. Row 5 is `B B B R B B B`.
    *   Base color: `B`.
    *   Signature color: `R` (Red) at index 3.
    *   Output: Row 5 unchanged.
    *   Above the `R` at (5, 3):
        *   (4, 3) is `B`.
        *   (3, 3) is `B`.
        *   (2, 3) is `B`.
        *   (1, 3) is `R`.
        *   (0, 3) is `.` (empty).
    *   So the stack extends 4 cells upwards. The tip is `R`. The intermediate cells are `B`.
    *   Why 4 cells?
    *   In Example 1, `A` extended 3 cells (rows 2, 1, 0).
    *   In Example 2, `R` extended 4 cells (rows 4, 3, 2, 1).
    *   Is there a mapping from color to length?
    *   `A` -> 3?
    *   `R` -> 4?
    *   Let's check Example 3.

*   **Example 3:**
    *   Input: 9x9 grid. Row 7 is `B A B B B A B R B`.
    *   Base color: `B`.
    *   Signatures: `A` at index 1, `A` at index 5, `R` at index 7.
    *   Output: Row 7 unchanged.
    *   Column 1 (above `A`):
        *   (6, 1) `B`
        *   (5, 1) `B`
        *   (4, 1) `A`
        *   (3, 1) `.`
        *   Length: 3 cells (rows 6, 5, 4). Tip is `A`.
    *   Column 5 (above `A`):
        *   (6, 5) `B`
        *   (5, 5) `B`
        *   (4, 5) `A`
        *   Length: 3 cells. Tip is `A`.
    *   Column 7 (above `R`):
        *   (6, 7) `B`
        *   (5, 7) `B`
        *   (4, 7) `B`
        *   (3, 7) `R`
        *   Length: 4 cells. Tip is `R`.
    *   This confirms the pattern:
        *   `A` (Azure) creates a stack of length 3.
        *   `R` (Red) creates a stack of length 4.
        *   The stack consists of the base color (`B`) filling the space, and the signature color at the very tip (furthest from the drone line).
        *   Direction: Upwards (rows decreasing).

*   **Example 4:**
    *   Input: 13x10 grid. Row 9 is `B B R B B B A B B B`.
    *   Base color: `B`.
    *   Signatures: `R` at index 2, `A` at index 6.
    *   Output: Row 9 unchanged.
    *   Column 2 (above `R`):
        *   (8, 2) `B`
        *   (7, 2) `B`
        *   (6, 2) `B`
        *   (5, 2) `R`
        *   Length: 4 cells. Tip is `R`.
    *   Column 6 (above `A`):
        *   (8, 6) `B`
        *   (7, 6) `B`
        *   (6, 6) `A`
        *   Length: 3 cells. Tip is `A`.
    *   This confirms the lengths again. `R` -> 4, `A` -> 3.
    *   Direction is consistently Upwards.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Drone Line:** A specific row containing a sequence of colors

... [6355 chars truncated]
alt-4 sports qwen3.5-122b: k=4
"Players standing in a scrimmage line break formation at the whistle — each position sprints a different number of yards depending on their jersey color."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (11576 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A "scrimmage line" of uniformly dressed players (likely the background color or a specific row/column of a specific color) stretches across the field.
*   **Exception:** A few players wear "distinctly colored jerseys" mixed in.
*   **Action:** At the whistle, each uniquely jerseyed player "sprints perpendicular to the line".
*   **Trail:** They trail teammates behind them.
*   **Distance:** The sprint distance depends on the jersey color.
*   **Result:** The scrimmage line remains. Each sprinting player leaves a trail of teammates connecting back to the line, with the colored jersey at the lead.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 9x6 grid. Row 4 (0-indexed) is `B A B B B B`. The rest are `.` (black).
    *   Output: Row 4 is `B A B B B B`. Column 1 (where 'A' is) has `A` at row 0, `B` at row 1, `B` at row 2.
    *   Observation: The 'A' is at (3, 1). It moved "up" (perpendicular to the horizontal line). The trail consists of 'B's (the uniform color) connecting the 'A' back to the line. The 'A' is at the top of the trail.
    *   Wait, let's look closer.
    *   Input Row 3 (0-indexed): `B A B B B B`.
    *   Output Row 3: `B A B B B B`.
    *   Output Column 1: Row 0 is `A`, Row 1 is `B`, Row 2 is `B`.
    *   So the 'A' moved from (3,1) to (0,1). The cells (1,1) and (2,1) became 'B'.
    *   Why did it move to row 0? Is it distance based on color?
    *   'A' is Azure. 'B' is Blue.
    *   The line is mostly 'B'. The unique player is 'A'.
    *   The trail is made of 'B's.
    *   Direction: Up.

*   **Example 2:**
    *   Input: 10x7 grid. Row 5 is `B B B R B B B`. Rest `.`.
    *   Output: Row 5 is `B B B R B B B`.
    *   Column 3 (where 'R' is): Row 1 is `R`, Row 2 is `B`, Row 3 is `B`, Row 4 is `B`.
    *   Input 'R' was at (5, 3). Output 'R' is at (1, 3).
    *   Trail: (2,3), (3,3), (4,3) are 'B'.
    *   Direction: Up.
    *   Distance: From row 5 to row 1. Length of trail = 3 'B's + 1 'R' = 4 cells total? Or just the 'B's?
    *   Let's check the distance.
    *   Ex 1: 'A' at row 3. Moved to row 0. Distance = 3 steps.
    *   Ex 2: 'R' at row 5. Moved to row 1. Distance = 4 steps.
    *   Is there a mapping from Color to Distance?
    *   Ex 1: Color 'A' (Azure). Distance 3.
    *   Ex 2: Color 'R' (Red). Distance 4.
    *   Wait, let's look at Example 3.

*   **Example 3:**
    *   Input: 9x9 grid. Row 7 is `B A B B B A B R B`.
    *   Output: Row 7 is `B A B B B A B R B`.
    *   Column 1 ('A'): 'A' at (4, 1). Trail 'B's at (5,1), (6,1).
        *   Input 'A' at (7,1). Output 'A' at (4,1). Distance = 3 steps.
    *   Column 5 ('A'): 'A' at (4, 5). Trail 'B's at (5,5), (6,5).
        *   Input 'A' at (7,5). Output 'A' at (4,5). Distance = 3 steps.
    *   Column 7 ('R'): 'R' at (3, 7). Trail 'B's at (4,7), (5,7), (6,7).
        *   Input 'R' at (7,7). Output 'R' at (3,7). Distance = 4 steps.
    *   Consistency:
        *   'A' (Azure) -> Distance 3.
        *   'R' (Red) -> Distance 4.
    *   Direction: Up.

*   **Example 4:**
    *   Input: 13x10 grid. Row 9 is `B B R B B B A B B B`.
    *   Output: Row 9 is `B B R B B B A B B B`.
    *   Column 2 ('R'): 'R' at (5, 2). Trail 'B's at (6,2), (7,2), (8,2).
        *   Input 'R' at (9,2). Output 'R' at (5,2). Distance = 4 steps.
    *   Column 6 ('A'): 'A' at (6, 6). Trail 'B's at (7,6), (8,6).
        *   Input 'A' at (9,6). Output 'A' at (6,6). Distance = 3 steps.
    *   Consistency:
        *   'A' -> Distance 3.
        *   'R' -> Distance 4.
    *   Direction: Up.

**3. Synthesize the Rules:**

*   **Grid Structure:** There is a horizontal "scrimmage line" (a row filled mostly with a background color, here 'B' Blue, with some "unique" colors).
*   **Unique Players:** Cells in the scrimmage line that are not the background color ('B').
*   **Action:** Each unique player moves perpendicular to the line. In all examples, the line is horizontal, and the movement is **Up** (towards row 0).
*   **Trail:** The cells between the original position and the new position are filled with the background color ('B').
*   **Distance:** The distance moved depends on the color of the unique player.
    *   'A' (Azure) moves 3 steps.
    *   'R' (Red) moves 4 steps.
    *   What about other colors? The test input has 'R' and 'A'.
    *   Wait, is the distance fixed per color, or is it related to the color index/value?
    *   Let's check the color key provided: `.=black B=blue R=red G=green Y=yellow X=grey M=magenta O=orange A=azure W=maroon`.
    *   Maybe it's alphabetical order? A=1, B=2, R=18... No.
    *   Maybe it's specific mapping learned from examples.
    *   'A' -> 3.
    *   'R' -> 4.
    *   Is there a pattern?
    *   Let's look at the Test Input.
    *   Test Input Row 6: `B R B A B B B A B R B`.
    *   Unique colo

... [6606 chars truncated]
alt-5 weather qwen3.5-122b: k=4
"Storm cells embedded in a pressure front push updrafts of different heights — warm cells climb higher than cool ones before condensing."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (11114 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A long pressure front stretches across the atmosphere, mostly uniform but with distinct thermal anomalies embedded at certain points."
*   **Action:** "Each thermal anomaly drives an updraft column perpendicular to the front."
*   **Details:** "The column's height depends on the anomaly's thermal signature, with the anomaly type visible at the cloud top."
*   **Grid details:** "The front stays in place. Updraft columns extend from each anomaly position, topped by the anomaly's color."

**Interpretation:**
*   There is a "front" which seems to be a row of colored pixels (non-black) in the input grid.
*   "Thermal anomalies" are specific colored pixels within this front row.
*   "Updraft columns" extend from these anomalies.
*   "Perpendicular to the front": Since the front is horizontal (a row), the columns extend vertically (up or down). Looking at the examples, they extend upwards.
*   "Column's height depends on the anomaly's thermal signature": This implies different colors might result in different heights.
*   "Topped by the anomaly's color": The top pixel of the column should match the color of the anomaly.
*   "The front stays in place": The original row of pixels remains unchanged in the output.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 9x6 grid. Row 3 (0-indexed) is `B A B B B B`.
    *   Output: Row 3 is `B A B B B B`.
    *   Changes: Above the 'A' at (3, 1), there is a column of 'B's and an 'A' at the top? Wait.
    *   Let's look closely at Example 1 Output:
        Row 0: `. A . . . .`
        Row 1: `. B . . . .`
        Row 2: `. B . . . .`
        Row 3: `B A B B B B`
    *   The 'A' is at (3, 1). Above it, at (2, 1) is 'B', at (1, 1) is 'B', at (0, 1) is 'A'.
    *   Wait, the description says "topped by the anomaly's color". The anomaly is 'A'. The top is 'A'.
    *   What is the rest of the column? It seems to be filled with 'B'.
    *   Why 'B'? The front row is mostly 'B's. Maybe the column is filled with the "background" color of the front? Or maybe the color of the neighbors?
    *   Let's check the height. The column goes from row 3 up to row 0. Height = 3 cells above the front.
    *   Is there a rule for height?
    *   Let's look at other anomalies. In Example 1, there is only one 'A'. The rest are 'B'.
    *   The 'B's in the front row do not generate columns. Only 'A' generates a column? Or maybe 'B' is the "front" color and 'A' is the "anomaly"?
    *   Hypothesis: The dominant color in the row is the "front". Other colors are "anomalies".
    *   In Ex 1, row is `B A B B B B`. Dominant is B. Anomaly is A.
    *   Column above A: `A` at top, `B` below it.
    *   Wait, looking at Ex 1 output again:
        Row 0: `. A . . . .`
        Row 1: `. B . . . .`
        Row 2: `. B . . . .`
        Row 3: `B A B B B B`
    *   The column is at column index 1.
    *   Cells: (0,1)=A, (1,1)=B, (2,1)=B.
    *   So the column consists of the anomaly color at the top, and the front color filling the rest?
    *   Height: It reaches the top of the grid (Row 0).

*   **Example 2:**
    *   Input: 10x7 grid. Row 5 is `B B B R B B B`.
    *   Dominant color: B. Anomaly: R.
    *   Output:
        Row 1: `. . . R . . .`
        Row 2: `. . . B . . .`
        Row 3: `. . . B . . .`
        Row 4: `. . . B . . .`
        Row 5: `B B B R B B B`
    *   Column is at index 3 (where R is).
    *   Cells above R: (4,3)=B, (3,3)=B, (2,3)=B, (1,3)=R.
    *   Top is R (anomaly color). Rest are B (front color).
    *   Height: Reaches Row 1. Why not Row 0?
    *   Grid height is 10. Front is at Row 5.
    *   Distance to top (Row 0) is 5.
    *   Column height is 4 cells (Rows 1, 2, 3, 4).
    *   Why height 4?
    *   Maybe height depends on the anomaly color?
    *   In Ex 1, Anomaly A, Height 3 (Rows 0, 1, 2). Front at Row 3.
    *   In Ex 2, Anomaly R, Height 4 (Rows 1, 2, 3, 4). Front at Row 5.
    *   Let's check the colors. A vs R.
    *   Maybe height is determined by the color value? Or specific mapping?
    *   Let's look at Example 3.

*   **Example 3:**
    *   Input: 9x9 grid. Row 7 is `B A B B B A B R B`.
    *   Dominant: B. Anomalies: A (at col 1), A (at col 5), R (at col 7).
    *   Output:
        Row 3: `. . . . . . . R .` (Col 7)
        Row 4: `. A . . . A . B .` (Col 1, 5, 7)
        Row 5: `. B . . . B . B .` (Col 1, 5, 7)
        Row 6: `. B . . . B . B .` (Col 1, 5, 7)
        Row 7: `B A B B B A B R B`
    *   Let's analyze the columns.
    *   Col 1 (Anomaly A):
        *   Row 7: A
        *   Row 6: B
        *   Row 5: B
        *   Row 4: A
        *   Top is Row 4. Height = 3 cells above front (Rows 4, 5, 6).
    *   Col 5 (Anomaly A):
        *   Row 7: A
        *   Row 6: B
        *   Row 5: B
        *   Row 4: A
        *   Top is Row 4. Height = 3 cells above

... [6159 chars truncated]
alt-6 architecture qwen3.5-122b: fail
"Keystones set into a foundation wall dictate how tall their supporting columns must be — marble keystones demand shorter columns than granite ones."
Fail (best cell_acc=0.86 at k=1)
Best Attempt
vs
Expected
Reasoning (13429 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A foundation wall of uniform brick runs across the site.
*   **Keystones:** A few distinctly colored keystones are mortared into specific positions in the wall.
*   **Action:** From each keystone, a column rises perpendicular to the wall.
*   **Column Height:** Determined by the keystone material.
*   **Capstone:** A matching capstone is placed at the top of the column.
*   **Grid Details:** The wall remains intact. Columns of brick rise from keystone positions, each crowned with a capstone matching the keystone's color.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . . .
    . . . . . .
    . . . . . .
    B A B B B B
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    ```
    *   Grid size: 9 rows x 6 columns.
    *   Row 3 (0-indexed) contains `B A B B B B`.
    *   Most cells are `.` (black).
    *   The "wall" seems to be the row containing non-black colors. Here it's row 3.
    *   The "keystones" are the non-black cells in that row.
    *   In this row: `B` (blue), `A` (azure), `B` (blue), `B` (blue), `B` (blue), `B` (blue).
    *   Wait, the description says "uniform brick". `B` usually stands for Blue. But in the context of "brick", maybe `B` represents the brick color? Or maybe the wall is made of `B` and the keystones are the other colors?
    *   Let's look at the Output.
*   **Output:**
    ```
    . A . . . .
    . B . . . .
    . B . . . .
    B A B B B B
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    ```
    *   The wall row (row 3) is unchanged: `B A B B B B`.
    *   Above the `A` at (3, 1), there is a column.
    *   The column consists of `B` at (2, 1) and (1, 1).
    *   The top of the column at (0, 1) is `A`.
    *   So, above the `A`, we have `B`, `B`, `A`.
    *   Wait, let's look closer.
    *   Input Row 3: `B A B B B B`.
    *   Output Row 3: `B A B B B B`.
    *   Output Row 2: `. B . . . .` (Column above A is B)
    *   Output Row 1: `. B . . . .` (Column above A is B)
    *   Output Row 0: `. A . . . .` (Top of column above A is A)
    *   The `B`s in the wall row (indices 0, 2, 3, 4, 5) did not generate columns.
    *   Only the `A` generated a column.
    *   Why? The description says "distinctly colored keystones". `B` is likely the "brick" color (Blue). `A` is Azure. So `A` is the keystone.
    *   The column rises "perpendicular to the wall". Since the wall is horizontal, the column goes up (or down?). In the example, it goes up (rows 0, 1, 2).
    *   "Column height is determined by the keystone material".
    *   "Matching capstone placed at the top".
    *   In the example, the keystone is `A`. The capstone is `A`. The column body is `B` (brick).
    *   How high is the column?
    *   The wall is at row 3. The top is at row 0. That's a height of 3 cells above the wall (rows 2, 1, 0).
    *   Is the height determined by the color `A`? Or is it fixed to the edge of the grid?
    *   Let's check the Test Input to see if there are other colors or if the height varies.

**3. Analyze the Test Input:**
*   **Input:**
    ```
    . . . . . . . . . . .
    . . . . . . . . . . .
    . . . . . . . . . . .
    . . . . . . . . . . .
    . . . . . . . . . . .
    . . . . . . . . . . .
    B R B A B B B A B R B
    . . . . . . . . . . .
    . . . . . . . . . . .
    ```
    *   Grid size: 9 rows x 11 columns.
    *   Wall row: Row 6 (0-indexed).
    *   Wall content: `B R B A B B B A B R B`.
    *   Colors present: `B` (Blue), `R` (Red), `A` (Azure).
    *   Assumption: `B` is the "brick" color (foundation wall). `R` and `A` are "keystones".
    *   Positions of keystones in Row 6:
        *   Index 1: `R`
        *   Index 3: `A`
        *   Index 7: `A`
        *   Index 9: `R`
    *   Positions of `B` (brick): 0, 2, 4, 5, 6, 8, 10.

**4. Deduce the Transformation Rule:**
*   **Wall:** The row containing the sequence of colors. In the example, it was row 3. In the test, it is row 6.
*   **Keystones:** Any cell in the wall row that is NOT the background color (`.`) AND NOT the "brick" color (`B`).
    *   Wait, in the example, the wall was `B A B B B B`. `B` was treated as the wall material. `A` was the keystone.
    *   In the test input, the wall is `B R B A B B B A B R B`.
    *   So `B` is the wall material. `R` and `A` are keystones.
*   **Column Construction:**
    *   For each keystone at `(row_wall, col)`:
        *   A column rises perpendicular to the wall. In the example, it went UP.
        *   The column consists of "brick" (`B`) cells.
        *   The top of the column is a "capstone" matching the keystone color.
        *   How high does it go?
        *   In the example: Wall at row 3. Column goes to row 0. Height = 3 cells above wall.
        *   Is the height fixed to the top of the grid? Or is it de

... [8462 chars truncated]
alt-7 warfare qwen3.5-122b: k=3
"Signal flares lodged in a trench wall launch at different altitudes depending on the order they encode — reconnaissance flares arc lower than artillery calls."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (10410 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A "fortified trench line" stretches across the battlefield. This implies a row of non-black pixels (colored pixels) in the input grid.
*   **Elements:** "Colored signal flares embedded at intervals" within the trench.
*   **Action:** "Each flare fires perpendicular to the trench, trailing smoke behind it."
*   **Result:** "The altitude reached depends on the flare's color, with the flare visible at the apex."
*   **Grid details:** "The trench remains. Smoke trails extend from each flare position, with the colored flare at the far end."

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 9x6 grid. Row 3 (0-indexed) is `B A B B B B`. All other rows are `.`.
    *   Output: Row 3 is `B A B B B B`.
    *   Changes:
        *   At column 1 (index 1), there is an 'A' (Azure). In the output, above it at (0,1) is 'A', at (1,1) is 'B', at (2,1) is 'B'. Wait, let's look closer.
        *   Input Row 3: `B A B B B B` (indices 0 to 5).
        *   Output Row 3: `B A B B B B`.
        *   Output Column 1: Row 0 is 'A', Row 1 is 'B', Row 2 is 'B'.
        *   Wait, the metaphor says "trailing smoke behind it". Usually, smoke trails from the source to the apex.
        *   Let's check the colors.
        *   Input at (3, 1) is 'A'. Output has 'A' at (0, 1). The cells between (3,1) and (0,1) are (2,1) and (1,1). In the output, (2,1) is 'B' and (1,1) is 'B'.
        *   Input at (3, 0) is 'B'. Output at (3,0) is 'B'. No change above it?
        *   Input at (3, 2) is 'B'. Output at (3,2) is 'B'. No change above it?
        *   Input at (3, 3) is 'B'. Output at (3,3) is 'B'. No change above it?
        *   Input at (3, 4) is 'B'. Output at (3,4) is 'B'. No change above it?
        *   Input at (3, 5) is 'B'. Output at (3,5) is 'B'. No change above it?
        *   Why did 'A' trigger a change but 'B's didn't?
        *   Maybe 'B' is the "trench" color (background of the trench) and others are "flares"?
        *   In Example 1, the trench row is `B A B B B B`. 'B' appears 5 times, 'A' appears 1 time.
        *   The 'A' shoots up. The trail consists of 'B's? And the apex is 'A'.
        *   Distance: From row 3 to row 0 is 3 steps.
        *   Let's look at Example 2.

*   **Example 2:**
    *   Input: 10x7 grid. Row 5 is `B B B R B B B`.
    *   Output: Row 5 is `B B B R B B B`.
    *   Changes:
        *   At column 3 (index 3), there is an 'R' (Red).
        *   Output Column 3: Row 1 is 'R', Row 2 is 'B', Row 3 is 'B', Row 4 is 'B'.
        *   Wait, Row 5 is the source.
        *   Source: (5, 3) is 'R'.
        *   Apex: (1, 3) is 'R'.
        *   Trail: (2,3), (3,3), (4,3) are 'B'.
        *   Why did it stop at Row 1?
        *   In Example 1, 'A' went from Row 3 to Row 0. Distance = 3.
        *   In Example 2, 'R' went from Row 5 to Row 1. Distance = 4.
        *   Is there a relationship between color and height?
        *   Colors involved: 'A' (Azure), 'B' (Blue), 'R' (Red).
        *   'A' height: 3 (rows 0, 1, 2 above row 3).
        *   'R' height: 4 (rows 1, 2, 3, 4 above row 5).
        *   Wait, let's count the number of cells filled.
        *   Ex 1: 'A' at (3,1). Apex at (0,1). Cells filled: (0,1)=A, (1,1)=B, (2,1)=B. Total 3 cells above source.
        *   Ex 2: 'R' at (5,3). Apex at (1,3). Cells filled: (1,3)=R, (2,3)=B, (3,3)=B, (4,3)=B. Total 4 cells above source.
        *   Is 'B' the smoke color? In Ex 1, the trench is mostly 'B'. In Ex 2, the trench is mostly 'B'.
        *   Hypothesis: The "trench" color is the dominant color in the row. The "flare" colors are the non-dominant colors.
        *   The flare shoots perpendicular (upwards in these examples).
        *   The trail is filled with the trench color ('B').
        *   The apex is the flare color.
        *   Height depends on the flare color.
        *   Let's check Example 3 to confirm height logic and direction.

*   **Example 3:**
    *   Input: 9x9 grid. Row 7 is `B A B B B A B R B`.
    *   Output: Row 7 is `B A B B B A B R B`.
    *   Changes:
        *   Column 1: 'A' at (7,1). Apex at (4,1) is 'A'. Trail (5,1), (6,1) are 'B'. Height = 3 cells above source (rows 4, 5, 6).
        *   Column 5: 'A' at (7,5). Apex at (4,5) is 'A'. Trail (5,5), (6,5) are 'B'. Height = 3 cells above source.
        *   Column 7: 'R' at (7,7). Apex at (3,7) is 'R'. Trail (4,7), (5,7), (6,7) are 'B'. Height = 4 cells above source (rows 3, 4, 5, 6).
    *   Consistency:
        *   'A' (Azure) -> Height 3.
        *   'R' (Red) -> Height 4.
        *   'B' (Blue) -> No change (it's the trench color).
    *   Direction: Upwards.
    *   Trail Color: 'B' (Blue).
    *   Apex Color: Flare Color ('A' or 'R').

**3. Synthesize the Rules:**

1.  **Identify the Trench:** Find the row containing a sequence of colored pixels. In all examples, this is a sing

... [5431 chars truncated]
alt-8 theater qwen3.5-122b: fail
"Trapdoors in the stage floor spring open and raise performers on lifts — lead actors rise higher than the chorus, each standing on a pillar of light matching their spotlight color."
Fail (best cell_acc=0.86 at k=3)
Best Attempt
vs
Expected
Reasoning (11366 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A stage floor with trapdoor markers.
*   **Action:** Each trapdoor activates, raising a column from below.
*   **Height:** The height of the lift depends on the marker color.
*   **Top:** The performer's spotlight is visible at the top (which seems to imply the marker color itself is at the top of the column).
*   **Grid details:** The stage floor stays level. Columns extend perpendicular from each trapdoor.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 9x6 grid. Row 4 (0-indexed) has `B A B B B B`. All other cells are `.`.
    *   Output: 9x6 grid.
        *   Row 4 remains `B A B B B B`.
        *   Above the `A` at (3, 1) [row, col], there is a column of `A`s going up? No, let's look closer.
        *   Input Row 3 (0-indexed): `B A B B B B`.
        *   Output Row 0: `. A . . . .`
        *   Output Row 1: `. B . . . .`
        *   Output Row 2: `. B . . . .`
        *   Output Row 3: `B A B B B B`
        *   Wait, let's look at the columns.
        *   Col 0: Input has `B` at row 3. Output has `B` at row 3. No change above.
        *   Col 1: Input has `A` at row 3. Output has `A` at row 0, `B` at row 1, `B` at row 2, `A` at row 3.
            *   Wait, the output at (0,1) is `A`. At (1,1) is `B`. At (2,1) is `B`. At (3,1) is `A`.
            *   This looks like a column extending upwards from the marker.
            *   The marker is `A`. The column above it is `A`, `B`, `B`.
            *   Why `B`?
            *   Let's check the other columns.
            *   Col 2: Input `B` at row 3. Output `B` at row 3. No change above.
            *   Col 3: Input `B` at row 3. Output `B` at row 3. No change above.
            *   Col 4: Input `B` at row 3. Output `B` at row 3. No change above.
            *   Col 5: Input `B` at row 3. Output `B` at row 3. No change above.
        *   So only the `A` triggered a change.
        *   The change is a column extending upwards.
        *   The top of the column (row 0) is `A`.
        *   The cells below it (row 1, 2) are `B`.
        *   The marker itself (row 3) is `A`.
        *   Why are rows 1 and 2 `B`?
        *   Maybe the height depends on the color?
        *   Let's look at Example 2.

*   **Example 2:**
    *   Input: 10x7 grid. Row 5 has `B B B R B B B`.
    *   Output:
        *   Row 5: `B B B R B B B` (Unchanged).
        *   Col 3 (where `R` is):
            *   Row 1: `R`
            *   Row 2: `B`
            *   Row 3: `B`
            *   Row 4: `B`
            *   Row 5: `R`
        *   Other columns (`B`): No change above.
    *   Comparison with Example 1:
        *   Ex 1: Marker `A` at row 3. Column goes up to row 0. Height = 3 cells above.
            *   Top cell (row 0) is `A`.
            *   Middle cells (row 1, 2) are `B`.
        *   Ex 2: Marker `R` at row 5. Column goes up to row 1. Height = 4 cells above.
            *   Top cell (row 1) is `R`.
            *   Middle cells (row 2, 3, 4) are `B`.
    *   Hypothesis:
        *   Specific colors trigger columns. `B` (Blue) seems to be the "floor" or "inactive" color, or maybe the filler color.
        *   `A` (Azure) and `R` (Red) trigger columns.
        *   The column extends upwards from the marker.
        *   The top of the column takes the color of the marker.
        *   The cells in between the top and the marker are filled with `B` (Blue).
        *   How is the height determined?
            *   Ex 1: `A` at row 3. Top at row 0. Height = 3.
            *   Ex 2: `R` at row 5. Top at row 1. Height = 4.
            *   Is there a fixed height? Or does it depend on the color?
            *   Maybe `A` = height 3? `R` = height 4?
            *   Let's check Example 3.

*   **Example 3:**
    *   Input: 9x9 grid. Row 7 has `B A B B B A B R B`.
    *   Output:
        *   Row 7: `B A B B B A B R B` (Unchanged).
        *   Col 1 (`A` at row 7):
            *   Row 4: `A`
            *   Row 5: `B`
            *   Row 6: `B`
            *   Row 7: `A`
            *   Height = 3 cells above (rows 4, 5, 6).
        *   Col 5 (`A` at row 7):
            *   Row 4: `A`
            *   Row 5: `B`
            *   Row 6: `B`
            *   Row 7: `A`
            *   Height = 3 cells above.
        *   Col 7 (`R` at row 7):
            *   Row 3: `R`
            *   Row 4: `B`
            *   Row 5: `B`
            *   Row 6: `B`
            *   Row 7: `R`
            *   Height = 4 cells above (rows 3, 4, 5, 6).
    *   Consistency Check:
        *   `A` (Azure) always creates a column of height 3 (marker + 2 `B`s + 1 `A` on top? No, marker is at bottom).
            *   Ex 1: `A` at row 3. Top at row 0. Distance = 3. Cells filled: (0,1)=A, (1,1)=B, (2,1)=B. Marker at (3,1)=A.
            *   Ex 3: `A` at row 7. Top at row 4. Distance = 3. Cells filled: (4,1)=A, (5,1)=B, (6,1)=B. Mark

... [6378 chars truncated]
alt-9 gardening qwen3.5-122b: fail
"Seeds of different species planted along an irrigation channel send shoots upward — sunflowers reach taller than marigolds, each bloom showing its true color at the tip."
Fail (best cell_acc=0.15 at k=1)
Best Attempt
vs
Expected
Reasoning (15019 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** An irrigation channel runs across the garden bed.
*   **Elements:** Seeds planted at intervals along the channel.
*   **Action:** Each seed germinates and sends a stem upward.
*   **Stem properties:** Uniform green color.
*   **Flower properties:** The flower's color appears at the top of the stem.
*   **Grid details:** The channel remains. Stems of uniform green rise from each seed position, capped by the flower color.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . . .
    . . . . . .
    . . . . . .
    B A B B B B
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    ```
    *   Grid size: 9 rows x 6 columns.
    *   Row 3 (0-indexed) contains colored pixels: `B A B B B B`. This looks like the "channel".
    *   Other rows are empty (`.`).
*   **Output:**
    ```
    . A . . . .
    . B . . . .
    . B . . . .
    B A B B B B
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    . . . . . .
    ```
    *   The channel row (Row 3) remains unchanged.
    *   Above the channel, there are changes.
    *   Let's look at the columns where the channel has non-black pixels.
        *   Col 0: `B` at Row 3. Output has `.` at Row 0, 1, 2. Wait, looking closely at the output provided in the prompt.
        *   Output Row 0: `. A . . . .` -> Col 1 is `A`.
        *   Output Row 1: `. B . . . .` -> Col 1 is `B`.
        *   Output Row 2: `. B . . . .` -> Col 1 is `B`.
        *   Output Row 3: `B A B B B B` -> Channel.
    *   Wait, let's re-examine the input/output alignment.
    *   Input Row 3: `B A B B B B` (Indices 0 to 5).
    *   Output Row 3: `B A B B B B`.
    *   Output Row 2: `. B . . . .` (Index 1 is `B`).
    *   Output Row 1: `. B . . . .` (Index 1 is `B`).
    *   Output Row 0: `. A . . . .` (Index 1 is `A`).
    *   This implies a stem growing upwards from the seed at (Row 3, Col 1).
    *   The seed at (Row 3, Col 1) is `A` (Azure).
    *   The stem seems to be Green (`G`)? No, the output shows `B` and `A`.
    *   Let's check the color key: `G=green`.
    *   The output shows `B` (Blue) and `A` (Azure) in the stem area.
    *   Wait, the metaphor says "Stems of uniform green rise from each seed position, capped by the flower color."
    *   If the stem is green, I should see `G`. But I see `B` and `A`.
    *   Let's look at the seed colors in the channel: `B` (Blue), `A` (Azure), `B`, `B`, `B`, `B`.
    *   In the output, only the column corresponding to `A` (Col 1) has changes above the channel.
    *   Why only Col 1?
    *   Maybe the metaphor implies specific seeds germinate? Or maybe the example output is specific to the seed type?
    *   Let's re-read the metaphor: "Each seed germinates... The stem height depends on the seed variety, with the flower's color appearing at the top."
    *   "Stems of uniform green rise... capped by the flower color."
    *   If the stem is green, why are there `B`s in the output?
    *   Maybe the `B` in the output represents the stem? But `B` is Blue. `G` is Green.
    *   Is it possible the prompt description is slightly misleading or I am misinterpreting the colors in the example?
    *   Let's look at the example output again.
        Row 0: `. A . . . .`
        Row 1: `. B . . . .`
        Row 2: `. B . . . .`
        Row 3: `B A B B B B`
    *   The seed at (3, 1) is `A`.
    *   Above it, we have `B`, `B`, `A` going up from the channel.
    *   Wait, Row 2 is `B`, Row 1 is `B`, Row 0 is `A`.
    *   So the stack is `A` (top), `B`, `B`, `A` (base).
    *   This doesn't match "Stems of uniform green".
    *   Is it possible the example output provided in the prompt text is actually different from what I'm reading?
    *   Let's check the text provided in the prompt carefully.
    *   Input:
        ```
        . . . . . .
        . . . . . .
        . . . . . .
        B A B B B B
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        ```
    *   Output:
        ```
        . A . . . .
        . B . . . .
        . B . . . .
        B A B B B B
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        . . . . . .
        ```
    *   Okay, looking at the pattern:
        *   Channel is at Row 3.
        *   Seed at Col 1 is `A`.
        *   Above it (Rows 2, 1, 0), we see `B`, `B`, `A`.
        *   Wait, Row 2 is `B`, Row 1 is `B`, Row 0 is `A`.
        *   This looks like the stem is made of `B` (Blue) and the flower is `A` (Azure).
        *   But the metaphor says "Stems of uniform green".
        *   Maybe the metaphor is a *description* of the logic, but the colors in the example are specific to the input colors?
        *   Or maybe "green" in the metaphor is a placeholder for "stem color", and in this specific exa

... [10043 chars truncated]

Task 454: 7953d61e

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Ex5 In
Ex5 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A compass rose unfurls from a single petal, each cardinal direction revealing a ... [27 chars truncated] MARC valid 1
alt-1 biology A cell undergoes mitotic division, but each daughter inherits the mother's memor ... [90 chars truncated] MARC valid 1
alt-10 astronomy A nebula's core image is captured by four telescopes orbiting at different angle ... [131 chars truncated] fail
alt-11 ocean/sailing A cartographer draws a single chart of an island and pins four copies to the nav ... [113 chars truncated] fail
alt-12 electronics A chip designer copies a single logic block into four quadrants of a die, rotati ... [123 chars truncated] fail
alt-13 mythology Janus looks not in two directions but four—each face gazes outward from th ... [100 chars truncated] fail
alt-14 dance Four couples learn the same choreography but start facing different walls of the ... [130 chars truncated] fail
alt-15 geology A crystal seed grows into four twinned domains—each domain preserves the a ... [147 chars truncated] MARC valid 3
alt-2 cooking A baker quarters her dough and lays each piece into the pan with a different twi ... [96 chars truncated] MARC valid 4
alt-3 music A quartet takes a single melodic phrase and each musician enters from a differen ... [146 chars truncated] fail
alt-4 sports A coach diagrams a play on a whiteboard, then tells each squad to run it facing ... [82 chars truncated] MARC valid 1
alt-5 weather A storm cell splits into four fronts, each sweeping outward from the eye in a di ... [98 chars truncated] fail
alt-6 architecture An architect takes a single ornamental tile and sets it at four rotations around ... [100 chars truncated] MARC valid 2
alt-7 warfare A general deploys the same battalion formation to hold four quadrants of a fortr ... [131 chars truncated] MARC valid 5
alt-8 theater A stage manager blocks the same scene four times on a revolving stage—each ... [158 chars truncated] MARC valid 1
alt-9 gardening A gardener takes a single planting grid and sows it into four raised beds, turni ... [106 chars truncated] fail
original qwen3.5-122b: k=1
"A compass rose unfurls from a single petal, each cardinal direction revealing a new face of the same bloom."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10986 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and a training example.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A small mosaic tile — a 4×4 swatch of stained glass". Wait, the description says "4x4 swatch". Let's check the training example input.
    *   Example 1 Input:
        Y W B A
        A Y B A
        Y A A B
        B B B A
        This is a 4x4 grid.
    *   Test Input:
        Y M Y Y
        Y M Y Y
        O M O W
        W Y W O
        This is also a 4x4 grid.
*   **Output:** "The cathedral floor is exactly four tiles wide and four tiles tall — a 2×2 arrangement of the original swatch and its three rotated echoes."
    *   Wait, the text says "cathedral floor is exactly four tiles wide and four tiles tall". This implies the output is 4x4?
    *   Let's check the Example 1 Output.
        Y W B A A A B A
        A Y B A B B A B
        Y A A B W Y A B
        B B B A Y A Y B
        A B B B B Y A Y
        B A A Y B A Y W
        A B Y A B A B B
        A B W Y A B A A
        This is an 8x8 grid.
    *   There is a contradiction in the metaphorical description text provided in the prompt versus the actual data.
    *   Text says: "cathedral floor is exactly four tiles wide and four tiles tall".
    *   Data says: Input is 4x4, Output is 8x8.
    *   Text says: "2x2 arrangement of the original swatch and its three rotated echoes".
    *   If the original swatch is 4x4, a 2x2 arrangement of them would be 8x8.
    *   So the text "four tiles wide and four tiles tall" likely refers to the *tiles* in the arrangement (meaning 2x2 tiles, where each tile is 4x4 pixels), or it's a slight error in the metaphor description provided in the prompt context. Given the training example clearly shows an 8x8 output from a 4x4 input, I must follow the pattern in the data.
    *   The pattern is: Input 4x4 -> Output 8x8.
    *   The output is composed of 4 quadrants (2x2 arrangement).
    *   The quadrants are transformations of the input grid.
    *   "The tile dreams of itself from every direction. It gazes north and sees its own face." -> Top-Left quadrant is likely the original.
    *   "It turns its head east, west, and south, and at each glance the reflection has spun — as if the tile were placed on a lazy Susan and photographed at each quarter-turn." -> The other three quadrants are rotations of the original.
    *   "These four portraits are pressed together... the original anchoring one corner while its dizzied twins fill the remaining three."
    *   Let's determine the specific rotations for each quadrant.
    *   Standard layout for 2x2 arrangement of rotations usually follows a specific order.
    *   Let's analyze Example 1 to deduce the rotation mapping.

**2. Analyze Example 1:**
Input (4x4):
Row 0: Y W B A
Row 1: A Y B A
Row 2: Y A A B
Row 3: B B B A

Output (8x8):
Row 0: Y W B A | A A B A
Row 1: A Y B A | B B A B
Row 2: Y A A B | W Y A B
Row 3: B B B A | Y A Y B
-------------------------
Row 4: A B B B | B Y A Y
Row 5: B A A Y | B A Y W
Row 6: A B Y A | B A B B
Row 7: A B W Y | A B A A

Let's break down the Output into 4 quadrants (Top-Left, Top-Right, Bottom-Left, Bottom-Right). Each is 4x4.

**Top-Left (TL):**
Y W B A
A Y B A
Y A A B
B B B A
This matches the Input exactly.
So, TL = Input (0 degrees rotation).

**Top-Right (TR):**
A A B A
B B A B
W Y A B
Y A Y B
Let's compare this to the Input.
Input:
Y W B A
A Y B A
Y A A B
B B B A

Let's try rotating the Input 90 degrees clockwise.
Input Col 0 (bottom to top) -> Row 0: B Y A Y
Input Col 1 (bottom to top) -> Row 1: B A Y W
Input Col 2 (bottom to top) -> Row 2: B A B B
Input Col 3 (bottom to top) -> Row 3: A A B A
This doesn't match TR.

Let's try rotating the Input 90 degrees counter-clockwise.
Input Col 3 (top to bottom) -> Row 0: A A B A
Input Col 2 (top to bottom) -> Row 1: B B A B
Input Col 1 (top to bottom) -> Row 2: W Y A B
Input Col 0 (top to bottom) -> Row 3: Y A Y B
Let's check TR again:
Row 0: A A B A (Matches)
Row 1: B B A B (Matches)
Row 2: W Y A B (Matches)
Row 3: Y A Y B (Matches)
So, TR = Input rotated 90 degrees Counter-Clockwise (or 270 degrees Clockwise).

**Bottom-Left (BL):**
A B B B
B A A Y
A B Y A
A B W Y
Let's compare to Input.
Input:
Y W B A
A Y B A
Y A A B
B B B A

Let's try rotating Input 180 degrees.
Input Row 3 reversed -> Row 0: A B B B
Input Row 2 reversed -> Row 1: B A A Y
Input Row 1 reversed -> Row 2: A B Y A
Input Row 0 reversed -> Row 3: A B W Y
Let's check BL again:
Row 0: A B B B (Matches)
Row 1: B A A Y (Matches)
Row 2: A B Y A (Matches)
Row 3: A B W Y (Matches)
So, BL = Input rotated 180 degrees.

**Bottom-Right (BR):**
B Y A Y
B A Y W
B A B B
A B A A
Let's compare to Input.
Let's try rotating Input 90 degrees Clockwise.
Input Col 0 (bottom to top) -> Row 0: B Y A Y
Input Col 1 (bottom to top) -> Row 1: B A Y W
Input Col 2 (bottom to top) -> Row 2: B A B B
I

... [6240 chars truncated]
alt-1 biology qwen3.5-122b: k=1
"A cell undergoes mitotic division, but each daughter inherits the mother's memory at a different angle of the spindle—four offspring, four orientations, one genome."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10676 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A small tissue sample of colored cells... replicate." -> Input is a small grid, output is a larger grid.
*   "The organism divides into four daughter colonies..." -> The output grid is composed of 4 copies of the input grid.
*   "...each carrying the same genetic pattern but rotated on its axis..." -> The 4 copies are rotated versions of the original input.
*   "...assembling into a larger organism exactly twice the width and twice the height." -> If input is $H \times W$, output is $2H \times 2W$.
*   "The original tissue sits in one corner. Three sibling colonies fill the remaining corners..." -> This suggests a specific arrangement of the 4 rotated copies. Usually, this implies a $2 \times 2$ block structure where each block is a transformed version of the input.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    Dimensions: $4 \times 4$.
*   **Output:**
    ```
    Y W B A A A B A
    A Y B A B B A B
    Y A A B W Y A B
    B B B A Y A Y B
    A B B B B Y A Y
    B A A Y B A Y W
    A B Y A B A B B
    A B W Y A B A A
    ```
    Dimensions: $8 \times 8$.
    This confirms the "twice width, twice height" rule. The output is composed of four $4 \times 4$ quadrants.

    Let's break down the output into four $4 \times 4$ quadrants:
    *   **Top-Left (TL):**
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        This is exactly the **Input**. So, TL = Input (0 degrees rotation).

    *   **Top-Right (TR):**
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        Let's compare this to the Input.
        Input:
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        Let's try rotating the Input 90 degrees clockwise.
        Row 1 becomes Col 4 (bottom to top? or top to bottom?).
        Standard 90 deg clockwise: $(r, c) \to (c, H-1-r)$.
        Input Row 0: `Y W B A` -> becomes Col 3 (last col) from top to bottom? No, usually Row 0 becomes Col Last.
        Let's visualize 90 deg clockwise rotation of Input:
        Original:
        Y W B A
        A Y B A
        Y A A B
        B B B A

        Rotated 90 CW:
        B Y A Y
        B A Y W
        B A A B
        A B A A
        (Wait, let's check indices)
        (0,0)=Y -> (0,3)
        (0,1)=W -> (1,3)
        (0,2)=B -> (2,3)
        (0,3)=A -> (3,3)
        (1,0)=A -> (0,2)
        ...
        Let's write it out properly.
        New Row 0: Old Col 0 (bottom to top) -> B, Y, A, Y.
        New Row 1: Old Col 1 (bottom to top) -> B, A, Y, W.
        New Row 2: Old Col 2 (bottom to top) -> B, A, A, B.
        New Row 3: Old Col 3 (bottom to top) -> A, B, A, A.
        So 90 CW is:
        B Y A Y
        B A Y W
        B A A B
        A B A A
        Does this match TR?
        TR is:
        A A B A
        B B A B
        W Y A B
        Y A Y B
        No match.

        Let's try 90 degrees Counter-Clockwise (CCW).
        New Row 0: Old Col 3 (top to bottom) -> A, A, B, A.
        New Row 1: Old Col 2 (top to bottom) -> B, B, A, B.
        New Row 2: Old Col 1 (top to bottom) -> W, Y, A, B.
        New Row 3: Old Col 0 (top to bottom) -> Y, A, Y, B.
        Let's check TR again:
        A A B A
        B B A B
        W Y A B
        Y A Y B
        **Match!**
        So, **TR = Input rotated 90 degrees Counter-Clockwise**.

    *   **Bottom-Left (BL):**
        ```
        A B B B
        B A A Y
        A B Y A
        A B W Y
        ```
        Let's compare to Input.
        Input:
        Y W B A
        A Y B A
        Y A A B
        B B B A

        Let's try 180 degrees rotation.
        180 is equivalent to flipping horizontally then vertically (or vice versa).
        Row 0 becomes Row 3 reversed.
        Row 0: Y W B A -> Rev: A B W Y. This should be Row 3 of 180 rot.
        Row 1: A Y B A -> Rev: A B Y A. This should be Row 2 of 180 rot.
        Row 2: Y A A B -> Rev: B A A Y. This should be Row 1 of 180 rot.
        Row 3: B B B A -> Rev: A B B B. This should be Row 0 of 180 rot.
        So 180 Rotated Input:
        A B B B
        B A A Y
        A B Y A
        A B W Y
        Does this match BL?
        BL is:
        A B B B
        B A A Y
        A B Y A
        A B W Y
        **Match!**
        So, **BL = Input rotated 180 degrees**.

    *   **Bottom-Right (BR):**
        ```
        B Y A Y
        B A Y W
        B A A B
        A B A A
        ```
        Let's compare to Input.
        We already calculated 90 CW earlier:
        B Y A Y
        B A Y W
        B A A B
        A B A A
        Does this match BR?
        BR is:
        B Y A Y
        B A Y W
        B A A B
        A B A A
       

... [5826 chars truncated]
alt-10 astronomy qwen3.5-122b: fail
"A nebula's core image is captured by four telescopes orbiting at different angles—each returns the same stellar nursery rotated by its orbital position, and the composite is stitched into one grand mosaic."
Fail (best cell_acc=0.94 at k=2)
Best Attempt
vs
Expected
Reasoning (9614 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A small square field (grid).
*   **Output:** A larger square field (mosaic).
*   **Dimensions:** The output is twice the dimensions of the input (2x2 tiling).
*   **Content:** The output consists of four tiles. Each tile is the same stellar field (the input grid) but rotated according to the telescope's orbital attitude.
*   **Key phrase:** "Each tile is the same stellar field at a different rotational angle."
*   **Implication:** The input grid is $N \times N$. The output grid is $2N \times 2N$. The output is composed of 4 quadrants. Each quadrant corresponds to a rotation of the input grid.
*   **Rotation Angles:** Usually, in these types of puzzles, the rotations are 0, 90, 180, 270 degrees. I need to determine the order and placement of these rotations in the 2x2 layout.

**2. Analyze the Training Examples:**

**Example 1:**
Input ($4 \times 4$):
```
Y W B A
A Y B A
Y A A B
B B B A
```
Output ($8 \times 8$):
```
Y W B A | A A B A
A Y B A | B B A B
Y A A B | W Y A B
B B B A | Y A Y B
-----------------
A B B B | B Y A Y
B A A Y | B A Y W
A B Y A | B A B B
A B W Y | A B A A
```

Let's break down the output into 4 quadrants ($4 \times 4$ each).
Top-Left (TL):
```
Y W B A
A Y B A
Y A A B
B B B A
```
This matches the Input exactly. So TL = Input (0 degrees rotation).

Top-Right (TR):
```
A A B A
B B A B
W Y A B
Y A Y B
```
Let's check rotations of the Input.
Input:
Y W B A
A Y B A
Y A A B
B B B A

Rotate 90 deg clockwise:
B Y A Y
B A Y W
B A A B
A B B A
(This doesn't match TR).

Rotate 90 deg counter-clockwise:
A B A A
B A A Y
B Y A B
A B W Y
(This doesn't match TR).

Rotate 180 deg:
A B B B
B A A Y
A B Y A
A B W Y
(This doesn't match TR).

Let's look at TR again:
A A B A
B B A B
W Y A B
Y A Y B

Let's look at the columns of the Input.
Col 4: A, A, B, A.
Row 1 of TR: A, A, B, A.
Col 3 of Input: B, B, A, B.
Row 2 of TR: B, B, A, B.
Col 2 of Input: W, Y, A, B.
Row 3 of TR: W, Y, A, B.
Col 1 of Input: Y, A, Y, B.
Row 4 of TR: Y, A, Y, B.

So TR is the Input rotated 90 degrees *counter-clockwise*?
Let's check 90 CCW rotation of Input:
Input:
Y W B A
A Y B A
Y A A B
B B B A

90 CCW:
Col 4 becomes Row 1: A A B A.
Col 3 becomes Row 2: B B A B.
Col 2 becomes Row 3: W Y A B.
Col 1 becomes Row 4: Y A Y B.
Matches TR exactly.
So TR = Input rotated 90 degrees Counter-Clockwise (or 270 degrees Clockwise).

Bottom-Left (BL):
```
A B B B
B A A Y
A B Y A
A B W Y
```
Let's check rotations.
Input:
Y W B A
A Y B A
Y A A B
B B B A

Rotate 180 degrees:
A B B B
B A A Y
A B Y A
A B W Y
Matches BL exactly.
So BL = Input rotated 180 degrees.

Bottom-Right (BR):
```
B Y A Y
B A Y W
B A B B
A B A A
```
Let's check rotations.
Input:
Y W B A
A Y B A
Y A A B
B B B A

Rotate 90 degrees Clockwise:
B Y A Y
B A Y W
B A A B
A B B A
Wait, let's look closer at BR.
Row 1: B Y A Y
Row 2: B A Y W
Row 3: B A B B
Row 4: A B A A

Let's check 90 CW rotation of Input:
Row 1 of 90 CW = Col 1 of Input (bottom to top) = B, Y, A, Y. Matches Row 1 of BR.
Row 2 of 90 CW = Col 2 of Input (bottom to top) = B, A, Y, W. Matches Row 2 of BR.
Row 3 of 90 CW = Col 3 of Input (bottom to top) = B, A, A, B. Matches Row 3 of BR.
Row 4 of 90 CW = Col 4 of Input (bottom to top) = A, B, B, A. Matches Row 4 of BR.
So BR = Input rotated 90 degrees Clockwise.

**Summary of Example 1 Layout:**
TL: 0 deg (Original)
TR: 90 deg CCW (270 deg CW)
BL: 180 deg
BR: 90 deg CW

Wait, let's re-verify the TR rotation.
Input:
Y W B A
A Y B A
Y A A B
B B B A

TR:
A A B A
B B A B
W Y A B
Y A Y B

If I rotate Input 90 CCW:
Top row becomes Left col (reversed? No).
Standard 90 CCW: $(x, y) \to (y, N-1-x)$.
Row 0: Y W B A -> Col 0 (bottom to top): Y, A, Y, B.
Row 1: A Y B A -> Col 1 (bottom to top): A, B, A, W.
Row 2: Y A A B -> Col 2 (bottom to top): B, A, A, B.
Row 3: B B B A -> Col 3 (bottom to top): A, B, B, A.
Result:
A B B A
B A A B
A B A W
Y A Y B
This does NOT match TR.

Let's re-examine TR.
TR:
A A B A
B B A B
W Y A B
Y A Y B

Input:
Y W B A
A Y B A
Y A A B
B B B A

Look at TR Row 1: A A B A. This is Input Col 4 (top to bottom).
Look at TR Row 2: B B A B. This is Input Col 3 (top to bottom).
Look at TR Row 3: W Y A B. This is Input Col 2 (top to bottom).
Look at TR Row 4: Y A Y B. This is Input Col 1 (top to bottom).

So TR is constructed by taking columns of Input from Right to Left and making them rows from Top to Bottom.
This is a **90 degree Counter-Clockwise rotation**.
Wait, let's visualize 90 CCW.
Original:
1 2
3 4
90 CCW:
2 4
1 3
Col 2 (2,4) becomes Row 1. Col 1 (1,3) becomes Row 2.
So yes, taking columns from Right to Left and making them rows Top to Bottom is 90 CCW.
Let's check my previous manual rotation calculation.
Input:
Y W B A
A Y B A
Y A A B
B B B A

Col 4: A, A, B, A. -> Row 1 of TR. Correct.
Col 3: B, B, A, B. -> Row 2 of TR. Correct.
Col 2: W, Y, A, B. -> Row 3 of TR. Corr

... [4662 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fail
"A cartographer draws a single chart of an island and pins four copies to the navigation table, each turned so a different coast faces north—together they map every approach to the harbor."
Fail (best cell_acc=0.06 at k=5)
Best Attempt
vs
Expected
Reasoning (9105 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A small square nautical chart (grid).
*   **Output:** A master chart (larger grid).
*   **Transformation:** "Assemble a master chart by placing four copies of the island map into a larger frame. Each copy is rotated so that a different shoreline points upward, giving navigators a view from every bearing."
*   **Grid details:** "The master chart is twice the width and height of the original, divided into four quadrants. Each quadrant holds the same island chart at a different rotation."

**2. Analyze the Training Examples:**

Let's look at Example 1:
Input (4x4):
Y W B A
A Y B A
Y A A B
B B B A

Output (8x8):
Y W B A A A B A
A Y B A B B A B
Y A A B W Y A B
B B B A Y A Y B
A B B B B Y A Y
B A A Y B A Y W
A B Y A B A B B
A B W Y A B A A

Let's break down the output into four 4x4 quadrants.
Top-Left (TL):
Y W B A
A Y B A
Y A A B
B B B A
This is exactly the Input. So, TL = Input (0 degrees rotation).

Top-Right (TR):
A A B A
B B A B
W Y A B
Y A Y B
Let's compare this to the Input.
Input:
Y W B A
A Y B A
Y A A B
B B B A

TR Row 1: A A B A. Input Col 4 (reversed?): A A B A.
TR Row 2: B B A B. Input Col 3 (reversed?): B A A B -> B A A B. No.
Let's check rotations.
Input rotated 90 degrees clockwise:
B Y A Y
B A Y W
B A A B
A B A A
Doesn't match TR.

Input rotated 90 degrees counter-clockwise:
A B A A
B A A Y
B Y A W
A B B B
Doesn't match TR.

Input rotated 180 degrees:
A B B B
B A A Y
A B Y A
A B W Y
Doesn't match TR.

Let's look at the structure again.
TL = Input.
Let's look at Bottom-Left (BL):
A B B B
B A A Y
A B Y A
A B W Y
This looks like the 180-degree rotation of the Input.
Input:
Y W B A
A Y B A
Y A A B
B B B A
180 Rot:
A B B B
B A A Y
A B Y A
A B W Y
Yes, BL is Input rotated 180 degrees.

Let's look at Bottom-Right (BR):
B Y A Y
B A Y W
B A A B
A B A A
This looks like the 90-degree clockwise rotation of the Input.
Input:
Y W B A
A Y B A
Y A A B
B B B A
90 CW:
B Y A Y
B A Y W
B A A B
A B A A
Yes, BR is Input rotated 90 degrees clockwise.

Now let's look at Top-Right (TR) again.
A A B A
B B A B
W Y A B
Y A Y B
This looks like the 90-degree counter-clockwise rotation of the Input.
Input:
Y W B A
A Y B A
Y A A B
B B B A
90 CCW:
A B A A
B A A Y
B Y A W
A B B B
Wait, TR is:
A A B A
B B A B
W Y A B
Y A Y B
Let's check 90 CCW again.
Col 4 becomes Row 1: A A B A.
Col 3 becomes Row 2: B A A B. (TR Row 2 is B B A B). Mismatch.
Col 2 becomes Row 3: W Y A B. (TR Row 3 is W Y A B). Match.
Col 1 becomes Row 4: Y A Y B. (TR Row 4 is Y A Y B). Match.

Let's re-examine TR Row 2.
Input Col 3 is B A A B.
TR Row 2 is B B A B.
Wait, let's look at the Input again.
Y W B A
A Y B A
Y A A B
B B B A

Let's check the quadrants again.
TL:
Y W B A
A Y B A
Y A A B
B B B A
(Input)

TR:
A A B A
B B A B
W Y A B
Y A Y B

BL:
A B B B
B A A Y
A B Y A
A B W Y
(Input 180)

BR:
B Y A Y
B A Y W
B A A B
A B A A
(Input 90 CW)

Let's check TR again.
Is it Input 90 CCW?
Input 90 CCW:
A B A A
B A A Y
B Y A W
A B B B
TR:
A A B A
B B A B
W Y A B
Y A Y B
This is NOT 90 CCW.

Let's check if TR is a reflection.
Input Transpose (Swap rows/cols):
Y A Y B
W Y A B
B B A B
A A B A
TR is:
A A B A
B B A B
W Y A B
Y A Y B
This is the Transpose flipped vertically (or Transpose rotated 180).
Transpose:
Y A Y B
W Y A B
B B A B
A A B A
Flip Vertically:
A A B A
B B A B
W Y A B
Y A Y B
This matches TR exactly.
So TR = Transpose(Input) flipped vertically.
Alternatively, Transpose(Input) flipped vertically is equivalent to rotating 90 degrees counter-clockwise?
Let's check 90 CCW again.
Input:
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
90 CCW:
4 8 12 16
3 7 11 15
2 6 10 14
1 5 9 13
Transpose:
1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16
Flip Vertically:
4 8 12 16
3 7 11 15
2 6 10 14
1 5 9 13
Yes, Transpose + Flip Vertical = 90 CCW.
Wait, why did my manual check of 90 CCW fail earlier?
Input:
Y W B A
A Y B A
Y A A B
B B B A
90 CCW:
Row 1 = Col 4 (top to bottom) -> A A B A.
Row 2 = Col 3 (top to bottom) -> B A A B.
Row 3 = Col 2 (top to bottom) -> W Y A B.
Row 4 = Col 1 (top to bottom) -> Y A Y B.
So 90 CCW should be:
A A B A
B A A B
W Y A B
Y A Y B
TR is:
A A B A
B B A B
W Y A B
Y A Y B
Difference is in Row 2.
90 CCW Row 2: B A A B.
TR Row 2: B B A B.
Input Col 3 is B A A B.
Wait, Input Col 3 is:
Row 1: B
Row 2: B
Row 3: A
Row 4: B
Ah, I misread the Input grid in my manual trace.
Input:
Y W B A
A Y B A
Y A A B
B B B A
Col 3 is: B, B, A, B.
So 90 CCW Row 2 is B B A B.
This matches TR Row 2.
So TR IS Input rotated 90 degrees Counter-Clockwise.

Let's re-verify the quadrants for Example 1.
TL: Input (0 deg)
TR: Input (90 deg CCW)
BL: Input (180 deg)
BR: Input (90 deg CW)

Wait, usually "four copies... different rotation... every bearing" implies 0, 90, 180, 270.
Order in grid:
TL TR
BL BR
If TL=0, TR=90 CCW (270 CW), BL=180, BR=90 CW.
Let's check the order.
TL: 0 deg.
TR: 270 deg (90 CCW).
BL: 180 

... [4183 chars truncated]
alt-12 electronics qwen3.5-122b: fail
"A chip designer copies a single logic block into four quadrants of a die, rotating each copy so the pin-outs face outward in every direction—same circuit, four orientations, one integrated package."
Fail (best cell_acc=0.97 at k=1)
Best Attempt
vs
Expected
Reasoning (9756 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A small square silicon block (grid).
*   **Output:** A larger die (grid) made of four copies of the input block.
*   **Layout:** 2x2 layout of the copies.
*   **Transformation:** Each copy is rotated so its interface pins face a different edge. This implies rotations of 0, 90, 180, and 270 degrees.
*   **Dimensions:** The output is twice the dimensions of the input. If input is $N \times N$, output is $2N \times 2N$.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    Size: 4x4.
*   **Output:**
    ```
    Y W B A A A B A
    A Y B A B B A B
    Y A A B W Y A B
    B B B A Y A Y B
    A B B B B Y A Y
    B A A Y B A Y W
    A B Y A B A B B
    A B W Y A B A A
    ```
    Size: 8x8.

Let's break down the output into four 4x4 quadrants to see the rotation pattern.
Top-Left (TL):
```
Y W B A
A Y B A
Y A A B
B B B A
```
This matches the Input exactly. So, TL is Input rotated 0 degrees.

Top-Right (TR):
```
A A B A
B B A B
W Y A B
Y A Y B
```
Let's check the Input rotated 90 degrees clockwise.
Input:
Y W B A
A Y B A
Y A A B
B B B A

Rotate 90 CW:
Row 1 becomes Col 4 (bottom to top? No, standard matrix rotation).
(0,0)->(0,3), (0,1)->(1,3), (0,2)->(2,3), (0,3)->(3,3)
Let's visualize:
Original:
Y W B A
A Y B A
Y A A B
B B B A

90 CW:
B Y A Y
B A Y W
B B A B
A A B A
Wait, let's look at the TR quadrant again.
TR:
A A B A
B B A B
W Y A B
Y A Y B

Let's check 90 degrees Counter-Clockwise (CCW).
Original:
Y W B A
A Y B A
Y A A B
B B B A

90 CCW:
A B A A
B B A B
A Y A W
Y A Y B
This doesn't match TR exactly.

Let's check 180 degrees.
180:
A B B B
B A A Y
A B Y A
A B W Y
Doesn't match TR.

Let's check 270 degrees (or 90 CW).
270 CW (90 CCW):
A B A A
B B A B
A Y A W
Y A Y B
Wait, looking at TR again:
Row 1: A A B A
Row 2: B B A B
Row 3: W Y A B
Row 4: Y A Y B

Let's look at the Input columns.
Col 4: A A B A. This matches TR Row 1.
Col 3: B B A B. This matches TR Row 2.
Col 2: W Y A B. This matches TR Row 3.
Col 1: Y A Y B. This matches TR Row 4.

So TR is the Input rotated 90 degrees **Counter-Clockwise** (or 270 degrees Clockwise).
Let's verify:
Input:
Y W B A
A Y B A
Y A A B
B B B A

Rotate 90 CCW:
Top row becomes Left column (reversed? No).
Top row (Y W B A) becomes Left column (A B W Y) reading bottom to top?
Let's do standard rotation logic.
New(i, j) = Old(j, N-1-i) for 90 CW.
New(i, j) = Old(N-1-j, i) for 90 CCW.

Let's check TR Row 1: A A B A.
This corresponds to Input Column 4 (A A B A).
TR Row 2: B B A B.
This corresponds to Input Column 3 (B B A B).
TR Row 3: W Y A B.
This corresponds to Input Column 2 (W Y A B).
TR Row 4: Y A Y B.
This corresponds to Input Column 1 (Y A Y B).

So TR is Input rotated 90 degrees **Counter-Clockwise**.
Wait, usually "interface pins face a different edge" implies a sequence.
TL: 0 deg.
TR: 90 deg?
BL: 180 deg?
BR: 270 deg?

Let's check Bottom-Left (BL).
BL:
A B B B
B A A Y
A B Y A
A B W Y

Let's check Input rotated 180 degrees.
Input:
Y W B A
A Y B A
Y A A B
B B B A

180 Rotation:
A B B B
B A A Y
A B Y A
A B W Y
This matches BL exactly. So BL is Input rotated 180 degrees.

Let's check Bottom-Right (BR).
BR:
B Y A Y
B A Y W
B B A B
A A B A

Let's check Input rotated 90 degrees Clockwise.
Input:
Y W B A
A Y B A
Y A A B
B B B A

90 CW:
B Y A Y
B A Y W
B B A B
A A B A
This matches BR exactly. So BR is Input rotated 90 degrees Clockwise.

**Summary of Quadrants:**
TL: 0 degrees (Original)
TR: 270 degrees (90 CCW)
BL: 180 degrees
BR: 90 degrees (90 CW)

Wait, let's re-read the metaphor. "Each copy is rotated so its interface pins face a different edge of the package."
Usually, this implies a specific order.
Top-Left: Top edge faces Top? (0 deg)
Top-Right: Top edge faces Right? (90 CW)
Bottom-Left: Top edge faces Left? (90 CCW / 270 CW)
Bottom-Right: Top edge faces Bottom? (180 deg)

Let's check the example again.
TL: 0 deg.
TR: 270 deg (90 CCW).
BL: 180 deg.
BR: 90 deg (90 CW).

This order (0, 270, 180, 90) seems a bit odd if we think of standard reading order (TL, TR, BL, BR).
Let's check the "interface pins" idea.
If the input has a specific "top", rotating it 90 CW makes the top face Right.
Rotating 180 makes top face Bottom.
Rotating 270 CW (90 CCW) makes top face Left.

In the example:
TL (0): Top faces Top.
TR (270): Top faces Left.
BL (180): Top faces Bottom.
BR (90): Top faces Right.

This arrangement puts the "Top" edges facing: Top, Left, Bottom, Right.
This is a counter-clockwise spiral of orientations?
TL: Top
TR: Left
BL: Bottom
BR: Right

Let's look at the Test Input to see if there's a pattern I missed or if I should just apply the specific rotation mapping found in the example.
The prompt says "Four identical circuit copies, each at a successive quarter-turn, tile the silicon perfectly."
"Successive quarter-turn" usual

... [4810 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"Janus looks not in two directions but four—each face gazes outward from the crossroads, and behind every visage lies the same divine countenance, merely turned upon its axis."
Fail (best cell_acc=0.25 at k=1)
Best Attempt
vs
Expected
Reasoning (11015 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A small square mosaic depicting a divine face in colored tesserae." -> This implies the input is a square grid of colored cells.
*   **Action:** "Erect a four-sided shrine at the crossroads. Each face of the shrine bears the same mosaic portrait, but rotated so the god appears to gaze down each of the four roads." -> This suggests the output is composed of four copies of the input image, arranged in a specific way.
*   **Grid details:** "The shrine's unfolded plan is twice the original mosaic in each dimension—four panels in a 2×2 arrangement, each a rotated copy of the sacred image." -> The output grid dimensions are $2N \times 2N$ where $N \times N$ is the input grid dimensions. The output consists of 4 quadrants. Each quadrant is a rotated version of the input.
*   **Rotation:** "rotated so the god appears to gaze down each of the four roads." Usually, in these types of puzzles (ARC-like), "four roads" implies North, South, East, West. If the original image faces "Up" (North), the other three should face East, South, and West.
    *   Top-Left (North-West quadrant): Original orientation? Or maybe the shrine faces outwards?
    *   Let's look at the training example to deduce the specific rotation pattern.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    Size: $4 \times 4$.
*   **Output:**
    ```
    Y W B A | A A B A
    A Y B A | B B A B
    ---------+---------
    Y A A B | W Y A B
    B B B A | Y A Y B
    ---------+---------
    A B B B | B Y A Y
    B A A Y | B A Y W
    ---------+---------
    A B Y A | B A B B
    A B W Y | A B A A
    ```
    Size: $8 \times 8$.
    This confirms the $2N \times 2N$ structure.
    Let's break down the output into four $4 \times 4$ quadrants.
    *   **Top-Left (TL):**
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        This is exactly the **Input**.
    *   **Top-Right (TR):**
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        Let's compare this to the Input.
        Input Row 0: Y W B A -> TR Col 3 (bottom to top)? No.
        Input Row 0: Y W B A -> TR Row 0: A A B A.
        Input Row 1: A Y B A -> TR Row 1: B B A B.
        Input Row 2: Y A A B -> TR Row 2: W Y A B.
        Input Row 3: B B B A -> TR Row 3: Y A Y B.
        Let's check rotations.
        Input rotated 90 deg clockwise:
        Row 0 becomes Col 3 (bottom to top).
        Row 0: Y W B A -> Col 3: Y, W, B, A (top to bottom).
        Let's check TR Col 3: A, B, B, B. No.
        Let's check TR Col 0: A, B, W, Y.
        Input Row 0 reversed: A B W Y. Matches TR Col 0? No, TR Col 0 is A, B, W, Y.
        Wait, TR Col 0 is A, B, W, Y.
        Input Row 0 is Y W B A. Reversed is A B W Y.
        So TR Col 0 is Input Row 0 reversed.
        Input Row 1 is A Y B A. Reversed is A B Y A.
        TR Col 1 is A, B, Y, A. Matches.
        Input Row 2 is Y A A B. Reversed is B A A Y.
        TR Col 2 is B, A, A, Y. Matches.
        Input Row 3 is B B B A. Reversed is A B B B.
        TR Col 3 is A, B, B, B. Matches.
        So TR is the Input rotated 90 degrees **Counter-Clockwise**?
        Let's visualize 90 CCW rotation.
        (0,0) -> (3,0). (0,1) -> (2,0). (0,2) -> (1,0). (0,3) -> (0,0).
        Input (0,0)=Y. TR (3,0)=Y.
        Input (0,1)=W. TR (2,0)=W.
        Input (0,2)=B. TR (1,0)=B.
        Input (0,3)=A. TR (0,0)=A.
        Let's check TR Row 0: A A B A.
        TR (0,0)=A. TR (0,1)=A. TR (0,2)=B. TR (0,3)=A.
        Input Col 3 is A, A, B, A.
        So TR Row 0 is Input Col 3.
        TR Row 1 is Input Col 2.
        TR Row 2 is Input Col 1.
        TR Row 3 is Input Col 0.
        This corresponds to a **90 degree Counter-Clockwise rotation**.
        Wait, let's re-verify.
        Input:
        Y W B A
        A Y B A
        Y A A B
        B B B A
        90 CCW:
        A A B A (Col 3 read top-down)
        B B A B (Col 2 read top-down)
        W Y A B (Col 1 read top-down)
        Y A Y B (Col 0 read top-down)
        Let's check the TR quadrant in the example output:
        A A B A
        B B A B
        W Y A B
        Y A Y B
        Yes, TR is Input rotated 90 degrees Counter-Clockwise.

    *   **Bottom-Left (BL):**
        ```
        A B B B
        B A A Y
        A B Y A
        A B W Y
        ```
        Let's compare to Input.
        Input Row 3: B B B A. BL Row 0: A B B B. (Reversed)
        Input Row 2: Y A A B. BL Row 1: B A A Y. (Reversed)
        Input Row 1: A Y B A. BL Row 2: A B Y A. (Reversed)
        Input Row 0: Y W B A. BL Row 3: A B W Y. (Reversed)
        So BL is Input rotated 180 degrees.
        Let's check 180 rotation.
        (0,0) -> (3,3). Y -> Y.
        (0,1)

... [6188 chars truncated]
alt-14 dance qwen3.5-122b: fail
"Four couples learn the same choreography but start facing different walls of the ballroom—when the music plays, the identical routine unfolds in four orientations simultaneously, filling the entire floor."
Fail (best cell_acc=0.09 at k=1)
Best Attempt
vs
Expected
Reasoning (11964 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A small square dance floor with colored position markers for a single couple's routine." This implies the input is a small grid (likely 4x4 based on the examples).
*   **Output:** "Expand the ballroom to twice the size and station four couples in its quadrants." This implies the output grid dimensions are double the input dimensions. If input is $N \times N$, output is $2N \times 2N$.
*   **Transformation:** "Each couple performs the identical choreography but begins facing a different wall, so their colored traces rotate relative to one another." This suggests the input pattern is replicated four times in the four quadrants of the output grid, but each quadrant is rotated.
*   **Grid details:** "The full ballroom floor is a 2×2 grid of dance squares. Each square holds the same pattern of colored positions, rotated by a quarter-turn from its neighbor."
    *   This confirms the $2 \times 2$ block structure.
    *   Top-Left (TL), Top-Right (TR), Bottom-Left (BL), Bottom-Right (BR).
    *   "Rotated by a quarter-turn from its neighbor". Usually, this implies a specific rotation sequence. Let's look at the training example to deduce the specific rotations.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    Dimensions: $4 \times 4$.
*   **Output:**
    ```
    Y W B A A A B A
    A Y B A B B A B
    Y A A B W Y A B
    B B B A Y A Y B
    A B B B B Y A Y
    B A A Y B A Y W
    A B Y A B A B B
    A B W Y A B A A
    ```
    Dimensions: $8 \times 8$.
    This confirms the "twice the size" rule ($4 \times 4 \to 8 \times 8$).

*   **Quadrant Analysis:**
    Let's break the $8 \times 8$ output into four $4 \times 4$ quadrants.
    *   **Top-Left (TL) Quadrant (Rows 0-3, Cols 0-3):**
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        This is exactly the Input grid. So, TL = Input (0 degrees rotation).

    *   **Top-Right (TR) Quadrant (Rows 0-3, Cols 4-7):**
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        Let's compare this to the Input.
        Input:
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        Let's try rotating the Input 90 degrees clockwise.
        Row 0 becomes Col 3 (last col).
        Row 1 becomes Col 2.
        Row 2 becomes Col 1.
        Row 3 becomes Col 0.
        Rotated 90 CW:
        ```
        B Y A Y
        B A Y W
        B A A B
        A B A A
        ```
        This doesn't match TR.

        Let's try rotating 90 degrees counter-clockwise.
        Row 0 becomes Col 0.
        Row 1 becomes Col 1.
        Row 2 becomes Col 2.
        Row 3 becomes Col 3.
        Rotated 90 CCW:
        ```
        A B A A
        B A A B
        B A Y W
        A Y A Y
        ```
        This doesn't match TR either.

        Let's look at the TR quadrant again:
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        Let's look at the Input again:
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        Is it a reflection?
        Horizontal flip of Input:
        ```
        A B W Y
        A B Y A
        B A A Y
        A B B B
        ```
        No.
        Vertical flip of Input:
        ```
        B B B A
        Y A A B
        A Y B A
        Y W B A
        ```
        No.

        Let's look at the relationship between TL and TR.
        TL:
        Y W B A
        A Y B A
        Y A A B
        B B B A

        TR:
        A A B A
        B B A B
        W Y A B
        Y A Y B

        Let's check the corners.
        TL Top-Left: Y. TR Top-Left: A.
        TL Top-Right: A. TR Top-Right: A.
        TL Bottom-Left: B. TR Bottom-Left: Y.
        TL Bottom-Right: A. TR Bottom-Right: B.

        Let's check the rotation hypothesis again. Maybe the "neighbor" relationship implies a specific order.
        Usually, in these puzzles, the quadrants are:
        TL: Original
        TR: Rotated 90 deg CW?
        BL: Rotated 90 deg CCW?
        BR: Rotated 180 deg?
        Or some other pattern.

        Let's re-examine TR.
        Input Row 0: Y W B A
        TR Col 3 (last col): A B B B (from bottom to top? No, A B B B is Input Col 3).
        Wait, look at TR Col 3: A, B, B, B.
        Input Col 3 is A, A, B, A.
        Input Col 0 is Y, A, Y, B.

        Let's look at TR Row 0: A A B A.
        Input Col 3 is A, A, B, A.
        So TR Row 0 = Input Col 3.
        TR Row 1: B B A B.
        Input Col 2 is B, B, A, B.
        So TR Row 1 = Input Col 2.
        TR Row 2: W Y A B.
        Input Col 1 is W, Y, A, B.
        So TR Row 2 = Input Col 1.
        TR Row 3: Y A Y B.
        Input Col 0 is Y, A, Y, B.
        So TR Row 3 =

... [7055 chars truncated]
alt-15 geology qwen3.5-122b: k=3
"A crystal seed grows into four twinned domains—each domain preserves the atomic lattice of the original nucleus but is rotated at the twin boundary, so the mineral displays the same internal order from every cleaved face."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (9991 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A small square cross-section of a crystal lattice (unit cell).
*   **Output:** A twinned crystal cross-section, twice the dimensions of the seed lattice.
*   **Structure:** A 2x2 block of domains.
*   **Transformation:** Each domain is a rotated copy of the original unit cell.
*   **Key phrase:** "joined seamlessly at their twin planes". This implies the rotation isn't just arbitrary; it's likely related to the position in the 2x2 grid.
*   **Dimensions:** If input is $N \times N$, output is $2N \times 2N$.

**2. Analyze the Training Examples:**

**Example 1:**
Input ($4 \times 4$):
Y W B A
A Y B A
Y A A B
B B B A

Output ($8 \times 8$):
Y W B A | A A B A
A Y B A | B B A B
Y A A B | W Y A B
B B B A | Y A Y B
-----------------
A B B B | B Y A Y
B A A Y | B A Y W
A B Y A | B A B B
A B W Y | A B A A

Let's break down the output into four $4 \times 4$ quadrants.
Top-Left (TL):
Y W B A
A Y B A
Y A A B
B B B A
This is exactly the Input. So, TL = Input (Rotation 0).

Top-Right (TR):
A A B A
B B A B
W Y A B
Y A Y B
Let's compare this to the Input.
Input:
Y W B A
A Y B A
Y A A B
B B B A

TR Row 1: A A B A. Input Row 1: Y W B A. No obvious match.
TR Row 1: A A B A. Input Col 4: A A B A.
TR Row 2: B B A B. Input Col 3: B B A B.
TR Row 3: W Y A B. Input Col 2: W Y A A. Wait, Input Col 2 is W Y A B.
TR Row 4: Y A Y B. Input Col 1: Y A Y B.

So TR is the Input rotated 90 degrees clockwise?
Let's check 90 deg clockwise rotation of Input:
Row 1 becomes Col 4 (bottom to top? or top to bottom?).
Standard 90 deg clockwise:
(0,0) -> (0,3)
(0,1) -> (1,3)
(0,2) -> (2,3)
(0,3) -> (3,3)
Let's visualize:
Input:
Y W B A
A Y B A
Y A A B
B B B A

Rotated 90 CW:
B Y A Y
B A Y W
B B A B
A B A A
This does not match TR.

Let's check 90 deg Counter-Clockwise (CCW):
A B A A
B A Y W
B B A B
Y A Y B
This does not match TR.

Let's check 180 deg:
A B B B
B A A Y
A B Y A
A B W Y
This matches the Bottom-Left (BL) quadrant!
BL:
A B B B
B A A Y
A B Y A
A B W Y
Yes, BL is Input rotated 180 degrees.

Let's check Bottom-Right (BR):
B Y A Y
B A Y W
B A B B
A B A A
This matches the 90 deg CW rotation I calculated earlier.
Let's re-verify 90 CW.
Input:
Y W B A
A Y B A
Y A A B
B B B A

90 CW:
Col 1 (bottom-up) -> Row 1: B Y A Y. Matches BR Row 1.
Col 2 (bottom-up) -> Row 2: B A Y W. Matches BR Row 2.
Col 3 (bottom-up) -> Row 3: B B A B. Matches BR Row 3.
Col 4 (bottom-up) -> Row 4: A B A A. Matches BR Row 4.
So BR is Input rotated 90 degrees Clockwise.

Let's re-examine TR.
TR:
A A B A
B B A B
W Y A B
Y A Y B
This looks like Input rotated 90 degrees Counter-Clockwise?
Let's check 90 CCW again.
Col 4 (top-down) -> Row 1: A A B A. Matches TR Row 1.
Col 3 (top-down) -> Row 2: B B A B. Matches TR Row 2.
Col 2 (top-down) -> Row 3: W Y A B. Matches TR Row 3.
Col 1 (top-down) -> Row 4: Y A Y B. Matches TR Row 4.
Yes, TR is Input rotated 90 degrees Counter-Clockwise.

So the pattern for Example 1 is:
TL: 0 degrees (Original)
TR: 90 degrees CCW
BL: 180 degrees
BR: 90 degrees CW

Wait, let's look at the "twinning" metaphor.
Usually, twinning involves reflection or specific rotations.
Let's check the arrangement:
TL (0) | TR (90 CCW)
-------|-------
BL (180)| BR (90 CW)

Is there a simpler relationship?
TR is Transpose?
Input:
Y W B A
A Y B A
Y A A B
B B B A
Transpose:
Y A Y B
W Y A B
B B A B
A A B A
This is TR flipped vertically? Or TR rotated?
TR:
A A B A
B B A B
W Y A B
Y A Y B
Transpose Row 1: Y A Y B. TR Row 4: Y A Y B.
Transpose Row 2: W Y A B. TR Row 3: W Y A B.
Transpose Row 3: B B A B. TR Row 2: B B A B.
Transpose Row 4: A A B A. TR Row 1: A A B A.
So TR is the Transpose of the Input, flipped vertically (or rotated 90 CCW).
Actually, 90 CCW is equivalent to Transpose then Flip Vertical (or Flip Horizontal then Transpose).
Let's stick with rotations.
TL: 0
TR: 90 CCW
BL: 180
BR: 90 CW

Let's check Example 2 to confirm.
Input ($4 \times 4$):
M R M R
M M X X
B B B R
X B R B

Output ($8 \times 8$):
TL:
M R M R
M M X X
B B B R
X B R B
(Matches Input)

TR:
R X R B
M X B R
R M B B
M M B X
Let's check 90 CCW of Input.
Input Col 4 (top-down): R X R B. Matches TR Row 1.
Input Col 3 (top-down): M X B R. Matches TR Row 2.
Input Col 2 (top-down): R M B B. Matches TR Row 3.
Input Col 1 (top-down): M M B X. Matches TR Row 4.
Yes, TR is 90 CCW.

BL:
B R B X
R B B B
X X M M
R M R M
Let's check 180 of Input.
Input Row 4 reversed: B R B X. Matches BL Row 1.
Input Row 3 reversed: R B B B. Matches BL Row 2.
Input Row 2 reversed: X X M M. Matches BL Row 3.
Input Row 1 reversed: R M R M. Matches BL Row 4.
Yes, BL is 180.

BR:
X B M M
B B M R
R B X M
B R X R
Let's check 90 CW of Input.
Input Col 1 (bottom-up): X B M M. Matches BR Row 1.
Input Col 2 (bottom-up): B B M R. Matches BR Row 2.
Input Col 3 (bottom-up): R B X M. Matches BR Row 3.
Input Col 4 (bottom-up): B R X R. 

... [5117 chars truncated]
alt-2 cooking qwen3.5-122b: k=4
"A baker quarters her dough and lays each piece into the pan with a different twist of the wrist, so the same marbling appears from four different angles on the finished pastry."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (9401 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A small square of marbled dough". This implies the input is a square grid.
*   **Output:** "The baking sheet is twice as wide and twice as tall as the original dough square." This implies the output grid dimensions are $2N \times 2N$ if the input is $N \times N$.
*   **Process:** "Place the original dough in one corner... Cut three identical copies and rotate each by a different quarter-turn before pressing them into the remaining corners".
*   **Result:** "Four portions tile it perfectly... one seamless sheet."
*   **Interpretation:** The output grid is composed of four quadrants. Each quadrant is a copy of the input grid, but rotated.
    *   Top-Left (TL): Original orientation (0 degrees).
    *   Top-Right (TR): Rotated 90 degrees? Or -90?
    *   Bottom-Left (BL): Rotated 180 degrees?
    *   Bottom-Right (BR): Rotated 270 degrees?
    *   The description says "rotate each by a different quarter-turn". This usually implies 0, 90, 180, 270 degrees.
    *   Let's check the examples to determine the specific rotation order for each quadrant.

**2. Analyze the Training Examples:**

**Example 1:**
Input ($4 \times 4$):
Y W B A
A Y B A
Y A A B
B B B A

Output ($8 \times 8$):
Y W B A | A A B A
A Y B A | B B A B
Y A A B | W Y A B
B B B A | Y A Y B
-----------------
A B B B | B Y A Y
B A A Y | B A Y W
A B Y A | B A B B
A B W Y | A B A A

Let's break down the quadrants.
Input Grid $I$:
Row 0: Y W B A
Row 1: A Y B A
Row 2: Y A A B
Row 3: B B B A

Quadrant 1 (Top-Left, $4 \times 4$):
Y W B A
A Y B A
Y A A B
B B B A
This matches Input $I$ exactly. So TL = $I$ (0 deg rotation).

Quadrant 2 (Top-Right, $4 \times 4$):
A A B A
B B A B
W Y A B
Y A Y B
Let's see if this is a rotation of $I$.
If we rotate $I$ 90 degrees clockwise:
Col 0 becomes Row 0 (reversed): B Y A Y -> No.
Col 0 becomes Row 0 (normal): B Y A Y -> No.
Let's try 90 degrees counter-clockwise (or 270 clockwise).
Col 3 (A A B A) becomes Row 0.
Col 2 (B B A B) becomes Row 1.
Col 1 (W Y A B) becomes Row 2.
Col 0 (Y A Y B) becomes Row 3.
Let's check the TR quadrant:
Row 0: A A B A (Matches Col 3 of I)
Row 1: B B A B (Matches Col 2 of I)
Row 2: W Y A B (Matches Col 1 of I)
Row 3: Y A Y B (Matches Col 0 of I)
So TR is $I$ rotated 90 degrees Counter-Clockwise (or 270 degrees Clockwise).

Quadrant 3 (Bottom-Left, $4 \times 4$):
A B B B
B A A Y
A B Y A
A B W Y
Let's check rotations.
180 degrees rotation of $I$:
Row 3 reversed: A B B B (Matches Row 0 of BL)
Row 2 reversed: B A A Y (Matches Row 1 of BL)
Row 1 reversed: A B Y A (Matches Row 2 of BL)
Row 0 reversed: A B W Y (Matches Row 3 of BL)
So BL is $I$ rotated 180 degrees.

Quadrant 4 (Bottom-Right, $4 \times 4$):
B Y A Y
B A Y W
B A B B
A B A A
Let's check rotations.
90 degrees clockwise rotation of $I$:
Col 0 (Y A Y B) becomes Row 0 (reversed? No, usually Col 0 bottom-up becomes Row 0).
Let's visualize 90 deg clockwise:
Row 0 becomes Col 3.
Row 1 becomes Col 2.
Row 2 becomes Col 1.
Row 3 becomes Col 0.
So Row 0 of rotated grid is Col 0 of original read bottom-to-top.
Col 0 of I: Y, A, Y, B. Bottom-to-top: B, Y, A, Y.
Matches Row 0 of BR: B Y A Y.
Row 1 of rotated grid is Col 1 of original read bottom-to-top.
Col 1 of I: W, Y, A, B. Bottom-to-top: B, A, Y, W.
Matches Row 1 of BR: B A Y W.
Row 2 of rotated grid is Col 2 of original read bottom-to-top.
Col 2 of I: B, B, A, B. Bottom-to-top: B, A, B, B.
Matches Row 2 of BR: B A B B.
Row 3 of rotated grid is Col 3 of original read bottom-to-top.
Col 3 of I: A, A, B, A. Bottom-to-top: A, B, A, A.
Matches Row 3 of BR: A B A A.
So BR is $I$ rotated 90 degrees Clockwise.

**Summary of Example 1:**
TL: 0 deg
TR: 270 deg (90 CCW)
BL: 180 deg
BR: 90 deg (CW)

Let's check Example 2 to confirm.

**Example 2:**
Input ($4 \times 4$):
M R M R
M M X X
B B B R
X B R B

Output ($8 \times 8$):
TL:
M R M R
M M X X
B B B R
X B R B
(Matches Input)

TR:
R X R B
M X B R
R M B B
M M B X
Let's check 270 deg (90 CCW).
Col 3 (R X R B) -> Row 0. Matches.
Col 2 (M X B R) -> Row 1. Matches.
Col 1 (R M B B) -> Row 2. Matches.
Col 0 (M M B X) -> Row 3. Matches.
So TR is 270 deg.

BL:
B R B X
R B B B
X X M M
R M R M
Let's check 180 deg.
Row 3 reversed (X B R B -> B R B X). Matches Row 0.
Row 2 reversed (B B B R -> R B B B). Matches Row 1.
Row 1 reversed (M M X X -> X X M M). Matches Row 2.
Row 0 reversed (M R M R -> R M R M). Matches Row 3.
So BL is 180 deg.

BR:
X B M M
B B M R
R B X M
B R X R
Let's check 90 deg (CW).
Col 0 (M M B X) -> Row 0 (X B M M). Matches.
Col 1 (R M B B) -> Row 1 (B B M R). Matches.
Col 2 (M X B R) -> Row 2 (R B X M). Matches.
Col 3 (R X R B) -> Row 3 (B R X R). Matches.
So BR is 90 deg.

**Conclusion on Transformation Rule:**
Given an input grid $I$ of size $N \times N$.
The output grid $O$ is of size $2N \times 2N$.
$O$ is composed of four $N \times N$ q

... [4635 chars truncated]
alt-3 music qwen3.5-122b: fail
"A quartet takes a single melodic phrase and each musician enters from a different inversion—the theme heard right-side-up, upside-down, backwards, and in retrograde inversion—filling the concert hall with symmetry."
Fail (best cell_acc=0.25 at k=1)
Best Attempt
vs
Expected
Reasoning (11525 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A "short musical phrase" (a small grid).
*   **Output:** A "larger score" (a larger grid).
*   **Structure:** The output is a 2x2 arrangement of the original phrase's block.
*   **Transformation:**
    *   Top-Left: Original reading.
    *   Top-Right: Transformed version (rotated).
    *   Bottom-Left: Transformed version (rotated).
    *   Bottom-Right: Transformed version (rotated).
*   **Specifics:** "each quadrant a different rotational reading".
*   **Size:** The full score is twice the size in each dimension. If input is $N \times M$, output is $2N \times 2M$.
*   **Rotation:** The description says "rotated as if the sheet music were physically turned". Usually, this implies 90-degree increments.
    *   Quadrant 1 (Top-Left): 0 degrees (Original).
    *   Quadrant 2 (Top-Right): 90 degrees clockwise? Or counter-clockwise?
    *   Quadrant 3 (Bottom-Left): 180 degrees?
    *   Quadrant 4 (Bottom-Right): 270 degrees?
    *   Let's check the training example to deduce the specific rotation order.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    Size: 4 rows, 4 columns.
*   **Output:**
    ```
    Y W B A A A B A
    A Y B A B B A B
    Y A A B W Y A B
    B B B A Y A Y B
    A B B B B Y A Y
    B A A Y B A Y W
    A B Y A B A B B
    A B W Y A B A A
    ```
    Size: 8 rows, 8 columns.
    This confirms the $2N \times 2M$ structure.

*   **Let's break down the Output into 4 quadrants (4x4 each):**
    *   **Top-Left (TL):**
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        This matches the Input exactly. So TL = Input (0° rotation).

    *   **Top-Right (TR):**
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        Let's compare this to the Input.
        Input:
        Row 0: Y W B A
        Row 1: A Y B A
        Row 2: Y A A B
        Row 3: B B B A

        TR Row 0: A A B A. This looks like Input Column 3 (reversed? or just column 3?).
        Input Col 3: A, A, B, A.
        TR Row 0 is A A B A.
        TR Row 1: B B A B. Input Col 2: B, B, A, B.
        TR Row 2: W Y A B. Input Col 1: W, Y, A, B.
        TR Row 3: Y A Y B. Input Col 0: Y, A, Y, B.

        So TR is constructed from Input columns.
        TR Row $i$ = Input Column $(3-i)$? No.
        TR Row 0 = Input Col 3.
        TR Row 1 = Input Col 2.
        TR Row 2 = Input Col 1.
        TR Row 3 = Input Col 0.
        This corresponds to a **90-degree Counter-Clockwise rotation** (or 270 degrees Clockwise).
        Let's verify standard rotation definitions.
        Input $(r, c)$ goes to Output $(c, N-1-r)$ for 90 deg clockwise.
        Input $(r, c)$ goes to Output $(N-1-c, r)$ for 90 deg counter-clockwise.
        Here, Input Col 3 becomes TR Row 0.
        Input $(0,3) \to$ TR $(0,0)$.
        Input $(1,3) \to$ TR $(0,1)$.
        Input $(2,3) \to$ TR $(0,2)$.
        Input $(3,3) \to$ TR $(0,3)$.
        So Input $(r, c)$ maps to TR $(c, 3-r)$? No.
        Let's look at indices.
        Input $(r, c)$.
        TR $(r', c')$.
        TR Row 0 is Input Col 3. So $r'=0$ corresponds to $c=3$.
        TR Row 1 is Input Col 2. So $r'=1$ corresponds to $c=2$.
        TR Row $r'$ corresponds to Input Col $3-r'$.
        Within the row, TR $(r', c')$ takes value from Input $(c', 3-r')$.
        Let's check: TR $(0,0)$ is Input $(0,3)$ = A. Correct.
        TR $(0,1)$ is Input $(1,3)$ = A. Correct.
        TR $(0,2)$ is Input $(2,3)$ = B. Correct.
        TR $(0,3)$ is Input $(3,3)$ = A. Correct.
        TR $(1,0)$ is Input $(0,2)$ = B. Correct.
        This transformation is: $New(r, c) = Old(c, N-1-r)$.
        Wait, $Old(c, N-1-r)$ means row index is $c$, col index is $N-1-r$.
        Let's check 90 deg Clockwise: $(r, c) \to (c, N-1-r)$.
        Let's check 90 deg Counter-Clockwise: $(r, c) \to (N-1-c, r)$.
        My derived mapping: TR $(r', c') = Input(c', 3-r')$.
        Let $r = c'$, $c = 3-r'$. Then $r' = 3-c$, $c' = r$.
        So Input $(r, c)$ goes to TR $(3-c, r)$.
        This is $(N-1-c, r)$. This is **90 degrees Counter-Clockwise**.
        Wait, let's re-verify visually.
        Input:
        Y W B A
        A Y B A
        Y A A B
        B B B A

        Rotate 90 CCW:
        A B B B
        A B A B
        B B A Y
        A A Y W
        (Top row becomes left col, bottom row becomes right col... wait)
        90 CCW: Top row (Y W B A) becomes Left column (top to bottom).
        So Left col should be Y, W, B, A.
        My TR analysis:
        TR Row 0: A A B A (Input Col 3)
        TR Row 1: B B A B (Input Col 2)
        TR Row 2: W Y A B (Input Col 1)
        TR Row 3: Y A Y B (Input Col 0)
        This means the Rightmost column of Input becomes the Top row of TR.
        This is a **9

... [6585 chars truncated]
alt-4 sports qwen3.5-122b: k=1
"A coach diagrams a play on a whiteboard, then tells each squad to run it facing a different sideline—same formation, four orientations, full-court coverage."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11878 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A small tactical diagram with colored position markers on a square clipboard." -> This implies the input is a small square grid.
*   **Output:** "Deploy four squads onto a court twice the size: one runs the play as drawn, the others execute the same formation but oriented toward different edges of the field, so together they tile the full arena."
*   **Grid details:** "The full court is four clipboard-sized zones. Each zone holds the same formation rotated to face a different direction, and together they fill the doubled playing surface without gaps."
*   **Key takeaway:** The output grid is twice the width and twice the height of the input grid. The input grid is repeated 4 times in a 2x2 arrangement. However, the description says "oriented toward different edges". This suggests rotation.
    *   "one runs the play as drawn" -> Top-Left (TL) is likely the original input.
    *   "others execute the same formation but oriented toward different edges" -> This implies rotations.
    *   "together they tile the full arena" -> The 4 quadrants make up the 2x2 larger grid.
    *   Usually, in these types of puzzles (ARC-like), "oriented toward different edges" often means 0, 90, 180, 270 degree rotations.
    *   Let's check the arrangement. A common pattern for "four squads... oriented toward different edges" is:
        *   Top-Left: Original (0 degrees)
        *   Top-Right: Rotated 90 degrees clockwise? Or reflected?
        *   Bottom-Left: Rotated 270 degrees?
        *   Bottom-Right: Rotated 180 degrees?
    *   Let's look at the "tiling" aspect. If I have a square $N \times N$, the output is $2N \times 2N$.
    *   Let's verify with the Training Example 1.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    Size: 4x4.
*   **Output:**
    ```
    Y W B A A A B A
    A Y B A B B A B
    Y A A B W Y A B
    B B B A Y A Y B
    A B B B B Y A Y
    B A A Y B A Y W
    A B Y A B A B B
    A B W Y A B A A
    ```
    Size: 8x8.
    This confirms the "twice the size" rule ($4 \times 4 \to 8 \times 8$).

    Let's break down the 8x8 output into four 4x4 quadrants.
    *   **Top-Left (TL) Quadrant (Rows 0-3, Cols 0-3):**
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        This matches the Input exactly. So TL = Input.

    *   **Top-Right (TR) Quadrant (Rows 0-3, Cols 4-7):**
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        Let's compare this to the Input.
        Input:
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        Is TR a rotation of Input?
        Let's try rotating Input 90 degrees clockwise.
        Row 0 becomes Col 3 (last col).
        Row 1 becomes Col 2.
        Row 2 becomes Col 1.
        Row 3 becomes Col 0.
        Rotated 90 CW:
        ```
        B Y A Y
        B A Y W
        B A A B
        A B A A
        ```
        Does this match TR?
        TR:
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        No.
        Let's try rotating Input 90 degrees counter-clockwise (270 CW).
        Row 0 becomes Col 0.
        Row 1 becomes Col 1.
        Row 2 becomes Col 2.
        Row 3 becomes Col 3.
        Rotated 270 CW:
        ```
        A B A A
        B A Y W
        B A A B
        A Y B Y
        ```
        Does this match TR?
        TR:
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        No.
        Let's try rotating Input 180 degrees.
        Reverse rows, then reverse cols.
        Input:
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        180 Rot:
        ```
        A B B B
        B A A Y
        A B Y A
        A B W Y
        ```
        Does this match TR? No.

    *   Let's look at the Bottom-Left (BL) Quadrant (Rows 4-7, Cols 0-3):
        ```
        A B B B
        B A A Y
        A B Y A
        A B W Y
        ```
        Wait, this looks exactly like the 180 degree rotation I calculated above!
        Let's re-verify.
        Input:
        R0: Y W B A
        R1: A Y B A
        R2: Y A A B
        R3: B B B A

        180 Rotation:
        R0' = Reverse(R3) = A B B B
        R1' = Reverse(R2) = B A A Y
        R2' = Reverse(R1) = A B Y A
        R3' = Reverse(R0) = A B W Y

        BL Quadrant:
        A B B B
        B A A Y
        A B Y A
        A B W Y
        Yes! BL is Input rotated 180 degrees.

    *   Let's look at the Bottom-Right (BR) Quadrant (Rows 4-7, Cols 4-7):
        ```
        B Y A Y
        B A Y W
        B A A B
        A B A A
        ```
        Let's compare this to the 90 degree clockwise rotation I calculated earlier.
        9

... [6947 chars truncated]
alt-5 weather qwen3.5-122b: fail
"A storm cell splits into four fronts, each sweeping outward from the eye in a different rotational bearing, painting the radar map with the same cloud signature turned four ways."
Fail (best cell_acc=0.06 at k=1)
Best Attempt
vs
Expected
Reasoning (11587 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A small square radar return showing a colorful storm pattern." -> This implies the input is a square grid.
*   **Output:** "The storm propagates into four quadrants of a larger radar display." -> This implies the output is a larger grid, likely 2x the dimensions of the input in both width and height (since there are four quadrants).
*   **Transformation:** "Each quadrant carries the same precipitation pattern but rotated as though the wind shear twisted each front to a different compass bearing." -> This suggests the input grid is copied into four quadrants of the output grid.
*   **Rotation:** "rotated by successive quarter-turns." -> This implies specific rotations for each quadrant.
    *   Top-Left (Quadrant 1): Usually 0 degrees (original).
    *   Top-Right (Quadrant 2): Usually 90 degrees clockwise.
    *   Bottom-Left (Quadrant 3): Usually 270 degrees clockwise (or 90 counter-clockwise).
    *   Bottom-Right (Quadrant 4): Usually 180 degrees.
    *   *Wait, let's verify with the training example.*

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    Dimensions: 4x4.
*   **Output:**
    ```
    Y W B A A A B A
    A Y B A B B A B
    Y A A B W Y A B
    B B B A Y A Y B
    A B B B B Y A Y
    B A A Y B A Y W
    A B Y A B A B B
    A B W Y A B A A
    ```
    Dimensions: 8x8.
    This confirms the output is 2x the input dimensions (4x4 -> 8x8).

*   **Let's check the quadrants:**
    *   **Top-Left (0:4, 0:4):**
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        Matches Input exactly. So, Top-Left is Input (0° rotation).

    *   **Top-Right (0:4, 4:8):**
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        Let's see if this is a rotation of the Input.
        Input:
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
        Rotate 90° Clockwise:
        Row 0 becomes Col 3 (last col).
        Row 1 becomes Col 2.
        Row 2 becomes Col 1.
        Row 3 becomes Col 0.
        Let's construct 90° CW rotation of Input:
        Col 0 (Y, A, Y, B) -> Row 3 (B, Y, A, Y) ? No.
        Standard 90° CW:
        (r, c) -> (c, N-1-r)
        Row 0: Y W B A -> Col 3: Y, W, B, A (top to bottom)
        Row 1: A Y B A -> Col 2: A, Y, B, A
        Row 2: Y A A B -> Col 1: Y, A, A, B
        Row 3: B B B A -> Col 0: B, B, B, A
        Resulting Grid:
        ```
        B Y A Y
        B A Y W
        B B A B
        A A B A
        ```
        Let's compare this with the Top-Right quadrant of the Output:
        Output TR:
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        This looks like the 90° CW rotation I calculated, but flipped vertically? Or is it 90° Counter-Clockwise?
        Let's try 90° CCW (Counter-Clockwise):
        (r, c) -> (N-1-c, r)
        Row 0 (Y W B A) -> Col 0 (Y, W, B, A) bottom to top? No.
        Row 0 becomes Col 0 (top to bottom).
        Row 1 becomes Col 1.
        Row 2 becomes Col 2.
        Row 3 becomes Col 3.
        Wait, 90 CCW:
        Top row becomes Left column.
        Y W B A -> Left col: Y, W, B, A.
        A Y B A -> 2nd col: A, Y, B, A.
        Y A A B -> 3rd col: Y, A, A, B.
        B B B A -> 4th col: B, B, B, A.
        Result:
        ```
        Y A Y B
        W Y A B
        B B A B
        A A B A
        ```
        Compare with Output TR:
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        This is the 90° CCW result flipped vertically (upside down).
        Or, it is the 90° CW result flipped horizontally?
        Let's look at the Output TR again:
        Row 0: A A B A (Matches Input Row 3 reversed? No. Input Row 3 is B B B A. Input Row 0 is Y W B A.)
        Let's look at the Output TR columns.
        Col 0: A, B, W, Y.
        Col 1: A, B, Y, A.
        Col 2: B, A, A, B.
        Col 3: A, B, B, B.
        Input Rows:
        R0: Y W B A
        R1: A Y B A
        R2: Y A A B
        R3: B B B A

        Let's try rotating Input 90° Clockwise again.
        Input:
        Y W B A
        A Y B A
        Y A A B
        B B B A

        90 CW:
        B Y A Y
        B A Y W
        B B A B
        A A B A

        Output TR:
        A A B A
        B B A B
        W Y A B
        Y A Y B

        Notice Output TR Row 0 is 90 CW Row 3.
        Output TR Row 1 is 90 CW Row 2.
        Output TR Row 2 is 90 CW Row 1.
        Output TR Row 3 is 90 CW Row 0.
        So Output TR is the 90° CW rotation flipped vertically (or rotated 180 then 90 CW? No).
        Actually, let's look at the sequence of rota

... [6797 chars truncated]
alt-6 architecture qwen3.5-122b: k=2
"An architect takes a single ornamental tile and sets it at four rotations around a central point, creating a larger mosaic panel where the same design faces every wall of the room."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10088 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A small square decorative tile (grid).
*   **Output:** A 2x2 panel made of four copies of the tile.
*   **Transformation:** Each tile is rotated so the pattern radiates outward in a different direction.
*   **Grid Details:** The output is exactly 4 times the area (2x width, 2x height). No grout lines.
*   **Key phrase:** "Each tile is rotated so that the pattern radiates outward in a different direction". This usually implies rotations of 0, 90, 180, 270 degrees.
*   **Layout:** A 2x2 arrangement of these rotated tiles.
    *   Top-Left (TL)
    *   Top-Right (TR)
    *   Bottom-Left (BL)
    *   Bottom-Right (BR)

**2. Analyze the Training Examples:**

**Example 1:**
Input (4x4):
Y W B A
A Y B A
Y A A B
B B B A

Output (8x8):
Y W B A | A A B A
A Y B A | B B A B
Y A A B | W Y A B
B B B A | Y A Y B
-----------------
A B B B | B Y A Y
B A A Y | B A Y W
A B Y A | B A B B
A B W Y | A B A A

Let's look at the quadrants of the output.
Input size: $N \times N$ (4x4). Output size: $2N \times 2N$ (8x8).

**Quadrant 1 (Top-Left):**
Y W B A
A Y B A
Y A A B
B B B A
This matches the Input exactly. So, TL is Input rotated 0 degrees.

**Quadrant 2 (Top-Right):**
A A B A
B B A B
W Y A B
Y A Y B
Let's compare this to the Input.
Input:
Y W B A
A Y B A
Y A A B
B B B A

If I rotate Input 90 degrees clockwise:
Row 0 becomes Col 3 (bottom to top? No, standard rotation).
Let's visualize 90 deg clockwise rotation of Input:
Original:
(0,0) Y (0,1) W (0,2) B (0,3) A
(1,0) A (1,1) Y (1,2) B (1,3) A
(2,0) Y (2,1) A (2,2) A (2,3) B
(3,0) B (3,1) B (3,2) B (3,3) A

Rotated 90 CW:
Row 0: B Y A Y (Col 0 bottom to top) -> Wait.
(3,0) B, (2,0) Y, (1,0) A, (0,0) Y -> B Y A Y
(3,1) B, (2,1) A, (1,1) Y, (0,1) W -> B A Y W
(3,2) B, (2,2) A, (1,2) B, (0,2) B -> B A B B
(3,3) A, (2,3) B, (1,3) A, (0,3) A -> A B A A
This matches the Bottom-Right quadrant of the output!
Let's check the Bottom-Right quadrant of the output:
B Y A Y
B A Y W
B A B B
A B A A
Yes, TR is NOT 90 CW. BR is 90 CW.

Let's check Top-Right quadrant again:
A A B A
B B A B
W Y A B
Y A Y B
This looks like the Input rotated 90 degrees Counter-Clockwise (CCW).
Input:
Y W B A
A Y B A
Y A A B
B B B A

Rotated 90 CCW:
Row 0: A A B A (Col 3 top to bottom) -> A, A, B, A. Matches.
Row 1: B B A B (Col 2 top to bottom) -> B, B, A, B. Matches.
Row 2: W Y A B (Col 1 top to bottom) -> W, Y, A, B. Matches.
Row 3: Y A Y B (Col 0 top to bottom) -> Y, A, Y, B. Matches.
So, Top-Right is Input rotated 90 degrees CCW (or 270 CW).

Let's check Bottom-Left quadrant:
A B B B
B A A Y
A B Y A
A B W Y
This looks like Input rotated 180 degrees.
Input:
Y W B A
A Y B A
Y A A B
B B B A

Rotated 180:
Row 0: A B B B (Row 3 reversed) -> A, B, B, B. Matches.
Row 1: B A A Y (Row 2 reversed) -> B, A, A, Y. Matches.
Row 2: A B Y A (Row 1 reversed) -> A, B, Y, A. Matches.
Row 3: A B W Y (Row 0 reversed) -> A, B, W, Y. Matches.
So, Bottom-Left is Input rotated 180 degrees.

Let's check Bottom-Right quadrant again:
B Y A Y
B A Y W
B A B B
A B A A
This matches Input rotated 90 degrees Clockwise.
Row 0: B Y A Y (Col 0 bottom to top) -> B, Y, A, Y. Matches.
Row 1: B A Y W (Col 1 bottom to top) -> B, A, Y, W. Matches.
Row 2: B A B B (Col 2 bottom to top) -> B, A, B, B. Matches.
Row 3: A B A A (Col 3 bottom to top) -> A, B, A, A. Matches.

**Summary of Example 1:**
Input $I$.
Output is a 2x2 grid of tiles:
TL: $I$ (0 deg)
TR: $I$ rotated 90 CCW (270 CW)
BL: $I$ rotated 180
BR: $I$ rotated 90 CW

Wait, let's re-read the metaphor. "Each tile is rotated so that the pattern radiates outward in a different direction".
Usually, "radiating outward" from the center of the 2x2 panel implies:
TL: Top-Left corner points to Top-Left? Or pattern flows towards TL?
If the pattern radiates *outward* from the center of the 2x2 panel:
TL tile should point towards Top-Left.
TR tile should point towards Top-Right.
BL tile should point towards Bottom-Left.
BR tile should point towards Bottom-Right.

Let's look at the rotations again.
TL: 0 deg.
TR: 90 CCW.
BL: 180.
BR: 90 CW.

Let's check Example 2 to confirm this pattern.

**Example 2:**
Input (4x4):
M R M R
M M X X
B B B R
X B R B

Output (8x8):
M R M R | R X R B
M M X X | M X B R
B B B R | R M B B
X B R B | M M B X
-----------------
B R B X | X B M M
R B B B | B B M R
X X M M | R B X M
R M R M | B R X R

**Quadrant 1 (TL):**
M R M R
M M X X
B B B R
X B R B
Matches Input exactly. (0 deg).

**Quadrant 2 (TR):**
R X R B
M X B R
R M B B
M M B X
Let's check if this is 90 CCW rotation of Input.
Input:
M R M R
M M X X
B B B R
X B R B

90 CCW (Col 3 top-down, Col 2 top-down...):
Col 3: R, X, R, B -> Row 0: R X R B. Matches.
Col 2: M, X, B, R -> Row 1: M X B R. Matches.
Col 1: R, M, B, B -> Row 2: R M B B. Matches.
Col 0: M, M, B, X -> Row 3: M M B X. Matches.
So TR 

... [5199 chars truncated]
alt-7 warfare qwen3.5-122b: k=5
"A general deploys the same battalion formation to hold four quadrants of a fortress—each regiment faces a different gate, but the internal structure of each unit is identical, merely wheeled into position."
MARC valid, solved with k=5
Prediction
vs
Expected
Reasoning (9268 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A small colored battle map (a grid).
*   **Output:** A fortress map (a larger grid).
*   **Transformation:** "Garrison a fortress by placing four copies of the formation into its four quadrants."
*   **Details:** "The fortress map is twice the span of one formation in each direction." This means if the input is $N \times M$, the output is $2N \times 2M$.
*   **Rotation:** "Each copy is wheeled to face a different cardinal wall, so the same tactical shape guards every approach." This implies the four quadrants contain rotated versions of the input grid.
*   **Quadrants:**
    *   Top-Left (TL)
    *   Top-Right (TR)
    *   Bottom-Left (BL)
    *   Bottom-Right (BR)
*   **Orientation:** "Four identical regiments, each rotated to a different heading".
    *   Usually, in these types of puzzles (ARC-like), the rotations are 0, 90, 180, 270 degrees.
    *   Let's check the examples to determine the specific rotation mapping for each quadrant.

**2. Analyze the Training Examples:**

**Example 1:**
Input ($4 \times 4$):
Y W B A
A Y B A
Y A A B
B B B A

Output ($8 \times 8$):
Y W B A | A A B A
A Y B A | B B A B
Y A A B | W Y A B
B B B A | Y A Y B
-----------------
A B B B | B Y A Y
B A A Y | B A Y W
A B Y A | B A B B
A B W Y | A B A A

Let's break down the quadrants.
Input Grid $I$:
Row 0: Y W B A
Row 1: A Y B A
Row 2: Y A A B
Row 3: B B B A

Output Quadrant TL (Top-Left):
Y W B A
A Y B A
Y A A B
B B B A
This is exactly the Input Grid $I$. (Rotation 0 degrees).

Output Quadrant TR (Top-Right):
A A B A
B B A B
W Y A B
Y A Y B
Let's see how this relates to $I$.
$I$ rotated 90 degrees clockwise?
Row 0 of $I$ becomes Col 3 of rotated.
Col 3 of $I$ is A, A, B, A.
Row 0 of TR is A, A, B, A.
Let's check Row 1 of TR: B, B, A, B.
Col 2 of $I$ is B, B, A, B.
Row 2 of TR: W, Y, A, B.
Col 1 of $I$ is W, Y, A, B.
Row 3 of TR: Y, A, Y, B.
Col 0 of $I$ is Y, A, Y, B.
So TR is $I$ rotated 90 degrees clockwise.

Output Quadrant BL (Bottom-Left):
A B B B
B A A Y
A B Y A
A B W Y
Let's check rotations.
$I$ rotated 180 degrees?
Row 3 of $I$ reversed: A B B B. Matches Row 0 of BL.
Row 2 of $I$ reversed: B A A Y. Matches Row 1 of BL.
Row 1 of $I$ reversed: A B Y A. Matches Row 2 of BL.
Row 0 of $I$ reversed: A B W Y. Matches Row 3 of BL.
So BL is $I$ rotated 180 degrees.

Output Quadrant BR (Bottom-Right):
B Y A Y
B A Y W
B A B B
A B A A
Let's check rotations.
$I$ rotated 270 degrees clockwise (or 90 counter-clockwise)?
Col 0 of $I$ (Y, A, Y, B) becomes Row 0 of rotated? No, usually Col 0 becomes Row 0 in 90 CCW.
Let's check Row 0 of BR: B Y A Y.
Col 0 of $I$ is Y, A, Y, B. Reversed is B, Y, A, Y.
Row 1 of BR: B A Y W.
Col 1 of $I$ is W, Y, A, B. Reversed is B, A, Y, W.
Row 2 of BR: B A B B.
Col 2 of $I$ is B, B, A, B. Reversed is B, A, B, B.
Row 3 of BR: A B A A.
Col 3 of $I$ is A, A, B, A. Reversed is A, B, A, A.
So BR is $I$ rotated 270 degrees clockwise.

**Summary of Example 1:**
TL: 0 deg
TR: 90 deg CW
BL: 180 deg
BR: 270 deg CW

Let's verify with Example 2.

**Example 2:**
Input ($4 \times 4$):
M R M R
M M X X
B B B R
X B R B

Output ($8 \times 8$):
TL:
M R M R
M M X X
B B B R
X B R B
(Matches Input)

TR:
R X R B
M X B R
R M B B
M M B X
Let's check 90 deg CW rotation of Input.
Input Col 3 (R, X, R, B) -> TR Row 0 (R, X, R, B). Correct.
Input Col 2 (M, X, B, R) -> TR Row 1 (M, X, B, R). Correct.
Input Col 1 (R, M, B, B) -> TR Row 2 (R, M, B, B). Correct.
Input Col 0 (M, M, B, X) -> TR Row 3 (M, M, B, X). Correct.

BL:
B R B X
R B B B
X X M M
R M R M
Let's check 180 deg rotation of Input.
Input Row 3 reversed (B, R, B, X) -> BL Row 0. Correct.
Input Row 2 reversed (R, B, B, B) -> BL Row 1. Correct.
Input Row 1 reversed (X, X, M, M) -> BL Row 2. Correct.
Input Row 0 reversed (R, M, R, M) -> BL Row 3. Correct.

BR:
X B M M
B B M R
R B X M
B R X R
Let's check 270 deg CW rotation of Input.
Input Col 0 (M, M, B, X) reversed -> (X, B, M, M). Matches BR Row 0.
Input Col 1 (R, M, B, B) reversed -> (B, B, M, R). Matches BR Row 1.
Input Col 2 (M, X, B, R) reversed -> (R, B, X, M). Matches BR Row 2.
Input Col 3 (R, X, R, B) reversed -> (B, R, X, R). Matches BR Row 3.

**Conclusion:**
The transformation rule is consistent across examples.
Given an input grid $I$ of size $H \times W$:
1.  Create an output grid of size $2H \times 2W$.
2.  **Top-Left Quadrant:** Copy of $I$ (0 degrees rotation).
3.  **Top-Right Quadrant:** $I$ rotated 90 degrees clockwise.
4.  **Bottom-Left Quadrant:** $I$ rotated 180 degrees.
5.  **Bottom-Right Quadrant:** $I$ rotated 270 degrees clockwise.

Let's double check Example 3 just to be sure.
Input:
M O O M
O B M M
W B M M
W B M B

TL: Matches Input.
TR: 90 CW.
Col 3 (M, M, M, B) -> Row 0 (M, M, M, B).
Col 2 (O, M, M, M) -> Row 1 (O, M, M, M).
Col 1 (O, B, B, B) -> Row 2 (O, B, B, B).
Col 0 (M, O, W, 

... [4403 chars truncated]
alt-8 theater qwen3.5-122b: k=1
"A stage manager blocks the same scene four times on a revolving stage—each time the platform turns, the audience sees the identical tableau from a new angle, and all four frozen moments are captured in a single panoramic photograph."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9762 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A "small square stage" (a grid).
*   **Action:** "Photograph four performances of the same tableau, each taken after the revolving stage has turned another quarter-rotation."
*   **Output:** "Arrange the four photographs into a grid to create one composite panorama."
*   **Grid details:** "The panoramic image is twice the height and width of a single stage shot."
*   **Quadrants:** "Each quadrant holds one rotation of the tableau."

**Interpretation:**
*   Input is an $N \times N$ grid.
*   Output is a $2N \times 2N$ grid.
*   The output consists of 4 quadrants.
*   Each quadrant is a rotated version of the input grid.
*   The rotations are quarter-turns (90 degrees).
*   I need to figure out the order of rotations in the quadrants (Top-Left, Top-Right, Bottom-Left, Bottom-Right).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    Size: $4 \times 4$.
*   **Output:**
    ```
    Y W B A A A B A
    A Y B A B B A B
    Y A A B W Y A B
    B B B A Y A Y B
    A B B B B Y A Y
    B A A Y B A Y W
    A B Y A B A B B
    A B W Y A B A A
    ```
    Size: $8 \times 8$.

Let's break down the output into four $4 \times 4$ quadrants.
*   **Top-Left (TL):**
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    This matches the Input exactly. So, TL = Input (0 degrees rotation).

*   **Top-Right (TR):**
    ```
    A A B A
    B B A B
    W Y A B
    Y A Y B
    ```
    Let's check rotations of the Input.
    Input:
    ```
    Y W B A
    A Y B A
    Y A A B
    B B B A
    ```
    Rotate 90 deg clockwise:
    Row 1 becomes Col 4 (bottom to top? No, standard matrix rotation).
    Let's visualize.
    (0,0) Y -> (0,3)
    (0,1) W -> (1,3)
    (0,2) B -> (2,3)
    (0,3) A -> (3,3)
    (1,0) A -> (0,2)
    ...
    Let's write out the 90 deg clockwise rotation of Input:
    Row 0: A B A Y (Last col of input read bottom-up? No. Last col of input is A, A, B, A. Read bottom-up: A, B, A, A. Wait.)
    Standard 90 deg clockwise:
    New Row 0 = Old Col 0 (read bottom to top) -> B, Y, A, Y.
    New Row 1 = Old Col 1 (read bottom to top) -> B, A, Y, W.
    New Row 2 = Old Col 2 (read bottom to top) -> B, A, B, B.
    New Row 3 = Old Col 3 (read bottom to top) -> A, B, A, A.
    Let's check TR again:
    ```
    A A B A
    B B A B
    W Y A B
    Y A Y B
    ```
    This doesn't look like 90 deg clockwise.
    Let's check 90 deg counter-clockwise.
    New Row 0 = Old Col 3 (read top to bottom) -> A, A, B, A.
    New Row 1 = Old Col 2 (read top to bottom) -> B, B, A, B.
    New Row 2 = Old Col 1 (read top to bottom) -> W, Y, A, B.
    New Row 3 = Old Col 0 (read top to bottom) -> Y, A, Y, B.
    Let's compare this with TR:
    TR Row 0: A A B A. Matches.
    TR Row 1: B B A B. Matches.
    TR Row 2: W Y A B. Matches.
    TR Row 3: Y A Y B. Matches.
    So, **TR = Input rotated 90 degrees Counter-Clockwise (or 270 degrees Clockwise).**

*   **Bottom-Left (BL):**
    ```
    A B B B
    B A A Y
    A B Y A
    A B W Y
    ```
    Let's check rotations.
    We have 0 deg (TL) and 270 deg (TR).
    Maybe BL is 180 deg?
    Input 180 deg:
    Row 0 = Old Row 3 reversed -> A B B B.
    Row 1 = Old Row 2 reversed -> B A A Y.
    Row 2 = Old Row 1 reversed -> A B Y A.
    Row 3 = Old Row 0 reversed -> A B W Y.
    Let's compare with BL:
    BL Row 0: A B B B. Matches.
    BL Row 1: B A A Y. Matches.
    BL Row 2: A B Y A. Matches.
    BL Row 3: A B W Y. Matches.
    So, **BL = Input rotated 180 degrees.**

*   **Bottom-Right (BR):**
    ```
    B Y A Y
    B A Y W
    B A B B
    A B A A
    ```
    Let's check the remaining rotation: 90 degrees Clockwise.
    Input 90 deg Clockwise:
    Row 0 = Old Col 0 (bottom to top) -> B, Y, A, Y.
    Row 1 = Old Col 1 (bottom to top) -> B, A, Y, W.
    Row 2 = Old Col 2 (bottom to top) -> B, A, B, B.
    Row 3 = Old Col 3 (bottom to top) -> A, B, A, A.
    Let's compare with BR:
    BR Row 0: B Y A Y. Matches.
    BR Row 1: B A Y W. Matches.
    BR Row 2: B A B B. Matches.
    BR Row 3: A B A A. Matches.
    So, **BR = Input rotated 90 degrees Clockwise.**

**Summary of Transformation Rule:**
Given an $N \times N$ input grid $G$:
The output is a $2N \times 2N$ grid composed of four $N \times N$ quadrants.
*   **Top-Left:** $G$ (0 degrees)
*   **Top-Right:** $G$ rotated 90 degrees Counter-Clockwise (270 degrees Clockwise)
*   **Bottom-Left:** $G$ rotated 180 degrees
*   **Bottom-Right:** $G$ rotated 90 degrees Clockwise

Wait, let's re-read the metaphor. "Photograph four performances... each taken after the revolving stage has turned another quarter-rotation."
Usually, a stage turns in one direction.
If it starts at 0, then 90, then 180, then 270.
The arrangement in the output grid 

... [4954 chars truncated]
alt-9 gardening qwen3.5-122b: fail
"A gardener takes a single planting grid and sows it into four raised beds, turning the template a quarter-turn for each bed so the same floral pattern blooms in every cardinal direction."
Fail (best cell_acc=0.03 at k=5)
Best Attempt
vs
Expected
Reasoning (11894 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A small square planting plan (grid).
*   **Output:** A garden twice the size (2x2 arrangement of beds).
*   **Transformation:**
    *   The full garden is a 2x2 arrangement of beds.
    *   Each bed is the same size as the original plan.
    *   Every bed is a rotated copy.
    *   "rows that once ran east-west now run north-south, and so on for each successive bed."
    *   This implies a rotation of 90 degrees for each subsequent bed in the sequence.
    *   Let's visualize the 2x2 layout of the output grid. It consists of 4 quadrants: Top-Left (TL), Top-Right (TR), Bottom-Left (BL), Bottom-Right (BR).
    *   The input grid is $N \times N$. The output grid is $2N \times 2N$.
    *   The description says "Each bed follows the same planting plan but rotated...".
    *   Let's look at the examples to determine the specific rotation order.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input ($4 \times 4$):
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
    *   Output ($8 \times 8$):
        ```
        Y W B A | A A B A
        A Y B A | B B A B
        Y A A B | W Y A B
        B B B A | Y A Y B
        -----------------
        A B B B | B Y A Y
        B A A Y | B A Y W
        A B Y A | B A B B
        A B W Y | A B A A
        ```
    *   Let's check the quadrants.
    *   **TL (Top-Left):** Matches Input exactly.
        ```
        Y W B A
        A Y B A
        Y A A B
        B B B A
        ```
    *   **TR (Top-Right):**
        ```
        A A B A
        B B A B
        W Y A B
        Y A Y B
        ```
        Let's see if this is a rotation of the Input.
        Input:
        Row 0: Y W B A
        Row 1: A Y B A
        Row 2: Y A A B
        Row 3: B B B A
        Rotate 90 deg clockwise:
        Col 0 becomes Row 0 (reversed): B Y A Y -> No.
        Col 0 (bottom to top) becomes Row 0: B Y A Y.
        Col 1 (bottom to top) becomes Row 1: B A Y W.
        Col 2 (bottom to top) becomes Row 2: B A B B.
        Col 3 (bottom to top) becomes Row 3: A A A A.
        Let's check TR again.
        TR Row 0: A A B A.
        TR Row 1: B B A B.
        TR Row 2: W Y A B.
        TR Row 3: Y A Y B.
        Let's try rotating Input 90 degrees *counter-clockwise*.
        Col 3 (top to bottom) becomes Row 0: A A B A. Matches TR Row 0.
        Col 2 (top to bottom) becomes Row 1: B B A B. Matches TR Row 1.
        Col 1 (top to bottom) becomes Row 2: W Y A B. Matches TR Row 2.
        Col 0 (top to bottom) becomes Row 3: Y A Y B. Matches TR Row 3.
        So, TR is Input rotated 90 degrees Counter-Clockwise (CCW). Or 270 degrees Clockwise.

    *   **BL (Bottom-Left):**
        ```
        A B B B
        B A A Y
        A B Y A
        A B W Y
        ```
        Let's check rotations.
        Input rotated 180 degrees?
        Row 3 reversed: A B B B. Matches BL Row 0.
        Row 2 reversed: B A A Y. Matches BL Row 1.
        Row 1 reversed: A B Y A. Matches BL Row 2.
        Row 0 reversed: A B W Y. Matches BL Row 3.
        So, BL is Input rotated 180 degrees.

    *   **BR (Bottom-Right):**
        ```
        B Y A Y
        B A Y W
        B A B B
        A B A A
        ```
        Let's check rotations.
        Input rotated 90 degrees Clockwise (CW)?
        Col 0 (bottom to top): B Y A Y. Matches BR Row 0.
        Col 1 (bottom to top): B A Y W. Matches BR Row 1.
        Col 2 (bottom to top): B A B B. Matches BR Row 2.
        Col 3 (bottom to top): A A A A. Wait, BR Row 3 is A B A A.
        Let's re-examine BR Row 3.
        Input Col 3 is A A B A. Bottom to top is A B A A.
        Matches BR Row 3.
        So, BR is Input rotated 90 degrees Clockwise.

    *   **Summary of Example 1:**
        TL: 0 deg (Original)
        TR: 90 deg CCW (or 270 CW)
        BL: 180 deg
        BR: 90 deg CW

    *   Wait, let's look at the metaphor again. "rows that once ran east-west now run north-south, and so on for each successive bed."
    *   Usually, a sequence implies an order. TL -> TR -> BL -> BR? Or TL -> TR -> BR -> BL?
    *   Let's check the rotation direction.
    *   TL: 0
    *   TR: 90 CCW
    *   BL: 180
    *   BR: 90 CW
    *   This looks like a specific pattern. Let's check other examples to confirm.

*   **Example 2:**
    *   Input ($4 \times 4$):
        ```
        M R M R
        M M X X
        B B B R
        X B R B
        ```
    *   Output ($8 \times 8$):
        TL:
        ```
        M R M R
        M M X X
        B B B R
        X B R B
        ```
        (Matches Input)
    *   TR:
        ```
        R X R B
        M X B R
        R M B B
        M M B X
        ```
        Let's check Input rotated 90 CCW.
        Col 3 (top-down): R X R B. Matches TR Row 0.
        Col 2 (top-down): M X B R. Matches TR R

... [6974 chars truncated]

Task 467: 7ddcd7ec

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A comet streaks away from its home planet, leaving a glowing trail across the ni ... [8 chars truncated] MARC valid 1
alt-1 biology A cell nucleus sends out tendrils of cytoplasm, each filament stretching toward ... [70 chars truncated] fail
alt-10 astronomy A binary star system pulses at the center of the field, and certain gravitationa ... [107 chars truncated] MARC valid 1
alt-11 ocean/sailing An anchored buoy bobs in the water, and the wake from passing swells catches its ... [75 chars truncated] MARC valid 3
alt-12 electronics A chip sits on the circuit board, and certain pins have fired—current race ... [69 chars truncated] fail
alt-13 mythology A sacred altar stands at the crossroads, and from its corners the gods have cast ... [118 chars truncated] fail
alt-14 dance A pair of dancers holds a tight formation at the center, but soloists have broke ... [101 chars truncated] fail
alt-15 geology A volcanic plug of hardened magma sits in the bedrock, and fracture lines have a ... [125 chars truncated] fail
alt-2 cooking A pat of butter sits in a hot pan, and the rivulets of melted fat race away from ... [39 chars truncated] MARC valid 2
alt-3 music A resonant chord hangs in the air, and certain overtones escape from it, each ha ... [75 chars truncated] fail
alt-4 sports A rugby scrum holds firm at the center, but breakaway runners have already peele ... [84 chars truncated] MARC valid 2
alt-5 weather The eye of the storm is eerily calm, but at certain edges the wind has already f ... [73 chars truncated] MARC valid 2
alt-6 architecture Flying buttresses spring from the corners of a cathedral tower, each one arching ... [65 chars truncated] fig alone solves
alt-7 warfare A fortress holds the center, but sappers have already breached at the corners an ... [97 chars truncated] fig alone solves
alt-8 theater The lead actors hold their positions at center stage, but spotlight operators ha ... [106 chars truncated] fail
alt-9 gardening A mature shrub sits in the garden bed, and runners have already sprouted from ce ... [78 chars truncated] fail
original qwen3.5-122b: k=1
"A comet streaks away from its home planet, leaving a glowing trail across the night sky."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10614 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A 10x10 grid of black void (`.`).
*   **Objects:**
    *   "Planet": A solid 2x2 world.
    *   "Comets": One or two comets launched from its corners. Each is a single bright spark sitting diagonally adjacent to the planet's surface.
    *   "Color": The planet and its comets share one color.
*   **Action:**
    *   Comets hurtle away from the planet.
    *   They blaze a trail across the void.
    *   They drop one spark of light in every row they cross.
    *   They fly diagonally outward until they crash into the edge of the universe.
    *   The planet stays fixed.
*   **Constraints:**
    *   Planet is far enough from edges for comets to streak.
    *   Grid is 10x10.

**2. Analyze the Training Example:**
*   **Input:**
    *   Grid size: 10x10.
    *   Background: `.` (black).
    *   Object: A cluster of `Y` (yellow) pixels.
    *   Let's locate the `Y` pixels in the input:
        *   Row 1 (index 1): Col 6 (index 6) -> `(1, 6)`
        *   Row 2 (index 2): Col 4, 5 -> `(2, 4), (2, 5)`
        *   Row 3 (index 3): Col 4, 5 -> `(3, 4), (3, 5)`
        *   Row 4 (index 4): Col 6 -> `(4, 6)`
    *   Wait, let's look closer at the shape.
        *   Row 1: `......Y...` (index 1, col 6)
        *   Row 2: `....YY....` (index 2, col 4, 5)
        *   Row 3: `....YY....` (index 3, col 4, 5)
        *   Row 4: `......Y...` (index 4, col 6)
    *   This looks like a 2x2 square in the middle `(2,4), (2,5), (3,4), (3,5)` plus two "comets" at `(1,6)` and `(4,6)`.
    *   Wait, the description says "comets... sitting diagonally adjacent to the planet's surface".
    *   Planet: 2x2 block. Let's assume the 2x2 block is the core.
        *   Core: `(2,4), (2,5), (3,4), (3,5)`.
    *   Comets:
        *   One at `(1,6)`. Relative to the top-right corner of the 2x2 block `(2,5)`, `(1,6)` is `(-1, +1)`. This is diagonally adjacent (top-right).
        *   One at `(4,6)`. Relative to the bottom-right corner of the 2x2 block `(3,5)`, `(4,6)` is `(+1, +1)`. This is diagonally adjacent (bottom-right).
    *   So the input contains the "Planet" (2x2) and the initial "Comets" (1 pixel each).
    *   Total color: Yellow (`Y`).

*   **Output:**
    *   The 2x2 planet remains at `(2,4), (2,5), (3,4), (3,5)`.
    *   The comets have left trails.
    *   Let's trace the trails.
    *   Top-right comet started at `(1,6)`. It moves diagonally outward.
        *   Direction: Top-Right (Up-Right). Row decreases, Col increases.
        *   Path: `(1,6) -> (0,7)`.
        *   Output shows `Y` at `(0,7)`.
        *   Wait, looking at the output grid provided in the prompt:
            *   Row 0: `.......Y..` -> `(0, 7)` is `Y`.
            *   Row 1: `......Y...` -> `(1, 6)` is `Y`.
            *   Row 2: `....YY....` -> `(2, 4), (2, 5)` are `Y`.
            *   Row 3: `....YY....` -> `(3, 4), (3, 5)` are `Y`.
            *   Row 4: `......Y...` -> `(4, 6)` is `Y`.
            *   Row 5: `.......Y..` -> `(5, 7)` is `Y`.
            *   Row 6: `........Y.` -> `(6, 8)` is `Y`.
            *   Row 7: `.........Y` -> `(7, 9)` is `Y`.
            *   Row 8: `..........`
            *   Row 9: `..........`
    *   Let's re-evaluate the comet directions.
    *   Comet 1: Started at `(1,6)`. In output, we see `Y` at `(0,7)`. This is Up-Right.
    *   Comet 2: Started at `(4,6)`. In output, we see `Y` at `(5,7), (6,8), (7,9)`. This is Down-Right.
    *   Wait, the input had `Y` at `(1,6)` and `(4,6)`.
    *   The output keeps the input `Y`s and adds new ones.
    *   Top comet `(1,6)` extends to `(0,7)`.
    *   Bottom comet `(4,6)` extends to `(5,7), (6,8), (7,9)`.
    *   Why did the top one stop at `(0,7)`? Because row 0 is the edge.
    *   Why did the bottom one stop at `(7,9)`? Because col 9 is the edge.
    *   So the rule is: Identify the 2x2 planet. Identify the single pixels diagonally adjacent to the corners of the planet. Extend lines from these single pixels diagonally away from the planet until the grid boundary is reached. Fill those cells with the same color.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Background:** Black (`.`).
    *   **Planet:** A 2x2 square of a specific color.
    *   **Comets:** Single pixels of the same color, located diagonally adjacent to the corners of the 2x2 planet.
    *   **Trails:** New pixels of the same color created by extending the comets' paths.

2.  **AFFORDANCES:**
    *   The Planet is static.
    *   The Comets define a direction.
    *   The direction is determined by the position of the comet relative to the planet center/corner.
    *   If a comet is at Top-Right of the planet, it moves Top-Right.
    *   If a comet is at Bottom-Right of the planet, it moves Bottom-Right.
    *   If a comet is at Top-Left, it moves Top-Left.
    *   If a comet is at Bottom-Left, 

... [5724 chars truncated]
alt-1 biology qwen3.5-122b: fail
"A cell nucleus sends out tendrils of cytoplasm, each filament stretching toward the membrane wall along the path first signaled by a pioneer molecule."
Fail (best cell_acc=0.92 at k=1)
Best Attempt
vs
Expected
Reasoning (11030 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A dense cluster of organelles forms the nucleus, with scout molecules perched at its diagonal edges."
    *   This suggests there is a central shape (nucleus) and some specific pixels (scouts) located at the corners or diagonal edges of this shape.
*   **What to do:** "Each scout molecule initiates a chain of replication, spawning identical molecules in a line from itself to the cell membrane, following the trajectory away from the nucleus."
    *   This implies a ray-casting or line-drawing operation.
    *   The "scout molecules" are the starting points.
    *   They spawn a line of the same color.
    *   The direction is "away from the nucleus".
    *   The line goes "to the cell membrane" (the edge of the grid).
*   **Grid details:** 10x10 grid, black background, single color for all living material.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . . . . . . .
    . . . . . . Y . . .
    . . . . Y Y . . . .
    . . . . Y Y . . . .
    . . . . . . Y . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    ```
    *   There is a cluster of 'Y' (yellow) pixels.
    *   Let's identify the shape. It looks like a diamond or a rotated square.
    *   Coordinates (row, col) 0-indexed:
        *   (1, 6)
        *   (2, 4), (2, 5)
        *   (3, 4), (3, 5)
        *   (4, 6)
    *   Wait, let's look closer.
        Row 1: col 6
        Row 2: col 4, 5
        Row 3: col 4, 5
        Row 4: col 6
    *   This forms a shape. The "nucleus" is the block of Y's.
    *   The "scout molecules" are described as being at "diagonal edges".
    *   In the output, we see new Y's appearing.
    *   **Output:**
        ```
        . . . . . . . Y . .
        . . . . . . Y . . .
        . . . . Y Y . . . .
        . . . . Y Y . . . .
        . . . . . . Y . . .
        . . . . . . . Y . .
        . . . . . . . . Y .
        . . . . . . . . . Y
        . . . . . . . . . .
        . . . . . . . . . .
        ```
    *   Let's compare Input and Output.
    *   Input Y's: (1,6), (2,4), (2,5), (3,4), (3,5), (4,6).
    *   Output Y's: All Input Y's are preserved.
    *   New Y's:
        *   (0, 7)
        *   (5, 7)
        *   (6, 8)
        *   (7, 9)
    *   Let's trace the lines.
    *   Look at the top-most Y in the cluster: (1, 6).
        *   In the output, there is a Y at (0, 7).
        *   Direction: Up-Right (row -1, col +1).
        *   This is "away from the nucleus". The center of the cluster seems to be around row 2.5, col 4.5.
        *   (1, 6) is top-right relative to the center. So moving Up-Right makes sense.
    *   Look at the bottom-most Y in the cluster: (4, 6).
        *   In the output, there are Y's at (5, 7), (6, 8), (7, 9).
        *   Direction: Down-Right (row +1, col +1).
        *   (4, 6) is bottom-right relative to the center. So moving Down-Right makes sense.
    *   What about the left side? (2, 4) and (3, 4).
        *   There are no new Y's extending to the left.
        *   Why? Maybe the "scouts" are only specific pixels.
        *   The description says "scout molecules perched at its diagonal edges".
        *   The shape is somewhat diamond-like.
        *   Top point: (1, 6).
        *   Bottom point: (4, 6).
        *   Left points: (2, 4), (3, 4).
        *   Right points: (2, 5), (3, 5) ... wait, (1,6) and (4,6) are further right than (2,5) and (3,5).
        *   Actually, let's look at the shape again.
            Row 1:      . . . . . . Y . . .  (col 6)
            Row 2:      . . . . Y Y . . . .  (col 4, 5)
            Row 3:      . . . . Y Y . . . .  (col 4, 5)
            Row 4:      . . . . . . Y . . .  (col 6)
        *   The "Rightmost" pixels are at col 6 (rows 1 and 4).
        *   The "Leftmost" pixels are at col 4 (rows 2 and 3).
        *   The "Topmost" pixel is at row 1 (col 6).
        *   The "Bottommost" pixel is at row 4 (col 6).
        *   The new lines appear starting from (1, 6) going Up-Right and from (4, 6) going Down-Right.
        *   Why not from the left side?
        *   Maybe the "scouts" are defined by the convex hull corners?
        *   Or maybe the "diagonal edges" implies specific corners.
        *   Let's look at the "trajectory away from the nucleus".
        *   Center of mass approx: Row 2.5, Col 5.
        *   Pixel (1, 6): Vector from center is (-1.5, +1). Direction is Up-Right.
        *   Pixel (4, 6): Vector from center is (+1.5, +1). Direction is Down-Right.
        *   Pixel (2, 4): Vector from center is (-0.5, -1). Direction is Left.
        *   Pixel (3, 4): Vector from center is (+0.5, -1). Direction is Left.
        *   Pixel (2, 5): Vector from center is (-0.5, 0). Direction is Up.
        *   Pixel (3, 5): Vector from center is (+0.5, 0). Direction is Do

... [6078 chars truncated]
alt-10 astronomy qwen3.5-122b: k=1
"A binary star system pulses at the center of the field, and certain gravitational lensing artifacts streak diagonally outward like phantom images toward the edge of the telescope's frame."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10278 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A compact stellar mass sits in the grid with lensing artifacts appearing at diagonal adjacencies."
    *   "Compact stellar mass": This likely refers to a central block of colored pixels.
    *   "Lensing artifacts appearing at diagonal adjacencies": This suggests there are specific pixels connected diagonally to the main mass.
*   **What to do:** "Each artifact replicates itself outward along its diagonal trajectory, one pixel per frame, until it exits the field of view."
    *   "Artifact": The pixels that are diagonally adjacent to the main mass.
    *   "Replicates itself outward along its diagonal trajectory": The artifact moves away from the center along the diagonal line it is on.
    *   "One pixel per frame": This implies a trail or extension. Since it's a static transformation (Input -> Output), "one pixel per frame" likely means extending the line of artifacts until the edge of the grid.
    *   "Until it exits the field of view": The line continues to the edge of the grid.
*   **Grid details:** "10x10 dark sky, all luminous objects in one color."
    *   Background is black (`.`).
    *   Objects are a single color (in the examples, `Y` for yellow, in the test input `A` for azure).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . . . . . . .
    . . . . . . Y . . .
    . . . . Y Y . . . .
    . . . . Y Y . . . .
    . . . . . . Y . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    ```
    *   There is a central block of `Y`s.
    *   Let's identify the "compact stellar mass". It looks like a 2x2 block at (2,4), (2,5), (3,4), (3,5) (0-indexed row, col).
    *   Wait, let's look closer.
    *   Row 1: `Y` at col 6.
    *   Row 2: `Y` at col 4, 5.
    *   Row 3: `Y` at col 4, 5.
    *   Row 4: `Y` at col 6.
    *   So the shape is:
        ```
          Y
        Y Y
        Y Y
          Y
        ```
        This looks like a diamond or a cross shape, but specifically, there's a 2x2 core and two single pixels attached diagonally?
        Let's check coordinates (row, col):
        (1, 6)
        (2, 4), (2, 5)
        (3, 4), (3, 5)
        (4, 6)
    *   The "compact stellar mass" is likely the 2x2 block at rows 2-3, cols 4-5.
    *   The "lensing artifacts" are the pixels at (1, 6) and (4, 6).
    *   Wait, (1, 6) is diagonally adjacent to (2, 5). (4, 6) is diagonally adjacent to (3, 5).
    *   Let's check the Output.
*   **Output:**
    ```
    . . . . . . . Y . .
    . . . . . . Y . . .
    . . . . Y Y . . . .
    . . . . Y Y . . . .
    . . . . . . Y . . .
    . . . . . . . Y . .
    . . . . . . . . Y .
    . . . . . . . . . Y
    . . . . . . . . . .
    . . . . . . . . . .
    ```
    *   The original pixels remain.
    *   New pixels appear.
    *   Let's trace the new pixels.
    *   Original artifact at (1, 6). In output, we see `Y` at (0, 7).
        *   (1, 6) -> (0, 7). This is moving Up-Right (row -1, col +1).
        *   Does it continue? The output shows `Y` at (0, 7). The grid ends at row 0. So it stops there.
    *   Original artifact at (4, 6). In output, we see `Y` at (5, 7), (6, 8), (7, 9).
        *   (4, 6) -> (5, 7) -> (6, 8) -> (7, 9).
        *   This is moving Down-Right (row +1, col +1).
    *   So the rule seems to be: Identify the "artifacts" (pixels diagonally adjacent to the main mass). Extend a line of that color from the artifact outwards along the diagonal direction away from the center of the mass, until the grid boundary.

    *   Wait, let's re-evaluate the "center".
    *   The 2x2 block is at (2,4), (2,5), (3,4), (3,5). Center is roughly (2.5, 4.5).
    *   Artifact 1: (1, 6). Vector from center: (1-2.5, 6-4.5) = (-1.5, 1.5). Direction is Up-Right.
    *   Artifact 2: (4, 6). Vector from center: (4-2.5, 6-4.5) = (1.5, 1.5). Direction is Down-Right.
    *   The extension follows the direction away from the center.
    *   Artifact 1 extends to (0, 7).
    *   Artifact 2 extends to (5, 7), (6, 8), (7, 9).
    *   What about the other side? The 2x2 block has corners at (2,4), (2,5), (3,4), (3,5).
    *   Diagonals from (2,4) would be (1,3) and (3,3).
    *   Diagonals from (3,4) would be (2,3) and (4,3).
    *   Diagonals from (2,5) would be (1,6) and (3,6).
    *   Diagonals from (3,5) would be (2,6) and (4,6).
    *   In the input, we have pixels at (1,6) and (4,6).
    *   (1,6) is diagonal to (2,5).
    *   (4,6) is diagonal to (3,5).
    *   So the "artifacts" are the pixels that are already present in the input grid that are diagonally adjacent to the main block.
    *   The transformation is: For every pixel that is diagonally adjacent to the main block (the "artifact"), draw a line of that color extending from that pixel in the direction away from the main 

... [5329 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=3
"An anchored buoy bobs in the water, and the wake from passing swells catches its mooring lines, sending ripples racing diagonally toward the distant shore."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (10431 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Object:** A square buoy float.
*   **Context:** Sits in water (dark ocean surface).
*   **Initial State:** Ripple crests forming at certain diagonal corners.
*   **Action:** Each ripple propagates diagonally away from the buoy, advancing one wave-length per step, until it reaches the shoreline at the grid's edge.
*   **Grid:** 10x10.
*   **Colors:** Buoy and ripples are in one color. Background is black (`.`).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** A shape made of `Y` (yellow).
        *   Row 1: `.`
        *   Row 2: `.` `.` `.` `.` `.` `.` `Y` `.` `.` `.` (Index 6)
        *   Row 3: `.` `.` `.` `.` `Y` `Y` `.` `.` `.` `.` (Indices 4, 5)
        *   Row 4: `.` `.` `.` `.` `Y` `Y` `.` `.` `.` `.` (Indices 4, 5)
        *   Row 5: `.` `.` `.` `.` `.` `.` `Y` `.` `.` `.` (Index 6)
        *   Rest are `.`
        *   The shape looks like a diamond or a cross, but specifically, it looks like a central 2x2 block with single pixels extending diagonally outwards? No, let's look closer.
        *   (2,6), (3,4), (3,5), (4,4), (4,5), (5,6).
        *   Wait, let's map coordinates (row, col) 0-indexed.
        *   (1, 6)
        *   (2, 4), (2, 5)
        *   (3, 4), (3, 5)
        *   (4, 6)
        *   This looks like a 2x2 square at (2,4)-(3,5) with two "arms" extending diagonally.
        *   Top-right arm: (1,6) is diagonal from (2,5).
        *   Bottom-right arm: (4,6) is diagonal from (3,5).
        *   Wait, (1,6) is row 1, col 6. (2,5) is row 2, col 5. Difference: (-1, +1). That's Top-Right diagonal.
        *   (4,6) is row 4, col 6. (3,5) is row 3, col 5. Difference: (+1, +1). That's Bottom-Right diagonal.
        *   So the "buoy" seems to be the 2x2 block at rows 2-3, cols 4-5.
        *   The "ripples" are the single pixels at (1,6) and (4,6).
    *   **Output:**
        *   The original shape remains.
        *   New `Y`s appear.
        *   Row 0: `.` `.` `.` `.` `.` `.` `.` `Y` `.` `.` (Index 7). This is (0, 7).
        *   Row 1: `.` `.` `.` `.` `.` `.` `Y` `.` `.` `.` (Index 6). This is (1, 6). (Original)
        *   Row 2: `.` `.` `.` `.` `Y` `Y` `.` `.` `.` `.` (Indices 4, 5). (Original)
        *   Row 3: `.` `.` `.` `.` `Y` `Y` `.` `.` `.` `.` (Indices 4, 5). (Original)
        *   Row 4: `.` `.` `.` `.` `.` `.` `Y` `.` `.` `.` (Index 6). (Original)
        *   Row 5: `.` `.` `.` `.` `.` `.` `.` `Y` `.` `.` (Index 7). This is (5, 7).
        *   Row 6: `.` `.` `.` `.` `.` `.` `.` `.` `Y` `.` (Index 8). This is (6, 8).
        *   Row 7: `.` `.` `.` `.` `.` `.` `.` `.` `.` `Y` (Index 9). This is (7, 9).
        *   Row 8: `.` `.` `.` `.` `.` `.` `.` `.` `.` `.`
        *   Row 9: `.` `.` `.` `.` `.` `.` `.` `.` `.` `.`
    *   **Observation:**
        *   The "ripples" propagate diagonally.
        *   Top-Right ripple: Started at (1,6). Propagated to (0,7).
        *   Bottom-Right ripple: Started at (4,6). Propagated to (5,7), (6,8), (7,9).
        *   Why did the top one stop at (0,7)? Because it hit the top edge (row 0).
        *   Why did the bottom one stop at (7,9)? Because it hit the right edge (col 9).
        *   Wait, the metaphor says "until it reaches the shoreline at the grid's edge".
        *   The "buoy" is the central block. The "ripples" are the initial diagonal pixels.
        *   The transformation extends these diagonal lines from the initial ripple pixels until they hit a boundary.
        *   Direction of propagation:
            *   (1,6) -> (0,7). Direction: Up-Right (-1, +1).
            *   (4,6) -> (5,7) -> (6,8) -> (7,9). Direction: Down-Right (+1, +1).
        *   So, identify the "source" pixels (the ones sticking out from the main block) and extend them in their respective diagonal directions until the grid boundary.

*   **Example 2:**
    *   **Input:**
        *   (2, 2), (2, 3)
        *   (3, 2), (3, 3)
        *   (4, 4)
        *   Shape: 2x2 block at (2,2)-(3,3). One pixel at (4,4).
        *   (4,4) is diagonal from (3,3). Direction: Down-Right (+1, +1).
    *   **Output:**
        *   Original shape remains.
        *   New pixels: (5,5), (6,6), (7,7), (8,8), (9,9).
        *   This confirms the Down-Right propagation from (4,4).
        *   It stops at (9,9) because that's the corner.

*   **Example 3:**
    *   **Input:**
        *   (2, 6)
        *   (3, 4), (3, 5)
        *   (4, 4), (4, 5)
        *   (5, 3)
        *   Shape: 2x2 block at (3,4)-(4,5).
        *   Pixel at (2,6). Relative to block? (2,6) is Up-Right from (3,5).
        *   Pixel at (5,3). Relative to block? (5,3) is Down-Left from (4,4).
    *   **Output:**
        *   Original shape remains.
        *   From (2,6): Propagates Up-Right.
            *   (1, 7)
            *   (0, 8)
            *   Stops at top edge.
        *   From (5,3): Propagates Down-Left.


... [5479 chars truncated]
alt-12 electronics qwen3.5-122b: fail
"A chip sits on the circuit board, and certain pins have fired—current races diagonally along trace lines toward the edge connectors of the PCB."
Fail (best cell_acc=0.30 at k=1)
Best Attempt
vs
Expected
Reasoning (11085 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A square integrated circuit (IC) on a board.
*   **Input:** A 10x10 dark PCB (black background `.`) with active copper in one color.
*   **Key Elements:** "Active signal pins at certain diagonal corners". "Each active pin drives current along its diagonal trace". "Lighting up one via per step". "Until the signal reaches the board's edge connector".
*   **Interpretation:**
    *   There is a shape or pattern of a specific color in the input grid.
    *   This shape seems to represent "active signal pins" or a source.
    *   The transformation involves extending lines from this shape diagonally.
    *   The lines go until they hit the edge of the grid.
    *   The color of the extension matches the color of the source shape.

**2. Analyze the Training Example:**
*   **Input:**
    *   Background: `.` (black)
    *   Shape: `Y` (yellow)
    *   Shape coordinates (0-indexed, row, col):
        *   (1, 6)
        *   (2, 4), (2, 5)
        *   (3, 4), (3, 5)
        *   (4, 6)
    *   This looks like a diamond or a rotated square shape.
    *   Let's check the diagonals.
    *   Top-right part of the shape: (1, 6), (2, 5), (3, 4). This is a diagonal going down-left.
    *   Bottom-right part of the shape: (2, 5), (3, 5), (4, 6). This is a diagonal going down-right.
    *   Wait, let's look at the Output.
*   **Output:**
    *   The original `Y` shape remains.
    *   New `Y` pixels appear.
    *   Let's trace the new pixels.
    *   Row 0: (0, 7) is `Y`.
    *   Row 1: (1, 6) is `Y` (original).
    *   Row 2: (2, 4), (2, 5) are `Y` (original).
    *   Row 3: (3, 4), (3, 5) are `Y` (original).
    *   Row 4: (4, 6) is `Y` (original).
    *   Row 5: (5, 7) is `Y`.
    *   Row 6: (6, 8) is `Y`.
    *   Row 7: (7, 9) is `Y`.
    *   Row 8: None.
    *   Row 9: None.
    *   Wait, let's look closer at the input shape.
        *   (1, 6)
        *   (2, 4), (2, 5)
        *   (3, 4), (3, 5)
        *   (4, 6)
    *   This shape is symmetric.
    *   Let's look at the extensions.
    *   Extension 1: From (1, 6) going Up-Right? (0, 7). Yes.
    *   Extension 2: From (4, 6) going Down-Right? (5, 7), (6, 8), (7, 9). Yes.
    *   Are there extensions on the left side?
        *   Input has (2, 4) and (3, 4).
        *   Output does *not* show extensions going Up-Left from (2, 4) -> (1, 3) or Down-Left from (3, 4) -> (4, 3).
        *   Wait, let's re-examine the output grid provided in the prompt.
        *   Output Row 0: `. . . . . . . Y . .` -> (0, 7)
        *   Output Row 1: `. . . . . . Y . . .` -> (1, 6)
        *   Output Row 2: `. . . . Y Y . . . .` -> (2, 4), (2, 5)
        *   Output Row 3: `. . . . Y Y . . . .` -> (3, 4), (3, 5)
        *   Output Row 4: `. . . . . . Y . . .` -> (4, 6)
        *   Output Row 5: `. . . . . . . Y . .` -> (5, 7)
        *   Output Row 6: `. . . . . . . . Y .` -> (6, 8)
        *   Output Row 7: `. . . . . . . . . Y` -> (7, 9)
        *   Output Row 8: `. . . . . . . . . .`
        *   Output Row 9: `. . . . . . . . . .`
    *   So, extensions happened from the "right side" of the shape.
    *   Specifically, from (1, 6) going Up-Right (delta row -1, delta col +1).
    *   And from (4, 6) going Down-Right (delta row +1, delta col +1).
    *   Why not the left side? (2, 4) and (3, 4).
    *   Maybe the "active signal pins" are specific points.
    *   The metaphor says: "active signal pins at certain diagonal corners".
    *   The shape looks like a diamond. The corners are Top (1,6), Bottom (4,6), Left (2,4)/(3,4)?, Right (2,5)/(3,5)?.
    *   Actually, (1,6) is the top-most point. (4,6) is the bottom-most point.
    *   (2,4) and (3,4) form the left edge. (2,5) and (3,5) form the right edge.
    *   The extensions go from the Top point (1,6) towards Top-Right.
    *   The extensions go from the Bottom point (4,6) towards Bottom-Right.
    *   Why Top-Right and Bottom-Right?
    *   Maybe it depends on the "active signal pins".
    *   Let's look at the Test Input to see if there's a pattern there.

**3. Analyze the Test Input:**
*   **Input:**
    *   Background: `.`
    *   Shape: `A` (azure)
    *   Shape coordinates:
        *   (3, 5)
        *   (4, 3), (4, 4)
        *   (5, 3), (5, 4)
        *   (6, 2), (6, 5)
    *   Wait, let's map it carefully.
    *   Row 3: `. . . . . A . . . .` -> (3, 5)
    *   Row 4: `. . . A A . . . . .` -> (4, 3), (4, 4)
    *   Row 5: `. . . A A . . . . .` -> (5, 3), (5, 4)
    *   Row 6: `. . A . . A . . . .` -> (6, 2), (6, 5)
    *   This shape is different from the training example.
    *   Training Example Shape:
        *   (1, 6)
        *   (2, 4), (2, 5)
        *   (3, 4), (3, 5)
        *   (4, 6)
        *   It was a solid diamond (filled).
    *   Test Input Shape:
        *   (3, 5)
        *   (4, 3), (4, 4)
     

... [6151 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"A sacred altar stands at the crossroads, and from its corners the gods have cast bolts of divine fire, each one scorching a path diagonally across the mortal plane until it strikes the world's edge."
Fail (best cell_acc=0.30 at k=1)
Best Attempt
vs
Expected
Reasoning (10999 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A consecrated square altar sits in the realm, with divine sparks already placed at certain diagonal corners." -> This suggests there are specific colored pixels (sparks) in the input grid.
*   "Each spark burns forward along its diagonal, igniting one tile per moment, blazing a trail until it reaches the boundary of the world." -> This describes the transformation rule. The colored pixels extend along their diagonals.
*   "Grid details: 10x10 void, all sacred fire in one color." -> The grid is 10x10. The "sacred fire" refers to the color of the sparks. In the examples, the color is Yellow (Y). In the test input, the color is Azure (A).

**2. Analyze the Training Example:**
*   **Input:**
    *   A 10x10 grid.
    *   Most cells are black (.).
    *   There is a cluster of Yellow (Y) pixels.
    *   Let's locate the Y pixels:
        *   Row 1 (index 1): Col 6 (index 6) -> (1, 6)
        *   Row 2 (index 2): Col 4 (index 4), Col 5 (index 5) -> (2, 4), (2, 5)
        *   Row 3 (index 3): Col 4 (index 4), Col 5 (index 5) -> (3, 4), (3, 5)
        *   Row 4 (index 4): Col 6 (index 6) -> (4, 6)
    *   Wait, let's look closer at the input grid provided in the text.
    *   Input Row 0: . . . . . . . . . .
    *   Input Row 1: . . . . . . Y . . .  (Y at index 6)
    *   Input Row 2: . . . . Y Y . . . .  (Y at index 4, 5)
    *   Input Row 3: . . . . Y Y . . . .  (Y at index 4, 5)
    *   Input Row 4: . . . . . . Y . . .  (Y at index 6)
    *   Input Row 5-9: All dots.
    *   So the shape is a diamond or a cross-like shape centered around (2.5, 4.5)? No, let's look at the coordinates.
    *   (1, 6), (2, 4), (2, 5), (3, 4), (3, 5), (4, 6).
    *   This looks like two diagonal lines intersecting or a specific pattern.
    *   Let's check the Output.
    *   Output Row 0: . . . . . . . Y . . (Y at index 7)
    *   Output Row 1: . . . . . . Y . . . (Y at index 6) - Original
    *   Output Row 2: . . . . Y Y . . . . (Y at index 4, 5) - Original
    *   Output Row 3: . . . . Y Y . . . . (Y at index 4, 5) - Original
    *   Output Row 4: . . . . . . Y . . . (Y at index 6) - Original
    *   Output Row 5: . . . . . . . Y . . (Y at index 7)
    *   Output Row 6: . . . . . . . . Y . (Y at index 8)
    *   Output Row 7: . . . . . . . . . Y (Y at index 9)
    *   Output Row 8: . . . . . . . . . .
    *   Output Row 9: . . . . . . . . . .

    *   Wait, looking at the output, the original Y pixels are preserved.
    *   New Y pixels appear at:
        *   (0, 7)
        *   (5, 7)
        *   (6, 8)
        *   (7, 9)
    *   Let's trace the diagonals.
    *   The "sparks" seem to be the outermost points of the shape? Or is it extending from specific points?
    *   The metaphor says "divine sparks already placed at certain diagonal corners".
    *   In the input, the shape is somewhat symmetric.
    *   Let's look at the diagonals.
    *   Main diagonal direction: Top-Left to Bottom-Right (r increases, c increases).
    *   Anti-diagonal direction: Top-Right to Bottom-Left (r increases, c decreases).
    *   Let's look at the new pixels in the output.
    *   (0, 7) is above (1, 6). (1, 6) is a Y. (0, 7) is Top-Right of (1, 6). This is an anti-diagonal extension upwards.
    *   (5, 7) is below (4, 6). (4, 6) is a Y. (5, 7) is Bottom-Right of (4, 6). This is a main diagonal extension downwards.
    *   (6, 8) is below (5, 7).
    *   (7, 9) is below (6, 8).
    *   So it seems like the pixel at (4, 6) extends down-right: (5, 7), (6, 8), (7, 9).
    *   And the pixel at (1, 6) extends up-right: (0, 7).
    *   What about the left side?
    *   Input has (2, 4) and (3, 4).
    *   Output has (2, 4) and (3, 4). No new pixels on the left side?
    *   Let's re-read the metaphor: "Each spark burns forward along its diagonal".
    *   Maybe "forward" implies a specific direction? Or maybe it depends on the "corner"?
    *   "divine sparks already placed at certain diagonal corners".
    *   In the input shape:
        *   Top-most Y is at (1, 6).
        *   Bottom-most Y is at (4, 6).
        *   Left-most Ys are at (2, 4) and (3, 4).
        *   Right-most Ys are at (1, 6) and (4, 6).
    *   Wait, the shape is:
        . . . . . . Y . . .
        . . . . Y Y . . . .
        . . . . Y Y . . . .
        . . . . . . Y . . .
    *   It looks like a diamond rotated 45 degrees, but the left side is flat (vertical line at col 4). The right side is a point at col 6.
    *   Actually, (1,6) and (4,6) are the rightmost points. (2,4) and (3,4) are the leftmost points.
    *   The output adds a trail starting from (4,6) going down-right.
    *   The output adds a trail starting from (1,6) going up-right.
    *   Why not from the left side?
    *   Maybe the "sparks" are only the ones on the right? Or maybe the direction is determined by something else.
  

... [6062 chars truncated]
alt-14 dance qwen3.5-122b: fail
"A pair of dancers holds a tight formation at the center, but soloists have broken away at the corners, each chassé-ing diagonally across the ballroom floor toward the far wall."
Fail (best cell_acc=0.98 at k=3)
Best Attempt
vs
Expected
Reasoning (11064 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A compact square formation of dancers holds position, with solo dancers poised at certain diagonal corners.
*   **Action:** Each soloist performs a series of diagonal chassé steps, advancing one position per beat away from the formation, until they reach the edge of the dance floor.
*   **Grid:** 10x10 dark ballroom floor (black dots `.`), all dancers in one color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** A 10x10 grid.
        *   There is a central block of `Y` (yellow).
        *   Specifically:
            *   Row 1 (index 1): `Y` at col 6.
            *   Row 2: `Y` at col 4, 5.
            *   Row 3: `Y` at col 4, 5.
            *   Row 4: `Y` at col 6.
        *   Wait, let's look closer at the coordinates (0-indexed).
        *   Input `Y` positions:
            *   (1, 6)
            *   (2, 4), (2, 5)
            *   (3, 4), (3, 5)
            *   (4, 6)
        *   This looks like a diamond shape or a square rotated 45 degrees, but slightly irregular. Let's trace the "formation".
        *   The "compact square formation" seems to be the 2x2 block at (2,4), (2,5), (3,4), (3,5).
        *   The "solo dancers" seem to be the ones at (1,6) and (4,6). Wait, looking at the output might clarify.
    *   **Output:**
        *   The 2x2 block remains at (2,4), (2,5), (3,4), (3,5).
        *   The `Y` at (1,6) moved to (0,7).
        *   The `Y` at (4,6) moved to (5,7), (6,8), (7,9).
        *   Wait, let's look at the output `Y` positions:
            *   (0, 7)
            *   (1, 6)
            *   (2, 4), (2, 5)
            *   (3, 4), (3, 5)
            *   (4, 6)
            *   (5, 7)
            *   (6, 8)
            *   (7, 9)
        *   Comparing Input to Output:
            *   Input had `Y` at (1,6). Output has `Y` at (0,7) AND (1,6).
            *   Input had `Y` at (4,6). Output has `Y` at (4,6), (5,7), (6,8), (7,9).
            *   The central 2x2 block (2,4)-(3,5) stayed the same.
            *   It seems the "soloists" are the ones *outside* the main 2x2 block.
            *   In Input 1:
                *   (1,6) is outside.
                *   (4,6) is outside.
            *   In Output 1:
                *   (1,6) extended to (0,7). Direction: Up-Right (row -1, col +1).
                *   (4,6) extended to (5,7), (6,8), (7,9). Direction: Down-Right (row +1, col +1).
            *   Why did (1,6) go Up-Right and (4,6) go Down-Right?
            *   Let's check the position relative to the center.
            *   Center of 2x2 block is roughly between rows 2-3 and cols 4-5.
            *   (1,6) is Top-Right relative to the block. It moved further Top-Right.
            *   (4,6) is Bottom-Right relative to the block. It moved further Bottom-Right.
            *   Wait, the metaphor says "advancing one position per beat away from the formation, until they reach the edge".
            *   So, identify the "formation" (the core block). Identify the "soloists" (pixels of the same color connected to the formation but not part of the core block? Or just specific pixels?).
            *   In Example 1, the core seems to be the 2x2 square. The other pixels are attached to the corners of this square.
            *   (1,6) is attached to (2,5) diagonally.
            *   (4,6) is attached to (3,5) diagonally.
            *   They move diagonally away from the center of the 2x2 block.
            *   (1,6) -> (0,7). Next would be (-1, 8) which is off grid. So it stops at edge.
            *   (4,6) -> (5,7) -> (6,8) -> (7,9). Next (8,10) off grid.
            *   So the rule seems to be: Find the main 2x2 block. Find other pixels of the same color connected diagonally to the corners of this block. Extend a line of that color from those pixels in the same diagonal direction until the grid edge.

*   **Example 2:**
    *   **Input:**
        *   `G` positions:
            *   (2, 2), (2, 3)
            *   (3, 2), (3, 3)
            *   (4, 4)
        *   Core 2x2 block: (2,2), (2,3), (3,2), (3,3).
        *   Soloist: (4,4). This is attached to (3,3) diagonally (Bottom-Right).
    *   **Output:**
        *   Core block stays.
        *   (4,4) extends to (5,5), (6,6), (7,7), (8,8), (9,9).
        *   Direction: Down-Right.
        *   This matches the hypothesis. The soloist at the bottom-right corner of the core block moves down-right.

*   **Example 3:**
    *   **Input:**
        *   `O` positions:
            *   (2, 6)
            *   (3, 4), (3, 5)
            *   (4, 4), (4, 5)
            *   (5, 3)
        *   Core 2x2 block: (3,4), (3,5), (4,4), (4,5).
        *   Soloists:
            *   (2, 6): Attached to (3,5) diagonally (Top-Right).
            *   (5, 3): Attached to (4,4) diagonally (Bottom-Left).
    *   **Output:**
        *   Core block stays.
      

... [6081 chars truncated]
alt-15 geology qwen3.5-122b: fail
"A volcanic plug of hardened magma sits in the bedrock, and fracture lines have already begun propagating diagonally from its corners, splitting the crust one stratum at a time toward the tectonic boundary."
Fail (best cell_acc=0.92 at k=1)
Best Attempt
vs
Expected
Reasoning (10433 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A solid square intrusion of igneous rock sits in the formation, with initial fracture points at certain diagonal corners."
    *   This suggests there is a central block of a specific color (the "igneous rock").
    *   There are "fracture points" at diagonal corners of this block.
*   **What to do:** "Each fracture propagates diagonally away from the intrusion, cracking one layer per step, until it reaches the edge of the geological survey area."
    *   This implies lines extending from the corners of the central block.
    *   The direction is "diagonally away".
    *   The propagation continues until the grid edge.
*   **Grid details:** "10x10 dark bedrock, all igneous material and fractures in one color."
    *   Background is black (`.`).
    *   The object and the lines are the same color.

**2. Analyze the Training Example:**
*   **Input:**
    *   Background: `.` (black)
    *   Object: A 2x2 square of `Y` (yellow) at rows 1-4, cols 5-6 (0-indexed). Wait, let's look closer.
    *   Row 1: `... . . . Y . . .` (Index 6 is Y)
    *   Row 2: `... . . Y Y . . .` (Indices 4, 5 are Y)
    *   Row 3: `... . . Y Y . . .` (Indices 4, 5 are Y)
    *   Row 4: `... . . . Y . . .` (Index 6 is Y)
    *   Actually, let's map the coordinates (row, col) 0-indexed.
    *   Row 1: (1, 6) is Y.
    *   Row 2: (2, 4), (2, 5) are Y.
    *   Row 3: (3, 4), (3, 5) are Y.
    *   Row 4: (4, 6) is Y.
    *   This shape looks like a diamond or a rotated square, or maybe a 2x2 square with corners extended?
    *   Let's check the shape again.
        *   (1, 6)
        *   (2, 4), (2, 5)
        *   (3, 4), (3, 5)
        *   (4, 6)
    *   This is not a solid square. It looks like a 2x2 square at (2,4)-(3,5) with two extra pixels at (1,6) and (4,6).
    *   Wait, the description says "solid square intrusion".
    *   Let's re-examine the input grid in Example 1.
    *   Row 0: all `.`
    *   Row 1: `.` `.` `.` `.` `.` `.` `Y` `.` `.` `.` -> (1, 6)
    *   Row 2: `.` `.` `.` `.` `Y` `Y` `.` `.` `.` `.` -> (2, 4), (2, 5)
    *   Row 3: `.` `.` `.` `.` `Y` `Y` `.` `.` `.` `.` -> (3, 4), (3, 5)
    *   Row 4: `.` `.` `.` `.` `.` `.` `Y` `.` `.` `.` -> (4, 6)
    *   Row 5-9: all `.`
    *   The "solid square" part of the description might refer to the core 2x2 block at (2,4), (2,5), (3,4), (3,5).
    *   The "initial fracture points at certain diagonal corners" might refer to the pixels at (1,6) and (4,6).
    *   Wait, (1,6) is top-right relative to the 2x2 block?
        *   Top-right of 2x2 is (2,5). (1,6) is (-1, +1) from (2,5). That is diagonal up-right.
        *   Bottom-right of 2x2 is (3,5). (4,6) is (+1, +1) from (3,5). That is diagonal down-right.
    *   So the input shape consists of a 2x2 square plus two pixels extending diagonally from the top-right and bottom-right corners.
    *   Let's look at the Output of Example 1.
    *   Row 0: `.` `.` `.` `.` `.` `.` `.` `Y` `.` `.` -> (0, 7)
    *   Row 1: `.` `.` `.` `.` `.` `.` `Y` `.` `.` `.` -> (1, 6) (Existing)
    *   Row 2: `.` `.` `.` `.` `Y` `Y` `.` `.` `.` `.` -> (2, 4), (2, 5) (Existing)
    *   Row 3: `.` `.` `.` `.` `Y` `Y` `.` `.` `.` `.` -> (3, 4), (3, 5) (Existing)
    *   Row 4: `.` `.` `.` `.` `.` `.` `Y` `.` `.` `.` -> (4, 6) (Existing)
    *   Row 5: `.` `.` `.` `.` `.` `.` `.` `Y` `.` `.` -> (5, 7)
    *   Row 6: `.` `.` `.` `.` `.` `.` `.` `.` `Y` `.` -> (6, 8)
    *   Row 7: `.` `.` `.` `.` `.` `.` `.` `.` `.` `Y` -> (7, 9)
    *   Row 8: `.` `.` `.` `.` `.` `.` `.` `.` `.` `.`
    *   Row 9: `.` `.` `.` `.` `.` `.` `.` `.` `.` `.`
    *   The output adds pixels at (0,7), (5,7), (6,8), (7,9).
    *   Let's trace the lines.
    *   Existing "fracture points": (1,6) and (4,6).
    *   Line 1 starting from (1,6): Goes to (0,7). Direction: Up-Right (-1, +1).
    *   Line 2 starting from (4,6): Goes to (5,7), (6,8), (7,9). Direction: Down-Right (+1, +1).
    *   So the rule seems to be: Identify the "intrusion" (the 2x2 square). Identify the "fracture points" (pixels adjacent diagonally to the square corners). Extend lines from these fracture points diagonally away from the square until the edge.
    *   Wait, the description says "initial fracture points at certain diagonal corners". In the input, the pixels at (1,6) and (4,6) are already there. They act as the start of the lines.
    *   The output extends these lines.
    *   Why only right side? The input only has pixels on the right side of the 2x2 block.
    *   The 2x2 block is at cols 4,5. The extra pixels are at col 6.
    *   So the "fracture points" are the pixels that are *not* part of the main square block but are connected diagonally.
    *   Or, simpler: Find the connected component of the color. It looks like a cross or diamond shape.
    *   Actually, let's look at the T

... [5520 chars truncated]
alt-2 cooking qwen3.5-122b: k=2
"A pat of butter sits in a hot pan, and the rivulets of melted fat race away from it along the scratches in the surface."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10653 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A solid square of butter occupies the center, with droplets of grease already forming at certain corners."
*   **What to do:** "Each droplet traces a groove in the pan's surface, leaving a trail of grease one spot at a time in a straight line until it hits the rim."
*   **Grid details:** 10x10 black pan surface, butter and grease in a single color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** A 10x10 grid. Most cells are black (`.`). There is a cluster of yellow (`Y`) cells.
        *   Row 1 (index 1): `Y` at col 6.
        *   Row 2: `Y` at col 4, 5.
        *   Row 3: `Y` at col 4, 5.
        *   Row 4: `Y` at col 6.
        *   This looks like a 2x2 square of `Y` at (2,4), (2,5), (3,4), (3,5) plus two "droplets" at (1,6) and (4,6). Wait, let's look closer.
        *   Input Grid:
            ```
            . . . . . . . . . .
            . . . . . . Y . . .  (1, 6)
            . . . . Y Y . . . .  (2, 4), (2, 5)
            . . . . Y Y . . . .  (3, 4), (3, 5)
            . . . . . . Y . . .  (4, 6)
            . . . . . . . . . .
            ...
            ```
        *   The "butter" seems to be the 2x2 block of `Y` at rows 2-3, cols 4-5.
        *   The "droplets" seem to be the single `Y` cells at (1,6) and (4,6).
        *   Wait, the description says "solid square of butter... with droplets... at certain corners".
        *   Let's check the Output Grid:
            ```
            . . . . . . . Y . .  (0, 7)
            . . . . . . Y . . .  (1, 6)
            . . . . Y Y . . . .  (2, 4), (2, 5)
            . . . . Y Y . . . .  (3, 4), (3, 5)
            . . . . . . Y . . .  (4, 6)
            . . . . . . . Y . .  (5, 7)
            . . . . . . . . Y .  (6, 8)
            . . . . . . . . . Y  (7, 9)
            . . . . . . . . . .
            . . . . . . . . . .
            ```
        *   The 2x2 block remains unchanged.
        *   The `Y` at (1,6) stays.
        *   The `Y` at (4,6) stays.
        *   New `Y`s appear: (0,7), (5,7), (6,8), (7,9).
        *   Let's trace the lines.
        *   From (1,6): It goes up-right to (0,7). That's one step.
        *   From (4,6): It goes down-right to (5,7), (6,8), (7,9). That's a diagonal line.
        *   Why did (1,6) stop at (0,7)? Because it hit the rim (row 0).
        *   Why did (4,6) go down-right?
        *   Let's look at the "corners" of the butter. The butter is the 2x2 block at (2,4)-(3,5).
        *   Corners of the butter: Top-Left (2,4), Top-Right (2,5), Bottom-Left (3,4), Bottom-Right (3,5).
        *   The droplets in the input are at (1,6) and (4,6).
        *   (1,6) is adjacent to Top-Right (2,5)? No, (2,5) is row 2, col 5. (1,6) is row 1, col 6. That's diagonal up-right from (2,5).
        *   (4,6) is adjacent to Bottom-Right (3,5)? (3,5) is row 3, col 5. (4,6) is row 4, col 6. That's diagonal down-right from (3,5).
        *   So the droplets are located diagonally outward from the corners of the square.
        *   The transformation extends these droplets in the same direction until the edge of the grid.
        *   Direction for (1,6): It is at (1,6). The butter corner is (2,5). Vector is (-1, +1). So it continues in direction (-1, +1). Next is (0,7). Next is (-1, 8) -> out of bounds. So it stops at (0,7).
        *   Direction for (4,6): It is at (4,6). The butter corner is (3,5). Vector is (+1, +1). So it continues in direction (+1, +1). Next is (5,7), (6,8), (7,9), (8,10) -> out. So it fills (5,7), (6,8), (7,9).
        *   Wait, the input already had (1,6) and (4,6). The output keeps them and adds the trail.
        *   So the rule seems to be: Identify the central square. Identify the "droplets" (single pixels of the same color adjacent diagonally to the corners of the square). Extend these droplets in the direction away from the square until the grid boundary.

*   **Example 2:**
    *   **Input:**
        ```
        . . . . . . . . . .
        . . . . . . . . . .
        . . G G . . . . . .  (2, 2), (2, 3)
        . . G G . . . . . .  (3, 2), (3, 3)
        . . . . G . . . . .  (4, 4)
        . . . . . . . . . .
        ...
        ```
        *   Butter: 2x2 Green (`G`) block at rows 2-3, cols 2-3.
        *   Droplet: Single `G` at (4,4).
        *   Relation: (4,4) is diagonal down-right from Bottom-Right corner (3,3).
    *   **Output:**
        ```
        . . . . . . . . . .
        . . . . . . . . . .
        . . G G . . . . . .
        . . G G . . . . . .
        . . . . G . . . . .
        . . . . . G . . . .  (5, 5)
        . . . . . . G . . .  (6, 6)
        . . . . . . . G . .  (7, 7)
        . . . . . . . . G .  (8, 8)
        . . . . . . . . . G  (9, 9)
        ```
        *   The droplet at (4,4) extends down-right to the corner (9,9).
        *   This confirms the hypothesis: Find th

... [5705 chars truncated]
alt-3 music qwen3.5-122b: fail
"A resonant chord hangs in the air, and certain overtones escape from it, each harmonic climbing its own staircase of octaves until it fades beyond hearing."
Fail (best cell_acc=0.27 at k=2)
Best Attempt
vs
Expected
Reasoning (12102 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A cluster of sustained notes forms the chord body, with stray harmonics vibrating at its diagonal edges."
    *   This suggests there is a main shape (the "chord body") and some "stray harmonics" (pixels) attached to it, likely on the diagonals.
*   "Each escaped harmonic ascends step by step along its own diagonal staircase, one tone per beat, until it reaches the edge of audible range."
    *   "Escaped harmonic": These are the stray pixels.
    *   "Ascends step by step along its own diagonal staircase": They move diagonally.
    *   "Until it reaches the edge": They move until they hit the boundary of the grid.
    *   "One tone per beat": This implies a trail or a sequence of movement. However, looking at the examples, it seems like the movement leaves a trail or the pixel moves to a specific position. Let's look at the examples to clarify the "ascends" part.
*   "Grid details: 10x10 silence grid, all sounding tones in one color."
    *   The grid is 10x10.
    *   The background is black (`.`).
    *   The active color is consistent within a grid (e.g., Yellow in Ex 1, Green in Ex 2, Azure in Test).

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:**
    *   A block of `Y` (Yellow) pixels.
    *   Coordinates (row, col) 0-indexed:
        *   (1, 6)
        *   (2, 4), (2, 5)
        *   (3, 4), (3, 5)
        *   (4, 6)
    *   Shape: A central 2x2 block at (2,4)-(3,5) with two single pixels attached at (1,6) and (4,6).
    *   Wait, let's look closer.
    *   Row 1: `......Y...` -> (1, 6)
    *   Row 2: `....YY....` -> (2, 4), (2, 5)
    *   Row 3: `....YY....` -> (3, 4), (3, 5)
    *   Row 4: `......Y...` -> (4, 6)
    *   The "chord body" seems to be the 2x2 square at (2,4), (2,5), (3,4), (3,5).
    *   The "stray harmonics" are at (1,6) and (4,6).
    *   Let's check the diagonals.
    *   (1,6) is top-right relative to the block.
    *   (4,6) is bottom-right relative to the block.
*   **Output:**
    *   Row 0: `.......Y..` -> (0, 7)
    *   Row 1: `......Y...` -> (1, 6)
    *   Row 2: `....YY....` -> (2, 4), (2, 5)
    *   Row 3: `....YY....` -> (3, 4), (3, 5)
    *   Row 4: `......Y...` -> (4, 6)
    *   Row 5: `.......Y..` -> (5, 7)
    *   Row 6: `........Y.` -> (6, 8)
    *   Row 7: `.........Y` -> (7, 9)
    *   Row 8: `..........`
    *   Row 9: `..........`
    *   Observation:
        *   The central 2x2 block remains unchanged.
        *   The pixel at (1, 6) moved to (0, 7). It moved Up-Right (row -1, col +1).
        *   The pixel at (4, 6) moved to (5, 7), (6, 8), (7, 9). It moved Down-Right (row +1, col +1).
        *   Wait, the input had (1,6) and (4,6).
        *   Output has (0,7) AND (1,6). So (1,6) stayed? Or did it move and leave a trail?
        *   Output has (4,6), (5,7), (6,8), (7,9). So (4,6) stayed and extended?
        *   Let's re-read the metaphor: "Each escaped harmonic ascends step by step along its own diagonal staircase... until it reaches the edge".
        *   "Ascends" usually means going up. But in Example 1, one goes up (1,6 -> 0,7) and one goes down (4,6 -> 5,7 -> 6,8 -> 7,9).
        *   Maybe "ascends" refers to the pitch (frequency), not spatial Y-axis. Or maybe "staircase" implies direction.
        *   Let's look at the "stray harmonics vibrating at its diagonal edges".
        *   In Input 1:
            *   (1,6) is adjacent diagonally to (2,5). (2,5) is top-right of the 2x2 block. So (1,6) is "above-right" of the block.
            *   (4,6) is adjacent diagonally to (3,5). (3,5) is bottom-right of the 2x2 block. So (4,6) is "below-right" of the block.
        *   In Output 1:
            *   The pixel at (1,6) seems to have generated a trail going Up-Right: (0,7). The original (1,6) remains.
            *   The pixel at (4,6) seems to have generated a trail going Down-Right: (5,7), (6,8), (7,9). The original (4,6) remains.
        *   So the rule seems to be: Identify the "stray" pixels connected diagonally to the main body. Extend them diagonally away from the body until the grid edge.
        *   Direction for (1,6): It is at the top-right corner of the shape. It extends Up-Right (row decreases, col increases).
        *   Direction for (4,6): It is at the bottom-right corner of the shape. It extends Down-Right (row increases, col increases).
        *   Why did (1,6) only go one step? Because (0,7) is the edge.
        *   Why did (4,6) go multiple steps? Because it started at row 4, and went to row 9 (edge).
        *   Wait, looking at Output 1 again.
        *   Row 0: `.......Y..` (0,7)
        *   Row 1: `......Y...` (1,6)
        *   Row 2: `....YY....`
        *   Row 3: `....YY....`
        *   Row 4: `......Y...` (4,6)
        *   Row 5: `.......Y..` (5,7)
        *   Row 6: `........Y.` (6,8)
        *   R

... [7177 chars truncated]
alt-4 sports qwen3.5-122b: k=2
"A rugby scrum holds firm at the center, but breakaway runners have already peeled off at the corners, sprinting diagonally toward the try line without looking back."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10981 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scenario:** A "tight pack of players forms the scrum" (a cluster of colored pixels).
*   **Scenario:** "Individual runners positioned just off certain corners" (specific pixels adjacent to the cluster).
*   **Action:** "Each breakaway runner continues their sprint diagonally away from the pack, covering one yard per stride, until they reach the sideline or end zone."
*   **Grid:** 10x10 pitch.
*   **Colors:** Players are one team color on black turf (black is '.').

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** A cluster of 'Y' (yellow) pixels.
        *   Row 1: (1, 6) -> Y
        *   Row 2: (2, 4), (2, 5) -> Y
        *   Row 3: (3, 4), (3, 5) -> Y
        *   Row 4: (4, 6) -> Y
        *   Wait, let's look at coordinates (row, col) 0-indexed.
        *   Input Y positions:
            *   (1, 6)
            *   (2, 4), (2, 5)
            *   (3, 4), (3, 5)
            *   (4, 6)
        *   This looks like a diamond or a cross shape.
            *   (1,6)
            *   (2,4), (2,5)
            *   (3,4), (3,5)
            *   (4,6)
        *   Actually, let's look closer.
            *   Row 1: . . . . . . Y . . . (Index 6)
            *   Row 2: . . . . Y Y . . . . (Index 4, 5)
            *   Row 3: . . . . Y Y . . . . (Index 4, 5)
            *   Row 4: . . . . . . Y . . . (Index 6)
        *   This forms a shape.
    *   **Output:**
        *   The original 'Y' cluster remains.
        *   New 'Y' pixels appear.
        *   Row 0: . . . . . . . Y . . (Index 7) -> Wait, looking at the output provided in the prompt.
        *   Output Row 0: . . . . . . . Y . . (Index 7)
        *   Output Row 1: . . . . . . Y . . . (Index 6) - Original
        *   Output Row 2: . . . . Y Y . . . . (Index 4, 5) - Original
        *   Output Row 3: . . . . Y Y . . . . (Index 4, 5) - Original
        *   Output Row 4: . . . . . . Y . . . (Index 6) - Original
        *   Output Row 5: . . . . . . . Y . . (Index 7)
        *   Output Row 6: . . . . . . . . Y . (Index 8)
        *   Output Row 7: . . . . . . . . . Y (Index 9)
        *   Output Row 8: . . . . . . . . . .
        *   Output Row 9: . . . . . . . . . .
    *   **Observation:**
        *   There is a "pack" in the middle (Rows 2-3, Cols 4-5).
        *   There are "runners" at (1, 6) and (4, 6).
        *   Wait, the output shows a trail extending from (1, 6) upwards? No, (0, 7) is above (1, 6).
        *   Let's check the trail direction.
        *   From (1, 6), a trail goes to (0, 7). That is Up-Right (North-East).
        *   From (4, 6), a trail goes to (5, 7), (6, 8), (7, 9). That is Down-Right (South-East).
        *   Why these directions?
        *   The "pack" is roughly centered around rows 2-3, cols 4-5.
        *   The pixel at (1, 6) is Top-Right relative to the pack. It moves further Top-Right.
        *   The pixel at (4, 6) is Bottom-Right relative to the pack. It moves further Bottom-Right.
        *   Wait, let's look at the shape again.
        *   Input:
            *   (1, 6)
            *   (2, 4), (2, 5)
            *   (3, 4), (3, 5)
            *   (4, 6)
        *   The "pack" seems to be the 2x2 block at (2,4)-(3,5).
        *   The "runners" are the single pixels attached to the corners of this block.
        *   (1, 6) is attached to the top-right corner (2, 5)? No, (2, 5) is adjacent to (1, 5) and (2, 6). (1, 6) is diagonal to (2, 5).
        *   (4, 6) is diagonal to (3, 5).
        *   So the "runners" are the pixels that are diagonally adjacent to the main 2x2 block?
        *   Let's check Example 2.

*   **Example 2:**
    *   **Input:**
        *   Row 2: . . G G . . . . . . (Indices 2, 3)
        *   Row 3: . . G G . . . . . . (Indices 2, 3)
        *   Row 4: . . . . G . . . . . (Index 4)
        *   Wait, let's map coordinates.
        *   (2, 2), (2, 3)
        *   (3, 2), (3, 3)
        *   (4, 4)
    *   **Output:**
        *   Original G's remain.
        *   New G's appear at:
            *   (5, 5)
            *   (6, 6)
            *   (7, 7)
            *   (8, 8)
            *   (9, 9)
    *   **Observation:**
        *   Pack: 2x2 block at (2,2)-(3,3).
        *   Runner: Single pixel at (4, 4).
        *   (4, 4) is diagonally adjacent to the bottom-right corner of the pack (3, 3).
        *   The trail extends from (4, 4) in the same diagonal direction (Down-Right / South-East) until the edge of the grid.
        *   (4, 4) -> (5, 5) -> (6, 6) -> (7, 7) -> (8, 8) -> (9, 9).

*   **Re-evaluating Example 1:**
    *   Pack: 2x2 block at (2,4)-(3,5).
    *   Runners:
        *   (1, 6): This is Top-Right relative to the pack. Specifically, it's diagonal to (2, 5).
        *   (4, 6): This is Bottom-Right relative to the pack. Specifically, it's diagonal to (3, 5).
    *   Trails:
       

... [6056 chars truncated]
alt-5 weather qwen3.5-122b: k=2
"The eye of the storm is eerily calm, but at certain edges the wind has already found a crack, and it spirals outward in straight jets toward the horizon."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10136 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A dense pressure center sits in the grid with wisps of wind already escaping at diagonal gaps."
*   "Each wisp extends into a jet stream, pushing one cell diagonally per step away from the eye until it dissipates at the grid's edge."
*   "Grid details: 10x10 dark sky, storm material in a single color."

Interpretation:
*   "Dense pressure center": This likely refers to a cluster of colored cells in the input grid.
*   "Wisps of wind already escaping at diagonal gaps": This suggests there are specific cells in the cluster that act as starting points for lines.
*   "Extends into a jet stream": Lines are drawn from these starting points.
*   "Pushing one cell diagonally per step away from the eye": The lines go diagonally outwards.
*   "Until it dissipates at the grid's edge": The lines stop when they hit the boundary.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
. . . . . . . . . .
. . . . . . Y . . .
. . . . Y Y . . . .
. . . . Y Y . . . .
. . . . . . Y . . .
. . . . . . . . . .
. . . . . . . . . .
. . . . . . . . . .
. . . . . . . . . .
. . . . . . . . . .
```
The colored cells (Y) form a shape.
Let's look at the coordinates (row, col) 0-indexed.
(1, 6)
(2, 4), (2, 5)
(3, 4), (3, 5)
(4, 6)

Output:
```
. . . . . . . Y . .
. . . . . . Y . . .
. . . . Y Y . . . .
. . . . Y Y . . . .
. . . . . . Y . . .
. . . . . . . Y . .
. . . . . . . . Y .
. . . . . . . . . Y
. . . . . . . . . .
. . . . . . . . . .
```
Changes:
New Y's appear at:
(0, 7)
(5, 7)
(6, 8)
(7, 9)

Let's trace the lines.
The original shape looks like a diamond or a cross with a hole?
(1,6), (2,4), (2,5), (3,4), (3,5), (4,6).
It looks like two 2x2 blocks shifted? No.
(2,4)-(3,5) is a 2x2 block.
(1,6) is top right of that block? No, (1,6) is above (2,6) which is empty.
(4,6) is below (3,6) which is empty.
Actually, let's look at the "diagonal gaps".
The 2x2 block is at rows 2-3, cols 4-5.
The single cells are at (1,6) and (4,6).
Wait, looking at the output, the new cells form a diagonal line going down-right from (1,6)?
(1,6) -> (0,7)? No, (0,7) is up-right from (1,6).
(1,6) -> (2,7)? No.
Let's look at the new cells: (0,7), (5,7), (6,8), (7,9).
(0,7) is diagonal from (1,6). Direction: Up-Right (-1, +1).
(5,7) is diagonal from (4,6). Direction: Down-Right (+1, +1).
(6,8) is diagonal from (5,7).
(7,9) is diagonal from (6,8).

So, it seems specific "corner" cells of the shape emit diagonal lines.
Which cells?
(1,6) emitted Up-Right.
(4,6) emitted Down-Right.
Why these?
Maybe they are the "tips" of the shape?
The shape is somewhat symmetric around the vertical axis between col 4 and 5? No.
Let's look at the shape again.
Row 1: . . . . . . Y . . . (Col 6)
Row 2: . . . . Y Y . . . . (Col 4, 5)
Row 3: . . . . Y Y . . . . (Col 4, 5)
Row 4: . . . . . . Y . . . (Col 6)

It looks like a 'C' shape or a bracket facing left? Or a diamond missing the left side?
Actually, it looks like a 2x2 square at (2,4)-(3,5) with two cells attached at (1,6) and (4,6).
The cells (1,6) and (4,6) are the ones that extend.
(1,6) extends Up-Right to (0,7).
(4,6) extends Down-Right to (5,7), (6,8), (7,9).

Why Up-Right for (1,6)?
Why Down-Right for (4,6)?
Maybe it depends on the "gap".
(1,6) has neighbors (2,5) (diagonal down-left).
(4,6) has neighbors (3,5) (diagonal up-left).
The "wind" escapes at diagonal gaps.
Maybe the direction is determined by the empty space adjacent diagonally?
Or maybe it's about the "outermost" corners.
(1,6) is the top-most right-most cell.
(4,6) is the bottom-most right-most cell.
They extend away from the center of the mass?
Center of mass roughly at (2.5, 4.5).
(1,6) is Top-Right relative to center. Extends Up-Right.
(4,6) is Bottom-Right relative to center. Extends Down-Right.

**Example 2:**
Input:
```
. . . . . . . . . .
. . . . . . . . . .
. . G G . . . . . .
. . G G . . . . . .
. . . . G . . . . .
. . . . . . . . . .
. . . . . . . . . .
. . . . . . . . . .
. . . . . . . . . .
. . . . . . . . . .
```
Colored cells (G):
(2, 2), (2, 3)
(3, 2), (3, 3)
(4, 4)

Shape: 2x2 block at top-left (2,2)-(3,3) and a single cell at (4,4).
Output:
```
. . . . . . . . . .
. . . . . . . . . .
. . G G . . . . . .
. . G G . . . . . .
. . . . G . . . . .
. . . . . G . . . .
. . . . . . G . . .
. . . . . . . G . .
. . . . . . . . G .
. . . . . . . . . G
```
New cells:
(5, 5)
(6, 6)
(7, 7)
(8, 8)
(9, 9)

These form a diagonal line starting from (4,4) going Down-Right.
(4,4) -> (5,5) -> ... -> (9,9).
The 2x2 block at (2,2)-(3,3) does not emit anything.
Why?
In Example 1, the 2x2 block didn't emit. The single cells attached to it did.
In Example 2, the 2x2 block didn't emit. The single cell attached to it did.
So the rule seems to be: Identify "tip" cells or "protruding" cells.
In Ex 1, (1,6) and (4,6) are tips.
In Ex 2, (4,4) is a tip.
How to define a tip?
Maybe cells that

... [5193 chars truncated]
alt-6 architecture qwen3.5-122b: fig alone solves
"Flying buttresses spring from the corners of a cathedral tower, each one arching diagonally outward to brace against the distant foundation wall."
alt-7 warfare qwen3.5-122b: fig alone solves
"A fortress holds the center, but sappers have already breached at the corners and now tunnel outward, digging one trench segment per day until they reach the battlefield's edge."
alt-8 theater qwen3.5-122b: fail
"The lead actors hold their positions at center stage, but spotlight operators have caught a cue—each beam slides diagonally toward the wings, illuminating one floor tile at a time."
Fail (best cell_acc=0.27 at k=1)
Best Attempt
vs
Expected
Reasoning (11574 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A cluster of actors stands together.
*   **Initial State:** Individual spotlights are already hitting the floor at certain diagonal corners of the group.
*   **Action:** Each spotlight glides away from center stage along its diagonal, marking one tile per beat, until it reaches the edge of the stage.
*   **Grid:** 10x10 dark stage (black background).
*   **Color:** All lit areas are in a single color.

**2. Analyze the Training Example:**
*   **Input:**
    *   Background: `.` (black)
    *   Object: A cluster of `Y` (yellow) pixels.
    *   Shape of cluster:
        ```
        . . . . . . . . . .
        . . . . . . Y . . .  (Row 1, Col 6)
        . . . . Y Y . . . .  (Row 2, Col 4, 5)
        . . . . Y Y . . . .  (Row 3, Col 4, 5)
        . . . . . . Y . . .  (Row 4, Col 6)
        . . . . . . . . . .
        ...
        ```
        Wait, let's look closer at the input grid coordinates (0-indexed).
        Row 1: `Y` at index 6.
        Row 2: `Y` at indices 4, 5.
        Row 3: `Y` at indices 4, 5.
        Row 4: `Y` at index 6.
        This looks like a diamond or a cross shape, but specifically:
        (1,6), (2,4), (2,5), (3,4), (3,5), (4,6).
        Actually, looking at the pattern:
        Row 1: `......Y...`
        Row 2: `....YY....`
        Row 3: `....YY....`
        Row 4: `......Y...`
        It looks like a shape.
    *   "Spotlights already hitting the floor at certain diagonal corners of the group."
        In the input, there are no extra pixels outside the main cluster. The description says "spotlights already hitting the floor". This might imply the existing pixels *are* the spotlights or the cluster *is* the actors.
        Let's look at the Output.
*   **Output:**
    *   The original cluster remains.
    *   New `Y` pixels appear.
    *   Let's trace the new pixels.
        Row 0: `.......Y..` (Index 7)
        Row 1: `......Y...` (Index 6 - Original)
        Row 2: `....YY....` (Indices 4, 5 - Original)
        Row 3: `....YY....` (Indices 4, 5 - Original)
        Row 4: `......Y...` (Index 6 - Original)
        Row 5: `.......Y..` (Index 7)
        Row 6: `........Y.` (Index 8)
        Row 7: `.........Y` (Index 9)
        Row 8: `..........`
        Row 9: `..........`
    *   Wait, let's re-examine the Input vs Output carefully.
    *   Input Row 1: `......Y...` (Col 6)
    *   Output Row 0: `.......Y..` (Col 7)
    *   Output Row 1: `......Y...` (Col 6)
    *   Output Row 2: `....YY....` (Col 4, 5)
    *   Output Row 3: `....YY....` (Col 4, 5)
    *   Output Row 4: `......Y...` (Col 6)
    *   Output Row 5: `.......Y..` (Col 7)
    *   Output Row 6: `........Y.` (Col 8)
    *   Output Row 7: `.........Y` (Col 9)
    *   It seems like a diagonal line is being extended.
    *   Where does it start?
    *   The "cluster" is the group of actors.
    *   The "spotlights" are the pixels extending from the cluster.
    *   In the Input, there is a `Y` at (1,6) and (4,6).
    *   In the Output, there is a diagonal line going from (1,6) upwards-right to (0,7)? No, (0,7) is top-right of (1,6).
    *   And a diagonal line going from (4,6) downwards-right to (5,7), (6,8), (7,9).
    *   Let's check the coordinates again.
    *   Input `Y`s: (1,6), (2,4), (2,5), (3,4), (3,5), (4,6).
    *   Output `Y`s:
        (0,7) - New
        (1,6) - Old
        (2,4), (2,5) - Old
        (3,4), (3,5) - Old
        (4,6) - Old
        (5,7) - New
        (6,8) - New
        (7,9) - New
    *   It looks like the pixels at (1,6) and (4,6) are the "corners" from which spotlights emanate.
    *   (1,6) is the top-most pixel of the right side of the cluster.
    *   (4,6) is the bottom-most pixel of the right side of the cluster.
    *   The spotlight from (1,6) goes Up-Right: (0,7).
    *   The spotlight from (4,6) goes Down-Right: (5,7), (6,8), (7,9).
    *   Why Up-Right and Down-Right?
    *   The metaphor says: "Each spotlight glides away from center stage along its diagonal".
    *   "Center stage" usually implies the center of the grid or the center of the cluster.
    *   If the cluster is the "actors", the "spotlights" are the extensions.
    *   In the input, the extensions are not there yet (or maybe the single pixels at the tips are the start of the spotlights?).
    *   Actually, the input has the cluster. The output has the cluster + extensions.
    *   The extensions form diagonal lines.
    *   One line goes from (1,6) to (0,7). Direction: (-1, +1).
    *   One line goes from (4,6) to (7,9). Direction: (+1, +1).
    *   Both go towards the right edge (increasing column index).
    *   One goes up, one goes down.
    *   This suggests the "spotlights" originate from the right-most points of the cluster and project outwards diagonally away from the center of the cluster (vertically).
    *   Or, they project towards the

... [6607 chars truncated]
alt-9 gardening qwen3.5-122b: fail
"A mature shrub sits in the garden bed, and runners have already sprouted from certain root nodes, creeping diagonally across the soil toward the garden fence."
Fail (best cell_acc=0.27 at k=2)
Best Attempt
vs
Expected
Reasoning (12511 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A dense root ball forms a square mass, with runner shoots emerging at diagonal corners."
    *   This suggests there is a central square block of a specific color (the "root ball").
    *   There are "runner shoots" emerging from the corners of this square.
*   "Each runner extends one node at a time along its diagonal path, growing steadily until it reaches the edge of the garden bed."
    *   This implies a growth process.
    *   The "runners" are lines of the same color extending diagonally from the corners of the square mass.
    *   They grow until they hit the boundary of the grid.
*   "Grid details: 10x10 dark soil, all plant matter in one color."
    *   Background is black (`.`).
    *   The object is a single color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:**
        *   A 2x2 square of Yellow (`Y`) at rows 2-3, cols 4-5 (0-indexed: rows 1-2, cols 4-5? Let's check indices).
        *   Row 1: `... Y ...` (col 5)
        *   Row 2: `.. Y Y ..` (cols 4, 5)
        *   Row 3: `.. Y Y ..` (cols 4, 5)
        *   Row 4: `... Y ...` (col 5)
        *   Wait, let's look closer at the input grid for Example 1.
        *   Row 0: `..........`
        *   Row 1: `.....Y....` (Y at index 5)
        *   Row 2: `....YY....` (Y at 4, 5)
        *   Row 3: `....YY....` (Y at 4, 5)
        *   Row 4: `.....Y....` (Y at 5)
        *   This looks like a diamond shape or a cross, not a square mass.
        *   Let's re-read the input carefully.
        *   Input:
            ```
            . . . . . . . . . .
            . . . . . . Y . . .
            . . . . Y Y . . . .
            . . . . Y Y . . . .
            . . . . . . Y . . .
            . . . . . . . . . .
            ...
            ```
        *   The "square mass" description in the prompt might be slightly metaphorical or referring to the core. The core here is the 2x2 block of Ys at (2,4), (2,5), (3,4), (3,5).
        *   There are single Ys at (1,5) and (4,5). These look like "shoots" emerging from the top-right and bottom-right corners of the 2x2 block?
        *   Actually, (1,5) is above (2,5). (4,5) is below (3,5).
        *   Wait, the output shows diagonal lines.
        *   Output:
            ```
            . . . . . . . Y . .
            . . . . . . Y . . .
            . . . . Y Y . . . .
            . . . . Y Y . . . .
            . . . . . . Y . . .
            . . . . . . . Y . .
            . . . . . . . . Y .
            . . . . . . . . . Y
            . . . . . . . . . .
            . . . . . . . . . .
            ```
        *   The 2x2 block remains at (2,4)-(3,5).
        *   There is a diagonal line going up-right from the top-right corner of the 2x2 block?
            *   Top-right of 2x2 is (2,5).
            *   Output has Y at (1,6), (0,7).
            *   Wait, Input had Y at (1,5). Output has Y at (1,6).
            *   Input had Y at (4,5). Output has Y at (5,6), (6,7), (7,8).
        *   Let's look at the "shoots" in the input again.
            *   Input has Y at (1,5). This is directly above the top-right corner (2,5).
            *   Input has Y at (4,5). This is directly below the bottom-right corner (3,5).
            *   Wait, looking at the input grid text provided in the prompt:
                Row 1: `.....Y....` (Index 5)
                Row 2: `....YY....` (Indices 4, 5)
                Row 3: `....YY....` (Indices 4, 5)
                Row 4: `.....Y....` (Index 5)
            *   This forms a shape like a vertical line of 3 with a horizontal bar in the middle? No, it's a 2x2 square with one pixel above the right column and one pixel below the right column.
            *   Actually, it looks like a 2x2 square at rows 2-3, cols 4-5.
            *   Plus a pixel at (1,5) and (4,5).
            *   So the "root ball" is the 2x2 square. The "shoots" are the pixels at (1,5) and (4,5).
            *   Wait, the metaphor says "runner shoots emerging at diagonal corners".
            *   In the output, we see diagonal lines extending from the corners of the 2x2 square.
            *   Top-Right corner of 2x2 is (2,5). The line goes (1,6), (0,7).
            *   Bottom-Right corner of 2x2 is (3,5). The line goes (4,6), (5,7), (6,8), (7,9).
            *   Wait, the input had pixels at (1,5) and (4,5). These are *not* on the diagonal path from the corners (2,5) and (3,5).
            *   (1,5) is North of (2,5). (4,5) is South of (3,5).
            *   The output *replaces* or *extends* these?
            *   In the output, (1,5) is gone. (4,5) is gone.
            *   Instead, we have (1,6), (0,7) and (4,6), (5,7), (6,8), (7,9).
            *   This suggests the input pixels at (1,5) and (4,5) indicate the *direction* or *presence* of a runner, but the runner actually grows diagonally from the corner of the square.
      

... [7523 chars truncated]

Task 488: 834ec97d

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A beacon sinks one step into the earth, and its light rains upward in alternatin ... [49 chars truncated] MARC valid 1
alt-1 biology A single spore settles one layer deeper into the tissue, and from where it was, ... [96 chars truncated] fig alone solves
alt-10 astronomy A lone star collapses one shell inward, and the radiation it shed fans outward t ... [94 chars truncated] fig alone solves
alt-11 ocean/sailing An anchor drags one fathom deeper, and above where it caught, phosphorescent tid ... [89 chars truncated] MARC valid 2
alt-12 electronics A charged component drops to the next bus line, and above its former trace, curr ... [116 chars truncated] fig alone solves
alt-13 mythology A fallen god descends one step into the underworld, and from the threshold they ... [91 chars truncated] MARC valid 2
alt-14 dance The soloist glides one step downstage, and in their wake every other floor light ... [96 chars truncated] fig alone solves
alt-15 geology A mineral deposit subsides one stratum, and above the fault line it left, veins ... [109 chars truncated] fail
alt-2 cooking A single raisin sinks to the next layer of batter, and above where it rested, sa ... [83 chars truncated] MARC valid 2
alt-3 music A struck note descends one step on the staff, and its overtones shimmer upward t ... [91 chars truncated] fail
alt-4 sports A lone player drops back one yard, and the floodlights above their former positi ... [109 chars truncated] MARC valid 3
alt-5 weather A single ember drifts one notch closer to the ground, and above its old altitude ... [99 chars truncated] MARC valid 1
alt-6 architecture A cornerstone is lowered one course, and above where it was laid, golden pillars ... [96 chars truncated] fail
alt-7 warfare A general retreats one trench line, and from the abandoned position upward, sign ... [99 chars truncated] MARC valid 1
alt-8 theater The lead actor steps downstage by one mark, and the spotlight grid above their f ... [102 chars truncated] fig alone solves
alt-9 gardening A bulb is pressed one inch deeper into the soil, and from where it rested, golde ... [101 chars truncated] fig alone solves
original qwen3.5-122b: k=1
"A beacon sinks one step into the earth, and its light rains upward in alternating columns like prison bars against the night sky."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11207 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A single beacon glows alone in a dark field". This implies there is one distinct object (the beacon) in a background of black (.) cells.
*   **Action:** "The beacon is heavy; it sinks one step deeper into the ground." This suggests the beacon moves down by one row.
*   **Effect:** "As it falls, it casts its light upward like rain falling in reverse, illuminating every other column above where it once stood".
    *   "Casts its light upward": The effect happens in the rows *above* the beacon's position.
    *   "Every other column": This implies a pattern of columns. If the beacon is at column $c$, the light affects columns $c, c-2, c+2, c-4, c+4, \dots$ (columns with the same parity as $c$).
    *   "Golden bars of light": The color of the light is Yellow (Y).
    *   "The columns that catch the light share a kinship with the beacon's own column, stepping in rhythm with it (every other one)": Confirms the parity rule.
    *   "The sky above fills with these golden stripes, but the darkness below the beacon remains untouched": The transformation only affects rows *above* the beacon's final position. The rows below or at the beacon's position (except the beacon itself) remain black.
*   **Beacon Identity:** "The beacon itself keeps its original color and identity."
*   **Grid Details:** Dark field = black (.). Beacon's rain = yellow (Y).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . .
    . . . . .
    . . M . .
    . . . . .
    . . . . .
    ```
    *   Grid size: 5x5.
    *   Beacon: 'M' (Magenta) at row 2, column 2 (0-indexed). Let's check indices.
        *   Row 0: . . . . .
        *   Row 1: . . . . .
        *   Row 2: . . M . .  -> Row index 2, Col index 2.
        *   Row 3: . . . . .
        *   Row 4: . . . . .
*   **Output:**
    ```
    Y . Y . Y
    Y . Y . Y
    Y . Y . Y
    . . M . .
    . . . . .
    ```
    *   Beacon 'M' is now at Row 3, Column 2.
    *   Wait, the description says "sinks one step deeper". In the input, M was at Row 2. In the output, M is at Row 3. So it moved down by 1.
    *   The "light" (Y) appears in rows *above* the beacon's *new* position? Or *old* position?
    *   Let's look at the output rows.
        *   Row 0: Y . Y . Y
        *   Row 1: Y . Y . Y
        *   Row 2: Y . Y . Y
        *   Row 3: . . M . .  (Beacon is here)
        *   Row 4: . . . . .
    *   The beacon moved from (2, 2) to (3, 2).
    *   The yellow stripes are in rows 0, 1, 2. These are the rows *above* the beacon's new position (Row 3).
    *   The columns with Y are 0, 2, 4. The beacon is at column 2. So columns with the same parity as the beacon's column (even columns) are filled with Y.
    *   The rows affected are all rows strictly above the beacon's final row.
    *   The beacon's original position (2, 2) is now part of the "sky" (Row 2), so it gets painted Y? Yes, Row 2 Col 2 is Y in the output. Wait, looking closely at the output provided in the prompt:
        Output Row 2: `Y . Y . Y`.
        So the cell (2, 2) which was 'M' in input is now 'Y' in output?
        Let's re-read the output grid provided in the prompt carefully.
        Output:
        Row 0: Y . Y . Y
        Row 1: Y . Y . Y
        Row 2: Y . Y . Y
        Row 3: . . M . .
        Row 4: . . . . .
        
        In the input, M was at (2, 2).
        In the output, M is at (3, 2).
        So the beacon moved down.
        The cell (2, 2) is now Y. This means the original position of the beacon is overwritten by the light pattern because it is now "above" the beacon's resting place.
        The description says: "The sky above fills with these golden stripes... Only the sky above the beacon's resting place is painted".
        So, if the beacon rests at row $R_{final}$, all rows $r < R_{final}$ are painted.
        The columns painted are those where $c \equiv c_{beacon} \pmod 2$.
        The beacon itself stays at $(R_{final}, c_{beacon})$.
        Everything else remains black (.).

**3. Conceptual Digestion:**

1.  **Identify the CAST:**
    *   **Background:** Black cells (.).
    *   **Beacon:** A single non-black cell (in Example 1, it's 'M'). In the Test Input, it's 'G' (Green).
    *   **Light:** Yellow cells (Y).

2.  **Identify the AFFORDANCES:**
    *   The Beacon can move down by 1 row.
    *   The Beacon defines a column index ($c_{beacon}$).
    *   The Beacon defines a final row index ($r_{beacon\_final} = r_{beacon\_initial} + 1$).
    *   The Light can fill cells with color Y.
    *   The Light is constrained to rows above the final beacon position.
    *   The Light is constrained to columns with the same parity as the beacon's column.

3.  **Identify the TRANSFORMATION RULE:**
    *   Locate the unique non-black cell (the Beacon) in the input grid. Let its coordinates be $(r_{start}, c_

... [6267 chars truncated]
alt-1 biology qwen3.5-122b: fig alone solves
"A single spore settles one layer deeper into the tissue, and from where it was, hyphae streak upward through every other vein, staining them gold as they reach for the surface."
alt-10 astronomy qwen3.5-122b: fig alone solves
"A lone star collapses one shell inward, and the radiation it shed fans outward through every other spoke of the nebula, painting them gold from the core to the outermost rim."
alt-11 ocean/sailing qwen3.5-122b: k=2
"An anchor drags one fathom deeper, and above where it caught, phosphorescent tides glow gold through every other channel from the surface down to the anchor's old depth."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (12366 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark sea with a single colored anchor at some depth."
    *   "Dark sea" implies a black background (`.`).
    *   "Single colored anchor" implies a single non-black pixel of a specific color.
    *   "At some depth" implies a specific row index.
*   **Action:** "The anchor sinks one level."
    *   The anchor moves down by one row.
*   **Action:** "Golden bioluminescence fills alternating water columns from the surface down to where the anchor previously rested."
    *   "Golden bioluminescence" implies Yellow (`Y`).
    *   "Alternating water columns" implies every other column (e.g., 0, 2, 4... or 1, 3, 5...).
    *   "From the surface down to where the anchor previously rested" implies filling rows from 0 up to the anchor's *original* row index.
*   **Grid details:**
    *   "Dimensions unchanged."
    *   "Black background."
    *   "Anchor color one row lower."
    *   "Yellow in same-parity columns from row zero through the anchor's original row."

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 5x5 grid. Anchor is Magenta (`M`) at row 2, col 2 (0-indexed).
        ```
        . . . . .
        . . . . .
        . . M . .
        . . . . .
        . . . . .
        ```
    *   Output:
        ```
        Y . Y . Y
        Y . Y . Y
        Y . Y . Y
        . . M . .
        . . . . .
        ```
    *   Observation:
        *   Anchor `M` moved from (2, 2) to (3, 2). It sank one level.
        *   Yellow `Y` appears in columns 0, 2, 4 (even columns).
        *   Yellow `Y` appears in rows 0, 1, 2.
        *   Row 3 and 4 are empty (except for the moved anchor).
        *   The anchor's original position was row 2. The yellow fills rows 0 to 2.
        *   The columns filled are 0, 2, 4. These are the same parity as the anchor's column (2 is even).
        *   Wait, let's check the parity rule. Anchor col is 2 (even). Yellow cols are 0, 2, 4 (even).
        *   Let's check Example 2 to confirm.

*   **Example 2:**
    *   Input: 3x3 grid. Anchor is Red (`R`) at row 1, col 1.
        ```
        . R .
        . . .
        . . .
        ```
    *   Output:
        ```
        . Y .
        . R .
        . . .
        ```
    *   Observation:
        *   Anchor `R` moved from (1, 1) to (2, 1). It sank one level.
        *   Yellow `Y` appears in column 1.
        *   Yellow `Y` appears in row 0.
        *   Anchor's original row was 1. Yellow fills rows 0 to 1?
        *   Wait, in the output, row 1 has the anchor `R` at (1,1) in the *input*, but in the *output*, the anchor is at (2,1).
        *   Let's look at the output grid again.
        *   Output Row 0: `. Y .` -> Col 1 is Yellow.
        *   Output Row 1: `. R .` -> Col 1 is Red (Anchor).
        *   Output Row 2: `. . .` -> Empty.
        *   Wait, the description says "Anchor sinks one level".
        *   Input Anchor: (1, 1). Output Anchor: (2, 1). This matches "sinks one level".
        *   Description says "Yellow in same-parity columns from row zero through the anchor's original row."
        *   Anchor original row: 1.
        *   Anchor original col: 1 (odd).
        *   Yellow should be in odd columns (1) from row 0 to row 1.
        *   Let's check the output provided in Example 2.
        *   Output Row 0: `. Y .` (Col 1 is Y).
        *   Output Row 1: `. R .` (Col 1 is R).
        *   Wait, if the anchor sinks to row 2, why is there an `R` at row 1 in the output?
        *   Let's re-read the output for Example 2 carefully.
        *   Input:
            ```
            . R .
            . . .
            . . .
            ```
        *   Output:
            ```
            . Y .
            . R .
            . . .
            ```
        *   If the anchor sinks one level, it should go from (1,1) to (2,1).
        *   In the output, the `R` is at (1,1).
        *   This contradicts "Anchor sinks one level".
        *   Let's re-read the metaphorical description again. "The anchor sinks one level."
        *   Let's look at Example 1 again.
        *   Input Anchor: (2, 2). Output Anchor: (3, 2). This matches "sinks one level".
        *   Why does Example 2 look different?
        *   Input:
            ```
            . R .
            . . .
            . . .
            ```
        *   Output:
            ```
            . Y .
            . R .
            . . .
            ```
        *   In Example 2, the `R` stays at (1,1).
        *   Is it possible the description "Anchor sinks one level" applies to the *visual* effect or is there a nuance?
        *   Or maybe I am misinterpreting the output of Example 2.
        *   Let's check the text provided in the prompt for Example 2 Output.
        *   Output:
            ```
            . Y .
            . R .
            . . .
            ```
        *   If the anchor was

... [7387 chars truncated]
alt-12 electronics qwen3.5-122b: fig alone solves
"A charged component drops to the next bus line, and above its former trace, current surges through every other wire in the ribbon cable, glowing gold from the header to the component's old socket."
alt-13 mythology qwen3.5-122b: k=2
"A fallen god descends one step into the underworld, and from the threshold they left, golden chains hang from the heavens through every other pillar of the celestial gate."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11018 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A dark realm with one uniquely colored divine figure at a position." -> The input grid has a black background (.) and one non-black pixel (the "figure").
*   "The figure descends one level." -> The figure moves down by one row.
*   "Golden chains appear in alternating pillars stretching from the highest heaven down to the threshold the figure just vacated." -> "Golden chains" likely refers to Yellow (Y). "Alternating pillars" suggests columns. "Highest heaven" is the top row. "Threshold the figure just vacated" is the original row of the figure. So, Yellow pixels appear in specific columns from the top row down to the original row of the figure.
*   "Grid details: Dimensions match. Black background. Figure's color one row below origin. Yellow in same-parity columns, top row through figure's original row inclusive." -> This clarifies the metaphor.
    *   Dimensions: Same as input.
    *   Background: Black (.).
    *   Figure: Moves down one row (row index + 1).
    *   Yellow (Y): Appears in columns with the same parity as the figure's column. Range: From row 0 (top) to the figure's *original* row (inclusive).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 5x5 grid. Figure 'M' (magenta) at (2, 2) (0-indexed: row 2, col 2).
    *   Output:
        *   Figure 'M' is now at (3, 2). (Moved down 1 row).
        *   Yellow 'Y' appears in columns 0, 2, 4. (Same parity as col 2).
        *   Yellow 'Y' appears in rows 0, 1, 2. (From top to original row 2).
        *   Row 3 and 4 are mostly black, except the figure at (3,2).
        *   Wait, let's check the output grid provided:
            Y . Y . Y
            Y . Y . Y
            Y . Y . Y
            . . M . .
            . . . . .
        *   Original Figure Position: (2, 2).
        *   New Figure Position: (3, 2).
        *   Yellow Columns: 0, 2, 4. (Even columns, matching col 2).
        *   Yellow Rows: 0, 1, 2. (Top to original row).
        *   This matches the description perfectly.

*   **Example 2:**
    *   Input: 3x3 grid. Figure 'R' (red) at (1, 1).
    *   Output:
        *   Figure 'R' is now at (2, 1). (Moved down 1 row).
        *   Yellow 'Y' appears in column 1. (Same parity as col 1).
        *   Yellow 'Y' appears in rows 0, 1. (Top to original row 1).
        *   Output grid:
            . Y .
            . R .
            . . .
        *   Wait, looking at the provided output for Example 2:
            . Y .
            . R .
            . . .
        *   Original Figure Position: (1, 1).
        *   New Figure Position: (2, 1).
        *   Yellow Columns: 1. (Odd columns, matching col 1).
        *   Yellow Rows: 0, 1. (Top to original row 1).
        *   This matches the description perfectly.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Background:** Black pixels (.).
    *   **Divine Figure:** The single non-black pixel in the input grid. Let's call its color $C$ and position $(r, c)$.
    *   **Golden Chains:** Yellow pixels (Y).

2.  **AFFORDANCES:**
    *   The Figure can move.
    *   The Figure leaves a trail or triggers a pattern (Yellow pillars).
    *   The Grid boundaries constrain the movement and pattern.

3.  **TRANSFORMATION RULE:**
    *   Find the coordinates $(r, c)$ of the unique non-black pixel in the input grid. Let its color be $C$.
    *   Create an output grid of the same dimensions, initialized with black (.).
    *   Place the Figure $C$ at position $(r+1, c)$. (If $r+1$ is out of bounds, presumably it stays or wraps, but examples show valid moves. In Example 1, $r=2 \to 3$. In Example 2, $r=1 \to 2$. The grid height is 5 and 3 respectively. So $r+1$ is valid).
    *   For every column $j$ such that $j \equiv c \pmod 2$ (same parity as the figure's column):
        *   For every row $i$ from $0$ to $r$ (inclusive):
            *   Set pixel $(i, j)$ to Yellow (Y).
    *   All other pixels remain Black (.).

**4. Apply to Test Input:**

*   **Input Grid:**
    12 rows, 12 columns.
    Let's locate the figure.
    Row 0: . . . . . . . . . . . .
    Row 1: . . . . . . . . . . . .
    Row 2: . . . . . . . . . . . .
    Row 3: . . . . . G . . . . . .  <- Figure 'G' (Green) is here.
    Row 4: . . . . . . . . . . . .
    ...
    Row 11: . . . . . . . . . . . .

    *   Figure Color: G (Green).
    *   Figure Position: Row 3, Column 5 (0-indexed).
        *   Row index $r = 3$.
        *   Column index $c = 5$.

*   **Transformation Steps:**
    1.  **New Figure Position:** $(r+1, c) = (4, 5)$. Place 'G' at Row 4, Col 5.
    2.  **Yellow Pillars:**
        *   Target Columns: Same parity as $c=5$. So, odd columns: 1, 3, 5, 7, 9, 11.
        *   Target Rows: From top (0) to original row $r=3$ inclusive. So, rows 0, 1, 2, 3.
        *   Fill these intersections with 'Y'.
    3.  **Background:** All oth

... [6039 chars truncated]
alt-14 dance qwen3.5-122b: fig alone solves
"The soloist glides one step downstage, and in their wake every other floor light behind them fires gold, creating luminous stripes from the back wall to the spot they departed."
alt-15 geology qwen3.5-122b: fail
"A mineral deposit subsides one stratum, and above the fault line it left, veins of gold ore crystallize through every other fracture, running from the surface down to the old deposit layer."
Fail (best cell_acc=0.83 at k=1)
Best Attempt
vs
Expected
Reasoning (10919 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A dark cross-section of rock with one colored mineral inclusion."
    *   "Dark cross-section" implies a black background (`.`).
    *   "One colored mineral inclusion" implies there is a single non-black pixel in the input grid.
*   **Action:** "The inclusion drops one stratum."
    *   "Drops one stratum" means the colored pixel moves down by one row.
*   **Action:** "Gold ore fills alternating vertical fractures from the surface to the inclusion's former depth."
    *   "Gold ore" corresponds to Yellow (`Y`).
    *   "Alternating vertical fractures" suggests a pattern in columns.
    *   "From the surface to the inclusion's former depth" defines the vertical range of the yellow pixels.
    *   "Former depth" means the row index where the colored pixel was originally located.
*   **Grid details:**
    *   "Grid same size."
    *   "Black background."
    *   "Mineral color one row below." -> The original colored pixel moves down 1 row.
    *   "Yellow in same-parity columns from row zero through original row inclusive." -> This clarifies the "alternating vertical fractures" part. It means columns with the same parity (even or odd) as the original column of the mineral get filled with Yellow from row 0 down to the original row index (inclusive).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . .
    . . . . .
    . . M . .
    . . . . .
    . . . . .
    ```
    *   Grid size: 5x5.
    *   Background: `.` (black).
    *   Mineral: `M` (magenta) at row 2, column 2 (0-indexed). Let's verify indices.
        *   Row 0: `.....`
        *   Row 1: `.....`
        *   Row 2: `..M..` -> Index 2.
        *   Row 3: `.....`
        *   Row 4: `.....`
    *   So, Original Position: (2, 2). Color: M.
*   **Output:**
    ```
    Y . Y . Y
    Y . Y . Y
    Y . Y . Y
    . . M . .
    . . . . .
    ```
    *   Grid size: 5x5.
    *   Mineral Position: Row 3, Column 2. (Moved down 1 row).
    *   Yellow Pattern:
        *   Row 0: `Y . Y . Y` (Cols 0, 2, 4 are Y)
        *   Row 1: `Y . Y . Y` (Cols 0, 2, 4 are Y)
        *   Row 2: `Y . Y . Y` (Cols 0, 2, 4 are Y)
        *   Row 3: `. . M . .` (Mineral is here, no Y)
        *   Row 4: `. . . . .`
    *   Let's check the rule "Yellow in same-parity columns from row zero through original row inclusive."
        *   Original Row: 2.
        *   Original Column: 2 (Even).
        *   "Same-parity columns": Columns 0, 2, 4 (Even columns).
        *   "From row zero through original row inclusive": Rows 0, 1, 2.
        *   So, cells (r, c) where $0 \le r \le 2$ and $c \in \{0, 2, 4\}$ should be Yellow.
        *   Looking at the output:
            *   Row 0: Cols 0, 2, 4 are Y. Correct.
            *   Row 1: Cols 0, 2, 4 are Y. Correct.
            *   Row 2: Cols 0, 2, 4 are Y. Correct.
            *   Row 3: Mineral M is at (3, 2).
    *   Wait, the description says "Mineral color one row below". In the output, M is at (3, 2). Original was (2, 2). So it moved down 1.
    *   The description says "Gold ore fills... from the surface to the inclusion's former depth."
        *   Former depth = Row 2.
        *   So rows 0, 1, 2 get filled.
    *   The description says "Yellow in same-parity columns".
        *   Original column = 2 (Even).
        *   So even columns (0, 2, 4) get filled.
    *   This matches the output perfectly.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Background:** Black (`.`).
    *   **Mineral:** A single colored pixel (e.g., `M`, `G`).
    *   **Gold Ore:** Yellow (`Y`).
    *   **Grid:** Rectangular matrix.

2.  **AFFORDANCES:**
    *   **Mineral:** Can move down one row.
    *   **Columns:** Can be identified by parity (even/odd).
    *   **Rows:** Can be identified by index.
    *   **Empty space:** Can be filled with Yellow.

3.  **TRANSFORMATION RULE:**
    *   **Step 1:** Locate the single non-black pixel (Mineral) in the input grid. Let its position be $(r_{orig}, c_{orig})$ and its color be $C$.
    *   **Step 2:** Create an output grid initialized with black (`.`).
    *   **Step 3:** Place the Mineral at $(r_{orig} + 1, c_{orig})$ in the output grid. (If $r_{orig} + 1$ is out of bounds, handle appropriately, though examples suggest valid moves).
    *   **Step 4:** Identify the set of columns $C_{set}$ such that $c \in C_{set}$ if $c \equiv c_{orig} \pmod 2$. (Same parity as original column).
    *   **Step 5:** For every row $r$ from $0$ to $r_{orig}$ (inclusive):
        *   For every column $c$ in $C_{set}$:
            *   Set grid cell $(r, c)$ to Yellow (`Y`).
    *   **Step 6:** Ensure the Mineral's new position does not overwrite the Yellow pattern (though in the example, the mineral is at row $r_{orig}+1$, and the yellow stops at $r_{orig}$, so they don't overlap).

**4. Apply to Test Input:**

*   **Input G

... [5943 chars truncated]
alt-2 cooking qwen3.5-122b: k=2
"A single raisin sinks to the next layer of batter, and above where it rested, saffron bleeds upward through every other strand of pastry lattice, dyeing them gold."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11045 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark sheet of dough with one colored morsel placed somewhere within it."
    *   "Dark sheet of dough" implies a black background (represented by `.`).
    *   "One colored morsel" implies a single non-black pixel in the input grid.
*   **Action:** "The morsel drops one layer."
    *   This suggests the colored pixel moves down by one row.
*   **Action:** "Saffron threads rise from its former position, coloring every other vertical strand of lattice from that level all the way to the top crust."
    *   "Saffron threads" implies Yellow (`Y`).
    *   "Rise from its former position" implies the yellow pixels appear in the rows *above* the original position of the morsel.
    *   "Coloring every other vertical strand" implies a pattern based on column parity (even or odd indices).
    *   "From that level all the way to the top crust" implies filling from the top row (row 0) down to the row *above* the original morsel's row.
*   **Grid details:** "Same dimensions. Black background. The morsel keeps its color one row lower. Yellow occupies columns matching the original column's even-or-odd character, filling from row zero through the morsel's former row."
    *   This clarifies the previous points.
    *   Morsel moves from $(r, c)$ to $(r+1, c)$.
    *   Yellow fills columns $c'$ where $c' \equiv c \pmod 2$ (same parity).
    *   Yellow fills rows $0$ to $r-1$ (from top to the row above the original position).
    *   Wait, let's re-read carefully: "filling from row zero through the morsel's former row."
    *   Does "through the morsel's former row" mean including the row where the morsel *was*?
    *   Let's check the examples to verify the extent of the yellow fill.

**2. Analyze Training Examples:**

*   **Example 1:**
    *   Input: 5x5 grid. Morsel `M` (magenta) at row 2, col 2 (0-indexed).
        *   Row 0: `.` `.` `.` `.` `.`
        *   Row 1: `.` `.` `.` `.` `.`
        *   Row 2: `.` `.` `M` `.` `.`
        *   Row 3: `.` `.` `.` `.` `.`
        *   Row 4: `.` `.` `.` `.` `.`
    *   Output:
        *   Row 0: `Y` `.` `Y` `.` `Y`
        *   Row 1: `Y` `.` `Y` `.` `Y`
        *   Row 2: `Y` `.` `Y` `.` `Y`
        *   Row 3: `.` `.` `M` `.` `.`
        *   Row 4: `.` `.` `.` `.` `.`
    *   Analysis:
        *   Original Morsel: (2, 2). Color `M`.
        *   New Morsel: (3, 2). Color `M`. (Dropped one layer).
        *   Yellow Pattern: Columns 0, 2, 4 are filled with `Y`. Column 2 is the original column. 0, 2, 4 have the same parity as 2 (even).
        *   Yellow Rows: Rows 0, 1, 2 are filled.
        *   Wait, the description said "filling from row zero through the morsel's former row".
        *   Original row was 2. Yellow is in rows 0, 1, 2. So it includes the original row.
        *   However, in the output, at (2, 2), there is a `Y`. But the morsel moved to (3, 2). So (2, 2) is now empty of the morsel, so it can be `Y`.
        *   Wait, look at row 2 in output: `Y . Y . Y`. The original morsel was at (2,2). Now it's `Y`. The morsel is at (3,2).
        *   So the rule is:
            1.  Identify original morsel position $(r, c)$ and color $C$.
            2.  Place morsel $C$ at $(r+1, c)$.
            3.  Fill cells $(i, j)$ with `Y` if $0 \le i \le r$ and $j \equiv c \pmod 2$.
            4.  All other cells are `.` (black).
            5.  Note: If the morsel lands on a spot that would be yellow, the morsel takes precedence? Or does the yellow overwrite? In Example 1, the morsel moves to row 3. The yellow stops at row 2. So no overlap.
            6.  What if the morsel is at the bottom row? It can't drop. The problem description says "drops one layer". Usually implies valid move. Let's assume input morsel is not at the bottom row.

*   **Example 2:**
    *   Input: 3x3 grid. Morsel `R` (red) at row 1, col 1.
        *   Row 0: `.` `R` `.`
        *   Row 1: `.` `.` `.`
        *   Row 2: `.` `.` `.`
        *   Wait, looking at the provided text for Example 2:
            Input:
            . R .
            . . .
            . . .
            So Morsel is at (0, 1).
    *   Output:
        . Y .
        . R .
        . . .
    *   Analysis:
        *   Original Morsel: (0, 1). Color `R`.
        *   New Morsel: (1, 1). Color `R`.
        *   Yellow Pattern: Columns matching parity of 1 (odd). So column 1.
        *   Yellow Rows: From row 0 through original row 0. So just row 0.
        *   Output Row 0: `.` `Y` `.`. (Col 1 is `Y`).
        *   Output Row 1: `.` `R` `.`. (Morsel moved here).
        *   Output Row 2: `.` `.` `.`.
    *   This confirms the rule:
        *   Morsel moves from $(r, c)$ to $(r+1, c)$.
        *   Yellow fills columns $j$ where $j \equiv c \pmod 2$.
        *   Yellow fills rows $i$ where $0 \le i \le r$.
        *   The cell $(r, c)$ becomes `Y` (since $r \le r$ and $c \equiv 

... [6054 chars truncated]
alt-3 music qwen3.5-122b: fail
"A struck note descends one step on the staff, and its overtones shimmer upward through every other string, turning them gold from the resonance chamber to the tuning pegs."
Fail (best cell_acc=0.83 at k=1)
Best Attempt
vs
Expected
Reasoning (10921 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A silent dark staff with a single colored note placed on it."
    *   "Dark staff" implies a black background (represented by `.`).
    *   "Single colored note" implies there is exactly one non-black pixel in the input grid.
*   **Action:** "The note slides down one position."
    *   The colored pixel moves from its current position $(r, c)$ to $(r+1, c)$.
*   **Action:** "Golden harmonics ripple upward along alternating strings from where the note originated to the very top of the instrument."
    *   "Golden harmonics" implies Yellow (`Y`) color.
    *   "Ripple upward" implies filling cells above the original position.
    *   "From where the note originated" implies starting from the original row $r$.
    *   "To the very top" implies going up to row 0.
    *   "Along alternating strings" implies specific columns.
    *   "Same parity as the note's column" (from Grid details section).
*   **Grid details:**
    *   "Dimensions match input."
    *   "Black background."
    *   "The colored note sits one row below its starting position." -> Confirms the move down.
    *   "Yellow fills alternating columns (same parity as the note's column) from the top edge down through the note's original row." -> Confirms the yellow pattern.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . .
    . . . . .
    . . M . .
    . . . . .
    . . . . .
    ```
    *   Grid size: 5x5.
    *   Note: Magenta (`M`) at row 2, column 2 (0-indexed). Let's verify indices.
        *   Row 0: `.....`
        *   Row 1: `.....`
        *   Row 2: `..M..` -> Index 2.
        *   Row 3: `.....`
        *   Row 4: `.....`
    *   So, Note is at $(2, 2)$. Color is `M`.
*   **Output:**
    ```
    Y . Y . Y
    Y . Y . Y
    Y . Y . Y
    . . M . .
    . . . . .
    ```
    *   Note position: Row 3, Column 2. It moved down by 1. $(2, 2) \to (3, 2)$.
    *   Yellow pattern:
        *   Columns 0, 2, 4 are filled with `Y`.
        *   Columns 1, 3 are `.`.
        *   Rows filled: 0, 1, 2.
        *   Row 3 has the note `M` at col 2. The yellow pattern stops *at* the original row? Or does it overwrite?
        *   Let's check the description: "from the top edge down through the note's original row."
        *   Original row was 2.
        *   In the output, Row 2 is `Y . Y . Y`. So the yellow fills the original row as well.
        *   Row 3 is `. . M . .`. The note is there. The yellow does not extend to the new row.
        *   Columns: The note was at column 2. The yellow appears in columns 0, 2, 4. These are even columns. Column 2 is even. So "same parity" means if column index is even, fill even columns. If odd, fill odd columns.
        *   Range: From top (row 0) down to original row (row 2).

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Background:** Black (`.`).
    *   **Note:** A single colored pixel (e.g., `M`, `G`).
    *   **Harmonics:** Yellow (`Y`) pixels.
*   **AFFORDANCES:**
    *   The Note can move vertically.
    *   The Note defines a column parity.
    *   The Note defines a vertical range for the harmonics.
*   **TRANSFORMATION RULE:**
    1.  Locate the single non-black pixel (the Note) at $(r_{orig}, c_{orig})$ with color $C$.
    2.  Create a new grid initialized with black (`.`).
    3.  Place the Note at $(r_{orig} + 1, c_{orig})$ with color $C$.
    4.  Identify the target columns for the harmonics. These are all columns $c$ such that $c \equiv c_{orig} \pmod 2$.
    5.  For each target column $c$, fill cells $(r, c)$ with Yellow (`Y`) for all rows $0 \le r \le r_{orig}$.
    6.  Ensure the Note's new position does not overwrite the harmonics if they overlap (though in this specific logic, the harmonics stop at $r_{orig}$ and the note moves to $r_{orig}+1$, so they don't overlap). Wait, let's check the example again.
        *   Example: Note at (2, 2). New Note at (3, 2).
        *   Harmonics: Rows 0, 1, 2. Columns 0, 2, 4.
        *   Intersection: (2, 2) is in the harmonic range. In the output, (2, 2) is `Y`. The Note is at (3, 2).
        *   So the original position of the note becomes Yellow (if it matches the column parity, which it does).
        *   The new position of the note is the Note color.
    7.  Everything else remains Black (`.`).

**4. Apply to Test Input:**

*   **Input Grid:**
    ```
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . G . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    ```
*   **Dimensions:**
    *   Rows: 12
    *   Columns: 12
*   **Locate Note:**
    *   Scanning rows...
    *   Row 0: All `.`
    *   Row 1: All `.`
    *  

... [5936 chars truncated]
alt-4 sports qwen3.5-122b: k=3
"A lone player drops back one yard, and the floodlights above their former position cast golden stripes down every other lane of the field, illuminating the turf all the way to the end zone."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (11208 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark playing field with one uniquely colored player standing somewhere on it."
    *   This implies a grid mostly filled with black (`.`) and one non-black cell (the "player").
*   **Action:** "The player retreats one position."
    *   "Retreats" usually implies moving away from something or moving in a specific direction. Looking at the examples will clarify the direction.
*   **Effect:** "Golden floodlight stripes activate above their old spot, lighting every other lane from the far boundary down to where the player stood."
    *   "Golden" corresponds to Yellow (`Y`).
    *   "Stripes" implies columns.
    *   "Above their old spot" implies the area *above* the original position of the player.
    *   "Lighting every other lane" implies a pattern (e.g., columns 0, 2, 4... or 1, 3, 5...).
    *   "From the far boundary down to where the player stood" implies the filling starts from the top row (row 0) and goes down to the row where the player *was* originally.
*   **Grid details:**
    *   "Same grid size."
    *   "Black background."
    *   "Player's color preserved one row lower." -> This confirms the "retreat" direction. If the player moves "one row lower", they move from row $r$ to row $r+1$.
    *   "Yellow appears in columns sharing the original column's parity, filling rows from zero to the player's original row inclusive." -> This is a very specific rule.
        *   "Original column's parity": If the player was at column $c$, then columns $c, c-2, c-4...$ and $c+2, c+4...$ get filled. Basically, columns with the same index parity (even/odd) as the original column.
        *   "Filling rows from zero to the player's original row inclusive": Rows $0$ to $r_{original}$ get filled with Yellow in those specific columns.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 5x5 grid. Player `M` (magenta) at (2, 2) (0-indexed: row 2, col 2).
    *   Output:
        *   Player `M` is now at (3, 2). (Row 2 -> Row 3). This matches "retreats one position" (downwards).
        *   Yellow `Y` appears in columns 0, 2, 4. (Original col was 2, which is even. So even columns get filled).
        *   Yellow fills rows 0, 1, 2. (Original row was 2. So rows 0 to 2 inclusive).
        *   Row 3 and 4 are black (except for the moved player).
    *   Matches the description perfectly.

*   **Example 2:**
    *   Input: 3x3 grid. Player `R` (red) at (1, 1).
    *   Output:
        *   Player `R` is now at (2, 1). (Row 1 -> Row 2).
        *   Yellow `Y` appears in column 1. (Original col 1 is odd. So odd columns get filled).
        *   Yellow fills rows 0, 1. (Original row 1. So rows 0 to 1 inclusive).
        *   Row 2 is black (except for the moved player).
    *   Matches the description perfectly.

*   **Example 3:**
    *   Input: 9x9 grid. Player `W` (maroon) at (4, 2).
    *   Output:
        *   Player `W` is now at (5, 2). (Row 4 -> Row 5).
        *   Yellow `Y` appears in columns 0, 2, 4, 6, 8. (Original col 2 is even).
        *   Yellow fills rows 0, 1, 2, 3, 4. (Original row 4).
    *   Matches the description perfectly.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Background:** Black (`.`).
    *   **Player:** A single non-black cell (e.g., `M`, `R`, `W`, `G`).
    *   **Floodlight:** Yellow (`Y`).

2.  **AFFORDANCES:**
    *   **Player:** Can move down one row. Can define the "original position" for the floodlight effect.
    *   **Floodlight:** Can fill specific columns (based on parity of original column) in specific rows (from top to original row).

3.  **TRANSFORMATION RULE:**
    *   Locate the unique non-black cell at $(r, c)$. Let its color be $C$.
    *   Create a new grid of the same size, initialized with black (`.`).
    *   Place the player at $(r+1, c)$ with color $C$. (If $r+1$ is out of bounds, handle accordingly, though examples suggest valid moves).
    *   Identify the set of columns $K = \{k \mid k \equiv c \pmod 2\}$.
    *   For each column $k \in K$:
        *   For each row $i$ from $0$ to $r$ (inclusive):
            *   Set cell $(i, k)$ to Yellow (`Y`).
    *   Note: If the player moves to a position that overlaps with the floodlight area, the player color takes precedence (based on Example 1, row 3 col 2 is `M`, not `Y`, although row 3 is outside the floodlight range $0..2$ anyway). Wait, let's check overlap logic.
    *   In Example 1: Player moves from (2,2) to (3,2). Floodlight covers rows 0-2. No overlap.
    *   In Example 2: Player moves from (1,1) to (2,1). Floodlight covers rows 0-1. No overlap.
    *   In Example 3: Player moves from (4,2) to (5,2). Floodlight covers rows 0-4. No overlap.
    *   Hypothesis: The floodlight fills rows $0$ to $r_{original}$. The player moves to $r_{original} + 1$. So the player is always just below the floodlight a

... [6229 chars truncated]
alt-5 weather qwen3.5-122b: k=1
"A single ember drifts one notch closer to the ground, and above its old altitude, golden rain falls in alternating curtains from the cloud ceiling down to where the ember hovered."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10500 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark sky with one colored ember suspended at some altitude."
    *   "Dark sky" implies a black background (`.`).
    *   "One colored ember" implies a single non-black pixel in the grid.
*   **Action:** "The ember descends one level."
    *   The colored pixel moves down by 1 row.
*   **Action:** "Curtains of golden rain appear above its former position, falling through every other vertical channel from the highest altitude to the ember's old height."
    *   "Golden rain" implies Yellow (`Y`).
    *   "Above its former position" means rows above the original row of the ember.
    *   "Falling through every other vertical channel" implies a pattern based on column index.
    *   "From the highest altitude to the ember's old height" means from row 0 down to the original row index (inclusive or exclusive? Let's check examples).
*   **Grid details:** "Grid unchanged in size. Black background. The ember's color is placed one row below origin. Yellow fills every column with the same parity as the ember's column, from row zero through the ember's original row."
    *   This clarifies the "every other vertical channel" part. It depends on the parity (even/odd) of the ember's column index.
    *   "From row zero through the ember's original row" means rows $0$ to $r_{old}$ inclusive.
    *   "The ember's color is placed one row below origin" means the new position is $(r_{old} + 1, c_{old})$.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    . . . . .
    . . . . .
    . . M . .
    . . . . .
    . . . . .
    ```
    *   Grid size: 5x5.
    *   Ember: Magenta (`M`) at row 2, col 2 (0-indexed). $r=2, c=2$.
*   **Output:**
    ```
    Y . Y . Y
    Y . Y . Y
    Y . Y . Y
    . . M . .
    . . . . .
    ```
    *   Ember moved: From (2, 2) to (3, 2). This matches "descends one level".
    *   Yellow rain:
        *   Columns filled with `Y`: 0, 2, 4.
        *   Ember's column was 2 (even).
        *   Filled columns are even (0, 2, 4). This matches "same parity as the ember's column".
        *   Rows filled: 0, 1, 2.
        *   Ember's original row was 2.
        *   Filled rows are 0 to 2 inclusive. This matches "from row zero through the ember's original row".
    *   Note: The cell at (2, 2) in the output is `M` (the ember's new position is (3,2), but the rain stops at the *original* row). Wait, looking at the output grid:
        Row 0: Y . Y . Y
        Row 1: Y . Y . Y
        Row 2: Y . Y . Y  <- The ember was here originally. Now it has Y in col 2?
        Row 3: . . M . .  <- The ember is here now.
        Row 4: . . . . .
    *   Wait, the description says "Yellow fills every column... from row zero through the ember's original row."
    *   In the output, at (2, 2), there is a `Y`. But the ember was at (2, 2). The ember moved to (3, 2). So the original spot (2, 2) is now covered by the rain?
    *   Let's check the text: "The ember's color is placed one row below origin." -> (3, 2) is M.
    *   "Yellow fills every column... from row zero through the ember's original row." -> Rows 0, 1, 2.
    *   So at (2, 2), the rain overwrites the background. Since the ember moved, the original spot is empty (black) unless covered by rain. The rain covers it.
    *   So the logic holds:
        1.  Find Ember $(r, c)$.
        2.  Move Ember to $(r+1, c)$.
        3.  Fill columns $k$ where $k \equiv c \pmod 2$ with `Y` for rows $0$ to $r$ (inclusive).
        4.  Background is `.`.

**3. Analyze Test Input:**
*   **Input Grid:**
    ```
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . G . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    ```
*   **Grid Size:** 12 rows, 12 columns.
*   **Ember:** Green (`G`).
*   **Location:**
    *   Row 0: `.`
    *   Row 1: `.`
    *   Row 2: `.`
    *   Row 3: `. . . . . G . . . . . .`
    *   Let's count indices.
    *   Row 3.
    *   Col 0: `.`
    *   Col 1: `.`
    *   Col 2: `.`
    *   Col 3: `.`
    *   Col 4: `.`
    *   Col 5: `G`
    *   So Ember is at $(r=3, c=5)$.
*   **Transformation:**
    1.  **Move Ember:** New position is $(r+1, c) = (4, 5)$. Color is `G`.
    2.  **Rain:**
        *   Color: `Y` (Yellow).
        *   Columns: Same parity as $c=5$. So odd columns (1, 3, 5, 7, 9, 11).
        *   Rows: From 0 through original row $r=3$. So rows 0, 1, 2, 3.
    3.  **Background:** `.` (Black).

**4. Constructing the Output Grid:**
*   Dimensions: 12x12.
*   Initialize with `.`.
*   Place `G` at (4, 5).
*   Place `Y` at $(row, col)$ where $0 \le row \le 3$ and $col \in \{1, 3, 5, 7, 9, 11\}$.

Let's verify the columns.
Input row 

... [5512 chars truncated]
alt-6 architecture qwen3.5-122b: fail
"A cornerstone is lowered one course, and above where it was laid, golden pillars rise through every other bay of the facade, from the foundation line up to the rooftop cornice."
Fail (best cell_acc=0.82 at k=1)
Best Attempt
vs
Expected
Reasoning (11089 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark facade with a single colored stone set into it."
    *   "Dark facade" implies a black background (`.`).
    *   "Single colored stone" implies one non-black pixel in the grid.
*   **Action:** "The stone is reset one course lower."
    *   "Course" usually refers to a row in masonry.
    *   "Reset one course lower" means the colored stone moves down by 1 row.
*   **Action:** "Golden columns spring up in alternating bays from the stone's former course to the top of the structure."
    *   "Golden columns" means Yellow (`Y`) pixels.
    *   "Alternating bays" implies a pattern based on column index (parity).
    *   "From the stone's former course to the top" means the columns extend from row 0 up to the row where the stone *was* originally.
*   **Grid details:**
    *   "Same dimensions."
    *   "Black background."
    *   "Stone's color one row below original." -> The original colored pixel moves down 1 row.
    *   "Yellow in columns matching original column parity, from top row through the stone's former row." -> This clarifies the "alternating bays" part. If the stone was at column $c$, then columns $c, c-2, c+2, \dots$ (same parity) get filled with Yellow from row 0 to row $r_{original}$.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . .
    . . . . .
    . . M . .
    . . . . .
    . . . . .
    ```
    *   Grid size: 5x5.
    *   Stone: Magenta (`M`) at row 2, column 2 (0-indexed). Let's verify indices.
        *   Row 0: `.`
        *   Row 1: `.`
        *   Row 2: `. . M . .` -> Index 2.
        *   Row 3: `.`
        *   Row 4: `.`
    *   Stone position: $(r=2, c=2)$. Color: `M`.
*   **Output:**
    ```
    Y . Y . Y
    Y . Y . Y
    Y . Y . Y
    . . M . .
    . . . . .
    ```
    *   Stone position: Row 3, Column 2. Color: `M`.
        *   Original row was 2. New row is 3. This matches "reset one course lower".
    *   Yellow columns:
        *   Row 0: `Y . Y . Y` -> Cols 0, 2, 4 are Yellow.
        *   Row 1: `Y . Y . Y` -> Cols 0, 2, 4 are Yellow.
        *   Row 2: `Y . Y . Y` -> Cols 0, 2, 4 are Yellow.
        *   Row 3: `. . M . .` -> No Yellow.
        *   Row 4: `. . . . .` -> No Yellow.
    *   Logic check:
        *   Original Stone Row: 2.
        *   Yellow fills from Top (Row 0) through Stone's Former Row (Row 2).
        *   Columns matching original column parity. Original column was 2 (even).
        *   Even columns are 0, 2, 4.
        *   So, Rows 0, 1, 2 have Yellow at Cols 0, 2, 4.
        *   The stone moves to Row 3, Col 2.
    *   This perfectly matches the description.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . G . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    ```
*   **Dimensions:**
    *   Count rows: 12 rows.
    *   Count columns: 12 columns.
*   **Locate the Stone:**
    *   Scanning rows...
    *   Row 0: All `.`
    *   Row 1: All `.`
    *   Row 2: All `.`
    *   Row 3: `. . . . . . G . . . . .`
        *   Let's count indices (0-based):
        *   0: `.`
        *   1: `.`
        *   2: `.`
        *   3: `.`
        *   4: `.`
        *   5: `.`
        *   6: `G`
        *   7: `.`
        *   ...
    *   So, Stone is Green (`G`) at Row 3, Column 6.
    *   $r_{orig} = 3$, $c_{orig} = 6$.

**4. Apply Transformation Rules:**
*   **Rule 1: Move Stone.**
    *   New position: $(r_{orig} + 1, c_{orig})$.
    *   New position: $(4, 6)$.
    *   Color remains `G`.
*   **Rule 2: Add Yellow Columns.**
    *   Color: Yellow (`Y`).
    *   Rows: From Top (0) through Stone's Former Row ($r_{orig} = 3$). So rows 0, 1, 2, 3.
    *   Columns: Matching original column parity.
        *   $c_{orig} = 6$ (Even).
        *   So, all even columns: 0, 2, 4, 6, 8, 10.
    *   Intersection: For rows 0 to 3, set columns 0, 2, 4, 6, 8, 10 to `Y`.
    *   Note: The stone's original position $(3, 6)$ is overwritten by the column logic?
        *   In the training example:
            *   Original Stone at (2, 2).
            *   Yellow columns at rows 0, 1, 2.
            *   Row 2, Col 2 became `Y` in the output grid shown in the example?
            *   Let's check the training output again.
            *   Output Row 2: `Y . Y . Y`.
            *   Wait, the stone moved to Row 3.
            *   So at Row 2, Col 2, there is a `Y`.
            *   The stone is no longer at Row 2. It is at Row 3.
            *   So the "former course" includes the row where the stone *was*.
            *   Does the stone overwrite the yellow column at its new pos

... [6113 chars truncated]
alt-7 warfare qwen3.5-122b: k=1
"A general retreats one trench line, and from the abandoned position upward, signal flares illuminate every other column of no-man's-land in gold, all the way back to headquarters."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10444 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A dark battlefield (black background) with a single colored marker at some position.
*   **Action:** The marker falls back one row.
*   **Effect:** Golden signal flares (Yellow) light up alternating vertical columns from the marker's old position to the rearmost line (row 0).
*   **Grid details:**
    *   Dimensions preserved.
    *   Black background.
    *   Marker color one row lower.
    *   Yellow fills same-parity columns from row zero to original marker row inclusive.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . .
    . . . . .
    . . M . .
    . . . . .
    . . . . .
    ```
    *   Grid size: 5x5.
    *   Marker: 'M' (Magenta) at row 2, column 2 (0-indexed). Let's verify indices.
        *   Row 0: . . . . .
        *   Row 1: . . . . .
        *   Row 2: . . M . .  -> Marker is at (2, 2).
        *   Row 3: . . . . .
        *   Row 4: . . . . .
*   **Output:**
    ```
    Y . Y . Y
    Y . Y . Y
    Y . Y . Y
    . . M . .
    . . . . .
    ```
    *   Marker 'M' moved from (2, 2) to (3, 2). This matches "falls back one row".
    *   Yellow 'Y' appears in columns 0, 2, 4.
    *   Yellow appears in rows 0, 1, 2.
    *   The original marker position was (2, 2).
    *   The columns filled with Yellow are 0, 2, 4. These are even columns. The marker column is 2 (even). So "same-parity columns" means columns with the same parity as the marker's column index.
    *   The rows filled with Yellow are 0, 1, 2. This is from row 0 to the original marker row (2) inclusive.
    *   The description says "from the marker's old position to the rearmost line". Usually, row 0 is the top (rearmost in a battlefield context often implies back/top). The example shows Y from row 0 to row 2.
    *   So, for every column $c$ where $c \equiv \text{marker\_col} \pmod 2$, and for every row $r$ where $0 \le r \le \text{original\_marker\_row}$, set cell $(r, c)$ to Yellow.
    *   The marker moves to $(\text{original\_marker\_row} + 1, \text{marker\_col})$.
    *   Everything else remains black ('.').

**3. Conceptual Digestion:**
*   **CAST:**
    *   **Background:** Black ('.').
    *   **Marker:** A specific colored pixel (e.g., 'M', 'G').
    *   **Signal Flares:** Yellow ('Y') pixels.
*   **AFFORDANCES:**
    *   The Marker can move down one row.
    *   The Marker's position determines the pattern of flares.
    *   The flares occupy specific columns and rows based on the Marker's original position.
*   **TRANSFORMATION RULE:**
    1.  Locate the unique non-black pixel (the Marker) in the input grid. Let its position be $(r_{old}, c_{old})$ and its color be $C$.
    2.  Create an output grid of the same dimensions, initialized with black ('.').
    3.  Place the Marker at the new position $(r_{new}, c_{new}) = (r_{old} + 1, c_{old})$.
    4.  Identify the columns to be filled with Yellow ('Y'). These are columns $c$ such that $c \equiv c_{old} \pmod 2$ (same parity).
    5.  Identify the rows to be filled with Yellow ('Y'). These are rows $r$ such that $0 \le r \le r_{old}$.
    6.  For all cells $(r, c)$ satisfying the column and row conditions, set the color to 'Y'.
    7.  Note: If the new marker position overlaps with a flare, the marker color takes precedence (though in the example, the marker moves to row 3, and flares stop at row 2, so no overlap). If the marker moves to a row within the flare range, the marker color should likely overwrite the flare color. In the example, $r_{old}=2$, flares go up to row 2. Marker moves to row 3. No overlap.
    8.  Wait, let's re-read carefully: "Yellow fills same-parity columns from row zero to original marker row inclusive."
    9.  "Marker falls back one row."
    10. So, Output Grid:
        *   Initialize with '.'.
        *   For $r$ from 0 to $r_{old}$:
            *   For $c$ from 0 to width-1:
                *   If $c \equiv c_{old} \pmod 2$:
                    *   Set $(r, c)$ to 'Y'.
        *   Set $(r_{old} + 1, c_{old})$ to $C$ (Marker Color).

**4. Apply to Test Input:**
*   **Input Grid:**
    ```
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . G . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    . . . . . . . . . . . .
    ```
*   **Dimensions:**
    *   Rows: 12
    *   Columns: 12
*   **Locate Marker:**
    *   Scanning rows...
    *   Row 0: all .
    *   Row 1: all .
    *   Row 2: all .
    *   Row 3: . . . . . G . . . . . .
        *   Index 0: .
        *   Index 1: .
        *   Index 2: .
        *   Index 3: .
        *   Index 4: .
        *   Index 5: G
    *   So, Marker is 'G' (Green).
    *   Position: $r_{old} = 3$, $c_{old} = 5$.
* 

... [5462 chars truncated]
alt-8 theater qwen3.5-122b: fig alone solves
"The lead actor steps downstage by one mark, and the spotlight grid above their former blocking fires every other gel in amber, washing the stage from the flies to the mark they left."
alt-9 gardening qwen3.5-122b: fig alone solves
"A bulb is pressed one inch deeper into the soil, and from where it rested, golden shoots push upward through every other furrow, breaking the surface all the way to the garden wall."

Task 543: 9110e3c5

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Ex5 In
Ex5 Out
Ex6 In
Ex6 Out
Ex7 In
Ex7 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original In a noisy room, the loudest voice shapes the echo on the wall. MARC valid 2
alt-1 biology In a petri dish teeming with competing colonies, the species that outgrows all o ... [126 chars truncated] MARC valid 4
alt-10 astronomy A crowded star field is surveyed, and the most abundant spectral class determine ... [70 chars truncated] MARC valid 3
alt-11 ocean/sailing A harbor crowded with ships flying many flags — the fleet with the greates ... [81 chars truncated] MARC valid 4
alt-12 electronics A circuit board buzzes with signals on many frequencies, but the dominant freque ... [62 chars truncated] MARC valid 2
alt-13 mythology Many minor spirits haunt a sacred grove, but the one whose presence is felt most ... [60 chars truncated] MARC valid 3
alt-14 dance A crowded dance floor where many styles collide — whichever style claims t ... [69 chars truncated] MARC valid 3
alt-15 geology A core sample reveals many minerals, but the one that saturates the rock determi ... [58 chars truncated] MARC valid 2
alt-2 cooking A chef tastes a complex stew and names the ingredient that overpowers everything ... [90 chars truncated] MARC valid 2
alt-3 music An orchestra warms up in cacophony, but one section drowns out the rest — ... [86 chars truncated] MARC valid 4
alt-4 sports On a field where players from many teams have wandered in, the team with the mos ... [63 chars truncated] MARC valid 3
alt-5 weather A weather map swirls with many fronts, but one air mass dominates the region  ... [81 chars truncated] MARC valid 3
alt-6 architecture A city block is surveyed from above — whichever building material dominate ... [88 chars truncated] MARC valid 5
alt-7 warfare Scouts survey a battlefield crowded with banners from many factions. The faction ... [87 chars truncated] MARC valid 4
alt-8 theater After a chaotic audition, the actor who appeared in the most scenes gets their s ... [75 chars truncated] MARC valid 2
alt-9 gardening A garden overrun with many species yields to whichever plant spreads most aggres ... [104 chars truncated] MARC valid 4
original qwen3.5-122b: k=2
"In a noisy room, the loudest voice shapes the echo on the wall."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10999 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **"Crowded square buzzes with chatter... seven paces on each side."**: The input grid is 7x7.
*   **"Most voices are faint... one color is practically shouting over everyone else"**: There is a dominant color in the input grid. I need to count the occurrences of each color to find the most frequent one.
*   **"That dominant voice... chooses a signature gesture, a pose struck in azure light on a small dark stage."**: The output grid is 3x3 ("tiny three-by-three platform"). The background of the output grid seems to be black (represented by `.`). The "pose" is drawn in Azure (`A`).
*   **"Each color-voice has rehearsed its own distinctive pose... The loudest voice steps onto the stage and strikes the only pose it knows."**: This implies that the dominant color in the input determines the shape/pattern drawn in Azure (`A`) on the 3x3 output grid. Different dominant colors map to different 3x3 patterns.
*   **"No matter how chaotic the crowd, only one pose appears — chosen not by where anyone stood, but simply by who was loudest."**: The position of the dominant color in the input doesn't matter, only the count. The output is always 3x3.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
B . B . O . .
B B W B . B .
. . B B . R .
. . . . G . B
. Y . B . . B
. . B . R . A
. . B . O G B
```
Grid size: 7x7.
Let's count the colors:
B (Blue):
Row 1: 2
Row 2: 4
Row 3: 2
Row 4: 1
Row 5: 2
Row 6: 1
Row 7: 2
Total B: 2+4+2+1+2+1+2 = 14.

O (Orange): 2
W (Maroon): 1
R (Red): 2
G (Green): 2
Y (Yellow): 1
A (Azure): 1

Dominant color: **B (Blue)** with 14 occurrences.

Output:
```
. . A
A A .
. A .
```
This is a 3x3 grid.
Pattern:
(0,2) is A
(1,0) is A, (1,1) is A
(2,1) is A
Rest are `.`.
Shape looks like a 'Z' or a specific symbol. Let's visualize:
. . #
# # .
. # .

**Example 2:**
Input:
```
. G . G X G .
. . G G . . .
A . . . . . G
G Y G W G . G
. . W G B G G
. G G G . G .
. . . . . . G
```
Grid size: 7x7.
Let's count the colors:
G (Green):
Row 1: 3
Row 2: 2
Row 3: 1
Row 4: 4
Row 5: 3
Row 6: 4
Row 7: 1
Total G: 3+2+1+4+3+4+1 = 18.

X (Grey): 1
A (Azure): 1
Y (Yellow): 1
W (Maroon): 2
B (Blue): 1

Dominant color: **G (Green)** with 18 occurrences.

Output:
```
. A A
. A .
. A .
```
This is a 3x3 grid.
Pattern:
(0,1) is A, (0,2) is A
(1,1) is A
(2,1) is A
Rest are `.`.
Shape looks like a '7' or a specific symbol.
. # #
. # .
. # .

**3. Synthesize the Transformation Rule:**
1.  **Count Frequencies**: Count the number of cells for each color in the 7x7 input grid.
2.  **Identify Dominant Color**: Find the color with the highest count.
3.  **Map Color to Pattern**: There is a mapping from the dominant color to a specific 3x3 pattern drawn in Azure (`A`) on a black (`.`) background.
    *   Blue (B) -> Pattern 1:
        . . A
        A A .
        . A .
    *   Green (G) -> Pattern 2:
        . A A
        . A .
        . A .
4.  **Generate Output**: Create a 3x3 grid. Fill it with the pattern corresponding to the dominant color found in step 2.

**4. Analyze the Test Input:**
Input:
```
G . G . . . G
G . W X . . X
. G . G . R W
A G . G . . O
. G X . . G G
. . G G . . .
. . G . Y . .
```
Grid size: 7x7.
Let's count the colors:

**G (Green):**
Row 1: 3 (indices 0, 2, 6)
Row 2: 1 (index 0)
Row 3: 2 (indices 1, 3)
Row 4: 2 (indices 1, 3)
Row 5: 3 (indices 1, 5, 6)
Row 6: 2 (indices 2, 3)
Row 7: 1 (index 2)
Total G: 3 + 1 + 2 + 2 + 3 + 2 + 1 = 14.

**W (Maroon):**
Row 2: 1
Row 3: 1
Total W: 2.

**X (Grey):**
Row 2: 2
Row 5: 1
Total X: 3.

**R (Red):**
Row 3: 1
Total R: 1.

**A (Azure):**
Row 4: 1
Total A: 1.

**O (Orange):**
Row 4: 1
Total O: 1.

**Y (Yellow):**
Row 7: 1
Total Y: 1.

**B (Blue):**
None.

**Counts:**
G: 14
X: 3
W: 2
R: 1
A: 1
O: 1
Y: 1

Dominant Color: **G (Green)** with 14 occurrences.

**5. Determine the Output Pattern:**
Since the dominant color is **Green (G)**, I need to use the pattern associated with Green from the training examples.
From Example 2, where Green was dominant:
Output was:
```
. A A
. A .
. A .
```

**6. Construct the Final Output:**
The output grid is 3x3.
Row 1: `.` `A` `A`
Row 2: `.` `A` `.`
Row 3: `.` `A` `.`

Let's double check the counts for the test input to be absolutely sure.
Input:
G . G . . . G  -> G: 3
G . W X . . X  -> G: 1, W: 1, X: 2
. G . G . R W  -> G: 2, R: 1, W: 1
A G . G . . O  -> A: 1, G: 2, O: 1
. G X . . G G  -> G: 3, X: 1
. . G G . . .  -> G: 2
. . G . Y . .  -> G: 1, Y: 1

Total G: 3 + 1 + 2 + 2 + 3 + 2 + 1 = 14.
Total X: 2 + 1 = 3.
Total W: 1 + 1 = 2.
Total R: 1.
Total A: 1.
Total O: 1.
Total Y: 1.

Max is G (14).
Pattern for G is from Example 2.
Example 2 Output:
. A A
. A .
. A .

Wait, let me look closer at Example 1 and 2 to ensure I haven't missed a nuance.
Example 1: Dominant B. Output:
. . A
A A .
. A .
Example 2: Dominant G. Output:
. A A
. A .
. A .

... [6056 chars truncated]
alt-1 biology qwen3.5-122b: k=4
"In a petri dish teeming with competing colonies, the species that outgrows all others leaves its signature protein folded in a characteristic shape — not where it grew, but how it marks its territory."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (11015 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A crowded culture plate (grid) with microorganisms (colored pixels).
*   **Dominance:** One species vastly outnumbers the rest.
*   **Mutation:** Rare mutant strains appear as isolated specimens.
*   **Task:** Identify the dominant species.
*   **Output:** A 3x3 protein fold (grid) rendered in azure (A) against a dark background (black/.).
*   **Grid Size:** Input is 7x7. Output is 3x3.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 7x7 grid.
    *   Colors present: B (Blue), O (Orange), W (Maroon), R (Red), G (Green), Y (Yellow), A (Azure).
    *   Counts:
        *   B: 12
        *   O: 2
        *   W: 1
        *   R: 2
        *   G: 1
        *   Y: 1
        *   A: 1
    *   Dominant species: Blue (B).
    *   Output: 3x3 grid with A (Azure) and . (Black).
    *   Output Pattern:
        . . A
        A A .
        . A .
    *   Observation: The output is a 3x3 pattern of Azure pixels. The background is black. The pattern seems specific. Is it related to the shape of the dominant color? Or is it a fixed pattern for the dominant color? Or does it depend on the positions of the dominant color?
    *   Let's look at the positions of B in the input.
        (0,0), (0,2), (1,0), (1,1), (1,3), (1,5), (2,2), (2,3), (3,6), (4,3), (4,6), (5,2), (6,2), (6,6).
        Wait, let me recount carefully.
        Row 0: B . B . O . . -> B at 0, 2
        Row 1: B B W B . B . -> B at 0, 1, 3, 5
        Row 2: . . B B . R . -> B at 2, 3
        Row 3: . . . . G . B -> B at 6
        Row 4: . Y . B . . B -> B at 3, 6
        Row 5: . . B . R . A -> B at 2
        Row 6: . . B . O G B -> B at 2, 6
        Total B count: 2 + 4 + 2 + 1 + 2 + 1 + 2 = 14.
        Other colors: O(2), W(1), R(2), G(1), Y(1), A(1).
        Dominant is definitely B.
    *   Output Pattern:
        . . A
        A A .
        . A .
        This looks like a specific shape. Is it the shape of the dominant color's distribution? No, the dominant color is scattered.
        Is it a fixed pattern associated with the dominant color?
        Let's check other examples.

*   **Example 2:**
    *   Input: 7x7 grid.
    *   Colors: G, X, A, Y, W, B.
    *   Counts:
        *   G: 15 (Row 0: 3, Row 1: 2, Row 2: 1, Row 3: 4, Row 4: 3, Row 5: 3, Row 6: 1) -> 3+2+1+4+3+3+1 = 17? Let's count properly.
        R0: . G . G X G . -> G at 1, 3, 5 (3)
        R1: . . G G . . . -> G at 2, 3 (2)
        R2: A . . . . . G -> G at 6 (1)
        R3: G Y G W G . G -> G at 0, 2, 4, 6 (4)
        R4: . . W G B G G -> G at 3, 5, 6 (3)
        R5: . G G G . G . -> G at 1, 2, 3, 5 (4)
        R6: . . . . . . G -> G at 6 (1)
        Total G: 3+2+1+4+3+4+1 = 18.
        Dominant is Green (G).
    *   Output:
        . A A
        . A .
        . A .
    *   Pattern:
        . A A
        . A .
        . A .
    *   This is different from Example 1's pattern.
    *   Example 1 (Dominant B):
        . . A
        A A .
        . A .
    *   Example 2 (Dominant G):
        . A A
        . A .
        . A .
    *   Hypothesis: The output pattern depends on the dominant color. Each color has a specific 3x3 "signature" or "fold".

*   **Example 3:**
    *   Input: 7x7 grid.
    *   Colors: R, B, X, G, W, Y, O, M.
    *   Counts:
        *   R:
            R0: . . R . B X G -> 1
            R1: . . R W . R . -> 2
            R2: R R R Y R . . -> 4
            R3: . R . R O R . -> 3
            R4: R R . . R R M -> 4
            R5: . R R . R . . -> 3
            R6: X . Y R . R R -> 3
            Total R: 1+2+4+3+4+3+3 = 20.
        *   Dominant is Red (R).
    *   Output:
        . . .
        A A A
        . . .
    *   Pattern: Middle row is all Azure.
    *   This confirms the hypothesis: The dominant color determines the 3x3 Azure pattern.

*   **Example 4:**
    *   Input: 7x7 grid.
    *   Colors: R, X, B, W, A.
    *   Counts:
        *   R:
            R0: R . . R R . X -> 3
            R1: . R R . . . R -> 3
            R2: . B . . . . . -> 0
            R3: . . . . R . W -> 1
            R4: . W . . . . R -> 1
            R5: . . R B . . A -> 1
            R6: R . . R R . . -> 3
            Total R: 3+3+0+1+1+1+3 = 12.
        *   Other colors: X(2), B(2), W(2), A(1).
        *   Dominant is Red (R).
    *   Output:
        . . .
        A A A
        . . .
    *   Matches Example 3. Red -> Middle row Azure.

**3. Synthesize the Rule:**
1.  **Count** the occurrences of each color in the 7x7 input grid.
2.  **Identify** the dominant color (the one with the highest count).
3.  **Map** the dominant color to a specific 3x3 pattern of Azure (A) pixels on a black (.) background.
    *   Blue (B) ->
        . . A
        A A .
        . A .
    *   Green (G) ->
        . A A
        . 

... [6183 chars truncated]
alt-10 astronomy qwen3.5-122b: k=3
"A crowded star field is surveyed, and the most abundant spectral class determines which constellation template is projected onto the observatory dome."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (10607 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 7x7 grid ("dense star field").
*   **Content:** Stars of various spectral types (colors). One class vastly outnumbers the rest ("dominant class").
*   **Task:** Identify the dominant class.
*   **Output:** A 3x3 grid ("constellation projection").
*   **Output Color:** "illuminated in azure on the dark dome". This suggests the output grid will contain 'A' (azure) and '.' (black/dark).
*   **Logic:** The dominant class triggers a specific constellation projection (a fixed pattern).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 7x7 grid.
    *   Colors present: B (blue), O (orange), W (maroon), R (red), G (green), Y (yellow), A (azure).
    *   Let's count the colors:
        *   B: 1, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49. Wait, let's count properly.
        *   Row 1: B . B . O . . (2 B, 1 O)
        *   Row 2: B B W B . B . (4 B, 1 W)
        *   Row 3: . . B B . R . (2 B, 1 R)
        *   Row 4: . . . . G . B (1 G, 1 B)
        *   Row 5: . Y . B . . B (1 Y, 2 B)
        *   Row 6: . . B . R . A (1 B, 1 R, 1 A)
        *   Row 7: . . B . O G B (2 B, 1 O, 1 G)
        *   Total B: 2+4+2+1+2+1+2 = 14.
        *   Total others: O(2), W(1), R(2), G(2), Y(1), A(1).
        *   Dominant color: Blue (B).
    *   Output: 3x3 grid.
        *   . . A
        *   A A .
        *   . A .
    *   Pattern: Looks like a specific shape made of 'A's.

*   **Example 2:**
    *   Input: 7x7 grid.
    *   Colors present: G, X, A, Y, W, B.
    *   Let's count G:
        *   Row 1: . G . G X G . (3 G)
        *   Row 2: . . G G . . . (2 G)
        *   Row 3: A . . . . . G (1 G)
        *   Row 4: G Y G W G . G (4 G)
        *   Row 5: . . W G B G G (3 G)
        *   Row 6: . G G G . G . (4 G)
        *   Row 7: . . . . . . G (1 G)
        *   Total G: 3+2+1+4+3+4+1 = 18.
        *   Others are sparse.
        *   Dominant color: Green (G).
    *   Output: 3x3 grid.
        *   . A A
        *   . A .
        *   . A .
    *   Pattern: Different shape made of 'A's.

*   **Example 3:**
    *   Input: 7x7 grid.
    *   Colors present: R, B, X, G, W, Y, O, M.
    *   Let's count R:
        *   Row 1: . . R . B X G (1 R)
        *   Row 2: . . R W . R . (2 R)
        *   Row 3: R R R Y R . . (4 R)
        *   Row 4: . R . R O R . (3 R)
        *   Row 5: R R . . R R M (4 R)
        *   Row 6: . R R . R . . (3 R)
        *   Row 7: X . Y R . R R (3 R)
        *   Total R: 1+2+4+3+4+3+3 = 20.
        *   Dominant color: Red (R).
    *   Output: 3x3 grid.
        *   . . .
        *   A A A
        *   . . .
    *   Pattern: Horizontal line in the middle.

**3. Synthesize the Rule:**
*   **Step 1:** Count the frequency of each color in the 7x7 input grid.
*   **Step 2:** Identify the most frequent color (the "dominant class").
*   **Step 3:** Map the dominant color to a specific 3x3 pattern of Azure ('A') pixels on a Black ('.') background.
*   **Step 4:** Output the 3x3 grid.

**4. Determine the Mapping:**
*   Example 1: Dominant = Blue (B). Pattern:
    . . A
    A A .
    . A .
    (This looks like a '7' or a specific constellation shape).
*   Example 2: Dominant = Green (G). Pattern:
    . A A
    . A .
    . A .
    (This looks like a 'J' or a hook).
*   Example 3: Dominant = Red (R). Pattern:
    . . .
    A A A
    . . .
    (This is a horizontal line).

I need to find the pattern for the dominant color in the Test Input.

**5. Analyze Test Input:**
*   Input Grid:
    G . G . . . G
    G . W X . . X
    . G . G . R W
    A G . G . . O
    . G X . . G G
    . . G G . . .
    . . G . Y . .

*   Count colors:
    *   **G (Green):**
        *   Row 1: 3 (indices 0, 2, 6)
        *   Row 2: 1 (index 0)
        *   Row 3: 2 (indices 1, 3)
        *   Row 4: 2 (indices 1, 3)
        *   Row 5: 3 (indices 1, 5, 6)
        *   Row 6: 2 (indices 2, 3)
        *   Row 7: 1 (index 2)
        *   Total G: 3 + 1 + 2 + 2 + 3 + 2 + 1 = 14.
    *   **X (Grey):**
        *   Row 2: 2
        *   Row 5: 1
        *   Total X: 3.
    *   **W (Maroon):**
        *   Row 2: 1
        *   Row 3: 1
        *   Total W: 2.
    *   **R (Red):**
        *   Row 3: 1
        *   Total R: 1.
    *   **A (Azure):**
        *   Row 4: 1
        *   Total A: 1.
    *   **O (Orange):**
        *   Row 4: 1
        *   Total O: 1.
    *   **Y (Yellow):**
        *   Row 7: 1
        *   Total Y: 1.
    *   **. (Black):** The rest.

*   **Dominant Color:** Green (G) with 14 occurrences.
*   **Mapping:** I need the pattern associated with Green (G).
*   From Example 2, the dominant color was Green (G).
*   The output pattern for Green (G) in Example 2 was:
    . A A
    . A .
    . A .

**6. Verification:**
*   Does the l

... [5694 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=4
"A harbor crowded with ships flying many flags — the fleet with the greatest number of vessels gets its ensign woven into the harbormaster's signal pennant."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (10895 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A busy harbor with ships flying flags of many nations.
*   **Dominance:** One fleet vastly outnumbers the others.
*   **Action:** Identify the dominant fleet by flag count.
*   **Output:** The harbormaster hoists that pennant.
*   **Grid Details:**
    *   Input grid size: 7x7.
    *   Output grid size: 3x3 (implied by "signal pennant is 3x3").
    *   Output content: "stitched in azure on a dark field". This suggests the output grid will be mostly black (.) with some Azure (A) pixels forming a pattern.
    *   "Dominant fleet": This implies finding the most frequent color in the input grid.
    *   "Signal pennant": This implies the pattern of the dominant color in the input grid determines the pattern of Azure in the output grid.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 7x7 grid.
    *   Colors present: B (Blue), O (Orange), W (White/Grey?), R (Red), G (Green), Y (Yellow), A (Azure).
    *   Let's count the colors in the input:
        *   B: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15... wait, let's count properly.
        *   Row 1: B . B . O . . (2 B)
        *   Row 2: B B W B . B . (4 B)
        *   Row 3: . . B B . R . (2 B)
        *   Row 4: . . . . G . B (1 B)
        *   Row 5: . Y . B . . B (2 B)
        *   Row 6: . . B . R . A (1 B)
        *   Row 7: . . B . O G B (2 B)
        *   Total B: 2+4+2+1+2+1+2 = 14.
        *   Other colors: O(2), W(1), R(2), G(2), Y(1), A(1).
        *   Dominant color: Blue (B).
    *   Output: 3x3 grid.
        *   . . A
        *   A A .
        *   . A .
    *   Observation: The output is a 3x3 pattern of Azure (A) on Black (.).
    *   Hypothesis: The pattern of the dominant color (B) in the input grid is mapped to the 3x3 output grid. But how? The input is 7x7. The output is 3x3.
    *   Maybe the input grid is divided into 3x3 regions? 7 is not divisible by 3.
    *   Maybe the dominant color forms a shape?
    *   Let's look at the positions of B in the input.
        (0,0), (0,2)
        (1,0), (1,1), (1,3), (1,5)
        (2,2), (2,3)
        (3,6)
        (4,3), (4,6)
        (5,2)
        (6,2), (6,6)
    *   This looks scattered.
    *   Let's look at the Output pattern again:
        . . A
        A A .
        . A .
        (Indices: (0,2), (1,0), (1,1), (2,1))
    *   Is there a subgrid in the input that matches this?
    *   Let's check the corners or center.
    *   Maybe the input grid represents a larger image where the dominant color is the "foreground" and others are "background".
    *   Let's re-read the metaphor: "One fleet vastly outnumbers the others... The harbormaster hoists that pennant."
    *   "Signal pennant is 3x3".
    *   Maybe the 7x7 grid contains a 3x3 pattern hidden within the dominant color's distribution?
    *   Or maybe the 7x7 grid *is* the pattern, but scaled? No, 7x7 to 3x3 is a reduction.
    *   Let's look at Example 2.
    *   Input:
        . G . G X G .
        . . G G . . .
        A . . . . . G
        G Y G W G . G
        . . W G B G G
        . G G G . G .
        . . . . . . G
    *   Count G:
        R1: 3
        R2: 2
        R3: 1
        R4: 4
        R5: 3
        R6: 4
        R7: 1
        Total G: 18.
    *   Other colors: X(1), A(1), Y(1), W(2), B(1).
    *   Dominant: Green (G).
    *   Output:
        . A A
        . A .
        . A .
    *   Pattern of A in output: (0,1), (0,2), (1,1), (2,1).
    *   Let's look at the positions of G in the input.
        (0,1), (0,3), (0,5)
        (1,2), (1,3)
        (2,6)
        (3,0), (3,2), (3,4), (3,6)
        (4,3), (4,5), (4,6)
        (5,1), (5,2), (5,3), (5,5)
        (6,6)
    *   This doesn't immediately look like the output pattern.
    *   Let's look at Example 3.
    *   Input:
        . . R . B X G
        . . R W . R .
        R R R Y R . .
        . R . R O R .
        R R . . R R M
        . R R . R . .
        X . Y R . R R
    *   Count R:
        R1: 1
        R2: 2
        R3: 4
        R4: 3
        R5: 4
        R6: 3
        R7: 3
        Total R: 20.
    *   Dominant: Red (R).
    *   Output:
        . . .
        A A A
        . . .
    *   Pattern: Middle row is all A.
    *   Let's look at R positions.
        (0,2)
        (1,2), (1,5)
        (2,0), (2,1), (2,2), (2,4)
        (3,1), (3,3), (3,5)
        (4,0), (4,1), (4,4), (4,5)
        (5,1), (5,2), (5,4)
        (6,3), (6,5), (6,6)
    *   Is there a 3x3 area in the input that is mostly R?
    *   Or is the output pattern derived from the *shape* of the dominant color?
    *   Let's look at the "Signal Pennant" description again. "stitched in azure on a dark field".
    *   This implies the output is always 3x3, with A and .
    *   The pattern of A corresponds to the pattern of the dominant color.
    *   How do we map 7x7 to 3x3?
    *   Maybe we divide the 7x7

... [5952 chars truncated]
alt-12 electronics qwen3.5-122b: k=2
"A circuit board buzzes with signals on many frequencies, but the dominant frequency triggers a specific LED pattern on the diagnostic display."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11133 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Noisy circuit board", "signals across many frequency bands".
*   **Task:** "Identify the dominant frequency". "Each frequency is mapped to a unique diagnostic LED pattern". "Light up that pattern".
*   **Grid Details:** Input is 7x7. Output is 3x3.
*   **Output Color:** "lit in azure on a dark panel". This suggests the output grid will contain 'A' (azure) and '.' (black/dark).
*   **Interpretation:** I need to find the most frequent color in the input grid (the "dominant frequency"). Then, I need to map that color to a specific 3x3 pattern (the "diagnostic LED pattern"). The output grid is 3x3.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** 7x7 grid.
    *   Colors present: B (blue), O (orange), W (white/grey?), R (red), G (green), Y (yellow), A (azure).
    *   Let's count the frequencies of each color in the input.
    *   Row 1: B . B . O . . -> 2 B, 1 O
    *   Row 2: B B W B . B . -> 4 B, 1 W
    *   Row 3: . . B B . R . -> 2 B, 1 R
    *   Row 4: . . . . G . B -> 1 G, 1 B
    *   Row 5: . Y . B . . B -> 1 Y, 2 B
    *   Row 6: . . B . R . A -> 1 B, 1 R, 1 A
    *   Row 7: . . B . O G B -> 2 B, 1 O, 1 G
    *   Total Counts:
        *   B: 2+4+2+1+2+1+2 = 14
        *   O: 1+1 = 2
        *   W: 1
        *   R: 1+1 = 2
        *   G: 1+1 = 2
        *   Y: 1
        *   A: 1
        *   .: Rest
    *   Dominant Color: **B (Blue)** with 14 occurrences.
*   **Output:** 3x3 grid.
    *   . . A
    *   A A .
    *   . A .
    *   This is a pattern of 'A's.
    *   Let's look at the shape. It looks like a specific digit or symbol.
    *   Row 1: ..A
    *   Row 2: AA.
    *   Row 3: .A.
    *   This looks like the number '2' or 'Z' or something similar? Or maybe it's specific to the color B.
    *   Wait, the description says "Each frequency is mapped to a unique diagnostic LED pattern". This implies there is a mapping from Input Color -> Output Pattern.
    *   In Example 1, Input Dominant = B. Output Pattern = specific arrangement of A's.

**Example 2:**
*   **Input:** 7x7 grid.
    *   Colors present: G, X, A, Y, W, B.
    *   Let's count frequencies.
    *   Row 1: . G . G X G . -> 3 G, 1 X
    *   Row 2: . . G G . . . -> 2 G
    *   Row 3: A . . . . . G -> 1 A, 1 G
    *   Row 4: G Y G W G . G -> 4 G, 1 Y, 1 W
    *   Row 5: . . W G B G G -> 3 G, 1 W, 1 B
    *   Row 6: . G G G . G . -> 4 G
    *   Row 7: . . . . . . G -> 1 G
    *   Total Counts:
        *   G: 3+2+1+4+3+4+1 = 18
        *   X: 1
        *   A: 1
        *   Y: 1
        *   W: 1+1 = 2
        *   B: 1
    *   Dominant Color: **G (Green)** with 18 occurrences.
*   **Output:** 3x3 grid.
    *   . A A
    *   . A .
    *   . A .
    *   This is a pattern of 'A's.
    *   Shape:
        *   ..AA (Wait, 3 cols) -> . A A
        *   . A .
        *   . A .
    *   This looks like the number '1' or '7' or 'L' rotated?
    *   Let's check the shape again.
        *   Row 1: . A A
        *   Row 2: . A .
        *   Row 3: . A .
    *   It looks like a vertical line on the right side, with a top bar extending left. Like a '7' or 'L' shape.

**Hypothesis:**
1.  Count the occurrences of each non-black color in the 7x7 input grid.
2.  Identify the color with the highest count (the "dominant frequency").
3.  Map this dominant color to a specific 3x3 pattern made of 'A' (azure) on a background of '.' (black).
4.  The mapping seems to be: Color -> Shape.
    *   Blue (B) -> Shape 1 (Example 1)
    *   Green (G) -> Shape 2 (Example 2)
    *   I need to figure out the mapping rule. Is it based on the shape of the letter? Or a standard 7-segment display? Or a specific set of icons?
    *   Let's look at the shapes again.
    *   Blue (B) Pattern:
        . . A
        A A .
        . A .
        This looks like a '2' on a 3x3 grid?
        2:
        AAA
        ..A
        AAA
        No.
        Maybe it represents the letter 'B'?
        B:
        AA.
        A.A
        AA.
        No.
        Maybe it represents the number of the color in a list?
        Maybe it's a 7-segment display representation?
        3x3 grid is small for 7-segment.
        Let's look at the Test Input to see what the dominant color is.

**Test Input:**
*   Grid:
    G . G . . . G
    G . W X . . X
    . G . G . R W
    A G . G . . O
    . G X . . G G
    . . G G . . .
    . . G . Y . .
*   Let's count frequencies.
    *   Row 1: G . G . . . G -> 3 G
    *   Row 2: G . W X . . X -> 1 G, 1 W, 2 X
    *   Row 3: . G . G . R W -> 2 G, 1 R, 1 W
    *   Row 4: A G . G . . O -> 2 G, 1 A, 1 O
    *   Row 5: . G X . . G G -> 3 G, 1 X
    *   Row 6: . . G G . . . -> 2 G
    *   Row 7: . . G . Y . . -> 1 G, 1 Y
    *   Total Counts:
        *   G: 3 + 1 + 2 + 2 + 3 + 2 + 1 = 14
        *   X: 2 + 1 = 3
 

... [6241 chars truncated]
alt-13 mythology qwen3.5-122b: k=3
"Many minor spirits haunt a sacred grove, but the one whose presence is felt most strongly leaves its unique rune glowing on the altar stone."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (8726 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A "sacred grove" (7x7 grid) with "spiritual presences" (colored pixels).
*   **Dominance:** One spirit manifests "far more intensely" than others. This suggests finding the most frequent color or the "background" color that stands out.
*   **Action:** "Sense which spirit dominates the grove." -> Identify the dominant color.
*   **Result:** "Each spirit, when it prevails, inscribes its personal rune on the altar — a compact, fixed glyph." -> The output is a 3x3 grid (the "altar rune").
*   **Visuals:** "glowing azure on dark stone". This might imply the output color is Azure (A) or related to the dominant color.
*   **Grid Details:** Input is 7x7. Output is 3x3.

**2. Analyze the Training Examples:**

**Example 1:**
Input (7x7):
B . B . O . .
B B W B . B .
. . B B . R .
. . . . G . B
. Y . B . . B
. . B . R . A
. . B . O G B

Colors present:
B (Blue): 1, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49.
Let's count properly.
Row 1: B, B, O (2 B)
Row 2: B, B, W, B, B (4 B)
Row 3: B, B, R (2 B)
Row 4: G, B (1 B)
Row 5: Y, B, B (2 B)
Row 6: B, R, A (1 B)
Row 7: B, O, G, B (2 B)
Total B count: 2+4+2+1+2+1+2 = 14.
Total cells: 49.
Other colors: O(2), W(1), R(2), G(2), Y(1), A(1).
Dominant color is Blue (B).

Output (3x3):
. . A
A A .
. A .

The output contains 'A' (Azure) and '.' (Black).
The pattern of 'A's looks like a specific shape.
Let's look at the positions of the dominant color (B) in the input.
(0,0), (0,2)
(1,0), (1,1), (1,3), (1,5)
(2,2), (2,3)
(3,6)
(4,3), (4,6)
(5,2)
(6,2), (6,6)
This doesn't immediately look like a 3x3 pattern.

Let's look at the output shape:
. . A
A A .
. A .
This looks like a specific glyph.
Is it related to the dominant color? The dominant color is B. The output uses A.
Wait, the description says "glowing azure on dark stone". Maybe the output is always Azure (A) regardless of the dominant color? Or maybe the dominant color determines the shape, and the color is fixed to A?
Let's check Example 2.

**Example 2:**
Input (7x7):
. G . G X G .
. . G G . . .
A . . . . . G
G Y G W G . G
. . W G B G G
. G G G . G .
. . . . . . G

Dominant color count:
G:
R1: 3
R2: 2
R3: 1
R4: 4
R5: 3
R6: 4
R7: 1
Total G: 3+2+1+4+3+4+1 = 18.
Other colors: X(1), A(1), Y(1), W(2), B(1).
Dominant color is Green (G).

Output (3x3):
. A A
. A .
. A .

The output uses 'A' (Azure) again.
The shape is:
. A A
. A .
. A .
This is different from Example 1.
So the shape depends on the input, but the color is always Azure (A).
How is the shape derived?
Maybe it's a downsampling? Or a specific pattern matching?
The input is 7x7. The output is 3x3.
7x7 to 3x3 suggests a reduction.
Maybe the 7x7 grid is divided into regions?
Or maybe it's about the "spirit" (dominant color) forming a shape.
Let's look at the positions of the dominant color in Example 2 (G).
(0,1), (0,3), (0,5)
(1,2), (1,3)
(2,6)
(3,0), (3,2), (3,4), (3,6)
(4,3), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,5)
(6,6)
This is scattered.

Let's look at the "non-dominant" colors.
Example 1: Dominant B. Non-dominant: O, W, R, G, Y, A.
Example 2: Dominant G. Non-dominant: X, A, Y, W, B.
Example 3:
Input:
. . R . B X G
. . R W . R .
R R R Y R . .
. R . R O R .
R R . . R R M
. R R . R . .
X . Y R . R R

Dominant color count:
R:
R1: 1
R2: 3
R3: 4
R4: 3
R5: 4
R6: 3
R7: 3
Total R: 1+3+4+3+4+3+3 = 21.
Dominant is Red (R).

Output (3x3):
. . .
A A A
. . .

Output uses 'A' (Azure).
Shape is a horizontal line in the middle row.

**Hypothesis 1: The output is a 3x3 representation of the dominant color's distribution.**
How to map 7x7 to 3x3?
Maybe divide the 7x7 grid into 3x3 blocks?
7 is not divisible by 3.
Maybe center 3x3?
Maybe it's about the "rune" being a specific symbol associated with the dominant color?
But the dominant colors are different (B, G, R) and the output color is always A.
The description says "Each spirit, when it prevails, inscribes its personal rune... Read the glowing rune."
This implies the shape is the "rune" of the dominant spirit.
But how do we know which shape corresponds to which spirit?
Wait, the examples show different shapes for different dominant colors.
Ex 1 (B):
. . A
A A .
. A .
Ex 2 (G):
. A A
. A .
. A .
Ex 3 (R):
. . .
A A A
. . .

Is there a relationship between the dominant color and the shape?
B -> Shape 1
G -> Shape 2
R -> Shape 3
But I don't have a mapping table. I need to derive the shape from the input grid itself.
The input grid contains the dominant color scattered.
Maybe the scattered pixels form the shape when viewed in a specific way?
Or maybe the *other* colors form the shape?
Let's check the non-dominant pixels in Example 3 (R is dominant).
Non-R pixels:
(0,2) B, (0,3) X, (0,4) G
(1,3) W
(2,3) Y
(3,4)

... [3846 chars truncated]
alt-14 dance qwen3.5-122b: k=3
"A crowded dance floor where many styles collide — whichever style claims the most dancers gets its signature formation frozen in the spotlight."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (12768 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A 7x7 "dance floor" (input grid).
*   **Action:** Identify the "dominant dance style" (most frequent color?).
*   **Result:** "Each style, when it takes over, resolves into a characteristic formation — a compact arrangement."
*   **Output:** A 3x3 "spotlight formation" (output grid).
*   **Color:** The output is "illuminated in azure on a dark stage". This suggests the output grid will contain 'A' (azure) and '.' (black/dark).
*   **Key Insight:** The dominant color in the input determines the shape of the 'A's in the 3x3 output grid. The 'A's form a pattern corresponding to the dominant color's "characteristic formation".

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 7x7 grid.
    *   Colors present: B (blue), . (black), O (orange), W (maroon), R (red), G (green), Y (yellow), A (azure).
    *   Let's count the frequencies of non-black colors.
        *   B: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12... Let's count carefully.
        *   Row 1: B, B, O (2 B)
        *   Row 2: B, B, W, B, B (4 B)
        *   Row 3: B, B, R (2 B)
        *   Row 4: G, B (1 B)
        *   Row 5: Y, B, B (2 B)
        *   Row 6: B, R, A (1 B)
        *   Row 7: B, O, G, B (2 B)
        *   Total B count: 2+4+2+1+2+1+2 = 14.
        *   Other colors: O(2), W(1), R(2), G(2), Y(1), A(1).
        *   Dominant color is **B (Blue)**.
    *   Output: 3x3 grid.
        ```
        . . A
        A A .
        . A .
        ```
    *   Pattern of A's:
        (0,2), (1,0), (1,1), (2,1).
        This looks like a specific shape. Is it related to the letter 'B'? Or a number? Or just a shape associated with Blue?
        Let's look at the shape formed by the B's in the input? No, the input B's are scattered.
        Maybe the shape corresponds to the letter 'B' in a 3x3 pixel font?
        B in 3x3:
        A A A
        A . A
        A A A
        Or:
        A A .
        A . A
        A A A
        The output is:
        . . A
        A A .
        . A .
        This doesn't look like a standard 'B'.
        Let's re-read the metaphor: "Each style, when it takes over, resolves into a characteristic formation".
        Maybe the dominant color *is* the formation?
        Wait, look at the output colors. They are 'A' (azure) and '.' (black).
        So the output is always a 3x3 mask of 'A's.
        The question is: Which 3x3 pattern corresponds to which dominant color?

    *   Let's check Example 2.
    *   Input: 7x7 grid.
    *   Colors: G, X, A, Y, W, B.
    *   Count G:
        R1: 3
        R2: 2
        R3: 1
        R4: 4
        R5: 3
        R6: 3
        R7: 1
        Total G: 17.
    *   Dominant color is **G (Green)**.
    *   Output:
        ```
        . A A
        . A .
        . A .
        ```
    *   Pattern of A's:
        (0,1), (0,2), (1,1), (2,1).
        This looks like a '7' or a 'J' or part of a 'G'?
        Let's look at the shape again.
        . A A
        . A .
        . A .
        It looks like a vertical line with a top right extension.

    *   Let's check Example 3.
    *   Input: 7x7 grid.
    *   Colors: R, B, X, G, W, Y, O, M.
    *   Count R:
        R1: 1
        R2: 3
        R3: 5
        R4: 4
        R5: 4
        R6: 3
        R7: 3
        Total R: 23.
    *   Dominant color is **R (Red)**.
    *   Output:
        ```
        . . .
        A A A
        . . .
        ```
    *   Pattern of A's:
        (1,0), (1,1), (1,2).
        This is a horizontal line in the middle. Looks like the letter 'I' or 'H' or just a line.

    *   **Hypothesis:** The output 3x3 grid represents the dominant color's letter in a 3x3 pixel font.
        *   Example 1: Dominant B. Output shape:
            . . A
            A A .
            . A .
            Does this look like a 'B'?
            Standard 3x3 B:
            A A A
            A . A
            A A A
            Or:
            A A .
            A . A
            A A .
            The output is:
            . . A
            A A .
            . A .
            This looks like a '7' or a 'L' or something.
            Wait, let's look at the counts again.
            Maybe it's not the letter of the color.
            Maybe it's the shape formed by the dominant color in the input?
            In Ex 1, B is everywhere.
            In Ex 2, G is everywhere.
            In Ex 3, R is everywhere.

    *   Let's reconsider the "characteristic formation".
    *   Maybe the output shape corresponds to the *number* of the dominant color in some way? No.
    *   Maybe the output shape is the letter of the color name?
        *   B -> B?
        *   G -> G?
        *   R -> R?
        Let's check 3x3 representations of letters.
        R:
        A A A
        A . A
        A A A
        (Like B but bottom leg).
        Output for R (Ex 3) is:
      

... [7831 chars truncated]
alt-15 geology qwen3.5-122b: k=2
"A core sample reveals many minerals, but the one that saturates the rock determines which crystal habit is etched into the field notebook."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10761 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** Geological cross-section, mineral types in rock.
*   **Task:** Identify the dominant mineral by abundance.
*   **Output:** A 3x3 crystal habit sketch drawn in azure (A) on a dark page (black .).
*   **Input Grid Size:** 7x7.
*   **Output Grid Size:** 3x3.
*   **Key Concept:** "Dominant mineral" -> "Abundance". "Crystal habit" -> "Fixed geometric form". "Azure on dark page" -> Output is mostly black (.) with some azure (A).

**2. Analyze the Training Examples:**

**Example 1:**
Input (7x7):
B . B . O . .
B B W B . B .
. . B B . R .
. . . . G . B
. Y . B . . B
. . B . R . A
. . B . O G B

Let's count the colors in the input:
B (Blue): 1, 3, 5, 6, 8, 10, 11, 13, 15, 17, 19, 21, 23, 25, 27... wait, let's count properly.
Row 1: B, B, O (2 B)
Row 2: B, B, W, B, B (4 B)
Row 3: B, B, R (2 B)
Row 4: G, B (1 B)
Row 5: Y, B, B (2 B)
Row 6: B, R, A (1 B)
Row 7: B, O, G, B (2 B)
Total B count: 2+4+2+1+2+1+2 = 14.
Total cells: 49.
Other colors:
O: 2
W: 1
R: 2
G: 2
Y: 1
A: 1
. (Black): 49 - 14 - 2 - 1 - 2 - 2 - 1 - 1 = 26.

Dominant color is B (Blue) with 14 occurrences.
Output (3x3):
. . A
A A .
. A .

The output contains 'A' (Azure) and '.' (Black).
The metaphor says "drawn in azure on a dark page". So the output is a 3x3 pattern of A's and .'s.
The pattern seems to represent the "crystal habit" of the dominant mineral.
How is the pattern derived?
The dominant mineral is Blue (B).
Let's look at the positions of B in the input grid.
(0,0), (0,2)
(1,0), (1,1), (1,3), (1,5)
(2,2), (2,3)
(3,6)
(4,3), (4,6)
(5,2)
(6,2), (6,6)

This looks scattered. Is there a specific shape formed by the dominant color?
Or is the output pattern related to the *shape* of the dominant color's distribution?
Or is it a specific symbol associated with the dominant color?
Wait, the metaphor says "Each mineral, when dominant, produces a characteristic crystal habit". This implies the output shape depends on *which* color is dominant.
In Example 1, B is dominant. Output shape is:
. . A
A A .
. A .
This looks like a specific shape.

Let's check Example 2.
Input (7x7):
. G . G X G .
. . G G . . .
A . . . . . G
G Y G W G . G
. . W G B G G
. G G G . G .
. . . . . . G

Count colors:
G (Green):
Row 1: 3
Row 2: 2
Row 3: 1
Row 4: 4
Row 5: 3
Row 6: 4
Row 7: 1
Total G: 3+2+1+4+3+4+1 = 18.
Total cells: 49.
Other colors:
X: 1
A: 1
Y: 1
W: 2
B: 1
.: 49 - 18 - 1 - 1 - 1 - 2 - 1 = 25.

Dominant color is G (Green) with 18 occurrences.
Output (3x3):
. A A
. A .
. A .

So, if B is dominant -> Shape 1.
If G is dominant -> Shape 2.

The task is to find the dominant color in the Test Input, and then output the corresponding 3x3 shape associated with that color.
But I don't have a lookup table of "Color -> Shape". I need to infer the rule or the mapping from the examples.
Wait, usually in these ARC-like tasks, the rule is consistent.
Is the output shape derived from the input grid itself?
Maybe the dominant color forms a shape in the 7x7 grid that maps to the 3x3 grid?
Or maybe the output shape is fixed for a specific color?
Let's look at the positions of the dominant color in the input grids again.

Example 1 (Dominant B):
B positions:
(0,0), (0,2)
(1,0), (1,1), (1,3), (1,5)
(2,2), (2,3)
(3,6)
(4,3), (4,6)
(5,2)
(6,2), (6,6)
Does this form a recognizable shape? It looks like noise.
However, the output is 3x3.
Maybe the 7x7 grid is divided into 3x3 regions? No, 7 is not divisible by 3.
Maybe the output is a "downsampled" version?
Or maybe the output represents the *count* of the dominant color modulo something? No, it's a shape.

Let's reconsider the metaphor. "Sketch it in the notebook". "Crystal habit".
This suggests the output is a symbol representing the mineral.
If the rule is "Color X always maps to Shape Y", I need to find the mapping.
But I only have two examples.
Example 1: B -> Shape 1
Example 2: G -> Shape 2
Test Input: I need to find the dominant color.
Let's count colors in Test Input.

Test Input:
G . G . . . G
G . W X . . X
. G . G . R W
A G . G . . O
. G X . . G G
. . G G . . .
. . G . Y . .

Count:
G:
Row 1: 3 (0, 2, 6)
Row 2: 1 (0)
Row 3: 2 (1, 3)
Row 4: 2 (1, 3)
Row 5: 3 (1, 5, 6)
Row 6: 2 (2, 3)
Row 7: 1 (2)
Total G: 3+1+2+2+3+2+1 = 14.

Other colors:
W: 2
X: 3
R: 1
A: 1
O: 1
Y: 1
.: 49 - 14 - 2 - 3 - 1 - 1 - 1 - 1 = 26.

Dominant color is G (Green) with 14 occurrences.
In Example 2, G was also dominant (18 occurrences).
If the rule is "Dominant Color determines the Output Shape", then since G is dominant in both Example 2 and the Test Input, the output should be the same as Example 2's output.
Example 2 Output:
. A A
. A .
. A .

Is it that simple?
Let's check if there's any other logic.
Maybe the shape depends on the *count*?
Ex 1: B count = 14. Shape 1.
Ex 2: G count = 18. Shape 2.
Test: G count = 14.
If it depends on count, Test (14) might match Ex 

... [5944 chars truncated]
alt-2 cooking qwen3.5-122b: k=2
"A chef tastes a complex stew and names the ingredient that overpowers everything else — each overpowering flavor gets plated in its own distinctive garnish pattern."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11881 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 7x7 grid ("stew pot") with many ingredients (colors).
*   **Observation:** One flavor (color) dominates the broth.
*   **Task:** Identify the dominant color.
*   **Output:** A 3x3 grid ("plate") representing a "garnish" corresponding to the dominant flavor.
*   **Output Style:** "Garnished in azure on a clean dark surface." This suggests the output grid is 3x3, likely containing the dominant color and/or Azure (A) and Black (.).
*   **Key Phrase:** "Each dominant flavor has a traditional plating style — a specific arrangement of garnish on a small square plate." This implies there's a mapping from the dominant color to a specific 3x3 pattern.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** 7x7 grid.
    *   Colors present: B (Blue), . (Black), O (Orange), W (Maroon), R (Red), G (Green), Y (Yellow), A (Azure).
    *   Let's count the occurrences of each color to find the "dominant flavor".
    *   B: (0,0), (0,2), (1,0), (1,1), (1,3), (1,5), (2,2), (2,3), (3,6), (4,3), (4,6), (5,2), (6,2), (6,6). Count = 14.
    *   .: (0,1), (0,3), (0,4), (0,5), (0,6), (1,2), (1,4), (1,6), (2,0), (2,1), (2,4), (2,6), (3,0), (3,1), (3,2), (3,3), (3,5), (4,0), (4,2), (4,4), (4,5), (5,0), (5,1), (5,3), (5,5), (6,0), (6,1), (6,3), (6,4), (6,5). Count = 30.
    *   Wait, the metaphor says "one flavor dominates". Usually, in these puzzles, the background (black/dot) is ignored or treated differently. Let's look at the non-black colors.
    *   Non-black colors: B, O, W, R, G, Y, A.
    *   B count: 14.
    *   O count: 2.
    *   W count: 1.
    *   R count: 2.
    *   G count: 2.
    *   Y count: 1.
    *   A count: 1.
    *   Dominant non-black color is **Blue (B)**.
*   **Output:** 3x3 grid.
    ```
    . . A
    A A .
    . A .
    ```
    *   Colors in output: A (Azure) and . (Black).
    *   Pattern:
        ```
        . . A
        A A .
        . A .
        ```
    *   This looks like a specific shape made of Azure pixels.
    *   The metaphor says "garnished in azure". So the output is likely a pattern of Azure pixels on a black background.
    *   The pattern corresponds to the dominant color **Blue**.

**Example 2:**
*   **Input:** 7x7 grid.
    *   Colors present: G, ., X, A, Y, W, B.
    *   Let's count non-black colors.
    *   G: (0,1), (0,3), (0,5), (1,2), (1,3), (2,6), (3,0), (3,2), (3,4), (3,6), (4,3), (4,5), (4,6), (5,1), (5,2), (5,3), (5,5), (6,6). Count = 18.
    *   X: (0,4), (1,2 is G), (3,3 is W), (4,2 is W). Wait, let's recount carefully.
    *   Row 0: . G . G X G . -> G:3, X:1
    *   Row 1: . . G G . . . -> G:2
    *   Row 2: A . . . . . G -> A:1, G:1
    *   Row 3: G Y G W G . G -> G:4, Y:1, W:1
    *   Row 4: . . W G B G G -> W:1, G:3, B:1
    *   Row 5: . G G G . G . -> G:4
    *   Row 6: . . . . . . G -> G:1
    *   Total G: 3+2+1+4+3+4+1 = 18.
    *   Total X: 1.
    *   Total A: 1.
    *   Total Y: 1.
    *   Total W: 2.
    *   Total B: 1.
    *   Dominant non-black color is **Green (G)**.
*   **Output:** 3x3 grid.
    ```
    . A A
    . A .
    . A .
    ```
    *   Colors in output: A (Azure) and . (Black).
    *   Pattern:
        ```
        . A A
        . A .
        . A .
        ```
    *   This pattern corresponds to the dominant color **Green**.

**3. Synthesize the Transformation Rule:**
*   **Step 1:** Count the frequency of each non-black color in the 7x7 input grid.
*   **Step 2:** Identify the color with the highest frequency (the "dominant flavor").
*   **Step 3:** Map this dominant color to a specific 3x3 pattern made of Azure (A) pixels on a Black (.) background.
*   **Step 4:** Output the 3x3 grid.

**4. Determine the Mapping:**
*   From Example 1: Dominant = Blue (B) -> Pattern 1.
    Pattern 1:
    . . A
    A A .
    . A .
*   From Example 2: Dominant = Green (G) -> Pattern 2.
    Pattern 2:
    . A A
    . A .
    . A .

I need to figure out the mapping logic. Is it based on the shape of the letter? Or is it a fixed lookup table?
Since I only have two examples, I can't build a full lookup table for all colors. However, I need to solve the Test Input.
Let's check the Test Input to see which color is dominant. If it's Blue or Green, I can just copy the pattern. If it's a new color, I need to deduce the pattern generation rule.

**5. Analyze Test Input:**
*   **Input:** 7x7 grid.
    ```
    G . G . . . G
    G . W X . . X
    . G . G . R W
    A G . G . . O
    . G X . . G G
    . . G G . . .
    . . G . Y . .
    ```
*   **Count non-black colors:**
    *   **G (Green):**
        *   Row 0: 3 (indices 0, 2, 6)
        *   Row 1: 1 (index 0)
        *   Row 2: 2 (indices 1, 3)
        *   Row 3: 2 (indices 1, 3)
        *   Row 4: 3 (indices 1, 5, 6)
        *   Row 5: 2 (indices 2, 3)
        *   Row 6: 1 (index 2)
        *   Total G: 3 + 1 +

... [6944 chars truncated]
alt-3 music qwen3.5-122b: k=4
"An orchestra warms up in cacophony, but one section drowns out the rest — and the conductor's baton traces a gesture unique to that section's instrument family."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (11616 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A chaotic warm-up where many instruments play simultaneously." -> The input grid contains various colors scattered around.
*   **Dominance:** "One instrumental section is far louder and more numerous than the scattered soloists from other sections." -> There is one specific color that appears much more frequently than others in the input grid. This is the "dominant section".
*   **Action:** "The conductor responds with a specific baton gesture — a compact motion pattern unique to that instrument family. Transcribe the gesture." -> The output is a 3x3 grid representing a "gesture".
*   **Output Details:** "The conductor's gesture is a 3×3 notation in azure on silence." -> The output grid is 3x3. The background is black ('.'). The gesture itself is drawn in Azure ('A').
*   **Goal:** Identify the dominant color in the input, find a pattern associated with it (likely its shape or arrangement), and map that to a 3x3 grid using 'A' for the pattern and '.' for the background.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 7x7 grid.
    *   Colors present: B (Blue), O (Orange), W (Maroon), R (Red), G (Green), Y (Yellow), A (Azure).
    *   Counts:
        *   B: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12... Let's count properly.
        *   Row 1: B, B, O (2 B)
        *   Row 2: B, B, W, B, B (4 B)
        *   Row 3: B, B, R (2 B)
        *   Row 4: G, B (1 B)
        *   Row 5: Y, B, B (2 B)
        *   Row 6: B, R, A (1 B)
        *   Row 7: B, O, G, B (2 B)
        *   Total B: 2+4+2+1+2+1+2 = 14.
        *   Other colors: O(2), W(1), R(2), G(2), Y(1), A(1).
        *   Dominant color: **Blue (B)**.
    *   Output: 3x3 grid.
        ```
        . . A
        A A .
        . A .
        ```
    *   Observation: The output contains 'A' (Azure). The shape formed by 'A's looks like a specific pattern. Is it related to the shape of the Blue pixels in the input?
    *   Let's look at the Blue pixels in the input. They seem scattered.
    *   Wait, the metaphor says "Transcribe the gesture". The gesture is "unique to that instrument family".
    *   Maybe the dominant color *is* the instrument family. The output is the "gesture" for that family.
    *   Is there a mapping from Color -> 3x3 Pattern?
    *   Let's check Example 2.

*   **Example 2:**
    *   Input: 7x7 grid.
    *   Colors: G, X, A, Y, W, B.
    *   Counts:
        *   G: Row 1(3), Row 2(2), Row 3(1), Row 4(4), Row 5(3), Row 6(3), Row 7(1). Total: 3+2+1+4+3+3+1 = 17.
        *   Others are sparse.
        *   Dominant color: **Green (G)**.
    *   Output:
        ```
        . A A
        . A .
        . A .
        ```
    *   Comparison: Example 1 (Blue) -> Pattern 1. Example 2 (Green) -> Pattern 2.
    *   This suggests there is a specific 3x3 pattern associated with each color.

*   **Example 3:**
    *   Input: 7x7 grid.
    *   Colors: R, B, X, G, W, Y, O, M.
    *   Counts:
        *   R: Row 1(1), Row 2(3), Row 3(5), Row 4(4), Row 5(4), Row 6(3), Row 7(3). Total: 1+3+5+4+4+3+3 = 23.
        *   Dominant color: **Red (R)**.
    *   Output:
        ```
        . . .
        A A A
        . . .
        ```
    *   Pattern: A horizontal line in the middle row.

*   **Example 4:**
    *   Input: 7x7 grid.
    *   Colors: R, X, B, W, A.
    *   Counts:
        *   R: Row 1(3), Row 2(3), Row 3(0), Row 4(1), Row 5(1), Row 6(1), Row 7(2). Total: 3+3+0+1+1+1+2 = 11.
        *   Wait, let's recount carefully.
        *   Row 1: R, R, R (3)
        *   Row 2: R, R, R (3)
        *   Row 3: B (0 R)
        *   Row 4: R (1)
        *   Row 5: R (1)
        *   Row 6: R (1)
        *   Row 7: R, R, R (3)
        *   Total R: 11.
        *   Other colors: X(1), B(2), W(2), A(1).
        *   Dominant color: **Red (R)**.
    *   Output:
        ```
        . . .
        A A A
        . . .
        ```
    *   This matches Example 3. Red -> Horizontal Line.

**3. Synthesize the Rule:**
*   **Step 1:** Count the frequency of each color in the 7x7 input grid.
*   **Step 2:** Identify the most frequent color (the "dominant section").
*   **Step 3:** Map this dominant color to a specific 3x3 pattern using Azure ('A') on a black background ('.').
*   **Step 4:** The mapping seems to be:
    *   Blue (B) ->
        ```
        . . A
        A A .
        . A .
        ```
    *   Green (G) ->
        ```
        . A A
        . A .
        . A .
        ```
    *   Red (R) ->
        ```
        . . .
        A A A
        . . .
        ```
    *   What about other colors? I need to check the Test Input to see which color is dominant there.

**4. Analyze the Test Input:**
*   Input Grid:
    ```
    G . G . . . G
    G . W X . . X
    . G . G . R W
    A G . G . . O
    . G X . . G G
    . . G G . . .
    . . G . Y . .
    ```
*

... [6682 chars truncated]
alt-4 sports qwen3.5-122b: k=3
"On a field where players from many teams have wandered in, the team with the most jerseys gets to raise their unique pennant on the scoreboard."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (12237 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A "chaotic scrimmage field" (the input grid) with "athletes in various team colors".
*   **Dominance:** "One team's jersey color appears far more often than any other." -> This implies finding the most frequent color in the input grid.
*   **Action:** "Count the jerseys and identify the team with the largest presence." -> Confirm the most frequent color.
*   **Output Object:** "Each team has a signature pennant shape. Hoist the winning team's pennant on the scoreboard." -> The output is a 3x3 grid representing a "pennant".
*   **Output Appearance:** "The scoreboard pennant is 3×3, displayed in azure against a dark board." -> The output grid is 3x3. The background is likely black (.) and the pennant shape is Azure (A).
*   **Goal:** Determine the shape of the pennant based on the dominant color found in the input.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 7x7 grid.
    *   Colors present: B (Blue), O (Orange), W (Maroon), R (Red), G (Green), Y (Yellow), A (Azure).
    *   Counts:
        *   B: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12... let's count carefully.
        *   Row 1: B, B (2)
        *   Row 2: B, B, B, B (4) -> Total 6
        *   Row 3: B, B (2) -> Total 8
        *   Row 4: B (1) -> Total 9
        *   Row 5: B, B (2) -> Total 11
        *   Row 6: B (1) -> Total 12
        *   Row 7: B, B (2) -> Total 14
        *   Other colors: O(2), W(1), R(2), G(2), Y(1), A(1).
        *   Dominant color: Blue (B).
    *   Output: 3x3 grid.
        ```
        . . A
        A A .
        . A .
        ```
    *   Observation: The output contains 'A' (Azure) and '.' (Black). The shape formed by 'A's looks like a specific pattern. Is it related to the dominant color 'B'? Or is it a fixed shape for the "winning team"?
    *   Wait, the description says "Each team has a signature pennant shape." This implies different dominant colors might yield different shapes. Or maybe the shape is fixed and the color is always Azure?
    *   The description says "displayed in azure against a dark board". This suggests the output color is always Azure (A) regardless of the input dominant color. The shape is the variable.
    *   Let's check the shape in Example 1. It looks like a '7' or a specific symbol.
    *   Let's check the dominant color again. It is Blue (B).
    *   Is there a mapping between the dominant color and the shape?
    *   Let's look at Example 2.

*   **Example 2:**
    *   Input: 7x7 grid.
    *   Colors: G (Green), X (Grey), A (Azure), Y (Yellow), W (Maroon), B (Blue).
    *   Counts:
        *   G: Row 1(3), Row 2(2), Row 3(1), Row 4(4), Row 5(3), Row 6(3), Row 7(1). Total: 3+2+1+4+3+3+1 = 17.
        *   Others are much fewer.
        *   Dominant color: Green (G).
    *   Output: 3x3 grid.
        ```
        . A A
        . A .
        . A .
        ```
    *   Shape: Looks like an 'L' or a '7' rotated? Or a specific letter?
    *   Comparing Example 1 (Blue) and Example 2 (Green).
        *   Ex 1 (Blue):
            . . A
            A A .
            . A .
        *   Ex 2 (Green):
            . A A
            . A .
            . A .
    *   These shapes are different. So the shape depends on the dominant color.

*   **Example 3:**
    *   Input: 7x7 grid.
    *   Colors: R (Red), B (Blue), X (Grey), G (Green), W (Maroon), Y (Yellow), O (Orange), M (Magenta).
    *   Counts:
        *   R: Row 1(1), Row 2(3), Row 3(5), Row 4(4), Row 5(4), Row 6(3), Row 7(3). Total: 1+3+5+4+4+3+3 = 23.
        *   Dominant color: Red (R).
    *   Output: 3x3 grid.
        ```
        . . .
        A A A
        . . .
        ```
    *   Shape: A horizontal line in the middle.

**3. Hypothesis Formulation:**
*   **Task:** Identify the most frequent color in the 7x7 input grid.
*   **Transformation:** Map that dominant color to a specific 3x3 pattern made of Azure (A) on a Black (.) background.
*   **Mapping Logic:** I need to figure out the mapping between the dominant color and the 3x3 shape.
    *   Blue (B) -> Shape 1
    *   Green (G) -> Shape 2
    *   Red (R) -> Shape 3
    *   Test Input Dominant Color -> Shape ?

Let's look at the shapes again.
*   **Blue (B):**
    . . A
    A A .
    . A .
    (Coordinates: (0,2), (1,0), (1,1), (2,1)) - Wait, let's use (row, col) 0-indexed.
    (0,2), (1,0), (1,1), (2,1).
    This looks like a 'Z' or 'S' or '7' or 'L' or something.
    Actually, let's look at the letters.
    B -> ?
    G -> ?
    R -> ?

    Maybe the shape represents the letter of the color?
    *   **R (Red):**
        . . .
        A A A
        . . .
        This is a horizontal line. Does 'R' look like a horizontal line? No.
        Does 'R' stand for something else?
        Maybe it's the number of letters? No.
        Maybe it's related t

... [7364 chars truncated]
alt-5 weather qwen3.5-122b: k=3
"A weather map swirls with many fronts, but one air mass dominates the region — and the forecast icon it produces on the bulletin board is uniquely its own."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (13599 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A satellite view of weather systems.
*   **Observation:** One type of front covers far more area than scattered pockets of other conditions.
*   **Task:** Read the dominant weather pattern. Each type of dominant front produces a characteristic forecast symbol (a compact icon). Display that icon on the forecast board.
*   **Grid Details:** Input is 7x7. Output is 3x3.
*   **Color Key:** `.`=black, `B`=blue, `R`=red, `G`=green, `Y`=yellow, `X`=grey, `M`=magenta, `O`=orange, `A`=azure, `W`=maroon.
*   **Output Color:** The description says "rendered in azure on a dark bulletin board". This implies the output grid will likely contain `A` (azure) and `.` (black/dark).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input (7x7):
        ```
        B . B . O . .
        B B W B . B .
        . . B B . R .
        . . . . G . B
        . Y . B . . B
        . . B . R . A
        . . B . O G B
        ```
    *   Output (3x3):
        ```
        . . A
        A A .
        . A .
        ```
    *   **Observation:**
        *   Count colors in Input:
            *   B (Blue): 1, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49. Wait, let's count properly.
            *   Row 1: B, B, O (2 B)
            *   Row 2: B, B, W, B, B (4 B)
            *   Row 3: B, B, R (2 B)
            *   Row 4: G, B (1 B)
            *   Row 5: Y, B, B (2 B)
            *   Row 6: B, R, A (1 B)
            *   Row 7: B, O, G, B (2 B)
            *   Total B: 2+4+2+1+2+1+2 = 14.
            *   Total cells: 49.
            *   Other colors: O(2), W(1), R(2), G(2), Y(1), A(1).
            *   Dominant color is Blue (B).
        *   Output contains `A` (Azure) and `.` (Black).
        *   The output shape is 3x3.
        *   The pattern in the output looks like a specific shape made of `A`s.
        *   Let's check the position of the dominant color `B` in the input.
        *   Is there a 3x3 subgrid in the input that matches the output pattern?
        *   Or is the output a representation of the dominant color's shape?
        *   Let's look at the counts again. B is definitely the most frequent.
        *   The output is a 3x3 grid.
        *   Let's look at the distribution of B in the input.
        *   Maybe the output represents the "shape" of the dominant color?
        *   Let's look at Example 2.

*   **Example 2:**
    *   Input (7x7):
        ```
        . G . G X G .
        . . G G . . .
        A . . . . . G
        G Y G W G . G
        . . W G B G G
        . G G G . G .
        . . . . . . G
        ```
    *   Output (3x3):
        ```
        . A A
        . A .
        . A .
        ```
    *   **Observation:**
        *   Count colors:
            *   G (Green): Row 1(3), Row 2(2), Row 3(1), Row 4(4), Row 5(3), Row 6(4), Row 7(1). Total = 3+2+1+4+3+4+1 = 18.
            *   Other colors: X(1), A(1), Y(1), W(2), B(1).
            *   Dominant color is Green (G).
        *   Output is 3x3 with `A` and `.`.
        *   The pattern of `A`s is:
            ```
            . A A
            . A .
            . A .
            ```
        *   This looks like a specific shape.

*   **Example 3:**
    *   Input (7x7):
        ```
        . . R . B X G
        . . R W . R .
        R R R Y R . .
        . R . R O R .
        R R . . R R M
        . R R . R . .
        X . Y R . R R
        ```
    *   Output (3x3):
        ```
        . . .
        A A A
        . . .
        ```
    *   **Observation:**
        *   Count colors:
            *   R (Red): Row 1(1), Row 2(2), Row 3(4), Row 4(3), Row 5(4), Row 6(3), Row 7(2). Total = 1+2+4+3+4+3+2 = 19.
            *   Other colors: B(1), X(2), G(1), W(1), Y(2), O(1), M(1).
            *   Dominant color is Red (R).
        *   Output is 3x3 with `A` and `.`.
        *   Pattern:
            ```
            . . .
            A A A
            . . .
            ```
            (A horizontal line in the middle).

**3. Synthesize the Transformation Rule:**

*   **Step 1: Identify the Dominant Color.**
    *   Ex 1: Blue (B) is dominant.
    *   Ex 2: Green (G) is dominant.
    *   Ex 3: Red (R) is dominant.
    *   This matches the metaphor "One type of front covers far more area".

*   **Step 2: Determine the Output Pattern.**
    *   The output is always 3x3.
    *   The output uses `A` (Azure) for the "symbol" and `.` (Black) for background.
    *   The symbol seems to depend on the dominant color.
    *   Let's check if the symbol corresponds to the dominant color's initial letter or some property.
        *   Ex 1: Dominant B (Blue). Output shape:
            ```
            . . A
            A A .
            . A .
            ```
            This look

... [8631 chars truncated]
alt-6 architecture qwen3.5-122b: k=5
"A city block is surveyed from above — whichever building material dominates the skyline determines which blueprint the city planner stamps onto the zoning permit."
MARC valid, solved with k=5
Prediction
vs
Expected
Reasoning (11342 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** Aerial view of a city block (7x7 grid).
*   **Dominant Material:** One material overwhelmingly dominates the landscape.
*   **Rare Materials:** Appear in isolated buildings.
*   **Task:** Identify the prevailing construction material.
*   **Action:** Stamp the permit with the appropriate mark.
*   **Output:** A 3x3 grid (zoning stamp).
*   **Ink Color:** Azure (A).
*   **Permit Color:** Dark (likely black '.').

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 7x7 grid.
    *   Colors present: B (Blue), . (Black), O (Orange), W (Maroon), R (Red), G (Green), Y (Yellow), A (Azure).
    *   Let's count the frequency of each color in the input.
        *   B: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49. Wait, let's count properly.
        *   Row 1: B . B . O . . (2 B)
        *   Row 2: B B W B . B . (4 B)
        *   Row 3: . . B B . R . (2 B)
        *   Row 4: . . . . G . B (1 B)
        *   Row 5: . Y . B . . B (2 B)
        *   Row 6: . . B . R . A (1 B)
        *   Row 7: . . B . O G B (2 B)
        *   Total B count: 2+4+2+1+2+1+2 = 14.
        *   Total cells: 49.
        *   Other colors: . (many), O (2), W (1), R (2), G (2), Y (1), A (1).
        *   Dominant color seems to be B (Blue).
    *   Output: 3x3 grid.
        *   . . A
        *   A A .
        *   . A .
    *   The output contains 'A' (Azure) and '.' (Black).
    *   The pattern of 'A's in the output looks like a specific shape.
    *   Let's look at the shape of the dominant color in the input.
    *   Where are the B's located?
        (0,0), (0,2)
        (1,0), (1,1), (1,3), (1,5)
        (2,2), (2,3)
        (3,6)
        (4,3), (4,6)
        (5,2)
        (6,2), (6,6)
    *   This doesn't look like a simple shape.
    *   Let's re-read the metaphor. "Stamp the permit with the appropriate mark." "The zoning stamp is 3x3, inked in azure on a dark permit."
    *   Maybe the output represents the *shape* of the dominant color? Or maybe it's a specific symbol associated with the dominant color?
    *   Let's look at the output pattern again:
        . . A
        A A .
        . A .
        This looks like a 'T' or a cross or something.
    *   Let's check the other examples to see if the output pattern is constant or depends on the input.

*   **Example 2:**
    *   Input: 7x7.
    *   Colors: G, ., X, A, Y, W, B.
    *   Count G:
        R1: 3
        R2: 2
        R3: 1
        R4: 4
        R5: 3
        R6: 4
        R7: 1
        Total G: 18.
    *   Dominant color is G (Green).
    *   Output:
        . A A
        . A .
        . A .
    *   This is a different pattern than Example 1.
    *   Example 1 Output:
        . . A
        A A .
        . A .
    *   Example 2 Output:
        . A A
        . A .
        . A .
    *   So the output pattern depends on the input.

*   **Example 3:**
    *   Input: 7x7.
    *   Colors: R, ., B, X, G, W, Y, O, M.
    *   Count R:
        R1: 1
        R2: 3
        R3: 5
        R4: 4
        R5: 4
        R6: 3
        R7: 3
        Total R: 23.
    *   Dominant color is R (Red).
    *   Output:
        . . .
        A A A
        . . .
    *   Pattern: A horizontal line in the middle.

*   **Example 4:**
    *   Input: 7x7.
    *   Colors: R, ., X, B, W, A.
    *   Count R:
        R1: 3
        R2: 3
        R3: 0
        R4: 1
        R5: 1
        R6: 1
        R7: 3
        Total R: 12.
    *   Count .:
        R1: 3
        R2: 3
        R3: 5
        R4: 5
        R5: 5
        R6: 4
        R7: 3
        Total .: 28.
    *   Wait, '.' is usually background. The metaphor says "One material overwhelmingly dominates". Usually, '.' is empty space/background. In Example 1, B was dominant (14 vs 28 dots). In Example 2, G was dominant (18 vs 28 dots). In Example 3, R was dominant (23 vs 26 dots). In Example 4, R is 12, . is 28.
    *   Let's check the counts again for Example 4.
        R1: R . . R R . X -> 3 R
        R2: . R R . . . R -> 3 R
        R3: . B . . . . . -> 0 R
        R4: . . . . R . W -> 1 R
        R5: . W . . . . R -> 1 R
        R6: . . R B . . A -> 1 R
        R7: R . . R R . . -> 3 R
        Total R = 12.
        Total cells = 49.
        Total '.' = 49 - 12 - (1 B + 1 W + 1 W + 1 B + 1 A + 1 X) = 49 - 12 - 6 = 31.
        So '.' is the most frequent. But the output is:
        . . .
        A A A
        . . .
        This matches Example 3's output.
        In Example 3, R was dominant (23). In Example 4, R is NOT dominant (12).
        However, the output is the same.
        Why?
        Maybe the rule isn't about the *most frequent* color, but a specific color?
        Or maybe the rule is about the shape 

... [6405 chars truncated]
alt-7 warfare qwen3.5-122b: k=4
"Scouts survey a battlefield crowded with banners from many factions. The faction that fields the most soldiers gets its battle standard replicated on the war room map."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (10884 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A contested field with factions. One faction vastly outnumbers the others.
*   **Action:** Count forces, determine the majority faction.
*   **Symbol:** Each faction has a unique battle standard (small, fixed emblem).
*   **Output:** Reproduce that emblem on the strategic map.
*   **Grid Details:** Input is 7x7. Output is 3x3.
*   **Emblem Color:** The description mentions "azure on a dark map". This suggests the output grid will likely contain 'A' (azure) and '.' (black/dark).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 7x7 grid.
    *   Colors present: B (blue), O (orange), W (maroon), R (red), G (green), Y (yellow), A (azure).
    *   Counts:
        *   B: 10
        *   O: 2
        *   W: 1
        *   R: 2
        *   G: 1
        *   Y: 1
        *   A: 1
    *   Majority: Blue (B).
    *   Output: 3x3 grid.
        ```
        . . A
        A A .
        . A .
        ```
    *   Observation: The output contains 'A' and '.'. The pattern looks like a specific shape. Is it related to the position of the majority color in the input? Or is it a fixed shape associated with the majority color?
    *   Let's check the position of 'B's in the input.
        (0,0), (0,2), (1,0), (1,1), (1,3), (1,5), (2,2), (2,3), (3,6), (4,3), (4,6), (5,2), (6,2), (6,6).
        Wait, let me recount carefully.
        Row 0: B . B . O . . -> B at 0, 2
        Row 1: B B W B . B . -> B at 0, 1, 3, 5
        Row 2: . . B B . R . -> B at 2, 3
        Row 3: . . . . G . B -> B at 6
        Row 4: . Y . B . . B -> B at 3, 6
        Row 5: . . B . R . A -> B at 2
        Row 6: . . B . O G B -> B at 2, 6
        Total B count: 2 + 4 + 2 + 1 + 2 + 1 + 2 = 14.
        Other colors: O(2), W(1), R(2), G(1), Y(1), A(1).
        Majority is definitely Blue (B).
    *   Output pattern:
        . . A
        A A .
        . A .
        This looks like a specific shape. Is it the shape of the letter 'B'? No. Is it the shape of the majority color's distribution? No, the input is 7x7, output is 3x3.
    *   Hypothesis: The output is a 3x3 representation of the majority color's "emblem". But the description says "Each faction carries a unique battle standard". This implies the standard is fixed for a color.
    *   Let's look at Example 2.

*   **Example 2:**
    *   Input: 7x7 grid.
    *   Colors: G, X, A, Y, W, B.
    *   Counts:
        *   G: 15 (Row 0: 3, Row 1: 2, Row 2: 1, Row 3: 4, Row 4: 3, Row 5: 3, Row 6: 1) -> 3+2+1+4+3+3+1 = 17? Let's count properly.
        R0: . G . G X G . (3 G)
        R1: . . G G . . . (2 G)
        R2: A . . . . . G (1 G)
        R3: G Y G W G . G (4 G)
        R4: . . W G B G G (3 G)
        R5: . G G G . G . (4 G)
        R6: . . . . . . G (1 G)
        Total G = 3+2+1+4+3+4+1 = 18.
        Others: X(1), A(1), Y(1), W(2), B(1).
        Majority: Green (G).
    *   Output:
        ```
        . A A
        . A .
        . A .
        ```
    *   Comparison:
        Ex 1 (Majority B):
        . . A
        A A .
        . A .
        Ex 2 (Majority G):
        . A A
        . A .
        . A .
    *   The output shapes are different. This confirms that the output shape depends on the majority color.
    *   The output uses 'A' (azure) to draw the shape on a '.' (black) background.
    *   So, the task is: Identify the most frequent color in the 7x7 input. Map that color to a specific 3x3 pattern using 'A'.

*   **Example 3:**
    *   Input: 7x7 grid.
    *   Colors: R, B, X, G, W, Y, O, M.
    *   Counts:
        *   R:
            R0: 2
            R1: 3
            R2: 5
            R3: 4
            R4: 4
            R5: 3
            R6: 3
            Total R = 24.
        *   Others are sparse.
        *   Majority: Red (R).
    *   Output:
        ```
        . . .
        A A A
        . . .
        ```
    *   Pattern for R: A horizontal line in the middle row.

*   **Example 4:**
    *   Input: 7x7 grid.
    *   Colors: R, X, B, W, A.
    *   Counts:
        *   R:
            R0: 3
            R1: 3
            R2: 0
            R3: 1
            R4: 1
            R5: 1
            R6: 3
            Total R = 12.
        *   Others: X(1), B(2), W(2), A(1).
        *   Majority: Red (R).
    *   Output:
        ```
        . . .
        A A A
        . . .
        ```
    *   Pattern for R matches Example 3. This confirms the mapping is color-dependent.

**3. Synthesize the Rule:**
1.  **Count** the occurrences of each color in the 7x7 input grid.
2.  **Identify** the color with the highest count (the "majority faction").
3.  **Retrieve** the 3x3 "battle standard" (emblem) associated with that specific color.
4.  **Render** the emblem using 'A' (azure) for the active parts and '.' (black) for the background.

**4. Determine the Mapping (Color -> 3x3 Pattern):**
I ne

... [5958 chars truncated]
alt-8 theater qwen3.5-122b: k=2
"After a chaotic audition, the actor who appeared in the most scenes gets their signature mask hung on the marquee — each mask a different silhouette."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10955 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A casting call, performers on stage.
*   **Key Concept:** "One performer keeps showing up in scene after scene, while others make only fleeting cameos." -> This implies finding the most frequent element (color) in the input grid.
*   **Action:** "Identify the performer with the most appearances." -> Find the dominant color.
*   **Output:** "Each lead actor is known for a unique mask silhouette. Display that mask on the marquee." -> The output is a 3x3 grid representing a "mask" associated with the dominant color.
*   **Grid Details:** Input is 7x7. Output is 3x3.
*   **Color Key:** `.`=black, `B`=blue, `R`=red, `G`=green, `Y`=yellow, `X`=grey, `M`=magenta, `O`=orange, `A`=azure, `W`=maroon.
*   **Specific Output Detail:** "rendered in azure against a dark backdrop." -> The output mask seems to be made of 'A' (azure) and '.' (black/dark backdrop).

**2. Analyze the Training Examples:**

**Example 1:**
Input (7x7):
```
B . B . O . .
B B W B . B .
. . B B . R .
. . . . G . B
. Y . B . . B
. . B . R . A
. . B . O G B
```
Let's count the colors:
B: 1+1+1+1+1+1+1+1+1+1+1+1 = 12? Let's count carefully.
Row 1: B, B (2)
Row 2: B, B, B, B (4)
Row 3: B, B (2)
Row 4: B (1)
Row 5: B, B (2)
Row 6: B (1)
Row 7: B, B (2)
Total B = 2+4+2+1+2+1+2 = 14.

Other colors:
O: 2
W: 1
R: 2
G: 2
Y: 1
A: 1
.: Many.

Dominant color is **B (Blue)**.

Output (3x3):
```
. . A
A A .
. A .
```
The output consists of `A` (azure) and `.` (black).
The shape formed by `A` looks like a specific pattern.
Let's look at the positions of `B` in the input.
Maybe the output shape corresponds to the shape of the dominant color in the input?
Or maybe it's a specific "mask" associated with that color?
The prompt says "Each lead actor is known for a unique mask silhouette." This suggests a mapping from Color -> Mask Shape.
However, I only have one example for Blue. I need to check Example 2 to see if the rule holds.

**Example 2:**
Input (7x7):
```
. G . G X G .
. . G G . . .
A . . . . . G
G Y G W G . G
. . W G B G G
. G G G . G .
. . . . . . G
```
Let's count colors:
G:
Row 1: 3
Row 2: 2
Row 3: 1
Row 4: 4
Row 5: 3
Row 6: 4
Row 7: 1
Total G = 3+2+1+4+3+4+1 = 18.

Other colors:
X: 1
A: 1
Y: 1
W: 2
B: 1
.: Many.

Dominant color is **G (Green)**.

Output (3x3):
```
. A A
. A .
. A .
```
Again, the output is made of `A` and `.`.
The shape is different from Example 1.
Example 1 (Blue) shape:
```
. . A
A A .
. A .
```
Example 2 (Green) shape:
```
. A A
. A .
. A .
```

**Hypothesis:**
1.  Identify the most frequent non-background color in the 7x7 input grid. (Background is likely `.`).
2.  Map that color to a specific 3x3 pattern made of `A` (azure) on `.` (black).
3.  The mapping seems to be Color -> Shape.
    *   Blue (B) -> Shape 1
    *   Green (G) -> Shape 2

Wait, is there a geometric relationship?
Let's look at the distribution of the dominant color in the input grid.
In Example 1 (Blue), the B's are scattered.
In Example 2 (Green), the G's are scattered.
It's unlikely to be a direct downsampling of the 7x7 grid to 3x3 because the patterns are sparse and specific.
The prompt says "Each lead actor is known for a unique mask silhouette." This implies a fixed lookup table or a generative rule based on the color itself.
Since I don't have a full lookup table, I need to infer the rule for the Test Input.

**Test Input:**
```
G . G . . . G
G . W X . . X
. G . G . R W
A G . G . . O
. G X . . G G
. . G G . . .
. . G . Y . .
```
Let's count the colors to find the dominant one.
G:
Row 1: 3
Row 2: 1
Row 3: 2
Row 4: 2
Row 5: 3
Row 6: 2
Row 7: 1
Total G = 3+1+2+2+3+2+1 = 14.

Other colors:
W: 2
X: 3
R: 1
A: 1
O: 1
Y: 1
.: Many.

Dominant color is **G (Green)**.

Since the dominant color is Green (G), and in Example 2 the dominant color was also Green (G), the output should be the same mask as in Example 2.
Example 2 Output:
```
. A A
. A .
. A .
```

Let's double check the counts.
**Example 1:**
B count:
R1: B . B . O . . (2)
R2: B B W B . B . (4)
R3: . . B B . R . (2)
R4: . . . . G . B (1)
R5: . Y . B . . B (2)
R6: . . B . R . A (1)
R7: . . B . O G B (2)
Total B = 14.
Next highest?
O: 2
W: 1
R: 2
G: 2
Y: 1
A: 1
B is definitely the winner.

**Example 2:**
G count:
R1: . G . G X G . (3)
R2: . . G G . . . (2)
R3: A . . . . . G (1)
R4: G Y G W G . G (4)
R5: . . W G B G G (3)
R6: . G G G . G . (4)
R7: . . . . . . G (1)
Total G = 18.
Next highest?
W: 2
X: 1
A: 1
Y: 1
B: 1
G is definitely the winner.

**Test Input:**
G count:
R1: G . G . . . G (3)
R2: G . W X . . X (1)
R3: . G . G . R W (2)
R4: A G . G . . O (2)
R5: . G X . . G G (3)
R6: . . G G . . . (2)
R7: . . G . Y . . (1)
Total G = 14.

Other counts:
X: R2(2) + R5(1) = 3.
W: R2(1) + R3(1) = 2.
R: 1.
A: 1.
O: 1.
Y: 1.
G is definitely the winner.

**Conclusion:**
The task is to identify the most frequent color in the 7x7

... [6045 chars truncated]
alt-9 gardening qwen3.5-122b: k=4
"A garden overrun with many species yields to whichever plant spreads most aggressively — and the gardener marks the plot with that species' characteristic leaf pressed into clay."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (10788 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A "wildly overgrown garden plot" (7x7 grid).
*   **Problem:** "One species has spread everywhere, while rare specimens appear only once or twice." This implies there is a dominant color (the "invasive species") and other colors are rare.
*   **Action:** "Identify the most prolific species by its sheer abundance." -> Find the most frequent color in the input grid.
*   **Action:** "Each invasive species leaves a unique leaf impression." -> This suggests the output is related to the shape or pattern of the dominant color.
*   **Action:** "Press the dominant species' leaf into a small clay tile." -> The output is a 3x3 grid ("clay tile").
*   **Visuals:** "leaf print in azure on dark earth." -> The output grid should be 3x3. The background is likely black (.) and the pattern is Azure (A).
*   **Summary:** Find the most frequent color in the 7x7 input. Create a 3x3 output grid where the pattern corresponds to the distribution of that color, but mapped somehow to a 3x3 space. The output uses 'A' for the pattern and '.' for the background.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 7x7 grid.
    *   Colors present: B, O, W, R, G, Y, A.
    *   Counts:
        *   B: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12... Let's count properly.
        *   Row 1: B . B . O . . (2 B)
        *   Row 2: B B W B . B . (4 B)
        *   Row 3: . . B B . R . (2 B)
        *   Row 4: . . . . G . B (1 B)
        *   Row 5: . Y . B . . B (2 B)
        *   Row 6: . . B . R . A (1 B)
        *   Row 7: . . B . O G B (2 B)
        *   Total B = 2+4+2+1+2+1+2 = 14.
        *   Other colors: O(2), W(1), R(2), G(2), Y(1), A(1).
        *   Dominant color: Blue (B).
    *   Output: 3x3 grid.
        . . A
        A A .
        . A .
    *   Observation: The output contains 'A' (Azure) and '.' (Black). The pattern of 'A's needs to match the pattern of 'B's in the input.
    *   How is the 7x7 mapped to 3x3?
    *   Let's look at the positions of B in the input.
        (0,0), (0,2)
        (1,0), (1,1), (1,3), (1,5)
        (2,2), (2,3)
        (3,6)
        (4,3), (4,6)
        (5,2)
        (6,2), (6,6)
    *   This looks scattered. Let's look at the output pattern:
        (0,2)
        (1,0), (1,1)
        (2,1)
    *   Is there a subgrid extraction? Or a downsampling?
    *   Let's check the center 3x3 of the input?
        Rows 2-4, Cols 2-4 (0-indexed):
        (2,2)B, (2,3)B, (2,4).
        (3,2)., (3,3)., (3,4)G
        (4,2)., (4,3)B, (4,4).
        Pattern: B B . / . . . / . B . -> A A . / . . . / . A .
        Output is: . . A / A A . / . A .
        Doesn't match directly.
    *   Let's check corners?
    *   Let's check if the input grid is divided into 3x3 blocks? 7x7 doesn't divide evenly.
    *   Maybe it's about the *shape* formed by the dominant color?
    *   Let's look at Example 2.
    *   Input:
        . G . G X G .
        . . G G . . .
        A . . . . . G
        G Y G W G . G
        . . W G B G G
        . G G G . G .
        . . . . . . G
    *   Counts:
        G: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15...
        Row 1: 3 G
        Row 2: 2 G
        Row 3: 1 G
        Row 4: 4 G
        Row 5: 3 G
        Row 6: 4 G
        Row 7: 1 G
        Total G = 18.
        Dominant: Green (G).
    *   Output:
        . A A
        . A .
        . A .
    *   Pattern of A: (0,1), (0,2), (1,1), (2,1).
    *   Let's look at the positions of G in the input.
        (0,1), (0,3), (0,5)
        (1,2), (1,3)
        (2,6)
        (3,0), (3,2), (3,4), (3,6)
        (4,3), (4,5), (4,6)
        (5,1), (5,2), (5,3), (5,5)
        (6,6)
    *   This seems too scattered to map directly to a 3x3 grid without some logic.
    *   Wait, look at the output of Ex 1 again:
        . . A
        A A .
        . A .
    *   Look at the output of Ex 2:
        . A A
        . A .
        . A .
    *   Look at the output of Ex 3:
        . . .
        A A A
        . . .
    *   Look at the output of Ex 4:
        . . .
        A A A
        . . .
    *   In Ex 3 and 4, the output is a horizontal line in the middle row.
    *   Let's check Ex 3 Input.
        . . R . B X G
        . . R W . R .
        R R R Y R . .
        . R . R O R .
        R R . . R R M
        . R R . R . .
        X . Y R . R R
    *   Dominant color: R (Red).
        Row 1: 1
        Row 2: 3
        Row 3: 4
        Row 4: 3
        Row 5: 4
        Row 6: 3
        Row 7: 3
        Total R = 21.
    *   Output: Middle row is A A A.
    *   Let's check Ex 4 Input.
        R . . R R . X
        . R R . . . R
        . B . . . . .
        . . . . R . W
        . W . . . . R
        . . R B . . A
        R . . R R . .
    *   Dominant color: R (Red).
        Row 1: 3
        Row 2: 3
        Row 3: 0
        Row 4: 1
        Row 5: 1
        

... [5857 chars truncated]

Task 596: 9b30e358

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A reflection pool mirrors what stands at its edge, rippling upward into the sky. MARC valid 2
alt-1 biology A cell's DNA unfurls upward from its nucleus, replicating its coiled sequence in ... [80 chars truncated] fig alone solves
alt-10 astronomy A constellation anchored near the horizon casts its light upward through the dar ... [87 chars truncated] fail
alt-11 ocean/sailing Coral formations on the seabed send their colors rippling upward through the wat ... [115 chars truncated] fig alone solves
alt-12 electronics A signal pattern is loaded into the lowest registers of a shift buffer; the cloc ... [116 chars truncated] fail
alt-13 mythology An inscription at the base of a monolith chants itself upward into the blank sto ... [110 chars truncated] fail
alt-14 dance Dancers in the back row hold a formation; their choreography cascades forward th ... [124 chars truncated] fail
alt-15 geology A stratum of mineral veins lies deep in the bedrock; tectonic pressure pushes re ... [140 chars truncated] fig alone solves
alt-2 cooking A chef's mise en place sits at the bottom of the pan; as the heat rises, the lay ... [95 chars truncated] fig alone solves
alt-3 music A bass riff sits low on the staff, and the echo chamber above repeats its phrase ... [115 chars truncated] fig alone solves
alt-4 sports The starting lineup is posted on the bottom of the scoreboard; as the crowd's ro ... [82 chars truncated] fail
alt-5 weather Storm clouds gather at the ground and their banded layers of pressure and color ... [99 chars truncated] fail
alt-6 architecture The foundation of a tower holds an ornate frieze; as the building rises, the mas ... [103 chars truncated] fail
alt-7 warfare A regiment is dug in at the base of a hill; as reinforcements arrive, they stack ... [108 chars truncated] fail
alt-8 theater The actors take their marks downstage; the mirror-curtain behind them multiplies ... [132 chars truncated] fail
alt-9 gardening Seeds planted in the lowest furrows sprout upward row by row, each new growth ri ... [88 chars truncated] fig alone solves
original qwen3.5-122b: k=2
"A reflection pool mirrors what stands at its edge, rippling upward into the sky."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11171 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "Quiet, empty expanse of still water stretches across the upper portion... At the shore along the bottom edge, a colorful monument stands".
*   **Action:** "The monument at the water's edge gazes down into the pool and sees its own reflection climbing upward... The monument's image scrolls upward through the water... endlessly tiling its echo toward the horizon."
*   **Constraint:** "The original monument never moves — it remains planted at the shore while its ghost fills every empty inch of sky-water above."
*   **Grid details:** "The world varies in size but the shore is always at the bottom. The still water is one uniform color. The monument is the cluster of living colors rooted to the bottom edge. After the reflection, every row of water has been claimed by the monument's upward echo, and the world is the same size as before."

**Interpretation:**
*   **Input Grid:** Contains a background color (water) in the upper rows and a pattern (monument) in the lower rows.
*   **Transformation:** The pattern at the bottom is repeated upwards to fill the entire grid.
*   **Direction:** The pattern starts from the bottom and repeats upwards.
*   **Mechanism:** It looks like a vertical tiling or repetition of the bottom section.
*   **Key phrase:** "The monument's image scrolls upward... endlessly tiling its echo". This suggests the bottom pattern is the source, and it repeats to fill the space above.
*   **Key phrase:** "The original monument never moves". This implies the bottom rows of the output should match the bottom rows of the input.
*   **Key phrase:** "The world is the same size as before". Input and Output dimensions are identical.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** 10 rows, 5 columns.
    *   Rows 0-4: All 'X' (grey).
    *   Rows 5-9: A pattern involving 'R' (red) and 'A' (azure).
    *   Row 5: `X R R R X`
    *   Row 6: `X X R X X`
    *   Row 7: `X A A X X`
    *   Row 8: `X X A A X`
    *   Row 9: `X X A X X`
*   **Output:** 10 rows, 5 columns.
    *   Row 0: `X R R R X` (Matches Input Row 5)
    *   Row 1: `X X R X X` (Matches Input Row 6)
    *   Row 2: `X A A X X` (Matches Input Row 7)
    *   Row 3: `X X A A X` (Matches Input Row 8)
    *   Row 4: `X X A X X` (Matches Input Row 9)
    *   Row 5: `X R R R X` (Matches Input Row 5)
    *   Row 6: `X X R X X` (Matches Input Row 6)
    *   Row 7: `X A A X X` (Matches Input Row 7)
    *   Row 8: `X X A A X` (Matches Input Row 8)
    *   Row 9: `X X A X X` (Matches Input Row 9)
*   **Observation:** The bottom 5 rows (the "monument") are repeated to fill the top 5 rows. The pattern height seems to be 5 rows. The input had 5 rows of background 'X' and 5 rows of pattern. The output replaces the background rows with the pattern rows, repeating the pattern from the bottom up.
*   **Pattern Height:** In this case, the pattern occupies the bottom half (rows 5-9). The output repeats this block of 5 rows twice to fill the 10 rows.
*   **Wait, let's look closer.**
    *   Input Rows 0-4 are background.
    *   Input Rows 5-9 are the "monument".
    *   Output Rows 0-4 are copies of Input Rows 5-9.
    *   Output Rows 5-9 are copies of Input Rows 5-9.
    *   So, the transformation is: Identify the repeating unit at the bottom. Tile it upwards to fill the grid.
    *   How is the repeating unit defined? In Example 1, the background is uniform 'X'. The pattern starts where the non-background colors appear? Or is it simply the bottom half?
    *   Let's check the colors. Background is 'X'. Monument has 'R' and 'A'.
    *   The "monument" seems to be the contiguous block of non-background rows at the bottom.
    *   In Example 1, rows 5-9 contain 'R' and 'A'. Rows 0-4 contain only 'X'.
    *   So the "monument" is rows 5-9.
    *   The output fills the whole grid with this 5-row pattern.

**Example 2:**
*   **Input:** 10 rows, 7 columns.
    *   Rows 0-5: All 'G' (green).
    *   Rows 6-9: Pattern involving 'W' (maroon) and 'R' (red).
    *   Row 6: `G G G W R W G`
    *   Row 7: `G G G R W R G`
    *   Row 8: `G G G W W W G`
    *   Row 9: `G G G G W G G`
*   **Output:** 10 rows, 7 columns.
    *   Row 0: `G G G W W W G` (Matches Input Row 8)
    *   Row 1: `G G G G W G G` (Matches Input Row 9)
    *   Row 2: `G G G W R W G` (Matches Input Row 6)
    *   Row 3: `G G G R W R G` (Matches Input Row 7)
    *   Row 4: `G G G W W W G` (Matches Input Row 8)
    *   Row 5: `G G G G W G G` (Matches Input Row 9)
    *   Row 6: `G G G W R W G` (Matches Input Row 6)
    *   Row 7: `G G G R W R G` (Matches Input Row 7)
    *   Row 8: `G G G W W W G` (Matches Input Row 8)
    *   Row 9: `G G G G W G G` (Matches Input Row 9)
*   **Observation:**
    *   Background is 'G'.
    *   Monument rows are 6, 7, 8, 9. (4 rows).
    *   Output Row 9 matches Input Row 9.
    *

... [6177 chars truncated]
alt-1 biology qwen3.5-122b: fig alone solves
"A cell's DNA unfurls upward from its nucleus, replicating its coiled sequence into the empty cytoplasm above until every space carries the organism's signature."
alt-10 astronomy qwen3.5-122b: fail
"A constellation anchored near the horizon casts its light upward through the dark, each band of sky catching the star pattern in reverse as it tiles toward the zenith."
Fail (best cell_acc=0.04 at k=1)
Best Attempt
vs
Expected
Reasoning (12683 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A small constellation of colored stars sits in the lowest rows of a uniform night sky." -> There is a pattern at the bottom of the grid, and the rest is a uniform background color.
*   "The starlight propagates upward, each empty band of sky receiving the constellation's rows in reverse order, wrapping through the pattern as needed until every band from horizon to zenith is illuminated." -> The pattern at the bottom is copied upwards to fill the empty space.
*   "wrapping through the pattern as needed" -> This suggests a repeating pattern.
*   "reverse order" -> This is a key detail. The rows of the constellation are copied upwards in reverse order.
*   "The sky's dimensions remain fixed. The original constellation stays near the horizon; the dark bands above fill with the tiling star pattern." -> The input grid has a background color (sky) and a pattern at the bottom (constellation). The output grid should have the pattern filling the entire grid, starting from the bottom and going up, repeating the rows of the constellation in reverse order.

**2. Analyze the Training Example:**
*   **Input:**
    *   10 rows, 5 columns.
    *   Rows 0-4: All 'X' (grey). This is the "uniform night sky".
    *   Rows 5-9: A pattern involving 'R' (red) and 'A' (azure).
        *   Row 5: X R R R X
        *   Row 6: X X R X X
        *   Row 7: X A A X X
        *   Row 8: X X A A X
        *   Row 9: X X A X X
    *   Wait, looking closely at the input provided in the prompt:
        Input:
        X X X X X
        X X X X X
        X X X X X
        X X X X X
        X X X X X
        X R R R X
        X X R X X
        X A A X X
        X X A A X
        X X A X X
    *   The "constellation" seems to be the non-background part. The background is 'X'.
    *   The non-background rows are rows 5, 6, 7, 8, 9.
    *   Let's check the Output:
        X R R R X
        X X R X X
        X A A X X
        X X A A X
        X X A X X
        X R R R X
        X X R X X
        X A A X X
        X X A A X
        X X A X X
    *   The output grid is 10x5.
    *   The bottom 5 rows (5-9) are identical to the input bottom 5 rows.
    *   The top 5 rows (0-4) are filled with the pattern from the bottom.
    *   Let's look at the order.
        *   Input Bottom Rows (constellation):
            Row 5: X R R R X
            Row 6: X X R X X
            Row 7: X A A X X
            Row 8: X X A A X
            Row 9: X X A X X
        *   Output Top Rows (0-4):
            Row 0: X R R R X (Matches Input Row 5)
            Row 1: X X R X X (Matches Input Row 6)
            Row 2: X A A X X (Matches Input Row 7)
            Row 3: X X A A X (Matches Input Row 8)
            Row 4: X X A X X (Matches Input Row 9)
    *   Wait, the metaphor says "receiving the constellation's rows in reverse order".
    *   Let's re-read carefully: "each empty band of sky receiving the constellation's rows in reverse order".
    *   If the constellation is rows 5-9.
    *   Reverse order of rows 5-9 would be 9, 8, 7, 6, 5.
    *   If we fill upwards from the horizon (bottom), the first empty band above the constellation (Row 4) should get the last row of the constellation (Row 9)? Or does it mean the sequence of rows is reversed?
    *   Let's look at the Output again.
        Output Row 0: X R R R X (Same as Input Row 5)
        Output Row 1: X X R X X (Same as Input Row 6)
        ...
        Output Row 4: X X A X X (Same as Input Row 9)
        Output Row 5: X R R R X (Same as Input Row 5)
        ...
        Output Row 9: X X A X X (Same as Input Row 9)
    *   In the output, the pattern repeats every 5 rows.
    *   Row 0 matches Row 5. Row 1 matches Row 6. Row 4 matches Row 9.
    *   This looks like a simple vertical tiling of the bottom block.
    *   Why does the metaphor say "reverse order"?
    *   Maybe the "constellation" is defined differently?
    *   Or maybe "reverse order" refers to the propagation direction? "propagates upward... receiving... in reverse order".
    *   If I propagate upward from the bottom, the row immediately above the bottom block (Row 4) should correspond to the row immediately below the top of the bottom block? No.
    *   Let's look at the example output again.
        Input Bottom Block (Rows 5-9):
        5: RRR
        6: .R.
        7: AA.
        8: .AA
        9: .A.
        (Simplified)
        Output Top Block (Rows 0-4):
        0: RRR
        1: .R.
        2: AA.
        3: .AA
        4: .A.
    *   This is NOT reverse order. Row 0 is Row 5. Row 4 is Row 9.
    *   If it were reverse order, Row 4 (first filled from bottom) would be Row 9. Row 0 (last filled) would be Row 5.
    *   Wait, let's look at the metaphor again. "each empty band of sky receiving the constellation's rows in reverse order".
    *   Maybe the "constella

... [7701 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fig alone solves
"Coral formations on the seabed send their colors rippling upward through the water column, each wave crest carrying the reef's layers in reverse until the surface shimmers with the pattern below."
alt-12 electronics qwen3.5-122b: fail
"A signal pattern is loaded into the lowest registers of a shift buffer; the clock pulses it upward through the empty banks, each cycle reading the pattern backward until every register is charged."
Fail (best cell_acc=0.70 at k=2)
Best Attempt
vs
Expected
Reasoning (12132 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A sequence of colored voltage levels occupies the bottom registers of an otherwise zeroed-out buffer array."
    *   This suggests the input grid has some data at the bottom and "empty" (or background) values elsewhere.
    *   In the examples, the "empty" value seems to be the dominant color filling the top part of the grid.
*   **Action:** "On each clock tick the signal propagates upward one bank, filling registers in reverse order of the source pattern, wrapping around when the sequence is exhausted, until all banks hold data."
    *   "Propagates upward one bank": The pattern moves up.
    *   "Filling registers in reverse order of the source pattern": This is a bit ambiguous. Does it mean the pattern is reversed? Or does it mean the filling happens from bottom to top?
    *   "Wrapping around when the sequence is exhausted": The pattern repeats.
    *   "Until all banks hold data": The whole grid gets filled with the pattern.
*   **Grid details:** "The buffer dimensions are unchanged. The source registers at the bottom retain their values; the empty banks above are filled with the cycling signal."
    *   Input dimensions = Output dimensions.
    *   The bottom part (source) stays the same.
    *   The top part (empty) gets filled by repeating the source pattern upwards.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** 10 rows, 5 columns.
    *   Rows 0-4: All 'X' (grey).
    *   Rows 5-9: A pattern of 'R' (red) and 'A' (azure).
    *   Row 5: `X R R R X`
    *   Row 6: `X X R X X`
    *   Row 7: `X A A X X`
    *   Row 8: `X X A A X`
    *   Row 9: `X X A X X`
    *   Wait, looking closely at the input:
        Row 0-4: `X X X X X`
        Row 5: `X R R R X`
        Row 6: `X X R X X`
        Row 7: `X A A X X`
        Row 8: `X X A A X`
        Row 9: `X X A X X`
    *   The "source" seems to be the non-X rows at the bottom.
    *   Actually, looking at the output:
        Row 0: `X R R R X` (Same as Input Row 5)
        Row 1: `X X R X X` (Same as Input Row 6)
        Row 2: `X A A X X` (Same as Input Row 7)
        Row 3: `X X A A X` (Same as Input Row 8)
        Row 4: `X X A X X` (Same as Input Row 9)
        Row 5: `X R R R X` (Same as Input Row 5)
        Row 6: `X X R X X` (Same as Input Row 6)
        Row 7: `X A A X X` (Same as Input Row 7)
        Row 8: `X X A A X` (Same as Input Row 8)
        Row 9: `X X A X X` (Same as Input Row 9)
    *   **Observation:** The pattern from the bottom rows (5-9) is repeated upwards to fill the top rows (0-4).
    *   The pattern height is 5 rows. The total height is 10 rows.
    *   The top 5 rows are copies of the bottom 5 rows.
    *   Specifically, Row $i$ in output = Row $i + 5$ in input? No.
    *   Output Row 0 = Input Row 5.
    *   Output Row 1 = Input Row 6.
    *   ...
    *   Output Row 4 = Input Row 9.
    *   Output Row 5 = Input Row 5.
    *   Output Row 9 = Input Row 9.
    *   So, the bottom block of rows (the "source pattern") is tiled upwards.
    *   The "source pattern" seems to be defined by the contiguous block of non-background rows at the bottom. Here, rows 5-9 are the pattern. Rows 0-4 are background 'X'.
    *   The transformation copies the bottom block to the top block.

**Example 2:**
*   **Input:** 10 rows, 7 columns.
    *   Background color: 'G' (green).
    *   Rows 0-5: All 'G'.
    *   Rows 6-9: Pattern involving 'W' (maroon) and 'R' (red).
        Row 6: `G G G W R W G`
        Row 7: `G G G R W R G`
        Row 8: `G G G W W W G`
        Row 9: `G G G G W G G`
    *   **Output:**
        Row 0: `G G G W W W G` (Same as Input Row 8)
        Row 1: `G G G G W G G` (Same as Input Row 9)
        Row 2: `G G G W R W G` (Same as Input Row 6)
        Row 3: `G G G R W R G` (Same as Input Row 7)
        Row 4: `G G G W W W G` (Same as Input Row 8)
        Row 5: `G G G G W G G` (Same as Input Row 9)
        Row 6: `G G G W R W G` (Same as Input Row 6)
        Row 7: `G G G R W R G` (Same as Input Row 7)
        Row 8: `G G G W W W G` (Same as Input Row 8)
        Row 9: `G G G G W G G` (Same as Input Row 9)
    *   **Observation:**
        *   The bottom block is rows 6-9 (4 rows).
        *   The top block is rows 0-5 (6 rows).
        *   The output fills the top rows with the pattern from the bottom rows, repeating upwards.
        *   Let's check the order.
        *   Output Row 9 = Input Row 9.
        *   Output Row 8 = Input Row 8.
        *   Output Row 7 = Input Row 7.
        *   Output Row 6 = Input Row 6.
        *   Output Row 5 = Input Row 9. (Wrapping around)
        *   Output Row 4 = Input Row 8.
        *   Output Row 3 = Input Row 7.
        *   Output Row 2 = Input Row 6.
        *   Output Row 1 = Input Row 9.
        *   Output Row 0 = Input Row 8.
    *   **Pattern Logic:**
        *   Identify the "source

... [7168 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"An inscription at the base of a monolith chants itself upward into the blank stone, each verse carved in reverse order, the incantation looping until the entire pillar bears the sacred text."
Fail (best cell_acc=0.70 at k=1)
Best Attempt
vs
Expected
Reasoning (12782 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Colored runes are carved into the bottommost rows of a tall, featureless monolith."
*   **Action:** "The inscription propagates upward from the runes, each empty row of stone receiving the next verse in reverse order of the original text, cycling through the verses until the pillar is fully engraved."
*   **Grid Details:** "The monolith's dimensions are preserved. The base inscription remains; the blank stone above fills with the cycling runic pattern."

**Interpretation:**
*   "Bottommost rows": There is a pattern at the bottom of the grid.
*   "Empty rows": The rows above the pattern are filled with a background color (likely the "featureless monolith" color).
*   "Propagates upward": The pattern from the bottom moves up.
*   "Reverse order of the original text": This suggests the sequence of rows at the bottom is reversed as it goes up.
*   "Cycling through the verses": The pattern repeats.
*   "Base inscription remains": The original bottom rows stay as they are.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Grid size: 10 rows, 5 columns.
    *   Background color: X (grey).
    *   Pattern at bottom:
        Row 5 (0-indexed): `X R R R X`
        Row 6: `X X R X X`
        Row 7: `X A A X X`
        Row 8: `X X A A X`
        Row 9: `X X A X X`
    *   Wait, let's look at the rows containing non-X colors.
        Row 5: `X R R R X`
        Row 6: `X X R X X`
        Row 7: `X A A X X`
        Row 8: `X X A A X`
        Row 9: `X X A X X`
    *   Actually, looking closely at the input:
        Rows 0-4 are all `X X X X X`.
        Rows 5-9 contain the pattern.
    *   **Output:**
        ```
        X R R R X
        X X R X X
        X A A X X
        X X A A X
        X X A X X
        X R R R X
        X X R X X
        X A A X X
        X X A A X
        X X A X X
        ```
    *   **Observation:**
        The output grid is 10x5.
        The bottom 5 rows (5-9) in the output are identical to the bottom 5 rows in the input.
        The top 5 rows (0-4) in the output are identical to the bottom 5 rows in the input.
        Specifically:
        Output Row 0 = Input Row 5
        Output Row 1 = Input Row 6
        Output Row 2 = Input Row 7
        Output Row 3 = Input Row 8
        Output Row 4 = Input Row 9
        Output Row 5 = Input Row 5
        ...
        Output Row 9 = Input Row 9

    *   **Re-evaluating the Metaphor:**
        "each empty row of stone receiving the next verse in reverse order of the original text"
        "cycling through the verses"
        
        Let's look at the pattern block. It seems to be 5 rows high.
        Input has 5 empty rows (0-4) and 5 pattern rows (5-9).
        Output has the pattern repeated.
        Top half (0-4) matches Bottom half (5-9).
        This looks like a simple repetition or tiling of the pattern found at the bottom.
        
        Does "reverse order" apply?
        Input Pattern Rows (bottom to top):
        Row 9: `X X A X X`
        Row 8: `X X A A X`
        Row 7: `X A A X X`
        Row 6: `X X R X X`
        Row 5: `X R R R X`
        
        Output Top Rows (0-4):
        Row 0: `X R R R X` (Matches Input Row 5)
        Row 1: `X X R X X` (Matches Input Row 6)
        Row 2: `X A A X X` (Matches Input Row 7)
        Row 3: `X X A A X` (Matches Input Row 8)
        Row 4: `X X A X X` (Matches Input Row 9)
        
        So the top half is a direct copy of the bottom half, not reversed.
        Wait, the metaphor says "reverse order of the original text".
        If the "text" is the sequence of rows from bottom to top (Row 9, 8, 7, 6, 5), then "reverse order" would be 5, 6, 7, 8, 9.
        The output top rows are 5, 6, 7, 8, 9.
        So the "verse" is the block of rows. The "original text" is the block at the bottom.
        If we read the inscription from bottom to top (as one might read a carving going up), the sequence is Row 9 -> Row 5.
        The propagation goes upward.
        Row 4 gets the "next verse".
        If the sequence is defined bottom-up (9, 8, 7, 6, 5), then the "next" one going up from 5 would be... wait.
        
        Let's look at the structure simply.
        The grid is divided into two halves vertically.
        The bottom half contains a pattern.
        The top half is empty (background color).
        The transformation fills the top half with the pattern from the bottom half.
        In Example 1, the pattern height is exactly half the grid height (5 rows out of 10).
        The top half becomes a copy of the bottom half.
        
        Is it always a copy? Or is it a reflection?
        Input Bottom:
        5: RRR
        6: .R.
        7: A

... [7785 chars truncated]
alt-14 dance qwen3.5-122b: fail
"Dancers in the back row hold a formation; their choreography cascades forward through the empty floor, each wave of movement reversing through the formation's steps until the whole stage pulses in unison."
Fail (best cell_acc=0.52 at k=1)
Best Attempt
vs
Expected
Reasoning (12882 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A compact arrangement of colored dancers occupies the rearmost rows of an empty dance floor."
    *   This implies there is a pattern of non-background colors at the bottom of the grid.
    *   The rest of the grid (top rows) is "empty" (likely a background color).
*   **What to do:** "The choreography flows forward row by row, each empty position receiving the formation in reverse row order, cycling through the full routine when it's exhausted, until every row of the floor is dancing."
    *   "Flows forward row by row": The pattern moves upwards from the bottom.
    *   "Each empty position receiving the formation in reverse row order": This is a bit ambiguous. Does it mean the rows of the pattern are copied upwards?
    *   "Cycling through the full routine when it's exhausted": If the pattern has $N$ rows, and we need to fill $M$ rows above it, we repeat the pattern.
    *   "Until every row of the floor is dancing": The entire grid should be filled with the pattern.
    *   "The rear formation stays in place": The original pattern at the bottom remains unchanged.
    *   "The empty rows in front fill with the cycling choreographic pattern": The rows above the pattern are filled by repeating the pattern rows.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Grid size: 10 rows, 5 columns.
    *   Background color: X (grey).
    *   Pattern starts at row index 5 (0-indexed) or row 6 (1-indexed). Let's count from top (0) to bottom (9).
    *   Rows 0-4 are all X.
    *   Rows 5-9 contain the pattern.
    *   Row 5: `X R R R X`
    *   Row 6: `X X R X X`
    *   Row 7: `X A A X X`
    *   Row 8: `X X A A X`
    *   Row 9: `X X A X X`
    *   So the "pattern" consists of 5 rows (indices 5, 6, 7, 8, 9).
*   **Output:**
    ```
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Rows 0-4 are now filled.
    *   Row 0 matches Row 5.
    *   Row 1 matches Row 6.
    *   Row 2 matches Row 7.
    *   Row 3 matches Row 8.
    *   Row 4 matches Row 9.
    *   Rows 5-9 remain exactly the same as input.
    *   Wait, let's look closer.
    *   Input Pattern Rows (bottom 5):
        1. `X R R R X`
        2. `X X R X X`
        3. `X A A X X`
        4. `X X A A X`
        5. `X X A X X`
    *   Output Top Rows (top 5):
        1. `X R R R X` (Matches Input Row 5)
        2. `X X R X X` (Matches Input Row 6)
        3. `X A A X X` (Matches Input Row 7)
        4. `X X A A X` (Matches Input Row 8)
        5. `X X A X X` (Matches Input Row 9)
    *   So the transformation is: Identify the contiguous block of non-background rows at the bottom. Copy these rows upwards to fill the empty background rows above them, maintaining the order.
    *   The description says "reverse row order". Let's re-read carefully: "each empty position receiving the formation in reverse row order".
    *   In the example:
        *   Bottom row of pattern is Row 9 (`X X A X X`).
        *   Top row of pattern is Row 5 (`X R R R X`).
        *   Output Row 0 is `X R R R X` (Top of pattern).
        *   Output Row 4 is `X X A X X` (Bottom of pattern).
        *   This is *not* reverse row order. This is direct copy order.
        *   Let's check the text again: "receiving the formation in reverse row order".
        *   Maybe "reverse row order" refers to how the pattern is perceived? Or maybe I am misinterpreting "reverse".
        *   If the pattern is rows 5, 6, 7, 8, 9.
        *   Filling rows 0, 1, 2, 3, 4.
        *   Row 0 gets Row 5. Row 1 gets Row 6...
        *   This is a direct copy.
        *   Why does the text say "reverse row order"?
        *   "The choreography flows forward row by row".
        *   Maybe the "formation" is defined from the bottom up?
        *   If the formation is defined as [Row 9, Row 8, Row 7, Row 6, Row 5] (bottom to top).
        *   Then filling "forward" (top to bottom) with this formation...
        *   Row 0 gets Row 9? No, Row 0 gets Row 5.
        *   Let's look at the wording again. "each empty position receiving the formation in reverse row order".
        *   Perhaps it means the rows of the pattern are taken in the order they appear in the grid (top to bottom of the pattern block) and placed into the empty rows (top to bottom of the empty block).
        *   Let's ignore the potentially confusing "reverse" phrasing for a moment and focus on the visual evidence of the training example.
        *   Visual Evidence: The block of colored rows at the bottom is repeated upwards to fill the grid. The order of rows is preserved. Row $i$ of the output (wher

... [7903 chars truncated]
alt-15 geology qwen3.5-122b: fig alone solves
"A stratum of mineral veins lies deep in the bedrock; tectonic pressure pushes replicas of those layers upward through the blank stone, each thrust reversing through the vein sequence until the cliff face is fully banded."
alt-2 cooking qwen3.5-122b: fig alone solves
"A chef's mise en place sits at the bottom of the pan; as the heat rises, the layers of flavor climb upward, repeating their seasoning in waves until the whole dish is infused."
alt-3 music qwen3.5-122b: fig alone solves
"A bass riff sits low on the staff, and the echo chamber above repeats its phrase upward, each iteration a faithful inversion rolling back through the motif until the silence is filled with sound."
alt-4 sports qwen3.5-122b: fail
"The starting lineup is posted on the bottom of the scoreboard; as the crowd's roar swells, the roster stamps itself upward through the empty tiers of the stadium."
Fail (best cell_acc=0.70 at k=1)
Best Attempt
vs
Expected
Reasoning (11032 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A few rows of colored jerseys are assembled at the base of a monochrome stadium seating chart."
    *   This implies the input grid has some rows at the bottom that are "colored" (non-background) and the rest are "monochrome" (background color).
    *   Looking at the training example, the background seems to be 'X' (grey). The "colored jerseys" are the non-X rows at the bottom.
*   **Action:** "The roster replicates upward tier by tier, reading backward through the lineup each cycle, wrapping around when it reaches the last player, until every seat displays a jersey."
    *   "Roster replicates upward": The pattern from the bottom rows is copied to the rows above.
    *   "Reading backward through the lineup each cycle": This suggests a reversal or a specific order of copying.
    *   "Wrapping around": It's a repeating pattern.
    *   "Until every seat displays a jersey": The whole grid gets filled.
*   **Grid details:** "The stadium dimensions stay the same. Original lineup remains at the bottom; empty tiers above are filled with the cycling roster pattern."
    *   Input dimensions = Output dimensions.
    *   The bottom rows (the "original lineup") stay as they are.
    *   The rows above (the "empty tiers") are filled based on the pattern found in the bottom rows.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Grid size: 10 rows, 5 columns.
    *   Background: X.
    *   "Colored" rows at the bottom: Rows 5 to 9 (0-indexed: 5, 6, 7, 8, 9). Wait, let's count.
    *   Rows 0-4 are all X.
    *   Rows 5-9 contain colors (R, A).
    *   So there are 5 "pattern" rows at the bottom.
*   **Output:**
    ```
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Rows 5-9 in Output are identical to Rows 5-9 in Input. This confirms "Original lineup remains at the bottom".
    *   Rows 0-4 in Output are filled.
    *   Let's look at the pattern of rows 5-9:
        *   Row 5: `X R R R X`
        *   Row 6: `X X R X X`
        *   Row 7: `X A A X X`
        *   Row 8: `X X A A X`
        *   Row 9: `X X A X X`
    *   Let's look at the filled rows 0-4 in Output:
        *   Row 0: `X R R R X` (Same as Row 5)
        *   Row 1: `X X R X X` (Same as Row 6)
        *   Row 2: `X A A X X` (Same as Row 7)
        *   Row 3: `X X A A X` (Same as Row 8)
        *   Row 4: `X X A X X` (Same as Row 9)
    *   Wait, the description says "reading backward through the lineup each cycle".
    *   Let's re-read carefully: "The roster replicates upward tier by tier, reading backward through the lineup each cycle".
    *   If the roster is the block of non-background rows (Rows 5-9), let's call them $P_0, P_1, P_2, P_3, P_4$ where $P_0$ is Row 5 and $P_4$ is Row 9.
    *   The output rows above are $O_0, O_1, O_2, O_3, O_4$.
    *   In the example output:
        *   $O_0 = P_0$
        *   $O_1 = P_1$
        *   $O_2 = P_2$
        *   $O_3 = P_3$
        *   $O_4 = P_4$
    *   This looks like a direct copy upwards, not backward.
    *   Let's check the description again: "reading backward through the lineup each cycle".
    *   Maybe the "lineup" is defined differently? Or maybe the example output I'm seeing is just a simple repetition?
    *   Let's look at the example output again.
        *   Input Rows 5-9:
            5: X R R R X
            6: X X R X X
            7: X A A X X
            8: X X A A X
            9: X X A X X
        *   Output Rows 0-4:
            0: X R R R X
            1: X X R X X
            2: X A A X X
            3: X X A A X
            4: X X A X X
    *   This is exactly the same sequence. Row 0 matches Row 5. Row 4 matches Row 9.
    *   Why does the text say "reading backward"?
    *   Maybe "backward" refers to the direction of filling? Filling from bottom to top?
    *   Or maybe "lineup" refers to the sequence of rows $9, 8, 7, 6, 5$?
    *   If the sequence is $9, 8, 7, 6, 5$ (bottom to top), and we fill upwards starting from row 4 (just above the block):
        *   Row 4 gets Row 9? No, Row 4 is `X X A X X` which is Row 9.
        *   Row 3 gets Row 8? Row 3 is `X X A A X` which is Row 8.
        *   Row 2 gets Row 7? Row 2 is `X A A X X` which is Row 7.
        *   Row 1 gets Row 6? Row 1 is `X X R X X` which is Row 6.
        *   Row 0 gets Row 5? Row 0 is `X R R R X` which is Row 5.
    *   Okay, so the pattern is: The block of colored rows is repeated upwards.
    *   Specifically, the row immediately above the colored block takes the value of the *bottom-most* colored row. The next one up takes the second from bottom, etc.
    *   L

... [6101 chars truncated]
alt-5 weather qwen3.5-122b: fail
"Storm clouds gather at the ground and their banded layers of pressure and color surge upward through the atmosphere, each altitude echoing the pattern below in rolling repetition."
Fail (best cell_acc=0.70 at k=1)
Best Attempt
vs
Expected
Reasoning (12514 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "At the base of a calm, uniform sky, a compact formation of colored cloud bands has settled."
    *   This suggests the input grid has a "sky" (background) and "cloud bands" (foreground pattern) at the bottom.
    *   "Calm, uniform sky" likely means a single color filling most of the grid initially.
    *   "Compact formation... at the base" means the pattern is at the bottom rows.
*   "What to do: The cloud bands propagate upward through the empty atmosphere, each new altitude receiving the next band in reverse sequence, cycling back through the formation endlessly until the sky is full."
    *   "Propagate upward": The pattern moves from bottom to top.
    *   "Each new altitude receiving the next band in reverse sequence": This is the tricky part. Let's look at the example to understand "reverse sequence".
    *   "Cycling back through the formation endlessly": It's a repeating pattern.
    *   "Until the sky is full": The output grid should be filled with this pattern, likely replacing the original background.
*   "Grid details: The sky retains its original dimensions. The ground-level clouds persist while the vacant atmosphere above fills with the repeating banded cycle."
    *   Input dimensions = Output dimensions.
    *   The bottom part (ground-level clouds) stays the same? Or is it the source of the pattern?
    *   "Vacant atmosphere above fills": The top part of the grid gets filled.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Size: 10 rows, 5 columns.
    *   Background: X (grey).
    *   Pattern at bottom: Rows 5-9 (0-indexed: 5, 6, 7, 8, 9).
    *   Row 5: `X R R R X`
    *   Row 6: `X X R X X`
    *   Row 7: `X A A X X`
    *   Row 8: `X X A A X`
    *   Row 9: `X X A X X`
    *   Wait, let's look at the rows containing non-X colors.
    *   Rows 0-4 are all X.
    *   Rows 5-9 contain the pattern.
    *   Actually, looking closely at the input:
        Row 0: X X X X X
        Row 1: X X X X X
        Row 2: X X X X X
        Row 3: X X X X X
        Row 4: X X X X X
        Row 5: X R R R X
        Row 6: X X R X X
        Row 7: X A A X X
        Row 8: X X A A X
        Row 9: X X A X X
    *   So the "cloud bands" are in the bottom 5 rows. The top 5 rows are "empty atmosphere" (X).

*   **Output:**
    ```
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Size: 10 rows, 5 columns.
    *   Row 0: `X R R R X` (Same as Input Row 5)
    *   Row 1: `X X R X X` (Same as Input Row 6)
    *   Row 2: `X A A X X` (Same as Input Row 7)
    *   Row 3: `X X A A X` (Same as Input Row 8)
    *   Row 4: `X X A X X` (Same as Input Row 9)
    *   Row 5: `X R R R X` (Same as Input Row 5)
    *   Row 6: `X X R X X` (Same as Input Row 6)
    *   Row 7: `X A A X X` (Same as Input Row 7)
    *   Row 8: `X X A A X` (Same as Input Row 8)
    *   Row 9: `X X A X X` (Same as Input Row 9)

*   **Observation:**
    *   The pattern from the bottom 5 rows (Rows 5-9) is repeated upwards to fill the top 5 rows (Rows 0-4).
    *   Specifically, Output Row $i$ seems to be Input Row $(i + 5) \pmod{10}$? No.
    *   Let's check the mapping.
    *   Input Pattern Rows: 5, 6, 7, 8, 9.
    *   Output Rows 0-4 match Input Rows 5-9 exactly.
    *   Output Rows 5-9 match Input Rows 5-9 exactly.
    *   So the transformation is: Identify the repeating unit (the non-background rows at the bottom). Tile this unit upwards to fill the grid.
    *   Wait, the metaphor says "propagate upward... each new altitude receiving the next band in reverse sequence".
    *   Let's re-read carefully: "each new altitude receiving the next band in reverse sequence".
    *   In the example:
        *   Bottom row (9) is `X X A X X`.
        *   Row above (8) is `X X A A X`.
        *   Row above (7) is `X A A X X`.
        *   Row above (6) is `X X R X X`.
        *   Row above (5) is `X R R R X`.
        *   These are the "bands".
        *   The output fills the top rows (0-4) with these bands.
        *   Output Row 4 is `X X A X X` (Same as Input Row 9).
        *   Output Row 3 is `X X A A X` (Same as Input Row 8).
        *   Output Row 2 is `X A A X X` (Same as Input Row 7).
        *   Output Row 1 is `X X R X X` (Same as Input Row 6).
        *   Output Row 0 is `X R R R X` (Same as Input Row 5).
    *   So, Output Row 0 corresponds to Input Row 5. Output Row 4 corresponds to Input Row 9.
    *   This means the sequence of bands is taken from the bottom block (Rows 5-9) and placed into the top block (Rows 0-4) in the *same order* (Top-to-Bottom of the block maps to Top-to-Bottom of the target area).
    

... [7565 chars truncated]
alt-6 architecture qwen3.5-122b: fail
"The foundation of a tower holds an ornate frieze; as the building rises, the mason lays each course by reading the frieze backward, returning to its end whenever the pattern is spent."
Fail (best cell_acc=0.04 at k=1)
Best Attempt
vs
Expected
Reasoning (11735 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A decorated foundation band sits at the base of an unfinished tower, its rows of colored stonework forming a compact design against a plain wall."
    *   This implies there is a specific section at the bottom of the grid (the "frieze" or "foundation band") that contains a pattern.
    *   The rest of the grid (the "tower" or "wall") is "plain" (likely a single color, like the background).
*   **What to do:** "The mason builds upward from just above the frieze, laying stone courses that mirror the frieze rows in reverse order, wrapping back to the bottom of the frieze sequence each time it's exhausted, until the tower is complete."
    *   "Builds upward from just above the frieze": The transformation happens in the area above the patterned section.
    *   "Laying stone courses that mirror the frieze rows in reverse order": The rows above the frieze are filled with rows taken from the frieze.
    *   "Reverse order": If the frieze rows are $F_1, F_2, ..., F_k$ (from top to bottom of the frieze), the filling starts with $F_k, F_{k-1}, ..., F_1$.
    *   "Wrapping back to the bottom of the frieze sequence each time it's exhausted": Once the sequence $F_k, ..., F_1$ is used, it repeats $F_k, ..., F_1$ again.
    *   "Until the tower is complete": This fills the entire grid height.
    *   "The frieze stays at the base": The original patterned rows at the bottom remain unchanged.
    *   "The bare wall above is filled with the cycling masonry": The background rows are replaced by the patterned rows.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Grid size: 10 rows, 5 columns.
    *   Background color: X (grey).
    *   Patterned section (Frieze): Rows 5 to 9 (0-indexed: 5, 6, 7, 8, 9). Wait, let's look closer.
    *   Rows 0-4 are all X.
    *   Rows 5-9 contain R and A mixed with X.
    *   Let's identify the "frieze". The description says "foundation band sits at the base".
    *   Rows 5, 6, 7, 8, 9 look like the pattern.
    *   Let's check the Output.
*   **Output:**
    ```
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Rows 5-9 in Output are identical to Rows 5-9 in Input. This confirms "The frieze stays at the base".
    *   Rows 0-4 in Output are filled.
    *   Let's look at the sequence of rows in the frieze (Input Rows 5-9):
        *   Row 5: `X R R R X`
        *   Row 6: `X X R X X`
        *   Row 7: `X A A X X`
        *   Row 8: `X X A A X`
        *   Row 9: `X X A X X`
    *   Let's look at the sequence of rows in the filled area (Output Rows 0-4):
        *   Row 0: `X R R R X` (Matches Input Row 5)
        *   Row 1: `X X R X X` (Matches Input Row 6)
        *   Row 2: `X A A X X` (Matches Input Row 7)
        *   Row 3: `X X A A X` (Matches Input Row 8)
        *   Row 4: `X X A X X` (Matches Input Row 9)
    *   Wait, the metaphor says "mirror the frieze rows in reverse order".
    *   Frieze rows (top to bottom): $R_5, R_6, R_7, R_8, R_9$.
    *   Reverse order: $R_9, R_8, R_7, R_6, R_5$.
    *   If the rule was "reverse order", Output Row 0 should be $R_9$.
    *   Output Row 0 is `X R R R X`, which is $R_5$.
    *   Output Row 1 is `X X R X X`, which is $R_6$.
    *   ...
    *   Output Row 4 is `X X A X X`, which is $R_9$.
    *   So the Output Rows 0-4 are exactly the same as Input Rows 5-9.
    *   This contradicts the "reverse order" part of the metaphor *if* "reverse order" means the sequence of rows is reversed.
    *   Let's re-read the metaphor carefully: "laying stone courses that mirror the frieze rows in reverse order".
    *   Maybe "reverse order" refers to the spatial arrangement? Or maybe I am misinterpreting the "frieze".
    *   Let's look at the Input again.
    *   Input Rows 0-4 are X. Input Rows 5-9 are pattern.
    *   Output Rows 0-4 are pattern. Output Rows 5-9 are pattern.
    *   The pattern in Output 0-4 is identical to Input 5-9.
    *   So the transformation is: Copy the bottom block of rows to the top block of rows.
    *   Why does the metaphor say "reverse order"?
    *   Maybe the "frieze" is defined differently?
    *   "A decorated foundation band sits at the base". This implies the bottom rows.
    *   "The mason builds upward from just above the frieze". This implies the rows *above* the frieze are filled.
    *   "laying stone courses that mirror the frieze rows in reverse order".
    *   If the frieze is rows 5-9.
    *   If I build upward from row 4 (just above row 5).
    *   Row 4 gets filled. Row 3 gets filled. Row 2 gets filled. Row 1 gets filled. Row 0 gets filled.
    *   If I take th

... [6735 chars truncated]
alt-7 warfare qwen3.5-122b: fail
"A regiment is dug in at the base of a hill; as reinforcements arrive, they stack into the empty terrain above, each wave a mirror-march of the original formation cycling through its ranks."
Fail (best cell_acc=0.70 at k=1)
Best Attempt
vs
Expected
Reasoning (12430 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A compact formation of colored battalions occupies the lowest rows of an empty battlefield grid."
    *   This implies there is a pattern of non-background colors at the bottom of the grid.
    *   The "empty battlefield" suggests the rest of the grid is filled with a background color (likely 'X' or 'O' based on the examples).
*   **What to do:** "Reinforcements fill the empty ground above, deploying rank by rank in the reverse order of the original formation, looping back through the ranks when all have been placed, until the field is full."
    *   "Empty ground above": The rows above the formation need to be filled.
    *   "Reverse order of the original formation": This suggests taking the rows of the formation and reversing their sequence.
    *   "Looping back through the ranks": This suggests a repeating pattern. If the formation has $N$ rows, and we need to fill $M$ rows above, we repeat the reversed formation rows cyclically.
    *   "Until the field is full": The output grid has the same dimensions as the input grid.
*   **Grid details:** "The battlefield dimensions are preserved. The original regiment holds position while the empty terrain above fills with cycling deployments."
    *   The bottom rows (the "regiment") stay exactly where they are.
    *   The top rows (the "empty terrain") are overwritten by the pattern derived from the bottom rows.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X X X X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Grid size: 10 rows, 5 columns.
    *   Background color: X (grey).
    *   "Formation" (non-X rows):
        *   Row 5 (0-indexed): `X R R R X`
        *   Row 6: `X X R X X`
        *   Row 7: `X A A X X`
        *   Row 8: `X X A A X`
        *   Row 9: `X X A X X`
    *   Wait, let's look closer. The description says "lowest rows".
    *   Rows 0-4 are all X.
    *   Rows 5-9 contain colors R and A mixed with X.
    *   Let's check the Output.
*   **Output:**
    ```
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    X R R R X
    X X R X X
    X A A X X
    X X A A X
    X X A X X
    ```
    *   Rows 5-9 in Output are identical to Rows 5-9 in Input. This confirms "The original regiment holds position".
    *   Rows 0-4 in Output are:
        *   Row 0: `X R R R X` (Same as Input Row 5)
        *   Row 1: `X X R X X` (Same as Input Row 6)
        *   Row 2: `X A A X X` (Same as Input Row 7)
        *   Row 3: `X X A A X` (Same as Input Row 8)
        *   Row 4: `X X A X X` (Same as Input Row 9)
    *   Wait, the metaphor says "reverse order of the original formation".
    *   Let's check the order.
    *   Input Formation Rows (bottom up):
        1.  Row 9: `X X A X X`
        2.  Row 8: `X X A A X`
        3.  Row 7: `X A A X X`
        4.  Row 6: `X X R X X`
        5.  Row 5: `X R R R X`
    *   If it were "reverse order", the top rows (0-4) should be:
        *   Row 0: Row 9 (`X X A X X`)
        *   Row 1: Row 8 (`X X A A X`)
        *   ...
    *   But the Output shows:
        *   Row 0: `X R R R X` (Input Row 5)
        *   Row 1: `X X R X X` (Input Row 6)
        *   ...
        *   Row 4: `X X A X X` (Input Row 9)
    *   This means the pattern filling the top is simply a copy of the formation rows starting from the *top* of the formation (Row 5) downwards.
    *   Let's re-read the metaphor carefully: "deploying rank by rank in the reverse order of the original formation".
    *   Maybe "original formation" refers to the visual stack from top to bottom?
    *   If the formation is Rows 5, 6, 7, 8, 9.
    *   "Reverse order" usually means 9, 8, 7, 6, 5.
    *   But the output fills 0, 1, 2, 3, 4 with 5, 6, 7, 8, 9.
    *   This is the *same* order, not reverse.
    *   Let's look at the wording again: "Reinforcements fill the empty ground above, deploying rank by rank in the reverse order of the original formation".
    *   Perhaps the "original formation" is defined from the bottom up? i.e., Rank 1 is the bottom-most row.
    *   If Rank 1 = Row 9, Rank 2 = Row 8... Rank 5 = Row 5.
    *   "Reverse order of the original formation" -> Reverse of (9, 8, 7, 6, 5) is (5, 6, 7, 8, 9).
    *   This matches the output!
    *   So, the logic is: Identify the contiguous block of non-background rows at the bottom. Let's call this block $B$. Let the rows of $B$ be $r_1, r_2, ..., r_k$ where $r_1$ is the top row of the block and $r_k$ is the bottom row.
    *   The metaphor says "reverse order". If we consider the formation as a stack from bottom to top (standard military formation logic often starts from the front/bottom), the order is $r_k, r_{k-1}, ..., r_1$. Reversing this gives $r_1, r_2, ..., r_k$.
    *   Alternatively, s

... [7454 chars truncated]
alt-8 theater qwen3.5-122b: fail
"The actors take their marks downstage; the mirror-curtain behind them multiplies their blocking upward into the wings, each reflection unspooling the scene in reverse until every fly bar carries a frozen tableau."
Fail (best cell_acc=0.70 at k=2)
Best Attempt
vs
Expected
Reasoning (10844 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A stage with costumed figures (colored pixels) in the bottom rows and an empty backdrop (background color) in the rest.
*   **Action:** The blocking pattern (the arrangement of figures) projects upward.
*   **Mechanism:** Each row of empty stage receives the next line of the arrangement in reverse, cycling through the full tableau until the entire stage is populated.
*   **Grid Details:** Dimensions unchanged. Downstage positions (bottom) remain. Empty upstage (top) fills with repeated, reversed cycles of the blocking.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 10x5 grid. Background is X (grey).
    *   Bottom rows (rows 5-9, 0-indexed):
        *   Row 5: `X R R R X`
        *   Row 6: `X X R X X`
        *   Row 7: `X A A X X`
        *   Row 8: `X X A A X`
        *   Row 9: `X X A X X`
    *   Top rows (rows 0-4) are all `X X X X X`.
    *   Output:
        *   Row 0: `X R R R X` (Matches Input Row 5)
        *   Row 1: `X X R X X` (Matches Input Row 6)
        *   Row 2: `X A A X X` (Matches Input Row 7)
        *   Row 3: `X X A A X` (Matches Input Row 8)
        *   Row 4: `X X A X X` (Matches Input Row 9)
        *   Row 5: `X R R R X` (Matches Input Row 5)
        *   Row 6: `X X R X X` (Matches Input Row 6)
        *   Row 7: `X A A X X` (Matches Input Row 7)
        *   Row 8: `X X A A X` (Matches Input Row 8)
        *   Row 9: `X X A X X` (Matches Input Row 9)
    *   Observation: The pattern from the bottom (the "actors") is repeated upwards. It looks like the bottom 5 rows form a block. The top 5 rows are filled by copying this block.
    *   Wait, the description says "each row of empty stage receiving the next line of the arrangement in reverse". Let's look closer.
    *   Input Bottom Block (Rows 5-9):
        5: `X R R R X`
        6: `X X R X X`
        7: `X A A X X`
        8: `X X A A X`
        9: `X X A X X`
    *   Output Top Block (Rows 0-4):
        0: `X R R R X` (Same as Row 5)
        1: `X X R X X` (Same as Row 6)
        2: `X A A X X` (Same as Row 7)
        3: `X X A A X` (Same as Row 8)
        4: `X X A X X` (Same as Row 9)
    *   This looks like a direct copy, not a reverse. Let's re-read the description carefully. "each row of empty stage receiving the next line of the arrangement in reverse".
    *   Maybe "reverse" refers to the order of rows?
    *   If I take the block of actors (Rows 5-9) and reverse the order of rows:
        9: `X X A X X`
        8: `X X A A X`
        7: `X A A X X`
        6: `X X R X X`
        5: `X R R R X`
    *   If I fill the top rows (0-4) with this reversed sequence:
        Row 0 should be Row 9? No, Output Row 0 is `X R R R X` (Row 5).
    *   Let's check Example 2.

*   **Example 2:**
    *   Input: 10x7 grid. Background is G (green).
    *   Bottom rows (Rows 6-9):
        6: `G G G W R W G`
        7: `G G G R W R G`
        8: `G G G W W W G`
        9: `G G G G W G G`
    *   Top rows (0-5) are all `G G G G G G G`.
    *   Output:
        0: `G G G W W W G` (Matches Input Row 8)
        1: `G G G G W G G` (Matches Input Row 9)
        2: `G G G W R W G` (Matches Input Row 6)
        3: `G G G R W R G` (Matches Input Row 7)
        4: `G G G W W W G` (Matches Input Row 8)
        5: `G G G G W G G` (Matches Input Row 9)
        6: `G G G W R W G` (Matches Input Row 6)
        7: `G G G R W R G` (Matches Input Row 7)
        8: `G G G W W W G` (Matches Input Row 8)
        9: `G G G G W G G` (Matches Input Row 9)
    *   Let's analyze the pattern here.
    *   The "Actor Block" seems to be the non-background rows at the bottom.
    *   In Ex 1, the actor block is rows 5-9 (height 5). The grid height is 10. The top 5 rows are filled.
    *   In Ex 2, the actor block is rows 6-9 (height 4). The grid height is 10. The top 6 rows are filled.
    *   Let's look at the filling order in Ex 2.
    *   Actor Block Rows:
        A1 (Row 6): `G G G W R W G`
        A2 (Row 7): `G G G R W R G`
        A3 (Row 8): `G G G W W W G`
        A4 (Row 9): `G G G G W G G`
    *   Output Top Rows (0-5):
        Row 0: `G G G W W W G` (A3)
        Row 1: `G G G G W G G` (A4)
        Row 2: `G G G W R W G` (A1)
        Row 3: `G G G R W R G` (A2)
        Row 4: `G G G W W W G` (A3)
        Row 5: `G G G G W G G` (A4)
    *   Sequence: A3, A4, A1, A2, A3, A4.
    *   This looks like a cycle of the actor block rows.
    *   The cycle seems to be A1, A2, A3, A4.
    *   The filling starts from the top (Row 0).
    *   Row 0 gets A3. Row 1 gets A4. Row 2 gets A1. Row 3 gets A2.
    *   Why A3, A4, A1, A2?
    *   Maybe it's "reversed cycles"?
    *   If the cycle is A1, A2, A3, A4.
    *   Reversed cycle: A4, A3, A2, A1.
    *   If we fill upwards from the bottom of the empty space?
    *   Empty space is Rows 0-5.
    *   Row 5 is adjacent to Row 6 (A

... [5847 chars truncated]
alt-9 gardening qwen3.5-122b: fig alone solves
"Seeds planted in the lowest furrows sprout upward row by row, each new growth ring echoing the planting pattern in reverse until the entire bed blooms from soil to sky."

Task 674: ae3edfdc

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original Loyal pets hear their owner's whistle and come running home. MARC valid 1
alt-1 biology Two nuclei in a shared cell each emit chemical signals along their axes. Scatter ... [161 chars truncated] fig alone solves
alt-10 astronomy Two stars anchor a binary system — a blue giant and a red dwarf. Orange co ... [314 chars truncated] MARC valid 1
alt-11 ocean/sailing Two lighthouses stand in a dark harbor — one flashing blue, one flashing r ... [296 chars truncated] fig alone solves
alt-12 electronics Two ICs sit on a dark circuit board — one marked blue, one red. Orange cap ... [340 chars truncated] fig alone solves
alt-13 mythology Two gods dwell in the void — one cloaked in blue flame, one in red. Their ... [240 chars truncated] fig alone solves
alt-14 dance Two lead dancers hold their marks on a dark stage — one in blue, one in re ... [238 chars truncated] MARC valid 1
alt-15 geology Two magma vents pierce a dark plain — one glowing blue-hot, one red-hot. O ... [341 chars truncated] MARC valid 1
alt-2 cooking Two master chefs stand at their stations, each calling back their scattered ingr ... [235 chars truncated] fig alone solves
alt-3 music Two conductors stand on a vast stage, each commanding their own section of the o ... [280 chars truncated] fig alone solves
alt-4 sports Two quarterbacks drop back in the pocket. Their receivers, spread wide along the ... [232 chars truncated] fig alone solves
alt-5 weather Two storm eyes form on the radar, one cold-blue, one angry-red. Orange lightning ... [265 chars truncated] fig alone solves
alt-6 architecture Two monuments stand in an empty plaza. Along the avenues radiating north, south, ... [318 chars truncated] MARC valid 1
alt-7 warfare Two generals plant their banners on the battlefield — one blue, one red. T ... [253 chars truncated] fail
alt-8 theater Two spotlight operators sit in the rigging above a dark stage. Each has colored ... [272 chars truncated] fig alone solves
alt-9 gardening Two ancient trees grow in a vast garden — one with blue bark, one with red ... [324 chars truncated] fig alone solves
original qwen3.5-122b: k=1
"Loyal pets hear their owner's whistle and come running home."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10919 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A 15x15 dark field (black dots `.`).
*   **Homes:** Two homes, one Blue (`B`), one Red (`R`).
*   **Pets:**
    *   Blue owner keeps Orange (`O`) cats.
    *   Red owner keeps Green (`G`) dogs.
*   **Movement:** Pets wander off along roads (rows and columns) from their homes.
*   **Strays:** Some animals roam the field but belong to nobody (wrong color for the home, or maybe just extra pets).
*   **Action:** Owners call pets home.
*   **Pet Behavior:** Pets bolt straight back along the road (row/column) they came from. They stop at the "yard" — the very first patch of grass next to the front door.
*   **Stray Behavior:** Strays vanish (disappear).
*   **Result:** Only homes and their returned pets remain. Pets huddle as close as possible, one on each side they returned from.

**2. Analyze the Training Example:**
*   **Input:**
    *   Grid size: 15x15.
    *   Blue Home (`B`) at (2, 3) (0-indexed: row 2, col 3).
    *   Red Home (`R`) at (10, 11).
    *   Orange (`O`) pets:
        *   (0, 3) - Same column as B, above.
        *   (2, 0) - Same row as B, left.
        *   (2, 9) - Same row as B, right.
        *   (8, 3) - Same column as B, below.
    *   Green (`G`) pets:
        *   (10, 5) - Same row as R, left.
        *   (14, 11) - Same column as R, below.
    *   Other `O` or `G`? No other colors mentioned in the text, but let's check the grid.
    *   Wait, let's look at the input grid provided in Example 1.
        *   Row 0: `O` at col 3.
        *   Row 2: `O` at col 0, `B` at col 3, `O` at col 9.
        *   Row 8: `O` at col 3.
        *   Row 10: `G` at col 5, `R` at col 11.
        *   Row 14: `G` at col 11.
    *   So, `B` is at (2,3). `R` is at (10,11).
    *   `O`s are at (0,3), (2,0), (2,9), (8,3). All are in the same row or column as `B`.
    *   `G`s are at (10,5), (14,11). All are in the same row or column as `R`.
    *   Are there any strays? The description says "A few stray animals roam the field too". In Example 1, all `O`s are associated with `B` and all `G`s with `R`. There are no `O`s near `R` or `G`s near `B`. Wait, let's check the output.
*   **Output:**
    *   `B` remains at (2,3).
    *   `R` remains at (10,11).
    *   `O`s are now at:
        *   (1, 3) - Above `B`.
        *   (2, 2) - Left of `B`.
        *   (2, 4) - Right of `B`.
        *   (3, 3) - Below `B`.
    *   `G`s are now at:
        *   (10, 10) - Left of `R`.
        *   (11, 11) - Below `R`.
    *   All other cells are `.`.
    *   Wait, looking closely at the output grid for Example 1:
        *   Row 1: `O` at col 3. (Was at 0,3). Moved to adjacent cell (1,3).
        *   Row 2: `O` at col 2, `B` at col 3, `O` at col 4. (Was at 2,0 and 2,9). Moved to adjacent cells (2,2) and (2,4).
        *   Row 3: `O` at col 3. (Was at 8,3). Moved to adjacent cell (3,3).
        *   Row 10: `G` at col 10, `R` at col 11. (Was at 10,5). Moved to adjacent cell (10,10).
        *   Row 11: `G` at col 11. (Was at 14,11). Moved to adjacent cell (11,11).
    *   **Rule Interpretation:**
        *   Identify the "Home" colors: Blue (`B`) and Red (`R`).
        *   Identify "Pet" colors associated with each home: Orange (`O`) for Blue, Green (`G`) for Red.
        *   Find all instances of Pet colors in the grid.
        *   Check if they are in the same row or column as their corresponding Home.
        *   If a pet is in the same row/column as its home, it moves to the cell immediately adjacent to the home in that direction.
        *   If there are multiple pets in the same direction (e.g., two `O`s above `B`), do they stack? The description says "curling up in the very first patch of grass next to the front door". This implies only one pet per direction per home. If there are multiple pets in the same line, they all move to the same spot? Or do they disappear? Or does the example not show this case?
        *   In Example 1, there is only one pet per direction for each home.
            *   `B` (2,3):
                *   Up: `O` at (0,3) -> moves to (1,3).
                *   Down: `O` at (8,3) -> moves to (3,3).
                *   Left: `O` at (2,0) -> moves to (2,2).
                *   Right: `O` at (2,9) -> moves to (2,4).
            *   `R` (10,11):
                *   Left: `G` at (10,5) -> moves to (10,10).
                *   Down: `G` at (14,11) -> moves to (11,11).
                *   Up: None.
                *   Right: None.
        *   What about "Strays"? The description says "A few stray animals roam the field too, but they belong to nobody... The strays, hearing no familiar voice, simply vanish into the night."
        *   This implies if there is an `O` not in the same row/col as `B`, it vanishes. Or if there is a `G` not in the same row/col as `R`, it vanishes. Or if there is an `O` near `R`?
        *   I

... [5982 chars truncated]
alt-1 biology qwen3.5-122b: fig alone solves
"Two nuclei in a shared cell each emit chemical signals along their axes. Scattered organelles that detect the right signal retract along their microtubule, docking flush against the nucleus membrane. Organelles deaf to both signals dissolve."
alt-10 astronomy qwen3.5-122b: k=1
"Two stars anchor a binary system — a blue giant and a red dwarf. Orange comets orbit along the blue star's gravitational meridians; green asteroids drift along the red dwarf's. A gravitational pulse causes every body to fall inward, each settling into the closest stable orbit — one unit from its star, same bearing. Rogue debris with no gravitational parent is flung into the void."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10360 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A star chart with two stars and small bodies aligned along their cardinal axes at various distances, plus unbound debris.
*   **What to do:** Collapse each body to one cell from its star, preserving direction. Remove debris.
*   **Grid details:** 15x15 black. B and R are stars. O on B's axes, G on R's. Output: adjacent positions.

**2. Analyze the Training Example:**
*   **Input:**
    *   Grid size: 15x15.
    *   Background: `.` (black).
    *   Stars: `B` (Blue) at (2, 3) [0-indexed row, col] -> Row 2, Col 3. `R` (Red) at (10, 11).
    *   Bodies associated with B: `O` (Orange).
        *   (0, 3) - North of B.
        *   (2, 0) - West of B.
        *   (2, 8) - East of B.
        *   (8, 3) - South of B.
    *   Bodies associated with R: `G` (Green).
        *   (10, 5) - West of R.
        *   (14, 11) - South of R.
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Row 0: `...O.......` -> (0, 3) is O.
    *   Row 2: `O..B....O....` -> (2, 0) is O, (2, 3) is B, (2, 8) is O.
    *   Row 8: `...O.......` -> (8, 3) is O.
    *   Row 10: `.....G....R..` -> (10, 5) is G, (10, 11) is R.
    *   Row 14: `..........G..` -> (14, 11) is G.
    *   So, B is at (2, 3). R is at (10, 11).
    *   O's are at (0, 3), (2, 0), (2, 8), (8, 3). All are on the same row or column as B.
    *   G's are at (10, 5), (14, 11). All are on the same row or column as R.
*   **Output:**
    *   B is still at (2, 3). R is still at (10, 11).
    *   O's are now adjacent to B.
        *   (0, 3) moved to (1, 3) [North].
        *   (2, 0) moved to (2, 2) [West].
        *   (2, 8) moved to (2, 4) [East].
        *   (8, 3) moved to (3, 3) [South].
    *   G's are now adjacent to R.
        *   (10, 5) moved to (10, 10) [West].
        *   (14, 11) moved to (11, 11) [South].
    *   Wait, let's check the output grid provided.
    *   Row 1: `...O.......` -> (1, 3) is O.
    *   Row 2: `..OBO......` -> (2, 2) is O, (2, 3) is B, (2, 4) is O.
    *   Row 3: `...O.......` -> (3, 3) is O.
    *   Row 10: `..........GR.` -> (10, 10) is G, (10, 11) is R.
    *   Row 11: `...........G.` -> (11, 11) is G.
    *   This confirms the rule: Objects of a specific color orbit a specific star. They move to the cell immediately adjacent to the star in the direction they were originally located relative to the star.
    *   "Remove debris": The prompt mentions "unbound debris". In the example, all O's and G's were on the axes of B and R respectively. If there were other colors or objects not on the axes, they would be removed. In the example, all non-star objects were on the axes.
    *   "Collapse each body to one cell from its star, preserving direction."

**3. Conceptual Digestion:**
*   **CAST:**
    *   **Stars:** `B` (Blue) and `R` (Red). These are the anchors.
    *   **Satellites/Orbiters:** `O` (Orange) belongs to `B`. `G` (Green) belongs to `R`.
    *   **Debris:** Any other colored cells not aligned with a star on cardinal axes (though none appear in the examples, the rule implies removal).
    *   **Background:** `.` (Black).
*   **AFFORDANCES:**
    *   Stars stay in place.
    *   Orbiters move.
    *   Movement is constrained to the cardinal direction (Up, Down, Left, Right) relative to the star.
    *   Target position is distance 1 from the star.
*   **TRANSFORMATION RULE:**
    1.  Identify the positions of the Stars (`B` and `R`).
    2.  Identify the positions of the Orbiters (`O` for `B`, `G` for `R`).
    3.  For each Orbiter:
        *   Determine its relative position to its assigned Star (North, South, East, West).
        *   Move the Orbiter to the cell immediately adjacent to the Star in that direction.
        *   If multiple orbiters are in the same direction, they might overlap? The example shows distinct directions. If there were two on the same side, the rule "Collapse each body to one cell" implies they might stack or overwrite. However, usually in these puzzles, distinct objects map to distinct slots or overwrite. Given "Collapse... to one cell", it implies the final state has the object at distance 1. If two objects are on the same ray, they both try to occupy the same cell. Let's assume standard overwrite or just place the color there. In the test input, we need to check for collisions.
    4.  Clear all original positions of the orbiters (unless they are the target position, which is unlikely given "various distances").
    5.  Clear any debris (objects not associated with a star on a cardinal axis).
    6.  Keep the background black.

**4. Analyze the Test Input:**
*   **Grid Size:** 15x15.
*   **Stars:**
    *   `B` (Blue): Row 6, Col 5. (0-indexed: Row 6, Col 5). Let's verify.
        *   Row 6: `O . . . . B . . . . . . . . O`
        *   Indices: 0(O), 1(.), 2(.), 3(.),

... [5453 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fig alone solves
"Two lighthouses stand in a dark harbor — one flashing blue, one flashing red. Orange buoys have been set along the blue lighthouse's cardinal bearings, and green channel markers line the red lighthouse's. A harbor master orders all markers reeled in to the nearest mooring — one boat-length from their lighthouse, same heading. Driftwood is cleared from the water."
alt-12 electronics qwen3.5-122b: fig alone solves
"Two ICs sit on a dark circuit board — one marked blue, one red. Orange capacitors are soldered at various points along the blue chip's trace lines running in the four cardinal directions. Green resistors sit on the red chip's traces. A design revision calls for all components to be moved to the pad immediately next to their chip, same trace direction. Floating components with no trace connection are desoldered."
alt-13 mythology qwen3.5-122b: fig alone solves
"Two gods dwell in the void — one cloaked in blue flame, one in red. Their acolytes, scattered along the sacred axes of their temples, hear the summoning horn and rush to kneel at the threshold — one step from the divine seat, on whichever sacred road they traveled. Wandering souls with no patron are unmade."
alt-14 dance qwen3.5-122b: k=1
"Two lead dancers hold their marks on a dark stage — one in blue, one in red. Their partners, positioned at various distances along the four cardinal lines, hear the music shift and glide inward, each finishing one step from their lead, maintaining the line they started on. Dancers without a lead drift offstage."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9760 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A stage with two leads and partner dancers along their cardinal lines at various distances, plus extras.
*   **Action:** Each partner glides to one step from their lead, same direction. Extras exit.
*   **Grid details:** 15x15 black. B and R are leads. O on B's lines, G on R's lines. Output: one cell from lead.
*   **Interpretation:**
    *   **Leads:** Blue (B) and Red (R).
    *   **Partners:** Orange (O) associated with Blue (B). Green (G) associated with Red (R).
    *   **Lines:** Cardinal lines (horizontal and vertical) extending from the leads.
    *   **Movement:** Partners move to be "one step from their lead, same direction". This implies if a partner is at distance $d$ from the lead along a cardinal line, they move to distance 1 from the lead along that same line.
    *   **Extras:** Any other colored cells that are not partners or leads. They "exit" (disappear/become black).
    *   **Output:** The resulting grid state.

**2. Analyze the Training Example:**
*   **Input:**
    *   Lead B at (2, 3) (0-indexed row, col). Let's check coordinates.
    *   Row 0: `...O...` -> O at (0, 3).
    *   Row 2: `O..B...O...` -> O at (2, 0), B at (2, 3), O at (2, 9).
    *   Row 8: `...O...` -> O at (8, 3).
    *   Row 10: `....G...R..` -> G at (10, 5), R at (10, 11).
    *   Row 14: `......G..` -> G at (14, 12).
    *   Wait, let's look closer at the input grid provided in the prompt.
    *   Input Grid:
        R0: . . . O . . . . . . . . . . . (O at 0,3)
        R1: . . . . . . . . . . . . . . .
        R2: O . . B . . . . . O . . . . . (O at 2,0; B at 2,3; O at 2,9)
        R3-R7: Empty
        R8: . . . O . . . . . . . . . . . (O at 8,3)
        R9: Empty
        R10: . . . . . G . . . . . R . . . (G at 10,5; R at 10,11)
        R11-R13: Empty
        R14: . . . . . . . . . . . G . . . (G at 14,12)
    *   Leads: B at (2,3), R at (10,11).
    *   Partners for B (O):
        *   (0,3): Same column (col 3). Above B. Distance = 2.
        *   (2,0): Same row (row 2). Left of B. Distance = 3.
        *   (2,9): Same row (row 2). Right of B. Distance = 6.
        *   (8,3): Same column (col 3). Below B. Distance = 6.
    *   Partners for R (G):
        *   (10,5): Same row (row 10). Left of R. Distance = 6.
        *   (14,12): Same column (col 12). Below R. Distance = 4.
    *   Extras: None visible in this specific input description, but the rule says "Extras exit".
    *   Output Grid:
        R0: . . . . . . . . . . . . . . .
        R1: . . . O . . . . . . . . . . . (O at 1,3)
        R2: . . O B O . . . . . . . . . . (O at 2,2; B at 2,3; O at 2,4)
        R3: . . . O . . . . . . . . . . . (O at 3,3)
        R4-R9: Empty
        R10: . . . . . . . . . . G R . . . (G at 10,10; R at 10,11)
        R11: . . . . . . . . . . . G . . . (G at 11,11)
        R12-R14: Empty
    *   **Transformation Logic Verification:**
        *   **B (2,3):**
            *   Partner O at (0,3) [Up]: Moves to (1,3) [1 step Up].
            *   Partner O at (2,0) [Left]: Moves to (2,2) [1 step Left].
            *   Partner O at (2,9) [Right]: Moves to (2,4) [1 step Right].
            *   Partner O at (8,3) [Down]: Moves to (3,3) [1 step Down].
            *   Result: O at (1,3), (2,2), (2,4), (3,3). B stays at (2,3).
        *   **R (10,11):**
            *   Partner G at (10,5) [Left]: Moves to (10,10) [1 step Left].
            *   Partner G at (14,12) [Down]: Moves to (11,11) [1 step Down].
            *   Result: G at (10,10), (11,11). R stays at (10,11).
        *   **Extras:** None in input, so none to remove.
        *   **Grid Size:** 15x15.
    *   **Conclusion:** The rule is confirmed.
        1.  Identify Leads (B, R).
        2.  Identify Partners (O for B, G for R).
        3.  Identify Extras (Any other color).
        4.  For each Partner, find the Lead it belongs to.
        5.  Check if the Partner is on the same row or column as the Lead.
        6.  Move the Partner to the cell immediately adjacent to the Lead in the direction of the original position.
        7.  Remove all Extras.
        8.  Keep Leads in place.
        9.  Fill rest with black (.).

**3. Analyze the Test Input:**
*   **Grid:** 15x15.
*   **Input Grid:**
    R0: . . . . . . . . . . . G . . . (G at 0,11)
    R1: . . . . . . . . . . . . . . .
    R2: . . . . . . . . . . . . . . .
    R3: G . . . . . . . . . . R . . . (G at 3,0; R at 3,11)
    R4: . . . . . . . . . . . . . . .
    R5: . . . . . . . . . . . . . . .
    R6: O . . . . B . . . . . . . . O (O at 6,0; B at 6,5; O at 6,14)
    R7: . . . . . . . . . . . . . . .
    R8: . . . . . . . . . . . . . . .
    R9: . . . . . . . . . . . . . . .
    R10: . . . . . . . . . . . . . . .
    R11: . . . . . . . . . . . . . . .
    R12: . . . . . . . . . . . G . . . (G at 12,11)
    R13: . . . . . . . . . . . . .

... [4787 chars truncated]
alt-15 geology qwen3.5-122b: k=1
"Two magma vents pierce a dark plain — one glowing blue-hot, one red-hot. Orange mineral deposits have crystallized along the blue vent's fracture lines extending in the four cardinal directions. Green mineral veins trace the red vent's fractures. A seismic compression event drives every deposit inward along its fracture until it fuses to the vent wall — one cell out, same bearing. Loose sediment is erased."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9710 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** Geological survey, vents, mineral deposits, fracture lines, sediment.
*   **Action:** Compress each deposit to one cell from its vent along the same fracture. Erase sediment.
*   **Grid Details:**
    *   15x15 black background.
    *   `B` (Blue) and `R` (Red) are vents.
    *   `O` (Orange) is on `B`'s fractures.
    *   `G` (Green) is on `R`'s fractures.
    *   "Collapse to adjacent positions."

**2. Analyze the Training Example (Example 1):**
*   **Input:**
    *   Vents: `B` at (2, 3) [0-indexed row, col], `R` at (10, 11).
    *   `O` (Orange) locations: (0, 3), (2, 0), (2, 8), (8, 3).
    *   `G` (Green) locations: (10, 5), (14, 11).
    *   Background: `.` (Black).
*   **Output:**
    *   `B` remains at (2, 3).
    *   `R` remains at (10, 11).
    *   `O` locations in output: (1, 3), (2, 2), (2, 4), (3, 3).
        *   Wait, let's look closer.
        *   Input `O` at (0, 3) -> Output `O` at (1, 3). This is adjacent to `B` at (2, 3) vertically.
        *   Input `O` at (2, 0) -> Output `O` at (2, 2). This is adjacent to `B` at (2, 3) horizontally.
        *   Input `O` at (2, 8) -> Output `O` at (2, 4). This is adjacent to `B` at (2, 3) horizontally.
        *   Input `O` at (8, 3) -> Output `O` at (3, 3). This is adjacent to `B` at (2, 3) vertically.
    *   `G` locations in output: (10, 10), (11, 11).
        *   Input `G` at (10, 5) -> Output `G` at (10, 10). This is adjacent to `R` at (10, 11) horizontally.
        *   Input `G` at (14, 11) -> Output `G` at (11, 11). This is adjacent to `R` at (10, 11) vertically.
*   **Interpretation:**
    *   `B` is a source. `O` particles associated with `B` move towards `B` until they are immediately adjacent to `B`.
    *   `R` is a source. `G` particles associated with `R` move towards `R` until they are immediately adjacent to `R`.
    *   The "fracture lines" seem to be the cardinal directions (Up, Down, Left, Right) from the vent.
    *   If an `O` is on the same row or column as `B`, it moves to the cell next to `B` in that direction.
    *   If a `G` is on the same row or column as `R`, it moves to the cell next to `R` in that direction.
    *   "Erase sediment": Any other colored pixels not associated with the vents (if any) are removed. In Example 1, all non-black pixels were `B`, `R`, `O`, or `G`.
    *   What if multiple deposits are on the same line? In Example 1, there was only one `O` per direction relative to `B` (Up, Down, Left, Right). Same for `R` and `G`.
    *   Let's check the positions again.
        *   `B` at (2,3).
        *   `O` at (0,3) is North of `B`. Moves to (1,3) (North of `B`).
        *   `O` at (2,0) is West of `B`. Moves to (2,2) (West of `B`).
        *   `O` at (2,8) is East of `B`. Moves to (2,4) (East of `B`).
        *   `O` at (8,3) is South of `B`. Moves to (3,3) (South of `B`).
        *   `R` at (10,11).
        *   `G` at (10,5) is West of `R`. Moves to (10,10) (West of `R`).
        *   `G` at (14,11) is South of `R`. Moves to (11,11) (South of `R`).
    *   Rule: For every `O` on the same row or column as `B`, move it to the cell adjacent to `B` in that direction. For every `G` on the same row or column as `R`, move it to the cell adjacent to `R` in that direction. All other non-vent pixels are removed (or rather, only the moved deposits remain). The vents `B` and `R` stay in place.

**3. Analyze the Test Input:**
*   **Grid Size:** 15x15.
*   **Vents:**
    *   `B` (Blue) at (6, 5). (Row 6, Col 5).
    *   `R` (Red) at (3, 11). (Row 3, Col 11).
*   **Deposits:**
    *   `O` (Orange) associated with `B`.
        *   (6, 0) - West of `B`.
        *   (6, 14) - East of `B`.
    *   `G` (Green) associated with `R`.
        *   (0, 11) - North of `R`.
        *   (3, 0) - West of `R`.
        *   (12, 11) - South of `R`.
*   **Other pixels:**
    *   There are `G`s at (0, 11), (3, 0), (12, 11).
    *   There are `O`s at (6, 0), (6, 14).
    *   Wait, let's verify coordinates carefully.
    *   Row 0: `G` at col 11.
    *   Row 3: `G` at col 0, `R` at col 11.
    *   Row 6: `O` at col 0, `B` at col 5, `O` at col 14.
    *   Row 12: `G` at col 11.
    *   All other cells are `.`.

**4. Apply Transformation Rule:**
*   **Vents:** Keep `B` at (6, 5) and `R` at (3, 11).
*   **`O` deposits (for `B`):**
    *   `O` at (6, 0): Same row as `B` (Row 6). `B` is at Col 5. `O` is to the West (Col 0 < Col 5).
        *   Target: Adjacent West of `B` -> (6, 4).
    *   `O` at (6, 14): Same row as `B` (Row 6). `B` is at Col 5. `O` is to the East (Col 14 > Col 5).
        *   Target: Adjacent East of `B` -> (6, 6).
    *   Are there any `O`s on the same column as `B` (Col 5)? No.
*   **`G` deposits (for `R`):**
    *   `G` at (0, 11): Same column as `R` (Col 11). `R` is at Row 3. `G` is to the North (Row 0 < Row 3).
      

... [4791 chars truncated]
alt-2 cooking qwen3.5-122b: fig alone solves
"Two master chefs stand at their stations, each calling back their scattered ingredients. The orange spices fly to the blue chef's cutting board; the green herbs rush to the red chef's. Each ingredient lands on the side it was fetched from, right next to the chef's hand. Anything unclaimed is swept off the counter."
alt-3 music qwen3.5-122b: fig alone solves
"Two conductors stand on a vast stage, each commanding their own section of the orchestra. The brass players scattered along the blue conductor's sightlines gather close, taking the seat directly beside the podium in whichever direction they were sitting. The woodwinds do the same for the red conductor. Musicians not in anyone's line of sight leave the stage."
alt-4 sports qwen3.5-122b: fig alone solves
"Two quarterbacks drop back in the pocket. Their receivers, spread wide along the yard lines and sidelines, run tight comeback routes, stopping exactly one step from the QB. Receivers wearing orange answer the blue QB's cadence; green jerseys respond to the red QB. Players from neither roster walk off the field."
alt-5 weather qwen3.5-122b: fig alone solves
"Two storm eyes form on the radar, one cold-blue, one angry-red. Orange lightning bolts crackle along the blue eye's meridians; green rain bands spiral along the red eye's. As the storms intensify, all that distant energy contracts until each bolt and band hugs the eyewall — one pixel from the calm center. Scattered cloud wisps dissipate."
alt-6 architecture qwen3.5-122b: k=1
"Two monuments stand in an empty plaza. Along the avenues radiating north, south, east, and west from the blue monument, orange lanterns have been placed at various distances. Green banners line the streets extending from the red monument. A decree orders every lantern and banner moved to the nearest lamppost — the one directly beside its monument. Decorations not on any avenue are removed."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9371 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A plaza with two monuments and decorations placed along straight roads extending from each.
*   **Action:** Move each decoration to the position immediately adjacent to its monument, keeping the same street direction. Remove everything else.
*   **Grid details:** 15x15 grid.
*   **Monuments:** B (Blue) and R (Red).
*   **Decorations:** O (Orange) on B's cardinal lines, G (Green) on R's.
*   **Output:** One cell away from center (This part is a bit ambiguous, "Output: one cell away from center" might refer to the position of the decorations relative to the monument, or it might be a hint about the final state). Let's look at the examples to clarify.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:**
    *   B is at (2, 3) (0-indexed row, col). Let's check coordinates.
    *   Row 0: `...O.......` -> O at (0, 3)
    *   Row 2: `O..B...O...` -> O at (2, 0), B at (2, 3), O at (2, 9)
    *   Row 8: `...O.......` -> O at (8, 3)
    *   Row 10: `.....G...R..` -> G at (10, 5), R at (10, 11)
    *   Row 14: `.......G...` -> G at (14, 11)
    *   Wait, let's look closer at the input grid provided in the prompt text.
    *   Input Row 0: `. . . O . . . . . . . . . . .` -> O at (0, 3)
    *   Input Row 2: `O . . B . . . . . O . . . . .` -> O at (2, 0), B at (2, 3), O at (2, 9)
    *   Input Row 8: `. . . O . . . . . . . . . . .` -> O at (8, 3)
    *   Input Row 10: `. . . . . G . . . . . R . . .` -> G at (10, 5), R at (10, 11)
    *   Input Row 14: `. . . . . . . . . . . G . . .` -> G at (14, 11)
    *   So, Monuments: B at (2, 3), R at (10, 11).
    *   Decorations for B (Orange): (0, 3), (2, 0), (2, 9), (8, 3).
        *   (0, 3) is North of B (same col, row < 2).
        *   (2, 0) is West of B (same row, col < 3).
        *   (2, 9) is East of B (same row, col > 3).
        *   (8, 3) is South of B (same col, row > 2).
    *   Decorations for R (Green): (10, 5), (14, 11).
        *   (10, 5) is West of R (same row, col < 11).
        *   (14, 11) is South of R (same col, row > 11).
*   **Output:**
    *   Row 1: `. . . O . . . . . . . . . . .` -> O at (1, 3)
    *   Row 2: `. . O B O . . . . . . . . . .` -> O at (2, 2), B at (2, 3), O at (2, 4)
    *   Row 3: `. . . O . . . . . . . . . . .` -> O at (3, 3)
    *   Row 10: `. . . . . . . . . . G R . . .` -> G at (10, 10), R at (10, 11)
    *   Row 11: `. . . . . . . . . . . G . . .` -> G at (11, 11)
    *   All other cells are `.`.
*   **Transformation Logic:**
    *   The decorations (O and G) move to be immediately adjacent to their respective monuments (B and R).
    *   They maintain their relative direction (North, South, East, West).
    *   Specifically:
        *   O at (0, 3) [North] moves to (1, 3) [North of B].
        *   O at (2, 0) [West] moves to (2, 2) [West of B].
        *   O at (2, 9) [East] moves to (2, 4) [East of B].
        *   O at (8, 3) [South] moves to (3, 3) [South of B].
        *   G at (10, 5) [West] moves to (10, 10) [West of R].
        *   G at (14, 11) [South] moves to (11, 11) [South of R].
    *   The original positions of decorations are cleared (become `.`).
    *   The monuments (B, R) stay in place.
    *   Any decorations not on the cardinal lines of a monument? In this example, all decorations seem to be on cardinal lines.
    *   "Remove everything else" implies clearing the grid except for the monuments and the moved decorations.

**3. Analyze the Test Input:**
*   **Grid Size:** 15x15.
*   **Locate Monuments:**
    *   B (Blue): Row 6, Col 5. (0-indexed: Row 6 is the 7th line).
        *   Line 6: `O . . . . B . . . . . . . . O`
        *   Wait, let's count carefully.
        *   Row 0: `. . . . . . . . . . . G . . .` -> G at (0, 11)
        *   Row 3: `G . . . . . . . . . . R . . .` -> G at (3, 0), R at (3, 11)
        *   Row 6: `O . . . . B . . . . . . . . O` -> O at (6, 0), B at (6, 5), O at (6, 14)
        *   Row 12: `. . . . . . . . . . . G . . .` -> G at (12, 11)
    *   Let's verify coordinates.
    *   **Monument B:** Row 6, Column 5.
    *   **Monument R:** Row 3, Column 11.
*   **Locate Decorations:**
    *   **Orange (O) associated with B:**
        *   (6, 0): West of B (Row 6, Col 0 < 5).
        *   (6, 14): East of B (Row 6, Col 14 > 5).
        *   Are there any North/South O's?
        *   Scanning rows...
        *   Row 0: G
        *   Row 3: G, R
        *   Row 6: O, B, O
        *   Row 12: G
        *   No other O's.
    *   **Green (G) associated with R:**
        *   (0, 11): North of R (Row 0 < 3, Col 11).
        *   (3, 0): West of R (Row 3, Col 0 < 11).
        *   (12, 11): South of R (Row 12 > 3, Col 11).
        *   Are there any East G's?
        *   Scanning... No other G's.
*   **Transformation Plan:**


... [4500 chars truncated]
alt-7 warfare qwen3.5-122b: fail
"Two generals plant their banners on the battlefield — one blue, one red. Their scouts, deployed far along the cardinal roads, receive the recall signal. Each scout marches back and takes up a guard position one pace from the banner, on whichever road they were patrolling. Deserters with no allegiance vanish in the fog of war."
Fail (best cell_acc=0.00 at k=1)
No grid
vs
Expected
Reasoning (11520 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A battlefield with two banners (B and R) and scouts (O and G) stretched along straight roads from each. Unaffiliated figures stand elsewhere.
*   **Action:** Each scout returns to the position one step from their general's banner, preserving their patrol direction. Unaffiliated figures are removed.
*   **Grid details:** 15x15 black background. B (Blue) and R (Red) are banners. O (Orange) scouts belong to B. G (Green) scouts belong to R.
*   **Transformation:** "Collapse to adjacent." This implies moving the scouts closer to their respective banners. Specifically, "returns to the position one step from their general's banner". This suggests that if a scout is on the same row or column as a banner, it moves to the cell immediately adjacent to the banner in that direction.

**2. Analyze the Training Example:**
*   **Input:**
    *   B at (2, 3) (0-indexed: row 2, col 3).
    *   R at (10, 11).
    *   O scouts at: (0, 3), (2, 0), (2, 8), (8, 3).
    *   G scouts at: (10, 5), (14, 12).
    *   Wait, let's look closer at the input grid provided in Example 1.
    *   Row 0: `...O.......` -> O at (0, 3).
    *   Row 2: `O..B....O....` -> O at (2, 0), B at (2, 3), O at (2, 8).
    *   Row 8: `...O.......` -> O at (8, 3).
    *   Row 10: `.....G....R..` -> G at (10, 5), R at (10, 11).
    *   Row 14: `..........G..` -> G at (14, 12).
*   **Output:**
    *   Row 1: `...O.......` -> O at (1, 3).
    *   Row 2: `..OBO......` -> O at (2, 2), B at (2, 3), O at (2, 4).
    *   Row 3: `...O.......` -> O at (3, 3).
    *   Row 10: `..........GR.` -> G at (10, 10), R at (10, 11).
    *   Row 11: `..........G..` -> G at (11, 11).
    *   All other cells are black.
*   **Observations:**
    *   **B (Blue) Banner:** Located at (2, 3).
        *   O at (0, 3) moved to (1, 3). This is 1 step North of B.
        *   O at (2, 0) moved to (2, 2). This is 1 step West of B.
        *   O at (2, 8) moved to (2, 4). This is 1 step East of B.
        *   O at (8, 3) moved to (3, 3). This is 1 step South of B.
        *   Basically, all O's aligned with B on the same row or column moved to the cell immediately adjacent to B in that direction.
    *   **R (Red) Banner:** Located at (10, 11).
        *   G at (10, 5) moved to (10, 10). This is 1 step West of R.
        *   G at (14, 12) moved to (11, 11). This is 1 step South of R.
        *   Wait, G at (14, 12) is on column 12. R is at column 11. They are not on the same row or column.
        *   Let's re-examine the input for G at (14, 12).
        *   Input Row 14: `. . . . . . . . . . . . G . .` -> G is at index 12.
        *   Input Row 10: `. . . . . G . . . . . R . . .` -> R is at index 11.
        *   Output Row 11: `. . . . . . . . . . . G . . .` -> G is at index 11.
        *   Wait, the output shows G at (11, 11). R is at (10, 11). So G moved to be South of R.
        *   But the input G was at (14, 12). This is not aligned with R (10, 11).
        *   Let's check the input again.
        *   Input Row 10: `.....G....R..` -> G at (10, 5), R at (10, 11).
        *   Input Row 14: `..........G..` -> G at (14, 12).
        *   Output Row 10: `..........GR.` -> G at (10, 10), R at (10, 11).
        *   Output Row 11: `..........G..` -> G at (11, 11).
        *   Wait, looking at the provided text for Example 1 Output:
            Row 10: `. . . . . . . . . . G R . . .` -> G at (10, 10), R at (10, 11).
            Row 11: `. . . . . . . . . . . G . . .` -> G at (11, 11).
        *   So the G at (14, 12) moved to (11, 11).
        *   Why (11, 11)? R is at (10, 11). (11, 11) is directly South of R.
        *   Why did the G at (14, 12) move there? It wasn't aligned.
        *   Maybe I misread the input coordinates.
        *   Input Row 14: `. . . . . . . . . . . . G . .`
            Indices: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
            Char at 12 is G.
        *   Input Row 10: `. . . . . G . . . . . R . . .`
            Indices: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
            Char at 5 is G. Char at 11 is R.
        *   So G(14, 12) is not aligned with R(10, 11).
        *   However, in the output, there is a G at (11, 11).
        *   Is it possible the input description in the prompt text has a typo or I am misinterpreting "aligned"?
        *   "scouts stretched along straight roads from each". This implies alignment.
        *   Let's look at the "Unaffiliated figures are removed" part.
        *   In Example 1, all O's and G's seem to have moved. None were removed.
        *   Wait, let's look at the Input Row 14 again.
        *   `. . . . . . . . . . . . G . .`
        *   Maybe the G is at (14, 11)?
        *   Let's count dots.
        *   Row 14: `.` (0) `.` (1) `.` (2) `.` (3) `.` (4) `.` (5) `.` (6) `.` (7) `.` (8) `.` (9) `.` (10) `.` (11

... [6601 chars truncated]
alt-8 theater qwen3.5-122b: fig alone solves
"Two spotlight operators sit in the rigging above a dark stage. Each has colored gel filters stored at various distances along the catwalks running north-south and east-west from their chair. When the director calls 'places,' every filter slides along its catwalk rail to the slot right next to its operator. Filters that fell off the catwalks are lost."
alt-9 gardening qwen3.5-122b: fig alone solves
"Two ancient trees grow in a vast garden — one with blue bark, one with red. Orange mushrooms have sprouted along the roots extending in the four cardinal directions from the blue tree, while green moss patches cling to the red tree's roots. Come autumn, the roots contract, pulling each growth tight against the trunk — one handspan away, same direction. Weeds with no root connection wither."

Task 706: b7256dcd

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A single drop of dye falls into water and stains whatever clay sculpture it touc ... [4 chars truncated] MARC valid 1
alt-1 biology A virus touches a host organism and rewrites its entire DNA, then disintegrates. ... [109 chars truncated] fail
alt-10 astronomy A comet grazes a nebula and its trail paints every particle of the cloud in the ... [56 chars truncated] fail
alt-11 ocean/sailing A flare tossed against the hull of a ghost ship illuminates every plank in its c ... [44 chars truncated] MARC valid 1
alt-12 electronics A charged capacitor touches one node of a circuit and every connected trace adop ... [57 chars truncated] fig alone solves
alt-13 mythology A demigod touches a stone idol and their divine essence flows through every crac ... [84 chars truncated] fail
alt-14 dance A soloist brushes against a formation and every dancer in the troupe mirrors the ... [78 chars truncated] fail
alt-15 geology A mineral vein touches a rock formation and its pigment seeps through every fiss ... [64 chars truncated] fail
alt-2 cooking A pinch of saffron dropped beside a block of tofu saturates it entirely with col ... [62 chars truncated] fail
alt-3 music A tuning fork struck near a crystal glass makes the entire glass resonate at the ... [53 chars truncated] fail
alt-4 sports A coach standing at the sideline taps a player, and suddenly the whole team dons ... [69 chars truncated] fail
alt-5 weather A single lightning bolt strikes one edge of a cloud and electrifies the entire f ... [60 chars truncated] fail
alt-6 architecture A mason places a colored keystone beside an arch, and every brick in the connect ... [82 chars truncated] fail
alt-7 warfare A spy infiltrates a fortress through a single gate and raises their banner over ... [46 chars truncated] fig alone solves
alt-8 theater A spotlight operator touches a prop and the entire set piece floods with that li ... [62 chars truncated] fail
alt-9 gardening A single bee dusted with pollen lands on one petal and the entire flower blooms ... [72 chars truncated] fail
original qwen3.5-122b: k=1
"A single drop of dye falls into water and stains whatever clay sculpture it touches."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9166 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Background:** "Orange lake" -> Orange cells (O) are the background/water.
*   **Objects:** "Sculptures made of magenta clay" -> Magenta cells (M) form connected shapes.
*   **Agents:** "Droplets of vivid color" -> Single cells of colors other than Orange (O) and Magenta (M). Examples given: Green (G), Yellow (Y), Blue (B).
*   **Action:**
    *   Droplets reach out to what they touch.
    *   If a droplet touches a clay sculpture (M), the sculpture absorbs the color.
    *   "Every cell of connected clay transforms to match the dye." -> This implies connected components of M change color if adjacent to a specific droplet color.
    *   "The droplet, spent, dissolves back into the orange water and vanishes." -> Droplet cells become Orange (O).
    *   "Droplets that float alone, touching no sculpture, simply sink and disappear without a trace." -> Droplets not touching M become Orange (O).
    *   "Any sculpture that no droplet touched remains its original magenta clay." -> M cells not adjacent to any droplet stay M.
*   **Summary of Transformation:**
    1.  Identify connected components of Magenta (M).
    2.  Identify single cells of other colors (let's call them "Dyes").
    3.  Check adjacency between Dyes and M components.
    4.  If a Dye cell is adjacent (orthogonally, presumably) to an M component:
        *   All M cells in that connected component change to the Dye's color.
        *   The Dye cell itself changes to Orange (O).
    5.  If a Dye cell is not adjacent to any M component:
        *   The Dye cell changes to Orange (O).
    6.  M components not adjacent to any Dye remain M.
    7.  Orange (O) cells remain Orange (O).

**2. Analyze Training Example 1:**
Input:
O M M G O
O O O Y O
O O O M O
O O M M M
O O O M O

Grid:
(0,0)O (0,1)M (0,2)M (0,3)G (0,4)O
(1,0)O (1,1)O (1,2)O (1,3)Y (1,4)O
(2,0)O (2,1)O (2,2)O (2,3)M (2,4)O
(3,0)O (3,1)O (3,2)M (3,3)M (3,4)M
(4,0)O (4,1)O (4,2)O (4,3)M (4,4)O

Magenta Components:
1.  Top-left cluster: (0,1), (0,2).
    *   Adjacent to G at (0,3).
    *   Adjacent to Y at (1,3)? No, (0,2) is adjacent to (0,3)G. (0,2) is adjacent to (1,2)O. (0,1) is adjacent to (1,1)O.
    *   Wait, let's look at connectivity.
    *   M at (0,1) connects to M at (0,2).
    *   M at (0,2) is adjacent to G at (0,3).
    *   So this component should turn Green.
2.  Bottom cluster: (2,3), (3,2), (3,3), (3,4), (4,3).
    *   (2,3) connects to (3,3).
    *   (3,2) connects to (3,3).
    *   (3,3) connects to (3,4).
    *   (3,3) connects to (4,3).
    *   This is one large connected component.
    *   Is it adjacent to any dye?
    *   (2,3) is adjacent to Y at (1,3).
    *   So this component should turn Yellow.

Dyes:
*   G at (0,3). Adjacent to M component 1. Becomes O.
*   Y at (1,3). Adjacent to M component 2. Becomes O.

Output:
O G G O O
O O O O O
O O O Y O
O O Y Y Y
O O O Y O

Let's check the output against my hypothesis.
*   (0,1)M -> G. (0,2)M -> G. Correct.
*   (0,3)G -> O. Correct.
*   (1,3)Y -> O. Correct.
*   (2,3)M -> Y. (3,2)M -> Y. (3,3)M -> Y. (3,4)M -> Y. (4,3)M -> Y. Correct.
*   All O remain O.

Hypothesis holds.
Rule:
1.  Find connected components of M (4-connectivity).
2.  Find all non-O, non-M cells (Dyes).
3.  For each Dye cell:
    *   If it is orthogonally adjacent to an M component:
        *   Change all M cells in that component to the Dye's color.
        *   Change the Dye cell to O.
    *   If it is not adjacent to any M component:
        *   Change the Dye cell to O.
4.  M components not touched by any Dye remain M.
5.  O cells remain O.

Wait, what if a component is adjacent to multiple dyes of different colors?
The description says: "If a droplet is brushing against a clay sculpture, the sculpture drinks in the color completely".
It doesn't explicitly specify priority if multiple dyes touch the same sculpture.
However, in the training example, the components are distinct.
Let's look at the Test Input to see if there are conflicts.

**3. Analyze Test Input:**
Input Grid:
Y O M O O O X
M M M O O O O
O O M O B O O
O O O O M M O
O O O O M M O
M M A O O O O
O M O O O O O

Dimensions: 7 rows, 7 columns.

Let's map the grid coordinates (row, col).
Row 0: Y(0,0), O(0,1), M(0,2), O(0,3), O(0,4), O(0,5), X(0,6)
Row 1: M(1,0), M(1,1), M(1,2), O(1,3), O(1,4), O(1,5), O(1,6)
Row 2: O(2,0), O(2,1), M(2,2), O(2,3), B(2,4), O(2,5), O(2,6)
Row 3: O(3,0), O(3,1), O(3,2), O(3,3), M(3,4), M(3,5), O(3,6)
Row 4: O(4,0), O(4,1), O(4,2), O(4,3), M(4,4), M(4,5), O(4,6)
Row 5: M(5,0), M(5,1), A(5,2), O(5,3), O(5,4), O(5,5), O(5,6)
Row 6: O(6,0), M(6,1), O(6,2), O(6,3), O(6,4), O(6,5), O(6,6)

**Step 1: Identify Magenta (M) Components.**
Let's list M cells and find connectivity.
M cells:
(0,2)
(1,0), (1,1), (1,2)
(2,2)
(3,4), (3,5)
(4,4), (4,5)
(5,0), (5,1)
(6,1

... [4346 chars truncated]
alt-1 biology qwen3.5-122b: fail
"A virus touches a host organism and rewrites its entire DNA, then disintegrates. Organisms never contacted by any pathogen remain unchanged. Free-floating viruses with no host simply decay."
Fail (best cell_acc=0.67 at k=1)
Best Attempt
vs
Expected
Reasoning (11206 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Warm habitat with clay-colored organisms and scattered microbes of various strains."
*   **Action:** "Each microbe that physically contacts an organism infects it completely, recoloring every cell of the organism to match the microbe's strain. The infecting microbe is consumed in the process. Microbes that touch nothing simply dissolve. Uninfected organisms persist."
*   **Grid Details:**
    *   Background is orange (O).
    *   Infected organisms display the color of their infecting microbe.
    *   Uninfected organisms remain magenta (M).
    *   All lone microbes are gone.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O
    ```
*   **Output:**
    ```
    O G G O O
    O O O O O
    O O O Y O
    O O Y Y Y
    O O O Y O
    ```
*   **Observations:**
    *   Background color seems to be Orange (O).
    *   There are "organisms" and "microbes".
    *   In the input, we see M (magenta), G (green), Y (yellow).
    *   In the output, the M's have changed.
    *   Let's look at the shapes.
    *   Input Row 0: `O M M G O`. There is a block of `M M` next to a `G`.
    *   Input Row 1: `O O O Y O`. There is a `Y`.
    *   Input Row 2: `O O O M O`. There is an `M`.
    *   Input Row 3: `O O M M M`. There is a block of `M M M`.
    *   Input Row 4: `O O O M O`. There is an `M`.
    *   Wait, the description says "Uninfected organisms remain magenta". This implies M is the default color of an organism.
    *   The description says "Background is orange". So O is background.
    *   The description says "scattered microbes of various strains". So G, Y, etc., are likely microbes.
    *   The description says "Each microbe that physically contacts an organism infects it completely".
    *   Let's identify the "organisms". They seem to be connected components of Magenta (M).
    *   Let's identify the "microbes". They seem to be single cells of non-M, non-O colors (like G, Y).
    *   Let's check connectivity.
    *   Input:
        (0,1) M, (0,2) M. (0,3) G.
        (1,3) Y.
        (2,3) M.
        (3,2) M, (3,3) M, (3,4) M.
        (4,3) M.
    *   Let's trace the M components.
        *   Component 1: (0,1), (0,2).
        *   Component 2: (2,3).
        *   Component 3: (3,2), (3,3), (3,4), (4,3).
        *   Wait, (2,3) is adjacent to (3,3). So (2,3) is connected to Component 3.
        *   Let's re-evaluate connectivity.
        *   (0,1) M, (0,2) M. Neighbors: (0,3) G.
        *   (2,3) M. Neighbors: (1,3) Y, (3,3) M.
        *   (3,2) M, (3,3) M, (3,4) M. Neighbors: (2,3) M, (4,3) M.
        *   (4,3) M. Neighbors: (3,3) M.
        *   So there is a large connected component of M's: (2,3), (3,2), (3,3), (3,4), (4,3).
        *   There is a separate connected component of M's: (0,1), (0,2).
    *   Now look at the microbes (G, Y).
        *   G at (0,3). It touches M at (0,2).
        *   Y at (1,3). It touches M at (2,3).
    *   Transformation:
        *   The M component {(0,1), (0,2)} touches G. So it becomes G.
            *   Output at (0,1), (0,2) is G. Correct.
        *   The M component {(2,3), (3,2), (3,3), (3,4), (4,3)} touches Y. So it becomes Y.
            *   Output at (2,3), (3,2), (3,3), (3,4), (4,3) is Y. Correct.
        *   The microbes G and Y are consumed (disappear/replaced by background?).
            *   Output at (0,3) is O. Correct.
            *   Output at (1,3) is O. Correct.
    *   What about M's that don't touch anything?
        *   In this example, all M's touched something.
        *   Wait, look at row 3 in output: `O O Y Y Y`. Input was `O O M M M`.
        *   Look at row 4 in output: `O O O Y O`. Input was `O O O M O`.
        *   Look at row 2 in output: `O O O Y O`. Input was `O O O M O`.
        *   Wait, in input row 2, col 3 is M. In output row 2, col 3 is Y.
        *   In input row 3, col 2,3,4 are M. In output row 3, col 2,3,4 are Y.
        *   In input row 4, col 3 is M. In output row 4, col 3 is Y.
        *   So the big M blob turned Y because it touched Y.
        *   The small M blob {(0,1), (0,2)} turned G because it touched G.
    *   What if an M touches multiple microbes? The description says "Each microbe that physically contacts an organism infects it completely". It doesn't specify priority. But usually, in these puzzles, if an organism touches multiple, it might be ambiguous. However, looking at the grid, usually, an organism touches one specific microbe type or none.
    *   What if a microbe touches nothing? "Microbes that touch nothing simply dissolve." -> They become background (O).
    *   What if an organism touches nothing? "Uninfected organisms persist." -> They remain M.
    *   What is the background? O.
    *   So the rule is:
        1.  Identify connected components of Mag

... [6212 chars truncated]
alt-10 astronomy qwen3.5-122b: fail
"A comet grazes a nebula and its trail paints every particle of the cloud in the comet's spectral hue, while the comet itself burns away."
Fail (best cell_acc=0.67 at k=2)
Best Attempt
vs
Expected
Reasoning (11618 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A warm void with nebula formations and lone comets of various spectral colors."
*   **Action:** "A comet touching a nebula recolors the entire connected gas cloud to match its spectrum. The comet is consumed. Comets that pass through empty space simply fade. Untouched nebulae keep their original glow."
*   **Grid Details:** "Same void. Background is the amber cosmos. Painted nebulae display the comet's color. Untouched nebulae remain magenta. No comets survive."
*   **Color Key:**
    *   `.` = black
    *   `B` = blue
    *   `R` = red
    *   `G` = green
    *   `Y` = yellow
    *   `X` = grey
    *   `M` = magenta
    *   `O` = orange
    *   `A` = azure
    *   `W` = maroon

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        O M M G O
        O O O Y O
        O O O M O
        O O M M M
        O O O M O
        ```
    *   Output:
        ```
        O G G O O
        O O O O O
        O O O Y O
        O O Y Y Y
        O O O Y O
        ```
    *   Observations:
        *   Background seems to be `O` (orange).
        *   `M` (magenta) appears to be the "nebula" or "gas cloud".
        *   `G` (green) and `Y` (yellow) appear to be "comets".
        *   In the input, there is a `G` at (0, 3) and a `Y` at (1, 3).
        *   There are `M`s connected to these comets.
        *   The `G` at (0,3) is adjacent to `M`s at (0,2) and (0,1). Wait, looking at the grid:
            Row 0: O M M G O. `G` is at (0,3). `M`s are at (0,1), (0,2). They are connected.
            Row 1: O O O Y O. `Y` is at (1,3).
            Row 2: O O O M O. `M` at (2,3).
            Row 3: O O M M M. `M`s at (3,2), (3,3), (3,4).
            Row 4: O O O M O. `M` at (4,3).
        *   Let's check connectivity.
            *   `G` at (0,3). Neighbors: (0,2)=M, (0,4)=O, (1,3)=Y.
            *   `Y` at (1,3). Neighbors: (0,3)=G, (1,2)=O, (1,4)=O, (2,3)=M.
            *   `M`s form a connected component?
                (0,1)-(0,2) connected.
                (0,2) touches (0,3)=G.
                (1,3)=Y touches (2,3)=M.
                (2,3)=M touches (3,3)=M.
                (3,3)=M touches (3,2)=M, (3,4)=M, (4,3)=M.
            *   So there is a large connected component of `M`s.
            *   However, the output shows:
                Row 0: O G G O O. The `M`s at (0,1), (0,2) became `G`. The `G` at (0,3) became `O` (background).
                Row 1: O O O O O. The `Y` at (1,3) became `O`.
                Row 2: O O O Y O. The `M` at (2,3) became `Y`.
                Row 3: O O Y Y Y. The `M`s at (3,2), (3,3), (3,4) became `Y`.
                Row 4: O O O Y O. The `M` at (4,3) became `Y`.
            *   Interpretation:
                *   `O` is the background (empty space/void).
                *   `M` is the nebula (target to be colored).
                *   `G` and `Y` are comets (sources of color).
                *   The `G` comet is adjacent to the `M` cluster at the top. It colors the connected `M`s it touches.
                *   The `Y` comet is adjacent to the `M` cluster at the bottom. It colors the connected `M`s it touches.
                *   Wait, are the `M`s one big cluster or two?
                    *   Top cluster: (0,1), (0,2). Connected to `G` at (0,3).
                    *   Bottom cluster: (2,3), (3,2), (3,3), (3,4), (4,3). Connected to `Y` at (1,3).
                    *   Are they connected to each other?
                        (0,2) is M. (1,2) is O. (0,3) is G. (1,3) is Y.
                        (2,3) is M.
                        Is there a path of `M`s between top and bottom?
                        (0,2) -> (0,1). No other M neighbors.
                        (2,3) -> (3,3) -> (3,2), (3,4), (4,3).
                        There is no path of `M`s connecting the top group to the bottom group. They are separated by `O`s and the comets `G` and `Y`.
                *   So, `G` colors the `M`s connected to it. `Y` colors the `M`s connected to it.
                *   The comets themselves (`G`, `Y`) turn into background (`O`) after "consuming" themselves.
                *   The `M`s that are not connected to any comet remain `M`? In this example, all `M`s were connected to a comet.
                *   Wait, look at row 0 output: `O G G O O`. The `G` at (0,3) became `O`. The `M`s at (0,1), (0,2) became `G`.
                *   Look at row 1 output: `O O O O O`. The `Y` at (1,3) became `O`.
                *   Look at row 2 output: `O O O Y O`. The `M` at (2,3) became `Y`.
                *   So the rule seems to be:
                    1. Identify connected components of `M` (magenta).
                    2. Identify "comet" colors (anything not `O` or `M`? Or specific colors?). In Ex 1, `G` and `Y` are comets.
                    3. If a comet is adjacent to an `M` componen

... [6642 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=1
"A flare tossed against the hull of a ghost ship illuminates every plank in its color, and the flare sinks beneath the waves."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10724 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A warm sea (background color), drifting vessel wreckage (ships), individual signal flares.
*   **Action:** A flare touching a vessel lights up the whole connected hull in the flare's color. The flare is extinguished. Flares in open water fizzle out. Ships no flare reaches keep their ghostly appearance.
*   **Grid Details:**
    *   Background: Amber ocean (Orange 'O').
    *   Illuminated ships: Show the flare's color.
    *   Unlit ships: Remain magenta ('M').
    *   Flares: All flares are gone in the output.
*   **Key Insight:** This sounds like a flood-fill or connected component coloring problem.
    *   "Vessel wreckage" likely corresponds to a specific color (Magenta 'M' based on "Unlit ships remain magenta").
    *   "Signal flares" likely correspond to other colors (Y, G, B, A, etc.) that are distinct from the background and the ships.
    *   "Touching a vessel": Adjacency (likely 4-way or 8-way).
    *   "Connected hull": Connected components of the ship color.
    *   "Flare extinguished": The flare color pixels disappear (turn into background or ship color?). The description says "Illuminated ships show the flare's color". This implies the ship pixels change to the flare color.
    *   "Flares in open water fizzle out": If a flare is not adjacent to a ship, it disappears (turns to background?).
    *   "Ships no flare reaches keep their ghostly appearance": Unlit ship pixels remain Magenta ('M').
    *   "Background is the amber ocean": Background is Orange ('O').

**2. Analyze the Training Example:**
Input:
O M M G O
O O O Y O
O O O M O
O O M M M
O O O M O

Output:
O G G O O
O O O O O
O O O Y O
O O Y Y Y
O O O Y O

Let's break down the Input grid:
Row 0: O M M G O
Row 1: O O O Y O
Row 2: O O O M O
Row 3: O O M M M
Row 4: O O O M O

Colors present:
O (Orange) - Background
M (Magenta) - Ships (Unlit)
G (Green) - Flare?
Y (Yellow) - Flare?

Let's look at the Output grid:
Row 0: O G G O O  -> The M M became G G. The G became O.
Row 1: O O O O O  -> The Y became O.
Row 2: O O O Y O  -> The M became Y.
Row 3: O O Y Y Y  -> The M M M became Y Y Y.
Row 4: O O O Y O  -> The M became Y.

Observations:
1.  **Background:** 'O' stays 'O'.
2.  **Flares:** 'G' at (0,3) and 'Y' at (1,3) are gone in the output (replaced by 'O').
3.  **Ships:** 'M' pixels change color if they are connected to a flare.
    *   The 'M' at (0,1) and (0,2) are adjacent to 'G' at (0,3). They turn 'G'.
    *   The 'M' at (2,3), (3,2), (3,3), (3,4), (4,3) form a connected component.
    *   The 'Y' at (1,3) is adjacent to 'M' at (2,3).
    *   So the connected component of 'M's starting at (2,3) gets colored 'Y'.
    *   Wait, let's check connectivity.
    *   (0,1) M, (0,2) M. (0,3) is G. (0,2) touches (0,3). So (0,1)-(0,2) component gets G.
    *   (2,3) M. (1,3) is Y. (2,3) touches (1,3). So (2,3) component gets Y.
    *   (3,2) M, (3,3) M, (3,4) M. (4,3) M.
    *   Are (2,3) and (3,2) connected? (2,3) is M. (3,3) is M. They are vertically adjacent. So yes.
    *   So the whole group of Ms in the bottom right is connected to the Y at (1,3). They all turn Y.
    *   The G at (0,3) turns to O (background).
    *   The Y at (1,3) turns to O (background).
    *   The Ms that were lit turn to the flare color.
    *   The Ms that were not lit... are there any? In this example, all Ms seem to be lit.
    *   Wait, look at row 0: O M M G O. The Ms are at (0,1), (0,2). G is at (0,3). They touch.
    *   Look at row 2: O O O M O. M at (2,3). Y at (1,3). They touch.
    *   Look at row 3: O O M M M. Ms at (3,2), (3,3), (3,4).
    *   Look at row 4: O O O M O. M at (4,3).
    *   Connectivity of Ms:
        *   (2,3) touches (3,3).
        *   (3,3) touches (3,2), (3,4), (4,3).
        *   So all Ms in rows 2,3,4 are one component.
        *   This component touches Y at (1,3). So it becomes Y.
    *   Connectivity of Ms in row 0:
        *   (0,1), (0,2).
        *   (0,2) touches G at (0,3). So it becomes G.
    *   Flares G and Y disappear (become O).

**Hypothesis:**
1.  Identify Background color (O).
2.  Identify Ship color (M).
3.  Identify Flare colors (anything not O or M).
4.  Find connected components of Ship color (M).
5.  For each Ship component, check if it is adjacent (4-way) to any Flare pixel.
6.  If a Ship component is adjacent to a Flare of color C:
    *   Change all pixels in that Ship component to color C.
    *   Remove the Flare pixel (change it to Background O).
    *   *Correction*: What if a component touches multiple flares? The example doesn't show this. Usually, in these puzzles, it's one-to-one or the first one found. Or maybe the flares are distinct. Let's assume one flare per component or they don't conflict.
    *   Actually, looking at the description: "A flare touching a vessel lights up the whole connected hull in the fl

... [5895 chars truncated]
alt-12 electronics qwen3.5-122b: fig alone solves
"A charged capacitor touches one node of a circuit and every connected trace adopts its voltage color — then the capacitor is spent."
alt-13 mythology qwen3.5-122b: fail
"A demigod touches a stone idol and their divine essence flows through every crack, transforming the whole statue — then the demigod ascends, leaving no trace."
Fail (best cell_acc=0.67 at k=1)
Best Attempt
vs
Expected
Reasoning (11226 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A mythic landscape with stone idols and wandering demigods.
*   **Action:** A demigod adjacent to an idol imbues the entire connected statue with their essence color. The demigod ascends and vanishes. Demigods near no idol ascend anyway. Unblessed idols keep their stone color.
*   **Grid Details:**
    *   Background is the mortal plane.
    *   Blessed idols glow with divine color.
    *   Unblessed idols remain magenta.
    *   No demigods remain.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O
    ```
*   **Output:**
    ```
    O G G O O
    O O O O O
    O O O Y O
    O O Y Y Y
    O O O Y O
    ```
*   **Color Key:**
    *   `.` = black
    *   `B` = blue
    *   `R` = red
    *   `G` = green
    *   `Y` = yellow
    *   `X` = grey
    *   `M` = magenta
    *   `O` = orange
    *   `A` = azure
    *   `W` = maroon

*   **Interpretation of the Metaphor:**
    *   "Idols": These seem to be the `M` (magenta) cells. The description says "Unblessed idols remain magenta". In the output, some `M`s change color, some stay `M`. Wait, looking at the output, there are no `M`s left in the output of Example 1.
    *   Let's check the output of Example 1 again.
        Input `M`s are at: (0,1), (0,2), (2,3), (3,2), (3,3), (3,4), (4,3).
        Output at these positions:
        (0,1) -> G
        (0,2) -> G
        (2,3) -> Y
        (3,2) -> Y
        (3,3) -> Y
        (3,4) -> Y
        (4,3) -> Y
        Wait, looking closely at the output grid provided in the prompt:
        Row 0: O G G O O
        Row 1: O O O O O
        Row 2: O O O Y O
        Row 3: O O Y Y Y
        Row 4: O O O Y O
        There are no `M`s in the output.
        The description says "Unblessed idols remain magenta". This implies if an idol is not touched by a demigod, it stays `M`. But in Example 1, all `M`s changed color. This suggests all `M`s were "blessed".
    *   "Demigods": These seem to be the non-background, non-idol colors. In Example 1, the non-`O` (background?) and non-`M` (idol) colors are `G` (green) at (0,3) and `Y` (yellow) at (1,3).
    *   "Background": `O` (orange) seems to be the background/mortal plane.
    *   "Connected Statue": This implies connectivity. Usually 4-connectivity or 8-connectivity. Given the grid nature, 4-connectivity is standard unless specified.
    *   "Imbues the entire connected statue": This suggests that if a demigod is adjacent to an idol, the *connected component* of idols takes the demigod's color.
    *   "Demigod ascends and vanishes": The demigod cell itself changes. In the output, the `G` at (0,3) became `O`. The `Y` at (1,3) became `O`. So demigods turn into background color (`O`).
    *   "Demigods near no idol ascend anyway": If a demigod is not adjacent to an idol, it just vanishes (becomes background).
    *   "Unblessed idols keep their stone color": If an idol (`M`) is not adjacent to any demigod, it stays `M`.

    *   **Hypothesis:**
        1.  Identify Background color. In Example 1, `O` is dominant. Let's assume `O` is background.
        2.  Identify Idols. `M` (magenta).
        3.  Identify Demigods. Any color that is not Background (`O`) and not Idol (`M`). In Example 1: `G` and `Y`.
        4.  Identify Connected Components of Idols.
            *   Component 1: (0,1), (0,2). Connected horizontally.
            *   Component 2: (2,3), (3,2), (3,3), (3,4), (4,3). Let's check connectivity.
                (2,3) is adjacent to (3,3).
                (3,2) is adjacent to (3,3).
                (3,3) is adjacent to (3,4).
                (3,3) is adjacent to (4,3).
                So these form one large connected component of `M`s.
        5.  Check Adjacency to Demigods.
            *   Component 1 (`M`s at (0,1), (0,2)):
                *   Adjacent to `G` at (0,3)? Yes, (0,2) is adjacent to (0,3).
                *   So Component 1 takes color `G`.
                *   Demigod `G` at (0,3) vanishes (becomes `O`).
            *   Component 2 (`M`s at (2,3), (3,2), (3,3), (3,4), (4,3)):
                *   Adjacent to `Y` at (1,3)? Yes, (2,3) is adjacent to (1,3).
                *   So Component 2 takes color `Y`.
                *   Demigod `Y` at (1,3) vanishes (becomes `O`).
        6.  Result:
            *   Background `O` stays `O`.
            *   Demigods become `O`.
            *   Idols connected to a demigod take that demigod's color.
            *   Idols not connected to any demigod stay `M`.

    *   **Verification with Example 1:**
        *   Input `M`s:
            *   (0,1), (0,2) -> Connected. Adjacent to `G` at (0,3). Become `G`.
            *   (2,3), (3,2), (3,3), (3,4), (4,3) -> Connected. Adjacent to `Y` at (1,3). Become `Y`.
        *   Input Demigods:
         

... [6313 chars truncated]
alt-14 dance qwen3.5-122b: fail
"A soloist brushes against a formation and every dancer in the troupe mirrors the soloist's costume color — then the soloist takes a final bow and exits."
Fail (best cell_acc=0.67 at k=1)
Best Attempt
vs
Expected
Reasoning (11174 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A warm stage with dancer formations and lone soloists in vivid costumes."
*   **Action:** "A soloist touching a formation recolors the entire connected troupe to match. The soloist exits. Soloists near no formation simply leave. Unmatched formations keep their original costumes."
*   **Grid Details:** "Same stage. Background is the floor. Recolored formations wear the soloist's hue. Unchanged formations remain magenta. No soloists are present."

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O
    ```
    *   Colors present: O (Orange), M (Magenta), G (Green), Y (Yellow).
    *   Background seems to be 'O' (Orange) based on the "warm stage" description and the prevalence of 'O'. Let's verify.
    *   "Unchanged formations remain magenta." This implies 'M' is the default color of a formation if it doesn't get recolored.
    *   "Recolored formations wear the soloist's hue." This implies 'G' and 'Y' are soloists.
    *   "Soloist touching a formation recolors the entire connected troupe to match."
    *   "The soloist exits." This means the soloist cell itself becomes background or disappears.
    *   "Soloists near no formation simply leave."

    Let's look at the Input grid again:
    Row 0: O M M G O
    Row 1: O O O Y O
    Row 2: O O O M O
    Row 3: O O M M M
    Row 4: O O O M O

    Let's identify connected components of 'M' (Magenta).
    Component 1: (0,1), (0,2).
    Component 2: (2,3).
    Component 3: (3,2), (3,3), (3,4), (4,3).

    Let's identify 'G' (Green) and 'Y' (Yellow).
    'G' is at (0,3).
    'Y' is at (1,3).

    Let's look at the Output grid:
    Row 0: O G G O O
    Row 1: O O O O O
    Row 2: O O O Y O
    Row 3: O O Y Y Y
    Row 4: O O O Y O

    Wait, the output description says "Unchanged formations remain magenta."
    In the output, I see 'G' and 'Y' appearing where 'M' used to be.
    Specifically:
    Input (0,1)='M', (0,2)='M'. Output (0,1)='G', (0,2)='G'.
    Input (0,3)='G'. Output (0,3)='O'.
    Input (1,3)='Y'. Output (1,3)='O'.
    Input (2,3)='M'. Output (2,3)='Y'.
    Input (3,2)='M', (3,3)='M', (3,4)='M', (4,3)='M'. Output (3,2)='Y', (3,3)='Y', (3,4)='Y', (4,3)='Y'.

    Let's re-read the metaphor carefully.
    "A soloist touching a formation recolors the entire connected troupe to match."
    "The soloist exits." -> Soloist cell becomes background (O).
    "Unchanged formations keep their original costumes." -> Wait, the output description says "Unchanged formations remain magenta." But in the example output, there are NO magenta 'M's left. All 'M's became 'G' or 'Y'.
    Let's check the input again.
    Input M's:
    1. (0,1), (0,2). Adjacent to G at (0,3).
    2. (2,3). Adjacent to Y at (1,3).
    3. (3,2), (3,3), (3,4), (4,3). Adjacent to Y at (1,3)? No, (2,3) is M. (1,3) is Y. (2,3) is adjacent to (1,3). (3,3) is adjacent to (2,3). So the group at (2,3) and the group at (3,2-4) are connected via (2,3).
    Let's check connectivity of M's.
    (0,1)-(0,2) is a group.
    (2,3) is a single M.
    (3,2)-(3,3)-(3,4) and (4,3) form a group.
    Are (2,3) and (3,3) connected? Yes, vertically adjacent.
    So there are two main groups of M:
    Group A: (0,1), (0,2).
    Group B: (2,3), (3,2), (3,3), (3,4), (4,3).

    Soloists:
    G at (0,3).
    Y at (1,3).

    Interaction:
    G at (0,3) is adjacent to M at (0,2). So Group A gets recolored to G.
    Y at (1,3) is adjacent to M at (2,3). So Group B gets recolored to Y.
    The soloists themselves (G at 0,3 and Y at 1,3) become background (O).
    The M's that were recolored become the color of the soloist.
    The M's that were NOT recolored... wait, in the example, ALL M's were recolored.
    Is there an M that wasn't recolored?
    Input:
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O

    Let's check the Output again.
    O G G O O  <- (0,1),(0,2) became G. (0,3) became O.
    O O O O O  <- (1,3) became O.
    O O O Y O  <- (2,3) became Y.
    O O Y Y Y  <- (3,2),(3,3),(3,4) became Y.
    O O O Y O  <- (4,3) became Y.

    So, every M was connected to a soloist.
    What if an M is not connected to a soloist? The rule says "Unmatched formations keep their original costumes." But the "Grid details" section says "Unchanged formations remain magenta." This implies if an M is not touched by a soloist, it stays M.
    However, in the example, all M's were touched.
    Also, the background is 'O'.
    The soloists 'G' and 'Y' disappear (become 'O').

    **Hypothesis:**
    1.  Identify the background color. In the example, it's 'O'. In the test input, 'O' is also very prevalent. Let's assume 'O' is background.
    2.  Identify "Formations". These are connected components of 'M' (Magenta).
    3.  Identify "Soloists".

... [6225 chars truncated]
alt-15 geology qwen3.5-122b: fail
"A mineral vein touches a rock formation and its pigment seeps through every fissure, staining the entire mass — then the vein is depleted."
Fail (best cell_acc=0.27 at k=1)
Best Attempt
vs
Expected
Reasoning (10795 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Warm bedrock with rock formations and scattered mineral veins".
*   **Action:** "A mineral vein adjacent to a formation stains the whole connected mass in its pigment."
*   **Condition:** "The vein is exhausted." (Implies the vein color disappears or changes).
*   **Condition:** "Veins near no formation simply erode." (Implies isolated veins disappear/change).
*   **Condition:** "Unstained formations keep their original mineral color."
*   **Grid Details:**
    *   "Same bedrock." -> Background color remains constant.
    *   "Background is the warm substrate." -> Likely 'O' (Orange) based on the examples.
    *   "Stained formations display the vein's pigment." -> Formations take the color of adjacent veins.
    *   "Unstained formations remain magenta." -> Formations that don't touch a vein stay 'M' (Magenta).
    *   "No loose veins remain." -> Veins that don't stain a formation disappear (likely turn into background).

**2. Analyze the Training Example 1:**
Input:
O M M G O
O O O Y O
O O O M O
O O M M M
O O O M O

Output:
O G G O O
O O O O O
O O O Y O
O O Y Y Y
O O O Y O

*   **Colors:**
    *   O = Orange (Background/Bedrock)
    *   M = Magenta (Formations/Unstained)
    *   G = Green (Vein?)
    *   Y = Yellow (Vein?)
*   **Observations:**
    *   Input has a block of M's at (0,1), (0,2). Adjacent to G at (0,3).
    *   Input has a Y at (1,3). Adjacent to M's? No, (1,3) is Y. Below it is M at (2,3).
    *   Input has M's at (3,2), (3,3), (3,4). Adjacent to Y at (4,3)? No, (4,3) is M. Wait, let's look at coordinates.
    *   Let's map the grid (row, col):
        *   (0,1)=M, (0,2)=M. Neighbor (0,3)=G.
        *   (1,3)=Y. Neighbor (2,3)=M.
        *   (3,2)=M, (3,3)=M, (3,4)=M. Neighbor (4,3)=M. Wait, (4,3) is M. Where is the vein?
        *   Let's re-read the input grid carefully.
        Row 0: O M M G O
        Row 1: O O O Y O
        Row 2: O O O M O
        Row 3: O O M M M
        Row 4: O O O M O

    *   **Formations (M):**
        *   Group 1: (0,1), (0,2). Connected.
        *   Group 2: (2,3). Single.
        *   Group 3: (3,2), (3,3), (3,4), (4,3). Connected block.
    *   **Veins (Non-O, Non-M):**
        *   G at (0,3).
        *   Y at (1,3).
    *   **Background (O):** Everywhere else.

    *   **Transformation:**
        *   Group 1 (M at 0,1 & 0,2) is adjacent to G (0,3). In Output, these become G.
        *   Group 2 (M at 2,3) is adjacent to Y (1,3). In Output, this becomes Y.
        *   Group 3 (M at 3,2, 3,3, 3,4, 4,3). Is it adjacent to a vein?
            *   (3,2) neighbors: (2,2)=O, (3,1)=O, (4,2)=O, (3,3)=M.
            *   (3,3) neighbors: (2,3)=M, (3,2)=M, (4,3)=M, (3,4)=M.
            *   (3,4) neighbors: (2,4)=O, (3,3)=M, (4,4)=O, (3,5)=O.
            *   (4,3) neighbors: (3,3)=M, (4,2)=O, (4,4)=O, (5,3)=O.
            *   Wait, looking at the Output for Group 3:
                Row 3: O O Y Y Y
                Row 4: O O O Y O
            *   So Group 3 became Y. Why?
            *   Is it connected to Group 2?
            *   Group 2 is at (2,3). Group 3 includes (3,3). They are vertically adjacent.
            *   So Group 2 and Group 3 are actually one connected component of M's.
            *   Let's check connectivity of M's.
                *   (0,1)-(0,2) are connected.
                *   (2,3) is connected to (3,3).
                *   (3,3) is connected to (3,2), (3,4), (4,3).
                *   So (2,3) and the bottom block are one big M-component.
            *   This big M-component is adjacent to Y at (1,3).
            *   So the whole big M-component turns Y.
            *   The top M-component (0,1)-(0,2) is adjacent to G at (0,3). So it turns G.
            *   The veins G and Y disappear (turn to O).
            *   Wait, in the output:
                *   (0,3) was G, now O.
                *   (1,3) was Y, now O.
            *   So veins turn into background color (O) after staining.

    *   **Refined Rule:**
        1.  Identify connected components of "Formation" color (M).
        2.  Identify "Vein" colors (anything not Background O and not Formation M).
        3.  For each Formation component:
            *   Check if it is adjacent (orthogonally) to any Vein cell.
            *   If yes, the entire Formation component takes the color of the adjacent Vein.
            *   If multiple veins? (Not seen in example, assume one or priority). In Ex 1, top M touches G, bottom M touches Y. They are separate components.
            *   If no adjacent vein, the Formation component remains M (Unstained).
        4.  All Vein cells turn into Background color (O).
        5.  Background cells remain Background.

    *   **Wait, let's re-verify the "Unstained formations remain magenta" part.**
        *   In Ex 1, all M's were adjacent to a vein.
        * 

... [5940 chars truncated]
alt-2 cooking qwen3.5-122b: fail
"A pinch of saffron dropped beside a block of tofu saturates it entirely with color and flavor, while the spice itself vanishes into the broth."
Fail (best cell_acc=0.67 at k=2)
Best Attempt
vs
Expected
Reasoning (14151 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A cutting board with pale dough shapes and individual spice grains scattered about.
*   **Action:**
    *   "Spice grain resting against a dough shape infuses the entire connected piece with its hue." -> If a spice touches a dough shape, the whole connected component of that dough shape changes color to the spice color.
    *   "The grain dissolves." -> The spice grain itself disappears (becomes background or part of the dough?).
    *   "Spices that touch no dough wash away." -> Spices not touching any dough disappear.
    *   "Unseasoned dough keeps its original color." -> Dough not touched by spices remains its original color.
*   **Grid Details:**
    *   "Background is the bare surface." -> Likely a specific color (maybe black '.' or a specific background color). Looking at the examples, 'O' (orange) seems to be the "dough" or "pale" color, and other colors are spices. Wait, let's look at the examples to confirm roles.
    *   "Infused dough takes the spice color throughout." -> The connected component of the dough changes color.
    *   "Plain dough stays pale." -> Dough not touched stays 'O'.
    *   "No loose spices remain." -> Spices are removed from the grid after transfer.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        O M M G O
        O O O Y O
        O O O M O
        O O M M M
        O O O M O
        ```
    *   Output:
        ```
        O G G O O
        O O O O O
        O O O Y O
        O O Y Y Y
        O O O Y O
        ```
    *   **Observation:**
        *   'O' appears to be the "dough" (pale color).
        *   'M', 'G', 'Y' appear to be "spices".
        *   In the input, there is a large connected region of 'O's.
        *   Let's check connectivity. Usually, 4-connectivity (up, down, left, right) is standard for these puzzles unless specified otherwise.
        *   Let's trace the 'O's.
            *   (0,0) is O. (0,4) is O. (1,0)-(1,2) are O. (1,4) is O. (2,0)-(2,2) are O. (2,4) is O. (3,0)-(3,1) are O. (4,0)-(4,2) are O. (4,4) is O.
            *   Wait, the 'O's are not all connected.
            *   Let's look at the Output.
            *   Top row: `O G G O O`. Input was `O M M G O`.
                *   (0,0) O -> O.
                *   (0,1) M -> G.
                *   (0,2) M -> G.
                *   (0,3) G -> O.
                *   (0,4) O -> O.
            *   This looks like the 'M's and 'G' turned into 'G' or 'O'.
            *   Wait, the description says "Spice grain resting against a dough shape infuses the entire connected piece with its hue."
            *   This implies the *dough* changes color. The *spice* disappears.
            *   In the output, the cells that were spices (M, G, Y) seem to have become either the spice color (if they were part of the dough?) or the background?
            *   Let's re-read carefully: "Infused dough takes the spice color throughout." "The grain dissolves."
            *   This implies the spice cell itself becomes part of the dough or disappears.
            *   In Example 1 Output:
                *   (0,1) was M, became G.
                *   (0,2) was M, became G.
                *   (0,3) was G, became O.
                *   (1,3) was Y, became O.
                *   (2,3) was M, became Y.
                *   (3,2) was M, became Y.
                *   (3,3) was M, became Y.
                *   (3,4) was M, became Y.
                *   (4,3) was M, became Y.
            *   This is confusing. Let's look at the "Dough" vs "Spice" distinction again.
            *   Hypothesis 1: 'O' is the dough. Other colors are spices.
            *   If 'O' is dough, then in Input 1:
                *   There is a connected component of 'O's.
                *   Let's find the connected components of 'O'.
                *   Component 1: (0,0), (1,0), (1,1), (1,2), (2,0), (2,1), (2,2), (3,0), (3,1), (4,0), (4,1), (4,2).
                    *   This component touches:
                        *   (0,1) M
                        *   (0,2) M
                        *   (1,3) Y
                        *   (2,3) M
                        *   (3,2) M
                        *   (4,3) M
                    *   Wait, (0,1) is M. (0,2) is M. (1,3) is Y. (2,3) is M. (3,2) is M. (4,3) is M.
                    *   If this component gets infused, it should take *one* color. But in the output, some parts are G, some are Y, some are O.
                    *   Output for this component:
                        *   (0,0) O -> O
                        *   (1,0) O -> O
                        *   (1,1) O -> O
                        *   (1,2) O -> O
                        *   (2,0) O -> O
                        *   (2,1) O -> O
                        *   (2,2) O -> O


... [9256 chars truncated]
alt-3 music qwen3.5-122b: fail
"A tuning fork struck near a crystal glass makes the entire glass resonate at the fork's pitch, and in doing so, the fork goes silent."
Fail (best cell_acc=0.67 at k=1)
Best Attempt
vs
Expected
Reasoning (10898 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A silent concert hall with glass sculptures and scattered tuning forks.
*   **Action:** A tuning fork touching a sculpture makes the whole sculpture sing in the fork's key.
*   **Consequence:** The fork falls mute (disappears).
*   **Condition:** Forks near no sculpture simply fade (disappear).
*   **State:** Untouched sculptures hold their original hum (color).
*   **Grid Details:**
    *   Background is silence (likely a specific color, need to check examples).
    *   Resonating sculptures show the fork's color.
    *   Unreached sculptures stay magenta (M).
    *   All forks are gone.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O
    ```
*   **Output:**
    ```
    O G G O O
    O O O O O
    O O O Y O
    O O Y Y Y
    O O O Y O
    ```
*   **Observations:**
    *   Input colors: O (orange), M (magenta), G (green), Y (yellow).
    *   Output colors: O, G, Y. No M, no G, no Y in the input positions where they were? Wait.
    *   Let's look at the "Forks" and "Sculptures".
    *   Metaphor says: "Forks near no sculpture simply fade." "Resonating sculptures show the fork's color." "Unreached sculptures stay magenta."
    *   In the input, we see M (magenta). In the output, some M's become other colors, some stay M? No, looking at the output, there are no M's. Wait, let me check the output again.
    *   Output:
        Row 0: O G G O O
        Row 1: O O O O O
        Row 2: O O O Y O
        Row 3: O O Y Y Y
        Row 4: O O O Y O
    *   Input had M's at: (0,1), (0,2), (2,3), (3,2), (3,3), (3,4), (4,3).
    *   Output has:
        (0,1) -> G
        (0,2) -> G
        (2,3) -> Y
        (3,2) -> Y
        (3,3) -> Y
        (3,4) -> Y
        (4,3) -> Y
    *   It seems all M's changed color.
    *   Where did the new colors come from?
    *   Input had G at (0,3) and Y at (1,3).
    *   The M's at (0,1) and (0,2) became G. The G was at (0,3).
    *   The M's at (2,3), (3,2), (3,3), (3,4), (4,3) became Y. The Y was at (1,3).
    *   It looks like M represents "Sculptures" (unreached ones stay magenta, but here they changed, so they were reached).
    *   Other colors (G, Y) represent "Forks".
    *   O (Orange) seems to be the "Background" or "Silence".
    *   Rule Hypothesis:
        *   M = Sculpture.
        *   Non-M, Non-O = Fork (Source of color).
        *   O = Background/Silence.
        *   If a Fork (color C) is adjacent to a Sculpture (M), the Sculpture turns color C.
        *   The Fork itself disappears (turns into Background O? Or stays? In the output, the G at (0,3) became O. The Y at (1,3) became O).
        *   So Forks turn into Background (O).
        *   Sculptures (M) turn into the color of the adjacent Fork.
        *   What if a Sculpture is adjacent to multiple Forks? Or no Forks?
        *   In the example, the M's adjacent to G became G. The M's adjacent to Y became Y.
        *   Let's check adjacency.
        *   G is at (0,3). Neighbors: (0,2)=M, (0,4)=O, (1,3)=Y.
        *   M at (0,2) is adjacent to G. It became G.
        *   M at (0,1) is adjacent to M at (0,2). It became G. This implies propagation? Or just adjacency to the *original* fork?
        *   Let's look at the cluster of M's.
        *   Top cluster: (0,1), (0,2). Adjacent to G(0,3). Both became G.
        *   Bottom cluster: (2,3), (3,2), (3,3), (3,4), (4,3). Adjacent to Y(1,3).
        *   Y is at (1,3). Neighbors: (0,3)=G, (1,2)=O, (1,4)=O, (2,3)=M.
        *   M at (2,3) is adjacent to Y. It became Y.
        *   M at (3,3) is adjacent to (2,3). It became Y.
        *   M at (3,2) is adjacent to (3,3). It became Y.
        *   M at (3,4) is adjacent to (3,3). It became Y.
        *   M at (4,3) is adjacent to (3,3). It became Y.
        *   It seems like a flood fill or connected component logic.
        *   "A tuning fork touching a sculpture makes the whole sculpture sing in the fork's key."
        *   "Whole sculpture" might imply a connected group of M's acts as one sculpture?
        *   Or it implies that the color propagates through the M's.
        *   Let's check the connectivity.
        *   Top M's: (0,1)-(0,2). Connected to G(0,3).
        *   Bottom M's: (2,3) connected to Y(1,3). (3,3) connected to (2,3). (3,2), (3,4), (4,3) connected to (3,3). All these M's form a single connected component of M's.
        *   This component is adjacent to Y(1,3).
        *   So the rule seems to be: Identify connected components of M (Sculptures). If a component is adjacent to a Fork (non-M, non-O color), the entire component takes that Fork's color. The Fork itself turns into O (Background).
        *   What if a component is adjacent to multiple Forks? The example doesn't show this.
        *   What if a component is adjac

... [5928 chars truncated]
alt-4 sports qwen3.5-122b: fail
"A coach standing at the sideline taps a player, and suddenly the whole team dons that coach's jersey color — but the coach steps off the field."
Fail (best cell_acc=0.67 at k=1)
Best Attempt
vs
Expected
Reasoning (12047 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A playing field with clusters of uniformed players and individual coaches positioned around the edges.
*   **Action:**
    *   A coach adjacent to a team re-uniforms every connected player in the coach's color.
    *   Then the coach leaves.
    *   Coaches near no team simply exit.
    *   Uncoached teams keep their original kit.
*   **Grid Details:**
    *   Background is the pitch.
    *   Recolored teams wear the coach's hue.
    *   Uncoached teams stay in their original jerseys.
    *   No coaches remain on the field.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O
    ```
    *   Colors present: O (Orange), M (Magenta), G (Green), Y (Yellow).
    *   Let's identify "teams" and "coaches".
    *   The description says "clusters of uniformed players" and "individual coaches".
    *   Usually, in these puzzles, one color represents the background or a specific entity type.
    *   Looking at the input, 'O' (Orange) seems to be the most frequent color, possibly the background or the "pitch". However, the description says "Background is the pitch". Let's look at the output.
    *   **Output:**
        ```
        O G G O O
        O O O O O
        O O O Y O
        O O Y Y Y
        O O O Y O
        ```
    *   Comparing Input and Output:
        *   Input (0,1) is M, Output (0,1) is G.
        *   Input (0,2) is M, Output (0,2) is G.
        *   Input (1,3) is Y, Output (1,3) is Y.
        *   Input (2,3) is M, Output (2,3) is Y.
        *   Input (3,2) is M, Output (3,2) is Y.
        *   Input (3,3) is M, Output (3,3) is Y.
        *   Input (3,4) is M, Output (3,4) is Y.
        *   Input (4,3) is M, Output (4,3) is Y.
        *   Input (0,3) is G, Output (0,3) is O.
        *   Input (1,1) is O, Output (1,1) is O.
        *   Input (1,2) is O, Output (1,2) is O.
        *   Input (1,4) is O, Output (1,4) is O.
        *   Input (2,0) is O, Output (2,0) is O.
        *   Input (2,1) is O, Output (2,1) is O.
        *   Input (2,2) is O, Output (2,2) is O.
        *   Input (2,4) is O, Output (2,4) is O.
        *   Input (3,0) is O, Output (3,0) is O.
        *   Input (3,1) is O, Output (3,1) is O.
        *   Input (4,0) is O, Output (4,0) is O.
        *   Input (4,1) is O, Output (4,1) is O.
        *   Input (4,2) is O, Output (4,2) is O.
        *   Input (4,4) is O, Output (4,4) is O.
        *   Input (0,0) is O, Output (0,0) is O.
        *   Input (0,4) is O, Output (0,4) is O.

    *   Wait, let's look closer at the changes.
    *   Input has a cluster of M's at top left: (0,1), (0,2).
    *   Input has a G at (0,3).
    *   Input has a Y at (1,3).
    *   Input has a cluster of M's at bottom right: (2,3), (3,2), (3,3), (3,4), (4,3).
    *   The rest are O's.
    *   In the output:
        *   The M's at (0,1), (0,2) became G.
        *   The G at (0,3) became O.
        *   The M's at bottom right became Y.
        *   The Y at (1,3) stayed Y.
        *   All O's stayed O.

    *   Hypothesis:
        *   'O' is the background/pitch.
        *   Other colors are "teams" or "coaches".
        *   The description says "clusters of uniformed players" (Teams) and "individual coaches".
        *   In the input, we have clusters of M (Magenta). We have single pixels of G (Green) and Y (Yellow).
        *   The single pixels (G, Y) seem to act as "coaches".
        *   The clusters (M) seem to act as "teams".
        *   Rule: A coach (single pixel of a color different from the background and different from the team color?) adjacent to a team (cluster of a specific color) changes the team's color to the coach's color.
        *   Then the coach leaves (becomes background color 'O').
        *   Let's check adjacency.
        *   Top Left:
            *   Team: M at (0,1), (0,2).
            *   Coach: G at (0,3).
            *   Are they adjacent? (0,2) is M, (0,3) is G. Yes, horizontally adjacent.
            *   Result: M's become G. G becomes O (leaves).
            *   Output matches: (0,1)->G, (0,2)->G, (0,3)->O.
        *   Bottom Right:
            *   Team: M at (2,3), (3,2), (3,3), (3,4), (4,3).
            *   Coach: Y at (1,3).
            *   Are they adjacent? (1,3) is Y. (2,3) is M. Yes, vertically adjacent.
            *   Result: M's become Y. Y becomes O (leaves).
            *   Output matches: (2,3)->Y, (3,2)->Y, (3,3)->Y, (3,4)->Y, (4,3)->Y, (1,3)->O.
        *   Wait, in the output provided in the example:
            *   (1,3) is Y.
            *   Let's re-read the example output carefully.
            *   Input:
                O M M G O
                O O O Y O
                O O O M O
                O O M M M
                O O O M O
            *   Output:
                O G G O O
  

... [7119 chars truncated]
alt-5 weather qwen3.5-122b: fail
"A single lightning bolt strikes one edge of a cloud and electrifies the entire formation with its color, while the bolt itself flickers out."
Fail (best cell_acc=0.67 at k=1)
Best Attempt
vs
Expected
Reasoning (10529 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A warm sky with cloud formations and scattered sparks of colored lightning."
*   **Action:** "A bolt touching a cloud charges the whole connected cloud mass with the bolt's color. The bolt vanishes. Bolts that strike empty sky dissipate."
*   **Result:** "Uncharged clouds hold their original shade."
*   **Grid Details:** "Background is orange warmth. Charged clouds glow in the bolt's hue. Uncharged clouds remain magenta. All lightning is gone."

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O
    ```
    *   Colors present: O (Orange), M (Magenta), G (Green), Y (Yellow).
    *   Background seems to be O (Orange).
    *   "Clouds" seem to be M (Magenta).
    *   "Bolts" seem to be G (Green) and Y (Yellow).
*   **Output:**
    ```
    O G G O O
    O O O O O
    O O O Y O
    O O Y Y Y
    O O O Y O
    ```
    *   Let's trace the changes.
    *   Input (0,1) is M. Input (0,2) is M. Input (0,3) is G.
    *   In Output, (0,1) is G, (0,2) is G. The G at (0,3) is gone (became O).
    *   Input (1,3) is Y.
    *   In Output, (1,3) is O.
    *   Input (2,3) is M. Input (3,2) is M, (3,3) is M, (3,4) is M. Input (4,3) is M.
    *   In Output, (2,3) is Y. (3,2) is Y, (3,3) is Y, (3,4) is Y. (4,3) is Y.
    *   Wait, let's look closer at connectivity.
    *   **Magenta (M) regions:**
        *   Region 1: (0,1), (0,2). Connected to G at (0,3)? Yes, (0,2) is adjacent to (0,3).
        *   Region 2: (2,3), (3,2), (3,3), (3,4), (4,3). Connected to Y at (1,3)? Yes, (2,3) is adjacent to (1,3).
    *   **Transformation:**
        *   The G at (0,3) touches the M region {(0,1), (0,2)}. The M region turns G. The G itself disappears (turns to background O).
        *   The Y at (1,3) touches the M region {(2,3), (3,2), (3,3), (3,4), (4,3)}. The M region turns Y. The Y itself disappears (turns to background O).
        *   Wait, look at Output (0,0) is O. Input (0,0) is O.
        *   Look at Output (0,3) is O. Input (0,3) is G. So the "bolt" color disappears and becomes background.
        *   Look at Output (1,3) is O. Input (1,3) is Y. So the "bolt" color disappears and becomes background.
        *   Look at Output (0,1), (0,2) became G.
        *   Look at Output (2,3), (3,2), (3,3), (3,4), (4,3) became Y.
    *   **Hypothesis:**
        *   Background = Orange (O).
        *   Clouds = Magenta (M).
        *   Bolts = Non-Orange, Non-Magenta colors (G, Y, etc.).
        *   Rule: If a Bolt color is adjacent (orthogonally?) to a Cloud (M), the entire connected component of Clouds (M) connected to that Bolt takes the Bolt's color. The Bolt itself turns into Background (O).
        *   What if a Bolt is not adjacent to any Cloud? "Bolts that strike empty sky dissipate." -> Bolt turns to Background (O).
        *   What if a Cloud is not adjacent to any Bolt? "Uncharged clouds hold their original shade." -> Cloud remains M.
        *   Let's check the example again.
        *   Are there any M's that didn't change?
        *   Input M's: (0,1), (0,2), (2,3), (3,2), (3,3), (3,4), (4,3).
        *   All M's changed.
        *   Are there any Bolts that didn't change?
        *   Input Bolts: G at (0,3), Y at (1,3).
        *   Both changed to O.
        *   Are there any M's that were not connected to a Bolt?
        *   In this example, all M's were connected to a Bolt.
        *   Let's check connectivity.
        *   (0,1) M is adjacent to (0,2) M. (0,2) M is adjacent to (0,3) G. So the group {(0,1), (0,2)} is connected to G.
        *   (2,3) M is adjacent to (1,3) Y. (2,3) M is adjacent to (3,3) M. (3,3) M is adjacent to (3,2) M, (3,4) M, (4,3) M. So the group {(2,3), (3,2), (3,3), (3,4), (4,3)} is connected to Y.
        *   So the rule holds: Find connected components of M. If a component is adjacent to a non-O, non-M cell (Bolt), change the whole component to the Bolt's color. Change the Bolt cell to O. If a Bolt is not adjacent to any M, it becomes O. If an M component is not adjacent to any Bolt, it stays M.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Background:** Orange (O). Represents "empty sky" or "warmth".
    *   **Clouds:** Magenta (M). Represents "cloud formations".
    *   **Bolts:** Any color other than O or M (e.g., G, Y, B, R, etc.). Represents "colored lightning".
    *   **Grid:** The canvas.

2.  **AFFORDANCES:**
    *   **Clouds (M):** Can be "charged". They form connected regions. They can change color.
    *   **Bolts:** Can "touch" clouds. They transfer their color. They disappear (become O) after touching.
    *   **Background (O):** Passive. Fills the space where Bolts disappear.

3.  **TRANSFORMATION RULE:**
    *   Identify all connected components of Magenta (M) cells (using 4-connectivity).
    *   Identify all "Bolt" cel

... [5571 chars truncated]
alt-6 architecture qwen3.5-122b: fail
"A mason places a colored keystone beside an arch, and every brick in the connected structure adopts that stone's glaze — then the keystone crumbles to dust."
Fail (best cell_acc=0.67 at k=1)
Best Attempt
vs
Expected
Reasoning (11024 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** Construction site with brick structures and scattered colored keystones.
*   **Action:**
    *   A keystone adjacent to a structure glazes the entire connected building in the keystone's color.
    *   The keystone dissolves (disappears).
    *   Keystones beside nothing crumble away (disappear).
    *   Unglazed structures keep their raw brick.
*   **Grid Details:**
    *   Background is bare ground.
    *   Glazed structures show keystone color throughout.
    *   Unglazed structures remain magenta.
    *   No keystones remain.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O
    ```
    *   Colors present: O (orange), M (magenta), G (green), Y (yellow).
    *   Background seems to be O (orange).
    *   Structures seem to be M (magenta).
    *   Keystones seem to be G (green) and Y (yellow).
*   **Output:**
    ```
    O G G O O
    O O O O O
    O O O Y O
    O O Y Y Y
    O O O Y O
    ```
    *   Let's trace the changes.
    *   Input (0,1) is M. Input (0,2) is M. Input (0,3) is G.
    *   Output (0,1) is G. Output (0,2) is G. Output (0,3) is O.
    *   Wait, the description says "Unglazed structures remain magenta". In the output, the M's at (0,1) and (0,2) became G. The G at (0,3) became O (background?).
    *   Input (1,3) is Y. Output (1,3) is O.
    *   Input (2,3) is M. Output (2,3) is Y.
    *   Input (3,2) is M. Output (3,2) is Y.
    *   Input (3,3) is M. Output (3,3) is Y.
    *   Input (3,4) is M. Output (3,4) is Y.
    *   Input (4,3) is M. Output (4,3) is Y.
    *   Input (4,4) is M. Output (4,4) is Y.
    *   Wait, let's look closer at the "structure" definition.
    *   In the input, M forms a connected component?
        *   (0,1), (0,2) are connected.
        *   (2,3) is isolated from top M's? No, (1,3) is Y. (2,3) is M. (3,2), (3,3), (3,4) are M. (4,3) is M.
        *   Let's check connectivity of M's.
        *   Group 1: (0,1), (0,2). Adjacent to G at (0,3).
        *   Group 2: (2,3), (3,2), (3,3), (3,4), (4,3).
            *   (2,3) is adjacent to Y at (1,3).
            *   (3,2), (3,3), (3,4) are adjacent to each other.
            *   (4,3) is adjacent to (3,3).
            *   So Group 2 is a connected component of M's.
            *   Is it adjacent to Y? Yes, (2,3) touches (1,3) which is Y.
    *   What happens to the keystones (G and Y)?
        *   G at (0,3) disappears (becomes O).
        *   Y at (1,3) disappears (becomes O).
    *   What happens to the structures (M)?
        *   Group 1 (0,1), (0,2) becomes G.
        *   Group 2 (2,3), (3,2), (3,3), (3,4), (4,3) becomes Y.
    *   What about the background O? It stays O.
    *   Wait, the description says "Unglazed structures remain magenta". In the output, there are no M's left. This implies all structures were glazed.
    *   Wait, look at the output again.
        *   Row 0: O G G O O. (0,1) and (0,2) became G. (0,3) became O.
        *   Row 1: O O O O O. (1,3) became O.
        *   Row 2: O O O Y O. (2,3) became Y.
        *   Row 3: O O Y Y Y. (3,2), (3,3), (3,4) became Y.
        *   Row 4: O O O Y O. (4,3) became Y.
    *   So, M's connected to G became G. M's connected to Y became Y.
    *   The keystones themselves (G, Y) turned into background (O).
    *   The background (O) stayed O.
    *   Are there any M's that didn't change? No.
    *   Are there any keystones that didn't change? No.
    *   Wait, the description says "Keystones beside nothing crumble away". In this example, G is beside M (structure). Y is beside M (structure). So they glaze.
    *   What defines "Structure"? In the input, M is the only color besides O, G, Y. M is described as "raw brick" in the "Grid details" section ("Unglazed structures remain magenta"). So M = Structure.
    *   What defines "Keystone"? G and Y are the colors that disappear and cause coloring. So G, Y = Keystone.
    *   What defines "Background"? O = Background.
    *   Rule Hypothesis:
        1.  Identify connected components of "Structure" pixels (M).
        2.  Identify "Keystone" pixels (colors other than Background and Structure).
        3.  If a Structure component is adjacent (orthogonally?) to a Keystone of color C, the entire Structure component changes to color C.
        4.  The Keystone pixel itself changes to Background color.
        5.  If a Structure component is not adjacent to any Keystone, it remains Structure color (M).
        6.  If a Keystone is not adjacent to any Structure, it changes to Background color.
        7.  Background pixels remain Background.

    *   Let's check the adjacency.
        *   G at (0,3) is adjacent to M at (0,2). So M component {(0,1), (0,2)} becomes G. G becomes O.
        *   Y at (1,3) is adjacent to M at (2,3). So M component {(2,3), (3,2), (3,3), (3,4

... [6048 chars truncated]
alt-7 warfare qwen3.5-122b: fig alone solves
"A spy infiltrates a fortress through a single gate and raises their banner over every tower — then vanishes into legend."
alt-8 theater qwen3.5-122b: fail
"A spotlight operator touches a prop and the entire set piece floods with that light's color, while the operator slips backstage into darkness."
Fail (best cell_acc=0.67 at k=1)
Best Attempt
vs
Expected
Reasoning (10220 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A dark stage with set pieces and individual spotlight operators carrying colored gels.
*   **Action:** An operator adjacent to a set piece bathes the whole connected prop in their gel's color. The operator exits. Operators near no set piece leave anyway. Unlit set pieces keep their original look.
*   **Grid Details:**
    *   Background is dark boards (likely a specific color, maybe black or grey, but let's check the examples).
    *   Lit set pieces glow in the operator's color.
    *   Unlit pieces stay magenta.
    *   No operators remain visible.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O
    ```
*   **Output:**
    ```
    O G G O O
    O O O O O
    O O O Y O
    O O Y Y Y
    O O O Y O
    ```
*   **Observations:**
    *   Colors present in Input: O (Orange), M (Magenta), G (Green), Y (Yellow).
    *   Colors present in Output: O (Orange), G (Green), Y (Yellow). M (Magenta) is gone.
    *   The background seems to be 'O' (Orange). In the metaphor, "Background is the dark boards". Wait, usually background is black or grey. Here 'O' is dominant. Let's look at the "Unlit pieces stay magenta" part. In the input, there are 'M's. In the output, 'M's are gone.
    *   Let's re-read the metaphor carefully. "Unlit set pieces keep their original look." "Unlit pieces stay magenta." This implies 'M' represents the unlit set pieces.
    *   "Operators adjacent to a set piece bathes the whole connected prop in their gel's color."
    *   "Operators near no set piece leave anyway."
    *   "No operators remain visible."
    *   So, 'M' is the set piece. Other colors (G, Y) are operators?
    *   Let's check the positions.
    *   Input Row 0: `O M M G O`. There is a 'G' at (0,3). It is adjacent to 'M' at (0,2).
    *   Input Row 1: `O O O Y O`. There is a 'Y' at (1,3). It is adjacent to 'M' at (0,2) (diagonal? usually adjacency is 4-way) or 'M' at (2,3)? No, (2,3) is 'M'. Wait, let's look at the grid structure.
    *   Let's assume 4-way adjacency (Up, Down, Left, Right).
    *   Input Grid:
        (0,0)O (0,1)M (0,2)M (0,3)G (0,4)O
        (1,0)O (1,1)O (1,2)O (1,3)Y (1,4)O
        (2,0)O (2,1)O (2,2)O (2,3)M (2,4)O
        (3,0)O (3,1)O (3,2)M (3,3)M (3,4)M
        (4,0)O (4,1)O (4,2)O (4,3)M (4,4)O
    *   Output Grid:
        (0,0)O (0,1)G (0,2)G (0,3)O (0,4)O
        (1,0)O (1,1)O (1,2)O (1,3)O (1,4)O
        (2,0)O (2,1)O (2,2)O (2,3)Y (2,4)O
        (3,0)O (3,1)O (3,2)Y (3,3)Y (3,4)Y
        (4,0)O (4,1)O (4,2)O (4,3)Y (4,4)O
    *   Changes:
        *   The 'G' at (0,3) disappeared. The 'M's at (0,1) and (0,2) turned into 'G'.
        *   The 'Y' at (1,3) disappeared. The 'M's at (2,3), (3,2), (3,3), (3,4), (4,3) turned into 'Y'.
        *   Wait, let's trace the connected components of 'M'.
        *   Component 1: (0,1), (0,2). Are they connected to others? (0,2) is adjacent to (1,2) which is 'O'. (0,1) adjacent to (1,1) 'O'. So this is an isolated group of 'M's.
        *   Component 2: (2,3), (3,2), (3,3), (3,4), (4,3).
            *   (2,3) adj (3,3).
            *   (3,2) adj (3,3).
            *   (3,3) adj (3,4), (4,3).
            *   So these form a connected shape.
        *   Operators:
            *   'G' at (0,3). Adjacent to 'M' at (0,2). This operator is next to Component 1.
            *   'Y' at (1,3). Adjacent to 'M' at (2,3). This operator is next to Component 2.
        *   Transformation:
            *   Component 1 (M's at 0,1 and 0,2) gets colored by the adjacent operator 'G'. The operator 'G' disappears (becomes background 'O'?).
            *   Component 2 (M's at 2,3, 3,2, 3,3, 3,4, 4,3) gets colored by the adjacent operator 'Y'. The operator 'Y' disappears.
            *   Background 'O' remains 'O'.
    *   Hypothesis:
        *   'M' represents "Set Pieces" (unlit).
        *   Other non-background colors (G, Y, etc.) represent "Operators".
        *   Background is 'O' (Orange).
        *   Rule: Find connected components of 'M'. If an 'M' component is adjacent to an Operator cell, change all 'M's in that component to the Operator's color. Remove the Operator cell (turn it into Background). If an 'M' component is not adjacent to any Operator, it stays 'M' (based on "Unlit set pieces keep their original look" / "Unlit pieces stay magenta").
        *   Wait, the metaphor says "Unlit pieces stay magenta". In the output, there are no 'M's. This implies all 'M' components in the example were lit.
        *   Also, "Operators near no set piece leave anyway." This means if an operator is not adjacent to any 'M', it just disappears (becomes background).
        *   "No operators remain visible." All operator cells become background.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    Y O M O O O X
    M M M O O 

... [5352 chars truncated]
alt-9 gardening qwen3.5-122b: fail
"A single bee dusted with pollen lands on one petal and the entire flower blooms in that pollen's color — then the bee flies away, never to return."
Fail (best cell_acc=0.67 at k=1)
Best Attempt
vs
Expected
Reasoning (11489 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A garden bed with flower clusters and individual pollen-carrying bees.
*   **Action:** A bee touching a flower transforms the whole connected bloom to match its pollen color. The bee departs.
*   **Condition:** Bees that find no flower simply drift off. Unpollinated flowers keep their original hue.
*   **Grid Details:**
    *   Background is soil.
    *   Pollinated flowers show the bee's pollen color.
    *   Unpollinated flowers remain magenta.
    *   All bees are gone.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    O M M G O
    O O O Y O
    O O O M O
    O O M M M
    O O O M O
    ```
    *   Colors present: O (Orange), M (Magenta), G (Green), Y (Yellow).
    *   Metaphor mapping:
        *   "Flower clusters": Likely the connected components of non-background colors.
        *   "Bees": Likely specific colored pixels that act as agents.
        *   "Soil": Background color.
        *   "Pollen color": The color of the bee.
        *   "Unpollinated flowers remain magenta": This suggests M is the default flower color.
        *   "Bee touching a flower": Adjacency.
        *   "Transforms the whole connected bloom": Connected component flood fill.
        *   "Bee departs": The bee pixel itself changes or disappears.
        *   "Bees that find no flower simply drift off": Bees not adjacent to flowers disappear/change.

    *   Let's look at the Input vs Output for Example 1.
    *   Input:
        Row 0: O M M G O
        Row 1: O O O Y O
        Row 2: O O O M O
        Row 3: O O M M M
        Row 4: O O O M O
    *   Output:
        Row 0: O G G O O
        Row 1: O O O O O
        Row 2: O O O Y O
        Row 3: O O Y Y Y
        Row 4: O O O Y O

    *   **Hypothesis 1: Background is Orange (O).**
        *   In the input, O is very frequent. In the output, O is still very frequent.
        *   If O is soil, then M, G, Y are flowers/bees.
        *   Let's check the colors.
        *   Input has M (Magenta), G (Green), Y (Yellow).
        *   Output has G, Y. M is gone (replaced by G or Y or O).
        *   Wait, the description says "Unpollinated flowers remain magenta". In the output, there are no M's.
        *   Let's re-read carefully: "Unpollinated flowers keep their original hue." "Unpollinated flowers remain magenta." This implies M is the color of the flower itself.
        *   So, M = Flower.
        *   What are G and Y? They are likely the "Bees".
        *   What is O? "Background is soil". So O = Soil.
        *   Let's verify this mapping.
        *   Input:
            (0,1) M, (0,2) M. (0,3) G.
            (1,3) Y.
            (2,3) M.
            (3,2) M, (3,3) M, (3,4) M.
            (4,3) M.
        *   Output:
            (0,1) G, (0,2) G. (0,3) O. (G bee turned into soil? Or G bee colored the M's?)
            (1,3) O. (Y bee turned into soil?)
            (2,3) Y.
            (3,2) Y, (3,3) Y, (3,4) Y.
            (4,3) Y.

    *   **Refined Hypothesis:**
        *   **O (Orange)** = Soil (Background).
        *   **M (Magenta)** = Flower (Target).
        *   **G (Green), Y (Yellow)** = Bees (Agents).
        *   **Rule:**
            1.  Identify connected components of Flowers (M).
            2.  Identify Bees (G, Y).
            3.  If a Bee is adjacent to a Flower component, that entire Flower component changes color to the Bee's color.
            4.  The Bee itself disappears (becomes Soil/O).
            5.  If a Bee is not adjacent to any Flower, it disappears (becomes Soil/O).
            6.  If a Flower component is not touched by any Bee, it remains Magenta (M).
            7.  Wait, in the output of Example 1, there are no M's left.
                *   Input M's:
                    *   Cluster 1: (0,1), (0,2). Adjacent to G at (0,3).
                    *   Cluster 2: (2,3). Adjacent to Y at (1,3) and M at (3,3)? No, (2,3) is M. (1,3) is Y. (3,3) is M.
                    *   Cluster 3: (3,2), (3,3), (3,4), (4,3).
                *   Let's check connectivity of M's.
                    *   (0,1) connects to (0,2).
                    *   (2,3) connects to (3,3).
                    *   (3,3) connects to (3,2), (3,4), (4,3).
                    *   So (2,3), (3,2), (3,3), (3,4), (4,3) form one large connected component of M's.
                    *   (0,1), (0,2) form another component.
                *   Bees:
                    *   G at (0,3). Adjacent to M at (0,2).
                    *   Y at (1,3). Adjacent to M at (2,3).
                *   Transformation:
                    *   Component 1 (M at 0,1; 0,2) is touched by G. Becomes G.
                    *   Component 2 (M at 2,3; 3,2; 3,3; 3,4; 4,3) is touched by Y. Becomes Y.
                    *   Bees G and Y become Soil (O).
                *   Output Check:
                    *   (0,1) G, (0,2) G. (0,

... [6585 chars truncated]

Task 731: bbb1b8b6

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Ex5 In
Ex5 Out
Ex6 In
Ex6 Out
Ex7 In
Ex7 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A lock only turns when the right key fits perfectly into its grooves. MARC valid 1
alt-1 biology A cell membrane only absorbs molecules whose shape perfectly matches its recepto ... [52 chars truncated] MARC valid 1
alt-10 astronomy An eclipse is total only when the shadow perfectly covers every exposed surface ... [56 chars truncated] fail
alt-11 ocean/sailing Cargo loads into a hull only when every crate fits a hold and every hold gets a ... [59 chars truncated] MARC valid 2
alt-12 electronics A circuit board powers on only when every socket receives a component and no com ... [63 chars truncated] fig alone solves
alt-13 mythology A cursed mask lifts its enchantment only when every rune carved into it is match ... [70 chars truncated] MARC valid 7
alt-14 dance A partner dance is complete only when every open hand finds a matching grip R ... [62 chars truncated] MARC valid 6
alt-15 geology Magma fills a cavern system only when every chamber has a lava channel feeding i ... [84 chars truncated] MARC valid 5
alt-2 cooking A pastry chef fills a mold only when the batter volume is the exact shape of the ... [64 chars truncated] fig alone solves
alt-3 music A melody only harmonizes with a silence pattern when every note lands exactly in ... [75 chars truncated] fig alone solves
alt-4 sports A defensive formation only breaks when attackers fill every single gap simultane ... [67 chars truncated] MARC valid 2
alt-5 weather Rain saturates parched earth only when every raindrop finds dry ground — i ... [74 chars truncated] MARC valid 1
alt-6 architecture Stained glass is installed only when every pane matches every empty window frame ... [62 chars truncated] fig alone solves
alt-7 warfare A siege engine breaches a fortress only when every battering ram targets a weak ... [72 chars truncated] fail
alt-8 theater Understudies take the stage only when there is exactly one understudy for every ... [84 chars truncated] fig alone solves
alt-9 gardening Seeds take root only when every seed finds a plot of tilled soil and no soil is ... [54 chars truncated] fail
original qwen3.5-122b: k=1
"A lock only turns when the right key fits perfectly into its grooves."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (12323 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A grey wall divides two rooms.
*   **Left Room:** A blue vault door with gaps (empty keyholes).
*   **Right Room:** A colored key floating in darkness.
*   **Action:** Slide the key into the lock.
*   **Condition:** If every tooth fits perfectly into every keyhole (no extra teeth, no empty holes), the key merges with the vault door.
*   **Result:**
    *   Match: The door is transformed (blue + key color).
    *   Mismatch: The vault stays sealed (unchanged).
*   **Grid Details:**
    *   Grey wall (`X`) is in the center.
    *   Vault door is blue (`B`) with dark gaps (`.`).
    *   Key is a single color (e.g., `M`, `R`, etc.).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    B B B B X . . . .
    B . . B X . M M .
    B . . B X . M M .
    B B B B X . . . .
    ```
    *   Left side (Lock): 4x4 grid.
        *   Row 0: `B B B B`
        *   Row 1: `B . . B`
        *   Row 2: `B . . B`
        *   Row 3: `B B B B`
        *   This looks like a frame of `B` with a 2x2 hole of `.` in the middle.
    *   Separator: Column 4 is `X` (grey wall).
    *   Right side (Key): 4x4 grid.
        *   Row 0: `. . . .`
        *   Row 1: `. M M .`
        *   Row 2: `. M M .`
        *   Row 3: `. . . .`
        *   This looks like a 2x2 block of `M` (magenta) surrounded by `.`.
*   **Output:**
    ```
    B B B B
    B M M B
    B M M B
    B B B B
    ```
    *   The output is just the left side (the lock), but the `.` gaps are filled with the key color `M`.
    *   The separator `X` and the right side are gone.
    *   The transformation happened because the shape of the key (`M` block) matched the shape of the gaps (`.` block) in the lock.
    *   Lock gaps: Rows 1-2, Cols 1-2 (relative to left grid).
    *   Key shape: Rows 1-2, Cols 1-2 (relative to right grid).
    *   They match perfectly.

**3. Analyze the Test Input:**
*   **Input:**
    ```
    B B B B X R . . .
    . B B . X R R R R
    . B B . X R . . .
    . . . . X . . . .
    ```
*   **Dimensions:** 4 rows, 9 columns.
*   **Separator:** Column 4 is `X`.
*   **Left Side (Lock):** Columns 0-3 (4x4).
    *   Row 0: `B B B B`
    *   Row 1: `. B B .`
    *   Row 2: `. B B .`
    *   Row 3: `. . . .`
    *   Let's identify the "gaps" (`.`) inside the blue structure.
    *   Row 0: All `B`.
    *   Row 1: `.` at col 0, `B` at 1, `B` at 2, `.` at 3.
    *   Row 2: `.` at col 0, `B` at 1, `B` at 2, `.` at 3.
    *   Row 3: All `.`.
    *   Wait, the metaphor says "blue vault door has gaps cut into it". Usually, the `B` forms the structure and `.` forms the holes.
    *   In Example 1:
        *   Lock: `B B B B`, `B . . B`, `B . . B`, `B B B B`.
        *   Holes were the 2x2 `.` in the center.
        *   Key was 2x2 `M` in the center.
        *   Match -> Fill holes with `M`.
    *   In Test Input:
        *   Lock:
            `B B B B`
            `. B B .`
            `. B B .`
            `. . . .`
        *   This looks less like a "door with gaps" and more like a specific shape.
        *   Let's look at the "Key" side (Right side, Cols 5-8).
        *   Right Side:
            Row 0: `R . . .`
            Row 1: `R R R R`
            Row 2: `R . . .`
            Row 3: `. . . .`
        *   Key Color: `R` (Red).
        *   Key Shape:
            Row 0: `R` at col 0 (relative).
            Row 1: `R R R R` (all 4).
            Row 2: `R` at col 0.
            Row 3: Empty.
            Wait, let's look closer at the input grid provided in the prompt.
            Input:
            `B B B B X R . . .`
            `. B B . X R R R R`
            `. B B . X R . . .`
            `. . . . X . . . .`

            Left Grid (Lock):
            R0: `B B B B`
            R1: `. B B .`
            R2: `. B B .`
            R3: `. . . .`

            Right Grid (Key):
            R0: `R . . .`
            R1: `R R R R`
            R2: `R . . .`
            R3: `. . . .`

*   **Conceptual Digestion:**
    1.  **CAST:**
        *   `X`: Separator/Wall.
        *   Left Subgrid: The Lock. Composed of `B` (structure) and `.` (gaps).
        *   Right Subgrid: The Key. Composed of a specific color (e.g., `R`) and `.` (background).
    2.  **AFFORDANCES:**
        *   The Lock has specific positions marked as `.` (gaps).
        *   The Key has specific positions marked as the Key Color (teeth).
        *   The Key can be "slid" into the Lock. This implies a spatial correspondence. Since the grids are split by a wall, we compare the pattern of `.` in the Lock to the pattern of the Key Color in the Key.
        *   Usually, in these puzzles, the dimensions of the subgrids are the same. Here both are 4x4.
        *   The "fit" condition: The set of coordinates where the Lock has `.` must exactly match the set of coordinates where the Key has the Key Color.
    3.  **TRANSFORMATION 

... [7347 chars truncated]
alt-1 biology qwen3.5-122b: k=1
"A cell membrane only absorbs molecules whose shape perfectly matches its receptor sites. Mismatched molecules bounce off harmlessly."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (12187 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A blue tissue sample with empty receptor cavities sits beside a colored molecular cluster, separated by a grey membrane wall.
*   **Action:**
    *   Left 4x4 region = Tissue. Black cells (`.`) = Receptor cavities.
    *   Right 4x4 region = Molecular cluster.
    *   Middle column = Grey membrane (`X`).
    *   Condition: If *every* colored molecule aligns precisely with *every* cavity in the tissue, the molecules bind and fill the receptors.
    *   Condition: If even one molecule has no matching cavity or one cavity has no molecule, the tissue rejects the cluster entirely.
    *   Output: The 4x4 tissue, either filled (with the molecules) or unchanged.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    B B B B X . . . .
    B . . B X . M M .
    B . . B X . M M .
    B B B B X . . . .
    ```
    *   Left 4x4 (Tissue):
        ```
        B B B B
        B . . B
        B . . B
        B B B B
        ```
        Black cells (`.`) are at (1,1), (1,2), (2,1), (2,2) (0-indexed). There are 4 cavities.
    *   Right 4x4 (Cluster):
        ```
        . . . .
        . M M .
        . M M .
        . . . .
        ```
        Colored cells are `M` (magenta). There are 4 `M` cells.
    *   Membrane: Column 4 is `X`.
*   **Output:**
    ```
    B B B B
    B M M B
    B M M B
    B B B B
    ```
    *   The tissue is filled. The black cavities (`.`) in the left grid are replaced by the color of the molecules (`M`) from the right grid.
    *   The condition "every colored molecule aligns precisely with every cavity" seems to imply a count match or a shape match. Here, there are 4 cavities and 4 molecules. The output shows the cavities filled with the molecule color.

**3. Analyze the Test Input:**
*   **Input:**
    ```
    B B B B X R . . .
    . B B . X R R R R
    . B B . X R . . .
    . . . . X . . . .
    ```
    *   Left 4x4 (Tissue):
        ```
        B B B B
        . B B .
        . B B .
        . . . .
        ```
        Black cells (`.`) are at:
        Row 1: Col 0, Col 3
        Row 2: Col 0, Col 3
        Row 3: Col 0, Col 1, Col 2, Col 3
        Total cavities = 2 + 2 + 4 = 8 cavities.
    *   Right 4x4 (Cluster):
        ```
        R . . .
        R R R R
        R . . .
        . . . .
        ```
        Colored cells are `R` (red).
        Row 0: Col 0 (1 cell)
        Row 1: Col 0, 1, 2, 3 (4 cells)
        Row 2: Col 0 (1 cell)
        Row 3: None
        Total molecules = 1 + 4 + 1 = 6 molecules.
    *   Membrane: Column 4 is `X`.

**4. Conceptual Digestion:**

*   **CAST:**
    *   **Tissue:** The 4x4 grid on the left. Contains structural elements (Blue `B`) and receptor cavities (Black `.`).
    *   **Cluster:** The 4x4 grid on the right. Contains colored molecules (e.g., `M`, `R`).
    *   **Membrane:** The separator column (`X`).
    *   **Output:** The modified Tissue grid.

*   **AFFORDANCES:**
    *   **Cavities (`.`):** Can be filled by molecules.
    *   **Molecules (Colored):** Can fill cavities.
    *   **Tissue Structure (`B`):** Remains unchanged.
    *   **Cluster:** Provides the color for filling.

*   **TRANSFORMATION RULE:**
    *   Count the number of black cells (`.`) in the Left 4x4 grid (Cavities).
    *   Count the number of non-black, non-grey cells in the Right 4x4 grid (Molecules).
    *   Compare the counts.
    *   **Case 1 (Match):** If Count(Cavities) == Count(Molecules), replace all `.` in the Left grid with the color of the Molecules.
    *   **Case 2 (Mismatch):** If Count(Cavities) != Count(Molecules), the tissue rejects the cluster. The Left grid remains unchanged (Output = Input Left Grid).
    *   *Refinement on "Aligns precisely":* The metaphor says "aligns precisely". In the training example, the shape of the molecules (2x2 square) matches the shape of the cavities (2x2 square). In the test input, the shapes are different.
        *   Cavities shape:
            ```
            . . . . (Row 3)
            . B B . (Row 2)
            . B B . (Row 1)
            B B B B (Row 0)
            ```
            Wait, let's look at the input again.
            Row 0: B B B B
            Row 1: . B B .
            Row 2: . B B .
            Row 3: . . . .
            Cavities are at (1,0), (1,3), (2,0), (2,3), (3,0), (3,1), (3,2), (3,3). Total 8.
        *   Molecules shape:
            Row 0: R . . .
            Row 1: R R R R
            Row 2: R . . .
            Row 3: . . . .
            Molecules are at (0,0), (1,0), (1,1), (1,2), (1,3), (2,0). Total 6.
    *   The metaphor says: "If every colored molecule aligns precisely with every cavity... If even one molecule has no matching cavity or one cavity has no molecule, the tissue rejects the cluster entirely."
    *   This implies a bijection or exact match in quantity and potentially position/shape.
    *   In the tr

... [7202 chars truncated]
alt-10 astronomy qwen3.5-122b: fail
"An eclipse is total only when the shadow perfectly covers every exposed surface — partial alignment and the sky remains unchanged."
Fail (best cell_acc=0.50 at k=3)
Best Attempt
vs
Expected
Reasoning (11020 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Input Format:**
The input is a grid of characters representing colors.
The grid seems to be composed of three parts:
- Left 4x4 area: "The body" (Celestial body).
- Middle column (5th column): "The orbital plane" (Grey 'X').
- Right 4x4 area: "The shadow" (Shadow pattern).
Total width = 4 + 1 + 4 = 9 columns.
Height = 4 rows.

**2. Analyze the Metaphorical Description:**
- "A blue celestial body with exposed bright patches sits beside a colored shadow pattern, divided by a grey orbital plane."
- "Left 4x4 is the body. Right 4x4 is the shadow. Grey column is the orbital divider."
- "If the shadow fills every exposed patch exactly, the color of the shadow replaces the brightness."
- "If alignment is off, the celestial body appears as it was before the transit."
- "Output is 4x4."

Let's interpret "exposed bright patches". In the examples, the "body" (left 4x4) consists mostly of Blue ('B') and Black ('.').
In Example 1:
Left:
B B B B
B . . B
B . . B
B B B B
The 'B's form a border. The '.'s are inside.
Right (Shadow):
. . . .
. M M .
. M M .
. . . .
The 'M's (Magenta) are inside a border of '.'s.
Output:
B B B B
B M M B
B M M B
B B B B
Here, the '.'s in the body were replaced by 'M's from the shadow. The 'B's remained 'B'.
Wait, the description says "If the shadow fills every exposed patch exactly".
In Ex 1, the body has '.' at (1,1), (1,2), (2,1), (2,2) (0-indexed).
The shadow has 'M' at (1,1), (1,2), (2,1), (2,2).
The '.'s in the body correspond to the non-background pixels in the shadow? Or does the shadow pattern overlay the body?
The description says "color of the shadow replaces the brightness". "Brightness" likely refers to the '.' (black/empty) spots in the blue body.
So, if the shadow has a color at position (r, c), and the body has a '.' at (r, c), does it replace it?
In Ex 1, the shadow has 'M' where the body has '.'. The output has 'M' where the body had '.'.
The 'B's in the body remained 'B'.
The '.'s in the shadow (background) didn't change the 'B's in the body.

Let's look at Example 2:
Left (Body):
B B B B
B . . B
B . . B
B B B B
Right (Shadow):
R R . .
R R . .
. . . .
. . . .
Output:
B B B B
B . . B
B . . B
B B B B
Here, the shadow has 'R's at (0,0), (0,1), (1,0), (1,1).
The body has 'B's at these positions.
The body has '.' at (1,1), (1,2), (2,1), (2,2).
The shadow has '.' at (1,1), (1,2), (2,1), (2,2).
The output is identical to the input body.
Why? "If alignment is off, the celestial body appears as it was before the transit."
What defines "alignment"?
In Ex 1, the non-background pixels in the shadow ('M') matched the background pixels ('.') in the body exactly in position.
In Ex 2, the non-background pixels in the shadow ('R') are at (0,0), (0,1), (1,0), (1,1).
The background pixels in the body ('.') are at (1,1), (1,2), (2,1), (2,2).
They do not match. The 'R's are on top of 'B's. The '.'s in shadow are on top of '.'s in body.
So the condition "shadow fills every exposed patch exactly" implies:
1. Identify "exposed patches" in the body. These seem to be the '.' (black) cells.
2. Identify the "shadow pattern". These seem to be the non-'.' cells in the right 4x4 grid.
3. Check if the set of coordinates of non-'.' cells in the shadow matches the set of coordinates of '.' cells in the body.
   - If Match: Replace the '.' cells in the body with the corresponding colors from the shadow.
   - If No Match: Keep the body as is.

Let's check Example 3:
Left (Body):
B B B B
B . . .
B . B B
B . B .
Right (Shadow):
. . . .
. O O O
. O . .
. O . O
Output:
B B B B
B O O O
B O B B
B O B O

Body '.' positions:
(1,1), (1,2), (1,3)
(2,1)
(3,1), (3,3)
Total 6 dots.

Shadow non-'.' positions (Color 'O'):
(1,1), (1,2), (1,3)
(2,1)
(3,1), (3,3)
Total 6 'O's.
The positions match exactly.
The output replaces the '.' in the body with 'O' from the shadow.
The 'B's in the body remain 'B'.
The '.' in the shadow are ignored (they don't overwrite 'B's).

So the rule seems to be:
1. Extract the 4x4 Body (Left) and 4x4 Shadow (Right).
2. Identify the "mask" of the Body: Where are the '.' (black) pixels? Let's call this set $P_{body}$.
3. Identify the "mask" of the Shadow: Where are the non-'.' (colored) pixels? Let's call this set $P_{shadow}$.
4. Compare $P_{body}$ and $P_{shadow}$.
   - If $P_{body} == P_{shadow}$ (same coordinates):
     - Create Output Grid = Body Grid.
     - For every coordinate $(r, c)$ in $P_{body}$, set Output$(r, c)$ = Shadow$(r, c)$.
   - If $P_{body} \neq P_{shadow}$:
     - Output Grid = Body Grid (unchanged).

Let's re-verify with Example 2.
Body '.' at: (1,1), (1,2), (2,1), (2,2).
Shadow non-'.' ('R') at: (0,0), (0,1), (1,0), (1,1).
Sets are different.
Output = Body. Correct.

Let's re-verify with Example 1.
Body '.' at: (1,1), (1,2), (2,1), (2,2).
Shadow non-'.' ('M') at: (1,1), (1,2), (2,1), (2,2).
Sets are same.
Output = Body with '.' replaced by 'M'. Corr

... [6026 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=2
"Cargo loads into a hull only when every crate fits a hold and every hold gets a crate — mismatched manifest and the ship sails empty."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11207 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A blue ship hull with open cargo holds sits beside colored crates on a grey dock.
*   **Action:**
    *   If every crate maps to an open hold and every hold has a crate -> Cargo is loaded (colors fill the hull).
    *   Otherwise -> Ship departs with empty holds.
*   **Grid Layout:**
    *   Left 4x4: Hull.
    *   Right 4x4: Dock cargo.
    *   Middle column (implied by 'X' in examples): Gangway (separator).
    *   Output: 4x4 hull.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Grid (8x4? No, let's look at the structure).
    *   Input:
        ```
        B B B B X . . . .
        B . . B X . M M .
        B . . B X . M M .
        B B B B X . . . .
        ```
        Wait, the input description says "Left 4x4 is the hull. Right 4x4 is the dock cargo. Grey column is the gangway."
        Let's count columns in Example 1 Input.
        Row 1: `B B B B X . . . .` -> 4 B's, 1 X, 4 dots. Total 9 columns.
        Row 2: `B . . B X . M M .` -> 4 chars, 1 X, 4 chars.
        Row 3: `B . . B X . M M .`
        Row 4: `B B B B X . . . .`
        So the input is a 4x9 grid.
        Left 4x4 (Cols 0-3): Hull.
        Col 4: Gangway (X).
        Right 4x4 (Cols 5-8): Dock Cargo.

    *   **Hull (Left 4x4):**
        ```
        B B B B
        B . . B
        B . . B
        B B B B
        ```
        This looks like a container with a border of Blue (B) and empty space (.) inside. The "open cargo holds" are the `.` cells inside the hull.
        There are 4 empty cells inside the hull: (1,1), (1,2), (2,1), (2,2).

    *   **Dock Cargo (Right 4x4):**
        ```
        . . . .
        . M M .
        . M M .
        . . . .
        ```
        There are 4 Magenta (M) crates. They form a 2x2 block.

    *   **Output:**
        ```
        B B B B
        B M M B
        B M M B
        B B B B
        ```
        The empty spots in the hull are filled with the color of the crates (M).
        Condition check: "If every crate maps to an open hold and every hold has a crate".
        Number of empty holds in hull = 4.
        Number of crates in dock = 4.
        They match. So the cargo is loaded. The hull interior takes the color of the crates.

*   **Example 2:**
    *   Input:
        ```
        B B B B X R R . .
        B . . B X R R . .
        B . . B X . . . .
        B B B B X . . . .
        ```
    *   **Hull:**
        ```
        B B B B
        B . . B
        B . . B
        B B B B
        ```
        Empty holds: 4 (at 1,1; 1,2; 2,1; 2,2).
    *   **Dock Cargo:**
        ```
        R R . .
        R R . .
        . . . .
        . . . .
        ```
        Crates: 4 Red (R) crates.
    *   **Output:**
        ```
        B B B B
        B . . B
        B . . B
        B B B B
        ```
        Wait, the output is the same as the input hull. The empty spots remain empty (`.`).
        Why?
        Let's re-read the condition: "If every crate maps to an open hold and every hold has a crate, the cargo is loaded and colors fill the hull. Otherwise the ship departs with empty holds."
        In Example 1: 4 holds, 4 crates. Match -> Loaded.
        In Example 2: 4 holds, 4 crates. Match -> Loaded?
        But the output shows empty holds.
        Let's look closer at Example 2 Output.
        Output:
        ```
        B B B B
        B . . B
        B . . B
        B B B B
        ```
        This means the cargo was *not* loaded.
        Why?
        Maybe the arrangement matters?
        In Example 1, the crates were a 2x2 block. The holds were a 2x2 block.
        In Example 2, the crates were a 2x2 block. The holds were a 2x2 block.
        Wait, look at the Dock Cargo in Example 2 again.
        Row 0: `R R . .`
        Row 1: `R R . .`
        Row 2: `. . . .`
        Row 3: `. . . .`
        This is a 2x2 block of R.
        The Hull interior is a 2x2 block of `.`.
        Why did Example 1 load and Example 2 not load?
        Let's re-examine Example 1 Dock Cargo.
        Row 0: `. . . .`
        Row 1: `. M M .`
        Row 2: `. M M .`
        Row 3: `. . . .`
        This is also a 2x2 block.
        Is there a difference in the Hull?
        Example 1 Hull:
        `B B B B`
        `B . . B`
        `B . . B`
        `B B B B`
        Example 2 Hull:
        `B B B B`
        `B . . B`
        `B . . B`
        `B B B B`
        They are identical.
        Is there a difference in the Cargo?
        Example 1 Cargo: M (Magenta).
        Example 2 Cargo: R (Red).
        Is there a difference in the "Gangway"?
        Both have X.
        Is there a difference in the "Dock Cargo" position?
        Example 1 Cargo is centered vertically (Rows 1-2).
        Example 2 Cargo is at the top (Rows 0-1).
        Maybe the "mapping" implies spatial correspondence?
        "If ev

... [6261 chars truncated]
alt-12 electronics qwen3.5-122b: fig alone solves
"A circuit board powers on only when every socket receives a component and no component is left unplaced — an incomplete board stays dark."
alt-13 mythology qwen3.5-122b: k=7
"A cursed mask lifts its enchantment only when every rune carved into it is matched by a counter-sigil — incomplete rites leave the curse intact."
MARC valid, solved with k=7
Prediction
vs
Expected
Reasoning (10870 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and several training examples.

**1. Analyze the Input Structure:**
The input is a grid. Looking at the examples, the input grid seems to be composed of three parts:
- A 4x4 grid on the left (Columns 0-3).
- A single column in the middle (Column 4) which is always 'X' (grey).
- A 4x4 grid on the right (Columns 5-8).
Wait, let's check the dimensions.
Example 1 Input:
B B B B X . . . .
B . . B X . M M .
B . . B X . M M .
B B B B X . . . .
This looks like 4 rows.
Columns:
0: B
1: B
2: B
3: B
4: X
5: .
6: .
7: .
8: .
So the input is 4 rows by 9 columns.
Left part: 4x4 (Cols 0-3).
Separator: 1 column (Col 4) with 'X'.
Right part: 4x4 (Cols 5-8).
Output: 4x4 grid.

**2. Analyze the Metaphor:**
- "Left 4x4 is the mask." -> This corresponds to the left part of the input.
- "Right 4x4 is the sigil array." -> This corresponds to the right part of the input.
- "Grey column is the altar." -> The 'X' column.
- "If every counter-sigil corresponds to a rune-slot and every slot is matched, the sigils fill the mask and transform it."
- "Imperfect alignment leaves the mask cursed and unchanged."

This suggests a conditional transformation.
- The "mask" (Left 4x4) has a structure. It seems to define "slots" or "holes".
- The "sigil array" (Right 4x4) contains colored pixels.
- The transformation involves copying the sigils into the mask.
- The condition "every counter-sigil corresponds to a rune-slot and every slot is matched" implies a check. If the check passes, the mask is filled. If not, it remains unchanged (or maybe just the mask part is outputted?).
- Let's look at the outputs.
    - Example 1 Output:
      B B B B
      B M M B
      B M M B
      B B B B
      Input Left:
      B B B B
      B . . B
      B . . B
      B B B B
      Input Right:
      . . . .
      . M M .
      . M M .
      . . . .
      Here, the '.' in the mask (Left) are replaced by 'M' from the sigil (Right). The 'B' border remains 'B'.
      The Right grid has 'M's in the same positions as the '.' in the Left grid.
      Wait, let's check positions.
      Left (1,1) is '.', Right (1,1) is 'M'.
      Left (1,2) is '.', Right (1,2) is 'M'.
      Left (2,1) is '.', Right (2,1) is 'M'.
      Left (2,2) is '.', Right (2,2) is 'M'.
      All other positions in Left are 'B'. All other positions in Right are '.'.
      So it looks like: Output = Left, but where Left is '.', take value from Right.
      Is there a condition? "If every counter-sigil corresponds to a rune-slot and every slot is matched".
      In Ex 1, the '.' in Left match the non-'.' in Right. The 'B' in Left match the '.' in Right.
      It seems like a superposition where Right fills the holes in Left.

    - Example 2:
      Input Left:
      B B B B
      B . . B
      B . . B
      B B B B
      Input Right:
      R R . .
      R R . .
      . . . .
      . . . .
      Output:
      B B B B
      B . . B
      B . . B
      B B B B
      Here, the Output is identical to the Input Left.
      Why?
      In Ex 1, the Right grid had 'M's exactly where Left had '.'.
      In Ex 2, the Right grid has 'R's at (0,0), (0,1), (1,0), (1,1).
      The Left grid has 'B' at (0,0), (0,1), (1,0), (1,1).
      The Left grid has '.' at (1,1), (1,2), (2,1), (2,2).
      The Right grid has '.' at (1,1), (1,2), (2,1), (2,2).
      So the 'R's in Right are on top of 'B's in Left. The '.' in Right are on top of '.' in Left.
      The output is unchanged.
      Hypothesis: The transformation only happens if the non-background pixels in the Right grid align perfectly with the background pixels ('.') in the Left grid.
      Or, more specifically: The Right grid acts as a "filler". It fills the holes ('.') in the Left grid.
      Condition: "If every counter-sigil corresponds to a rune-slot and every slot is matched".
      "Counter-sigil" = non-black/non-background pixel in Right?
      "Rune-slot" = hole ('.') in Left?
      "Every slot is matched" = Every '.' in Left has a corresponding non-'.' in Right?
      "Every counter-sigil corresponds to a rune-slot" = Every non-'.' in Right corresponds to a '.' in Left?
      Basically, the set of coordinates where Right is not '.' must be exactly equal to the set of coordinates where Left is '.'.
      Let's check Ex 1:
      Left '.' coords: (1,1), (1,2), (2,1), (2,2).
      Right non-'.' coords: (1,1)='M', (1,2)='M', (2,1)='M', (2,2)='M'.
      Sets match. Transformation happens. Output = Left with Right values filling Left holes.
      Let's check Ex 2:
      Left '.' coords: (1,1), (1,2), (2,1), (2,2).
      Right non-'.' coords: (0,0)='R', (0,1)='R', (1,0)='R', (1,1)='R'.
      Sets do not match. Transformation does not happen. Output = Left.

    - Example 3:
      Input Left:
      B B B B
      B . . .
      B . B B
      B . B .
      Left '.' coords: (1,1), (1,2), (1,3), (2,1), (3,1), (3,3).
      Input Right:
      . . . .
      . O O O
      . O . .

... [5879 chars truncated]
alt-14 dance qwen3.5-122b: k=6
"A partner dance is complete only when every open hand finds a matching grip — unmatched dancers stand still in their original positions."
MARC valid, solved with k=6
Prediction
vs
Expected
Reasoning (11040 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A blue dance formation with open positions faces colored dancers waiting across a grey stage divide.
*   **Action:** If every dancer finds an open position and every position has a dancer, partners join and color fills the formation. If not, the original formation holds.
*   **Grid Details:**
    *   Left 4x4 is the formation.
    *   Right 4x4 is the waiting dancers.
    *   Grey column (X) is the divide.
    *   Output is 4x4.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Left (Formation):
        B B B B
        B . . B
        B . . B
        B B B B
        (A hollow square of Blue 'B's)
    *   Input Right (Dancers):
        . . . .
        . M M .
        . M M .
        . . . .
        (A solid square of Magenta 'M's in the middle 2x2)
    *   Output:
        B B B B
        B M M B
        B M M B
        B B B B
    *   Observation: The 'M's filled the '.' spots inside the 'B' frame. The counts match?
        Left '.' count: 4 (positions (1,1), (1,2), (2,1), (2,2) - 0-indexed).
        Right non-'.' count: 4 (M's).
        Result: The '.' spots in the left grid are replaced by the non-'.' colors from the right grid.

*   **Example 2:**
    *   Input Left:
        B B B B
        B . . B
        B . . B
        B B B B
        (Hollow square, 4 empty spots)
    *   Input Right:
        R R . .
        R R . .
        . . . .
        . . . .
        (4 Red 'R's in top-left 2x2)
    *   Output:
        B B B B
        B . . B
        B . . B
        B B B B
    *   Observation: The output is identical to the input left grid. The '.' spots were NOT filled.
    *   Why? The metaphor says: "If every dancer finds an open position and every position has a dancer... If not, the original formation holds."
    *   In Ex 1, Left had 4 holes, Right had 4 dancers. Match -> Fill.
    *   In Ex 2, Left had 4 holes, Right had 4 dancers. Wait, why didn't it fill?
    *   Let's look closer at Ex 2 Right grid.
        R R . .
        R R . .
        . . . .
        . . . .
        There are 4 'R's.
        Left grid has 4 '.' spots.
        Why no fill?
        Maybe the shape matters? Or the position?
        In Ex 1, the M's were in the center 2x2. The holes were in the center 2x2.
        In Ex 2, the R's are in the top-left 2x2. The holes are in the center 2x2.
        Hypothesis: The dancers must match the *shape* or *position* of the holes? Or maybe the count isn't the only factor.
        Let's re-read the metaphor: "If every dancer finds an open position and every position has a dancer". This implies a bijection or a perfect fit.
        In Ex 1, the M's form a 2x2 block. The holes form a 2x2 block. They align perfectly.
        In Ex 2, the R's form a 2x2 block. The holes form a 2x2 block. But the R's are at (0,0)-(1,1) relative to the right grid, while holes are at (1,1)-(2,2) relative to the left grid.
        Wait, the grids are separate. The transformation likely involves mapping the Right grid onto the Left grid.
        If the Right grid is simply "the source of colors", how do we know where to put them?
        Maybe the Right grid represents the *pattern* to fill?
        In Ex 1, Right grid has M's at (1,1), (1,2), (2,1), (2,2). Left grid has holes at (1,1), (1,2), (2,1), (2,2). They match coordinates.
        In Ex 2, Right grid has R's at (0,0), (0,1), (1,0), (1,1). Left grid has holes at (1,1), (1,2), (2,1), (2,2). Coordinates do not match. Result: No change.
        Hypothesis: The Right grid acts as a mask. If the non-black pixels in the Right grid align with the black pixels (holes) in the Left grid (assuming 0-indexed coordinates within the 4x4 subgrids), then the fill happens. If the pattern of non-black pixels in the Right grid does not match the pattern of black pixels in the Left grid, nothing happens.
        Let's check Ex 1 again.
        Left Holes: (1,1), (1,2), (2,1), (2,2).
        Right Non-Black: (1,1), (1,2), (2,1), (2,2).
        Match? Yes.
        Ex 2:
        Left Holes: (1,1), (1,2), (2,1), (2,2).
        Right Non-Black: (0,0), (0,1), (1,0), (1,1).
        Match? No.
        Result: No change.

*   **Example 3:**
    *   Input Left:
        B B B B
        B . . .
        B . B B
        B . B .
        Holes at: (1,1), (1,2), (1,3), (2,1), (3,1), (3,3). Total 6 holes.
    *   Input Right:
        . . . .
        . O O O
        . O . .
        . O . O
        Non-Black (O) at: (1,1), (1,2), (1,3), (2,1), (3,1), (3,3). Total 6 O's.
    *   Output:
        B B B B
        B O O O
        B O B B
        B O B O
    *   Observation: The holes in Left are exactly filled by the O's from Right. The coordinates match perfectly.
    *   Left Holes: (1,1), (1,2), (1,3), (2,1), (3,1), (3,3).
    *   Right O's: (1,1), (1,2), (1,3), (2,1), (3,1), (3,3).
    *   Match? Yes. Fill ha

... [6079 chars truncated]
alt-15 geology qwen3.5-122b: k=5
"Magma fills a cavern system only when every chamber has a lava channel feeding it and every channel reaches a chamber — partial eruptions leave the rock cold."
MARC valid, solved with k=5
Prediction
vs
Expected
Reasoning (11005 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Input Structure:**
The input grid is 4 rows by 9 columns (based on the examples).
Wait, let's look at the examples.
Example 1 Input:
B B B B X . . . .
B . . B X . M M .
B . . B X . M M .
B B B B X . . . .
This looks like 4 rows. The columns are:
Col 0-3: Left 4x4 block (Rock)
Col 4: X (Grey fault line)
Col 5-8: Right 4x4 block (Magma map)
Total width = 4 + 1 + 4 = 9 columns.
Height = 4 rows.

The Output is a 4x4 grid.

**2. Analyze the Metaphor:**
- "Left 4x4 is the rock." -> This is the target area or the container.
- "Right 4x4 is the magma map." -> This is the source of color.
- "Grey column is the fault line." -> Separator.
- "If every magma channel maps to a chamber and every chamber has a channel, the lava fills the voids with color."
- "Incomplete alignment means the rock stays cool and unchanged."

This suggests a matching condition.
Let's look at the "Rock" (Left 4x4). It seems to define "chambers" or "voids".
In Example 1:
Left:
B B B B
B . . B
B . . B
B B B B
This looks like a hollow square. The '.' are the "voids" or "chambers". The 'B's are the walls.
Right:
. . . .
. M M .
. M M .
. . . .
This looks like a filled square of 'M's inside a border of '.'.
Output:
B B B B
B M M B
B M M B
B B B B
The '.' in the left grid were replaced by 'M' from the right grid.

In Example 2:
Left:
B B B B
B . . B
B . . B
B B B B
Same rock structure (hollow square).
Right:
R R . .
R R . .
. . . .
. . . .
Output:
B B B B
B . . B
B . . B
B B B B
The output is identical to the input left grid. The '.' remained '.'.
Why? The metaphor says "Incomplete alignment means the rock stays cool and unchanged."
In Example 1, the Right grid had M's exactly where the Left grid had '.' (relative to the shape).
In Example 2, the Right grid has R's in the top-left 2x2 area. The Left grid has '.' in the center 2x2 area. They don't match. So no change.

In Example 3:
Left:
B B B B
B . . .
B . B B
B . B .
Right:
. . . .
. O O O
. O . .
. O . O
Output:
B B B B
B O O O
B O B B
B O B O
Here, the '.' in the Left grid are replaced by 'O' from the Right grid.
Let's check the positions.
Left '.' positions: (1,1), (1,2), (1,3), (2,1), (3,1), (3,3).
Right non-'.' positions: (1,1), (1,2), (1,3), (2,1), (3,1), (3,3).
They match perfectly. The 'O's fill the '.' spots.

In Example 4:
Left:
. . . B
B . . .
B B . .
B B B .
Right:
R R . .
R R . .
. R R .
. R R .
Output:
. . . B
B . . .
B B . .
B B B .
Output is same as Left.
Left '.' positions: (0,0), (0,1), (0,2), (1,1), (1,2), (2,2), (3,3).
Right non-'.' positions: (0,0), (0,1), (1,0), (1,1), (2,1), (2,2), (3,1), (3,2).
Do they match?
Left has '.' at (0,0). Right has 'R' at (0,0). Match.
Left has '.' at (0,1). Right has 'R' at (0,1). Match.
Left has '.' at (0,2). Right has '.' at (0,2). Mismatch (Left wants color, Right has empty).
Left has '.' at (1,1). Right has 'R' at (1,1). Match.
Left has '.' at (1,2). Right has '.' at (1,2). Mismatch.
Left has '.' at (2,2). Right has 'R' at (2,2). Match.
Left has '.' at (3,3). Right has '.' at (3,3). Mismatch.
Since not all '.' in Left correspond to non-'.' in Right (and vice versa? "every magma channel maps to a chamber and every chamber has a channel"), the condition fails.
Wait, let's re-read the condition: "If every magma channel maps to a chamber and every chamber has a channel".
This implies a bijection or exact overlap between the set of "voids" in the Rock and the set of "magma" in the Magma map.
Let $V_L$ be the set of coordinates $(r, c)$ where Left grid has '.' (void).
Let $V_R$ be the set of coordinates $(r, c)$ where Right grid has a color (magma).
Condition: $V_L == V_R$.
If $V_L == V_R$, then Output grid is Left grid but with '.' replaced by the color found in Right grid at that position.
If $V_L \neq V_R$, then Output grid is just the Left grid (unchanged).

Let's verify this hypothesis with Example 5.
Left:
B B . .
B . . B
B . . B
B B . .
$V_L$: (0,2), (0,3), (1,1), (1,2), (2,1), (2,2), (3,2), (3,3).
Right:
. . G G
. G G .
. G G .
. . G G
$V_R$: (0,2), (0,3), (1,1), (1,2), (2,1), (2,2), (3,2), (3,3).
They match exactly.
Output:
B B G G
B G G B
B G G B
B B G G
The '.' in Left are replaced by 'G' from Right.
This confirms the hypothesis.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Rock (Left 4x4):** Defines the structure. Contains 'B' (walls) and '.' (voids/chambers).
    *   **Magma Map (Right 4x4):** Defines the potential color source. Contains '.' (empty) and colored pixels (magma channels).
    *   **Fault Line (Column 4):** Separator, ignored in logic.
    *   **Output (4x4):** The result of the interaction.

2.  **AFFORDANCES:**
    *   **Rock:** Can hold magma in its voids.
    *   **Magma Map:** Can provide color.
    *   **Alignment:** The spatial arrangement of voids in Rock must match the spatial arrangement of magma in Magma Map.

3.  **TRANSFORMATION RULE:**
    *   Extract the set o

... [6020 chars truncated]
alt-2 cooking qwen3.5-122b: fig alone solves
"A pastry chef fills a mold only when the batter volume is the exact shape of the hollow — too much or too little and the mold stays empty."
alt-3 music qwen3.5-122b: fig alone solves
"A melody only harmonizes with a silence pattern when every note lands exactly in a rest — otherwise the orchestra plays the original score unaltered."
alt-4 sports qwen3.5-122b: k=2
"A defensive formation only breaks when attackers fill every single gap simultaneously — if even one gap is uncovered, the defense holds firm."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11556 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A blue defensive wall with openings faces a colored attacking squad across a grey midfield line.
*   **Action:**
    *   If attackers perfectly occupy every gap in the wall, they break through and appear in those positions.
    *   If any gap is left unfilled or any attacker has no gap, the wall stands unchanged.
*   **Grid Layout:**
    *   Left 4x4: Defensive wall (Blue 'B' and gaps '.').
    *   Right 4x4: Attacking formation (Colored squares, likely 'R' in the test input, but could be others).
    *   Middle column: Grey 'X' (Midfield).
    *   Output: The 4x4 wall, either breached (attackers fill gaps) or intact (original wall).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Wall (Left 4x4):
        ```
        B B B B
        B . . B
        B . . B
        B B B B
        ```
        (A hollow square of Blue 'B's with a 2x2 hole in the middle).
    *   Input Attackers (Right 4x4):
        ```
        . . . .
        . M M .
        . M M .
        . . . .
        ```
        (A 2x2 block of Magenta 'M's in the middle).
    *   Midfield: Column of 'X'.
    *   Output:
        ```
        B B B B
        B M M B
        B M M B
        B B B B
        ```
    *   **Observation:** The attackers (M) perfectly match the shape and position of the gaps (.) in the wall. The gaps are at (1,1), (1,2), (2,1), (2,2) (0-indexed). The attackers are at the corresponding positions in the right grid. The result is the wall with the gaps filled by the attacker color.

*   **Example 2:**
    *   Input Wall (Left 4x4):
        ```
        B B B B
        B . . B
        B . . B
        B B B B
        ```
        (Same hollow square).
    *   Input Attackers (Right 4x4):
        ```
        R R . .
        R R . .
        . . . .
        . . . .
        ```
        (A 2x2 block of Red 'R's in the top-left of the attacker grid).
    *   Midfield: Column of 'X'.
    *   Output:
        ```
        B B B B
        B . . B
        B . . B
        B B B B
        ```
    *   **Observation:** The attackers (R) do *not* match the gaps in the wall. The gaps are in the center, attackers are top-left. The condition "attackers perfectly occupy every gap" is not met. The wall stands unchanged.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Wall:** The 4x4 grid on the left. Contains 'B' (Blue) and '.' (Black/Empty).
    *   **Attackers:** The 4x4 grid on the right. Contains colored pixels (e.g., 'M', 'R') and '.' (Empty).
    *   **Midfield:** The column of 'X' separating them.
    *   **Gaps:** The '.' cells within the Wall grid.
    *   **Attackers' Shape:** The pattern of non-'.' cells in the Attacker grid.

*   **AFFORDANCES:**
    *   The Wall defines a target shape (the set of coordinates where '.' exists).
    *   The Attackers define a source shape (the set of coordinates where non-'.' exists).
    *   The transformation checks for a match between the Wall's gaps and the Attackers' shape.

*   **TRANSFORMATION RULE:**
    1.  Extract the 4x4 Wall grid ($W$) and the 4x4 Attacker grid ($A$).
    2.  Identify the coordinates of the "gaps" in $W$. Let $G_W = \{(r, c) \mid W[r][c] == '.'\}$.
    3.  Identify the coordinates of the "attackers" in $A$. Let $G_A = \{(r, c) \mid A[r][c] \neq '.'\}$.
    4.  Compare the sets $G_W$ and $G_A$.
    5.  **Condition:** If $G_W == G_A$ (exact match in coordinates), then the wall is breached.
        *   **Breached Output:** Create a new grid $O$ where $O[r][c] = A[r][c]$ if $(r, c) \in G_W$, otherwise $O[r][c] = W[r][c]$. Essentially, fill the gaps in the wall with the corresponding attacker colors.
    6.  **Condition:** If $G_W \neq G_A$ (mismatch in shape or position), the wall is intact.
        *   **Intact Output:** $O = W$.

    *Refinement on "Attackers perfectly occupy every gap":*
    Does it mean the shape must match exactly?
    In Example 1: Gaps are 4 cells. Attackers are 4 cells. Positions match. Result: Filled.
    In Example 2: Gaps are 4 cells (center). Attackers are 4 cells (top-left). Positions do not match. Result: Unchanged.
    What if the number of attackers is different? The rule says "perfectly occupy every gap". This implies a bijection or exact set equality of the non-wall cells and the attacker cells.
    Also, "any attacker has no gap" implies if there are attackers where there are no gaps, it fails. "any gap is left unfilled" implies if there are gaps where there are no attackers, it fails.
    So, $G_W$ must equal $G_A$.

**4. Apply to Test Input:**

*   **Input Grid:**
    ```
    B B B B X R . . .
    . B B . X R R R R
    . B B . X R . . .
    . . . . X . . . .
    ```
    Wait, let's parse the input carefully.
    The input is a single block of text.
    Row 1: `B B B B X R . . .` -> Wall Row 1: `B B B B`, Midfield: `X`, Attackers Row 1: `R . . .

... [6589 chars truncated]
alt-5 weather qwen3.5-122b: k=1
"Rain saturates parched earth only when every raindrop finds dry ground — if rain falls on stone or dry patches stay unwatered, the drought persists."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11320 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A blue landscape with patches of dry earth sits beside a colored rain pattern, divided by a grey cloud bank.
*   **Action:** If the rain pattern is the exact complement of the dry patches, the rain soaks in and colors the earth. Otherwise, the land remains unchanged.
*   **Grid Layout:**
    *   Left 4x4: Terrain (Blue landscape with dry earth patches).
    *   Right 4x4: Rainfall pattern.
    *   Middle Column: Grey cloud bank (Separator).
    *   Output: 4x4 terrain.
*   **Colors:**
    *   Blue (B) = Landscape/Water?
    *   Black (.) = Dry Earth?
    *   Grey (X) = Cloud Bank (Separator).
    *   Other colors (R, M, etc.) = Rain colors.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    B B B B X . . . .
    B . . B X . M M .
    B . . B X . M M .
    B B B B X . . . .
    ```
    *   Left 4x4 (Terrain):
        ```
        B B B B
        B . . B
        B . . B
        B B B B
        ```
        This looks like a blue frame with a black (dry earth) center.
    *   Middle Column (Separator): `X X X X`
    *   Right 4x4 (Rain):
        ```
        . . . .
        . M M .
        . M M .
        . . . .
        ```
        This looks like a black frame with a magenta (M) center.
*   **Output:**
    ```
    B B B B
    B M M B
    B M M B
    B B B B
    ```
    *   The output is the Left 4x4 terrain, but the black (.) patches in the center have been replaced by the Magenta (M) color from the corresponding positions in the Rain pattern.
    *   Wait, let's look closer.
    *   Terrain:
        (0,0) B, (0,1) B, (0,2) B, (0,3) B
        (1,0) B, (1,1) ., (1,2) ., (1,3) B
        (2,0) B, (2,1) ., (2,2) ., (2,3) B
        (3,0) B, (3,1) B, (3,2) B, (3,3) B
    *   Rain:
        (0,0) ., (0,1) ., (0,2) ., (0,3) .
        (1,0) ., (1,1) M, (1,2) M, (1,3) .
        (2,0) ., (2,1) M, (2,2) M, (2,3) .
        (3,0) ., (3,1) ., (3,2) ., (3,3) .
    *   Output:
        (1,1) became M. (1,2) became M. (2,1) became M. (2,2) became M.
        The rest remained B.
    *   Condition Check: "If the rain pattern is the exact complement of the dry patches".
        *   Dry patches in Terrain: (1,1), (1,2), (2,1), (2,2) are `.`.
        *   Rain pattern at those positions: (1,1) is M, (1,2) is M, (2,1) is M, (2,2) is M.
        *   Rain pattern at non-dry positions (where Terrain is B): (0,0) is ., (0,1) is ., etc.
        *   Is it a complement?
            *   Terrain has `.` where Rain has `M`.
            *   Terrain has `B` where Rain has `.`.
            *   This implies a relationship: Where Terrain is `.` (dry), Rain has color `C`. Where Terrain is `B` (blue), Rain has `.` (empty/no rain).
            *   The rule says: "If the rain pattern is the exact complement of the dry patches, the rain soaks in and colors the earth."
            *   "Complement" here likely means: The non-background pixels in the Rain grid correspond exactly to the background (dry earth) pixels in the Terrain grid.
            *   In the example:
                *   Terrain `.` positions: {(1,1), (1,2), (2,1), (2,2)}
                *   Rain non-`.` positions: {(1,1), (1,2), (2,1), (2,2)} (Color M)
                *   They match perfectly.
            *   Result: The `.` in Terrain are replaced by the color from Rain.
            *   What if they don't match? "Otherwise the land remains unchanged".

**3. Analyze the Test Input:**
*   **Input:**
    ```
    B B B B X R . . .
    . B B . X R R R R
    . B B . X R . . .
    . . . . X . . . .
    ```
*   **Left 4x4 (Terrain):**
    ```
    B B B B
    . B B .
    . B B .
    . . . .
    ```
    *   Dry patches (`.`):
        *   Row 1: (1,0), (1,3)
        *   Row 2: (2,0), (2,3)
        *   Row 3: (3,0), (3,1), (3,2), (3,3)
    *   Blue patches (`B`):
        *   Row 0: All
        *   Row 1: (1,1), (1,2)
        *   Row 2: (2,1), (2,2)
*   **Middle Column:** `X X X X` (Separator)
*   **Right 4x4 (Rain):**
    ```
    R . . .
    R R R R
    R . . .
    . . . .
    ```
    *   Non-`.` positions (Rain color R):
        *   Row 0: (0,0)
        *   Row 1: (1,0), (1,1), (1,2), (1,3)
        *   Row 2: (2,0)
        *   Row 3: None
*   **Check Condition:** "If the rain pattern is the exact complement of the dry patches".
    *   Dry patches in Terrain (where value is `.`):
        *   (1,0), (1,3)
        *   (2,0), (2,3)
        *   (3,0), (3,1), (3,2), (3,3)
    *   Rain pattern non-`.` positions (where value is `R`):
        *   (0,0)
        *   (1,0), (1,1), (1,2), (1,3)
        *   (2,0)
    *   Comparison:
        *   Terrain `.` at (1,0) -> Rain `R` at (1,0). Match.
        *   Terrain `.` at (1,3) -> Rain `R` at (1,3). Match.
        *   Terrain `.` at (2,0) -> Rain `R` at (2,0). Match.
        *   Terrain `.` at (2,3) -> Rain `.` at (2,3). **Mismatch**. Rain is empty here.
        *   Terr

... [6359 chars truncated]
alt-6 architecture qwen3.5-122b: fig alone solves
"Stained glass is installed only when every pane matches every empty window frame precisely — a single mismatch and the frames stay open."
alt-7 warfare qwen3.5-122b: fail
"A siege engine breaches a fortress only when every battering ram targets a weak point — scattered or misaligned strikes leave the walls untouched."
Fail (best cell_acc=0.25 at k=4)
Best Attempt
vs
Expected
Reasoning (11994 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scenario:** A blue fortress (Left 4x4) faces a colored siege formation (Right 4x4) across a grey no-man's-land (Middle column).
*   **Action:** "If every siege weapon aligns with a weak point and every weak point faces a weapon, the walls fall and the color fills the breaches. Misalignment means the fortress stands."
*   **Grid Layout:**
    *   Left 4x4: Fortress (mostly Blue 'B', with some holes '.' or other colors).
    *   Middle Column: Buffer zone (Grey 'X').
    *   Right 4x4: Siege (Colored shapes, e.g., 'R', 'M', 'O').
    *   Output: 4x4 Fortress grid.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Fortress (Left 4x4):
        B B B B
        B . . B
        B . . B
        B B B B
        (A hollow square of Blue)
    *   Input Siege (Right 4x4):
        . . . .
        . M M .
        . M M .
        . . . .
        (A 2x2 block of Magenta 'M' in the center)
    *   Output:
        B B B B
        B M M B
        B M M B
        B B B B
    *   Observation: The Magenta block from the siege replaced the empty spots ('.') inside the fortress. The fortress shape (walls) remained Blue. The siege shape matched the hole shape perfectly.

*   **Example 2:**
    *   Input Fortress:
        B B B B
        B . . B
        B . . B
        B B B B
    *   Input Siege:
        R R . .
        R R . .
        . . . .
        . . . .
        (A 2x2 block of Red 'R' in the top-left of the siege area)
    *   Output:
        B B B B
        B . . B
        B . . B
        B B B B
    *   Observation: The fortress remained unchanged. The siege shape (2x2 Red) did *not* match the hole shape (2x2 empty space in the center of the fortress). Wait, let's look closer.
    *   Fortress holes are at (1,1), (1,2), (2,1), (2,2) (0-indexed).
    *   Siege shape is at (0,0), (0,1), (1,0), (1,1) relative to the siege grid.
    *   The metaphor says: "If every siege weapon aligns with a weak point and every weak point faces a weapon".
    *   In Example 1: Fortress holes are at rows 1,2 cols 1,2. Siege M's are at rows 1,2 cols 1,2 (relative to siege grid). They align perfectly. Result: Fill holes with Siege color.
    *   In Example 2: Fortress holes are at rows 1,2 cols 1,2. Siege R's are at rows 0,1 cols 0,1. They do not align. Result: No change.

*   **Example 3:**
    *   Input Fortress:
        B B B B
        B . . .
        B . B B
        B . B .
    *   Input Siege:
        . . . .
        . O O O
        . O . .
        . O . O
    *   Output:
        B B B B
        B O O O
        B O B B
        B O B O
    *   Observation:
        *   Fortress holes ('.'):
            Row 1: cols 1, 2, 3
            Row 2: col 1
            Row 3: col 1, 3
        *   Siege colors ('O'):
            Row 1: cols 1, 2, 3
            Row 2: col 1
            Row 3: col 1, 3
        *   The pattern of 'O's in the siege grid matches exactly the pattern of '.' in the fortress grid.
        *   Result: The '.' in the fortress are replaced by 'O'.

*   **Example 4:**
    *   Input Fortress:
        . . . B
        B . . .
        B B . .
        B B B .
    *   Input Siege:
        R R . .
        R R . .
        . R R .
        . R R .
    *   Output:
        . . . B
        B . . .
        B B . .
        B B B .
    *   Observation:
        *   Fortress holes ('.'):
            Row 0: 0, 1, 2
            Row 1: 1, 2, 3
            Row 2: 2, 3
            Row 3: 3
        *   Siege colors ('R'):
            Row 0: 0, 1
            Row 1: 0, 1
            Row 2: 1, 2
            Row 3: 1, 2
        *   The patterns do not match.
        *   Result: No change.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Fortress:** The 4x4 grid on the left. Contains 'B' (walls) and '.' (weak points/holes).
    *   **Siege:** The 4x4 grid on the right. Contains colored pixels (weapons) and '.' (empty space).
    *   **Buffer:** The column of 'X' separating them.
    *   **Weak Points:** The '.' cells in the Fortress.
    *   **Weapons:** The non-'.' cells in the Siege.

2.  **AFFORDANCES:**
    *   The Fortress defines a target shape (the arrangement of weak points).
    *   The Siege defines a projectile shape (the arrangement of weapons).
    *   The transformation allows the Siege color to overwrite the Fortress weak points *if and only if* the shapes match.

3.  **TRANSFORMATION RULE:**
    *   Extract the 4x4 Fortress grid (columns 0-3).
    *   Extract the 4x4 Siege grid (columns 5-8).
    *   Identify the coordinates of all '.' (weak points) in the Fortress. Let this set be $P_{fortress}$.
    *   Identify the coordinates of all non-'.' (weapons) in the Siege. Let this set be $P_{siege}$.
    *   Compare the sets $P_{fortress}$ and $P_{siege}$.
    *   **Condition:** If $P_{fortress} == P_{siege}$ (exact match of coordinates), then:
        *   Cr

... [7000 chars truncated]
alt-8 theater qwen3.5-122b: fig alone solves
"Understudies take the stage only when there is exactly one understudy for every absent lead — otherwise the curtain stays down and the original cast performs."
alt-9 gardening qwen3.5-122b: fail
"Seeds take root only when every seed finds a plot of tilled soil and no soil is left unseeded — partial planting yields nothing."
Fail (best cell_acc=0.31 at k=3)
Best Attempt
vs
Expected
Reasoning (11673 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Input Structure:**
The input grid seems to be composed of three parts based on the description:
- "Left 4x4 is the garden bed."
- "Right 4x4 is the seed tray."
- "Grey column is the bench."

Let's look at the dimensions.
The examples show input grids that are 4 rows high.
The columns seem to be: 4 columns (Garden) + 1 column (Grey/X) + 4 columns (Seeds) = 9 columns total.
Let's verify this with the examples.

Example 1 Input:
Row 1: B B B B X . . . . (4 Bs, 1 X, 4 dots) -> 9 cols
Row 2: B . . B X . M M . (4 Bs/dots, 1 X, 4 dots/Ms) -> 9 cols
Row 3: B . . B X . M M .
Row 4: B B B B X . . . .
Total size: 4x9.

Output:
4x4 grid.
Row 1: B B B B
Row 2: B M M B
Row 3: B M M B
Row 4: B B B B

Example 2 Input:
Row 1: B B B B X R R . .
Row 2: B . . B X R R . .
Row 3: B . . B X . . . .
Row 4: B B B B X . . . .
Output:
B B B B
B . . B
B . . B
B B B B

Example 3 Input:
Row 1: B B B B X . . . .
Row 2: B . . . X . O O O
Row 3: B . B B X . O . .
Row 4: B . B . X . O . O
Output:
B B B B
B O O O
B O B B
B O B O

Test Input:
Row 1: B B B B X R . . .
Row 2: . B B . X R R R R
Row 3: . B B . X R . . .
Row 4: . . . . X . . . .

**2. Conceptual Digestion:**

**CAST:**
- **Garden Bed (Left 4x4):** This seems to be the target area where changes happen. It contains Blue (B) borders and Black (.) empty spaces inside.
- **Seed Tray (Right 4x4):** This contains colored pixels (M, R, O, etc.) and empty spaces (.). These represent the "seeds".
- **Bench (Column 5, X):** This is a separator. It doesn't seem to participate in the logic other than separating the two 4x4 grids.
- **Output (4x4):** This is the transformed Garden Bed.

**AFFORDANCES:**
- The Garden Bed has a structure. In all examples, the border is Blue (B). The interior is Black (.) or sometimes Blue (B) in Example 3.
- The Seed Tray has colored pixels.
- The transformation involves moving or copying colors from the Seed Tray to the Garden Bed.
- The metaphor says: "If every seed aligns with tilled soil and every plot receives a seed, the garden blooms in color. If the match is imperfect, the bed stays as it was."
- "Tilled soil" likely refers to the empty spots (.) in the Garden Bed.
- "Seeds" are the colored pixels in the Seed Tray.
- "Aligns" suggests a positional relationship. Since both are 4x4, it's likely a direct mapping (row i, col j in Garden corresponds to row i, col j in Seed Tray).
- "Every plot receives a seed": This implies that if a spot in the Garden Bed is empty (tilled soil), it should receive a seed from the corresponding spot in the Seed Tray.
- "If the match is imperfect, the bed stays as it was": This is the tricky part. What constitutes a "match"?
    - In Example 1:
        - Garden:
          B B B B
          B . . B
          B . . B
          B B B B
        - Seeds:
          . . . .
          . M M .
          . M M .
          . . . .
        - Output:
          B B B B
          B M M B
          B M M B
          B B B B
        - Here, the empty spots (.) in the Garden (at (1,1), (1,2), (2,1), (2,2) using 0-indexed) correspond exactly to the M M / M M spots in the Seed Tray. The border B spots in Garden correspond to . spots in Seed Tray.
        - It seems the rule is: If Garden(i,j) is '.', replace it with Seed(i,j). If Garden(i,j) is 'B', keep it 'B'.
        - Wait, let's check Example 2.
    - In Example 2:
        - Garden:
          B B B B
          B . . B
          B . . B
          B B B B
        - Seeds:
          R R . .
          R R . .
          . . . .
          . . . .
        - Output:
          B B B B
          B . . B
          B . . B
          B B B B
        - Here, the Garden has '.' at (1,1), (1,2), (2,1), (2,2).
        - The Seeds have 'R' at (0,0), (0,1), (1,0), (1,1).
        - The output Garden remains unchanged (all '.' remain '.').
        - Why? The metaphor says "If every seed aligns with tilled soil and every plot receives a seed".
        - In Ex 1, the seeds (M) were exactly where the tilled soil (.) was.
        - In Ex 2, the seeds (R) are at the top left of the seed tray. The tilled soil is in the middle of the garden. They do not align positionally.
        - So, "aligns" means position (i, j) in Garden matches position (i, j) in Seed Tray.
        - Condition: "If every seed aligns with tilled soil". This implies that for every non-empty cell in the Seed Tray, the corresponding cell in the Garden Bed must be 'tilled soil' (i.e., '.').
        - Condition: "and every plot receives a seed". This implies that for every 'tilled soil' cell in the Garden Bed, there must be a seed in the corresponding cell in the Seed Tray.
        - Basically, the pattern of non-empty cells in the Seed Tray must exactly match the pattern of empty cells (.) in the Garden Bed.
        - If this condition is met, the Garden Bed's empty cells are filled with the colors from the Seed Tra

... [6691 chars truncated]

Task 786: ccd554ac

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Ex5 In
Ex5 Out
Ex6 In
Ex6 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A fabric swatch dreams of becoming the whole bolt of cloth. MARC valid 2
alt-1 biology A single cell carries the blueprint of the whole organism. Watch it undergo mito ... [100 chars truncated] fig alone solves
alt-10 astronomy A constellation is glimpsed through a small telescope aperture. Pull back, and t ... [131 chars truncated] MARC valid 5
alt-11 ocean/sailing A cartographer charts one square of ocean with its islands and depths. The admir ... [117 chars truncated] fail
alt-12 electronics An engineer etches a single circuit module onto a wafer. The module's own pin co ... [106 chars truncated] fail
alt-13 mythology A god carves a single rune into the void. The rune's own geometry compels it to ... [112 chars truncated] fail
alt-14 dance A dancer marks a small square of floor with their routine. The company then fill ... [126 chars truncated] fail
alt-15 geology A crystal seed holds a unit cell — the smallest repeating structure. Under ... [112 chars truncated] fig alone solves
alt-2 cooking A baker scores a single decorative tile into fondant, then rolls out enough copi ... [105 chars truncated] fail
alt-3 music A short musical phrase insists on being heard — it echoes across the orche ... [92 chars truncated] fail
alt-4 sports A coach draws a play on a small whiteboard, then discovers the stadium jumbotron ... [110 chars truncated] fail
alt-5 weather A single storm cell is photographed by satellite. The pressure system then clone ... [88 chars truncated] MARC valid 1
alt-6 architecture An architect designs one window panel, then lets the window's own proportions de ... [97 chars truncated] MARC valid 1
alt-7 warfare A general arranges one squadron into formation, then deploys the formation acros ... [114 chars truncated] fail
alt-8 theater A choreographer blocks one scene on a tiny stage model. Opening night, the scene ... [125 chars truncated] fail
alt-9 gardening A gardener designs a planting square — then lets the square's own dimensio ... [94 chars truncated] fail
original qwen3.5-122b: k=2
"A fabric swatch dreams of becoming the whole bolt of cloth."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11872 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A small swatch of fabric displays a motif woven from a single dye color against an undyed background." -> There is a pattern (motif) and a background.
*   "This fragment remembers the dimensions of the loom it was cut from." -> The input grid size might be relevant, or the pattern size.
*   "The swatch is placed on the loom and allowed to replicate itself" -> Tiling / Repetition.
*   "it knows how many times to repeat across the warp by counting its own columns, and how many times to stack along the weft by counting its own rows." -> This is the crucial instruction.
    *   Number of horizontal repetitions = Number of columns in the input grid? Or number of columns in the pattern?
    *   Number of vertical repetitions = Number of rows in the input grid? Or number of rows in the pattern?
*   "The pattern propagates like a crystal growing from a seed, each copy seamlessly kissing its neighbor at the edges until the bolt is complete." -> Tiling the input grid to fill a larger area.
*   "A wider swatch stretches further across; a taller swatch grows further down." -> Confirms the dimensions determine the repetition count.
*   "The dye never bleeds or shifts — every copy is a perfect echo of the original." -> No modification of the pattern itself, just repetition.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        . . A
        A A A
        A . .
        ```
        Dimensions: 3 rows, 3 columns.
    *   Output:
        ```
        . . A . . A . . A
        A A A A A A A A A
        A . . A . . A . .
        . . A . . A . . A
        A A A A A A A A A
        A . . A . . A . .
        . . A . . A . . A
        A A A A A A A A A
        A . . A . . A . .
        ```
        Dimensions: 9 rows, 9 columns.
    *   Observation:
        *   Input width = 3. Output width = 9. Repetition factor = 3.
        *   Input height = 3. Output height = 9. Repetition factor = 3.
        *   The output is the input grid tiled 3x3 times.
        *   Does the repetition count match the input dimensions? Yes, 3x3 input -> 3x3 tiling.

*   **Example 2:**
    *   Input:
        ```
        B .
        B B
        ```
        Dimensions: 2 rows, 2 columns.
    *   Output:
        ```
        B . B .
        B B B B
        B . B .
        B B B B
        ```
        Dimensions: 4 rows, 4 columns.
    *   Observation:
        *   Input width = 2. Output width = 4. Repetition factor = 2.
        *   Input height = 2. Output height = 4. Repetition factor = 2.
        *   The output is the input grid tiled 2x2 times.
        *   Does the repetition count match the input dimensions? Yes, 2x2 input -> 2x2 tiling.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** The "seed swatch". It contains the pattern to be replicated.
    *   **Output Grid:** The "bolt of fabric". It is the result of tiling the input grid.
    *   **Dimensions:** The height ($H$) and width ($W$) of the input grid determine the tiling factor.

2.  **AFFORDANCES:**
    *   The input grid can be copied.
    *   The input grid can be arranged in a larger grid structure.
    *   The dimensions of the input grid dictate the scale of the output.

3.  **TRANSFORMATION RULE:**
    *   Let the input grid have dimensions $H \times W$.
    *   The output grid is constructed by tiling the input grid $H$ times vertically and $W$ times horizontally.
    *   Output dimensions will be $(H \times H) \times (W \times W)$.
    *   Specifically, Output cell $(r, c)$ corresponds to Input cell $(r \pmod H, c \pmod W)$.

**4. Apply Rule to Test Input:**

*   **Test Input:**
    ```
    . A A . .
    A A A A A
    . A A . .
    A A A A A
    . A A . A
    ```
*   **Dimensions:**
    *   Rows ($H$): 5
    *   Columns ($W$): 5
*   **Transformation:**
    *   Tile the input grid 5 times horizontally.
    *   Tile the input grid 5 times vertically.
    *   Output dimensions: $5 \times 5 = 25$ rows, $5 \times 5 = 25$ columns.
*   **Wait, let me double check the dimensions.**
    *   Row 1: `. A A . .` (5 chars)
    *   Row 2: `A A A A A` (5 chars)
    *   Row 3: `. A A . .` (5 chars)
    *   Row 4: `A A A A A` (5 chars)
    *   Row 5: `. A A . A` (5 chars)
    *   Yes, it is a 5x5 grid.
*   **Output Construction:**
    *   The output will be a 25x25 grid.
    *   It consists of the 5x5 input pattern repeated 5 times across and 5 times down.

    Let's write out the rows.
    Input Row 1: `. A A . .`
    Input Row 2: `A A A A A`
    Input Row 3: `. A A . .`
    Input Row 4: `A A A A A`
    Input Row 5: `. A A . A`

    The output will consist of 5 blocks of these 5 rows.
    Block 1 (Rows 1-5):
    Row 1: `. A A . .` repeated 5 times -> `. A A . . . A A . . . A A . . . A A . . . A A . .`
    Row 2: `A A A A A` repeated 5 times -> `A A A

... [6944 chars truncated]
alt-1 biology qwen3.5-122b: fig alone solves
"A single cell carries the blueprint of the whole organism. Watch it undergo mitosis — not just once, but enough times that its own proportions dictate the size of the colony."
alt-10 astronomy qwen3.5-122b: k=5
"A constellation is glimpsed through a small telescope aperture. Pull back, and the universe reveals that pattern repeating like a crystalline lattice — the aperture's own shape governing the cosmic tiling."
MARC valid, solved with k=5
Prediction
vs
Expected
Reasoning (10384 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A small patch of sky (the input grid).
*   **What to do:** Zoom out to reveal the cosmic lattice.
*   **Transformation:** The patch repeats across the sky as many times as it is wide, and down as many times as it is tall.
*   **Grid details:** The full sky map is an infinite-seeming mosaic of the original star pattern, each copy abutting its neighbors with no gaps.

**Interpretation:**
The input grid is a tile. The output grid is a larger grid formed by tiling the input grid.
Specifically, "repeats across the sky as many times as it is wide" suggests the number of horizontal repetitions equals the width of the input grid.
"and down as many times as it is tall" suggests the number of vertical repetitions equals the height of the input grid.

Let $W$ be the width of the input grid (number of columns).
Let $H$ be the height of the input grid (number of rows).
The output grid should have dimensions $(H \times H) \times (W \times W)$.
Wait, let's check the examples to confirm this hypothesis.

**2. Analyze Training Examples:**

*   **Example 1:**
    *   Input: 3x3 grid.
        ```
        . . A
        A A A
        A . .
        ```
    *   Output: 9x9 grid.
        ```
        . . A . . A . . A
        A A A A A A A A A
        A . . A . . A . .
        . . A . . A . . A
        A A A A A A A A A
        A . . A . . A . .
        . . A . . A . . A
        A A A A A A A A A
        A . . A . . A . .
        ```
    *   Analysis: Input width $W=3$, height $H=3$. Output width $9 = 3 \times 3$. Output height $9 = 3 \times 3$.
    *   Pattern: The input grid is repeated 3 times horizontally and 3 times vertically.
    *   Hypothesis confirmed: Output dimensions are $(H \times H) \times (W \times W)$. The content is the input grid tiled $H \times W$ times.

*   **Example 2:**
    *   Input: 2x2 grid.
        ```
        B .
        B B
        ```
    *   Output: 4x4 grid.
        ```
        B . B .
        B B B B
        B . B .
        B B B B
        ```
    *   Analysis: Input $W=2, H=2$. Output $W=4, H=4$. Tiled 2x2.
    *   Hypothesis confirmed.

*   **Example 3:**
    *   Input: 2x2 grid.
        ```
        . G
        G .
        ```
    *   Output: 4x4 grid.
        ```
        . G . G
        G . G .
        . G . G
        G . G .
        ```
    *   Analysis: Input $W=2, H=2$. Output $W=4, H=4$. Tiled 2x2.
    *   Hypothesis confirmed.

*   **Example 4:**
    *   Input: 4x4 grid.
        ```
        . . R .
        R . R .
        . R . R
        R R R .
        ```
    *   Output: 16x16 grid.
    *   Analysis: Input $W=4, H=4$. Output $W=16, H=16$. Tiled 4x4.
    *   Hypothesis confirmed.

*   **Example 5:**
    *   Input: 3x3 grid.
        ```
        R . R
        . R .
        R R R
        ```
    *   Output: 9x9 grid.
    *   Analysis: Input $W=3, H=3$. Output $W=9, H=9$. Tiled 3x3.
    *   Hypothesis confirmed.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** A "tile" or "patch".
    *   **Output Grid:** A "mosaic" or "lattice".
    *   **Elements:** Individual cells (pixels) with specific colors.

2.  **AFFORDANCES:**
    *   The input grid can be copied.
    *   The copies can be arranged in a grid structure.
    *   The arrangement dimensions depend on the input grid's dimensions.

3.  **TRANSFORMATION RULE:**
    *   Let the input grid be $I$ with height $H$ and width $W$.
    *   Construct an output grid $O$ with height $H \times H$ and width $W \times W$.
    *   For any cell $(r, c)$ in the output grid (where $0 \le r < H^2$ and $0 \le c < W^2$):
        *   The value $O[r, c]$ is equal to $I[r \pmod H, c \pmod W]$.
    *   Essentially, tile the input grid $H$ times vertically and $W$ times horizontally.

**4. Apply Rule to Test Input:**

*   **Test Input:**
    ```
    . A A . .
    A A A A A
    . A A . .
    A A A A A
    . A A . A
    ```
*   **Dimensions:**
    *   Rows ($H$): 5
    *   Columns ($W$): 5
*   **Output Dimensions:**
    *   Rows: $5 \times 5 = 25$
    *   Columns: $5 \times 5 = 25$
*   **Tiling:**
    *   The 5x5 input pattern will be repeated 5 times horizontally and 5 times vertically.
    *   Total blocks: 25 blocks of the 5x5 pattern.

**Input Grid Content:**
Row 0: `. A A . .`
Row 1: `A A A A A`
Row 2: `. A A . .`
Row 3: `A A A A A`
Row 4: `. A A . A`

**Construction Plan:**
I need to generate a 25x25 grid.
Each row of the output corresponds to a row of the input, repeated 5 times horizontally.
The sequence of rows in the output corresponds to the sequence of rows in the input, repeated 5 times vertically.

Let's denote the input rows as $R_0, R_1, R_2, R_3, R_4$.
The output rows will be:
Block 1 (Rows 0-4): $R_0, R_1, R_2, R_3, R_4$ (each expanded horizontally)
Block 2 (Rows 5-9): $R_0, R_1, R_2, R_3, R_4$ (each expanded horizontally)
Block 3 (Rows 10-14):

... [5390 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fail
"A cartographer charts one square of ocean with its islands and depths. The admiralty then tiles the chart to fill the entire navigation table — the chart's own grid lines deciding the mosaic."
Fail (best cell_acc=0.04 at k=1)
Best Attempt
vs
Expected
Reasoning (11359 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A single nautical chart tile.
*   **What to do:** Tile the chart across the navigation table.
*   **Specifics:** "lay as many copies across as the chart has longitude lines, and stack as many down as it has latitude lines."
*   **Grid details:** "seamless patchwork of identical charts, every island and depth marking recurring in perfect periodicity."

**Interpretation:**
The input is a small grid (the "chart tile"). The output is a larger grid created by repeating (tiling) the input grid.
The description says "lay as many copies across as the chart has longitude lines". In grid terms, "longitude lines" usually correspond to columns. So, if the input has $C$ columns, repeat the input $C$ times horizontally.
It also says "stack as many down as it has latitude lines". In grid terms, "latitude lines" usually correspond to rows. So, if the input has $R$ rows, repeat the input $R$ times vertically.

Let's verify this interpretation with the Training Example.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    . . A
    A A A
    A . .
    ```
    Dimensions: 3 rows, 3 columns.
*   **Output:**
    ```
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    ```
    Dimensions: 9 rows, 9 columns.
*   **Analysis:**
    Input width = 3. Output width = 9. $9 = 3 \times 3$.
    Input height = 3. Output height = 9. $9 = 3 \times 3$.
    The output consists of the input pattern repeated 3 times horizontally and 3 times vertically.
    This matches the metaphor: "as many copies across as the chart has longitude lines" (3 columns -> 3 copies across) and "stack as many down as it has latitude lines" (3 rows -> 3 copies down).

**3. Analyze Test Input:**
*   **Input:**
    ```
    . A A . .
    A A A A A
    . A A . .
    A A A A A
    . A A . A
    ```
*   **Dimensions:**
    Rows ($R$) = 5
    Columns ($C$) = 5
*   **Transformation Rule:**
    Repeat the input grid $C$ times horizontally and $R$ times vertically.
    Since $R=5$ and $C=5$, the output will be a $25 \times 25$ grid.
    Wait, let me double check the "longitude lines" and "latitude lines" phrasing.
    Usually, longitude lines run North-South (vertical lines), defining columns. Latitude lines run East-West (horizontal lines), defining rows.
    "as the chart has longitude lines" -> Number of columns.
    "stack as many down as it has latitude lines" -> Number of rows.
    So, Horizontal Repetition Count = Input Width.
    Vertical Repetition Count = Input Height.

    Input Width = 5.
    Input Height = 5.
    Output Width = $5 \times 5 = 25$.
    Output Height = $5 \times 5 = 25$.

    Let's check the content.
    Input Row 1: `. A A . .`
    Input Row 2: `A A A A A`
    Input Row 3: `. A A . .`
    Input Row 4: `A A A A A`
    Input Row 5: `. A A . A`

    The output will consist of 5 blocks of rows. Each block of rows is identical to the input rows.
    Within each row, the pattern `. A A . .` will be repeated 5 times.

    Let's construct the first row of the output.
    Input Row 1: `. A A . .`
    Repeated 5 times: `. A A . .` + `. A A . .` + `. A A . .` + `. A A . .` + `. A A . .`
    Result: `. A A . . . A A . . . A A . . . A A . . . A A . .`

    Let's construct the second row of the output.
    Input Row 2: `A A A A A`
    Repeated 5 times: `A A A A A` + `A A A A A` + ...
    Result: `A A A A A A A A A A A A A A A A A A A A A A A A A`

    Let's construct the third row of the output.
    Input Row 3: `. A A . .`
    Same as Row 1.

    Let's construct the fourth row of the output.
    Input Row 4: `A A A A A`
    Same as Row 2.

    Let's construct the fifth row of the output.
    Input Row 5: `. A A . A`
    Repeated 5 times: `. A A . A` + `. A A . A` + ...
    Result: `. A A . A . A A . A . A A . A . A A . A . A A . A`

    Then this block of 5 rows is repeated 5 times vertically.
    So Rows 1-5 of output = Rows 1-5 of input tiled horizontally.
    Rows 6-10 of output = Rows 1-5 of input tiled horizontally.
    ...
    Rows 21-25 of output = Rows 1-5 of input tiled horizontally.

**4. Conceptual Digestion:**
1.  **CAST:**
    *   **Input Grid:** The "nautical chart tile". It contains the pattern to be replicated.
    *   **Output Grid:** The "navigation table". It is the canvas where the tiling happens.
    *   **Elements:** Colored cells (represented by characters). They are passive; they just move/replicate.
2.  **AFFORDANCES:**
    *   The grid structure allows for repetition.
    *   The dimensions of the input grid dictate the repetition factor.
3.  **TRANSFORMATION RULE:**
    *   Let Input Grid be $G$ with dimensions $H \times W$.
    *   Output Grid $G'$ has dimensions $(H \times H) \times (W \

... [6386 chars truncated]
alt-12 electronics qwen3.5-122b: fail
"An engineer etches a single circuit module onto a wafer. The module's own pin count determines how many copies are stamped across the silicon — width pins across, height pins down."
Fail (best cell_acc=0.04 at k=1)
Best Attempt
vs
Expected
Reasoning (11912 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A small circuit module: colored traces and components on a dark substrate.
*   **What to do:** Stamp the module across the wafer: as many copies horizontally as the module has columns of pins, and as many vertically as it has rows of pins.
*   **Grid details:** The finished wafer is a uniform array of identical modules, every trace and pad in perfect registration with its neighbors.

**Interpretation:**
*   The input grid represents a "module".
*   The output grid represents the "wafer" created by tiling this module.
*   The tiling dimensions are determined by the dimensions of the input module itself.
*   Specifically: "as many copies horizontally as the module has columns of pins, and as many vertically as it has rows of pins."
*   Wait, let's look at the wording carefully: "as many copies horizontally as the module has columns of pins". This usually implies the width of the output is `input_width * input_width`. Similarly, height is `input_height * input_height`.
*   Let's check the training example to verify this hypothesis.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    . . A
    A A A
    A . .
    ```
    Dimensions: 3 rows, 3 columns.
*   **Output:**
    ```
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    ```
    Dimensions: 9 rows, 9 columns.
*   **Relationship:**
    *   Input Width = 3. Output Width = 9. (3 * 3)
    *   Input Height = 3. Output Height = 9. (3 * 3)
    *   The output consists of the input pattern repeated 3 times horizontally and 3 times vertically.
    *   This matches the description: "as many copies horizontally as the module has columns... and as many vertically as it has rows".
    *   So, if Input is $H \times W$, Output is $(H \times H) \times (W \times W)$.
    *   Wait, the description says "columns of pins" and "rows of pins". In the context of the grid, "columns" usually means width ($W$) and "rows" means height ($H$).
    *   So, Repetition Count Horizontal = $W$. Repetition Count Vertical = $H$.
    *   Output Width = $W \times W$. Output Height = $H \times H$.
    *   Let's check the content.
        *   Row 1 of Output: Row 1 of Input repeated 3 times.
        *   Row 2 of Output: Row 2 of Input repeated 3 times.
        *   Row 3 of Output: Row 3 of Input repeated 3 times.
        *   Row 4 of Output: Row 1 of Input repeated 3 times.
        *   ...
        *   Essentially, the input grid is tiled $W \times H$ times.

**3. Analyze Test Input:**
*   **Input Grid:**
    ```
    . A A . .
    A A A A A
    . A A . .
    A A A A A
    . A A . A
    ```
*   **Dimensions:**
    *   Rows ($H$) = 5
    *   Columns ($W$) = 5
*   **Transformation Rule:**
    *   Tile the input grid $W$ times horizontally and $H$ times vertically.
    *   Since $W=5$ and $H=5$, the output will be a $25 \times 25$ grid.
    *   The pattern is simply the input grid repeated.
    *   Output Row $i$ corresponds to Input Row $(i \pmod H)$.
    *   Output Column $j$ corresponds to Input Column $(j \pmod W)$.
    *   Actually, since it's a direct tiling, Output cell $(r, c)$ = Input cell $(r \pmod H, c \pmod W)$.

**4. Step-by-Step Construction:**
*   Input Rows:
    1.  `. A A . .`
    2.  `A A A A A`
    3.  `. A A . .`
    4.  `A A A A A`
    5.  `. A A . A`

*   Output Construction:
    *   The output will have 5 blocks of rows vertically. Each block is a copy of the 5 input rows.
    *   Within each row, the 5 input columns are repeated 5 times horizontally.

    *   **Block 1 (Rows 1-5):**
        *   Row 1: `. A A . .` repeated 5 times -> `. A A . . . A A . . . A A . . . A A . . . A A . .`
        *   Row 2: `A A A A A` repeated 5 times -> `A A A A A A A A A A A A A A A A A A A A A A A A A`
        *   Row 3: `. A A . .` repeated 5 times -> `. A A . . . A A . . . A A . . . A A . . . A A . .`
        *   Row 4: `A A A A A` repeated 5 times -> `A A A A A A A A A A A A A A A A A A A A A A A A A`
        *   Row 5: `. A A . A` repeated 5 times -> `. A A . A . A A . A . A A . A . A A . A . A A . A`

    *   **Block 2 (Rows 6-10):** Same as Block 1.
    *   **Block 3 (Rows 11-15):** Same as Block 1.
    *   **Block 4 (Rows 16-20):** Same as Block 1.
    *   **Block 5 (Rows 21-25):** Same as Block 1.

**5. Verification:**
*   Input dimensions: 5x5.
*   Output dimensions: 25x25.
*   Logic: Tiling the input grid $N \times N$ times where $N$ is the dimension (since it's square).
*   Wait, is it always square? The description says "columns of pins" and "rows of pins".
    *   Example 1: Input 3x3. Output 9x9. Repetition 3x3.
    *   Test Input: 5x5. Output 25x25. Repetition 5x5.
    *   The rule holds.

**6. Formatting the Output:**
*   I nee

... [6933 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"A god carves a single rune into the void. The rune's own geometry compels it to propagate — its width spawning echoes across the horizon, its height summoning reflections into the abyss."
Fail (best cell_acc=0.99 at k=2)
Best Attempt
vs
Expected
Reasoning (10473 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "A sacred rune: colored sigils inscribed against the dark primordial void." -> The input grid is the "rune".
*   "The rune obeys its nature and replicates: it manifests across the firmament as many times as it has columns, and descends as many times as it has rows." -> This suggests tiling or repeating the input grid.
    *   "as many times as it has columns" -> Horizontal repetition count = number of columns in input.
    *   "descends as many times as it has rows" -> Vertical repetition count = number of rows in input.
*   "Grid details: The cosmos is inscribed with a perfect lattice of identical runes, each sigil touching its twin, the void between them shared and seamless." -> This confirms it's a direct tiling/repetition without gaps.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 3x3 grid.
        ```
        . . A
        A A A
        A . .
        ```
    *   Output: 9x9 grid.
        *   Rows: 9. Input rows: 3. 9 / 3 = 3.
        *   Cols: 9. Input cols: 3. 9 / 3 = 3.
    *   Wait, the description says "as many times as it has columns" (3 times horizontally) and "descends as many times as it has rows" (3 times vertically).
    *   Input dimensions: $H_{in} = 3, W_{in} = 3$.
    *   Output dimensions: $H_{out} = 9, W_{out} = 9$.
    *   Repetition factor: $H_{in}$ vertically, $W_{in}$ horizontally.
    *   Let's check the content.
        *   Top-left 3x3 block matches input.
        *   Top-middle 3x3 block matches input.
        *   Top-right 3x3 block matches input.
        *   Middle-left 3x3 block matches input.
        *   ... and so on.
    *   It looks like the input grid is tiled $W_{in} \times H_{in}$ times.
    *   Wait, let's re-read carefully: "manifests across the firmament as many times as it has columns". Input has 3 columns. So it repeats 3 times horizontally.
    *   "descends as many times as it has rows". Input has 3 rows. So it repeats 3 times vertically.
    *   Total output size: $(H_{in} \times H_{in}) \times (W_{in} \times W_{in})$.
    *   Example 1 Input: 3x3. Output: 9x9. Matches.

*   **Example 2:**
    *   Input: 2x2 grid.
        ```
        B .
        B B
        ```
    *   Output: 4x4 grid.
        ```
        B . B .
        B B B B
        B . B .
        B B B B
        ```
    *   Input dimensions: $H_{in} = 2, W_{in} = 2$.
    *   Output dimensions: $H_{out} = 4, W_{out} = 4$.
    *   Repetition: 2 times horizontally, 2 times vertically.
    *   Matches the rule: Repeat $W_{in}$ times horizontally, $H_{in}$ times vertically.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** The "Rune" or "Sigil". It contains colored cells (A, B, etc.) and empty cells (.).
    *   **Output Grid:** The "Firmament" or "Cosmos". It is composed of multiple copies of the Input Grid.

2.  **AFFORDANCES:**
    *   The Input Grid can be copied.
    *   The copies can be arranged in a grid pattern.
    *   The arrangement dimensions depend on the Input Grid's dimensions.

3.  **TRANSFORMATION RULE:**
    *   Let the input grid be $G$ with height $H$ and width $W$.
    *   The output grid $G'$ is constructed by tiling $G$.
    *   The number of horizontal repetitions is $W$.
    *   The number of vertical repetitions is $H$.
    *   Therefore, the output grid has height $H \times H$ and width $W \times W$.
    *   Specifically, $G'[i][j] = G[i \pmod H][j \pmod W]$.
    *   Wait, let's verify the repetition count again.
    *   Example 1: Input 3x3. Output 9x9. Repetition 3x3.
    *   Example 2: Input 2x2. Output 4x4. Repetition 2x2.
    *   Rule: Tile the input grid $W$ times horizontally and $H$ times vertically.

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . A A . .
    A A A A A
    . A A . .
    A A A A A
    . A A . A
    ```
*   **Dimensions:**
    *   Rows ($H$): 5
    *   Columns ($W$): 5
*   **Transformation:**
    *   Horizontal repetitions: $W = 5$.
    *   Vertical repetitions: $H = 5$.
    *   Output Dimensions: $5 \times 5 = 25$ rows, $5 \times 5 = 25$ columns.
*   **Construction:**
    *   The output will consist of the 5x5 input pattern repeated 5 times across and 5 times down.
    *   Essentially, the output is a 25x25 grid where every 5x5 block is identical to the input.

**Let's write down the Input Grid explicitly:**
Row 0: `. A A . .`
Row 1: `A A A A A`
Row 2: `. A A . .`
Row 3: `A A A A A`
Row 4: `. A A . A`

**Output Structure:**
The output will have 25 rows.
Rows 0-4: Input Row 0 repeated 5 times horizontally.
Rows 5-9: Input Row 1 repeated 5 times horizontally.
Rows 10-14: Input Row 2 repeated 5 times horizontally.
Rows 15-19: Input Row 3 repeated 5 times horizontally.
Rows 20-24: Input Row 4 repeated 5 times horizontally.

Wait, looking at the pattern of repetition.
If I tile the grid $W$ times horizontally, row $r$ of the

... [5506 chars truncated]
alt-14 dance qwen3.5-122b: fail
"A dancer marks a small square of floor with their routine. The company then fills the ballroom — each dancer performing the same steps, the original square's proportions deciding how many dancers fit."
Fail (best cell_acc=0.04 at k=1)
Best Attempt
vs
Expected
Reasoning (12204 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A small dance floor tile: colored footprints and positions against dark empty floor." -> This suggests the input is a small pattern (tile).
*   "What to do: Fill the ballroom: place as many dancers across as the tile has steps wide, and as many rows as the tile has steps deep." -> This suggests tiling or repeating the input pattern.
*   "Each performer mirrors the original routine." -> This might imply reflection, but let's check the examples.
*   "Grid details: The ballroom is a grid of synchronized dancers, every footprint and pause replicated — the floor a seamless repetition of the original choreography." -> This strongly suggests a simple repetition (tiling) of the input grid to fill a larger output grid. The phrase "mirrors the original routine" might be poetic for "copies the pattern". Let's verify with the examples.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
. . A
A A A
A . .
```
Dimensions: 3 rows, 3 columns.

Output:
```
. . A . . A . . A
A A A A A A A A A
A . . A . . A . .
. . A . . A . . A
A A A A A A A A A
A . . A . . A . .
. . A . . A . . A
A A A A A A A A A
A . . A . . A . .
```
Dimensions: 9 rows, 9 columns.

Observation:
The input is 3x3.
The output is 9x9.
9 is 3 * 3.
It looks like the input pattern is repeated 3 times horizontally and 3 times vertically.
Let's check the content.
Row 1 of Input: `. . A`
Row 1 of Output: `. . A . . A . . A` -> This is Input Row 1 repeated 3 times.
Row 2 of Input: `A A A`
Row 2 of Output: `A A A A A A A A A` -> This is Input Row 2 repeated 3 times.
Row 3 of Input: `A . .`
Row 3 of Output: `A . . A . . A . .` -> This is Input Row 3 repeated 3 times.

Row 4 of Output matches Row 1 of Output.
Row 5 of Output matches Row 2 of Output.
Row 6 of Output matches Row 3 of Output.
...
Row 7 matches Row 1.
Row 8 matches Row 2.
Row 9 matches Row 3.

So the transformation rule is: **Tile the input grid $N \times N$ times to create an output grid of size $(N \times H) \times (N \times W)$**, where $H$ and $W$ are the height and width of the input grid.
Wait, let's look at the dimensions again.
Input: 3x3.
Output: 9x9.
Multiplier is 3.
Is the multiplier always equal to the dimension size?
Input width = 3. Output width = 9. Multiplier = 3.
Input height = 3. Output height = 9. Multiplier = 3.

Let's check the Test Input to see if this hypothesis holds.

**3. Analyze the Test Input:**
Input:
```
. A A . .
A A A A A
. A A . .
A A A A A
. A A . A
```
Dimensions:
Rows: 5
Columns: 5

If the rule is "Tile the input $N \times N$ times where $N$ is the dimension size", then:
Input is 5x5.
Output should be $(5 \times 5) \times (5 \times 5) = 25 \times 25$.
The pattern should be the input grid repeated 5 times horizontally and 5 times vertically.

Let's re-read the metaphorical description to ensure I'm not missing a nuance about "mirrors".
"Each performer mirrors the original routine."
In Example 1, there is no mirroring (reflection). It is direct repetition.
`. . A` becomes `. . A . . A . . A`.
If it were mirrored, it might look like `. . A A . .` or something.
The text says "mirrors the original routine" in the sense of "copies the behavior/pattern", not geometric reflection. "Synchronized dancers" implies identical copies. "Seamless repetition" confirms tiling.

So the rule is:
Given an input grid of size $H \times W$.
The output grid is constructed by repeating the input grid $H$ times vertically and $W$ times horizontally?
In Example 1: $H=3, W=3$. Output is $3H \times 3W$.
So the repetition factor is equal to the dimension size.
Let's check if the repetition factor is always the dimension size.
Example 1: Input 3x3. Output 9x9. Factor 3.
Test Input: Input 5x5. Output should be 25x25. Factor 5.

Wait, is there any other interpretation?
"place as many dancers across as the tile has steps wide" -> Width of output = Width of tile * Width of tile?
"and as many rows as the tile has steps deep" -> Height of output = Height of tile * Height of tile?
Yes, "steps wide" usually refers to the width of the tile. If the tile is 5 steps wide, we place 5 dancers across? No, "place as many dancers across as the tile has steps wide".
If the tile is 5 steps wide, does that mean the output width is 5 * 5?
Or does it mean the output width is just 5?
In Example 1: Tile is 3 steps wide. Output is 9 steps wide.
So "place as many dancers across" likely means "repeat the tile pattern across".
If the tile is $W$ wide, and we repeat it $W$ times, the total width is $W^2$.
The description says "place as many dancers across as the tile has steps wide". This phrasing is slightly ambiguous.
Interpretation A: The number of *tiles* across is equal to the width of the tile. (Width = $W \times W$).
Interpretation B: The number of *dancers* (pixels) across is equal to the width of th

... [7243 chars truncated]
alt-15 geology qwen3.5-122b: fig alone solves
"A crystal seed holds a unit cell — the smallest repeating structure. Under pressure, the crystal grows, stacking that cell into a lattice whose extent is governed by the cell's own axes."
alt-2 cooking qwen3.5-122b: fail
"A baker scores a single decorative tile into fondant, then rolls out enough copies to frost the entire cake — the tile's own shape decides how many cuts to make in each direction."
Fail (best cell_acc=0.04 at k=4)
Best Attempt
vs
Expected
Reasoning (11342 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A small fondant tile with colored sugar decorations pressed into a dark chocolate base.
    *   This implies the input grid is a "tile" or a pattern unit.
    *   The "dark chocolate base" likely corresponds to the background color (black `.`).
    *   The "colored sugar decorations" are the non-black pixels.
*   **What to do:** Repeat the tile across the countertop: lay as many copies side-by-side as the tile is wide, and stack as many rows as the tile is tall.
    *   "Repeat the tile": This suggests tiling or repeating the input pattern.
    *   "lay as many copies side-by-side as the tile is wide": If the input width is $W$, the output width should be $W \times W$.
    *   "stack as many rows as the tile is tall": If the input height is $H$, the output height should be $H \times H$.
    *   "seamless mosaic of identical fondant squares": The output is formed by repeating the input grid $W$ times horizontally and $H$ times vertically.
    *   "No gaps, no overlaps": Standard tiling.
    *   "every sugar crystal in its mirrored position": This part is slightly confusing. "Mirrored position" might imply reflection, but looking at the examples will clarify if it's simple repetition or reflection. Let's look at the examples.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 3x3 grid.
        ```
        . . A
        A A A
        A . .
        ```
    *   Output: 9x9 grid.
        *   Input Width ($W$) = 3. Input Height ($H$) = 3.
        *   Output Width = 9 ($3 \times 3$). Output Height = 9 ($3 \times 3$).
        *   Let's check the pattern.
        *   Top-left 3x3 block of output:
            ```
            . . A
            A A A
            A . .
            ```
            Matches input.
        *   Top-middle 3x3 block:
            ```
            . . A
            A A A
            A . .
            ```
            Matches input.
        *   Top-right 3x3 block:
            ```
            . . A
            A A A
            A . .
            ```
            Matches input.
        *   Middle-left 3x3 block:
            ```
            . . A
            A A A
            A . .
            ```
            Matches input.
        *   It seems to be a simple repetition (tiling) of the input grid.
        *   Wait, let's look closer at the "mirrored position" phrase in the description. "every sugar crystal in its mirrored position".
        *   Let's check Example 1 output again.
            Row 1: `. . A . . A . . A` -> Input Row 1 repeated 3 times.
            Row 2: `A A A A A A A A A` -> Input Row 2 repeated 3 times.
            Row 3: `A . . A . . A . .` -> Input Row 3 repeated 3 times.
            Row 4: `. . A . . A . . A` -> Input Row 1 repeated 3 times.
            ...
            It looks like simple repetition (tiling). The phrase "mirrored position" might be flavor text or I might be misinterpreting it. Or maybe it means the position relative to the tile boundaries? No, "identical fondant squares" suggests no mirroring/flipping. Let's check other examples to be sure.

*   **Example 2:**
    *   Input: 2x2 grid.
        ```
        B .
        B B
        ```
    *   Output: 4x4 grid.
        *   Input Width = 2, Height = 2. Output Width = 4, Height = 4.
        *   Output Row 1: `B . B .` -> Input Row 1 (`B .`) repeated 2 times.
        *   Output Row 2: `B B B B` -> Input Row 2 (`B B`) repeated 2 times.
        *   Output Row 3: `B . B .` -> Input Row 1 repeated 2 times.
        *   Output Row 4: `B B B B` -> Input Row 2 repeated 2 times.
    *   This confirms the tiling hypothesis: Output is the input grid repeated $W$ times horizontally and $H$ times vertically.

*   **Example 3:**
    *   Input: 2x2 grid.
        ```
        . G
        G .
        ```
    *   Output: 4x4 grid.
        *   Output Row 1: `. G . G` -> Input Row 1 repeated.
        *   Output Row 2: `G . G .` -> Input Row 2 repeated.
        *   Output Row 3: `. G . G` -> Input Row 1 repeated.
        *   Output Row 4: `G . G .` -> Input Row 2 repeated.
    *   Confirms tiling.

*   **Example 4:**
    *   Input: 4x4 grid.
        ```
        . . R .
        R . R .
        . R . R
        R R R .
        ```
    *   Output: 16x16 grid.
        *   Input Width = 4, Height = 4. Output Width = 16, Height = 16.
        *   Output Row 1: `. . R . . . R . . . R . . . R .` -> Input Row 1 repeated 4 times.
        *   Output Row 2: `R . R . R . R . R . R . R . R .` -> Input Row 2 repeated 4 times.
        *   ...
        *   Output Row 5: `. . R . . . R . . . R . . . R .` -> Input Row 1 repeated 4 times.
    *   Confirms tiling.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** A "tile" or "pattern unit". It contains a background color (usually `.`) and foreground 

... [6408 chars truncated]
alt-3 music qwen3.5-122b: fail
"A short musical phrase insists on being heard — it echoes across the orchestra pit, each instrument picking it up until the phrase's own meter fills the entire score."
Fail (best cell_acc=0.04 at k=2)
Best Attempt
vs
Expected
Reasoning (11594 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A brief motif: colored notes against silent rests on a small staff." -> The input grid is a small pattern (motif).
*   "What to do: Let the motif repeat itself: it sounds across as many voices as it has beats, and cascades down through as many measures as it has lines." -> This suggests tiling or repeating the input pattern.
*   "Grid details: The full score is a seamless wall of sound — the motif tiled perfectly so that every entrance and rest aligns with its neighbors." -> This confirms the output is a larger grid formed by repeating the input grid.
*   "as many voices as it has beats" -> Width of output = Width of input * something? Or maybe the output dimensions are related to the input dimensions.
*   "cascades down through as many measures as it has lines" -> Height of output = Height of input * something?

Let's look at the training examples to determine the repetition factor.

**2. Analyze Training Example 1:**
*   Input:
    ```
    . . A
    A A A
    A . .
    ```
    Dimensions: 3 rows, 3 columns.
*   Output:
    ```
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    ```
    Dimensions: 9 rows, 9 columns.
*   Relationship:
    *   Input Width = 3, Output Width = 9. Factor = 3.
    *   Input Height = 3, Output Height = 9. Factor = 3.
    *   It looks like the input pattern is tiled 3x3 times.
    *   Wait, let's check the content.
    *   Row 1 of Output: `. . A` repeated 3 times.
    *   Row 2 of Output: `A A A` repeated 3 times.
    *   Row 3 of Output: `A . .` repeated 3 times.
    *   Row 4 of Output: Same as Row 1.
    *   Row 5 of Output: Same as Row 2.
    *   Row 6 of Output: Same as Row 3.
    *   Row 7 of Output: Same as Row 1.
    *   Row 8 of Output: Same as Row 2.
    *   Row 9 of Output: Same as Row 3.
    *   So the output is the input grid repeated 3 times horizontally and 3 times vertically.
    *   Why 3? The input is 3x3. Maybe the repetition factor is equal to the dimension size? Or maybe it's always 3x3 tiling regardless of input size? Or maybe it's related to the number of non-black cells?
    *   Let's check Example 2.

**3. Analyze Training Example 2:**
*   Input:
    ```
    B .
    B B
    ```
    Dimensions: 2 rows, 2 columns.
*   Output:
    ```
    B . B .
    B B B B
    B . B .
    B B B B
    ```
    Dimensions: 4 rows, 4 columns.
*   Relationship:
    *   Input Width = 2, Output Width = 4. Factor = 2.
    *   Input Height = 2, Output Height = 4. Factor = 2.
    *   The input pattern is tiled 2x2 times.
    *   Row 1: `B .` repeated 2 times.
    *   Row 2: `B B` repeated 2 times.
    *   Row 3: `B .` repeated 2 times.
    *   Row 4: `B B` repeated 2 times.

**4. Deduce the Transformation Rule:**
*   In Example 1 (3x3 input), the output is 3x3 tiling (9x9 output).
*   In Example 2 (2x2 input), the output is 2x2 tiling (4x4 output).
*   Hypothesis: The input grid of size $H \times W$ is tiled $H \times W$ times? No, that would mean Output Height = $H^2$ and Output Width = $W^2$.
    *   Ex 1: $H=3, W=3$. Output $9 \times 9$. $3^2 = 9$. Matches.
    *   Ex 2: $H=2, W=2$. Output $4 \times 4$. $2^2 = 4$. Matches.
*   Alternative Hypothesis: The input grid is tiled $N \times N$ times where $N$ is the dimension size (assuming square input).
    *   Ex 1: Input 3x3. Tile 3x3.
    *   Ex 2: Input 2x2. Tile 2x2.
*   Let's check the Test Input.
    *   Input:
        ```
        . A A . .
        A A A A A
        . A A . .
        A A A A A
        . A A . A
        ```
    *   Dimensions: 5 rows, 5 columns.
    *   If the rule is "Tile the input grid $N \times N$ times where $N$ is the dimension size", then for a 5x5 input, the output should be a 5x5 tiling of the input.
    *   Output Dimensions: $5 \times 5 = 25$ rows, $5 \times 5 = 25$ columns.
    *   Wait, is it always square?
    *   Ex 1: 3x3 -> 9x9.
    *   Ex 2: 2x2 -> 4x4.
    *   Test Input: 5x5.
    *   It seems consistent. The rule is: Given an $N \times N$ input grid, create an output grid of size $N^2 \times N^2$ by tiling the input grid $N$ times horizontally and $N$ times vertically.
    *   Let's re-read the metaphor. "sounds across as many voices as it has beats" (Width factor = Width?), "cascades down through as many measures as it has lines" (Height factor = Height?).
    *   "Beats" usually corresponds to columns (horizontal). "Lines" usually corresponds to rows (vertical).
    *   So, repeat horizontally $W$ times, repeat vertically $H$ times.
    *   Since the inputs are square ($W=H=N$), the output is $N \times N$ tiling.
    *   Test Input is 5x5. So I need to tile it 5 times horizontally and 5 times vertically.

**5. Conceptual Digestion:**
1.  *

... [6633 chars truncated]
alt-4 sports qwen3.5-122b: fail
"A coach draws a play on a small whiteboard, then discovers the stadium jumbotron mirrors the diagram across the whole field — the play's dimensions dictating how many times it appears."
Fail (best cell_acc=0.04 at k=1)
Best Attempt
vs
Expected
Reasoning (10707 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A small play diagram with colored player positions on a dark field.
*   **What to do:** Project the diagram onto the full field: repeat it horizontally as many times as the diagram is wide, and vertically as many times as the diagram is tall.
*   **Grid details:** The jumbotron shows a massive formation of identical play diagrams tiled edge-to-edge, filling the screen perfectly.

**Interpretation:**
The input grid represents a "small play diagram".
The output grid represents the "full field".
The transformation rule is tiling/repeating the input grid.
Specifically: "repeat it horizontally as many times as the diagram is wide, and vertically as many times as the diagram is tall."
Let $W$ be the width of the input grid (number of columns).
Let $H$ be the height of the input grid (number of rows).
The output grid should be constructed by tiling the input grid $W$ times horizontally and $H$ times vertically.
So the output dimensions will be $(H \times H)$ rows and $(W \times W)$ columns.
Wait, let's re-read carefully: "repeat it horizontally as many times as the diagram is wide".
If the diagram is $W$ wide, repeat it $W$ times. Total width = $W \times W$.
"and vertically as many times as the diagram is tall".
If the diagram is $H$ tall, repeat it $H$ times. Total height = $H \times H$.

Let's check the Training Example 1 to verify this hypothesis.

**2. Analyze Training Example 1:**
Input:
```
. . A
A A A
A . .
```
Dimensions: Height $H = 3$, Width $W = 3$.
According to the rule:
Repeat horizontally $W=3$ times.
Repeat vertically $H=3$ times.
Expected Output Dimensions: Height $3 \times 3 = 9$, Width $3 \times 3 = 9$.

Let's look at the provided Output for Example 1:
```
. . A . . A . . A
A A A A A A A A A
A . . A . . A . .
. . A . . A . . A
A A A A A A A A A
A . . A . . A . .
. . A . . A . . A
A A A A A A A A A
A . . A . . A . .
```
Dimensions: 9 rows, 9 columns.
Structure:
Rows 1-3: Input row 1 repeated 3 times, Input row 2 repeated 3 times, Input row 3 repeated 3 times.
Rows 4-6: Same as Rows 1-3.
Rows 7-9: Same as Rows 1-3.
This confirms the tiling hypothesis. The input pattern is tiled $W \times W$ times (width-wise) and $H \times H$ times (height-wise).
Actually, looking at the output:
Row 1 of output is `Input Row 1` + `Input Row 1` + `Input Row 1`.
Row 2 of output is `Input Row 2` + `Input Row 2` + `Input Row 2`.
Row 3 of output is `Input Row 3` + `Input Row 3` + `Input Row 3`.
Row 4 of output is `Input Row 1` + `Input Row 1` + `Input Row 1`.
...
So yes, the input grid is repeated $W$ times horizontally and $H$ times vertically.

**3. Analyze Test Input:**
Input Grid:
```
. A A . .
A A A A A
. A A . .
A A A A A
. A A . A
```
Let's determine dimensions.
Row 1: `. A A . .` (5 chars)
Row 2: `A A A A A` (5 chars)
Row 3: `. A A . .` (5 chars)
Row 4: `A A A A A` (5 chars)
Row 5: `. A A . A` (5 chars)

Height $H = 5$.
Width $W = 5$.

**4. Apply Transformation Rule:**
Rule: Tile the input grid $W$ times horizontally and $H$ times vertically.
$W = 5$, $H = 5$.
Output Width = $5 \times 5 = 25$.
Output Height = $5 \times 5 = 25$.

The output will consist of 25 rows.
Each row will consist of the corresponding input row repeated 5 times.
The sequence of rows will be: Input Row 1, Input Row 2, Input Row 3, Input Row 4, Input Row 5, repeated 5 times.

Let's construct the rows.
Input Row 1: `. A A . .`
Repeated 5 times: `. A A . . . A A . . . A A . . . A A . . . A A . .`
Input Row 2: `A A A A A`
Repeated 5 times: `A A A A A A A A A A A A A A A A A A A A A A A A A`
Input Row 3: `. A A . .`
Repeated 5 times: `. A A . . . A A . . . A A . . . A A . . . A A . .`
Input Row 4: `A A A A A`
Repeated 5 times: `A A A A A A A A A A A A A A A A A A A A A A A A A`
Input Row 5: `. A A . A`
Repeated 5 times: `. A A . A . A A . A . A A . A . A A . A . A A . A`

The block of 5 rows (1-5) is repeated 5 times vertically.
So rows 1-5 are as above.
Rows 6-10 are identical to rows 1-5.
Rows 11-15 are identical to rows 1-5.
Rows 16-20 are identical to rows 1-5.
Rows 21-25 are identical to rows 1-5.

**5. Verification:**
Input:
. A A . .
A A A A A
. A A . .
A A A A A
. A A . A

Width = 5. Height = 5.
Output Width = 25. Output Height = 25.
Pattern:
Row 1: . A A . . repeated 5 times.
Row 2: A A A A A repeated 5 times.
Row 3: . A A . . repeated 5 times.
Row 4: A A A A A repeated 5 times.
Row 5: . A A . A repeated 5 times.
This block of 5 rows is repeated 5 times.

Let's double check the color codes.
. = black
A = azure
Input uses . and A.
Output should use . and A.

Let's write out the rows explicitly to ensure no copy-paste errors in thought process.
Row 1 string: `. A A . .`
Concatenated 5 times with spaces: `. A A . . . A A . . . A A . . . A A . . . A A . .`
Wait, the format requires spaces between characters.
Input row 1: `. A A . .`
Output row 1: `. A A . . . A 

... [5707 chars truncated]
alt-5 weather qwen3.5-122b: k=1
"A single storm cell is photographed by satellite. The pressure system then clones itself across the map — its own footprint determining how far the front extends."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11461 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A small weather cell: colored bands of precipitation against calm dark skies." -> This suggests the input is a small pattern (the "cell").
*   "What to do: The cell replicates across the radar screen, spawning copies equal to its own width across the horizon and copies equal to its own height from pole to equator." -> This implies tiling or repeating the input pattern.
    *   "copies equal to its own width across the horizon": If the input width is $W$, the output width should be $W \times W$? Or does it mean repeat it $W$ times horizontally?
    *   "copies equal to its own height from pole to equator": If the input height is $H$, the output height should be $H \times H$? Or does it mean repeat it $H$ times vertically?
*   "Grid details: The radar map becomes a repeating mosaic of identical storm cells, seamless and perfectly periodic." -> This confirms the tiling nature. The output is a larger grid composed of the input grid repeated.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . A
    A A A
    A . .
    ```
    Dimensions: Height $H = 3$, Width $W = 3$.
*   **Output:**
    ```
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    ```
    Dimensions: Height $H_{out} = 9$, Width $W_{out} = 9$.
*   **Relationship:**
    *   Input $3 \times 3$. Output $9 \times 9$.
    *   $9 = 3 \times 3$.
    *   The output looks like the input pattern tiled $3 \times 3$ times.
    *   Let's check the tiling.
        *   Top-left $3 \times 3$ block matches input.
        *   Top-middle $3 \times 3$ block matches input.
        *   Top-right $3 \times 3$ block matches input.
        *   Middle-left $3 \times 3$ block matches input.
        *   ... and so on.
    *   So, the rule is: Tile the input grid $H \times W$ times? No, wait.
    *   Input width $W=3$. Output width $9$. Repetition count horizontally = 3.
    *   Input height $H=3$. Output height $9$. Repetition count vertically = 3.
    *   The description says "spawning copies equal to its own width across the horizon and copies equal to its own height from pole to equator".
    *   "copies equal to its own width": Width is 3. So 3 copies horizontally.
    *   "copies equal to its own height": Height is 3. So 3 copies vertically.
    *   This matches the example perfectly. The output is the input grid repeated $W$ times horizontally and $H$ times vertically.

**3. Analyze the Test Input:**
*   **Input:**
    ```
    . A A . .
    A A A A A
    . A A . .
    A A A A A
    . A A . A
    ```
*   **Dimensions:**
    *   Height ($H$) = 5 rows.
    *   Width ($W$) = 5 columns.
*   **Transformation Rule:**
    *   Repeat the input grid $W$ times horizontally (5 times).
    *   Repeat the input grid $H$ times vertically (5 times).
    *   Output dimensions will be $(H \times H) \times (W \times W) = 25 \times 25$.
    *   Wait, let's re-read the description carefully. "spawning copies equal to its own width across the horizon".
    *   If width is 5, spawn 5 copies. Total width = $5 \times 5 = 25$.
    *   "copies equal to its own height from pole to equator".
    *   If height is 5, spawn 5 copies. Total height = $5 \times 5 = 25$.
    *   So the output should be a $25 \times 25$ grid consisting of the $5 \times 5$ input pattern tiled 5 times in each direction.

**4. Step-by-Step Construction:**
*   Input Grid ($5 \times 5$):
    Row 0: `. A A . .`
    Row 1: `A A A A A`
    Row 2: `. A A . .`
    Row 3: `A A A A A`
    Row 4: `. A A . A`

*   Horizontal Repetition (5 times):
    Each row of the output will be the corresponding input row repeated 5 times.
    Example Row 0: `. A A . .` + `. A A . .` + `. A A . .` + `. A A . .` + `. A A . .`
    Length: $5 \times 5 = 25$.

*   Vertical Repetition (5 times):
    The block of 5 rows (which is the horizontally expanded input) will be repeated 5 times.
    Total rows: $5 \times 5 = 25$.

*   Let's verify the colors.
    `.` = black
    `A` = azure
    Input contains `.` and `A`.

*   Let's construct the rows.
    Row 0 pattern: `. A A . .`
    Row 1 pattern: `A A A A A`
    Row 2 pattern: `. A A . .`
    Row 3 pattern: `A A A A A`
    Row 4 pattern: `. A A . A`

    Expanded Row 0 (5x): `. A A . . . A A . . . A A . . . A A . . . A A . .`
    Expanded Row 1 (5x): `A A A A A A A A A A A A A A A A A A A A A A A A A`
    Expanded Row 2 (5x): `. A A . . . A A . . . A A . . . A A . . . A A . .`
    Expanded Row 3 (5x): `A A A A A A A A A A A A A A A A A A A A A A A A A`
    Expanded Row 4 (5x): `. A A . A . A A . A . A A . A . A A . A . A A . A`

    The output grid consists of these 5 expanded rows repeated 5 times vertically.
    So Rows 0-4 are the expanded rows.
    Rows 5-9 

... [6470 chars truncated]
alt-6 architecture qwen3.5-122b: k=1
"An architect designs one window panel, then lets the window's own proportions determine how many panels fill the cathedral wall — width begets columns, height begets rows."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10370 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A small stained-glass panel with colored glass pieces set in a dark leading frame." This implies the input grid is a small pattern (the "panel").
*   **Task:** "Install copies of the panel into the cathedral window: as many columns as the panel has panes across, and as many rows as the panel has panes down."
*   **Output:** "The finished rose window is a grid of identical panels fitted edge to edge, each piece of colored glass in its proper place."
*   **Interpretation:** The input grid is a tile. The output grid is a tiling of this input grid. Specifically, if the input grid has dimensions $H \times W$, the output grid should be a repetition of this input grid $W$ times horizontally and $H$ times vertically. Wait, let's re-read carefully: "as many columns as the panel has panes across, and as many rows as the panel has panes down."
    *   "Panel has panes across" = Width of input grid ($W$).
    *   "Panel has panes down" = Height of input grid ($H$).
    *   So, the output grid should have $W$ columns of panels and $H$ rows of panels.
    *   Total Output Width = $W \times W$.
    *   Total Output Height = $H \times H$.
    *   Essentially, the output is the input grid tiled $W \times H$ times? No, "as many columns as the panel has panes across" means the number of *panel copies* horizontally is $W$. "as many rows as the panel has panes down" means the number of *panel copies* vertically is $H$.
    *   So if Input is $H \times W$, Output is $(H \times H) \times (W \times W)$.
    *   Let's check the training example to confirm this hypothesis.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    . . A
    A A A
    A . .
    ```
    Dimensions: Height $H=3$, Width $W=3$.
*   **Output:**
    ```
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    ```
    Dimensions: Height $9$, Width $9$.
*   **Analysis:**
    *   Input $3 \times 3$. Output $9 \times 9$.
    *   $9 = 3 \times 3$.
    *   The output consists of the input pattern repeated.
    *   Row 1 of Output: `. . A` followed by `. . A` followed by `. . A`. This is the first row of the input repeated 3 times.
    *   Row 2 of Output: `A A A` followed by `A A A` followed by `A A A`. This is the second row of the input repeated 3 times.
    *   Row 3 of Output: `A . .` followed by `A . .` followed by `A . .`. This is the third row of the input repeated 3 times.
    *   Row 4 of Output: Same as Row 1.
    *   Row 5 of Output: Same as Row 2.
    *   Row 6 of Output: Same as Row 3.
    *   Row 7 of Output: Same as Row 1.
    *   Row 8 of Output: Same as Row 2.
    *   Row 9 of Output: Same as Row 3.
    *   So, the transformation is: Tile the input grid $W$ times horizontally and $H$ times vertically.
    *   Since $W=3$ and $H=3$ in the example, the output is a $3 \times 3$ grid of the input tiles.
    *   Total size: $(H \times H) \times (W \times W)$.
    *   Wait, the description says "as many columns as the panel has panes across" ($W$) and "as many rows as the panel has panes down" ($H$).
    *   So number of tile columns = $W$. Number of tile rows = $H$.
    *   Total Output Width = $W \times W$.
    *   Total Output Height = $H \times H$.
    *   This matches the example ($3 \times 3$ input -> $9 \times 9$ output).

**3. Analyze Test Input:**
*   **Input Grid:**
    ```
    . A A . .
    A A A A A
    . A A . .
    A A A A A
    . A A . A
    ```
*   **Dimensions:**
    *   Height ($H$) = 5 rows.
    *   Width ($W$) = 5 columns.
*   **Transformation Rule:**
    *   Create an output grid where the input grid is repeated $W$ times horizontally and $H$ times vertically.
    *   Since $H=5$ and $W=5$, the output will be a $5 \times 5$ grid of the input tiles.
    *   Output Height = $5 \times 5 = 25$ rows.
    *   Output Width = $5 \times 5 = 25$ columns.
    *   Wait, let's re-read the instruction carefully. "as many columns as the panel has panes across, and as many rows as the panel has panes down."
    *   Panel panes across = Width = 5.
    *   Panel panes down = Height = 5.
    *   So we need 5 columns of panels and 5 rows of panels.
    *   Total Output Width = $5 \times 5 = 25$.
    *   Total Output Height = $5 \times 5 = 25$.
    *   The pattern is simply the input grid tiled.

**4. Step-by-Step Construction:**
*   Input Row 1: `. A A . .`
*   Input Row 2: `A A A A A`
*   Input Row 3: `. A A . .`
*   Input Row 4: `A A A A A`
*   Input Row 5: `. A A . A`

*   The output will consist of 5 blocks of rows. Each block corresponds to the 5 input rows.
*   Within each row of the output, the input row pattern is repeated 5 times.

*   **Block 1 (Rows 1-5 of Output):**
    *   Output Row 1: Input Row 1 repeated 5 times

... [5373 chars truncated]
alt-7 warfare qwen3.5-122b: fail
"A general arranges one squadron into formation, then deploys the formation across the battlefield — the squadron's own rank-and-file count dictating how many units fill the theater of war."
Fail (best cell_acc=0.04 at k=1)
Best Attempt
vs
Expected
Reasoning (11587 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A small squadron: colored soldiers standing in formation against empty dark ground." -> This suggests the input is a small pattern (the "squadron") on a background (likely black/dot).
*   "What to do: Marshal the army by copying the squadron: deploy as many units across the front as there are soldiers in a row, and as many ranks deep as there are rows in the squadron." -> This sounds like tiling or repeating the input pattern.
    *   "as many units across the front as there are soldiers in a row" -> This is slightly ambiguous. Does it mean the width of the output is `width * width`? Or does it mean repeat the pattern horizontally `width` times?
    *   "as many ranks deep as there are rows in the squadron" -> This suggests the height of the output is `height * height`.
    *   "Grid details: The battlefield is covered in a seamless grid of identical squadrons, every soldier in lockstep with their counterpart in neighboring units." -> This confirms tiling/repetition. The output is a larger grid composed of copies of the input grid.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . A
    A A A
    A . .
    ```
    Dimensions: 3 rows, 3 columns.
    Content: A 3x3 pattern.
*   **Output:**
    ```
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    ```
    Dimensions: 9 rows, 9 columns.
    Observation: The input is 3x3. The output is 9x9.
    The output consists of the input pattern repeated 3 times horizontally and 3 times vertically.
    3 (input width) * 3 (repetitions) = 9 (output width).
    3 (input height) * 3 (repetitions) = 9 (output height).
    The metaphor says "as many units across the front as there are soldiers in a row". In the input row `. . A`, there are 3 cells. Or maybe it means the width of the input grid is 3. "as many ranks deep as there are rows in the squadron". The input has 3 rows.
    So, if Input is $H \times W$, Output is $(H \times H) \times (W \times W)$? Or is it $(H \times W) \times (W \times W)$?
    In the example, $H=3, W=3$. Output is $9 \times 9$.
    Let's check the repetition logic.
    Row 1 of Output: `. . A` repeated 3 times.
    Row 2 of Output: `A A A` repeated 3 times.
    Row 3 of Output: `A . .` repeated 3 times.
    Row 4 of Output: Same as Row 1.
    Row 5 of Output: Same as Row 2.
    Row 6 of Output: Same as Row 3.
    Row 7 of Output: Same as Row 1.
    Row 8 of Output: Same as Row 2.
    Row 9 of Output: Same as Row 3.
    So the transformation is simply tiling the input grid $N \times N$ times, where $N$ is the dimension of the input grid (assuming square).
    Wait, let's look at the wording again: "deploy as many units across the front as there are soldiers in a row".
    In the input `. . A`, there are 3 columns. So repeat 3 times horizontally.
    "as many ranks deep as there are rows in the squadron".
    In the input, there are 3 rows. So repeat 3 times vertically.
    So if Input is $R \times C$, Output is $(R \times R) \times (C \times C)$.
    In the example, $R=3, C=3$. Output is $9 \times 9$.
    This matches the observation.

**3. Analyze the Test Input:**
*   **Input:**
    ```
    . A A . .
    A A A A A
    . A A . .
    A A A A A
    . A A . A
    ```
*   **Dimensions:**
    Rows ($R$) = 5
    Columns ($C$) = 5
*   **Transformation Rule:**
    Based on the training example and the metaphor:
    1.  Determine the number of rows in the input ($R$).
    2.  Determine the number of columns in the input ($C$).
    3.  The output grid will have dimensions $(R \times R) \times (C \times C)$.
    4.  The output grid is constructed by tiling the input grid $R$ times vertically and $C$ times horizontally.
    *   Wait, let's re-read the metaphor carefully. "as many units across the front as there are soldiers in a row".
        *   "soldiers in a row" could mean the number of non-background pixels, or the width of the grid.
        *   In Example 1, row 1 is `. . A`. Width is 3. Non-background is 1. The output width is 9. $3 \times 3 = 9$. So it uses the grid width.
        *   "as many ranks deep as there are rows in the squadron".
        *   In Example 1, rows = 3. Output height = 9. $3 \times 3 = 9$. So it uses the grid height.
    *   So for the Test Input:
        *   $R = 5$
        *   $C = 5$
        *   Output Height = $5 \times 5 = 25$
        *   Output Width = $5 \times 5 = 25$
        *   The pattern is the 5x5 input grid repeated 5 times horizontally and 5 times vertically.

**4. Constructing the Output:**
Input Grid ($I$):
Row 0: `. A A . .`
Row 1: `A A A A A`
Row 2: `. A A . .`
Row 3: `A A A A A`
Row 4: `. A A . A`

Output Grid ($O$):
Size: 25 rows, 25 columns.
Structure:
B

... [6626 chars truncated]
alt-8 theater qwen3.5-122b: fail
"A choreographer blocks one scene on a tiny stage model. Opening night, the scene is performed simultaneously on a grid of stages — the model's own dimensions deciding the size of the theater complex."
Fail (best cell_acc=0.80 at k=5)
Best Attempt
vs
Expected
Reasoning (11387 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A miniature stage with colored actors positioned against a dark backdrop." -> This implies the input grid is a small pattern (the "stage").
*   "What to do: Replicate the scene: build as many stages side by side as the model is wide, and stack as many tiers as the model is tall." -> This suggests tiling or repeating the input pattern.
*   "Each stage performs the identical blocking." -> The pattern is repeated exactly.
*   "Grid details: The audience sees a vast wall of identical stages, every actor in the same position, every dark space preserved — a seamless theatrical mosaic." -> This confirms the output is a larger grid formed by repeating the input grid both horizontally and vertically.
*   "build as many stages side by side as the model is wide" -> If the input width is $W$, the output width is $W \times W$? Or does it mean repeat $W$ times? Let's check the examples.
*   "stack as many tiers as the model is tall" -> If the input height is $H$, the output height is $H \times H$? Or repeat $H$ times?

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 3x3 grid.
        ```
        . . A
        A A A
        A . .
        ```
    *   Output: 9x9 grid.
        ```
        . . A . . A . . A
        A A A A A A A A A
        A . . A . . A . .
        . . A . . A . . A
        A A A A A A A A A
        A . . A . . A . .
        . . A . . A . . A
        A A A A A A A A A
        A . . A . . A . .
        ```
    *   Observation: The input is 3x3. The output is 9x9. The input pattern is repeated 3 times horizontally and 3 times vertically.
    *   Rule Hypothesis: Repeat the input grid $N$ times horizontally and $N$ times vertically, where $N$ is the dimension of the input (width/height). Since the input is square (3x3), $N=3$. Output size = $3 \times 3$ by $3 \times 3$ = 9x9.

*   **Example 2:**
    *   Input: 2x2 grid.
        ```
        B .
        B B
        ```
    *   Output: 4x4 grid.
        ```
        B . B .
        B B B B
        B . B .
        B B B B
        ```
    *   Observation: Input is 2x2. Output is 4x4. The input pattern is repeated 2 times horizontally and 2 times vertically.
    *   Rule Confirmation: If input is $H \times W$, output is $(H \times H) \times (W \times W)$? Or is it repeating $H$ times vertically and $W$ times horizontally?
    *   In Ex 1: Input 3x3. Output 9x9. Repeated 3 times in both directions.
    *   In Ex 2: Input 2x2. Output 4x4. Repeated 2 times in both directions.
    *   Let's check non-square inputs.

*   **Example 3:**
    *   Input: 2x2 grid.
        ```
        . G
        G .
        ```
    *   Output: 4x4 grid.
        ```
        . G . G
        G . G .
        . G . G
        G . G .
        ```
    *   Observation: Input 2x2. Output 4x4. Repeated 2 times in both directions.

*   **Example 4:**
    *   Input: 4x4 grid.
        ```
        . . R .
        R . R .
        . R . R
        R R R .
        ```
    *   Output: 16x16 grid.
        ```
        . . R . . . R . . . R . . . R .
        R . R . R . R . R . R . R . R .
        . R . R . R . R . R . R . R . R
        R R R . R R R . R R R . R R R .
        ... (repeats 4 times vertically)
        ```
    *   Observation: Input 4x4. Output 16x16. Repeated 4 times horizontally and 4 times vertically.
    *   Rule Confirmation: The input grid is tiled $H$ times vertically and $W$ times horizontally, where $H$ and $W$ are the height and width of the input grid. Since all examples so far are square ($H=W$), the output is $H^2 \times W^2$.

*   **Example 5:**
    *   Input: 3x3 grid.
        ```
        R . R
        . R .
        R R R
        ```
    *   Output: 9x9 grid.
        ```
        R . R R . R R . R
        . R . . R . . R .
        R R R R R R R R R
        ... (repeats 3 times vertically)
        ```
    *   Observation: Input 3x3. Output 9x9. Repeated 3 times horizontally and 3 times vertically.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** The "miniature stage". It contains colored cells (actors) and empty cells (dark backdrop).
    *   **Output Grid:** The "vast wall of identical stages". It is a larger grid composed of multiple copies of the input grid.

2.  **AFFORDANCES:**
    *   The input grid can be copied.
    *   The copies can be arranged in a grid layout.
    *   The dimensions of the arrangement depend on the dimensions of the input grid itself.

3.  **TRANSFORMATION RULE:**
    *   Let the input grid have height $H$ and width $W$.
    *   The output grid is constructed by tiling the input grid.
    *   The number of repetitions horizontally is $W$.
    *   The number of repetitions vertically is $H$.
    *   Therefore, the output grid dimensions will be $(H \times H)$ rows by $(W \times W)$ columns.
    *   Specifically, for 

... [6441 chars truncated]
alt-9 gardening qwen3.5-122b: fail
"A gardener designs a planting square — then lets the square's own dimensions tell them how many times to repeat it across the plot, filling the garden bed edge to edge."
Fail (best cell_acc=0.04 at k=1)
Best Attempt
vs
Expected
Reasoning (11959 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "What you see: A small planting template: colored flowers set among dark soil patches." -> This suggests the input grid is a small pattern (template).
*   "What to do: Lay the template down repeatedly: as many times across as there are columns in the template, and as many times down as there are rows." -> This suggests tiling or repeating the input grid.
*   "Grid details: The garden bed is a uniform quilt of identical planting squares, every flower and every bare patch in perfect periodic alignment." -> This confirms the output is a larger grid formed by repeating the input grid pattern.
*   Specifically, "as many times across as there are columns in the template" means if the input width is $W$, the output width is $W \times W$.
*   "as many times down as there are rows" means if the input height is $H$, the output height is $H \times H$.
*   So, the transformation rule is to tile the input grid $N \times N$ times, where $N$ is the dimension of the input grid (assuming square input, or width/height respectively). Let's check the examples to confirm dimensions.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    . . A
    A A A
    A . .
    ```
    Dimensions: 3 rows, 3 columns.
*   **Output:**
    ```
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    . . A . . A . . A
    A A A A A A A A A
    A . . A . . A . .
    ```
    Dimensions: 9 rows, 9 columns.
*   **Observation:** The input is $3 \times 3$. The output is $9 \times 9$.
    $9 = 3 \times 3$.
    The output consists of the input grid repeated 3 times horizontally and 3 times vertically.
    Row 1 of output = Row 1 of input + Row 1 of input + Row 1 of input.
    Row 4 of output = Row 1 of input + Row 1 of input + Row 1 of input.
    Basically, Output[i][j] = Input[i % H][j % W].
    Here $H=3, W=3$. Output size is $3H \times 3W$.

**3. Analyze Test Input:**
*   **Input:**
    ```
    . A A . .
    A A A A A
    . A A . .
    A A A A A
    . A A . A
    ```
*   **Dimensions:**
    Rows: 5
    Columns: 5
*   **Transformation Rule:** Based on the metaphor and Example 1, I need to tile this $5 \times 5$ grid $5$ times horizontally and $5$ times vertically.
    Output dimensions will be $25 \times 25$.
    Wait, let me re-read the metaphor carefully.
    "as many times across as there are columns in the template" -> Width multiplier = Input Width.
    "as many times down as there are rows" -> Height multiplier = Input Height.
    So if Input is $H \times W$, Output is $(H \times H) \times (W \times W)$.
    In Example 1: Input $3 \times 3$, Output $9 \times 9$. Multiplier is 3.
    In Test Input: Input $5 \times 5$. Multiplier should be 5.
    Output size: $25 \times 25$.

    Let's check the constraint on output size. Usually, these puzzles result in manageable grids. A $25 \times 25$ grid is quite large to write out manually, but the instruction says "write out the complete predicted output grid". I must follow the instruction.

    Let's double check the input grid content.
    Row 0: `. A A . .`
    Row 1: `A A A A A`
    Row 2: `. A A . .`
    Row 3: `A A A A A`
    Row 4: `. A A . A`

    Wait, looking closely at the last row of the test input provided in the prompt:
    `. A A . A`
    Is it 5 columns?
    `.` (1) `A` (2) `A` (3) `.` (4) `A` (5). Yes.

    So the pattern is a $5 \times 5$ block.
    I need to repeat this block 5 times horizontally and 5 times vertically.

    Let's construct the output row by row.
    The output will have 25 rows.
    Each row will consist of the corresponding input row repeated 5 times.
    Since the input has 5 rows, the output rows 0-4 will be Input Row 0 repeated 5 times, Input Row 1 repeated 5 times, ..., Input Row 4 repeated 5 times.
    Then rows 5-9 will be the same sequence (Input Row 0 repeated 5 times, etc.).
    And so on, for 5 blocks of rows.

    Let's define the Input Rows:
    R0: `. A A . .`
    R1: `A A A A A`
    R2: `. A A . .`
    R3: `A A A A A`
    R4: `. A A . A`

    The Output Row structure for any block $k$ (where $k=0..4$):
    Block Row 0: R0 R0 R0 R0 R0 (concatenated)
    Block Row 1: R1 R1 R1 R1 R1
    Block Row 2: R2 R2 R2 R2 R2
    Block Row 3: R3 R3 R3 R3 R3
    Block Row 4: R4 R4 R4 R4 R4

    This block of 5 rows repeats 5 times vertically.

    Let's verify the "columns in the template" part.
    Input width = 5. So repeat 5 times across.
    Input height = 5. So repeat 5 times down.
    Total width = 25. Total height = 25.

    Wait, is there any ambiguity?
    "as many times across as there are columns in the template" -> 5 times.
    "as many times down as there are rows" -> 5 times.
    This seems consistent with Example 1 ($3 \times 3 \to 9 \times 9$).

    Let's prepare the string for the out

... [6992 chars truncated]

Task 798: cf98881b

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Ex5 In
Ex5 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original Three stained glass windows shine through each other, and the brightest light wi ... [3 chars truncated] MARC valid 1
alt-1 biology Three genes compete for expression in the same tissue, and dominance determines ... [22 chars truncated] MARC valid 2
alt-10 astronomy Three nebulae drift into alignment and the brightest emission overwhelms the oth ... [35 chars truncated] fig alone solves
alt-11 ocean/sailing Three tidal charts overlap at the same harbor, and the strongest current dictate ... [23 chars truncated] MARC valid 1
alt-12 electronics Three circuit layers are etched on the same board, and the highest-voltage trace ... [32 chars truncated] MARC valid 2
alt-13 mythology Three pantheons claim the same mortal realm, and divine rank settles who rules e ... [16 chars truncated] fig alone solves
alt-14 dance Three dance troupes rehearse on a triptych floor, and the prima claims every mar ... [44 chars truncated] fig alone solves
alt-15 geology Three mineral veins are compressed into one stratum, and the hardest crystal win ... [26 chars truncated] fail
alt-2 cooking Three sauces are layered over the same dish, and only the richest flavor survive ... [15 chars truncated] MARC valid 1
alt-3 music Three instrument sections rehearse separately, and the loudest voice claims each ... [25 chars truncated] MARC valid 4
alt-4 sports Three relay teams pass through the same lane, and the fastest runner at each che ... [24 chars truncated] fail
alt-5 weather Three weather fronts converge on the same valley, and the most violent system do ... [26 chars truncated] fail
alt-6 architecture Three blueprints are printed on translucent vellum and stacked — the bolde ... [35 chars truncated] fig alone solves
alt-7 warfare Three armies converge on contested ground, and rank determines who holds each sq ... [24 chars truncated] fail
alt-8 theater Three casts rehearse the same scene on a triptych stage, and the star's spotligh ... [14 chars truncated] MARC valid 2
alt-9 gardening Three seed trays are pressed into one bed, and the most aggressive root system c ... [16 chars truncated] fig alone solves
original qwen3.5-122b: k=1
"Three stained glass windows shine through each other, and the brightest light wins."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10559 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A triptych of stained glass windows separated by pillars of red stone.
*   **Components:**
    *   Left window: Golden sunlight (Y).
    *   Center window: Wine-colored warmth (W).
    *   Right window: Cool blue moonlight (B).
    *   Separators: Red stone pillars (R).
    *   Clear glass: Black/Darkness (.).
*   **Action:** Remove the red stone pillars and stack the three windows one behind the other.
*   **Layering Logic (Priority):**
    *   Nearest (Left/Yellow) dominates.
    *   If Left is clear (.), then Middle (Wine/White) shows through.
    *   If Left and Middle are clear (.), then Right (Blue) shows through.
    *   If all three are clear (.), darkness remains (.).
*   **Grid Structure:** The input grid contains three square panes separated by columns of red stone.
    *   Left Pane: Yellow (Y) and Clear (.).
    *   Separator: Red (R).
    *   Middle Pane: Wine (W) and Clear (.).
    *   Separator: Red (R).
    *   Right Pane: Blue (B) and Clear (.).
*   **Output:** A single window (grid) representing the stacked result.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . Y R . . . W R . . . .
    Y Y . Y R W . W . R . . . .
    Y . Y Y R . W W . R B B . B
    . Y Y Y R . W . . R B B B B
    ```
    *   Dimensions: 4 rows, 14 columns.
    *   Structure:
        *   Left Pane: Columns 0-3 (4x4).
        *   Separator 1: Column 4 (Red R).
        *   Middle Pane: Columns 5-8 (4x4).
        *   Separator 2: Column 9 (Red R).
        *   Right Pane: Columns 10-13 (4x4).
    *   Let's check the content of the panes.
        *   Left (Cols 0-3): Contains Y and ..
        *   Middle (Cols 5-8): Contains W and ..
        *   Right (Cols 10-13): Contains B and ..
        *   Separators (Cols 4, 9): Contain R.
*   **Output:**
    ```
    . . . Y
    Y Y W Y
    Y W Y Y
    B Y Y Y
    ```
    *   Dimensions: 4 rows, 4 columns.
    *   This confirms the output is the size of one pane (4x4).
    *   Let's verify the layering logic row by row.
    *   **Row 0:**
        *   Left: `. . . Y`
        *   Middle: `. . . W`
        *   Right: `. . . .`
        *   Logic:
            *   Col 0: L=., M=., R=. -> Output .
            *   Col 1: L=., M=., R=. -> Output .
            *   Col 2: L=., M=., R=. -> Output .
            *   Col 3: L=Y, M=W, R=. -> Output Y (Y dominates).
        *   Result: `. . . Y`. Matches.
    *   **Row 1:**
        *   Left: `Y Y . Y`
        *   Middle: `W . W .`
        *   Right: `. . . .`
        *   Logic:
            *   Col 0: L=Y -> Y
            *   Col 1: L=Y -> Y
            *   Col 2: L=., M=W -> W
            *   Col 3: L=Y -> Y
        *   Result: `Y Y W Y`. Matches.
    *   **Row 2:**
        *   Left: `Y . Y Y`
        *   Middle: `. W W .`
        *   Right: `B B . B`
        *   Logic:
            *   Col 0: L=Y -> Y
            *   Col 1: L=., M=W -> W
            *   Col 2: L=Y -> Y
            *   Col 3: L=Y -> Y
        *   Result: `Y W Y Y`. Matches.
    *   **Row 3:**
        *   Left: `. Y Y Y`
        *   Middle: `. W . .`
        *   Right: `B B B B`
        *   Logic:
            *   Col 0: L=., M=., R=B -> B
            *   Col 1: L=Y -> Y
            *   Col 2: L=Y -> Y
            *   Col 3: L=Y -> Y
        *   Result: `B Y Y Y`. Matches.

**3. Conceptual Digestion:**
1.  **CAST:**
    *   **Input Grid:** A composite image containing three sub-grids (panes) separated by vertical columns of a specific color (Red/R).
    *   **Panes:** Three square grids of equal dimensions.
        *   Pane 1 (Left): Source of Layer 1 (Priority 1). Color Y.
        *   Pane 2 (Middle): Source of Layer 2 (Priority 2). Color W.
        *   Pane 3 (Right): Source of Layer 3 (Priority 3). Color B.
    *   **Separators:** Vertical columns of color R.
    *   **Empty Space:** Color `.` (black/darkness).
    *   **Output Grid:** A single square grid of the same dimensions as the individual panes.
2.  **AFFORDANCES:**
    *   The grid can be parsed into sub-grids based on the separator columns.
    *   Pixels in the panes can be treated as layers.
    *   A pixel in the output is determined by the non-empty pixel from the highest priority layer at that coordinate.
    *   Priority order: Left Pane > Middle Pane > Right Pane.
    *   "Empty" is defined as `.`.
3.  **TRANSFORMATION RULE:**
    *   Identify the dimensions of the sub-grids (Height H, Width W).
    *   Identify the column indices of the separators (Red R).
    *   Extract the three sub-grids:
        *   $G_1$ (Left): Columns $0$ to $W-1$.
        *   $G_2$ (Middle): Columns $W+1$ to $2W$.
        *   $G_3$ (Right): Columns $2W+2$ to $3W+1$.
        *   (Assuming 1 column separator).
    *   Create an output grid $O$ of size $H \times W$.
    *   For each cell $(r, c)$ wh

... [5745 chars truncated]
alt-1 biology qwen3.5-122b: k=2
"Three genes compete for expression in the same tissue, and dominance determines which phenotype shows."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (9932 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A chromosome with three coding regions separated by silent introns."
    *   This suggests the input grid contains distinct sections (regions) separated by something else (introns).
    *   "The first region glows gold" -> Yellow (Y).
    *   "The second region bruises dark" -> Maroon (W) or maybe Black (.)? "Dark" usually implies W or B or M. Let's look at the examples.
    *   "The third pulses faintly blue" -> Blue (B).
    *   "Against inert junk DNA" -> The background or separators.
*   **Action:** "Splice out the introns and let the three genes fight for expression in the same cell."
    *   This implies removing the separators and overlaying the regions.
    *   "The chromosome shrinks to just one gene's length once the introns are removed." -> The output grid is smaller than the input grid.
    *   "Each locus displays whichever competing allele dominates." -> This is a superposition/overlay operation with a priority rule.
*   **Dominance Rule:**
    *   "Golden allele is fully dominant" -> Yellow (Y) wins.
    *   "Dark one is intermediate" -> Maroon (W) wins over Blue, loses to Yellow.
    *   "Blue one is recessive" -> Blue (B) loses to Yellow and Maroon.
    *   "Only the most dominant trait that's present at each locus gets expressed." -> If Y is present, output Y. Else if W is present, output W. Else if B is present, output B. Else (background/intron), output background (likely .).

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
. . . Y R . . . W R . . . .
Y Y . Y R W . W . R . . . .
Y . Y Y R . W W . R B B . B
. Y Y Y R . W . . R B B B B
```
Output:
```
. . . Y
Y Y W Y
Y W Y Y
B Y Y Y
```
*   **Grid Size:** Input is 4 rows x 14 columns. Output is 4 rows x 4 columns.
*   **Structure:**
    *   There are vertical columns of 'R' (Red). Let's check their positions.
    *   Row 0: `R` at index 4, `R` at index 9.
    *   Row 1: `R` at index 4, `R` at index 9.
    *   Row 2: `R` at index 4, `R` at index 9.
    *   Row 3: `R` at index 4, `R` at index 9.
    *   It seems 'R' acts as the "intron" or separator.
    *   The regions are between the 'R's.
    *   Region 1: Columns 0-3 (before first R).
    *   Region 2: Columns 5-8 (between Rs).
    *   Region 3: Columns 10-13 (after second R).
    *   Wait, the output width is 4. The regions are width 4.
    *   Let's check the content of the regions.
    *   **Region 1 (Cols 0-3):**
        *   R0: `. . . Y`
        *   R1: `Y Y . Y`
        *   R2: `Y . Y Y`
        *   R3: `. Y Y Y`
    *   **Region 2 (Cols 5-8):**
        *   R0: `. . . W`
        *   R1: `W . W .`
        *   R2: `. W W .`
        *   R3: `. W . .`
    *   **Region 3 (Cols 10-13):**
        *   R0: `. . . .`
        *   R1: `. . . .`
        *   R2: `B B . B`
        *   R3: `B B B B`
    *   **Separators:** Column 4 and Column 9 are all 'R'.
    *   **Overlay Logic:**
        *   We have 3 layers of 4x4 grids.
        *   Layer 1 (Gold/Y): Region 1.
        *   Layer 2 (Dark/W): Region 2.
        *   Layer 3 (Blue/B): Region 3.
        *   Priority: Y > W > B > .
        *   Let's check cell (0,0): L1=`.`, L2=`.`, L3=`.` -> Output `.`. Correct.
        *   Cell (0,3): L1=`Y`, L2=`W`, L3=`.` -> Output `Y`. Correct.
        *   Cell (1,2): L1=`.`, L2=`W`, L3=`.` -> Output `W`. Correct.
        *   Cell (2,0): L1=`Y`, L2=`.`, L3=`B` -> Output `Y`. Correct.
        *   Cell (3,0): L1=`.`, L2=`.`, L3=`B` -> Output `B`. Correct.
        *   Cell (3,1): L1=`Y`, L2=`W`, L3=`B` -> Output `Y`. Correct.
    *   **Conclusion:** The 'R' columns define the boundaries. The regions between them are superimposed. The priority is Y > W > B.

**Example 2:**
Input:
```
Y Y Y Y R W . W . R . . . B
Y Y . . R W W . . R B . . .
Y . Y Y R . . . W R . B . B
. . . . R . . W . R B . B .
```
Output:
```
Y Y Y Y
Y Y . .
Y B Y Y
B . W .
```
*   **Grid Size:** Input 4x14. Output 4x4.
*   **Separators:** 'R' at col 4 and col 9.
*   **Region 1 (0-3):**
    *   `Y Y Y Y`
    *   `Y Y . .`
    *   `Y . Y Y`
    *   `. . . .`
*   **Region 2 (5-8):**
    *   `W . W .`
    *   `W W . .`
    *   `. . . W`
    *   `. . W .`
*   **Region 3 (10-13):**
    *   `. . . B`
    *   `B . . .`
    *   `. B . B`
    *   `B . B .`
*   **Overlay Check:**
    *   (0,0): Y, W, . -> Y.
    *   (0,3): Y, ., B -> Y.
    *   (1,0): Y, W, B -> Y.
    *   (2,1): ., ., B -> B.
    *   (2,3): Y, W, B -> Y.
    *   (3,0): ., ., B -> B.
    *   (3,2): ., W, B -> W.
    *   (3,3): ., ., . -> .
*   **Conclusion:** The logic holds perfectly. 'R' is the delimiter. Three regions of equal width are extracted and overlaid. Priority: Y > W > B.

**3. Analyze the Test Input:**
Input:
```
. . Y . R W . W . R B B . .
Y Y . Y R W W W . R B B B .
. . . . R . W W W R B B . B
. 

... [5175 chars truncated]
alt-10 astronomy qwen3.5-122b: fig alone solves
"Three nebulae drift into alignment and the brightest emission overwhelms the others at each pixel of the telescope."
alt-11 ocean/sailing qwen3.5-122b: k=1
"Three tidal charts overlap at the same harbor, and the strongest current dictates flow at each mooring."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11011 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A long nautical chart showing three harbor zones separated by breakwaters marked in red."
    *   This suggests the input grid has distinct sections separated by a specific color (Red/R).
    *   "Gold currents swirl in the first zone" -> Zone 1 contains Yellow (Y).
    *   "Dark undertows pull in the second" -> Zone 2 contains Maroon (W) (Dark undertows usually imply dark colors, W is Maroon).
    *   "Blue eddies circle in the third" -> Zone 3 contains Blue (B).
    *   "each against still water" -> Background is likely Black (.).
*   **Action:** "Remove the breakwater markings and let the three zones flood into one compact harbor."
    *   "Remove breakwater markings" -> Remove Red (R) columns/lines.
    *   "Flood into one compact harbor" -> The output grid is smaller, likely combining the zones.
*   **Priority/Interaction:**
    *   "Gold currents overpower anything beneath them." -> Yellow (Y) is highest priority.
    *   "Dark undertows assert themselves where gold water is still." -> Maroon (W) is second priority (over Black, but under Yellow).
    *   "Blue eddies only form where both stronger currents are absent." -> Blue (B) is lowest priority (only appears if no Y or W).
*   **Output:** "A single small harbor chart where each mooring point shows whichever current was most powerful."
    *   This implies a superposition or overlay of the three zones.
    *   The zones are separated by Red columns in the input.
    *   The output seems to be the width of one zone (since there are 3 zones and the output is "compact").
    *   Let's check the dimensions in the training example.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    . . . Y R . . . W R . . . .
    Y Y . Y R W . W . R . . . .
    Y . Y Y R . W W . R B B . B
    . Y Y Y R . W . . R B B B B
    ```
    Dimensions: 4 rows, 14 columns.
    Red (R) columns appear at index 4 and index 9 (0-indexed).
    Let's check the columns:
    Col 0-3: Zone 1 (contains Y, .)
    Col 4: Breakwater (R)
    Col 5-8: Zone 2 (contains W, .)
    Col 9: Breakwater (R)
    Col 10-13: Zone 3 (contains B, .)
    So there are 3 zones of width 4, separated by 1 column of R.
    Total width = 4 + 1 + 4 + 1 + 4 = 14. Matches input width.

*   **Output:**
    ```
    . . . Y
    Y Y W Y
    Y W Y Y
    B Y Y Y
    ```
    Dimensions: 4 rows, 4 columns.
    This matches the width of a single zone.
    The output is formed by overlaying the three zones.
    Let's verify the overlay logic (Priority: Y > W > B > .).

    *   **Row 0:**
        *   Zone 1 (Cols 0-3): `. . . Y`
        *   Zone 2 (Cols 5-8): `. . . W`
        *   Zone 3 (Cols 10-13): `. . . .`
        *   Overlay:
            *   Col 0: . vs . vs . -> .
            *   Col 1: . vs . vs . -> .
            *   Col 2: . vs . vs . -> .
            *   Col 3: Y vs W vs . -> Y (Y > W)
        *   Result Row 0: `. . . Y`. Matches output.

    *   **Row 1:**
        *   Zone 1: `Y Y . Y`
        *   Zone 2: `W . W .`
        *   Zone 3: `. . . .`
        *   Overlay:
            *   Col 0: Y vs W vs . -> Y
            *   Col 1: Y vs . vs . -> Y
            *   Col 2: . vs W vs . -> W
            *   Col 3: Y vs . vs . -> Y
        *   Result Row 1: `Y Y W Y`. Matches output.

    *   **Row 2:**
        *   Zone 1: `Y . Y Y`
        *   Zone 2: `. W W .`
        *   Zone 3: `B B . B`
        *   Overlay:
            *   Col 0: Y vs . vs B -> Y
            *   Col 1: . vs W vs B -> W (W > B)
            *   Col 2: Y vs W vs . -> Y
            *   Col 3: Y vs . vs B -> Y
        *   Result Row 2: `Y W Y Y`. Matches output.

    *   **Row 3:**
        *   Zone 1: `. Y Y Y`
        *   Zone 2: `. W . .`
        *   Zone 3: `B B B B`
        *   Overlay:
            *   Col 0: . vs . vs B -> B
            *   Col 1: Y vs W vs B -> Y
            *   Col 2: Y vs . vs B -> Y
            *   Col 3: Y vs . vs B -> Y
        *   Result Row 3: `B Y Y Y`. Matches output.

**3. Conceptual Digestion:**
1.  **CAST:**
    *   **Red (R):** Breakwaters / Separators. They define the boundaries between zones. They are removed in the output.
    *   **Yellow (Y):** Gold currents. Highest priority layer.
    *   **Maroon (W):** Dark undertows. Medium priority layer.
    *   **Blue (B):** Blue eddies. Lowest priority layer.
    *   **Black (.):** Still water / Background. Lowest priority (transparent).
    *   **Zones:** Three distinct rectangular regions of equal width separated by single columns of Red.
2.  **AFFORDANCES:**
    *   Zones can be extracted based on the Red separators.
    *   Zones can be superimposed (overlaid) on top of each other.
    *   Colors have a hierarchy of opacity/power: Y > W > B > ..
3.  **TRANSFORMATION RULE:**
    *   Identify

... [6239 chars truncated]
alt-12 electronics qwen3.5-122b: k=2
"Three circuit layers are etched on the same board, and the highest-voltage trace burns through at each junction."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11023 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A wide circuit board with three trace regions separated by red power rails."
    *   This suggests the input grid has distinct sections separated by a specific color (Red 'R').
    *   "Gold traces carry high voltage on the left" -> Left section (Yellow 'Y'?).
    *   "Dark traces carry medium voltage in the center" -> Center section (Maroon 'W'?).
    *   "Blue traces carry low voltage on the right" -> Right section (Blue 'B'?).
    *   "Bare substrate" -> Black/Dot '.'.
*   **Action:** "Remove the power rail dividers and collapse all three layers onto one compact board."
    *   This implies the output grid will be smaller than the input grid. The "red power rails" act as separators.
    *   "Collapse all three layers onto one compact board" suggests superimposing the three sections.
*   **Logic:** "At each junction, the gold high-voltage trace dominates. The dark medium trace connects only where gold is absent. The blue low trace only appears where both higher traces left bare substrate."
    *   Priority: Gold (Y) > Dark (W) > Blue (B) > Substrate (.).
    *   Wait, let's check the colors in the examples.
    *   Example 1 Input:
        *   Left part: Y, .
        *   Separator: R
        *   Middle part: W, .
        *   Separator: R
        *   Right part: B, .
    *   Example 1 Output:
        *   Combines Y, W, B.
        *   Rule seems to be: If Y is present, output Y. Else if W is present, output W. Else if B is present, output B. Else output '.'.
    *   Let's verify the "Red power rails" part. In the input, 'R' appears as vertical columns separating the regions.
    *   Let's check the dimensions.
    *   Example 1 Input: 4 rows, 14 columns.
    *   Example 1 Output: 4 rows, 4 columns.
    *   Input structure:
        *   Cols 0-3: Left region (Y, .)
        *   Col 4: Separator (R)
        *   Cols 5-8: Middle region (W, .)
        *   Col 9: Separator (R)
        *   Cols 10-13: Right region (B, .)
    *   Wait, let's look closer at Example 1 Input.
        Row 0: `. . . Y R . . . W R . . . .`
        Indices:
        0-3: `. . . Y` (Left)
        4: `R` (Sep)
        5-8: `. . . W` (Middle)
        9: `R` (Sep)
        10-13: `. . . .` (Right)
        Row 1: `Y Y . Y R W . W . R . . . .`
        0-3: `Y Y . Y`
        4: `R`
        5-8: `W . W .`
        9: `R`
        10-13: `. . . .`
        Row 2: `Y . Y Y R . W W . R B B . B`
        0-3: `Y . Y Y`
        4: `R`
        5-8: `. W W .`
        9: `R`
        10-13: `B B . B`
        Row 3: `. Y Y Y R . W . . R B B B B`
        0-3: `. Y Y Y`
        4: `R`
        5-8: `. W . .`
        9: `R`
        10-13: `B B B B`

    *   Output Row 0: `. . . Y`
        *   Left: `. . . Y`
        *   Mid: `. . . W`
        *   Right: `. . . .`
        *   Superposition:
            *   Col 0: . + . + . = .
            *   Col 1: . + . + . = .
            *   Col 2: . + . + . = .
            *   Col 3: Y + W + . = Y (Y dominates W)
        *   Wait, the output is `. . . Y`.
        *   Let's check Row 1 Output: `Y Y W Y`
        *   Left: `Y Y . Y`
        *   Mid: `W . W .`
        *   Right: `. . . .`
        *   Superposition:
            *   Col 0: Y + W + . = Y
            *   Col 1: Y + . + . = Y
            *   Col 2: . + W + . = W
            *   Col 3: Y + . + . = Y
            *   Result: `Y Y W Y`. Matches.
        *   Row 2 Output: `Y W Y Y`
        *   Left: `Y . Y Y`
        *   Mid: `. W W .`
        *   Right: `B B . B`
        *   Superposition:
            *   Col 0: Y + . + B = Y
            *   Col 1: . + W + B = W (W dominates B)
            *   Col 2: Y + W + . = Y
            *   Col 3: Y + . + B = Y
            *   Result: `Y W Y Y`. Matches.
        *   Row 3 Output: `B Y Y Y`
        *   Left: `. Y Y Y`
        *   Mid: `. W . .`
        *   Right: `B B B B`
        *   Superposition:
            *   Col 0: . + . + B = B
            *   Col 1: Y + W + B = Y (Y dominates W and B)
            *   Col 2: Y + . + B = Y
            *   Col 3: Y + . + B = Y
            *   Result: `B Y Y Y`. Matches.

    *   **Transformation Rule:**
        1.  Identify the vertical separator columns containing 'R'.
        2.  Split the grid into three regions based on these separators.
            *   Region 1: Columns before the first 'R'.
            *   Region 2: Columns between the first 'R' and the second 'R'.
            *   Region 3: Columns after the second 'R'.
        3.  The regions should have the same width. (In Ex 1, width is 4).
        4.  Create an output grid of the same height and the width of one region.
        5.  For each cell (r, c) in the output grid:
            *   Get value from Region 1 at (r, c).
            *   Get value from Region 2 at (r, c).
            *   Get value from Region 3 at (r, c).
            *   Apply 

... [6173 chars truncated]
alt-13 mythology qwen3.5-122b: fig alone solves
"Three pantheons claim the same mortal realm, and divine rank settles who rules each sacred site."
alt-14 dance qwen3.5-122b: fig alone solves
"Three dance troupes rehearse on a triptych floor, and the prima claims every mark she touches when the panels fold together."
alt-15 geology qwen3.5-122b: fail
"Three mineral veins are compressed into one stratum, and the hardest crystal wins each pocket in the rock."
Fail (best cell_acc=0.44 at k=3)
Best Attempt
vs
Expected
Reasoning (9560 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A wide cross-section of bedrock showing three mineral zones separated by seams of red jasper."
    *   This suggests the input grid has three distinct sections separated by a specific color (Red 'R').
    *   "Gold ore fills pockets in the first zone, darkite in the second, and blue chalcedony in the third — each embedded in empty matrix stone."
    *   Zone 1: Contains 'Y' (Gold) and '.' (Empty).
    *   Zone 2: Contains 'W' (Darkite - Maroon) and '.' (Empty).
    *   Zone 3: Contains 'B' (Blue Chalcedony) and '.' (Empty).
    *   Separators: 'R' (Red Jasper).
*   **Transformation:** "The jasper seams erode away and tectonic pressure crushes the three zones into one thin stratum."
    *   This implies the 'R' columns are removed.
    *   The three zones are stacked or merged horizontally.
    *   "Gold ore, being hardest, fills any pocket it occupies. Dark mineral claims spaces where gold is absent. Blue chalcedony crystallizes only in pockets both harder minerals left vacant."
    *   This describes a priority rule for merging the zones.
    *   Priority: Gold (Y) > Darkite (W) > Blue Chalcedony (B).
    *   Empty (.) is the lowest priority (background).
    *   Essentially, for each position in the resulting grid, we look at the corresponding positions in the three zones. If Zone 1 has Y, output Y. Else if Zone 2 has W, output W. Else if Zone 3 has B, output B. Else output '.'.
*   **Grid Details:** "A single compressed stratum where each pocket holds whichever mineral was hardest on the Mohs scale."
    *   This confirms the merging logic.
    *   The input grid seems to be composed of 3 blocks separated by columns of 'R'.
    *   Let's check the dimensions.
    *   Example 1 Input: 4 rows, 14 columns.
        *   Zone 1: Cols 0-3 (4 cols).
        *   Separator: Col 4 ('R').
        *   Zone 2: Cols 5-8 (4 cols).
        *   Separator: Col 9 ('R').
        *   Zone 3: Cols 10-13 (4 cols).
        *   Output: 4 rows, 4 columns.
    *   So the transformation is: Remove 'R' columns. Overlay the three 4x4 blocks.
    *   Overlay Rule: Y > W > B > .
    *   Wait, let's verify the colors.
        *   Zone 1 has Y and ..
        *   Zone 2 has W and ..
        *   Zone 3 has B and ..
        *   Priority: Y (Gold) > W (Darkite) > B (Blue).
        *   Wait, the description says "Dark mineral claims spaces where gold is absent". Darkite is W.
        *   "Blue chalcedony crystallizes only in pockets both harder minerals left vacant". Blue is B.
        *   So Priority: Y > W > B.
        *   What about '.'? It's the matrix stone. If all are '.', result is '.'.

**2. Analyze Training Examples:**

**Example 1:**
Input:
. . . Y R . . . W R . . . .
Y Y . Y R W . W . R . . . .
Y . Y Y R . W W . R B B . B
. Y Y Y R . W . . R B B B B

Structure:
Rows: 4
Cols: 14
Separators at index 4 and 9 (0-indexed).
Block 1 (Cols 0-3):
. . . Y
Y Y . Y
Y . Y Y
. Y Y Y

Block 2 (Cols 5-8):
. . . W
W . W .
. W W .
. W . .

Block 3 (Cols 10-13):
. . . .
. . . .
B B . B
B B B B

Output:
. . . Y
Y Y W Y
Y W Y Y
B Y Y Y

Let's check the overlay logic (Y > W > B > .):
Row 0:
B1: . . . Y
B2: . . . W
B3: . . . .
Col 0: ., ., . -> .
Col 1: ., ., . -> .
Col 2: ., ., . -> .
Col 3: Y, W, . -> Y (Y wins)
Result Row 0: . . . Y. Matches.

Row 1:
B1: Y Y . Y
B2: W . W .
B3: . . . .
Col 0: Y, W, . -> Y
Col 1: Y, ., . -> Y
Col 2: ., W, . -> W
Col 3: Y, ., . -> Y
Result Row 1: Y Y W Y. Matches.

Row 2:
B1: Y . Y Y
B2: . W W .
B3: B B . B
Col 0: Y, ., B -> Y
Col 1: ., W, B -> W (W > B)
Col 2: Y, W, . -> Y
Col 3: Y, ., B -> Y
Result Row 2: Y W Y Y. Matches.

Row 3:
B1: . Y Y Y
B2: . W . .
B3: B B B B
Col 0: ., ., B -> B
Col 1: Y, W, B -> Y
Col 2: Y, ., B -> Y
Col 3: Y, ., B -> Y
Result Row 3: B Y Y Y. Matches.

Logic confirmed:
1. Identify columns containing 'R'. These are separators.
2. Split the grid into three sub-grids based on the separators.
3. The sub-grids should be of equal width.
4. Merge the three sub-grids cell by cell.
5. Priority: Y > W > B > . (Yellow > Maroon > Blue > Black).
   Wait, is it strictly Y > W > B?
   In Row 3 Col 0: B1=., B2=., B3=B -> Result B.
   In Row 2 Col 1: B1=., B2=W, B3=B -> Result W.
   In Row 1 Col 2: B1=., B2=W, B3=. -> Result W.
   In Row 0 Col 3: B1=Y, B2=W, B3=. -> Result Y.
   Yes, Y overrides W, W overrides B.
   What if B1 has Y and B2 has W? Y wins.
   What if B1 has . and B2 has W and B3 has B? W wins.
   What if B1 has . and B2 has . and B3 has B? B wins.
   What if all are .? Result is ..

**Example 2:**
Input:
Y Y Y Y R W . W . R . . . B
Y Y . . R W W . . R B . . .
Y . Y Y R . . . W R . B . B
. . . . R . . W . R B . B .

Block 1 (0-3):
Y Y Y Y
Y Y . .
Y . Y Y
. . . .

Block 2 (5-8):
W . W .
W W . .
. .

... [4905 chars truncated]
alt-2 cooking qwen3.5-122b: k=1
"Three sauces are layered over the same dish, and only the richest flavor survives at each bite."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10718 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A long plating board divided into three seasoning stations by strips of hot pepper."
    *   This suggests the input grid is wider than the output grid.
    *   There are "strips of hot pepper" acting as dividers. In the color key, 'R' is red. Let's check if 'R' acts as a divider.
    *   "Gold butter sauce on the left, dark reduction in the middle, berry coulis on the right".
    *   This implies three distinct regions separated by the 'R' strips.
    *   Left region: Gold butter (Yellow 'Y'?).
    *   Middle region: Dark reduction (Maroon 'W'?).
    *   Right region: Berry coulis (Blue 'B'?).
    *   "each dabbed onto a grid of tasting portions."
*   **Action:** "Remove the pepper dividers and stack all three sauces onto one small plate."
    *   This implies the output grid is smaller (likely the width of one section).
    *   The three sections are stacked or overlaid.
*   **Priority/Blending Rule:**
    *   "Where butter was spooned, its richness overpowers everything beneath." -> Yellow ('Y') is highest priority.
    *   "Where only reduction was placed, it dominates the berry." -> Maroon ('W') is middle priority.
    *   "The coulis only shines through where the plate was otherwise bare." -> Blue ('B') is lowest priority.
    *   "The final plate is a single small square where each bite carries whichever sauce was most assertive at that spot." -> This confirms a layering/overlay logic based on priority.
    *   Priority Order: Yellow ('Y') > Maroon ('W') > Blue ('B').
    *   What about empty space ('.')? It seems to be the background. If a spot is empty in all layers, it remains empty.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
. . . Y R . . . W R . . . .
Y Y . Y R W . W . R . . . .
Y . Y Y R . W W . R B B . B
. Y Y Y R . W . . R B B B B
```
Output:
```
. . . Y
Y Y W Y
Y W Y Y
B Y Y Y
```

*   **Grid Dimensions:**
    *   Input: 4 rows, 14 columns.
    *   Output: 4 rows, 4 columns.
*   **Structure:**
    *   The input seems to be divided into three 4-column sections separated by columns of 'R'.
    *   Let's check the columns.
    *   Col 0-3: Section 1 (Left)
    *   Col 4: 'R' (Divider)
    *   Col 5-8: Section 2 (Middle)
    *   Col 9: 'R' (Divider)
    *   Col 10-13: Section 3 (Right)
    *   Wait, let's count columns in Input Example 1.
    *   Row 1: `. . . Y R . . . W R . . . .` -> 14 chars.
    *   Indices: 0,1,2,3 (Left), 4 (R), 5,6,7,8 (Mid), 9 (R), 10,11,12,13 (Right).
    *   So the structure is: 4 cols | 1 col (R) | 4 cols | 1 col (R) | 4 cols.
    *   Total width = 4 + 1 + 4 + 1 + 4 = 14. Matches.
    *   Output width = 4. Matches the width of one section.
*   **Content Mapping:**
    *   Left Section (Cols 0-3): Contains mostly 'Y' and '.'.
    *   Middle Section (Cols 5-8): Contains mostly 'W' and '.'.
    *   Right Section (Cols 10-13): Contains mostly 'B' and '.'.
    *   This matches the metaphor: Left=Butter(Y), Mid=Reduction(W), Right=Coulis(B).
*   **Transformation Logic:**
    *   For each cell (r, c) in the 4x4 output grid:
        *   Look at Input(r, c) [Left], Input(r, c+5) [Mid], Input(r, c+10) [Right].
        *   Apply priority: Y > W > B > .
    *   Let's verify Row 0:
        *   Left: `. . . Y`
        *   Mid: `. . . W`
        *   Right: `. . . .`
        *   Col 0: ., ., . -> .
        *   Col 1: ., ., . -> .
        *   Col 2: ., ., . -> .
        *   Col 3: Y, W, . -> Y (Y wins)
        *   Output Row 0: `. . . Y`. Matches.
    *   Let's verify Row 1:
        *   Left: `Y Y . Y`
        *   Mid: `W . W .`
        *   Right: `. . . .`
        *   Col 0: Y, W, . -> Y
        *   Col 1: Y, ., . -> Y
        *   Col 2: ., W, . -> W
        *   Col 3: Y, ., . -> Y
        *   Output Row 1: `Y Y W Y`. Matches.
    *   Let's verify Row 2:
        *   Left: `Y . Y Y`
        *   Mid: `. W W .`
        *   Right: `B B . B`
        *   Col 0: Y, ., B -> Y
        *   Col 1: ., W, B -> W (W > B)
        *   Col 2: Y, W, . -> Y
        *   Col 3: Y, ., B -> Y
        *   Output Row 2: `Y W Y Y`. Matches.
    *   Let's verify Row 3:
        *   Left: `. Y Y Y`
        *   Mid: `. W . .`
        *   Right: `B B B B`
        *   Col 0: ., ., B -> B
        *   Col 1: Y, W, B -> Y
        *   Col 2: Y, ., B -> Y
        *   Col 3: Y, ., B -> Y
        *   Output Row 3: `B Y Y Y`. Matches.

**3. Analyze the Test Input:**

Input:
```
. . Y . R W . W . R B B . .
Y Y . Y R W W W . R B B B .
. . . . R . W W W R B B . B
. Y Y . R W . W W R B . . .
```

*   **Dimensions:**
    *   Rows: 4
    *   Columns: Let's count.
    *   Row 1: `. . Y . R W . W . R B B . .` -> 14 chars.
    *   Structure is the same: 4 cols | 1 col (R) | 4 cols | 1 col (R) | 4 cols.
    *   Left Section: Cols 0-3.
    *   Middle Sect

... [5922 chars truncated]
alt-3 music qwen3.5-122b: k=4
"Three instrument sections rehearse separately, and the loudest voice claims each beat in the final score."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (10500 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A long musical staff divided into three rehearsal rooms by walls of percussion."
    *   "Long musical staff": Likely a grid.
    *   "Three rehearsal rooms": The grid seems to be divided into three sections.
    *   "Walls of percussion": There are separators. In the examples, I see a column of 'R' (Red) appearing repeatedly. Let's check the examples.
*   **Input Structure:**
    *   Example 1 Input: 4 rows, 14 columns.
        *   Row 1: `. . . Y R . . . W R . . . .`
        *   Row 2: `Y Y . Y R W . W . R . . . .`
        *   Row 3: `Y . Y Y R . W W . R B B . B`
        *   Row 4: `. Y Y Y R . W . . R B B B B`
        *   Notice the 'R's. They appear at indices 4 and 9 (0-indexed).
        *   Let's check the columns.
        *   Col 4 is all 'R'. Col 9 is all 'R'.
        *   So the "walls of percussion" are columns of Red (R).
        *   This divides the grid into three "rooms" (sections of columns).
        *   Room 1: Cols 0-3 (4 columns).
        *   Room 2: Cols 5-8 (4 columns).
        *   Room 3: Cols 10-13 (4 columns).
        *   The walls are at Col 4 and Col 9.
    *   Example 2 Input: 4 rows, 14 columns.
        *   Col 4 is 'R'. Col 9 is 'R'.
        *   Same structure.
    *   Example 3 Input: 4 rows, 14 columns.
        *   Col 4 is 'R'. Col 9 is 'R'.
        *   Same structure.
    *   Example 4 Input: 4 rows, 14 columns.
        *   Col 4 is 'R'. Col 9 is 'R'.
        *   Same structure.
    *   Test Input: 4 rows, 14 columns.
        *   Col 4 is 'R'. Col 9 is 'R'.
        *   Same structure.
    *   So, the input is always 4x14. It consists of three 4x4 blocks separated by two columns of Red (R).
    *   Block 1 (Left): Columns 0-3.
    *   Block 2 (Middle): Columns 5-8.
    *   Block 3 (Right): Columns 10-13.
    *   The Red columns (4 and 9) are the "walls".

*   **Transformation:** "Tear down the percussion walls and merge the three rooms into one ensemble."
    *   This implies combining the three 4x4 blocks into a single 4x4 output grid.
    *   "At each beat, the brass plays over everything, the strings fill in where brass rests, and the woodwinds only sound where both others are silent."
    *   This describes a priority layering system.
    *   "Brass fills the first room": Block 1 (Left) is Brass.
    *   "Strings hum in the second": Block 2 (Middle) is Strings.
    *   "Woodwinds whisper in the third": Block 3 (Right) is Woodwinds.
    *   "Brass plays over everything": Brass (Block 1) has highest priority. If a cell in Block 1 is not empty (black/dot), it takes precedence.
    *   "Strings fill in where brass rests": Strings (Block 2) have medium priority. If Block 1 is empty (dot) and Block 2 is not empty, Block 2 takes precedence.
    *   "Woodwinds only sound where both others are silent": Woodwinds (Block 3) have lowest priority. If Block 1 and Block 2 are empty, Block 3 takes precedence.
    *   "Silence" corresponds to the black dot `.`.
    *   "Final score is one compact arrangement": The output is a 4x4 grid.
    *   "Each beat belongs to whichever section's voice carried farthest": This confirms the priority logic.

**2. Verify with Training Examples:**

*   **Example 1:**
    *   Block 1 (Left):
        ```
        . . . Y
        Y Y . Y
        Y . Y Y
        . Y Y Y
        ```
    *   Block 2 (Middle):
        ```
        . . . W
        W . W .
        . W W .
        . W . .
        ```
    *   Block 3 (Right):
        ```
        . . . .
        . . . .
        B B . B
        B B B B
        ```
    *   Output:
        ```
        . . . Y
        Y Y W Y
        Y W Y Y
        B Y Y Y
        ```
    *   Let's check cell (0,0): B1=`.`, B2=`.`, B3=`.` -> Output `.`. Correct.
    *   Cell (0,3): B1=`Y`, B2=`W`, B3=`.`. Priority B1 > B2 > B3. Output `Y`. Correct.
    *   Cell (1,2): B1=`.`, B2=`W`, B3=`.`. Priority B1 empty, B2 `W`. Output `W`. Correct.
    *   Cell (2,0): B1=`Y`, B2=`.`, B3=`B`. Priority B1 `Y`. Output `Y`. Correct.
    *   Cell (3,0): B1=`.`, B2=`.`, B3=`B`. Priority B1 empty, B2 empty, B3 `B`. Output `B`. Correct.
    *   Logic holds: Priority is Block 1 > Block 2 > Block 3. Non-dot overrides dot.

*   **Example 2:**
    *   Block 1:
        ```
        Y Y Y Y
        Y Y . .
        Y . Y Y
        . . . .
        ```
    *   Block 2:
        ```
        W . W .
        W W . .
        . . . W
        . . W .
        ```
    *   Block 3:
        ```
        . . . B
        B . . .
        . B . B
        B . B .
        ```
    *   Output:
        ```
        Y Y Y Y
        Y Y . .
        Y B Y Y
        B . W .
        ```
    *   Check (2,1): B1=`.`, B2=`.`, B3=`B`. Output `B`. Correct.
    *   Check (3,0): B1=`.`, B2=`.`, B3=`B`. Output `B`. Correct.
    *   Check (3,2): B1=`.`, B2=`W`, B3=`B`. Output `W`. Correct.
    *   Logic holds.

*  

... [5599 chars truncated]
alt-4 sports qwen3.5-122b: fail
"Three relay teams pass through the same lane, and the fastest runner at each checkpoint holds the baton."
Fail (best cell_acc=0.12 at k=1)
Best Attempt
vs
Expected
Reasoning (9753 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A long track with three zones separated by hurdle barriers."
    *   This suggests the input grid is divided into sections.
    *   "Gold jerseys sprint through the first zone, dark uniforms through the second, and blue kits through the third".
    *   "Some lanes occupied, some empty."
    *   "Hurdle barriers" likely separate these zones.
*   **Action:** "Collapse the hurdle barriers and overlay every zone onto a single stretch."
    *   This implies stacking or merging the zones.
    *   "At each position, the gold runner claims the spot if present; otherwise the dark uniform holds it; otherwise the blue kit stands there."
    *   This defines a priority order: Gold > Dark > Blue.
    *   "Empty positions stay vacant."
*   **Grid details:** "One short stretch of track where each position is held by whichever team's runner arrived with the highest rank."
    *   This confirms the priority logic.
    *   "Highest rank" likely corresponds to the order mentioned: Gold (1st), Dark (2nd), Blue (3rd).

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
. . . Y R . . . W R . . . .
Y Y . Y R W . W . R . . . .
Y . Y Y R . W W . R B B . B
. Y Y Y R . W . . R B B B B
```
Output:
```
. . . Y
Y Y W Y
Y W Y Y
B Y Y Y
```

Let's look at the Input dimensions: 4 rows, 14 columns.
Let's look at the Output dimensions: 4 rows, 4 columns.

The metaphor mentions "three zones".
Let's try to identify the zones in the input.
The colors mentioned are Gold (Y), Dark (W?), Blue (B).
Wait, the color key says:
Y = yellow (Gold?)
W = maroon (Dark?)
B = blue (Blue)
R = red (Hurdle barriers?)

Let's check the input for separators.
Row 1: `. . . Y R . . . W R . . . .`
Row 2: `Y Y . Y R W . W . R . . . .`
Row 3: `Y . Y Y R . W W . R B B . B`
Row 4: `. Y Y Y R . W . . R B B B B`

There is a column of `R`s.
Column 5 is `R`.
Column 10 is `R`.
Let's check indices (0-based):
Col 0: . Y Y .
Col 1: . Y . Y
Col 2: . . Y Y
Col 3: Y Y Y Y
Col 4: R R R R  <-- Separator 1
Col 5: . W . .
Col 6: . . W W
Col 7: . W W .
Col 8: . . . .
Col 9: R R R R  <-- Separator 2
Col 10: . . B B
Col 11: . . B B
Col 12: . . . B
Col 13: . . B B

So the input grid seems to be divided into three sections by columns of Red (R).
Zone 1: Columns 0-3 (Width 4). Contains Y (Yellow/Gold).
Zone 2: Columns 5-8 (Width 4). Contains W (Maroon/Dark).
Zone 3: Columns 10-13 (Width 4). Contains B (Blue).

The Output is 4x4. This matches the width of each zone.
The logic is "overlay every zone onto a single stretch".
Priority: Gold (Y) > Dark (W) > Blue (B).
Let's verify this priority with the output.

Output Row 0: `. . . Y`
Input Row 0:
Zone 1 (0-3): `. . . Y`
Zone 2 (5-8): `. . . W` (Wait, col 5 is `.`, 6 is `.`, 7 is `.`, 8 is `.`? No, let's re-read input row 0)
Input Row 0: `. . . Y R . . . W R . . . .`
Indices:
0: .
1: .
2: .
3: Y
4: R (Sep)
5: .
6: .
7: .
8: W
9: R (Sep)
10: .
11: .
12: .
13: .

Zone 1: `. . . Y`
Zone 2: `. . . W`
Zone 3: `. . . .`

Overlay logic:
Pos 0: Z1(.), Z2(.), Z3(.) -> .
Pos 1: Z1(.), Z2(.), Z3(.) -> .
Pos 2: Z1(.), Z2(.), Z3(.) -> .
Pos 3: Z1(Y), Z2(W), Z3(.) -> Y (Gold wins)
Output Row 0: `. . . Y`. Matches.

Output Row 1: `Y Y W Y`
Input Row 1: `Y Y . Y R W . W . R . . . .`
Zone 1: `Y Y . Y`
Zone 2: `W . W .`
Zone 3: `. . . .`
Overlay:
Pos 0: Y, W, . -> Y
Pos 1: Y, ., . -> Y
Pos 2: ., W, . -> W (Dark wins over empty)
Pos 3: Y, ., . -> Y
Result: `Y Y W Y`. Matches.

Output Row 2: `Y W Y Y`
Input Row 2: `Y . Y Y R . W W . R B B . B`
Zone 1: `Y . Y Y`
Zone 2: `. W W .`
Zone 3: `B B . B`
Overlay:
Pos 0: Y, ., B -> Y
Pos 1: ., W, B -> W (Dark > Blue)
Pos 2: Y, W, . -> Y
Pos 3: Y, ., B -> Y
Result: `Y W Y Y`. Matches.

Output Row 3: `B Y Y Y`
Input Row 3: `. Y Y Y R . W . . R B B B B`
Zone 1: `. Y Y Y`
Zone 2: `. W . .`
Zone 3: `B B B B`
Overlay:
Pos 0: ., ., B -> B
Pos 1: Y, W, B -> Y
Pos 2: Y, ., B -> Y
Pos 3: Y, ., B -> Y
Result: `B Y Y Y`. Matches.

**Transformation Rule:**
1.  Identify the separator color. In the example, it is Red (R). The separator forms vertical columns dividing the grid into three equal-width zones.
2.  Extract the three zones.
    *   Zone 1 (Left): Columns before the first separator column.
    *   Zone 2 (Middle): Columns between the first and second separator columns.
    *   Zone 3 (Right): Columns after the second separator column.
3.  The zones should have the same dimensions (Height x Width).
4.  Create an output grid of the same dimensions as one zone.
5.  For each cell (r, c) in the output grid:
    *   Check the value in Zone 1 at (r, c). If not empty (.), it takes precedence.
    *   Else, check the value in Zone 2 at (r, c). If not empty (.), it takes precedence.
    *   Else, check the value in Zone 3 at (r, c). If not empty (.), it takes precedence.
    *   Else, t

... [5011 chars truncated]
alt-5 weather qwen3.5-122b: fail
"Three weather fronts converge on the same valley, and the most violent system dominates each patch of sky."
Fail (best cell_acc=0.44 at k=3)
Best Attempt
vs
Expected
Reasoning (10297 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A long weather map split into three forecast zones by lines of thunderstorms."
    *   "Long weather map": The input grid seems to be wider than it is tall, or at least has distinct sections.
    *   "Split into three forecast zones by lines of thunderstorms": There are vertical lines of a specific color acting as separators. Looking at the examples, the color 'R' (Red) appears in vertical columns. Let's check the examples.
    *   "Sunshine blazes in the first zone": Zone 1 (left of first R line). Color 'Y' (Yellow) is prominent here.
    *   "Fog creeps through the second": Zone 2 (between R lines). Color 'W' (Maroon/White? Key says W=maroon, but metaphor says fog. Let's look at the colors).
    *   "Frost settles in the third": Zone 3 (right of second R line). Color 'B' (Blue) is prominent here.
    *   "Each against clear skies": Background is '.' (black).
*   **Action:** "Let the storm walls dissolve and the three fronts collapse into one small region."
    *   "Storm walls dissolve": The 'R' lines disappear.
    *   "Three fronts collapse into one small region": The three zones are merged or compressed into a smaller grid.
*   **Logic:** "Sunshine burns away everything beneath it. Fog rolls in wherever sun doesn't reach. Frost only crystallizes on patches both clear and fog-free."
    *   This sounds like a priority rule or a superposition rule.
    *   "Sunshine burns away everything beneath it": Y overrides others?
    *   "Fog rolls in wherever sun doesn't reach": W overrides others if Y is not there?
    *   "Frost only crystallizes on patches both clear and fog-free": B appears where neither Y nor W is present? Or maybe B is the base?
    *   "Final forecast covers a small square of sky where each cell shows whichever weather pattern was most forceful."
    *   This implies a superposition of the three zones onto a smaller grid.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
. . . Y R . . . W R . . . .
Y Y . Y R W . W . R . . . .
Y . Y Y R . W W . R B B . B
. Y Y Y R . W . . R B B B B

Grid Size: 4 rows, 14 columns.
Separators: 'R' appears in column 5 and column 10 (0-indexed: 4 and 9).
Zone 1 (Cols 0-3): Contains Y and .
Zone 2 (Cols 6-8): Contains W and .
Zone 3 (Cols 11-13): Contains B and .

Output:
. . . Y
Y Y W Y
Y W Y Y
B Y Y Y

Output Size: 4 rows, 4 columns.
This matches the width of Zone 1 (4 cols).
Let's check the content.
Row 0:
In: . . . Y | R | . . . W | R | . . . .
Out: . . . Y
Zone 1: . . . Y
Zone 2: . . . W
Zone 3: . . . .
Result: . . . Y
It seems Zone 1 is the base. Zone 2 (W) overwrites Zone 1? Zone 3 (B) overwrites Zone 1?
Let's look at Row 1:
In: Y Y . Y | R | W . W | R | . . . .
Out: Y Y W Y
Zone 1: Y Y . Y
Zone 2: W . W
Zone 3: . . . .
Result: Y Y W Y
Here, at col 2 (0-indexed in output), Zone 1 has '.', Zone 2 has 'W'. Output has 'W'.
At col 0, Zone 1 has 'Y', Zone 2 has 'W'. Output has 'Y'.
So Y > W.
At col 1, Zone 1 has 'Y', Zone 2 has '.'. Output has 'Y'.
At col 3, Zone 1 has 'Y', Zone 2 has 'W' (Wait, Zone 2 is cols 6-8. Col 3 of output corresponds to col 3 of Zone 1, col 3 of Zone 2, col 3 of Zone 3).
Let's align columns.
Zone 1 width = 4.
Zone 2 width = 3.
Zone 3 width = 4.
Wait, Output width is 4.
Zone 1: 4 cols.
Zone 2: 3 cols.
Zone 3: 4 cols.
If they collapse into one small region, how do they align?
Maybe they are superimposed based on row index, but column index is modulo or something?
Or maybe the "small region" is the size of the largest zone? Or the first zone?
In Ex 1, Output is 4x4. Zone 1 is 4x4. Zone 2 is 3x4. Zone 3 is 4x4.
Let's look at the columns of Zone 2.
Row 0: . . . W (Cols 6,7,8,9? No, R is at 4 and 9. So Zone 2 is 5,6,7,8. Wait.
Input Row 0: . . . Y R . . . W R . . . .
Indices: 0123 4 5678 9 0123
R at 4. R at 9.
Zone 1: 0-3 (4 cols).
Zone 2: 5-8 (4 cols).
Zone 3: 10-13 (4 cols).
Okay, all zones are 4 columns wide.
Let's re-read the input string for Ex 1.
`. . . Y R . . . W R . . . .`
Count:
0: .
1: .
2: .
3: Y
4: R
5: .
6: .
7: .
8: W
9: R
10: .
11: .
12: .
13: .
So Zone 1 (0-3): . . . Y
Zone 2 (5-8): . . . W
Zone 3 (10-13): . . . .
Output Row 0: . . . Y
Comparison:
Col 0: Z1=., Z2=., Z3=. -> Out=.
Col 1: Z1=., Z2=., Z3=. -> Out=.
Col 2: Z1=., Z2=., Z3=. -> Out=.
Col 3: Z1=Y, Z2=W, Z3=. -> Out=Y.
Rule: Y overrides W.

Row 1:
In: `Y Y . Y R W . W . R . . . .`
Z1: Y Y . Y
Z2: W . W . (Wait, indices 5,6,7,8. 5=W, 6=., 7=W, 8=.)
Z3: . . . .
Out: Y Y W Y
Col 0: Y, W, . -> Y
Col 1: Y, ., . -> Y
Col 2: ., W, . -> W
Col 3: Y, ., . -> Y
Rule: Y overrides W. W overrides ..

Row 2:
In: `Y . Y Y R . W W . R B B . B`
Z1: Y . Y Y
Z2: . W W .
Z3: B B . B
Out: Y W Y Y
Col 0: Y, ., B -> Y
Col 1: ., W, B -> W
Col 2: Y, W, . -> Y
Col 3: Y, ., B -> Y
Rule: Y overrides W and B. W overrides B. B overrides ..
Priority: Y > W > B > .

... [5489 chars truncated]
alt-6 architecture qwen3.5-122b: fig alone solves
"Three blueprints are printed on translucent vellum and stacked — the boldest ink shows through at each point."
alt-7 warfare qwen3.5-122b: fail
"Three armies converge on contested ground, and rank determines who holds each square of the battlefield."
Fail (best cell_acc=0.44 at k=1)
Best Attempt
vs
Expected
Reasoning (10529 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A long battlefield divided into three encampments by walls of fire.
*   **Forces:**
    *   Imperial Guard: Gold (Yellow/Y).
    *   Mercenaries: Dark Armor (Maroon/W).
    *   Conscripts: Blue (Blue/B).
*   **Action:** Fire walls fall. Forces rush to claim territory.
*   **Hierarchy/Conflict Resolution:**
    *   Imperial Guards (Y) seize any ground they touch. (Highest priority)
    *   Mercenaries (W) hold positions the guard ignored. (Medium priority)
    *   Conscripts (B) occupy what both others left vacant. (Lowest priority)
*   **Output:** A small square where each position flies the banner of whichever force outranked the rest.

**2. Analyze the Training Example:**
*   **Input Grid:**
    ```
    . . . Y R . . . W R . . . .
    Y Y . Y R W . W . R . . . .
    Y . Y Y R . W W . R B B . B
    . Y Y Y R . W . . R B B B B
    ```
    Dimensions: 4 rows, 14 columns.
    Colors present: . (black), Y (yellow), R (red), W (maroon), B (blue).
    Note: The metaphor mentions "walls of fire". In the input, there are columns of 'R' (Red).
    Let's look at the columns.
    Col 0: . Y Y .
    Col 1: . Y . Y
    Col 2: . . Y Y
    Col 3: Y Y Y Y
    Col 4: R R R R  <- This looks like a wall.
    Col 5: . W . .
    Col 6: . . W W
    Col 7: . W W .
    Col 8: . . . .
    Col 9: R R R R  <- Another wall.
    Col 10: . . B B
    Col 11: . . B B
    Col 12: . . . B
    Col 13: . . B B

    The input seems to be divided into three sections by the Red (R) columns.
    Section 1 (Left of first R): Cols 0-3. Contains mostly Y.
    Section 2 (Between Rs): Cols 5-8. Contains mostly W.
    Section 3 (Right of second R): Cols 10-13. Contains mostly B.

    The metaphor says: "Imperial guards seize any ground they touch. Mercenaries hold positions the guard ignored. Conscripts only occupy what both others left vacant."
    This implies a superposition or overlay logic.
    However, the output is a "small square".
    Input size: 4x14. Output size: 4x4.
    The output corresponds to the dimensions of one of the sections (4 rows, 4 columns).
    The sections are separated by walls of Red (R).
    Section 1: Cols 0-3 (Width 4).
    Section 2: Cols 5-8 (Width 4).
    Section 3: Cols 10-13 (Width 4).
    The walls are at Col 4 and Col 9.
    So the input consists of three 4x4 grids separated by 1-column walls of Red.

    **Transformation Logic:**
    We have three 4x4 grids (let's call them G1, G2, G3).
    G1 contains Y (Imperial Guard).
    G2 contains W (Mercenaries).
    G3 contains B (Conscripts).
    The output is a single 4x4 grid.
    The rule is about priority: Y > W > B.
    For each cell position (r, c) in the 4x4 output:
    - Check the corresponding cell in G1. If it is Y, Output is Y.
    - Else, check the corresponding cell in G2. If it is W, Output is W.
    - Else, check the corresponding cell in G3. If it is B, Output is B.
    - Else, Output is . (black/empty).

    Let's verify this with Example 1.
    **G1 (Cols 0-3):**
    . . . Y
    Y Y . Y
    Y . Y Y
    . Y Y Y

    **G2 (Cols 5-8):**
    . . . W
    W . W .
    . W W .
    . W . .
    Wait, let's look closer at the input columns for G2.
    Input Row 0: . . . Y R . . . W R ... -> Cols 5,6,7,8 are . . . W
    Input Row 1: Y Y . Y R W . W . R ... -> Cols 5,6,7,8 are W . W .
    Input Row 2: Y . Y Y R . W W . R ... -> Cols 5,6,7,8 are . W W .
    Input Row 3: . Y Y Y R . W . . R ... -> Cols 5,6,7,8 are . W . .

    **G3 (Cols 10-13):**
    Input Row 0: ... W R . . . . -> Cols 10,11,12,13 are . . . .
    Input Row 1: ... R . . . . -> Cols 10,11,12,13 are . . . .
    Input Row 2: ... R B B . B -> Cols 10,11,12,13 are B B . B
    Input Row 3: ... R B B B B -> Cols 10,11,12,13 are B B B B

    **Output:**
    . . . Y
    Y Y W Y
    Y W Y Y
    B Y Y Y

    Let's check cell by cell (r, c).
    (0,0): G1=., G2=., G3=. -> Output . (Matches)
    (0,1): G1=., G2=., G3=. -> Output . (Matches)
    (0,2): G1=., G2=., G3=. -> Output . (Matches)
    (0,3): G1=Y, G2=W, G3=. -> Priority Y > W. Output Y. (Matches)

    (1,0): G1=Y, G2=W, G3=. -> Priority Y. Output Y. (Matches)
    (1,1): G1=Y, G2=., G3=. -> Priority Y. Output Y. (Matches)
    (1,2): G1=., G2=W, G3=. -> Priority W. Output W. (Matches)
    (1,3): G1=Y, G2=., G3=. -> Priority Y. Output Y. (Matches)

    (2,0): G1=Y, G2=., G3=B -> Priority Y. Output Y. (Matches)
    (2,1): G1=., G2=W, G3=B -> Priority W. Output W. (Matches)
    (2,2): G1=Y, G2=W, G3=. -> Priority Y. Output Y. (Matches)
    (2,3): G1=Y, G2=., G3=B -> Priority Y. Output Y. (Matches)

    (3,0): G1=., G2=., G3=B -> Priority B. Output B. (Matches)
    (3,1): G1=Y, G2=W, G3=B -> Priority Y. Output Y. (Matches)
    (3,2): G1=Y, G2=., G3=B -> Priority Y. Output Y. (Matches)
    (3,3): G1=Y, G

... [5730 chars truncated]
alt-8 theater qwen3.5-122b: k=2
"Three casts rehearse the same scene on a triptych stage, and the star's spotlight always wins."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10931 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A wide stage split into three panels by curtains of crimson (Red).
*   **Characters:**
    *   Left panel: Leads in gold (Yellow).
    *   Middle panel: Understudies in somber tones (Grey? Black? Maroon? Let's check examples).
    *   Right panel: Chorus in blue (Blue).
    *   Background: Darkness (Black/Dot).
*   **Action:** Draw back the crimson curtains and collapse all three panels into one intimate stage.
*   **Priority Rule:**
    *   Lead (Yellow) > Understudy > Chorus (Blue).
    *   Chorus only occupies marks left entirely empty.
*   **Grid Details:** The final blocking diagram is a single compact stage where each mark belongs to whichever performer had highest billing.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
. . . Y R . . . W R . . . .
Y Y . Y R W . W . R . . . .
Y . Y Y R . W W . R B B . B
. Y Y Y R . W . . R B B B B

Output:
. . . Y
Y Y W Y
Y W Y Y
B Y Y Y

*   **Observation:**
    *   Input dimensions: 4 rows, 14 columns.
    *   Output dimensions: 4 rows, 4 columns.
    *   There are vertical lines of 'R' (Red) in the input.
    *   Let's locate the 'R's.
        *   Row 0: Col 4, Col 9.
        *   Row 1: Col 4, Col 9.
        *   Row 2: Col 4, Col 9.
        *   Row 3: Col 4, Col 9.
    *   The 'R's form two vertical dividers.
    *   This splits the grid into three sections:
        *   Left Section: Cols 0-3 (Width 4). Contains mostly 'Y' (Yellow).
        *   Middle Section: Cols 5-8 (Width 4). Contains mostly 'W' (Maroon) and '.'.
        *   Right Section: Cols 10-13 (Width 4). Contains mostly 'B' (Blue) and '.'.
    *   The Output is 4x4. This matches the width of each section.
    *   Let's look at the content of the Output compared to the sections.
    *   Output Row 0: `. . . Y`
        *   Left (0-3): `. . . Y`
        *   Middle (5-8): `. . . W`
        *   Right (10-13): `. . . .`
        *   Result: `. . . Y`. The 'Y' from Left overwrites the '.' from Middle and Right.
    *   Output Row 1: `Y Y W Y`
        *   Left: `Y Y . Y`
        *   Middle: `W . W .`
        *   Right: `. . . .`
        *   Result: `Y Y W Y`.
            *   Col 0: Left=Y, Mid=., Rgt=. -> Y
            *   Col 1: Left=Y, Mid=., Rgt=. -> Y
            *   Col 2: Left=., Mid=W, Rgt=. -> W
            *   Col 3: Left=Y, Mid=., Rgt=. -> Y
    *   Output Row 2: `Y W Y Y`
        *   Left: `Y . Y Y`
        *   Middle: `. W W .`
        *   Right: `B B . B`
        *   Result: `Y W Y Y`.
            *   Col 0: Left=Y, Mid=., Rgt=B -> Y (Lead > Chorus)
            *   Col 1: Left=., Mid=W, Rgt=B -> W (Understudy > Chorus)
            *   Col 2: Left=Y, Mid=W, Rgt=. -> Y (Lead > Understudy)
            *   Col 3: Left=Y, Mid=., Rgt=B -> Y (Lead > Chorus)
    *   Output Row 3: `B Y Y Y`
        *   Left: `. Y Y Y`
        *   Middle: `. W . .`
        *   Right: `B B B B`
        *   Result: `B Y Y Y`.
            *   Col 0: Left=., Mid=., Rgt=B -> B
            *   Col 1: Left=Y, Mid=W, Rgt=B -> Y (Lead > Understudy > Chorus)
            *   Col 2: Left=Y, Mid=., Rgt=B -> Y
            *   Col 3: Left=Y, Mid=., Rgt=B -> Y

    *   **Hypothesis:** The input grid is divided into three equal-width vertical strips separated by columns of Red ('R'). The output grid is formed by superimposing these three strips. The priority order is: Yellow ('Y') > Middle Color ('W' in this case) > Blue ('B') > Empty ('.').
    *   Wait, the metaphor says "Understudies in somber tones". In Example 1, the middle color is 'W' (Maroon). Maroon is somber.
    *   Priority: Yellow (Lead) > Maroon (Understudy) > Blue (Chorus).
    *   What if there are other colors? The metaphor says "somber tones". In Example 2, let's check.

**Example 2:**
Input:
Y Y Y Y R W . W . R . . . B
Y Y . . R W W . . R B . . .
Y . Y Y R . . . W R . B . B
. . . . R . . W . R B . B .

Output:
Y Y Y Y
Y Y . .
Y B Y Y
B . W .

*   **Observation:**
    *   Input dimensions: 4 rows, 14 columns.
    *   Output dimensions: 4 rows, 4 columns.
    *   Red ('R') columns are at indices 4 and 9.
    *   Left Strip (0-3):
        *   R0: Y Y Y Y
        *   R1: Y Y . .
        *   R2: Y . Y Y
        *   R3: . . . .
    *   Middle Strip (5-8):
        *   R0: W . W .
        *   R1: W W . .
        *   R2: . . . W
        *   R3: . . W .
    *   Right Strip (10-13):
        *   R0: . . . B
        *   R1: B . . .
        *   R2: . B . B
        *   R3: B . B .
    *   Output:
        *   R0: Y Y Y Y (Left dominates)
        *   R1: Y Y . . (Left dominates)
        *   R2: Y B Y Y
            *   Col 0: Left=Y, Mid=., Rgt=. -> Y
            *   Col 1: Left=., Mid=., Rgt=B -> B (Chorus takes empty)
            *   Col 2: Left=Y, Mid=., Rgt=. -> Y
            *   Col 3: Left=Y, Mid=W, Rgt=B -> Y (Lea

... [6177 chars truncated]
alt-9 gardening qwen3.5-122b: fig alone solves
"Three seed trays are pressed into one bed, and the most aggressive root system claims each plot."

Task 815: d364b489

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original Each blue star is a compass rose, casting its colored light in the four cardinal ... [12 chars truncated] MARC valid 1
alt-1 biology Each blue cell is a living organism that undergoes mitosis, budding off four dif ... [161 chars truncated] fail
alt-10 astronomy Blue protostars float in the void. Each one ignites and ejects four jets of diff ... [181 chars truncated] fail
alt-11 ocean/sailing Blue buoys bob in dark waters. Each buoy deploys four colored signal flags ̵ ... [143 chars truncated] MARC valid 1
alt-12 electronics Blue transistors sit on a dark circuit board. When powered, each transistor driv ... [179 chars truncated] MARC valid 1
alt-13 mythology Blue rune stones are scattered across a dark altar. When invoked, each stone awa ... [178 chars truncated] MARC valid 1
alt-14 dance Blue dancers stand poised on a dark ballroom floor. At the downbeat, each dancer ... [176 chars truncated] fail
alt-15 geology Blue volcanic vents puncture a dark basalt plain. Each vent erupts simultaneousl ... [160 chars truncated] MARC valid 1
alt-2 cooking The blue ingredients are pats of butter dropped onto a hot black skillet — ... [207 chars truncated] fail
alt-3 music Each blue note sits on a silent black staff. When struck, it resonates and produ ... [194 chars truncated] fail
alt-4 sports Each blue player stands on a dark field and executes a signature move — se ... [165 chars truncated] fail
alt-5 weather Blue storm eyes sit calmly in a dark sky. Around each eye, the storm wall spins ... [201 chars truncated] fail
alt-6 architecture Blue cornerstones are laid into a dark foundation. From each cornerstone, the ar ... [187 chars truncated] MARC valid 1
alt-7 warfare Blue command posts are established across a dark battlefield. Each post deploys ... [170 chars truncated] fail
alt-8 theater On a darkened stage, blue spotlights mark the positions of solo performers. As t ... [215 chars truncated] MARC valid 2
alt-9 gardening Blue seed pods rest in dark soil. When spring arrives, each pod splits open and ... [172 chars truncated] MARC valid 2
original qwen3.5-122b: k=1
"Each blue star is a compass rose, casting its colored light in the four cardinal directions."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (8720 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark night sky dotted with bright blue stars, each one alone in the void..." -> The input grid contains black dots (.) and blue dots (B).
*   **Action:** "When dawn begins, each blue star awakens as a compass rose, projecting its cardinal beams into the surrounding darkness..." -> Each 'B' in the input triggers a transformation in its neighbors.
*   **Beams:**
    *   "a warm glow to the north" -> North is Up. Color? "Warm glow" usually implies Red or Orange. Let's look at the examples.
    *   "a sunset hue to the west" -> West is Left. Color? "Sunset" often implies Orange or Red.
    *   "a violet flash to the east" -> East is Right. Color? "Violet" implies Magenta or Purple.
    *   "a cool shimmer to the south" -> South is Down. Color? "Cool shimmer" implies Blue, Cyan, or Azure.
    *   "The star itself remains blue at the center of its cross." -> The 'B' stays 'B'.
*   **Edge Cases:** "Stars near the edge of the sky simply lose whichever beam would fly beyond the horizon." -> If a neighbor is out of bounds, no color is placed there.
*   **Grid Details:** "North is at the top, west is at the left." Standard grid orientation.

**2. Analyze the Training Examples:**

**Example 1:**
Input Grid (10x10):
Row 0: . . . . . B . . . . (B at 0,5)
Row 1: . . . . . . . . . .
Row 2: B . . . . . . . . . (B at 2,0)
Row 3: . . . . . . . . . B (B at 3,9)
Row 4: . . . . . . . . . .
Row 5: . . . . . B . . . . (B at 5,5)
Row 6: . . . . . . . . . .
Row 7: . . . . . . . . . .
Row 8: . . B . . . . . . . (B at 8,2)
Row 9: . . . . . . . . . B (B at 9,9)

Output Grid (10x10):
Row 0: . . . . O B M . . .
Row 1: R . . . . A . . . .
Row 2: B M . . . . . . . R
Row 3: A . . . . . . . O B
Row 4: . . . . . R . . . A
Row 5: . . . . O B M . . .
Row 6: . . . . . A . . . .
Row 7: . . R . . . . . . .
Row 8: . O B M . . . . . R
Row 9: . . A . . . . . O B

Let's map the colors to directions based on the description and the output.
Center 'B' is at (0,5).
Neighbors in Output:
(0,4) is 'O'. West of (0,5).
(0,6) is 'M'. East of (0,5).
(1,5) is 'A'. South of (0,5).
North of (0,5) is out of bounds.

Center 'B' is at (2,0).
Neighbors in Output:
(2,1) is 'M'. East of (2,0).
(1,0) is 'R'. North of (2,0).
(3,0) is 'A'. South of (2,0).
West of (2,0) is out of bounds.

Center 'B' is at (3,9).
Neighbors in Output:
(3,8) is 'O'. West of (3,9).
(2,9) is 'R'. North of (3,9).
(4,9) is 'A'. South of (3,9).
East of (3,9) is out of bounds.

Center 'B' is at (5,5).
Neighbors in Output:
(5,4) is 'O'. West.
(5,6) is 'M'. East.
(4,5) is 'R'. North.
(6,5) is 'A'. South.

Center 'B' is at (8,2).
Neighbors in Output:
(8,1) is 'O'. West.
(8,3) is 'M'. East.
(7,2) is 'R'. North.
(9,2) is 'A'. South.

Center 'B' is at (9,9).
Neighbors in Output:
(9,8) is 'O'. West.
(8,9) is 'R'. North.
South and East are out of bounds.

**Mapping Colors to Directions:**
*   **North (Up):** 'R' (Red). Description said "warm glow". Red fits.
*   **West (Left):** 'O' (Orange). Description said "sunset hue". Orange fits.
*   **East (Right):** 'M' (Magenta). Description said "violet flash". Magenta fits.
*   **South (Down):** 'A' (Azure). Description said "cool shimmer". Azure fits.
*   **Center:** 'B' (Blue). Stays Blue.

**Conflict Resolution:**
What if two stars project beams onto the same cell?
In Example 1, let's check for overlaps.
B at (0,5) puts A at (1,5).
B at (5,5) puts R at (4,5).
B at (2,0) puts M at (2,1).
B at (3,9) puts O at (3,8).
B at (8,2) puts M at (8,3).
B at (9,9) puts O at (9,8).
There don't seem to be any overlaps in Example 1 where two beams land on the same cell.
Wait, let's look closer.
B at (0,5) -> South is (1,5) = A.
B at (5,5) -> North is (4,5) = R.
No overlap.
B at (2,0) -> East is (2,1) = M.
B at (8,2) -> North is (7,2) = R.
No overlap.
It seems Example 1 is sparse enough to avoid conflicts. I need to assume a rule for conflicts if they arise in the test input. Usually, in these puzzles, if a cell is already colored by one star, another might overwrite it, or they might not overlap. Or perhaps the order doesn't matter because the colors are distinct per direction.
Wait, if Star A puts 'R' (North) on a cell, and Star B puts 'O' (West) on the same cell, what happens?
Let's check the Test Input to see if overlaps occur.

**3. Analyze the Test Input:**
Grid Size: 10x10 (based on visual count, let's verify).
Row 0: . B . . . . . . . B  (B at 0,1 and 0,9)
Row 1: . . . . . . . . . .
Row 2: . . . . . . . B . .  (B at 2,7)
Row 3: . . . B . . . . . .  (B at 3,3)
Row 4: . . . . . . . . . .
Row 5: . . . . . . . . . .
Row 6: B . . . . . . B . .  (B at 6,0 and 6,7)
Row 7: . . . . . . . . . .
Row 8: . . . . . . . . . .
Row 9: . . . . B . . . . .  (B at 9,4)

Let's list the coordinates of 'B's:
1.  (0, 1)
2.  (0, 9)
3.  (2, 7)
4.  (3, 3)
5.  (6, 0)
6.  (6, 7)
7.  (9

... [3876 chars truncated]
alt-1 biology qwen3.5-122b: fail
"Each blue cell is a living organism that undergoes mitosis, budding off four differentiated daughter cells into its immediate neighborhood, each daughter expressing a unique pigment gene depending on which pole of the mother it emerged from."
Fail (best cell_acc=0.92 at k=2)
Best Attempt
vs
Expected
Reasoning (9794 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A dark petri dish with scattered blue organisms resting in isolation."
    *   "Dark petri dish" -> Black background (`.`).
    *   "Scattered blue organisms" -> Blue cells (`B`) are the active elements.
    *   "Resting in isolation" -> They don't touch each other in the input (need to verify this).
*   **Action:** "Each organism buds four specialized daughter cells into adjacent cardinal positions, each daughter differentiated by its polar orientation from the mother."
    *   "Each organism" -> Every `B` cell triggers an action.
    *   "Buds four specialized daughter cells" -> Four new cells appear around the `B`.
    *   "Adjacent cardinal positions" -> Up, Down, Left, Right neighbors.
    *   "Differentiated by its polar orientation" -> The color of the daughter cell depends on its direction relative to the mother `B`.
*   **Grid details:** 10x10 grid, black background. Dimensions unchanged.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input has `B` at (0,5), (2,0), (3,9), (5,5), (8,2), (9,9).
    *   Let's check the neighbors of a `B` in the output.
    *   Take `B` at (0,5).
        *   Left (0,4): `O` (Orange)
        *   Right (0,6): `M` (Magenta)
        *   Down (1,5): `A` (Azure)
        *   Up: Out of bounds.
    *   Take `B` at (2,0).
        *   Right (2,1): `M` (Magenta)
        *   Down (3,0): `A` (Azure)
        *   Left: Out of bounds.
        *   Up (1,0): `R` (Red)
    *   Take `B` at (3,9).
        *   Left (3,8): `O` (Orange)
        *   Up (2,9): `R` (Red)
        *   Down (4,9): `A` (Azure)
        *   Right: Out of bounds.
    *   Take `B` at (5,5).
        *   Left (5,4): `O` (Orange)
        *   Right (5,6): `M` (Magenta)
        *   Up (4,5): `R` (Red)
        *   Down (6,5): `A` (Azure)
    *   Take `B` at (8,2).
        *   Left (8,1): `O` (Orange)
        *   Right (8,3): `M` (Magenta)
        *   Up (7,2): `R` (Red)
        *   Down (9,2): `A` (Azure)
    *   Take `B` at (9,9).
        *   Left (9,8): `O` (Orange)
        *   Up (8,9): `R` (Red)
        *   Right/Down: Out of bounds.

    *   **Pattern Hypothesis:**
        *   Center: `B` (Blue) stays `B`.
        *   Left neighbor: `O` (Orange).
        *   Right neighbor: `M` (Magenta).
        *   Up neighbor: `R` (Red).
        *   Down neighbor: `A` (Azure).
        *   Background: `.` (Black).

    *   Let's verify this mapping with Example 2.

*   **Example 2:**
    *   Input `B` locations: (1,6), (3,9), (5,3), (7,7), (9,1).
    *   Check `B` at (1,6):
        *   Left (1,5): `O`
        *   Right (1,7): `M`
        *   Up (0,6): `R`
        *   Down (2,6): `A`
        *   Output matches: Row 0 col 6 is `R`. Row 1 col 5 is `O`, col 7 is `M`. Row 2 col 6 is `A`.
    *   Check `B` at (3,9):
        *   Left (3,8): `O`
        *   Up (2,9): `R`
        *   Down (4,9): `A`
        *   Output matches.
    *   Check `B` at (5,3):
        *   Left (5,2): `O`
        *   Right (5,4): `M`
        *   Up (4,3): `R`
        *   Down (6,3): `A`
        *   Output matches.
    *   Check `B` at (7,7):
        *   Left (7,6): `O`
        *   Right (7,8): `M`
        *   Up (6,7): `R`
        *   Down (8,7): `A`
        *   Output matches.
    *   Check `B` at (9,1):
        *   Left (9,0): `O`
        *   Right (9,2): `M`
        *   Up (8,1): `R`
        *   Down: Out of bounds.
        *   Output matches.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Mother Cell:** Blue (`B`).
    *   **Daughter Cells:** Orange (`O`), Magenta (`M`), Red (`R`), Azure (`A`).
    *   **Background:** Black (`.`).
    *   **Grid:** 10x10.

2.  **AFFORDANCES:**
    *   A `B` cell generates neighbors.
    *   Neighbors overwrite the background `.`.
    *   If neighbors overlap (not seen in examples, but possible in theory), usually one takes precedence or they merge. In the provided examples, `B`s are isolated enough that their immediate neighbors don't overlap with other `B`s or their neighbors. Wait, let's check overlap.
    *   Example 1: `B` at (0,5) and `B` at (5,5). Distance is 5. No overlap.
    *   Example 2: `B` at (1,6) and `B` at (3,9). Distance is far.
    *   Test Input: Let's check distances.
        *   (0,1) and (0,9).
        *   (2,7).
        *   (3,3).
        *   (6,0) and (6,6).
        *   (9,4).
        *   Closest pair: (2,7) and (3,3)? No. (6,0) and (6,6)? No.
        *   (0,1) and (3,3)? No.
        *   (2,7) and (6,6)? No.
        *   It seems `B`s are sufficiently isolated.
    *   What if a neighbor position is occupied by another `B`? The rule says "buds... into adjacent cardinal positions". Usually, the mother `B` remains. If a daughter lands on another `B`, the `B` likely stays `B` (Mother > Daughter). If a daughter lands on a daughter from another mother, we need a priority rule. However, 

... [4923 chars truncated]
alt-10 astronomy qwen3.5-122b: fail
"Blue protostars float in the void. Each one ignites and ejects four jets of differently-colored plasma — one jet fired one parsec in each cardinal direction, each jet's emission spectrum determined by its orientation relative to the star's magnetic poles."
Fail (best cell_acc=0.77 at k=1)
Best Attempt
vs
Expected
Reasoning (10776 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark void with blue protostars at scattered coordinates."
    *   "Dark void" implies a black background (`.`).
    *   "Blue protostars" implies blue pixels (`B`) are the active elements.
*   **Action:** "Each protostar ejects one uniquely colored plasma jet into each cardinal neighbor cell."
    *   "Cardinal neighbor" means Up, Down, Left, Right.
    *   "Uniquely colored plasma jet" implies that the color of the jet depends on the direction relative to the protostar.
    *   "Ejects... into" implies the neighbor cells change color.
*   **Grid:** 10x10, black background.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:**
        ```
        . . . . . B . . . .
        . . . . . . . . . .
        B . . . . . . . . .
        . . . . . . . . . B
        . . . . . . . . . .
        . . . . . B . . . .
        . . . . . . . . . .
        . . . . . . . . . .
        . . B . . . . . . .
        . . . . . . . . . B
        ```
        Blue pixels (`B`) are at: (0,5), (2,0), (3,9), (5,5), (8,2), (9,9).
    *   **Output:**
        ```
        . . . . O B M . . .
        R . . . . A . . . .
        B M . . . . . . . R
        A . . . . . . . O B
        . . . . . R . . . A
        . . . . O B M . . .
        . . . . . A . . . .
        . . R . . . . . . .
        . O B M . . . . . R
        . . A . . . . . O B
        ```
    *   **Observation:**
        *   The original `B` pixels remain `B`.
        *   Neighbors of `B` change color.
        *   Let's check the neighbors of the `B` at (0,5).
            *   Left (0,4): `O` (Orange)
            *   Right (0,6): `M` (Magenta)
            *   Down (1,5): `A` (Azure)
            *   Up: Out of bounds.
        *   Let's check the neighbors of the `B` at (2,0).
            *   Right (2,1): `M` (Magenta)
            *   Down (3,0): `A` (Azure)
            *   Left: Out of bounds.
            *   Up (1,0): `R` (Red)
        *   Let's check the neighbors of the `B` at (3,9).
            *   Left (3,8): `O` (Orange)
            *   Up (2,9): `R` (Red)
            *   Down (4,9): `A` (Azure)
            *   Right: Out of bounds.
        *   Let's check the neighbors of the `B` at (5,5).
            *   Left (5,4): `O` (Orange)
            *   Right (5,6): `M` (Magenta)
            *   Up (4,5): `R` (Red)
            *   Down (6,5): `A` (Azure)
        *   Let's check the neighbors of the `B` at (8,2).
            *   Left (8,1): `O` (Orange)
            *   Right (8,3): `M` (Magenta)
            *   Up (7,2): `R` (Red)
            *   Down (9,2): `A` (Azure)
        *   Let's check the neighbors of the `B` at (9,9).
            *   Left (9,8): `O` (Orange)
            *   Up (8,9): `R` (Red)
            *   Right: Out of bounds.
            *   Down: Out of bounds.

    *   **Pattern Identification:**
        *   **Up:** Red (`R`)
        *   **Down:** Azure (`A`)
        *   **Left:** Orange (`O`)
        *   **Right:** Magenta (`M`)
        *   **Center:** Blue (`B`) remains Blue.
        *   **Background:** Black (`.`) remains Black unless overwritten.
        *   **Conflict Resolution:** In Example 1, do any neighbors overlap?
            *   (0,5) neighbors: (0,4), (0,6), (1,5).
            *   (2,0) neighbors: (1,0), (2,1), (3,0).
            *   (3,9) neighbors: (2,9), (3,8), (4,9).
            *   (5,5) neighbors: (4,5), (5,4), (5,6), (6,5).
            *   (8,2) neighbors: (7,2), (8,1), (8,3), (9,2).
            *   (9,9) neighbors: (8,9), (9,8).
            *   No overlaps in Example 1.
            *   Wait, let's look closer at (1,0). It is `R`. This comes from `B` at (2,0) going Up.
            *   Let's look at (2,1). It is `M`. This comes from `B` at (2,0) going Right.
            *   Let's look at (3,0). It is `A`. This comes from `B` at (2,0) going Down.
            *   Let's look at (4,5). It is `R`. This comes from `B` at (5,5) going Up.
            *   Let's look at (6,5). It is `A`. This comes from `B` at (5,5) going Down.
            *   Let's look at (5,4). It is `O`. This comes from `B` at (5,5) going Left.
            *   Let's look at (5,6). It is `M`. This comes from `B` at (5,5) going Right.
            *   Let's look at (7,2). It is `R`. This comes from `B` at (8,2) going Up.
            *   Let's look at (9,2). It is `A`. This comes from `B` at (8,2) going Down.
            *   Let's look at (8,1). It is `O`. This comes from `B` at (8,2) going Left.
            *   Let's look at (8,3). It is `M`. This comes from `B` at (8,2) going Right.
            *   Let's look at (8,9). It is `R`. This comes from `B` at (9,9) going Up.
            *   Let's look at (9,8). It is `O`. This comes from `B` at (9,9) going Left.
            *   Let's look at (2,9). It is `R`. This comes from `B` at (3,9) going Up.
            *   Let's look at (4,9). It is `A`. 

... [5872 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=1
"Blue buoys bob in dark waters. Each buoy deploys four colored signal flags — one hoisted in each cardinal direction, each flag a different color to warn sailors of specific hazards to the north, south, east, and west."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (8758 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Dark ocean waters with blue buoys anchored at various positions."
    *   "Dark ocean waters" likely refers to the black background (`.`).
    *   "Blue buoys" refers to the blue cells (`B`).
*   **Action:** "Each buoy raises one uniquely colored signal flag in each cardinal neighbor cell."
    *   "Cardinal neighbor cell" means Up, Down, Left, Right.
    *   "Uniquely colored signal flag" implies that for each neighbor, a specific color is assigned.
    *   The phrase "uniquely colored" might mean the colors are distinct for each direction relative to the buoy, or distinct across the whole grid. Let's look at the examples to deduce the mapping.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
. . . . . B . . . .
. . . . . . . . . .
B . . . . . . . . .
. . . . . . . . . B
. . . . . . . . . .
. . . . . B . . . .
. . . . . . . . . .
. . . . . . . . . .
. . B . . . . . . .
. . . . . . . . . B
```
Output:
```
. . . . O B M . . .
R . . . . A . . . .
B M . . . . . . . R
A . . . . . . . O B
. . . . . R . . . A
. . . . O B M . . .
. . . . . A . . . .
. . R . . . . . . .
. O B M . . . . . R
. . A . . . . . O B
```

Let's look at specific `B` locations in the input and see what happens in the output.

*   **Buoy 1:** Input (0, 5) is `B`.
    *   Neighbors in Output:
        *   (0, 4) Left: `O` (Orange)
        *   (0, 6) Right: `M` (Magenta)
        *   (1, 5) Down: `A` (Azure)
        *   Up is out of bounds.
*   **Buoy 2:** Input (2, 0) is `B`.
    *   Neighbors in Output:
        *   (1, 0) Up: `R` (Red)
        *   (3, 0) Down: `A` (Azure)
        *   (2, 1) Right: `M` (Magenta)
        *   Left is out of bounds.
*   **Buoy 3:** Input (3, 9) is `B`.
    *   Neighbors in Output:
        *   (2, 9) Up: `R` (Red)
        *   (4, 9) Down: `A` (Azure)
        *   (3, 8) Left: `O` (Orange)
        *   Right is out of bounds.
*   **Buoy 4:** Input (5, 5) is `B`.
    *   Neighbors in Output:
        *   (4, 5) Up: `R` (Red)
        *   (6, 5) Down: `A` (Azure)
        *   (5, 4) Left: `O` (Orange)
        *   (5, 6) Right: `M` (Magenta)
*   **Buoy 5:** Input (8, 2) is `B`.
    *   Neighbors in Output:
        *   (7, 2) Up: `R` (Red)
        *   (9, 2) Down: `A` (Azure)
        *   (8, 1) Left: `O` (Orange)
        *   (8, 3) Right: `M` (Magenta)
*   **Buoy 6:** Input (9, 9) is `B`.
    *   Neighbors in Output:
        *   (8, 9) Up: `R` (Red)
        *   Left: `O` (Orange)
        *   Right/Down out of bounds.

**Pattern Deduction:**
It seems the colors assigned to the neighbors depend on the direction relative to the buoy.
*   **Up:** `R` (Red)
*   **Down:** `A` (Azure)
*   **Left:** `O` (Orange)
*   **Right:** `M` (Magenta)

Let's verify this hypothesis against all instances in Example 1.
*   Buoy at (0, 5): Left `O`, Right `M`, Down `A`. Matches.
*   Buoy at (2, 0): Up `R`, Right `M`, Down `A`. Matches.
*   Buoy at (3, 9): Up `R`, Left `O`, Down `A`. Matches.
*   Buoy at (5, 5): Up `R`, Left `O`, Right `M`, Down `A`. Matches.
*   Buoy at (8, 2): Up `R`, Left `O`, Right `M`, Down `A`. Matches.
*   Buoy at (9, 9): Up `R`, Left `O`. Matches.

Wait, check the output grid for overlaps or conflicts.
In Example 1, do any neighbor cells overlap?
*   Buoy (0,5) affects (0,4), (0,6), (1,5).
*   Buoy (2,0) affects (1,0), (3,0), (2,1).
*   Buoy (3,9) affects (2,9), (4,9), (3,8).
*   Buoy (5,5) affects (4,5), (6,5), (5,4), (5,6).
*   Buoy (8,2) affects (7,2), (9,2), (8,1), (8,3).
*   Buoy (9,9) affects (8,9).

None of these neighbor coordinates overlap in Example 1. So we don't know how conflicts are resolved (e.g., if two buoys are adjacent). However, the rule seems consistent:
*   `B` stays `B`.
*   `.` becomes a color based on its position relative to a `B`.
    *   If cell is `Up` of `B` -> `R`
    *   If cell is `Down` of `B` -> `A`
    *   If cell is `Left` of `B` -> `O`
    *   If cell is `Right` of `B` -> `M`
    *   If cell is `.` and not a neighbor of any `B`, it stays `.`.

Let's check the Test Input to see if there are any overlaps.

**3. Test Input Analysis:**
Grid size: 10x10.
Input Grid:
Row 0: `. B . . . . . . . B` -> B at (0, 1), B at (0, 9)
Row 1: `. . . . . . . . . .`
Row 2: `. . . . . . . B . .` -> B at (2, 7)
Row 3: `. . . B . . . . . .` -> B at (3, 3)
Row 4: `. . . . . . . . . .`
Row 5: `. . . . . . . . . .`
Row 6: `B . . . . . . B . .` -> B at (6, 0), B at (6, 7)
Row 7: `. . . . . . . . . .`
Row 8: `. . . . . . . . . .`
Row 9: `. . . . B . . . . .` -> B at (9, 4)

List of Buoys (B):
1.  (0, 1)
2.  (0, 9)
3.  (2, 7)
4.  (3, 3)
5.  (6, 0)
6.  (6, 7)
7.  (9, 4)

Let's determine the neighbors for each buoy and assign colors.
Rule:
*   Up (r-1, c) -> R
*   Down (r+1, c) -> A
*   Left (r, c-1) -> O
*   Right (r, c+1) -> M

**Processing Buoy 1: (0, 1)**
*   Up: (-1, 1) -> Out of 

... [3950 chars truncated]
alt-12 electronics qwen3.5-122b: k=1
"Blue transistors sit on a dark circuit board. When powered, each transistor drives current through four colored traces — one trace extending one node in each cardinal direction, each trace carrying a different voltage level visualized as a unique color."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9659 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A dark circuit board with blue transistors at various nodes."
*   **Action:** "Each transistor energizes one uniquely colored trace into each cardinal neighbor node."
*   **Grid:** 10x10, black background.
*   **Input:** Contains black (`.`) and blue (`B`) cells.
*   **Output:** Contains black (`.`), blue (`B`), and other colors (`R`, `G`, `Y`, `X`, `M`, `O`, `A`, `W`).

**2. Analyze the Training Example (Example 1):**
*   **Input Grid:**
    *   (0, 5) is B
    *   (2, 0) is B
    *   (3, 9) is B
    *   (5, 5) is B
    *   (8, 2) is B
    *   (9, 9) is B
    *   Rest are `.`
*   **Output Grid:**
    *   Let's look at the neighbors of the `B` cells in the input.
    *   **B at (0, 5):**
        *   Neighbors: (0, 4), (0, 6), (1, 5). (Top is out of bounds).
        *   Output at (0, 4) is `O` (Orange).
        *   Output at (0, 6) is `M` (Magenta).
        *   Output at (1, 5) is `A` (Azure).
        *   The `B` itself remains `B`.
    *   **B at (2, 0):**
        *   Neighbors: (1, 0), (3, 0), (2, 1). (Left is out of bounds).
        *   Output at (1, 0) is `R` (Red).
        *   Output at (3, 0) is `A` (Azure).
        *   Output at (2, 1) is `M` (Magenta).
        *   The `B` itself remains `B`.
    *   **B at (3, 9):**
        *   Neighbors: (2, 9), (4, 9), (3, 8). (Right is out of bounds).
        *   Output at (2, 9) is `R` (Red).
        *   Output at (4, 9) is `A` (Azure).
        *   Output at (3, 8) is `O` (Orange).
        *   The `B` itself remains `B`.
    *   **B at (5, 5):**
        *   Neighbors: (4, 5), (6, 5), (5, 4), (5, 6).
        *   Output at (4, 5) is `R` (Red).
        *   Output at (6, 5) is `A` (Azure).
        *   Output at (5, 4) is `O` (Orange).
        *   Output at (5, 6) is `M` (Magenta).
        *   The `B` itself remains `B`.
    *   **B at (8, 2):**
        *   Neighbors: (7, 2), (9, 2), (8, 1), (8, 3).
        *   Output at (7, 2) is `R` (Red).
        *   Output at (9, 2) is `A` (Azure).
        *   Output at (8, 1) is `O` (Orange).
        *   Output at (8, 3) is `M` (Magenta).
        *   The `B` itself remains `B`.
    *   **B at (9, 9):**
        *   Neighbors: (8, 9), (9, 8). (Bottom and Right out of bounds).
        *   Output at (8, 9) is `R` (Red).
        *   Output at (9, 8) is `O` (Orange).
        *   The `B` itself remains `B`.

**3. Identify the Pattern/Rules:**
*   **Source:** Blue (`B`) cells act as sources.
*   **Target:** The immediate cardinal neighbors (Up, Down, Left, Right) of the Blue cells change color.
*   **Color Mapping:**
    *   Let's check the direction-to-color mapping.
    *   **B at (0, 5):**
        *   Left (0, 4) -> `O`
        *   Right (0, 6) -> `M`
        *   Down (1, 5) -> `A`
    *   **B at (2, 0):**
        *   Up (1, 0) -> `R`
        *   Down (3, 0) -> `A`
        *   Right (2, 1) -> `M`
    *   **B at (3, 9):**
        *   Up (2, 9) -> `R`
        *   Down (4, 9) -> `A`
        *   Left (3, 8) -> `O`
    *   **B at (5, 5):**
        *   Up (4, 5) -> `R`
        *   Down (6, 5) -> `A`
        *   Left (5, 4) -> `O`
        *   Right (5, 6) -> `M`
    *   **B at (8, 2):**
        *   Up (7, 2) -> `R`
        *   Down (9, 2) -> `A`
        *   Left (8, 1) -> `O`
        *   Right (8, 3) -> `M`
    *   **B at (9, 9):**
        *   Up (8, 9) -> `R`
        *   Left (9, 8) -> `O`

*   **Consistent Mapping:**
    *   **Up (North):** Red (`R`)
    *   **Down (South):** Azure (`A`)
    *   **Left (West):** Orange (`O`)
    *   **Right (East):** Magenta (`M`)
    *   **Center (Source):** Blue (`B`) remains Blue.
    *   **Background:** Black (`.`) remains Black unless overwritten by a trace.

*   **Conflict Resolution:**
    *   What if two `B` cells are adjacent?
    *   In Example 1, no `B` cells are adjacent.
    *   In the Test Input, let's check for adjacency.
    *   Test Input `B` locations:
        *   (0, 1)
        *   (0, 9)
        *   (2, 7)
        *   (3, 3)
        *   (6, 0)
        *   (6, 7)
        *   (9, 4)
    *   Let's check distances.
        *   (0, 1) and (0, 9) - far.
        *   (0, 1) and (2, 7) - far.
        *   (2, 7) and (3, 3) - far.
        *   (2, 7) and (6, 7) - same column, distance 4.
        *   (6, 0) and (6, 7) - same row, distance 7.
        *   (6, 7) and (9, 4) - far.
    *   It seems no `B` cells are adjacent in the test input either. So no overlap conflicts to resolve.
    *   Wait, let's double check the coordinates.
    *   Input:
        Row 0: . B . . . . . . . B  -> (0, 1), (0, 9)
        Row 1: . . . . . . . . . .
        Row 2: . . . . . . . B . .  -> (2, 7)
        Row 3: . . . B . . . . . .  -> (3, 3)
        Row 4: . . . . . . . . . .
        Row 5: . . . . . . . . . .
        Row 6: B . . . . . . B . .  -> (6, 0), (6, 7)
        Row 

... [4881 chars truncated]
alt-13 mythology qwen3.5-122b: k=1
"Blue rune stones are scattered across a dark altar. When invoked, each stone awakens four guardian spirits — one spirit manifesting in each cardinal direction, one step from the stone, each spirit cloaked in a color that reveals which wind it commands."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9145 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark altar with blue rune stones placed at scattered positions."
    *   "Dark altar" -> Black background (`.`).
    *   "Blue rune stones" -> Blue cells (`B`).
*   **Action:** "Each rune stone summons one uniquely colored spirit into each cardinal neighbor cell."
    *   "Cardinal neighbor cell" -> Up, Down, Left, Right neighbors.
    *   "Uniquely colored spirit" -> This implies specific colors for specific directions relative to the rune stone.
    *   "Summons" -> The spirit appears in the neighbor cell.
*   **Grid:** 10x10, black background.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:**
        *   (0, 5) is B
        *   (2, 0) is B
        *   (3, 9) is B
        *   (5, 5) is B
        *   (8, 2) is B
        *   (9, 9) is B
    *   **Output:**
        *   Let's look at the neighbors of the B at (0, 5).
            *   Left (0, 4): `O` (Orange)
            *   Right (0, 6): `M` (Magenta)
            *   Down (1, 5): `A` (Azure)
            *   Up: Out of bounds.
        *   Let's look at the neighbors of the B at (2, 0).
            *   Right (2, 1): `M` (Magenta)
            *   Down (3, 0): `A` (Azure)
            *   Left: Out of bounds.
            *   Up (1, 0): `R` (Red)
        *   Let's look at the neighbors of the B at (3, 9).
            *   Left (3, 8): `O` (Orange)
            *   Up (2, 9): `R` (Red)
            *   Down (4, 9): `A` (Azure)
            *   Right: Out of bounds.
        *   Let's look at the neighbors of the B at (5, 5).
            *   Left (5, 4): `O` (Orange)
            *   Right (5, 6): `M` (Magenta)
            *   Up (4, 5): `R` (Red)
            *   Down (6, 5): `A` (Azure)
        *   Let's look at the neighbors of the B at (8, 2).
            *   Left (8, 1): `O` (Orange)
            *   Right (8, 3): `M` (Magenta)
            *   Up (7, 2): `R` (Red)
            *   Down (9, 2): `A` (Azure)
        *   Let's look at the neighbors of the B at (9, 9).
            *   Left (9, 8): `O` (Orange)
            *   Up (8, 9): `R` (Red)
            *   Right/Down: Out of bounds.

    *   **Pattern Identification:**
        *   Blue (`B`) is the source.
        *   Neighbors change color based on direction relative to the `B`.
        *   **Left** neighbor becomes **Orange (`O`)**.
        *   **Right** neighbor becomes **Magenta (`M`)**.
        *   **Up** neighbor becomes **Red (`R`)**.
        *   **Down** neighbor becomes **Azure (`A`)**.
        *   The `B` itself remains `B`.
        *   If multiple `B`s affect the same cell, there might be a conflict. In Example 1, do any neighbors overlap?
            *   (0,5) affects (0,4), (0,6), (1,5).
            *   (2,0) affects (1,0), (2,1), (3,0).
            *   (3,9) affects (2,9), (3,8), (4,9).
            *   (5,5) affects (4,5), (5,4), (5,6), (6,5).
            *   (8,2) affects (7,2), (8,1), (8,3), (9,2).
            *   (9,9) affects (8,9), (9,8).
            *   No overlaps in Example 1.
        *   What about the background? It stays black (`.`) unless overwritten by a spirit.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Blue Rune Stones (`B`):** The active agents. They stay in place.
    *   **Black Background (`.`):** The passive canvas.
    *   **Spirits (`O`, `M`, `R`, `A`):** The effects generated by the stones in adjacent cells.

2.  **AFFORDANCES:**
    *   `B` generates colored cells in its 4 cardinal directions.
    *   `.` can be overwritten by spirits.
    *   Boundaries limit where spirits can appear.

3.  **TRANSFORMATION RULE:**
    *   Iterate through every cell in the grid.
    *   If a cell contains `B`:
        *   Keep it as `B`.
        *   Check its neighbors:
            *   **Up** (row - 1, col): Set to `R` (Red).
            *   **Down** (row + 1, col): Set to `A` (Azure).
            *   **Left** (row, col - 1): Set to `O` (Orange).
            *   **Right** (row, col + 1): Set to `M` (Magenta).
    *   If a cell is `.` and not affected by any `B`, it remains `.`.
    *   If a cell is affected by multiple `B`s (overlap), I need to check if there's a precedence rule. Since the training example doesn't show overlaps, I will assume standard overwriting or that overlaps don't happen in the test case. If they do, usually the last one processed or a specific priority applies. However, looking at the test input, I should check for overlaps.

**4. Apply Rule to Test Input:**

**Test Input Grid:**
Row 0: `. B . . . . . . . B`
Row 1: `. . . . . . . . . .`
Row 2: `. . . . . . . B . .`
Row 3: `. . . B . . . . . .`
Row 4: `. . . . . . . . . .`
Row 5: `. . . . . . . . . .`
Row 6: `B . . . . . . B . .`
Row 7: `. . . . . . . . . .`
Row 8: `. . . . . . . . . .`
Row 9: `. . . . B . . . . .`

**Locations of `B`:**
1.  (0, 1)
2.  (0, 9)
3.  (2, 7)
4.  (3, 3)
5.  (6, 0)
6.  (6

... [4160 chars truncated]
alt-14 dance qwen3.5-122b: fail
"Blue dancers stand poised on a dark ballroom floor. At the downbeat, each dancer extends four limbs — one reaching toward each cardinal direction — and each limb trails a differently colored ribbon one pace outward, painting the adjacent tiles."
Fail (best cell_acc=0.77 at k=1)
Best Attempt
vs
Expected
Reasoning (9135 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A dark ballroom floor (black background) with blue dancers (blue pixels).
*   **Action:** Each dancer extends one uniquely colored ribbon into each cardinal neighbor tile.
*   **Grid:** 10x10, black background.
*   **Input:** Contains blue pixels ('B') on a black background ('.').
*   **Output:** Should contain the original blue pixels plus new colored pixels around them.

**2. Analyze the Training Example 1:**
*   **Input:**
    ```
    . . . . . B . . . .
    . . . . . . . . . .
    B . . . . . . . . .
    . . . . . . . . . B
    . . . . . . . . . .
    . . . . . B . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . B . . . . . . .
    . . . . . . . . . B
    ```
    Blue pixels at: (0,5), (2,0), (3,9), (5,5), (8,2), (9,9).

*   **Output:**
    ```
    . . . . O B M . . .
    R . . . . A . . . .
    B M . . . . . . . R
    A . . . . . . . O B
    . . . . . R . . . A
    . . . . O B M . . .
    . . . . . A . . . .
    . . R . . . . . . .
    . O B M . . . . . R
    . . A . . . . . O B
    ```

*   **Observation of Changes:**
    *   The original 'B' pixels remain 'B'.
    *   Around each 'B', there are new colored pixels in the cardinal directions (Up, Down, Left, Right).
    *   Let's check the neighbors of the 'B' at (0,5):
        *   Left (0,4): 'O' (Orange)
        *   Right (0,6): 'M' (Magenta)
        *   Down (1,5): 'A' (Azure)
        *   Up: Out of bounds.
    *   Let's check the neighbors of the 'B' at (2,0):
        *   Right (2,1): 'M' (Magenta)
        *   Down (3,0): 'A' (Azure)
        *   Left: Out of bounds.
        *   Up (1,0): 'R' (Red)
    *   Let's check the neighbors of the 'B' at (3,9):
        *   Left (3,8): 'O' (Orange)
        *   Up (2,9): 'R' (Red)
        *   Down (4,9): 'A' (Azure)
        *   Right: Out of bounds.
    *   Let's check the neighbors of the 'B' at (5,5):
        *   Left (5,4): 'O' (Orange)
        *   Right (5,6): 'M' (Magenta)
        *   Up (4,5): 'R' (Red)
        *   Down (6,5): 'A' (Azure)
    *   Let's check the neighbors of the 'B' at (8,2):
        *   Left (8,1): 'O' (Orange)
        *   Right (8,3): 'M' (Magenta)
        *   Up (7,2): 'R' (Red)
        *   Down (9,2): 'A' (Azure)
    *   Let's check the neighbors of the 'B' at (9,9):
        *   Left (9,8): 'O' (Orange)
        *   Up (8,9): 'R' (Red)
        *   Right: Out of bounds.
        *   Down: Out of bounds.

*   **Pattern Identification:**
    *   For every Blue pixel ('B') at position $(r, c)$:
        *   The pixel to the **Left** $(r, c-1)$ becomes **Orange** ('O').
        *   The pixel to the **Right** $(r, c+1)$ becomes **Magenta** ('M').
        *   The pixel **Above** $(r-1, c)$ becomes **Red** ('R').
        *   The pixel **Below** $(r+1, c)$ becomes **Azure** ('A').
    *   What happens if multiple 'B's affect the same tile?
        *   In Example 1, there are no overlapping neighbor tiles.
        *   Let's check the Test Input for overlaps.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Dancers:** Blue pixels ('B'). They are the sources of the transformation.
    *   **Floor:** Black background ('.'). This is the canvas.
    *   **Ribbons:** The colored pixels ('O', 'M', 'R', 'A') that appear in the cardinal directions adjacent to the dancers.

2.  **AFFORDANCES:**
    *   A 'B' pixel can generate colored neighbors.
    *   A '.' pixel can be overwritten by a ribbon color if it is adjacent to a 'B'.
    *   A 'B' pixel remains 'B' (it is the source).
    *   Boundary conditions: If a neighbor is out of bounds, no ribbon is placed there.

3.  **TRANSFORMATION RULE:**
    *   Iterate through every cell in the grid.
    *   If a cell contains 'B':
        *   Set cell $(r, c-1)$ to 'O' (if valid).
        *   Set cell $(r, c+1)$ to 'M' (if valid).
        *   Set cell $(r-1, c)$ to 'R' (if valid).
        *   Set cell $(r+1, c)$ to 'A' (if valid).
    *   If a cell is not 'B' and not affected by a 'B', it remains '.'.
    *   If a cell is affected by multiple 'B's, we need to determine priority. Looking at the training example, there are no conflicts. However, usually in these puzzles, if there's a conflict, one color might overwrite another, or they might sum up. Given the specific colors (Left=O, Right=M, Up=R, Down=A), it's likely a deterministic mapping based on direction relative to the source. If two sources target the same cell, it implies a conflict. Let's look at the Test Input to see if conflicts exist.

**4. Analyze Test Input:**
Input Grid:
```
. B . . . . . . . B
. . . . . . . . . .
. . . . . . . B . .
. . . B . . . . . .
. . . . . . . . . .
. . . . . . . . . .
B . . . . . . B . .
. . . . . . . . . .
. . . . . . . . . .
. . . . B . . . . .
```
Coordinates of 'B':
1.  (0, 1)
2.  (0, 9)
3.  (2, 7)
4.  (3, 3)
5.  (6, 0)
6.  (6, 6)
7.  (9, 4)

Let's list the target cells for eac

... [4219 chars truncated]
alt-15 geology qwen3.5-122b: k=1
"Blue volcanic vents puncture a dark basalt plain. Each vent erupts simultaneously in four cardinal directions, depositing a unique mineral in each — one colored deposit per direction, extending exactly one cell outward from the mouth."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (8864 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A dark basalt plain with blue volcanic vents at scattered locations."
    *   "Dark basalt plain" -> Black background (`.`).
    *   "Blue volcanic vents" -> Blue cells (`B`) in the input grid.
*   **Action:** "Each vent deposits one uniquely colored mineral into each cardinal neighbor cell."
    *   "Vent" -> The blue cell (`B`).
    *   "Deposits" -> Changes the color of the neighbor cells.
    *   "One uniquely colored mineral" -> This implies the color depends on the direction or position relative to the vent.
    *   "Each cardinal neighbor cell" -> Up, Down, Left, Right neighbors of the `B` cell.
*   **Grid Details:** 10x10 grid, black background.

**2. Analyze the Training Examples:**

*   **Example 1 Input:**
    *   Row 0: `B` at (0, 5)
    *   Row 2: `B` at (2, 0)
    *   Row 3: `B` at (3, 9)
    *   Row 5: `B` at (5, 5)
    *   Row 8: `B` at (8, 2)
    *   Row 9: `B` at (9, 9)
    *   Rest are `.` (black).

*   **Example 1 Output:**
    *   Let's look at the neighbors of the `B` cells in the output.
    *   **Vent at (0, 5):**
        *   Left (0, 4): `O` (Orange)
        *   Right (0, 6): `M` (Magenta)
        *   Down (1, 5): `A` (Azure)
        *   Up: Out of bounds.
    *   **Vent at (2, 0):**
        *   Right (2, 1): `M` (Magenta)
        *   Down (3, 0): `A` (Azure)
        *   Left: Out of bounds.
        *   Up (1, 0): `R` (Red)
    *   **Vent at (3, 9):**
        *   Left (3, 8): `O` (Orange)
        *   Up (2, 9): `R` (Red)
        *   Down (4, 9): `A` (Azure)
        *   Right: Out of bounds.
    *   **Vent at (5, 5):**
        *   Left (5, 4): `O` (Orange)
        *   Right (5, 6): `M` (Magenta)
        *   Up (4, 5): `R` (Red)
        *   Down (6, 5): `A` (Azure)
    *   **Vent at (8, 2):**
        *   Left (8, 1): `O` (Orange)
        *   Right (8, 3): `M` (Magenta)
        *   Up (7, 2): `R` (Red)
        *   Down (9, 2): `A` (Azure)
    *   **Vent at (9, 9):**
        *   Left (9, 8): `O` (Orange)
        *   Up (8, 9): `R` (Red)
        *   Right: Out of bounds.
        *   Down: Out of bounds.

*   **Pattern Recognition:**
    *   The `B` cells remain `B` in the output.
    *   The neighbors change color based on their direction relative to the `B` cell.
    *   **Left Neighbor:** Becomes `O` (Orange).
    *   **Right Neighbor:** Becomes `M` (Magenta).
    *   **Up Neighbor:** Becomes `R` (Red).
    *   **Down Neighbor:** Becomes `A` (Azure).
    *   Let's verify this mapping across all vents in Example 1.
        *   (0, 5): Left(0,4)=O, Right(0,6)=M, Down(1,5)=A. Matches.
        *   (2, 0): Right(2,1)=M, Down(3,0)=A, Up(1,0)=R. Matches.
        *   (3, 9): Left(3,8)=O, Up(2,9)=R, Down(4,9)=A. Matches.
        *   (5, 5): Left(5,4)=O, Right(5,6)=M, Up(4,5)=R, Down(6,5)=A. Matches.
        *   (8, 2): Left(8,1)=O, Right(8,3)=M, Up(7,2)=R, Down(9,2)=A. Matches.
        *   (9, 9): Left(9,8)=O, Up(8,9)=R. Matches.
    *   **Conflict Resolution:** What if two vents affect the same cell?
        *   In Example 1, there are no overlapping neighbor cells.
        *   Let's check the Test Input for potential overlaps.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Background:** Black (`.`).
    *   **Vents:** Blue (`B`). These are the sources of the transformation.
    *   **Minerals:** The colors deposited in the neighbor cells (Red, Orange, Magenta, Azure).
    *   **Grid:** 10x10 canvas.

2.  **AFFORDANCES:**
    *   A `B` cell can influence its 4 cardinal neighbors (Up, Down, Left, Right).
    *   A `.` cell can be overwritten by a mineral color if it is adjacent to a `B`.
    *   A `B` cell stays `B`.

3.  **TRANSFORMATION RULE:**
    *   Iterate through every cell in the grid.
    *   If a cell contains `B`:
        *   Keep it as `B`.
        *   Check its neighbors.
        *   If the neighbor is to the **Left** (col - 1), set it to **Orange (`O`)**.
        *   If the neighbor is to the **Right** (col + 1), set it to **Magenta (`M`)**.
        *   If the neighbor is **Up** (row - 1), set it to **Red (`R`)**.
        *   If the neighbor is **Down** (row + 1), set it to **Azure (`A`)**.
    *   If a cell is `.` and not adjacent to any `B`, it remains `.`.
    *   **Priority/Overlap:** If a cell is a neighbor to multiple `B`s, which color takes precedence?
        *   Looking at the metaphor: "Each vent deposits...". Usually, in these puzzles, if there's a conflict, there might be a specific order or they might not overlap in the test case.
        *   Let's check the Test Input for overlaps.

**4. Apply Rule to Test Input:**

**Test Input Grid:**
Row 0: `. B . . . . . . . B`  -> B at (0, 1), B at (0, 9)
Row 1: `. . . . . . . . . .`
Row 2: `. . . . . . . B . .`  -> B at (2, 7)
Row 3: `. . . B . . . . . .`  -> B at (3, 3)
Row 4: `. . . . . . . . . .`
Row 5: `. . . . . . 

... [3897 chars truncated]
alt-2 cooking qwen3.5-122b: fail
"The blue ingredients are pats of butter dropped onto a hot black skillet — as they melt, each one sends colored rivulets of seasoning in the four cardinal directions: a single dash of paprika upward, turmeric leftward, beet reduction rightward, and a cool mint glaze dripping down."
Fail (best cell_acc=0.77 at k=1)
Best Attempt
vs
Expected
Reasoning (9063 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark iron skillet with blue pats of butter at scattered positions."
    *   "Dark iron skillet" -> Black background (`.`).
    *   "Blue pats of butter" -> Blue pixels (`B`).
*   **Action:** "Each pat melts and releases exactly one colored seasoning streak into each cardinal neighbor cell, each direction producing a distinct spice color."
    *   "Each pat" -> Every `B` in the input grid.
    *   "Melts" -> The `B` remains? Or disappears? Let's check the examples.
    *   "Releases exactly one colored seasoning streak into each cardinal neighbor cell" -> For every `B`, look at its 4 neighbors (Up, Down, Left, Right).
    *   "Each direction producing a distinct spice color" -> This implies a mapping from direction to color.
    *   "Cardinal neighbor cell" -> Up, Down, Left, Right.
    *   "Distinct spice color" -> The colors used in the output for the neighbors must be specific to the direction relative to the `B`.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
. . . . . B . . . .
. . . . . . . . . .
B . . . . . . . . .
. . . . . . . . . B
. . . . . . . . . .
. . . . . B . . . .
. . . . . . . . . .
. . . . . . . . . .
. . B . . . . . . .
. . . . . . . . . B
```
Output:
```
. . . . O B M . . .
R . . . . A . . . .
B M . . . . . . . R
A . . . . . . . O B
. . . . . R . . . A
. . . . O B M . . .
. . . . . A . . . .
. . R . . . . . . .
. O B M . . . . . R
. . A . . . . . O B
```

Let's look at specific `B` locations in the input and see what happens in the output.

*   **Input `B` at (0, 5):** (Row 0, Col 5)
    *   Neighbors:
        *   Up: None (boundary)
        *   Down: (1, 5) -> Output has `A` at (1, 5).
        *   Left: (0, 4) -> Output has `O` at (0, 4).
        *   Right: (0, 6) -> Output has `M` at (0, 6).
    *   The `B` itself remains `B` at (0, 5).

*   **Input `B` at (2, 0):**
    *   Neighbors:
        *   Up: (1, 0) -> Output has `R` at (1, 0).
        *   Down: (3, 0) -> Output has `A` at (3, 0).
        *   Left: None.
        *   Right: (2, 1) -> Output has `M` at (2, 1).
    *   The `B` itself remains `B` at (2, 0).

*   **Input `B` at (3, 9):**
    *   Neighbors:
        *   Up: (2, 9) -> Output has `R` at (2, 9).
        *   Down: (4, 9) -> Output has `A` at (4, 9).
        *   Left: (3, 8) -> Output has `O` at (3, 8).
        *   Right: None.
    *   The `B` itself remains `B` at (3, 9).

*   **Input `B` at (5, 5):**
    *   Neighbors:
        *   Up: (4, 5) -> Output has `R` at (4, 5).
        *   Down: (6, 5) -> Output has `A` at (6, 5).
        *   Left: (5, 4) -> Output has `O` at (5, 4).
        *   Right: (5, 6) -> Output has `M` at (5, 6).
    *   The `B` itself remains `B` at (5, 5).

*   **Input `B` at (8, 2):**
    *   Neighbors:
        *   Up: (7, 2) -> Output has `R` at (7, 2).
        *   Down: (9, 2) -> Output has `A` at (9, 2).
        *   Left: (8, 1) -> Output has `O` at (8, 1).
        *   Right: (8, 3) -> Output has `M` at (8, 3).
    *   The `B` itself remains `B` at (8, 2).

*   **Input `B` at (9, 9):**
    *   Neighbors:
        *   Up: (8, 9) -> Output has `R` at (8, 9).
        *   Down: None.
        *   Left: (9, 8) -> Output has `O` at (9, 8).
        *   Right: None.
    *   The `B` itself remains `B` at (9, 9).

**Pattern Identification:**
For every Blue (`B`) cell in the input:
1.  The cell itself stays Blue (`B`).
2.  The cell to the **Left** becomes **Orange (`O`)**.
3.  The cell to the **Right** becomes **Magenta (`M`)**.
4.  The cell **Above** (Up) becomes **Red (`R`)**.
5.  The cell **Below** (Down) becomes **Azure (`A`)**.

Let's verify this mapping with the colors provided in the key:
*   Left: `O` (Orange)
*   Right: `M` (Magenta)
*   Up: `R` (Red)
*   Down: `A` (Azure)

Let's check for conflicts. In Example 1, do any neighbor cells overlap?
*   `B` at (0,5) puts `A` at (1,5).
*   `B` at (5,5) puts `R` at (4,5).
*   `B` at (2,0) puts `M` at (2,1).
*   `B` at (3,9) puts `R` at (2,9).
*   `B` at (8,2) puts `R` at (7,2).
*   `B` at (9,9) puts `R` at (8,9).
*   `B` at (0,5) puts `O` at (0,4).
*   `B` at (3,9) puts `O` at (3,8).
*   `B` at (5,5) puts `O` at (5,4).
*   `B` at (8,2) puts `O` at (8,1).
*   `B` at (9,9) puts `O` at (9,8).
*   `B` at (0,5) puts `M` at (0,6).
*   `B` at (2,0) puts `M` at (2,1).
*   `B` at (5,5) puts `M` at (5,6).
*   `B` at (8,2) puts `M` at (8,3).
*   `B` at (0,5) puts `A` at (1,5).
*   `B` at (3,9) puts `A` at (4,9).
*   `B` at (5,5) puts `A` at (6,5).
*   `B` at (8,2) puts `A` at (9,2).

Wait, let's check overlap at (2,1).
`B` at (2,0) -> Right neighbor is (2,1). Color `M`.
Is there another `B` affecting (2,1)?
`B` at (0,5) -> Down is (1,5).
`B` at (5,5) -> Up is (4,5).
`B` at (3,9) -> Left is (3,8).
`B` at (8,2) -> Up is (7,2).
`B` at

... [4162 chars truncated]
alt-3 music qwen3.5-122b: fail
"Each blue note sits on a silent black staff. When struck, it resonates and produces four harmonic overtones — each overtone rings out to one adjacent position in the cardinal directions, and each direction vibrates at a different frequency, glowing with its own color."
Fail (best cell_acc=0.77 at k=1)
Best Attempt
vs
Expected
Reasoning (9687 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A silent dark score with blue notes placed at scattered positions." -> Black background (.), Blue notes (B).
*   **Action:** "Each blue note resonates, producing one colored harmonic in each cardinal neighbor, with the color determined by direction."
*   **Grid:** 10x10, black background.
*   **Key:** `.`=black, `B`=blue, `R`=red, `G`=green, `Y`=yellow, `X`=grey, `M`=magenta, `O`=orange, `A`=azure, `W`=maroon.

**2. Analyze the Training Example (Example 1):**
*   **Input:**
    ```
    . . . . . B . . . .
    . . . . . . . . . .
    B . . . . . . . . .
    . . . . . . . . . B
    . . . . . . . . . .
    . . . . . B . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . B . . . . . . .
    . . . . . . . . . B
    ```
    Blue pixels at: (0,5), (2,0), (3,9), (5,5), (8,2), (9,9). (Row, Col)

*   **Output:**
    ```
    . . . . O B M . . .
    R . . . . A . . . .
    B M . . . . . . . R
    A . . . . . . . O B
    . . . . . R . . . A
    . . . . O B M . . .
    . . . . . A . . . .
    . . R . . . . . . .
    . O B M . . . . . R
    . . A . . . . . O B
    ```

*   **Observation of Transformation:**
    Let's look at a specific Blue pixel in the input and see what happens in the output.
    *   **Pixel at (0, 5):**
        *   Input: `B` at (0,5).
        *   Output: `B` remains at (0,5).
        *   Neighbors:
            *   Top: None (boundary).
            *   Bottom (1,5): `A` (Azure).
            *   Left (0,4): `O` (Orange).
            *   Right (0,6): `M` (Magenta).
    *   **Pixel at (2, 0):**
        *   Input: `B` at (2,0).
        *   Output: `B` remains at (2,0).
        *   Neighbors:
            *   Top (1,0): `R` (Red).
            *   Bottom (3,0): `A` (Azure).
            *   Left: None.
            *   Right (2,1): `M` (Magenta).
    *   **Pixel at (3, 9):**
        *   Input: `B` at (3,9).
        *   Output: `B` remains at (3,9).
        *   Neighbors:
            *   Top (2,9): `R` (Red).
            *   Bottom (4,9): `A` (Azure).
            *   Left (3,8): `O` (Orange).
            *   Right: None.
    *   **Pixel at (5, 5):**
        *   Input: `B` at (5,5).
        *   Output: `B` remains at (5,5).
        *   Neighbors:
            *   Top (4,5): `R` (Red).
            *   Bottom (6,5): `A` (Azure).
            *   Left (5,4): `O` (Orange).
            *   Right (5,6): `M` (Magenta).
    *   **Pixel at (8, 2):**
        *   Input: `B` at (8,2).
        *   Output: `B` remains at (8,2).
        *   Neighbors:
            *   Top (7,2): `R` (Red).
            *   Bottom (9,2): `A` (Azure).
            *   Left (8,1): `O` (Orange).
            *   Right (8,3): `M` (Magenta).
    *   **Pixel at (9, 9):**
        *   Input: `B` at (9,9).
        *   Output: `B` remains at (9,9).
        *   Neighbors:
            *   Top (8,9): `R` (Red).
            *   Bottom: None.
            *   Left (9,8): `O` (Orange).
            *   Right: None.

*   **Pattern Identification:**
    For every Blue pixel (`B`) at position $(r, c)$:
    *   The pixel itself stays `B`.
    *   The Top neighbor $(r-1, c)$ becomes `R` (Red).
    *   The Bottom neighbor $(r+1, c)$ becomes `A` (Azure).
    *   The Left neighbor $(r, c-1)$ becomes `O` (Orange).
    *   The Right neighbor $(r, c+1)$ becomes `M` (Magenta).

    Let's check for conflicts. In Example 1, the blue pixels are far enough apart that their neighbors don't overlap.
    (0,5) neighbors: (1,5), (0,4), (0,6).
    (2,0) neighbors: (1,0), (3,0), (2,1).
    (3,9) neighbors: (2,9), (4,9), (3,8).
    (5,5) neighbors: (4,5), (6,5), (5,4), (5,6).
    (8,2) neighbors: (7,2), (9,2), (8,1), (8,3).
    (9,9) neighbors: (8,9), (9,8).
    No overlaps observed in Example 1.

    **Color Mapping:**
    *   Up (North) -> Red (R)
    *   Down (South) -> Azure (A)
    *   Left (West) -> Orange (O)
    *   Right (East) -> Magenta (M)
    *   Center -> Blue (B)

    Wait, let's double check the colors.
    Top neighbor of (0,5) is (1,5). In output, (1,5) is `A`. Wait.
    Let's re-examine Example 1 Output carefully.
    Input (0,5) is B.
    Output Row 0: `. . . . O B M . . .` -> (0,4)=O, (0,5)=B, (0,6)=M.
    Output Row 1: `R . . . . A . . . .` -> (1,0)=R, (1,5)=A.
    So for B at (0,5):
    Left (0,4) -> O (Orange)
    Right (0,6) -> M (Magenta)
    Bottom (1,5) -> A (Azure)
    Top (None)

    Input (2,0) is B.
    Output Row 1: `R . . . . A . . . .` -> (1,0)=R.
    Output Row 2: `B M . . . . . . . R` -> (2,0)=B, (2,1)=M.
    Output Row 3: `A . . . . . . . O B` -> (3,0)=A.
    So for B at (2,0):
    Top (1,0) -> R (Red)
    Right (2,1) -> M (Magenta)
    Bottom (3,0) -> A (Azure)
    Left (None)

    Input (3,9) is B.
    Output Row 2: `... R` -> (2,9)=R.
    Output Row 3: `... O B` -> (3,8)=O, (3,9)=B.
    Output Row 4: `... A` -&

... [4900 chars truncated]
alt-4 sports qwen3.5-122b: fail
"Each blue player stands on a dark field and executes a signature move — sending four different colored passes simultaneously to teammates stationed one step away in each cardinal direction. Each direction receives a pass of a unique color."
Fail (best cell_acc=0.77 at k=1)
Best Attempt
vs
Expected
Reasoning (9053 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A dark playing field (black background) with blue athletes (blue pixels).
*   **Action:** Each athlete distributes one uniquely colored pass to each of the four cardinal neighbors (up, down, left, right), one step away.
*   **Grid:** 10x10, black background.
*   **Key:** `.`=black, `B`=blue, `R`=red, `G`=green, `Y`=yellow, `X`=grey, `M`=magenta, `O`=orange, `A`=azure, `W`=maroon.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    . . . . . B . . . .
    . . . . . . . . . .
    B . . . . . . . . .
    . . . . . . . . . B
    . . . . . . . . . .
    . . . . . B . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . B . . . . . . .
    . . . . . . . . . B
    ```
    Blue pixels (`B`) are at: (0,5), (2,0), (3,9), (5,5), (8,2), (9,9).

*   **Output:**
    ```
    . . . . O B M . . .
    R . . . . A . . . .
    B M . . . . . . . R
    A . . . . . . . O B
    . . . . . R . . . A
    . . . . O B M . . .
    . . . . . A . . . .
    . . R . . . . . . .
    . O B M . . . . . R
    . . A . . . . . O B
    ```

*   **Observation:**
    *   The original blue pixels (`B`) remain in their positions.
    *   Around each blue pixel, the four cardinal neighbors change color.
    *   Let's check the neighbors of a specific blue pixel.
    *   Take `B` at (0,5).
        *   Left (0,4): `O` (Orange)
        *   Right (0,6): `M` (Magenta)
        *   Down (1,5): `A` (Azure)
        *   Up: Out of bounds.
    *   Take `B` at (2,0).
        *   Right (2,1): `M` (Magenta)
        *   Down (3,0): `A` (Azure)
        *   Left: Out of bounds.
        *   Up (1,0): `R` (Red)
    *   Take `B` at (3,9).
        *   Left (3,8): `O` (Orange)
        *   Up (2,9): `R` (Red)
        *   Down (4,9): `A` (Azure)
        *   Right: Out of bounds.
    *   Take `B` at (5,5).
        *   Left (5,4): `O` (Orange)
        *   Right (5,6): `M` (Magenta)
        *   Up (4,5): `R` (Red)
        *   Down (6,5): `A` (Azure)
    *   Take `B` at (8,2).
        *   Left (8,1): `O` (Orange)
        *   Right (8,3): `M` (Magenta)
        *   Up (7,2): `R` (Red)
        *   Down (9,2): `A` (Azure)
    *   Take `B` at (9,9).
        *   Left (9,8): `O` (Orange)
        *   Up (8,9): `R` (Red)
        *   Right: Out of bounds.
        *   Down: Out of bounds.

*   **Pattern Identification:**
    *   The blue pixel stays `B`.
    *   The neighbors get specific colors based on their relative position to the blue pixel.
    *   Left neighbor -> `O` (Orange)
    *   Right neighbor -> `M` (Magenta)
    *   Up neighbor -> `R` (Red)
    *   Down neighbor -> `A` (Azure)
    *   Wait, let's re-verify.
    *   `B` at (0,5): Left(0,4)=O, Right(0,6)=M, Down(1,5)=A. (Up is out).
    *   `B` at (2,0): Right(2,1)=M, Down(3,0)=A, Up(1,0)=R. (Left is out).
    *   `B` at (3,9): Left(3,8)=O, Up(2,9)=R, Down(4,9)=A. (Right is out).
    *   `B` at (5,5): Left(5,4)=O, Right(5,6)=M, Up(4,5)=R, Down(6,5)=A.
    *   `B` at (8,2): Left(8,1)=O, Right(8,3)=M, Up(7,2)=R, Down(9,2)=A.
    *   `B` at (9,9): Left(9,8)=O, Up(8,9)=R. (Right/Down out).

    *   **Rule:**
        *   For every `B` at `(r, c)`:
            *   `(r, c-1)` becomes `O` (Orange) [Left]
            *   `(r, c+1)` becomes `M` (Magenta) [Right]
            *   `(r-1, c)` becomes `R` (Red) [Up]
            *   `(r+1, c)` becomes `A` (Azure) [Down]
        *   If a cell is targeted by multiple `B`s, what happens?
            *   In the example, do any neighbors overlap?
            *   `B` at (0,5) affects (1,5). `B` at (5,5) affects (4,5) and (6,5). No overlap in this example.
            *   Let's check the test input for potential overlaps.

**3. Conceptual Digestion:**
1.  **CAST:**
    *   **Blue Athletes (`B`):** The active agents. They stay in place.
    *   **Black Field (`.`):** The passive background. It gets overwritten by the "passes".
    *   **Passes (Colored pixels):** The result of the action. They occupy the cells adjacent to the athletes.
2.  **AFFORDANCES:**
    *   `B` can emit colors to adjacent cells.
    *   `.` can be overwritten.
    *   Colors are directional: Up=Red, Down=Azure, Left=Orange, Right=Magenta.
3.  **TRANSFORMATION RULE:**
    *   Iterate through the grid.
    *   If a cell contains `B`:
        *   Set cell to `B` (it remains).
        *   Set cell above to `R` (if within bounds).
        *   Set cell below to `A` (if within bounds).
        *   Set cell left to `O` (if within bounds).
        *   Set cell right to `M` (if within bounds).
    *   If a cell is not `B` and not targeted by a `B`, it remains `.`.
    *   **Conflict Resolution:** The prompt doesn't explicitly state what happens if two `B`s target the same cell. However, looking at the metaphor "distributes one uniquely colored pass", implies the pass is specific to the direction. If two athletes pass to the same sp

... [4155 chars truncated]
alt-5 weather qwen3.5-122b: fail
"Blue storm eyes sit calmly in a dark sky. Around each eye, the storm wall spins out four colored weather phenomena — one in each cardinal direction — a red lightning flash above, an orange glow to the west, a magenta aurora to the east, and a cool azure rainfall below."
Fail (best cell_acc=0.00 at k=1)
No grid
vs
Expected
Reasoning (10234 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "A dark sky with blue storm eyes at scattered locations."
    *   "Dark sky" likely corresponds to the black background (`.`).
    *   "Blue storm eyes" likely corresponds to the blue pixels (`B`).
*   **Action:** "Each storm eye radiates one unique colored weather event into each of its four cardinal neighbors."
    *   "Radiates" implies spreading out from the source.
    *   "One unique colored weather event" implies that for each neighbor (Up, Down, Left, Right), a specific color is assigned.
    *   "Four cardinal neighbors" means the cells directly adjacent (N, S, E, W).
*   **Grid:** 10x10, black background.

**2. Analyze the Training Examples:**

*   **Example 1 Input:**
    *   Blue pixels (`B`) are at:
        *   (0, 5)
        *   (2, 0)
        *   (3, 9)
        *   (5, 5)
        *   (8, 2)
        *   (9, 9)
    *   Rest are black (`.`).

*   **Example 1 Output:**
    *   Let's look at the neighbors of the `B` pixels in the output.
    *   **Source (0, 5):**
        *   Left (0, 4): `O` (Orange)
        *   Right (0, 6): `M` (Magenta)
        *   Down (1, 5): `A` (Azure)
        *   Up: Out of bounds.
    *   **Source (2, 0):**
        *   Right (2, 1): `M` (Magenta)
        *   Down (3, 0): `A` (Azure)
        *   Left: Out of bounds.
        *   Up (1, 0): `R` (Red)
    *   **Source (3, 9):**
        *   Left (3, 8): `O` (Orange)
        *   Up (2, 9): `R` (Red)
        *   Down (4, 9): `A` (Azure)
        *   Right: Out of bounds.
    *   **Source (5, 5):**
        *   Left (5, 4): `O` (Orange)
        *   Right (5, 6): `M` (Magenta)
        *   Up (4, 5): `R` (Red)
        *   Down (6, 5): `A` (Azure)
    *   **Source (8, 2):**
        *   Left (8, 1): `O` (Orange)
        *   Right (8, 3): `M` (Magenta)
        *   Up (7, 2): `R` (Red)
        *   Down (9, 2): `A` (Azure)
    *   **Source (9, 9):**
        *   Left (9, 8): `O` (Orange)
        *   Up (8, 9): `R` (Red)
        *   Right: Out of bounds.
        *   Down: Out of bounds.

*   **Pattern Recognition:**
    *   The `B` pixels remain `B` in the output.
    *   The neighbors of `B` change color based on their relative position to the `B`.
    *   Let's check the mapping:
        *   **Left neighbor:** Always `O` (Orange).
        *   **Right neighbor:** Always `M` (Magenta).
        *   **Up neighbor:** Always `R` (Red).
        *   **Down neighbor:** Always `A` (Azure).
    *   Let's verify this hypothesis against all instances in Example 1.
        *   (0, 5) -> Left(0,4)=O, Right(0,6)=M, Down(1,5)=A. (Up is N/A). Matches.
        *   (2, 0) -> Right(2,1)=M, Down(3,0)=A, Up(1,0)=R. (Left is N/A). Matches.
        *   (3, 9) -> Left(3,8)=O, Up(2,9)=R, Down(4,9)=A. (Right is N/A). Matches.
        *   (5, 5) -> Left(5,4)=O, Right(5,6)=M, Up(4,5)=R, Down(6,5)=A. Matches.
        *   (8, 2) -> Left(8,1)=O, Right(8,3)=M, Up(7,2)=R, Down(9,2)=A. Matches.
        *   (9, 9) -> Left(9,8)=O, Up(8,9)=R. (Right/Down N/A). Matches.
    *   What about overlapping neighbors?
        *   In Example 1, do any `B`s share neighbors?
        *   (0,5) and (5,5) are far apart.
        *   (2,0) and (8,2) are far apart.
        *   (3,9) and (9,9) are far apart.
        *   No overlaps in Example 1.
    *   What happens if a neighbor is already occupied by another `B`?
        *   The rule says "radiates... into each of its four cardinal neighbors". Usually, in these puzzles, the source `B` stays `B`. If a neighbor is another `B`, it likely stays `B` (source takes precedence) or the rule doesn't apply to `B` cells. Given the description "radiates... into neighbors", it implies empty cells or cells that can be overwritten. However, usually, sources are immutable. Let's assume `B` cells remain `B`.
    *   What happens if two `B`s radiate into the same cell?
        *   Example 1 doesn't show this. I need to be careful with the Test Input.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Background:** Black (`.`). Represents the "dark sky".
    *   **Source:** Blue (`B`). Represents "storm eyes".
    *   **Effect:** Colored pixels (`R`, `G`, `Y`, `X`, `M`, `O`, `A`, `W`). Represents "weather events".
    *   **Specific Mapping:**
        *   Up (`-1, 0`) -> Red (`R`)
        *   Down (`+1, 0`) -> Azure (`A`)
        *   Left (`0, -1`) -> Orange (`O`)
        *   Right (`0, +1`) -> Magenta (`M`)

2.  **AFFORDANCES:**
    *   `B` cells trigger the transformation in adjacent cells.
    *   `.` cells can be overwritten by the weather events.
    *   `B` cells likely persist (don't get overwritten by neighbors' radiation, or simply define the center).
    *   Boundary conditions: Cells outside the grid are ignored.

3.  **TRANSFORMATION RULE:**
    *   Iterate through every cell in the grid.
    *   If a cell contains `B`:
        *   Keep it as 

... [5363 chars truncated]
alt-6 architecture qwen3.5-122b: k=1
"Blue cornerstones are laid into a dark foundation. From each cornerstone, the architect extends one decorative facade element in each cardinal direction — each facade a different colored tile — creating a small cross-shaped ornament centered on the stone."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (8932 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A dark building foundation with blue cornerstones set at various positions."
    *   "Dark building foundation" -> Black background (`.`).
    *   "Blue cornerstones" -> Blue pixels (`B`) in the input grid.
*   **Action:** "Each cornerstone extends one uniquely colored facade tile into each cardinal neighbor position."
    *   "Cornerstone" -> The blue pixel (`B`).
    *   "Extends" -> Places something in the grid.
    *   "One uniquely colored facade tile" -> A specific color associated with the direction.
    *   "Each cardinal neighbor position" -> Up, Down, Left, Right relative to the cornerstone.
*   **Grid details:** 10x10 grid, black background.

**2. Analyze the Training Examples:**

*   **Example 1 Input:**
    *   Row 0: `B` at (0, 5)
    *   Row 2: `B` at (2, 0)
    *   Row 3: `B` at (3, 9)
    *   Row 5: `B` at (5, 5)
    *   Row 8: `B` at (8, 2)
    *   Row 9: `B` at (9, 9)
    *   All other cells are `.` (black).

*   **Example 1 Output:**
    *   Let's look at the neighbors of the `B` at (0, 5).
        *   Left (0, 4): `O` (Orange)
        *   Right (0, 6): `M` (Magenta)
        *   Down (1, 5): `A` (Azure)
        *   Up: Out of bounds.
    *   Let's look at the neighbors of the `B` at (2, 0).
        *   Right (2, 1): `M` (Magenta)
        *   Down (3, 0): `A` (Azure)
        *   Left: Out of bounds.
        *   Up (1, 0): `R` (Red)
    *   Let's look at the neighbors of the `B` at (3, 9).
        *   Left (3, 8): `O` (Orange)
        *   Up (2, 9): `R` (Red)
        *   Down (4, 9): `A` (Azure)
        *   Right: Out of bounds.
    *   Let's look at the neighbors of the `B` at (5, 5).
        *   Left (5, 4): `O` (Orange)
        *   Right (5, 6): `M` (Magenta)
        *   Up (4, 5): `R` (Red)
        *   Down (6, 5): `A` (Azure)
    *   Let's look at the neighbors of the `B` at (8, 2).
        *   Left (8, 1): `O` (Orange)
        *   Right (8, 3): `M` (Magenta)
        *   Up (7, 2): `R` (Red)
        *   Down (9, 2): `A` (Azure)
    *   Let's look at the neighbors of the `B` at (9, 9).
        *   Left (9, 8): `O` (Orange)
        *   Up (8, 9): `R` (Red)
        *   Right: Out of bounds.
        *   Down: Out of bounds.

*   **Pattern Identification:**
    *   The blue pixel (`B`) stays in place.
    *   The neighbors are filled with specific colors based on direction.
    *   **Left:** `O` (Orange)
    *   **Right:** `M` (Magenta)
    *   **Up:** `R` (Red)
    *   **Down:** `A` (Azure)
    *   Wait, let's double check the mapping.
        *   (0, 5) `B`: Left(0,4)=`O`, Right(0,6)=`M`, Down(1,5)=`A`. Up is out.
        *   (2, 0) `B`: Right(2,1)=`M`, Down(3,0)=`A`, Up(1,0)=`R`. Left is out.
        *   (3, 9) `B`: Left(3,8)=`O`, Up(2,9)=`R`, Down(4,9)=`A`. Right is out.
        *   (5, 5) `B`: Left(5,4)=`O`, Right(5,6)=`M`, Up(4,5)=`R`, Down(6,5)=`A`.
        *   (8, 2) `B`: Left(8,1)=`O`, Right(8,3)=`M`, Up(7,2)=`R`, Down(9,2)=`A`.
        *   (9, 9) `B`: Left(9,8)=`O`, Up(8,9)=`R`. Right/Down out.

    *   **Rule:**
        *   For every `B` at `(r, c)`:
            *   Set `(r, c-1)` to `O` (if valid).
            *   Set `(r, c+1)` to `M` (if valid).
            *   Set `(r-1, c)` to `R` (if valid).
            *   Set `(r+1, c)` to `A` (if valid).
        *   The `B` itself remains `B`.
        *   All other cells remain `.` (unless overwritten by a neighbor rule).
        *   What if neighbors overlap? The examples don't show overlapping neighbors from different `B`s. Let's check the test input for potential overlaps.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Background:** Black (`.`).
    *   **Agents/Seeds:** Blue pixels (`B`).
    *   **Effects:** Colored pixels (`O`, `M`, `R`, `A`) placed in adjacent cells.

2.  **AFFORDANCES:**
    *   `B` pixels act as sources.
    *   They emit specific colors in specific directions.
    *   Left -> Orange (`O`)
    *   Right -> Magenta (`M`)
    *   Up -> Red (`R`)
    *   Down -> Azure (`A`)

3.  **TRANSFORMATION RULE:**
    *   Iterate through every cell in the 10x10 grid.
    *   If a cell contains `B`:
        *   Check its 4 cardinal neighbors.
        *   If the neighbor is within grid bounds, change its color according to the direction relative to the `B`.
        *   Left neighbor becomes `O`.
        *   Right neighbor becomes `M`.
        *   Top neighbor becomes `R`.
        *   Bottom neighbor becomes `A`.
    *   The `B` cell itself remains `B`.
    *   Cells not affected by any `B` remain `.`.
    *   (Implicit assumption: If multiple `B`s affect the same cell, there might be a conflict, but usually in these puzzles, inputs are designed to avoid conflicts or there's a priority. Looking at the test input, I need to check for overlaps).

**4. Apply to Test Input:**

**Test Input Grid:**
Row 0: `. B . . . . .

... [3977 chars truncated]
alt-7 warfare qwen3.5-122b: fail
"Blue command posts are established across a dark battlefield. Each post deploys four differently-flagged scouts — one marching one step in each cardinal direction, each scout carrying a banner of a distinct color to mark their assigned heading."
Fail (best cell_acc=0.77 at k=1)
Best Attempt
vs
Expected
Reasoning (9548 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A dark battlefield with blue command posts at scattered positions."
    *   "Dark battlefield" -> Black background (`.`).
    *   "Blue command posts" -> Blue pixels (`B`).
*   **Action:** "Each command post sends one uniquely colored scout one step into each cardinal direction."
    *   "Each command post" -> Every `B` in the input grid acts as a source.
    *   "Sends one uniquely colored scout" -> This implies the scouts have specific colors.
    *   "One step into each cardinal direction" -> Up, Down, Left, Right from the `B` position.
    *   "Uniquely colored" -> This is the tricky part. Does "uniquely colored" mean every scout from a specific post has a different color? Or does it mean the color depends on the direction?
    *   Let's look at the training examples to deduce the color mapping.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    . . . . . B . . . .
    . . . . . . . . . .
    B . . . . . . . . .
    . . . . . . . . . B
    . . . . . . . . . .
    . . . . . B . . . .
    . . . . . . . . . .
    . . . . . . . . . .
    . . B . . . . . . .
    . . . . . . . . . B
    ```
    Blue pixels (`B`) are at:
    (0, 5)
    (2, 0)
    (3, 9)
    (5, 5)
    (8, 2)
    (9, 9)

*   **Output:**
    ```
    . . . . O B M . . .
    R . . . . A . . . .
    B M . . . . . . . R
    A . . . . . . . O B
    . . . . . R . . . A
    . . . . O B M . . .
    . . . . . A . . . .
    . . R . . . . . . .
    . O B M . . . . . R
    . . A . . . . . O B
    ```
    Let's check the neighbors of the `B` positions in the output.

    *   **Source (0, 5):**
        *   Left (0, 4): `O` (Orange)
        *   Right (0, 6): `M` (Magenta)
        *   Down (1, 5): `A` (Azure)
        *   Up: Out of bounds.
    *   **Source (2, 0):**
        *   Right (2, 1): `M` (Magenta)
        *   Down (3, 0): `A` (Azure)
        *   Left: Out of bounds.
        *   Up (1, 0): `R` (Red)
    *   **Source (3, 9):**
        *   Left (3, 8): `O` (Orange)
        *   Up (2, 9): `R` (Red)
        *   Down (4, 9): `A` (Azure)
        *   Right: Out of bounds.
    *   **Source (5, 5):**
        *   Left (5, 4): `O` (Orange)
        *   Right (5, 6): `M` (Magenta)
        *   Up (4, 5): `R` (Red)
        *   Down (6, 5): `A` (Azure)
    *   **Source (8, 2):**
        *   Left (8, 1): `O` (Orange)
        *   Right (8, 3): `M` (Magenta)
        *   Up (7, 2): `R` (Red)
        *   Down (9, 2): `A` (Azure)
    *   **Source (9, 9):**
        *   Left (9, 8): `O` (Orange)
        *   Up (8, 9): `R` (Red)
        *   Right: Out of bounds.
        *   Down: Out of bounds.

    **Pattern Deduction:**
    It seems the color of the scout depends on the direction relative to the command post (`B`).
    *   **Left:** `O` (Orange)
    *   **Right:** `M` (Magenta)
    *   **Up:** `R` (Red)
    *   **Down:** `A` (Azure)

    Let's verify this hypothesis against all instances in Example 1.
    *   (0, 5): Left->O, Right->M, Down->A. (Up is out). Matches.
    *   (2, 0): Right->M, Down->A, Up->R. (Left is out). Matches.
    *   (3, 9): Left->O, Up->R, Down->A. (Right is out). Matches.
    *   (5, 5): Left->O, Right->M, Up->R, Down->A. Matches.
    *   (8, 2): Left->O, Right->M, Up->R, Down->A. Matches.
    *   (9, 9): Left->O, Up->R. (Right/Down out). Matches.

    **Conflict Resolution:**
    What if two command posts send scouts to the same cell?
    In Example 1, do any overlap?
    (0,5) sends Down to (1,5).
    (2,0) sends Up to (1,0).
    (2,0) sends Right to (2,1).
    (3,9) sends Up to (2,9).
    (5,5) sends Up to (4,5).
    (5,5) sends Down to (6,5).
    (8,2) sends Up to (7,2).
    (8,2) sends Down to (9,2).
    (9,9) sends Up to (8,9).
    None of the target cells overlap in Example 1.
    However, the rule is clear:
    *   `B` at `(r, c)`
    *   `(r, c-1)` becomes `O` (Left)
    *   `(r, c+1)` becomes `M` (Right)
    *   `(r-1, c)` becomes `R` (Up)
    *   `(r+1, c)` becomes `A` (Down)
    *   The `B` itself remains `B`.
    *   Background remains `.` unless overwritten.

    Wait, check the output grid for Example 1 again.
    Row 0: `. . . . O B M . . .` -> (0,4)=O, (0,5)=B, (0,6)=M. Correct.
    Row 1: `R . . . . A . . . .` -> (1,0)=R (from 2,0 Up), (1,5)=A (from 0,5 Down). Correct.
    Row 2: `B M . . . . . . . R` -> (2,0)=B, (2,1)=M (from 2,0 Right), (2,9)=R (from 3,9 Up). Correct.
    Row 3: `A . . . . . . . O B` -> (3,0)=A (from 2,0 Down), (3,8)=O (from 3,9 Left), (3,9)=B. Correct.
    Row 4: `. . . . . R . . . A` -> (4,5)=R (from 5,5 Up), (4,9)=A (from 3,9 Down). Correct.
    Row 5: `. . . . O B M . . .` -> (5,4)=O, (5,5)=B, (5,6)=M. Correct.
    Row 6: `. . . . . A . . . .` -> (6,5)=A (from 5,5 Down). Correct.
    Row 7: `. . R . . . . . . .` -> (7,2)=R (from 8

... [4653 chars truncated]
alt-8 theater qwen3.5-122b: k=2
"On a darkened stage, blue spotlights mark the positions of solo performers. As the scene begins, each performer gestures outward and four differently-colored follow spots ignite — one illuminating the space directly above, below, left, and right of the performer, each gel a different hue."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (9848 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A dark stage with blue spotlights marking performer positions."
    *   "Dark stage" implies a black background (`.`).
    *   "Blue spotlights" implies the input contains blue pixels (`B`).
    *   "Performer positions" are the locations of the `B` pixels.
*   **Action:** "Each performer triggers four uniquely colored follow spots, one in each cardinal neighbor cell."
    *   "Performer" = `B` pixel.
    *   "Triggers" = causes changes in the grid.
    *   "Four uniquely colored follow spots" = 4 new pixels appear.
    *   "One in each cardinal neighbor cell" = Up, Down, Left, Right relative to the `B`.
    *   "Uniquely colored" = The colors are specific and likely consistent across examples.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input has `B` at: (0,5), (2,0), (3,9), (5,5), (8,2), (9,9).
    *   Let's check the neighbors of a `B` in the output.
    *   Take `B` at (0,5).
        *   Left (0,4): `O` (Orange)
        *   Right (0,6): `M` (Magenta)
        *   Down (1,5): `A` (Azure)
        *   Up: Out of bounds.
    *   Take `B` at (2,0).
        *   Right (2,1): `M` (Magenta)
        *   Down (3,0): `A` (Azure)
        *   Left: Out of bounds.
        *   Up (1,0): `R` (Red)
    *   Take `B` at (3,9).
        *   Left (3,8): `O` (Orange)
        *   Up (2,9): `R` (Red)
        *   Down (4,9): `A` (Azure)
        *   Right: Out of bounds.
    *   Take `B` at (5,5).
        *   Left (5,4): `O` (Orange)
        *   Right (5,6): `M` (Magenta)
        *   Up (4,5): `R` (Red)
        *   Down (6,5): `A` (Azure)
    *   Take `B` at (8,2).
        *   Left (8,1): `O` (Orange)
        *   Right (8,3): `M` (Magenta)
        *   Up (7,2): `R` (Red)
        *   Down (9,2): `A` (Azure)
    *   Take `B` at (9,9).
        *   Left (9,8): `O` (Orange)
        *   Up (8,9): `R` (Red)
        *   Right/Down: Out of bounds.

    *   **Pattern Identified:**
        *   For every `B` at position $(r, c)$:
            *   Top neighbor $(r-1, c)$ becomes `R` (Red).
            *   Bottom neighbor $(r+1, c)$ becomes `A` (Azure).
            *   Left neighbor $(r, c-1)$ becomes `O` (Orange).
            *   Right neighbor $(r, c+1)$ becomes `M` (Magenta).
        *   The `B` itself remains `B`.
        *   If multiple `B`s affect the same cell, what happens?
            *   Let's check for overlaps.
            *   In Example 1, `B` at (0,5) and `B` at (5,5). No overlap.
            *   `B` at (2,0) and `B` at (8,2). No overlap.
            *   `B` at (3,9) and `B` at (9,9). No overlap.
            *   Wait, let's look closer at Example 2 to see if there are overlaps or specific interactions.

*   **Example 2:**
    *   Input `B` locations: (1,6), (3,9), (5,3), (7,7), (9,1).
    *   Let's check neighbors for `B` at (1,6).
        *   Top (0,6): `R`
        *   Bottom (2,6): `A`
        *   Left (1,5): `O`
        *   Right (1,7): `M`
    *   Let's check neighbors for `B` at (3,9).
        *   Top (2,9): `R`
        *   Bottom (4,9): `A`
        *   Left (3,8): `O`
        *   Right: Out of bounds.
    *   Let's check neighbors for `B` at (5,3).
        *   Top (4,3): `R`
        *   Bottom (6,3): `A`
        *   Left (5,2): `O`
        *   Right (5,4): `M`
    *   Let's check neighbors for `B` at (7,7).
        *   Top (6,7): `R`
        *   Bottom (8,7): `A`
        *   Left (7,6): `O`
        *   Right (7,8): `M`
    *   Let's check neighbors for `B` at (9,1).
        *   Top (8,1): `R`
        *   Bottom: Out of bounds.
        *   Left (9,0): `O`
        *   Right (9,2): `M`

    *   **Consistency Check:**
        *   Top: `R` (Red)
        *   Bottom: `A` (Azure)
        *   Left: `O` (Orange)
        *   Right: `M` (Magenta)
        *   Center: `B` (Blue)
        *   Background: `.` (Black)

    *   **Conflict Resolution:**
        *   Are there any cases where two `B`s try to color the same cell?
        *   In Example 1:
            *   (0,5) affects (1,5) -> A.
            *   (5,5) affects (4,5) -> R.
            *   No direct conflict in Example 1.
        *   In Example 2:
            *   (1,6) affects (2,6) -> A.
            *   (3,9) affects (2,9) -> R.
            *   (5,3) affects (4,3) -> R.
            *   (7,7) affects (6,7) -> R.
            *   (9,1) affects (8,1) -> R.
            *   No direct conflict in Example 2.
        *   Hypothesis: If conflicts occur, usually one overwrites the other, or they are the same color. Given the specific colors (R, A, O, M), a cell can only be one color. If a cell is a neighbor to two different `B`s, it might be a conflict.
        *   Let's check the Test Input for potential conflicts.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Performer:** The Blue pixel (`B`). It is the source of the transformation.
    *   **Stage:** The grid itself,

... [4884 chars truncated]
alt-9 gardening qwen3.5-122b: k=2
"Blue seed pods rest in dark soil. When spring arrives, each pod splits open and sends four differently-colored roots and shoots into the cardinal directions — each tendril emerges one cell away and blooms in a color unique to its compass bearing."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (9141 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Dark soil with blue seed pods scattered at various positions."
    *   "Dark soil" likely corresponds to the black background (`.`).
    *   "Blue seed pods" correspond to the blue pixels (`B`).
*   **Action:** "Each seed pod sprouts one uniquely colored tendril into each cardinal neighbor."
    *   "Cardinal neighbor" means Up, Down, Left, Right.
    *   "Sprouts one uniquely colored tendril" implies that for every `B` in the input, its neighbors in the output will change color.
    *   "Uniquely colored" suggests specific colors for specific directions relative to the seed pod.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input has `B` at (0, 5), (2, 0), (3, 9), (5, 5), (8, 2), (9, 9).
    *   Let's check the neighbors of a `B` in the output.
    *   Take `B` at (0, 5).
        *   Left neighbor (0, 4) becomes `O` (Orange).
        *   Right neighbor (0, 6) becomes `M` (Magenta).
        *   Down neighbor (1, 5) becomes `A` (Azure).
        *   Up neighbor is out of bounds.
    *   Take `B` at (2, 0).
        *   Right neighbor (2, 1) becomes `M` (Magenta).
        *   Down neighbor (3, 0) becomes `A` (Azure).
        *   Left/Up out of bounds.
    *   Take `B` at (3, 9).
        *   Left neighbor (3, 8) becomes `O` (Orange).
        *   Up neighbor (2, 9) becomes `R` (Red).
        *   Down neighbor (4, 9) becomes `A` (Azure).
        *   Right out of bounds.
    *   Take `B` at (5, 5).
        *   Left (5, 4) -> `O`.
        *   Right (5, 6) -> `M`.
        *   Up (4, 5) -> `R`.
        *   Down (6, 5) -> `A`.
    *   Take `B` at (8, 2).
        *   Left (8, 1) -> `O`.
        *   Right (8, 3) -> `M`.
        *   Up (7, 2) -> `R`.
        *   Down (9, 2) -> `A`.
    *   Take `B` at (9, 9).
        *   Left (9, 8) -> `O`.
        *   Up (8, 9) -> `R`.
        *   Right/Down out of bounds.

    *   **Pattern Hypothesis:**
        *   Left of `B` -> `O` (Orange)
        *   Right of `B` -> `M` (Magenta)
        *   Up of `B` -> `R` (Red)
        *   Down of `B` -> `A` (Azure)
        *   The `B` itself remains `B`.
        *   Background `.` remains `.` unless overwritten by a tendril.

*   **Example 2:**
    *   Input `B` locations: (1, 6), (3, 9), (5, 3), (7, 7), (9, 1).
    *   Check `B` at (1, 6):
        *   Left (1, 5) -> `O`.
        *   Right (1, 7) -> `M`.
        *   Up (0, 6) -> `R`.
        *   Down (2, 6) -> `A`.
    *   Check `B` at (3, 9):
        *   Left (3, 8) -> `O`.
        *   Up (2, 9) -> `R`.
        *   Down (4, 9) -> `A`.
    *   Check `B` at (5, 3):
        *   Left (5, 2) -> `O`.
        *   Right (5, 4) -> `M`.
        *   Up (4, 3) -> `R`.
        *   Down (6, 3) -> `A`.
    *   Check `B` at (7, 7):
        *   Left (7, 6) -> `O`.
        *   Right (7, 8) -> `M`.
        *   Up (6, 7) -> `R`.
        *   Down (8, 7) -> `A`.
    *   Check `B` at (9, 1):
        *   Left (9, 0) -> `O`.
        *   Right (9, 2) -> `M`.
        *   Up (8, 1) -> `R`.
        *   Down out of bounds.

    *   **Confirmation:** The rule holds perfectly.
        *   `B` stays `B`.
        *   `B`'s Left neighbor becomes `O`.
        *   `B`'s Right neighbor becomes `M`.
        *   `B`'s Up neighbor becomes `R`.
        *   `B`'s Down neighbor becomes `A`.
        *   If multiple `B`s affect the same cell, we need to check for conflicts. In the examples, `B`s are spaced out enough that their neighbors don't overlap. Let's check the test input for overlaps.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Seed Pods:** Blue pixels (`B`). These are the active agents.
    *   **Soil:** Black pixels (`.`). These are the passive background.
    *   **Tendrils:** Colored pixels (`O`, `M`, `R`, `A`) that appear around the seed pods.

2.  **AFFORDANCES:**
    *   A `B` pixel can generate neighbors.
    *   A `.` pixel can be overwritten by a tendril color.
    *   A `B` pixel persists in the output.

3.  **TRANSFORMATION RULE:**
    *   Iterate through every cell in the grid.
    *   If a cell contains `B`:
        *   Keep it as `B`.
        *   Set the cell to its Left (col-1) to `O` (Orange).
        *   Set the cell to its Right (col+1) to `M` (Magenta).
        *   Set the cell to its Up (row-1) to `R` (Red).
        *   Set the cell to its Down (row+1) to `A` (Azure).
    *   Boundary checks apply (ignore neighbors outside the 10x10 grid).
    *   If a cell is not a neighbor of any `B`, it remains `.`.
    *   (Implicit assumption based on examples): Neighbors of `B` overwrite `.`. If two `B`s target the same neighbor, the examples don't show this case, but usually, in these puzzles, inputs are designed to avoid ambiguity or one rule takes precedence. Given the spacing in the test input, I should check for over

... [4363 chars truncated]

Task 819: d4469b4b

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Ex5 In
Ex5 Out
Ex6 In
Ex6 Out
Ex7 In
Ex7 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original Every tribe has a sacred sigil, and scattering the warriors across the battlefie ... [46 chars truncated] MARC valid 1
alt-1 biology Cells of a single species colonize the petri dish in unpredictable clusters, but ... [101 chars truncated] MARC valid 4
alt-10 astronomy Stars of a single spectral class flicker across the observation plate, but the a ... [159 chars truncated] MARC valid 3
alt-11 ocean/sailing Flotsam of one cargo type bobs across the dark water in no discernible pattern, ... [135 chars truncated] MARC valid 3
alt-12 electronics Charge carriers are scattered randomly across the semiconductor, but the dopant ... [149 chars truncated] MARC valid 3
alt-13 mythology The oracle's bones land differently every cast, but the god who stained them has ... [127 chars truncated] MARC valid 3
alt-14 dance Dancers wander the darkened stage during the overture, but when the spotlight hi ... [135 chars truncated] MARC valid 3
alt-15 geology Mineral deposits surface in random veins, but the assayer needs only the color o ... [124 chars truncated] MARC valid 3
alt-2 cooking No matter how you scatter the spice across the cutting board, when it hits the h ... [124 chars truncated] MARC valid 3
alt-3 music The notes are scattered across the staff like a child's first attempt at composi ... [162 chars truncated] MARC valid 3
alt-4 sports The players scramble across the field in chaos, but when the referee blows the w ... [144 chars truncated] MARC valid 3
alt-5 weather Storm cells gather in different patterns each day, but every front — cold, ... [143 chars truncated] MARC valid 5
alt-6 architecture Bricks tumble from the demolition in random heaps, but the mason who sees their ... [149 chars truncated] MARC valid 3
alt-7 warfare Scouts report skirmish positions scattered across the map, but the general cares ... [141 chars truncated] MARC valid 3
alt-8 theater The actors mill about backstage in disarray, but when the curtain rises, each tr ... [139 chars truncated] MARC valid 4
alt-9 gardening Seeds blow in the wind and land wherever they please, but when the gardener find ... [139 chars truncated] MARC valid 3
original qwen3.5-122b: k=1
"Every tribe has a sacred sigil, and scattering the warriors across the battlefield doesn't change the banner they march under."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (13498 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 5x5 grid ("battlefield").
*   **Content:** "Warriors of a single tribe" (Blue, Red, or Green) scattered among "empty darkness" (black `.`).
*   **Task:** Identify the tribe color from the input grid.
*   **Output:** A 3x3 grid ("ancestral seal").
*   **Sigils:**
    *   **Blue Tribe:** "radiates outward from the center in four directions". This sounds like a plus sign `+` shape. Center + Up + Down + Left + Right.
    *   **Red Tribe:** "stands tall, crowned with a broad brim". This sounds like a T shape or an inverted T. "Stands tall" implies vertical. "Crowned with a broad brim" implies a horizontal top. So, a T shape.
    *   **Green Tribe:** "hunkers into one corner, bracing two walls that meet at the foundation". This sounds like an L shape. "One corner", "two walls".
*   **Sigil Color:** Grey (`X`).
*   **Sigil Background:** Black (`.`).
*   **Sigil Size:** 3x3.
*   **Sigil Stones:** "always five stones placed". Wait, let's check the shapes.
    *   Blue (Plus): Center (1) + 4 directions (4) = 5 stones. Matches.
    *   Red (T): Top row (3) + Middle column (2 below top) = 5 stones. Matches.
    *   Green (L): Corner (1) + 2 walls (2 vertical, 2 horizontal? No, usually L is 3x3 corner). Let's visualize an L in 3x3.
        *   Option 1: Left col (3) + Bottom row (3). Overlap at corner. Total 5 stones.
        *   Option 2: Top row (3) + Right col (3). Overlap. Total 5 stones.
        *   Description: "hunkers into one corner, bracing two walls that meet at the foundation". "Foundation" usually implies bottom. "Corner" implies a specific corner. "Two walls" implies vertical and horizontal lines meeting.
        *   Let's check the training example to confirm the Green shape.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    B . B . .
    B . . B B
    B B . B .
    . B . B .
    B . . . B
    ```
    *   Color: Blue (`B`).
    *   Pattern: Scattered `B`s.
*   **Output:**
    ```
    . X .
    X X X
    . X .
    ```
    *   Shape: A plus sign `+`.
    *   Center is `X`. Top, Bottom, Left, Right are `X`. Corners are `.`.
    *   This matches the "Blue tribe's sigil radiates outward from the center in four directions" description.
    *   It confirms the output is 3x3.
    *   It confirms the sigil color is Grey (`X`).
    *   It confirms the background is Black (`.`).

**3. Analyze the Test Input:**
*   **Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Color:** Green (`G`).
*   **Task:** Determine the Green tribe's sigil based on the description and apply it to a 3x3 grid.

**4. Determine the Green Sigil Shape:**
*   Description: "The green tribe's sigil hunkers into one corner, bracing two walls that meet at the foundation."
*   "Hunkers into one corner": Suggests an L-shape occupying a corner of the 3x3 grid.
*   "Bracing two walls that meet at the foundation": "Foundation" implies the bottom. "Two walls" implies a vertical line and a horizontal line.
*   "Meet at the foundation": The intersection is at the bottom.
*   So, it's likely an L-shape in the bottom-left or bottom-right corner.
*   Let's look at the "five stones" constraint.
    *   An L-shape in a 3x3 grid using 5 stones usually means a full column and a full row meeting at a corner.
    *   Example: Bottom row (3 stones) + Left column (3 stones). Intersection at bottom-left. Total = 3 + 3 - 1 = 5 stones.
    *   Example: Bottom row (3 stones) + Right column (3 stones). Intersection at bottom-right. Total = 5 stones.
*   Which corner? "Hunkers into one corner". "Foundation" usually means bottom.
*   Is there a convention for "Green"?
    *   Blue = Plus (Centered).
    *   Red = T (Top centered).
    *   Green = L (Corner).
*   Let's re-read carefully: "bracing two walls that meet at the foundation".
    *   "Foundation" = Bottom.
    *   "Two walls" = Vertical and Horizontal.
    *   "Meet at the foundation" = The corner is at the bottom.
    *   So it's either Bottom-Left or Bottom-Right.
    *   Usually, if not specified, Left is the default reading direction. Or perhaps "hunkers" implies stability, often associated with the bottom-left in reading order (start).
    *   Let's check if there are other clues. "Ancestral sigil... stamped onto a 3x3 seal".
    *   Is there a standard set of shapes for these puzzles (ARC-like)?
    *   Often, Green corresponds to an L-shape.
    *   Let's consider the phrase "hunkers into one corner".
    *   Let's consider the phrase "meet at the foundation".
    *   If I draw an L in the bottom-left:
        ```
        . . .
        . . .
        X X X
        X . .
        X . .
        ```
        Wait, 3x3.
        ```
        . . .
        X . .
        X X X
        ```
        This is 5 stones. Left col (3) + Bottom row (3).
        Or:
        ```
        . . 

... [8510 chars truncated]
alt-1 biology qwen3.5-122b: k=4
"Cells of a single species colonize the petri dish in unpredictable clusters, but every species folds into the same genus-specific protein regardless of where the colonies took root."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (5419 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 5x5 grid ("culture dish") with scattered colored cells ("colonies") on a black background ("empty medium").
*   **Output:** A 3x3 grid ("protein structure") in grey ("X") on black (".").
*   **Rule:** "Ignore the colony placement entirely. Identify the species by its color and express its signature protein — a compact molecular shape unique to that lineage."
*   **Key Insight:** The specific arrangement of the colored cells in the 5x5 input doesn't matter for the *shape* of the output. The *color* of the cells determines the *shape* of the 3x3 output. The output is always a 3x3 grid of grey ('X') and black ('.').

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Color: Blue (B)
    *   Input Grid: 5x5 with scattered B's.
    *   Output Grid: 3x3
        ```
        . X .
        X X X
        . X .
        ```
    *   Shape: A plus sign or cross.

*   **Example 2:**
    *   Input Color: Red (R)
    *   Input Grid: 5x5 with scattered R's.
    *   Output Grid: 3x3
        ```
        X X X
        . X .
        . X .
        ```
    *   Shape: An 'L' shape or a corner. Specifically, top row full, middle col full. Looks like a '7' or a corner.

*   **Example 3:**
    *   Input Color: Green (G)
    *   Input Grid: 5x5 with scattered G's.
    *   Output Grid: 3x3
        ```
        . . X
        . . X
        X X X
        ```
    *   Shape: An 'L' shape rotated. Bottom row full, right col full.

*   **Example 4:**
    *   Input Color: Blue (B)
    *   Input Grid: 5x5 with scattered B's.
    *   Output Grid: 3x3
        ```
        . X .
        X X X
        . X .
        ```
    *   Shape: Same as Example 1. This confirms that the color determines the shape, not the specific input pattern. Blue always maps to the cross shape.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** 5x5 matrix containing background (.) and a specific foreground color (C).
    *   **Output Grid:** 3x3 matrix containing background (.) and foreground (X).
    *   **Species Identity:** Defined by the foreground color in the input grid.
    *   **Signature Protein:** The specific 3x3 pattern associated with that color.

2.  **AFFORDANCES:**
    *   The input grid allows identification of the dominant non-black color.
    *   The output grid is fixed size (3x3).
    *   The mapping is Color -> Pattern.

3.  **TRANSFORMATION RULE:**
    *   Step 1: Identify the unique non-black color present in the 5x5 input grid.
    *   Step 2: Retrieve the pre-defined 3x3 pattern associated with that color based on the training examples.
    *   Step 3: Construct the 3x3 output grid using 'X' for the pattern and '.' for the background.

    *   **Mappings observed:**
        *   Blue (B) -> Cross shape (Plus sign)
            ```
            . X .
            X X X
            . X .
            ```
        *   Red (R) -> Top-Left Corner shape (Top row + Middle col)
            ```
            X X X
            . X .
            . X .
            ```
        *   Green (G) -> Bottom-Right Corner shape (Bottom row + Right col)
            ```
            . . X
            . . X
            X X X
            ```

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Step 1: Identify Color.**
    *   Scanning the grid, the non-black color is Green (G).
*   **Step 2: Retrieve Pattern.**
    *   From Example 3, Green (G) maps to the Bottom-Right Corner shape.
    *   Pattern:
        ```
        . . X
        . . X
        X X X
        ```
*   **Step 3: Construct Output.**
    *   Row 1: . . X
    *   Row 2: . . X
    *   Row 3: X X X

**5. Verification:**
*   Does the logic hold? Yes. Example 1 and 4 both use Blue and produce the same output. Example 2 uses Red and produces a different output. Example 3 uses Green and produces a third output. The test input uses Green. Therefore, the output must match Example 3's output.

**6. Formatting:**
*   The user wants the reasoning first, then the final answer in a specific block.
*   Color key: X=grey, .=black.
*   Output format: 3 lines, characters separated by spaces.

**Reasoning Summary:**
1.  **Identify Species:** The input grid contains Green (G) cells scattered on a black background.
2.  **Determine Signature:** Based on the training examples, specifically Example 3, the Green species corresponds to a specific 3x3 grey pattern.
3.  **Pattern Retrieval:** The pattern for Green is a right-aligned 'L' shape (bottom row and right column filled with 'X').
4.  **Construct Output:** Create the 3x3 grid with 'X' in the bottom row and right column, and '.' elsewhere.

**Output Grid:**
. . X
. . X
X X X

Let's double check Example 3.
Input: Green.
Output:
. . X
. . X
X X X
Yes.

Test Input: Green.
Out

... [437 chars truncated]
alt-10 astronomy qwen3.5-122b: k=3
"Stars of a single spectral class flicker across the observation plate, but the astronomer doesn't care about the constellation — she cares about the class, because each spectral type always collapses into the same remnant silhouette."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (9022 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Stars of one spectral color scattered across a dark sky plate." This implies a grid where one color (the "star") is scattered among a background color (likely black/dot `.`).
*   **Output:** "Classify the spectral type by color and predict the stellar remnant — a small fixed shape that spectral class alone determines." This implies the output is a 3x3 grid (based on "3x3 remnant silhouette") containing a specific shape made of a specific color (likely grey `X` based on the examples).
*   **Grid details:** Input is 5x5. Output is 3x3.
*   **Key Insight:** The output shape depends *only* on the spectral class (color) of the stars in the input. The arrangement of stars in the input might be irrelevant, or it might be a distractor, or it might encode the color. However, the description says "spectral class alone determines". This suggests I need to map the input color to a specific 3x3 pattern.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Color: Blue (`B`).
    *   Input Grid: 5x5 with `B` and `.`.
    *   Output Grid: 3x3.
    *   Output Pattern:
        ```
        . X .
        X X X
        . X .
        ```
        This looks like a plus sign or a cross.
    *   Mapping: Blue (`B`) -> Plus Sign (`+`) made of `X`.

*   **Example 2:**
    *   Input Color: Red (`R`).
    *   Input Grid: 5x5 with `R` and `.`.
    *   Output Grid: 3x3.
    *   Output Pattern:
        ```
        X X X
        . X .
        . X .
        ```
        This looks like an 'L' shape or a 'T' rotated? No, top row full, middle col full. It looks like a 'T' shape but the vertical bar goes down from the center. Wait, let's look closer.
        Row 1: X X X
        Row 2: . X .
        Row 3: . X .
        This is a 'T' shape.
    *   Mapping: Red (`R`) -> 'T' shape made of `X`.

*   **Example 3:**
    *   Input Color: Green (`G`).
    *   Input Grid: 5x5 with `G` and `.`.
    *   Output Grid: 3x3.
    *   Output Pattern:
        ```
        . . X
        . . X
        X X X
        ```
        This looks like an 'L' shape (bottom row full, right col full).
    *   Mapping: Green (`G`) -> 'L' shape made of `X`.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input:** A 5x5 grid containing a background (`.`) and a foreground color (spectral type).
    *   **Output:** A 3x3 grid containing a background (`.`) and a foreground color (`X`, representing the remnant).
    *   **Role:** The input color determines the output shape. The specific positions of the input stars do not seem to matter for the shape, only the color itself. The output color is always `X` (grey).

*   **AFFORDANCES:**
    *   The input grid allows identification of the dominant non-background color.
    *   The output grid allows rendering a 3x3 pattern.
    *   The transformation maps Color -> Shape.

*   **TRANSFORMATION RULE:**
    1.  Identify the unique non-background color in the 5x5 input grid.
    2.  Look up the corresponding 3x3 pattern associated with that color.
    3.  Construct the 3x3 output grid using `X` for the shape and `.` for the background.

    *   **Color Mapping:**
        *   Blue (`B`) -> Plus Sign (`+`)
            ```
            . X .
            X X X
            . X .
            ```
        *   Red (`R`) -> T-Shape (`T`)
            ```
            X X X
            . X .
            . X .
            ```
        *   Green (`G`) -> L-Shape (`L`)
            ```
            . . X
            . . X
            X X X
            ```

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Identify Color:** The non-background color is Green (`G`).
*   **Retrieve Pattern:** Based on Example 3, Green (`G`) corresponds to the 'L' shape pattern.
*   **Pattern:**
    ```
    . . X
    . . X
    X X X
    ```
*   **Construct Output:**
    Row 1: `.` `.` `X`
    Row 2: `.` `.` `X`
    Row 3: `X` `X` `X`

**5. Verification:**
*   Does the logic hold?
    *   Ex 1: Blue -> Cross.
    *   Ex 2: Red -> T.
    *   Ex 3: Green -> L.
    *   Test: Green -> L.
*   The output format requires spaces between characters.
*   The output color is `X` (grey) as per the examples.
*   The background is `.` (black).

**6. Final Output Generation:**
The test input has Green stars.
According to Example 3, Green stars map to the L-shaped remnant.
The L-shaped remnant is:
. . X
. . X
X X X

Let's double check the coordinates for Example 3.
Input:
. G . G .
G G . . .
. G . . .
. . G . .
G G G . .
Output:
. . X
. . X
X X X

Yes, the pattern is definitely:
Row 0: . . X
Row 1: . . X
Row 2: X X X

Test Input:
. G . G G
. . G . .
G . . . .
. . G . G
. . . . G
Color is G.
So output is the same as Example 3 output.

Wait, is there any dependency on the

... [4076 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=3
"Flotsam of one cargo type bobs across the dark water in no discernible pattern, but the harbormaster knows: cotton drifts into one mooring shape, silk another, spice a third — the cargo declares its own berth."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (5749 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** 5x5 grid ("ocean") with one "cargo color" scattered across black (.) background.
*   **Output:** 3x3 grid ("mooring pattern") in grey (X) and black (.), fixed per cargo color.
*   **Task:** Identify the cargo type by its color and assign the mooring configuration.
*   **Key Insight:** The output pattern depends *only* on the color of the scattered pixels in the input. The specific arrangement of the scattered pixels in the 5x5 input seems to be noise or "flotsam", while the output is a canonical 3x3 shape associated with that color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input Color:** Blue (B).
    *   **Input Grid:** 5x5 with B's scattered.
    *   **Output Grid:** 3x3.
        ```
        . X .
        X X X
        . X .
        ```
        This looks like a plus sign or a cross shape.
    *   **Mapping:** Blue (B) -> Cross shape.

*   **Example 2:**
    *   **Input Color:** Red (R).
    *   **Input Grid:** 5x5 with R's scattered.
    *   **Output Grid:** 3x3.
        ```
        X X X
        . X .
        . X .
        ```
        This looks like an inverted 'T' shape.
    *   **Mapping:** Red (R) -> Inverted T shape.

*   **Example 3:**
    *   **Input Color:** Green (G).
    *   **Input Grid:** 5x5 with G's scattered.
    *   **Output Grid:** 3x3.
        ```
        . . X
        . . X
        X X X
        ```
        This looks like an 'L' shape (bottom row full, right column full).
    *   **Mapping:** Green (G) -> L shape.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input:** A 5x5 grid containing a specific color (Cargo) and black (Background).
    *   **Output:** A 3x3 grid containing Grey (X) and Black (.).
    *   **Role:** The input color determines the output shape. The input grid layout is irrelevant to the output shape, only the presence of the color matters.

*   **AFFORDANCES:**
    *   The input grid allows us to detect the dominant non-black color.
    *   The output grid is a fixed template associated with that color.

*   **TRANSFORMATION RULE:**
    1.  Scan the 5x5 input grid to identify the unique non-black color present (let's call it $C$).
    2.  Look up the canonical 3x3 pattern associated with color $C$.
    3.  Output that 3x3 pattern using Grey (X) for the pattern pixels and Black (.) for the empty pixels.

    *   **Color -> Pattern Mapping:**
        *   Blue (B) -> Plus/Cross:
            ```
            . X .
            X X X
            . X .
            ```
        *   Red (R) -> Inverted T:
            ```
            X X X
            . X .
            . X .
            ```
        *   Green (G) -> L-shape (Bottom-Right corner):
            ```
            . . X
            . . X
            X X X
            ```

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Step 1: Identify Color.**
    *   Scanning the grid, I see dots (.) and Green (G).
    *   The cargo color is Green (G).

*   **Step 2: Retrieve Pattern.**
    *   From Example 3, Green (G) corresponds to the L-shape pattern.
    *   Pattern:
        ```
        . . X
        . . X
        X X X
        ```

*   **Step 3: Construct Output.**
    *   The output must be a 3x3 grid.
    *   Row 1: . . X
    *   Row 2: . . X
    *   Row 3: X X X

**5. Verification:**
*   Does the logic hold? Yes, the prompt explicitly states "each cargo has one berth pattern, regardless of where the flotsam drifts." This confirms that the spatial arrangement in the 5x5 input doesn't matter, only the color.
*   Example 1 (Blue) -> Cross.
*   Example 2 (Red) -> Inverted T.
*   Example 3 (Green) -> L-shape.
*   Test Input (Green) -> L-shape.

**6. Formatting:**
*   The output needs to be in the specific format requested.
*   Characters separated by spaces.
*   Final block labeled "ANSWER:".

Let's double check the Green pattern from Example 3.
Input:
. G . G .
G G . . .
. G . . .
. . G . .
G G G . .
Output:
. . X
. . X
X X X

Yes, that matches my derivation.

Test Input:
. G . G G
. . G . .
G . . . .
. . G . G
. . . . G
Color is G.
Output should be the Green pattern.

Output Grid:
. . X
. . X
X X X

Wait, let me look closer at Example 3's output.
Output:
. . X
. . X
X X X
This is an 'L' shape rotated or just an 'L' in the bottom right.
Row 1: dot, dot, X
Row 2: dot, dot, X
Row 3: X, X, X

Okay, ready to write the response.

**Step-by-step reasoning for the final output:**
1.  **Identify the Cargo Color:** The test input grid contains black (`.`) and green (`G`) pixels. The metaphorical description states we need to identify the cargo type by its color. Thus, the cargo color is Green (`G`).
2.  **Retrieve the Mooring Pattern:** Based on the training examples, each color maps to a specific 3x3 p

... [782 chars truncated]
alt-12 electronics qwen3.5-122b: k=3
"Charge carriers are scattered randomly across the semiconductor, but the dopant type determines the junction geometry — each impurity, no matter how it diffuses, always produces the same circuit signature on the output pin."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (9995 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** 5x5 grid ("substrate") with one "dopant color" scattered across a "dark" (black '.') background.
*   **Output:** 3x3 grid ("junction pattern") in grey ('X'), specific to the dopant type.
*   **Task:** Identify the dopant color from the input and map it to a specific 3x3 pattern.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** 5x5 grid containing Blue ('B') and Black ('.').
    *   **Dopant Color:** Blue ('B').
    *   **Output:** 3x3 grid.
        ```
        . X .
        X X X
        . X .
        ```
    *   **Pattern:** A cross shape (plus sign) in the center.

*   **Example 2:**
    *   **Input:** 5x5 grid containing Red ('R') and Black ('.').
    *   **Dopant Color:** Red ('R').
    *   **Output:** 3x3 grid.
        ```
        X X X
        . X .
        . X .
        ```
    *   **Pattern:** An 'L' shape or a corner shape? Top row full, middle column full. Looks like a '7' or a specific corner. Let's look closer.
        Row 0: X X X
        Row 1: . X .
        Row 2: . X .
        This looks like a 'T' shape rotated or a specific glyph. Actually, it looks like the top row and the middle column.

*   **Example 3:**
    *   **Input:** 5x5 grid containing Green ('G') and Black ('.').
    *   **Dopant Color:** Green ('G').
    *   **Output:** 3x3 grid.
        ```
        . . X
        . . X
        X X X
        ```
    *   **Pattern:** Bottom row full, right column full. Looks like an 'L' shape (bottom-right corner).

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input Grid:** Represents a "substrate" with impurities. The background is black ('.'). The foreground is the "dopant" color (B, R, G).
    *   **Output Grid:** Represents a "junction pattern" or a symbol associated with the dopant color. The output is always 3x3. The active pixels are Grey ('X'), inactive are Black ('.').
    *   **Mapping:** There is a one-to-one mapping between the specific color present in the input and a specific 3x3 pattern.

*   **AFFORDANCES:**
    *   The input grid allows us to identify the dominant non-black color.
    *   The output grid is fixed for each color.
    *   The transformation ignores the *positions* of the dopants in the 5x5 input. It only cares about *which* color is present. The metaphor says "Identify the dopant by its color and read off the junction geometry". This implies the geometry is intrinsic to the color, not derived from the spatial arrangement in the 5x5 grid.

*   **TRANSFORMATION RULE:**
    1.  Scan the 5x5 input grid to find the non-black color (the dopant).
    2.  Look up the corresponding 3x3 pattern associated with that color based on the training examples.
    3.  Construct the 3x3 output grid using 'X' for the pattern and '.' for the background.

    *   **Blue (B) Pattern:**
        ```
        . X .
        X X X
        . X .
        ```
        (Plus sign / Cross)

    *   **Red (R) Pattern:**
        ```
        X X X
        . X .
        . X .
        ```
        (Top row + Middle column)

    *   **Green (G) Pattern:**
        ```
        . . X
        . . X
        X X X
        ```
        (Bottom row + Right column)

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Identify Dopant:** The non-black color is Green ('G').
*   **Retrieve Pattern:** Based on Example 3, the Green pattern is:
    ```
    . . X
    . . X
    X X X
    ```
*   **Construct Output:**
    Row 1: . . X
    Row 2: . . X
    Row 3: X X X

**5. Verification:**
*   Does the test input contain any other colors? No, just '.' and 'G'.
*   Is the mapping consistent?
    *   Ex 1 (Blue) -> Cross.
    *   Ex 2 (Red) -> Top-Mid T-shape.
    *   Ex 3 (Green) -> Bottom-Right L-shape.
    *   Test (Green) -> Should match Ex 3.

**6. Formatting:**
*   Output needs to be a 3x3 grid.
*   Characters separated by spaces.
*   Final block labeled "ANSWER:".

Let's double check the patterns.
Ex 1 (Blue):
. X .
X X X
. X .
(Center cross)

Ex 2 (Red):
X X X
. X .
. X .
(Top bar, middle vertical)

Ex 3 (Green):
. . X
. . X
X X X
(Right bar, bottom horizontal)

Test Input has Green.
So the output must be the Green pattern.

Output Grid:
. . X
. . X
X X X

Let's write down the steps for the final response.
1. Identify the dopant color in the test input. It is Green (G).
2. Recall the pattern associated with Green from Example 3.
3. The pattern is a 3x3 grid where the bottom row and the rightmost column are filled with 'X' (grey), and the rest are '.' (black).
4. Format the output.

Wait, looking closely at Example 2 (Red):
X X X
. X .
. X .
This is Top Row + Middle Column.

Looking closely at Example 3 (Green):
. . X
. . X
X X X
This is Right Column + Bottom Row.

Looking closely at Example 1 (Blue):
. X .
X X

... [5022 chars truncated]
alt-13 mythology qwen3.5-122b: k=3
"The oracle's bones land differently every cast, but the god who stained them has already chosen the omen — each deity's dye reveals one and only one sacred glyph, and the throw pattern is mere theater."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (6110 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Oracle bones tinted in one deity's sacred color, scattered across a dark cloth."
    *   "Oracle bones": These are likely the colored pixels in the input grid.
    *   "One deity's sacred color": The input grid contains pixels of a single non-black color (plus black background).
    *   "Scattered across a dark cloth": The background is black (`.`).
*   **Task:** "Read the dye color to identify the deity and inscribe the sacred glyph — each god commands one eternal symbol, indifferent to how the bones fell."
    *   "Read the dye color": The specific color present in the input determines the output.
    *   "Inscribe the sacred glyph": The output is a specific pattern (glyph) associated with that color.
    *   "Indifferent to how the bones fell": The arrangement of the colored pixels in the input doesn't matter for the *shape* of the output, only the *color* matters. The output is fixed per deity (color).
*   **Grid details:**
    *   Input: 5x5 casting cloth.
    *   Output: 3x3 divine glyph in grey (`X`), fixed per deity.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Color: Blue (`B`).
    *   Input Grid: 5x5 with `B` and `.`.
    *   Output Grid: 3x3.
    *   Output Pattern:
        ```
        . X .
        X X X
        . X .
        ```
        This looks like a plus sign or a cross.
    *   Mapping: Blue (`B`) -> Plus Sign (`+` shape in 3x3).

*   **Example 2:**
    *   Input Color: Red (`R`).
    *   Input Grid: 5x5 with `R` and `.`.
    *   Output Grid: 3x3.
    *   Output Pattern:
        ```
        X X X
        . X .
        . X .
        ```
        This looks like an inverted 'T' or a '7' shape? No, it's a top row full, and a middle column. Like a 'T' rotated or just a specific shape. Let's call it Shape R.
    *   Mapping: Red (`R`) -> Shape R.

*   **Example 3:**
    *   Input Color: Green (`G`).
    *   Input Grid: 5x5 with `G` and `.`.
    *   Output Grid: 3x3.
    *   Output Pattern:
        ```
        . . X
        . . X
        X X X
        ```
        This looks like an 'L' shape (bottom row full, right column full).
    *   Mapping: Green (`G`) -> Shape G (L-shape).

**3. Conceptual Digestion:**

1.  **Identify the CAST:**
    *   **Input:** A 5x5 grid containing a background color (black `.`) and a foreground color (the "sacred color").
    *   **Output:** A 3x3 grid containing a background color (black `.`) and a foreground color (grey `X`).
    *   **Deity/Color:** The specific foreground color in the input determines which 3x3 pattern is generated.

2.  **Identify the AFFORDANCES:**
    *   The input grid's spatial arrangement of the colored pixels is irrelevant ("indifferent to how the bones fell").
    *   The input grid's size is fixed at 5x5.
    *   The output grid's size is fixed at 3x3.
    *   The output color is always Grey (`X`).
    *   The output shape is determined solely by the input color.

3.  **Identify the TRANSFORMATION RULE:**
    *   Step 1: Identify the unique non-black color in the 5x5 input grid.
    *   Step 2: Map this color to a specific 3x3 pattern based on the training examples.
        *   Blue (`B`) -> Plus Sign (`.` `X` `.`, `X` `X` `X`, `.` `X` `.`)
        *   Red (`R`) -> Top Bar + Middle Stem (`X` `X` `X`, `.` `X` `.`, `.` `X` `.`)
        *   Green (`G`) -> Bottom Bar + Right Stem (`.` `.` `X`, `.` `.` `X`, `X` `X` `X`)
    *   Step 3: Generate the 3x3 output grid using the mapped pattern.

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Step 1: Identify Color.**
    *   The non-black pixels are `G` (Green).
    *   So, the "Deity" is Green.
*   **Step 2: Retrieve Pattern.**
    *   From Example 3, Green (`G`) maps to the L-shape pattern:
        ```
        . . X
        . . X
        X X X
        ```
*   **Step 3: Construct Output.**
    *   The output must be a 3x3 grid.
    *   The pattern is:
        Row 1: `.` `.` `X`
        Row 2: `.` `.` `X`
        Row 3: `X` `X` `X`

**5. Verification:**
*   Does the logic hold?
    *   Ex 1: Blue -> Cross.
    *   Ex 2: Red -> T-shape (inverted).
    *   Ex 3: Green -> L-shape.
    *   Test: Green -> L-shape.
*   The instruction says "indifferent to how the bones fell", confirming the input pattern doesn't matter, only the color.
*   The output color is specified as "grey" (`X`) in the description ("Output: 3x3 divine glyph in grey").
*   The output size is 3x3.

**6. Formatting:**
*   I need to output the reasoning steps.
*   Then I need to write the final grid in the specified format.
*   Color key: `X` is grey. `.` is black.
*   The output grid should use spaces between characters.

**Drafting the Output:**
Row 1: . . X
Row 2: . . X
Row 3: X X X

Let's double check

... [1158 chars truncated]
alt-14 dance qwen3.5-122b: k=3
"Dancers wander the darkened stage during the overture, but when the spotlight hits, each company snaps into its signature lift — the choreography is written in the color of their shoes, not in their wandering."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (12195 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** 5x5 stage with one slipper color (scattered dancers).
*   **Output:** 3x3 lift formation in grey (X), unique per company (slipper color).
*   **Key Concept:** "Identify the company by slipper color and call the signature lift — a compact formation each company always performs, regardless of starting positions."
*   **Implication:** The input grid contains a specific color (the "slipper color"). The output grid is always 3x3 and consists of 'X' (grey) and '.' (black). The pattern of 'X's depends on the "company" (the color of the input).
*   **Wait, let's look at the examples.**
    *   Example 1: Input color is Blue (B). Output is a specific 3x3 pattern of X's.
    *   Example 2: Input color is Red (R). Output is a specific 3x3 pattern of X's.
    *   Example 3: Input color is Green (G). Output is a specific 3x3 pattern of X's.
    *   Test Input: Input color is Green (G).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Color: Blue (B)
    *   Input Grid (5x5):
        ```
        B . B . .
        B . . B B
        B B . B .
        . B . B .
        B . . . B
        ```
    *   Output Grid (3x3):
        ```
        . X .
        X X X
        . X .
        ```
    *   Pattern: A cross shape (plus sign). Center is X, top, bottom, left, right are X. Corners are dots.

*   **Example 2:**
    *   Input Color: Red (R)
    *   Input Grid (5x5):
        ```
        R . R . R
        R . . . R
        R R . . .
        R . . R R
        R R R . R
        ```
    *   Output Grid (3x3):
        ```
        X X X
        . X .
        . X .
        ```
    *   Pattern: An inverted 'T' shape? Or a '7' shape? Top row is all X. Middle column is all X.
        Row 0: X X X
        Row 1: . X .
        Row 2: . X .
        This looks like a 'T' shape.

*   **Example 3:**
    *   Input Color: Green (G)
    *   Input Grid (5x5):
        ```
        . G . G .
        G G . . .
        . G . . .
        . . G . .
        G G G . .
        ```
    *   Output Grid (3x3):
        ```
        . . X
        . . X
        X X X
        ```
    *   Pattern: An 'L' shape (rotated). Bottom row is all X. Right column is all X.
        Row 0: . . X
        Row 1: . . X
        Row 2: X X X

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input:** A 5x5 grid containing scattered pixels of a specific color (B, R, or G) and background (black '.').
    *   **Output:** A 3x3 grid containing pixels of color Grey (X) and background (black '.').
    *   **Role of Input Color:** It determines *which* 3x3 pattern to output. It acts as a key or ID for the "company".
    *   **Role of Input Positions:** The specific positions of the colored pixels in the 5x5 grid seem irrelevant to the *shape* of the output, based on the description "regardless of starting positions". The description says "Identify the company by slipper color". This implies the mapping is Color -> Pattern.
    *   **Role of Output Color:** Always Grey (X).

*   **AFFORDANCES:**
    *   The input grid provides the "Company ID" (Color).
    *   The system has a lookup table mapping Colors to 3x3 Patterns.
    *   The output is generated by selecting the pattern associated with the dominant color in the input.

*   **TRANSFORMATION RULE:**
    *   Step 1: Identify the non-black color present in the 5x5 input grid.
    *   Step 2: Map this color to a specific 3x3 pattern of 'X's.
        *   Blue (B) -> Cross (+)
        *   Red (R) -> T-shape (Top bar + Middle stem)
        *   Green (G) -> L-shape (Bottom bar + Right stem)
    *   Step 3: Construct the 3x3 output grid using 'X' for the pattern and '.' for empty space.

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Step 1: Identify Color.**
    *   The non-black color is Green (G).
*   **Step 2: Map Color to Pattern.**
    *   From Example 3, Green (G) maps to the pattern:
        ```
        . . X
        . . X
        X X X
        ```
*   **Step 3: Construct Output.**
    *   The output should be exactly the pattern found in Example 3.

**5. Verification:**
*   Does the description "regardless of starting positions" hold?
    *   Example 1 (Blue): Scattered B's. Output: Cross.
    *   Example 2 (Red): Scattered R's. Output: T-shape.
    *   Example 3 (Green): Scattered G's. Output: L-shape.
    *   Test (Green): Scattered G's. Output: Should be L-shape.
*   The logic holds. The specific arrangement of G's in the test input doesn't matter, only the fact that they are G's.
*   Wait, is there any possibility that the *count* or *arrangement* matters?
    *   Example 1 Blue count: 12 Bs.
    *   Example 2 Red count: 13 Rs.
    *   Example 3 Green count: 10 Gs.
    *   Test Green count: 8 Gs.
    *   Since the descript

... [7273 chars truncated]
alt-15 geology qwen3.5-122b: k=3
"Mineral deposits surface in random veins, but the assayer needs only the color of the ore to know its crystal habit — each mineral, no matter how its veins run, always cleaves into the same lattice."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (9800 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** 5x5 grid representing a "rock face" with "one ore color" scattered in "dark rock" (black `.`).
*   **Output:** 3x3 grid representing a "crystal lattice" in grey (`X`), fixed per mineral.
*   **Task:** Identify the mineral by ore color and predict its crystal habit.
*   **Key Insight:** The output is a 3x3 pattern of grey `X`s and black `.`s. The pattern depends on the color of the "ore" in the input. The input is 5x5, output is 3x3. The "ore" color seems to determine *which* 3x3 pattern to output.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input Color:** Blue (`B`).
    *   **Input Grid:**
        ```
        B . B . .
        B . . B B
        B B . B .
        . B . B .
        B . . . B
        ```
    *   **Output Grid:**
        ```
        . X .
        X X X
        . X .
        ```
    *   **Observation:** The output is a cross shape (plus sign) made of `X`s.

*   **Example 2:**
    *   **Input Color:** Red (`R`).
    *   **Input Grid:**
        ```
        R . R . R
        R . . . R
        R R . . .
        R . . R R
        R R R . R
        ```
    *   **Output Grid:**
        ```
        X X X
        . X .
        . X .
        ```
    *   **Observation:** The output is an 'L' shape (or inverted 'T' without the bottom bar? No, it's top row full, middle col full). Let's look closer.
        Row 0: X X X
        Row 1: . X .
        Row 2: . X .
        This looks like a 'T' shape rotated or just a specific pattern. It's a top bar and a vertical stem down the middle.

*   **Example 3:**
    *   **Input Color:** Green (`G`).
    *   **Input Grid:**
        ```
        . G . G .
        G G . . .
        . G . . .
        . . G . .
        G G G . .
        ```
    *   **Output Grid:**
        ```
        . . X
        . . X
        X X X
        ```
    *   **Observation:** The output is an 'L' shape in the bottom right corner.
        Row 0: . . X
        Row 1: . . X
        Row 2: X X X

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input:** A 5x5 grid containing a specific color (Blue, Red, Green) and black background.
    *   **Output:** A 3x3 grid containing grey (`X`) and black (`.`).
    *   **Role:** The input color acts as a "key" or "identifier" for a specific 3x3 template. The spatial arrangement of the ore in the 5x5 input seems irrelevant to the *shape* of the output, only the *color* matters. The prompt says "predict its crystal habit — a compact lattice unique to that mineral, independent of vein placement." This confirms that the specific positions of the colored pixels in the input do not determine the output shape, only the color does.

*   **AFFORDANCES:**
    *   The colored pixels identify the mineral type.
    *   The black pixels are background.
    *   The output is a fixed 3x3 pattern associated with that mineral type.

*   **TRANSFORMATION RULE:**
    *   Step 1: Identify the non-black color present in the 5x5 input grid.
    *   Step 2: Map that color to a specific 3x3 pattern based on the training examples.
    *   Step 3: Output that 3x3 pattern.

    *   **Mappings derived from examples:**
        *   **Blue (`B`)** -> Cross shape:
            ```
            . X .
            X X X
            . X .
            ```
        *   **Red (`R`)** -> Top-bar + Middle-stem shape:
            ```
            X X X
            . X .
            . X .
            ```
        *   **Green (`G`)** -> Bottom-right L shape:
            ```
            . . X
            . . X
            X X X
            ```

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Identify Color:** The non-black color is Green (`G`).
*   **Retrieve Pattern:** Look up the pattern for Green (`G`) from Example 3.
    *   Pattern:
        ```
        . . X
        . . X
        X X X
        ```
*   **Construct Output:**
    Row 1: `.` `.` `X`
    Row 2: `.` `.` `X`
    Row 3: `X` `X` `X`

**5. Verification:**
*   Does the logic hold?
    *   Example 1 (Blue) -> Cross.
    *   Example 2 (Red) -> T-shape (Top row + Middle col).
    *   Example 3 (Green) -> L-shape (Bottom row + Right col).
    *   Test Input has Green.
    *   Therefore, Output should be the Green pattern.
*   Is there any other interpretation?
    *   Could the position of the ore matter?
        *   Ex 1 (Blue): Ore is scattered. Output is centered cross.
        *   Ex 2 (Red): Ore is scattered. Output is top-aligned T.
        *   Ex 3 (Green): Ore is scattered. Output is bottom-right L.
    *   The prompt explicitly says "independent of vein placement". This strongly suggests the spatial distribution in the 5x5 grid is noise/distractor, and only the color matters.
    *   The prompt says "Output: 3x3 crystal lattice

... [4842 chars truncated]
alt-2 cooking qwen3.5-122b: k=3
"No matter how you scatter the spice across the cutting board, when it hits the heat, it always crystallizes into the same garnish pattern — cumin curls one way, paprika another, dried basil a third."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (13410 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 5x5 dark board (black background, represented by '.') with one colored spice scattered randomly.
*   **Output:** A 3x3 plated garnish in grey (represented by 'X'), shape determined by spice identity.
*   **Task:** Identify the spice (color) and output the corresponding 3x3 pattern.
*   **Key Insight:** The input grid contains a specific color pattern. The output grid is always 3x3 and uses 'X' (grey) and '.' (black). The shape of the 'X's in the output depends on the color of the 'spice' in the input.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** 5x5 grid. Color used: Blue ('B').
    *   **Input Pattern:**
        ```
        B . B . .
        B . . B B
        B B . B .
        . B . B .
        B . . . B
        ```
    *   **Output:** 3x3 grid.
        ```
        . X .
        X X X
        . X .
        ```
    *   **Observation:** The output looks like a plus sign or a cross. The input color is Blue.

*   **Example 2:**
    *   **Input:** 5x5 grid. Color used: Red ('R').
    *   **Input Pattern:**
        ```
        R . R . R
        R . . . R
        R R . . .
        R . . R R
        R R R . R
        ```
    *   **Output:** 3x3 grid.
        ```
        X X X
        . X .
        . X .
        ```
    *   **Observation:** The output looks like an 'L' shape or a corner. The input color is Red.

*   **Example 3:**
    *   **Input:** 5x5 grid. Color used: Green ('G').
    *   **Input Pattern:**
        ```
        . G . G .
        G G . . .
        . G . . .
        . . G . .
        G G G . .
        ```
    *   **Output:** 3x3 grid.
        ```
        . . X
        . . X
        X X X
        ```
    *   **Observation:** The output looks like an 'L' shape rotated or a corner. The input color is Green.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input Grid:** A container holding a "spice" (colored pixels).
    *   **Spice Color:** The identifier. It determines the output shape.
    *   **Output Grid:** The "plate" or "garnish". It's always 3x3.
    *   **Garnish Color:** Always Grey ('X').
    *   **Background:** Always Black ('.').

*   **AFFORDANCES:**
    *   The input grid's specific color maps to a specific 3x3 binary mask (where 'X' is 1 and '.' is 0).
    *   The spatial arrangement of the colored pixels in the 5x5 input seems random or "scattered", suggesting the specific positions don't matter, only the *presence* of the color.
    *   Wait, let's look closer at the input patterns. Are they just random noise of that color, or do they encode the shape?
    *   Example 1 (Blue):
        Row 0: B . B . .
        Row 1: B . . B B
        Row 2: B B . B .
        Row 3: . B . B .
        Row 4: B . . . B
        Total Bs: 2+3+3+2+2 = 12.
        Output shape: Cross.
    *   Example 2 (Red):
        Row 0: R . R . R
        Row 1: R . . . R
        Row 2: R R . . .
        Row 3: R . . R R
        Row 4: R R R . R
        Total Rs: 3+2+2+3+4 = 14.
        Output shape: Top row full, middle col full (inverted L).
    *   Example 3 (Green):
        Row 0: . G . G .
        Row 1: G G . . .
        Row 2: . G . . .
        Row 3: . . G . .
        Row 4: G G G . .
        Total Gs: 2+2+1+1+3 = 9.
        Output shape: Bottom row full, right col full (L shape).

    *   **Hypothesis 1:** The color determines the shape.
        *   Blue -> Cross
        *   Red -> Top-Left-ish L (Top row + Middle col)
        *   Green -> Bottom-Right-ish L (Bottom row + Right col)

    *   **Hypothesis 2:** The input pattern *is* the shape, just scaled or distorted?
        *   Input is 5x5. Output is 3x3.
        *   Let's check if the input pattern resembles the output pattern.
        *   Ex 1 Output:
            . X .
            X X X
            . X .
            This is a cross.
            Input Ex 1:
            B . B . .
            B . . B B
            B B . B .
            . B . B .
            B . . . B
            Does this look like a cross? Not really. It looks like scattered noise.
        *   Ex 2 Output:
            X X X
            . X .
            . X .
            Input Ex 2:
            R . R . R
            R . . . R
            R R . . .
            R . . R R
            R R R . R
            Does this look like the output?
            Top row of output is XXX. Input top row is R.R.R. (3 items).
            Middle col of output is X.X. Input middle col is . . . . . (0 items).
            So it's not a direct spatial mapping.

    *   **Hypothesis 3:** The color is the key. I need to deduce the mapping from Color -> Shape based on the examples.
        *   Blue (B) -> Cross (+)
        *   Red (R) -> Top bar + Middle vertical (looks like a 'T' rotated or an inverted 'L' with a long top). Specifically: Row 0 is all X, Col 1 is all X.
        *   Green (

... [8476 chars truncated]
alt-3 music qwen3.5-122b: k=3
"The notes are scattered across the staff like a child's first attempt at composition, but every instrument, when it hears its own timbre echoed back, reflexively plays the same signature riff — the melody is in the voice, not the score."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (9738 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Random notes written in a single instrument's color of ink splashed across a dark staff."
    *   This implies the input grid contains a background color (black `.`) and a foreground color (the "instrument's ink").
    *   The input grid size is 5x5.
*   **Output:** "Recognize the instrument by its ink color and play its signature riff — a compact motif that never changes regardless of what was written on the page."
    *   This implies the output grid size is 3x3.
    *   The output grid consists of a specific pattern (the "riff").
    *   The pattern is "fixed per instrument". This means the color of the input determines the pattern in the output.
    *   The output pattern uses `X` (grey) for the "riff" and `.` (black) for the background, based on the examples. Wait, let's check the examples.
    *   Example 1 Input: Blue (`B`). Output: `X` and `.`.
    *   Example 2 Input: Red (`R`). Output: `X` and `.`.
    *   Example 3 Input: Green (`G`). Output: `X` and `.`.
    *   So, the output is always a 3x3 grid of `X` (grey) and `.` (black). The specific arrangement of `X`s depends on the input color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Color: Blue (`B`).
    *   Input Grid:
        ```
        B . B . .
        B . . B B
        B B . B .
        . B . B .
        B . . . B
        ```
    *   Output Grid:
        ```
        . X .
        X X X
        . X .
        ```
    *   Pattern: A cross shape (plus sign). Center is `X`, top, bottom, left, right are `X`. Corners are `.`.
    *   Let's check the position of `B`s in the input.
        *   (0,0), (0,2)
        *   (1,0), (1,3), (1,4)
        *   (2,0), (2,1), (2,3)
        *   (3,1), (3,3)
        *   (4,0), (4,4)
    *   This looks like a scattered pattern. The metaphor says "Random notes...". The output is the "signature riff".
    *   Hypothesis: The input color maps to a specific 3x3 pattern.
    *   Blue (`B`) -> Cross pattern.

*   **Example 2:**
    *   Input Color: Red (`R`).
    *   Input Grid:
        ```
        R . R . R
        R . . . R
        R R . . .
        R . . R R
        R R R . R
        ```
    *   Output Grid:
        ```
        X X X
        . X .
        . X .
        ```
    *   Pattern: An inverted 'T' shape? Or a '7' shape?
        *   Row 0: X X X
        *   Row 1: . X .
        *   Row 2: . X .
        *   It looks like a 'T' rotated 180 degrees? No, it's a T shape. Top bar, middle stem.
        *   Wait, let's look closer.
        *   (0,0), (0,1), (0,2) are X.
        *   (1,1) is X.
        *   (2,1) is X.
        *   This is a 'T' shape.
    *   Red (`R`) -> T shape.

*   **Example 3:**
    *   Input Color: Green (`G`).
    *   Input Grid:
        ```
        . G . G .
        G G . . .
        . G . . .
        . . G . .
        G G G . .
        ```
    *   Output Grid:
        ```
        . . X
        . . X
        X X X
        ```
    *   Pattern: An 'L' shape (rotated/flipped).
        *   Row 0: . . X
        *   Row 1: . . X
        *   Row 2: X X X
        *   This is an 'L' shape in the bottom right corner.
    *   Green (`G`) -> L shape (bottom-right).

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** A 5x5 canvas containing a specific color (the "instrument") scattered on a black background. The specific arrangement of the colored pixels seems irrelevant ("Random notes"), only the *color* matters.
    *   **Output Grid:** A 3x3 canvas representing the "riff".
    *   **Instrument Color:** The key variable. Blue, Red, Green map to specific shapes.
    *   **Riff Pattern:** A fixed 3x3 binary mask (Grey `X` vs Black `.`) associated with the instrument color.

2.  **AFFORDANCES:**
    *   The input grid allows us to identify the dominant non-black color.
    *   The output grid allows us to display a 3x3 pattern.
    *   The transformation maps Color -> Pattern.

3.  **TRANSFORMATION RULE:**
    *   Step 1: Identify the non-black color present in the 5x5 input grid.
    *   Step 2: Retrieve the pre-defined 3x3 pattern associated with that color.
    *   Step 3: Output the 3x3 pattern using `X` for the pattern pixels and `.` for the background.

    *   **Mappings observed:**
        *   Blue (`B`) -> Cross (`+`)
            ```
            . X .
            X X X
            . X .
            ```
        *   Red (`R`) -> T-shape
            ```
            X X X
            . X .
            . X .
            ```
        *   Green (`G`) -> L-shape (bottom-right)
            ```
            . . X
            . . X
            X X X
            ```

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Step 1: Identify Color.**
    *   The non-black color is Green (`

... [4786 chars truncated]
alt-4 sports qwen3.5-122b: k=3
"The players scramble across the field in chaos, but when the referee blows the whistle, each team falls into formation — and every team only knows one formation, branded into muscle memory by the color of their jersey."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (7347 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** 5x5 field with one jersey color scattered.
*   **Output:** 3x3 formation diagram in grey (X), unique to that team.
*   **Metaphor:** "Players in matching jerseys" (the colored pixels in the input) scattered on a "dark playing field" (black background `.`).
*   **Task:** Identify the jersey color and call the team's "one and only formation" (a specific 3x3 pattern of grey `X`s).
*   **Key Insight:** The input grid contains a specific color (e.g., Blue, Red, Green). The output grid is always 3x3 and consists of `X` (grey) and `.` (black). The pattern of `X`s depends on the color present in the input.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Color: Blue (`B`).
    *   Input Grid: 5x5 with `B`s scattered.
    *   Output Grid: 3x3.
        ```
        . X .
        X X X
        . X .
        ```
    *   Pattern: A plus sign or cross shape. Center is `X`, top, bottom, left, right are `X`. Corners are `.`.

*   **Example 2:**
    *   Input Color: Red (`R`).
    *   Input Grid: 5x5 with `R`s scattered.
    *   Output Grid: 3x3.
        ```
        X X X
        . X .
        . X .
        ```
    *   Pattern: An 'L' shape or a 'T' shape rotated? Top row is all `X`. Middle column is all `X`. It looks like a 'T' shape but the top bar is full width. Wait, let's look closer.
        Row 0: X X X
        Row 1: . X .
        Row 2: . X .
        This is a 'T' shape.

*   **Example 3:**
    *   Input Color: Green (`G`).
    *   Input Grid: 5x5 with `G`s scattered.
    *   Output Grid: 3x3.
        ```
        . . X
        . . X
        X X X
        ```
    *   Pattern: An 'L' shape (bottom row full, right column full).

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input:** A 5x5 grid containing a specific color (B, R, G) and background `.`.
    *   **Output:** A 3x3 grid containing `X` (grey) and `.` (black).
    *   **Role of Input Color:** The specific color determines which 3x3 pattern is selected.
    *   **Role of Input Pattern:** The arrangement of the colored pixels in the 5x5 grid seems irrelevant to the *shape* of the output, other than identifying the color. The prompt says "Identify the jersey color and call the team's one and only formation". This implies the mapping is Color -> Shape. The specific positions of the pixels in the 5x5 input might just be noise or "scattered players". Let's verify if the positions matter.
        *   Ex 1 (Blue): 12 Blue pixels.
        *   Ex 2 (Red): 12 Red pixels.
        *   Ex 3 (Green): 10 Green pixels.
        *   The counts vary. The positions vary. The output depends solely on the color.

*   **AFFORDANCES:**
    *   The input grid allows us to detect the dominant non-black color.
    *   The output grid is a fixed template associated with that color.

*   **TRANSFORMATION RULE:**
    *   Step 1: Scan the 5x5 input grid to find the non-black color (the "jersey color").
    *   Step 2: Map the color to a specific 3x3 pattern of `X`s.
        *   Blue (`B`) -> Plus Sign (`+`)
            ```
            . X .
            X X X
            . X .
            ```
        *   Red (`R`) -> T-Shape (`T`)
            ```
            X X X
            . X .
            . X .
            ```
        *   Green (`G`) -> L-Shape (`L`)
            ```
            . . X
            . . X
            X X X
            ```
    *   Step 3: Construct the 3x3 output grid using `X` for the shape and `.` for the background.

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Identify Color:** The non-black color is Green (`G`).
*   **Retrieve Pattern:** Based on Example 3, Green corresponds to the L-Shape pattern.
    *   Pattern:
        Row 0: `.` `.` `X`
        Row 1: `.` `.` `X`
        Row 2: `X` `X` `X`
*   **Construct Output:**
    ```
    . . X
    . . X
    X X X
    ```

**5. Verification:**
*   Does the logic hold?
    *   Ex 1: Blue -> Cross.
    *   Ex 2: Red -> T.
    *   Ex 3: Green -> L.
    *   Test: Green -> L.
*   The prompt asks for "Conceptual Digestion" first.
    1.  **CAST**: Input is a 5x5 grid with scattered colored pixels on black. Output is a 3x3 grid with grey pixels on black. The colored pixels represent "players", the output represents the "formation".
    2.  **AFFORDANCES**: The input grid allows color identification. The color acts as a key to a lookup table of formations.
    3.  **TRANSFORMATION RULE**: Detect the unique non-black color in the input. Replace the 5x5 grid with a 3x3 grid representing the specific formation associated with that color.
        *   Blue = Cross
        *   Red = T
        *   Green = L (Bottom-Right corner heavy)
*   Test Input has Green pixels.
*   Therefore, output is the Green formation (L-shape)

... [2383 chars truncated]
alt-5 weather qwen3.5-122b: k=5
"Storm cells gather in different patterns each day, but every front — cold, warm, or occluded — always leaves behind the same pressure signature on the barograph, as if the atmosphere has only three fingerprints."
MARC valid, solved with k=5
Prediction
vs
Expected
Reasoning (7555 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 5x5 map with scattered cells of a specific color (the "front").
*   **Output:** A 3x3 grid representing a "pressure signature" in grey (X).
*   **Task:** Identify the color of the front in the input and map it to a specific 3x3 pattern.
*   **Key Insight:** The output is always a 3x3 grid of grey (X) and black (.) cells. The pattern depends on the input color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Color: Blue (B)
    *   Input Grid: 5x5 with scattered B's.
    *   Output Grid:
        ```
        . X .
        X X X
        . X .
        ```
    *   Pattern: A plus sign (+) shape in the center.

*   **Example 2:**
    *   Input Color: Red (R)
    *   Input Grid: 5x5 with scattered R's.
    *   Output Grid:
        ```
        X X X
        . X .
        . X .
        ```
    *   Pattern: An 'L' shape or a corner shape (Top row full, middle column full). Wait, let's look closer.
        Row 0: X X X
        Row 1: . X .
        Row 2: . X .
        This looks like an inverted 'T' or a specific shape. Let's call it Shape R.

*   **Example 3:**
    *   Input Color: Green (G)
    *   Input Grid: 5x5 with scattered G's.
    *   Output Grid:
        ```
        . . X
        . . X
        X X X
        ```
    *   Pattern: An 'L' shape in the bottom right corner.
        Row 0: . . X
        Row 1: . . X
        Row 2: X X X
        This looks like a corner shape. Let's call it Shape G.

*   **Example 4:**
    *   Input Color: Blue (B)
    *   Input Grid: 5x5 with scattered B's.
    *   Output Grid:
        ```
        . X .
        X X X
        . X .
        ```
    *   Pattern: Same as Example 1. Confirms Blue -> Plus Sign.

*   **Example 5:**
    *   Input Color: Green (G)
    *   Input Grid: 5x5 with scattered G's.
    *   Output Grid:
        ```
        . . X
        . . X
        X X X
        ```
    *   Pattern: Same as Example 3. Confirms Green -> Bottom-Right Corner.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input:** A 5x5 grid containing a specific color (B, R, G) scattered among black (.) cells.
    *   **Output:** A 3x3 grid containing grey (X) and black (.) cells.
    *   **Mapping:** The specific color present in the input determines the specific 3x3 pattern in the output. The spatial arrangement of the colored cells in the 5x5 input seems irrelevant to the *shape* of the output, only the *color* matters. The output is a "signature" for that color.

*   **AFFORDANCES:**
    *   The colored cells identify the "Front Type".
    *   The output grid is a fixed template associated with that Front Type.
    *   The output grid is always 3x3.
    *   The output grid uses Grey (X) for the active parts of the signature and Black (.) for the inactive parts.

*   **TRANSFORMATION RULE:**
    1.  Scan the 5x5 input grid to identify the non-black color present (B, R, G, etc.).
    2.  Retrieve the pre-defined 3x3 pattern associated with that color based on the training examples.
    3.  Construct the 3x3 output grid using that pattern.

    *   **Blue (B) Pattern:**
        ```
        . X .
        X X X
        . X .
        ```
    *   **Red (R) Pattern:**
        ```
        X X X
        . X .
        . X .
        ```
    *   **Green (G) Pattern:**
        ```
        . . X
        . . X
        X X X
        ```

**4. Apply to Test Input:**

*   **Test Input:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Identify Color:** The non-black color is Green (G).
*   **Retrieve Pattern:** Look up the pattern for Green (G) from the training examples (Example 3 and Example 5).
    *   Pattern:
        ```
        . . X
        . . X
        X X X
        ```
*   **Construct Output:**
    Row 1: . . X
    Row 2: . . X
    Row 3: X X X

**5. Verification:**
*   Does the input contain only G and .? Yes.
*   Is the output 3x3? Yes.
*   Is the output using X and .? Yes.
*   Does the pattern match the Green examples?
    *   Example 3 Output:
        . . X
        . . X
        X X X
    *   Example 5 Output:
        . . X
        . . X
        X X X
    *   Test Input Color: G.
    *   Match confirmed.

**6. Formatting:**
*   The user wants the reasoning first.
*   Then the final output in a specific block format.
*   Characters separated by spaces.

**Step-by-step reasoning for the final response:**
1.  **Identify the Input Color:** I examine the test input grid. The cells contain either black (.) or green (G). Therefore, the "front" color is Green.
2.  **Recall/Map Color to Pattern:** I look at the training examples to see what output pattern corresponds to Green.
    *   Example 3 has Green input and produces a specific 3x3 pattern.
    *   Example 5 has Green input and produces the same 3x3 pattern.
    *   The pattern is: Top-right corne

... [2574 chars truncated]
alt-6 architecture qwen3.5-122b: k=3
"Bricks tumble from the demolition in random heaps, but the mason who sees their glaze knows exactly which keystone to carve — each clay has one destiny, and the rubble's arrangement is irrelevant to the arch it will become."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (13275 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** "Rubble of one type of glazed brick scattered across a dark foundation."
    *   "Dark foundation" likely refers to the black (`.`) background.
    *   "Rubble of one type of glazed brick" refers to the colored pixels (B, R, G, etc.) scattered in the input grid.
    *   Input size is 5x5.
*   **Output:** "Identify the glaze color and carve the keystone pattern that clay was always meant to form."
    *   "Identify the glaze color": This implies the specific color of the scattered bricks matters.
    *   "Carve the keystone pattern": This implies a specific shape or pattern is formed in the output.
    *   "in grey": The output grid uses `X` (grey) for the pattern and `.` (black) for the background.
    *   Output size is 3x3.
*   **Key Insight:** The input is a 5x5 grid with a specific color scattered on a black background. The output is a 3x3 grid with a specific pattern of `X`s on a black background. The pattern depends on the input color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Color: Blue (`B`).
    *   Input Grid (5x5):
        ```
        B . B . .
        B . . B B
        B B . B .
        . B . B .
        B . . . B
        ```
    *   Output Grid (3x3):
        ```
        . X .
        X X X
        . X .
        ```
    *   Pattern: A plus sign or cross shape centered in the 3x3 grid.
    *   Let's check the position of the `B`s.
        *   (0,0), (0,2)
        *   (1,0), (1,3), (1,4)
        *   (2,0), (2,1), (2,3)
        *   (3,1), (3,3)
        *   (4,0), (4,4)
    *   This looks like a random scattering. The metaphor says "Rubble".
    *   The output is a specific shape associated with the color Blue.
    *   Shape: `+` (Cross).

*   **Example 2:**
    *   Input Color: Red (`R`).
    *   Input Grid (5x5):
        ```
        R . R . R
        R . . . R
        R R . . .
        R . . R R
        R R R . R
        ```
    *   Output Grid (3x3):
        ```
        X X X
        . X .
        . X .
        ```
    *   Pattern: An inverted 'T' shape? Or a '7' shape?
        *   Row 0: X X X
        *   Row 1: . X .
        *   Row 2: . X .
        *   This looks like a 'T' shape (top bar and vertical stem).
    *   Shape: `T`.

*   **Example 3:**
    *   Input Color: Green (`G`).
    *   Input Grid (5x5):
        ```
        . G . G .
        G G . . .
        . G . . .
        . . G . .
        G G G . .
        ```
    *   Output Grid (3x3):
        ```
        . . X
        . . X
        X X X
        ```
    *   Pattern: An 'L' shape (rotated).
        *   Row 0: . . X
        *   Row 1: . . X
        *   Row 2: X X X
        *   This is an 'L' shape in the bottom right corner.
    *   Shape: `L`.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input:** A 5x5 grid containing a specific color (the "glaze") and black (`.`). The arrangement of the colored pixels seems random or "rubble-like".
    *   **Output:** A 3x3 grid containing grey (`X`) and black (`.`).
    *   **Role of Color:** The specific color present in the input determines the shape of the pattern in the output.
    *   **Role of Input Pattern:** The specific arrangement of the "rubble" in the 5x5 grid seems irrelevant to the *shape* of the output, other than identifying the color. Wait, let me double-check if the input pattern maps to the output pattern directly.
        *   Example 1 (Blue): Input has scattered Bs. Output is a Cross.
        *   Example 2 (Red): Input has scattered Rs. Output is a T.
        *   Example 3 (Green): Input has scattered Gs. Output is an L.
    *   Is there a mapping between Color and Shape?
        *   Blue -> Cross (+)
        *   Red -> T
        *   Green -> L
    *   Is there a mapping based on the *count* of pixels?
        *   Ex 1 (Blue): Count = 2+3+3+2+2 = 12 pixels.
        *   Ex 2 (Red): Count = 3+2+2+3+4 = 14 pixels.
        *   Ex 3 (Green): Count = 2+2+1+1+3 = 9 pixels.
        *   Output pixels:
            *   Ex 1: 5 pixels.
            *   Ex 2: 5 pixels.
            *   Ex 3: 5 pixels.
        *   The number of output pixels is constant (5). The number of input pixels varies. So it's not a direct count mapping.
    *   Is there a mapping based on the *positions*?
        *   Maybe the input grid represents a larger canvas, and the output is a zoomed-in or extracted feature?
        *   Or maybe the input grid *is* the pattern, but obscured?
        *   Let's look at the "rubble" again.
        *   Ex 1 (Blue):
            B . B . .
            B . . B B
            B B . B .
            . B . B .
            B . . . B
            Does this look like a Cross?
            Center is (2,2). It's `.`.
            (1,2) is `.`. (3,2) is `.`. (2,1) is `B`. (2,3) is `B`.
            It doesn't look like a clear cross.
        *   Ex 2 (Red):
            R . R . 

... [8356 chars truncated]
alt-7 warfare qwen3.5-122b: k=3
"Scouts report skirmish positions scattered across the map, but the general cares only about the color of the enemy banner — each kingdom deploys to a single siege formation, no matter how their scouts were arranged."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (9868 chars)
The user wants me to solve a grid transformation puzzle based on provided examples and a metaphorical description.

**1. Analyze the Metaphorical Description:**
*   **Input:** 5x5 war map with one colored force (Enemy positions).
*   **Output:** 3x3 siege formation in grey (X).
*   **Key Concept:** "Identify the kingdom by banner color and deploy its predetermined siege formation — a compact tactical shape."
*   **Implication:** The color of the input grid determines the shape of the output grid. The output is always 3x3 and uses 'X' (grey) for the shape and '.' (black) for empty space.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input Color:** Blue (B).
    *   **Input Grid:** 5x5 with B's scattered.
    *   **Output Grid:** 3x3.
    *   **Output Pattern:**
        ```
        . X .
        X X X
        . X .
        ```
        This looks like a plus sign or a cross.
    *   **Observation:** The input color is Blue. The output shape is a cross.

*   **Example 2:**
    *   **Input Color:** Red (R).
    *   **Input Grid:** 5x5 with R's scattered.
    *   **Output Grid:** 3x3.
    *   **Output Pattern:**
        ```
        X X X
        . X .
        . X .
        ```
        This looks like an inverted 'T' or a '7' shape.
    *   **Observation:** The input color is Red. The output shape is a T-shape (top row full, middle column full).

*   **Example 3:**
    *   **Input Color:** Green (G).
    *   **Input Grid:** 5x5 with G's scattered.
    *   **Output Grid:** 3x3.
    *   **Output Pattern:**
        ```
        . . X
        . . X
        X X X
        ```
        This looks like an 'L' shape (bottom row full, right column full).
    *   **Observation:** The input color is Green. The output shape is an L-shape.

**3. Conceptual Digestion:**

*   **CAST:**
    *   **Input Grid:** A 5x5 canvas containing a specific color (the "Kingdom Banner"). The arrangement of the colored pixels in the input seems irrelevant to the specific shape, other than identifying the color. The prompt says "scattered across a dark war map", implying the pattern in the input might just be noise or a representation of the "force" presence, but the *color* is the key identifier.
    *   **Output Grid:** A 3x3 canvas.
    *   **Elements:** Colored pixels (B, R, G) in input. Grey pixels (X) and Black pixels (.) in output.

*   **AFFORDANCES:**
    *   The input color maps to a specific 3x3 template.
    *   The output is always 3x3.
    *   The output uses 'X' for the active part of the formation and '.' for the background.

*   **TRANSFORMATION RULE:**
    *   Step 1: Identify the dominant non-black color in the 5x5 input grid.
    *   Step 2: Map this color to a specific 3x3 pattern based on the training examples.
        *   Blue (B) -> Cross (+)
        *   Red (R) -> Inverted T (Top bar + Middle vertical)
        *   Green (G) -> L-shape (Bottom bar + Right vertical)
    *   Step 3: Generate the 3x3 grid using 'X' for the pattern and '.' for empty space.

**4. Analyze the Test Input:**

*   **Input Grid:**
    ```
    . G . G G
    . . G . .
    G . . . .
    . . G . G
    . . . . G
    ```
*   **Identify Color:** The non-black color present is Green (G).
*   **Retrieve Pattern:** Based on Example 3, Green (G) corresponds to the L-shape pattern.
*   **Pattern Details (from Example 3):**
    ```
    . . X
    . . X
    X X X
    ```
    (Top-right 2 cells and Bottom row).

**5. Verification:**
*   Does the input pattern matter?
    *   Example 1 Input B pattern:
        B . B . .
        B . . B B
        B B . B .
        . B . B .
        B . . . B
    *   Example 2 Input R pattern:
        R . R . R
        R . . . R
        R R . . .
        R . . R R
        R R R . R
    *   Example 3 Input G pattern:
        . G . G .
        G G . . .
        . G . . .
        . . G . .
        G G G . .
    *   Test Input G pattern:
        . G . G G
        . . G . .
        G . . . .
        . . G . G
        . . . . G
    *   The input patterns are all different. The output depends solely on the color. The prompt says "Identify the kingdom by banner color". This confirms color is the key.
    *   The prompt says "deploy its predetermined siege formation". This implies a fixed mapping from Color -> Shape.
    *   Since the Test Input uses Green (G), I must use the Green shape from Example 3.

**6. Constructing the Output:**
*   Color: Green (G)
*   Shape: L-shape (Bottom row full, Right column full).
*   Grid Size: 3x3.
*   Representation:
    Row 1: . . X
    Row 2: . . X
    Row 3: X X X

**7. Final Check:**
*   Input: 5x5 with Green.
*   Rule: Green -> L-shape (Example 3).
*   Output: 3x3 grid with X's forming the L-shape.
*   Format: Space separated characters, one row per line.

Let's double check the Example 3 output again.
Example 3 Output:
. . X
. . X
X X X

Yes, that matches my derivation.

Wait, let's look closer at the shapes.
Blue (Ex 1):
. X .
X X X
. X .
(Cross)

Red (Ex 2):
X

... [4904 chars truncated]
alt-8 theater qwen3.5-122b: k=4
"The actors mill about backstage in disarray, but when the curtain rises, each troupe — distinguishable only by the color of their masks — strikes a single iconic tableau that has been theirs since antiquity."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (13533 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Performers in identical colored masks milling about a dark backstage."
    *   "Dark backstage" likely refers to the background color, which is black (`.`).
    *   "Performers in identical colored masks" refers to the non-black pixels in the input grid. In the examples, these are single colors (B, R, G).
    *   "Milling about" suggests they are scattered.
*   **Action:** "Note the mask color and reveal the troupe's eternal tableau — one frozen pose per company, regardless of where they stood in the wings."
    *   "Note the mask color": The input contains a specific color (e.g., Blue, Red, Green).
    *   "Reveal the troupe's eternal tableau": The output is a specific pattern.
    *   "One frozen pose per company": This implies the output pattern depends on the input color or the arrangement of that color.
    *   "Regardless of where they stood": The specific positions in the 5x5 input might not matter directly, or they form a shape that is abstracted.
*   **Grid Details:**
    *   Input: 5x5 grid.
    *   Output: 3x3 grid.
    *   Output background: Grey (`X`). Wait, the description says "Output: 3x3 tableau in grey". Let's check the examples.
    *   Example 1 Output: `.` and `X`. The background seems to be `.` (black) and the shape is `X` (grey). Or vice versa. Let's look closer.
    *   Example 1 Input: Blue (`B`). Output: `.` and `X`.
    *   Example 2 Input: Red (`R`). Output: `X` and `.`.
    *   Example 3 Input: Green (`G`). Output: `.` and `X`.
    *   Example 4 Input: Blue (`B`). Output: `.` and `X`.
    *   Wait, the description says "Output: 3x3 tableau in grey". In the examples, the output grids contain `.` and `X`.
    *   Let's check the color key: `X=grey`, `.=black`.
    *   In Example 1, the output has `X` forming a cross shape on a `.` background.
    *   In Example 2, the output has `X` forming a 'T' shape (inverted?) on a `.` background.
    *   In Example 3, the output has `X` forming an 'L' shape on a `.` background.
    *   In Example 4, the output has `X` forming a cross shape on a `.` background.
    *   So the "tableau" is drawn using `X` (grey) on a `.` (black) background. The description "tableau in grey" likely means the active pixels are grey.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Color: Blue (`B`).
    *   Input Grid (5x5):
        ```
        B . B . .
        B . . B B
        B B . B .
        . B . B .
        B . . . B
        ```
    *   Output Grid (3x3):
        ```
        . X .
        X X X
        . X .
        ```
    *   Observation: The output is a "plus" sign or cross shape made of `X`.
    *   Input Pattern Analysis: Let's look at the distribution of `B`.
        *   Row 0: B at 0, 2
        *   Row 1: B at 0, 3, 4
        *   Row 2: B at 0, 1, 3
        *   Row 3: B at 1, 3
        *   Row 4: B at 0, 4
        *   This looks like noise or a specific shape. Let's try to map the 5x5 to 3x3.
        *   Maybe it's about counting? Or specific sub-grids?
        *   Let's look at the center of the 5x5 grid. Center is (2,2). It is `.`.
        *   Let's look at the shape formed by the colored pixels.
        *   Is it a representation of the letter 'B'? No.
        *   Is it related to the number of pixels? Count of B = 2+3+3+2+2 = 12.
        *   Is it related to the bounding box?
        *   Let's look at the Output Shape: A cross.
        *   Is there a connection between the input color and the output shape?
        *   Example 1 (Blue) -> Cross.
        *   Example 4 (Blue) -> Cross.
        *   This suggests the output shape is determined by the *color* of the input pixels.
        *   Let's verify this hypothesis.
        *   Example 2 (Red) -> Shape:
            ```
            X X X
            . X .
            . X .
            ```
            This looks like an inverted 'T' or a '7' shape.
        *   Example 3 (Green) -> Shape:
            ```
            . . X
            . . X
            X X X
            ```
            This looks like an 'L' shape (rotated).

    *   **Hypothesis:** The transformation maps the input color to a specific 3x3 pattern.
        *   Blue (`B`) -> Cross (`+`)
        *   Red (`R`) -> Inverted T (`T` upside down)
        *   Green (`G`) -> L-shape (bottom-right corner filled)

    *   Let's check the Test Input.
    *   Test Input Color: Green (`G`).
    *   If the hypothesis holds, the output should be the Green pattern.
    *   Green Pattern from Example 3:
        ```
        . . X
        . . X
        X X X
        ```
    *   Let's double check if the input arrangement matters.
    *   In Example 1 (Blue), the B's are scattered.
    *   In Example 4 (Blue), the B's are:
        ```
        . . . . .
        . . B B B
        . B . B B
        . B . B .
        . . . . B
     

... [8584 chars truncated]
alt-9 gardening qwen3.5-122b: k=3
"Seeds blow in the wind and land wherever they please, but when the gardener finds them, she knows by their hue which trellis shape to build — every flower climbs its own geometry, indifferent to where it was sown."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (13508 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** 5x5 grid ("soil") with scattered "seeds" of one color.
*   **Output:** 3x3 grid ("trellis") in grey (X).
*   **Task:** Identify the flower by seed color and construct its trellis. The trellis is a "compact frame that each species requires, always the same shape."
*   **Key Insight:** The input grid contains a specific color (the "seed"). The output grid is always 3x3 and uses 'X' (grey) to form a specific pattern. The pattern depends on the seed color.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input Color:** Blue (B).
    *   **Input Grid:** 5x5 with scattered B's.
    *   **Output Grid:** 3x3.
        ```
        . X .
        X X X
        . X .
        ```
    *   **Pattern:** A plus sign or cross shape. Center is X, top, bottom, left, right are X. Corners are dots.
    *   **Observation:** The input grid has B's. The output is a specific shape made of X's.

*   **Example 2:**
    *   **Input Color:** Red (R).
    *   **Input Grid:** 5x5 with scattered R's.
    *   **Output Grid:** 3x3.
        ```
        X X X
        . X .
        . X .
        ```
    *   **Pattern:** An 'L' shape or a corner shape? Top row is all X. Middle and bottom rows have X in the middle column. It looks like a 'T' rotated or an inverted 'L' with a stem. Let's look closer.
        Row 0: X X X
        Row 1: . X .
        Row 2: . X .
        This looks like a 'T' shape. Top bar, vertical stem down the middle.

*   **Example 3:**
    *   **Input Color:** Green (G).
    *   **Input Grid:** 5x5 with scattered G's.
    *   **Output Grid:** 3x3.
        ```
        . . X
        . . X
        X X X
        ```
    *   **Pattern:** An 'L' shape. Bottom row is all X. Right column is all X.
    *   **Observation:** The input grid has G's. The output is a specific shape made of X's.

**3. Synthesize the Transformation Rule:**
*   The input grid size is 5x5. The output grid size is 3x3.
*   The input contains a specific color (B, R, G).
*   The output is a 3x3 pattern of 'X' (grey) and '.' (black).
*   The pattern is determined by the input color.
    *   Blue (B) -> Plus sign (+)
    *   Red (R) -> T-shape (inverted T)
    *   Green (G) -> L-shape (bottom-right corner)
*   Wait, is the pattern determined *solely* by the color, or is there information in the input grid that dictates the pattern?
    *   The prompt says: "Identify the flower by seed color and construct its trellis — a compact frame that each species requires, always the same shape."
    *   This implies the shape is fixed per species (color).
    *   However, I need to check if the input grid actually contains the shape encoded in the positions of the seeds, or if the color just maps to a pre-defined shape.
    *   Let's check the positions of the seeds in the input grids.
    *   **Example 1 (Blue):**
        B . B . .
        B . . B B
        B B . B .
        . B . B .
        B . . . B
        There are many B's. It doesn't look like a clear 3x3 pattern embedded in the 5x5. It looks like noise or just "scattered seeds".
    *   **Example 2 (Red):**
        R . R . R
        R . . . R
        R R . . .
        R . . R R
        R R R . R
        Again, scattered.
    *   **Example 3 (Green):**
        . G . G .
        G G . . .
        . G . . .
        . . G . .
        G G G . .
        Scattered.

    *   **Hypothesis:** The transformation is a lookup table based on the dominant color present in the input.
        *   Blue -> Plus
        *   Red -> T
        *   Green -> L (bottom-right)
    *   **Test Input:**
        . G . G G
        . . G . .
        G . . . .
        . . G . G
        . . . . G
        The dominant color is Green (G).
    *   **Prediction:** Since the input color is Green, the output should match the Green pattern from Example 3.
    *   **Green Pattern:**
        . . X
        . . X
        X X X

    *   **Wait, let me double check the "Metaphorical Description" again.**
        "Identify the flower by seed color and construct its trellis — a compact frame that each species requires, always the same shape."
        This strongly supports the "Color -> Fixed Shape" hypothesis.
        "Input: 5x5 soil with one seed color. Output: 3x3 trellis pattern in grey, fixed per species."
        This confirms the output is fixed per species (color).

    *   **Let's verify the Test Input Color.**
        Row 0: . G . G G (3 Gs)
        Row 1: . . G . . (1 G)
        Row 2: G . . . . (1 G)
        Row 3: . . G . G (2 Gs)
        Row 4: . . . . G (1 G)
        Total Gs: 8.
        No other colors present.
        So the species is Green.

    *   **Retrieve Green Pattern from Example 3:**
        Input: Green (G)
        Output:
        . . X
        . . X
        X X X

    *   **Wait, is there any other possibility?**

... [8568 chars truncated]

Task 893: e50d258f

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original The hottest ember escapes the dying campfires MARC valid 2
alt-1 biology Among the petri dishes, the colony with the most aggressive infection is isolate ... [11 chars truncated] MARC valid 1
alt-10 astronomy The astronomer scans each nebula in the field of view and trains the telescope o ... [42 chars truncated] fail
alt-11 ocean/sailing The harbor pilot eyes each vessel at anchor and boards the one flying the most r ... [17 chars truncated] fail
alt-12 electronics The technician tests each circuit board on the bench and pulls the one with the ... [27 chars truncated] MARC valid 1
alt-13 mythology The oracle peers into each sacred pool and chooses the vision stained deepest wi ... [17 chars truncated] MARC valid 1
alt-14 dance The choreographer watches each troupe rehearse and selects the company whose dan ... [33 chars truncated] MARC valid 1
alt-15 geology The geologist cores each outcrop and keeps only the sample richest in ruby depos ... [3 chars truncated] fail
alt-2 cooking The chef tastes each simmering pot and serves only the spiciest one fig alone solves
alt-3 music The conductor auditions each ensemble and advances the one whose brass section r ... [12 chars truncated] fig alone solves
alt-4 sports The scout watches every scrimmage and drafts the squad that drew the most blood fail
alt-5 weather The storm chaser surveys the radar mosaic and drives toward the cell crackling w ... [22 chars truncated] fail
alt-6 architecture The demolition crew inspects every condemned building and topples the one most r ... [23 chars truncated] fail
alt-7 warfare The general studies the battlefield map and commits reserves to the sector bleed ... [12 chars truncated] fig alone solves
alt-8 theater The critic watches each act through opera glasses and gives the standing ovation ... [36 chars truncated] fail
alt-9 gardening The gardener walks between raised beds and harvests only from the one bursting w ... [26 chars truncated] fail
original qwen3.5-122b: k=2
"The hottest ember escapes the dying campfires"
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (9469 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Scattered across the darkness like campfires in a valley".
*   **Elements:**
    *   "Darkness" = Black (`.`).
    *   "Campfires" = Rectangular patches of Azure (`A`) coals.
    *   "Sparks of red flame" = Red (`R`) embers.
    *   "Blue smoke" = Blue (`B`) cinders.
    *   "Valley floor" = Black background.
*   **Action:** "Count the red-hot embers in each hearth — they are the true measure of its heat."
*   **Selection:** "The fire burning hottest, the one with the most living flame, refuses to die. Rescue it from the night and carry it forward whole."
*   **Output:** "Lift the hottest fire out intact — every coal, ember, and cinder in its exact arrangement — leaving the cold night behind."

**Interpretation:**
1.  Identify distinct rectangular regions (campfires) composed primarily of Azure (`A`), containing Red (`R`) and Blue (`B`) pixels, surrounded by Black (`.`).
2.  Count the number of Red (`R`) pixels in each region.
3.  Select the region with the highest count of Red (`R`) pixels.
4.  Extract that specific rectangular region as the output grid.

**2. Analyze the Training Examples:**

**Example 1:**
Input Grid (10x10):
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
Let's identify the "campfires". They seem to be connected components of non-black pixels, or specifically rectangular blocks.
Looking at the input, there are two distinct clusters separated by columns of dots.
Cluster 1 (Left): Columns 0-3.
Cluster 2 (Right): Columns 5-9.

Let's look at Cluster 1 (Left):
Rows 0-9, Cols 0-3.
It looks like a 10x4 block, but let's check the content.
Row 0: B B B A
Row 1: B A B B
Row 2: A R A B
Row 3: B B B A
Row 4: A B A A
Row 5: . . . . (Wait, row 5 starts with dots)
Row 6: . . . .
Row 7: . A R R
Row 8: . R R B
Row 9: . R B A

Actually, looking closely at the structure:
There is a block on the left (cols 0-3) and a block on the right (cols 5-9).
Left Block:
Rows 0-4 seem to form a shape. Rows 7-9 form another shape?
Let's check the connectivity.
Row 0: B B B A
Row 1: B A B B
Row 2: A R A B
Row 3: B B B A
Row 4: A B A A
Row 5: . . . .
Row 6: . . . .
Row 7: . A R R
Row 8: . R R B
Row 9: . R B A

Wait, the description says "compact rectangular bed".
Let's look at the Right Block (Cols 5-9):
Row 0: . . . . .
Row 1: . B A A B A
Row 2: . A B A R A
Row 3: . A A A A B
Row 4: . A B R A R
Row 5: . A A A B A
Row 6: . B B A B A
Row 7: . A B B A R
Row 8: . . . . .
Row 9: . . . . .

This looks like a rectangular block from Row 1 to Row 7, Cols 5 to 9.
Let's count Red (`R`) in the Right Block:
Row 1: 0
Row 2: 1 (at col 8)
Row 3: 0
Row 4: 2 (at col 7, 9)
Row 5: 0
Row 6: 0
Row 7: 1 (at col 9)
Total R in Right Block = 1 + 2 + 1 = 4.

Now let's look at the Left Block. It seems split into two parts vertically?
Part 1: Rows 0-4, Cols 0-3.
R count:
Row 0: 0
Row 1: 0
Row 2: 1 (at col 1)
Row 3: 0
Row 4: 0
Total = 1.

Part 2: Rows 7-9, Cols 0-3 (actually cols 1-3 based on dots).
Row 7: . A R R (R count 2)
Row 8: . R R B (R count 2)
Row 9: . R B A (R count 1)
Total = 5.

Wait, the Output is:
```
A R R
R R B
R B A
```
This matches the bottom-left cluster (Rows 7-9, Cols 1-3).
Let's check the R count for this specific cluster.
Row 7: A R R -> 2 Reds.
Row 8: R R B -> 2 Reds.
Row 9: R B A -> 1 Red.
Total Reds = 5.

Let's check the Right Cluster again.
Rows 1-7, Cols 5-9.
R count:
Row 1: B A A B A (0)
Row 2: A B A R A (1)
Row 3: A A A A B (0)
Row 4: A B R A R (2)
Row 5: A A A B A (0)
Row 6: B B A B A (0)
Row 7: A B B A R (1)
Total Reds = 4.

Let's check the Top-Left Cluster.
Rows 0-4, Cols 0-3.
R count:
Row 0: B B B A (0)
Row 1: B A B B (0)
Row 2: A R A B (1)
Row 3: B B B A (0)
Row 4: A B A A (0)
Total Reds = 1.

So we have three "campfires":
1. Top-Left: 1 Red.
2. Right: 4 Reds.
3. Bottom-Left: 5 Reds.

The rule says: "The fire burning hottest, the one with the most living flame [Red], refuses to die. Rescue it...".
Max Red count is 5 (Bottom-Left).
The output corresponds exactly to the Bottom-Left cluster.
The cluster is defined by the bounding box of the connected non-black pixels in that region.
Rows 7-9, Cols 1-3.
Content:
A R R
R R B
R B A
This matches the output exactly.

**Example 2:**
Input Grid (10x10):
```
. . . . . . A A A A
. A A A A . A R R A
. A B A A . A A A A
. A A R A . A R B A
. A A A A . A A A A
. . . . . . . . . .
. . . A A A A A A .
. . . A A A R A A .
. . . A R A B A A .
. . . A B A A A A .
```
Let's identify clusters.
Cluster 1 (Top-Right): Rows 0-4, Cols 6-9.
Content:
A A A A
A R R A
A A A A
A R B A
A A A A
Red Count:
Row 0: 0
Row 1: 2
Row 2: 0
Row 3: 1
Row 4: 0
Total = 3.

Cluster 2 (Bottom-Middle): Rows 6-9, Cols 3-8.
Content:
A A A A A A
A A A R A 

... [4502 chars truncated]
alt-1 biology qwen3.5-122b: k=1
"Among the petri dishes, the colony with the most aggressive infection is isolated for study"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10561 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Several tissue samples sit in separate culture wells, each a pale azure matrix hosting scattered red pathogens and blue nutrients".
*   **Action:** "The pathologist selects the specimen showing the most virulent red spread and transfers it to the slide".
*   **Grid Details:**
    *   "Azure cell walls form each sample's body" -> 'A' (Azure) represents the structure of the samples/wells.
    *   "red marks are infection sites" -> 'R' (Red) represents the pathogens.
    *   "blue marks are benign inclusions" -> 'B' (Blue) represents nutrients/inclusions.
    *   "black is the empty tray between wells" -> '.' (Black) represents the background/separation.
*   **Goal:** Select the "specimen showing the most virulent red spread" and "transfer it to the slide". This implies extracting a subgrid corresponding to one of the "wells" or "samples".
*   **Interpretation:** The input grid contains multiple distinct regions (wells) separated by black space ('.'). Each region is defined by Azure ('A') boundaries or content. I need to identify these regions, count the 'R's (red pathogens) in each, find the one with the most 'R's, and output that specific region.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
Output:
```
A R R
R R B
R B A
```

*   **Observation:** The input grid has black ('.') separating distinct areas.
    *   Top-left area:
        ```
        B B B A
        B A B B
        A R A B
        B B B A
        A B A A
        ```
        Wait, looking at the layout, there are vertical and horizontal black lines.
        Let's look for connected components of non-black cells.
        Actually, looking at the input, there seem to be two main blocks separated by a column of dots and rows of dots.
        Let's trace the non-black regions.
        Region 1 (Top Left):
        Rows 0-4, Cols 0-3.
        ```
        B B B A
        B A B B
        A R A B
        B B B A
        A B A A
        ```
        Count of 'R': 1 (at 2,1).
        
        Region 2 (Top Right):
        Rows 0-4, Cols 5-9.
        ```
        . . . . .
        B A A B A
        A B A R A
        A A A A B
        A B R A R
        ```
        Wait, Row 0 is all dots in cols 5-9.
        Let's look at the structure again.
        Row 0: `B B B A . . . . . .` -> Left block starts. Right block starts at col 5? No, col 5 is dot.
        Row 1: `B A B B . B A A B A` -> Left block cols 0-3. Right block cols 5-9.
        Row 2: `A R A B . A B A R A` -> Left block cols 0-3. Right block cols 5-9.
        Row 3: `B B B A . A A A A B` -> Left block cols 0-3. Right block cols 5-9.
        Row 4: `A B A A . A B R A R` -> Left block cols 0-3. Right block cols 5-9.
        Row 5: `. . . . . A A A B A` -> Left block ends. Right block continues.
        Row 6: `. . . . . B B A B A` -> Right block continues.
        Row 7: `. A R R . A B B A R` -> Left block? No, col 1-3 are `A R R`. Col 5-9 are `A B B A R`.
        Row 8: `. R R B . . . . . .` -> Left block `R R B`. Right block empty.
        Row 9: `. R B A . . . . . .` -> Left block `R B A`. Right block empty.

        It looks like there are two distinct "wells" or "samples".
        Sample 1 (Left):
        Rows 0-4, Cols 0-3.
        Rows 7-9, Cols 1-3.
        Wait, Row 5 and 6 are empty on the left. So the left sample is split? Or is it one large shape?
        Let's look at the Output.
        Output:
        ```
        A R R
        R R B
        R B A
        ```
        This matches the bottom-left section of the input (Rows 7-9, Cols 1-3).
        Let's check the content of that section:
        Row 7: `. A R R .` -> Cols 1-3 are `A R R`.
        Row 8: `. R R B .` -> Cols 1-3 are `R R B`.
        Row 9: `. R B A .` -> Cols 1-3 are `R B A`.
        This matches the output exactly.
        
        Why was this selected?
        Let's count 'R's in the potential candidates.
        Candidate 1 (Top Left):
        ```
        B B B A
        B A B B
        A R A B
        B B B A
        A B A A
        ```
        'R' count: 1.
        
        Candidate 2 (Top Right):
        ```
        B A A B A
        A B A R A
        A A A A B
        A B R A R
        A A A B A
        B B A B A
        A B B A R
        ```
        (Rows 1-7, Cols 5-9).
        'R' count:
        Row 2: 1
        Row 4: 2
        Row 7: 1
        Total: 4.
        
        Candidate 3 (Bottom Left):
        ```
        A R R
        R R B
        R B A
        ```
        (Rows 7-9, Cols 1-3).
        'R' count:
        Row 7: 2
        Row 8: 2
        Row 9: 1
        Tot

... [5639 chars truncated]
alt-10 astronomy qwen3.5-122b: fail
"The astronomer scans each nebula in the field of view and trains the telescope on the one pulsing with the most red giants"
Fail (best cell_acc=0.07 at k=1)
Best Attempt
vs
Expected
Reasoning (9279 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A dark sky holds several distinct nebulae..."
*   **Elements:**
    *   "Azure gas" -> Color 'A' (Azure).
    *   "Red giant stars" -> Color 'R' (Red).
    *   "Blue dwarf stars" -> Color 'B' (Blue).
    *   "Black void" -> Color '.' (Black).
*   **Structure:** "distinct nebulae" implies connected components of non-black pixels.
*   **Task:** "Count the red giants in each nebula and focus the observatory's full aperture on the most evolved cluster".
    *   "Count the red giants": Count 'R's in each connected component (nebula).
    *   "Most evolved cluster": The nebula with the highest count of 'R's.
    *   "Focus the observatory's full aperture on": Extract or highlight this specific nebula. Usually, in these types of puzzles, this means outputting the subgrid containing that specific object, or the object itself isolated. Given the output size in the example, it looks like extracting the bounding box of the selected nebula.

**2. Analyze the Training Example:**
*   **Input Grid:**
    ```
    B B B A . . . . . .
    B A B B . B A A B A
    A R A B . A B A R A
    B B B A . A A A A B
    A B A A . A B R A R
    . . . . . A A A B A
    . . . . . B B A B A
    . A R R . A B B A R
    . R R B . . . . . .
    . R B A . . . . . .
    ```
*   **Output Grid:**
    ```
    A R R
    R R B
    R B A
    ```
*   **Observation:**
    *   The input has black '.' separating regions.
    *   Let's identify the connected components (nebulae) of non-black pixels.
    *   **Nebula 1 (Top Left):**
        Rows 0-4, Cols 0-3 roughly.
        Let's trace connectivity (4-way or 8-way? Usually 4-way in these grid puzzles unless specified, but let's check).
        (0,0)B, (0,1)B, (0,2)B, (0,3)A
        (1,0)B, (1,1)A, (1,2)B, (1,3)B
        (2,0)A, (2,1)R, (2,2)A, (2,3)B
        (3,0)B, (3,1)B, (3,2)B, (3,3)A
        (4,0)A, (4,1)B, (4,2)A, (4,3)A
        This looks like one big block on the left.
        Let's count 'R's in this block.
        (2,1) is R.
        Are there others?
        (4,0)A, (4,1)B, (4,2)A, (4,3)A.
        Wait, let's look at the grid again.
        Row 0: B B B A
        Row 1: B A B B
        Row 2: A R A B
        Row 3: B B B A
        Row 4: A B A A
        Row 5: . . . .
        So the top-left block is rows 0-4, cols 0-3.
        'R' count: Just one at (2,1).
    *   **Nebula 2 (Top Right):**
        Row 1: (1,5)B, (1,6)A, (1,7)A, (1,8)B, (1,9)A
        Row 2: (2,5)A, (2,6)B, (2,7)A, (2,8)R, (2,9)A
        Row 3: (3,5)A, (3,6)A, (3,7)A, (3,8)A, (3,9)B
        Row 4: (4,5)A, (4,6)B, (4,7)R, (4,8)A, (4,9)R
        Row 5: (5,5)A, (5,6)A, (5,7)A, (5,8)B, (5,9)A
        Row 6: (6,5)B, (6,6)B, (6,7)A, (6,8)B, (6,9)A
        Row 7: (7,5)A, (7,6)B, (7,7)B, (7,8)A, (7,9)R
        This seems to be a large connected component on the right side.
        Let's count 'R's here.
        (2,8)R
        (4,7)R
        (4,9)R
        (7,9)R
        Total 'R's = 4.
    *   **Nebula 3 (Bottom Left):**
        Row 7: (7,1)A, (7,2)R, (7,3)R
        Row 8: (8,1)R, (8,2)R, (8,3)B
        Row 9: (9,1)R, (9,2)B, (9,3)A
        This is a block at the bottom left.
        Let's count 'R's here.
        (7,2)R, (7,3)R
        (8,1)R, (8,2)R
        (9,1)R
        Total 'R's = 5.
    *   **Comparison:**
        Nebula 1: 1 Red.
        Nebula 2: 4 Reds.
        Nebula 3: 5 Reds.
    *   **Selection:** "Most evolved cluster" = Nebula with most Red stars = Nebula 3 (5 Reds).
    *   **Output:**
        ```
        A R R
        R R B
        R B A
        ```
        Let's check the content of Nebula 3 in the input.
        Row 7: . A R R . ... -> Cols 1-3 are A R R
        Row 8: . R R B . ... -> Cols 1-3 are R R B
        Row 9: . R B A . ... -> Cols 1-3 are R B A
        This matches the output exactly.
    *   **Conclusion:** The task is to identify connected components of non-black pixels, count the number of 'R' pixels in each component, select the component with the maximum count of 'R's, and output the subgrid corresponding to the bounding box of that component.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    R A A A . . . . . .
    A A B A . . R A B .
    B R A B . . A A A .
    A A A A . . R B A .
    . . . . . . A A R .
    . . . . . . R A B .
    . B R A R . B A A .
    . A A B A . . . . .
    . B R A B . . . . .
    . . . . . . . . . .
    ```
*   **Step 1: Identify Connected Components (Nebulae).**
    *   **Nebula 1 (Top Left):**
        Starts at (0,0).
        Row 0: R A A A (Cols 0-3)
        Row 1: A A B A (Cols 0-3)
        Row 2: B R A B (Cols 0-3)
        Row 3: A A A A (Cols 0-3)
        Row 4: . . . . (End of block)
        Let's check connectivity.
        (0,0)R connects to (0,1)A, (1,0)A.
        (1,0)A connects to (1,1)A, (2,0)B.
        (2,0)B connects to (2,1)R, (3,0)A.
        (3,0)A 

... [4327 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fail
"The harbor pilot eyes each vessel at anchor and boards the one flying the most red distress flags"
Fail (best cell_acc=0.22 at k=2)
Best Attempt
vs
Expected
Reasoning (10495 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A dark harbor with ships at anchor.
*   **Elements:**
    *   **Hulls:** Azure (A).
    *   **Distress Pennants:** Red (R).
    *   **Courtesy Flags:** Blue (B).
    *   **Water:** Black (.).
*   **Action:** "Count the distress signals on each vessel and row out to the one most urgently calling for help."
*   **Interpretation:**
    *   "Vessels" are likely connected components of Azure (A) pixels, possibly including other colors associated with the ship (R, B).
    *   "Distress signals" are Red (R) pixels.
    *   "Most urgently calling for help" implies finding the vessel with the *most* Red (R) pixels.
    *   "Row out to the one" implies extracting or isolating that specific vessel from the rest of the grid.
    *   The output should be the subgrid containing the selected vessel.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** 10x10 grid.
    *   There are two distinct clusters of non-black pixels separated by a column of black pixels (column 5, index 4).
    *   Left Cluster (cols 0-3):
        *   Row 0: B B B A
        *   Row 1: B A B B
        *   Row 2: A R A B
        *   Row 3: B B B A
        *   Row 4: A B A A
        *   Row 5-9: mostly empty or scattered.
        *   Let's look closer at connectivity.
        *   Left side seems to be a block.
        *   Right side (cols 6-9):
        *   Row 0: . . . .
        *   Row 1: B A A B A (Wait, col 5 is ., col 6 is B)
        *   Let's trace the "ships".
        *   Ship 1 (Left):
            *   (0,0)B, (0,1)B, (0,2)B, (0,3)A
            *   (1,0)B, (1,1)A, (1,2)B, (1,3)B
            *   (2,0)A, (2,1)R, (2,2)A, (2,3)B
            *   (3,0)B, (3,1)B, (3,2)B, (3,3)A
            *   (4,0)A, (4,1)B, (4,2)A, (4,3)A
            *   (7,1)R, (7,2)R, (7,3)B ... wait, row 7 has R R B at cols 1,2,3.
            *   (8,1)R, (8,2)R, (8,3)B
            *   (9,1)R, (9,2)B, (9,3)A
            *   Actually, let's look at the Output.
            *   Output is 3x3:
                A R R
                R R B
                R B A
            *   This looks like a specific part of the input.
            *   Where is this in the input?
            *   Rows 7-9, Cols 1-3:
                Row 7: . A R R . -> Cols 1,2,3 are A R R.
                Row 8: . R R B . -> Cols 1,2,3 are R R B.
                Row 9: . R B A . -> Cols 1,2,3 are R B A.
            *   So the output corresponds to the bottom-left cluster.
            *   Why this one?
            *   Let's count Red (R) pixels in the clusters.
            *   Cluster 1 (Top-Leftish):
                *   (2,1) is R.
                *   Any others? (4,?) No.
                *   Let's check connectivity.
                *   Top Left block: (0,0)-(4,3). Contains one R at (2,1).
                *   Bottom Left block: (7,1)-(9,3). Contains R at (7,1), (7,2), (8,1), (8,2), (9,1). Total 5 Rs.
            *   Cluster 2 (Right side):
                *   (1,6)B, (1,7)A, (1,8)A, (1,9)B, (1,10)A? No grid is 10 wide.
                *   Let's map indices 0-9.
                *   Row 1: . . . . . B A A B A -> Cols 5-9.
                *   Row 2: . . . . . A B A R A -> Col 8 is R.
                *   Row 3: . . . . . A A A A B
                *   Row 4: . . . . . A B R A R -> Cols 7, 9 are R.
                *   Row 5: . . . . . A A A B A
                *   Row 6: . . . . . B B A B A
                *   Row 7: . . . . . A B B A R -> Col 9 is R.
                *   Let's count Rs in Right Cluster: (2,8), (4,7), (4,9), (7,9). Total 4 Rs.
            *   Comparison:
                *   Top-Left Cluster: 1 R.
                *   Bottom-Left Cluster: 5 Rs.
                *   Right Cluster: 4 Rs.
            *   The "most urgently calling for help" is the one with the most Red pixels.
            *   Winner: Bottom-Left Cluster (5 Rs).
            *   Output is the bounding box of that cluster.
            *   Bounding box of Bottom-Left Cluster:
                *   Rows: 7, 8, 9.
                *   Cols: 1, 2, 3.
                *   Content:
                    Row 7: A R R
                    Row 8: R R B
                    Row 9: R B A
            *   Matches the Example 1 Output exactly.

**Example 2:**
*   **Input:** 10x10 grid.
    *   Two main clusters separated by a column of dots (col 5).
    *   Left Cluster (Cols 1-4):
        *   Row 1: A A A A
        *   Row 2: A B A A
        *   Row 3: A A R A
        *   Row 4: A A A A
        *   Rs count: 1 (at 3,3).
    *   Right Cluster (Cols 6-9):
        *   Row 0: A A A A
        *   Row 1: A R R A
        *   Row 2: A A A A
        *   Row 3: A R B A
        *   Row 4: A A A A
        *   Row 6: A A A A A A (Wait, row 6 starts at col 3? No, let's look at the grid).
        *   Input Grid:
            . . . . . . A A A A  (Row 0, Cols 6-9)
            . A 

... [5525 chars truncated]
alt-12 electronics qwen3.5-122b: k=1
"The technician tests each circuit board on the bench and pulls the one with the most overheating components"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10370 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A dark workbench (black background `.`) holds several PCBs (Printed Circuit Boards) side by side.
*   **PCB Appearance:** Azure substrate (`A`) with red-hot resistors (`R`) and blue capacitors (`B`).
*   **Task:** Thermal-scan each board, identify which has the most red-hot components (`R`), and remove it for rework.
*   **Grid Details:** Azure substrate fills each board, red components are overheating, blue components are nominal, black bench space separates the boards.

**Interpretation:**
*   The grid contains multiple distinct objects (PCBs) separated by black space (`.`).
*   Each PCB is primarily made of Azure (`A`).
*   Each PCB contains Red (`R`) and Blue (`B`) pixels.
*   The goal is to select *one* specific PCB based on a criterion: "most red-hot components".
*   "Remove it for rework" implies extracting that specific PCB from the larger grid.
*   The output should be the subgrid corresponding to the selected PCB.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
Output:
```
A R R
R R B
R B A
```

*   **Observation:** The input grid is 10x10. The output is 3x3.
*   **Structure:** There seem to be two distinct regions separated by black space (`.`).
    *   Left region (cols 0-3):
        ```
        B B B A
        B A B B
        A R A B
        B B B A
        A B A A
        ```
        Wait, looking at the black separators.
        Row 0: `B B B A . . . . . .` -> Left block ends at col 3.
        Row 1: `B A B B . B A A B A` -> Left block `B A B B`, Right block `B A A B A`.
        Row 2: `A R A B . A B A R A` -> Left `A R A B`, Right `A B A R A`.
        Row 3: `B B B A . A A A A B` -> Left `B B B A`, Right `A A A A B`.
        Row 4: `A B A A . A B R A R` -> Left `A B A A`, Right `A B R A R`.
        Row 5: `. . . . . A A A B A` -> Left is empty/separator, Right `A A A B A`.
        Row 6: `. . . . . B B A B A` -> Right `B B A B A`.
        Row 7: `. A R R . A B B A R` -> Left `A R R` (shifted?), Right `A B B A R`.
        Row 8: `. R R B . . . . . .` -> Left `R R B`.
        Row 9: `. R B A . . . . . .` -> Left `R B A`.

    *   Let's look for connected components of non-black pixels.
    *   **Component 1 (Left-ish):**
        Rows 0-4, Cols 0-3.
        ```
        B B B A
        B A B B
        A R A B
        B B B A
        A B A A
        ```
        Count of `R`: 1 (at 2,1).
    *   **Component 2 (Right-ish):**
        Rows 1-7, Cols 5-9.
        ```
        B A A B A
        A B A R A
        A A A A B
        A B R A R
        A A A B A
        B B A B A
        A B B A R
        ```
        Count of `R`: 1 (at 2,8 relative to grid, 1,3 relative to block) + 2 (at 4,7 and 4,9) + 1 (at 7,9). Total 4 `R`s.
    *   **Component 3 (Bottom Left):**
        Rows 7-9, Cols 1-3.
        ```
        A R R
        R R B
        R B A
        ```
        Count of `R`: 2 (row 7) + 2 (row 8) + 1 (row 9) = 5 `R`s.
        Wait, let's check connectivity.
        Row 7: `. A R R . ...` -> Cols 1,2,3 are `A R R`.
        Row 8: `. R R B . ...` -> Cols 1,2,3 are `R R B`.
        Row 9: `. R B A . ...` -> Cols 1,2,3 are `R B A`.
        This forms a 3x3 block.
        Is it connected to the top-left block?
        Top-left block ends at Row 4.
        Rows 5, 6 are all `.` in cols 0-3.
        So Component 3 is distinct from Component 1.

    *   **Comparison:**
        Component 1 (Top Left): 1 Red.
        Component 2 (Right): 4 Reds.
        Component 3 (Bottom Left): 5 Reds.

    *   **Output:**
        ```
        A R R
        R R B
        R B A
        ```
        This matches Component 3 exactly.
        Component 3 has the most Red (`R`) pixels (5).
        Component 2 has 4 Reds.
        Component 1 has 1 Red.

    *   **Conclusion:** The rule is to identify connected components of non-black pixels (PCBs), count the number of Red (`R`) pixels in each, and output the subgrid of the component with the maximum count of Red pixels.

**3. Analyze the Test Input:**

Input:
```
R A A A . . . . . .
A A B A . . R A B .
B R A B . . A A A .
A A A A . . R B A .
. . . . . . A A R .
. . . . . . R A B .
. B R A R . B A A .
. A A B A . . . . .
. B R A B . . . . .
. . . . . . . . . .
```

*   **Step 1: Identify Connected Components (PCBs).**
    *   **Component 1 (Top Left):**
        Rows 0-3, Cols 0-3.
        Row 0: `R A A A`
        Row 1: `A A B A`
        Row 2: `B R A B`
        Row 3: `A A A A`
        Separated from others by `.` in Row 4 and Cols 4+.
        Let's check connectivity.
        (0,0) to (3,3) is a solid block of non-black.
        Size: 4x4.
        Content

... [5472 chars truncated]
alt-13 mythology qwen3.5-122b: k=1
"The oracle peers into each sacred pool and chooses the vision stained deepest with blood prophecy"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9304 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "Several still pools lie in a dark temple floor". This suggests there are multiple distinct regions or "pools" separated by something.
*   **Elements:**
    *   "Azure water fills each pool": 'A' represents the background or content of the pools.
    *   "Red stains are blood omens": 'R' represents specific features within the pools.
    *   "Blue lights are benign spirits": 'B' represents other features within the pools.
    *   "Black stone separates the pools": '.' represents the separator or background between pools.
*   **Task:** "Read the omens in each pool, select the one where red prophecy bleeds most thickly, and deliver that vision alone".
    *   "Read the omens in each pool": Analyze the content of each distinct region defined by the black stone ('.').
    *   "Select the one where red prophecy bleeds most thickly": Find the pool with the highest count of 'R' (red).
    *   "Deliver that vision alone": Output the grid corresponding to that specific pool.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
Output:
```
A R R
R R B
R B A
```

Let's break down the input grid.
The separator is '.' (black).
Let's identify the connected components of non-'.' cells.
Looking at the grid:
Rows 0-4, Cols 0-3 seem to form a block.
Rows 0-4, Cols 5-9 seem to form a block.
Rows 5-9, Cols 5-9 seem to form a block.
Rows 7-9, Cols 1-3 seem to form a block.

Let's trace the connected components (4-connectivity usually, or just rectangular regions separated by '.').
The '.' acts as a wall.
Let's look at the structure.
Top-Left Block (Rows 0-4, Cols 0-3):
B B B A
B A B B
A R A B
B B B A
A B A A
Size: 5x4.
Red count ('R'): 1 (at 2,1).

Top-Right Block (Rows 0-4, Cols 5-9):
. . . . . (Row 0 cols 5-9 are dots? No, Row 0 is `B B B A . . . . . .`. So cols 5-9 are dots.)
Wait, let's look closer at the input string.
Row 0: `B B B A . . . . . .` -> Cols 0-3 are `B B B A`. Cols 4-9 are `.`.
Row 1: `B A B B . B A A B A` -> Cols 0-3 `B A B B`. Col 4 `.`. Cols 5-9 `B A A B A`.
Row 2: `A R A B . A B A R A` -> Cols 0-3 `A R A B`. Col 4 `.`. Cols 5-9 `A B A R A`.
Row 3: `B B B A . A A A A B` -> Cols 0-3 `B B B A`. Col 4 `.`. Cols 5-9 `A A A A B`.
Row 4: `A B A A . A B R A R` -> Cols 0-3 `A B A A`. Col 4 `.`. Cols 5-9 `A B R A R`.
Row 5: `. . . . . A A A B A` -> Cols 0-4 `.`. Cols 5-9 `A A A B A`.
Row 6: `. . . . . B B A B A` -> Cols 0-4 `.`. Cols 5-9 `B B A B A`.
Row 7: `. A R R . A B B A R` -> Col 0 `.`. Cols 1-3 `A R R`. Col 4 `.`. Cols 5-9 `A B B A R`.
Row 8: `. R R B . . . . . .` -> Col 0 `.`. Cols 1-3 `R R B`. Cols 4-9 `.`.
Row 9: `. R B A . . . . . .` -> Col 0 `.`. Cols 1-3 `R B A`. Cols 4-9 `.`.

So we have distinct rectangular regions separated by columns/rows of dots.
Region 1 (Top Left): Rows 0-4, Cols 0-3.
Content:
B B B A
B A B B
A R A B
B B B A
A B A A
Red count: 1.

Region 2 (Top Right): Rows 1-4, Cols 5-9.
Wait, Row 0 Cols 5-9 are dots. So this region starts at Row 1.
Content:
B A A B A
A B A R A
A A A A B
A B R A R
Red count: 3 (Row 2 col 8, Row 4 col 7, Row 4 col 9).
Wait, let's check indices.
Row 1: B A A B A (0 R)
Row 2: A B A R A (1 R)
Row 3: A A A A B (0 R)
Row 4: A B R A R (2 R)
Total R = 3.

Region 3 (Bottom Right): Rows 5-7, Cols 5-9.
Row 5: A A A B A
Row 6: B B A B A
Row 7: A B B A R
Red count: 1 (Row 7 col 9).

Region 4 (Bottom Left-ish): Rows 7-9, Cols 1-3.
Row 7: A R R
Row 8: R R B
Row 9: R B A
Red count: 2 (Row 7) + 2 (Row 8) + 1 (Row 9) = 5.

Let's check the Output.
Output:
A R R
R R B
R B A
This matches Region 4 exactly.
Region 4 has 5 Reds.
Region 1 has 1 Red.
Region 2 has 3 Reds.
Region 3 has 1 Red.
The rule "select the one where red prophecy bleeds most thickly" holds. The output is the subgrid of the region with the maximum number of 'R's.

**3. Analyze the Test Input:**

Input:
```
R A A A . . . . . .
A A B A . . R A B .
B R A B . . A A A .
A A A A . . R B A .
. . . . . . A A R .
. . . . . . R A B .
. B R A R . B A A .
. A A B A . . . . .
. B R A B . . . . .
. . . . . . . . . .
```

Let's identify the regions separated by '.'.
The grid is 10x10.

**Region 1 (Top Left):**
Rows 0-3, Cols 0-3.
Row 0: R A A A
Row 1: A A B A
Row 2: B R A B
Row 3: A A A A
Red count:
Row 0: 1 (R at 0,0)
Row 1: 0
Row 2: 1 (R at 2,1)
Row 3: 0
Total R = 2.

**Region 2 (Top Right):**
Rows 1-3, Cols 6-8.
Wait, let's look at the columns.
Row 0: `R A A A . . . . . .` -> Cols 0-3 filled. Cols 4-9 dots.
Row 1: `A A B A . . R A B .` -> Cols 0-3 filled. Cols 4-5 dots. Cols 6-8 filled (`R A B`). Col 9 dot.
Row 2: `B R A B . . A A A .` -> Cols 0-3 filled. Cols 4-5 dots. Cols 6-8 filled (`A A A`). Col 9 d

... [4409 chars truncated]
alt-14 dance qwen3.5-122b: k=1
"The choreographer watches each troupe rehearse and selects the company whose dancers blush the most with exertion"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10466 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "Several dance studios separated by dark hallways, each filled with azure-clad dancers, some flushed red with effort, others cool blue with reserve".
*   **Action:** "Observe which studio holds the most red-flushed performers and invite that entire company to the gala".
*   **Grid Details:**
    *   "Azure leotards fill each studio" -> 'A' represents the dancers/studio content.
    *   "red flush marks passionate dancers" -> 'R' represents specific dancers.
    *   "blue calm marks reserved ones" -> 'B' represents specific dancers.
    *   "black corridors divide the studios" -> '.' represents the separators/hallways.
*   **Goal:** Find the "studio" with the most 'R's and output that specific region.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    B B B A . . . . . .
    B A B B . B A A B A
    A R A B . A B A R A
    B B B A . A A A A B
    A B A A . A B R A R
    . . . . . A A A B A
    . . . . . B B A B A
    . A R R . A B B A R
    . R R B . . . . . .
    . R B A . . . . . .
    ```
*   **Output:**
    ```
    A R R
    R R B
    R B A
    ```
*   **Observation:**
    *   The input grid contains regions separated by '.' (black).
    *   Let's identify the regions (studios).
    *   Region 1 (Top Left):
        ```
        B B B A
        B A B B
        A R A B
        B B B A
        A B A A
        ```
        Wait, looking at the '.' separators.
        Row 0: `B B B A . . . . . .` -> The first 4 columns are non-dot.
        Row 1: `B A B B . B A A B A` -> Cols 0-3 are non-dot. Cols 5-9 are non-dot.
        Row 2: `A R A B . A B A R A` -> Cols 0-3 non-dot. Cols 5-9 non-dot.
        Row 3: `B B B A . A A A A B` -> Cols 0-3 non-dot. Cols 5-9 non-dot.
        Row 4: `A B A A . A B R A R` -> Cols 0-3 non-dot. Cols 5-9 non-dot.
        Row 5: `. . . . . A A A B A` -> Cols 0-4 are dots. Cols 5-9 non-dot.
        Row 6: `. . . . . B B A B A` -> Cols 0-4 are dots. Cols 5-9 non-dot.
        Row 7: `. A R R . A B B A R` -> Col 0 is dot. Cols 1-3 non-dot. Col 4 is dot. Cols 5-9 non-dot.
        Row 8: `. R R B . . . . . .` -> Col 0 is dot. Cols 1-3 non-dot. Cols 4-9 are dots.
        Row 9: `. R B A . . . . . .` -> Col 0 is dot. Cols 1-3 non-dot. Cols 4-9 are dots.

    *   Let's define the connected components of non-dot characters.
    *   **Component 1 (Top Left):**
        Rows 0-4, Cols 0-3.
        Grid:
        ```
        B B B A
        B A B B
        A R A B
        B B B A
        A B A A
        ```
        Count of 'R': 1 (at row 2, col 1).
    *   **Component 2 (Top Right):**
        Rows 1-4, Cols 5-9.
        Grid:
        ```
        B A A B A
        A B A R A
        A A A A B
        A B R A R
        ```
        Count of 'R': 3 (at row 2 col 8, row 4 col 7, row 4 col 9).
    *   **Component 3 (Bottom Right):**
        Rows 5-7, Cols 5-9.
        Grid:
        ```
        A A A B A
        B B A B A
        A B B A R
        ```
        Count of 'R': 1 (at row 7 col 9).
    *   **Component 4 (Bottom Left):**
        Rows 7-9, Cols 1-3.
        Grid:
        ```
        A R R
        R R B
        R B A
        ```
        Count of 'R': 6 (Row 7: 2, Row 8: 2, Row 9: 1). Wait, let's check the input again.
        Row 7: `. A R R . ...` -> Cols 1,2,3 are A, R, R.
        Row 8: `. R R B . ...` -> Cols 1,2,3 are R, R, B.
        Row 9: `. R B A . ...` -> Cols 1,2,3 are R, B, A.
        Total 'R's in this block: 2 + 2 + 1 = 5.
        Let's re-count Component 2 'R's.
        Row 1: `B A A B A` (0 R)
        Row 2: `A B A R A` (1 R)
        Row 3: `A A A A B` (0 R)
        Row 4: `A B R A R` (2 R)
        Total 'R's in Component 2: 3.
        Let's re-count Component 1 'R's.
        Row 0: `B B B A` (0 R)
        Row 1: `B A B B` (0 R)
        Row 2: `A R A B` (1 R)
        Row 3: `B B B A` (0 R)
        Row 4: `A B A A` (0 R)
        Total 'R's in Component 1: 1.
        Let's re-count Component 3 'R's.
        Row 5: `A A A B A` (0 R)
        Row 6: `B B A B A` (0 R)
        Row 7: `A B B A R` (1 R)
        Total 'R's in Component 3: 1.

    *   Comparing 'R' counts:
        Comp 1: 1
        Comp 2: 3
        Comp 3: 1
        Comp 4: 5
    *   The output is:
        ```
        A R R
        R R B
        R B A
        ```
        This matches Component 4 exactly.
    *   **Rule:** Identify connected regions of non-black ('.') cells. Count the number of 'R' (red) cells in each region. Select the region with the highest count of 'R'. Output that region as a subgrid.

**3. Analyze the Test Input:**
*   **Input:**
    ```
    R A A A . . . . . .
    A A B A . . R A B .
    B R A B . . A A A .
    A A A A . . R B A .
    . . . . . . A A R .
    . . . . . . R A B .
    . B R A R . B A A .
    . A A B A . . . . .
    . B R A B . . . . .
    . . . . . . . . . 

... [5556 chars truncated]
alt-15 geology qwen3.5-122b: fail
"The geologist cores each outcrop and keeps only the sample richest in ruby deposits"
Fail (best cell_acc=0.14 at k=2)
Best Attempt
vs
Expected
Reasoning (9634 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** "A dark landscape exposes several rock formations..."
*   **Elements:**
    *   "Azure matrix forms each rock body" -> 'A' (Azure) is the main structure of the objects.
    *   "Red crystals are rubies" -> 'R' (Red) are specific features inside the objects.
    *   "Blue crystals are sapphires" -> 'B' (Blue) are other features inside the objects.
    *   "Black terrain separates the outcrops" -> '.' (Black) is the background/separator.
*   **Task:** "Assay each outcrop for ruby concentration and extract the formation with the greatest red gem density".
    *   "Outcrop" = A connected component of 'A's (possibly containing 'R' and 'B').
    *   "Ruby concentration" = Density of 'R's within an outcrop.
    *   "Extract the formation" = Select the specific outcrop that has the highest density of 'R's.
    *   "Greatest red gem density" = Maximize (Count of R) / (Total size of outcrop) or maybe just Count of R? Usually "density" implies ratio, but in these puzzles, it often means the count relative to size or just the count if sizes are similar. Let's look at the examples to clarify.

**2. Analyze the Training Examples:**

**Example 1:**
Input Grid:
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
Output Grid:
```
A R R
R R B
R B A
```

*   **Observation:** The output is a small 3x3 grid.
*   **Input Analysis:**
    *   There are black dots '.' separating regions.
    *   Let's identify connected components of non-black pixels (A, R, B).
    *   **Region 1 (Top Left):**
        Rows 0-4, Cols 0-3 roughly.
        (0,0)B (0,1)B (0,2)B (0,3)A
        (1,0)B (1,1)A (1,2)B (1,3)B
        (2,0)A (2,1)R (2,2)A (2,3)B
        (3,0)B (3,1)B (3,2)B (3,3)A
        (4,0)A (4,1)B (4,2)A (4,3)A
        This looks like a 5x4 block.
        Let's count 'R's here. Only one 'R' at (2,1).
        Total pixels: 20.
        R count: 1.
    *   **Region 2 (Right Side):**
        Rows 1-7, Cols 5-9 roughly.
        (1,5)B (1,6)A (1,7)A (1,8)B (1,9)A
        (2,5)A (2,6)B (2,7)A (2,8)R (2,9)A
        (3,5)A (3,6)A (3,7)A (3,8)A (3,9)B
        (4,5)A (4,6)B (4,7)R (4,8)A (4,9)R
        (5,5)A (5,6)A (5,7)A (5,8)B (5,9)A
        (6,5)B (6,6)B (6,7)A (6,8)B (6,9)A
        (7,5)A (7,6)B (7,7)B (7,8)A (7,9)R
        This is a large block.
        Let's count 'R's here.
        (2,8), (4,7), (4,9), (7,9). Total 4 'R's.
        Total pixels: 5 rows * 5 cols = 25 pixels.
        R count: 4.
    *   **Region 3 (Bottom Left):**
        Rows 7-9, Cols 1-3 roughly.
        (7,1)A (7,2)R (7,3)R
        (8,1)R (8,2)R (8,3)B
        (9,1)R (9,2)B (9,3)A
        This is a 3x3 block.
        Let's count 'R's here.
        (7,2), (7,3), (8,1), (8,2), (9,1). Total 5 'R's.
        Total pixels: 9.
        R count: 5.
    *   **Comparison:**
        Region 1: 1 R / 20 pixels = 5%
        Region 2: 4 R / 25 pixels = 16%
        Region 3: 5 R / 9 pixels = 55.5%
    *   **Selection:** Region 3 has the highest density of 'R's.
    *   **Output:** The output grid matches Region 3 exactly.
        ```
        A R R
        R R B
        R B A
        ```
        Wait, let's check the coordinates of Region 3 in the input.
        Row 7: . A R R . ... -> Cols 1,2,3 are A, R, R.
        Row 8: . R R B . ... -> Cols 1,2,3 are R, R, B.
        Row 9: . R B A . ... -> Cols 1,2,3 are R, B, A.
        Yes, the output is exactly the subgrid corresponding to Region 3.

**Example 2:**
Input Grid:
```
. . . . . . A A A A
. A A A A . A R R A
. A B A A . A A A A
. A A R A . A R B A
. A A A A . A A A A
. . . . . . . . . .
. . . A A A A A A .
. . . A A A R A A .
. . . A R A B A A .
. . . A B A A A A .
```
Output Grid:
```
A A A A
A R R A
A A A A
A R B A
A A A A
```

*   **Observation:** The output is a 5x4 grid.
*   **Input Analysis:**
    *   **Region 1 (Top Right):**
        Rows 0-4, Cols 6-9.
        (0,6)A (0,7)A (0,8)A (0,9)A
        (1,6)A (1,7)R (1,8)R (1,9)A
        (2,6)A (2,7)A (2,8)A (2,9)A
        (3,6)A (3,7)R (3,8)B (3,9)A
        (4,6)A (4,7)A (4,8)A (4,9)A
        Size: 5 rows x 4 cols = 20 pixels.
        R count: (1,7), (1,8), (3,7). Total 3 'R's.
        Density: 3/20 = 15%.
    *   **Region 2 (Top Left-ish):**
        Rows 1-4, Cols 1-4.
        (1,1)A (1,2)A (1,3)A (1,4)A
        (2,1)A (2,2)B (2,3)A (2,4)A
        (3,1)A (3,2)A (3,3)R (3,4)A
        (4,1)A (4,2)A (4,3)A (4,4)A
        Size: 4 rows x 4 cols = 16 pixels.
        R count: (3,3). Total 1 'R'.
        Density: 1/16 = 6.25%.
    *   **Region 3 (Bottom Middle):**
        Rows 6-9, Cols 3-8.
        (6,3)A (6,4)A (6,5)A (6,6)A (6,7)A (6,8)A
        (7,3)A (7,4)A (7,5)A (7,6)R (7,7)A (7,8)A
        (8,3)A (8,4)R (8,5)A (8,6)B (8,7)A (8,8)A
    

... [4655 chars truncated]
alt-2 cooking qwen3.5-122b: fig alone solves
"The chef tastes each simmering pot and serves only the spiciest one"
alt-3 music qwen3.5-122b: fig alone solves
"The conductor auditions each ensemble and advances the one whose brass section roars loudest"
alt-4 sports qwen3.5-122b: fail
"The scout watches every scrimmage and drafts the squad that drew the most blood"
Fail (best cell_acc=0.14 at k=3)
Best Attempt
vs
Expected
Reasoning (9464 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   "Several practice fields are laid out on a training ground": This suggests the input grid contains multiple distinct regions or "fields".
*   "each team wearing azure jerseys": The dominant color in these fields is Azure (A).
*   "with a few players marked in red penalty cards": There are Red (R) pixels within the Azure fields.
*   "and blue captain bands": There are Blue (B) pixels within the Azure fields.
*   "black grass separates the fields": Black (.) pixels act as separators or background.
*   "Survey each field, tally the red cards, and recruit the team that played hardest":
    *   "Survey each field": Identify the distinct regions separated by black.
    *   "tally the red cards": Count the number of Red (R) pixels in each field.
    *   "recruit the team that played hardest": Select the field with the highest count of Red (R) pixels.
    *   "played hardest": Implies the one with the most "fouls" (Red cards).
*   "Grid details": Azure jerseys fill each squad; red marks are fouls committed, blue marks are leadership badges; black grass separates the fields.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
Grid size: 10x10.
Separators: `.` (black).
Fields:
1.  Top-left region (rows 0-4, cols 0-3 roughly):
    *   Contains A, B, R.
    *   Let's trace the connected components of non-black pixels.
    *   Region 1 (Top Left):
        (0,0)B, (0,1)B, (0,2)B, (0,3)A
        (1,0)B, (1,1)A, (1,2)B, (1,3)B
        (2,0)A, (2,1)R, (2,2)A, (2,3)B
        (3,0)B, (3,1)B, (3,2)B, (3,3)A
        (4,0)A, (4,1)B, (4,2)A, (4,3)A
        Red count: 1 (at 2,1).
    *   Region 2 (Top Right):
        (1,5)B, (1,6)A, (1,7)A, (1,8)B, (1,9)A
        (2,5)A, (2,6)B, (2,7)A, (2,8)R, (2,9)A
        (3,5)A, (3,6)A, (3,7)A, (3,8)A, (3,9)B
        (4,5)A, (4,6)B, (4,7)R, (4,8)A, (4,9)R
        (5,5)A, (5,6)A, (5,7)A, (5,8)B, (5,9)A
        (6,5)B, (6,6)B, (6,7)A, (6,8)B, (6,9)A
        (7,5)A, (7,6)B, (7,7)B, (7,8)A, (7,9)R
        Red count: 3 (at 2,8; 4,7; 4,9; 7,9). Wait, let's look closer.
        (2,8) is R. (4,7) is R. (4,9) is R. (7,9) is R. Total 4 Reds?
        Let's re-examine the input grid structure.
        Row 0: B B B A . . . . . .
        Row 1: B A B B . B A A B A
        Row 2: A R A B . A B A R A
        Row 3: B B B A . A A A A B
        Row 4: A B A A . A B R A R
        Row 5: . . . . . A A A B A
        Row 6: . . . . . B B A B A
        Row 7: . A R R . A B B A R
        Row 8: . R R B . . . . . .
        Row 9: . R B A . . . . . .

        Separators are `.`.
        Let's identify connected components of non-`.` pixels.
        Component 1 (Left):
        Rows 0-4, Cols 0-3.
        (0,0-3), (1,0-3), (2,0-3), (3,0-3), (4,0-3).
        Also (7,1-3), (8,1-3), (9,1-3)?
        Row 5, 6 are all `.` in cols 0-4.
        Row 7 starts with `.` then `A R R`.
        Row 8 starts with `.` then `R R B`.
        Row 9 starts with `.` then `R B A`.
        Wait, Row 7 col 0 is `.`. Row 7 col 1 is `A`.
        Is the left block connected to the bottom-left block?
        Row 4 ends with `A` at col 3. Row 5 is all `.`. So they are separated vertically.
        So we have:
        Block 1 (Top Left): Rows 0-4, Cols 0-3.
        Block 2 (Top Right): Rows 1-7, Cols 5-9.
        Block 3 (Bottom Left): Rows 7-9, Cols 1-3.
        Let's check connectivity.
        Block 1:
        R0: B B B A
        R1: B A B B
        R2: A R A B
        R3: B B B A
        R4: A B A A
        Reds: 1 (at 2,1).

        Block 2:
        R1: B A A B A (cols 5-9)
        R2: A B A R A
        R3: A A A A B
        R4: A B R A R
        R5: A A A B A
        R6: B B A B A
        R7: A B B A R
        Reds: (2,8), (4,7), (4,9), (7,9). Total 4.

        Block 3:
        R7: A R R (cols 1-3)
        R8: R R B
        R9: R B A
        Reds: (7,1), (7,2), (8,0), (8,1), (9,0). Total 5.
        Wait, looking at the output for Example 1:
        Output:
        A R R
        R R B
        R B A
        This matches Block 3 exactly.
        Why Block 3?
        Block 1 Red count: 1.
        Block 2 Red count: 4.
        Block 3 Red count: 5.
        The rule "recruit the team that played hardest" (most red cards) selects Block 3.
        Output is the subgrid corresponding to Block 3.

**Example 2:**
Input:
```
. . . . . . A A A A
. A A A A . A R R A
. A B A A . A A A A
. A A R A . A R B A
. A A A A . A A A A
. . . . . . . . . .
. . . A A A A A A .
. . . A A A R A A .
. . . A R A B A A .
. . . A B A A A A .
```
Separators: `.`
Block 1 (Top Right):
Rows 0-4, Cols 6-9.
R0: A A A A
R1: A R R A
R2: A A A A
R3: A R B A
R4: A A A A
Reds: (1,7), (1,8), (3,7). Total 3.

Blo

... [4464 chars truncated]
alt-5 weather qwen3.5-122b: fail
"The storm chaser surveys the radar mosaic and drives toward the cell crackling with the most lightning"
Fail (best cell_acc=0.07 at k=1)
Best Attempt
vs
Expected
Reasoning (10778 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** Weather radar, storm cells, dark sky.
*   **Elements:**
    *   Azure (A) = Cloud mass.
    *   Red (R) = Lightning activity (cores).
    *   Blue (B) = Precipitation (rain shafts).
    *   Black (.) = Clear sky.
*   **Task:** "Read each cell's electrical intensity by its red signatures, then zoom the camera on the most electrified system."
*   **Interpretation:**
    *   "Electrical intensity" is likely determined by the number of Red (R) pixels in a connected region or cluster.
    *   "Most electrified system" means the cluster with the most Red pixels.
    *   "Zoom the camera" means cropping the grid to show only that specific cluster.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
Output:
```
A R R
R R B
R B A
```

*   **Observation:** The input grid is 10x10. The output grid is 3x3.
*   **Structure:** There seem to be two distinct clusters of non-black pixels separated by a column of black pixels (column 5, index 4).
    *   Left Cluster (cols 0-3):
        ```
        B B B A
        B A B B
        A R A B
        B B B A
        A B A A
        . . . .
        . . . .
        . A R R
        . R R B
        . R B A
        ```
        Wait, looking closely at the input:
        Row 0: B B B A . . . . . .
        Row 1: B A B B . B A A B A
        Row 2: A R A B . A B A R A
        Row 3: B B B A . A A A A B
        Row 4: A B A A . A B R A R
        Row 5: . . . . . A A A B A
        Row 6: . . . . . B B A B A
        Row 7: . A R R . A B B A R
        Row 8: . R R B . . . . . .
        Row 9: . R B A . . . . . .

    *   There is a vertical separator of dots at column 4 (index 4).
    *   Left side (cols 0-3): Contains A, B, R.
    *   Right side (cols 5-9): Contains A, B, R.

    *   Let's count Red (R) pixels in each connected component.
    *   **Left Component:**
        *   (2,1) is R.
        *   (7,1), (7,2) are R.
        *   (8,1), (8,2) are R.
        *   (9,1) is R.
        *   Are they connected?
            *   (2,1) is isolated from the bottom group by rows 3,4,5,6 which have no R in cols 0-3?
            *   Row 3: B B B A (No R)
            *   Row 4: A B A A (No R)
            *   Row 5: . . . . (No R)
            *   Row 6: . . . . (No R)
            *   Row 7: . A R R (R at 7,1 and 7,2)
            *   Row 8: . R R B (R at 8,1 and 8,2)
            *   Row 9: . R B A (R at 9,1)
            *   So there are two distinct groups of R on the left? Or is the whole left block one "system"?
            *   Usually, "system" implies a connected component of non-background pixels.
            *   Let's check connectivity of non-black pixels on the left.
            *   Rows 0-4 are connected. Rows 7-9 are connected. Rows 5-6 are empty on the left. So they are two separate components on the left.
            *   Component 1 (Top Left): R count = 1 (at 2,1).
            *   Component 2 (Bottom Left): R count = 5 (at 7,1; 7,2; 8,1; 8,2; 9,1).
    *   **Right Component:**
        *   Rows 1-4 have pixels. Rows 5-7 have pixels.
        *   Row 1: B A A B A (R count 0)
        *   Row 2: A B A R A (R count 1 at 2,8)
        *   Row 3: A A A A B (R count 0)
        *   Row 4: A B R A R (R count 2 at 4,7; 4,9)
        *   Row 5: A A A B A (R count 0)
        *   Row 6: B B A B A (R count 0)
        *   Row 7: A B B A R (R count 1 at 7,9)
        *   Are these connected?
            *   Row 1 connects to Row 2. Row 2 connects to Row 3. Row 3 connects to Row 4. Row 4 connects to Row 5. Row 5 connects to Row 6. Row 6 connects to Row 7.
            *   So the Right side is one large connected component.
            *   Total R count on Right = 1 + 2 + 1 = 4.

    *   **Comparison:**
        *   Top Left Component: 1 R.
        *   Bottom Left Component: 5 R.
        *   Right Component: 4 R.
    *   **Winner:** Bottom Left Component (5 R).
    *   **Output:**
        ```
        A R R
        R R B
        R B A
        ```
        Let's check the Bottom Left Component in the input:
        Row 7: . A R R
        Row 8: . R R B
        Row 9: . R B A
        Cols 1-3.
        The output matches exactly the subgrid defined by the bounding box of the Bottom Left Component.
        Row 7, cols 1-3: A R R
        Row 8, cols 1-3: R R B
        Row 9, cols 1-3: R B A
        This matches the output perfectly.

    *   **Hypothesis:**
        1.  Identify connected components of non-black pixels (A, B, R).
        2.  Count the number of Red (R) pixels in each component.
        3.  Select the component with the maximum number of Red pixels.
        4.  Crop the grid to the bounding box of that selected componen

... [5829 chars truncated]
alt-6 architecture qwen3.5-122b: fail
"The demolition crew inspects every condemned building and topples the one most riddled with fire damage"
Fail (best cell_acc=0.07 at k=1)
Best Attempt
vs
Expected
Reasoning (9871 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A city block with structures separated by empty lots.
*   **Building Materials:** Azure stone (A) forms walls.
*   **Damage:** Red scorch marks (R) = fire damage. Blue water stains (B) = water damage.
*   **Separators:** Black lots (.) separate structures.
*   **Task:** Survey fire damage (R), then extract the one bearing the deepest burns for the wrecking ball.
*   **Interpretation:**
    *   "Structures" are likely connected components of non-black pixels.
    *   "Fire damage" corresponds to Red (R) pixels.
    *   "Deepest burns" likely means the structure with the most Red pixels, or perhaps the most intense concentration.
    *   "Extract" means isolate that specific structure in the output grid.
    *   "Wrecking ball" implies removing everything else.

**2. Analyze the Training Examples:**

**Example 1:**
Input:
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
Output:
```
A R R
R R B
R B A
```

*   **Observation:** The input grid is 10x10. The output grid is 3x3.
*   **Structure Identification:**
    *   There are black pixels (.) acting as separators.
    *   Let's look at the connected components of non-black pixels.
    *   Top-Left block (rows 0-4, cols 0-3):
        ```
        B B B A
        B A B B
        A R A B
        B B B A
        A B A A
        ```
        This block contains 1 Red pixel (R) at (2,1).
    *   Top-Right block (rows 0-4, cols 5-9):
        ```
        . . . . .
        B A A B A
        A B A R A
        A A A A B
        A B R A R
        ```
        Wait, looking at the input again.
        Row 0: `B B B A . . . . . .` -> Left block ends at col 3. Right side is empty.
        Row 1: `B A B B . B A A B A` -> Left block cols 0-3. Right block cols 5-9.
        Row 2: `A R A B . A B A R A` -> Left block cols 0-3. Right block cols 5-9.
        Row 3: `B B B A . A A A A B` -> Left block cols 0-3. Right block cols 5-9.
        Row 4: `A B A A . A B R A R` -> Left block cols 0-3. Right block cols 5-9.
        Row 5: `. . . . . A A A B A` -> Right block cols 5-9.
        Row 6: `. . . . . B B A B A` -> Right block cols 5-9.
        Row 7: `. A R R . A B B A R` -> Left block cols 1-3 (A R R). Right block cols 5-9.
        Row 8: `. R R B . . . . . .` -> Left block cols 1-3 (R R B).
        Row 9: `. R B A . . . . . .` -> Left block cols 1-3 (R B A).

    *   Let's trace the connected components properly.
    *   **Component 1 (Top Left):**
        Rows 0-4, Cols 0-3.
        Pixels:
        (0,0)B (0,1)B (0,2)B (0,3)A
        (1,0)B (1,1)A (1,2)B (1,3)B
        (2,0)A (2,1)R (2,2)A (2,3)B
        (3,0)B (3,1)B (3,2)B (3,3)A
        (4,0)A (4,1)B (4,2)A (4,3)A
        Red count: 1 (at 2,1).

    *   **Component 2 (Top Right):**
        Rows 1-7, Cols 5-9.
        (1,5)B (1,6)A (1,7)A (1,8)B (1,9)A
        (2,5)A (2,6)B (2,7)A (2,8)R (2,9)A
        (3,5)A (3,6)A (3,7)A (3,8)A (3,9)B
        (4,5)A (4,6)B (4,7)R (4,8)A (4,9)R
        (5,5)A (5,6)A (5,7)A (5,8)B (5,9)A
        (6,5)B (6,6)B (6,7)A (6,8)B (6,9)A
        (7,5)A (7,6)B (7,7)B (7,8)A (7,9)R
        Red count: 4 (at 2,8; 4,7; 4,9; 7,9).

    *   **Component 3 (Bottom Left):**
        Rows 7-9, Cols 1-3.
        (7,1)A (7,2)R (7,3)R
        (8,1)R (8,2)R (8,3)B
        (9,1)R (9,2)B (9,3)A
        Red count: 5 (at 7,2; 7,3; 8,1; 8,2; 9,1).

    *   **Comparison:**
        Component 1: 1 Red.
        Component 2: 4 Reds.
        Component 3: 5 Reds.
    *   **Selection:** Component 3 has the most Red pixels ("deepest burns").
    *   **Output:**
        ```
        A R R
        R R B
        R B A
        ```
        This matches the output grid exactly. It is the bounding box of Component 3.

**3. Formulate the Rule:**
1.  Identify connected components of non-black pixels (Azure, Red, Blue). Black pixels (.) act as separators.
2.  Count the number of Red pixels (R) in each connected component.
3.  Select the component with the highest count of Red pixels.
4.  Extract the subgrid corresponding to the bounding box of that selected component.
5.  Output that subgrid.

**4. Apply to Test Input:**

Test Input:
```
R A A A . . . . . .
A A B A . . R A B .
B R A B . . A A A .
A A A A . . R B A .
. . . . . . A A R .
. . . . . . R A B .
. B R A R . B A A .
. A A B A . . . . .
. B R A B . . . . .
. . . . . . . . . .
```

*   **Step 1: Identify Connected Components.**
    *   **Component 1 (Top Left):**
        Rows 0-3, Cols 0-3.
        (0,0)R (0,1)A (0,2)A (0,3)A
        (1,0)A (1,1)A (1,2)B (1,3)A
        (2,0)B (2,1)R (2,2)A (2,3)B
        (3,0)A (3,1)A (3,2)A (3,3)A
        Red count: 2 (at 0,0 and 2,1).

    *   **Component 2 (Top Right):**
        Rows 1-3, Cols

... [4901 chars truncated]
alt-7 warfare qwen3.5-122b: fig alone solves
"The general studies the battlefield map and commits reserves to the sector bleeding the most"
alt-8 theater qwen3.5-122b: fail
"The critic watches each act through opera glasses and gives the standing ovation to whichever scene burned brightest"
Fail (best cell_acc=0.14 at k=2)
Best Attempt
vs
Expected
Reasoning (9191 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "A stage divided into spotlit tableaux by dark curtains".
    *   "Dark curtains" likely correspond to the black dots (`.`).
    *   "Tableaux" are the distinct regions separated by the black dots.
*   **Content:** "each scene features azure-costumed chorus members with a few performers in scarlet and sapphire".
    *   "Azure-costumed chorus members" -> `A` (Azure) seems to be the background or dominant color within the tableaux.
    *   "Scarlet" -> `R` (Red).
    *   "Sapphire" -> `B` (Blue).
*   **Action:** "Judge which tableau radiates the most scarlet passion and pull that scene forward for the encore".
    *   "Radiates the most scarlet passion" -> Count the number of `R` (Red) pixels in each tableau.
    *   "Pull that scene forward" -> Select the tableau with the highest count of `R`.
    *   "Encore" -> Output this selected tableau.

**2. Analyze the Training Examples:**

**Example 1:**
Input Grid:
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
*   **Separators:** The `.` (black) pixels seem to form vertical and horizontal lines dividing the grid.
    *   Looking at the input, there is a vertical line of `.` at column 4 (0-indexed) and column 5? Let's check indices.
    *   Row 0: `B B B A . . . . . .` -> `.` starts at index 4.
    *   Row 1: `B A B B . B A A B A` -> `.` at index 4.
    *   Row 2: `A R A B . A B A R A` -> `.` at index 4.
    *   Row 3: `B B B A . A A A A B` -> `.` at index 4.
    *   Row 4: `A B A A . A B R A R` -> `.` at index 4.
    *   Row 5: `. . . . . A A A B A` -> `.` at indices 0,1,2,3,4.
    *   Row 6: `. . . . . B B A B A` -> `.` at indices 0,1,2,3,4.
    *   Row 7: `. A R R . A B B A R` -> `.` at indices 0, 4.
    *   Row 8: `. R R B . . . . . .` -> `.` at indices 0, 4, 5, 6, 7, 8, 9.
    *   Row 9: `. R B A . . . . . .` -> `.` at indices 0, 4, 5, 6, 7, 8, 9.

    It looks like the grid is divided into rectangular regions by the `.` pixels.
    Let's identify the regions (tableaux).
    Region 1 (Top Left): Rows 0-4, Cols 0-3.
    Region 2 (Top Right): Rows 0-4, Cols 5-9.
    Region 3 (Bottom Left): Rows 5-9, Cols 0-3? Wait, Row 5 has `.` at 0-4. Row 6 has `.` at 0-4. Row 7 has `.` at 0 and 4. Row 8 has `.` at 0 and 4-9. Row 9 has `.` at 0 and 4-9.
    Actually, let's look at the structure more simply.
    The `.` pixels act as walls.
    Let's trace the connected components of non-`.` pixels.
    
    Component 1 (Top Left):
    (0,0)-(0,3), (1,0)-(1,3), (2,0)-(2,3), (3,0)-(3,3), (4,0)-(4,3).
    Content:
    B B B A
    B A B B
    A R A B
    B B B A
    A B A A
    Count of R: 1 (at 2,1).
    
    Component 2 (Top Right):
    (0,5)-(0,9), (1,5)-(1,9), (2,5)-(2,9), (3,5)-(3,9), (4,5)-(4,9).
    Content:
    . . . . . (Wait, row 0 cols 5-9 are `.`)
    Let's re-read Row 0: `B B B A . . . . . .`
    Cols 0-3: `B B B A`
    Col 4: `.`
    Cols 5-9: `. . . . .`
    So Top Right region in rows 0-4 starts at col 5.
    Row 0: `.` `.` `.` `.` `.`
    Row 1: `B A A B A`
    Row 2: `A B A R A`
    Row 3: `A A A A B`
    Row 4: `A B R A R`
    Wait, Row 0 cols 5-9 are `.`. So the region starts at Row 1?
    Let's check connectivity.
    Row 1 Col 5 is `B`. Row 0 Col 5 is `.`. So it's bounded by `.` on top.
    Row 1 Col 4 is `.`. Bounded on left.
    Row 1 Col 9 is `A`.
    Row 2 Col 5 is `A`.
    ...
    Row 4 Col 9 is `R`.
    Row 5 Col 5 is `A`.
    Row 5 Col 4 is `.`.
    Row 5 Cols 5-9: `A A A B A`.
    Row 6 Cols 5-9: `B B A B A`.
    Row 7 Cols 5-9: `A B B A R`.
    Row 8 Cols 5-9: `. . . . .`.
    So there is a large region on the right side spanning Rows 1-7, Cols 5-9.
    Let's count R's in this Right Region.
    Row 1: 0
    Row 2: 1 (at 2,8)
    Row 3: 0
    Row 4: 2 (at 4,7 and 4,9)
    Row 5: 0
    Row 6: 0
    Row 7: 1 (at 7,9)
    Total R's = 1 + 2 + 1 = 4.
    
    Component 3 (Bottom Left):
    Rows 5-9, Cols 0-3?
    Row 5: `. . . .` (Cols 0-3 are `.`)
    Row 6: `. . . .`
    Row 7: `. A R R` (Col 0 is `.`, Cols 1-3 are `A R R`)
    Row 8: `. R R B` (Col 0 is `.`, Cols 1-3 are `R R B`)
    Row 9: `. R B A` (Col 0 is `.`, Cols 1-3 are `R B A`)
    So this region is Rows 7-9, Cols 1-3.
    Content:
    A R R
    R R B
    R B A
    Count of R:
    Row 7: 2
    Row 8: 2
    Row 9: 1
    Total R's = 5.
    
    Comparing R counts:
    Top Left: 1
    Top Right (merged with middle right?): 4
    Bottom Left: 5
    
    The Output is:
    A R R
    R R B
    R B A
    This matches the Bottom Left region exactly.
    This confirms the rule: Find the connected region of non-black pixels separated by black pixels. Count the number of Red (`R`) pixels in each region. Select the region with 

... [4242 chars truncated]
alt-9 gardening qwen3.5-122b: fail
"The gardener walks between raised beds and harvests only from the one bursting with the most ripe tomatoes"
Fail (best cell_acc=0.07 at k=1)
Best Attempt
vs
Expected
Reasoning (10183 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** "Several raised garden beds separated by dark mulch paths".
    *   "Dark mulch paths" likely correspond to the black (`.`) cells.
    *   "Raised garden beds" likely correspond to the connected regions of non-black cells.
*   **Content of beds:** "each bed a carpet of azure foliage dotted with red ripe fruit and blue flowers".
    *   "Azure foliage" = `A` (Azure).
    *   "Red ripe fruit" = `R` (Red).
    *   "Blue flowers" = `B` (Blue).
*   **Task:** "Count the red ripeness in each bed and carry away the entire harvest from the most productive plot".
    *   "Count the red ripeness" = Count the number of `R` cells in each connected bed.
    *   "Most productive plot" = The bed with the highest count of `R`.
    *   "Carry away the entire harvest" = Extract/Output the subgrid corresponding to that specific bed.

**2. Analyze the Training Examples:**

**Example 1:**
Input Grid:
```
B B B A . . . . . .
B A B B . B A A B A
A R A B . A B A R A
B B B A . A A A A B
A B A A . A B R A R
. . . . . A A A B A
. . . . . B B A B A
. A R R . A B B A R
. R R B . . . . . .
. R B A . . . . . .
```
*   **Separators:** The `.` (black) cells seem to form vertical and horizontal lines separating regions.
    *   Column 4 (0-indexed) is all `.`.
    *   Row 5 (0-indexed) is all `.`.
    *   This divides the grid into 4 quadrants (Top-Left, Top-Right, Bottom-Left, Bottom-Right).
*   **Regions (Beds):**
    1.  **Top-Left (Rows 0-4, Cols 0-3):**
        *   Cells:
            B B B A
            B A B B
            A R A B
            B B B A
            A B A A
        *   Count `R`: 1 (at row 2, col 1).
    2.  **Top-Right (Rows 0-4, Cols 5-9):**
        *   Cells:
            . . . . . (Wait, col 4 is separator)
            Let's look at cols 5-9.
            Row 0: . . . . . (Actually row 0 cols 5-9 are `.`) -> Wait, looking at input:
            Row 0: `B B B A . . . . . .` -> Cols 5-9 are `.`.
            Row 1: `B A B B . B A A B A` -> Cols 5-9 are `B A A B A`.
            Row 2: `A R A B . A B A R A` -> Cols 5-9 are `A B A R A`.
            Row 3: `B B B A . A A A A B` -> Cols 5-9 are `A A A A B`.
            Row 4: `A B A A . A B R A R` -> Cols 5-9 are `A B R A R`.
            So Top-Right region is Rows 1-4, Cols 5-9.
            Count `R`: Row 2 has 1, Row 4 has 2. Total = 3.
    3.  **Bottom-Left (Rows 6-9, Cols 0-3):**
        *   Row 5 is separator.
        *   Row 6: `. . . .`
        *   Row 7: `. A R R`
        *   Row 8: `. R R B`
        *   Row 9: `. R B A`
        *   Wait, Row 6 is all `.`. So the region starts at Row 7.
        *   Cells:
            A R R
            R R B
            R B A
        *   Count `R`: Row 7 (2), Row 8 (2), Row 9 (1). Total = 5.
    4.  **Bottom-Right (Rows 6-9, Cols 5-9):**
        *   Row 6: `A A A B A`
        *   Row 7: `A B B A R`
        *   Row 8: `. . . . .`
        *   Row 9: `. . . . .`
        *   Wait, Row 8 and 9 cols 5-9 are `.`.
        *   So region is Rows 6-7, Cols 5-9.
        *   Count `R`: Row 7 has 1. Total = 1.

*   **Comparison:**
    *   Top-Left: 1 `R`
    *   Top-Right: 3 `R`s
    *   Bottom-Left: 5 `R`s
    *   Bottom-Right: 1 `R`
*   **Winner:** Bottom-Left (5 `R`s).
*   **Output:**
    ```
    A R R
    R R B
    R B A
    ```
    This matches the Bottom-Left region exactly.
    Note: The output grid dimensions are 3x3. The input region was Rows 7-9, Cols 1-3 (since col 0 is `.`).
    Let's check the input Bottom-Left region again.
    Row 7: `. A R R` -> Cols 1,2,3 are `A R R`.
    Row 8: `. R R B` -> Cols 1,2,3 are `R R B`.
    Row 9: `. R B A` -> Cols 1,2,3 are `R B A`.
    Yes, the output is the bounding box of the winning region.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   `.` (Black): Paths/Separators. They define the boundaries of the "beds".
    *   `A` (Azure): Foliage (Background of the bed).
    *   `R` (Red): Fruit (The metric for productivity).
    *   `B` (Blue): Flowers (Decorative, irrelevant to counting).
    *   Other colors? None in example 1.
    *   **Beds:** Connected components of non-black cells. In Example 1, they are rectangular blocks separated by full rows/cols of black.

2.  **AFFORDANCES:**
    *   Beds can be counted (specifically the `R` cells within them).
    *   Beds can be extracted (cropped from the main grid).
    *   Beds can be compared based on the count of `R`.

3.  **TRANSFORMATION RULE:**
    *   Step 1: Identify connected regions of non-black cells (`.`). These are the "beds".
    *   Step 2: For each bed, count the number of Red (`R`) cells.
    *   Step 3: Identify the bed with the maximum count of Red cells. (Tie-breaking rule not specified, assume unique max or first found).
    *   Step 4: Extract the subgrid corresponding to the bounding box of that winning bed.
    *   Step 5: Output this 

... [5285 chars truncated]

Task 898: e633a9e5

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A photograph printed with extra-thick borders, like a Polaroid that bleeds at th ... [8 chars truncated] MARC valid 2
alt-1 biology A cell whose membrane thickens before division, reinforcing its outer walls whil ... [25 chars truncated] fail
alt-10 astronomy A constellation whose outer stars undergo gravitational lensing, each appearing ... [60 chars truncated] MARC valid 1
alt-11 ocean/sailing A ship's flag where the border stripes bleed wide from salt spray, while the cen ... [24 chars truncated] MARC valid 1
alt-12 electronics A circuit board where the peripheral traces are laid down in redundant double-wi ... [70 chars truncated] fail
alt-13 mythology A magic mirror that fattens the frame of any vision it shows — the edges o ... [67 chars truncated] fail
alt-14 dance A formation where the dancers on the perimeter take one step outward and leave a ... [83 chars truncated] MARC valid 1
alt-15 geology A crystal whose outer faces grow thicker laminations under pressure while the co ... [37 chars truncated] fail
alt-2 cooking A dumpling whose crimped edges are pinched extra-thick, while the filling in the ... [34 chars truncated] fail
alt-3 music A chord whose root and fifth are doubled in the bass and treble registers while ... [46 chars truncated] MARC valid 2
alt-4 sports A coach who stations extra defenders along the sidelines and end zones but leave ... [43 chars truncated] MARC valid 3
alt-5 weather A pressure system whose outer bands intensify and widen while the eye remains ee ... [23 chars truncated] fail
alt-6 architecture A building whose corner pillars and outer walls are doubled in thickness for loa ... [63 chars truncated] fail
alt-7 warfare A fortress that doubles its outer garrison walls but keeps only a single watchto ... [30 chars truncated] MARC valid 1
alt-8 theater A stage where the actors on the wings and in the back row deliver each line twic ... [77 chars truncated] fail
alt-9 gardening A raised bed whose border plants are set in double rows for a lush hedge effect, ... [36 chars truncated] MARC valid 1
original qwen3.5-122b: k=2
"A photograph printed with extra-thick borders, like a Polaroid that bleeds at the edges."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11036 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("tiny mosaic tile, three paces by three paces").
*   **Output:** A 5x5 grid ("wall it's mounted on is always five-by-five").
*   **Transformation Logic:**
    *   "Edges of the mosaic are sticky — they cling to the frame and leave an echo of themselves".
    *   "Outermost stones on every side press themselves into the plaster twice".
    *   "Center stones... sit calmly without doubling".
    *   "Crust thickens at the rim while the middle stays thin".
    *   "No stone changes color".
    *   Essentially, this sounds like an upscaling or padding operation where the border pixels are duplicated.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input (3x3):
        ```
        B G X
        B R A
        A G A
        ```
    *   Output (5x5):
        ```
        B B G X X
        B B G X X
        B B R A A
        A A G A A
        A A G A A
        ```
    *   Let's check the mapping.
    *   Input Row 0: `B G X` -> Output Rows 0 & 1: `B B G X X`
    *   Input Row 1: `B R A` -> Output Row 2: `B B R A A`
    *   Input Row 2: `A G A` -> Output Rows 3 & 4: `A A G A A`
    *   Wait, let's look closer at the columns.
    *   Input Col 0: `B B A` -> Output Cols 0 & 1: `B B`, `B B`, `B B`, `A A`, `A A`
    *   Input Col 1: `G R G` -> Output Col 2: `G`, `G`, `R`, `G`, `G`
    *   Input Col 2: `X A A` -> Output Cols 3 & 4: `X X`, `X X`, `A A`, `A A`, `A A`

    *   It looks like the 3x3 grid is expanded to 5x5.
    *   The corners are duplicated.
    *   The edges (non-corner) are duplicated.
    *   The center is not duplicated.
    *   Let's visualize the indices.
    *   Input indices: (0,0) to (2,2).
    *   Output indices: (0,0) to (4,4).
    *   Mapping hypothesis:
        *   Input (0,0) -> Output (0,0), (0,1), (1,0), (1,1) ? No, looking at Ex 1:
            *   Input (0,0) is B. Output (0,0), (0,1), (1,0), (1,1) are all B.
            *   Input (0,1) is G. Output (0,2), (1,2) are G.
            *   Input (0,2) is X. Output (0,3), (0,4), (1,3), (1,4) are X.
            *   Input (1,0) is B. Output (2,0), (2,1) are B.
            *   Input (1,1) is R. Output (2,2) is R.
            *   Input (1,2) is A. Output (2,3), (2,4) are A.
            *   Input (2,0) is A. Output (3,0), (3,1), (4,0), (4,1) are A.
            *   Input (2,1) is G. Output (3,2), (4,2) are G.
            *   Input (2,2) is A. Output (3,3), (3,4), (4,3), (4,4) are A.

    *   This looks like a specific scaling rule.
    *   Let's define the output grid $O$ of size $5 \times 5$ based on input grid $I$ of size $3 \times 3$.
    *   $O_{i,j}$ depends on $I_{r,c}$.
    *   Let's look at the "doubling" description again. "Outermost stones on every side press themselves into the plaster twice".
    *   This implies the border rows and columns of the input are expanded to 2 rows/cols in the output. The inner row/col remains 1 row/col.
    *   Input Rows: 0, 1, 2.
    *   Output Rows mapping:
        *   Input Row 0 -> Output Rows 0, 1.
        *   Input Row 1 -> Output Row 2.
        *   Input Row 2 -> Output Rows 3, 4.
    *   Input Cols: 0, 1, 2.
    *   Output Cols mapping:
        *   Input Col 0 -> Output Cols 0, 1.
        *   Input Col 1 -> Output Col 2.
        *   Input Col 2 -> Output Cols 3, 4.

    *   Let's verify this with Example 1.
        *   Input Row 0: `B G X`. Output Rows 0, 1 should be `B B G X X`.
            *   Col 0 (B) -> Cols 0, 1 (B B).
            *   Col 1 (G) -> Col 2 (G).
            *   Col 2 (X) -> Cols 3, 4 (X X).
            *   Result: `B B G X X`. Matches.
        *   Input Row 1: `B R A`. Output Row 2 should be `B B R A A`.
            *   Col 0 (B) -> Cols 0, 1 (B B).
            *   Col 1 (R) -> Col 2 (R).
            *   Col 2 (A) -> Cols 3, 4 (A A).
            *   Result: `B B R A A`. Matches.
        *   Input Row 2: `A G A`. Output Rows 3, 4 should be `A A G A A`.
            *   Col 0 (A) -> Cols 0, 1 (A A).
            *   Col 1 (G) -> Col 2 (G).
            *   Col 2 (A) -> Cols 3, 4 (A A).
            *   Result: `A A G A A`. Matches.

    *   Let's verify with Example 2.
        *   Input:
            ```
            M X X
            X B O
            Y X R
            ```
        *   Row 0: `M X X`. Output Rows 0, 1: `M M X X X`.
            *   M -> MM, X -> X, X -> XX.
            *   Matches Output Rows 0, 1.
        *   Row 1: `X B O`. Output Row 2: `X X B O O`.
            *   X -> XX, B -> B, O -> OO.
            *   Matches Output Row 2.
        *   Row 2: `Y X R`. Output Rows 3, 4: `Y Y X R R`.
            *   Y -> YY, X -> X, R -> RR.
            *   Matches Output Rows 3, 4.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** A 3x3 matrix of colored 

... [6244 chars truncated]
alt-1 biology qwen3.5-122b: fail
"A cell whose membrane thickens before division, reinforcing its outer walls while the nucleus stays lean."
Fail (best cell_acc=0.40 at k=3)
Best Attempt
vs
Expected
Reasoning (10043 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("colony").
*   **Output:** A 5x5 grid ("organism").
*   **Transformation:** "Peripheral cells replicate outward, doubling the organism's skin layer, while interior cells hold steady." "Edges bulk up". "Whole body swells from a compact square into a plumper one."
*   **Key Insight:** The input is 3x3. The output is 5x5. This suggests an expansion.
*   **Specifics:** "Every original color is preserved — only the boundary cells have divided."

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input (3x3):
        B G X
        B R A
        A G A
    *   Output (5x5):
        B B G X X
        B B G X X
        B B R A A
        A A G A A
        A A G A A
    *   Observation:
        *   Top-left corner (0,0) is B. In output, (0,0), (0,1), (1,0), (1,1) are B. It looks like a 2x2 block.
        *   Top-middle (0,1) is G. In output, (0,2), (1,2) are G. Wait, let's look closer.
        *   Let's map input coordinates $(r, c)$ to output coordinates.
        *   Input size $3 \times 3$. Output size $5 \times 5$.
        *   Let's check the center cell of input: (1,1) is R. In output, (2,2) is R.
        *   Let's check the corners.
            *   Input (0,0) = B. Output (0,0), (0,1), (1,0), (1,1) = B.
            *   Input (0,2) = X. Output (0,3), (0,4), (1,3), (1,4) = X.
            *   Input (2,0) = A. Output (3,0), (3,1), (4,0), (4,1) = A.
            *   Input (2,2) = A. Output (3,3), (3,4), (4,3), (4,4) = A.
        *   Let's check the edges (non-corner).
            *   Input (0,1) = G. Output (0,2), (1,2) = G. Wait, looking at the output grid:
                Row 0: B B G X X
                Row 1: B B G X X
                Row 2: B B R A A
                Row 3: A A G A A
                Row 4: A A G A A
            *   Let's trace the input cells to the output blocks.
            *   Input (0,0) [B] -> Output block top-left 2x2? No, (0,0) to (1,1) is 2x2.
            *   Input (0,1) [G] -> Output (0,2) and (1,2). That's a 2x1 vertical strip?
            *   Input (0,2) [X] -> Output (0,3), (0,4), (1,3), (1,4). That's a 2x2 block.
            *   Input (1,0) [B] -> Output (2,0), (2,1). That's a 1x2 horizontal strip?
            *   Input (1,1) [R] -> Output (2,2). That's a 1x1 cell.
            *   Input (1,2) [A] -> Output (2,3), (2,4). That's a 1x2 horizontal strip.
            *   Input (2,0) [A] -> Output (3,0), (3,1), (4,0), (4,1). That's a 2x2 block.
            *   Input (2,1) [G] -> Output (3,2), (4,2). That's a 2x1 vertical strip.
            *   Input (2,2) [A] -> Output (3,3), (3,4), (4,3), (4,4). That's a 2x2 block.

    *   **Hypothesis:** This looks like a scaling operation where corners and edges are treated differently.
    *   Let's look at the mapping again.
        Input $3 \times 3$. Output $5 \times 5$.
        Center of input is (1,1). Center of output is (2,2).
        Distance from center:
        (1,1) -> (2,2) : 1x1
        (0,1) [Top Edge] -> (0,2), (1,2) : 2x1 (Vertical expansion?)
        (1,0) [Left Edge] -> (2,0), (2,1) : 1x2 (Horizontal expansion?)
        (0,0) [Top-Left Corner] -> (0,0), (0,1), (1,0), (1,1) : 2x2
        (0,2) [Top-Right Corner] -> (0,3), (0,4), (1,3), (1,4) : 2x2
        (2,0) [Bottom-Left Corner] -> (3,0), (3,1), (4,0), (4,1) : 2x2
        (2,2) [Bottom-Right Corner] -> (3,3), (3,4), (4,3), (4,4) : 2x2
        (2,1) [Bottom Edge] -> (3,2), (4,2) : 2x1
        (1,2) [Right Edge] -> (2,3), (2,4) : 1x2

    *   Wait, let's re-examine Example 1 Output carefully.
        Row 0: B B G X X
        Row 1: B B G X X
        Row 2: B B R A A
        Row 3: A A G A A
        Row 4: A A G A A

        Let's map Input $(r, c)$ to Output regions.
        Input (0,0) = B. Output region: Rows 0-1, Cols 0-1. (2x2)
        Input (0,1) = G. Output region: Rows 0-1, Col 2. (2x1)
        Input (0,2) = X. Output region: Rows 0-1, Cols 3-4. (2x2)
        Input (1,0) = B. Output region: Row 2, Cols 0-1. (1x2)
        Input (1,1) = R. Output region: Row 2, Col 2. (1x1)
        Input (1,2) = A. Output region: Row 2, Cols 3-4. (1x2)
        Input (2,0) = A. Output region: Rows 3-4, Cols 0-1. (2x2)
        Input (2,1) = G. Output region: Rows 3-4, Col 2. (2x1)
        Input (2,2) = A. Output region: Rows 3-4, Cols 3-4. (2x2)

    *   **Pattern:**
        *   **Corners (0,0), (0,2), (2,0), (2,2):** Expand to 2x2 blocks.
        *   **Edges (0,1), (2,1):** Expand to 2x1 blocks (vertical stretch).
        *   **Edges (1,0), (1,2):** Expand to 1x2 blocks (horizontal stretch).
        *   **Center (1,1):** Stays 1x1.

    *   Let's check if this holds for Example 2.
    *   **Example 2:**
        Input:
        M X X
        X B O
        Y X R
        Output:
        M M X X X
        M M X X X
        X X B O O
        Y Y X

... [5157 chars truncated]
alt-10 astronomy qwen3.5-122b: k=1
"A constellation whose outer stars undergo gravitational lensing, each appearing twice in the sky, while the central star shines undistorted."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11561 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("3x3 star field").
*   **Output:** A 5x5 grid ("Output is a 5x5 field").
*   **Transformation:** "every star along the boundary is gravitationally lensed into a double image." "The star at the exact center of mass... remains a single point of light." "The cluster's apparent size doubles at the fringes."
*   **Key Insight:** The input is 3x3. The output is 5x5. The center element stays the same (single). The boundary elements are "doubled".
*   **Visualizing the "Doubling":**
    *   Input 3x3 indices: (0,0) to (2,2).
    *   Output 5x5 indices: (0,0) to (4,4).
    *   Center of Input: (1,1). Center of Output: (2,2).
    *   The description says "boundary stars appear twice".
    *   Let's look at the Training Example to understand exactly *how* they appear twice.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    B G X
    B R A
    A G A
    ```
    (3 rows, 3 cols)
*   **Output:**
    ```
    B B G X X
    B B G X X
    B B R A A
    A A G A A
    A A G A A
    ```
    (5 rows, 5 cols)

*   **Mapping Input to Output:**
    *   Input Center (1,1) is 'R'. Output Center (2,2) is 'R'. This matches "center... remains a single point".
    *   Input Corners:
        *   (0,0) 'B' -> Output (0,0), (0,1), (1,0), (1,1)? No, (1,1) is R.
        *   Let's look at the Output structure. It looks like a 2x2 expansion of the corners and edges, but the center is 1x1.
        *   Actually, let's look at the Output as a 5x5 grid.
        *   Row 0: B B G X X
        *   Row 1: B B G X X
        *   Row 2: B B R A A
        *   Row 3: A A G A A
        *   Row 4: A A G A A

    *   Let's try to map Input cells to Output blocks.
    *   Input (0,0) 'B'. Output has a 2x2 block of 'B's at top-left?
        *   Output (0,0), (0,1), (1,0), (1,1) are B, B, B, B. Wait, Output (1,1) is B in the example provided?
        *   Let's re-read the example output carefully.
        *   Output:
            B B G X X
            B B G X X
            B B R A A
            A A G A A
            A A G A A
        *   Wait, the example output provided in the prompt text is:
            ```
            B B G X X
            B B G X X
            B B R A A
            A A G A A
            A A G A A
            ```
        *   Let's check the center of this output. Row 2, Col 2 is 'R'.
        *   Let's check the Input Center. Row 1, Col 1 is 'R'.
        *   So Input(1,1) -> Output(2,2).
        *   Now let's look at Input(0,0) 'B'. In Output, we see 'B's at (0,0), (0,1), (1,0), (1,1).
        *   Wait, if Output(1,1) is 'B', then Output(2,2) is 'R'.
        *   Let's check the indices again.
        *   Output Row 0: B B G X X
        *   Output Row 1: B B G X X
        *   Output Row 2: B B R A A
        *   Output Row 3: A A G A A
        *   Output Row 4: A A G A A
        *   Wait, looking at Row 2: B B R A A. The center is 'R'.
        *   Looking at Row 1: B B G X X.
        *   Looking at Row 0: B B G X X.
        *   This implies a scaling factor.
        *   Input 3x3 -> Output 5x5.
        *   Usually, scaling 3x3 to 5x5 isn't a simple integer scale (like 2x would be 6x6).
        *   However, the pattern looks like:
            *   Top-Left 2x2 block corresponds to Input(0,0).
            *   Top-Middle 2x1 block? No.
            *   Let's look at the columns.
            *   Col 0, 1 seem to come from Input Col 0.
            *   Col 2 seems to come from Input Col 1.
            *   Col 3, 4 seem to come from Input Col 2.
            *   Let's check Rows.
            *   Row 0, 1 seem to come from Input Row 0.
            *   Row 2 seems to come from Input Row 1.
            *   Row 3, 4 seem to come from Input Row 2.

    *   **Hypothesis:**
        *   Input dimensions: $H \times W = 3 \times 3$.
        *   Output dimensions: $H' \times W' = 5 \times 5$.
        *   Mapping logic:
            *   Input Row 0 maps to Output Rows 0, 1.
            *   Input Row 1 maps to Output Row 2.
            *   Input Row 2 maps to Output Rows 3, 4.
            *   Input Col 0 maps to Output Cols 0, 1.
            *   Input Col 1 maps to Output Col 2.
            *   Input Col 2 maps to Output Cols 3, 4.
        *   Let's verify this with the Example 1 data.
        *   Input(0,0) = B. Output(0,0), (0,1), (1,0), (1,1) should be B.
            *   Output Row 0: B B ...
            *   Output Row 1: B B ...
            *   Matches.
        *   Input(0,1) = G. Output(0,2), (1,2) should be G.
            *   Output Row 0: ... G ...
            *   Output Row 1: ... G ...
            *   Matches.
        *   Input(0,2) = X. Output(0,3), (0,4), (1,3), (1,4) should be X.
            *   Output Row 0: ... X X
            *   Output Row 1: ... X X
            *   Matches.
        *   Input(1,0) = B. Output(2,0), (2,1) should be B.
            *   

... [6603 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: k=1
"A ship's flag where the border stripes bleed wide from salt spray, while the central emblem stays crisp."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10655 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("3x3 signal flag", "nine colored patches").
*   **Output:** A 5x5 grid ("5x5 banner").
*   **Transformation:** "Weather the flag: the outermost stripes and bands — exposed to wind and wave — fray and spread, each doubling in width. The protected center patch, sheltered by its neighbors, retains its original slim profile."
*   **Key Insight:** The outer elements of the 3x3 grid expand, while the center element stays the same size relative to the expansion logic.
*   **Grid Details:** Input 3x3 -> Output 5x5.
*   **Visualizing the expansion:**
    *   Input dimensions: $3 \times 3$.
    *   Output dimensions: $5 \times 5$.
    *   This suggests a scaling factor. $3 \to 5$ isn't a simple integer scale like $2 \times$.
    *   Let's look at the "doubling in width" part.
    *   If the outer "bands" double, and the center stays "slim".
    *   Let's look at the structure of a 3x3 grid. It has a center cell (1,1) and 8 surrounding cells.
    *   The description says "outermost stripes and bands". In a 3x3 grid, the "outermost" usually refers to the border cells.
    *   The "protected center patch" is the cell at (1,1) (0-indexed).
    *   If the border cells expand and the center stays the same, how does 3x3 become 5x5?
    *   Let's hypothesize a coordinate mapping.
    *   Input indices: $0, 1, 2$.
    *   Output indices: $0, 1, 2, 3, 4$.
    *   Center of input is index 1. Center of output is index 2.
    *   If the center patch (index 1) retains its "slim profile", it might map to a single cell in the output, or a specific region.
    *   If the outer bands "double in width", maybe the cells at index 0 and 2 expand to cover more space.
    *   Let's look at Example 1 to deduce the exact rule.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    B G X
    B R A
    A G A
    ```
    (Row 0: B, G, X; Row 1: B, R, A; Row 2: A, G, A)
*   **Output:**
    ```
    B B G X X
    B B G X X
    B B R A A
    A A G A A
    A A G A A
    ```
*   **Mapping Analysis:**
    *   Input (0,0) is 'B'. Output (0,0), (0,1), (1,0), (1,1) are 'B'. This looks like a 2x2 block.
    *   Input (0,1) is 'G'. Output (0,2), (1,2) are 'G'. This looks like a 2x1 block (width 1, height 2).
    *   Input (0,2) is 'X'. Output (0,3), (0,4), (1,3), (1,4) are 'X'. This looks like a 2x2 block.
    *   Input (1,0) is 'B'. Output (2,0), (2,1) are 'B'. This looks like a 1x2 block (width 2, height 1).
    *   Input (1,1) is 'R'. Output (2,2) is 'R'. This is a 1x1 block.
    *   Input (1,2) is 'A'. Output (2,3), (2,4) are 'A'. This looks like a 1x2 block.
    *   Input (2,0) is 'A'. Output (3,0), (3,1), (4,0), (4,1) are 'A'. This looks like a 2x2 block.
    *   Input (2,1) is 'G'. Output (3,2), (4,2) are 'G'. This looks like a 2x1 block.
    *   Input (2,2) is 'A'. Output (3,3), (3,4), (4,3), (4,4) are 'A'. This looks like a 2x2 block.

*   **Pattern Recognition:**
    *   The output grid is 5x5.
    *   The input grid is 3x3.
    *   Let's define the mapping from Input $(r, c)$ to Output regions.
    *   Input Center $(1,1)$ maps to Output Center $(2,2)$. Size 1x1.
    *   Input Corners $(0,0), (0,2), (2,0), (2,2)$ map to 2x2 blocks in the output corners.
        *   $(0,0) \to$ Output rows 0-1, cols 0-1.
        *   $(0,2) \to$ Output rows 0-1, cols 3-4.
        *   $(2,0) \to$ Output rows 3-4, cols 0-1.
        *   $(2,2) \to$ Output rows 3-4, cols 3-4.
    *   Input Edges (non-corner) $(0,1), (1,0), (1,2), (2,1)$ map to 2x1 or 1x2 blocks.
        *   $(0,1)$ (Top Edge) $\to$ Output rows 0-1, col 2. (Height 2, Width 1).
        *   $(2,1)$ (Bottom Edge) $\to$ Output rows 3-4, col 2. (Height 2, Width 1).
        *   $(1,0)$ (Left Edge) $\to$ Output row 2, cols 0-1. (Height 1, Width 2).
        *   $(1,2)$ (Right Edge) $\to$ Output row 2, cols 3-4. (Height 1, Width 2).

*   **Refining the Rule:**
    *   It seems like the input grid is being "upscaled" but with specific rules for the center vs the border.
    *   Let's look at the indices.
    *   Input $r \in \{0, 1, 2\}$, $c \in \{0, 1, 2\}$.
    *   Output $R \in \{0, 1, 2, 3, 4\}$, $C \in \{0, 1, 2, 3, 4\}$.
    *   Mapping logic:
        *   If Input $r=0$: Output rows 0, 1.
        *   If Input $r=1$: Output row 2.
        *   If Input $r=2$: Output rows 3, 4.
        *   If Input $c=0$: Output cols 0, 1.
        *   If Input $c=1$: Output col 2.
        *   If Input $c=2$: Output cols 3, 4.
    *   Let's check this against the example.
        *   Input (0,0) -> Output rows 0-1, cols 0-1. Correct (2x2).
        *   Input (0,1) -> Output rows 0-1, col 2. Correct (2x1).
        *   Input (0,2) -> Output rows 0-1, cols 3-4. Correct (2x2).
        *   Input (1,0) -> Output row 2, cols 0-1. Correct (1x2).
        *   Input (1,1) -> Output row 2, col 2. Correct (1x1).
       

... [5760 chars truncated]
alt-12 electronics qwen3.5-122b: fail
"A circuit board where the peripheral traces are laid down in redundant double-width for noise immunity, while the core signal path stays single-trace."
Fail (best cell_acc=0.32 at k=2)
Best Attempt
vs
Expected
Reasoning (10893 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** 3x3 grid.
*   **Output:** 5x5 grid.
*   **Metaphor:** "Harden for production: every trace running along the board's edge is doubled for redundancy... The single trace at the center... stays at standard width."
*   **Key phrase:** "Output is a 5x5 board."
*   **Key phrase:** "Component colors are unchanged; edge traces are doubled."
*   **Interpretation:** The input grid represents a 3x3 layout. The output grid is a 5x5 layout. The description suggests an expansion. "Edge traces are doubled" likely means the border cells of the input are expanded or replicated in the output. The center stays "standard width".
*   Let's look at the dimensions. Input 3x3 -> Output 5x5. This is a scaling factor of roughly 1.5? No, 3 to 5 isn't a simple integer scaling.
*   Let's look at the training examples to understand the mapping.

**2. Analyze Training Example 1:**
Input:
B G X
B R A
A G A

Output:
B B G X X
B B G X X
B B R A A
A A G A A
A A G A A

Let's align them.
Input (3x3):
(0,0)=B, (0,1)=G, (0,2)=X
(1,0)=B, (1,1)=R, (1,2)=A
(2,0)=A, (2,1)=G, (2,2)=A

Output (5x5):
Row 0: B B G X X
Row 1: B B G X X
Row 2: B B R A A
Row 3: A A G A A
Row 4: A A G A A

Let's try to map Input cells to Output blocks.
Input (0,0) is B. Output top-left 2x2 block is B.
Input (0,1) is G. Output top-middle 2x1 block? No, Row 0 has B B G X X. Row 1 has B B G X X.
It looks like the columns are expanded.
Col 0 of Input (B, B, A) -> Output Cols 0,1 (B, B, B, A, A).
Col 1 of Input (G, R, G) -> Output Col 2 (G, G, R, G, G).
Col 2 of Input (X, A, A) -> Output Cols 3,4 (X, X, A, A, A).

Let's check the rows.
Row 0 of Input (B, G, X) -> Output Rows 0,1 (B B G X X).
Row 1 of Input (B, R, A) -> Output Row 2 (B B R A A).
Row 2 of Input (A, G, A) -> Output Rows 3,4 (A A G A A).

So the mapping seems to be:
Input (0,0) -> Output (0,0), (0,1), (1,0), (1,1) [2x2 block]
Input (0,1) -> Output (0,2), (1,2) [2x1 block]
Input (0,2) -> Output (0,3), (0,4), (1,3), (1,4) [2x2 block]

Input (1,0) -> Output (2,0), (2,1) [1x2 block]
Input (1,1) -> Output (2,2) [1x1 block]
Input (1,2) -> Output (2,3), (2,4) [1x2 block]

Input (2,0) -> Output (3,0), (3,1), (4,0), (4,1) [2x2 block]
Input (2,1) -> Output (3,2), (4,2) [2x1 block]
Input (2,2) -> Output (3,3), (3,4), (4,3), (4,4) [2x2 block]

Wait, let's look closer at the Output grid structure.
Rows 0,1 correspond to Input Row 0.
Row 2 corresponds to Input Row 1.
Rows 3,4 correspond to Input Row 2.
So Input Rows 0 and 2 are expanded to 2 rows each. Input Row 1 stays 1 row.
Total rows = 2 + 1 + 2 = 5.

Columns 0,1 correspond to Input Col 0.
Col 2 corresponds to Input Col 1.
Columns 3,4 correspond to Input Col 2.
So Input Cols 0 and 2 are expanded to 2 columns each. Input Col 1 stays 1 column.
Total cols = 2 + 1 + 2 = 5.

This matches the "edge traces are doubled" metaphor.
The "edge" of the 3x3 board consists of the outer ring of cells.
The "center" is the single cell at (1,1).
The metaphor says: "every trace running along the board's edge is doubled... The single trace at the center... stays at standard width."
In the context of the grid cells:
- Cells on the boundary of the 3x3 grid (Row 0, Row 2, Col 0, Col 2) are "edge traces".
- The cell at (1,1) is the "center trace".
- "Doubled" means expanded by a factor of 2 in the relevant dimension?
- If a cell is on the edge, it gets expanded. If it's in the center, it doesn't.
- Specifically, looking at the expansion pattern:
  - Top Row (Row 0): Expanded vertically (2 rows).
  - Bottom Row (Row 2): Expanded vertically (2 rows).
  - Middle Row (Row 1): Not expanded vertically (1 row).
  - Left Col (Col 0): Expanded horizontally (2 cols).
  - Right Col (Col 2): Expanded horizontally (2 cols).
  - Middle Col (Col 1): Not expanded horizontally (1 col).

Let's verify this logic with Example 2.

**3. Analyze Training Example 2:**
Input:
M X X
X B O
Y X R

Output:
M M X X X
M M X X X
X X B O O
Y Y X R R
Y Y X R R

Input (0,0)=M. Output (0,0)-(1,1) is M. (2x2)
Input (0,1)=X. Output (0,2)-(1,2) is X. (2x1)
Input (0,2)=X. Output (0,3)-(1,4) is X. (2x2)
Input (1,0)=X. Output (2,0)-(2,1) is X. (1x2)
Input (1,1)=B. Output (2,2) is B. (1x1)
Input (1,2)=O. Output (2,3)-(2,4) is O. (1x2)
Input (2,0)=Y. Output (3,0)-(4,1) is Y. (2x2)
Input (2,1)=X. Output (3,2)-(4,2) is X. (2x1)
Input (2,2)=R. Output (3,3)-(4,4) is R. (2x2)

This confirms the pattern perfectly.
Rule:
- Input grid is 3x3.
- Output grid is 5x5.
- Expansion factors:
  - Rows: Top (2x), Middle (1x), Bottom (2x).
  - Cols: Left (2x), Middle (1x), Right (2x).
- Essentially, the border cells of the 3x3 input are scaled by 2 in the direction perpendicular to the edge they are on?
  - Actually, it's simpler:
  - Row 0 of input becomes Rows 0-1 of output.
  - Row 1 of input becomes Row 2 of output.
  - Row 2 of input bec

... [6058 chars truncated]
alt-13 mythology qwen3.5-122b: fail
"A magic mirror that fattens the frame of any vision it shows — the edges of the scene echo and repeat, but the heart of the image stays true."
Fail (best cell_acc=0.32 at k=1)
Best Attempt
vs
Expected
Reasoning (9571 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Input and Output Dimensions:**
- Input: 3x3 grid.
- Output: 5x5 grid.
- This suggests an expansion or padding operation.

**2. Analyze the Metaphorical Description:**
- "A 3×3 vision... Input is a 3×3 vision. Output is a 5×5 vision."
- "The outermost tiles of the vision bleed outward, each reflected once more at the boundary like a hall of mirrors — but only at the edges."
- "The single tile at the center, the truest part of the prophecy, remains unduplicated."
- "The vision swells in its frame."
- "Tile colors remain; the edges are magically doubled."

**3. Analyze the Training Example:**
Input:
B G X
B R A
A G A

Output:
B B G X X
B B G X X
B B R A A
A A G A A
A A G A A

Let's map the input indices (r, c) to output indices (R, C).
Input size: 3x3. Output size: 5x5.
Center of input is (1, 1) (0-indexed). Value is R.
Center of output is (2, 2). Value is R.
So the center pixel stays in the center.

Let's look at the corners.
Input Top-Left (0,0) is B.
Output Top-Left (0,0) is B.
Output (0,1) is B.
Output (1,0) is B.
Output (1,1) is B.
It looks like the top-left 2x2 block of the output is filled with the top-left pixel of the input.

Input Top-Right (0,2) is X.
Output Top-Right (0,4) is X.
Output (0,3) is X.
Output (1,4) is X.
Output (1,3) is X.
It looks like the top-right 2x2 block of the output is filled with the top-right pixel of the input.

Input Bottom-Left (2,0) is A.
Output Bottom-Left (4,0) is A.
Output (4,1) is A.
Output (3,0) is A.
Output (3,1) is A.
It looks like the bottom-left 2x2 block of the output is filled with the bottom-left pixel of the input.

Input Bottom-Right (2,2) is A.
Output Bottom-Right (4,4) is A.
Output (4,3) is A.
Output (3,4) is A.
Output (3,3) is A.
It looks like the bottom-right 2x2 block of the output is filled with the bottom-right pixel of the input.

Let's look at the edges (non-corner).
Input Top-Middle (0,1) is G.
Output Row 0, Cols 2 is G.
Output Row 1, Cols 2 is G.
Wait, let's look at the Output grid again.
Row 0: B B G X X
Row 1: B B G X X
Row 2: B B R A A
Row 3: A A G A A
Row 4: A A G A A

Let's break down the Output 5x5 grid into regions based on the Input 3x3 grid.
Input:
(0,0) (0,1) (0,2)
(1,0) (1,1) (1,2)
(2,0) (2,1) (2,2)

Output:
(0,0) (0,1) | (0,2) | (0,3) (0,4)
(1,0) (1,1) | (1,2) | (1,3) (1,4)
-----------------------------
(2,0) (2,1) | (2,2) | (2,3) (2,4)
-----------------------------
(3,0) (3,1) | (3,2) | (3,3) (3,4)
(4,0) (4,1) | (4,2) | (4,3) (4,4)

Let's check the values.
Output (0,0), (0,1), (1,0), (1,1) are all B. Input (0,0) is B.
Output (0,2), (1,2) are G. Input (0,1) is G.
Output (0,3), (0,4), (1,3), (1,4) are X. Input (0,2) is X.

Output (2,0), (2,1) are B. Input (1,0) is B.
Output (2,2) is R. Input (1,1) is R.
Output (2,3), (2,4) are A. Input (1,2) is A.

Output (3,0), (3,1), (4,0), (4,1) are A. Input (2,0) is A.
Output (3,2), (4,2) are G. Input (2,1) is G.
Output (3,3), (3,4), (4,3), (4,4) are A. Input (2,2) is A.

**Pattern Identification:**
It seems like each cell in the 3x3 input grid is expanded into a 2x2 block in the 5x5 output grid, *except* for the center cell?
Wait, if every cell was 2x2, the output would be 6x6.
The output is 5x5.
Let's look at the mapping again.
Input (0,0) -> Output (0,0), (0,1), (1,0), (1,1). (2x2 block)
Input (0,1) -> Output (0,2), (1,2). (2x1 block? No, look at row 2)
Input (0,1) is G. Output (0,2) is G, (1,2) is G. Output (2,2) is R. Output (3,2) is G, (4,2) is G.
So Input (0,1) maps to Output (0,2) and (1,2).
Input (1,1) maps to Output (2,2). Just 1x1.
Input (2,1) maps to Output (3,2) and (4,2).

Input (1,0) is B. Output (2,0) is B, (2,1) is B.
Input (1,2) is A. Output (2,3) is A, (2,4) is A.

So the rule seems to be:
- Corners (0,0), (0,2), (2,0), (2,2) expand to 2x2 blocks.
- Edges (0,1), (1,0), (1,2), (2,1) expand to 2x1 or 1x2 blocks?
  - (0,1) [Top Edge] -> Output (0,2), (1,2). Vertical strip of height 2.
  - (2,1) [Bottom Edge] -> Output (3,2), (4,2). Vertical strip of height 2.
  - (1,0) [Left Edge] -> Output (2,0), (2,1). Horizontal strip of width 2.
  - (1,2) [Right Edge] -> Output (2,3), (2,4). Horizontal strip of width 2.
- Center (1,1) -> Output (2,2). Single pixel.

Let's verify this structure.
Input Grid $I$ of size $3 \times 3$.
Output Grid $O$ of size $5 \times 5$.

Mapping logic:
- $I_{0,0}$ (Top-Left) $\rightarrow$ $O_{0:2, 0:2}$ (Top-Left 2x2)
- $I_{0,1}$ (Top-Mid) $\rightarrow$ $O_{0:2, 2}$ (Top-Mid column, rows 0-1)
- $I_{0,2}$ (Top-Right) $\rightarrow$ $O_{0:2, 3:5}$ (Top-Right 2x2)
- $I_{1,0}$ (Mid-Left) $\rightarrow$ $O_{2, 0:2}$ (Mid-Left row, cols 0-1)
- $I_{1,1}$ (Center) $\rightarrow$ $O_{2, 2}$ (Center pixel)
- $I_{1,2}$ (Mid-Right) $\rightarrow$ $O_{2, 3:5}$ (Mid-Right row, cols 3-4)
- $I_{2,0}$ (Bot-Left) $\rightarrow$ $O_{3:5, 0:2}$ (Bot-Left 2x2)
- $I_{2,1}$ (Bot-Mid) $\rightarrow$ $O_{3:5, 2}$ (Bot-Mid co

... [4685 chars truncated]
alt-14 dance qwen3.5-122b: k=1
"A formation where the dancers on the perimeter take one step outward and leave a shadow of themselves behind, while the dancer at the center holds perfectly still."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10611 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("3x3 dance formation").
*   **Output:** A 5x5 grid ("Output is a 5x5 formation").
*   **Action:** "Every dancer along the outside edge steps outward, but their afterimage lingers in the original spot — doubling their visual presence."
*   **Center:** "The center dancer... neither moves nor echoes."
*   **Result:** "The troupe's footprint grows while the choreography's structure holds."
*   **Key takeaway:** The border cells of the 3x3 input are expanded/duplicated to create a 5x5 output. The center cell remains unchanged in position relative to the center, but the grid size increases.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    B G X
    B R A
    A G A
    ```
    (3x3)
*   **Output:**
    ```
    B B G X X
    B B G X X
    B B R A A
    A A G A A
    A A G A A
    ```
    (5x5)

*   **Mapping Input to Output:**
    Let's label input coordinates $(r, c)$ where $r, c \in \{0, 1, 2\}$.
    Let's label output coordinates $(R, C)$ where $R, C \in \{0, 1, 2, 3, 4\}$.

    Input Center: $(1, 1)$ is 'R'.
    Output Center: $(2, 2)$ is 'R'.
    So the center pixel maps to the center pixel of the larger grid.

    Input Corners:
    $(0, 0)$ is 'B'. Output has 'B' at $(0,0), (0,1), (1,0), (1,1)$? No, let's look closer.
    Output Top-Left 2x2 block:
    B B
    B B
    This corresponds to Input $(0,0)$ 'B'.

    Input Top-Edge Middle: $(0, 1)$ is 'G'.
    Output Top-Edge Middle area:
    Row 0: B B **G** X X
    Row 1: B B **G** X X
    It seems the 'G' is at $(0, 2)$ and $(1, 2)$.
    Wait, let's look at the structure.
    Input:
    00 01 02
    10 11 12
    20 21 22

    Output:
    00 01 02 03 04
    10 11 12 13 14
    20 21 22 23 24
    30 31 32 33 34
    40 41 42 43 44

    Let's check the values in the output example.
    Row 0: B B G X X
    Row 1: B B G X X
    Row 2: B B R A A
    Row 3: A A G A A
    Row 4: A A G A A

    Let's try to map Input cells to Output blocks.
    Input $(0,0)$ = B. Output $(0,0), (0,1), (1,0), (1,1)$ are all B.
    Input $(0,1)$ = G. Output $(0,2), (1,2)$ are G.
    Input $(0,2)$ = X. Output $(0,3), (0,4), (1,3), (1,4)$ are X.
    Input $(1,0)$ = B. Output $(2,0), (2,1)$ are B.
    Input $(1,1)$ = R. Output $(2,2)$ is R.
    Input $(1,2)$ = A. Output $(2,3), (2,4)$ are A.
    Input $(2,0)$ = A. Output $(3,0), (3,1), (4,0), (4,1)$ are A.
    Input $(2,1)$ = G. Output $(3,2), (4,2)$ are G.
    Input $(2,2)$ = A. Output $(3,3), (3,4), (4,3), (4,4)$ are A.

    **Pattern Hypothesis:**
    The 3x3 grid is scaled up to 5x5.
    However, it's not a simple 2x scaling (which would make 6x6).
    It looks like the corners are 2x2 blocks.
    The edges (non-corner) are 2x1 or 1x2 blocks?
    The center is 1x1.

    Let's visualize the scaling factor.
    Input width 3 -> Output width 5.
    $3 \times 2 - 1 = 5$.
    This suggests an overlap or a specific expansion rule.
    Let's look at the mapping again.
    Input $(r, c)$ maps to Output region.
    If $r=0, c=0$ (Corner): Output $(0..1, 0..1)$ -> 2x2 block.
    If $r=0, c=1$ (Top Edge): Output $(0..1, 2)$ -> 2x1 block (vertical).
    If $r=0, c=2$ (Corner): Output $(0..1, 3..4)$ -> 2x2 block.
    If $r=1, c=0$ (Left Edge): Output $(2, 0..1)$ -> 1x2 block (horizontal).
    If $r=1, c=1$ (Center): Output $(2, 2)$ -> 1x1 block.
    If $r=1, c=2$ (Right Edge): Output $(2, 3..4)$ -> 1x2 block (horizontal).
    If $r=2, c=0$ (Corner): Output $(3..4, 0..1)$ -> 2x2 block.
    If $r=2, c=1$ (Bottom Edge): Output $(3..4, 2)$ -> 2x1 block (vertical).
    If $r=2, c=2$ (Corner): Output $(3..4, 3..4)$ -> 2x2 block.

    Wait, let's re-verify the "Edge" mapping.
    Input $(0,1)$ is G. Output has G at $(0,2)$ and $(1,2)$. That is a 2x1 vertical block.
    Input $(1,0)$ is B. Output has B at $(2,0)$ and $(2,1)$. That is a 1x2 horizontal block.
    Input $(1,2)$ is A. Output has A at $(2,3)$ and $(2,4)$. That is a 1x2 horizontal block.
    Input $(2,1)$ is G. Output has G at $(3,2)$ and $(4,2)$. That is a 2x1 vertical block.

    So the rule seems to be:
    - Corners expand to 2x2.
    - Edges (non-corner) expand to 2x1 (if top/bottom) or 1x2 (if left/right).
    - Center stays 1x1.

    Let's check the coordinates mathematically.
    Input $(r, c)$.
    Output rows $R$, cols $C$.
    If $r=0$: Output rows 0, 1.
    If $r=1$: Output row 2.
    If $r=2$: Output rows 3, 4.
    If $c=0$: Output cols 0, 1.
    If $c=1$: Output col 2.
    If $c=2$: Output cols 3, 4.

    Let's check if this simple mapping holds for all cells.
    Input $(0,0)$ -> Rows 0,1; Cols 0,1. (2x2). Correct.
    Input $(0,1)$ -> Rows 0,1; Col 2. (2x1). Correct.
    Input $(0,2)$ -> Rows 0,1; Cols 3,4. (2x2). Correct.
    Input $(1,0)$ -> Row 2; Cols 0,1. (1x2). Correct.
    Input $(1,1)$ -> Row 2; Col 2. (1x1). Correct.
    In

... [5755 chars truncated]
alt-15 geology qwen3.5-122b: fail
"A crystal whose outer faces grow thicker laminations under pressure while the core lattice stays a single layer deep."
Fail (best cell_acc=0.32 at k=2)
Best Attempt
vs
Expected
Reasoning (9402 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("mineral cross-section").
*   **Output:** A 5x5 grid ("cross-section widens").
*   **Transformation:** "Outermost zones... accrete additional layers... doubling in thickness. The innermost zone... remains a single lamination."
*   **Interpretation:**
    *   The input is 3x3.
    *   The output is 5x5.
    *   "Outermost zones" likely refers to the border cells of the 3x3 grid.
    *   "Innermost zone" refers to the center cell of the 3x3 grid.
    *   "Doubling in thickness" suggests that the border cells expand.
    *   "Remains a single lamination" suggests the center cell stays as is (or expands differently).
    *   Let's look at the dimensions. 3x3 to 5x5.
    *   If the center is 1 cell, and the border is expanded.
    *   Let's check the examples to understand the mapping.

**2. Analyze Training Examples:**

**Example 1:**
Input:
B G X
B R A
A G A

Output:
B B G X X
B B G X X
B B R A A
A A G A A
A A G A A

Let's map Input (3x3) to Output (5x5).
Input indices: (0,0) to (2,2).
Output indices: (0,0) to (4,4).

Input Center: (1,1) is 'R'.
Output Center area:
Row 2, Col 2 is 'R'.
Surrounding 'R' in output:
(1,2) is G, (2,1) is B, (2,3) is A, (3,2) is G.
Wait, let's look at the structure.
Output Row 0: B B G X X
Output Row 1: B B G X X
Output Row 2: B B R A A
Output Row 3: A A G A A
Output Row 4: A A G A A

Let's look at the Input corners and edges.
Input (0,0) = B. Output (0,0), (0,1), (1,0), (1,1) are B. This is a 2x2 block of B.
Input (0,1) = G. Output (0,2), (1,2) are G. This is a 2x1 block? No, look at (0,2) and (1,2).
Input (0,2) = X. Output (0,3), (0,4), (1,3), (1,4) are X. This is a 2x2 block of X.
Input (1,0) = B. Output (2,0), (2,1) are B.
Input (1,1) = R. Output (2,2) is R. Just 1x1?
Input (1,2) = A. Output (2,3), (2,4) are A.
Input (2,0) = A. Output (3,0), (3,1), (4,0), (4,1) are A.
Input (2,1) = G. Output (3,2), (4,2) are G.
Input (2,2) = A. Output (3,3), (3,4), (4,3), (4,4) are A.

Let's re-evaluate the "doubling" concept.
Input size: 3x3.
Output size: 5x5.
This looks like an expansion where the border cells are scaled up by 2x2, and the center cell is scaled up by 1x1?
Let's check the coordinates.
If we treat the input as a grid of "pixels".
Input (0,0) -> Output (0,0), (0,1), (1,0), (1,1). (2x2 block)
Input (0,1) -> Output (0,2), (1,2). (2x1 block)
Input (0,2) -> Output (0,3), (0,4), (1,3), (1,4). (2x2 block)
Input (1,0) -> Output (2,0), (2,1). (1x2 block)
Input (1,1) -> Output (2,2). (1x1 block)
Input (1,2) -> Output (2,3), (2,4). (1x2 block)
Input (2,0) -> Output (3,0), (3,1), (4,0), (4,1). (2x2 block)
Input (2,1) -> Output (3,2), (4,2). (2x1 block)
Input (2,2) -> Output (3,3), (3,4), (4,3), (4,4). (2x2 block)

Wait, the output dimensions are 5x5.
If corners are 2x2, edges are 2x1 or 1x2, center is 1x1.
Total width: 2 (left col) + 1 (mid col) + 2 (right col) = 5.
Total height: 2 (top row) + 1 (mid row) + 2 (bottom row) = 5.
This matches perfectly.

So the rule is:
- Corner cells of the 3x3 input become 2x2 blocks in the 5x5 output.
- Edge cells (non-corner) of the 3x3 input become 2x1 (horizontal) or 1x2 (vertical) blocks in the 5x5 output.
- Center cell of the 3x3 input becomes a 1x1 block in the 5x5 output.

Let's verify with Example 2.
Input:
M X X
X B O
Y X R

Output:
M M X X X
M M X X X
X X B O O
Y Y X R R
Y Y X R R

Mapping:
Input (0,0) = M -> Output (0,0)-(1,1) = M M / M M. (2x2) Correct.
Input (0,1) = X -> Output (0,2)-(1,2) = X / X. (2x1 vertical strip). Correct.
Input (0,2) = X -> Output (0,3)-(1,4) = X X / X X. (2x2). Correct.
Input (1,0) = X -> Output (2,0)-(2,1) = X X. (1x2 horizontal strip). Correct.
Input (1,1) = B -> Output (2,2) = B. (1x1). Correct.
Input (1,2) = O -> Output (2,3)-(2,4) = O O. (1x2 horizontal strip). Correct.
Input (2,0) = Y -> Output (3,0)-(4,1) = Y Y / Y Y. (2x2). Correct.
Input (2,1) = X -> Output (3,2)-(4,2) = X / X. (2x1 vertical strip). Correct.
Input (2,2) = R -> Output (3,3)-(4,4) = R R / R R. (2x2). Correct.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Input Grid:** A 3x3 matrix representing mineral zones.
    *   **Output Grid:** A 5x5 matrix representing the expanded cross-section.
    *   **Cells:** Individual color units.
    *   **Roles:**
        *   Corner cells (4): Act as anchors for 2x2 expansion.
        *   Edge cells (4): Act as anchors for 2x1 or 1x2 expansion.
        *   Center cell (1): Acts as the core, remaining 1x1.

2.  **AFFORDANCES:**
    *   Cells can be replicated.
    *   Replication factor depends on position (Corner=2x2, Edge=2x1/1x2, Center=1x1).
    *   Colors are preserved during replication.

3.  **TRANSFORMATION RULE:**
    *   Map Input $I$ (3x3) to Output $O$ (5x5).
    *   For each cell $I_{r,c}$ where $r, c \in \{0, 1, 2\}$:
        *   If $(r, c)$ is a corner $

... [4567 chars truncated]
alt-2 cooking qwen3.5-122b: fail
"A dumpling whose crimped edges are pinched extra-thick, while the filling in the center stays a single thin layer."
Fail (best cell_acc=0.32 at k=2)
Best Attempt
vs
Expected
Reasoning (10086 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("3x3 tart").
*   **Output:** A 5x5 grid ("5x5 tart").
*   **Transformation:** "Seal the edges: the outer ring of ingredients gets folded over on itself, doubling in presence... The center filling stays as-is".
*   **Interpretation:** The input is 3x3. The output is 5x5. The center of the 3x3 grid corresponds to the center of the 5x5 grid. The "outer ring" of the 3x3 grid is expanded or duplicated to form the border of the 5x5 grid.
*   **Visualizing the expansion:**
    *   Input size: $3 \times 3$.
    *   Output size: $5 \times 5$.
    *   This looks like a scaling operation where the center pixel stays 1x1, but the border pixels are expanded.
    *   Let's look at the coordinates.
    *   Input $(r, c)$ where $r, c \in \{0, 1, 2\}$.
    *   Output $(R, C)$ where $R, C \in \{0, 1, 2, 3, 4\}$.
    *   Center of input is $(1, 1)$. Center of output is $(2, 2)$.
    *   The description says "outer ring... gets folded over on itself, doubling in presence".
    *   Let's check the examples to understand the mapping.

**2. Analyze Training Examples:**

**Example 1:**
Input:
B G X
B R A
A G A

Output:
B B G X X
B B G X X
B B R A A
A A G A A
A A G A A

Let's map Input to Output.
Input Grid $I$:
$I_{0,0}=B, I_{0,1}=G, I_{0,2}=X$
$I_{1,0}=B, I_{1,1}=R, I_{1,2}=A$
$I_{2,0}=A, I_{2,1}=G, I_{2,2}=A$

Output Grid $O$:
Row 0: B B G X X
Row 1: B B G X X
Row 2: B B R A A
Row 3: A A G A A
Row 4: A A G A A

Observations:
*   The center element $I_{1,1} = R$ appears at $O_{2,2} = R$.
*   The corners of the input seem to expand into 2x2 blocks in the output?
    *   $I_{0,0} = B$. In Output, top-left 2x2 block is B. ($O_{0,0}, O_{0,1}, O_{1,0}, O_{1,1}$ are B).
    *   $I_{0,2} = X$. In Output, top-right 2x2 block is X. ($O_{0,3}, O_{0,4}, O_{1,3}, O_{1,4}$ are X).
    *   $I_{2,0} = A$. In Output, bottom-left 2x2 block is A. ($O_{3,0}, O_{3,1}, O_{4,0}, O_{4,1}$ are A).
    *   $I_{2,2} = A$. In Output, bottom-right 2x2 block is A. ($O_{3,3}, O_{3,4}, O_{4,3}, O_{4,4}$ are A).
*   What about the edges (non-corner)?
    *   $I_{0,1} = G$. In Output, top edge middle. $O_{0,2}$ and $O_{1,2}$ are G. Wait, looking at Row 0: B B G X X. Row 1: B B G X X. So column 2 is G for rows 0 and 1.
    *   $I_{1,0} = B$. In Output, left edge middle. $O_{2,0}$ and $O_{2,1}$ are B. Wait, Row 2 is B B R A A. So Row 2, Col 0 and 1 are B.
    *   $I_{1,2} = A$. In Output, right edge middle. $O_{2,3}$ and $O_{2,4}$ are A.
    *   $I_{2,1} = G$. In Output, bottom edge middle. $O_{3,2}$ and $O_{4,2}$ are G.
*   What about the center?
    *   $I_{1,1} = R$. In Output, $O_{2,2} = R$. It is a single pixel.

Let's generalize the mapping rule based on this observation.
It looks like a specific scaling factor.
Input is $3 \times 3$. Output is $5 \times 5$.
Let's define the mapping from Input $(r, c)$ to Output regions.
The output grid can be seen as a $3 \times 3$ grid of blocks, but the blocks have different sizes.
Actually, it looks like the input grid is scaled up, but the center pixel is not scaled up in the same way as the border.
Or, more simply:
The input grid is $3 \times 3$.
The output grid is $5 \times 5$.
Let's look at the indices.
Input indices: 0, 1, 2.
Output indices: 0, 1, 2, 3, 4.

Mapping hypothesis:
*   Input $(0,0)$ -> Output $(0,0), (0,1), (1,0), (1,1)$ (2x2 block)
*   Input $(0,1)$ -> Output $(0,2), (1,2)$ (2x1 block)
*   Input $(0,2)$ -> Output $(0,3), (0,4), (1,3), (1,4)$ (2x2 block)
*   Input $(1,0)$ -> Output $(2,0), (2,1)$ (1x2 block)
*   Input $(1,1)$ -> Output $(2,2)$ (1x1 block)
*   Input $(1,2)$ -> Output $(2,3), (2,4)$ (1x2 block)
*   Input $(2,0)$ -> Output $(3,0), (3,1), (4,0), (4,1)$ (2x2 block)
*   Input $(2,1)$ -> Output $(3,2), (4,2)$ (2x1 block)
*   Input $(2,2)$ -> Output $(3,3), (3,4), (4,3), (4,4)$ (2x2 block)

Let's check this against Example 1.
$I_{0,0}=B \rightarrow O_{0..1, 0..1} = B$. Correct.
$I_{0,1}=G \rightarrow O_{0..1, 2} = G$. Correct.
$I_{0,2}=X \rightarrow O_{0..1, 3..4} = X$. Correct.
$I_{1,0}=B \rightarrow O_{2, 0..1} = B$. Correct.
$I_{1,1}=R \rightarrow O_{2, 2} = R$. Correct.
$I_{1,2}=A \rightarrow O_{2, 3..4} = A$. Correct.
$I_{2,0}=A \rightarrow O_{3..4, 0..1} = A$. Correct.
$I_{2,1}=G \rightarrow O_{3..4, 2} = G$. Correct.
$I_{2,2}=A \rightarrow O_{3..4, 3..4} = A$. Correct.

This rule seems consistent.
Let's check Example 2.
Input:
M X X
X B O
Y X R

Output:
M M X X X
M M X X X
X X B O O
Y Y X R R
Y Y X R R

Mapping check:
$I_{0,0}=M \rightarrow O_{0..1, 0..1} = M$. Correct.
$I_{0,1}=X \rightarrow O_{0..1, 2} = X$. Correct.
$I_{0,2}=X \rightarrow O_{0..1, 3..4} = X$. Correct.
$I_{1,0}=X \rightarrow O_{2, 0..1} = X$. Correct.
$I_{1,1}=B \rightarrow O_{2, 2} = B$. Correct.
$I_{1,2}=O \rightarrow O_{2, 3..4} = O$. Correct.
$I_{2,0}=Y \rightarrow O_{3..4, 0..1} = Y$. Correct.
$I_{2,1}=X

... [5149 chars truncated]
alt-3 music qwen3.5-122b: k=2
"A chord whose root and fifth are doubled in the bass and treble registers while the third rings out alone in the middle voice."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10679 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("3x3 score").
*   **Output:** A 5x5 grid ("5x5 score").
*   **Metaphor:** "Outermost voices and the opening and closing beats are doubled... Inner voice and middle beat remain solo."
*   **Key phrase:** "Edges simply resonate with more weight."
*   **Implication:** The input grid is expanded. The center remains the same, but the borders are expanded or duplicated.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input (3x3):
        ```
        B G X
        B R A
        A G A
        ```
    *   Output (5x5):
        ```
        B B G X X
        B B G X X
        B B R A A
        A A G A A
        A A G A A
        ```
    *   Observation:
        *   The input is 3x3. The output is 5x5.
        *   Let's look at the mapping.
        *   Input (0,0) is B. Output (0,0), (0,1), (1,0), (1,1) are B. It seems like a 2x2 block.
        *   Input (0,1) is G. Output (0,2), (1,2) are G. Wait, let's look closer.
        *   Input (0,2) is X. Output (0,3), (0,4), (1,3), (1,4) are X.
        *   Input (1,0) is B. Output (2,0), (2,1) are B.
        *   Input (1,1) is R. Output (2,2) is R.
        *   Input (1,2) is A. Output (2,3), (2,4) are A.
        *   Input (2,0) is A. Output (3,0), (3,1), (4,0), (4,1) are A.
        *   Input (2,1) is G. Output (3,2), (4,2) are G.
        *   Input (2,2) is A. Output (3,3), (3,4), (4,3), (4,4) are A.

    *   Let's try to find a scaling factor. 3x3 to 5x5 isn't a simple integer scaling (like 2x).
    *   Let's look at the structure.
        *   Top-left corner (0,0) of input becomes a 2x2 block in output?
        *   Top-middle (0,1) of input becomes a 2x1 block?
        *   Top-right (0,2) of input becomes a 2x2 block?
        *   Middle-left (1,0) of input becomes a 1x2 block?
        *   Center (1,1) of input becomes a 1x1 block?
        *   Middle-right (1,2) of input becomes a 1x2 block?
        *   Bottom-left (2,0) of input becomes a 2x2 block?
        *   Bottom-middle (2,1) of input becomes a 2x1 block?
        *   Bottom-right (2,2) of input becomes a 2x2 block?

    *   Let's verify this hypothesis on Example 1.
        *   Input:
            (0,0) B -> Output (0,0)-(1,1) B. (2x2)
            (0,1) G -> Output (0,2)-(1,2) G. (2x1)
            (0,2) X -> Output (0,3)-(1,4) X. (2x2)
            (1,0) B -> Output (2,0)-(2,1) B. (1x2)
            (1,1) R -> Output (2,2) R. (1x1)
            (1,2) A -> Output (2,3)-(2,4) A. (1x2)
            (2,0) A -> Output (3,0)-(4,1) A. (2x2)
            (2,1) G -> Output (3,2)-(4,2) G. (2x1)
            (2,2) A -> Output (3,3)-(4,4) A. (2x2)

    *   This pattern holds perfectly for Example 1.
    *   The rule seems to be:
        *   Corners (0,0), (0,2), (2,0), (2,2) expand to 2x2 blocks.
        *   Edges (0,1), (1,0), (1,2), (2,1) expand to 2x1 or 1x2 blocks.
            *   Top/Bottom edges (0,1) and (2,1) expand vertically to 2 rows, 1 column.
            *   Left/Right edges (1,0) and (1,2) expand horizontally to 1 row, 2 columns.
        *   Center (1,1) stays 1x1.

    *   Wait, let's re-examine the dimensions.
        *   Input width = 3. Output width = 5.
        *   Input height = 3. Output height = 5.
        *   Mapping:
            *   Col 0 -> Cols 0, 1
            *   Col 1 -> Col 2
            *   Col 2 -> Cols 3, 4
            *   Row 0 -> Rows 0, 1
            *   Row 1 -> Row 2
            *   Row 2 -> Rows 3, 4
        *   Let's check if this simple coordinate mapping works.
        *   If Input(r, c) maps to Output(r', c'):
            *   If r=0, r' in {0, 1}
            *   If r=1, r' = 2
            *   If r=2, r' in {3, 4}
            *   If c=0, c' in {0, 1}
            *   If c=1, c' = 2
            *   If c=2, c' in {3, 4}
        *   Let's check Example 1 with this rule.
            *   Input(0,0)=B. Output(0,0), (0,1), (1,0), (1,1) should be B. Matches.
            *   Input(0,1)=G. Output(0,2), (1,2) should be G. Matches.
            *   Input(0,2)=X. Output(0,3), (0,4), (1,3), (1,4) should be X. Matches.
            *   Input(1,0)=B. Output(2,0), (2,1) should be B. Matches.
            *   Input(1,1)=R. Output(2,2) should be R. Matches.
            *   Input(1,2)=A. Output(2,3), (2,4) should be A. Matches.
            *   Input(2,0)=A. Output(3,0), (3,1), (4,0), (4,1) should be A. Matches.
            *   Input(2,1)=G. Output(3,2), (4,2) should be G. Matches.
            *   Input(2,2)=A. Output(3,3), (3,4), (4,3), (4,4) should be A. Matches.

    *   This rule is consistent. It effectively doubles the border rows/cols and keeps the center single.
    *   Specifically:
        *   Row 0 becomes Rows 0 & 1.
        *   Row 1 becomes Row 2.
        *   Row 2 becomes Rows 3 & 4.
        *   Col 0 becomes Cols 0 & 1.
        *   Col 1 becomes Co

... [5866 chars truncated]
alt-4 sports qwen3.5-122b: k=3
"A coach who stations extra defenders along the sidelines and end zones but leaves a single midfielder anchoring the center."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (11391 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("playing field").
*   **Output:** A 5x5 grid.
*   **Description:** "Reinforce the flanks and the goal lines: any position touching the edge of the field gets a backup clone standing in the same spot. The heart of the pitch — the true center — stays occupied by a lone player. The formation swells outward without changing who stands where."
*   **Key phrase:** "perimeter positions are simply doubled."
*   **Key phrase:** "Output is a 5x5 field."

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input (3x3):
        B G X
        B R A
        A G A
    *   Output (5x5):
        B B G X X
        B B G X X
        B B R A A
        A A G A A
        A A G A A
    *   Observation:
        *   Top-left corner (0,0) is 'B'. In output, (0,0), (0,1), (1,0), (1,1) are 'B'. It looks like a 2x2 block.
        *   Top-middle (0,1) is 'G'. In output, (0,2), (1,2) are 'G'. Wait, let's look closer.
        *   Let's map Input coordinates $(r, c)$ to Output coordinates.
        *   Input size: $3 \times 3$. Output size: $5 \times 5$.
        *   Let's check the corners.
            *   Input(0,0) = B. Output(0,0)=B, Output(0,1)=B, Output(1,0)=B, Output(1,1)=B.
            *   Input(0,2) = X. Output(0,3)=X, Output(0,4)=X, Output(1,3)=X, Output(1,4)=X.
            *   Input(2,0) = A. Output(3,0)=A, Output(3,1)=A, Output(4,0)=A, Output(4,1)=A.
            *   Input(2,2) = A. Output(3,3)=A, Output(3,4)=A, Output(4,3)=A, Output(4,4)=A.
        *   Let's check the edges (non-corners).
            *   Input(0,1) = G. Output(0,2)=G, Output(1,2)=G.
            *   Input(1,0) = B. Output(2,0)=B, Output(2,1)=B.
            *   Input(1,2) = A. Output(2,3)=A, Output(2,4)=A.
            *   Input(2,1) = G. Output(3,2)=G, Output(4,2)=G.
        *   Let's check the center.
            *   Input(1,1) = R. Output(2,2)=R.
        *   Pattern Hypothesis:
            *   The input grid is scaled up.
            *   Corners become 2x2 blocks.
            *   Edges become 2x1 or 1x2 blocks?
            *   Center becomes 1x1 block?
            *   Let's look at the mapping more systematically.
            *   Input $3 \times 3$ indices: $0, 1, 2$.
            *   Output $5 \times 5$ indices: $0, 1, 2, 3, 4$.
            *   It looks like the input grid is expanded.
            *   Row 0 of Input -> Rows 0, 1 of Output?
                *   Input Row 0: B G X
                *   Output Rows 0, 1:
                    B B G X X
                    B B G X X
                *   It seems Input(0,0) expands to Output(0:2, 0:2). Input(0,1) expands to Output(0:2, 2:3). Input(0,2) expands to Output(0:2, 3:5).
                *   Wait, the widths don't sum up to 5 if we do 2+2+2.
                *   Let's check the columns.
                *   Col 0: B, B, A. Output Cols 0, 1: B, B, B, A, A.
                *   Col 1: G, R, G. Output Col 2: G, G, R, G, G.
                *   Col 2: X, A, A. Output Cols 3, 4: X, X, A, A, A, A.
            *   Let's re-examine Example 1 Output:
                Row 0: B B G X X
                Row 1: B B G X X
                Row 2: B B R A A
                Row 3: A A G A A
                Row 4: A A G A A
            *   Let's look at the mapping from Input $(r, c)$ to Output regions.
            *   Input(0,0) [B] -> Output(0,0), (0,1), (1,0), (1,1). (2x2 block)
            *   Input(0,1) [G] -> Output(0,2), (1,2). (2x1 block)
            *   Input(0,2) [X] -> Output(0,3), (0,4), (1,3), (1,4). (2x2 block)
            *   Input(1,0) [B] -> Output(2,0), (2,1). (1x2 block)
            *   Input(1,1) [R] -> Output(2,2). (1x1 block)
            *   Input(1,2) [A] -> Output(2,3), (2,4). (1x2 block)
            *   Input(2,0) [A] -> Output(3,0), (3,1), (4,0), (4,1). (2x2 block)
            *   Input(2,1) [G] -> Output(3,2), (4,2). (2x1 block)
            *   Input(2,2) [A] -> Output(3,3), (3,4), (4,3), (4,4). (2x2 block)

            *   Wait, let's check the dimensions again.
            *   Output Width = 5.
            *   Col 0, 1 come from Input Col 0?
            *   Col 2 comes from Input Col 1?
            *   Col 3, 4 come from Input Col 2?
            *   Output Height = 5.
            *   Row 0, 1 come from Input Row 0?
            *   Row 2 comes from Input Row 1?
            *   Row 3, 4 come from Input Row 2?

            *   Let's verify this "Expansion Rule":
                *   Input Row 0 -> Output Rows 0, 1.
                *   Input Row 1 -> Output Row 2.
                *   Input Row 2 -> Output Rows 3, 4.
                *   Input Col 0 -> Output Cols 0, 1.
                *   Input Col 1 -> Output Col 2.
                *   Input Col 2 -> Output Cols 3, 4.

            *   Let's check Example 1 with this rule:
                *   Input(0,0)=B ->

... [6607 chars truncated]
alt-5 weather qwen3.5-122b: fail
"A pressure system whose outer bands intensify and widen while the eye remains eerily calm and singular."
Fail (best cell_acc=0.32 at k=1)
Best Attempt
vs
Expected
Reasoning (10394 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Input and Output Dimensions:**
*   Input: 3x3 grid.
*   Output: 5x5 grid.
*   This suggests an expansion or scaling operation.

**2. Analyze the Metaphorical Description:**
*   "A 3×3 weather map — each cell a different atmospheric condition coded by color."
*   "The storm matures: its outermost bands swell, each replicating along the periphery as energy builds at the edges."
*   "The core of the system — the innermost cell — neither grows nor splits."
*   "The map expands as the storm's footprint bloats outward."
*   "Input is a 3×3 system. Output is a 5×5 system. Colors (conditions) are unchanged; the boundary bands have thickened."

**3. Analyze the Training Example:**
Input:
B G X
B R A
A G A

Output:
B B G X X
B B G X X
B B R A A
A A G A A
A A G A A

Let's look at the mapping from Input (3x3) to Output (5x5).
Let Input be $I$ with indices $i, j \in \{0, 1, 2\}$.
Let Output be $O$ with indices $r, c \in \{0, 1, 2, 3, 4\}$.

Let's visualize the Input:
(0,0)=B, (0,1)=G, (0,2)=X
(1,0)=B, (1,1)=R, (1,2)=A
(2,0)=A, (2,1)=G, (2,2)=A

Let's visualize the Output:
Row 0: B B G X X
Row 1: B B G X X
Row 2: B B R A A
Row 3: A A G A A
Row 4: A A G A A

Let's try to map specific cells.
The center of the 3x3 input is (1,1) which is 'R'.
In the 5x5 output, the center is (2,2).
Looking at Output (2,2), it is 'R'.
So the center cell maps to the center cell.

Let's look at the corners.
Input (0,0) is 'B'.
Output (0,0), (0,1), (1,0), (1,1) are 'B'.
Wait, Output (1,1) is 'B'. But Input (1,1) is 'R'.
This contradicts the idea that the center cell stays the same if we just scale up.
Let's re-examine the Output grid structure.

Output:
B B G X X
B B G X X
B B R A A
A A G A A
A A G A A

Let's break down the Output into regions corresponding to the Input cells.
Since 3x3 -> 5x5, it's not a simple integer scaling (like 2x2 per cell would be 6x6).
It looks like a specific expansion pattern.

Let's look at the Input again:
B G X
B R A
A G A

Let's look at the Output again:
B B G X X
B B G X X
B B R A A
A A G A A
A A G A A

Let's try to overlay the Input on the Output.
Input (0,0) = B. Output top-left 2x2 block is B B / B B.
Input (0,1) = G. Output top-middle column?
Output Row 0: B B G X X
Output Row 1: B B G X X
Output Row 2: B B R A A
Output Row 3: A A G A A
Output Row 4: A A G A A

Let's look at the columns.
Col 0: B, B, B, A, A
Col 1: B, B, B, A, A
Col 2: G, G, R, G, G
Col 3: X, X, A, A, A
Col 4: X, X, A, A, A

Let's look at the rows.
Row 0: B, B, G, X, X
Row 1: B, B, G, X, X
Row 2: B, B, R, A, A
Row 3: A, A, G, A, A
Row 4: A, A, G, A, A

Hypothesis 1: Each input cell expands to a 2x2 block, but the center is handled differently?
If every cell expanded to 2x2, we'd get 6x6.
If the center cell stays 1x1, and others expand?
Let's check the center 'R'. In output, 'R' is at (2,2).
Surrounding 'R' in output:
(1,2)=G, (2,1)=B, (2,3)=A, (3,2)=G.
These correspond to Input neighbors of (1,1):
Top: (0,1)=G.
Left: (1,0)=B.
Right: (1,2)=A.
Bottom: (2,1)=G.
So the neighbors of the center in the output match the neighbors of the center in the input.

Let's look at the corners of the input.
Input (0,0) = B.
Output (0,0), (0,1), (1,0), (1,1) are B.
Wait, Output (1,1) is B. But Input (1,1) is R.
This means the expansion of the corner (0,0) overlaps with the center position?
Or is the grid structure different?

Let's look at the Output indices again.
(0,0) B, (0,1) B, (0,2) G, (0,3) X, (0,4) X
(1,0) B, (1,1) B, (1,2) G, (1,3) X, (1,4) X
(2,0) B, (2,1) B, (2,2) R, (2,3) A, (2,4) A
(3,0) A, (3,1) A, (3,2) G, (3,3) A, (3,4) A
(4,0) A, (4,1) A, (4,2) G, (4,3) A, (4,4) A

Let's try to map Input cells to Output regions.
Input (0,0) [B] -> Output (0,0), (0,1), (1,0), (1,1). (2x2 block)
Input (0,1) [G] -> Output (0,2), (1,2). (2x1 block?)
Input (0,2) [X] -> Output (0,3), (0,4), (1,3), (1,4). (2x2 block)
Input (1,0) [B] -> Output (2,0), (2,1). (1x2 block?)
Input (1,1) [R] -> Output (2,2). (1x1 block)
Input (1,2) [A] -> Output (2,3), (2,4). (1x2 block?)
Input (2,0) [A] -> Output (3,0), (3,1), (4,0), (4,1). (2x2 block)
Input (2,1) [G] -> Output (3,2), (4,2). (2x1 block?)
Input (2,2) [A] -> Output (3,3), (3,4), (4,3), (4,4). (2x2 block)

Let's check if this covers the whole 5x5 grid.
Rows 0-1, Cols 0-1: Input (0,0) B. Matches.
Rows 0-1, Col 2: Input (0,1) G. Matches.
Rows 0-1, Cols 3-4: Input (0,2) X. Matches.
Row 2, Cols 0-1: Input (1,0) B. Matches.
Row 2, Col 2: Input (1,1) R. Matches.
Row 2, Cols 3-4: Input (1,2) A. Matches.
Rows 3-4, Cols 0-1: Input (2,0) A. Matches.
Rows 3-4, Col 2: Input (2,1) G. Matches.
Rows 3-4, Cols 3-4: Input (2,2) A. Matches.

This pattern seems consistent.
The rule appears to be:
- Corner cells (0,0), (0,2), (2,0), (2,2) expand to 2x2 blocks.
- Edge cells (0,1), (1,0), (1,2), (2,1) expand to 2x1 or 1x2 blocks (doubling the dimension pe

... [5508 chars truncated]
alt-6 architecture qwen3.5-122b: fail
"A building whose corner pillars and outer walls are doubled in thickness for load-bearing, while the central atrium is left open and unadorned."
Fail (best cell_acc=0.08 at k=1)
Best Attempt
vs
Expected
Reasoning (11652 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("3x3 floor plan", "nine rooms").
*   **Output:** A 5x5 grid ("Output is a 5x5 blueprint").
*   **Transformation:** "Reinforce the structure: the rooms along every exterior wall are widened, their footprint doubled as though buttressed from outside. The single room at the heart of the building keeps its original dimensions."
*   **Key phrase:** "The layout stretches but the room assignments never change."
*   **Interpretation:**
    *   Input is 3x3. Output is 5x5.
    *   The "heart" (center cell) stays the same size (1x1).
    *   The "exterior wall" rooms (the perimeter cells) are "widened" or "footprint doubled".
    *   Let's look at the dimensions. 3x3 to 5x5 implies an expansion.
    *   If the center is 1x1, and the perimeter expands, how does it map?
    *   Let's look at the Training Example 1 to understand the mapping.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    B G X
    B R A
    A G A
    ```
    (3 rows, 3 columns)
*   **Output:**
    ```
    B B G X X
    B B G X X
    B B R A A
    A A G A A
    A A G A A
    ```
    (5 rows, 5 columns)

*   **Mapping Analysis:**
    *   Input Center: `R` (Row 1, Col 1 in 0-indexed).
    *   Output Center: `R` (Row 2, Col 2 in 0-indexed).
    *   Input Top-Left: `B`. Output Top-Left 2x2 block: `B B / B B`.
    *   Input Top-Middle: `G`. Output Top-Middle 2x1 block? No, let's look closer.
    *   Input Top-Right: `X`. Output Top-Right 2x2 block: `X X / X X`.
    *   Input Middle-Left: `B`. Output Middle-Left 2x2 block: `B B / B B`.
    *   Input Middle-Right: `A`. Output Middle-Right 2x2 block: `A A / A A`.
    *   Input Bottom-Left: `A`. Output Bottom-Left 2x2 block: `A A / A A`.
    *   Input Bottom-Middle: `G`. Output Bottom-Middle 2x1 block?
    *   Input Bottom-Right: `A`. Output Bottom-Right 2x2 block: `A A / A A`.

    Let's re-examine the Output grid structure based on the Input grid structure.
    Input indices: (r, c) where r, c in {0, 1, 2}.
    Output indices: (R, C) where R, C in {0, 1, 2, 3, 4}.

    Let's check the corners of the Input:
    (0,0) `B` -> Output (0,0), (0,1), (1,0), (1,1) are all `B`. (2x2 block)
    (0,2) `X` -> Output (0,3), (0,4), (1,3), (1,4) are all `X`. (2x2 block)
    (2,0) `A` -> Output (3,0), (3,1), (4,0), (4,1) are all `A`. (2x2 block)
    (2,2) `A` -> Output (3,3), (3,4), (4,3), (4,4) are all `A`. (2x2 block)

    Let's check the edges (non-corners) of the Input:
    (0,1) `G` -> Output (0,2), (1,2) are `G`. (2x1 block vertically)
    (1,0) `B` -> Output (2,0), (2,1) are `B`. (1x2 block horizontally)
    (1,2) `A` -> Output (2,3), (2,4) are `A`. (1x2 block horizontally)
    (2,1) `G` -> Output (3,2), (4,2) are `G`. (2x1 block vertically)

    Let's check the center of the Input:
    (1,1) `R` -> Output (2,2) is `R`. (1x1 block)

    **Hypothesis:**
    The transformation scales the grid.
    Input size: 3x3. Output size: 5x5.
    It looks like a specific scaling rule.
    Usually, scaling 3x3 to 5x5 isn't a uniform integer scale factor (5/3 is not integer).
    However, the description says "rooms along every exterior wall are widened, their footprint doubled".
    "The single room at the heart of the building keeps its original dimensions."

    Let's visualize the "footprint doubled".
    If a room is 1x1, doubling the footprint could mean 2x2.
    If the center is 1x1, it stays 1x1.
    If the perimeter rooms become 2x2, how do they fit?
    3x3 grid has 8 perimeter cells and 1 center cell.
    If all 8 perimeter cells became 2x2, the total size would be much larger.
    But they are adjacent.
    Let's look at the Output grid again.
    Rows 0, 1 correspond to Input Row 0.
    Rows 3, 4 correspond to Input Row 2.
    Row 2 corresponds to Input Row 1.
    Cols 0, 1 correspond to Input Col 0.
    Cols 3, 4 correspond to Input Col 2.
    Col 2 corresponds to Input Col 1.

    So, Input Row 0 expands to Output Rows 0, 1. (Height 2)
    Input Row 1 expands to Output Row 2. (Height 1)
    Input Row 2 expands to Output Rows 3, 4. (Height 2)

    Input Col 0 expands to Output Cols 0, 1. (Width 2)
    Input Col 1 expands to Output Col 2. (Width 1)
    Input Col 2 expands to Output Cols 3, 4. (Width 2)

    This matches the "exterior wall rooms widened" description.
    The "exterior wall" corresponds to the first and last rows/cols.
    The "heart" corresponds to the middle row/col.
    So, the rule is:
    - Expand the first row of the input to 2 rows in the output.
    - Expand the last row of the input to 2 rows in the output.
    - Keep the middle row of the input as 1 row in the output.
    - Expand the first column of the input to 2 columns in the output.
    - Expand the last column of the input to 2 columns in the output.
    - Keep the middle column of the input as 1 column in the outp

... [6751 chars truncated]
alt-7 warfare qwen3.5-122b: k=1
"A fortress that doubles its outer garrison walls but keeps only a single watchtower at the center of the keep."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9900 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** 3x3 grid.
*   **Output:** 5x5 grid.
*   **Metaphor:** "Fortify the perimeter", "every unit along the border digs in, reinforcing its position so each edge cell holds twice the ground", "unit at dead center remains a single post", "formation expands outward".
*   **Key Insight:** The input is 3x3, output is 5x5. This suggests an expansion. The description mentions "border" cells holding "twice the ground" and the "center" remaining a "single post". This sounds like a scaling or upscaling operation where border pixels are duplicated or expanded, while the center pixel stays as is (or is surrounded).
*   Let's look at the dimensions. 3x3 to 5x5.
    *   If it were a simple 2x scaling, 3x3 would become 6x6.
    *   If it were a specific expansion, maybe the corners and edges are treated differently.
    *   "Each edge cell holds twice the ground" -> Maybe edge cells become 2x2 blocks?
    *   "Unit at dead center remains a single post" -> The center cell (1,1) in 0-indexed 3x3 stays 1x1?
    *   "Entire formation expands outward" -> The 5x5 grid needs to accommodate this.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    B G X
    B R A
    A G A
    ```
    (3 rows, 3 columns)
*   **Output:**
    ```
    B B G X X
    B B G X X
    B B R A A
    A A G A A
    A A G A A
    ```
    (5 rows, 5 columns)

*   **Mapping Input to Output:**
    Let's denote Input cells as $I_{r,c}$ where $r, c \in \{0, 1, 2\}$.
    Let's denote Output cells as $O_{r,c}$ where $r, c \in \{0, 1, 2, 3, 4\}$.

    Input Center: $I_{1,1} = R$.
    Output Center: $O_{2,2} = R$.
    Wait, looking at the output:
    Row 0: B B G X X
    Row 1: B B G X X
    Row 2: B B R A A
    Row 3: A A G A A
    Row 4: A A G A A

    Let's check the corners of the input:
    $I_{0,0} = B$. Output top-left 2x2 block is B B / B B.
    $I_{0,2} = X$. Output top-right 2x2 block is X X / X X.
    $I_{2,0} = A$. Output bottom-left 2x2 block is A A / A A.
    $I_{2,2} = A$. Output bottom-right 2x2 block is A A / A A.

    Let's check the edges of the input:
    $I_{0,1} = G$. Output top-middle area.
    Rows 0-1, Cols 2-3?
    Row 0: ... G X X
    Row 1: ... G X X
    It looks like $I_{0,1}$ corresponds to the column of Gs in the output.
    Specifically, Output Col 2 is G G G G G? No.
    Output Col 2: G, G, R, G, G.
    Wait, let's look closer.
    Input:
    (0,0) B  (0,1) G  (0,2) X
    (1,0) B  (1,1) R  (1,2) A
    (2,0) A  (2,1) G  (2,2) A

    Output:
    (0,0) B (0,1) B (0,2) G (0,3) X (0,4) X
    (1,0) B (1,1) B (1,2) G (1,3) X (1,4) X
    (2,0) B (2,1) B (2,2) R (2,3) A (2,4) A
    (3,0) A (3,1) A (3,2) G (3,3) A (3,4) A
    (4,0) A (4,1) A (4,2) G (4,3) A (4,4) A

    Let's try to map Input coordinates to Output regions.
    Input (0,0) [B] -> Output (0,0), (0,1), (1,0), (1,1). A 2x2 block.
    Input (0,1) [G] -> Output (0,2), (1,2). A 2x1 block?
    Input (0,2) [X] -> Output (0,3), (0,4), (1,3), (1,4). A 2x2 block.
    Input (1,0) [B] -> Output (2,0), (2,1). A 1x2 block?
    Input (1,1) [R] -> Output (2,2). A 1x1 block.
    Input (1,2) [A] -> Output (2,3), (2,4). A 1x2 block?
    Input (2,0) [A] -> Output (3,0), (3,1), (4,0), (4,1). A 2x2 block.
    Input (2,1) [G] -> Output (3,2), (4,2). A 2x1 block?
    Input (2,2) [A] -> Output (3,3), (3,4), (4,3), (4,4). A 2x2 block.

    Let's verify this pattern.
    Corners (0,0), (0,2), (2,0), (2,2) become 2x2 blocks.
    Edges (0,1), (1,0), (1,2), (2,1) become 2x1 or 1x2 blocks.
    Center (1,1) becomes 1x1 block.

    Let's check the dimensions.
    Width: 2 (from col 0) + 1 (from col 1) + 2 (from col 2) = 5.
    Height: 2 (from row 0) + 1 (from row 1) + 2 (from row 2) = 5.
    This matches the 5x5 output size.

    So the rule is:
    - Corner cells ($I_{0,0}, I_{0,2}, I_{2,0}, I_{2,2}$) expand to 2x2 blocks.
    - Edge cells ($I_{0,1}, I_{1,0}, I_{1,2}, I_{2,1}$) expand to 2x1 (vertical) or 1x2 (horizontal) blocks.
      - Top/Bottom edges ($I_{0,1}, I_{2,1}$) expand vertically (height 2, width 1).
      - Left/Right edges ($I_{1,0}, I_{1,2}$) expand horizontally (height 1, width 2).
    - Center cell ($I_{1,1}$) stays 1x1.

    Let's re-verify with the example data.
    Input:
    B G X
    B R A
    A G A

    Output construction:
    Row 0-1, Col 0-1: $I_{0,0}$ (B) -> 2x2 B.
    Row 0-1, Col 2: $I_{0,1}$ (G) -> 2x1 G.
    Row 0-1, Col 3-4: $I_{0,2}$ (X) -> 2x2 X.
    Row 2, Col 0-1: $I_{1,0}$ (B) -> 1x2 B.
    Row 2, Col 2: $I_{1,1}$ (R) -> 1x1 R.
    Row 2, Col 3-4: $I_{1,2}$ (A) -> 1x2 A.
    Row 3-4, Col 0-1: $I_{2,0}$ (A) -> 2x2 A.
    Row 3-4, Col 2: $I_{2,1}$ (G) -> 2x1 G.
    Row 3-4, Col 3-4: $I_{2,2}$ (A) -> 2x2 A.

    Let's check the Example Output provided:
    B B G X X
    B B G X X
    B B R A A
    A A G A A
    A A G A A

    My constru

... [5040 chars truncated]
alt-8 theater qwen3.5-122b: fail
"A stage where the actors on the wings and in the back row deliver each line twice for emphasis, while the soloist at center stage speaks once, crystal clear."
Fail (best cell_acc=0.32 at k=1)
Best Attempt
vs
Expected
Reasoning (10532 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("3x3 stage", "nine performers").
*   **Output:** A 5x5 grid ("5x5 tableau").
*   **Transformation:** "Every performer along the edges of the stage echoes their presence, appearing to multiply." "The lone figure at center stage remains singular and still."
*   **Interpretation:**
    *   The input is 3x3.
    *   The output is 5x5.
    *   The center element of the 3x3 input stays as is (singular).
    *   The edge elements of the 3x3 input are "doubled" or "multiplied".
    *   Looking at the output size (5x5) vs input size (3x3), it suggests an expansion.
    *   Let's look at the specific mapping.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    B G X
    B R A
    A G A
    ```
    (3 rows, 3 columns)
*   **Output:**
    ```
    B B G X X
    B B G X X
    B B R A A
    A A G A A
    A A G A A
    ```
    (5 rows, 5 columns)

*   **Mapping Analysis:**
    *   Input Center: `R` (at row 1, col 1, 0-indexed).
    *   Output Center: `R` (at row 2, col 2, 0-indexed).
    *   Input Corners:
        *   Top-Left `B` -> Output Top-Left 2x2 block of `B`s?
            *   Output (0,0), (0,1), (1,0), (1,1) are all `B`.
        *   Top-Right `X` -> Output Top-Right 2x2 block of `X`s?
            *   Output (0,3), (0,4), (1,3), (1,4) are all `X`.
        *   Bottom-Left `A` -> Output Bottom-Left 2x2 block of `A`s?
            *   Output (3,0), (3,1), (4,0), (4,1) are all `A`.
        *   Bottom-Right `A` -> Output Bottom-Right 2x2 block of `A`s?
            *   Output (3,3), (3,4), (4,3), (4,4) are all `A`.
    *   Input Edges (non-corner):
        *   Top-Middle `G` -> Output Top-Middle 2x2 block of `G`s?
            *   Output (0,2), (1,2) are `G`. Wait, looking at the output:
            *   Row 0: B B G X X
            *   Row 1: B B G X X
            *   Row 2: B B R A A
            *   Row 3: A A G A A
            *   Row 4: A A G A A
            *   Let's check the columns.
            *   Col 0: B, B, B, A, A
            *   Col 1: B, B, B, A, A
            *   Col 2: G, G, R, G, G
            *   Col 3: X, X, A, A, A
            *   Col 4: X, X, A, A, A
    *   Let's re-evaluate the structure.
    *   Input indices: (r, c) where r, c in {0, 1, 2}.
    *   Output indices: (R, C) where R, C in {0, 1, 2, 3, 4}.
    *   It looks like each cell in the 3x3 input is expanded into a 2x2 block in the 5x5 output, *except* for the center one?
    *   If every cell was 2x2, the output would be 6x6.
    *   Since the output is 5x5, there is an overlap or a specific scaling rule.
    *   Let's look at the "Edge performers are doubled" metaphor.
    *   Input:
        (0,0) (0,1) (0,2)
        (1,0) (1,1) (1,2)
        (2,0) (2,1) (2,2)
    *   Output:
        (0,0) (0,1) (0,2) (0,3) (0,4)
        (1,0) (1,1) (1,2) (1,3) (1,4)
        (2,0) (2,1) (2,2) (2,3) (2,4)
        (3,0) (3,1) (3,2) (3,3) (3,4)
        (4,0) (4,1) (4,2) (4,3) (4,4)

    *   Let's trace the values from the example.
    *   Input (0,0) = B. Output block: (0,0), (0,1), (1,0), (1,1) are B.
    *   Input (0,1) = G. Output block: (0,2), (1,2) are G. Wait, (0,2) and (1,2) are G. What about (0,3)? That's X.
    *   Input (0,2) = X. Output block: (0,3), (0,4), (1,3), (1,4) are X.
    *   Input (1,0) = B. Output block: (2,0), (2,1) are B. Wait, (2,0) is B, (2,1) is B.
    *   Input (1,1) = R. Output block: (2,2) is R. Just one cell?
    *   Input (1,2) = A. Output block: (2,3), (2,4) are A.
    *   Input (2,0) = A. Output block: (3,0), (3,1), (4,0), (4,1) are A.
    *   Input (2,1) = G. Output block: (3,2), (4,2) are G.
    *   Input (2,2) = A. Output block: (3,3), (3,4), (4,3), (4,4) are A.

    *   Let's look at the pattern of expansion.
    *   It seems like the grid is being scaled up.
    *   Input 3x3 -> Output 5x5.
    *   This looks like a "zoom" where the center pixel is 1x1, and the surrounding pixels are expanded to fill the space.
    *   Actually, let's look at the coordinates mapping.
    *   Input (0,0) -> Output (0,0), (0,1), (1,0), (1,1). (2x2)
    *   Input (0,1) -> Output (0,2), (1,2). (2x1 vertical strip?) No, look at row 0 and 1.
        *   Row 0: B B G X X
        *   Row 1: B B G X X
        *   So Input (0,1) 'G' maps to Output (0,2) and (1,2).
    *   Input (0,2) -> Output (0,3), (0,4), (1,3), (1,4). (2x2)
    *   Input (1,0) -> Output (2,0), (2,1). (1x2 horizontal strip?)
        *   Row 2: B B R A A
        *   So Input (1,0) 'B' maps to Output (2,0) and (2,1).
    *   Input (1,1) -> Output (2,2). (1x1)
    *   Input (1,2) -> Output (2,3), (2,4). (1x2 horizontal strip?)
        *   Row 2: B B R A A
        *   So Input (1,2) 'A' maps to Output (2,3) and (2,4).
    *   Input (2,0) -> Output (3,0), (3,1), (4,0), (4,1). (2x2)
    *   Input (2,1) -> Output (3,2), (4,2). (2x1 vertical strip?)
  

... [5634 chars truncated]
alt-9 gardening qwen3.5-122b: k=1
"A raised bed whose border plants are set in double rows for a lush hedge effect, while the centerpiece stands alone."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11342 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A 3x3 grid ("3x3 garden plot").
*   **Output:** A 5x5 grid ("Output is a 5x5 bed").
*   **Action:** "Fill in the borders: every plant along the edge of the bed is paired with an identical clone beside it, thickening the garden's frame."
*   **Center:** "The single plant at the very center stays solitary."
*   **Expansion:** "The garden expands into a lusher, wider plot without introducing new varieties."
*   **Specifics:** "perimeter rows are doubled."

**2. Analyze the Training Example:**
*   **Input:**
    ```
    B G X
    B R A
    A G A
    ```
    (3 rows, 3 columns)
*   **Output:**
    ```
    B B G X X
    B B G X X
    B B R A A
    A A G A A
    A A G A A
    ```
    (5 rows, 5 columns)

**3. Conceptual Digestion:**

*   **CAST:**
    *   Input Grid: 3x3 matrix of colors.
    *   Output Grid: 5x5 matrix of colors.
    *   Elements: Individual cells containing color codes.

*   **AFFORDANCES:**
    *   Cells can be duplicated.
    *   Rows can be duplicated.
    *   Columns can be duplicated.
    *   The center cell remains unique (in terms of position relative to the expansion).

*   **TRANSFORMATION RULE:**
    Let's look at the mapping from Input (3x3) to Output (5x5).
    Let Input be $I$ with indices $i, j \in \{0, 1, 2\}$.
    Let Output be $O$ with indices $r, c \in \{0, 1, 2, 3, 4\}$.

    Let's check the rows of the output against the input.
    Input Row 0: `B G X`
    Output Row 0: `B B G X X`
    Output Row 1: `B B G X X`
    It looks like Input Row 0 is expanded horizontally. `B` becomes `B B`, `G` becomes `G`, `X` becomes `X X`. Wait, looking closely at Output Row 0: `B B G X X`.
    Input Row 0 is `B G X`.
    If we double the first and last columns: `B` -> `B B`, `G` -> `G`, `X` -> `X X`.
    So Row 0 becomes `B B G X X`.
    Row 1 of Output is identical to Row 0 of Output.
    So Input Row 0 generates Output Rows 0 and 1.

    Input Row 1: `B R A`
    Output Row 2: `B B R A A`
    Output Row 3: `A A G A A` -> Wait, this doesn't match Input Row 1 directly.
    Let's re-examine the Output.
    Output:
    R0: B B G X X
    R1: B B G X X
    R2: B B R A A
    R3: A A G A A
    R4: A A G A A

    Let's look at the columns.
    Input Col 0: B, B, A
    Input Col 1: G, R, G
    Input Col 2: X, A, A

    Output Col 0: B, B, B, A, A
    Output Col 1: B, B, B, A, A
    Output Col 2: G, G, R, G, G
    Output Col 3: X, X, A, A, A
    Output Col 4: X, X, A, A, A

    Let's try to map Input $(i, j)$ to Output $(r, c)$.
    The output size is 5x5. The input is 3x3.
    This suggests a scaling factor. $3 \to 5$ isn't a simple integer scaling like $2 \times$.
    However, the description says "perimeter rows are doubled".
    Input Rows: 0, 1, 2.
    Output Rows: 0, 1, 2, 3, 4.
    It seems Input Row 0 maps to Output Rows 0 and 1.
    Input Row 1 maps to Output Row 2.
    Input Row 2 maps to Output Rows 3 and 4.
    Let's verify this vertical mapping.
    Input Row 0: `B G X` -> Output Rows 0, 1 should be based on this.
    Output Row 0: `B B G X X`
    Output Row 1: `B B G X X`
    So Input Row 0 is expanded horizontally to `B B G X X` and duplicated vertically.

    Input Row 1: `B R A` -> Output Row 2 should be based on this.
    Output Row 2: `B B R A A`
    This matches the horizontal expansion pattern: First col doubled, middle col single, last col doubled.
    `B` -> `B B`
    `R` -> `R`
    `A` -> `A A`
    So `B R A` -> `B B R A A`.
    This matches Output Row 2.

    Input Row 2: `A G A` -> Output Rows 3, 4 should be based on this.
    Output Row 3: `A A G A A`
    Output Row 4: `A A G A A`
    Horizontal expansion: `A` -> `A A`, `G` -> `G`, `A` -> `A A`.
    Result: `A A G A A`.
    This matches Output Rows 3 and 4.

    **Rule Synthesis:**
    1.  **Horizontal Expansion:** For each row in the input, expand it horizontally.
        *   The first element (column 0) is duplicated (becomes 2 columns).
        *   The middle element (column 1) stays single (becomes 1 column).
        *   The last element (column 2) is duplicated (becomes 2 columns).
        *   Total width: $2 + 1 + 2 = 5$.
    2.  **Vertical Expansion:** For each row in the input, duplicate it vertically.
        *   The first row (row 0) is duplicated (becomes 2 rows).
        *   The middle row (row 1) stays single (becomes 1 row).
        *   The last row (row 2) is duplicated (becomes 2 rows).
        *   Total height: $2 + 1 + 2 = 5$.

    **Verification with Example 1:**
    Input:
    R0: B G X
    R1: B R A
    R2: A G A

    Step 1: Horizontal Expansion (Col 0 -> 2, Col 1 -> 1, Col 2 -> 2)
    R0': B B G X X
    R1': B B R A A
    R2': A A G A A

    Step 2: Vertical Expansion (Row 0 -> 2, Row 1 -> 1, Row 2 -> 2)
    Out R0: R0' (B B G X X)
    Out R1: R0' (B B G X X)
    Out R2: R1

... [6534 chars truncated]

Task 971: f8b3ba0a

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A popularity contest among rare wildflowers in a vast meadow MARC valid 2
alt-1 biology A cell colony where the dominant species overwhelms the culture dish, but the re ... [44 chars truncated] MARC valid 1
alt-10 astronomy An astronomer filtering out the background stars to catalog the unusual objects ... [15 chars truncated] MARC valid 1
alt-11 ocean/sailing A harbor master logging the foreign flags among a fleet of local vessels fig alone solves
alt-12 electronics A technician scanning a circuit board for the components that differ from the st ... [16 chars truncated] fig alone solves
alt-13 mythology A pantheon of forgotten gods — the mortal masses worship one deity, but th ... [70 chars truncated] MARC valid 2
alt-14 dance A choreographer noting which guest dancers appear on a stage full of corps de ba ... [15 chars truncated] fig alone solves
alt-15 geology A geologist core-sampling a uniform sediment layer to find and rank the trace mi ... [16 chars truncated] MARC valid 1
alt-2 cooking Picking out the spices from a pot of plain rice MARC valid 1
alt-3 music An orchestra tuning up — the drone of the strings drowns everything, but t ... [37 chars truncated] MARC valid 3
alt-4 sports A stadium full of home fans with pockets of away supporters — the announce ... [26 chars truncated] fig alone solves
alt-5 weather A meteorologist scanning a radar map of calm skies for scattered storm cells MARC valid 2
alt-6 architecture A city inspector cataloging the odd buildings in a neighborhood of identical hou ... [3 chars truncated] MARC valid 1
alt-7 warfare A general surveying a battlefield map, ignoring his own legions to count the sca ... [20 chars truncated] fig alone solves
alt-8 theater A casting director reviewing headshots pinned to a board — most are extras ... [27 chars truncated] MARC valid 3
alt-9 gardening A groundskeeper inventorying the unusual blooms that have sprouted among the uni ... [17 chars truncated] fig alone solves
original qwen3.5-122b: k=2
"A popularity contest among rare wildflowers in a vast meadow"
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10437 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A meadow with patches of flowers.
*   **Dominant Element:** "One species dominates the landscape so thoroughly it has become the grass itself — the wallpaper of the world." This implies there is a background color that is ignored.
*   **Rare Elements:** "Scattered among this sea of sameness, a few rare wildflowers have taken root." These are the non-background colors.
*   **Structure:** "Each flower bed is a small square plot, and the black soil paths between them form a quiet grid." This suggests the input grid consists of blocks of colors separated by black lines (dots `.`).
*   **Task:** "The keeper's final report is a single column in her ledger — one flower color per line, written top to bottom from the most commonly spotted rarity down to the loneliest bloom in the field."
*   **Transformation Rule:**
    1.  Identify the background color (the "grass").
    2.  Identify the "flower beds" (blocks of non-background colors).
    3.  Count the occurrences of each distinct non-background color.
    4.  Sort these colors by frequency (count) in descending order (most common to least common).
    5.  Output a single column grid containing these colors in that sorted order.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Grid: 13 rows, 10 columns.
    *   Background: `.` (black).
    *   Structure: Rows 1, 3, 5, 7, 9, 11, 13 are all `.`. Rows 2, 4, 6, 8, 10, 12 contain colored blocks.
    *   Let's look at the colored blocks. They seem to be 2x2 blocks or similar.
    *   Row 2: `. G G . G G . G G .` -> Three `G` blocks.
    *   Row 4: `. B B . G G . G G .` -> One `B` block, Two `G` blocks.
    *   Row 6: `. G G . A A . G G .` -> Two `G` blocks, One `A` block.
    *   Row 8: `. G G . A A . G G .` -> Two `G` blocks, One `A` block.
    *   Row 10: `. G G . R R . R R .` -> One `G` block, Two `R` blocks.
    *   Row 12: `. R R . G G . G G .` -> Two `R` blocks, Two `G` blocks.
    *   Wait, let's look closer at the structure.
    *   The grid is 13x10.
    *   Rows 0, 2, 4, 6, 8, 10, 12 (0-indexed) are all `.`.
    *   Rows 1, 3, 5, 7, 9, 11 contain the data.
    *   In Row 1: `G G` at cols 1-2, `G G` at cols 4-5, `G G` at cols 7-8.
    *   In Row 3: `B B` at cols 1-2, `G G` at cols 4-5, `G G` at cols 7-8.
    *   In Row 5: `G G` at cols 1-2, `A A` at cols 4-5, `G G` at cols 7-8.
    *   In Row 7: `G G` at cols 1-2, `A A` at cols 4-5, `G G` at cols 7-8.
    *   In Row 9: `G G` at cols 1-2, `R R` at cols 4-5, `R R` at cols 7-8.
    *   In Row 11: `R R` at cols 1-2, `G G` at cols 4-5, `G G` at cols 7-8.
    *   It seems the "flower beds" are 2x2 blocks of color.
    *   Let's count the blocks.
    *   `G`: Row 1 (3), Row 3 (2), Row 5 (2), Row 7 (2), Row 9 (1), Row 11 (2). Total = 3+2+2+2+1+2 = 12 blocks.
    *   `B`: Row 3 (1). Total = 1 block.
    *   `A`: Row 5 (1), Row 7 (1). Total = 2 blocks.
    *   `R`: Row 9 (2), Row 11 (2). Total = 4 blocks.
    *   Counts: G=12, R=4, A=2, B=1.
    *   Output:
        R
        A
        B
    *   Wait, the output is R, A, B.
    *   My counts: G=12, R=4, A=2, B=1.
    *   The output excludes G. Why?
    *   Metaphor says: "One species dominates the landscape so thoroughly it has become the grass itself — the wallpaper of the world. But scattered among this sea of sameness, a few rare wildflowers have taken root... She walks every plot, ignoring the common ground-cover entirely — it is invisible to her practiced eye."
    *   So, the most frequent color is considered the "grass" (background) and is ignored in the count/report.
    *   In Example 1, G is the most frequent (12 blocks). So G is the grass.
    *   Remaining colors: R (4), A (2), B (1).
    *   Sorted by frequency descending: R, A, B.
    *   Output matches: R, A, B.

*   **Example 2:**
    *   Input Grid: 13 rows, 16 columns.
    *   Background: `.`.
    *   Rows with data: 1, 3, 5, 7, 9, 11.
    *   Blocks appear to be 2x2.
    *   Row 1: `M M`, `A A`, `A A`, `A A`, `A A`. (1 M, 4 A)
    *   Row 3: `A A`, `A A`, `R R`, `M M`, `A A`. (3 A, 1 R, 1 M)
    *   Row 5: `B B`, `A A`, `B B`, `A A`, `A A`. (3 A, 2 B)
    *   Row 7: `A A`, `B B`, `A A`, `A A`, `A A`. (4 A, 1 B)
    *   Row 9: `A A`, `A A`, `M M`, `A A`, `M M`. (3 A, 2 M)
    *   Row 11: `A A`, `A A`, `A A`, `A A`, `A A`. (5 A)
    *   Let's sum up the blocks.
    *   `A`: 4 + 3 + 3 + 4 + 3 + 5 = 22 blocks.
    *   `M`: 1 + 1 + 2 = 4 blocks.
    *   `R`: 1 block.
    *   `B`: 2 + 1 = 3 blocks.
    *   Counts: A=22, M=4, B=3, R=1.
    *   Most frequent is A. So A is the "grass".
    *   Remaining colors: M (4), B (3), R (1).
    *   Sorted descending: M, B, R.
    *   Output:
        M
        B
        R
    *   Matches the example output.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Grid:** The input is 

... [5500 chars truncated]
alt-1 biology qwen3.5-122b: k=1
"A cell colony where the dominant species overwhelms the culture dish, but the researcher only cares about the rare mutations"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10811 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A tissue sample with cells in a matrix.
*   **Dominant Colony:** One cell type vastly outnumbers all others.
*   **Mutant Strains:** Clusters of mutant cells in different colors.
*   **Task:** Ignore the dominant colony. Catalog each mutant strain by how many clusters it has formed.
*   **Output Format:** A single narrow column (one row per mutant strain).
*   **Ordering:** Most prolific (most clusters) to least prolific (fewest clusters).
*   **Coloring:** The output cells are colored to match the mutant strain.

**2. Analyze the Training Example 1:**
*   **Input Grid:**
    *   Size: 13 rows x 10 columns (approx, let's count).
    *   Rows:
        1.  . . . . . . . . . .
        2.  . G G . G G . G G .
        3.  . . . . . . . . . .
        4.  . B B . G G . G G .
        5.  . . . . . . . . . .
        6.  . G G . A A . G G .
        7.  . . . . . . . . . .
        8.  . G G . A A . G G .
        9.  . . . . . . . . . .
        10. . G G . R R . R R .
        11. . . . . . . . . . .
        12. . R R . G G . G G .
        13. . . . . . . . . . .
    *   Colors present: G (Green), B (Blue), A (Azure), R (Red).
    *   Background: . (Black/Empty).
    *   Let's count the clusters of each color.
    *   **Green (G):**
        *   Row 2: (2,2)-(2,3), (2,5)-(2,6), (2,8)-(2,9) -> 3 clusters? Or are they connected?
        *   Let's look at the structure. It seems to be a grid of 2x2 blocks separated by empty rows/cols.
        *   Row 2: G G . G G . G G . (3 blocks of G)
        *   Row 4: . B B . G G . G G . (1 block of B, 2 blocks of G)
        *   Row 6: . G G . A A . G G . (2 blocks of G, 1 block of A)
        *   Row 8: . G G . A A . G G . (2 blocks of G, 1 block of A)
        *   Row 10: . G G . R R . R R . (1 block of G, 2 blocks of R)
        *   Row 12: . R R . G G . G G . (1 block of R, 2 blocks of G)
        *   Total G blocks: 3 + 2 + 2 + 2 + 1 + 2 = 12 blocks.
        *   Total B blocks: 1 block.
        *   Total A blocks: 1 + 1 = 2 blocks.
        *   Total R blocks: 2 + 1 = 3 blocks.
    *   **Dominant Colony:** Green (G) has 12 blocks. It vastly outnumbers others.
    *   **Mutant Strains:** B, A, R.
    *   **Cluster Counts:**
        *   R: 3 clusters.
        *   A: 2 clusters.
        *   B: 1 cluster.
    *   **Output Grid:**
        *   R
        *   A
        *   B
    *   **Observation:** The output is a single column. The colors correspond to the mutant strains. The order is R (3), A (2), B (1). This matches "most prolific to least prolific".
    *   **Output Dimensions:** 3 rows, 1 column.

**3. Analyze the Test Input:**
*   **Input Grid:**
    *   Rows: 15 rows.
    *   Cols: 13 columns.
    *   Pattern: Similar to training. Rows of dots, rows of colored blocks.
    *   Let's identify the blocks. It looks like 2x2 blocks of color separated by single rows/cols of dots.
    *   Let's list the non-empty rows and the blocks within them.
    *   Row 2: . R R . Y Y . R R . R R .
        *   Blocks: R, Y, R, R. (3 R blocks, 1 Y block)
    *   Row 4: . B B . R R . Y Y . R R .
        *   Blocks: B, R, Y, R. (2 R blocks, 1 B block, 1 Y block)
    *   Row 6: . A A . R R . R R . A A .
        *   Blocks: A, R, R, A. (2 R blocks, 2 A blocks)
    *   Row 8: . R R . R R . B B . R R .
        *   Blocks: R, R, B, R. (3 R blocks, 1 B block)
    *   Row 10: . Y Y . R R . R R . R R .
        *   Blocks: Y, R, R, R. (3 R blocks, 1 Y block)
    *   Row 12: . R R . B B . R R . Y Y .
        *   Blocks: R, B, R, Y. (2 R blocks, 1 B block, 1 Y block)
    *   Row 14: . R R . R R . Y Y . R R .
        *   Blocks: R, R, Y, R. (3 R blocks, 1 Y block)

*   **Counting Clusters:**
    *   **Red (R):**
        *   Row 2: 3
        *   Row 4: 2
        *   Row 6: 2
        *   Row 8: 3
        *   Row 10: 3
        *   Row 12: 2
        *   Row 14: 3
        *   Total R = 3 + 2 + 2 + 3 + 3 + 2 + 3 = 18 blocks.
    *   **Yellow (Y):**
        *   Row 2: 1
        *   Row 4: 1
        *   Row 10: 1
        *   Row 12: 1
        *   Row 14: 1
        *   Total Y = 1 + 1 + 1 + 1 + 1 = 5 blocks.
    *   **Blue (B):**
        *   Row 4: 1
        *   Row 8: 1
        *   Row 12: 1
        *   Total B = 1 + 1 + 1 = 3 blocks.
    *   **Azure (A):**
        *   Row 6: 2
        *   Total A = 2 blocks.

*   **Identify Dominant Colony:**
    *   Red (R) has 18 blocks.
    *   Yellow (Y) has 5 blocks.
    *   Blue (B) has 3 blocks.
    *   Azure (A) has 2 blocks.
    *   Red is clearly the dominant colony ("vastly outnumbers all others").

*   **Identify Mutant Strains:**
    *   Y (Yellow)
    *   B (Blue)
    *   A (Azure)

*   **Order by Prolificacy (Cluster Count):**
    *   Y: 5 clusters
    *   B: 3 clusters
    *   A: 2 clusters

*   **Construct Output:**
    *   Single column.
    *   Row 1: Y (Yellow)
    *   Row 2: B (Blue)
    *   Row 

... [5856 chars truncated]
alt-10 astronomy qwen3.5-122b: k=1
"An astronomer filtering out the background stars to catalog the unusual objects in a star field"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11902 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A telescope's field of view (grid).
*   **Content:** Most cells have a "common stellar classification" (background). A few cells have "unusual spectral signatures" (anomalies).
*   **Task:**
    1.  Filter out the dominant background.
    2.  Catalog each anomalous spectral signature.
    3.  Count occurrences of each anomaly.
    4.  Publish findings: A single column list of anomalies, ordered from most frequent to rarest.
*   **Output Format:** A single column grid (one spectral color per entry).

**2. Analyze the Training Example 1:**
*   **Input Grid:**
    ```
    . . . . . . . . . .
    . G G . G G . G G .
    . . . . . . . . . .
    . B B . G G . G G .
    . . . . . . . . . .
    . G G . A A . G G .
    . . . . . . . . . .
    . G G . A A . G G .
    . . . . . . . . . .
    . G G . R R . R R .
    . . . . . . . . . .
    . R R . G G . G G .
    . . . . . . . . . .
    ```
    *   Grid size: 13 rows x 10 columns.
    *   Colors present: `.` (black), `G` (green), `B` (blue), `A` (azure), `R` (red).
    *   Let's count the occurrences of each non-background color.
    *   Background seems to be `.` (black) or `G` (green)?
    *   Looking at the structure: There are rows of dots `.` separating rows of colored blocks.
    *   Rows with colors: 2, 4, 6, 8, 10, 12.
    *   Row 2: `G G . G G . G G` -> 6 Gs.
    *   Row 4: `B B . G G . G G` -> 2 Bs, 4 Gs.
    *   Row 6: `G G . A A . G G` -> 4 Gs, 2 As.
    *   Row 8: `G G . A A . G G` -> 4 Gs, 2 As.
    *   Row 10: `G G . R R . R R` -> 2 Gs, 4 Rs.
    *   Row 12: `R R . G G . G G` -> 2 Rs, 4 Gs.
    *   Total counts:
        *   G: 6 + 4 + 4 + 4 + 2 + 4 = 24.
        *   B: 2.
        *   A: 2 + 2 = 4.
        *   R: 4 + 2 = 6.
        *   .: Many.
    *   The "dominant stellar background" is likely `G` (green) because it appears most frequently among the colored cells, or `.` (black) if we consider the whole grid. However, the metaphor says "Most cells contain the same common stellar classification". In the input, `.` is the most frequent character overall. But usually, in these puzzles, the "background" is the color that forms the pattern or is the most common non-empty color. Let's look at the output.
    *   **Output:**
        ```
        R
        A
        B
        ```
    *   This is a single column.
    *   The colors listed are R, A, B.
    *   Counts from my analysis: R=6, A=4, B=2.
    *   Order: Most frequent to rarest.
    *   R (6) > A (4) > B (2).
    *   This matches the output order.
    *   So, the rule is: Identify the non-background colors. Count their total occurrences in the grid. Sort them by count descending. Output them as a single column.
    *   What is the background? In this example, `.` is clearly the separator/empty space. `G` is the most frequent color among the "objects". If `G` were the background, it would be filtered out. The output lists R, A, B. `G` is not in the output. This implies `G` is the "dominant stellar background" (common classification) and `R`, `A`, `B` are the "anomalous spectral signatures".
    *   Wait, let's re-read the metaphor: "Most cells contain the same common stellar classification." In the input grid, `.` is the most common character. But `G` is the most common *colored* character. The output excludes `G`. So `G` is treated as the background/common classification. `.` is likely just empty space or noise, but `G` is the "common stellar classification".
    *   Let's check the counts again.
        *   G: 24
        *   R: 6
        *   A: 4
        *   B: 2
    *   If `G` is the background, we filter it out. We are left with R, A, B.
    *   Sort by frequency: R (6), A (4), B (2).
    *   Output matches.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    . . . . . . . . . . . . .
    . R R . Y Y . R R . R R .
    . . . . . . . . . . . . .
    . B B . R R . Y Y . R R .
    . . . . . . . . . . . . .
    . A A . R R . R R . A A .
    . . . . . . . . . . . . .
    . R R . R R . B B . R R .
    . . . . . . . . . . . . .
    . Y Y . R R . R R . R R .
    . . . . . . . . . . . . .
    . R R . B B . R R . Y Y .
    . . . . . . . . . . . . .
    . R R . R R . Y Y . R R .
    . . . . . . . . . . . . .
    ```
    *   Grid size: 15 rows x 13 columns.
    *   Colors present: `.` (black), `R` (red), `Y` (yellow), `B` (blue), `A` (azure).
    *   Structure: Similar to training example. Rows of dots separating rows of colored blocks.
    *   Let's count the occurrences of each colored cell.
    *   Row 2: `R R . Y Y . R R . R R` -> 6 Rs, 2 Ys.
    *   Row 4: `B B . R R . Y Y . R R` -> 2 Bs, 4 Rs, 2 Ys.
    *   Row 6: `A A . R R . R R . A A` -> 2 As, 4 Rs.
    *   Row 8: `R R . R R . B B . R R` -> 6 Rs, 2 Bs.
    *   Row 10: `Y Y . R R . R R . R R` -> 2 Ys, 6 Rs.
    *   Row 12: `R R . B

... [6977 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fig alone solves
"A harbor master logging the foreign flags among a fleet of local vessels"
alt-12 electronics qwen3.5-122b: fig alone solves
"A technician scanning a circuit board for the components that differ from the standard resistors"
alt-13 mythology qwen3.5-122b: k=2
"A pantheon of forgotten gods — the mortal masses worship one deity, but the oracle must rank the minor gods by the size of their remaining cults"
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10116 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A temple mosaic with uniform tiles.
*   **Dominant Deity:** Most tiles bear the sigil of the dominant deity. This implies there is a background color or a most frequent color that acts as the "canvas" or "background".
*   **Lesser Gods:** Scattered tiles carry marks of lesser gods in different sacred colors. These are the non-dominant colors.
*   **Task:** Set aside the dominant deity's sigil (ignore the background color). Count the tiles devoted to each lesser god (count the occurrences of each non-background color).
*   **Output:** Deliver the oracle's pronouncement ranking the minor deities from the one with the largest following to the smallest.
*   **Output Format:** A single column, one sacred color per line, listing minor deities from largest count to smallest count.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input Grid:**
    ```
    . . . . . . . . . .
    . G G . G G . G G .
    . . . . . . . . . .
    . B B . G G . G G .
    . . . . . . . . . .
    . G G . A A . G G .
    . . . . . . . . . .
    . G G . A A . G G .
    . . . . . . . . . .
    . G G . R R . R R .
    . . . . . . . . . .
    . R R . G G . G G .
    . . . . . . . . . .
    ```
*   **Colors present:** `.` (black), `G` (green), `B` (blue), `A` (azure), `R` (red).
*   **Dominant Color:** Looking at the grid, `.` (black) is the background grid lines. `G` (green) appears very frequently. Let's count.
    *   Row 2: 6 Gs
    *   Row 4: 2 Gs, 2 Bs
    *   Row 6: 4 Gs, 2 As
    *   Row 8: 4 Gs, 2 As
    *   Row 10: 2 Gs, 4 Rs
    *   Row 12: 2 Gs, 2 Rs
    *   Total G: 6 + 2 + 4 + 4 + 2 + 2 = 20.
    *   Total `.`: Many. But usually, in these puzzles, the "background" is the most frequent color. However, the description says "Most tiles bear the sigil of the dominant deity". In the visual representation, `.` is often the empty space. Let's look at the non-dot colors.
    *   Non-dot colors: G, B, A, R.
    *   Counts:
        *   G: 20
        *   B: 2
        *   A: 4
        *   R: 6
    *   If `G` is the dominant deity (most frequent non-background color), then we ignore `G`.
    *   Remaining colors: B (2), A (4), R (6).
    *   Ranking from largest to smallest: R (6), A (4), B (2).
    *   Output:
        ```
        R
        A
        B
        ```
    *   This matches the example output.
    *   **Hypothesis:** Identify the most frequent non-background color (excluding `.`). This is the "dominant deity". Ignore it. Count the remaining colors. Sort them by count descending. Output the color codes in a single column.

**Example 2:**
*   **Input Grid:**
    ```
    . . . . . . . . . . . . . . . .
    . M M . A A . A A . A A . A A .
    . . . . . . . . . . . . . . . .
    . A A . A A . R R . M M . A A .
    . . . . . . . . . . . . . . . .
    . B B . A A . B B . A A . A A .
    . . . . . . . . . . . . . . . .
    . A A . B B . A A . A A . A A .
    . . . . . . . . . . . . . . . .
    . A A . A A . M M . A A . M M .
    . . . . . . . . . . . . . . . .
    . A A . A A . A A . A A . A A .
    . . . . . . . . . . . . . . . .
    ```
*   **Colors present:** `.`, `M`, `A`, `R`, `B`.
*   **Counts of non-dot colors:**
    *   Row 2: 2 M, 8 A
    *   Row 4: 4 A, 2 R, 2 M
    *   Row 6: 2 B, 4 A, 2 B, 2 A -> 4 B, 6 A
    *   Row 8: 2 A, 2 B, 6 A -> 2 B, 8 A
    *   Row 10: 4 A, 2 M, 4 A -> 2 M, 8 A
    *   Row 12: 8 A
    *   Let's sum them up carefully.
    *   **A (Azure):**
        *   Row 2: 8
        *   Row 4: 4 + 2 = 6
        *   Row 6: 4 + 2 = 6
        *   Row 8: 2 + 6 = 8
        *   Row 10: 4 + 4 = 8
        *   Row 12: 8
        *   Total A = 8 + 6 + 6 + 8 + 8 + 8 = 44.
    *   **M (Magenta):**
        *   Row 2: 2
        *   Row 4: 2
        *   Row 10: 2
        *   Total M = 6.
    *   **R (Red):**
        *   Row 4: 2
        *   Total R = 2.
    *   **B (Blue):**
        *   Row 6: 4
        *   Row 8: 2
        *   Total B = 6.
    *   **Dominant Deity:** `A` (44 occurrences).
    *   **Lesser Gods:** M (6), B (6), R (2).
    *   **Ranking:** M and B are tied at 6. R is 2.
    *   **Output:**
        ```
        M
        B
        R
        ```
    *   Wait, the output is M, B, R.
    *   My counts: M=6, B=6, R=2.
    *   Why M before B? Alphabetical? Or order of appearance?
    *   Let's check order of appearance.
        *   Row 2: M appears first (col 2), A appears later.
        *   Row 4: A, R, M.
        *   Row 6: B, A.
        *   First appearance of M is Row 2. First appearance of B is Row 6.
        *   So M comes before B in reading order.
    *   Let's check Example 1 for tie-breaking.
        *   Counts: R=6, A=4, B=2. No ties.
    *   So for ties, likely reading order (top-to-bottom, left-to-right) of the first occurrence of that color.
    *   Let's re-verify Example 2 counts.
        *   Row 2: M M (2), A A A

... [5125 chars truncated]
alt-14 dance qwen3.5-122b: fig alone solves
"A choreographer noting which guest dancers appear on a stage full of corps de ballet performers"
alt-15 geology qwen3.5-122b: k=1
"A geologist core-sampling a uniform sediment layer to find and rank the trace mineral intrusions"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11234 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A cross-section of bedrock divided into a grid.
*   **Dominant Mineral:** Most cells contain the same dominant mineral. This implies there is a background color that appears most frequently or forms a matrix.
*   **Intrusions:** A few cells hold intrusions of different colored minerals.
*   **Task:** Disregard the dominant mineral matrix. Identify each trace mineral by its color and count the cells it occupies.
*   **Output Format:** An assay report (single column). List trace minerals from most abundant to rarest.
*   **Grid Details:** The output is a single column, one color per row.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input Grid:** 13 rows x 10 columns.
    *   **Colors present:** `.` (black), `G` (green), `B` (blue), `A` (azure), `R` (red).
    *   **Observation:**
        *   `.` appears in rows 0, 2, 4, 6, 8, 10, 12 (all columns). It seems to be the separator or background.
        *   `G` appears in blocks.
        *   `B` appears in one block.
        *   `A` appears in one block.
        *   `R` appears in blocks.
    *   **Dominant Mineral:** The description says "Most cells contain the same dominant mineral". Looking at the grid, `.` (black) is very frequent, but `G` (green) also appears quite a bit. However, the metaphor says "Disregard the dominant mineral matrix". Usually, in these puzzles, the background color (often black `.`) is the matrix. Let's look at the counts.
        *   `.`: 7 rows * 10 cols = 70 cells.
        *   `G`: Rows 1, 3, 5, 7, 9, 11.
            *   Row 1: 4 Gs.
            *   Row 3: 4 Gs.
            *   Row 5: 4 Gs.
            *   Row 7: 4 Gs.
            *   Row 9: 4 Gs.
            *   Row 11: 4 Gs.
            *   Total G = 24.
        *   `B`: Row 3, cols 1-2. Total 2.
        *   `A`: Rows 5, 7, cols 5-6. Total 4.
        *   `R`: Rows 9, 11.
            *   Row 9: 4 Rs.
            *   Row 11: 2 Rs.
            *   Total R = 6.
    *   **Output:**
        ```
        R
        A
        B
        ```
    *   **Interpretation:**
        *   The output lists colors `R`, `A`, `B`.
        *   Counts: R=6, A=4, B=2.
        *   Order: Most abundant to rarest.
        *   `G` (24) is excluded. Why? The description says "Disregard the dominant mineral matrix". `G` is the second most frequent color, but `.` is the most frequent. However, `G` forms a pattern (a grid of 2x2 blocks separated by `.`). `B`, `A`, `R` are "intrusions" replacing `G` in some blocks.
        *   Wait, let's look closer at the structure.
        *   The grid seems to be composed of 2x2 blocks separated by lines of `.`.
        *   Rows 1, 3, 5, 7, 9, 11 contain the colored blocks.
        *   Columns 1-2, 5-6, 9-10 contain the colored blocks.
        *   So there are 6 rows of blocks and 3 columns of blocks. Total 18 potential block positions.
        *   Let's check the content of these 2x2 blocks.
            *   (Row 1, Cols 1-2): G G
            *   (Row 1, Cols 5-6): G G
            *   (Row 1, Cols 9-10): G G
            *   (Row 3, Cols 1-2): B B (Intrusion)
            *   (Row 3, Cols 5-6): G G
            *   (Row 3, Cols 9-10): G G
            *   (Row 5, Cols 1-2): G G
            *   (Row 5, Cols 5-6): A A (Intrusion)
            *   (Row 5, Cols 9-10): G G
            *   (Row 7, Cols 1-2): G G
            *   (Row 7, Cols 5-6): A A (Intrusion)
            *   (Row 7, Cols 9-10): G G
            *   (Row 9, Cols 1-2): G G
            *   (Row 9, Cols 5-6): R R (Intrusion)
            *   (Row 9, Cols 9-10): R R (Intrusion)
            *   (Row 11, Cols 1-2): R R (Intrusion)
            *   (Row 11, Cols 5-6): G G
            *   (Row 11, Cols 9-10): G G
        *   So the "Dominant Mineral" is Green (`G`). It fills most of the block positions.
        *   The "Intrusions" are `B`, `A`, `R`.
        *   Count of Intrusion Cells:
            *   `B`: 2 cells (1 block).
            *   `A`: 4 cells (2 blocks).
            *   `R`: 6 cells (3 blocks).
        *   Output Order: R (6), A (4), B (2).
        *   This matches the output `R`, `A`, `B`.
        *   Conclusion: The task is to identify the background color (which forms the majority of the non-separator cells), ignore it, count the cells of all other colors, and list them sorted by count descending. The separator lines (`.`) are ignored.

**3. Analyze the Test Input:**

*   **Input Grid:** 15 rows x 13 columns.
*   **Structure:** Similar to Example 1.
    *   Rows 0, 2, 4, 6, 8, 10, 12, 14 are all `.`. These are separators.
    *   Rows 1, 3, 5, 7, 9, 11, 13 contain colored blocks.
    *   Columns 0, 3, 6, 9, 12 are `.`. These are vertical separators.
    *   Blocks are 2x2.
    *   Block Columns indices: 1-2, 4-5, 7-8, 10-11. (4 columns of blocks).
    *   Block Rows indices: 1, 3, 5, 7, 9, 11, 13. (7 rows of blocks).
   

... [6255 chars truncated]
alt-2 cooking qwen3.5-122b: k=1
"Picking out the spices from a pot of plain rice"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10726 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Input:** A large serving tray (grid) divided into compartments. Most are filled with a "staple grain" (background color). Scattered are "spices" (other colors).
*   **Action:** Discard the base ingredient (background color). Gather the remaining spices.
*   **Output:** Arrange them on a tasting strip (vertical column) from most abundant to least abundant.
*   **Grid Details:** A single vertical tasting strip, one spice per slot.

**2. Analyze the Training Example:**
*   **Input Grid:**
    *   Size: 13 rows x 10 columns (based on visual inspection of the text block).
    *   Background: `.` (black).
    *   Colors present: `G` (green), `B` (blue), `A` (azure), `R` (red).
    *   Let's count the occurrences of each non-background color.
    *   Row 2: G G . G G . G G -> 6 Gs
    *   Row 4: B B . G G . G G -> 2 Bs, 4 Gs
    *   Row 6: G G . A A . G G -> 4 Gs, 2 As
    *   Row 8: G G . A A . G G -> 4 Gs, 2 As
    *   Row 10: G G . R R . R R -> 2 Gs, 4 Rs
    *   Row 12: R R . G G . G G -> 2 Rs, 4 Gs
    *   Total Counts:
        *   G: 6 + 4 + 4 + 4 + 2 + 4 = 24
        *   B: 2
        *   A: 2 + 2 = 4
        *   R: 4 + 2 = 6
    *   Wait, let's look closer at the example input provided in the prompt.
    *   Input:
        ```
        . . . . . . . . . .
        . G G . G G . G G .
        . . . . . . . . . .
        . B B . G G . G G .
        . . . . . . . . . .
        . G G . A A . G G .
        . . . . . . . . . .
        . G G . A A . G G .
        . . . . . . . . . .
        . G G . R R . R R .
        . . . . . . . . . .
        . R R . G G . G G .
        . . . . . . . . . .
        ```
    *   Let's recount carefully.
    *   Row 2: `G G . G G . G G` -> 6 Gs.
    *   Row 4: `B B . G G . G G` -> 2 Bs, 4 Gs.
    *   Row 6: `G G . A A . G G` -> 4 Gs, 2 As.
    *   Row 8: `G G . A A . G G` -> 4 Gs, 2 As.
    *   Row 10: `G G . R R . R R` -> 2 Gs, 4 Rs.
    *   Row 12: `R R . G G . G G` -> 2 Rs, 4 Gs.
    *   Total G: 6 + 4 + 4 + 4 + 2 + 4 = 24.
    *   Total B: 2.
    *   Total A: 2 + 2 = 4.
    *   Total R: 4 + 2 = 6.
    *   Most abundant non-background color: G (24).
    *   Next: R (6).
    *   Next: A (4).
    *   Least: B (2).
    *   Output provided:
        ```
        R
        A
        B
        ```
    *   Wait, the output is `R`, `A`, `B`.
    *   My count says G is most abundant. Why is G not in the output?
    *   Re-reading the metaphor: "Discard the base ingredient that fills most compartments."
    *   Is `G` the base ingredient?
    *   In the input, `.` is clearly the background (empty space). `G` appears very frequently.
    *   Maybe `G` is considered the "staple grain" because it fills most compartments *among the colored ones*? Or maybe `G` is the background color for the spices?
    *   Let's look at the structure. The grid has rows of dots and rows of patterns.
    *   Rows 1, 3, 5, 7, 9, 11, 13 are all dots.
    *   Rows 2, 4, 6, 8, 10, 12 contain the patterns.
    *   In Row 2: `G G . G G . G G`.
    *   In Row 4: `B B . G G . G G`.
    *   In Row 6: `G G . A A . G G`.
    *   It seems `G` is the dominant color in the pattern rows.
    *   The metaphor says: "Discard the base ingredient that fills most compartments."
    *   If `.` is the tray, then `G` is the grain.
    *   So, we ignore `.` and `G`. We only count the "spices" (colors other than `.` and the dominant color `G`).
    *   Spices: `B`, `A`, `R`.
    *   Counts:
        *   B: 2
        *   A: 4
        *   R: 6
    *   Order from most abundant to least: R (6), A (4), B (2).
    *   Output:
        R
        A
        B
    *   This matches the training example output perfectly.
    *   So the rule is:
        1.  Identify the background color (usually `.`).
        2.  Identify the "staple grain" color. This is the most frequent non-background color in the grid.
        3.  Identify the "spices". These are all other colors present in the grid.
        4.  Count the occurrences of each spice color.
        5.  Sort the spice colors by count in descending order.
        6.  Create a vertical output grid (1 column) containing the spice colors in that order.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    . . . . . . . . . . . . .
    . R R . Y Y . R R . R R .
    . . . . . . . . . . . . .
    . B B . R R . Y Y . R R .
    . . . . . . . . . . . . .
    . A A . R R . R R . A A .
    . . . . . . . . . . . . .
    . R R . R R . B B . R R .
    . . . . . . . . . . . . .
    . Y Y . R R . R R . R R .
    . . . . . . . . . . . . .
    . R R . B B . R R . Y Y .
    . . . . . . . . . . . . .
    . R R . R R . Y Y . R R .
    . . . . . . . . . . . . .
    ```
*   **Dimensions:** 15 rows, 13 columns.
*   **Background:** `.` (black).
*   **Colors present:** `R`, `Y`, `B`, `A`.
*   **Step 1: Identify the "Stapl

... [5792 chars truncated]
alt-3 music qwen3.5-122b: k=3
"An orchestra tuning up — the drone of the strings drowns everything, but the conductor listens for the soloists"
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (10058 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A concert hall seating chart.
*   **Elements:** Uniform sections (drone ensemble) vs. solo instruments.
*   **Action:** "Tune out the droning ensemble" (ignore the most frequent color/background). "Listen for each soloist's voice and note how many chairs each claims" (count the occurrences of the other colors).
*   **Output:** A single column program listing soloists from most seats to fewest.
*   **Visuals:** The output is a single column, one color per line, ordered by frequency (descending).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Grid: 13 rows, 10 columns.
    *   Colors present: `.` (black), `G` (green), `B` (blue), `A` (azure), `R` (red).
    *   Let's count the non-black pixels.
    *   `G`:
        *   Row 2: 4
        *   Row 4: 4
        *   Row 6: 4
        *   Row 8: 4
        *   Row 10: 4
        *   Row 12: 4
        *   Total G = 24.
    *   `B`:
        *   Row 4: 2
        *   Total B = 2.
    *   `A`:
        *   Row 6: 2
        *   Row 8: 2
        *   Total A = 4.
    *   `R`:
        *   Row 10: 4
        *   Row 12: 2
        *   Total R = 6.
    *   Wait, let's look closer at the structure.
    *   The grid seems to be composed of 2x2 blocks separated by black rows/cols?
    *   Let's check the structure.
    *   Rows 1, 3, 5, 7, 9, 11, 13 are all `.`.
    *   Rows 2, 4, 6, 8, 10, 12 contain data.
    *   Columns 1, 4, 7, 10 seem to be `.`? No, let's look at indices.
    *   Row 2: `. G G . G G . G G .` -> Indices 2,3 are G; 5,6 are G; 8,9 are G.
    *   It looks like 2x2 blocks of color separated by 1-pixel black lines.
    *   Let's count the blocks.
    *   Row 2: G, G, G (3 blocks of G)
    *   Row 4: B, G, G (1 block B, 2 blocks G)
    *   Row 6: G, A, G (1 block G, 1 block A, 1 block G)
    *   Row 8: G, A, G (1 block G, 1 block A, 1 block G)
    *   Row 10: G, R, R (1 block G, 2 blocks R)
    *   Row 12: R, G, G (1 block R, 2 blocks G)
    *   Total Blocks:
        *   G: 3 + 2 + 2 + 2 + 1 + 2 = 12 blocks.
        *   B: 1 block.
        *   A: 2 blocks.
        *   R: 2 + 1 = 3 blocks.
    *   Output:
        R
        A
        B
    *   Counts: R=3, A=2, B=1.
    *   Order: R (3), A (2), B (1).
    *   This matches the "most seats to fewest" rule.
    *   Note: `G` is the "droning ensemble" (most frequent). It is excluded from the output.
    *   Wait, is `G` excluded because it's the most frequent overall, or because it's the background?
    *   In Example 1, G count is 12 blocks. R is 3, A is 2, B is 1. G is definitely the majority.
    *   The output lists R, A, B. G is missing.
    *   So the rule is: Identify the most frequent color (excluding black `.`). Exclude it. List the remaining colors sorted by frequency (descending).

*   **Example 2:**
    *   Input Grid: 13 rows, 16 columns.
    *   Structure: Similar 2x2 blocks separated by black lines.
    *   Rows 1, 3, 5, 7, 9, 11, 13 are `.`.
    *   Data rows: 2, 4, 6, 8, 10, 12.
    *   Data columns: 2,3; 5,6; 8,9; 11,12; 14,15. (5 blocks per row).
    *   Let's count blocks.
    *   Row 2: M, A, A, A, A (1 M, 4 A)
    *   Row 4: A, A, R, M, A (2 A, 1 R, 1 M, 1 A) -> 3 A, 1 R, 1 M.
    *   Row 6: B, A, B, A, A (2 B, 3 A)
    *   Row 8: A, B, A, A, A (1 B, 4 A)
    *   Row 10: A, A, M, A, M (2 A, 2 M)
    *   Row 12: A, A, A, A, A (5 A)
    *   Total Counts:
        *   A: 4 + 3 + 3 + 4 + 2 + 5 = 21 blocks.
        *   M: 1 + 1 + 2 = 4 blocks.
        *   B: 2 + 1 = 3 blocks.
        *   R: 1 block.
    *   Most frequent: A (21).
    *   Remaining: M (4), B (3), R (1).
    *   Output:
        M
        B
        R
    *   Order: M, B, R. Matches frequency descending.
    *   A is excluded.

*   **Example 3:**
    *   Input Grid: 13 rows, 13 columns.
    *   Structure: 2x2 blocks separated by black lines.
    *   Data rows: 2, 4, 6, 8, 10, 12.
    *   Data columns: 2,3; 5,6; 8,9; 11,12. (4 blocks per row).
    *   Row 2: B, B, A, B (3 B, 1 A)
    *   Row 4: B, R, B, R (2 B, 2 R)
    *   Row 6: R, B, B, B (1 R, 3 B)
    *   Row 8: B, B, A, B (3 B, 1 A)
    *   Row 10: B, A, B, Y (2 B, 1 A, 1 Y)
    *   Row 12: B, A, B, B (3 B, 1 A)
    *   Total Counts:
        *   B: 3 + 2 + 3 + 3 + 2 + 3 = 16 blocks.
        *   A: 1 + 1 + 1 + 1 = 4 blocks.
        *   R: 2 + 1 = 3 blocks.
        *   Y: 1 block.
    *   Most frequent: B (16).
    *   Remaining: A (4), R (3), Y (1).
    *   Output:
        A
        R
        Y
    *   Order: A, R, Y. Matches frequency descending.
    *   B is excluded.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Background:** Black pixels (`.`) form a grid structure (lines).
    *   **Cells:** 2x2 blocks of colored pixels.
    *   **Ensemble:** The color that appears most frequently among the colored blocks.
    *   **Soloists:** All other colors present in the grid.
    *   *

... [5106 chars truncated]
alt-4 sports qwen3.5-122b: fig alone solves
"A stadium full of home fans with pockets of away supporters — the announcer ranks the visiting teams"
alt-5 weather qwen3.5-122b: k=2
"A meteorologist scanning a radar map of calm skies for scattered storm cells"
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11382 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** Weather radar display, grid of cells.
*   **Input:** A grid with a dominant background color ("calm-weather reading") and several distinct colored blocks ("storm signatures").
*   **Task:**
    1.  Dismiss the prevailing fair weather (background color).
    2.  Identify distinct storm types (colors other than background).
    3.  Count occurrences of each storm type.
    4.  Order them from most widespread (highest count) to rarest (lowest count).
    5.  Output format: A single vertical column (one column grid), one storm type per row, in the color of the storm type.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Grid: 13 rows x 10 columns.
    *   Background: `.` (black).
    *   Colors present: `G` (green), `B` (blue), `A` (azure), `R` (red).
    *   Let's count the non-background cells.
        *   `G`:
            *   Row 2: 4 cells (G G . G G) -> actually looking at the grid:
                Row 2: . G G . G G . G G . (6 Gs)
                Row 4: . B B . G G . G G . (4 Gs)
                Row 6: . G G . A A . G G . (4 Gs)
                Row 8: . G G . A A . G G . (4 Gs)
                Row 10: . G G . R R . R R . (2 Gs)
                Row 12: . R R . G G . G G . (4 Gs)
                Total G = 6 + 4 + 4 + 4 + 2 + 4 = 24.
        *   `B`:
            *   Row 4: . B B . ... (2 Bs)
            *   Total B = 2.
        *   `A`:
            *   Row 6: . . . A A . . . (2 As)
            *   Row 8: . . . A A . . . (2 As)
            *   Total A = 4.
        *   `R`:
            *   Row 10: . . . R R . R R . (4 Rs)
            *   Row 12: . R R . . . . . . (2 Rs)
            *   Total R = 6.
    *   Counts: G=24, R=6, A=4, B=2.
    *   Wait, the output is:
        R
        A
        B
    *   Why is G missing?
    *   Let's re-read the metaphor: "Dismiss the prevailing fair weather that dominates the map."
    *   In Example 1, `.` is clearly the background. But `G` is very frequent. Is `G` considered the "prevailing fair weather" along with `.`? Or is `G` the background?
    *   Let's look at the structure. The grid has rows of `.` separating rows of data.
    *   Row 1: `.`
    *   Row 2: `. G G . G G . G G .`
    *   Row 3: `.`
    *   Row 4: `. B B . G G . G G .`
    *   ...
    *   It seems `.` is the separator/background.
    *   However, `G` appears in almost every data row.
    *   Let's check the counts again.
        *   G: 24
        *   R: 6
        *   A: 4
        *   B: 2
    *   Output order: R, A, B.
    *   This implies G is treated as the background or "prevailing weather" to be dismissed.
    *   Why? Because it's the most frequent non-dot color? Or because it forms a pattern?
    *   In the input, `G` appears in pairs `G G`. `B` appears in pairs `B B`. `A` appears in pairs `A A`. `R` appears in pairs `R R`.
    *   The "storm types" seem to be the distinct colored blocks.
    *   If `G` is the "prevailing fair weather", then we ignore it.
    *   Remaining colors: R (6), A (4), B (2).
    *   Order: Most widespread to rarest.
    *   R (6) > A (4) > B (2).
    *   Output matches: R, A, B.
    *   So the rule is: Identify the most frequent color (excluding the grid separator `.`). Treat that as the background/weather. Count the remaining colors. Sort by count descending. Output as a vertical list of single characters representing those colors.

*   **Example 2:**
    *   Input Grid: 13 rows x 16 columns.
    *   Background: `.`
    *   Colors: `M`, `A`, `R`, `B`.
    *   Let's count.
        *   `A`:
            *   Row 2: . A A . A A . A A . A A . (8 As)
            *   Row 4: . A A . A A . R R . M M . A A . (6 As)
            *   Row 6: . B B . A A . B B . A A . A A . (6 As)
            *   Row 8: . A A . B B . A A . A A . A A . (8 As)
            *   Row 10: . A A . A A . M M . A A . M M . (6 As)
            *   Row 12: . A A . A A . A A . A A . A A . (8 As)
            *   Total A = 8 + 6 + 6 + 8 + 6 + 8 = 42.
        *   `M`:
            *   Row 2: . M M . ... (2 Ms)
            *   Row 4: ... M M . ... (2 Ms)
            *   Row 10: ... M M . ... M M . (4 Ms)
            *   Total M = 2 + 2 + 4 = 8.
        *   `R`:
            *   Row 4: ... R R ... (2 Rs)
            *   Total R = 2.
        *   `B`:
            *   Row 6: . B B . ... B B . ... (4 Bs)
            *   Row 8: ... B B ... (2 Bs)
            *   Total B = 6.
    *   Counts: A=42, M=8, B=6, R=2.
    *   Most frequent non-dot color is `A`. So `A` is the "prevailing fair weather".
    *   Remaining colors: M (8), B (6), R (2).
    *   Sort descending: M, B, R.
    *   Output:
        M
        B
        R
    *   Matches Example 2 Output.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Grid:** The input is a 2D array of characters.
    *   **Separator:** `.` (black) acts as the grid structure/separato

... [6412 chars truncated]
alt-6 architecture qwen3.5-122b: k=1
"A city inspector cataloging the odd buildings in a neighborhood of identical houses"
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (11219 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** An aerial view of a city block (grid).
*   **Elements:**
    *   "Uniform lot parcels separated by narrow alleyways": This suggests a grid structure with separators. Looking at the input grids, there are rows of dots (`.`) separating rows of colored blocks.
    *   "Most lots contain identical buildings of the same color": There is a dominant background color or pattern. In the examples, `.` (black) seems to be the alleyway/separator. The colored blocks are the buildings.
    *   "A handful of lots hold buildings painted in distinctive colors": There are specific colored blocks that stand out.
    *   "Skip the cookie-cutter houses that dominate the neighborhood": Ignore the most frequent color or the background pattern.
    *   "Tally each unique architectural accent color and rank them": Count the occurrences of the non-dominant colors.
    *   "File your inspection report listing nonconforming buildings from most numerous to least": The output should be a list of these colors, sorted by frequency (count) in descending order.
    *   "The inspection report is a single narrow column — one colored entry per nonconforming type": The output grid is a single column (width 1) containing the color characters.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:**
        ```
        . . . . . . . . . .
        . G G . G G . G G .
        . . . . . . . . . .
        . B B . G G . G G .
        . . . . . . . . . .
        . G G . A A . G G .
        . . . . . . . . . .
        . G G . A A . G G .
        . . . . . . . . . .
        . G G . R R . R R .
        . . . . . . . . . .
        . R R . G G . G G .
        . . . . . . . . . .
        ```
    *   **Observation:**
        *   The grid has rows of `.` separating rows of content.
        *   Content rows look like: `. C C . C C . C C .` where C is a color.
        *   Let's count the colored blocks.
        *   Row 1: G G, G G, G G (6 Gs)
        *   Row 3: B B, G G, G G (2 Bs, 4 Gs)
        *   Row 5: G G, A A, G G (2 As, 4 Gs)
        *   Row 7: G G, A A, G G (2 As, 4 Gs)
        *   Row 9: G G, R R, R R (2 Rs, 4 Gs)
        *   Row 11: R R, G G, G G (2 Rs, 4 Gs)
        *   Total counts:
            *   G: 6 + 4 + 4 + 4 + 4 + 4 = 26
            *   B: 2
            *   A: 2 + 2 = 4
            *   R: 2 + 2 = 4
        *   Wait, let's look closer at the structure.
        *   The "cookie-cutter houses" are likely the most frequent color. Here, Green (G) appears everywhere.
        *   The "distinctive colors" are B, A, R.
        *   Counts of distinctive colors:
            *   A: 4 blocks (2 pairs)
            *   R: 4 blocks (2 pairs)
            *   B: 2 blocks (1 pair)
        *   Output:
            ```
            R
            A
            B
            ```
        *   Wait, the output order is R, A, B.
        *   My counts: A=4, R=4, B=2.
        *   Why is R before A?
        *   Let's re-examine the input grid structure.
        *   Maybe it's not counting individual cells, but "lots".
        *   A "lot" seems to be a 2x1 block of color (e.g., `G G`).
        *   Let's count the "lots" (pairs of colored cells).
        *   Row 1: G, G, G (3 lots of G)
        *   Row 3: B, G, G (1 lot of B, 2 lots of G)
        *   Row 5: G, A, G (1 lot of A, 2 lots of G)
        *   Row 7: G, A, G (1 lot of A, 2 lots of G)
        *   Row 9: G, R, R (1 lot of G, 2 lots of R)
        *   Row 11: R, G, G (1 lot of R, 2 lots of G)
        *   Total Lots:
            *   G: 3 + 2 + 2 + 2 + 1 + 2 = 12 lots.
            *   B: 1 lot.
            *   A: 1 + 1 = 2 lots.
            *   R: 2 + 1 = 3 lots.
        *   Ranking by number of lots:
            1.  R (3 lots)
            2.  A (2 lots)
            3.  B (1 lot)
        *   Output matches: R, A, B.
        *   So the rule is: Identify the dominant color (background). Count the occurrences of other colors (in terms of contiguous blocks/pairs). Sort them by count descending. Output as a single column.

*   **Example 2 (Implicit):** There is only one training example provided in the prompt text under "Training Examples". Wait, looking at the prompt structure:
    "## Training Examples
    Example 1:
    Input: ...
    Output: ..."
    There is no Example 2. Just one example.
    Okay, I will rely on the logic derived from Example 1.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Grid:** A matrix of characters.
    *   **Separators:** Rows of `.` (black) act as alleyways.
    *   **Lots:** Pairs of colored characters (e.g., `R R`) within the non-separator rows.
    *   **Dominant Color:** The color that appears most frequently (the "cookie-cutter houses"). In Example 1, this was Green (G).
    *   **Accent Colors:** All other colors present in the grid.
    *   **Output:** A vertical list (column) of t

... [6270 chars truncated]
alt-7 warfare qwen3.5-122b: fig alone solves
"A general surveying a battlefield map, ignoring his own legions to count the scattered enemy banners"
alt-8 theater qwen3.5-122b: k=3
"A casting director reviewing headshots pinned to a board — most are extras, but a few are named roles"
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (10309 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A casting board with headshot slots.
*   **Elements:**
    *   "Extras": Most slots are filled with the same type. This implies a background color or a dominant color that should be ignored.
    *   "Performers": A few slots feature distinctive costume colors.
    *   "Costume colors": These are the colors of interest.
*   **Task:**
    *   Ignore the extras (dominant color).
    *   Count how many slots each named-role costume (distinctive color) appears in.
    *   Print a playbill (output grid) listing featured roles.
    *   Order: From most appearances (top) to fewest (bottom).
*   **Output Format:** A single column grid. Each line contains the color code of a featured role.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Grid: 13 rows, 10 columns.
    *   Colors present: `.` (black), `G` (green), `B` (blue), `A` (azure), `R` (red).
    *   Structure: It looks like a grid of 2x2 blocks separated by `.` lines.
        *   Row 0: `.`
        *   Row 1: `. G G . G G . G G .` -> Blocks of `G`
        *   Row 2: `.`
        *   Row 3: `. B B . G G . G G .` -> Blocks of `B`, `G`, `G`
        *   Row 4: `.`
        *   Row 5: `. G G . A A . G G .` -> Blocks of `G`, `A`, `G`
        *   Row 6: `.`
        *   Row 7: `. G G . A A . G G .` -> Blocks of `G`, `A`, `G`
        *   Row 8: `.`
        *   Row 9: `. G G . R R . R R .` -> Blocks of `G`, `R`, `R`
        *   Row 10: `.`
        *   Row 11: `. R R . G G . G G .` -> Blocks of `R`, `G`, `G`
        *   Row 12: `.`
    *   "Extras": `G` (green) appears very frequently. It seems to be the background or "extra" color.
    *   "Performers": `B`, `A`, `R`.
    *   Counts:
        *   `B`: Appears in one 2x2 block (Row 3, Col 1-2). Count = 1 block.
        *   `A`: Appears in two 2x2 blocks (Row 5, Col 3-4; Row 7, Col 3-4). Count = 2 blocks.
        *   `R`: Appears in three 2x2 blocks (Row 9, Col 3-4; Row 9, Col 5-6; Row 11, Col 1-2). Count = 3 blocks.
    *   Wait, let's look closer at the counts.
        *   `B`: 1 block.
        *   `A`: 2 blocks.
        *   `R`: 3 blocks.
    *   Output:
        ```
        R
        A
        B
        ```
    *   Ordering: R (3) > A (2) > B (1). This matches "most appearances to fewest".
    *   Note: The output is a single column of characters.

*   **Example 2:**
    *   Input Grid: 13 rows, 16 columns.
    *   Colors: `.`, `M`, `A`, `R`, `B`.
    *   Structure: Similar grid of 2x2 blocks separated by `.` lines.
    *   "Extras": `A` (azure) appears most frequently.
    *   "Performers": `M`, `R`, `B`.
    *   Counts (counting 2x2 blocks):
        *   `M`: Row 1 (Col 1-2), Row 3 (Col 7-8), Row 9 (Col 5-6), Row 9 (Col 11-12). Total = 4 blocks.
        *   `B`: Row 5 (Col 1-2), Row 5 (Col 5-6), Row 7 (Col 3-4). Total = 3 blocks.
        *   `R`: Row 3 (Col 5-6). Total = 1 block.
    *   Output:
        ```
        M
        B
        R
        ```
    *   Ordering: M (4) > B (3) > R (1). Matches.

*   **Example 3:**
    *   Input Grid: 13 rows, 13 columns.
    *   Colors: `.`, `B`, `A`, `R`, `Y`.
    *   Structure: Grid of 2x2 blocks.
    *   "Extras": `B` (blue) appears most frequently.
    *   "Performers": `A`, `R`, `Y`.
    *   Counts:
        *   `A`: Row 1 (Col 5-6), Row 7 (Col 5-6), Row 9 (Col 3-4), Row 11 (Col 3-4). Total = 4 blocks.
        *   `R`: Row 3 (Col 3-4), Row 3 (Col 7-8), Row 5 (Col 1-2). Total = 3 blocks.
        *   `Y`: Row 9 (Col 7-8). Total = 1 block.
    *   Output:
        ```
        A
        R
        Y
        ```
    *   Ordering: A (4) > R (3) > Y (1). Matches.

**3. Conceptual Digestion:**

1.  **Identify the CAST:**
    *   **Background/Extras:** The color that forms the majority of the non-dot cells. In Ex 1 it's G, Ex 2 it's A, Ex 3 it's B.
    *   **Featured Roles:** The colors that appear less frequently than the background color.
    *   **Grid Structure:** The input is a grid where "slots" are 2x2 blocks of color, separated by rows and columns of dots (`.`).
    *   **Output:** A vertical list (single column) of the color codes for the Featured Roles.

2.  **Identify the AFFORDANCES:**
    *   The grid can be parsed into 2x2 cells.
    *   Each 2x2 cell has a uniform color.
    *   We can count the occurrences of each color (excluding the background color).
    *   We can sort these counts in descending order.

3.  **Identify the TRANSFORMATION RULE:**
    *   Step 1: Parse the input grid into 2x2 blocks. The grid is defined by rows/cols of `.` separating these blocks.
    *   Step 2: Identify the "background" color. This is the color that appears in the most 2x2 blocks.
    *   Step 3: Identify the "featured" colors. These are all other colors present in the 2x2 blocks.
    *   Step 4: Count the number of 2x2 blocks for each featured color.
    

... [5396 chars truncated]
alt-9 gardening qwen3.5-122b: fig alone solves
"A groundskeeper inventorying the unusual blooms that have sprouted among the uniform lawn squares"

Task 977: f9012d9b

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A tapestry weaver mends a moth-eaten hole by reading the rhythm of the surviving ... [9 chars truncated] MARC valid 1
alt-1 biology A geneticist reconstructs a corrupted segment of DNA by recognizing the codon re ... [47 chars truncated] MARC valid 1
alt-10 astronomy An astronomer reconstructs a corrupted region of a star map by exploiting the cr ... [51 chars truncated] fig alone solves
alt-11 ocean/sailing A cartographer restores a sea chart's missing corner by continuing the periodic ... [65 chars truncated] fig alone solves
alt-12 electronics A technician repairs a damaged circuit board by replacing a burned-out rectangul ... [88 chars truncated] fig alone solves
alt-13 mythology A scribe restores a damaged section of a divine tapestry by invoking the eternal ... [55 chars truncated] fig alone solves
alt-14 dance A choreographer fills an empty rectangle on the dance floor by extending the rep ... [61 chars truncated] MARC valid 3
alt-15 geology A mineralogist reconstructs a shattered section of a crystal cross-section by ex ... [65 chars truncated] MARC valid 1
alt-2 cooking A baker patches a torn sheet of decorative fondant by studying the repeating mot ... [40 chars truncated] MARC valid 1
alt-3 music A conductor reconstructs a water-damaged measure by listening to the ostinato th ... [43 chars truncated] MARC valid 1
alt-4 sports A choreographer restores a marching band's formation chart after coffee spills o ... [59 chars truncated] MARC valid 2
alt-5 weather A meteorologist fills in a satellite image's dead pixels by extending the perfec ... [60 chars truncated] fig alone solves
alt-6 architecture A restorer replaces missing tiles in a Roman mosaic floor by deducing the small ... [48 chars truncated] fig alone solves
alt-7 warfare A signals officer deciphers a garbled section of an encrypted message by recogni ... [50 chars truncated] MARC valid 1
alt-8 theater A stage manager re-blocks a scene after a lighting rig failure blacks out one se ... [82 chars truncated] MARC valid 2
alt-9 gardening A groundskeeper reseeds a rectangular bare patch in a formal garden by matching ... [57 chars truncated] MARC valid 2
original qwen3.5-122b: k=1
"A tapestry weaver mends a moth-eaten hole by reading the rhythm of the surviving threads."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10829 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A "tapestry" with a repeating motif (pattern).
*   **Problem:** A "moth-eaten hole" (rectangle of black canvas, represented by `.`) exists in the grid.
*   **Task:** Identify the repeating pattern (the "refrain") from the intact parts of the grid.
*   **Goal:** Fill in the missing part (the hole) with the correct colors based on the repeating pattern.
*   **Output:** The prompt asks for the "patch that makes the tapestry whole again". However, looking at the training example, the output is just a single character `A`. Let's look closer at the training example.

**2. Analyze Training Example 1:**
*   **Input:**
    ```
    A M . M
    M A M A
    A M A M
    M A M A
    ```
    *   Grid size: 4x4.
    *   Missing part: `.` at (0, 2) (0-indexed).
    *   Pattern analysis:
        *   Row 0: A M . M
        *   Row 1: M A M A
        *   Row 2: A M A M
        *   Row 3: M A M A
    *   It looks like a checkerboard pattern of A and M.
    *   Row 1: M A M A (Alternating M, A)
    *   Row 2: A M A M (Alternating A, M)
    *   Row 3: M A M A (Alternating M, A)
    *   Row 0 should follow the pattern. If Row 1 starts with M, Row 0 likely starts with A (checkerboard).
    *   Row 0: A M ? M. If it's a checkerboard, (0,0)=A, (0,1)=M, (0,2)=A, (0,3)=M.
    *   So the missing value is `A`.
*   **Output:** `A`.
*   **Interpretation:** The output is *only* the missing patch, not the whole grid. The prompt says "Sing only the missing notes — the patch that makes the tapestry whole again." This confirms I need to output the subgrid corresponding to the black `.` area.

**3. Analyze Test Input:**
*   **Input Grid:**
    ```
    A B A A . . .
    B A A B . . .
    A A B A . . .
    A B A A B A A
    B A A B A A B
    A A B A A B A
    A B A A B A A
    ```
*   **Dimensions:** 7 rows, 7 columns.
*   **Missing Area (Black `.`):**
    *   Row 0: cols 4, 5, 6 are `.`
    *   Row 1: cols 4, 5, 6 are `.`
    *   Row 2: cols 4, 5, 6 are `.`
    *   Rows 3-6: No `.`
    *   So the hole is a 3x3 rectangle at the top right corner.
    *   Coordinates: (0,4), (0,5), (0,6), (1,4), (1,5), (1,6), (2,4), (2,5), (2,6).
*   **Task:** Determine the 3x3 patch that fits into this hole based on the repeating pattern found in the rest of the grid.

**4. Pattern Discovery:**
Let's look at the non-black parts of the grid to find the repeating unit (motif).

Rows 3-6 seem fully intact.
Row 3: `A B A A B A A`
Row 4: `B A A B A A B`
Row 5: `A A B A A B A`
Row 6: `A B A A B A A`

Let's look for periodicity.
Row 3: `A B A A B A A`
Row 6: `A B A A B A A`
Row 3 and Row 6 are identical. This suggests a vertical period of 3?
Let's check Row 4 vs Row 7 (doesn't exist).
Let's check Row 0, 1, 2 against Row 3, 4, 5.
If vertical period is 3:
Row 0 should match Row 3.
Row 1 should match Row 4.
Row 2 should match Row 5.

Let's check the known values in Rows 0, 1, 2 against Rows 3, 4, 5.
*   **Row 0 vs Row 3:**
    *   Row 0: `A B A A . . .`
    *   Row 3: `A B A A B A A`
    *   Match on cols 0-3: `A B A A` matches `A B A A`.
    *   This strongly suggests Row 0 is identical to Row 3.
*   **Row 1 vs Row 4:**
    *   Row 1: `B A A B . . .`
    *   Row 4: `B A A B A A B`
    *   Match on cols 0-3: `B A A B` matches `B A A B`.
    *   This strongly suggests Row 1 is identical to Row 4.
*   **Row 2 vs Row 5:**
    *   Row 2: `A A B A . . .`
    *   Row 5: `A A B A A B A`
    *   Match on cols 0-3: `A A B A` matches `A A B A`.
    *   This strongly suggests Row 2 is identical to Row 5.

So the vertical period is 3. The pattern repeats every 3 rows.
Row $i$ is the same as Row $i+3$.
Therefore:
Row 0 = Row 3 = Row 6
Row 1 = Row 4
Row 2 = Row 5

Now let's look at horizontal periodicity within the rows.
Row 3: `A B A A B A A`
Let's check for a horizontal period.
Sequence: A, B, A, A, B, A, A
Is it period 3? A B A | A B A | A ...
Indices:
0: A
1: B
2: A
3: A
4: B
5: A
6: A
Pattern `A B A` repeats?
0: A, 3: A, 6: A. (Matches)
1: B, 4: B. (Matches)
2: A, 5: A. (Matches)
So the horizontal period is 3. The motif is `A B A`.

Let's verify this horizontal period with other rows.
Row 4: `B A A B A A B`
Pattern `B A A`?
0: B, 3: B, 6: B. (Matches)
1: A, 4: A. (Matches)
2: A, 5: A. (Matches)
Yes, horizontal period is 3. Motif is `B A A`.

Row 5: `A A B A A B A`
Pattern `A A B`?
0: A, 3: A, 6: A. (Matches)
1: A, 4: A. (Matches)
2: B, 5: B. (Matches)
Yes, horizontal period is 3. Motif is `A A B`.

Row 6: `A B A A B A A`
Same as Row 3. Motif `A B A`.

**5. Constructing the Missing Patch:**
The hole is at Rows 0, 1, 2 and Cols 4, 5, 6.
We need to fill a 3x3 grid.

**Row 0 (corresponds to Row 3):**
Row 3 is `A B A A B A A`.
The missing part is cols 4, 5, 6.
Values at Row 3, cols 4, 5, 6 are `B`, `A`, `A`.
So Row 0 of the patch should be `B A A`.

**Row 1 (corresponds to Row 4):**
Row 4 is `B A A B A A B`.

... [5841 chars truncated]
alt-1 biology qwen3.5-122b: k=1
"A geneticist reconstructs a corrupted segment of DNA by recognizing the codon repeat cycle that governs the rest of the strand."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10071 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A chromosome with colored nucleotides.
*   **Pattern:** Repeating in a known periodicity.
*   **Problem:** One stretch is dark (black cells, `.`), representing radiation damage.
*   **Task:** Identify the repeating unit (codon) from the healthy portion. Clone that pattern into the damaged region.
*   **Output:** Report *only* the repaired segment.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    A M . M
    M A M A
    A M A M
    M A M A
    ```
*   **Output:**
    ```
    A
    ```
*   **Observation:**
    *   The input grid has a black cell `.` at position (0, 2) (0-indexed).
    *   The rest of the grid seems to follow a pattern.
    *   Let's look at the rows:
        *   Row 0: A M . M
        *   Row 1: M A M A
        *   Row 2: A M A M
        *   Row 3: M A M A
    *   Rows 1, 2, 3 look like a checkerboard pattern of A and M.
    *   Row 0 is A M . M. If the pattern continues, it should be A M A M. So the `.` should be `A`.
    *   The output is just `A`.
    *   This matches the instruction: "report only the repaired segment". The damaged segment is the single black cell. The repaired value is `A`.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    A B A A . . .
    B A A B . . .
    A A B A . . .
    A B A A B A A
    B A A B A A B
    A A B A A B A
    A B A A B A A
    ```
*   **Dimensions:** 7 rows, 7 columns.
*   **Damaged Region:** There is a block of black cells `.` in the top right.
    *   Row 0: cols 4, 5, 6 are `.`
    *   Row 1: cols 4, 5, 6 are `.`
    *   Row 2: cols 4, 5, 6 are `.`
    *   Rows 3-6 seem fully populated.
*   **Goal:** Determine the values for the `.` cells based on the pattern in the rest of the grid, and output *only* the repaired segment (the block of `.` cells filled in).

**4. Conceptual Digestion:**

*   **CAST:**
    *   **Healthy Cells:** Colored cells (A, B) that establish the periodic pattern.
    *   **Damaged Cells:** Black cells (`.`) that need to be filled.
    *   **Output:** The subgrid corresponding to the damaged cells, filled with the predicted colors.

*   **AFFORDANCES:**
    *   The grid exhibits translational symmetry or a repeating tile pattern.
    *   The pattern can be deduced from the non-damaged rows/columns.
    *   The damaged region is a rectangular block.

*   **TRANSFORMATION RULE:**
    1.  Identify the repeating pattern in the input grid (rows and columns).
    2.  Locate the black cells (`.`).
    3.  Extrapolate the pattern to fill the black cells.
    4.  Extract the subgrid corresponding to the black cells' positions.
    5.  Output this subgrid.

**5. Pattern Recognition on Test Input:**

Let's look at the rows provided:
Row 0: `A B A A . . .`
Row 1: `B A A B . . .`
Row 2: `A A B A . . .`
Row 3: `A B A A B A A`
Row 4: `B A A B A A B`
Row 5: `A A B A A B A`
Row 6: `A B A A B A A`

Let's analyze the columns.
Col 0: A, B, A, A, B, A, A
Col 1: B, A, A, B, A, A, B
Col 2: A, A, B, A, A, B, A
Col 3: A, B, A, A, B, A, A
Col 4: ., ., ., B, A, A, B
Col 5: ., ., ., A, A, B, A
Col 6: ., ., ., A, B, A, A

Let's look for a repeating unit.
Compare Row 3 and Row 6.
Row 3: `A B A A B A A`
Row 6: `A B A A B A A`
They are identical. This suggests a vertical period of 3?
Let's check Row 0 vs Row 3.
Row 0: `A B A A . . .`
Row 3: `A B A A B A A`
If the period is 3, Row 0 should match Row 3.
Row 0 starts `A B A A`. Row 3 starts `A B A A`. This matches.
So Row 0 should be `A B A A B A A`.
The missing part is `B A A`.

Let's check Row 1 vs Row 4.
Row 1: `B A A B . . .`
Row 4: `B A A B A A B`
They match on the first 4 columns.
If period is 3, Row 1 should match Row 4.
So Row 1 should be `B A A B A A B`.
The missing part is `A A B`.

Let's check Row 2 vs Row 5.
Row 2: `A A B A . . .`
Row 5: `A A B A A B A`
They match on the first 4 columns.
If period is 3, Row 2 should match Row 5.
So Row 2 should be `A A B A A B A`.
The missing part is `A B A`.

Let's verify the horizontal periodicity.
Row 3: `A B A A B A A`
Is there a horizontal period?
`A B A A` ... `B A A`?
Let's look at the sequence `A B A A`.
Indices: 0:A, 1:B, 2:A, 3:A.
Indices: 4:B, 5:A, 6:A.
It looks like the sequence `A B A A` repeats?
If period is 4:
0: A
1: B
2: A
3: A
4: A (Expected) -> Actual is B. So horizontal period is not 4.

Let's look at the columns again.
Col 0: A B A A B A A (Period 3: A B A, A B A, A...)
Col 1: B A A B A A B (Period 3: B A A, B A A, B...)
Col 2: A A B A A B A (Period 3: A A B, A A B, A...)
Col 3: A B A A B A A (Period 3: A B A, A B A, A...)
Col 4: B A A B A A B (Period 3: B A A, B A A, B...)
Col 5: A A B A A B A (Period 3: A A B, A A B, A...)
Col 6: A B A A B A A (Period 3: A B A, A B A, A...)

It seems the vertical period is 3.
Row 0 = Row 3 = Row 6
Row 1 = Row 4
Row 2 = Row 5

Let's check the horizontal pattern based on the completed rows.
Row 3: `A B A A 

... [5095 chars truncated]
alt-10 astronomy qwen3.5-122b: fig alone solves
"An astronomer reconstructs a corrupted region of a star map by exploiting the crystalline periodicity of stars in a lattice galaxy."
alt-11 ocean/sailing qwen3.5-122b: fig alone solves
"A cartographer restores a sea chart's missing corner by continuing the periodic pattern of colored depth soundings that tile the rest of the map."
alt-12 electronics qwen3.5-122b: fig alone solves
"A technician repairs a damaged circuit board by replacing a burned-out rectangular cluster of components, reading their values from the board's repeating module layout."
alt-13 mythology qwen3.5-122b: fig alone solves
"A scribe restores a damaged section of a divine tapestry by invoking the eternal pattern that the gods wove into every repeating panel."
alt-14 dance qwen3.5-122b: k=3
"A choreographer fills an empty rectangle on the dance floor by extending the repeating formation that every other dancer follows in lockstep."
MARC valid, solved with k=3
Prediction
vs
Expected
Reasoning (10522 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A ballroom floor with dancers in colored costumes.
*   **Pattern:** Strictly periodic formation.
*   **Problem:** One rectangular section is empty (black cells, represented by `.`).
*   **Task:** Identify the repeating unit (period) from the occupied positions. Fill in the empty spots to continue the pattern.
*   **Output:** Only the placements for the vacant rectangle (the missing dancers).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        A M . M
        M A M A
        A M A M
        M A M A
        ```
    *   Output: `A`
    *   Observation: The grid is 4x4. There is one black cell at (0, 2) (0-indexed).
    *   Pattern Analysis:
        Row 0: A M . M
        Row 1: M A M A
        Row 2: A M A M
        Row 3: M A M A
        Looking at rows 1, 2, 3, there seems to be a checkerboard pattern of A and M.
        Row 1: M A M A
        Row 2: A M A M
        Row 3: M A M A
        If Row 0 follows the pattern of Row 2 (since Row 0 and Row 2 look similar in terms of A/M positions), Row 0 should be A M A M.
        The missing cell is at (0, 2). In the sequence A M A M, the 3rd element is A.
        So the output is `A`.
    *   Wait, the output format is just the missing part. Here the missing part is 1x1.
    *   Let's check periodicity.
        Columns:
        Col 0: A, M, A, M (Period 2: A, M)
        Col 1: M, A, M, A (Period 2: M, A)
        Col 2: ., M, A, M (Should be A, M, A, M -> A)
        Col 3: M, A, M, A (Period 2: M, A)
        Rows:
        Row 0: A, M, ., M
        Row 1: M, A, M, A
        Row 2: A, M, A, M
        Row 3: M, A, M, A
        It looks like a checkerboard pattern.
        (0,0)=A, (0,1)=M, (0,2)=?, (0,3)=M.
        If checkerboard, (0,2) should be A.
        Output is `A`. Matches.

*   **Example 2:**
    *   Input:
        ```
        R B R B R
        B B B B B
        R B R B R
        . . B B B
        . . R B R
        ```
    *   Output:
        ```
        B B
        R B
        ```
    *   Observation: Grid is 5x5. Missing rectangle is at bottom-left, 2x2 area (rows 3-4, cols 0-1).
    *   Pattern Analysis:
        Row 0: R B R B R (Period 2: R B)
        Row 1: B B B B B (All B)
        Row 2: R B R B R (Period 2: R B)
        Row 3: . . B B B
        Row 4: . . R B R
        Let's look at columns.
        Col 0: R, B, R, ., .
        Col 1: B, B, B, ., .
        Col 2: R, B, R, B, R
        Col 3: B, B, B, B, B
        Col 4: R, B, R, B, R
        It seems columns 0, 2, 4 are identical (R, B, R, B, R).
        Columns 1, 3 are identical (B, B, B, B, B).
        So Col 0 should be R, B, R, B, R.
        Missing cells in Col 0 are at Row 3 and Row 4.
        Row 3, Col 0 should be B.
        Row 4, Col 0 should be R.
        Col 1 should be B, B, B, B, B.
        Missing cells in Col 1 are at Row 3 and Row 4.
        Row 3, Col 1 should be B.
        Row 4, Col 1 should be B.
        So the 2x2 block is:
        (3,0)=B, (3,1)=B
        (4,0)=R, (4,1)=B
        Output:
        B B
        R B
        Matches the example output.

*   **Example 3:**
    *   Input:
        ```
        R R X R R X R
        R R X R R X R
        X X X X X X X
        R R X R R X R
        R R X R R X R
        X X X X X . .
        R R X R R . .
        ```
    *   Output:
        ```
        X X
        X R
        ```
    *   Observation: Grid is 7x7. Missing rectangle is bottom-right, 2x2 area (rows 5-6, cols 5-6).
    *   Pattern Analysis:
        Rows 0, 1, 3, 4 are identical: R R X R R X R.
        Row 2 is: X X X X X X X.
        Row 5 is: X X X X X . .
        Row 6 is: R R X R R . .
        It looks like the rows repeat with a period of 3?
        Row 0: Type 1
        Row 1: Type 1
        Row 2: Type 2
        Row 3: Type 1
        Row 4: Type 1
        Row 5: Type 2 (starts with X X X X X)
        Row 6: Type 1 (starts with R R X R R)
        Let's check the columns.
        Col 0: R, R, X, R, R, X, R. Pattern: R, R, X repeating?
        Col 1: R, R, X, R, R, X, R. Same.
        Col 2: X, X, X, X, X, X, X. All X.
        Col 3: R, R, X, R, R, X, R. Same as Col 0.
        Col 4: R, R, X, R, R, X, R. Same as Col 0.
        Col 5: X, X, X, X, X, ., .
        Col 6: R, R, X, R, R, ., .
        Let's look at the missing block (Rows 5,6; Cols 5,6).
        Row 5 corresponds to Row 2 (Type 2). Row 2 is all X. So Row 5 should be all X.
        Missing cells in Row 5 are at Col 5 and Col 6. Both should be X.
        Row 6 corresponds to Row 0 (Type 1). Row 0 is R R X R R X R.
        Missing cells in Row 6 are at Col 5 and Col 6.
        Col 5 in Row 0 is X.
        Col 6 in Row 0 is R.
        So Row 6 missing cells are X, R.
        Block:
        X X
        X R
        Matches example output.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Colored Cel

... [5525 chars truncated]
alt-15 geology qwen3.5-122b: k=1
"A mineralogist reconstructs a shattered section of a crystal cross-section by extending the unit cell that repeats throughout the intact lattice."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10563 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A crystal thin-section with colored mineral grains repeating in a perfect 2D unit cell.
*   **Problem:** One rectangular region has fractured away, leaving void (black `.`).
*   **Task:** Measure the unit cell dimensions from the surviving lattice. Predict the mineral arrangement in the fractured region.
*   **Output:** Report *only* that rectangular section (the missing part).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    A M . M
    M A M A
    A M A M
    M A M A
    ```
*   **Output:**
    ```
    A
    ```
*   **Observation:**
    *   The input grid is 4x4.
    *   There is a black cell at (0, 2) (0-indexed).
    *   The rest of the grid seems to follow a pattern.
    *   Let's check the pattern.
    *   Row 0: A M . M
    *   Row 1: M A M A
    *   Row 2: A M A M
    *   Row 3: M A M A
    *   Looking at rows 1, 2, 3, they look like a checkerboard pattern of A and M.
    *   Row 1: M A M A
    *   Row 2: A M A M
    *   Row 3: M A M A
    *   This suggests a period of 2 in both dimensions.
    *   If the pattern is a checkerboard:
        *   (0,0) is A.
        *   (0,1) is M.
        *   (0,2) should be A.
        *   (0,3) is M.
    *   The missing cell is at (0,2). Based on the checkerboard pattern (A, M, A, M...), the value should be A.
    *   The output is just `A`. This matches the prediction for the missing cell.
    *   So the task is to identify the repeating pattern (unit cell) and fill in the black `.` cells. The output is the subgrid corresponding to the black cells.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    A B A A . . .
    B A A B . . .
    A A B A . . .
    A B A A B A A
    B A A B A A B
    A A B A A B A
    A B A A B A A
    ```
*   **Dimensions:** 7 rows, 7 columns.
*   **Black Cells (`.`):**
    *   Row 0: cols 4, 5, 6
    *   Row 1: cols 4, 5, 6
    *   Row 2: cols 4, 5, 6
    *   Rows 3-6: No black cells.
    *   So the missing region is a 3x3 rectangle at the top right corner (rows 0-2, cols 4-6).
*   **Goal:** Determine the values for these 9 cells based on the repeating pattern found in the rest of the grid.

**4. Conceptual Digestion:**

*   **CAST:**
    *   **Colored Cells (A, B):** Mineral grains forming a lattice.
    *   **Black Cells (.):** Fractured void / missing data.
    *   **Grid:** The crystal thin-section.
*   **AFFORDANCES:**
    *   Colored cells define the periodicity (unit cell).
    *   Black cells need to be inferred from the periodicity.
    *   The output is the specific subgrid of inferred colors.
*   **TRANSFORMATION RULE:**
    1.  Identify the repeating unit cell pattern from the non-black cells.
    2.  Determine the dimensions of the rectangular region of black cells.
    3.  Extrapolate the pattern to fill the black region.
    4.  Output the filled black region as a separate grid.

**5. Pattern Recognition on Test Input:**

Let's look at the non-black part of the grid.
Rows 0-2, Cols 0-3:
```
A B A A
B A A B
A A B A
```
Rows 3-6, Cols 0-6:
```
A B A A B A A
B A A B A A B
A A B A A B A
A B A A B A A
```

Let's look for a repeating unit cell.
Let's check horizontal periodicity first.
Row 3: `A B A A B A A`
Indices: 0 1 2 3 4 5 6
Values: A B A A B A A
Is there a period?
A B A A ...
Maybe period 4?
0: A, 4: B (No)
Maybe period 3?
0: A, 3: A, 6: A.
1: B, 4: B.
2: A, 5: A.
Let's check Row 3 with period 3:
0: A
1: B
2: A
3: A (matches 0)
4: B (matches 1)
5: A (matches 2)
6: A (matches 0)
So Row 3 follows pattern `A B A` repeated. `A B A A B A A`.
Let's check Row 4: `B A A B A A B`
0: B
1: A
2: A
3: B (matches 0)
4: A (matches 1)
5: A (matches 2)
6: B (matches 0)
So Row 4 follows pattern `B A A` repeated.
Let's check Row 5: `A A B A A B A`
0: A
1: A
2: B
3: A (matches 0)
4: A (matches 1)
5: B (matches 2)
6: A (matches 0)
So Row 5 follows pattern `A A B` repeated.
Let's check Row 6: `A B A A B A A`
Same as Row 3. Pattern `A B A`.

So the vertical period seems to be 3 as well.
Row 3: `A B A`
Row 4: `B A A`
Row 5: `A A B`
Row 6: `A B A` (Same as Row 3)

So the unit cell is 3x3.
Let's verify this unit cell with the top-left section (Rows 0-2, Cols 0-3).
The unit cell (3x3) should be:
Row 0 of cell: `A B A`
Row 1 of cell: `B A A`
Row 2 of cell: `A A B`

Let's check the input grid against this 3x3 unit cell.
Input Grid (0-2, 0-3):
Row 0: `A B A A`
Expected (based on cell row 0 `A B A`): `A B A A` (Matches: 0->A, 1->B, 2->A, 3->A)
Row 1: `B A A B`
Expected (based on cell row 1 `B A A`): `B A A B` (Matches: 0->B, 1->A, 2->A, 3->B)
Row 2: `A A B A`
Expected (based on cell row 2 `A A B`): `A A B A` (Matches: 0->A, 1->A, 2->B, 3->A)

The pattern holds perfectly for the visible part.
The unit cell is:
```
A B A
B A A
A A B
```
This 3x3 block repeats across the grid.

**6. Predicting the Missing Region:**

The mis

... [5662 chars truncated]
alt-2 cooking qwen3.5-122b: k=1
"A baker patches a torn sheet of decorative fondant by studying the repeating motif stamped across the surviving surface."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10021 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scenario:** A sheet of fondant with a repeating colored stamp pattern covers a cake.
*   **Problem:** A rectangular piece is torn away, revealing black cells (the "bare cake").
*   **Task:** Determine the stamp's dimensions from the intact fondant. Cut a new patch using the same stamp, aligned to the surrounding pattern.
*   **Output:** Present *only* the patch itself (the missing rectangular piece).
*   **Grid Details:**
    *   Colored cells = Stamped fondant pattern.
    *   Black cells (`.`) = Torn-away gap.
    *   Output = The missing rectangular patch that fills the black area, matching the pattern.

**2. Analyze the Training Example:**
*   **Input:**
    ```
    A M . M
    M A M A
    A M A M
    M A M A
    ```
*   **Output:**
    ```
    A
    ```
*   **Observation:**
    *   There is a single black cell (`.`) at position (0, 2) (0-indexed row, col).
    *   The surrounding pattern seems to be a checkerboard of A and M.
    *   Row 0: A M . M -> If it were a checkerboard, it should be A M A M. So the missing cell is A.
    *   Row 1: M A M A
    *   Row 2: A M A M
    *   Row 3: M A M A
    *   The pattern repeats every 2x2 or is a simple checkerboard.
    *   The hole is 1x1. The output is 1x1 containing 'A'.
    *   This confirms the task: Identify the black region, determine the underlying pattern, and fill the black region with the correct colors to continue the pattern. The output is just the filled region.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    A B A A . . .
    B A A B . . .
    A A B A . . .
    A B A A B A A
    B A A B A A B
    A A B A A B A
    A B A A B A A
    ```
*   **Dimensions:** 7 rows, 7 columns.
*   **Black Cells (`.`):**
    *   Row 0: Cols 4, 5, 6
    *   Row 1: Cols 4, 5, 6
    *   Row 2: Cols 4, 5, 6
    *   Rows 3-6: No black cells.
    *   So the "hole" is a 3x3 rectangle at the top right corner (Rows 0-2, Cols 4-6).
*   **Goal:** Determine the 3x3 patch that fits into this hole based on the surrounding pattern.

**4. Conceptual Digestion:**

*   **CAST:**
    *   **Pattern Source:** The non-black cells (A, B).
    *   **Target:** The black cells (`.`).
    *   **Output:** The filled black cells.
*   **AFFORDANCES:**
    *   The colored cells define a periodic tiling or pattern.
    *   The black cells represent missing data that needs to be inferred.
    *   The pattern likely repeats horizontally and vertically.
*   **TRANSFORMATION RULE:**
    1.  Identify the bounding box of the black cells.
    2.  Analyze the non-black cells to find the repeating unit (periodicity) of the pattern.
    3.  Extrapolate the pattern into the black cell region.
    4.  Extract the subgrid corresponding to the black cell region.

**5. Pattern Analysis:**

Let's look at the rows provided:
Row 0: `A B A A . . .`
Row 1: `B A A B . . .`
Row 2: `A A B A . . .`
Row 3: `A B A A B A A`
Row 4: `B A A B A A B`
Row 5: `A A B A A B A`
Row 6: `A B A A B A A`

Let's look at the structure of the non-black part (Rows 3-6 are fully visible).
Row 3: `A B A A B A A`
Row 4: `B A A B A A B`
Row 5: `A A B A A B A`
Row 6: `A B A A B A A`

Notice Row 3 and Row 6 are identical: `A B A A B A A`.
This suggests a vertical period of 3?
Let's check Row 3 vs Row 0 (partial).
Row 3: `A B A A B A A`
Row 0: `A B A A . . .`
If the pattern continues vertically, Row 0 should match Row 3.
Row 0 starts `A B A A`. Row 3 starts `A B A A`. This matches perfectly.
So, Row 0 is likely identical to Row 3.
If Row 0 = Row 3, then the missing part of Row 0 (cols 4, 5, 6) should be `B A A`.

Let's check Row 1 vs Row 4.
Row 4: `B A A B A A B`
Row 1: `B A A B . . .`
Row 1 starts `B A A B`. Row 4 starts `B A A B`. This matches.
So, Row 1 is likely identical to Row 4.
If Row 1 = Row 4, then the missing part of Row 1 (cols 4, 5, 6) should be `A A B`.

Let's check Row 2 vs Row 5.
Row 5: `A A B A A B A`
Row 2: `A A B A . . .`
Row 2 starts `A A B A`. Row 5 starts `A A B A`. This matches.
So, Row 2 is likely identical to Row 5.
If Row 2 = Row 5, then the missing part of Row 2 (cols 4, 5, 6) should be `A B A`.

Let's verify the horizontal pattern to ensure consistency.
Row 3: `A B A A B A A`
Is there a horizontal period?
`A B A A` ... `B A A`
It looks like `A B A A` repeats?
Index 0-3: `A B A A`
Index 4-6: `B A A` (Start of next `A B A A`?)
If period is 4:
Pos 0: A
Pos 1: B
Pos 2: A
Pos 3: A
Pos 4: A (Wait, Row 3 has B at pos 4).
So horizontal period is not 4.

Let's look at the sequence `A B A A B A A`.
Maybe the period is 3?
`A B A` `A B A` `A`?
Row 3: `A B A` `A B A` `A`.
Pos 0: A
Pos 1: B
Pos 2: A
Pos 3: A
Pos 4: B
Pos 5: A
Pos 6: A
This looks like `A B A` repeated, but shifted or modified?
Actually, look at Row 3: `A B A A B A A`.
Look at Row 4: `B A A B A A B`.
Look at Row 5: `A A B A A B A`.
Look at Row 6: `A B A A B A A` (Same as Row 3).

Let's 

... [5042 chars truncated]
alt-3 music qwen3.5-122b: k=1
"A conductor reconstructs a water-damaged measure by listening to the ostinato that loops unchanged through every other bar."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (9513 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A musical score with repeating motifs across rows and columns.
*   **Problem:** A rectangular block of "ink" (colored cells) has washed away, leaving "silence" (black cells, represented by `.`).
*   **Task:** Identify the repeating pattern (motif) from the visible parts and fill in the missing rectangular block.
*   **Output:** Only the reconstructed fragment (the missing block).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    A M . M
    M A M A
    A M A M
    M A M A
    ```
    *   Grid size: 4x4.
    *   Missing part: One cell at (0, 2) (0-indexed). It is `.`.
    *   Pattern observation:
        *   Row 0: A M . M
        *   Row 1: M A M A
        *   Row 2: A M A M
        *   Row 3: M A M A
    *   Looking at columns:
        *   Col 0: A, M, A, M (Alternating)
        *   Col 1: M, A, M, A (Alternating)
        *   Col 2: ., M, A, M (Alternating, missing top)
        *   Col 3: M, A, M, A (Alternating)
    *   Looking at rows:
        *   Row 1: M A M A (Alternating M, A)
        *   Row 2: A M A M (Alternating A, M)
        *   Row 3: M A M A (Alternating M, A)
        *   Row 0: A M . M. If it follows the alternating pattern A M A M, the missing cell should be `A`.
    *   Output: `A`.
    *   This confirms the task is to fill in the missing `.` cells based on the surrounding pattern. The output is just the filled-in block. In this case, the block is 1x1.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    A B A A . . .
    B A A B . . .
    A A B A . . .
    A B A A B A A
    B A A B A A B
    A A B A A B A
    A B A A B A A
    ```
*   **Dimensions:** 7 rows, 7 columns.
*   **Missing Area:**
    *   Rows 0, 1, 2 have `.` at columns 4, 5, 6.
    *   Rows 3, 4, 5, 6 are fully filled.
    *   So the missing block is a 3x3 rectangle at the top right corner (Rows 0-2, Cols 4-6).
*   **Goal:** Determine the values for the 3x3 block of `.`s.

**4. Pattern Recognition:**
Let's look at the filled rows (3, 4, 5, 6) to understand the structure.
Row 3: `A B A A B A A`
Row 4: `B A A B A A B`
Row 5: `A A B A A B A`
Row 6: `A B A A B A A`

Let's look at the columns.
Col 0: A, B, A, A, B, A, A
Col 1: B, A, A, B, A, A, B
Col 2: A, A, B, A, A, B, A
Col 3: A, B, A, A, B, A, A
Col 4: ., ., ., B, A, A, B
Col 5: ., ., ., A, A, B, A
Col 6: ., ., ., A, B, A, A

Let's check for periodicity.
Row 3: `A B A A B A A`
Row 6: `A B A A B A A`
Row 3 and Row 6 are identical. This suggests a vertical period of 3?
Let's check Row 0 vs Row 3.
Row 3: `A B A A B A A`
Row 0: `A B A A . . .`
If Row 0 is identical to Row 3, then the missing part is `B A A`.
Let's check Row 1 vs Row 4.
Row 4: `B A A B A A B`
Row 1: `B A A B . . .`
If Row 1 is identical to Row 4, then the missing part is `A A B`.
Let's check Row 2 vs Row 5.
Row 5: `A A B A A B A`
Row 2: `A A B A . . .`
If Row 2 is identical to Row 5, then the missing part is `A B A`.

Let's verify this hypothesis (Vertical Periodicity = 3).
Rows:
0: A B A A . . .
1: B A A B . . .
2: A A B A . . .
3: A B A A B A A
4: B A A B A A B
5: A A B A A B A
6: A B A A B A A

Comparison:
Row 0 matches Row 3 (first 4 chars match: A B A A).
Row 1 matches Row 4 (first 4 chars match: B A A B).
Row 2 matches Row 5 (first 4 chars match: A A B A).
Row 3 matches Row 6 (full match).

This strongly suggests the pattern repeats every 3 rows vertically.
So, Row 0 = Row 3 = Row 6.
Row 1 = Row 4.
Row 2 = Row 5.

Let's check horizontal periodicity as well to be sure.
Row 3: `A B A A B A A`
Indices: 0 1 2 3 4 5 6
Values: A B A A B A A
Is there a horizontal period?
A B A A ...
B A A B ...
A A B A ...
It looks like a shift or a specific sequence.
Let's look at the sequence `A B A A`.
Row 3: `A B A A` `B A A`
Row 4: `B A A B` `A A B`
Row 5: `A A B A` `A B A`
Row 6: `A B A A` `B A A`

It seems the rows are cyclic shifts of each other or follow a specific tiling.
Let's look at the columns again.
Col 0: A B A A B A A (Period 3: A B A, A B A, A) -> A B A A B A A. Wait.
A, B, A, A, B, A, A.
Indices: 0, 1, 2, 3, 4, 5, 6.
Values: A, B, A, A, B, A, A.
Pattern: A B A repeats?
0: A
1: B
2: A
3: A
4: B
5: A
6: A
Yes, A B A repeats.
Col 1: B A A B A A B.
Pattern: B A A repeats?
0: B
1: A
2: A
3: B
4: A
5: A
6: B
Yes, B A A repeats.
Col 2: A A B A A B A.
Pattern: A A B repeats?
0: A
1: A
2: B
3: A
4: A
5: B
6: A
Yes, A A B repeats.
Col 3: A B A A B A A.
Pattern: A B A repeats. Same as Col 0.
Col 4: . . . B A A B.
Pattern should be A B A.
So Col 4 should be:
0: A
1: B
2: A
3: B
4: A
5: A
6: B
Wait, Col 4 values from rows 3-6 are:
Row 3: B
Row 4: A
Row 5: A
Row 6: B
Sequence: B, A, A, B.
If the period is 3 (A B A), then:
Index 0: A
Index 1: B
Index 2: A
Index 3: A (Wait, pattern A B A -> 0:A, 1:B, 2:A, 3:A, 4:B, 5:A, 6:A).
Let's check Col 0 again.
0: A
1: B
2: A
3: A
4: B
5: A
6: A
Matches A B A A B A A.
So Col 4 should fo

... [4528 chars truncated]
alt-4 sports qwen3.5-122b: k=2
"A choreographer restores a marching band's formation chart after coffee spills over one corner, using the drill's strict repeating pattern."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11190 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A stadium field diagram with colored uniforms tiling in a precise repeating formation.
*   **Problem:** A rectangular section is stained (black `.`) and illegible.
*   **Task:** Read the cadence of the repeating formation block from the clean portion. Fill in the stained rectangle with the marchers who must stand there.
*   **Output:** Submit *only* that rectangle (the restored part).
*   **Grid Details:** Colored cells = uniformed marchers. Black `.` = coffee stain.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        A M . M
        M A M A
        A M A M
        M A M A
        ```
    *   Output:
        ```
        A
        ```
    *   Observation: The input grid is 4x4. There is one black cell at (0, 2) (0-indexed). The output is a 1x1 grid containing 'A'.
    *   Pattern Analysis:
        *   Row 1: M A M A
        *   Row 2: A M A M
        *   Row 3: M A M A
        *   Row 0: A M . M
        *   Looking at columns:
            *   Col 0: A, M, A, M (Alternating)
            *   Col 1: M, A, M, A (Alternating)
            *   Col 2: ., M, A, M (Alternating) -> If Col 0 is A, M, A, M... Col 2 should be A, M, A, M. The missing cell is at (0,2). The sequence in Col 2 is `.` (top), M, A, M. If it follows the pattern of Col 0 (A, M, A, M), the top should be A.
            *   Col 3: M, A, M, A (Alternating)
        *   Looking at rows:
            *   Row 1: M A M A (Alternating M, A)
            *   Row 2: A M A M (Alternating A, M)
            *   Row 3: M A M A (Alternating M, A)
            *   Row 0: A M . M. If it alternates A, M, A, M... then the missing one is A.
        *   The pattern seems to be a checkerboard of A and M.
        *   The output is the content of the black cell(s). Here, just one cell.

*   **Example 2:**
    *   Input:
        ```
        R B R B R
        B B B B B
        R B R B R
        . . B B B
        . . R B R
        ```
    *   Output:
        ```
        B B
        R B
        ```
    *   Observation: Input is 5x5. Black cells are at (3,0), (3,1), (4,0), (4,1). This forms a 2x2 rectangle at the bottom left.
    *   Output is a 2x2 grid.
    *   Pattern Analysis:
        *   Row 0: R B R B R (Alternating R, B)
        *   Row 1: B B B B B (All B)
        *   Row 2: R B R B R (Alternating R, B)
        *   Row 3: . . B B B
        *   Row 4: . . R B R
        *   Let's look at columns.
            *   Col 0: R, B, R, ., .
            *   Col 1: B, B, B, ., .
            *   Col 2: R, B, R, B, R
            *   Col 3: B, B, B, B, B
            *   Col 4: R, B, R, B, R
        *   It looks like columns 0, 2, 4 follow the pattern R, B, R, B, R.
        *   Columns 1, 3 follow the pattern B, B, B, B, B.
        *   So, Col 0 should be R, B, R, B, R. The missing cells are at indices 3 and 4. So (3,0) should be B, (4,0) should be R.
        *   Col 1 should be B, B, B, B, B. The missing cells are at indices 3 and 4. So (3,1) should be B, (4,1) should be B.
        *   Let's check the Output provided:
            ```
            B B
            R B
            ```
            Row 0 of output corresponds to Input Row 3.
            Row 1 of output corresponds to Input Row 4.
            Col 0 of output corresponds to Input Col 0.
            Col 1 of output corresponds to Input Col 1.
            So Output(0,0) = Input(3,0) = B.
            Output(0,1) = Input(3,1) = B.
            Output(1,0) = Input(4,0) = R.
            Output(1,1) = Input(4,1) = B.
            This matches my deduction based on column patterns.
            Row patterns:
            Row 0: R B R B R
            Row 1: B B B B B
            Row 2: R B R B R
            Row 3: . . B B B -> If pattern repeats every 2 rows (Row 0, Row 2 are same; Row 1 is different). Row 3 should match Row 1? Row 1 is B B B B B. So Row 3 should be B B B B B. Missing are B B.
            Row 4: . . R B R -> If pattern repeats every 2 rows (Row 0, Row 2, Row 4 are same). Row 4 should match Row 0 (R B R B R). Missing are R B.
            This confirms the output:
            Row 3: B B
            Row 4: R B
            Matches the example output.

**3. Analyze the Test Input:**
*   Input Grid:
    ```
    A B A A . . .
    B A A B . . .
    A A B A . . .
    A B A A B A A
    B A A B A A B
    A A B A A B A
    A B A A B A A
    ```
*   Dimensions: 7 rows, 7 columns.
*   Black cells (`.`):
    *   Row 0: Cols 4, 5, 6
    *   Row 1: Cols 4, 5, 6
    *   Row 2: Cols 4, 5, 6
    *   Rows 3-6: No black cells.
*   The "stain" is a 3x3 rectangle at the top right corner (Rows 0-2, Cols 4-6).
*   Task: Determine the values for these 9 cells.

**4. Conceptual Digestion:**

*   **CAST:**
    *   **Grid:** The canvas containing the pattern.
    *   **Colored Cells:** The "marchers" or data points defining the p

... [6199 chars truncated]
alt-5 weather qwen3.5-122b: fig alone solves
"A meteorologist fills in a satellite image's dead pixels by extending the perfectly periodic pressure-front pattern visible everywhere else."
alt-6 architecture qwen3.5-122b: fig alone solves
"A restorer replaces missing tiles in a Roman mosaic floor by deducing the small repeating unit that generates the entire design."
alt-7 warfare qwen3.5-122b: k=1
"A signals officer deciphers a garbled section of an encrypted message by recognizing the cipher key repeats on a fixed grid cycle."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (10143 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** An encoded message grid of colored symbols tiling in a rigid repeating key.
*   **Problem:** One rectangular block was lost to radio interference, replaced by static (black `.`).
*   **Goal:** Recover the key's dimensions from the intact transmission. Apply the repeating key to reconstruct the garbled block and relay only the restored portion to command.
*   **Output:** The decrypted block (the restored portion).

**2. Analyze the Training Example:**
*   **Input:**
    ```
    A M . M
    M A M A
    A M A M
    M A M A
    ```
*   **Output:**
    ```
    A
    ```
*   **Observation:**
    *   The input grid has a black cell (`.`) at position (0, 2) (0-indexed, row 0, col 2).
    *   The rest of the grid seems to follow a pattern.
    *   Let's look at the pattern.
        Row 0: A M . M
        Row 1: M A M A
        Row 2: A M A M
        Row 3: M A M A
    *   Rows 1, 2, 3 look like a checkerboard pattern of A and M.
        Row 1: M A M A
        Row 2: A M A M
        Row 3: M A M A
    *   Row 0 starts with A M. If the pattern continues, it should be A M A M.
    *   The black cell is at (0, 2). If the pattern is A M A M, then (0, 2) should be 'A'.
    *   The output is just `A`. This matches the missing cell.
    *   So the task is to identify the missing black cell(s) and fill them in based on the surrounding pattern, then output *only* the filled-in part.
    *   Wait, the output is a single cell `A`. The input had one black cell.
    *   Let's check the dimensions. Input is 4x4. Output is 1x1.
    *   The "restored portion" implies the area that was black.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    A B A A . . .
    B A A B . . .
    A A B A . . .
    A B A A B A A
    B A A B A A B
    A A B A A B A
    A B A A B A A
    ```
*   **Dimensions:** 7 rows, 7 columns.
*   **Black Cells (`.`):**
    *   Row 0: cols 4, 5, 6
    *   Row 1: cols 4, 5, 6
    *   Row 2: cols 4, 5, 6
    *   Rows 3-6: No black cells.
*   **Target Area:** A 3x3 block at the top right corner (Rows 0-2, Cols 4-6).
*   **Goal:** Determine the values for these 9 cells based on the repeating pattern found in the rest of the grid.

**4. Conceptual Digestion:**

*   **CAST:**
    *   **Colored Cells (A, B, etc.):** These form the "key" or the repeating pattern.
    *   **Black Cells (`.`):** These represent the "interference" or missing data.
    *   **Output:** The specific subgrid corresponding to the black cells, filled with the correct colors derived from the pattern.

*   **AFFORDANCES:**
    *   The colored cells define a periodicity (tiling).
    *   The black cells need to be inferred.
    *   The pattern likely repeats horizontally and vertically.

*   **TRANSFORMATION RULE:**
    1.  Identify the rectangular region of black cells (`.`).
    2.  Analyze the non-black cells to determine the repeating pattern (periodicity in rows and columns).
    3.  Extrapolate the pattern into the black region.
    4.  Extract the subgrid corresponding to the black region.
    5.  Output this subgrid.

**5. Pattern Analysis on Test Input:**

Let's look at the non-black part of the grid.
Rows 0-2, Cols 0-3 are visible.
Rows 3-6, Cols 0-6 are visible.

Let's look at the structure.
Row 3: `A B A A B A A`
Row 4: `B A A B A A B`
Row 5: `A A B A A B A`
Row 6: `A B A A B A A`

Notice Row 3 and Row 6 are identical: `A B A A B A A`.
This suggests a vertical period.
Row 3: `A B A A B A A`
Row 4: `B A A B A A B`
Row 5: `A A B A A B A`
Row 6: `A B A A B A A` (Same as Row 3)

Let's check Row 2: `A A B A . . .`
If the vertical period is 3 (Rows 3, 4, 5 repeat), then Row 2 should match Row 5? Or Row 0 matches Row 3?
Let's check the sequence of rows:
Row 3: `A B A A B A A`
Row 4: `B A A B A A B`
Row 5: `A A B A A B A`
Row 6: `A B A A B A A` (Matches Row 3)

So the vertical pattern seems to repeat every 3 rows.
Sequence: R3, R4, R5, R3...
So R0 should match R3.
R1 should match R4.
R2 should match R5.

Let's verify this hypothesis with the visible parts of Rows 0, 1, 2.
Hypothesis:
Row 0 == Row 3 == `A B A A B A A`
Row 1 == Row 4 == `B A A B A A B`
Row 2 == Row 5 == `A A B A A B A`

Let's check the visible cells in Rows 0, 1, 2 against this hypothesis.
**Row 0:**
Input: `A B A A . . .`
Hypothesis (Row 3): `A B A A B A A`
Match on cols 0-3: `A B A A` vs `A B A A`. Perfect match.
Missing cols 4-6 should be `B A A`.

**Row 1:**
Input: `B A A B . . .`
Hypothesis (Row 4): `B A A B A A B`
Match on cols 0-3: `B A A B` vs `B A A B`. Perfect match.
Missing cols 4-6 should be `A A B`.

**Row 2:**
Input: `A A B A . . .`
Hypothesis (Row 5): `A A B A A B A`
Match on cols 0-3: `A A B A` vs `A A B A`. Perfect match.
Missing cols 4-6 should be `A B A`.

**Horizontal Pattern Check:**
Let's check if there is a horizontal period as well, just to be sure.
Row 3: `A B A A B A A`
Ind

... [5152 chars truncated]
alt-8 theater qwen3.5-122b: k=2
"A stage manager re-blocks a scene after a lighting rig failure blacks out one section, inferring positions from the perfectly mirrored blocking pattern elsewhere."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (10799 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A stage grid with colored spotlight pools.
*   **Pattern:** They repeat in a precise periodic arrangement.
*   **Problem:** One rectangular zone has gone completely dark (black, `.`).
*   **Goal:** Study the surviving pattern to determine the repeating unit. Fill in the dark zone with the correct colors.
*   **Output:** The restored light cues (the filled-in dark zone).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        A M . M
        M A M A
        A M A M
        M A M A
        ```
    *   Output:
        ```
        A
        ```
    *   Observation: The input grid is 4x4. There is a single black cell at (0, 2) (0-indexed). The output is a 1x1 grid containing 'A'.
    *   Pattern Analysis:
        *   Row 0: A M . M
        *   Row 1: M A M A
        *   Row 2: A M A M
        *   Row 3: M A M A
        *   Looking at rows 1, 2, 3, there seems to be a checkerboard pattern of A and M.
        *   Row 1: M A M A
        *   Row 2: A M A M
        *   Row 3: M A M A
        *   Row 0 should follow the pattern. If Row 1 starts with M, Row 0 should start with A (alternating rows).
        *   Row 0: A M ? M.
        *   If it's a checkerboard:
            *   (0,0)=A, (0,1)=M, (0,2)=A, (0,3)=M.
            *   (1,0)=M, (1,1)=A, (1,2)=M, (1,3)=A.
        *   The missing cell is at (0,2). Based on the checkerboard pattern, it should be 'A'.
        *   The output is just the content of the missing zone. The missing zone is 1x1.
        *   So the task is to identify the black region and fill it based on the surrounding periodic pattern.

*   **Example 2:**
    *   Input:
        ```
        R B R B R
        B B B B B
        R B R B R
        . . B B B
        . . R B R
        ```
    *   Output:
        ```
        B B
        R B
        ```
    *   Observation: The input grid is 5x5.
    *   Black cells (`.`) are at:
        *   (3, 0), (3, 1)
        *   (4, 0), (4, 1)
    *   This forms a 2x2 rectangular zone at the bottom-left corner.
    *   The output is a 2x2 grid:
        ```
        B B
        R B
        ```
    *   Pattern Analysis:
        *   Let's look at the columns.
        *   Col 0: R, B, R, ., .
        *   Col 1: B, B, B, ., .
        *   Col 2: R, B, R, B, R
        *   Col 3: B, B, B, B, B
        *   Col 4: R, B, R, B, R
        *   It looks like columns 2 and 4 are identical: R, B, R, B, R.
        *   Column 3 is all B.
        *   Column 1 is all B.
        *   Column 0 is R, B, R...
        *   Let's look at rows.
        *   Row 0: R B R B R (Alternating R, B)
        *   Row 1: B B B B B (All B)
        *   Row 2: R B R B R (Alternating R, B)
        *   Row 3: . . B B B
        *   Row 4: . . R B R
        *   The pattern seems to repeat every 2 rows.
            *   Row 0 type: R B R B R
            *   Row 1 type: B B B B B
            *   Row 2 type: R B R B R (Same as Row 0)
            *   Row 3 type: Should be same as Row 1 (B B B B B).
            *   Row 4 type: Should be same as Row 2 (R B R B R).
        *   Let's check the black zone (Rows 3-4, Cols 0-1).
        *   Row 3 should be B B B B B. So (3,0)=B, (3,1)=B.
        *   Row 4 should be R B R B R. So (4,0)=R, (4,1)=B.
        *   The missing block is:
            ```
            B B
            R B
            ```
        *   This matches the output exactly.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Grid:** The canvas containing the pattern.
    *   **Colored Cells:** The "spotlight pools" representing the valid data/pattern.
    *   **Black Cells (`.`):** The "blown-fuse zone" or the "missing data" that needs to be reconstructed.
    *   **Output:** The specific subgrid corresponding to the black cells, filled with the inferred colors.

2.  **AFFORDANCES:**
    *   The colored cells exhibit periodicity (repetition) in rows and/or columns.
    *   The black cells form a contiguous rectangular block.
    *   The pattern can be extrapolated from the non-black cells to cover the black cells.

3.  **TRANSFORMATION RULE:**
    *   Identify the rectangular region of black cells (`.`).
    *   Analyze the surrounding non-black cells to determine the underlying periodic pattern (e.g., checkerboard, row repetition, column repetition, tiling).
    *   Extrapolate the pattern into the black region.
    *   Extract the subgrid corresponding to the black region's dimensions and content.
    *   Output this subgrid.

**4. Apply to Test Input:**

*   **Input Grid:**
    ```
    A B A A . . .
    B A A B . . .
    A A B A . . .
    A B A A B A A
    B A A B A A B
    A A B A A B A
    A B A A B A A
    ```
    Dimensions: 7 rows, 7 columns.

*   **Identify Black Zone:**
    *   Row 0: `A B A A . . .` -> Cols 4, 5, 6 are black.
    *   Row 1: `B A A B . . .` -> Cols 4, 5, 6 are black.
    

... [5841 chars truncated]
alt-9 gardening qwen3.5-122b: k=2
"A groundskeeper reseeds a rectangular bare patch in a formal garden by matching the strict color rotation of the surrounding flower beds."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11202 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A parterre garden with flower colors repeating in a small fixed pattern across rows and columns.
*   **Problem:** One rectangular bed has died off, leaving bare earth (black, represented by `.`).
*   **Task:** Determine the repeating pattern from the living flowers. Fill in the dead bed (black cells) with the correct colors to continue the pattern.
*   **Output:** List *only* the replanted section (the part that was black).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input:
        ```
        A M . M
        M A M A
        A M A M
        M A M A
        ```
    *   Output:
        ```
        A
        ```
    *   Observation:
        *   The grid is 4x4.
        *   There is one black cell at (0, 2) (0-indexed).
        *   The surrounding pattern looks like a checkerboard of A and M.
        *   Row 0: A M . M -> If pattern is A M A M, then . should be A.
        *   Row 1: M A M A
        *   Row 2: A M A M
        *   Row 3: M A M A
        *   The pattern seems to be a 2x2 tile:
            A M
            M A
        *   Or simply alternating A and M.
        *   The missing cell is at row 0, col 2.
        *   Row 0 pattern: A, M, A, M. So index 2 is A.
        *   Output is just `A`. This matches the instruction "list only the replanted section". Since the dead patch is 1x1, the output is 1x1.

*   **Example 2:**
    *   Input:
        ```
        R B R B R
        B B B B B
        R B R B R
        . . B B B
        . . R B R
        ```
    *   Output:
        ```
        B B
        R B
        ```
    *   Observation:
        *   Grid size: 5 rows, 5 columns.
        *   Black cells (dead patch):
            *   Row 3: cols 0, 1
            *   Row 4: cols 0, 1
            *   So the dead patch is a 2x2 rectangle at bottom-left.
        *   Let's find the pattern.
        *   Row 0: R B R B R (Alternating R, B)
        *   Row 1: B B B B B (All B) -> Wait, this breaks the simple alternating pattern.
        *   Row 2: R B R B R (Same as Row 0)
        *   Row 3: . . B B B
        *   Row 4: . . R B R
        *   Let's look at columns.
        *   Col 0: R, B, R, ., .
        *   Col 1: B, B, B, ., .
        *   Col 2: R, B, R, B, R
        *   Col 3: B, B, B, B, B
        *   Col 4: R, B, R, B, R
        *   It looks like columns 0, 2, 4 follow pattern R, B, R, B, R.
        *   Columns 1, 3 follow pattern B, B, B, B, B.
        *   So the pattern repeats every 2 columns?
            *   Col 0: R B R B R
            *   Col 1: B B B B B
            *   Col 2: R B R B R (Same as Col 0)
            *   Col 3: B B B B B (Same as Col 1)
            *   Col 4: R B R B R (Same as Col 0)
        *   So the horizontal period is 2.
        *   Let's check rows.
            *   Row 0: R B R B R
            *   Row 1: B B B B B
            *   Row 2: R B R B R (Same as Row 0)
            *   Row 3: . . B B B (Should match Row 1 pattern B B B B B)
            *   Row 4: . . R B R (Should match Row 0 pattern R B R B R)
        *   So the vertical period is 2.
        *   The tile is 2x2:
            R B
            B B
        *   Let's check the dead patch location.
            *   Rows 3, 4. Cols 0, 1.
            *   Row 3 corresponds to Row 1 (since period is 2, 3 % 2 = 1). Row 1 is B B B B B. So cols 0, 1 should be B B.
            *   Row 4 corresponds to Row 0 (since period is 2, 4 % 2 = 0). Row 0 is R B R B R. So cols 0, 1 should be R B.
        *   Expected fill:
            Row 3, Cols 0-1: B B
            Row 4, Cols 0-1: R B
        *   Output given:
            B B
            R B
        *   This matches perfectly.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Colored Cells:** Represent the "living flowers". They define the periodic tiling pattern.
    *   **Black Cells (`.`):** Represent the "dead bed". This is the target area to be filled.
    *   **Grid:** The canvas containing both.
    *   **Output:** A subgrid corresponding exactly to the bounding box of the black cells, filled with the inferred pattern colors.

2.  **AFFORDANCES:**
    *   **Colored Cells:** Can be analyzed to find periodicity (horizontal and vertical).
    *   **Black Cells:** Can be replaced by inferred colors.
    *   **Pattern:** Can be extrapolated from existing colored cells to cover the black cells.

3.  **TRANSFORMATION RULE:**
    *   Identify the rectangular region of black cells (`.`).
    *   Analyze the non-black cells to determine the periodicity of the pattern (width $W$ and height $H$).
    *   The pattern repeats such that $Grid[r][c] = Grid[r \% H][c \% W]$ (assuming the pattern starts at 0,0, or finding the phase shift). More generally, $Grid[r][c] = Grid[r + kH][c + mW]$.
    *   Fill the black cells using this periodicity.
    *   Extract the subgrid corresponding to the black cells' 

... [6241 chars truncated]

Task 983: fbf15a0b

Training Examples

Ex1 In
Ex1 Out
Ex2 In
Ex2 Out
Ex3 In
Ex3 Out
Ex4 In
Ex4 Out
Test Input
Expected Output

Variants

Variant Domain Metaphor MARC Status Min k
original A pair of scissors snips along the dotted line, and the scrap paper falls away. MARC valid 2
alt-1 biology Two enzyme markers bind to the membrane wall, triggering mitosis in reverse R ... [142 chars truncated] fail
alt-10 astronomy Two binary pulsars orbit at the edge of a galaxy. Their synchronized pulses trig ... [214 chars truncated] fail
alt-11 ocean/sailing Two buoys bob at one edge of the nautical chart. The harbormaster draws a line b ... [184 chars truncated] fig alone solves
alt-12 electronics Two test probes touch down on one edge of the circuit board. A voltage spike alo ... [186 chars truncated] fail
alt-13 mythology Two runes are carved into one wall of the labyrinth. When read aloud, the labyri ... [163 chars truncated] MARC valid 4
alt-14 dance Two dancers freeze in position at one wing of the stage. The choreographer claps ... [148 chars truncated] MARC valid 4
alt-15 geology Two fault markers are exposed in one cliff face of the canyon. A seismic event s ... [183 chars truncated] fig alone solves
alt-2 cooking Two cloves pressed into the crust mark where the chef's knife will fall. The bla ... [151 chars truncated] fail
alt-3 music Two tuning pegs sit at one end of the instrument's neck. When tightened, they si ... [151 chars truncated] fig alone solves
alt-4 sports Two referees stand at one sideline, arms raised. At their signal the pitch split ... [190 chars truncated] MARC valid 2
alt-5 weather Two lightning rods stand on the roof's edge, and when the storm breaks, a curtai ... [138 chars truncated] fail
alt-6 architecture Two keystones are embedded in one facade of the cathedral. The master builder de ... [135 chars truncated] fig alone solves
alt-7 warfare Two signal flags are planted along the front line. The general orders a strategi ... [159 chars truncated] fail
alt-8 theater Two stagehands pin marks on one edge of the curtain. When the cue comes, the cur ... [150 chars truncated] MARC valid 1
alt-9 gardening Two stakes are driven into the soil at one border of the garden. Come autumn, th ... [148 chars truncated] fail
original qwen3.5-122b: k=2
"A pair of scissors snips along the dotted line, and the scrap paper falls away."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (11876 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Canvas:** The grid itself.
*   **Azure:** The background color (A).
*   **Tapestry patterns:** Other colors forming patterns on the grid.
*   **Grey pins:** Two grey pixels (X) marking a cut line.
*   **Cut:** The grid is cut in half along the line defined by the pins.
*   **Direction:** The pins whisper which direction to slice (across or down).
*   **Keeper:** The half with the pins is kept.
*   **Discard:** The other half is removed.
*   **Patch:** The pin holes (X) are replaced with Azure (A).
*   **Dimensions:** The cut is clean, resulting in exactly half the original size in one direction.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input Size: 20 rows, 21 columns.
    *   Output Size: 10 rows, 21 columns.
    *   Observation: The height is halved (20 -> 10). The width remains the same.
    *   Pin Location: There are two 'X' (grey) pixels in the input.
        *   Row 0, Col 0: X
        *   Row 2, Col 0: X
        *   Wait, let's look closer at the input grid provided in the text.
        *   Input Row 0: `X A A A A A A A A A A A A A A A A A A A A` (21 chars)
        *   Input Row 2: `X B A B A B A B A B A B A B A B A B A B` (21 chars)
        *   The 'X's are in the first column (index 0).
        *   They are in Row 0 and Row 2.
        *   Wait, the description says "two grey pins have been pressed into the frame".
        *   In Example 1, the X's are at (0,0) and (2,0).
        *   The output has 10 rows. The input has 20 rows.
        *   The output rows correspond to the first 10 rows of the input? Or the last 10?
        *   Let's check the content.
        *   Input Row 0: `X A A ...` -> Output Row 0: `A A A ...` (X became A).
        *   Input Row 1: `A A A ...` -> Output Row 1: `A A A ...`
        *   Input Row 2: `X B A ...` -> Output Row 2: `A B A ...` (X became A).
        *   Input Row 3: `A A A ...` -> Output Row 3: `A A A ...`
        *   ...
        *   Input Row 9: `A B A ...` -> Output Row 9: `A B A ...`
        *   Input Row 10: `A B A ...` -> This row is NOT in the output.
        *   So the top half (rows 0-9) is kept. The bottom half (rows 10-19) is discarded.
        *   The pins are in the top half (Row 0 and Row 2).
        *   Rule confirmation: Keep the half containing the pins. Replace pins with Azure (A).
        *   Wait, the description says "The two pins mark where the scissors should cut. They whisper which direction to slice".
        *   In Example 1, the pins are in the first column. They seem to indicate a horizontal cut line? Or do they indicate the side to keep?
        *   The description says "The half with the pins is the keeper".
        *   Since the pins are in the top half (rows 0-9), the top half is kept.
        *   The cut divides the 20 rows into two 10-row sections.
        *   The pins are located at (0,0) and (2,0). Both are in the top half.
        *   So, find the two 'X's. Determine which half of the grid they fall into (top/bottom or left/right). Keep that half. Replace 'X' with 'A'.

*   **Example 2:**
    *   Input Size: 20 rows, 10 columns.
    *   Output Size: 10 rows, 10 columns.
    *   Observation: Height halved (20 -> 10). Width same.
    *   Pin Location:
        *   Row 0, Col 9: X
        *   Row 2, Col 9: X
        *   (Indices: 0-based)
        *   Input Row 0: `A A A A A A A A A X`
        *   Input Row 2: `A A A A A A A A A X`
    *   The pins are in the top half (Rows 0-9).
    *   Output corresponds to Input Rows 0-9.
    *   Pins at (0,9) and (2,9) become 'A'.
    *   Output Row 0: `A A A A A A A A A A`
    *   Output Row 2: `A A A A A A A A A A`
    *   This confirms the rule: Find the two 'X's. Determine the split dimension (height or width). The grid dimensions are always even in the split direction. Keep the half containing the 'X's. Replace 'X's with 'A'.

**3. Conceptual Digestion:**

1.  **CAST:**
    *   **Grid:** The canvas.
    *   **Azure (A):** Background color, used for patching holes.
    *   **Grey (X):** Pins. They mark the location of the "keeper" half.
    *   **Other Colors (B, W, O, etc.):** Tapestry patterns. They are preserved in the kept half.

2.  **AFFORDANCES:**
    *   **X:** Can be found. Indicates the side to keep. Can be replaced by A.
    *   **Grid Dimensions:** Can be halved.
    *   **Half:** Can be selected based on the presence of X.

3.  **TRANSFORMATION RULE:**
    *   Step 1: Locate the two 'X' (grey) pixels in the input grid.
    *   Step 2: Determine the axis of symmetry/cut.
        *   If the grid width is even and height is odd, cut vertically?
        *   If the grid height is even and width is odd, cut horizontally?
        *   If both are even, look at the position of X.
        *   In Example 1: 20x21. Height is even (20), Width is odd (21). Cut is horizontal (halvin

... [6968 chars truncated]
alt-1 biology qwen3.5-122b: fail
"Two enzyme markers bind to the membrane wall, triggering mitosis in reverse — the cell cleaves along the marked axis, and only the half bearing the binding sites survives, its scars healing over with fresh cytoplasm."
Fail (best cell_acc=0.44 at k=2)
Best Attempt
vs
Expected
Reasoning (12036 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Context:** A living cell with organelles and two enzyme markers embedded in one wall of its membrane.
*   **Action:** The cell divides along the axis the enzymes indicate.
*   **Outcome:** The half carrying the enzymes persists, while the other half dissolves. The enzyme sites heal over (become background).
*   **Grid Details:** The output is half the input along the marked axis. Enzyme markers become background.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** 20 rows, 21 columns.
    *   **Colors:** A (azure/background), B (blue/organelles?), X (grey/enzymes?).
    *   **Observation:**
        *   Row 0: `X A A ...` (Starts with X)
        *   Row 2: `X B A B ...` (Starts with X)
        *   The X's appear in the first column (index 0).
        *   Wait, let's look closer.
        *   Row 0: `X A A A A A A A A A A A A A A A A A A A` (21 chars)
        *   Row 2: `X B A B A B A B A B A B A B A B A B A B`
        *   Other rows start with `A`.
        *   So the "enzymes" (X) are in the first column.
        *   The output has 10 rows. The input had 20 rows.
        *   The output rows match rows 2, 4, 6, 8, 10, 12, 14, 16, 18, 20 of the input? No.
        *   Let's check the output content.
        *   Output Row 0: `A A A ...` (Matches Input Row 1)
        *   Output Row 1: `A A A ...` (Matches Input Row 3)
        *   Output Row 2: `A B A B ...` (Matches Input Row 4)
        *   Wait, let's look at the dimensions.
        *   Input: 20 rows x 21 cols.
        *   Output: 10 rows x 21 cols.
        *   The output height is exactly half the input height.
        *   The X's are in the first column. This suggests a vertical cut? Or a horizontal cut?
        *   If the enzymes are in the first column, they indicate a vertical axis? Or do they indicate the cut line?
        *   "The cell divides along the axis the enzymes indicate".
        *   If enzymes are in column 0, maybe the cut is horizontal?
        *   Let's look at the content.
        *   Input Row 0 has X. Input Row 2 has X.
        *   Output Row 0 is `A A A ...`. Input Row 1 is `A A A ...`.
        *   Output Row 1 is `A A A ...`. Input Row 3 is `A A A ...`.
        *   Output Row 2 is `A B A B ...`. Input Row 4 is `A B A B ...`.
        *   It seems the output consists of rows 1, 3, 4, 5, 6, 7, 8, 9, 10, 11... wait.
        *   Let's count rows in Output Example 1.
        *   Output has 10 rows.
        *   Input has 20 rows.
        *   The X's are at (0,0) and (2,0).
        *   The output seems to be the bottom half? Or top half?
        *   Input Rows 0-9 vs Input Rows 10-19.
        *   Input Row 0: `X A ...`
        *   Input Row 10: `A B A B ...`
        *   Output Row 0: `A A A ...` (Matches Input Row 1)
        *   Output Row 9: `A B A B ...` (Matches Input Row 19? No, Input Row 19 is `A A A ...`)
        *   Let's check Input Row 19: `A A A ...`
        *   Output Row 9: `A B A B ...`
        *   Let's check Input Row 18: `A A A ...`
        *   Let's check Input Row 17: `A A A ...`
        *   Let's check Input Row 16: `A A A ...`
        *   Let's check Input Row 15: `A A A ...`
        *   Let's check Input Row 14: `A B A B ...`
        *   Let's check Input Row 13: `A A A ...`
        *   Let's check Input Row 12: `A B A B ...`
        *   Let's check Input Row 11: `A A A ...`
        *   Let's check Input Row 10: `A B A B ...`
        *   Let's check Input Row 9: `A B A B ...`
        *   Let's check Input Row 8: `A A A ...`
        *   Let's check Input Row 7: `A B A B ...`
        *   Let's check Input Row 6: `A B A B ...`
        *   Let's check Input Row 5: `A A A ...`
        *   Let's check Input Row 4: `A B A B ...`
        *   Let's check Input Row 3: `A A A ...`
        *   Let's check Input Row 2: `X B A B ...`
        *   Let's check Input Row 1: `A A A ...`
        *   Let's check Input Row 0: `X A A A ...`

        *   Output Row 0: `A A A ...` (Matches Input Row 1)
        *   Output Row 1: `A A A ...` (Matches Input Row 3)
        *   Output Row 2: `A B A B ...` (Matches Input Row 4)
        *   Output Row 3: `A A A ...` (Matches Input Row 5)
        *   Output Row 4: `A B A B ...` (Matches Input Row 6)
        *   Output Row 5: `A B A B ...` (Matches Input Row 7)
        *   Output Row 6: `A A A ...` (Matches Input Row 8)
        *   Output Row 7: `A B A B ...` (Matches Input Row 9)
        *   Output Row 8: `A B A B ...` (Matches Input Row 10)
        *   Output Row 9: `A B A B ...` (Matches Input Row 12) -- Wait, Input Row 11 is `A A A ...`.
        *   Let's re-read the Output Example 1 carefully.
        *   Output:
            1. `A A A ...`
            2. `A A A ...`
            3. `A B A B ...`
            4. `A A A ...`
            5. `A B A B ...`
            6. `A A A ...`
            7. `A B A B ...`
        

... [7048 chars truncated]
alt-10 astronomy qwen3.5-122b: fail
"Two binary pulsars orbit at the edge of a galaxy. Their synchronized pulses trigger a gravitational shear that bisects the galaxy — the far arm spirals into the void, while the pulsar-side endures. The pulsars themselves collapse into dark matter, invisible against the cosmic background."
Fail (best cell_acc=0.44 at k=2)
Best Attempt
vs
Expected
Reasoning (12435 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A galaxy with star clusters in repeating patterns and two pulsars positioned at one rim.
*   **What to do:** The galaxy is sheared in half along the pulsar axis. The far half disperses. The pulsars go dark.
*   **Grid details:** Output is the pulsar-side half. Pulsar positions become empty space.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** 20 rows, 19 columns.
        *   Background seems to be 'A' (azure).
        *   There is a pattern of 'B' (blue) and 'A' (azure) in some rows.
        *   There are two 'X' (grey) pixels in the first column (column 0).
            *   Row 0: `X A A ...`
            *   Row 2: `X B A ...`
        *   Wait, let's look closer at the 'X' positions.
        *   Row 0, Col 0 is 'X'.
        *   Row 2, Col 0 is 'X'.
        *   Are there other 'X's? Scanning... No other 'X's visible in the input text provided.
        *   The 'X's are on the left edge (Column 0).
    *   **Output:** 10 rows, 19 columns.
        *   The output height is exactly half of the input height (20 -> 10).
        *   The 'X's are gone.
        *   The content looks like the top half of the input, but with the 'X's replaced by 'A'.
        *   Let's check the rows.
        *   Input Row 0: `X A A ...` -> Output Row 0: `A A A ...` (X became A)
        *   Input Row 1: `A A A ...` -> Output Row 1: `A A A ...`
        *   Input Row 2: `X B A ...` -> Output Row 2: `A B A ...` (X became A)
        *   Input Row 3: `A A A ...` -> Output Row 3: `A A A ...`
        *   ...
        *   Input Row 9: `A B A ...` -> Output Row 9: `A B A ...`
        *   Input Row 10: `A B A ...` -> This row is NOT in the output.
        *   So the transformation cuts the grid in half horizontally.
        *   Which half? The top half (rows 0-9).
        *   Why the top half? The 'X's (pulsars) are in the top half (rows 0 and 2).
        *   The description says "Output is the pulsar-side half". Since pulsars are at the top, we keep the top half.
        *   "Pulsar positions become empty space." In the output, the 'X's are replaced by 'A' (azure). 'A' seems to be the background color here.
        *   "The far half disperses." The bottom half (rows 10-19) is discarded.

*   **Example 2:**
    *   **Input:** 20 rows, 10 columns.
        *   Background 'A'.
        *   Pattern 'O' (orange) and 'A'.
        *   'X' (grey) positions:
            *   Row 0, Col 9: `... A X`
            *   Row 2, Col 9: `... A X`
        *   The 'X's are on the right edge (Column 9).
    *   **Output:** 10 rows, 10 columns.
        *   Height is halved (20 -> 10).
        *   The 'X's are gone (replaced by 'A').
        *   The content corresponds to the top half of the input (Rows 0-9).
        *   Wait, let's check the rows again.
        *   Input Row 0: `A A A A A A A A A X` -> Output Row 0: `A A A A A A A A A A`
        *   Input Row 1: `A O A O A O A O A A` -> Output Row 1: `A O A O A O A O A A`
        *   Input Row 2: `A A A A A A A A A X` -> Output Row 2: `A A A A A A A A A A`
        *   ...
        *   Input Row 9: `A A A A A A A A A A` -> Output Row 9: `A A A A A A A A A A`
        *   Input Row 10: `A O A O A O A O A A` -> Discarded.
        *   So again, the grid is cut in half horizontally.
        *   The 'X's are in the top half.
        *   The output is the top half.
        *   'X's become 'A'.

    *   **Wait, is it always horizontal cut?**
    *   In Example 1, 'X's are at (0,0) and (2,0). Top-left.
    *   In Example 2, 'X's are at (0,9) and (2,9). Top-right.
    *   In both cases, the cut is horizontal, keeping the top half.
    *   The description says "sheared in half along the pulsar axis".
    *   If the pulsars are at the "rim", and the output is the "pulsar-side half".
    *   In both examples, the pulsars are in the top half of the grid. So the "pulsar-side half" is the top half.
    *   The cut seems to be exactly in the middle of the height.
    *   Input Height 20 -> Output Height 10.
    *   Input Width stays the same.
    *   'X' pixels are replaced by the background color 'A'.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    A W A W A X A X
    A A A A A A A A
    A W A W A W A W
    A A A A A A A A
    ```
*   **Dimensions:** 4 rows, 8 columns.
*   **Content:**
    *   Row 0: `A W A W A X A X`
    *   Row 1: `A A A A A A A A`
    *   Row 2: `A W A W A W A W`
    *   Row 3: `A A A A A A A A`
*   **Pulsars ('X'):**
    *   Row 0, Col 5: `X`
    *   Row 0, Col 7: `X`
    *   They are in the top row (Row 0).
*   **Transformation Logic:**
    1.  **Identify Pulsars:** Locate 'X' pixels. Here they are at (0, 5) and (0, 7).
    2.  **Determine Half:** The pulsars are in the top half of the grid. The grid height is 4. Half is 2. So we keep rows 0 and 1.
  

... [7505 chars truncated]
alt-11 ocean/sailing qwen3.5-122b: fig alone solves
"Two buoys bob at one edge of the nautical chart. The harbormaster draws a line between them and declares everything beyond the channel's midpoint off-limits — that half of the chart is torn away and discarded. The buoys are then erased, their purpose served."
alt-12 electronics qwen3.5-122b: fail
"Two test probes touch down on one edge of the circuit board. A voltage spike along their axis fries every trace beyond the midpoint — that half of the board goes dead and is snapped off. The probe contacts are soldered over, flush with the copper ground plane."
Fail (best cell_acc=0.44 at k=2)
Best Attempt
vs
Expected
Reasoning (13134 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A PCB (Printed Circuit Board) with repeating component patterns and two probe contact points on one edge.
*   **What to do:** The board is split at its center along the probe axis. The dead half is removed. Probe points are soldered flat.
*   **Grid details:** Output is the probe-side half. Probe locations become ground plane.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** 20 rows, 19 columns.
        *   Row 0: `X A A ...` (Starts with X)
        *   Row 2: `X B A B ...` (Starts with X)
        *   Other rows seem to be patterns of A and B.
        *   There are `X` characters in the first column at row 0 and row 2.
        *   The rest of the grid is filled with `A` and `B`.
    *   **Output:** 10 rows, 19 columns.
        *   The output height is exactly half of the input height (20 -> 10).
        *   The output width is the same as the input width (19).
        *   The content of the output matches the top half of the input, but with modifications.
        *   Let's check the top half of the input (rows 0-9):
            *   Row 0: `X A A ...` -> Output Row 0: `A A A ...` (X became A)
            *   Row 1: `A A A ...` -> Output Row 1: `A A A ...`
            *   Row 2: `X B A ...` -> Output Row 2: `A B A ...` (X became A)
            *   Row 3: `A A A ...` -> Output Row 3: `A A A ...`
            *   ...
            *   Row 9: `A B A ...` -> Output Row 9: `A B A ...`
        *   Wait, let's look closer at the input rows 0-9 vs output rows 0-9.
        *   Input Row 0: `X A A A A A A A A A A A A A A A A A A A`
        *   Output Row 0: `A A A A A A A A A A A A A A A A A A A A`
        *   Input Row 2: `X B A B A B A B A B A B A B A B A B A B`
        *   Output Row 2: `A B A B A B A B A B A B A B A B A B A B`
        *   It seems the `X` characters in the first column of the top half are replaced by `A`.
        *   The bottom half of the input (rows 10-19) is discarded.
        *   Why is the top half chosen? The description says "two probe contact points on one edge". In the input, `X` appears in the first column (left edge). There are two `X`s in the top half (Row 0 and Row 2). There are no `X`s in the bottom half.
        *   So the "probe axis" is likely the horizontal line separating the top and bottom halves. The "probe points" are the `X`s.
        *   "The board is split at its center along the probe axis." -> Split horizontally in the middle.
        *   "The dead half is removed." -> The half without probes (bottom half) is removed.
        *   "Probe points are soldered flat." -> The `X`s are replaced by the background color or a specific color. In this case, `X` becomes `A`. `A` seems to be the background color (azure).
        *   "Output is the probe-side half." -> Top half.
        *   "Probe locations become ground plane." -> `X` becomes `A`.

*   **Example 2:**
    *   **Input:** 20 rows, 10 columns.
        *   Row 0: `A A A A A A A A A X` (Ends with X)
        *   Row 2: `A A A A A A A A A X` (Ends with X)
        *   Other rows have patterns of `A` and `O`.
        *   `X` appears in the last column (right edge).
        *   `X` appears in Row 0 and Row 2.
    *   **Output:** 10 rows, 10 columns.
        *   Height is halved (20 -> 10).
        *   Width is same (10).
        *   Content matches top half of input.
        *   Input Row 0: `A A A A A A A A A X` -> Output Row 0: `A A A A A A A A A A` (X became A)
        *   Input Row 2: `A A A A A A A A A X` -> Output Row 2: `A A A A A A A A A A` (X became A)
        *   Again, the `X`s are replaced by `A`.
        *   The bottom half is discarded.
        *   The `X`s are on the right edge. The split is horizontal.
        *   Wait, the description says "split at its center along the probe axis".
        *   In Example 1, probes were on the Left Edge. Split was Horizontal.
        *   In Example 2, probes were on the Right Edge. Split was Horizontal.
        *   Is the split always horizontal? Or does it depend on where the probes are?
        *   In both examples, the input height is 20, output height is 10. The split is always horizontal (top half kept).
        *   The `X`s are the "probe contact points".
        *   In Example 1, `X` is at (0,0) and (2,0).
        *   In Example 2, `X` is at (0,9) and (2,9).
        *   In both cases, the `X`s are in the top half of the grid.
        *   The rule seems to be: Find the half containing the `X` markers. Keep that half. Replace `X` with `A` (background color).
        *   Wait, let's check if the split is always top/bottom.
        *   Input dimensions: 20x19 (Ex1), 20x10 (Ex2).
        *   Output dimensions: 10x19 (Ex1), 10x10 (Ex2).
        *   It seems the grid is always split horizontally in the middle.
        *   The "probe 

... [8196 chars truncated]
alt-13 mythology qwen3.5-122b: k=4
"Two runes are carved into one wall of the labyrinth. When read aloud, the labyrinth folds upon itself — the far half crumbles to dust, leaving only the corridors nearest the inscriptions. The runes fade into the stone, their magic spent."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (11754 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A labyrinth with patterned mosaics on its floors and two glowing runes on one outer wall.
*   **What to do:** The labyrinth collapses its far half. The rune-bearing half remains. The runes extinguish.
*   **Grid details:** Output is the rune-side half with rune positions returning to bare stone.

**Key Interpretations:**
*   "Labyrinth": The grid itself.
*   "Patterned mosaics": The background pattern (likely the repeating colors like A, B, G, Y, etc.).
*   "Two glowing runes on one outer wall": There are specific markers (likely 'X' based on the color key where X=grey, often used as a marker) located on one side of the grid.
*   "Collapses its far half": The grid is split in half. One half is kept, the other is discarded.
*   "Rune-bearing half remains": The half containing the 'X' markers is the one kept.
*   "Runes extinguish": The 'X' markers in the output should be replaced by the background color (likely 'A' or whatever the "bare stone" is).
*   "Output is the rune-side half": This implies a cropping operation.

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** 20 rows, 21 columns.
    *   Row 0: `X A A ...` (Starts with X)
    *   Row 2: `X B A B ...` (Starts with X)
    *   Other rows start with A.
    *   There are 'X's in the first column (Column 0).
    *   The grid seems to have a pattern of 'A' and 'B'.
*   **Output:** 10 rows, 21 columns.
    *   Wait, let's look closer.
    *   Input height: 20. Output height: 10.
    *   Input width: 21. Output width: 21.
    *   The output looks like the top half of the input?
    *   Let's check the content.
    *   Input Row 0: `X A A ...` -> Output Row 0: `A A A ...` (X became A).
    *   Input Row 1: `A A A ...` -> Output Row 1: `A A A ...`
    *   Input Row 2: `X B A B ...` -> Output Row 2: `A B A B ...` (X became A).
    *   Input Row 3: `A A A ...` -> Output Row 3: `A A A ...`
    *   ...
    *   Input Row 19: `A A A ...` -> Not in output.
    *   So, the output is the top half (rows 0-9).
    *   The 'X's are in the top half (Rows 0 and 2).
    *   The 'X's are replaced by 'A'.
    *   The bottom half (rows 10-19) is discarded.
    *   Why top half? Because the 'X's are in the top half.
    *   Wait, let's check the position of X.
    *   Input Row 0, Col 0 is X.
    *   Input Row 2, Col 0 is X.
    *   Are there X's in the bottom half? No.
    *   So the rule "Rune-bearing half remains" holds. The half containing X is kept.
    *   "Runes extinguish": X becomes A (the background color).
    *   "Collapses its far half": The other half is removed.
    *   Split direction: Horizontal split (top vs bottom).
    *   How to determine split direction? Usually, if X is on the left/right edge, it might be vertical. If X is on top/bottom edge, it might be horizontal. Here X is in Column 0 (left edge). But the split was horizontal (top half kept).
    *   Let's re-read the metaphor: "two glowing runes on one outer wall".
    *   In Example 1, X is at (0,0) and (2,0). This is the left wall.
    *   But the output is the top half. This contradicts "Rune-bearing half remains" if the split is vertical. If the split is vertical, the left half should be kept.
    *   Let's check the dimensions again.
    *   Input: 20x21. Output: 10x21.
    *   This is a horizontal cut. Top 10 rows kept.
    *   Why top? Maybe because the X's are in the top half?
    *   Let's check if there are X's in the bottom half. No.
    *   So the "Rune-bearing half" is the top half.
    *   Wait, the X's are on the *left* wall (Column 0).
    *   Maybe the "wall" refers to the edge of the *half*?
    *   Or maybe the split is determined by the location of the X's relative to the center.
    *   If X is in rows 0-9, keep rows 0-9.
    *   If X is in rows 10-19, keep rows 10-19.
    *   Let's check Example 2.

**Example 2:**
*   **Input:** 20 rows, 10 columns.
    *   Row 0: `A A A A A A A A A X` (X at end)
    *   Row 2: `A A A A A A A A A X` (X at end)
    *   X's are in Column 9 (Right edge).
    *   Rows with X: 0, 2.
    *   Output: 10 rows, 10 columns.
    *   Output Row 0: `A A A A A A A A A A` (X became A).
    *   Output Row 2: `A A A A A A A A A A` (X became A).
    *   Output contains rows 0-9 of input.
    *   Input rows 10-19 are discarded.
    *   Again, horizontal split. Top half kept.
    *   X's are in the top half (rows 0, 2).
    *   So the rule seems to be: Find the half (top/bottom or left/right) that contains the 'X' markers. Keep that half. Replace 'X' with background color 'A'.
    *   Wait, in Example 1 and 2, the split was horizontal (Top vs Bottom).
    *   In Example 1, X was on the Left edge. In Example 2, X was on the Right edge.
    *   In both cases, the split was horizontal.
    *   Why? Maybe because the grid is taller than it is wide?
    *   E

... [6820 chars truncated]
alt-14 dance qwen3.5-122b: k=4
"Two dancers freeze in position at one wing of the stage. The choreographer claps — the ensemble retreats, and the stage itself contracts to half its width toward the frozen pair. They bow out, replaced by empty floorboard."
MARC valid, solved with k=4
Prediction
vs
Expected
Reasoning (11902 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** "A stage with dancers arranged in repeating formations and two dancers frozen at one wing."
    *   "Dancers arranged in repeating formations": This likely refers to the patterned background or the main content of the grid (e.g., alternating colors like A B A B).
    *   "Two dancers frozen at one wing": This likely refers to specific distinct markers, possibly the 'X' (grey) characters seen in the examples. In the examples, 'X' appears in specific locations.
*   **What to do:** "The stage halves along the axis of the frozen dancers, keeping their side. They exit, leaving bare floor."
    *   "The stage halves along the axis of the frozen dancers": This suggests a cut or split. The 'X's define the axis or the boundary.
    *   "Keeping their side": We keep the part of the grid that contains the 'X's? Or the part defined by them? Let's look at the examples.
    *   "They exit, leaving bare floor": The 'X's themselves disappear (become 'A' or whatever the background color is).
    *   "Output is the frozen-dancer side. Their positions become bare stage."

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   Input: 20x21 grid.
    *   Pattern: Mostly 'A' (azure) and 'B' (blue) in a checkerboard-like or alternating row pattern.
    *   Markers: Two 'X' (grey) characters.
        *   Row 0, Col 0: 'X'
        *   Row 2, Col 0: 'X'
    *   Output: 10x21 grid.
    *   Observation: The output height is exactly half the input height (20 -> 10). The width remains the same (21).
    *   The 'X's were in the top half (rows 0 and 2). The output corresponds to the top half of the input grid (rows 0-9).
    *   Wait, let's check the content.
        *   Input Row 0: `X A A ...` -> Output Row 0: `A A A ...` (X became A).
        *   Input Row 2: `X B A ...` -> Output Row 2: `A B A ...` (X became A).
        *   Input Rows 10-19 are discarded.
    *   So, the rule seems to be: Find the 'X's. They define a split. Keep the half containing the 'X's. Remove the 'X's (replace with background 'A').
    *   Wait, the description says "The stage halves along the axis of the frozen dancers". In Ex 1, the X's are at the top left. The grid is split horizontally? Or vertically?
    *   Input height 20. Output height 10. Split is horizontal. The X's are in the top half. So we keep the top half.
    *   The X's are replaced by 'A'.

*   **Example 2:**
    *   Input: 20x10 grid.
    *   Markers: Two 'X' characters.
        *   Row 0, Col 9: 'X'
        *   Row 2, Col 9: 'X'
    *   Output: 10x10 grid.
    *   Observation: Input height 20. Output height 10. Width 10.
    *   Again, the grid is split horizontally. The X's are in the top half (rows 0 and 2).
    *   Output corresponds to Input Rows 0-9.
    *   The 'X's are replaced by 'A'.
    *   Wait, let's look closer at Ex 2 Input.
        *   Row 0: `A A A A A A A A A X`
        *   Row 2: `A A A A A A A A A X`
        *   Output Row 0: `A A A A A A A A A A`
        *   Output Row 2: `A A A A A A A A A A`
    *   So yes, keep the half with the X's, remove X's.

*   **Example 3:**
    *   Input: 16x46 grid.
    *   Markers: Two 'X' characters.
        *   Row 13, Col 0: 'X'
        *   Row 15, Col 0: 'X'
    *   Output: 8x46 grid.
    *   Observation: Input height 16. Output height 8.
    *   The X's are in the bottom half (rows 13 and 15).
    *   Output corresponds to Input Rows 8-15? Or Rows 0-7?
    *   Let's check the content.
        *   Input Row 13: `X A A ...`
        *   Input Row 15: `X A A ...`
        *   Output Row 0: `A A G A G ...` (Matches Input Row 2?)
        *   Output Row 1: `A A A A A ... G A G ...` (Matches Input Row 3?)
        *   Let's check Input Row 8: `A A G A G ...`
        *   Let's check Input Row 9: `A A A A A ... G A G ...`
        *   So Output Row 0 matches Input Row 8. Output Row 7 matches Input Row 15.
        *   So we kept the *bottom* half (Rows 8-15).
    *   The X's were in the bottom half. We kept the bottom half.
    *   The X's are replaced by 'A'.
    *   Wait, the description says "keeping their side". If X's are at the bottom, we keep the bottom side.
    *   So the rule is: Identify the half of the grid containing the 'X' markers. Crop the grid to that half. Replace 'X' with 'A'.

*   **Example 4:**
    *   Input: 10x21 grid.
    *   Markers: Two 'X' characters.
        *   Row 0, Col 0: 'X'
        *   Row 0, Col 2: 'X'
    *   Output: 10x11 grid.
    *   Observation: Input height 10. Output height 10. Input width 21. Output width 11.
    *   Here the split is vertical!
    *   The X's are in the left half (Cols 0 and 2).
    *   Output width is 11 (approx half of 21).
    *   Output corresponds to Input Cols 0-10.
    *   The X's are replaced by 'A'.
    *   Wait, let's check the content.
        *   Input Row 0: `X A X A A ...`
     

... [6971 chars truncated]
alt-15 geology qwen3.5-122b: fig alone solves
"Two fault markers are exposed in one cliff face of the canyon. A seismic event splits the plateau along their axis — the far half calves away like an iceberg. Erosion smooths the marker outcrops until they are indistinguishable from the surrounding bedrock."
alt-2 cooking qwen3.5-122b: fail
"Two cloves pressed into the crust mark where the chef's knife will fall. The blade bisects the pastry along their line, and the garnished half is plated while the other returns to the kitchen. The cloves are plucked before serving."
Fail (best cell_acc=0.44 at k=1)
Best Attempt
vs
Expected
Reasoning (11698 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A decorated pastry with two clove studs pressed into one edge, and various frosted patterns across the surface.
*   **What to do:** Slice through the pastry along the axis the cloves define, plate only the half that bore the cloves, and remove them before serving.
*   **Grid details:** Output is the clove-bearing half with cloves replaced by plain crust.

**Interpretation:**
*   "Pastry": The input grid.
*   "Clove studs": Specific markers in the grid. Looking at the training examples, I need to identify what represents the "cloves".
*   "One edge": The cloves are located on a specific boundary or side.
*   "Axis the cloves define": A line connecting the cloves.
*   "Slice through": Cut the grid along this line.
*   "Plate only the half that bore the cloves": Keep the side containing the cloves.
*   "Remove them before serving": The "cloves" themselves should be replaced by the background color ("plain crust").

**2. Analyze the Training Examples:**

**Example 1:**
*   **Input:** 20 rows, 21 columns.
    *   Row 0: `X A A A ...` (Starts with X)
    *   Row 1: `A A A A ...`
    *   Row 2: `X B A B ...` (Starts with X)
    *   Rest of rows seem to be patterns of A and B, or just A.
    *   Key observation: There are `X` characters in the first column (Column 0). Specifically at (0,0) and (2,0).
    *   Wait, let's look closer.
    *   Row 0: `X A A ...`
    *   Row 2: `X B A ...`
    *   Are there other X's? Scanning... No other X's visible in the provided text block.
    *   So the "cloves" are the `X` (grey) pixels.
    *   They are located at (0,0) and (2,0).
    *   They define an axis. Since they are in the same column (Column 0), the axis is vertical? Or does it define a cut line?
    *   "Slice through the pastry along the axis the cloves define". If cloves are at (0,0) and (2,0), the line connecting them is the vertical line x=0.
    *   "Plate only the half that bore the cloves". The cloves are on the left edge. So we keep the left side?
    *   "Output is the clove-bearing half with cloves replaced by plain crust."
    *   Let's check the Output dimensions.
    *   Input: 20 rows, 21 cols.
    *   Output: 10 rows, 21 cols.
    *   Wait, the output has 10 rows. The input has 20 rows.
    *   Let's check the content of the output.
    *   Output Row 0: `A A A ...` (Matches Input Row 1)
    *   Output Row 1: `A A A ...` (Matches Input Row 3)
    *   Output Row 2: `A B A ...` (Matches Input Row 4)
    *   Output Row 3: `A A A ...` (Matches Input Row 5)
    *   Output Row 4: `A B A ...` (Matches Input Row 6)
    *   Output Row 5: `A B A ...` (Matches Input Row 7)
    *   Output Row 6: `A A A ...` (Matches Input Row 8)
    *   Output Row 7: `A B A ...` (Matches Input Row 9)
    *   Output Row 8: `A B A ...` (Matches Input Row 10)
    *   Output Row 9: `A A A ...` (Matches Input Row 11)
    *   Wait, let's look at the mapping more carefully.
    *   Input Rows 0-19. Output Rows 0-9.
    *   Input Row 0 starts with X. Input Row 2 starts with X.
    *   The output seems to correspond to the bottom half of the input? Or the top half?
    *   Let's check the content.
    *   Input Row 1: `A A A ...` -> Output Row 0: `A A A ...`
    *   Input Row 3: `A A A ...` -> Output Row 1: `A A A ...`
    *   Input Row 4: `A B A ...` -> Output Row 2: `A B A ...`
    *   Input Row 5: `A A A ...` -> Output Row 3: `A A A ...`
    *   Input Row 6: `A B A ...` -> Output Row 4: `A B A ...`
    *   Input Row 7: `A B A ...` -> Output Row 5: `A B A ...`
    *   Input Row 8: `A A A ...` -> Output Row 6: `A A A ...`
    *   Input Row 9: `A B A ...` -> Output Row 7: `A B A ...`
    *   Input Row 10: `A B A ...` -> Output Row 8: `A B A ...`
    *   Input Row 11: `A A A ...` -> Output Row 9: `A A A ...`
    *   It looks like the output is rows 1 through 10 of the input? No, Input Row 10 is `A B A ...`. Output Row 8 is `A B A ...`.
    *   Let's list Input Rows 0-11:
        0: X...
        1: A...
        2: X...
        3: A...
        4: A B...
        5: A...
        6: A B...
        7: A B...
        8: A...
        9: A B...
        10: A B...
        11: A...
    *   Output Rows 0-9:
        0: A... (Matches Input 1)
        1: A... (Matches Input 3)
        2: A B... (Matches Input 4)
        3: A... (Matches Input 5)
        4: A B... (Matches Input 6)
        5: A B... (Matches Input 7)
        6: A... (Matches Input 8)
        7: A B... (Matches Input 9)
        8: A B... (Matches Input 10)
        9: A... (Matches Input 11)
    *   This mapping is weird. It skips Input Row 2 (which has an X). It skips Input Row 0 (which has an X).
    *   It seems to take the rows *between* the X's? Or below the X's?
    *   The X's are at Row 0 and Row 2.
    *   The output starts at Row 1.
    *   The output ends at Row 11.
    * 

... [6797 chars truncated]
alt-3 music qwen3.5-122b: fig alone solves
"Two tuning pegs sit at one end of the instrument's neck. When tightened, they silence everything beyond the halfway fret, leaving only the resonance closest to the headstock. The pegs themselves fall silent, blending into the wood."
alt-4 sports qwen3.5-122b: k=2
"Two referees stand at one sideline, arms raised. At their signal the pitch splits down the center parallel to their position — only their half of the field stays in play, the other half swallowed by fog. The referees step off the line and disappear into the crowd."
MARC valid, solved with k=2
Prediction
vs
Expected
Reasoning (12800 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A playing field with formations of players and two referees along one boundary line.
*   **Action:** The field is halved along the axis the referees define.
*   **Selection:** The active half is the one *nearest* the referees.
*   **Cleanup:** The referees then vacate their positions.
*   **Output:** The referee-side half, with referee positions replaced by empty field (which seems to be 'A' based on the examples, or just the background color).

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input Size:** 20 rows x 19 columns.
    *   **Referees:** There are 'X' (grey) characters. Looking at the input, there are 'X's in the first column (index 0) at row 0 and row 2. Wait, let's look closer.
    *   Row 0: `X A A ...`
    *   Row 2: `X B A B ...`
    *   Actually, looking at the pattern, 'X' appears at (0,0) and (2,0).
    *   The description says "two referees positioned along one boundary line". Here, the boundary line seems to be the left edge (column 0).
    *   "The field is halved along the axis the referees define." The referees are at column 0. The axis is likely vertical.
    *   "The active half is the one nearest the referees." Since the referees are on the left edge, the "nearest half" is the left half? Or does it mean the half *containing* the referees?
    *   Let's check the Output.
    *   Input has 20 rows. Output has 10 rows.
    *   Input has 19 columns. Output has 19 columns.
    *   Wait, the output rows are exactly the top 10 rows of the input?
    *   Let's check the content.
    *   Input Row 0: `X A A ...` -> Output Row 0: `A A A ...` (The X became A).
    *   Input Row 1: `A A A ...` -> Output Row 1: `A A A ...`
    *   Input Row 2: `X B A ...` -> Output Row 2: `A B A ...` (The X became A).
    *   Input Row 3: `A A A ...` -> Output Row 3: `A A A ...`
    *   ...
    *   Input Row 9: `A B A ...` -> Output Row 9: `A B A ...`
    *   Input Row 10: `A B A ...` -> Not in output.
    *   So the output is the top half of the grid (rows 0-9).
    *   The referees ('X') were in the top half (rows 0 and 2).
    *   The "axis the referees define" might be the horizontal line separating the top and bottom halves? No, the referees are at specific points.
    *   Let's re-read: "The field is halved along the axis the referees define."
    *   In Example 1, the referees are at (0,0) and (2,0). They are on the left edge.
    *   The output is the top 10 rows. The input has 20 rows. So it's a horizontal cut.
    *   Why top half? The referees are in the top half. "The active half is the one nearest the referees." Since the referees are in the top half, we keep the top half.
    *   "The referees then vacate their positions." The 'X's become 'A's (azure/background).
    *   So, rule hypothesis: Find the referees (X). Determine which half of the grid they are in (top/bottom or left/right). Keep that half. Replace X with background color (A).

*   **Example 2:**
    *   **Input Size:** 20 rows x 10 columns.
    *   **Referees:** 'X' characters.
    *   Row 0: `... A X` (Last column)
    *   Row 2: `... A X` (Last column)
    *   Referees are at (0, 9) and (2, 9). They are on the right edge.
    *   Input has 20 rows. Output has 10 rows.
    *   Output corresponds to rows 0-9 of the input.
    *   Input Row 0: `A A A A A A A A A X` -> Output Row 0: `A A A A A A A A A A` (X became A).
    *   Input Row 2: `A A A A A A A A A X` -> Output Row 2: `A A A A A A A A A A` (X became A).
    *   Again, the output is the top half (rows 0-9).
    *   The referees are in the top half.
    *   Wait, in Example 1, referees were on the left edge. In Example 2, referees are on the right edge. In both cases, the output is the top half.
    *   Why top half?
    *   Maybe the "axis" is defined by the row indices of the referees?
    *   In Ex 1, referees at row 0 and 2.
    *   In Ex 2, referees at row 0 and 2.
    *   Maybe the cut is horizontal, splitting the grid into top and bottom. The half containing the referees is kept.
    *   In both examples, the referees are in the top half (rows 0-9 of a 20-row grid).
    *   So the rule seems to be: Identify the half (top/bottom or left/right) containing the 'X' markers. Crop the grid to that half. Replace 'X' with 'A'.
    *   How is the "half" determined?
    *   Ex 1: 20 rows, 19 cols. Referees at col 0. Output is 10 rows, 19 cols. This implies a horizontal cut (splitting rows).
    *   Ex 2: 20 rows, 10 cols. Referees at col 9. Output is 10 rows, 10 cols. This implies a horizontal cut.
    *   Why horizontal and not vertical?
    *   Maybe because the referees are aligned horizontally? In Ex 1, rows 0 and 2. In Ex 2, rows 0 and 2. They are close to the top.
    *   If the cut was vertical, we would keep the left half (Ex 1) or right half (Ex 2).
    *  

... [7856 chars truncated]
alt-5 weather qwen3.5-122b: fail
"Two lightning rods stand on the roof's edge, and when the storm breaks, a curtain of rain erases everything on the far side of the building. The rods, their work done, rust into the same grey as the slate beneath them."
Fail (best cell_acc=0.00 at k=1)
No grid
vs
Expected
Reasoning (10671 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A rooftop with weathervanes and tile patterns, plus two lightning rods mounted along one edge.
*   **What to do:** A storm wipes away the half of the structure opposite the rods. The rods corrode into the roofing material.
*   **Grid details:** The rod-bearing half persists; rods become indistinguishable from the roof surface.

**2. Analyze the Training Example:**
*   **Input:** 20 rows x 21 columns.
    *   Row 0: `X A A A A A A A A A A A A A A A A A A A A` (Starts with X, rest A)
    *   Row 1: `A A A A A A A A A A A A A A A A A A A A A` (All A)
    *   Row 2: `X B A B A B A B A B A B A B A B A B A B` (Starts with X, then alternating B A)
    *   Row 3: `A A A A A A A A A A A A A A A A A A A A A` (All A)
    *   Row 4: `A B A B A B A B A B A B A B A B A B A B` (Alternating B A)
    *   ... and so on.
    *   There are rows with `X` at the beginning (Row 0, Row 2).
    *   There are rows with `A` at the beginning (Row 1, Row 3, Row 4, etc.).
    *   The `X` appears in the first column of specific rows.
    *   The rest of the grid seems to be a pattern of `A` (azure) and `B` (blue).
    *   Let's look at the structure.
    *   Rows 0-19.
    *   Rows with `X` at col 0: Row 0, Row 2.
    *   Wait, let's look closer at the input grid provided in the example.
    *   Row 0: `X A A ...`
    *   Row 1: `A A A ...`
    *   Row 2: `X B A B ...`
    *   Row 3: `A A A ...`
    *   Row 4: `A B A B ...`
    *   Row 5: `A A A ...`
    *   Row 6: `A B A B ...`
    *   Row 7: `A B A B ...`
    *   Row 8: `A A A ...`
    *   Row 9: `A B A B ...`
    *   Row 10: `A B A B ...`
    *   Row 11: `A A A ...`
    *   Row 12: `A B A B ...`
    *   Row 13: `A A A ...`
    *   Row 14: `A B A B ...`
    *   Row 15: `A A A ...`
    *   Row 16: `A A A ...`
    *   Row 17: `A A A ...`
    *   Row 18: `A A A ...`
    *   Row 19: `A A A ...`

    *   **Output:** 10 rows x 21 columns.
    *   The output height is exactly half the input height (20 -> 10).
    *   The output content matches the bottom half of the input? Or the top half?
    *   Let's check the output rows against input rows.
    *   Output Row 0: `A A A ...` (Matches Input Row 1)
    *   Output Row 1: `A A A ...` (Matches Input Row 3)
    *   Output Row 2: `A B A B ...` (Matches Input Row 4)
    *   Output Row 3: `A A A ...` (Matches Input Row 5)
    *   Output Row 4: `A B A B ...` (Matches Input Row 6)
    *   Output Row 5: `A B A B ...` (Matches Input Row 7)
    *   Output Row 6: `A A A ...` (Matches Input Row 8)
    *   Output Row 7: `A B A B ...` (Matches Input Row 9)
    *   Output Row 8: `A B A B ...` (Matches Input Row 10)
    *   Output Row 9: `A A A ...` (Matches Input Row 11)
    *   Wait, let's look at the Input Rows again.
    *   Input Row 0 has `X`. Input Row 2 has `X`.
    *   The metaphor says: "two lightning rods mounted along one edge". The `X` (grey) seems to represent the rods. They are in the first column.
    *   "A storm wipes away the half of the structure opposite the rods."
    *   "The rod-bearing half persists".
    *   This implies we keep the half containing the rods.
    *   In the input, the rods (`X`) are in the top rows (Row 0, Row 2).
    *   However, the output has 10 rows. The input has 20 rows.
    *   If we keep the "rod-bearing half", and the rods are at the top, we should keep the top half?
    *   Let's check the Output content again.
    *   Output Row 0: `A A A ...`
    *   Input Row 0: `X A A ...`
    *   Input Row 1: `A A A ...`
    *   Input Row 2: `X B A B ...`
    *   Input Row 3: `A A A ...`
    *   Input Row 4: `A B A B ...`
    *   Input Row 5: `A A A ...`
    *   Input Row 6: `A B A B ...`
    *   Input Row 7: `A B A B ...`
    *   Input Row 8: `A A A ...`
    *   Input Row 9: `A B A B ...`
    *   Input Row 10: `A B A B ...`
    *   Input Row 11: `A A A ...`
    *   Input Row 12: `A B A B ...`
    *   Input Row 13: `A A A ...`
    *   Input Row 14: `A B A B ...`
    *   Input Row 15: `A A A ...`
    *   Input Row 16: `A A A ...`
    *   Input Row 17: `A A A ...`
    *   Input Row 18: `A A A ...`
    *   Input Row 19: `A A A ...`

    *   Output Row 0: `A A A ...` (Matches Input Row 1)
    *   Output Row 1: `A A A ...` (Matches Input Row 3)
    *   Output Row 2: `A B A B ...` (Matches Input Row 4)
    *   Output Row 3: `A A A ...` (Matches Input Row 5)
    *   Output Row 4: `A B A B ...` (Matches Input Row 6)
    *   Output Row 5: `A B A B ...` (Matches Input Row 7)
    *   Output Row 6: `A A A ...` (Matches Input Row 8)
    *   Output Row 7: `A B A B ...` (Matches Input Row 9)
    *   Output Row 8: `A B A B ...` (Matches Input Row 10)
    *   Output Row 9: `A A A ...` (Matches Input Row 11)

    *   Wait, the output rows correspond to Input Rows 1, 3, 4, 5, 6, 7, 8, 9, 10, 11.
    *   This is not a simple "keep top half" or "keep bottom 

... [5680 chars truncated]
alt-6 architecture qwen3.5-122b: fig alone solves
"Two keystones are embedded in one facade of the cathedral. The master builder declares the wing beyond the nave redundant — it is demolished, and the keystones are plastered over to match the surrounding wall."
alt-7 warfare qwen3.5-122b: fail
"Two signal flags are planted along the front line. The general orders a strategic withdrawal: everything beyond the midfield is ceded to the enemy. The flags are struck and the posts left bare so the enemy cannot read the retreat's intent."
Fail (best cell_acc=0.44 at k=1)
Best Attempt
vs
Expected
Reasoning (13019 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A battlefield with troop formations and two signal flags posted along one edge.
*   **What to do:** Retreat from the far half, keeping only the territory nearest the flags. Remove the flags from their posts.
*   **Grid details:** The flag-side half remains. Flag positions become empty ground.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** 20 rows, 21 columns.
        *   Row 0: `X A A A ...` (Starts with X, rest A)
        *   Row 1: `A A A A ...` (All A)
        *   Row 2: `X B A B ...` (Starts with X, then alternating B A)
        *   ...
        *   There seem to be 'X' characters in the first column of some rows (Row 0, Row 2).
        *   The rest of the grid is filled with 'A' (azure) and 'B' (blue) in patterns.
    *   **Output:** 10 rows, 21 columns.
        *   The output has exactly half the number of rows of the input (20 -> 10).
        *   The content of the output rows matches the content of the input rows starting from Row 2? Let's check.
        *   Input Row 0: `X A A ...` -> Output Row 0: `A A A ...` (Wait, Input Row 1 is `A A A ...`, Output Row 0 is `A A A ...`)
        *   Input Row 1: `A A A ...` -> Output Row 0: `A A A ...`
        *   Input Row 2: `X B A B ...` -> Output Row 2: `A B A B ...` (The X is gone, replaced by A).
        *   Input Row 3: `A A A ...` -> Output Row 3: `A A A ...`
        *   Input Row 4: `A B A B ...` -> Output Row 4: `A B A B ...`
        *   ...
        *   Input Row 19: `A A A ...` -> Output Row 9: `A A A ...`
        *   Wait, let's look closer at the row indices.
        *   Input has 20 rows. Output has 10 rows.
        *   Input Row 0 starts with X. Input Row 2 starts with X.
        *   The metaphor says "two signal flags posted along one edge". The 'X' (grey) likely represents the flags. They are in the first column (left edge).
        *   "Retreat from the far half, keeping only the territory nearest the flags."
        *   If the flags are on the left edge, "nearest the flags" implies the left side? But the output width is the same as input width (21 columns). The height is halved.
        *   Let's re-read: "Retreat from the far half". Usually, grids are processed top-to-bottom or left-to-right.
        *   If the flags are on the *left* edge (Column 0), maybe the "half" refers to rows?
        *   Let's look at the rows containing flags. Row 0 and Row 2 have 'X'.
        *   The output has 10 rows. The input has 20 rows.
        *   The output rows correspond to Input Rows 1 through 10? Or 0 through 9?
        *   Let's check the content.
        *   Output Row 0: `A A A ...` matches Input Row 1.
        *   Output Row 1: `A A A ...` matches Input Row 3? No, Input Row 3 is `A A A ...`.
        *   Output Row 2: `A B A B ...` matches Input Row 4? Input Row 4 is `A B A B ...`.
        *   Wait, Input Row 2 is `X B A B ...`. Output Row 2 is `A B A B ...`. This looks like Input Row 2 with the X removed.
        *   Let's check the mapping more carefully.
        *   Input Rows:
            0: X A A ...
            1: A A A ...
            2: X B A B ...
            3: A A A ...
            4: A B A B ...
            5: A A A ...
            6: A B A B ...
            7: A B A B ...
            8: A A A ...
            9: A B A B ...
            10: A B A B ...
            11: A A A ...
            12: A B A B ...
            13: A A A ...
            14: A B A B ...
            15: A A A ...
            16: A A A ...
            17: A A A ...
            18: A A A ...
            19: A A A ...
        *   Output Rows:
            0: A A A ... (Matches Input 1)
            1: A A A ... (Matches Input 3)
            2: A B A B ... (Matches Input 4)
            3: A A A ... (Matches Input 5)
            4: A B A B ... (Matches Input 6)
            5: A A A ... (Matches Input 8)
            6: A B A B ... (Matches Input 9)
            7: A B A B ... (Matches Input 10)
            8: A A A ... (Matches Input 11)
            9: A B A B ... (Matches Input 12)
        *   This mapping is confusing. Let's look at the "half" concept.
        *   Input height = 20. Output height = 10.
        *   The metaphor says "Retreat from the far half, keeping only the territory nearest the flags."
        *   Flags are at (0,0) and (2,0). They are on the top-left edge.
        *   "Nearest the flags" usually means the top half if flags are at the top.
        *   If we keep the top half (Rows 0-9), we should see 10 rows.
        *   Let's check if Output Row 0 corresponds to Input Row 0 (with X removed).
            *   Input Row 0: `X A A ...`
            *   Output Row 0: `A A A ...`
            *   This matches if X becomes A (empty ground).
        *   Let's check Output Row 1 vs Input Row 1.
            *   Input Row 1: `A A A ...`
   

... [8049 chars truncated]
alt-8 theater qwen3.5-122b: k=1
"Two stagehands pin marks on one edge of the curtain. When the cue comes, the curtain is cut along its center seam and the unmarked half drops into the pit. The pins are pulled from the surviving drape, leaving no trace of the cut."
MARC valid, solved with k=1
Prediction
vs
Expected
Reasoning (12230 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **What you see:** A grand curtain with embroidered patterns and two small pins along one selvedge edge.
*   **What to do:** Cut the curtain in half along the axis the pins indicate, drop the unpinned half, and remove the pins from what remains.
*   **Grid details:** Output is the pinned half, pin locations replaced by curtain fabric.

**2. Analyze the Training Example:**
*   **Input:** 20 rows, 21 columns.
    *   Row 0: `X A A A A A A A A A A A A A A A A A A A A` (Starts with X, rest A)
    *   Row 1: `A A A A A A A A A A A A A A A A A A A A A` (All A)
    *   Row 2: `X B A B A B A B A B A B A B A B A B A B` (Starts with X, then alternating B A)
    *   ...
    *   There are `X` characters in the first column (index 0) at Row 0 and Row 2.
    *   The rest of the grid seems to be a pattern of `A` (azure) and `B` (blue).
    *   Let's check the position of `X`.
        *   Row 0, Col 0: `X`
        *   Row 2, Col 0: `X`
    *   The metaphor says "two small pins along one selvedge edge". The `X` characters are likely the pins. They are on the left edge (column 0).
    *   "Cut the curtain in half along the axis the pins indicate". The pins are at (0,0) and (2,0). They define a vertical line? Or do they define a horizontal cut?
    *   Wait, the metaphor says "Cut the curtain in half along the axis the pins indicate".
    *   If the pins are at (0,0) and (2,0), they are on the left edge.
    *   "Drop the unpinned half".
    *   "Output is the pinned half".
    *   Let's look at the Output dimensions.
    *   Input: 20 rows, 21 columns.
    *   Output: 10 rows, 21 columns.
    *   The output has exactly half the number of rows.
    *   This suggests a horizontal cut.
    *   Where is the cut?
    *   Input rows 0-19. Output rows 0-9.
    *   So the top half is kept.
    *   Why the top half?
    *   The pins are at Row 0 and Row 2. These are in the top half.
    *   The metaphor says "two small pins along one selvedge edge".
    *   If the pins are at (0,0) and (2,0), they are on the left edge.
    *   Maybe the "axis the pins indicate" is the horizontal axis defined by the pins? No, that doesn't make sense for a cut.
    *   Maybe the pins indicate *which half* to keep?
    *   "Drop the unpinned half". The half containing the pins is kept.
    *   The pins are in the top half (rows 0-9). The bottom half (rows 10-19) has no pins.
    *   So we keep the top half.
    *   "Remove the pins from what remains".
    *   In the output, the `X` at (0,0) and (2,0) are gone. They are replaced by `A`.
    *   Let's check the output grid content.
    *   Output Row 0: `A A A ...` (Input Row 0 was `X A A ...`, so X became A).
    *   Output Row 1: `A A A ...` (Input Row 1 was `A A A ...`).
    *   Output Row 2: `A B A B ...` (Input Row 2 was `X B A B ...`, so X became A).
    *   Output Row 3: `A A A ...` (Input Row 3 was `A A A ...`).
    *   ...
    *   Output Row 9: `A B A B ...` (Input Row 9 was `A B A B ...`).
    *   So the transformation is:
        1.  Identify the "pins" (special color, here `X`).
        2.  Determine which half of the grid contains the pins. The grid is split in half (horizontally or vertically?). In Example 1, the grid is 20x21. The output is 10x21. So it's a horizontal split. The pins are in the top half.
        3.  Keep the half with the pins.
        4.  Replace the pin locations with the background fabric color. In Example 1, the background seems to be `A` (azure) mostly, or at least the `X` is replaced by `A`.
        5.  Wait, looking closely at Example 1 Input Row 0: `X A A ...`. Output Row 0: `A A A ...`. So `X` -> `A`.
        6.  Input Row 2: `X B A B ...`. Output Row 2: `A B A B ...`. So `X` -> `A`.
        7.  Why `A`? `A` is the dominant color in the first column of the input (except for the Xs). Row 1 col 0 is `A`. Row 3 col 0 is `A`. So the "fabric" color at the pin location is `A`.

**3. Analyze the Test Input:**
*   **Input Grid:**
    ```
    A W A W A X A X
    A A A A A A A A
    A W A W A W A W
    A A A A A A A A
    ```
*   **Dimensions:** 4 rows, 8 columns.
*   **Colors:** `A` (azure), `W` (maroon), `X` (grey).
*   **Pins:** `X` characters.
    *   Row 0, Col 5: `X`
    *   Row 0, Col 7: `X`
*   **Location of Pins:** Top row (Row 0).
*   **Split Direction:**
    *   In Example 1, the grid was tall (20 rows) and the cut was horizontal (kept top 10 rows).
    *   Here, the grid is short (4 rows) and wide (8 columns).
    *   The metaphor says "Cut the curtain in half along the axis the pins indicate".
    *   In Example 1, pins were on the left edge (col 0). The cut was horizontal (splitting rows).
    *   Here, pins are on the top edge (row 0).
    *   If the pins are on the top edge, maybe the cut is vertical?
    *   Let's check the metaphor again: "two small pins along one selvedge edge".
    *   Se

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alt-9 gardening qwen3.5-122b: fail
"Two stakes are driven into the soil at one border of the garden. Come autumn, the gardener folds the plot in half along their line and mulches everything on the far side. The stakes are pulled up, leaving only soft earth behind."
Fail (best cell_acc=0.44 at k=2)
Best Attempt
vs
Expected
Reasoning (11814 chars)
The user wants me to solve a grid transformation puzzle based on a metaphorical description and training examples.

**1. Analyze the Metaphorical Description:**
*   **Scene:** A garden plot with plantings in repeating rows, and two wooden stakes along one edge.
*   **Action:** Fold the garden at its midline toward the stakes, discard the far half, and pull out the stakes.
*   **Result:** The stake-side half of the garden remains. Stake holes fill with soil.

**2. Analyze the Training Examples:**

*   **Example 1:**
    *   **Input:** 20 rows, 21 columns.
        *   Row 0: `X A A ...` (Starts with X)
        *   Row 2: `X B A B ...` (Starts with X)
        *   Other rows are mostly `A` or `A B` patterns.
        *   The `X` appears in the first column of Row 0 and Row 2.
        *   Wait, let's look closer at the input grid structure.
        *   Input dimensions: 20 rows x 21 columns.
        *   Output dimensions: 10 rows x 21 columns.
        *   The output height is exactly half the input height.
        *   The output content matches the bottom half of the input? Or the top half?
        *   Let's check the rows.
        *   Input Row 0: `X A A ...`
        *   Input Row 1: `A A A ...`
        *   Input Row 2: `X B A B ...`
        *   ...
        *   Input Row 19: `A A A ...`
        *   Output Row 0: `A A A ...` (Matches Input Row 1?)
        *   Output Row 1: `A A A ...` (Matches Input Row 3?)
        *   Output Row 2: `A B A B ...` (Matches Input Row 4?)
        *   Let's check the "stake" metaphor. "Two wooden stakes along one edge".
        *   In Input Example 1, `X` (grey) appears at (0,0) and (2,0). These are on the left edge (column 0).
        *   "Fold the garden at its midline toward the stakes".
        *   If stakes are on the left edge, the midline would be vertical?
        *   But the output height is halved (20 -> 10). This suggests a horizontal fold.
        *   If the fold is horizontal, the stakes should be on the top or bottom edge.
        *   Let's re-examine the input grid for Example 1.
        *   Rows 0-19.
        *   Output Rows 0-9.
        *   Let's look at the content of the output.
        *   Output Row 0: `A A A ...`
        *   Output Row 1: `A A A ...`
        *   Output Row 2: `A B A B ...`
        *   Output Row 3: `A A A ...`
        *   Output Row 4: `A B A B ...`
        *   Output Row 5: `A A A ...`
        *   Output Row 6: `A B A B ...`
        *   Output Row 7: `A B A B ...`
        *   Output Row 8: `A A A ...`
        *   Output Row 9: `A B A B ...`
        *   Let's compare this to the Input.
        *   Input Row 10: `A B A B ...`
        *   Input Row 11: `A A A ...`
        *   Input Row 12: `A B A B ...`
        *   Input Row 13: `A A A ...`
        *   Input Row 14: `A B A B ...`
        *   Input Row 15: `A A A ...`
        *   Input Row 16: `A A A ...`
        *   Input Row 17: `A A A ...`
        *   Input Row 18: `A A A ...`
        *   Input Row 19: `A A A ...`
        *   This doesn't seem to match the bottom half directly.
        *   Let's look at the top half.
        *   Input Row 0: `X A A ...`
        *   Input Row 1: `A A A ...`
        *   Input Row 2: `X B A B ...`
        *   Input Row 3: `A A A ...`
        *   Input Row 4: `A B A B ...`
        *   Input Row 5: `A A A ...`
        *   Input Row 6: `A B A B ...`
        *   Input Row 7: `A B A B ...`
        *   Input Row 8: `A A A ...`
        *   Input Row 9: `A B A B ...`
        *   Comparing Output to Input Top Half (Rows 0-9):
            *   Out 0 (`A A A`) vs In 0 (`X A A`). The `X` is gone.
            *   Out 1 (`A A A`) vs In 1 (`A A A`). Match.
            *   Out 2 (`A B A B`) vs In 2 (`X B A B`). The `X` is gone.
            *   Out 3 (`A A A`) vs In 3 (`A A A`). Match.
            *   Out 4 (`A B A B`) vs In 4 (`A B A B`). Match.
            *   Out 5 (`A A A`) vs In 5 (`A A A`). Match.
            *   Out 6 (`A B A B`) vs In 6 (`A B A B`). Match.
            *   Out 7 (`A B A B`) vs In 7 (`A B A B`). Match.
            *   Out 8 (`A A A`) vs In 8 (`A A A`). Match.
            *   Out 9 (`A B A B`) vs In 9 (`A B A B`). Match.
        *   So the Output is exactly the Top Half of the Input (Rows 0 to 9), but with the `X` characters replaced by `A` (azure/soil).
        *   Wait, the metaphor says "Fold the garden at its midline toward the stakes, discard the far half".
        *   If the stakes are on the left edge (Column 0), and we fold at the midline...
        *   Input height is 20. Midline is between row 9 and 10.
        *   If we fold "toward the stakes", and stakes are on the left... that implies a vertical fold?
        *   But the output height is halved. This implies a horizontal fold.
        *   If the fold is horizontal, the stakes must be on the top or bottom edge.
        *   In Example 1, `X` is at (0,0) and (2,0). These are on the left edge.
        *   However, the transformation clearly keeps the top half (rows 0-9) and removes the bottom half 

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